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Question 1
Incorrect
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A 55-year-old man with a ventricular rate of 210 beats per minute is admitted to the emergency department with atrial fibrillation. The patient develops ventricular fibrillation shortly after receiving pharmacotherapy to treat his arrhythmia, from which he is successfully resuscitated.
He has a PR interval of 40 Ms, a prominent delta wave in lead I, and a QRS duration of 120 Ms, according to an ECG from a previous admission.
Which of the following drugs is most likely to be involved in this patient's development of ventricular fibrillation?Your Answer: Amiodarone
Correct Answer: Digoxin
Explanation:The Wolff-Parkinson-White syndrome (WPWS) is linked to an additional electrical conduction pathway between the atria and ventricles. This accessory pathway (bundle of Kent), unlike the atrioventricular (AV) node, is incapable of slowing down a rapid rate of atrial depolarization. In other words, a short circuit bypasses the AV node. Patients with a rapid ventricular response or narrow complex AV re-entry tachycardia are more likely to develop atrial fibrillation or flutter.
Digoxin can promote impulse transmission through this accessory pathway if a patient with WPWS develops atrial fibrillation because it works by blocking the AV node. This can cause ventricular fibrillation and an extremely rapid ventricular rate. As a result, it’s not advised.
Adenosine, beta-blockers, and calcium channel blockers, among other drugs that interfere with AV nodal conduction, are also generally contraindicated.
The class III antiarrhythmic drugs amiodarone and ibutilide (K+ channel block) and procainamide (Na+ channel block) are the drugs of choice.
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This question is part of the following fields:
- Pharmacology
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Question 2
Incorrect
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A young male is undergoing inguinal hernia repair. During the procedure, the surgeons approach the inguinal canal and expose the superficial inguinal ring.
Which structure forms the lateral edge of the superficial inguinal ring?Your Answer: Rectus abdominis muscle
Correct Answer: External oblique aponeurosis
Explanation:The superficial inguinal ring is an opening in the aponeurosis of the external oblique muscle, just above and lateral to the pubic crest.
The superficial ring resembles a triangle more than a ring with the base lying on the pubic crest and its apex pointing towards the anterior superior iliac spine. The sides of the triangle are crura of the opening in the external oblique aponeurosis. The lateral crura of the triangle is attached to the pubic tubercle. The medial crura of the triangle is attached to the pubic crest.
The external oblique aponeurosis forms the anterior wall of the inguinal canal and also the lateral edge of the superficial inguinal ring. The rectus abdominis lies posteromedially, and the transversalis posterior to this.
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This question is part of the following fields:
- Anatomy
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Question 3
Correct
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An 85-year old female is being investigated and treated for pancytopenia of unknown origin. Her most recent blood test is shown below which shows that he has a low platelet count.
Hb-102 g/l
WBC - 2.9* 109/l
Platelets - 7 * 109/l
Which of the following normally stimulates platelet production?
Your Answer: Thrombopoietin
Explanation:Interleukin-4 is a cytokine which acts to regulate the responses of B and T cells.
Erythropoietin is responsible for the signal that initiated red blood cell production.
Granulocyte-colony stimulating factor stimulates the bone marrow to produce granulocytes.
Interleukin-5 is a cytokine that stimulates the proliferation and activation of eosinophils.
Thrombopoietin is the primary signal responsible for megakaryocyte and thus platelet production.
Platelets are also called thrombocytes. They, like red blood cells, are also derived from myeloid stem cells. The process involves a megakaryocyte developing from a common myeloid progenitor cell. A megakaryocyte is a large cell with a multilobulated nucleus, this grows to become massive where it will then break up to form platelets.Immune cells are generated from haematopoietic stem cells in bone marrow. They generate two main types of progenitors, myeloid and lymphoid progenitor cells, from which all immune cells are derived.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 4
Correct
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A 40-year old gentleman has palpitations and has gone to the emergency department. He is found to have monomorphic ventricular tachycardia. The resting potential of ventricular monocytes is maintained by which electrolyte?
Your Answer: Potassium
Explanation:Potassium maintains the resting potential of cardiac myocytes, with depolarization triggered by a rapid influx of sodium ions, and repolarization due to efflux of potassium. A slow influx of calcium is responsible for the longer duration of a cardiac action potential compared with skeletal muscle.
The cardiac action potential has several phases which have different mechanisms of action as seen below:
Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
These channels automatically deactivate after a few ms.Phase 1: caused by early repolarisation and an efflux of potassium.
Phase 2: Plateau – caused by a slow influx of calcium.
Phase 3 – Final repolarisation – caused by an efflux of potassium.
Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potentialOf note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.
Different sites have different conduction velocities:
1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec2. AV node conduction – 0.05 m/sec
3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 5
Correct
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What is the mechanism of the pupillary reflex arc?
Your Answer: Oculomotor nerve fibres from the Edinger-Westphal nuclei
Explanation:Pupil size is reduced by the pupillary light reflex and during accommodation for near vision. In the pupillary light reflex, light that strikes the retina is processed by retinal circuits that excite W-type retinal ganglion cells. These cells respond to diffuse illumination. The axons of some of the W-type cells project through the optic nerve and tract to the pretectal area, where they synapse in the olivary pretectal nucleus. This nucleus contains neurons that also respond to diffuse illumination. Activity of neurons of the olivary pretectal nucleus causes pupillary constriction by means of bilateral connections with parasympathetic preganglionic neurons in the Edinger-Westphal nuclei. The reflex results in contraction of the pupillary sphincter muscles in both eyes, even when light is shone into only one eye.
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This question is part of the following fields:
- Pathophysiology
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Question 6
Incorrect
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An 81-year old man was admitted to the Pulmonology Ward due to chronic obstructive airway disease (COPD) exacerbation. Upon physical examination, he was hypertensive at 140/90 mmHg, tachycardic at 114 beats per minute, and tachypnoeic at 33 breaths per minute.
Arterial blood gas analysis was obtained and showed the following results:
pH: 7.25 (Reference range: 7.35-7.45)
PaO2: 73 mmHg (9.7 kPa) (Reference range: 11.3-12.6 kPa)
PaCO2: 56 mmHg (7.5 kPa) (Reference range: 4.7-6.0 kPa)
SaO2: 90%
Standard bicarbonate: 29 mmol/L (Reference range: 20-28)
BE: +4 mmol/L (± 2)
Which of the following options has the most significant impact on his respiratory rate?Your Answer: Arterial PaCO2
Correct Answer: CSF pH
Explanation:The arterial blood gas analysis indicates presence of acute respiratory acidosis.
Central chemoreceptors are located in the ventral medulla and respond directly to presence of hydrogen ions in the CSF. When stimulated, it causes an increase in respiratory rate.
It is believed that hydrogen ions may be the only important direct stimulus for these neurons, however, CO2 is believed to stimulate these neurons secondarily by changing the hydrogen ion concentration.
Changes in O2 concentration have virtually no direct effect on the respiratory centre itself to alter respiratory drive. Although, O2 changes do have an indirect effect by acting through the peripheral chemoreceptors.
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This question is part of the following fields:
- Pathophysiology
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Question 7
Correct
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About the vagus nerve, which one of these is true ?
Your Answer: Gives off the recurrent laryngeal nerve on the right as it passes anteriorly across the subclavian artery
Explanation:The tenth cranial nerve (vagus nerve) has both sensory and motor divisions.
It emerges from the anterolateral surface of the medulla in a groove between the olive and the inferior cerebellar peduncle as a series of 8-10 rootlets . It leaves the skull through the middle compartment of the jugular foramen and descends within the carotid sheath between the internal carotid artery and internal jugular vein. The right vagus crosses in front of the first part of the subclavian artery. It gives off the right recurrent laryngeal nerve at this point.
The left recurrent laryngeal nerve passes around the ligamentum arteriosum.
The external laryngeal nerve supplies the cricothyroid muscle while the recurrent laryngeal nerve supplies the other laryngeal muscles.
The cranial part of the accessory nerve supplies all the muscles of the palate, via the pharyngeal plexus and the pharyngeal branch of the vagus nerve, except the tensor veli palatini which is supplied by the mandibular branch of the trigeminal nerve.
The Sternothyroid, Sternohyoid, and Omohyoid muscles are supplied by the ansa cervicalis while the thyrohyoid muscle is supplied by the hypoglossal nerve.
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This question is part of the following fields:
- Anatomy
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Question 8
Incorrect
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An 80-year-old female suffered a TIA 2 weeks ago. She has been admitted to the vascular ward as she will be undergoing carotid endarterectomy tomorrow morning. To explain the procedure and its complications, the surgeon gives her information about the procedure, telling her the artery will be tied during the operation.
She inquires about the areas supplied by the different arteries. You explain that the internal carotid artery supplies the brain while the external carotid artery ascends the neck and bifurcates into two arteries. One of these arteries is the superficial temporal artery. Which of the following is the second branch?Your Answer: Facial artery
Correct Answer: Maxillary artery
Explanation:Carotid endarterectomy is the procedure to relieve an obstruction in the carotid artery by opening the artery at its origin and stripping off the atherosclerotic plaque with the intima. This procedure is performed to prevent further episodes, especially in patients who have suffered ischemic strokes or transient ischemic attacks.
The external carotid artery terminates by dividing into the superficial temporal and maxillary branches. The maxillary artery is the larger of the two terminal branches and arises posterior to the neck of the mandible.
The other arteries mentioned in the answer options branch off from the following:
Temporal arteries from the maxillary artery
Middle meningeal artery from the maxillary artery
Lingual artery from the anterior aspect of the external carotid artery
Facial artery from the anterior aspect of the external carotid artery -
This question is part of the following fields:
- Anatomy
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Question 9
Correct
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With regards to devices for temperature management, all of these are used EXCEPT:
Your Answer: Thermistors use the resistance of a semiconductor bead which increases exponentially as the temperature increases
Explanation:There are different types of temperature measurement. These include:
Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially
Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)
Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature
Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output
Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.
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This question is part of the following fields:
- Clinical Measurement
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Question 10
Incorrect
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With respect to the peripheral nerve stimulators, which one is used to perform nerve blocking?
Your Answer: Using an insulated needle improves the success rate for the block
Correct Answer:
Explanation:The nerve stimulators deliver a stimulus lasting for 1-2 milliseconds (not second) to perform nerve blockage.
There are just 2 leads (not 3); one for the skin and other for the needle.
Prior to the administration of the local anaesthesia, a current of 0.25 – 0.5 mA (not 1-2mA) at the frequency of 1-2 Hz is preferred.
If the needle tip is close to the nerve, muscular contraction could be possible at the lowest possible current.
Insulated needles have improved the block success rate, as the current is only conducting through needle tip.
Stimulus to the femoral nerve which is placed in the mid lingual line causes withdrawer of the quadriceps and knee extension, that’s the dancing patella ( not plantar flexion).
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 11
Correct
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About the mechanism of action of bendroflumethiazide, Which of the following is correct?
Your Answer: Sodium-chloride symporter inhibitor
Explanation:Sodium-chloride symporter inhibitor.
The thiazide sensitive sodium chloride symporter is inhibited by thiazides at the proximal portion of the distal convoluted tubule leading to increased sodium and water excretion. Increased delivery of sodium to the distal portion of the distal convoluted tubule promotes potassium loss. This is why thiazides are associated with hyponatraemia and hypokalaemia.
Carbonic anhydrase inhibitors are used mainly in the treatment of glaucoma. They act on the proximal convoluted tubule to promote bicarbonate, sodium and potassium loss.
Sodium potassium chloride symporter is inhibited by Loop diuretics.
Epithelial sodium channels are inhibited by Amiloride.
Drugs which lead to nephrogenic diabetes insipidus such as lithium and demeclocycline, are Inhibitors of vasopressin. -
This question is part of the following fields:
- Pharmacology
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Question 12
Correct
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A 57-year old woman, presents to her general practitioner. She has a 2 week history of a vaginal hysterectomy for which she was placed under general anaesthesia.
On examination, she has notable weakness of dorsiflexion of her left foot and a high stepping gait.
Which nerve was most likely injured during her surgery?Your Answer: Common peroneal nerve
Explanation:The common peroneal (fibular) nerve is a peripheral nerve in the lower limb. It arises of the L4-S2 nerve roots and has sensory and motor innervations:
Sensory: Provides innervation of the lateral leg and foot dorsum.
Motor: Provides innervation of the short head of the biceps femoris, as well as muscles of the anterior and lateral leg compartments.
It is the most commonly damaged nerve in the lower extremity, as it is easily compressed by a plaster cast or injured when the fibula is fractured.
Damage to the common peroneal nerve will result in loss of dorsiflexion at ankle (footdrop, as feet are permanently plantarflexed), with the accompanying high stepping gait.
The saphenous and sural nerve only provide sensory innervation.
The tibial nerve arises from the sciatic nerve (like the common peroneal), but it provides motor innervation to the posterior leg compartments and intrinsic foot muscles. Injury to the tibial nerve will cause loss of plantar flexion, toe flexion and weakened foot inversion.
Extreme hip flexion into the lithotomy or Lloyd-Davies position can result in stretch damage to the neurones (sciatic and obturator nerves) or by applying direct pressure (femoral nerve compression).
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This question is part of the following fields:
- Pathophysiology
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Question 13
Correct
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Which statement is correct concerning breathing systems?
Your Answer: The reservoir bag can limit the pressure in the breathing system to about 40 cm of water
Explanation:Mapleson classified breathing systems into A, B, C, D and E. Jackson-Rees subsequently modified the Mapleson E by adding a double-ended bag to the end of the reservoir tubing, creating the Mapleson F. A Mapleson E or T-piece does not have a reservoir bag.
A Mapleson A system is a very efficient system for use during spontaneous ventilation. However, it is not suitable for use with patients less than 25 kg, due to the increased dead space at the distal / patient end. This system can be modified into a Lack system or coaxial Mapleson A, where the fresh gas flows through an outer tube (30 mm) and exhaled gases flow through the inner tube (14 mm).
The adjustable pressure limiting valve (APL) or expiratory valve allows exhaled gas and excess fresh gas to leave the breathing system. It is a one-way, adjustable spring-loaded valve, and gases escape when the pressure in the system exceeds the valve opening pressure. During spontaneous ventilation a pressure of less than 1 cm of water (0.1 kPa) is needed when the valve is in the open position (not 2 cm of H2O).
The reservoir bag is highly compliant and when over inflated, the rubber bag can limit the pressure in the system to about 40 cm of H2O.
This is due to the law of Laplace, which states that the pressure will fall as the radius of the bag increases:
Pressure = 2 x tension/radius.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 14
Incorrect
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Glyceryl trinitrate (GTN) used for the acute treatment of angina is best administered via the sublingual route.
Why is this the best route of administration?Your Answer: Poor gastric absorption
Correct Answer: High first pass metabolism
Explanation:Glyceryl trinitrate (GTN) has a significant first pass metabolism. About 90% of a dose of GTN is metabolised in the liver by the enzyme glutathione organic nitrate reductase.
An INSIGNIFICANT amount of metabolism occurs in the intestinal mucosa.
There is approximately 1% bioavailability after oral administration and 38% after sublingual administration.
GTN does NOT cause gastric irritation and it is well absorbed in the gastrointestinal tract.
The volume of distribution of GTN is 2.1 to 4.5 L/kg. This is HIGH.
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This question is part of the following fields:
- Pharmacology
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Question 15
Correct
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You've been summoned to the recovery room to examine a 28-year-old man who has had an inguinal hernia repaired.
His vital signs are normal, but you notice that he has developed abnormal upper-limb movements due to muscle contractions that cause repetitive twisting movements.
What do you think is the most likely source for this patient's condition?Your Answer: Prochlorperazine
Explanation:Dystonia is characterised by repetitive twisting movements or abnormal postures. They are classified as either primary or secondary.
Primary dystonia is a genetic disorder that is inherited in an autosomal dominant pattern.
Secondary dystonia can be caused by focal brain lesions, Parkinson’s disease, or certain medications.The following drugs cause the most common drug-induced dystonic reactions:
Antipsychotics, antiemetics (especially prochlorperazine and metoclopramide), and antidepressants.Following the administration of the neuroleptic prochlorperazine, 16 percent of patients experience restlessness (akathisia) and 4% experience dystonia.
Several published reports have linked the anaesthetics thiopentone, fentanyl, and propofol to opisthotonos and other abnormal neurologic sequelae. Dystonias following a general anaesthetic are uncommon. Tramadol has been linked to serotonin syndrome, while remifentanil has been linked to muscle rigidity.
The following are some of the risk factors:
Positive family history
Male
Children
An episode of acute dystonia occurred previously.
Dopamine receptor (D2) antagonists at high doses and recent cocaine useDystonia is treated in a variety of ways, including:
Benztropine (as a first-line therapy):
1-2 mg intravenous injection for adults
Child: 0.02 mg/kg to 1 mg maximumBenzodiazepines are a type of benzodiazepine (second line treatment).
Midazolam:
1-2 mg intravenously, or 5-10 mg IV/PO diazepam
Antihistamines with anticholinergic activity (H1receptor antagonists):
Promethazine 25-50 mg IV/IM, or diphenhydramine 50 mg IV/IM (1 mg/kg in children) are used when benztropine is not available.
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This question is part of the following fields:
- Pharmacology
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Question 16
Incorrect
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A breakthrough lipid-lowering therapy for stroke had a number needed to treat (NNT) of 20 for the prevention of the primary end-point. These results can be best described as:
Your Answer: For 1000 patients treated with active therapy, there would be 20 fewer strokes
Correct Answer: For 1000 patients treated with active therapy, there would be 50 fewer strokes
Explanation:Number needed to treat (NNT) is a time specific epidemiological measure that indicates how many patients would be require for an intervention to prevent one additional bad outcome. A perfect NNT would be 1, where everyone improves with treatment, thus the higher the NNT, the less effective the treatment.
Thus if you treat 1000 patients then you will expect to have 50 fewer strokes.
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This question is part of the following fields:
- Statistical Methods
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Question 17
Incorrect
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Which of the following options is correct regarding the coagulation pathway?
Your Answer: Thrombin converts plasminogen to plasmin
Correct Answer: Tissue factor released by damaged tissue initiates the extrinsic pathway
Explanation:The extrinsic pathway is considered as the main pathway of coagulation cascade.
Heparin is known to inhibit the activation of coagulation factors 2,9,10, and 11.
The extrinsic and intrinsic pathways meet at the activation of coagulation factor 10.
Fibrinogen is converted into Fibrin in the presence of Thrombin. Plasminogen is converted into plasmin during fibrinolysis to breakdown fibrin clot.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 18
Incorrect
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A laser is a device that stimulates atoms or molecules to emit light at particular wavelengths and amplifies that light, typically producing a very narrow beam of radiation. This can be of visible, infrared, or ultraviolet wavelengths. They have been widely utilized in theatre environment.
Which of the following safety measures is most likely to reduce chances of eye injury to the theatre personnel?Your Answer: Use of Class 1 laser devices
Correct Answer: Wearing laser protective goggles
Explanation:Eye damage is the most common potential hazard associated with laser energy. Everyone in the laser treatment room has the risk of eye exposure when working with a Class 3b or Class 4 healthcare laser system, and damage to various structures in the eye depending on wavelength of the laser if they are unprotected.
Red and near-infrared light (400-1400 nm) has very high penetration power. The light causes painless burns on the retina after it is absorbed by melanin in the pigment epithelium just behind the photoreceptors.
Infrared radiation (IR), or infrared light (>1060 nm), is a type of radiant energy that’s invisible to human eyes and hence won’t elicit the protective blink.
Ultraviolet light (<400 nm) is also a form of electromagnetic radiation which is can penetrate the cornea and be absorbed by the iris or the pupil and cause burn injuries or cataract occur due to irreversible photochemical retinal damage. Safety eyewear is the best method of providing eye protection and are designed to absorb light specific to the laser being used. Laser protective eyewear (LPE) includes glasses or goggles of proper optical density (OD). The lenses should not be glass or plastic. The LPE should withstand direct and diffuse scattered laser beams. The laser protection supervisor (LPS) or LSO is an individual who is responsible for any clinical area in which lasers are used. They are expected to have a certain level of equipment and determine what control measures are appropriate, for each individual system, but their presence does not guarantee the chances of having an eye injury. Class 1 lasers are generally safe under every conceivable condition and is not likely to cause any eye damage. Class 3b or Class 4 medical laser systems are utilized in healthcare which have their own safety precautions. Polarized spectacles can make your eyes more comfortable by eliminated glare, however, they will not be able to offer any protection against wavelengths at which laser act.
Using short bursts to reduce energy is also not correct as it would still be harmful to eye. -
This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 19
Incorrect
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A post-operative patient was given paracetamol and pethidine for post-operative analgesia. A few hours later, the patient developed fever of 38°C, hypertension, and agitation.
According to the patient's medical history, he is maintained on Levodopa and Selegiline for Parkinson's disease.
Which of the following is the most probable cause of his manifestation?Your Answer: Exacerbation of Parkinson's disease
Correct Answer: Pethidine
Explanation:Selegiline is a monoamine oxidase inhibitor. Inhibition of monoamine oxidase leads to increased levels of norepinephrine and serotonin in the central nervous system.
Pethidine, also known as meperidine, is a strong agonist at the mu and kappa receptors. It inhibits pain neurotransmission and blocks muscarinic-specific actions.
Administering opioid analgesic is relatively contraindicated to individuals taking monoamine oxidase inhibitors. This is because of the high incidence of serotonin syndrome, which is characterized by fever, agitation, tremor, clonus, hyperreflexia and diaphoresis. Onset of symptoms is within hours, and the treatment is mainly through sedation, paralysis, intubation and ventilation.
The clinical findings are more consistent with Serotonin syndrome rather than exacerbation of Parkinson’s. Parkinson’s Disease (PD) exacerbations are defined as patient-reported or caregiver-reported episodes of subacute worsening of PD motor function in 1 or more domains (bradykinesia, tremor, rigidity, or PD-related postural instability/gait disturbance) that caused a decline in functional status, developed over a period of < 2 months, did not fluctuate with medication timing, and are not caused by intentional adjustments of PD medications by the treating neurologist. Malignant hyperthermia usually occurs within minutes of administration of a volatile anaesthetic, such as halothane, or succinylcholine. There is massive release of calcium from the sarcoplasmic reticulum, leading to fever, acidosis, rhabdomyolysis, trismus, clonus, and hypertension. In sepsis, it more common for patients to present with hypotension rather than hypertension.
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This question is part of the following fields:
- Pharmacology
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Question 20
Incorrect
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What is the most sensitive method of detecting an intra-operative air embolism?
Your Answer: Central venous pressure monitor
Correct Answer: Transoesophageal echocardiogram
Explanation:An intra-operative air embolism occurs when air becomes trapped in the blood vessels during surgery.
A transoesophageal echocardiography (OE) uses invasive echocardiography to monitor the integrity and performance of the heart. It is the gold standard as it provides real-time imaging of the heart to enable early diagnosis and treatment.
Precordial doppler ultrasonography can also be used to detect into-operative air emboli. It is non-invasive and more practical, but is less sensitive.
A change in end-tidal CO2 could be indicative of and increase in physiological dead-space, but could also be indicative of any processes that reduces the excretion or increases the production of CO2, making it non-specific.
A transoesophageal stethoscope can be used to listen for the classic mill-wheel murmur produced by a large air embolus.
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This question is part of the following fields:
- Pathophysiology
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Question 21
Incorrect
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A 30-year old lady has a sub total thyroidectomy. On the 5th post-operative day, the wound becomes erythematous and there is a purulent discharge. The most likely organism causing this is:
Your Answer: Pseudomonas aeruginosa
Correct Answer: Staphylococcus aureus
Explanation:Staphylococcus aureus infection is the most likely cause.
Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.
SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
The organisms are usually derived from the patient’s own body.Measures that may increase the risk of SSI include:
-Shaving the wound using a single use electrical razor with a disposable head
-Using a non iodine impregnated surgical drape if one is needed
-Tissue hypoxia
-Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.Measures that may decrease the risk of SSI include:
1. Intraoperatively
– Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
-Cover surgical site with dressingIn contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.
2. Post operatively
Tissue viability advice for management of surgical wounds healing by secondary intentionUse of diathermy for skin incisions
In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 22
Incorrect
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A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a 57-year-old woman. Her vision is causing her problems.
A macroadenoma compressing the optic chiasm is visible on MRI.
What is the most likely visual field defect to be discovered during an examination?Your Answer: Binasal hemianopia
Correct Answer: Bitemporal hemianopia
Explanation:The pituitary gland plays a crucial role in the neuro-endocrine axis. It is located at the base of the skull in the sella turcica of the sphenoid bone. It is connected superiorly to the hypothalamus, third ventricle, and visual pathways, and laterally to the cavernous sinuses, internal carotid arteries, and cranial nerves III, IV, V, and VI.
Pituitary tumours make up about 10-15% of all intracranial tumours. The majority of adenomas are benign. Over-secretion of pituitary hormones (most commonly prolactin, growth hormone, or ACTH), under-secretion of hormones, or localised or generalised pressure effects can all cause symptoms.
Compression of the optic chiasm can result in visual field defects, the most common of which is bitemporal hemianopia. This is caused by compression of the nasal retinal fibres, which carry visual impulses from temporal vision across the optic chiasm to the contralateral sides before continuing to the optic tracts.
The interruption of the visual pathways distal to the optic chiasm causes a homonymous visual field defect. The loss of the right or left halves of each eye’s visual field is referred to as homonymous hemianopia. It’s usually caused by a middle or posterior cerebral artery territory stroke that affects the occipital lobe’s optic radiation or visual cortex.
Binasal hemianopia is a condition in which vision is lost in the inner half of both eyes (nasal or medial). It’s caused by compression of the temporal visual pathways, which don’t cross at the optic chiasm and instead continue to the ipsilateral optic tracts. Binasal hemianopia is a rare complication caused by the internal carotid artery impinging on the temporal (lateral) visual fibres.
A monocular visual loss (that is, loss of vision in only one eye) can be caused by a variety of factors, but if caused by nerve damage, the damage would be proximal to the optic chiasm on the ipsilateral side.
A central scotoma is another name for central visual field loss. Every normal mammalian eye has a scotoma, also known as a blind spot, in its field of vision. The optic disc is a region of the retina that lacks photoreceptor cells and is where the retinal ganglion cell axons that make up the optic nerve exit the retina. When both eyes are open, visual signals that are absent in one eye’s blind spot are provided for the other eye by the opposite visual cortex, even if the other eye is closed.
Scotomata can be caused by a variety of factors, including demyelinating disease such as multiple sclerosis, damage to nerve fibre layer in the retina, methyl alcohol, ethambutol, quinine, nutritional deficiencies, and vascular blockages either in the retina or in the optic nerve.
Bilateral scotoma can occur when a pituitary tumour compresses the optic chiasm, causing a bitemporal paracentral scotoma, which then spreads out to the periphery, causing bitemporal hemianopsia. A central scotoma in a pregnant woman could be a sign of severe pre-eclampsia.
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This question is part of the following fields:
- Pathophysiology
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Question 23
Correct
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Which of the following can be measured directly using spirometry?
Your Answer: Vital capacity
Explanation:Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).
It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.
During spirometry, the following measurements can be determined:
Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
Forced expiratory volume in one second (FEV1)
FEV1/FVC ratio
Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.
Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution
The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.
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This question is part of the following fields:
- Clinical Measurement
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Question 24
Incorrect
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A 31-year old Caucasian female came into the emergency department due to difficulty of breathing. History revealed exposure to room odorizes that are rich in alkyl nitrites. Upon physical examination, patient is tachypnoeic at 32 breaths per minute, desaturated at 88% while on a non-rebreather mask at 15 litres per minute oxygen. She was also noted to be cyanotic, however with clear breath sounds.
Considering the history, what is the most probable cause of her difficulty of breathing?Your Answer: Unusually high concentrations of haemoglobin containing iron in the ferrous form
Correct Answer: Increased affinity of bound oxygen to haemoglobin
Explanation:Amyl nitrate is part of the treatment of cyanide poisoning. The short acting nitrate causes oxidation of Fe2+ in haemoglobin to Fe3+ in methaemoglobin. Methaemoglobin combines with cyanide (cyanmethemoglobin), which reacts with sodium thiosulfate to convert nontoxic thiocyanate and methaemoglobin.
Methaemoglobin is formed when the iron in haemoglobin is converted from the reduced state (Fe2+) to the oxidized state (Fe3+). The oxidized form of haemoglobin (Fe3+) does not bind oxygen as readily as Fe2+, but has high affinity for cyanide. It also results to high affinity of bound oxygen to haemoglobin, thus leading to tissue hypoxia. Arterial oxygen tension is normal despite observations of cyanosis and dyspnoea. Methemoglobinemia can be treated with methylene blue and vitamin C.
Carboxyhaemoglobin can be due to carbon monoxide poisoning. In such cases, patients experience headache and dizziness, but do not develop cyanosis.
2,3-diphosphoglycerate causes a shift in the oxygen dissociation curve to the right, decreasing haemoglobin’s affinity to oxygen to facilitate unloading of oxygen to the tissues.
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This question is part of the following fields:
- Pathophysiology
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Question 25
Incorrect
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Among the following which one is not a criterion for the assessment of causality?
Your Answer: Temporality
Correct Answer: Sensitivity
Explanation:For establishing a cause effect relationship, following criteria must be met:
1. Coherence & Consistency
2. Temporal Precedence
3. Specificity
As can be seen, sensitivity (The probability of a positive test) is not among these deciding factors..
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This question is part of the following fields:
- Statistical Methods
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Question 26
Incorrect
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During the design phase of a study, which among the given is aimed at addressing confounding factors?
Your Answer: Bias sampling
Correct Answer: Randomisation
Explanation:Randomisation allows for performance of experimental trials in a random order. Using this method gives us control over the confounding variables that are not supposed to be held constant.
For an instance, by employing randomisation we get to control biological differences among individual human beings during experimental trials.
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This question is part of the following fields:
- Statistical Methods
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Question 27
Correct
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Which of the following correctly explains the mechanism of lowering blood pressure by nitroglycerine?
Your Answer: Nitric oxide
Explanation:Nitroglycerine is rapidly denitrated enzymatically in the smooth muscle cell to release the free radical nitric oxide (NO).
Released NO activated cytosolic guanylyl cyclase which increases cGMP (cyclin guanosine monophosphate) which causes dephosphorylation of myosin light chain kinase (MLCK) through a cGMP-dependent protein kinase.
Reduced availability of phosphorylated (active) MLCK interferes with activation of myosin and in turn, it fails to interact with actin to cause contraction. Consequently, relaxation occurs.
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This question is part of the following fields:
- Pharmacology
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Question 28
Incorrect
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An acidic drug with a pKA of 4.3 is injected intravenously into a patient.
At a normal physiological pH, the approximate ratio of ionised to unionised forms of this drug in the plasma is?Your Answer: 10,000:1
Correct Answer: 1000:01:00
Explanation:The pH at which the drug exists in 50 percent ionised and 50 percent unionised forms is known as the pKa.
To calculate the proportion of ionised to unionised form of an ACID, use the Henderson-Hasselbalch equation.
pH = pKa + log ([A-]/[HA])
or
pH = pKa + log [(salt)/(acid)]
pH = pKa + log ([ionised]/[unionised]).Hence, if the pKa − pH = 0, then 50% of drug is ionised and 50% is unionised.
In this example:
7.4 = 4.3 + log ([ionised]/[unionised])
7.4 − 4.3 = log ([ionised]/[unionised])
log 3.1 = log ([ionised]/[unionised])Simply put, the antilog is the inverse log calculation. In other words, if you know the logarithm of a number, you can use the antilog to find the value of the number. The antilogarithm’s definition is as follows:
y = antilog x = 10x
Antilog to the base 10 of 0 = 1, 1 = 10, 2 =100, 3 = 1000, and 4 = 10,000.
If you want to find the antilogarithm of 3.1, for a number between 3 and 4, the antilogarithm will return a value between 1000 and 10,000. The ratio is 1:1 if pKa = pH, that is, pH pKa = log 0. (50 percent ionised and unionised).
According to the above value, there is only one unionised molecule for every approximately 1000 (1259) ionised molecules of this drug in plasma, implying that this drug is largely ionised in plasma (99.99 percent ).
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This question is part of the following fields:
- Pharmacology
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Question 29
Incorrect
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If a patient is to be placed under general anaesthesia using total intravenous technique with target-controlled infusions of propofol and remifentanil, what safety precaution is the most vital in this a scenario?
Your Answer: Dedicated intravenous access for infusion
Correct Answer: Cannula access site clearly visible and regularly checked
Explanation:According to the Safe Anaesthesia Liaison Group, the most important factor to consider the cannula access, and if the patient is properly receiving the total intravenous anaesthesia. The cannula access must be regularly checked for kinks, leaks and disconnections.
Below are the safety precautions and policies to be followed for total intravenous anaesthesia among children and adults:
When administering TIVA, a non-return valve must be used on any intravenous fluid line;
When using equipment, it is essential that clinical staff know its limitations and uses;
Sites of intravenous infusions should be visible so they may be monitored for disconnection, leaks or perivenous infusion into the subcutaneous tissues; and,
Organisations must give preference to clearly labelled intravenous connectors and valves. -
This question is part of the following fields:
- Pathophysiology
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Question 30
Incorrect
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Weight of all of your patients in the ICU is analysed, and shows that your date set is skewed.
Which of the following will correctly show the average weight of your patients?Your Answer: Mean
Correct Answer: Median
Explanation:The question mentions a quantitative, ratio scale data set. The use of mean would be ideal under normal circumstances, however, in this situation median is preferred as it is less sensitive to the skewness of data. The median is usually preferred to other measures of central tendency when your data set is skewed (i.e., forms a skewed distribution)
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This question is part of the following fields:
- Statistical Methods
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