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  • Question 1 - A 28-year-old girl complained of severe abdominal pain and hematemesis and was rushed...

    Correct

    • A 28-year-old girl complained of severe abdominal pain and hematemesis and was rushed into the emergency department. She has an increased heart rate of 120 beats per minute and blood pressure of 90/65. She has a history of taking Naproxen for her Achilles tendinopathy. On urgent endoscopy, she is diagnosed with a bleeding peptic ulcer.

      The immediate treatment is to permanently stop the bleeding by performing embolization of the left gastric artery via an angiogram.

      What level of the vertebra will be used as a radiological marker for the origin of the artery that supplies the left gastric artery during the angiogram?

      Your Answer: T12

      Explanation:

      The left gastric artery is the smallest branch that originates from the coeliac trunk—the coeliac trunk branches of the abdominal aorta at the vertebral level of T12.

      The left gastric artery runs along the superior portion of the lesser curvature of the stomach. A peptic ulcer that is serious enough to erode through the stomach mucosa into a branch of the left gastric artery can cause massive blood loss in the stomach, leading to hematemesis. The patient also takes Naproxen, a non-steroidal anti-inflammatory drug that is a common cause for peptic ulcers in otherwise healthy patients.

      The left gastric artery is responsible for 85% of upper GI bleeds. In cases refractory to initial treatment, angiography is sometimes needed to embolise the vessel at its origin and stop bleeding. During an angiogram, the radiologist will enter the aorta via the femoral artery, ascend to the level of the 12th vertebrae and then enter the left gastric artery via the coeliac trunk.

      The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:

      T12 – Coeliac trunk

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta

    • This question is part of the following fields:

      • Anatomy
      205.2
      Seconds
  • Question 2 - A previously fit 26-year-old is undergoing surgery to repair an inguinal hernia. He...

    Correct

    • A previously fit 26-year-old is undergoing surgery to repair an inguinal hernia. He is breathing on his own, and a supraglottic airway is being maintained via a circle system with air/oxygen and sevoflurane.

      With a fresh gas flow of 14 L/min, the end-tidal CO2 reading is 8.1 kPa. CO2 pressure is 1.9 kPa. The percentages of oxygen inhaled and exhaled are 38 and 33 percent, respectively.

      What do you think is the most likely source for these readings?

      Your Answer: Incompetent expiratory valve

      Explanation:

      The patient is rebreathing carbon dioxide that has been exhaled.

      Exhaustion of the soda lime and failure of the expiratory valve are the two most likely causes. A leak in the inspiratory limb is a less likely cause. Increased inhaled and exhaled carbon dioxide levels may appear with a normal-looking capnogram if the expiratory valve is ineffective.

      The patient will exhale into both the inspiratory and expiratory limbs if the inspiratory valve is inoperable. A slanted downstroke inspiratory phase (as the patient inhales carbon dioxide-containing gas from the inspiratory limb) and increased end-tidal carbon dioxide can be seen on the capnogram.

      Even if the soda lime were exhausted, a high fresh gas flow would be enough to prevent rebreathing. The difference in oxygen concentrations in inspired and expired breaths would be less pronounced.

      Hypercapnia is caused by respiratory obstruction and malignant hyperthermia, but not by rebreathing.

    • This question is part of the following fields:

      • Pathophysiology
      179.2
      Seconds
  • Question 3 - A 27-year-old woman presents to emergency department. She is experiencing generalised seizures.

    She is...

    Correct

    • A 27-year-old woman presents to emergency department. She is experiencing generalised seizures.

      She is given emergency management of her symptoms before being referred to the neurologist who diagnoses her with new onset of tonic-clonic epilepsy.

      What is the most appropriate first line of treatment?

      Your Answer: Lamotrigine should be offered as first line of treatment

      Explanation:

      Tonic-clonic (Grand mal) epilepsy is characterised by a general loss of consciousness with violent involuntary muscle contractions.

      The NICE guidelines for treatment indicates the use of sodium valproate and lamotrigine, but sodium valproate unsuitable in this case and she is a woman of reproductive age and it is known to have teratogenic effects. Lamotrigine is a more suitable choice, prescribed as 800mg daily.

      NICE guidelines also advice an additional prescription of 5mg of folic acid daily for women on anticonvulsant therapy looking to get pregnant. It also warns of the need for extra contraceptive precaution as there is a possibly that the anticonvulsant agent can reduce levels of contraceptive agents.

      Stimulation of the vagal nerve stimulation is only necessary in patients who are refractory to medical treatment and not candidates for surgical resection.

    • This question is part of the following fields:

      • Pathophysiology
      229
      Seconds
  • Question 4 - Risk stratification is done prior to a major cardiac surgery using cardiopulmonary exercise...

    Correct

    • Risk stratification is done prior to a major cardiac surgery using cardiopulmonary exercise testing. Given the following options, which one is most likely to have the highest risk for post-operative cardiac morbidity?

      Your Answer: Anaerobic threshold (AT) of less than 11 mL/kg/minute

      Explanation:

      The ventilatory anaerobic threshold (VAT), formerly referred to as the anaerobic threshold, is an index used to estimate exercise capacity. During the initial (aerobic) phase of CPET, which lasts until 50–60% of Vo2max is reached, expired ventilation (VE) increases linearly with Vo2 and reflects aerobically produced CO2 in the muscles. Blood lactate levels do not change substantially during this phase, since muscle lactic acid production is minimal.

      During the latter half of exercise, anaerobic metabolism occurs because oxygen supply cannot keep up with the increasing metabolic requirements of exercising muscles. At this time, there is a significant increase in lactic acid production in the muscles and in the blood lactate concentration. The Vo2 at the onset of blood lactate accumulation is called the lactate threshold or the VAT. The VAT is also defined as the point at which minute ventilation increases disproportionately relative to Vo2, a response that is generally seen at 60–70% of Vo2max.

      The VAT is a useful measure as work below this level encompasses most daily living activities. The ability to achieve the VAT can help distinguish cardiac and non‐cardiac (pulmonary or musculoskeletal) causes of exercise limitation, since patients who fatigue before reaching VAT are likely to have a non‐cardiac problem.

      When VAT is detected, patients with PVo2 of ⩽10 ml/kg/min have a high event rate.

    • This question is part of the following fields:

      • Pathophysiology
      66.1
      Seconds
  • Question 5 - During the analysis phase, which of the provided options serves to control confounding...

    Incorrect

    • During the analysis phase, which of the provided options serves to control confounding factors?

      Your Answer: Blinding

      Correct Answer: Stratification

      Explanation:

      During analytical stage a technique called stratification is used for controlling confounding variables. This technique involves sorting out the data into discernible groups.

    • This question is part of the following fields:

      • Statistical Methods
      7.7
      Seconds
  • Question 6 - A patient has a myocardial infarction with anterior ST elevation. There are the...

    Correct

    • A patient has a myocardial infarction with anterior ST elevation. There are the following observations:

      Cardiac output 2.0 L/min
      Blood pressure 80/60 mmHg
      CVP 20 mmHg
      SpO2 91% on 4 L/min oxygen

      What is the most logical physiological explanation for these findings?

      Your Answer: Biventricular failure

      Explanation:

      The occlusion of the left anterior descending (LAD) coronary artery causes anterior ST elevation myocardial infarction (STEMI). It has the worst prognosis of all the infarct locations due to its larger infarct size. It has a higher rate of total mortality (27 percent versus 11 percent), heart failure (41 percent versus 15 percent), and a lower ejection fraction on admission than an inferior myocardial infarction (38 percent versus 55 percent ).

      The LAD artery supplies the majority of the interventricular septum, as well as the anterior, lateral, and apical walls of the left ventricle, as well as the majority of the right and left bundle branches and the bicuspid valve’s anterior papillary muscle (left ventricle).

      The left or right ventricle’s end-diastolic volume (EDV) is the volume of blood in each chamber at the end of diastole before systole. Preload is synonymous with the EDV.

      120 mL is a typical left ventricular EDV (range 65-240 mL). The EDV of the right ventricle in a typical range is (100-160 mL).

      With an ejection fraction (EF) of less than 45 percent, the patient is most likely suffering from systolic dysfunction. Increases in right and left ventricular end-diastolic pressures and volumes are likely with a reduced EF because the ventricles are not adequately emptied. The left atrium and the pulmonary vasculature are affected by the increased pressures on the left side of the heart.

      By causing an imbalance of the Starling forces acting across the capillaries, increased hydrostatic pressure in the pulmonary circulation favours the development of pulmonary oedema. With cardiogenic pulmonary oedema, capillary permeability is likely to remain unchanged.

      Biventricular failure will result as a result of the pressure changes being transmitted to the right side of the circulation. The patient’s systemic vascular resistance is likely to be elevated as well, but it is not the most likely cause of his symptoms. The patient is suffering from cardiogenic shock as a result of biventricular failure. The patient has low cardiac output and is hypotensive. Right ventricular filling pressures are elevated, indicating right ventricular dysfunction.

    • This question is part of the following fields:

      • Clinical Measurement
      227.6
      Seconds
  • Question 7 - A 28-year male patient presents to the GP with a 2-day history of...

    Correct

    • A 28-year male patient presents to the GP with a 2-day history of abdominal pain and bloody diarrhoea. He reports that he was completely fine until one week ago when headache and general tiredness appeared. After further questioning, he revealed eating at a dodgy takeaway 3 days before the start of his symptoms.

      Which of the following diagnosis is most likely?

      Your Answer: Campylobacter

      Explanation:

      Giardiasis is known to have a longer incubation time and doesn’t cause bloody diarrhoea.

      Cholera usually doesn’t cause bloody diarrhoea.

      Generally, most of the E.coli strains do not cause bloody diarrhoea.

      Diverticulitis can be a cause of bloody stool but the history here points out to an infectious cause.

      Campylobacter infection is the most probable cause as it is characterized by a prodrome, abdominal pain and bloody diarrhoea

    • This question is part of the following fields:

      • Physiology And Biochemistry
      90.2
      Seconds
  • Question 8 - The biochemical assessment of malnutrition can be measured by the amount of plasma...

    Incorrect

    • The biochemical assessment of malnutrition can be measured by the amount of plasma proteins.

      In acute starvation, which of these plasma proteins is the most sensitive indicator?

      Your Answer:

      Correct Answer: Retinol binding globulin

      Explanation:

      The half life of Retinol binding protein (RBP) is 10-12 hours and therefore reflects more acute changes in protein metabolism than any of these proteins. Therefore it is not commonly used as a parameter for nutritional assessment.

      The half life of Transthyretin (thyroxine binding pre-albumin) is only one to two days and so levels are less sensitive and this protein is not an albumin precursor. 15 mg/dL represents early malnutrition and a need for nutritional support.

      Albumin levels have been frequently as a marker of nutrition but this is not a very sensitive marker. It’s half life more than 30 days and significant change takes some time to be noticed. Also, synthesis of albumin is decreased with the onset of the stress response after burns. Unrelated to nutritional status, the synthesis of acute phase proteins increases and that of albumin decreases.

      A more accurate indicator of protein stores is transferrin. It’s response to acute changes in protein status is much faster. The half life of serum transferrin is shorter (8-10 days) and there are smaller body stores than albumin. A low serum transferrin level is below 200 mg/dL and below 100 mg/dL is considered severe. Serum transferrin levels can also affect serum transferrin level.

      Fibronectin is used a nutritional marker but levels decrease after seven days of starvation. It is a glycoprotein which plays a role in enhancing the phagocytosis of foreign particles.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 9 - A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise....

    Incorrect

    • A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise. On urine culture and sensitivity testing, E.coli was detected with resistance to ampicillin.
      What is the mechanism of resistance to ampicillin?

      Your Answer:

      Correct Answer: Beta-lactamase production

      Explanation:

      Ampicillin belongs to the family of penicillin. Resistance to this group of drugs is due to ?-lactamase production which opens the ?-lactam ring and inactivates Penicillin G and some closely related congeners. The majority of Staphylococci and some strains of gonococci, B. subtilis, E. coli, and a few other bacteria produce penicillinase.

      Resistance to cephalosporins is due to changes in penicillin-binding proteins.

      Resistance to macrolides are due to post-transcriptional methylation of 23s bacterial ribosomal RNA

      Resistance to fluoroquinolones is due to mutations in DNA gyrase.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 10 - Many of the processes we deal with in anaesthesia entail a relationship between...

    Incorrect

    • Many of the processes we deal with in anaesthesia entail a relationship between two or more variables.

      Which of the following relationships is a linear relationship?

      Your Answer:

      Correct Answer: The relationship between the junction potential and temperature in a thermocouple

      Explanation:

      Two bonded wires of dissimilar metals, iron/constantan or copper/constantan, make up a thermocouple (constantan is an alloy of copper and nickel). At the tip, a thermojunction voltage is generated that is proportional to temperature (Seebeck effect).

      All of the other connections are non-linear.

      For a single compartment model, the relationship between a decrease in plasma concentration of an intravenous bolus of a drug and time is a washout exponential.

      A sine wave is the relationship between current and degrees or time from a mains power source.

      A sigmoid curve represents the relationship between efficacy and log-dose of a pure agonist on mu receptors.

      The pressure of a fixed mass of gas and its volume (Boyle’s law) at a fixed temperature are inversely proportional, resulting in a hyperbolic curve.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 11 - Which statement best describes the bispectral index (BIS)? ...

    Incorrect

    • Which statement best describes the bispectral index (BIS)?

      Your Answer:

      Correct Answer: It decreases during normal sleep

      Explanation:

      The bispectral index (BIS) is one of several systems used in anaesthesiology as of 2003 to measure the effects of specific anaesthetic drugs on the brain and to track changes in the patient’s level of sedation or hypnosis. It is a complex mathematical algorithm that allows a computer inside an anaesthesia monitor to analyse data from a patient’s electroencephalogram (EEG) during surgery. It is a dimensionless number (0-100) that is a summative measurement of time domain, frequency domain and high order spectral parameters derived from electroencephalogram (EEG) signals.

      Sleep and anaesthesia have similar behavioural characteristics but are physiologically different but BIS monitors can be used to measure sleep depth. With increasing sleep depth during slow-wave sleep, BIS levels decrease. This correlates with changes in regional cerebral blood flow when measured using positron emission tomography (PET).

      BIS shows a dose-response relationship with the intravenous and volatile anaesthetic agents. Opioids produce a clinical change in the depth of sedation or analgesia but fail to produce significant changes in the BIS. Ketamine increases CMRO2 and EEG activity.

      BIS is unable to predict movement in response to a surgical stimulus. Some of these are spinal reflexes and not perceived by the cerebral cortex.

      BIS is used during cardiopulmonary bypass to measure depth of anaesthesia and an index of cerebral perfusion. However, it cannot predict subtle or significant cerebral damage.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 12 - Regarding the Valsalva manoeuvre, which of the following describes the cardiovascular changes in...

    Incorrect

    • Regarding the Valsalva manoeuvre, which of the following describes the cardiovascular changes in phase III in a normal patient?

      Your Answer:

      Correct Answer: Normal intrathoracic pressure, decrease in blood pressure, and increase in heart rate

      Explanation:

      When a person forcefully expires against a closed glottis, changes occur in intrathoracic pressure that dramatically affect venous return, cardiac output, arterial pressure, and heart rate. This forced expiratory effort is called a Valsalva maneuver.

      Initially during a Valsalva, intrathoracic (intrapleural) pressure becomes very positive due to compression of the thoracic organs by the contracting rib cage. This increased external pressure on the heart and thoracic blood vessels compresses the vessels and cardiac chambers by decreasing the transmural pressure across their walls. Venous compression, and the accompanying large increase in right atrial pressure, impedes venous return into the thorax. This reduced venous return, and along with compression of the cardiac chambers, reduces cardiac filling and preload despite a large increase in intrachamber pressures. Reduced filling and preload leads to a fall in cardiac output by the Frank-Starling mechanism. At the same time, compression of the thoracic aorta transiently increases aortic pressure (phase I); however, aortic pressure begins to fall (phase II) after a few seconds because cardiac output falls. Changes in heart rate are reciprocal to the changes in aortic pressure due to the operation of the baroreceptor reflex. During phase I, heart rate decreases because aortic pressure is elevated; during phase II, heart rate increases as the aortic pressure falls.

      When the person starts to breathe normally again, the intrathoracic pressure declines to normal levels, the aortic pressure briefly decreases as the external compression on the aorta is removed, and heart rate briefly increases reflexively (phase III). This is followed by an increase in aortic pressure (and reflex decrease in heart rate) as the cardiac output suddenly increases in response to a rapid increase in cardiac filling (phase IV). Aortic pressure also rises above normal because of a baroreceptor, sympathetic-mediated increase in systemic vascular resistance that occurred during the Valsava.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 13 - The plateau phase of the myocardial action potential is as a result of:...

    Incorrect

    • The plateau phase of the myocardial action potential is as a result of:

      Your Answer:

      Correct Answer: Slow influx of calcium

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 14 - A new proton pump inhibitor (PPI) is being evaluated in elderly patients who...

    Incorrect

    • A new proton pump inhibitor (PPI) is being evaluated in elderly patients who are taking aspiring. Study designed has 120 patients receiving the PPI, while a control group of 240 individuals is given the standard PPI. Over a span of 6 years, 24 of the group receiving the new PPI had an upper GI bleed compared to 60 individuals who received the standard PPI.

      How would you calculate the absolute risk reduction?

      Your Answer:

      Correct Answer: 5%

      Explanation:

      Absolute risk reduction = (Control event rate) – (Experimental event rate)

      Experimental event rate = 24 / 120 = 0.2

      Control event rate = 60 / 240 = 0.25

      Absolute risk reduction = 0.25 – 0.2 = 0.05 = 5% reduction

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 15 - The passage of glucose into the brain is facilitated by which transport method?...

    Incorrect

    • The passage of glucose into the brain is facilitated by which transport method?

      Your Answer:

      Correct Answer: Facilitated diffusion

      Explanation:

      Glucose transport is a highly regulated process accomplished mostly by facilitated diffusion using carrier proteins to cross cell membranes.

      There are many transporters, but the most important are known as glucose transporters (GLUTs).

      Stresses in various form of acute and chronic forms affect the activity of glucose transporters.
      They are responsive to many types of metabolic stress, including hypoxia, injury, hypoglycaemia, numerous metabolic inhibitors, stress hormones, and other influences such as growth factors.

      Numerous signalling pathways appear to be involved in transporter regulation.

      New evidence suggests that stresses regulating GLUTs are not only acute biological stresses. In addition, chronic low-grade inflammation, and their associated chronic diseases also lead to altered glucose transport. These include obesity, type 2 diabetes, cardiovascular disease, and the growth and spread of many tumours that are affected by altered glucose transporters. Some of these glucose transport effects are compensatory, while others are pathogenic.

      Ultimately, deliberate manipulation of GLUTs could be used as treatment for some of these chronic diseases.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 16 - Which of the following statement is true regarding the mechanism of action of...

    Incorrect

    • Which of the following statement is true regarding the mechanism of action of rifampicin?

      Your Answer:

      Correct Answer: Inhibit RNA synthesis

      Explanation:

      Rifampicin is a derivative of a rifamycin (other derivatives are rifabutin and rifapentine). It is bactericidal against both dividing and non-dividing mycobacterium and acts by inhibiting DNA-dependent RNA polymerase. Thus this drug inhibits RNA synthesis.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 17 - Which of the following options will best reflect the adequacy of preoxygenation prior...

    Incorrect

    • Which of the following options will best reflect the adequacy of preoxygenation prior to rapid sequence induction of a patient?

      Your Answer:

      Correct Answer: Expired fraction of oxygen (FEO2)

      Explanation:

      The most important determinant of preoxygenation adequacy is expired fraction of oxygen. Denitrogenating of the functional residual capacity is the purpose of preoxygenation. This is dependent on three vital factors: (1) respiratory rate; (2) inspired volume, and; (3) inspired oxygen concentration (FiO2).

      Arterial oxygen saturation does not efficiently determine adequacy of preoxygenation because of its inability to measure tissue reserves. Arterial partial pressure of oxygen is also unsuitable for determining preoxygenation adequacy. Moreover, the absence of central cyanosis is a very crude sign of low tissue oxygenation.

    • This question is part of the following fields:

      • Pathophysiology
      0
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  • Question 18 - A 60-year-old male is being reviewed in the peri-operative assessment before total knee...

    Incorrect

    • A 60-year-old male is being reviewed in the peri-operative assessment before total knee replacement. He had a history of a heart transplant 10 years back. His resting heart rate is 110 beats per minute. On examination, ECG showed sinus tachycardia.

      Which of the following explains this tachycardia?

      Your Answer:

      Correct Answer: Loss of parasympathetic innervation

      Explanation:

      Normally, at rest vagal influence is dominant producing the heart rate of 60-80 beats per minute even if the intrinsic automaticity of Sinoatrial Node is 100-110 beats per minute.

      The transplanted heart has no autonomic nervous supply. So, it will respond to endogenous and exogenous catecholamine. This loss of parasympathetic innervation is responsible for the tachycardia in this patient.

      Hypokalaemia can cause myocardial excitability and potential for ventricular ectopic and supraventricular arrhythmias. Hypothyroidism is also unlikely to cause tachycardia in this patient.

    • This question is part of the following fields:

      • Pathophysiology
      0
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  • Question 19 - A 73-year-old woman is admitted to the coronary care unit. She has been...

    Incorrect

    • A 73-year-old woman is admitted to the coronary care unit. She has been diagnosed with an acute myocardial infarction and has gone into a cardiogenic shock. As part of her treatment, she is prescribed a dobutamine infusion and placed on full haemodynamic monitoring.

      Over the next four days, her measurement are:

      Day1 Day2 Day3 Day4
      Infusion rate of dobutamine (mcg/kg/min): 5 10 15 25
      Cardiac output (L/min): 3.4 3.2 3.1 3.2
      Pulse rate (beats/min): 110 112 105 100
      Blood pressure (mmHg): 80/60 75/61 83/60 81/56

      Haemodynamic changes are noted as a result of response to treatment. What is the most probable cause?

      Your Answer:

      Correct Answer: Tolerance by down-regulation of beta1 receptors

      Explanation:

      Tachyphylaxis is the swiftly declining response to successive drug doses which vastly reduces its effectiveness in a short space of time, mostly as a result of an acute consumption of neurotransmitters.

      Tolerance or desensitisation is the slow decline in a person’s reaction to a drug due to continued use. It requires a longer time span than tachyphylaxis, usually over days or weeks.

      Down- regulation is a reduction in the amount of receptors available on target cells which decreases the affinity of the agent to the cells. For this to occur, the down-regulation of receptors must occur at a rate faster than receptor synthesis. This down-regulation often occurs with beta1 receptors due to:

      1) The transportation or receptors from the cell surface to the interior of the cell

      2) Degradation of receptors occurring over time.

      In this case, dobutamine is prescribed to treat cardiogenic shock. It is able to function by binding to beta1-adrenergic receptors to increase the contraction of the heart, thereby improving cardiac output. It also binds to beta2- and alpha1-adrenergic receptors to balance out the effects produced by binding to beta1 receptors and reduce the risk of system vasculature responses.

    • This question is part of the following fields:

      • Clinical Measurement
      0
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  • Question 20 - Regarding thyroid hormones, one of the following is true. ...

    Incorrect

    • Regarding thyroid hormones, one of the following is true.

      Your Answer:

      Correct Answer: Thyroid binding globulin (TBG) is increased in pregnancy

      Explanation:

      T3 is produced by peripheral de-iodination of T4. It is more active than T4.

      TBG, like most binding proteins, is increased in pregnancy. Because of this, measurement of free thyroid hormone concentration is more important than total.

      T4 and T3 concentrations are decreased in Illness and starvation.

      L-T4 that is the active molecule while D-T4 is inactive.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 21 - A 54-year-old man weighing 70kg, underwent mesh repair for inguinal hernia under general...

    Incorrect

    • A 54-year-old man weighing 70kg, underwent mesh repair for inguinal hernia under general anaesthesia. He was given intravenous co-amoxiclav (Augmentin) following which the patient developed widespread urticarial ras, became hypotensive (61/30 mmHg), and showed clinical signs of bronchospasm. Anaphylaxis is suspected in this patient.

      Which one of the following is considered as best initial pharmacological treatment for this condition?

      Your Answer:

      Correct Answer: Intravenous adrenaline 50 mcg

      Explanation:

      The drug of choice for the treatment of anaphylaxis is adrenaline. It has an intravenous route of administration. Since the patient already has intravenous access, the intramuscular route is not appropriate.

      Second-line pharmacological intervention includes the use of chlorpheniramine 10mg intravenous, Hydrocortisone 200mg.

    • This question is part of the following fields:

      • Pharmacology
      0
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  • Question 22 - Which of the following statements is true about fluid balance? ...

    Incorrect

    • Which of the following statements is true about fluid balance?

      Your Answer:

      Correct Answer: After intravenous administration of crystalloids, the distribution of these fluids throughout the body depends on its osmotic activity

      Explanation:

      When there is capillary leakage as seen in dependent oedema or ascites, oncotic pressure becomes a problem.

      The intracellular sodium concentration is very sensitive to the extracellular sodium concentrations. When there is an imbalance, osmosis occurs resulting in shifts in water between the two compartments.

      The microvascular endothelium relies upon osmosis and other processes as it is not freely permeable to water.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 23 - A 25-year-old man, has been scheduled for a splenectomy. For this procedure, he...

    Incorrect

    • A 25-year-old man, has been scheduled for a splenectomy. For this procedure, he requires a urethral catheter.

      Where does resistance first occur during the insertion of a catheter?

      Your Answer:

      Correct Answer: Membranous urethra

      Explanation:

      The membranous urethra is the shortest part of the urethra and the least dilatable part of it.

      This is as a result of it being surrounded by the external urethral sphincter which is made up of striated muscle and controls voluntary urine flow from the bladder to the urethra.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 24 - At sea level, Sevoflurane is administered via a plenum vaporiser. 100 mL of...

    Incorrect

    • At sea level, Sevoflurane is administered via a plenum vaporiser. 100 mL of the fresh gas flow is bypassed into the vaporising chamber. Temperature within the vaporising chamber is maintained at 20°C.

      The following fresh gas flows approximates best for the delivery of 1% sevoflurane.

      Your Answer:

      Correct Answer: 2.7 L/minute

      Explanation:

      The equation for calculating vaporiser output is:

      Vaporiser output (VO) mL = Carrier gas flow (mL/minute) × SVP of agent (kPa)
      Ambient pressure (kPa) − SVP of agent (kPa)

      The saturated vapour pressure of sevoflurane at 1 atm (100 kPa) and 20°C is 21 kPa.

      VO = (100 mL × 21 kPa)/(100 kPa − 21kPa) for sevoflurane,
      VO = 26.6 mL

      26.6 mL of 100% sevoflurane and 100 mL bypass carrier gas is being added to the fresh gas flow per minute.

      2660 mL of 1% sevoflurane and 100 mL bypass carrier gas is approximately 2.7 L/minute.

    • This question is part of the following fields:

      • Pharmacology
      0
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  • Question 25 - Which of the following facts about T cells is true? ...

    Incorrect

    • Which of the following facts about T cells is true?

      Your Answer:

      Correct Answer: Secrete IL-2 when activated

      Explanation:

      T cells function as a part of the body’s adaptive immune system. There are different types of T cells, including:

      Cytotoxic T cells: Function as killer cells by releasing cytotoxic granules into the membrane of targeted cells.

      T-Helper cells: When activated, they function to activate other immune cell types, assist in antibody production with B cells and releasing cytokines including IL-2.

      Memory T cells: Function as to provide immune memory against already encountered antigens.

      T cells possess specific glycoproteins and receptors on their surface.

      T-Helper cells work with HLA class II antigens on the cell surfaces in order to recognise foreign antigens

      T cells survive ranges from a few weeks, to a lifetime depending on the subtype in question.

      Immunoglobulins are expressed on the surface of, and secreted by B-lymphocytes.

      Native antigens are recognised by B cells. T cells only recognise antigens that have been processed by the cells and presented on the surface of the cell.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 26 - Prophylactic antibiotics are required for which of the following procedures? ...

    Incorrect

    • Prophylactic antibiotics are required for which of the following procedures?

      Your Answer:

      Correct Answer: Caesarean section

      Explanation:

      Staphylococcus aureus infection is the most likely cause.

      Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.

      SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
      The organisms are usually derived from the patient’s own body.

      Measures that may increase the risk of SSI include:
      -Shaving the wound using a single use electrical razor with a disposable head
      -Using a non iodine impregnated surgical drape if one is needed
      -Tissue hypoxia
      -Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.

      Measures that may decrease the risk of SSI include:
      1. Intraoperatively
      – Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
      -Cover surgical site with dressing

      In contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.

      2. Post operatively
      Tissue viability advice for management of surgical wounds healing by secondary intention

      Use of diathermy for skin incisions
      In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 27 - Concerning calcium metabolism and its control, which of these is correct? ...

    Incorrect

    • Concerning calcium metabolism and its control, which of these is correct?

      Your Answer:

      Correct Answer: Cholecalciferol is 25-hydroxylated in the liver

      Explanation:

      When there is a fall in ionised plasma calcium levels, the chief cells of the parathyroid glands are stimulated to secrete parathyroid hormone (PTH).

      50% of extracellular calcium occurs as non-ionised, protein- (albumin-)bound calcium.

      The degree of ionisation increases with low ph and decreases with high pH.

      There is increased renal calcium excretion with secretion of calcitonin.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 28 - One of the causes of increased pulse pressure is when the aorta becomes...

    Incorrect

    • One of the causes of increased pulse pressure is when the aorta becomes less compliant because of age-related changes. Another cause of increased pulse pressure is which of the following?

      Your Answer:

      Correct Answer: Increased stroke volume

      Explanation:

      Impaired ventricular relaxation reduces diastolic filling and therefore preload.

      Decreased blood volume decreases preload due to reduced venous return.

      Heart failure is characterized by reduced ejection fraction and therefore stroke volume.

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure (is increased by stroke volume) = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume
      Aortic stenosis would decrease stroke volume as end systolic volume would increase.
      This is because of an increase in afterload, an increase in resistance that the heart must pump against due to a hard stenotic valve.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 29 - The SI unit of energy is the joule. Energy can be kinetic, potential,...

    Incorrect

    • The SI unit of energy is the joule. Energy can be kinetic, potential, electrical or chemical energy.

      Which of these correlates with the most energy?

      Your Answer:

      Correct Answer: Energy released when 1 kg fat is metabolised to CO2 and water (the energy content of fat is 37 kJ/g)

      Explanation:

      The derived unit of energy, work or amount of heat is joule (J). It is defined as the amount of energy expended if a force of one newton (N) is applied through a distance of one metre (N·m)

      J = 1 kg·m/s2·m = 1 kg·m2/s2 or 1 kg·m2·s-2

      Kinetic energy (KE) = ½ MV2

      An object with a mass of 1500 kg moving at 30 m/s correlates to 675 kJ:

      KE = ½ (1500) × (30)2 = 750 × 900 = 675 kJ

      Total energy released when 1 kg fat is metabolised to CO2 and water is 37 MJ. 1 g fat produces 37 kJ/g, therefore 1 kg fat produces 37,000 × 1000 = 37 MJ.

      Raising the temperature of 1 kg water from 0°C to 100°C correlates to 420 kJ. The amount of energy needed to change the temperature of 1 kg of the substance by 1°C is the specific heat capacity. We have 1 kg water therefore:

      4,200 J × 100 = 420,000 J = 420 kJ

      In order to calculate the energy involved in raising a 100 kg mass to a height of 1 km against gravity, we need to calculate the potential energy (PE) of the mass:

      PE = mass × height attained × acceleration due to gravity
      PE = 100 kg × 1000 m × 10 m/s2 = 1 MJ

      The heat generated when a direct current of 10 amps flows through a heating element for 10 seconds when the potential difference across the element is 1000 volts can be calculated by applying Joule’s law of heating:

      Work done (WD) = V (potential difference) × I (current) × t (time)
      WD = 10 × 10 × 1000 = 100 kJ

    • This question is part of the following fields:

      • Physiology
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  • Question 30 - Which statement is the most accurate when describing electrical equipment and shock? ...

    Incorrect

    • Which statement is the most accurate when describing electrical equipment and shock?

      Your Answer:

      Correct Answer: Type CF is considered to safe for direct connection with the heart

      Explanation:

      There are different classes of electrical equipment that can be classified in the table below:

      Class 1 – provides basic protection only. It must be connected to earth and insulated from the mains supply

      Class II – provides double insulation for all equipment. It does not require an earth.

      Class III – uses safety extra low voltage (SELV) which does not exceed 24 V AC. There is no risk of gross electrocution but risk of microshock exists.

      Type B – All of above with low leakage currents (0.5mA for Class IB, 0.1 mA for Class IIB)

      Type BF – Same as with other equipment but has ‘floating circuit’ which means that the equipment applied to patient is isolated from all its other parts.

      Type CF – Class I or II equipment with ‘floating circuits’ that is considered to be safe for direct connection with the heart. There are extremely low leakage currents (0.05mA for Class I CF and 0.01mA for Class II CF)

    • This question is part of the following fields:

      • Clinical Measurement
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SESSION STATS - PERFORMANCE PER SPECIALTY

Anatomy (1/1) 100%
Pathophysiology (3/3) 100%
Statistical Methods (0/1) 0%
Clinical Measurement (1/1) 100%
Physiology And Biochemistry (1/1) 100%
Passmed