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Question 1
Correct
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From the options provided, which statement would most likely points towards Munchausen's syndrome by proxy?
Your Answer: It is a cause of sudden infant death
Explanation:Munchausen syndrome by proxy is a mental illness and a form of child abuse. The caretaker of a child, most often a mother or a father, either makes up fake symptoms or causes real symptoms to make it look like the child is sick. The person with MSP gains attention by seeking medical help for exaggerated or made-up symptoms of a child in his or her care. As health care providers strive to identify what’s causing the child’s symptoms, the deliberate actions of the mother or caretaker can often make the symptoms worse.The person with MSP does not seem to be motivated by a desire for any type of material gain. People with MSP may create or exaggerate a child’s symptoms in several ways. They may simply lie about symptoms, alter tests (such as contaminating a urine sample), falsify medical records, or they may actually induce symptoms through various means, such as poisoning, suffocating, starving, and causing infection.
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This question is part of the following fields:
- Behavioural Medicine And Psychiatry
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Question 2
Correct
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In a premature infant boy, an inguinal hernia will most likely:
Your Answer: Recur after surgery
Explanation:Inguinal hernias are a common surgical condition in preterm male infants. Surgical repair is usually suggested shortly after birth due to a fear of incarceration or strangulation. These hernias are often indirect as they pass though the processes vaginalis, rather than the posterior wall of the inguinal canal. Recurrence of the hernia is the most common post operative complication. While other complications can occur if left un-repaired, hydrocele and testicular atrophy are not as common, neither is spontaneous resolution.
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This question is part of the following fields:
- Paediatric Surgery
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Question 3
Correct
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A 6 year old female child with a history of controlled type 1 diabetes, presents with recurrent nightmares due to hypoglycaemia and early morning glycosuria. Her parents are well informed about the child’s condition and adjust her insulin requirements according to carbohydrate counting. What is the cause of the hypoglycaemia during the night in association with early morning glycosuria?
Your Answer: Somogyi effect
Explanation:Somogyi effect presents with night-time hypoglycaemia followed by early-morning hyperglycaemia, hence the glycosuria.
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This question is part of the following fields:
- Endocrinology
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Question 4
Correct
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A 2 month old baby presents to the clinic with vomiting. On examination he has ambiguous genitalia. The lab results are as follows: Na: 125mmol/L, K: 6mmol/L. Which of the following is the most likely diagnosis responsible for this patient's presentation?
Your Answer: Congenital adrenal hyperplasia
Explanation:Congenital adrenal hyperplasia (CAH) comprises a group of autosomal recessive defects in enzymes that are responsible for cortisol, aldosterone, and, in very rare cases, androgen synthesis. All forms of CAH are characterized by low levels of cortisol, high levels of ACTH, and adrenal hyperplasia. The exact clinical manifestations depend on the enzyme defect. The most common form of CAH, which is caused by a deficiency of 21β-hydroxylase, presents with hypotension, ambiguous genitalia, and virilization (in the female genotype), and/or precocious puberty (in both males and females). It is further characterized by hyponatremia, hyperkalaemia, and metabolic acidosis. Increased levels of 17-hydroxyprogesterone confirm the diagnosis of 21β-hydroxylase deficiency. Treatment of CAH involves lifelong glucocorticoid replacement therapy. Patients with a 21β-hydroxylase deficiency also require mineralocorticoid replacement with fludrocortisone. Complications of CAH include severe hypoglycaemia, adrenal insufficiency, and/or a failure to thrive.
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This question is part of the following fields:
- Endocrinology
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Question 5
Correct
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A 5 year old boy took a fall on his outstretched hand and presents to the emergency with pain around his elbow. On examination, the radial pulse is found to be absent on the affected side. Which of the following is the most likely diagnosis?
Your Answer: Angulated supracondylar fracture
Explanation:A supracondylar humerus fracture is a fracture of the distal humerus just above the elbow joint. The fracture is usually transverse or oblique and above the medial and lateral condyles and epicondyles. This fracture pattern is relatively rare in adults, but is the most common type of elbow fracture in children. They are historically associated with morbidity due to malunion, neurovascular complications, and compartment syndrome. Important arteries and nerves ( median nerve, radial nerve, brachial artery, and ulnar nerve) are located at the supracondylar area and can give rise to complications if these structures are injured. Most vulnerable structure to get damaged is Median Nerve. Damage/occlusion of the brachial artery is the cause of an absent radial pulse.
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This question is part of the following fields:
- Musculoskeletal
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Question 6
Correct
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According to NICE guidelines, which of the following should be avoided in breastfeeding women?
Your Answer: Lithium
Explanation:According to NICE guidelines:Do not offer lithium to women who are planning a pregnancy or pregnant, unless antipsychotic medication has not been effective.If antipsychotic medication has not been effective and lithium is offered to a woman who is planning a pregnancy or pregnant, ensure:the woman knows that there is a risk of fetal heart malformations when lithium is taken in the first trimester, but the size of the risk is uncertain. Lithium levels may be high in breast milk with a risk of toxicity for the baby.If a woman taking lithium becomes pregnant, consider stopping the drug gradually over 4 weeks if she is well. Explain to her that:stopping the medication may not remove the risk of fetal heart malformations and there is a risk of relapse, particularly in the postnatal period, if she has bipolar disorder.If a woman taking lithium becomes pregnant and is not well or is at high risk of relapse, consider:switching gradually to an antipsychotic or stopping lithium and restarting it in the second trimester (if the woman is not planning to breastfeed and her symptoms have responded better to lithium than to other drugs in the past) or continuing with lithium if she is at high risk of relapse and an antipsychotic is unlikely to be effective. If a woman continues taking lithium during pregnancy:- check plasma lithium levels every 4 weeks, then weekly from the 36th week. Adjust the dose to keep plasma lithium levels in the woman’s therapeutic range- ensure the woman maintains an adequate fluid balance- ensure the woman gives birth in the hospital- ensure monitoring by the obstetric team when labour starts, including checking plasma lithium levels and fluid balance because of the risk of dehydration and lithium toxicity- stop lithium during labour and check plasma lithium levels 12 hours after her last dose.
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This question is part of the following fields:
- Nutrition
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Question 7
Incorrect
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Which of the following does the inferior mesenteric artery supply?
Your Answer: From the duodenum to the first two thirds of the transverse colon
Correct Answer: From the splenic flexure to the first third of the rectum
Explanation:The coeliac axis supplies the liver and stomach and from the oesophagus to the first half of the duodenum. The second half of the duodenum to the first two thirds of the transverse colon is supplied by the superior mesenteric artery. The inferior mesenteric supplies the last third of the transverse colon (approximately from the splenic flexure) to the first third of the rectum. The last two thirds of the rectum are supplied by the middle rectal artery. The greater curvature of the stomach is supplied by branches of the splenic artery, which itself comes from the coeliac axis.
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This question is part of the following fields:
- Gastroenterology And Hepatology
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Question 8
Correct
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A 10-year-old boy presents with severe abdominal pain and jaundice. His family is originally from Ghana.An ultrasound shows evidence of gallstones. What is the most likely risk factor for the child to develop gallstones?
Your Answer: Sickle cell disease
Explanation:Based on the clinical scenario, the most likely risk factor in this child to develop gallstones is sickle cell disease.Note:Haemolysis is the most frequent cause for gallstones in children and the likeliest cause because of his ethnicity would be sickle cell disease. The gallstones are pigmented which form from bilirubin. 70% of patients with sickle cell disease will develop gallstones| the prevalence of gallstones is related to the rate of haemolysis.Other options:- Gilbert’s syndrome: it is a common condition in which bilirubin glucuronidation (i.e. converting bilirubin into a water-soluble form) is affected. During times of stress (viral illness, fasting, etc.) there is an excess bilirubin production, and jaundice may develop. It is a benign condition but there is some evidence of an increased risk of developing gallstones. However, sickle cell disease is a more likely risk factor in this case.- Hereditary spherocytosis: Hereditary spherocytosis is a disease of the white population and is less likely to be the underlying cause in this case.- Male gender: After puberty, the incidence of gallstones is higher in women. Before puberty, the incidence is equal.- Obesity: Obesity is a risk factor for gallstones and is thought to be behind the rising incidence among young adults. Nevertheless, haemolytic states remain the most common reason for gallstones in children.
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This question is part of the following fields:
- Gastroenterology And Hepatology
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Question 9
Correct
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Which of the following is true about Kwashiorkor Protein Energy Malnutrition?
Your Answer: Children affected have generalised oedema
Explanation:Protein energy malnutrition often presents in two common forms, Kwashiorkor and Marasmus. Kwashiorkor is characterised by a protein deficiency with an additional inadequate calorie intake. As a result, affected children present with oedema, muscular atrophy, and their weight for age is 60-80% of the expected weight. Their cutaneous tissue is however preserved. Marasmus on the other hand is characterised by a severe calorie deficiency leading to atrophy of the muscles and adipose tissue, with weight loss being less than 60% of the normal. In both cases, if the child is not promptly rehabilitated, the malnutrition could cause irreversible damage, such as hepatic, cardiac and renal impairments.
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This question is part of the following fields:
- Nutrition
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Question 10
Incorrect
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Which of the following conditions is inherited in an autosomal recessive fashion?
Your Answer: Osteogenesis Imperfecta
Correct Answer: Cystinosis
Explanation:Cystinosis is a condition characterized by accumulation of the amino acid cystine (a building block of proteins) within cells. This condition is inherited in an autosomal recessive pattern.Excess cystine damages cells and often forms crystals that can build up and cause problems in many organs and tissues. The kidneys and eyes are especially vulnerable to damage| the muscles, thyroid, pancreas, and testes may also be affected.There are three distinct types of cystinosis. In order of decreasing severity, they are nephropathic cystinosis, intermediate cystinosis, and non-nephropathic or ocular cystinosis.Nephropathic cystinosis begins in infancy, causing poor growth and a particular type of kidney damage (renal Fanconi syndrome) in which certain molecules that should be reabsorbed into the bloodstream are instead eliminated in the urine. The kidney problems lead to the loss of important minerals, salts, fluids, and many other nutrients. The loss of nutrients impairs growth and may result in soft, bowed bones (hypophosphatemic rickets), especially in the legs. The nutrient imbalances in the body lead to increased urination, thirst, dehydration, and abnormally acidic blood (acidosis). By about the age of 2, cystine crystals may be present in the clear covering of the eye (cornea). The build-up of these crystals in the eye causes pain and an increased sensitivity to light (photophobia). Untreated children will experience complete kidney failure by about the age of 10. Other signs and symptoms that may occur in untreated people, especially after adolescence, include muscle deterioration, blindness, inability to swallow, diabetes, thyroid and nervous system problems, and an inability to father children (infertility) in affected men.The signs and symptoms of intermediate cystinosis are the same as nephropathic cystinosis, but they occur at a later age.
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This question is part of the following fields:
- Genetics And Dysmorphology
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Question 11
Correct
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A 15 year old girl is brought to the emergency after collapsing at a shopping mall. She is accompanied by her mother who reveals that she has had amenorrhea for the past 7 consecutive months. There is fine hair on her body. Which of the following investigations is mandatory in this case?
Your Answer: Urea & Electrolytes
Explanation:Although some individuals with Anorexia Nervosa exhibit no laboratory abnormalities, the semistarvation characteristic of this disorder can affect most major organ systems and produce a variety of disturbances. The induced vomiting and abuse of laxatives, diuretics, and enemas can also cause a number of disturbances leading to abnormal laboratory findings.Haematology: Leukopenia and mild anaemia are common| thrombocytopenia occurs rarely.Chemistry: Dehydration may be reflected by an elevated blood urea nitrogen (BUN). Hypercholesterolemia is common. Liver function tests may be elevated.Hypomagnesemia, hypozincaemia, hypophosphatemia, and hyperamylasaemia are occasionally found. Induced vomiting may lead to metabolic alkalosis (elevated serum bicarbonate), hypochloraemia, and hypokalaemia, and laxative abuse may cause a metabolic acidosis. Serum thyroxine levels are usually in the low-normal range| triiodothyronine levels are decreased. Hyperadrenocorticism and abnormal responsiveness to a variety of neuroendocrine challenges are common.In females, low serum oestrogen levels are present, whereas males have low levels of serum testosterone. There is a regression of the hypothalamic-pituitary-gonadal axis in both sexes in that the 24-hour pattern of secretion of luteinizing hormone (LH) resembles that normally seen in prepubertal or pubertal individuals.
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This question is part of the following fields:
- Adolescent Health
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Question 12
Correct
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Which of the following IV blood products is most likely to cause an urticarial reaction?
Your Answer: Fresh frozen plasma
Explanation:Transfusion with blood products carries a risk of acute and more chronic adverse reactions. These reactions can either be immune mediated due to a component mismatch, or non immune, underpinned by bacterial or viral contamination. Reactions range from very mild such as urticaria, to life threatening in the case of transfusion-related acute lung injury. In transfusion with packed red blood cells, the most common adverse event is pyrexia, while urticaria is the most common adverse event that follows infusion with FFP.
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This question is part of the following fields:
- Haematology And Oncology
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Question 13
Correct
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Which of the following vaccines do not contain live organisms?
Your Answer: Polio (Salk)
Explanation:Live virus vaccines include: Vaccinia (smallpox), Measles, Mumps, Rubella (MMR combined vaccine), Varicella (chickenpox), Influenza (nasal spray), Rotavirus, Zoster (shingles) and Yellow fever. Inactivated vaccines are Polio (IPV), Hepatitis A and Rabies.
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This question is part of the following fields:
- Infectious Diseases
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Question 14
Correct
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A dental surgeon infiltrates local anaesthetic at the mandibular foramen to carry out a block of the right inferior alveolar nerve. Which of the following might occur as a result of the procedure?
Your Answer: Numbness of the lower teeth on the right side
Explanation:The inferior alveolar nerve supplies all the teeth of the respective hemimandible. It transverses the inferior alveolar canal and is a branch of the trigeminal nerve’s mandibular division. Therefore, in this case, the teeth of the right hemimandible will be numb.
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This question is part of the following fields:
- Anatomy
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Question 15
Correct
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A 6 year old child diagnosed with minimal change nephrotic syndrome, presents with lower limb oedema. Which of the following is most likely lost upon urination?
Your Answer: Anti-thrombin III
Explanation:Minimal change nephrotic syndrome leads to the loss of anti-thrombin III which protects the body from forming venous emboli. It may be triggered by virus, immunisations, medication, non-Hodgkin lymphoma, or leukaemiaCharacterised by oedema, proteinuria, hypoalbuminemia, and hypercholesterolemia.
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This question is part of the following fields:
- Nephro-urology
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Question 16
Correct
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Which of the following is true regarding congenital hypothyroidism?
Your Answer: It may lead to prolongation of unconjugated hyperbilirubinemia
Explanation:Congenital hypothyroidism (CH) is inadequate thyroid hormone production in new-born infants. It can occur because of an anatomic defect in the gland, an inborn error of thyroid metabolism, or iodine deficiency.CH is the most common neonatal endocrine disorder, and historically, thyroid dysgenesis was thought to account for approximately 80% of cases. However, studies have reported a change in the epidemiology, with a doubling in incidence to around 1 in 1500 live new-borns.Infants with congenital hypothyroidism are usually born at term or after term. Symptoms and signs include the following:Decreased activityLarge anterior fontanellePoor feeding and weight gainSmall stature or poor growthJaundiceDecreased stooling or constipationHypotoniaHoarse cryProlonged neonatal jaundice or unconjugated hyperbilirubinemia
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This question is part of the following fields:
- Neonatology
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Question 17
Correct
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What is the cause for tinea incognito?
Your Answer: Inappropriate treatment with steroid cream
Explanation:“Tinea incognito” is a term used to describe a tinea infection modified by topical steroids. It is caused by prolonged use of topical steroids, sometimes prescribed as a result of incorrect diagnosis. Topical steroids suppress the local immune response and allow the fungus to grow easily. As a result, the fungal infection may take on the bizarre appearance seen in this patient.The diagnosis of tinea incognito is simple to confirm by microscopic visualization of branching hyphae and spores typical of dermatophytes in a potassium hydroxide preparation.Treatment of tinea incognito requires cessation of all topical steroid use and implementation of specific antifungal treatment. A low-potency corticosteroid may be used briefly to avoid the flare often associated with abrupt cessation of a potent steroid. Patients should be warned of this possibility so they do not reinstitute use of topical steroids on their own.
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This question is part of the following fields:
- Dermatology
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Question 18
Correct
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A 13-year-old girl was recently diagnosed with type 1 diabetes mellitus about two weeks ago and started on an insulin pump. Which of the following complications is least likely to occur due to the treatment modality adopted?
Your Answer: Lipoatrophy
Explanation:Among the given options, lipoatrophy takes time to develop as it is a long-term complication of insulin therapy. Since it has only been two weeks since the initiation of insulin therapy, it is unlikely to occur so early.The risk of lipoatrophy is reduced with newer insulins and also can be avoided by site rotation.However, anaphylaxis, allergic reactions, infection and abscesses at the site of an insulin pump can occur in this patient as a complication of insulin therapy.
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This question is part of the following fields:
- Endocrinology
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Question 19
Correct
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Which of the given features is correct regarding coarctation of aorta?
Your Answer: 70% of patients have bicuspid aortic valves
Explanation:Coarctation of the aorta is one of the serious forms of congenital heart diseases Occurring in about 1 in 2,500 births. It is characterized by a congenitally narrowed proximal thoracic aorta. Coarctation can occur in isolation but can accompany other cardiac lesions, including a bicuspid aortic valve in 70% of the cases and berry aneurysms in 10% of the cases. Coarctation of the aorta is commonly found in association with Turner’s syndrome, Edward’s syndrome, and Patau syndrome.
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This question is part of the following fields:
- Cardiovascular
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Question 20
Correct
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A 3-month-old baby was brought to the paediatrics ward by her mother with a complaint of noisy breathing and difficulty feeding. On examination, the baby had a mild inspiratory stridor, and subsequent laryngoscopy reveals an omega-shaped epiglottis. Which of the following is the most likely diagnosis in this case?
Your Answer: Laryngomalacia
Explanation:Omega-shaped epiglottis is a characteristic feature in the X-ray of a patient with laryngomalacia.
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This question is part of the following fields:
- ENT
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Question 21
Correct
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A mother and her 2 year old girl is referred to a paediatrician on account of concerns over a possible squint. On examination the doctor uses a pen torch to assess the symmetry of the light reflex on each cornea. The following test was used to assess the child:
Your Answer: Hirschberg test
Explanation:In the Hirschberg test, the corneal reflex should fall in the same place in both eyes. If there is a malalignment then the reflection of the light will appear in different places in the two eyes. The cover test is then used to differentiate between a latent deviation, or a manifest deviation.In the Bruckner test, the direct ophthalmoscope is used to obtain a red reflex simultaneously in both eyes. If strabismus is present, the deviated eye will have a lighter and brighter reflex than the fixating eye.The swinging flashlight test is a test of the pupils response to light, and to check for a relative afferent pupillary defect (RAPD).The Angle Kappa test measures the angle between the line of sight and the corneal-pupillary axis. It is a monocular measurement.
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This question is part of the following fields:
- Ophthalmology
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Question 22
Correct
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Normal male puberty is characterized by which of the following features?
Your Answer: Thinning and reddening of scrotal skin is typical of Tanner stage 2
Explanation:Puberty is a period of transitioning into adulthood by developing full reproductive potential by undergoing drastic physiological and psychological changes. For boys, it occurs around 9-16 years of age typically. The process of pubertal changes is usually divided into stages called tanner’s stages. The physiologic changes of puberty are initiated by the release of gonadotropin-releasing hormones from the hypothalamus, which then interact with numerous endogenous and environmental stimuli to bring about the physical pubertal features. Tanner stage 2 in boys is characterized by the thinning and reddening of the scrotal skin.The growth spurt of around 9cm per year is expected in boys, at the peak velocity.Testicular enlargement of >3cm commences puberty.Pubarche, in the absence of other secondary sexual characteristics, is pathological.Adrenarche is the increase in the secretion of adrenal androgens, occurring prior to increased gonadotropin release.
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This question is part of the following fields:
- Endocrinology
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Question 23
Incorrect
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An 8 year old male who is unable to retract his previously retractile foreskin has been treated with 1% hydrocortisone for 3 months. He presents with a white and thickened foreskin. What would you do next to manage his condition?
Your Answer: Circumcision
Correct Answer: Circumcision with urethral calibration
Explanation:The boy suffers from balanitis xerotica obliterans (BXO) which is surgically treated with circumcision and urethral calibration. In fact, the condition is the only true medical indication for circumcision.
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This question is part of the following fields:
- Paediatric Surgery
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Question 24
Incorrect
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A 15-year-old girl is brought to the clinic by her mother, who is worried that her daughter might be using illicit substances. The patient is sweating and appears agitated, talkative and is repeatedly clenching her jaw. She has generalized piloerection. She has most likely taken which of the following substances?
Your Answer: Amphetamine
Correct Answer: MDMA (ecstasy)
Explanation:3,4-methylenedioxy-methamphetamine (MDMA) is a synthetic drug that alters mood and perception (awareness of surrounding objects and conditions). It is chemically similar to both stimulants and hallucinogens, producing feelings of increased energy, pleasure, emotional warmth, and distorted sensory and time perception. MDMA’s effects last about 3 to 6 hours, although many users take a second dose as the effects of the first dose begin to fade. Over the course of the week following moderate use of the drug, a person may experience:irritabilityimpulsiveness and aggressiondepressionsleep problemsanxietymemory and attention problemsdecreased appetitedecreased interest in and pleasure from sex
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This question is part of the following fields:
- Adolescent Health
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Question 25
Correct
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A 1 year old child presents with barking cough, coryza and shortness of breath. What will be the most likely outcome associated with this condition?
Your Answer: Natural resolution
Explanation:Croup is the most common aetiology for hoarseness, cough, and onset of acute stridor in febrile children. Symptoms of coryza may be absent, mild, or marked. The vast majority of children with croup recover without consequences or sequelae.
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This question is part of the following fields:
- Respiratory
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Question 26
Correct
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A 10-year-old boy is brought to the hospital by his mother following complaints of fatigue. Considering a possible diagnosis of iron deficiency anaemia, blood investigations, including a peripheral smear, were ordered. The reports confirmed iron deficiency anaemia. Which of the following abnormal red cell types is likely to be seen in the peripheral smear of this patient?
Your Answer: Pencil cells
Explanation:A peripheral blood film in iron deficiency anaemia can reveal the following morphologically variant RBCs:- Microcytic cells- Hypochromic cells- Pencil cells- Target cellsOther options:- Schistocytes can be caused by mechanical heart valves. – Rouleaux can be seen in chronic liver disease and malignant lymphoma. – Tear-drop poikilocytes can be seen in myelofibrosis. – Acanthocytes can be seen in liver disease and McLeod blood group phenotype.Pathological red cell forms include:- Target cells: Sickle-cell/thalassaemia, iron-deficiency anaemia, hyposplenism, and liver disease.- Tear-drop poikilocytes: Myelofibrosis- Spherocytes: Hereditary spherocytosis and autoimmune haemolytic anaemia- Basophilic stippling: Lead poisoning, thalassaemia, sideroblastic anaemia, and myelodysplasia- Howell-Jolly bodies: Hyposplenism- Heinz bodies: G6PD deficiency and alpha-thalassaemiaSchistocytes (‘helmet cells’): Intravascular haemolysis, mechanical heart valve, and disseminated intravascular coagulation- Pencil poikilocytes: Iron deficiency anaemia- Burr cells (echinocytes): Uraemia and pyruvate kinase deficiency – Acanthocytes: Abetalipoproteinemia
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This question is part of the following fields:
- Haematology And Oncology
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Question 27
Correct
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A 2 year old female was taken to her local emergency department with jerking movements in her limbs. This lasted for around 10 seconds, and then she fell unconscious. She soon regained consciousness - she was disorientated but afebrile with no symptoms of meningeal irritation. From the list of options, chose the most appropriate investigation route for this patient.
Your Answer: 24 hour EEG
Explanation:Many of the symptoms favour an epilepsy diagnosis: uncontrollable jerking of the limbs and a loss of consciousness. A 24-hour EEG is used to diagnose epilepsy.
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This question is part of the following fields:
- Neurology
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Question 28
Incorrect
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A well preterm baby in a thermo-neutral environment requires how much energy to maintain essential body functions?
Your Answer: 100kcal/kg/day
Correct Answer: 50kcal/kg/day
Explanation:The average amount of energy required by a well preterm baby in a thermo-neutral environment is 50/kcal/kg to maintain essential body functions while it takes about 70 kcal/kg/day for optimal growth. It is important to ensure that enough proteins are given per calorie to limit catabolism and promote cell building. Caloric need usually increases when the baby is ill.
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This question is part of the following fields:
- Nutrition
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Question 29
Incorrect
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What are the derivatives of the first brachial arch?
Your Answer: Gives rise to the muscles of facial expression
Correct Answer: Gives rise to the sphenomandibular ligament
Explanation:The first brachial arch (mandibular) gives rise to the mandibular and maxillary processes. Muscles and bones of this process originate within the arch’s mesoderm. The first arch cartilage (Meckel’s) ossifies to form the incus and malleus of the middle ear. Its perichondrium gives rise to he sphenomandibular ligament and through intermembraneous ossification after the mandible forms, the rest of the cartilage disappears. Muscles of the first arch include: mylohyoid, tensor tympany and palati, temporalis, masseter and lateral pterygoids and the anterior belly of the epigastric. This first arch is supplied by the trigeminal nerve.
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This question is part of the following fields:
- Embryology
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Question 30
Correct
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A 15-year-old girl presents with mild abdominal pain in the left lower quadrant for the last four months. An ultrasound scan demonstrates a 7cm simple ovarian cyst. What is the most appropriate course of action for this patient?
Your Answer: Functional ovarian cyst. Ovary sparing cystectomy
Explanation:The most prudent course of action in the given clinical scenario is an ovary-sparing cystectomy. The history is 3-months and is already chronic. Furthermore, the cyst is greater than 5cm in size and at risk of torsion. This will relieve the cause of pain, reduce the risk of torsion and save ovarian function.Other options:- This is a simple cyst and not a malignancy, so imaging and referral are not indicated.- Open oophorectomy was done in the past. However, this is very aggressive, and the modern approach is ovary-sparing.- As the cyst is 7cm and at risk of torsion, conservative management is not appropriate.
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This question is part of the following fields:
- Paediatric Surgery
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Question 31
Incorrect
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A 17-year-old teenage girl presents with a systolic blood pressure of 170 mmHg in all four limbs. Femoral pulses are palpable. Physical examination revealed several large café-au-lait patches and axillary freckling. The girl’s father died of intracerebral haemorrhage associated with hypertension at the age of 50. Which one of the following is the most likely cause of hypertension in this patient?
Your Answer: Polycystic kidney disease
Correct Answer: Renal artery stenosis
Explanation:The patient shows features of neurofibromatosis. The most likely cause for hypertension in this patient would be renal artery stenosis.Note:Neurofibromatosis is an inherited autosomal dominant disorder which could have affected this girl’s father, and she appears to have the classic skin lesions. A renal bruit might be heard in these patients. Polycystic kidney disease can occur in association with tuberous sclerosis, which also has skin lesions associated (different from those described in this patient). Most causes of hypertension in childhood have underlying renal causes, and a renal ultrasound with doppler is the first-line investigation of choice. Even if this is normal, further imaging would be indicated here, for example, isotope renal scans and angiography.
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This question is part of the following fields:
- Nephro-urology
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Question 32
Correct
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Absence of which of the following milestones warrants further assessment in a 15-month-old child?
Your Answer: Stand holding onto furniture
Explanation:By 15 months, it’s common for many toddlers to:- say three to five words.- understand and follow simple commands.- point to one body part.- walk alone and begin to run.- climb on furniture.- make marks with a crayon.- imitate activities, such as housework.
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This question is part of the following fields:
- Child Development
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Question 33
Correct
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Conjugated hyperbilirubinemia does NOT occur in which of the following conditions?
Your Answer: Spherocytosis
Explanation:Neonatal hyperbilirubinemia is a common clinical condition and can be categorized as conjugated and unconjugated hyperbilirubinemia. Conjugated hyperbilirubinemia results from obstructive or hepatocellular causes mainly. The causes of conjugated hyperbilirubinemia include inborn errors of metabolism like galactosemia and aminoaciduria, obstruction from choledochal cysts, and biliary atresia. Long term TPN also leads to conjugated hyperbilirubinemia. Spherocytosis is a hereditary condition belonging to the group of haemolytic anaemias, resulting from plasma membrane protein deficiency. This defect of the RBC plasma membrane decreases their life span, making them osmotically fragile and prone to haemolysis. This leads to an increase in the unconjugated bilirubin levels, with a risk of developing kernicterus.
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This question is part of the following fields:
- Neonatology
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Question 34
Correct
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The following is a sleep-related hormone released in an intermittent manner:
Your Answer: Prolactin
Explanation:Hormones can be secreted in a number of different ways, thus plasma levels of each may vary throughout the day. Many of these exhibit intermittent secretion related to sleep (growth hormone, and prolactin), while others are released based on circadian rhythms (cortisol). Some are released in a pulsatile fashion throughout the day such as FSH, LH, Thyroxine, while others are stress related like cortisol.
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This question is part of the following fields:
- Endocrinology
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Question 35
Correct
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All of the following drugs tend to worsen the symptoms of myasthenia gravis except?
Your Answer: Prednisolone
Explanation:Prednisone is used for the treatment of myasthenia gravis if there is no initial response to the anticholinesterase medications. Pyridostigmine can make the symptoms of myasthenia gravis worse if used in the initial stages of treatment.
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This question is part of the following fields:
- Pharmacology
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Question 36
Correct
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A 4 year old girl presents to the clinic with sore throat and a small painful ulcer in her mouth since yesterday and small painful ulcers on palms and soles that are not itchy. She is febrile (38.5 degree Celsius) and is refusing to eat for the past two days. Which of the following will be the most likely cause of this presentation?
Your Answer: Coxsackie virus
Explanation:Coxsackie viruses are a group of RNA viruses with over 20 serotypes| depending on specific viral characteristics, these serotypes are further divided into groups A and B. Infection is associated with a wide range of symptoms, which are dependent on the exact serotype. Hand, foot, and mouth disease (HFMD) and herpangina are commonly caused by group A coxsackie viruses, while pleurodynia and myocarditis are caused by group B coxsackie viruses. Both groups may cause viral meningitis, conjunctivitis, or flu‑like symptoms. Diagnostic procedures and treatment should be tailored to the specific disease manifestation. Coxsackie A :HerpanginaHand, foot, and mouth diseaseCharacteristics: highly contagiousClinical presentationGeneral symptoms: fever, reduced general conditionSkin/mucosaMaculopapular and partially vesicular rash on the hands and feetOral ulcersDiagnosis: clinicalTreatment: symptomaticPrognosis: almost always self‑limiting
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This question is part of the following fields:
- Infectious Diseases
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Question 37
Incorrect
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What proportion of salivary secretions is contributed by the submandibular glands?
Your Answer: 40%
Correct Answer: 0.7
Explanation:The submandibular glands provide the bulk of salivary secretions contributing close to 70%. The sublingual glands provide 5% and the remainder from the parotid.
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This question is part of the following fields:
- ENT
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Question 38
Correct
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In X linked dominant inheritance, what is the chance of an affected father's daughter inheriting the condition?
Your Answer: 1
Explanation:In the pattern of mendelian inheritance, X- linked dominant inheritance means that all who inherit the X chromosome will present with the condition. In the case of maternal x-linked inheritance sons and daughters have an equal chance of inheriting the condition as there is a 50% chance of inheriting the defective X chromosome from their mother as opposed to a non affected X chromosome from their father. However in paternal X-linked dominant inheritance, sons will be unaffected as they inherit a Y chromosome from their father while daughters are sure to inherit the defective X-chromosome.
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This question is part of the following fields:
- Genetics And Dysmorphology
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Question 39
Correct
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An abnormal red reflex is NOT a characteristic feature of which of the following ocular pathologies?
Your Answer: Amblyopia
Explanation:The red reflex examination is an important part of the paediatric ocular assessment. The red reflex is abnormal in conditions like retinoblastoma, retinopathy of prematurity, cataract, and retinal detachment. Amblyopia is a cortical developmental disorder that results in defective visual inputs to both the eyes. The disorder occurs during the cortical plasticity stage of embryonic development. The red reflex is normal in this case since there is no hindrance to the reflection of light from the ocular media and fundus.
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This question is part of the following fields:
- Ophthalmology
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Question 40
Correct
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A 5 month old boy presents with a history of one episode of green vomiting. Upon clinical examination, doctors notice an acutely swollen mass located in the groin, extending to the scrotum. What is the most probable diagnosis and what’s the most appropriate management?
Your Answer: Incarcerated indirect inguinal hernia, analgesia, sedation and attempt to reduce
Explanation:An incarcerated indirect inguinal hernia presents with abdominal pain, bloating, nausea, vomiting, and intestinal obstruction. It is characterized by the appearance of a tender mass in the inguinal area. Manual reduction in children requires analgesia and sedation.
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This question is part of the following fields:
- Paediatric Surgery
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