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Question 1
Correct
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A 16-year-old female presented to the hospital with a chief complaint of headache, photophobia, fever, and confusion. She is treated empirically with antibiotics. Which of the following represents the correct mechanism of action of the most commonly used first-line antibiotic class?
Your Answer: Inhibition of cell wall synthesis
Explanation:Based on the presenting symptoms, this is the case of bacterial meningitis. The treatment of choice for bacterial meningitis is a cephalosporin. Cephalosporin acts by inhibiting bacterial cell wall synthesis.
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This question is part of the following fields:
- Pharmacology
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Question 2
Correct
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A 30-year-old woman with a BMI of 24 kg/m2 consumes four glasses of wine on an empty stomach. Her serum alcohol are levels measured over the following five hours. The serum alcohol level of 30-year-old man with the same BMI and alcohol consumption is also measured over the same duration.
The peak concentration of alcohol is found to be greater in the woman than in the man.
Which of these offers best explanation for this observation?Your Answer: Lower volume of distribution
Explanation:The blood alcohol concentration depends on:
-The rate of alcohol absorption from the gastrointestinal tract
-The volume of distribution of alcohol in the body, and
-The rate of elimination of alcohol from the body.Total body water is approximately 50% in a female as compared to 60% in a typical male. This means that the volume of distribution of alcohol is lower in female compared with men. This is the principal reason for higher peak in alcohol levels.
About 4% of ingested alcohol is metabolised by the liver accounting for first pass metabolism and 0.4% is metabolised by gastric alcohol dehydrogenase (ADH). The absorbed alcohol is NOT distributed to fat cells but it is distributed throughout the water compartments (plasma, interstitial and intracellular) of the body. Women have very little gastric ADH, which further influences this exaggerated rise.
85-98% of the alcohol is oxidised by the liver to acetaldehyde and then to acetate. The metabolic pathway initially observes first order kinetics and then saturation or zero order kinetics leading to peaks in alcohol levels.
Clearance of ethanol per unit lean body mass is lower in male. The calculated alcohol elimination rate and liver volume per kilogram of lean body mass were 33% and 38% higher in women than in men, respectively.
Available evidence in the literature about the relationship of alcohol metabolism to the phases of the menstrual cycle is conflicting.
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This question is part of the following fields:
- Pathophysiology
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Question 3
Correct
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Regarding the carbon dioxide monitoring, which of the following statements is correct?
Your Answer: Carbon dioxide absorbs infrared radiation at 4.28 µm
Explanation:Carbon dioxide (CO2), is a carbonic gas made up of two dissimilar atoms, namely one carbon atom and two oxygen atoms. Capnography is a technique used to measure carbon dioxide during a respiratory cycle, and it consists in calculating the concentration of the partial pressure of CO2, through the absorption of the infrared light, namely that CO2 absorbs infrared radiation at a wavelength of 4.28 µm.
End-tidal CO2 (ETCO2), referring to the level of the carbon dioxide released at the end of an exhaled breath, is required to be continuously monitored, especially in ventilated patients, as it is a sensitive and a non invasive technique that provides immediate information about ventilation, circulation, and metabolism functions. ETCO2 is normally lower than the arterial partial pressure and varies between 0.6 and 0.7 kPa.
There are two methods used to measure carbon dioxide. The sidestream capnometer method samples gases at a set flow rate (150-200 mL/min) from a sampling area through small diameter tubing, and the mainstream analyser method that uses a direct measurement of the patient exhaled CO2 by a relatively large and heavy sensors. Sidestram method allows the analysis of multiple gases and anaesthetic vapours comparing to the mainstream method that does not allow the measurement of other gases.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 4
Correct
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A 25-year old lady is in the operating room and has had general anaesthesia for a knee arthroscopy.
Induction was done with fentanyl 1mcg/kg and propofol 2mg/kg. A supra-glottic airway was inserted and using and air oxygen mixture with 2.5% sevoflurane, her anaesthesia was maintained. The patient is allowed to spontaneously breathe using a Bain circuit, and the fresh gas flow is 9L/min. Over the next 30 minutes, the end-tidal Co2 rises from 4.5kPa to 8.4kPa, and the baseline reading on the capnograph is 0kPa.
The most appropriate initial action is which of the following?Your Answer: Hypoventilation
Explanation:The commonest and most likely cause of a gradual rise in end-tidal CO2 (EtCO2) occurring during anaesthesia in a spontaneously breathing patient is hypoventilation. This occurs from the respiratory depressant effects of the opioid and sevoflurane.
Malignant hyperthermia should be sought if the EtCO2 shows further progressive rise.
Causes of rebreathing and a rise in the baseline of the capnograph can be caused by exhausted soda lime and inadequate fresh gas flow into the Bain circuit.
A sudden rise in EtCO2 can be caused deflation of the tourniquet.
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This question is part of the following fields:
- Physiology
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Question 5
Correct
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Which of the following statement is not true regarding the effects of Dopamine infusions?
Your Answer: Decreasing gastric transit time
Explanation:Moderately high doses of dopamine produce a positive inotropic (direct?1 and D1 action + that due to Noradrenaline release), but the little chronotropic effect on the heart.
Vasoconstriction (?1 action) occurs only when large doses are infused.
At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.
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This question is part of the following fields:
- Pharmacology
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Question 6
Correct
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The most sensitive indicator of mild obstructive airway disease is?
Your Answer: Forced expiratory flow (FEF25-75%)
Explanation:The volume expired in the first second of maximal expiration after a maximal inspiration is known as forced expiratory volume in one second (FEV1), and it indicates how quickly full lungs can be emptied. It is the most commonly measured parameter for bronchoconstriction assessment.
The maximum volume of air exhaled after a maximal inspiration is known as the ‘slow’ vital capacity (VC). VC is normally equal to FVC after a forced vital capacity (FVC) or slow vital capacity (VC) manoeuvre, unless there is an airflow obstruction, in which case VC is usually higher than FVC.
The FEV1/FVC (Tiffeneau index) is a clinically useful index of airflow restriction that can be used to distinguish between restrictive and obstructive respiratory disorders.
The average expired flow over the middle half (25-75 percent) of the FVC manoeuvre is the forced expiratory volume (FEF25-75). The airflow from the resistance bronchioles corresponds to this. It’s a more sensitive indicator of mild small airway narrowing than FEV1, but it’s difficult to tell if the VC (or FVC) is decreasing or increasing.
The maximum expiratory flow rate achieved is called the peak expiratory flow (PEF), which is usually 8-14 L/second.
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This question is part of the following fields:
- Pathophysiology
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Question 7
Correct
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Which of the following statements is NOT true regarding the internal jugular vein?
Your Answer: The terminal part of the thoracic duct crosses anterior to it to insert into the right subclavian vein
Explanation:The internal jugular vein is found on both sides of the neck and collects blood from the brain, superficial regions of the face, and neck. It drains into the right atrium.
It is a continuation of the sigmoid sinus and begins in the posterior cranial fossa and exits the skull via the jugular foramen.
It runs within the carotid sheath as it descends in the neck and is accompanied by the vagus nerve posteriorly and the common carotid anteromedially.The hypoglossal nerve emerges from the hypoglossal canal medial to the internal carotid artery and the internal jugular vein and ninth, tenth, and eleventh cranial nerves.
The internal jugular vein crosses anterior to the thoracic duct on the left side.
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This question is part of the following fields:
- Anatomy
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Question 8
Correct
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Which of the following best explains the association between smoking and lower oxygen delivery to tissues?
Your Answer: Left shift of the oxygen dissociation curve
Explanation:Smoking is a major risk factor associated with perioperative respiratory and cardiovascular complications. Evidence also suggests that cigarette smoking causes imbalance in the prostaglandins and promotes vasoconstriction and excessive platelet aggregation. Two of the constituents of cigarette smoke, nicotine and carbon monoxide, have adverse cardiovascular effects. Carbon monoxide increases the incidence of arrhythmias and has a negative ionotropic effect both in animals and humans.
Smoking causes an increase in carboxyhaemoglobin levels, resulting in a leftward shift in which appears to represent a risk factor for some of these cardiovascular complications.
There are two mechanisms responsible for the leftward shift of oxyhaemoglobin dissociation curve when carbon monoxide is present in the blood. Carbon monoxide has a direct effect on oxyhaemoglobin, causing a leftward shift of the oxygen dissociation curve, and carbon monoxide also reduces the formation of 2,3-DPG by inhibiting glycolysis in the erythrocyte. Nicotine, on the other hand, has a stimulatory effect on the autonomic nervous system. The effects of nicotine on the cardiovascular system last less than 30 min.
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This question is part of the following fields:
- Physiology
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Question 9
Correct
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The pharmacologically inactive precursor of barbiturates is Barbituric acid. Because the molecule is heterocyclic, small structural changes can alter its pharmacological activity (structure function relationship).
Which of the following modifications to the molecule has the greatest impact on the effectiveness of the barbiturate derivative?Your Answer: Sulphur at C2
Explanation:Barbituric acid is the barbiturates’ pharmacologically inactive precursor. A pyrimidine heterocyclic nucleus is formed by the condensation of urea and malonic acid. Its pharmacological activity can be influenced by minor structural changes (structure function relationship).
The duration of action and potency as a sedative are influenced by the length of the side chains at C5. Barbiturates with three carbon atoms in their chain last longer than those with two. Anticonvulsant properties are enhanced by branched chains.
The addition of a methyl group at N1 causes a faster onset/offset of action, but it also causes excitatory phenomena (twitching/lower convulsive threshold).
The addition of oxygen and sulphur to C2 increases the molecule’s lipid solubility and thus its potency. Thiopentone (thiobarbiturate) has sulphur groups at C2, making it 20-200 times more lipid soluble than oxybarbiturates.
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This question is part of the following fields:
- Pharmacology
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Question 10
Correct
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Which of the following statement is not true regarding the effects of Dopamine in CNS?
Your Answer: Most of the administered dose is converted to Noradrenaline in sympathetic nerve terminals
Explanation:Nausea and vomiting occur commonly due to Chemoreceptor Trigger Zone (CTZ) stimulation by dopamine (Domperidone but not metoclopramide can be used for the treatment of this vomiting)
Dopamine itself cannot cross the blood-brain barrier (BBB) but its precursor levodopa can cross BBB.
Dopamine can modulate extrapyramidal symptoms like acute dyskinesia, tardive dyskinesia, Parkinsonism, and Neuroleptic malignant syndrome.
Dopamine inhibits the secretion of prolactin from the pituitary gland.
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This question is part of the following fields:
- Pharmacology
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Question 11
Correct
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Which of the following statement is false regarding dopamine?
Your Answer: Urine output decreases due to inhibition of proximal tubule Na+ reabsorption
Explanation:Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic ? and?1 (but not ?2 ) agonist.
The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of Dopamine dilates these vessels (by raising intracellular cAMP). This increases g.f.r. In addition, DA exerts a natriuretic effect by D1 receptors on proximal tubular cells.
Moderately high doses produce a positive inotropic (direct?1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.
Vasoconstriction (?1 action) occurs only when large doses are infused.
At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.
Dopamine is less arrhythmogenic than adrenaline
Regarding dopamine part of the dose is converted to Noradrenaline in sympathetic nerve terminals.
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This question is part of the following fields:
- Pharmacology
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Question 12
Correct
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Which statement is true about the autonomic nervous system?
Your Answer: Preganglionic synapse utilise Acetylcholine as the neurotransmitter in both parasympathetic and sympathetic systems
Explanation:With regards to the autonomic nervous system (ANS)
1. It is not under voluntary control
2. It uses reflex pathways and different to the somatic nervous system.
3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.With regards to the central nervous system (CNS)
1. There are myelinated preganglionic fibres which lead to the
ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.Most organs are under control of both systems although one system normally predominates.
The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.
There are short pre-ganglionic and long post ganglionic fibres.
Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.
There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.
Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.
The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.
The cranial outflow consists of
1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreasThe sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.
The PNS has long preganglionic and short post ganglionic fibres.
Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.Different types of these muscarinic receptors are present in different organs:
There are:
M1 = pupillary constriction, gastric acid secretion stimulation
M2 = inhibition of cardiac stimulation
M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
M4 = brain and adrenal medulla
M5 = brainThe lacrimal glands are solely under parasympathetic control.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 13
Correct
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A 20-year old male was involved in an accident and has presented to the Emergency Department with a pelvic crush injury.
The clinical exam according to ATLS protocol revealed the following:
Airway-patent
Breathing - respiratory rate 25 breaths per minute. Breath sounds are vesicular and there are no added sounds.
Circulation - Capillary refill time - 4 seconds. Peripheries are cool. Pulse 125 beats/min. BP - 125/95 mmHg.
Disability - GSC 15, anxious and in pain.
Secondary survey reveals no other injuries. The patient is administered high flow oxygen and IV access is established.
The most appropriate IV fluid regimen in this case will be which of the following?Your Answer: Judicious infusion of Hartmann's solution to maintain a systolic blood pressure greater than 90mmHg
Explanation:These clinical signs suggest that 15-30% of circulating blood volume has been lost.
Pelvic fractures are associated with significant haemorrhage (>2000 ml) that can be concealed. This may require aggressive fluid resuscitation which is initially with crystalloids and then blood. What is also important is including stabilisation of the fracture(s) and pain relief.
The Advanced Trauma Life Support (ATLS) classification of haemorrhagic shock is as follows:
Class I haemorrhage (blood loss up to 15%):
<750 ml of blood loss
Minimal tachycardia
No changes in blood pressure, RR or pulse pressure
Patients do not normally not require fluid replacement as will be restored in 24 hours, but in trauma, this needs to be correct.Class II haemorrhage (15-30% blood volume loss):
Uncomplicated haemorrhage requiring crystalloid resuscitation
Represents about 750 – 1500 ml of blood loss
Tachycardia, tachypnoea and a decrease in pulse pressure (due to a rise in diastolic component due action of catecholamines).
There are minimal systolic pressure changes.
There may be associated anxiety, fright or hostilityClass III haemorrhage (30-40% blood volume loss):
Complicated haemorrhagic state – crystalloid and probably blood replacement are required
There are classical signs of inadequate perfusion, marked tachycardia, tachypnoea, significant changes in mental state and measurable fall in systolic pressure.
Almost always require blood transfusion, but decision based on patient initial response to fluid resuscitation.Class IV haemorrhage (> 40% blood volume loss):
Preterminal event patient will die in minutes
Marked tachycardia, significant depression in systolic pressure and very narrow pulse pressure (or unobtainable diastolic pressure)
Mental state is markedly depressed
Skin cold and pale.
Needs rapid transfusion and immediate surgical intervention.A blood loss of >50% results in loss of consciousness, pulse and blood pressure.
Fluid resuscitation following trauma is a controversial area.
This clinical scenario points to a 15-30% blood loss. However, further crystalloid and blood replacement may be required after assessing the clinical situation. There is increasing evidence to suggest that transfusion of large volumes of crystalloid in the hospital setting are likely to be deleterious to the patient and hypotensive resuscitation and judicious blood and blood product resuscitation is a more appropriate option. A ratio of 1 unit of plasma to 1 unit of red blood cells is used to replace fluid volume in adults.
This patient does not require immediate transfusion of O negative blood and there is time for a formal crossmatch. The argument about colloids versus crystalloids has existed for decades. However, while they have a role in fluid resuscitation, they are not first line.
There is a risk of anaphylaxis, Hypernatraemia, and acute renal injury with colloidal solutions.
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This question is part of the following fields:
- Physiology
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Question 14
Incorrect
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A drug with a 2-hour half-life and a first-order kinetics of elimination is administered intravenously. The initial plasma concentration is calculated to be 12 mcg/mL and plasma concentrations is measured hourly.
At 6 hours, how much drug will be left?Your Answer: 0.75 mcg/mL
Correct Answer: 1.5 mcg/mL
Explanation:In first order kinetics the rate of elimination is proportional to plasma concentration.
Rate of elimination is described by the following equation:
C = C0. e^-kt
Where:
C=drug concentration,
C0= drug concentration at time zero (extrapolated),
k = rate constant and
t = time.The initial concentration of this drug is 12 mcg/ml therefore:
The plasma concentration will have halved to 6 mcg/ml at 2 hours.
The plasma concentration will have halved to 3 mcg/ml at 4 hours and
The plasma concentration will have halved to 1.5 mcg/ml t 6 hours. -
This question is part of the following fields:
- Pharmacology
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Question 15
Incorrect
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What is the most sensitive method of detecting an intra-operative air embolism?
Your Answer: Oesophageal stethoscope
Correct Answer: Transoesophageal echocardiogram
Explanation:An intra-operative air embolism occurs when air becomes trapped in the blood vessels during surgery.
A transoesophageal echocardiography (OE) uses invasive echocardiography to monitor the integrity and performance of the heart. It is the gold standard as it provides real-time imaging of the heart to enable early diagnosis and treatment.
Precordial doppler ultrasonography can also be used to detect into-operative air emboli. It is non-invasive and more practical, but is less sensitive.
A change in end-tidal CO2 could be indicative of and increase in physiological dead-space, but could also be indicative of any processes that reduces the excretion or increases the production of CO2, making it non-specific.
A transoesophageal stethoscope can be used to listen for the classic mill-wheel murmur produced by a large air embolus.
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This question is part of the following fields:
- Pathophysiology
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Question 16
Correct
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Which plasma protein will bind the thyroid hormone triiodothyronine (T3) more readily?
Your Answer: Thyroxine binding globulin
Explanation:Secreted T4 and T3 circulate in the bloodstream almost entirely bound to proteins. Normally only about 0.03% of total plasma T4 and 0.3% of total plasma T3 exist in the free state. Free T3 is biologically active and mediates the effects of thyroid hormone on peripheral tissues in addition to exerting negative feedback on the pituitary and hypothalamus. The major binding protein is thyroxine-binding globulin (TBG), which is synthesized in the liver and binds one molecule of T4 or T3. About 70% of circulating T4 and T3 is bound to TBGl 10% to 15% is bound to another specific thyroid-binding protein called transthyretin (TTR). Albumin binds 15% to 20%, and 3% to lipoproteins. Ordinarily only alterations in TBG concentration significantly affect total plasma T4 and T3 levels.
Two important biological functions have been ascribed to TBG. First, it maintains a large circulating reservoir of T4 that buffers any acute changes in thyroid gland function. Second, binding of plasma T4 and T3 to proteins prevents loss of these relatively small hormone molecules in urine and thereby helps conserve iodide. TTR transports T4 in CSF and provides thyroid hormones to the CNS.
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This question is part of the following fields:
- Physiology
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Question 17
Incorrect
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Which of the following statements most accurately describes a drug's efficacy or intrinsic activity?
Your Answer: Is a measure of the amount of drug required to produce a given effect
Correct Answer: Describes the ability of a drug to produce a therapeutic effect
Explanation:An agonist is a molecule with intrinsic efficacy and affinity for a receptor. The ability of a drug-receptor interaction to produce a maximal response is referred to as intrinsic efficacy or activity. Efficacy also refers to a drug’s ability to have a therapeutic or beneficial effect. Although the potencies of morphine and fentanyl differ, they both have the same intrinsic efficacy.
The amount of drug required to produce a given effect is referred to as potency. If drug X is effective in a dose of 100 mcg, its potency is greater than if drug Y is effective in a dose of 10 mg.
The therapeutic index, also known as the margin of safety, is a ratio of the lethal or serious side effect dose of a drug divided by the therapeutic dose of the same drug.
The term bioavailability refers to the ability of a substance to be absorbed. The area under a curve (AUC) of a graphic plot of plasma concentration and time is used to calculate oral bioavailability. It’s used to figure out how much of a drug to take and when to take it.
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This question is part of the following fields:
- Pharmacology
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Question 18
Incorrect
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A study aimed at assessing the validity of a novel diagnostic test for heart failure is being performed. The curators are worried that not all the patients will get the prevalent gold standard test.
Which type of bias is that?Your Answer: Attention bias
Correct Answer: Work-up bias
Explanation:Work up bias involves comparing the novel diagnostic test with the current standard test. A portion of the patients undergo the standard test while others undergo the new test as the standard test is costly. The result can be alteration in specify and sensitivity.
Selection bias is when randomisation is not achieved.
Attention bias refers to the person’s failure to consider various alternatives when he pre occupied by some other thoughts.
Instrument bias is related to the experience and extent of familiarization of the participating individuals with the test.
Co intervention bias is characterized by the groups receiving different co interventions.
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This question is part of the following fields:
- Statistical Methods
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Question 19
Incorrect
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A 24-year old female is brought to the emergency room due to urticarial rash and shortness of breath. Her mother reported that, prior to the symptoms, she took Co-amoxiclav (Augmentin) for her present ear infection. She also reported that she had no previous exposure to penicillin or any other related antibiotics.
Which of the following can help to differentiate between type 1 and type II hypersensitivity reaction in this case?Your Answer: Radio-allergosorbent test (RAST)
Correct Answer: IgE assay specific for amoxycilloyl
Explanation:Serum specific IgE assays against allergen sources/molecules are the most commonly used in vitro diagnostic approach. The measurement of specific IgE recognizing allergenic epitopes can be achieved both through the usage of single reagents (singleplex) or with a pre-defined panel of a number of molecules to be tested simultaneously (multiplex).
Several clinical entities have been described and those occurring immediately after drug exposure are immunoglobulin E (IgE)-mediated and explored by skin testing and by the in vitro measurement of serum-specific IgE. The sensitivity of these tests is not 100% and even for patients with a clear positive history, a drug provocation test may be required in order to confirm the diagnosis. The advantages of the in vitro determination of specific IgE antibodies when compared with in vivo testing are that the former poses no direct risk to the patient and does not require personnel with expertise. Even though in vitro tests are recommended in immediate hypersensitivity reactions, their exact place in the diagnostic procedure is not clear and certain authors do not use this method in daily practice. In one study, in terms of sensitivity, 11 of 26 patients (42%) with negative skin tests and a positive drug provocation challenge (or repeated clinical history) had specific IgE to benzylpenicilloyl or amoxicilloyl (4). The specificity of the test was 95–100%. Therefore, IgE measurements can avoid a potentially harmful drug provocation test.
An elevated serum tryptase does not differentiate between type 1 and type 2 hypersensitivity reaction. It indicates mast cell degranulation.
RAST is a useful aid to improve the overall diagnosis of drug allergies by using radioactive detection. This, however, is now rarely used.
Quantification of basophil activation by CD63 expression can be done by flow cytometry, which forms the basis of experimental drug-induced basophil stimulation tests.
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This question is part of the following fields:
- Pathophysiology
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Question 20
Incorrect
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A post-operative patient was brought to the recovery room after completion of dilation and curettage. Her medical history revealed that she was maintained on levodopa for Parkinson's disease. The nurses administered ondansetron 4 mg and dexamethasone 8 mg prior to transfer from the operating room to the recovery room. However, an additional antiemetic agent is warranted.
Which of the following agents should be prescribed to the patient?Your Answer: Prochlorperazine 12 mg IM
Correct Answer: Cyclizine 50 mg IV
Explanation:The Beers criteria, a US set of criteria for good prescribing in the older patient, preclude the use of metoclopramide in Parkinson’s disease. The Adverse Reactions Register of the UK Committee on Safety of Medicines (CSM) for the years 1967 to 1982 contained 479 reports of extrapyramidal reactions in which metoclopramide was the suspected drug; 455 were for dystonic-dyskinetic reactions, 20 for parkinsonism and four for tardive dyskinesia. Effects can occur within days of initiation of treatment and may take months to wear off.
Other antiemetics are available, such as cyclizine (Valoid), domperidone and ondansetron, which would be more appropriate to use in those with Parkinson’s disease.
Cyclizine is a piperazine derivative with histamine H1 receptor antagonist and anticholinergic activity. It is used for the treatment of nausea, vomiting, (particularly opioid-induced vomiting), vertigo, motion sickness, and labyrinthine disorders.
Prochlorperazine is an antipsychotic known to cause tardive dyskinesia, tremor and parkinsonian symptoms and is therefore likely to exacerbate Parkinson’s disease. Prochlorperazine is not favoured for older patients because of the increased risk of stroke and transient ischaemic attack (TIA).
Droperidol and phenothiazine are also potent antagonists on D2 receptors and must also be avoided.
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This question is part of the following fields:
- Pharmacology
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Question 21
Incorrect
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A 77-year-old woman is scheduled for day case cataract surgery under local anaesthesia. She has no cardiac or respiratory problems. Lisinopril is being used to treat her hypertension, which is under control.
Which of the following preoperative investigations are the most appropriate for this patient?Your Answer: FBC, urea and electrolytes and ECG
Correct Answer: No investigations
Explanation:Because the patient has mild systemic disease, he is ASA 2 and the procedure will be performed under local anaesthesia.
The following factors should be considered when requesting preoperative investigations:
Indications derived from a preliminary clinical examination
Whether or not a general anaesthetic will be used, the possibility of asymptomatic abnormalities, and the scope of the surgery.No special investigations are needed if the patient has no history of significant systemic disease and no abnormal findings on examination during the nurse-led assessment.
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This question is part of the following fields:
- Clinical Measurement
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Question 22
Incorrect
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Regarding amide local anaesthetics, which one factor has the most significant effect on its duration of action?
Your Answer: Tissue pH
Correct Answer: Protein binding
Explanation:When drugs are bound to proteins, drugs cannot cross membranes and exert their effect. Only the free (unbound) drug can be absorbed, distributed, metabolized, excreted and exert pharmacologic effect. Thus, when amide local anaesthetics are bound to ?1-glycoproteins, their duration of action are reduced.
The potency of local anaesthetics are affected by lipid solubility. Solubility influences the concentration of the drug in the extracellular fluid surrounding blood vessels. The brain, which is high in lipid content, will dissolve high concentration of lipid soluble drugs. When drugs are non-ionized and non-polarized, they are more lipid-soluble and undergo more extensive distribution. Hence allowing these drugs to penetrate the membrane of the target cells and exert their effect.
Tissue pKa and pH will determine the degree of ionization.
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This question is part of the following fields:
- Physiology
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Question 23
Incorrect
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A 25-year-old soldier is shot in the abdomen. He has multiple injuries, including a major disruption to the abdominal aorta. The bleeding is torrential and needs to be controlled by placing a vascular clamp immediately inferior to the diaphragm.
During this manoeuvre, which vessel may be injured?Your Answer: Superior mesenteric artery
Correct Answer: Inferior phrenic arteries
Explanation:The inferior phrenic nerves are at the highest risk of damage as they are the first branches of the abdominal aorta. The potential space at the level of the diaphragmatic hiatus is a potentially useful site for aortic occlusion. However, leaving the clamp applied for more than 10 -15 minutes usually leads to poor outcomes.
The superior phrenic artery branches from the thoracic aorta.
The abdominal aorta begins at the level of the body of T12 near the midline, as a continuation of the thoracic aorta. It descends and bifurcates at the level of L4 into the common iliac arteries.
The branches of the abdominal aorta (with their vertebra level) are:
1. Inferior phrenic arteries: T12 (upper border)
2. Coeliac artery: T12
3. Superior mesenteric artery: L1
4. Middle suprarenal arteries: L1
5. Renal arteries: Between L1 and L2
6. Gonadal arteries: L2 (in males, it is the testicular artery, and in females, the ovarian artery)
7. Inferior mesenteric artery: L3
8. Median sacral artery: L4
9. Lumbar arteries: Between L1 and L4 -
This question is part of the following fields:
- Anatomy
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Question 24
Correct
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Which of the following vertebral levels is the site where the oesophagus passes through the diaphragm to enter the abdominal cavity?
Your Answer: T10
Explanation:The diaphragm divides the thoracic cavity from the abdominal cavity. Structures penetrate the diaphragm at different vertebral levels through openings in the diaphragm to communicate between the two cavities. The diaphragm has openings at three vertebral levels:
T8: vena cava, terminal branches of the right phrenic nerve
T10: oesophagus, vagal trunks, left anterior phrenic vessels, oesophageal branches of the left gastric vessels
T12: descending aorta, thoracic duct, azygous and hemi-azygous vein -
This question is part of the following fields:
- Anatomy
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Question 25
Correct
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What can an outbreak of flu that has spread globally be termed as?
Your Answer: Pandemic
Explanation:An epidemic is declared when the increase in a give disease is above a certain level in a specific interval of time.
An endemic is the general, usual level of a disease in a population at a particular time.
A pandemic is an epidemic that is spread across many countries and continents.
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This question is part of the following fields:
- Statistical Methods
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Question 26
Incorrect
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In a study lasting over a period of two years, in which the mean age of 800 patients was 82 years, the efficacy of hip protectors in reducing femoral neck fractures was discussed.
Both experimental and control group had 400 members. Instances of fractures reported over the two year time duration were 10 for the control group (that were prescribed hip protector) and 20 for the control group.
What is the value of Absolute Risk Reduction?Your Answer: 2
Correct Answer: 0.025
Explanation:ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)
So,
ARR= (10/400)-(20/400)
ARR= 0.025-0.05
ARR= 0.025 (Numerical Value)
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This question is part of the following fields:
- Statistical Methods
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Question 27
Incorrect
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A man suffers damage to his vagus nerve during surgery on his neck. The vagus nerve is cut near its exit from the skull. The man loses his parasympathetic tone raising his heart rate and blood pressure.
What other feature will be likely present with a vagus nerve injury?Your Answer: Loss of anal tone
Correct Answer: Hoarse voice
Explanation:The vagus nerve is a mixed nerve with both autonomic and somatic effects. Its most important somatic effect is the motor supply to the larynx via recurrent laryngeal nerves. If one vagus nerve is damaged, the result will be the same as damage to a single recurrent laryngeal nerve, leading to hoarseness of voice.
The vagus exits the skull via the jugular foramen, accompanied by the accessory nerve.
Anal tone, erections, and urination are all controlled by the sacral parasympathetic and would not be affected by the loss of the vagus. Parasympathetic controlled pupillary constriction is via the oculomotor nerve and would not be affected by the loss of the vagus.
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This question is part of the following fields:
- Anatomy
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Question 28
Incorrect
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Which of the following herbal drug side effects or herb-drug interactions is the most likely?
Your Answer: Ginkgo Biloba : potentiation of GABAA agonists
Correct Answer: St. John's Wort : serotonin syndrome
Explanation:Patients who present for surgery may be on prescription medication or natural/herbal therapies. These have relevance for anaesthesia since they can cause drug interactions.
Ephedra (Ma Huang) is a drug derived from the plant Ephedra sinica that is used as a CNS stimulant, weight reduction aid, and asthma therapy. It is a combination of alkaloids that includes ephedrine which stimulates noradrenaline release from pre-synaptic neurones by acting directly on alpha and beta adrenoreceptors. The use of sympathomimetic drugs together can cause cardiovascular instability.
Ginkgo Biloba contains anti-oxidant characteristics and is used to treat Alzheimer’s disease, vascular dementia, and peripheral vascular disease. It lowers platelet adhesiveness and raises the risk of bleeding by decreasing platelet activating factor (PAF), especially in individuals who are also taking anticoagulants and antiplatelet drugs.
The extract from St. John’s Wort is utilised as an antidepressant because it is a cytochrome P450 isoenzyme inhibitor as well as a serotonin uptake inhibitor. When drugs like fentanyl or tramadol are used during an anaesthetic, there is a risk of serotonin syndrome developing.
The root of a pepper is used to make kava (Piper methysticum). It is a weak GABAA agonist which has the potential to augment the effects of propofol and benzodiazepines, which are volatile anaesthetics.
Garlic is made from the allium sativum plant and is used to treat hypertension and hyperlipidaemia. It includes cysteine, which inhibits platelet aggregation irreversibly, amplifying the effects of aspirin and NSAIDs.
Echinacea is a common herbal medicine that stimulates the immune system by modulating cytokine signalling. In individuals who require organ transplantation, it should be avoided.
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This question is part of the following fields:
- Pharmacology
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Question 29
Incorrect
-
Fixed performance devices like high air flow oxygen enrichment (HAFOE) masks have large volumes of air entrained into a flow of 100% oxygen.
The term that best describes the physics behind air entrainment is?Your Answer: Venturi effect
Correct Answer: Bernoulli's principle
Explanation:Bernoulli’s principle states that as the speed of a moving fluid increases, there is a simultaneously decrease in static pressure or a decrease in the fluid’s potential energy.
This is seen in the simultaneous increase in speed and kinetic energy and fall in pressure that causes entrainment of large volumes of air into a flow of 100% oxygen in the nozzle of HAFOE masks.The reduction in fluid pressure that happens when a fluid flows through a constriction in a tube is the Venturi effect.
When a flow of gas or liquid attaches itself to a nearby surface and remains attached even when the surface curves away from the initial direction of flow, this is the Coanda effect.
The branch of engineering and technology that is concerned with the building of devices that use the flow and pressure of a fluid for functions usually performed by electronic devices is Fluidics . Fluidic logic is used to power some ventilators.
The branch of engineering that utilises pressurised gases is Pneumatics.
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This question is part of the following fields:
- Basic Physics
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Question 30
Incorrect
-
The spinal cord tracts that transmits the sensations of pain, crude temperature, and light touch is?
Your Answer: Dorsal column
Correct Answer: Spinothalamic
Explanation:Dorsal column (ascending tract) – Proprioception, vibration, discriminative
Spinocerebellar (ascending tract) – Subconscious muscle position and tone
Corticospinal (descending tract) – Voluntary muscle
Rubrospinal (descending tract) – Flexor muscle tone
Vestibulospinal (descending tract) – Reflexes and muscle tone
Reticulospinal(descending tract) – Voluntary movements, head position.-
Autonomic – Descending tract.
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This question is part of the following fields:
- Anatomy
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Question 31
Incorrect
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Which of the following statements is true about oxygen face masks?
Your Answer: The air entrainment aperture in a 40% Venturi device is the same size as that on a 31% Venturi device
Correct Answer: The oxygen concentration delivered by high air flow oxygen enrichment devices is not dependent on the respiratory pattern of the patient
Explanation:The normal peak inspiratory flow in healthy individuals is 20-30 L/min during each normal tidal ventilation. This is expected to increase with greater respiratory rate and deeper inspiration.
Face masks are used to facilitate the delivery of oxygen from a breathing system to a patient. Face masks can be divided into two types: fixed performance or variable performance devices.
In fixed performance devices (also known as high air flow oxygen enrichment or HAFOE), fixed inspired oxygen concentration is delivered to the patent, independent and greater than that of the patient’s peak inspiratory flow rate (PIFR). No random entrainment is expected to occur at the time of PIFR, hence, the oxygen concentration in HAFOE devices is not dependent on the patient’s respiratory pattern.
Moreover, in HAFOE masks, the concentration of oxygen at a given oxygen flow rate is determined by the size of the constriction; a device with a greater entrainment aperture delivers a lower oxygen concentration. Therefore, a 40% Venturi device will have lesser entrainment aperture when compared to a 31% Venturi. Venturi masks allow relatively fixed concentrations of supplemental oxygen to be inspired e.g. 24%, 28%, 31%, 35%, 40% and 60% oxygen. These are colour coded and marked with the recommended oxygen flow rate.
Variable performance devices deliver variable inspired oxygen concentration to the patient, and is dependent on the PIFR. The PIFR can often exceed the flow rate at which oxygen or an oxygen/air mixture is supplied by the device, depending on a patient’s inspiratory effort. In addition, these masks allow expired air to be released through the holes in the sides of the mask. Thus, with increased respiratory rate, rebreathing of alveolar gas from inside the mask may occur.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 32
Incorrect
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The following statement is true with regards to the Nernst equation:
Your Answer: It is inversely proportional to the universal gas constant
Correct Answer: It is used to calculate the potential difference across a membrane when the individual ions are in equilibrium
Explanation:The Nernst equation is used to calculate the membrane potential at which the ions are in equilibrium across the cell membrane.
The normal resting membrane potential is -70 mV (not + 70 mV).
The equation is:
E = RT/FZ ln {[X]o
/[X]i}Where:
E is the equilibrium potential
R is the universal gas constant
T is the absolute temperature
F is the Faraday constant
Z is the valency of the ion
[X]o is the extracellular concentration of ion X
[X]i is the intracellular concentration of ion X. -
This question is part of the following fields:
- Physiology
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Question 33
Correct
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One of the non-pharmacologic management of COPD is smoking cessation. Given a case of a 60-year old patient with history of smoking for 30 years and a FEV1 of 70%, what would be the most probable five-year course of his FEV1 if he ceases to smoke?
Your Answer: The FEV1 will decrease at the same rate as a non-smoker
Explanation:For this patient, his forced expiratory volume in 1 second (FEV1) will decrease at the same rate as a non-smoker.
There is a notable, but slow, decline in FEV1 when an individual reaches the age of 26. An average reduction of 30 mls every year in non-smokers, while a more significant reduction of 50-70 mls is observed in approximately 20% of smokers.
Considering the age of the patient, individuals who begin smoking cessation by the age of 60 are far less likely to achieve normal FEV1 levels, even in the next five years. It is expected that their FEV1 will be approximately 14% less than their peers of the same age.
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This question is part of the following fields:
- Physiology
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Question 34
Incorrect
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A 65-year-old man, presents to the emergency department. He explains that an hour ago, he experienced central chest pain, which moved down his left arm.
On ECG, elevation in the ST-segment was noted in the anterior leads. He undergoes emergency percutaneous coronary intervention (PCI) which requires the cardiologist to access the heart via the femoral artery.
Where is the surface marking for identifying the femoral artery?Your Answer: Midway between the ASIS and the pubic tubercle
Correct Answer: Midway between the ASIS and the pubic symphysis
Explanation:The surface marking for locating the femoral artery is the mid-inguinal point, which is the halfway point between the anterior superior iliac spine (ASIS) and the pubic symphysis.
The other mentioned options are not specific for any landmark.
However, it is important to note the difference between the mid inguinal point and the midpoint of the inguinal ligament, which is travels from the ASIS to the pubic tubercle.
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This question is part of the following fields:
- Anatomy
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Question 35
Incorrect
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Which of the following explains the mode of action of Magnesium sulphate in preventing eclampsia in susceptible patients?
Your Answer: Reduction of cerebral oedema formation opposing movement of solutes across capillaries
Correct Answer: Dilatation of cerebral circulation due to calcium channel antagonism reducing cerebral vascular spasm
Explanation:Magnesium is a unique calcium antagonist as it can act on most types of calcium channels in vascular smooth muscle and as such would be expected to decrease intracellular calcium. One major effect of decreased intracellular calcium would be inactivation of calmodulin-dependent myosin light chain kinase activity and decreased contraction, causing arterial relaxation that may subsequently lower peripheral and cerebral vascular resistance, relieve vasospasm, and decrease arterial blood pressure.
The vasodilatory effect of MgSO4 has been investigated in a wide variety of vessels. For example, both in vivo and in vitro animal studies have shown that it is a vasodilator of large conduit arteries such as the aorta, as well as smaller resistance vessels including mesenteric, skeletal muscle, uterine, and cerebral arteries.
The theory of cerebrovascular vasospasm as the aetiology of eclampsia seemed to be reinforced by transcranial Doppler (TCD) studies which suggested that MgSO4 treatment caused dilation in the cerebral circulation as well as in animal studies that used large cerebral arteries.
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This question is part of the following fields:
- Pathophysiology
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Question 36
Incorrect
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Which of the following statements is correct about a characteristic that is normally distributed in a population?
Your Answer: Ten percent of individuals will be beyond two standard deviations from the mean
Correct Answer: There will be approximately equal numbers who have more or less of the characteristic than the mean
Explanation:68% of the population will be found in one standard deviation (SD) above plus one SD below the mean. Two SDs above plus two SDs below the mean will include 95% of the population.
The median can be greater or less than the mean as it is simply the mid point of the data after the data is arranged. Half the data are above and half below the median .
The mode is a true score, unlike the mean or the median. It is the most common score or the score obtained from the largest number of subjects in any given data.
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This question is part of the following fields:
- Statistical Methods
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Question 37
Incorrect
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Regarding sine wave damping, which one would approach equilibrium the fastest at zero amplitude, without overshoot?
Your Answer: Optimal damping
Correct Answer: Critical damping
Explanation:A damped sine wave is a smooth, periodic oscillation with an amplitude that approaches zero as time goes to infinity. In other words, the wave gets flatter as the x-values become larger.
Critical damping is defined as the threshold between overdamping and underdamping. In the case of critical damping, the oscillator returns to the equilibrium position as quickly as possible, without oscillating, and passes it once at most.
In overdamping, the system moves slowly towards the equilibrium. An underdamped system moves quickly to equilibrium, but will oscillate about the equilibrium point as it does so.
Optimal damping has a damping coefficient of around 0.64-0.7. It maximizes frequency response, minimizes overshoot of oscillations, and minimizes phase and amplitude distortion.
In an undamped system, the amplitude of the waves that are being generated remain unchanged and constant over time.
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This question is part of the following fields:
- Clinical Measurement
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Question 38
Incorrect
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Which of the following closely estimates the interstitial oncotic pressure acting on a pulmonary capillary?
Your Answer: 0 mmHg
Correct Answer: 17 mmHg
Explanation:The starling forces operate to maintain a homeostatic flow across the pulmonary capillary bed.
The outward driving force comprises of the capillary hydrostatic pressure (13 mmHg), negative interstitial fluid pressure (zero to slightly negative), and interstitial colloid osmotic pressure (17 mmHg). The inward driving force is controlled by the plasma colloid osmotic pressure (25 mmHg).
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This question is part of the following fields:
- Basic Physics
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Question 39
Incorrect
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A 40-year old female comes to the GP's office with unexplained weight gain, cold intolerance and fatigue. Her thyroid function tests are performed as there is a suspicion of hypothyroidism. A negative feedback mechanism is incorporated in the control of thyroid hormone release. All of choices below are also controlled by a negative feedback loop except:
Your Answer: Blood sugar
Correct Answer: Clotting cascade
Explanation:The correct answer is the clotting cascade, which occurs via a positive feedback mechanism. As clotting factors are attracted to a site, their presence attracts further clotting factors. This continues until a functioning clot is formed.
This patient has presented with symptoms of hypothyroidism and symptoms include weight gain, lethargy, cold intolerance, dry skin, coarse hair and constipation. It can be treated by replacing the missing thyroid hormone with levothyroxine which is a synthetic version of thyroxine (T4).
Serum carbon dioxide (CO2) is controlled via a negative feedback mechanism as well. Chemoreceptors can detect when the serum CO2 is high, and send an impulse to the respiratory centre of the brain to increase the respiratory rate. As a result, more CO2 is exhaled which lowers the serum concentration.
Cortisol is also released according to a negative feedback mechanism. Cortisol acts on both the hypothalamus and the anterior pituitary. Its action serve to decrease the formation of corticotrophin releasing hormone (CRH) and adrenocorticotropic hormone (ACTH), respectively. CRH acts on the anterior pituitary to release ACTH. This then acts on the adrenal gland to cause the release of cortisol. Thus, inhibition of CRH and ACTH formation results in high levels of cortisol which inhibit its further release.
Blood pressure (BP) is controlled via a negative feedback mechanism. Low BP results in renin-angiotensin-aldosterone system (RAAS) activation. This leads to vasoconstriction and retention of salt and water which increased BP.
Blood sugar is controlled via a negative feedback mechanism. A rise in blood sugar causes insulin to be released. Insulin acts to transport glucose into the cell which lowers blood sugar. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 40
Incorrect
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With regards to the repolarisation phase of the myocardial action potential, which of the following is responsible?
Your Answer: Slow efflux of calcium
Correct Answer: Efflux of potassium
Explanation:Cardiac conduction
Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium
Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop
Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period
Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period
Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 41
Correct
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Anaesthetic awareness is most probable in general anaesthesia for which surgical operation?
Your Answer: Emergency surgery for major trauma
Explanation:Awareness during general anaesthesia is a frightening experience, which may result in serious emotional injury and post-traumatic stress disorder.
The incidence of awareness during general anaesthesia with current anaesthetic agents and techniques has been reported as 0.2-0.4% in nonobstetric and noncardiac surgery, as 0.4% during caesarean section, and as 1.5% in cardiac surgery.
The incidence during major trauma surgery is higher. Incidence of recall has been reported to be as high as 11-43% in major trauma cases.
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This question is part of the following fields:
- Physiology
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Question 42
Correct
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A mercury barometer can be used to determine absolute pressure. A mercury manometer can be used to check blood pressure. The SI units of length(mm) are used to measure pressure.
Why is pressure expressed in millimetres of mercury (mmHg)?Your Answer: Pressure is directly proportional to length of the mercury column and is variable
Explanation:A mercury barometer can be used to determine absolute pressure. A glass tube with one closed end serves as the barometer. The open end is inserted into a mercury-filled open vessel. The mercury in the container is pushed into the tube by atmospheric pressure exerted on its surface. Absolute pressure is the distance between the tube’s meniscus and the mercury surface.
Pressure is defined as force in newtons per unit area (F) (A).
Mass of mercury = area (A) × density (ρ) × length (L)
Pressure = ((A × ρ × L) × 9.8 m/s2)/A
Pressure = ρ × L x 9.8
Pressure is proportional to LThe numerator and denominator of the above equation, area (A), cancel out. The constants are density and the gravitational acceleration value.
The length is proportional to the applied pressure.
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This question is part of the following fields:
- Physiology
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Question 43
Incorrect
-
A 64-year old male has shortness of breath on exertion and presented to the cardiology clinic. He has a transthoracic echo performed to help in assessing the function of his heart.
How can this echo aid in calculating cardiac output?Your Answer: (stroke volume / end diastolic LV volume ) * 100%
Correct Answer: (end diastolic LV volume - end systolic LV volume) x heart rate
Explanation:Cardiac output = stroke volume x heart rate
Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%
Stroke volume = end diastolic LV volume – end systolic LV volume
Pulse pressure = Systolic Pressure – Diastolic Pressure
Systemic vascular resistance = mean arterial pressure / cardiac output
Factors that increase pulse pressure include:
-a less compliant aorta (this tends to occur with advancing age)
-increased stroke volume -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 44
Correct
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Which nerve is responsible for the direct innervation of the sinoatrial node?
Your Answer: None of the above
Explanation:The sinoatrial node receives innervation from multiple nerves arising from the complex cardiac plexus.
The cardiac plexus sends tiny branches into cardiac vessels, alongside the right and left coronary arteries.
The vagal efferent fibres originate from the vagal and accessory nerves in the brainstem, and then travel to the cardiac plexus within the heart. The resulting vagal discharge controls heart rate.
No singular nerve directly innervates the sinoatrial node.
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This question is part of the following fields:
- Anatomy
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Question 45
Incorrect
-
Prophylactic antibiotics are required for which of the following procedures?
Your Answer: Tonsillectomy
Correct Answer: Appendicectomy
Explanation:Correctly used, antibiotic prophylaxis can reduce
the total use of antibiotics.
There is strong scientific support that antibiotic
prophylaxis reduces the development of infection after:- Operations and endoscopic procedures in the large intestine,
the rectum, and the stomach (including appendectomies and
penetrating abdominal trauma), and after percutaneous endoscopic gastrostomy (PEG) - Cardiovascular surgery, and insertion of pacemakers
- Breast cancer surgery
- Hysterectomy
- Reduction of simple fractures and prosthetic limb surgery
- Complicated surgery for cancer in the ear, nose, and throat
regions - Transrectal biopsy and resection of the prostate (febrile urinary
tract infection and blood poisoning).
In most cases the scientific evidence is inadequate to determine
which type of antibiotic is most effective for antibiotic prophylaxis. - Operations and endoscopic procedures in the large intestine,
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 46
Incorrect
-
Which peripheral nerve of the foot is often utilized to evaluate for neuromuscular blockade?
Your Answer: Deep peroneal nerve (anterior tibial nerve)
Correct Answer: Posterior tibial nerve
Explanation:The posterior tibial nerve lies on the posterior surface of the tibialis posterior and, lower down the leg, on the posterior surface of the tibia. The nerve accompanies the posterior tibial artery and lies at first on its medial side, then crosses posterior to it, and finally lies on its lateral side. The nerve, with the artery, passes behind the medial malleolus, between the tendons of the flexor digitorum longus and the flexor hallucis longus.
It gives off muscular branches to the soleus, flexor digitorum longus, flexor hallucis longus, and tibialis posterior. A medial calcaneal branches off to supply the skin over the medial surface of the heel, and an articular nerve to supply the ankle joint. Finally, it terminates to become the medial and lateral plantar nerves.
The saphenous nerve is a branch of the femoral nerve that gives off branches that supply the skin on the posteromedial surface of the leg.
The sural nerve is a branch of the tibial nerve that supplies the skin on the lower part of the posterolateral surface of the leg.
The superficial peroneal nerve is one of the terminal branches of the common peroneal nerve. It arises in the substance of the peroneus longus muscle on the lateral side of the neck of the fibular. It ascends between the peroneus longus and brevis muscles, and in the lower part of the leg it becomes cutaneous. Muscular branches of the superficial peroneal nerve supply the peroneus longus and brevis muscles, while medial and lateral cutaneous branches are distributed to the skin on the lower part of the leg and dorsum of the foot. In addition, the cutaneous branches supply the dorsal surfaces of the skin of all the toes, except the adjacent sides of the first and second toes and the lateral side of the little toe.
The superficial peroneal, sural and saphenous nerves cannot be used to assess neuromuscular blocks since they are sensory nerves.
The deep peroneal nerve enters the dorsum of the foot by passing deep to the extensor retinacula on the lateral side of the dorsalis pedis artery. It divides into terminal, medial, and lateral branches. The medial branch supplies the skin of the adjacent sides of the big and second toes. The lateral branch supplies the extensor digitorum brevis muscle. Both terminal branches give articular branches to the joints of the foot. This nerve is too deep to use for neuromuscular blockade assessment
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This question is part of the following fields:
- Anatomy
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Question 47
Incorrect
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What vessel is NOT considered a major branch of the descending thoracic aorta?
Your Answer: Oesophageal artery
Correct Answer: Inferior thyroid artery
Explanation:The descending thoracic aorta begins at the lower border of T4 near the midline as a continuation of the arch of the aorta. It descends and ends at the level of T12 at the aortic hiatus in the diaphragm, where it becomes the abdominal aorta.
The aorta gives off the following branches: (descending order)
1. Bronchial arteries
2. Mediastinal arteries
3. Oesophageal arteries
4. Pericardial arteries
5. Superior phrenic arteriesThe posterior intercostal arteries are branches that originate throughout the length of the posterior aspect of the descending thoracic aorta.
The inferior thyroid artery is usually derived from the thyrocervical trunk, a branch of the subclavian artery.
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This question is part of the following fields:
- Anatomy
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Question 48
Incorrect
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One of the causes of increased pulse pressure is when the aorta becomes less compliant because of age-related changes. Another cause of increased pulse pressure is which of the following?
Your Answer:
Correct Answer: Increased stroke volume
Explanation:Impaired ventricular relaxation reduces diastolic filling and therefore preload.
Decreased blood volume decreases preload due to reduced venous return.
Heart failure is characterized by reduced ejection fraction and therefore stroke volume.
Cardiac output = stroke volume x heart rate
Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%
Stroke volume = end diastolic LV volume – end systolic LV volume
Pulse pressure (is increased by stroke volume) = Systolic Pressure – Diastolic Pressure
Systemic vascular resistance = mean arterial pressure / cardiac output
Factors that increase pulse pressure include:
-a less compliant aorta (this tends to occur with advancing age)
-increased stroke volume
Aortic stenosis would decrease stroke volume as end systolic volume would increase.
This is because of an increase in afterload, an increase in resistance that the heart must pump against due to a hard stenotic valve. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 49
Incorrect
-
A 25-year old man needs an emergency appendicectomy and has gone to the operating room. During general anaesthesia, ventilation is achieved using a circle system with a fresh gas flow (FGF) of 1L/min, with and air/oxygen and sevoflurane combination. The capnograph trace is normal.
Changes to the end tidal and baseline CO2 measurements at 10 and 20 mins respectively are seen on the capnograph below:
10 minutes 20 minutes
End-tidal CO2 4.9 kPa 8.4 kPa
Baseline end-tidal CO2 0.2 kPa 2.4 kPa
The other vitals were as follows:
Pulse 100-105 beats per minute
Systolic blood pressure 120-133 mmHg
O2 saturation 99%.
The next most important immediate step is which of the following?Your Answer:
Correct Answer: Increase the FGF
Explanation:This scenario describes rebreathing management.
Changes is exhaustion of the soda lime and a progressive rise in circuit deadspace is the most likely explanation for the capnograph.
It is important that the soda lime canister is inspected for a change in colour of the granules. Initially fresh gas flow should be increased and then if necessary, replace the soda lime granules. Other strategies include changing to another circuit or bypassing the soda lime canister after the fresh gas flow is increased.
Any other causes of increased equipment deadspace should be excluded.
Intraoperative hypercarbia can be caused by:
1. Hypoventilation – Breathing spontaneously; drugs which include anaesthetic agents, opioids, residual neuromuscular blockade, pre-existing respiratory or neuromuscular disease and cerebrovascular accident.
2. Controlled ventilation- circuit leaks, disconnection, miscalculation of patient’s minute volume.
3. Rebreathing – Soda lime exhaustion with circle, inadequate fresh gas flow into Mapleson circuits, increased breathing system deadspace.
4. Endogenous source – Tourniquet release, hypermetabolic states (MH or thyroid storm) and release of vascular clamps.
5. Exogenous source – Absorption of CO2 absorption from the pneumoperitoneum. -
This question is part of the following fields:
- Physiology
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Question 50
Incorrect
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A patient is evaluated for persistent dysphonia six months after undergoing a subtotal thyroidectomy.
Which of the following is the most likely reason for the change in this patient's voice?Your Answer:
Correct Answer: Damage to recurrent laryngeal nerve
Explanation:After thyroid surgery, about 10-15% of patients experience a temporary subjective voice change of varying degrees. A frog in the throat or cracking of the voice, or a weak voice, are common descriptions. These modifications are only temporary, lasting a few days to a few weeks.
Swelling of the muscles in the area of the dissection, as well as inflammation and oedema of the larynx due to the dissection, or minor trauma from the tracheal tube, are all suspected causes.
On both sides of the thyroid gland, the superior laryngeal nerve (EBSLN) runs along the upper part. The muscles that fine-tune the vocal cords are innervated by these nerves. The quality of their voice is usually normal if they are injured, but making high-pitched sounds may be difficult. Injury to the EBSLN occurs in about 2% of the population.
Injuries to the recurrent laryngeal nerve (RLN) have been reported to occur in 1 percent to 14 percent of people. Except for the cricothyroid muscle, the RLN supplies all of the laryngeal intrinsic muscles.
This complication is usually unilateral and temporary, but it can also be bilateral and permanent, and it can be intentional or unintentional. The most common complication following thyroid surgery is a permanent lesion of damaged RLN, which manifests as an irreversible phonation dysfunction.
The crico-arytenoid joint dislocation is a relatively uncommon complication of tracheal intubation and blunt neck trauma. The probability is less than one in a thousand.
Vocal cord polyps affect 0.8 percent of people.
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This question is part of the following fields:
- Pathophysiology
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Question 51
Incorrect
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Which of the following can be evaluated by the Delphi method?
Your Answer:
Correct Answer: Expert consensus
Explanation:The Delphi method relies on expert consensus. This method kicks off with an open ended questionnaire and uses its responses as a survey instrument for the next round in which each of the participants is asked to rate the items that the investigators have summarized on the basis of the data collected in the first round. Any disagreement is further discussed in phases to come on the basis of information obtained from previous phases.
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This question is part of the following fields:
- Statistical Methods
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Question 52
Incorrect
-
A sevoflurane vaporiser with a 2 percent setting and a 200 kPa ambient pressure is used.
At this pressure, which of the following options best represents vaporiser output?Your Answer:
Correct Answer: The output is 1% because the saturated pressure of sevoflurane is unaffected by ambient pressure
Explanation:Ambient pressure has no effect on a volatile agent’s saturated vapour pressure (SVP). At a temperature of 20°C, the SVP of sevoflurane is approximately 21 kPa, or 21% of atmospheric pressure (100 kPa).
The SVP of sevoflurane remains the same when the ambient pressure is doubled to 200 kPa, but the output of the vaporiser is halved, now 21 percent of 200 kPa, equalling 10.5 percent. The vaporiser’s output has increased to 1%, but the partial pressure output has remained unchanged. The splitting ratio will not change because it is determined by temperature changes.
Calculations can be made as follows:
Vaporizer output % (ambient pressure) = % volatile (calibrated) x 100 kPa calibrated pressure/ambient pressure
2% = 2% (dialled) × 100/100
2% of 100 = 2 kPaAltitude, pressure 50 kPa
4% = 2% (dialled) × 100/50
4% of 50 = 2 kPaHigh pressure at 200 kPa
1% = 2% (dialled) × 100/200
1% of 200 = 2 kPaSevoflurane has a boiling point of 58°C and, unlike desflurane (which has a boiling point of 22.8°C), does not need to be heated and pressurised with a Tec 6 vaporiser.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 53
Incorrect
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Cells use adenosine-5-triphosphate (ATP) as a coenzyme and is a source of energy.
Glucose metabolism produces the most ATP from which of the following biochemical processes?
Your Answer:
Correct Answer: Electron transport phosphorylation in the mitochondria
Explanation:Glycolysis occurs in the cytoplasm of the cell. It converts 1 glucose molecule (6-carbon) to pyruvate (two 3-carbon molecules) and produces 4 ATP molecules and 2NADH but uses 2 ATP in the process with an overall net energy production of 2 ATP.
Pyruvate is then oxidised to acetyl coenzyme A (generating 2 NADH per pyruvate molecule). This takes place in the mitochondria and then enters the Krebs cycle (citric acid cycle). It produces 2 ATP, 8 NADH and 2 FADH2 per glucose molecule.
Electron transport phosphorylation takes place in the mitochondria. The aim of this process is to break down NADH and FADH2 and also to pump H+ into the outer compartment of the mitochondria. It produces 32 ATP with an overall net production of 36ATP.
In anaerobic respiration which occurs in the cytoplasm, pyruvate is reduced to NAD producing 2 ATP.
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This question is part of the following fields:
- Physiology
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Question 54
Incorrect
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The following results were obtained In a new drug trial:
Improved Not improved
Placebo group 36 26
Treatment group 44 16
Regarding the statistical analysis or interpretation of the trial, One of these is trueYour Answer:
Correct Answer: The data could be evaluated using the chi square test
Explanation:This data is in a 2 × 2 contingency table so a chi square test can be used. There is a special chi squared formula that gives a value that can be looked up in a table giving the p value.
Since we are comparing proportions not means, the Student’s t test CANNOT be used.
There is no linear regression to plot so Pearson’s co-efficient cannot be calculated.
Nothing is so obvious that no statistical analysis is needed.
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This question is part of the following fields:
- Statistical Methods
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Question 55
Incorrect
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Which of the following statement is true regarding the mechanism of action of rifampicin?
Your Answer:
Correct Answer: Inhibit RNA synthesis
Explanation:Rifampicin is a derivative of a rifamycin (other derivatives are rifabutin and rifapentine). It is bactericidal against both dividing and non-dividing mycobacterium and acts by inhibiting DNA-dependent RNA polymerase. Thus this drug inhibits RNA synthesis.
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This question is part of the following fields:
- Pharmacology
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Question 56
Incorrect
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You are given an intravenous induction agent. The following are its characteristics:
A racemic mixture of cyclohexanone rings with one chiral centre
Local anaesthetic properties.
Which of the following statements about its primary mechanism of action is most accurate?Your Answer:
Correct Answer: Non-competitive antagonist affecting Ca2+ channels
Explanation:Ketamine is the substance in question. Its structure and pharmacodynamic effects make it a one-of-a-kind intravenous induction agent. The molecule is made up of two cyclohexanone rings (2-(O-chlorophenyl)-2-methylamino cyclohexanone and 2-(O-chlorophenyl)-2-methylamino cyclohexanone). Ketamine has local anaesthetic properties and acts primarily on the brain and spinal cord.
It affects Ca2+ channels as a non-competitive antagonist for the N-D-methyl-aspartate (NMDA) receptor. It also acts as a local anaesthetic by interfering with neuronal Na+ channels.
Ketamine causes profound dissociative anaesthesia (profound amnesia and analgesia) as well as sedation.
Phenoxybenzamine, an alpha-1 adrenoreceptor antagonist, is an example of an irreversible competitive antagonist. It forms a covalent bond with the calcium influx receptor.
Benzodiazepines are GABAA receptor agonists that affect chloride influx.
Flumazenil is an inverse agonist that affects GABAA receptor chloride influx.
Ketamine is a cyclohexanone derivative that acts as a non-competitive Ca2+ channel antagonist.
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This question is part of the following fields:
- Pharmacology
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Question 57
Incorrect
-
Among the following, which statement is true regarding electrical safety in an operation theatre?
Your Answer:
Correct Answer: The higher the frequency of the current the less risk to the patient
Explanation:The operating theatre is an unusual place with several applications of electrical equipment to the human body. This can lead to potential dangers associated with it that need to be prevented. Electrical safety in the operation theatre is the understanding of how these potential dangers can occur and how they can be prevented.
Electricity can cause morbidity or mortality by one of the following ways:
(i) electrocution
(ii) burns
(iii) ignition of a flammable material, causing a fire or explosion.Electrocution is dependant on factors like duration of contact with electric current, the current pathway and the frequency and size of current.
Option A: The higher the frequency, the less effects of electrocution on the body.
Option B & D: Equipment can be classified in classes and types.
The class designation describes the method used for protection against electrocution. Class I is basic protection, class II is double insulation and class III is safety extra low voltage.
The type designation describes the degree of protection based on the maximum permissible leakage currents under normal and fault conditions.
Type B:
can be class I, II or III but the maximum leakage current must not exceed 100 µA. It is therefore not suitable for direct connection to the heart.
Type BF
Similar to type B, but uses an isolated (or floating) circuit.
Type CF
Only type CF protect against microshock as they allow leakage currents of 0.05 mA per electrode for class I and 0.01 mA for class II. Microshock is a small leakage current that can cause harm because of direct connection to the heart via transvenous lines or wires, bypassing the impedance of the skin, leading to ventricular fibrillation. Microshock current of 100 ?A is sufficient to cause VF.Option C: A 75mA electrocution can cause ventricular fibrillation. Use the following as a general guide to understand the effect of current size on the body.
1 mA – tingling pain
5 mA – pain
15 mA – tonic muscular contraction
50 mA – respiratory muscle paralysis
75 mA – ventricular fibrillation.Option E: Wet skin reduces the resistance to current flow and therefore increases the effects of electrocution.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 58
Incorrect
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The main site of storage of thyroid hormones in the thyroid gland is?
Your Answer:
Correct Answer: Thyroglobulin
Explanation:The follicle is the functional unit of the thyroid gland. The follicular cells surround the follicle which is filled with colloid. Suspended within the colloid is the is a pro-hormone complex thyroglobulin.
The synthesis and storage of thyroid hormones is done by follicular cells and the thyroglobulin within the colloid.
Iodide ions (I−) are actively transported against a concentration gradient into the follicular cell under the influence of thyroid stimulating hormone (TSH). It then undergoes oxidation to active iodine catalysed by thyroid peroxidase (TPO). The synthesis of thyroglobulin is in the follicular cells and it contains up to 140 tyrosine residues. The tyrosine residues of thyroglobulin and active iodine are merged to form mono- and di-iodotyrosines (MIT and DIT). The iodinated thyroglobulin is then taken up into the colloid where it is stored and dimerised. Two DIT molecules are joined to produce thyroxine (T4) while one MIT and one DIT molecule are joined to produce tri-iodotyrosine (T3) by a process catalysed by TPO.
Thyroglobulin droplets are taken up as vesicles into follicular cells by pinocytosis. This process is stimulated by TSH. When these vesicles fuse with lysosomes, hydrolysis of the thyroglobulin molecules and subsequent release of T4 and T3 into the circulation occurs.
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This question is part of the following fields:
- Pathophysiology
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Question 59
Incorrect
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All of the following are part of the endocrine response to uncontrolled bleeding except:
Your Answer:
Correct Answer: Increased secretion of insulin
Explanation:With regards to compensatory response to blood loss, the following sequence of events take place:
1. Decrease in venous return, right atrial pressure and cardiac output
2. Baroreceptor reflexes (carotid sinus and aortic arch) are immediately activated
3. There is decreased afferent input to the cardiovascular centre in medulla. This inhibits parasympathetic reflexes and increases sympathetic response
4. This results in an increased cardiac output and increased SVR by direct sympathetic stimulation. There is increased circulating catecholamines and local tissue mediators (adenosine, potassium, NO2)
5. Fluid moves into the intravascular space as a result of decreased capillary hydrostatic pressure absorbing interstitial fluid.A slower response is mounted by the hypothalamus-pituitary-adrenal axis.
6. Reduced renal blood flow is sensed by the intra renal baroreceptors and this stimulates release of renin by the juxta-glomerular apparatus.
7. There is cleavage of circulating Angiotensinogen to Angiotensin I, which is converted to Angiotensin II in the lungs (by Angiotensin Converting Enzyme ACE)Angiotensin II is a powerful vasoconstrictor that sets off other endocrine pathways.
8. The adrenal cortex releases Aldosterone
9. There is antidiuretic hormone release from posterior pituitary (also in response to hypovolaemia being sensed by atrial stretch receptors)
10. This leads to sodium and water retention in the distal convoluted renal tubule to conserve fluid
Fluid conservation is also aided by an increased amount of cortisol which is secreted in response to the increase in circulating catecholamines and sympathetic stimulation. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 60
Incorrect
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A 77-year-old man, is scheduled for an angiogram to investigate gastro-intestinal bleeding. The radiologist performing the angiogram inserts the catheter into the coeliac axis.
What level of the vertebrae does the coeliac axis normally arise from the aorta?Your Answer:
Correct Answer: T12
Explanation:The coeliac axis refers to one of the splanchnic arteries located within the abdomen.
It arises from the aorta almost horizontally at the level of the T12 vertebrae
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This question is part of the following fields:
- Anatomy
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Question 61
Incorrect
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An 85-year old female is being investigated and treated for pancytopenia of unknown origin. Her most recent blood test is shown below which shows that he has a low platelet count.
Hb-102 g/l
WBC - 2.9* 109/l
Platelets - 7 * 109/l
Which of the following normally stimulates platelet production?
Your Answer:
Correct Answer: Thrombopoietin
Explanation:Interleukin-4 is a cytokine which acts to regulate the responses of B and T cells.
Erythropoietin is responsible for the signal that initiated red blood cell production.
Granulocyte-colony stimulating factor stimulates the bone marrow to produce granulocytes.
Interleukin-5 is a cytokine that stimulates the proliferation and activation of eosinophils.
Thrombopoietin is the primary signal responsible for megakaryocyte and thus platelet production.
Platelets are also called thrombocytes. They, like red blood cells, are also derived from myeloid stem cells. The process involves a megakaryocyte developing from a common myeloid progenitor cell. A megakaryocyte is a large cell with a multilobulated nucleus, this grows to become massive where it will then break up to form platelets.Immune cells are generated from haematopoietic stem cells in bone marrow. They generate two main types of progenitors, myeloid and lymphoid progenitor cells, from which all immune cells are derived.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 62
Incorrect
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All of the following statements are false regarding tetracyclines except:
Your Answer:
Correct Answer:
Explanation:Tetracyclines inhibit protein synthesis through reversible binding to bacterial 30s ribosomal subunits (not 50s) which prevent binding of new incoming amino acids (aminoacyl-tRNA) and thus interfere with peptide growth.
They penetrate macrophages and are thus a drug of choice for treating infections due to intracellular organisms.
Tetracycline does not inhibit transpeptidation. Meanwhile, it is chloramphenicol which is responsible for inhibiting transpeptidation.
Tetracycline can get deposited in growing bone and teeth due to its calcium-binding effect and thus causes dental discoloration and dental hypoplasia. Due to this reason, they should be avoided in pregnant or lactating mothers.
Simultaneous administration of aluminium hydroxide can impede the absorption of tetracyclines.
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This question is part of the following fields:
- Pharmacology
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Question 63
Incorrect
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What part of the male urethra is completely surrounded by Bucks fascia?
Your Answer:
Correct Answer: Spongiosa part
Explanation:Bucks fascia refers to the layer of loose connective tissue, nerves and blood vessels that encapsulates the penile erectile bodies, the corpa cavernosa and the anterior part of the urethra, including the entirety of the spongiose part of the urethra.
It runs with the external spermatic fascia and the penile suspensory ligament.
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This question is part of the following fields:
- Anatomy
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Question 64
Incorrect
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A normal woman at term, not in labour, has her arterial blood gas analysed.
Which set of results is most likely her own?
Option - pH - PaCO2 - HCO3 - PaO2
A - 7.35 - 28 mmHg (3.73 kPa) - 27 mmol/L - 104 mmHg (13.8kPa)
B - 7.43 - 32 mmHg (4.27 kPa) - 21 mmol/L - 104 mmHg (13.8kPa)
C - 7.44 - 36 mmHg (4.8 kPa) - 27 mmol/L - 104 mmHg (13.8kPa)
D - 7.45 - 40 mmHg (5.33 kPa) - 21 mmol/L - 104 mmHg (13.8kPa)
E - 7.46 - 44 mmHg (5.87kPa) - 21 mmol/L - 104 mmHg (13.8kPa)Your Answer:
Correct Answer: B
Explanation:Due to an increased tidal volume with little change or slight increase in respiratory rate, Minute ventilation at term is increased by about 50%. Hypothalamic function are thought to influence by Progesterone, oestradiol and prostaglandins. This causes a mild compensated respiratory alkalosis.
Maternal PaCO2 is usually decreased to about 32 mmHg (4.27 kPa) as a result of this increased alveolar ventilation at term . A compensatory decrease in serum bicarbonate from 27 to 21 mmol/L by renal excretion lessens the impact of maternal alkalosis.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 65
Incorrect
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A 33-year old man was referred to you because of difficulty moving his limbs.
History revealed that he was placed under anaesthesia for a major surgery 12 hours prior to the referral. Other symptoms were noted such as anxiousness, agitation, and fever of 38°C. Upon physical examination, he was tachycardic at 119 beats per minute. Moreover, his medical history showed that he was on Fluoxetine for clinical depression.
The nurses reported that, because of his frequent complaints of axillary pain, he was given tramadol with paracetamol.
Which of the following is responsible for his clinical features?Your Answer:
Correct Answer: Tramadol
Explanation:Tramadol is weak agonist at the mu receptor. It inhibits the neuronal reuptake of serotonin and norepinephrine, and inhibits pain neurotransmission. It is given for moderate pain, chronic pain syndromes, and neuropathic pain.
Fluoxetine is a selective serotonin reuptake inhibitor (SSRI). It inhibits the neuronal reuptake of serotonin by inhibiting the serotonin transporter (SERT). It is the drug of choice for major depressive disorder, and is given for other psychiatric disorders such as anxiety, obsessive-compulsive, post-traumatic stress, and phobias.
When tramadol is given with SSRIs, serotonin syndrome may occur. Serotonin syndrome is characterized by fever, agitation, tremors, clonus, hyperreflexia and diaphoresis. The onset of symptoms may occur within a few hours, and the first-line treatment is sedation, paralysis, intubation and ventilation.
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This question is part of the following fields:
- Pharmacology
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Question 66
Incorrect
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Regarding the plateau phase of the cardiac potential, which electrolyte is the main determinant?
Your Answer:
Correct Answer: Ca2+
Explanation:The cardiac action potential has several phases which have different mechanisms of action as seen below:
Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
These channels automatically deactivate after a few msPhase 1: caused by early repolarisation and an efflux of potassium.
Phase 2: Plateau – caused by a slow influx of calcium.
Phase 3 – Final repolarisation – caused by an efflux of potassium.
Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potentialOf note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.
Different sites have different conduction velocities:
1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec2. AV node conduction – 0.05 m/sec
3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles
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This question is part of the following fields:
- Physiology
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Question 67
Incorrect
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The passage of glucose into the brain is facilitated by which transport method?
Your Answer:
Correct Answer: Facilitated diffusion
Explanation:Glucose transport is a highly regulated process accomplished mostly by facilitated diffusion using carrier proteins to cross cell membranes.
There are many transporters, but the most important are known as glucose transporters (GLUTs).
Stresses in various form of acute and chronic forms affect the activity of glucose transporters.
They are responsive to many types of metabolic stress, including hypoxia, injury, hypoglycaemia, numerous metabolic inhibitors, stress hormones, and other influences such as growth factors.Numerous signalling pathways appear to be involved in transporter regulation.
New evidence suggests that stresses regulating GLUTs are not only acute biological stresses. In addition, chronic low-grade inflammation, and their associated chronic diseases also lead to altered glucose transport. These include obesity, type 2 diabetes, cardiovascular disease, and the growth and spread of many tumours that are affected by altered glucose transporters. Some of these glucose transport effects are compensatory, while others are pathogenic.
Ultimately, deliberate manipulation of GLUTs could be used as treatment for some of these chronic diseases.
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This question is part of the following fields:
- Physiology
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Question 68
Incorrect
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You've been summoned to the recovery room to examine a 28-year-old man who has had an inguinal hernia repaired.
His vital signs are normal, but you notice that he has developed abnormal upper-limb movements due to muscle contractions that cause repetitive twisting movements.
What do you think is the most likely source for this patient's condition?Your Answer:
Correct Answer: Prochlorperazine
Explanation:Dystonia is characterised by repetitive twisting movements or abnormal postures. They are classified as either primary or secondary.
Primary dystonia is a genetic disorder that is inherited in an autosomal dominant pattern.
Secondary dystonia can be caused by focal brain lesions, Parkinson’s disease, or certain medications.The following drugs cause the most common drug-induced dystonic reactions:
Antipsychotics, antiemetics (especially prochlorperazine and metoclopramide), and antidepressants.Following the administration of the neuroleptic prochlorperazine, 16 percent of patients experience restlessness (akathisia) and 4% experience dystonia.
Several published reports have linked the anaesthetics thiopentone, fentanyl, and propofol to opisthotonos and other abnormal neurologic sequelae. Dystonias following a general anaesthetic are uncommon. Tramadol has been linked to serotonin syndrome, while remifentanil has been linked to muscle rigidity.
The following are some of the risk factors:
Positive family history
Male
Children
An episode of acute dystonia occurred previously.
Dopamine receptor (D2) antagonists at high doses and recent cocaine useDystonia is treated in a variety of ways, including:
Benztropine (as a first-line therapy):
1-2 mg intravenous injection for adults
Child: 0.02 mg/kg to 1 mg maximumBenzodiazepines are a type of benzodiazepine (second line treatment).
Midazolam:
1-2 mg intravenously, or 5-10 mg IV/PO diazepam
Antihistamines with anticholinergic activity (H1receptor antagonists):
Promethazine 25-50 mg IV/IM, or diphenhydramine 50 mg IV/IM (1 mg/kg in children) are used when benztropine is not available.
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This question is part of the following fields:
- Pharmacology
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Question 69
Incorrect
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A 70-year-old man presents with bilateral buttock claudication that spreads down the thigh and erectile dysfunction in a vascular clinic.
The left femoral pulse is not palpable on examination, and the right is weakly palpable. Leriche syndrome is diagnosed as the blood flow at the abdominal aortic bifurcation is blocked due to atherosclerosis. He is prepared for aortoiliac bypass surgery.
Which vertebral level will you find the affected artery that requires bypassing?Your Answer:
Correct Answer: L4
Explanation:The bifurcation of the abdominal aorta into common iliac arteries occurs at the level of L4. The bifurcation is a common site for atherosclerotic plaques as it is an area of high turbulence.
Leriche Syndrome is an aortoiliac occlusive disease and affects the distal abdominal aorta, iliac arteries, and femoropopliteal vessels. It has a triad of symptoms:
1. Claudication (cramping lower extremities pain that is reproducible by exercise)
2. Impotence (reduced penile arterial flow)
3. Absent/weak femoral pulses (hallmark)T12 – aorta enters the diaphragm with the thoracic duct and azygous veins
L2 – testicular or ovarian arteries branch off the aorta
L3 – inferior mesenteric artery
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This question is part of the following fields:
- Anatomy
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Question 70
Incorrect
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An otherwise fit 7-year-old boy for an elective tonsillectomy is seen holding a bottle of sugared orange squash at anaesthetic assessment . He appears to have consumed 120 mL of the bottle's contents.
What is the minimal safe fasting time prior to proceeding with a general anaesthetic in this patient?Your Answer:
Correct Answer: 1 hour
Explanation: -
This question is part of the following fields:
- Pathophysiology
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Question 71
Incorrect
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With a cervical dilation of 9 cm, a 23-year-old term primigravida is in labour. She is otherwise in good health. She's been in labour for 14 hours and counting.
Early foetal pulse decelerations can be seen on the cardiotocograph, and a recent foetal scalp blood sample revealed a pH of 7.25.
Which of the following is true about this patient's care and management?Your Answer:
Correct Answer: Monitor for downward trend in fetal scalp blood pH as caesarean section is not indicated at the present time
Explanation:Once the decision to deliver a baby by caesarean section has been made, it should be carried out with a level of urgency commensurate with the risk to the baby and the mother’s safety.
There are four types of caesarean section urgency:
Category 1 – Endangering the life of the mother or the foetus
Category 2 – Maternal or foetal compromise that is not immediately life threatening
Category 3 – Early delivery is required, but there is no risk to the mother or the foetus.
Category 4: Elective delivery at a time that is convenient for both the mother and the maternity staff.Caesarean sections for categories 1 and 2 should be performed as soon as possible after the decision is made, especially for category 1. For category 1 caesarean sections, a decision to deliver time of 30 minutes is currently used.
In most cases, Category 2 caesarean sections should be performed within 75 minutes of making the decision.
The condition of the woman and the unborn baby should be considered when making a decision for a quick delivery, as it may be harmful in some cases.
There is no evidence of foetal compromise in the example above (early foetal pulse decelerations and a pH of less than 7.25). Early foetal pulse decelerations are most likely caused by the uterus compressing the foetal head. The foetus is not harmed by these. A spinal anaesthetic is preferred over a general anaesthetic whenever possible.
If the foetal scalp blood pH is greater than 7.25, it’s a good idea to repeat the test later and look for any changes. When a foetus decelerates, the mother should be given oxygen, kept in a left lateral position, and kept hydrated to avoid the need for a caesarean section.
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This question is part of the following fields:
- Pathophysiology
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Question 72
Incorrect
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Which of the given statements is true about standard error of the mean?
Your Answer:
Correct Answer: Gets smaller as the sample size increases
Explanation:The standard error of the mean (SEM) is a measure of the spread expected for the mean of the observations – i.e. how ‘accurate’ the calculated sample mean is from the true population mean. The relationship between the standard error of the mean and the standard deviation is such that, for a given sample size, the standard error of the mean equals the standard deviation divided by the square root of the sample size.
SEM = SD / square root (n)
where SD = standard deviation and n = sample size
Therefore, the SEM gets smaller as the sample size (n) increases.
If we want to depict how widely scattered some measurements are, we use the standard deviation. For indicating the uncertainty around the estimate of the mean, we use the standard error of the mean. The standard error is most useful as a means of calculating a confidence interval. For a large sample, a 95% confidence interval is obtained as the values 1.96×SE either side of the mean.
A 95% confidence interval:
lower limit = mean – (1.96 * SEM)
upper limit = mean + (1.96 * SEM)
Results such as mean value are often presented along with a confidence interval. For example, in a study the mean height in a sample taken from a population is 183cm. You know that the standard error (SE) (the standard deviation of the mean) is 2cm. This gives a 95% confidence interval of 179-187cm (+/- 2 SE).
Hence, it would be wrong to say that confidence levels do not apply to standard error of the mean.
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This question is part of the following fields:
- Statistical Methods
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Question 73
Incorrect
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A 45-year-old woman complains of pain in her upper abdomen to her physician. The pain comes intermittently in waves and gets worse after eating food. There are no associated complaints of fever or bowel problems.
The pain intensity is 6/10, and paracetamol relieves it a little. There is suspicion that part of the biliary tree is blocked.
Which area of the duodenum does this blocked tube open into?Your Answer:
Correct Answer: 2nd part of the duodenum
Explanation:The patient is likely suffering from biliary colic since her pain is intermittent and comes and goes in waves. Biliary colic pain gets worse after eating, especially fatty food as bile helps digest fats. Gallstones are the most common cause of biliary colic and are usually located in the cystic duct or common bile duct. But since this patient has no signs of jaundice or steatorrhea, the duct most likely blocked is the cystic duct.
The cystic duct drains the gallbladder and combines with the common hepatic duct to form the common bile duct. The common bile duct then merges with the pancreatic duct and opens into the second part of the duodenum (major duodenal papilla).
The duodenojejunal flexure is attached to the diaphragm by the ligament of Treitz and is not associated with any common pathology.
The fourth part of the duodenum passes very close to the abdominal aorta and can be compressed by an abdominal aortic aneurysm.
The third part of the duodenum can be affected by superior mesenteric artery syndrome, where the duodenum is compressed between the SMA and the aorta, often in cases of reduced body fat.
The first part of the duodenum is the most common location for peptic ulcers affecting this organ. -
This question is part of the following fields:
- Anatomy
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Question 74
Incorrect
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Which among the given choices can be used to describe a persistent and expected level of disease in a particular population?
Your Answer:
Correct Answer: Endemic
Explanation:Phase 0 trials assist the scientists in studying the behaviour of drugs in humans by micro dosing patients. They are used to speed up the developmental process. They have no measurable therapeutic effect and efficiency.
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This question is part of the following fields:
- Statistical Methods
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Question 75
Incorrect
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Substitution at different positions of the barbituric ring give rise to different pharmacologic properties.
Substitution with and at which specific site of the ring affects lipid solubility the most?Your Answer:
Correct Answer: Sulphur atom at position 2
Explanation:Barbiturates are derived from barbituric acid, which itself is nondepressant, but appropriate side-chain substitutions result in CNS depressant activity that varies in potency and duration with carbon chain length, branching, and saturation.
Oxybarbiturates retain an oxygen atom on number 2-carbon atom of the barbituric acid ring.
Thiobarbiturates replace this oxygen atom with a sulphur atom, which confers greater lipid solubility. Generally speaking, a substitution such as sulphuration that increases lipid solubility is associated with greater hypnotic potency and more rapid onset, but shorter duration of action.
Addition of a methyl group to the nitrogen atom of the barbituric acid ring, as with oxybarbiturate methohexital, also results in a compound with a short duration of action.
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This question is part of the following fields:
- Pharmacology
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Question 76
Incorrect
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In a normal healthy adult breathing 100 percent oxygen, which of the following is the most likely cause of an alveolar-arterial (A-a) oxygen difference of 30 kPa?
Your Answer:
Correct Answer: Atelectasis
Explanation:The ‘ideal’ alveolar PO2 minus arterial PO2 is the alveolar-arterial (A-a) oxygen difference.
The ‘ideal’ alveolar PO2 is derived from the alveolar air equation and is the PO2 that the lung would have if there was no ventilation-perfusion (V/Q) inequality and it was exchanging gas at the same respiratory exchange ratio as real lung.
The amount of oxygen in the blood is measured directly in the arteries.
The A-a oxygen difference (or gradient) is a useful measure of shunt and V/Q mismatch, and it is less than 2 kPa in normal adults breathing air (15 mmHg). Because the shunt component is not corrected, the A-a difference increases when breathing 100 percent oxygen, and it can be up to 15 kPa (115 mmHg).
An abnormally low or abnormally high V/Q ratio within the lung can cause an increased A-a difference, though the former is more common. Atelectasis, which results in a low V/Q ratio, is the most likely cause of an A-a difference in a healthy adult breathing 100 percent oxygen.
Hypoventilation may cause an increase in alveolar (and thus arterial) CO2, lowering alveolar PO2 according to the alveolar air equation.
The alveolar PO2 is also reduced at high altitude.
Healthy people are unlikely to have a right-to-left shunt or an oxygen transport diffusion defect.
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This question is part of the following fields:
- Physiology
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Question 77
Incorrect
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Which of the following drugs would cause the most clinical concern if accidentally administered intravenously to a 4-year-old boy?
Your Answer:
Correct Answer: 20 mg codeine
Explanation:To begin, one must determine the child’s approximate weight. There are a variety of formulas to choose from. It is acceptable to use the advanced paediatric life support formula:
(age + 4) 2 = weight
A 5-year-old child will weigh around 18 kilogrammes.
The following are the appropriate doses of the drugs listed above:
Gentamicin (once daily) – 5-7 mg/kg = 90-126 mg and subsequent dose modified according to plasma levels
Ondansetron – 0.1 mg/kg, but a maximum of 4 mg as a single dose = 1.8 mg
Codeine should be administered orally at a dose of 1 mg/kg rather than intravenously, as the latter can cause ‘dangerous’ hypotension due to histamine release.
15 mg/kg paracetamol = 270 mg orally or intravenously (a loading dose of 20 mg/kg, or 360 mg, is sometimes recommended, which is not far short of the doses listed above).
Cefuroxime – the initial intravenous dose is 20 mg/kg (360 mg) depending on the indication (again, similar to the dose given in the answer options above). -
This question is part of the following fields:
- Pharmacology
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Question 78
Incorrect
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What makes the ultrasound nebulizer efficient?
Your Answer:
Correct Answer: Reduction in gas flow resistance
Explanation:Smallest drops reach not only the upper but also the lower respiratory tracks. As a result, the ultrasonic nebulizer is most efficient for the therapy of pulmonary diseases and stands out as a robust and reliable support within the clinical setting.
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This question is part of the following fields:
- Basic Physics
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Question 79
Incorrect
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A 40 year old female is planned for an critical appendicectomy. A rapid sequence induction is organised. The patient has had a preoperative respiratory tract evaluation and there are no adverse features. The patient is optimally positioned and preoxygenated. The anaesthetic assistant applies 10 N of cricoid pressure. Induction of anaesthesia is then carried out with 250 mg thiopentone and 100 mg suxamethonium with 30 N of cricoid pressure. Initial laryngoscopy reveals a grade 4 view. Three attempts are made at placing a size 7 mm ID tracheal tube two with a standard laryngoscope and one with a McCoy blade and bougie and one further attempt is made using a videolaryngoscope. At this point the suxamethonium is begins to "wear off". Oxygen saturation is 95%. Which one of the following options is the next most appropriate plan of action?
Your Answer:
Correct Answer: Maintain oxygenation and anaesthesia and declare a failed intubation
Explanation:Always call for help early. This patient is at risk of gastro-oesophageal reflux, which is why a rapid sequence induction has been chosen. The patient is not pregnant, and the surgery is not urgent.
Plan A is to perform a rapid sequence induction under optimal conditions and secure the airway with a tracheal tube.
No more than three attempts with a direct laryngoscope (plus one attempt with a videolaryngoscope) should be made to intubate the trachea. Keep in mind that suxamethonium is wearing off. Ensuring adequate neuromuscular blockade at this stage is crucial; this might include administering a non-depolarizing relaxant if oxygenation can be maintained with bag-mask ventilation. Given the non-immediate nature of the surgery, there should be a low threshold to abandon intubation attempts and resort to Plan B.
An alternative strategy can then be planned.
The most important initial step is to declare a “failed intubation.” This will prevent further intubation attempts and alert your assistant that Plan A has failed. Maintaining oxygenation and anesthesia is also critical before implementing Plan B.
Do not administer another dose of suxamethonium. Insert a supraglottic airway if oxygenation fails and adequate ventilation cannot be maintained.
Plan D follows the declaration of a CICO (Cannot Intubate, Cannot Oxygenate) situation.
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This question is part of the following fields:
- Pharmacology
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Question 80
Incorrect
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Which of the following vertebral levels is the site where the aorta perforates the diaphragm?
Your Answer:
Correct Answer: T12
Explanation:The diaphragm divides the thoracic cavity from the abdominal cavity. Structures penetrate the diaphragm at different vertebral levels through openings in the diaphragm to communicate between the two cavities. The diaphragm has openings at three vertebral levels:
T8: vena cava, terminal branches of the right phrenic nerve
T10: oesophagus, vagal trunks, left anterior phrenic vessels, oesophageal branches of the left gastric vessels
T12: descending aorta, thoracic duct, azygous and hemi-azygous vein -
This question is part of the following fields:
- Anatomy
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Question 81
Incorrect
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After consuming 12 g of paracetamol, a 37-year-old man is admitted to the medical admissions unit. He has hepatocellular necrosis in both clinical and biochemical aspects.
The most significant reason for paracetamol causing toxicity is?Your Answer:
Correct Answer: Glutathione is rapidly exhausted
Explanation:Phase I and phase II metabolism are used by the liver to break down paracetamol.
1st Phase:
Prostaglandin synthetase and cytochrome P450 (CYP1A2, CYP2E2, CYP3A4 and CYP2D6) to N-acetyl-p-benzoquinoneimine (NAPQI) and N-acetylbenzo-semiquinoneimine. NAPQI is a toxic metabolite that binds to the sulfhydryl groups of cellular proteins in hepatocytes, making it toxic. This can result in centrilobular necrosis.
Glutathione and glutathione transferases prevent NAPQI from binding to hepatocytes at low paracetamol doses by preferentially binding to these toxic metabolites. The cysteine and mercapturic acid conjugates are then excreted in the urine. Depletion of glutathione occurs at higher doses of paracetamol, resulting in high levels of NAPQI and the risk of hepatocellular damage. Hepatotoxicity would not be an issue if the body’s glutathione stores were sufficient.
N-acetylcysteine is a precursor for glutathione synthesis and is the drug of choice for the treatment of paracetamol overdose.
Phase II:
Conjugation with glucuronic acid to paracetamol glucuronide is the most common method of metabolism and excretion, accounting for 60% of renally excreted metabolites. Paracetamol sulphate (35%), unchanged paracetamol (5%), and mercapturic acid are among the other renally excreted metabolites (3 percent ). The capacity of conjugation pathways is limited. The capacity of the sulphate conjugation pathway is lower than that of the glucuronidation pathway.
Because of the low pH in the stomach, paracetamol absorption is minimal (pKa value is 9.5). Paracetamol is absorbed quickly and completely in the alkaline environment of the small intestine. Oral bioavailability is extremely high, approaching 100%.
As a result, measuring paracetamol levels in plasma after an injury is important. Peak plasma concentrations are reached after 30-60 minutes, with a volume of distribution of 0.95 L/kg. It binds to plasma proteins at a rate of 10% to 25%.
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This question is part of the following fields:
- Pharmacology
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Question 82
Incorrect
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Arrythmias can develop from abnormal conduction, which may be as a result of impaired blood flow in the coronary arteries which causes hypoxia. Phase 0 depolarisation can be slowed, and this leads to slower conduction speeds.
Rapid depolarisation in the cardiac action potential is caused by which movement of ions?Your Answer:
Correct Answer: Sodium influx
Explanation:Cardiac conduction
Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium
Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop
Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period
Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period
Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 83
Incorrect
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Which of the following statements below would best describe the receptor response to an opioid mu receptor agonist such as fentanyl?
Your Answer:
Correct Answer: Intrinsic activity determines maximal response
Explanation:Agonists activate the receptor as a direct result of binding to it with a characteristic affinity. Moreover, intrinsic activity of an agonist to its receptor determines the ability to create a maximal response.
Responses to low doses of a drug usually increase in direct proportion to dose. As doses increase, however, the response increment diminishes; finally, doses may be reached at which no further increase in response can be achieved. The relationship formed between the dose and response when plotted graphically is hyperbolic. This also shows that even at low receptor occupancy, a maximal response may be produced.
Antagonists bind to receptors in the same affinity as agonists, but they have no intrinsic efficacy. They do not activate generation of signal. Instead, they interfere with the ability of the agonist to activate the receptor.
Partial agonists are similar to full agonists in that they have similar affinity to the target receptor, but they produce a lower response than full agonists.
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This question is part of the following fields:
- Pharmacology
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Question 84
Incorrect
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Monitoring of which of the following is indicated in the prevention of propofol infusion syndrome?
Your Answer:
Correct Answer: Lactate
Explanation:Propofol infusion syndrome (PRIS) is characterized by lactic acidosis, bradyarrhythmia, rhabdomyolysis, cardiac and renal failure, and often leads to death. So, lactate monitoring is advised in patients with propofol infusion syndrome.
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This question is part of the following fields:
- Pharmacology
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Question 85
Incorrect
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At sea level, Sevoflurane is administered via a plenum vaporiser. 100 mL of the fresh gas flow is bypassed into the vaporising chamber. Temperature within the vaporising chamber is maintained at 20°C.
The following fresh gas flows approximates best for the delivery of 1% sevoflurane.Your Answer:
Correct Answer: 2.7 L/minute
Explanation:The equation for calculating vaporiser output is:
Vaporiser output (VO) mL = Carrier gas flow (mL/minute) × SVP of agent (kPa)
Ambient pressure (kPa) − SVP of agent (kPa)The saturated vapour pressure of sevoflurane at 1 atm (100 kPa) and 20°C is 21 kPa.
VO = (100 mL × 21 kPa)/(100 kPa − 21kPa) for sevoflurane,
VO = 26.6 mL26.6 mL of 100% sevoflurane and 100 mL bypass carrier gas is being added to the fresh gas flow per minute.
2660 mL of 1% sevoflurane and 100 mL bypass carrier gas is approximately 2.7 L/minute.
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This question is part of the following fields:
- Pharmacology
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Question 86
Incorrect
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Regarding the use of soda lime as part of a modern circle system with a vaporiser outside the circuit (VOC), which of the following is its most deleterious consequence?
Your Answer:
Correct Answer: Carbon monoxide formation
Explanation:When using dry soda lime for VOCs, very high amounts of carbon monoxide may be produced, regardless of the inhalational anaesthetic agent used. The carbon monoxide produced is sufficient enough to cause cytotoxic and anaemic hypoxia. To prevent this, soda lime canisters are shaken well to even out the packing of granules. This can help to evenly distribute gas flow for proper CO2 absorption and ventilation.
Compound A is formed when dry soda lime, or soda lime in high temperature, reacts with the inhalational anaesthetic Sevoflurane. Animal studies have shown renal toxicity in rats, but renal adverse effects in humans are yet to be observed.
When monitors are not employed with VOCs, deleterious effects are not for certain. However, monitors not employed with vaporiser inside the circuit (VIC) can lead to significant adverse events.
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This question is part of the following fields:
- Pathophysiology
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Question 87
Incorrect
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The mandibular division of the trigeminal nerve passes through which anatomic structure?
Your Answer:
Correct Answer: Foramen ovale
Explanation:The mandibular branch of the trigeminal nerve passes through the foramen ovale. Other structures that pass through this foramen are the accessory meningeal artery, and occasionally, the lesser petrosal nerve.
These are the structures that pass through the other openings in the cranial fossa:
Foramen rotundum – Maxillary branch of the trigeminal nerve
Foramen lacerum – Greater petrosal nerve, traversed by the internal carotid artery
Superior orbital fissure – Oculomotor nerve; trochlear nerve; lacrimal, frontal and nasociliary branches of the ophthalmic branch of the trigeminal nerve; abducens nerve, superior ophthalmic vein
Stylomastoid foramen – facial nerve
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This question is part of the following fields:
- Anatomy
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Question 88
Incorrect
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Tubes for vascular access and body cavity drainage are available in a variety of sizes.
When choosing an intravenous or intra-arterial cannula, which of the following measurements is used?Your Answer:
Correct Answer: Standard wire gauge (SWG)
Explanation:Standard wire gauge cannulas for intravenous and intraarterial use are available (SWG or G). The SWG is a former imperial unit (which requires metric conversion). The cross sectional area of wires is becoming more popular as a size measurement.
The number of wires that will fit into a standard hole template is referred to as SWG.
This standard sized hole can accommodate 22 thin wires side by side (each wire the diameter of a 22 gauge cannula)
In the same hole, 14 thicker wires would fit (each wire the diameter of a 14 gauge cannula)While the diameter and thus radius of a parallel sided tube are the most important determinants of fluid flow rate, they are not commonly used to compare cannula sizes.
The circumference of French gauge (FG) catheters (urinary or chest drains) is measured. Sizes of double lumen tracheal tubes are FG. Internal diameter is used to measure single lumen tubes.
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This question is part of the following fields:
- Pathophysiology
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Question 89
Incorrect
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Regarding gas laws, which one best explains the ability of a Bourdon gauge to measure temperature?
Your Answer:
Correct Answer: Charles's law
Explanation:Charles’ Law states that there is a direct correlation between temperature and volume, where pressure and amount gas are constant. As temperature increases, volume also increases.
Boyle’s Law states that Pressure is inversely proportional to volume, assuming that temperature and amount of gas are constant. As volume increases, pressure decreases. In Dalton’s law of partial pressure, the total pressure exerted by a mixture of gases is equal to the sum of the partial pressure of the gases in mixture.
According to Henry’s Law for concentration of dissolved gases, at a constant temperature, the amount of a given gas that dissolves in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid. An equivalent way of stating the law is that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid.
Gay-Lussac’s Law states that the pressure of a given mass of gas varies directly with the absolute temperature of the gas, when the volume is kept constant. This law is very similar to Charles’ Law, with the only difference being the type of container. Whereas the container in a Charles’ Law experiment is flexible, it is rigid in a Gay-Lussac’s Law experiment.
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This question is part of the following fields:
- Basic Physics
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Question 90
Incorrect
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A 53-year old female with a diagnosis of anaplastic thyroid carcinoma is admitted in the surgery department for an elective total thyroidectomy with radical neck dissection. The operation is expected to last for 10 hours.
Which of the following is the most suitable humidifier to use in an anaesthetic circuit for this case?Your Answer:
Correct Answer: Heat and moisture exchanger (HME)
Explanation:Adequate humidification is vital to maintain homeostasis of the airway. Heat and moisture exchangers conserve some of the exhaled water, heat and return them to inspired gases. Many heat and moisture exchangers also perform bacterial/viral filtration and prevent inhalation of small particles. Heat and moisture exchangers are also called condenser humidifier, artificial nose, etc. Most of them are disposable devices with exchanging medium enclosed in a plastic housing. For adult and paediatric age group different dead space types are available. Heat and moisture exchangers are helpful during anaesthesia and ventilatory breathing system. To reduce the damage of the upper respiratory tract through cooling and dehydration inspiratory air can be heated and humidified, thus preventing the serious complications. Moreover, they are the most appropriate humidification devices used for routine anaesthesia.
Gases can be bubbled through water to increase humidity. Passing gas through water at room temperature causes the gas to cool due to latent heat of vaporisation. The water bath can be heated. This improves the efficiency of the device and also reduces the incidence of bacterial colonisation.
Nebulisers use a venturi system which employs the Bernoulli effect. A gas at high flow passes through a constriction causing the gas to accelerate, reducing its potential energy allowing other gases or liquids to be entrained. This can include medications or in the case of humidification, water vapour. The size of the water droplet produced by nebulisation determines where in the airway it is deposited. Standard nebulisers produced droplets of 4 microns in diameter and these are deposited in the upper airway and trachea. Efficacy can be improved by passing the droplets over an anvil which further reduces particle size. The most efficient form of nebuliser is the ultrasonic nebuliser. Here a transducer immersed in water and vibrated at a frequency of 3MHz produces1-2micron droplets. These particles easily reach the bronchioles and provide excellent humidification.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 91
Incorrect
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Among the following which one is not a criterion for the assessment of causality?
Your Answer:
Correct Answer: Sensitivity
Explanation:For establishing a cause effect relationship, following criteria must be met:
1. Coherence & Consistency
2. Temporal Precedence
3. Specificity
As can be seen, sensitivity (The probability of a positive test) is not among these deciding factors..
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This question is part of the following fields:
- Statistical Methods
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Question 92
Incorrect
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A 48-year-old woman has presented to the emergency with abdominal pain and distension complaints. She is a known case of diabetes mellitus type 2 and has a BMI of 28 kg/m². On investigations, the liver function tests (LFTs) show raised alanine transaminase (ALT).
Liver ultrasound is performed next to visualize the blood flow into and out of the liver.
Which blood vessel supplies approximately one-third of the blood supply to the liver?
Your Answer:
Correct Answer: Hepatic artery proper
Explanation:The liver receives blood supply from two sources.
1. Hepatic artery proper
It arises from the celiac trunk via the common hepatic artery and brings oxygenated blood to the liver.
It contributes to approximately 30% of the blood supply of the liver.
2. Hepatic portal vein – supplies the liver with partially deoxygenated blood, carrying nutrients absorbed from the small intestine. It gets tributaries from the inferior mesenteric vein, splenic vein, and superior mesenteric veinThe inferior mesenteric artery supplies the hindgut.
The superior mesenteric artery supplies the pancreas and intestine up to the proximal two-thirds of the transverse colon.
The inferior phrenic artery supplies the inferior surface of the diaphragm and oesophagus. -
This question is part of the following fields:
- Anatomy
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Question 93
Incorrect
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Regarding the emergency oxygen flush, which is true?
Your Answer:
Correct Answer: May lead to awareness if used inappropriately
Explanation:When the emergency oxygen flush is pressed, 100% oxygen is supplied from the common gas outlet. This gas bypasses BOTH flowmeters and vaporisers. The flow of oxygen is usually 45 l/min at a PRESSURE OF 400 kPa.
There is an increased risk of pulmonary barotrauma when the emergency flush is pressed, especially when anaesthetising paediatric patients.
The inappropriate use of the flush causes dilution of anaesthetic gases and this increases the possibility of anaesthetic awareness .
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 94
Incorrect
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Which of the following is correct regarding nitric oxide?
Your Answer:
Correct Answer: Is produced by both inducible and constitutive forms of nitric oxide synthetase
Explanation:Nitric oxide is generated from L-arginine by nitric oxide synthase. It is produced in response to haemodynamic stress by the vascular endothelium, and it produces both smooth muscle relaxation and reduced vascular resistance.
Nitric oxide may be inactivated through interaction with other oxygen free radicals, (e.g. oxidised low-density lipoprotein (LDL)).
Nitric oxide causes the production of the second messenger, cyclic guanosine monophosphate (cGMP).
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This question is part of the following fields:
- Pathophysiology
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Question 95
Incorrect
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Which measurements is the most accurate for predicting fluid responsiveness?
Your Answer:
Correct Answer: Change in stroke volume following passive straight leg raise
Explanation:The passive leg raising (PLR) manoeuvre is a method of altering left and right ventricular preload and it is done with real-time measurement of stroke volume. It is a simple, quick, relatively unbiased, and accurate bedside test to guide fluid management and avoid fluid overload.
Pulse pressure variation (PPV), Stroke volume variation (SVV), superior vena cava diameter variation (threshold 36%) and end-expiratory occlusion test are used for dynamic tests of fluid responsiveness.
PPV is derived peripherally from the arterial pressure waveform.
Stroke volume variation (SVV) can be derived peripherally through pulse contour analysis of the arterial waveform. PPV and SVV have a threshold of 12% but since they are not used in patients who have cardiac arrhythmias, are spontaneous breathing, and in ventilated patients with low lung compliance and tidal volumes, they are of limited value.
The tests of fluid responsiveness’ accuracy is determined by calculating the area under the receiver operating characteristic curve (UROC) obtained by plotting the sensitivity of the parameter in predicting fluid responsiveness vs. 1-specificity.
Under optimal conditions, the ability to determine the need for fluid is best with PPV>SVV>LVEDA>CVP.
Central venous pressure (CVP) is a static test of preload (not preload responsiveness) and a key determinant of cardiac function. The left ventricular end-diastolic area (LVEDA) a static test of fluid responsiveness, is derived using echocardiography
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This question is part of the following fields:
- Clinical Measurement
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Question 96
Incorrect
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A 30-year-old man has been diagnosed with a direct inguinal hernia.
A direct inguinal hernia passes through Hesselbach's triangle. What forms the medial edge of this triangle?Your Answer:
Correct Answer: Rectus abdominis muscle
Explanation:The inguinal triangle of Hesselbach’s is an important clinical landmark on the posterior wall of the inguinal canal. It has the following relations:
Inferiorly – medial third of the inguinal ligament
Medially – lower lateral border of the rectus abdominis
Laterally – inferior epigastric vesselsDirect inguinal hernia is when the bowel bulges directly through the abdominal wall. These hernias usually protrude through Hesselbach’s triangle
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This question is part of the following fields:
- Anatomy
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Question 97
Incorrect
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Question 98
Incorrect
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Which of the following is true regarding correlation coefficient?
Your Answer:
Correct Answer: It can assume any value between -1 and 1
Explanation:The degree of correlation is summarised by the correlation coefficient (r). This indicates how closely the points lie to a line drawn through the plotted data. In parametric data this is called Pearson’s correlation coefficient and can take any value between -1 to +1. A correlation of -1.0 indicates a perfect negative correlation, and a correlation of 1.0 indicates a perfect positive correlation.
For example
r = 1 – strong positive correlation (e.g. systolic blood pressure always increases with age)
r = 0 – no correlation (e.g. there is no correlation between systolic blood pressure and age)
r = – 1 – strong negative correlation (e.g. systolic blood pressure always decreases with age)
Whilst correlation coefficients give information about how one variable may increase or decrease as another variable increases they do not give information about how much the variable will change. They also do not provide information on cause and effect.
In contrast to the correlation coefficient, linear regression may be used to predict how much one variable changes when a second variable is changed.
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This question is part of the following fields:
- Statistical Methods
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Question 99
Incorrect
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Which of the following can be measured directly using spirometry?
Your Answer:
Correct Answer: Vital capacity
Explanation:Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).
It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.
During spirometry, the following measurements can be determined:
Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
Forced expiratory volume in one second (FEV1)
FEV1/FVC ratio
Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.
Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution
The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.
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This question is part of the following fields:
- Clinical Measurement
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Question 100
Incorrect
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A 68-year-old man presents worried about his risk of motor neurone disease. No symptoms have developed, but his father suffered from motor neurone disease. Recently, his cousin has also been diagnosed with amyotrophic lateral sclerosis. He searched the internet for screening tests for motor neurone disease and found a blood test called ‘neuron’, and requests to have it done. You search this blood test and find a prospective study going on evaluating the potential benefits of this blood test. On average, this test diagnosed patients with the disease 8 months earlier than the patients who are diagnosed on the basis of their clinical symptoms. The patients diagnosed using this neuron test also survived, on average, 48 months from the diagnosis, whereas the patients diagnosed clinically survived an average of 39 months from the diagnosis. Considering the clear benefits, you decide to have it done on the patient.
Which of the following options best relate to the above scenario?Your Answer:
Correct Answer: Lead-time bias
Explanation:Hypochondriasis is an illness anxiety disorder, and describes excessively worriedness about the presence of a disease. While the woman is concerned about her possibility of developing motor neurone disease, she understands that no symptoms have yet appeared. Hypochondriasis involves patients who refuse to accept that they don’t have the disease, even if the results come back negative.
Late Look Bias occurs when the data is gathered or analysed at an inappropriate time e.g. when many of the subjects suffering from a fatal disease have died. This type of biasness might occur in some retrospective studies of motor neurone disease, but is not applicable to this prospective study.
In procedure bias, the researcher decides assignment of a treatment versus control and assigns particular patients to one group or the other non-randomly. This is unlikely to have occurred in this case, although it is not mentioned specifically. Of all the options, lead time-bias is a better answer.
The Hawthorne Effect refers to groups modifying their behaviour simply because they are aware of being observed. Any differences in the behaviour have not been mentioned in the question, and it is highly unlikely that a change in patient’s behaviour would have affected their length of survival in this case.
The correct option is lead-time bias. Even if the new blood test diagnoses the disease earlier, it doesn’t affect the outcome, as the survival time was still on average 43 months from the onset of symptoms in both groups. With the help of blood test, the disease was only detected 8 months earlier.
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This question is part of the following fields:
- Statistical Methods
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Question 101
Incorrect
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A 72-year old man has presented to the emergency room with sweating, nausea, chest pain, and an ECG that shows ST elevation. The ST segment of the ECG corresponds to a period of slow calcium influx in the cardiac action potential.
This equates to which phase in the cardiac action potential?Your Answer:
Correct Answer: Phase 2
Explanation:Understanding of the cardiac action potential helps with the understanding of the ECG which measures the electrical activity of the heart. This is reflected in its waveform.
The rapid depolarisation phase is reflected in the QRS complex. After this phase comes the plateau phase which is represented by the ST segment. Lastly, the T wave shows repolarisation, phase 3.The cardiac action potential has several phases which have different mechanisms of action as seen below:
Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
These channels automatically deactivate after a few msPhase 1: caused by early repolarisation and an efflux of potassium.
Phase 2: Plateau – caused by a slow influx of calcium. (ST segment)
Phase 3 – Final repolarisation – caused by an efflux of potassium. (T wave)
Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potentialOf note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.
Different sites have different conduction velocities:
1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec2. AV node conduction – 0.05 m/sec
3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 102
Incorrect
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A patient under brachial plexus regional block complains of pain under the cuff after the torniquet is inflated.
Which nerve was most probably 'missed' by the local anaesthetic?Your Answer:
Correct Answer: Intercostobrachial nerve
Explanation:The area described in the question is supplied by the intercostobrachial nerve, which provides sensory innervation to the portions of the axilla, tail of the breast, lateral chest wall and medial side of the arm.
It is a common for it to be ‘missed’ during administration of local anaesthesia because of its very superficial anatomic course. It may be anesthetized by giving an analgesia from the upper border of the biceps at the anterior axillary fold, to the margin of the triceps by the axillary floor.
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This question is part of the following fields:
- Pathophysiology
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Question 103
Incorrect
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A bolus of alfentanil has a faster onset of action than an equal dose of fentanyl.
Which of the following statements most accurately describes the difference?Your Answer:
Correct Answer: The pKa of alfentanil is less than that of fentanyl
Explanation:Unionised molecules are more likely than ionised molecules to cross membranes (such as the blood-brain barrier).
Because alfentanil and fentanyl are weak bases, the Henderson-Hasselbalch equation says that the ratio of ionised to unionised molecules is determined by the parent compound’s pKa in relation to physiological pH.
Alfentanil has a pKa of 6.5, while fentanyl has a pKa of 8.4.
At a pH of 7.4, 89 percent of alfentanil is unionised, whereas 9% of fentanyl is.As a result, alfentanil has a faster onset than fentanyl.
Fentanyl is 83% plasma protein bound
Alfentanil is 90% plasma protein bound.Alfentanil’s pharmacokinetics are affected by its higher plasma protein binding. Because alfentanil has a low hepatic extraction ratio (0.4), clearance is determined by the degree of protein binding rather than the time it takes to take effect.
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This question is part of the following fields:
- Pharmacology
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Question 104
Incorrect
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A 60-year-old man, with a history of excessive alcohol intake, presents for the first time in the emergency department with acute abdominal pain in the epigastric region.
On examination, the man is sweating and has a high-grade fever. His heart rate is 140/min and a BP of 92/59 mmHg.
The patient is diagnosed with acute pancreatitis. Which of the following is a complication you are most likely to see in this patient?Your Answer:
Correct Answer: Blue discolouration of the flank regions
Explanation:Bulky, greasy stools are associated with improper digestion that can be expected if the pancreas loses its exocrine function. This is common in long-term chronic pancreatitis but since this is the patient’s first presentation with such symptoms, this complication is unlikely.
Peripheral neuropathy is a common complication of chronic diabetes but has been reported with cases of chronic pancreatitis too.
Abdominal distention with shifting dullness is a classic symptom of underlying ascites. Ascites is a complication of many diseases but it is not common with the acute first-time presentation of pancreatitis.
Option E: This points towards abdominal obstruction but in the absence of the more common symptoms, nausea and bilious vomiting, this is unlikely.
Option A: Grey Turner’s sign is the pooling of blood in the retroperitoneal space between the last rib and the top of the hip. The pancreas is a retroperitoneal organ and inflammation of the pancreas can cause retroperitoneal haemorrhage. The sign takes 24-48 hours to develop and can predict a severe attack of acute pancreatitis. The patient has presented with acute pancreatitis due to his history of high alcohol intake, and acute on chronic is unlikely as this is his first presentation. He also has low blood pressure and an increased heart rate, which suggest blood loss with acute pancreatitis.
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This question is part of the following fields:
- Anatomy
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Question 105
Incorrect
-
Drug X, a new intravenous induction drug, is being administered as a bolus at regular time intervals, and the following data were observed:
Time following injection (hours) vs Plasma concentration of drug X (mcg/mL)
2 / 400
6 / 100
10 / 25
14 / 6.25
Which of the following values estimate the plasma half-life (T½) of drug X?
Your Answer:
Correct Answer: 2 hours
Explanation:Half life (T½) is the time required to change the amount of drug in the body by one-half (or 50%) during elimination. The time course of a drug in the body will depend on both the volume of distribution and the clearance.
Extrapolating the values from the plasma concentration vs time:
Plasma concentration at 0 hours = 800 mcg/mL
Plasma concentration at 2 hours = 400 mcg/mL
Plasma concentration at 4 hours = 200 mcg/mL
Plasma concentration at 6 hours = 100 mcg/mL
Plasma concentration at 8 hours = 50 mcg/mL
Plasma concentration at 10 hours = 25 mcg/mL
Plasma concentration at 12 hours = 12.5 mcg/mL
Plasma concentration at 14 hours = 6.25 mcg/mL -
This question is part of the following fields:
- Statistical Methods
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Question 106
Incorrect
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Question 107
Incorrect
-
The following foetal anatomical features functionally closes earliest at birth?
Your Answer:
Correct Answer: Foramen ovale
Explanation:Foramen ovale, ductus arteriosus (DA) and ductus venosus (DV) are the three important cardiac shunts in-utero.
At birth the umbilical vessels constrict in response to stretch as they are clamped. Blood flow through the ductus venosus (DV) decreases but the DV closes passively in 3-10 days.
As the pulmonary circulation is established, there is a drastic fall in pulmonary vascular resistance and an increased pulmonary blood flow. This increases flow and pressure in the Left Atrium that exceeds that of the right atrium. The difference in pressure usually leads to the IMMEDIATE closure of the foramen ovale.
The DA is functionally closed within the first 36-hours of birth in a healthy full-term newborn. Subsequent endothelial and fibroblast proliferation leads to permanent anatomical closure within 2 – 3 weeks.
Oxygenated blood from the placenta passes via the umbilical vein to the liver. Blood also bypasses the liver via the ductus venosus into the inferior vena cava (IVC). The Crista dividens is a tissue flap situated at the junction of the IVC and the right atrium (RA). This flap directs the oxygen-rich blood, along the posterior aspect of the IVC, through the foramen ovale into the left atrium (LA).
The Eustachian valve also known as the valve of The IVC is a remnant of the crista dividens.
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This question is part of the following fields:
- Anatomy
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Question 108
Incorrect
-
During a critical liver resection surgery, a 65-year-old man suffers uncontrolled hepatic bleeding. The 'Pringle manoeuvre is performed to stop the bleeding where the hepatic artery, portal vein, and common bile duct are clamped. These structures form the anterior boundary of the epiploic foramen.
Which of the following vessels also contributes to the boundary of this region?Your Answer:
Correct Answer: Inferior vena cava
Explanation:The epiploic foramen (foramen of Winslow or aditus to the lesser sac) is found behind the free right border of the lesser omentum. A short, 3 cm slit serves as the entrance to the lesser sac from the greater sac.
The epiploic foramen has the following boundaries:
Anteriorly: hepatoduodenal ligament, the bile duct (anteriorly on the right), the hepatic artery (anteriorly on the left), and the portal vein (posteriorly) together with nerves and lymphatics
Superiorly: the peritoneum of the posterior layer of the hepatoduodenal ligament runs over the caudate process of the liver
Posteriorly: inferior vena cava
Floor: upper border of the first part of the duodenum
The anterior and posterior walls of the foramen are normally
apposed, which partly explains why patients can develop large fluid
collections isolated to the greater or lesser sacRapid control of the hepatic artery and portal vein can be obtained by compression of the free edge of the lesser omentum (a ‘Pringle’ manoeuvre), which is a potentially useful technique in liver trauma and surgery.
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This question is part of the following fields:
- Anatomy
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Question 109
Incorrect
-
A new intravenous neuromuscular blocking agent has been developed. It has a hepatic extraction ratio of 0.25 and three quaternary nitrogen atoms in its structure. It has been discovered that it has a half-life of fifteen minutes in healthy volunteers.
Which of the following elimination mechanisms is the most likely to explain this pharmacological behaviour?Your Answer:
Correct Answer: It is filtered and not reabsorbed by the renal tubules
Explanation:The neuromuscular blocking agent is likely to be filtered and not reabsorbed by the renal tubules due to an exclusion process.
Neuromuscular blocking agents that contain one or more quaternary nitrogen atoms are polar and ionised. As a result, the molecules have low lipid solubility, low membrane diffusion capacity, and low distribution volume.
It’s unlikely that a compound with three quaternary nitrogen atoms is an ester. Its high polarity would prevent molecules from moving quickly into tissues.
When drugs have a low hepatic extraction ratio (0.3), the venous and arterial drug concentrations are nearly identical. The liver is not the primary site of drug metabolism.
Therefore:
Changes in liver blood flow have no effect on clearance.
Protein binding, intrinsic metabolism, and excretion are all very sensitive to changes in clearance.
When taken orally, there is no first-pass metabolism.There is no reason for the lungs to eliminate any neuromuscular blocking agent.
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This question is part of the following fields:
- Pharmacology
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Question 110
Incorrect
-
Which type of epithelium lines the luminal surface of the oesophagus?
Your Answer:
Correct Answer: Non keratinised stratified squamous epithelium
Explanation:Normally, the oesophagus is lined by non-keratinized stratified squamous epithelium. This epithelium can undergo metaplasia and convert to the columnar epithelium (stomach’s lining) in long-standing GERD that leads to Barret’s oesophagus.
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This question is part of the following fields:
- Anatomy
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Question 111
Incorrect
-
Which of the following is incorrect with regards to atrial natriuretic peptide?
Your Answer:
Correct Answer: Secreted mainly by the left atrium
Explanation:Atrial natriuretic peptide (ANP) is secreted mainly from myocytes of right atrium and ventricle in response to increased blood volume.
It is secreted by both the right and left atria (right >> left).It is a 28 amino acid peptide hormone, which acts via cGMP
degraded by endopeptidases.It serves to promote the excretion of sodium, lowers blood pressure, and antagonise the actions of angiotensin II and aldosterone.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 112
Incorrect
-
Which of the following statements is about the measurement of glomerular filtration rate (GFR) is correct?
Your Answer:
Correct Answer: The result matches clearance of the indicator if it is renally inert
Explanation:The measurements of GFR are done using renally inert indicators like inulin, where passive rate of filtration at the glomerulus = rate of excretion. Normal value is about 180 litres per day.
GFR is altered by renal blood flow but blood flow does not need to be measured.
The reabsorption of Na leads to a low excretion rate and low urine concentration and therefore its use as an indicator would lead to an erroneously LOW GFR.
If there is tubular secretion of any solute, the clearance value will be higher than that of inulin. This will be either due to tubular reabsorption or the solute not being freely filtered at the glomerulus.
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This question is part of the following fields:
- Physiology
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Question 113
Incorrect
-
When combined with a general anaesthetic or central neuraxial block, which of the following medications used to treat dementia involves the risk of significant hypotension?
Your Answer:
Correct Answer: Risperidone
Explanation:Atypical antipsychotic drugs include risperidone and quetiapine. They not only inhibit dopamine receptors in the limbic system, but also histamine (H1) and alpha2 adrenoreceptors. When combined with general and/or central neuraxial block, this might result in severe hypotension.
Donepezil (Aricept) is an acetylcholinesterase (AChE) inhibitor that increases the neurotransmitter acetylcholine in the cerebral cortex and hippocampus in a reversible, non-competitive manner. It is used to reduce the advancement of Alzheimer’s disease symptoms (AD). Rivastigmine and galantamine are two more drugs that work in the same way.
Ginkgo Biloba contains anti-oxidant characteristics and is used to treat early-stage Alzheimer’s disease, vascular dementia, and peripheral vascular disease. It lowers platelet adhesiveness and decreases platelet activating factor (PAF) increasing the risk f bleeding, especially in individuals who are also taking anticoagulants and antiplatelet medication.
Memantine is an antagonist of the NMDA receptor. Synaptic plasticity, which is thought to be a critical component of learning and memory, can be inhibited at high doses. The use of ketamine is a relative contraindication since antagonism of this receptor can cause a dissociative state.
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This question is part of the following fields:
- Pharmacology
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Question 114
Incorrect
-
You're summoned to the emergency room, where a 39-year-old man has been admitted following a cardiac arrest. He was rescued from a river, but little else is known about him.
CPR is being performed on the patient, who has been intubated. He's received three DC shocks and is still in VF. A rectal temperature of 29.5°C is taken with a low-reading thermometer.
Which of the following statements about his resuscitation is correct?Your Answer:
Correct Answer: No further DC shocks and no drugs should be given until his core temperature is greater than 30°C
Explanation:The guidelines for the management of cardiac arrest in hypothermic patients published by the UK Resuscitation Council differ slightly from the standard algorithm.
In a patient with a core temperature of less than 30°C, do the following:
If you’re on the shockable side of the algorithm (VF/VT), you should give three DC shocks.
Further shocks are not recommended until the patient has been rewarmed to a temperature of more than 30°C because the rhythm is refractory and unlikely to change.
There should be no drugs given because they will be ineffective.In a patient with a core temperature of 30°C to 35°C, do the following:
DC shocks are used as usual.
Because they are metabolised much more slowly, the time between drug doses should be doubled.Active rewarming and protection against hyperthermia should be given to the patient.
Option e is false because there is insufficient information to determine whether resuscitation should be stopped.
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This question is part of the following fields:
- Physiology
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Question 115
Incorrect
-
Which of the following statements is correct regarding opioid receptors?
Your Answer:
Correct Answer: Binding with an opioid agonist increases potassium conductance
Explanation:Opioid receptors are a large family of seven transmembrane domain receptors. They are of four types:
1) Delta opioid receptor
2) Mu opioid receptor
3) Kappa opioid receptor
4) Orphan receptor-like 1
They contain about 372-400 amino acids and thus their molecular weight is different.
Opioid receptor activation reduces the intracellular cAMP formation and opens K+ channels (mainly through µ and δ receptors) or suppresses voltage-gated N-type Ca2+ channels (mainly κ receptor). These actions result in neuronal hyperpolarization and reduced availability of intracellular Ca2+ which results in decreased neurotransmitter release by cerebral, spinal, and myenteric neurons (e.g. glutamate from primary nociceptive afferents).
However, other mechanisms and second messengers may also be involved, particularly in the long-term
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This question is part of the following fields:
- Pharmacology
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Question 116
Incorrect
-
Which of the following is true regarding the mechanism of action of daptomycin?
Your Answer:
Correct Answer: Interferes with the outer membrane of gram positive bacteria resulting in cell death
Explanation:Daptomycin alters the curvature of the membrane, which creates holes that leak ions. This causes rapid depolarization, resulting in loss of membrane potential. Thus it interferes with the outer membrane of gram-positive bacteria resulting in cell death.
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This question is part of the following fields:
- Pharmacology
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Question 117
Incorrect
-
An 82-year old male has shortness of breath which is made worse when he lies down but investigations have revealed a normal ejection fraction. Why might this be?
Your Answer:
Correct Answer: He has diastolic dysfunction
Explanation:Decreased stroke volume causes decreased ejection fraction which results in diastolic dysfunction.
Ejection fraction is not a useful measure in someone with diastolic dysfunction because stroke volume may be reduced whilst end-diastolic volume may be reduced.
Diastolic dysfunction may arise with reduced heart compliance.Ejection fraction measures of the proportion of blood leaving the ventricles with each beat and is calculated as follows:
Stroke volume / end-diastolic volume.A healthy ejection fraction is usually taken as 60% (based on a stroke volume of 70ml and end-diastolic volume of 120ml).
Respiratory inspiration causes a decreased pressure in the thoracic cavity, which in turn causes more blood to flow into the atrium.
Sitting up decreases venous because of the action of gravity on blood in the venous system.
Hypotension also decreases venous return.
A less compliant aorta, like in aortic stenosis increases end systolic left ventricular volume which decreases stroke volume.Systemic vascular resistance = mean arterial pressure / cardiac output.
Increased vascular resistance impedes the flow of blood back to the heart.Increased venous return increases end diastolic LV volume as there is more blood returning to the ventricles.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 118
Incorrect
-
Desflurane has which of the following characteristics when compared with halothane?
Your Answer:
Correct Answer: Less biodegradation
Explanation:Approximately 20% of halothane and 0.02% desflurane undergo hepatic biotransformation. Desflurane, halothane, and isoflurane are metabolised in the liver by cytochrome p450 to trifluoroacetate. Through an immunological mechanism involving trifluoroacetyl hapten formation, trifluoroacetate is thought to be responsible for hepatotoxicity.
Potency of inhaled anaesthetic agents is measured using the minimal alveolar concentration (MAC). The MAC of halothane is 0.74% while that of desflurane is 6.3%. The potency can also be compared using the oil: gas partition coefficient (224 and 18.7 for halothane and desflurane respectively).
Onset of action of volatile agents depends on the blood:gas partition coefficient. A lower blood:gas partition coefficient and insolubility in blood means faster onset and offset of action. The blood gas coefficient for halothane is 2.4 while that of desflurane is 0.42. Desflurane is less soluble than halothane in blood. Halothane has a pungent smell that can irritate the airway which limits its use for a gaseous induction especially in paediatric anaesthesia. desflurane is not pungent.
Desfluranes boiling point is only slightly above normal room temperature (22.8°C) making it extremely volatile while the boiling point of halothane is approximately 50.2°C.
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This question is part of the following fields:
- Pharmacology
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Question 119
Incorrect
-
Of the following, which is NOT a branch of the external carotid artery?
Your Answer:
Correct Answer: Mandibular artery
Explanation:The external carotid artery has eight important branches:
1. Superior thyroid artery
2. Ascending pharyngeal artery
3. Lingual artery
4. Facial artery
5. Occipital artery
6. Posterior auricular artery
7. Maxillary artery (terminal branch)
8. Superficial temporal artery (terminal branch)There is no mandibular artery but the first part of the maxillary artery is called the mandibular part as it is posterior to the lateral pterygoid muscle.
The maxillary artery is divided into three portions by its relation to the lateral pterygoid muscle:
first (mandibular) part: posterior to the lateral pterygoid muscle
second (pterygoid or muscular) part: within the lateral pterygoid muscle
third (pterygopalatine) part: anterior to the lateral pterygoid muscle -
This question is part of the following fields:
- Anatomy
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Question 120
Incorrect
-
Which of the following is a feature of a central venous pressure waveform?
Your Answer:
Correct Answer: An a wave due to atrial contraction
Explanation:The central venous pressure (CVP) waveform depicts changes of pressure within the right atrium. Different parts of the waveform are:
A wave: which represents atrial contraction. It is synonymous with the P wave seen during an ECG. It is often eliminated in the presence of atrial fibrillation, and increased tricuspid stenosis, pulmonary stenosis and pulmonary hypertension.
C wave: which represents right ventricle contraction at the point where the tricuspid valve bulges into the right atrium. It is synonymous with the QRS complex seen on ECG.
X descent: which represents relaxation of the atrial diastole and a decrease in atrial pressure, due to the downward movement of the right ventricle as it contracts. It is synonymous with the point before the T wave on ECG.
V wave: which represents an increase in atrial pressure just before the opening of the tricuspid valve. It is synonymous with the point after the T wave on ECG. It is increased in the background of a tricuspid regurgitation.
Y descent: which represents the emptying of the atrium as the tricuspid valve opens to allow for blood flow into the ventricle in early diastole.
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This question is part of the following fields:
- Pathophysiology
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Question 121
Incorrect
-
Which of the following statements is not true regarding Adrenaline?
Your Answer:
Correct Answer: Exerts its effect by decreasing intracellular calcium
Explanation:Noradrenaline also called norepinephrine belongs to the catecholamine family that functions in the brain and body as both a hormone and neurotransmitter.
They have sympathomimetic effects acting via adrenoceptors (?1, ?2,?1, ?2, ?3) or dopamine receptors (D1, D2).
May cause reflex bradycardia, reduce cardiac output and increase myocardial oxygen consumption
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This question is part of the following fields:
- Pharmacology
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Question 122
Incorrect
-
A 23-year-old man, has just undergone surgery under general anaesthesia. He has experienced a severe reaction to the anaesthetic agent resulting in malignant hyperthermia (MH) for which he has been referred for treatment.
What investigation can be conducted to determine a patient's susceptibility to malignant hyperthermia?Your Answer:
Correct Answer: In vitro muscle contraction test using caffeine
Explanation:Malignant hyperthermia (MH) is a autosomal dominant inherited medical condition which predisposes affected individuals to a clinical syndrome of hypermetabolism which involves abnormal ryanodine receptors in skeletal muscle causing a deregulation of calcium in muscle.
It is a life threatening condition requiring immediate medical intervention. It often lies dormant until triggered in susceptible individuals mostly by volatile inhaled anaesthetic agents and succinylcholine which is a muscle relaxant.
The signs and symptoms of MH are related to this hypermetabolism, which includes an increase in carbon dioxide production, metabolic and respiratory acidosis, accelerated oxygen consumption, heat production, activation of the sympathetic nervous system, hyperkalaemia, disseminated intravascular coagulation (DIC), and multiple organ dysfunction and failure.
Early signs of MH to look out for in patients includes an uptick in end-tidal carbon dioxide (even with increasing minute ventilation), tachycardia, muscle rigidity, tachypnoea, and hyperkalaemia. Later signs include fever, myoglobinuria, and multiple organ failure.
In vitro muscle contracture test (IVCT) is the standard for determining individual susceptibility to MH. It is conducted by measuring the force of muscle contraction after exposing the patient’s muscle sample to halothane and caffeine., the sample is normally taken from the vastus medialis or lateralis under regional anaesthesia.
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This question is part of the following fields:
- Clinical Measurement
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Question 123
Incorrect
-
A laser is a device that stimulates atoms or molecules to emit light at particular wavelengths and amplifies that light, typically producing a very narrow beam of radiation. This can be of visible, infrared, or ultraviolet wavelengths. They have been widely utilized in theatre environment.
Which of the following safety measures is most likely to reduce chances of eye injury to the theatre personnel?Your Answer:
Correct Answer: Wearing laser protective goggles
Explanation:Eye damage is the most common potential hazard associated with laser energy. Everyone in the laser treatment room has the risk of eye exposure when working with a Class 3b or Class 4 healthcare laser system, and damage to various structures in the eye depending on wavelength of the laser if they are unprotected.
Red and near-infrared light (400-1400 nm) has very high penetration power. The light causes painless burns on the retina after it is absorbed by melanin in the pigment epithelium just behind the photoreceptors.
Infrared radiation (IR), or infrared light (>1060 nm), is a type of radiant energy that’s invisible to human eyes and hence won’t elicit the protective blink.
Ultraviolet light (<400 nm) is also a form of electromagnetic radiation which is can penetrate the cornea and be absorbed by the iris or the pupil and cause burn injuries or cataract occur due to irreversible photochemical retinal damage. Safety eyewear is the best method of providing eye protection and are designed to absorb light specific to the laser being used. Laser protective eyewear (LPE) includes glasses or goggles of proper optical density (OD). The lenses should not be glass or plastic. The LPE should withstand direct and diffuse scattered laser beams. The laser protection supervisor (LPS) or LSO is an individual who is responsible for any clinical area in which lasers are used. They are expected to have a certain level of equipment and determine what control measures are appropriate, for each individual system, but their presence does not guarantee the chances of having an eye injury. Class 1 lasers are generally safe under every conceivable condition and is not likely to cause any eye damage. Class 3b or Class 4 medical laser systems are utilized in healthcare which have their own safety precautions. Polarized spectacles can make your eyes more comfortable by eliminated glare, however, they will not be able to offer any protection against wavelengths at which laser act.
Using short bursts to reduce energy is also not correct as it would still be harmful to eye. -
This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 124
Incorrect
-
At which of the following location is there no physiological oesophageal constriction?
Your Answer:
Correct Answer: Lower oesophageal sphincter
Explanation:The oesophagus is a muscular tube that connects the pharynx to the stomach. It begins at the lower border of the cricoid cartilage and C6 vertebra. It ends at T11.
The oesophagus has physiological constrictions at the following levels:
1. Cervical constriction: Pharyngo-oesophageal junction (15 cm from the incisor teeth) produced by the cricopharyngeal part of the inferior pharyngeal constrictor muscle
2. Thoracic constrictions:
i. where the oesophagus is first crossed by the arch of the aorta (22.5 cm from the incisor teeth)
ii. where the oesophagus is crossed by the left main bronchus (27.5 cm from the incisor teeth)
3. Diaphragmatic constriction: where the oesophagus passes through the oesophageal hiatus of the diaphragm (40 cm from the incisor teeth)Awareness of these constrictions is important for clinical purposes when it is required to pass instruments through the oesophagus into the stomach or when viewing radiographs of patients’ oesophagus.
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This question is part of the following fields:
- Anatomy
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Question 125
Incorrect
-
A 25-year old male with palpitations and dizziness presents to the emergency room. In the triage process, cardiac monitoring shows supraventricular tachycardia with a heart rate of 200 beats per minute. This high heart rate arises as a result of different specialised cells and nerve fibres in the heart which are responsible for conducting that action potential which is generated in the event of systole.
The fastest conduction velocity is carried out by which of the following?Your Answer:
Correct Answer: Purkinje fibres
Explanation:The correct answer is the Purkinje fibres, which conducts at a velocity of about 4m/sec.
The electrical conduction system of the heart starts with the SA node which generates spontaneous action potentials.
This is conducted across both atria by cell to cell conduction, and occurs at around 1 m/s. The only pathway for the action potential to enter the ventricles is through the AV node in a normal heart.
At this site, conduction is very slow at 0.05ms, which allows for the atria to completely contract and fill the ventricles with blood before the ventricles depolarise and contract.The action potentials are conducted through the Bundle of His from the AV node which then splits into the left and right bundle branches. This conduction is very fast, (,2m/s), and brings the action potential to the Purkinje fibres.
Purkinje fibres are specialised conducting cells which allow for a faster conduction speed of the action potential (,2-4m/s). This allows for a strong synchronized contraction from the ventricle and thus efficient generation of pressure in systole.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 126
Incorrect
-
The SI unit of measurement is kgm2s-2 in the System international d'unités (SI).
Which of the following derived units of measurement has this format?Your Answer:
Correct Answer: Energy
Explanation:The derived SI unit of force is Newton.
F = m·a (where a is acceleration)
F = 1 kg·m/s2The joule (J) is a converted unit of energy, work, or heat. When a force of one newton (N) is applied over a distance of one metre (Nm), the following amount of energy is expended:
J = 1 kg·m/s2·m =
J = 1 kg·m2/s2 or 1 kg·m2·s-2The unit of velocity is metres per second (m/s or ms-1).
The watt (W), or number of joules expended per second, is the SI unit of power:
J/s = kg·m2·s-2/s
J/s = kg·m2·s-3Pressure is measured in pascal (Pa) and is defined as force (N) per unit area (m2):
Pa = kg·m·s-2/m2
Pa = kg·m-1·s-2 -
This question is part of the following fields:
- Physiology
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Question 127
Incorrect
-
Regarding bilirubin, which one of the following statement is true?
Your Answer:
Correct Answer: Conjugated bilirubin is stored in the gall bladder
Explanation:Bilirubin is the tetrapyrrole and a catabolic product of heme. 70-90% of bilirubin is end product of haemoglobin degradation in the liver.
Bilirubin circulates in the blood in 2 forms; unconjugated and conjugated bilirubin.
Unconjugated bilirubin is insoluble in water. It travels through the bloodstream to the liver, where it changes from insoluble into a soluble form (i.e.; unconjugated into conjugated form).
This conjugated bilirubin travels from the liver into the small intestine and the gut bacteria convert bilirubin into urobilinogen and then into urobilin (not urobilin to urobilinogen). A very small amount passes into the kidneys and is excreted in urine.
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This question is part of the following fields:
- Physiology
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Question 128
Incorrect
-
The fluids with the highest osmolarity is?
Your Answer:
Correct Answer: 0.45% N. Saline with 5% glucose
Explanation:The concentration of solute particles per litre (mosm/L) = the osmolarity of a solution. Changes in water content, ambient temperature, and pressure affects osmolarity. The osmolarity of any solution can be calculated by adding the concentration of key solutes in it.
Individual manufacturers of crystalloids and colloids may have different absolute values but they are similar to these.
0.45% N. Saline with 5% glucose:
Tonicity – hypertonic
Osmolarity – 405 mosm/L
Kilocalories (kCal) – 1070.9% N. Saline:
Tonicity – isotonic
Osmolarity – 308 mosm/L
Kilocalories (kCal) – 05% Dextrose:
Tonicity – isotonic
Osmolarity – 253 mosm/L
Kilocalories (kCal) – 170Gelofusine (154 mmol/L Na, 120 mmol/L Cl):
Tonicity – isotonic
Osmolarity – 274 mosm/L
Kilocalories (kCal) – 0Hartmann’s solution:
Tonicity – isotonic
Osmolarity – 273 mosm/L
Kilocalories (kCal) – 9 -
This question is part of the following fields:
- Physiology
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Question 129
Incorrect
-
A 49-year-old woman is admitted to hospital. She is scheduled for surgery and is undergoing preoperative assessment.
As part of the preoperative assessment, her functional capacity is estimated. At 50kg in weight, she is able to cycle along a flat surface at a speed of 10-14 miles/hour (8 metabolic equivalents or METs).
Provide the best estimated value of oxygen consumption (VO2) for eight METs.Your Answer:
Correct Answer: 1400 mL/minute
Explanation:Oxygen consumption (VO2) refers to the optimal amount of oxygen used by the body during exercise.
It is calculated mathematically by:
VO2 = 3.5 x 50 x 8 = 1400 mL/kg/minute
where,
1 MET = 3.5 mL O2/kg/minute is utilized by the body.
Note:
1 MET Eating
Dressing
Use toilet
Walking slowly on level ground at 2-3 mph
2 METs Playing a musical instrument
Walking indoors around house
Light housework
4 METs Climbing a flight of stairs
Walking up hill
Running a short distance
Heavy housework, scrubbing floors, moving heavy furniture
Walking on level ground at 4 mph
Recreational activity, e.g. golf, bowling, dancing, tennis
6 METs Leisurely swimming
Leisurely cycling along the flat (8-10 mph)
8 METs Cycling along the flat (10-14 mph)
Basketball game
10 METs Moderate to hard swimming
Competitive football
Fast cycling (14-16 mph) -
This question is part of the following fields:
- Clinical Measurement
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Question 130
Incorrect
-
The required sample size in a trial of a new therapeutic agent varies with?
Your Answer:
Correct Answer: Level of statistical significance required
Explanation:The level of statistical significance required influences the sample size used. This is because sample size is used in the calculation of SD/SE.
Sample size does not affect
The level of acceptance
The alternative hypothesis with a general level set at p<0.05
The test to be used.Experience of the investigator and the type of patient recruited should have no bearing on the required sample size.
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This question is part of the following fields:
- Statistical Methods
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Question 131
Incorrect
-
A 27-year-old woman is admitted to the emergency room with an ectopic pregnancy that has ruptured.
The following is a description of the clinical examination:
Anxious
Capillary refill time of 3 seconds
Cool peripheries
Pulse 120 beats per minute
Blood pressure 120/95 mmHg
Respiratory rate 22 breaths per minute.
Which of the following is the most likely explanation for these clinical findings?Your Answer:
Correct Answer: Reduction in blood volume of 15-30%
Explanation:The following is the Advanced Trauma Life Support (ATLS) classification of haemorrhagic shock:
Class I haemorrhage:
It has blood loss up to 15%. There is very less tachycardia, and no changes in blood pressure, RR or pulse pressure. Usually, fluid replacement is not required.Class II haemorrhage:
It has 15-30% blood loss, equivalent to 750 – 1500 ml. There is tachycardia, tachypnoea and a decrease in pulse pressure. Patient may be frightened, hostile and anxious. It can be stabilised by crystalloid and blood transfusion.Class III haemorrhage:
There is 30-40% blood loss. It portrays inadequate perfusion, marked tachycardia, tachypnoea, altered mental state and fall in systolic pressure. It requires blood transfusion.Class IV haemorrhage:
There is > 40% blood volume loss. It is a preterminal event, and the patient will die in minutes. It portrays tachycardia, significant depression in systolic pressure and pulse pressure, altered mental state, and cold clammy skin. There is need for rapid transfusion and surgical intervention. -
This question is part of the following fields:
- Physiology
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Question 132
Incorrect
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Question 133
Incorrect
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A 74-year-old with a VVI pacemaker is undergoing a hip replacement.
Which of the following is most likely to predispose him to an electrical hazard?Your Answer:
Correct Answer: Use of cutting unipolar diathermy
Explanation:A single chamber pacemaker was implanted in the patient. In VVI mode, a pacemaker paces and senses the ventricle while being inhibited by a perceived ventricular event. The most likely electrical hazard from diathermy is electromagnetic interference (EMI).
EMI has the potential to cause the following: Inhibition of pacing
Asynchronous pacing
Reset to backup mode
Myocardial burns, and
Trigger VF.Diathermy entails the implementation of high-frequency electrical currents to produce heat and either make incisions or induce coagulation. Monopolar cautery involves disposable cautery pencils and electrosurgical diathermy units. In typical monopolar cautery, an electrical plate is placed on the patient’s skin and acts as an electrode, while the current passes between the instrument and the plate. Monopolar diathermy can therefore interfere with implanted metal devices and pacemaker function.
Bipolar diathermy, where the current passes between the forceps tips and not through the patient and is less likely to generate EMI.
Whilst the presence of a CVP line may in theory predispose the patient to microshock, the use of prerequisite CF electrical equipment makes this very unlikely. The presence of a CVP line and pacemaker does not therefore unduly increase the risk of an electrical hazard.
Isolating transformers are used to protect secondary circuits and individuals from electrical shocks. There is no step-up or step-down voltage (i.e. there is a ratio of 1 to 1 between the primary and secondary windings).
A ground (or earth) wire is normally connected to the metal case of an operating table to protect patients from accidental electrocution. In the event that a fault allows a live wire to make contact with the metal table (broken cable, loose connection etc.) it becomes live. The earth will provide an immediate path for current to safely flow through and so the table remains safe to touch. Being a low resistance path, the earth lets a large current flow through it when the fault occurs ensuring that the fuse or RCD will quickly blow. Without an operating table earth, the patient is not at more risk of an electrical hazard because of the pacemaker.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 134
Incorrect
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Of the following, which option best describes the muscle type that has the fastest twitch response to stimulation?
Your Answer:
Correct Answer: Type IIb skeletal muscle
Explanation:Human skeletal muscle is composed of a heterogeneous collection of muscle fibre types which differ histologically, biochemically and physiologically.
It can be biochemically classified into 2 groups. This is based on muscle fibre myosin ATPase histochemistry. These are:
Type 1 (slow twitch): Muscle fibres depend upon aerobic glycolytic metabolism and aerobic oxidative metabolism. They are rich in mitochondria, have a good blood supply, rich in myoglobin and are resistant to fatigue.
Type II (fast twitch): Muscle fibres are sub-divided into:
Type IIa – relies on aerobic/oxidative metabolism
Type IIb – relies on anaerobic/glycolytic metabolism.Fast twitch muscle fibres produce short bursts of power but are more easily fatigued.
Cardiac and smooth muscle twitches are relatively slow compared with skeletal muscle.
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This question is part of the following fields:
- Physiology
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Question 135
Incorrect
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Which of following statements is true regarding the comparison of fentanyl and alfentanil?
Your Answer:
Correct Answer: Fentanyl is more potent than alfentanil
Explanation:Fentanyl is a pethidine congener, 80–100 times more potent than morphine, both in analgesia and respiratory depression. Fentanyl is ten times more potent than alfentanil.
Alfentanil has a more rapid onset than fentanyl even if fentanyl is more lipid-soluble because both are basic compounds and alfentanil has lower pKa, so a greater proportion of alfentanil is unionized and is more available to cross membranes.
Elimination of alfentanil is higher than fentanyl due to its lower volume of distribution.
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This question is part of the following fields:
- Pharmacology
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Question 136
Incorrect
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A global cerebral blood flow (CBF) of 35 ml/100 g/min (Normal CBF = 54 ml/100 g/min) can lead to which of the following?
Your Answer:
Correct Answer: Poor prognostic EEG
Explanation:CBF is defined as the blood volume that flows per unit mass per unit time in brain tissue and is typically expressed in units of ml blood/100 g tissue/minute. The normal average CBF in adults human is about 50 ml/100 g/min, with lower values in the white matter (,20 ml/100 g/min) and greater values in the gray matter (,80 ml/100 g/min).
Low CBF levels between 30-40 ml/100 g/min may begin to show poor prognostic EEG. EEG findings consistently associated with a poor outcome are isoelectric EEG, low voltage EEG, and burst suppression (specifically burst suppression with identical bursts), as well as the absence of EEG reactivity.
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This question is part of the following fields:
- Physiology
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Question 137
Incorrect
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An inguinal hernia repair under general anaesthesia is scheduled for a fit 36-year-old man (75 kg). For perioperative and postoperative analgesia, you decide to perform an inguinal field block.
Which of the following local anaesthetic solutions is the most appropriate?Your Answer:
Correct Answer: 30 mL bupivacaine 0.5%
Explanation:Perioperative and postoperative analgesia can both be provided by an inguinal hernia field block. The Iliohypogastric and ilioinguinal nerves, as well as the skin, superficial fascia, and deeper structures, must be blocked for maximum effectiveness. The local anaesthetic should ideally have a long duration of action, be highly concentrated, and have a volume of at least 30 mL.
Plain bupivacaine has a maximum safe dose of 2 mg/kg body weight.
Because the patient weighs 75 kg, 150 mg bupivacaine can be safely administered. Both 30 mL 0.5 percent bupivacaine (150 mg) and 60 mL 0.25 percent bupivacaine (150 mg) are acceptable doses, but 30 mL 0.5 percent bupivacaine represents the optimal volume and strength, potentially providing a denser and longer block.
The maximum safe dose of plain lidocaine has been estimated to be between 3.5 and 5 mg/kg. The patient weighs 75 kg and can receive a maximum of 375 mg using the higher dosage regimen:
There are 200 mg of lidocaine in 10 mL of 2% lidocaine (and therefore 11 mL contains 220 mg)
200 mg of lidocaine is contained in 20 mL of 1% lidocaine.While alternatives are available, Although the doses of 11 mL lidocaine 2% and 20 mL lidocaine 1% are well within the dose limit, the volumes used are insufficient for effective field block for this surgery.
With 1 in 200,000 epinephrine, the maximum safe dose of lidocaine is 7 mg/kg. The patient can be given 525 mg in this case. Even with epinephrine, 60 mL of 1% lidocaine is 600 mg, which could be considered an overdose.
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This question is part of the following fields:
- Pharmacology
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Question 138
Incorrect
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A 57-year old woman, presents to her general practitioner. She has a 2 week history of a vaginal hysterectomy for which she was placed under general anaesthesia.
On examination, she has notable weakness of dorsiflexion of her left foot and a high stepping gait.
Which nerve was most likely injured during her surgery?Your Answer:
Correct Answer: Common peroneal nerve
Explanation:The common peroneal (fibular) nerve is a peripheral nerve in the lower limb. It arises of the L4-S2 nerve roots and has sensory and motor innervations:
Sensory: Provides innervation of the lateral leg and foot dorsum.
Motor: Provides innervation of the short head of the biceps femoris, as well as muscles of the anterior and lateral leg compartments.
It is the most commonly damaged nerve in the lower extremity, as it is easily compressed by a plaster cast or injured when the fibula is fractured.
Damage to the common peroneal nerve will result in loss of dorsiflexion at ankle (footdrop, as feet are permanently plantarflexed), with the accompanying high stepping gait.
The saphenous and sural nerve only provide sensory innervation.
The tibial nerve arises from the sciatic nerve (like the common peroneal), but it provides motor innervation to the posterior leg compartments and intrinsic foot muscles. Injury to the tibial nerve will cause loss of plantar flexion, toe flexion and weakened foot inversion.
Extreme hip flexion into the lithotomy or Lloyd-Davies position can result in stretch damage to the neurones (sciatic and obturator nerves) or by applying direct pressure (femoral nerve compression).
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This question is part of the following fields:
- Pathophysiology
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Question 139
Incorrect
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A 24-year-old female, presents to the emergency department via ambulance. She has just been involved in a car accident. She is examined and undergoes various diagnostic investigations. Her X-ray report states that a fracture was noted on the surgical neck of her humerus.
What structure is most likely to the damaged as a result of a surgical neck fracture of the humerus?Your Answer:
Correct Answer: Axillary nerve
Explanation:Fractures to the surgical neck of the humerus are common place as it is the weakest point of the proximal humerus bone.
The structures most likely to be damaged are the axillary nerve and the posterior circumflex humeral artery as they surround the surgical neck.
The radial nerve runs along the radial groove, so injury to it would likely occur with a mid-shaft fracture of the humerus.
The brachial artery is most likely to be injured as a result of a supracondylar fracture of the humerus which increases the risk of volkmaan’s ischemic contractures.
Injury to the musculocutaneous nerve is least likely to happen and it very uncommon.
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This question is part of the following fields:
- Anatomy
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Question 140
Incorrect
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Conclusive evidence suggests that rate for the prevalence of schizophrenia in United Kingdom is around 1%.
Which term can be used to describe that?Your Answer:
Correct Answer: Endemic
Explanation:An epidemic is declared when the increase in a give disease is above a certain level in a specific interval of time.
An endemic is the general, usual level of a disease in a population at a particular time.
A pandemic is an epidemic that is spread across many countries and continents.
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This question is part of the following fields:
- Statistical Methods
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Question 141
Incorrect
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Which of the following statement is correct regarding the difference between dabigatran and other anticoagulants?
Your Answer:
Correct Answer: Competitive thrombin inhibitor blocking both free and bound thrombin
Explanation:Dabigatran template is a prodrug and its active metabolite is a direct thrombin inhibitor. It is a synthetic, reversible, non-peptide thrombin inhibitor. This inhibition of thrombin results in a decrease of fibrin and reduces platelet aggregation.
Drugs like warfarin act by inhibiting the activation of vitamin K-dependent clotting factors. These factors are synthesized by the liver and activated by gamma-carboxylation of glutamate residues with the help of vitamin K. Hydroquinone form of vitamin K is converted to epoxide form in this reaction and regeneration of hydroquinone form by enzyme vitamin K epoxide reductase (VKOR) is required for this activity. Oral anticoagulants prevent this regeneration by inhibiting VKOR, thus vitamin K-dependent factors are not activated. These factors include clotting factors II, VII, IX, and X as well as anti-clotting proteins, protein C and protein S.
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This question is part of the following fields:
- Pharmacology
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Question 142
Incorrect
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Regarding laminar gas flow, which of the following options has the most influence on laminar flow?
Your Answer:
Correct Answer: Diameter of tube
Explanation:Laminar flow can be defined as the motion of a fluid where every particle in the fluid follows the same path of its previous particles. The following are properties of laminar flow of gas or fluids:
1. Smooth unobstructed flow of gas through a tube of relatively uniform diameter
2. Few directional changes
3. Slow, steady flow through straight smooth, rigid, large calibre, cylindrical tube
4. Outer layer flow slower than the centre due to friction, results in discrete cylindrical layers, or streamlines
5. Double flow by doubling pressure as long as the flow pattern remains laminarPoiseuille’s Law relates the factors that determine laminar flow. It indicates the degree of resistance to fluid flow through a tube. The resistance to fluid flow through a tube is directly related to the length, flow and viscosity; and inversely related to the radius of the tube to the fourth power. This means that, when the radius is doubled, there is increase in flow by a factor of 16.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 143
Incorrect
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A 27-year-old woman takes part in a study looking into the effects of different dietary substrates on metabolism. She receives a 24-hour ethyl alcohol infusion.
A constant volume, closed system respirometer is used to measure CO2 production and consumption. The production of carbon dioxide is found to be 200 mL/minute.
Which of the following values most closely resembles her anticipated O2 consumption at the conclusion of the trial?Your Answer:
Correct Answer: 300 mL/minute
Explanation:The respiratory quotient (RQ) is the ratio of CO2 produced by the body to O2 consumed in a given amount of time.
CO2 produced / O2 consumed = RQ
CO2 is produced at a rate of 200 mL per minute, while O2 is consumed at a rate of 250 mL per minute. An RQ of around 0.8 is typical for a mixed diet.
The RQ will change depending on the energy substrates consumed in the diet. Granulated sugar is a refined carbohydrate that contains 99.999 percent carbohydrate and no lipids, proteins, minerals, or vitamins.
Glucose and other hexose sugars (glucose and other hexose sugars):
RQ=1Fats:
RQ = 0.7Proteins:
Approximately 0.9 RQEthyl alcohol is a type of alcohol.
200/300 = 0.67 RQ
For complete oxidation, lipids and alcohol require more oxygen than carbohydrates.
When carbohydrate is converted to fat, the RQ can rise above 1.0. Fat deposition and weight gain are likely to occur in these circumstances.
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This question is part of the following fields:
- Physiology
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Question 144
Incorrect
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An 82-year-old male has severe abdominal pain that is out of proportion to the examination. He is a known case of atrial fibrillation and diverticulitis. Suspecting mesenteric ischemia, he was thoroughly investigated, and a mesenteric angiography shows ischemia of the left colic flexure.
Which artery gives off branches that supply this region directly?Your Answer:
Correct Answer: Inferior mesenteric artery (IMA)
Explanation:Mesenteric ischemia is ischemia of the blood vessels of the intestines. It can be life-threatening, especially if the small intestine is involved.
The inferior mesenteric artery originates 3-4 cm above the bifurcation of the abdominal aorta.
The left colic artery branches off the inferior mesenteric artery to supply the following:
– distal 1/3 of the transverse colon
– descending colonAt approximately the left colic flexure (splenic flexure), a transition occurs in the blood supply of the GI tract. The SMA supplies the proximal part to the flexure, and the IMA supplies the part distal to the flexure. This is why the left colic flexure is a watershed area and is prone to ischemia exacerbated by atherosclerotic changes or hypotension. The dominant arterial supply of the splenic flexure is usually from the left colic artery, but it may also get collaterals from the left branch of the middle colic artery.
The AMA and PMA do not exist.
The splenic artery directly supplies the spleen and has branches that supply the stomach and the pancreas.
The proximal two-thirds of the transverse colon is supplied by the middle colic artery, a branch of the SMA. -
This question is part of the following fields:
- Anatomy
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Question 145
Incorrect
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A 70-year-old man presents to hospital complaining of dysphagia. He is scheduled for a rigid oesophagoscopy.
On examination, He is noted to have severe osteoarthritis in his cervical spine resulting in limited rotation and flexion-extension. He has no other neurological signs or symptoms.
He is given anaesthesia for the procedure, which is complicated by a difficult intubation (Cormack-Lehane 3), but was eventually achieved using a gum elastic bougie.
After recovering from anaesthesia, he is examined and found to have severe motor weakness of upper limbs, and mild motor weakness of lower limbs, bladder dysfunction and sensory loss of varying degrees below the level of C5.
What incomplete spinal cord lesion is most likely to be responsible for his symptoms?Your Answer:
Correct Answer: Central cord syndrome
Explanation:Central cord syndrome is the most commonly occurring type of partial spinal cord lesion. It is more likely to occur in older patients with cervical spondylosis and a hyperextension injury. The injury to the spinal cord occurs in the grey matter causing the following symptoms:
Disproportionally higher motor function weakness in the upper limbs than in lower limbs
Dysfunction of the bladder
Degrees of sensory loss below the level of the lesionAn anterior spinal artery infarction will interrupt the corticospinal tract resulting in paralysis of motor function, loss of pain and temperature sensation, all occurring below the level of the injury.
Brown-Sequard syndrome occurs as a result of the hemisection of the spinal cord. Its symptoms include ipsilateral upper motor neurone paralysis and loss of proprioception, with contralateral loss of pain and temperature sensation.
Spinal cord infarctions rarely occur in the posterior spinal artery.
Cauda equina syndrome occurs as a result of compression of the lumbosacral spinal nerve roots below the level of the conus medullaris. Injury to these nerves will cause partial or complete loss of movement and sensation in this distribution.
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This question is part of the following fields:
- Pathophysiology
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Question 146
Incorrect
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What structure is most critical in providing support for the duodenojejunal flexure?
Your Answer:
Correct Answer: Ligament of Treitz
Explanation:The duodenojejunal flexure is the point where the duodenum becomes the jejunum.
The ligament of Treitz, which arises from the right crus of diaphragm, provides suspension for support.
Between the ileum and the caecum is the ligament of Treves.
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This question is part of the following fields:
- Anatomy
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Question 147
Incorrect
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Which of the following statements is not correct regarding Noradrenaline?
Your Answer:
Correct Answer: Predominantly work through effects on ?-adrenergic receptors
Explanation:Noradrenaline also called norepinephrine belongs to the catecholamine family that functions in the brain and body as both a hormone and neurotransmitter.
They have sympathomimetic effects acting via adrenoceptors (?1, ?2,?1, ?2, ?3) or dopamine receptors (D1, D2).
May cause reflex bradycardia, reduce cardiac output and increase myocardial oxygen consumption
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This question is part of the following fields:
- Pharmacology
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Question 148
Incorrect
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Which of the following statements best describes adenosine receptors?
Your Answer:
Correct Answer:
Explanation:Adenosine receptors are expressed on the surface of most cells.
Four subtypes are known to exist which are A1, A2A, A2B and A3.Of these, the A1 and A2 receptors are present peripherally and centrally. There are agonists at the A1 receptors which are antinociceptive, which reduce the sensitivity to a painful stimuli for the individual. There are also agonists at the A2 receptors which are algogenic and activation of these results in pain.
The role of adenosine and other A1 receptor agonists is currently under investigation for use in acute and chronic pain states.
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This question is part of the following fields:
- Physiology
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Question 149
Incorrect
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Which of the following drugs can have significant clinical effects on neonates when used in appropriate doses for a caesarean section?
Your Answer:
Correct Answer: Alfentanil
Explanation:Opioid should be avoided in the caesarean section as it crosses the placental membrane and causes respiratory depression.
Even though inhalational and intravenous anaesthetic agents readily cross the placenta, they do not have significant effects on APGAR score when used in clinical doses.
Vecuronium and suxamethonium are highly polar molecules and thus do not cross the placenta in significant amounts.
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This question is part of the following fields:
- Pharmacology
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Question 150
Incorrect
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A patient visits the radiology department for a magnetic resonance imaging (MRI) scan (MRI). The presence of metal implants must be ruled out prior to the scan.
In a strong magnetic field, which of the following metals is the safest?Your Answer:
Correct Answer: Chromium
Explanation:Ferromagnetism is the property of a substance that is magnetically attracted and can be magnetised indefinitely. A material is said to be paramagnetic if it is attracted to a magnetic field. A substance is said to be diamagnetic if it is repelled by a magnetic field.
Cobalt, iron, gadolinium, neodymium, and nickel are ferromagnetic.
Gadolinium is a ferromagnetic rare earth metal that is ferromagnetic below 20 degrees Celsius (its Curie temperature). MRI scans are enhanced with gadolinium-based contrast media.
When ferromagnetic materials are exposed to a magnetic field, they can cause a variety of issues like magnetic field interactions, heating, and image artefacts.
Titanium, lead, chromium, copper, aluminium, silver, gold, and tin are non ferromagnetic.
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This question is part of the following fields:
- Clinical Measurement
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