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  • Question 1 - Ventricular filling follows a delay caused by? ...

    Correct

    • Ventricular filling follows a delay caused by?

      Your Answer: AV node

      Explanation:

      The AV node is a conducting tissue found between the atria and the ventricles of the heart. It conducts electrical signal from the atria to the ventricles and acts a delaying mechanism preventing the atria and the ventricles from contracting at the same time. This decremental conduction prevents premature ventricular contraction in cases such as atrial fibrillation. A delay in the AV node is the reason for the PR segment seen on the ECG. In certain types of supraventricular tachycardia, a person could have two AV nodes; this will cause a loop in electrical current and uncontrollably rapid heart beat. When this electricity catches up with itself, it will dissipate and return to a normal heart rate.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      31.5
      Seconds
  • Question 2 - Which of the following diseases is caused by intra-articular and/or extra-articular deposition of...

    Incorrect

    • Which of the following diseases is caused by intra-articular and/or extra-articular deposition of calcium pyrophosphate dihydrate (CPPD) crystals, due to unknown causes?

      Your Answer: Gout

      Correct Answer: Pseudogout

      Explanation:

      Pseudogout or chondrocalcinosis is a rheumatological disease caused by the accumulation of crystals of calcium pyrophosphate dihydrate (CPPD) in the connective tissues. It is frequently associated with other conditions, such as trauma, amyloidosis, gout, hyperparathyroidism and old age, which suggests that it is secondary to degenerative or metabolic changes in the tissues. The knee is the most commonly affected joint. It causes symptoms similar to those of rheumatoid arthritis or osteoarthritis.

    • This question is part of the following fields:

      • Orthopaedics
      • Pathology
      47.9
      Seconds
  • Question 3 - A 55-year old lady underwent a major surgery for repair of an aortic...

    Correct

    • A 55-year old lady underwent a major surgery for repair of an aortic aneurysm. Her blood pressure was low throughout the intra-operative and the post-operative period, along with increasing serum creatinine and urea. Microscopic examination of her urine showed multiple granular and hyaline casts. What is the likely condition the patient is suffering from?

      Your Answer: Acute tubular necrosis

      Explanation:

      The most common predisposing factor leading to acute tubular necrosis is ischemia, typically seen in hospitalized patients with low blood pressure.

    • This question is part of the following fields:

      • Pathology
      • Renal
      59.5
      Seconds
  • Question 4 - The otic ganglion receives its preganglionic sympathetic fibres from which of the following...

    Incorrect

    • The otic ganglion receives its preganglionic sympathetic fibres from which of the following nerves?

      Your Answer: Trigeminal nerve

      Correct Answer: Glossopharyngeal nerve

      Explanation:

      The otic ganglion is a small (2–3 mm), oval shaped, flattened parasympathetic ganglion of a reddish-grey colour, located immediately below the foramen ovale in the infratemporal fossa and on the medial surface of the mandibular nerve. The preganglionic parasympathetic fibres originate in the inferior salivatory nucleus of the glossopharyngeal nerve. They leave the glossopharyngeal nerve by its tympanic branch and then pass via the tympanic plexus and the lesser petrosal nerve to the otic ganglion. Here, the fibres synapse, and the postganglionic fibres pass by communicating branches to the auriculotemporal nerve, which conveys them to the parotid gland. They produce vasodilator and secretomotor effects.

    • This question is part of the following fields:

      • Anatomy
      • Head & Neck
      27.5
      Seconds
  • Question 5 - A 27 year old women works in a dry-cleaning shop. She was exposed...

    Correct

    • A 27 year old women works in a dry-cleaning shop. She was exposed to massive amounts of carbon tetrachloride on her skin as well as inhaled. Which of the following organs is most susceptible to damage?

      Your Answer: Liver

      Explanation:

      Carbon tetrachloride (CCl4) is a common agent used in the dry cleaning industry and is thought to cause the formation of free radicals. It causes rapid breakdown of the endoplasmic reticulum due to decomposition of lipids and severe liver cell injury. Within less than 30 mins, hepatic protein synthesis declines, lipid export is reduced due to lack of apoprotein and there is an influx of calcium and cell death.

    • This question is part of the following fields:

      • Cell Injury & Wound Healing
      • Pathology
      29.7
      Seconds
  • Question 6 - The transmembrane proteins responsible for resting membrane potential of vascular smooth muscle cells...

    Correct

    • The transmembrane proteins responsible for resting membrane potential of vascular smooth muscle cells was blocked by a drug. Which of the following transmembrane proteins were blocked by this drug?

      Your Answer: K+ channels

      Explanation:

      The resting membrane potential is due to selective permeability of the membrane to potassium ions. The Na/K pump is responsible for the generation of a gradient across the membrane and it is due to the inherent ability of the K channels to allow diffusion back into the nerve at rest which charges the cells. In reality, the resting membrane potential is more positive because of small contributions by Na+ channels, Cl− channels and non-selective cation channels.

    • This question is part of the following fields:

      • General
      • Physiology
      65.6
      Seconds
  • Question 7 - You observe a procedure to harvest the left internal thoracic (mammary) artery to...

    Correct

    • You observe a procedure to harvest the left internal thoracic (mammary) artery to be used as a graft for coronary artery bypass surgery. The left internal thoracic artery is mobilised from the inside of the chest wall and divided near the caudal end of the sternum. After dividing the internal thoracic artery at its distal end, the specialist registrar asks you to name the artery that will now have increased blood supply so that adequate blood flow is maintained to the rectus abdominis on the left side. What would your answer be?

      Your Answer: Inferior epigastric artery

      Explanation:

      The rectus abdominis muscle is supplied by the superior epigastric artery which is a branch of the internal thoracic artery. If the internal thoracic artery is thus ligated, blood would no longer flow to it. However, the superior epigastric artery communicates with the inferior epigastric artery (a branch of the external iliac artery). This means that blood could flow from the external iliac, to the inferior epigastric, to the superior epigastric to the rectus abdominis.

      The superficial circumflex iliac artery and the superficial epigastric are two superficial branches of the femoral artery and do not supply the deep branches of the abdomen.

      The deep circumflex iliac artery travels along the iliac crest on the inner surface of the abdominal wall; being too lateral it doesn’t supply blood to the rectus abdominis.

      The distal portions of the umbilical arteries are obliterated in adults to form the medial umbilical folds.

    • This question is part of the following fields:

      • Abdomen
      • Anatomy
      23.3
      Seconds
  • Question 8 - Where would you insert the needle when drawing blood from a patient's median...

    Correct

    • Where would you insert the needle when drawing blood from a patient's median cubital vein?

      Your Answer: Anterior aspect of the elbow

      Explanation:

      The correct answer is to insert it into the anterior aspect of the elbow. If you look at the venous drainage of the upper limb, you will find that there are two main veins, the basilic and the cephalic vein; the connecting branch between these two veins is the median cubital vein. and this vein passes via the cubital fossa which is on the anterior aspect of the forearm.

    • This question is part of the following fields:

      • Anatomy
      • Upper Limb
      28.9
      Seconds
  • Question 9 - A terrorist running away from the police was shot in the back. The...

    Correct

    • A terrorist running away from the police was shot in the back. The bullet hit his left lung halfway between its apex and the diaphragmatic surface. Which part of the lung was most likely to be injured?

      Your Answer: Inferior lobe

      Explanation:

      The oblique fissure of the left lung is so sharp that the posterior surface of the left lung is mostly composed of the inferior lobe so that the point halfway between the apex and the diaphragmatic surface of the lung would result in injury to the inferior lobe.

      The hilum is the point on the medial surface of the lung where the structures that form the root of the lung enter and leave the lung.

      The lingual on the other hand is part of the superior lobe of the left lung and it is part of the anterior and superior sides of the lung.

      The middle lobe is only found on the right lung.

    • This question is part of the following fields:

      • Anatomy
      • Thorax
      12.1
      Seconds
  • Question 10 - Regarding the venous drainage of the heart which of these is correct? ...

    Correct

    • Regarding the venous drainage of the heart which of these is correct?

      Your Answer: The great cardiac vein is the largest tributary of the coronary sinus and this vein starts at the apex of the heart and ascends with the anterior ventricular branch of the left coronary artery

      Explanation:

      Most of the veins of the heart open into the coronary sinus. This is a wide venous channel, about 2.25 cm in length, situated in the posterior part of the coronary sulcus and covered by muscular fibres from the left atrium. Its tributaries are the great, small and middle cardiac veins, the posterior vein of the left ventricle and the oblique vein of the left atrium. The great cardiac vein is the largest tributary of the coronary sinus.

    • This question is part of the following fields:

      • Anatomy
      • Thorax
      51.9
      Seconds
  • Question 11 - Which of the following morphological features is most characteristic of hyaline degeneration? ...

    Correct

    • Which of the following morphological features is most characteristic of hyaline degeneration?

      Your Answer: Homogeneous, ground-glass, pink-staining appearance of cells

      Explanation:

      The characteristic morphological features of hyaline degeneration is ground-glass, pinking staining cytoplasm with an intact cell membrane. The accumulation of lipids, calcium salts, lipofuscin and an amorphous cytoplasm with an intact cell membrane are all characteristically found in different situations.

      Pyknotic nucleus and orphan Annie eye nucleus are not seen in hyaline degeneration.

    • This question is part of the following fields:

      • Cell Injury & Wound Healing
      • Pathology
      36.9
      Seconds
  • Question 12 - Which of the following toxins most likely results in continuous cAMP production, which...

    Correct

    • Which of the following toxins most likely results in continuous cAMP production, which pumps H2O, sodium, potassium, chloride and bicarbonate into the lumen of the small intestine and results in rapid dehydration?

      Your Answer: Cholera toxin

      Explanation:

      The cholera toxin (CTX or CT) is an oligomeric complex made up of six protein subunits: a single copy of the A subunit (part A), and five copies of the B subunit (part B), connected by a disulphide bond. The five B subunits form a five-membered ring that binds to GM1 gangliosides on the surface of the intestinal epithelium cells. The A1 portion of the A subunit is an enzyme that ADP-ribosylates G proteins, while the A2 chain fits into the central pore of the B subunit ring. Upon binding, the complex is taken into the cell via receptor-mediated endocytosis. Once inside the cell, the disulphide bond is reduced, and the A1 subunit is freed to bind with a human partner protein called ADP-ribosylation factor 6 (Arf6). Binding exposes its active site, allowing it to permanently ribosylate the Gs alpha subunit of the heterotrimeric G protein. This results in constitutive cAMP production, which in turn leads to secretion of H2O, Na+, K+, Cl−, and HCO3− into the lumen of the small intestine and rapid dehydration. The gene encoding the cholera toxin was introduced into V. cholerae by horizontal gene transfer.

    • This question is part of the following fields:

      • Microbiology
      • Pathology
      76.3
      Seconds
  • Question 13 - Calculate the pulmonary vascular resistance in an adult male with the following parameters:...

    Correct

    • Calculate the pulmonary vascular resistance in an adult male with the following parameters:

      Heart rate 70 beats/min

      Arterial [O2] 0.24 ml O2/min

      Venous [O2] 0.16 ml O2/mi

      Whole body O2 consumption 500 ml/min

      Pulmonary diastolic pressure 15 mmHg

      Pulmonary systolic pressure 25 mmHg

      Wedge pressure 5 mmHg.

      Your Answer: 2.0 resistance units (mmHg/l per min)

      Explanation:

      Pulmonary vascular resistance (PVR) = (Mean pulmonary artery pressure – Pulmonary capillary wedge pressure) divided by Cardiac output. To get cardiac output, Fick’s principle needs to be applied which states that VO2 = (CO × CAO2) – (CO × CVO2) where VO2 = oxygen consumption, CO = cardiac output, CA = oxygen concentration of arterial blood and CVO2 = oxygen concentration of venous blood. Thus, CO = VO2/CAO2– CVO2, CO = 500/0.24–0.16, CO = 500/0.8, CO = 6.25 l/min. To calculate mean pulmonary artery pressure, we use the formula: Mean pulmonary artery pressure = Diastolic pressure + 1/3(Systolic pressure – Diastolic pressure). Thus, Mean pulmonary artery pressure = 15 + 1/3(25 – 15) = 15 + 3. 33 = 18.33. Substituting these values in the first formula, PVR = 18.3–5/6.25 = 13.5/5.25 = 2.0 resistance units (mmHg/l per min) approximately.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      19.8
      Seconds
  • Question 14 - Pain in the right upper quadrant of the abdomen on ingestion of a...

    Correct

    • Pain in the right upper quadrant of the abdomen on ingestion of a fatty meal is seen in a condition which involves which of the following substances?

      Your Answer: Cholecystokinin

      Explanation:

      The clinical scenario described here favours the presence of gallstones. During food ingestion, vagal discharges stimulate gallbladder contraction. Moreover, presence of fat and amino acids in the intestinal lumen stimulates the release of cholecystokinin (CCK) in the duodenum. This causes sustained gallbladder contraction and relaxation of the sphincter of Oddi. If gallstones are present, there will be inflammation in the gallbladder and CCK will aggravate it due to contractions.

    • This question is part of the following fields:

      • Gastroenterology
      • Physiology
      18.6
      Seconds
  • Question 15 - If a tumour is found in both lobes of the prostate, without nodal...

    Correct

    • If a tumour is found in both lobes of the prostate, without nodal involvement or metastases, a histological grade of G2 and elevated PSA, what is the overall prostatic cancer stage?

      Your Answer: Stage II

      Explanation:

      The AJCC uses the TNM, Gleason score and PSA levels to determine the overall stage of prostatic cancer. This staging is as follows:

      Stage I: T1, N0, M0, Gleason score 6 or less, PSA less than 10; or T2a, N0, M0, Gleason score 6 or less, PSA less than 10

      Stage IIa: T1, N0, M0, Gleason score of 7, PSA less than 20; or T1, N0, M0, Gleason score of 6 or less, PSA at least 10 but less than 20; or T2a or T2b, N0, M0, Gleason score of 7 or less, PSA less than 20

      Stage IIb: T2c, N0, M0, any Gleason score, any PSA; or T1 or T2, N0, M0, any Gleason score PSA of 20 or more; or T1 or T2, N0, M0, Gleason score of 8 or higher, any PSA

      Stage III: T3, N0, M0, any Gleason score, any PSA Stage IV: T4, N0, M0,any Gleason score, any PSA; or any T, N1, M0,any Gleason score, any PSA; or Any T, any N, M1, any Gleason score, any PSA.

      The patient in this case has a T2 N0 M0 G2 tumour, meaning it belongs in stage II

    • This question is part of the following fields:

      • Pathology
      • Urology
      37.6
      Seconds
  • Question 16 - In which of the following conditions will the oxygen-haemoglobin dissociation curve shift to...

    Incorrect

    • In which of the following conditions will the oxygen-haemoglobin dissociation curve shift to the right?

      Your Answer: Decrease in temperature

      Correct Answer: Exercise

      Explanation:

      The oxygen-haemoglobin dissociation curve plots saturated haemoglobin against the oxygen tension and is usually a sigmoid plot. Each molecule of haemoglobin can bind to four molecules of oxygen reversibly. Factors that can influence the binding include: pH, concentration of 2,3-diphosphoglycerate (2,3-DPG), temperature, type of haemoglobin molecules, and presence of toxins, especially carbon monoxide. Shape of the curve is due to interaction of bound oxygen molecules with the incoming molecules. The binding of first molecule is difficult, with easier binding of the second and third molecule and increase in difficulty with the fourth molecule – partly as a result of crowding and partly as a natural tendency of oxygen to dissociate.

      Left shift of curve indicates haemoglobin’s increased affinity for oxygen (seen at lungs). Right shift indicates decreased affinity and is seen with an increase in body temperature, hydrogen ions, 2,3-diphosphoglycerate (DPG), carbon dioxide concentration and exercise. Under normal resting conditions in a healthy individual, the normal position of the curve is at a pH of 7.4. A shift in the position of the curve with a change in pH is called the Bohr effect. Left shift occurs in acute alkalosis, decrease in p(CO2), decrease in temperature and decrease in 2,3-DPG. The fetal haemoglobin curve is to the left of the adult haemoglobin to allow for oxygen diffusion across the placenta. The curve for myoglobin is even further to the left. Carbon monoxide has a much higher affinity for haemoglobin than oxygen does. Thus, carbon monoxide poisoning leads to hypoxia.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      43.5
      Seconds
  • Question 17 - A 50 year old man on warfarin therapy following insertion of a pacemaker...

    Correct

    • A 50 year old man on warfarin therapy following insertion of a pacemaker presented with epistaxis. Which of the following is true regarding blood coagulation?

      Your Answer: Patients with haemophilia A usually have a normal bleeding time

      Explanation:

      A prolonged bleeding time is seen in platelet disorders like thrombocytopenia. Patients with haemophilia A or B have a prolonged PTT but not a prolonged bleeding time.

      Ca2+ is necessary for coagulation.

      von Willebrand factor is an important part of the factor VIII complex and promotes platelet adhesion and aggregation.

      DIC results in depleted coagulation factors and accumulation of fibrin.

    • This question is part of the following fields:

      • General
      • Physiology
      76.8
      Seconds
  • Question 18 - After total thyroidectomy, which of the following investigations is recommended in the immediate...

    Correct

    • After total thyroidectomy, which of the following investigations is recommended in the immediate post-operative period?

      Your Answer: Serum calcium

      Explanation:

      Total thyroidectomy might sometimes result in inadvertent excision or damage of parathyroid glands, leading to hypoparathyroidism. Monitoring serum calcium levels in the post-operative period to detect hypocalcaemia is essential to diagnose and prevent this condition.

    • This question is part of the following fields:

      • Endocrine
      • Pathology
      22.9
      Seconds
  • Question 19 - A 27 year-old male patient was admitted to the hospital due to recurrent...

    Correct

    • A 27 year-old male patient was admitted to the hospital due to recurrent fever for the past 2 weeks. The patient claimed that he is an intravenous drug user. Following work up, the patient was diagnosed with infective endocarditis. Which is the most likely organism responsible for this diagnosis?

      Your Answer: Staphylococcus aureus

      Explanation:

      Acute bacterial endocarditis is a fulminant illness lasting over days to weeks (<2weeks). It is most likely due to Staphylococcus aureus especially in intravenous drug abusers.

    • This question is part of the following fields:

      • Microbiology
      • Pathology
      55.7
      Seconds
  • Question 20 - Which of these structures is most likely to be damaged if a patient...

    Correct

    • Which of these structures is most likely to be damaged if a patient loses consciousness days or weeks after an otherwise insignificant head trauma, especially in elderly patients?

      Your Answer: Dural bridging vein

      Explanation:

      A subdural haematoma is a type of hematoma, usually associated with traumatic brain injury, in which blood collects between the dura mater and the pia-arachnoid mater. Symptoms of subdural haemorrhage have a slower onset than those of epidural haemorrhages because the lower pressure veins bleed more slowly than arteries. These injuries are more common in elderly patients, especially those taking antiplatelet or anticoagulant drugs. Oedema and increased intracranial pressure are unusual.

    • This question is part of the following fields:

      • Neurology
      • Pathology
      49.7
      Seconds
  • Question 21 - The bronchial circulation is a part of the circulatory system that supplies nutrients and oxygen to the pulmonary...

    Correct

    • The bronchial circulation is a part of the circulatory system that supplies nutrients and oxygen to the pulmonary parenchyma. What percentage of cardiac output is received by bronchial circulation?

      Your Answer: 2%

      Explanation:

      The bronchial circulation is part of the systemic circulation and receives about 2% of the cardiac output from the left heart. Bronchial arteries arise from branches of the aorta, intercostal, subclavian or internal mammary arteries. The bronchial arteries supply the tracheobronchial tree with both nutrients and O2. It is complementary to the pulmonary circulation that brings deoxygenated blood to the lungs and carries oxygenated blood away from them in order to oxygenate the rest of the body.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      16
      Seconds
  • Question 22 - A tumour on the floor of the fourth ventricle is most likely to...

    Correct

    • A tumour on the floor of the fourth ventricle is most likely to compress which of the following cranial nerve nuclei?

      Your Answer: Abducent

      Explanation:

      The fourth ventricle, is a cavity of the brains ventricular system in which the cerebrospinal fluid is formed. This cavity is located behind the pons and upper half of the medulla oblongata. It extends from the cerebral aqueduct, to its connection to the third ventricle, and to the obex- which is the caudal tip of the fourth ventricle. The floor of the fourth ventricle consists of three parts – superior, intermediate and inferior. This inferior aspect of the floor of the fourth ventricle has the nucleus of the abducens nerve, CN VI which is looped over by the facial nerve.

    • This question is part of the following fields:

      • Anatomy
      • Head & Neck
      15.9
      Seconds
  • Question 23 - Which is the site of action of the drug omeprazole? ...

    Incorrect

    • Which is the site of action of the drug omeprazole?

      Your Answer: Na+/K+ pump

      Correct Answer: H+/K+ ATPase

      Explanation:

      H+/K+-ATPase or ‘proton pump’ located in the canalicular membrane plays a major role in acid secretion. The ATPase here is magnesium-dependent. Omeprazole is a proton pump inhibitor and blocks H+/K+- ATPase.

    • This question is part of the following fields:

      • Gastroenterology
      • Physiology
      44.5
      Seconds
  • Question 24 - In a cardiac cycle, what event does the closing of atrioventricular (AV) valves...

    Incorrect

    • In a cardiac cycle, what event does the closing of atrioventricular (AV) valves coincide with?

      Your Answer: Second heart sound

      Correct Answer: First heart sound

      Explanation:

      In the cardiac cycle, the closing of the atrioventricular (AV) valves coincides with the onset of ventricular systole. This event marks the beginning of the isovolumetric contraction phase, where the ventricles begin to contract, but the volume of blood in the ventricles remains the same because both the AV valves and the semilunar valves (aortic and pulmonary valves) are closed. The closing of the AV valves produces the first heart sound, known as “S1” or “lub.”

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      131.5
      Seconds
  • Question 25 - What will the destruction of endoplasmic reticulum stop? ...

    Correct

    • What will the destruction of endoplasmic reticulum stop?

      Your Answer: Synthesis of proteins

      Explanation:

      The rough endoplasmic reticulum is the factory for the manufacturing of proteins. It contains ribosomes attached to it and transports proteins that are destined for membranes and secretions. The rough ER is connected to the nuclear envelope and to the cisternae of the Golgi apparatus by vesicles that shuttle between the two compartments.

    • This question is part of the following fields:

      • General
      • Physiology
      27.2
      Seconds
  • Question 26 - One of the following structures is contained in the anterior compartment of the...

    Correct

    • One of the following structures is contained in the anterior compartment of the lower leg. Which is it?

      Your Answer: Extensor hallucis muscle

      Explanation:

      The lower leg is made up of four fascial compartments separated from one another by septa that contain the muscles of the lower leg. The four compartments are ; anterior, lateral, deep posterior and superficial posterior compartments.

      These are the compartments and there contents:

      i) Anterior compartment: Tibialis anterior muscle, extensor hallucis longus muscle, extensor digitorum longus muscle, peroneus tertius muscles, deep fibular nerve and anterior tibial blood vessels

      ii) Lateral compartment: Fibularis longus muscle, brevis muscles and superficial fibular nerve

      iii) Deep posterior compartment: Tibialis posterior m., flexor hallucis longus m., flexor digitorum longus m. ,popliteus m. , tibial nerve, posterior tibial artery and posterior tibial vessels such as the fibular artery.

      iv) Superficial posterior compartment: Gastrocnemius m., soleus m., plantaris m., medial sural cutaneous nerve

    • This question is part of the following fields:

      • Anatomy
      • Lower Limb
      43.1
      Seconds
  • Question 27 - A 45-year-old man complains of shortness of breath, cough and chest pain. Chest...

    Correct

    • A 45-year-old man complains of shortness of breath, cough and chest pain. Chest X ray revealed a perihilar mass with bronchiectasis in the left mid-lung. Which of the following is most probably associated with these findings?

      Your Answer: Bronchial carcinoid

      Explanation:

      Bronchial carcinoids are neuroendocrine tumours that arise from Kulchitsky’s cells of the bronchial epithelium. Kulchitsky’s cells belong to the diffuse endocrine system. Patients affected by this tumour may be asymptomatic or may present with symptoms of airway obstruction, like dyspnoea, wheezing, and cough. Other common findings are recurrent pneumonia, haemoptysis, chest pain and paraneoplastic syndromes. Chest radiographs are abnormal in the majority of cases. Peripheral carcinoids usually present as a solitary pulmonary nodule. For central lesions common findings include hilar or perihilar masses with or without atelectasis, bronchiectasis, or consolidation. Bronchial carcinoids most commonly arise in the large bronchi causing obstruction.

    • This question is part of the following fields:

      • Pathology
      • Respiratory
      70.3
      Seconds
  • Question 28 - During uterogrowth, the second pharyngeal arch gives rise to which structures? ...

    Incorrect

    • During uterogrowth, the second pharyngeal arch gives rise to which structures?

      Your Answer: Mylohyoid

      Correct Answer: Stylohyoid muscle

      Explanation:

      The second pharyngeal arch or hyoid arch, is the second of six pharyngeal arches that develops in fetal life during the fourth week of development and assists in forming the side and front of the neck. Derivatives:

      Skeletal – From the cartilage of the second arch arises:

      Stapes,

      Temporal styloid process,

      Stylohyoid ligament, and

      Lesser cornu of the hyoid bone.

      Muscles:

      Muscles of face

      Occipitofrontalis muscle

      Platysma

      Stylohyoid muscle

      Posterior belly of Digastric

      Stapedius muscle

      Auricular muscles

      Nerve supply: Facial nerve

    • This question is part of the following fields:

      • Anatomy
      • Embryology
      34.8
      Seconds
  • Question 29 - A 7-year old child from a rural setting complains of recurrent abdominal pain....

    Correct

    • A 7-year old child from a rural setting complains of recurrent abdominal pain. The child is found to have a heavy parasitic infestation and anaemia. Which type of anaemia is most likely seen in this patient?

      Your Answer: Iron deficiency anaemia

      Explanation:

      The most common cause of iron deficiency anaemia in children in developing countries is parasitic infection (hookworm, amoebiasis, schistosomiasis and whipworm).

    • This question is part of the following fields:

      • Microbiology
      • Pathology
      40.5
      Seconds
  • Question 30 - An electronic manufacturing engineer had abdominal distension and underwent a CT scan of...

    Correct

    • An electronic manufacturing engineer had abdominal distension and underwent a CT scan of the abdomen. Thereafter he was diagnosed with hepatic angiosarcoma. Exposure to what agent is responsible for the development of this neoplasm?

      Your Answer: Arsenic

      Explanation:

      Hepatic angiosarcomas are associated with particular carcinogens which includes: arsenic , thorotrast, and polyvinyl chloride. With exposure to this three agents, there is a very long latent period of many years between exposure and the development of tumours.

    • This question is part of the following fields:

      • Neoplasia
      • Pathology
      29.3
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Cardiovascular (2/3) 67%
Physiology (7/10) 70%
Orthopaedics (0/1) 0%
Pathology (11/12) 92%
Renal (1/1) 100%
Anatomy (6/8) 75%
Head & Neck (1/2) 50%
Cell Injury & Wound Healing (2/2) 100%
General (3/3) 100%
Abdomen (1/1) 100%
Upper Limb (1/1) 100%
Thorax (2/2) 100%
Microbiology (3/3) 100%
Gastroenterology (1/2) 50%
Urology (1/1) 100%
Respiratory (2/3) 67%
Endocrine (1/1) 100%
Neurology (1/1) 100%
Lower Limb (1/1) 100%
Embryology (0/1) 0%
Neoplasia (1/1) 100%
Passmed