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Question 1
Correct
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A 16-year-old autistic boy who has had learning difficulties is found to have large testes. Which condition does the child most likely have?
Your Answer: Fragile X syndrome
Explanation:Fragile X syndrome is a genetic condition that causes a range of developmental problems including learning disabilities and cognitive impairment. Usually, males are more severely affected by this disorder than females.Affected individuals usually have delayed development of speech and language by age 2. Most males with fragile X syndrome have mild to moderate intellectual disability, while about one-third of affected females are intellectually disabled. Children with fragile X syndrome may also have anxiety and hyperactive behaviour such as fidgeting or impulsive actions. They may have attention deficit disorder (ADD), which includes an impaired ability to maintain attention and difficulty focusing on specific tasks. About one-third of individuals with fragile X syndrome have features of autism spectrum disorder that affect communication and social interaction. Seizures occur in about 15 percent of males and about 5 percent of females with fragile X syndrome.Most males and about half of females with fragile X syndrome have characteristic physical features that become more apparent with age. These features include a long and narrow face, large ears, a prominent jaw and forehead, unusually flexible fingers, flat feet, and in males, enlarged testicles (macroorchidism) after puberty.
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This question is part of the following fields:
- Endocrinology
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Question 2
Correct
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An 18-year-old girl presents with complaints of primary amenorrhoea. Which of the following is the first sign of the onset of puberty?
Your Answer: Breast-bud development
Explanation:The first sign of pubarche in females is breast-bud development (thelarche).This begins between the ages of 9 and 12 years and continues to 12–18 years. Pubic hair growth occurs next (said to occur in stage 3), at ages 9–14 years, and is complete at 12–16 years. Menarche occurs relatively late in stage 4 (age 11–15 years) and is associated with a deceleration in growth. The peak height velocity is reached earlier (10–13 years) and growth is completed much earlier than in boys.
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This question is part of the following fields:
- Endocrinology
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Question 3
Incorrect
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An 11-year-old boy was brought by his mother because she noticed that his blood sugar level was high this morning.The boy was diagnosed with type-1 diabetes mellitus at the age of 6, following which his sugars have been under control with insulin. His mother insists that his mental, social, and physical development were all normal for his age.His is currently on a basal-bolus regime, where he takes insulin glargine at 9 pm every evening. What is the most likely explanation for the pattern shown by the boy's blood sugars?
Your Answer: Smogyi effect
Correct Answer: Dawn phenomenon
Explanation:The patient’s sugar levels typically show the Dawn phenomenon.Dawn phenomenon:This is an early morning rise in blood glucose levels secondary to a rise in hormones that increase blood glucose levels. The question suggests that he is undergoing a pubertal growth spurt, suggesting that an increase in these hormones is what has led to the higher morning glucose levels.Other options:- Inactivity at night-time: It is expected, and insulin dose should be adequate despite inactivity during the night.- Inadequate bedtime insulin: It is possible that this is a contributing factor. However, inadequate background insulin is also likely to result in high blood glucose in the day, which the question does not suggest.- Somogyi effect: There are no features suggestive of nocturnal hypoglycaemia that can cause the Somogyi effect.- Nocturnal glycogenesis: Glycogenesis would result in hypoglycaemia, not hyperglycaemia.
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This question is part of the following fields:
- Endocrinology
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Question 4
Correct
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Tall stature is NOT a characteristic finding in which of the following conditions?
Your Answer: Laurence-Moon Syndrome
Explanation:A height that is above the 97th percentile for age and sex is described as a tall stature. The most common cause of tall stature is constitutional or familial, followed by nutritional causes. Hormonal causes of tall stature include hyperthyroidism, growth hormone excess, and precocious puberty. Some important chromosomal and syndromic causes of tall stature are Klinefelter’s syndrome, homocystinuria, Marfan’s syndrome, Sotos syndrome, Beckwith-Weidman syndrome, and Weaver syndrome. Laurence-Moon syndrome is an autosomal recessive disorder characterized by short stature, retinitis pigmentosa, and spastic paraplegia.
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This question is part of the following fields:
- Endocrinology
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Question 5
Correct
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Which of the following would a 9-year old girl with newly diagnosed type 1 diabetes not require annually?
Your Answer: Retinopathy screening
Explanation:Retinopathy screening need not be done on an annual basis for a 9-year-old child. Screening for diabetic retinopathy should begin at the age of 12.Diabetes mellitus is an increasing problem in both developing and developed countries alike. Some of the risk factors include:ObesityFamily historyFemale sex Asian and African racesPresence of acanthosis nigricans is seen with type 2 but not type 1 diabetesThe diagnosis is mostly incidental or subacute.The treatment aims are good blood sugar control, maintenance of normal BMI, and reduction of complications. The treatment modality also includes lifestyle modifications and cessation of smoking. Even after all this, diabetic ketoacidosis can still occur.Management of diabetes mellitus – NICE guidelines (Updated, 2015): – Standard release metformin should be offered from the moment of diagnosis.- HBA1c should be measured every three months. The target HBA1c level of 48 mmol/mol (6.5%) or lower is ideal for minimising the risk of long term complications.- Children should undergo an eye examination by an optician every two years.- Annual immunisation against influenza and pneumococcal infections are essential.- There is an increased risk of psychological and psychosocial difficulties if the child with type 1 diabetes is on insulin or oral hypoglycaemic medications. These include anxiety disorder, depression, behavioural and conduct disorders and family conflict.- Annual monitoring to be done for:Hypertension starting at diagnosis.Dyslipidaemia starting at diagnosis.Screening for microalbuminuria starting at diagnosis.Diabetic retinopathy from 12 years of age.
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This question is part of the following fields:
- Endocrinology
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Question 6
Correct
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A 15-year-old is admitted in the emergency department following a collapse. He has a known history of asthma and type 1 diabetes.His arterial blood gas analysis reveals:pH: 7.05pO2: 8 kPapCO2: 8 kPaBase excess: -12 mmol/LHCO3-: 15 mmol/LWhich of the following interpretations is correct?
Your Answer: Mixed metabolic and respiratory acidosis
Explanation:In this case scenario, the pH is too low to be fully explained by a respiratory acidosis. Usually, if there is a metabolic acidosis, the respiratory system will try to compensate by hyperventilation and reduced pCO2. In this case, however, the pCO2 is raised suggesting the presence of a respiratory component.Therefore, this boy has mixed metabolic and respiratory acidosis, most probably due to severe exacerbation of this asthma, which led to diabetic ketoacidosis.Note:Normal values:pH: 7.35 – 7.45pO2: 10 – 14 kPapCO2: 4.5 – 6 kPaBase excess (BE): -2 – 2 mmol/LHCO3: 22 – 26 mmol/L
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This question is part of the following fields:
- Endocrinology
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Question 7
Incorrect
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A 15-year-old boy is described as having sparse, long, slightly pigmented, downy pubic hair. What is the present stage of pubic hair development in this boy according to the Tanner system?
Your Answer: Stage 3
Correct Answer: Stage 2
Explanation:Based on the clinical presentation, the pubic hair development is in Tanner stage 2.The Tanner stages for pubic hair are as follows:Stage 1 – pre-adolescentStage 2 – sparse hair that is long, slightly pigmented and downyStage 3 – hair spread over the junction of the pubes, darker and coarserStage 4 – adult-type hair, but the area covered is smaller than it is in an adult.Stage 5 – adult in quantity and type
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This question is part of the following fields:
- Endocrinology
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Question 8
Incorrect
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Which of the following statements is true regarding the patterns of secretion of hormones?
Your Answer: FSH, LH, GH and thyroxine are secreted in pulsatile pattern
Correct Answer: Cortisol is secreted in a circadian pattern
Explanation:Cortisol is secreted in a circadian pattern.The secretion of cortisol is regulated by the suprachiasmatic nucleus located in the hypothalamus.Other options:- FSH, LH, GH and prolactin are secreted in a pulsatile pattern, i.e. these hormones are secreted in an episodic manner rather than continuously.- Thyroxine is secreted in a continuous pattern, not pulsatile.- The secretion of ACTH is in response to stress.Secondary to stress, the hypothalamus secretes corticotrophin releasing hormones, which are transported to the pituitary gland via the hypophyseal–portal system. ACTH is then released by the pituitary gland and binds to its receptor on the adrenal gland, which releases cortisol.
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This question is part of the following fields:
- Endocrinology
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Question 9
Incorrect
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A 17-year-old female presents to the clinic with acne, hirsutism and oligomenorrhoea. Which of the following hormonal changes will hint towards the diagnosis of polycystic ovarian syndrome (PCOS)?
Your Answer: Increased FSH
Correct Answer: Raised LH:FSH ratio
Explanation:The European Society of Human Reproduction and Embryology/American Society for Reproductive Medicine Rotterdam consensus (ESHRE/ASRM) developed and enlarged the diagnosis of PCOS, requiring two of three features: anovulation or oligo-ovulation, clinical and/or biochemical hyperandrogenism, and polycystic ovarian morphology (PCOM) seen on ultrasound. Finally the Androgen Excess Society defined PCOS as hyperandrogenism with ovarian dysfunction or polycystic ovaries
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This question is part of the following fields:
- Endocrinology
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Question 10
Correct
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A 15-year-old girl is brought to the OBGYN clinic by her mother with primary amenorrhoea and poor pubertal development. Investigations reveal low oestrogen, and high LH and FSH. Which of the following is the most likely diagnosis?
Your Answer: Turner's syndrome
Explanation:Turner syndrome, a condition that affects only females, results when one of the X chromosomes (sex chromosomes) is missing or partially missing. Turner syndrome can cause a variety of medical and developmental problems, including short height, failure of the ovaries to develop and heart defects.Turner syndrome may be diagnosed before birth (prenatally), during infancy or in early childhood. Occasionally, in females with mild signs and symptoms of Turner syndrome, the diagnosis is delayed until the teen or young adult years.
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This question is part of the following fields:
- Endocrinology
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Question 11
Correct
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Which of the following is true regarding the anterior pituitary gland?
Your Answer: The majority of hormone production occurs in the pars distalis
Explanation:The pituitary gland synthesizes and releases various hormones that affect several organs throughout the body.The pituitary gland is entirely ectodermal in origin but is composed of 2 functionally distinct structures that differ in embryologic development and anatomy: the adenohypophysis (anterior pituitary) and the neurohypophysis (posterior pituitary).The anterior pituitary has three main regions:Pars distalis: Where the main hormone production occursPars tuberalis: Joins the pituitary stalk arising from the posterior pituitary glandPars intermedia: Divides the anterior and posterior parts of the pituitary gland. The pars distalis forms the majority of the adenohypophysis and resembles a typical endocrine gland.
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This question is part of the following fields:
- Endocrinology
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Question 12
Incorrect
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A 16-year-old woman presents with a 7 month history of secondary amenorrhoea and three months history of galactorrhoea. She has been otherwise well. She had menarche at the age of 12 and has otherwise had regular periods. She has been sexually active for approximately one year and has occasionally used condoms for contraception. She smokes five cigarettes daily and occasionally smokes cannabis.On examination, she appears well, and clinically euthyroid, has a pulse of 70 bpm and blood pressure of 112/70 mmHg.Investigations show:Serum oestradiol 130 nmol/L (130-600)Serum LH 4.5 mU/L (2-20)Serum FSH 2.2 mU/L (2-20)Serum prolactin 6340 mU/L (50-450)Free T4 7.2 pmol/L (10-22)TSH 2.2 mU/L (0.4-5.0)What is the most likely diagnosis?
Your Answer: Pregnancy
Correct Answer: Prolactinoma
Explanation:The patient has hyperprolactinaemia with otherwise normal oestradiol, FSH and LH. This is highly suggestive of Prolactinoma rather than a non functioning tumour.In polycystic ovaries, there is increase in the level of LH while FSH is normal or low.
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This question is part of the following fields:
- Endocrinology
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Question 13
Incorrect
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Regarding precocious puberty, which of the following statements is correct?
Your Answer: For the majority of girls there is an underlying medical problem such as a brain tumour, ovarian diseases, thyroid gland problems
Correct Answer: In about 5% of boys, precocious puberty is inherited from the father
Explanation:Precocious puberty is the attainment of normal pubertal biochemical and physical features at an abnormally earlier age. The age cut-offs commonly used to define precocious puberty are 8 years for females and 9 years for males. The onset of normal puberty is triggered by gonadotropic-releasing hormones from the hypothalamus.In most of the familial cases, the condition is transmitted by affected father. In boys, this makes up about 5% of the cases.Full adult height potential is not achieved in patients of precious puberty, although there is an advanced bone maturation.
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This question is part of the following fields:
- Endocrinology
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Question 14
Correct
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An infant was born yesterday with ambiguous genitalia. Mineralocorticoid deficiency and androgen excess are associated with the suspected diagnosis. What is the pathophysiology of the diagnosis?
Your Answer: Deficiency of 21-alphahydroxylase
Explanation:Congenital adrenal hyperplasia is a common cause of virilisation in females that can present as ambiguous genitalia at birth. Deficiency of the 21-alphahydroxylase enzyme is implicated in excess mineralocorticoid and androgens produced by the adrenal gland. Virilisation occurs when excess androgens are converted to testosterone in a genetically female foetus, causing the genitalia to resemble male genitalia. A deficiency of 5-alpha hydroxylase would rather decrease the production of testosterone and lead to the presentation of external female genitalia in a genetically male foetus. Autoantibodies against glutamic acid are seen in type 1 diabetes mellitus, while defects in the AIRE gene and the FOXP3 affect components of the immune system.
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This question is part of the following fields:
- Endocrinology
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Question 15
Correct
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Which among the following is a type of acquired anterior pituitary disorder?
Your Answer: Pituitary adenoma
Explanation:Among the given options, pituitary adenoma is an acquired anterior pituitary disorder which represent between 10 and 25% of all intracranial neoplasms.Other options:- Agenesis of the corpus callosum is characterised by the partial or complete absence of the corpus callosum. This condition is associated with pituitary hormone deficiencies.- Congenital disorders such as hydrocephalus or arachnoid cysts may be a cause of precocious puberty.- Pituitary hypoplasia and septo-optic dysplasia are congenital disorders of the pituitary gland.
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This question is part of the following fields:
- Endocrinology
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Question 16
Correct
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A 16-year-old boy is being treated with ADH for diabetes insipidus. His blood results show:fasting plasma glucose level: 6 mmol/l (3– 6)sodium 148 mmol/l (137–144)potassium 4.5 mmol/l (3.5–4.9)calcium 2.8 mmol/l (2.2–2.6). However, he still complains of polyuria, polydipsia and nocturia.What could be the most probable cause?
Your Answer: Nephrogenic diabetes insipidus
Explanation:Diabetes insipidus (DI) is defined as the passage of large volumes (>3 L/24 hr) of dilute urine (< 300 mOsm/kg). It has the following 2 major forms:Central (neurogenic, pituitary, or neurohypophyseal) DI, characterized by decreased secretion of antidiuretic hormone (ADH| also referred to as arginine vasopressin [AVP])Nephrogenic DI, characterized by decreased ability to concentrate urine because of resistance to ADH action in the kidney.The boy most probably has nephrogenic diabetes insidious (DI) not central DI so he is not responding to the ADH treatment.
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This question is part of the following fields:
- Endocrinology
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Question 17
Correct
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Which of the given clinical features is found in multiple endocrine neoplasia (MEN) type 1?
Your Answer: Carcinoid tumours
Explanation:Multiple endocrine neoplasia type 1 is a rare, autosomal dominant disorder characterized by a higher propensity to develop various endocrine and nonendocrine tumours. The primary endocrine tumours that are a part of this disorder include carcinoid tumours and tumours of parathyroid, enteropancreatic, and anterior pituitary origin. Carcinoid tumours encountered in MEN type 1 are mostly of the foregut region. Non-endocrine tumours found in MEN type 1 include meningiomas and ependymomas, lipomas, angiofibromas, collagenomas, and leiomyomas. The pathogenesis of MEN type 1 is the inactivating mutation of the tumour suppressor gene MEN 1, which encodes the protein menin.
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This question is part of the following fields:
- Endocrinology
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Question 18
Correct
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A 6 year old female child with a history of controlled type 1 diabetes, presents with recurrent nightmares due to hypoglycaemia and early morning glycosuria. Her parents are well informed about the child’s condition and adjust her insulin requirements according to carbohydrate counting. What is the cause of the hypoglycaemia during the night in association with early morning glycosuria?
Your Answer: Somogyi effect
Explanation:Somogyi effect presents with night-time hypoglycaemia followed by early-morning hyperglycaemia, hence the glycosuria.
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This question is part of the following fields:
- Endocrinology
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Question 19
Incorrect
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A 10 year old boy is being bullied by his classmates because he's obese and he is the shortest in his class. His mother is worried and brings him in to the clinic. History reveals he had a renal transplant last year. What is the most likely diagnosis?
Your Answer: Pseudo Cushing’s syndrome
Correct Answer: Cushing’s syndrome
Explanation:The boy had a renal transplant, for which he needs immune suppression. For the exogenous immune suppression an exogenous steroid is needed, which in this case is responsible for the primary Cushing syndrome manifesting with short stature. The administration of steroids before the physiological fusion of the growth plate can lead to premature fusion with permanent cessation of bone growth.
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This question is part of the following fields:
- Endocrinology
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Question 20
Correct
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A 14-year-old girl, in diabetic ketoacidosis, is brought to the emergency room with abdominal pain and vomiting. Arterial blood gases show:pH 7.01, pC02: 2.6, HC03:6, BE-19. The ketones are found to be 4.8. Which of the following most likely explains her blood gas analysis?
Your Answer: Metabolic acidosis with respiratory compensation
Explanation:Diabetes ketoacidosis is one of the most serious and acute complications of diabetes. At the time of presentation and during treatment of diabetic ketoacidosis (DKA), several metabolic and electrolyte derangements can ultimately result in respiratory compromise. Most commonly, hypokalaemia, hypomagnesemia and hypophosphatemia can eventually lead to respiratory muscles failure. Furthermore, tachypnoea, hyperpnea and more severely, Kussmaul breathing pattern can develop. Also, hydrostatic and non-hydrostatic pulmonary oedema can occur secondary to volume shifts into the extracellular space and secondary to increased permeability of the pulmonary capillaries. The presence of respiratory failure in patients with DKA is associated with higher morbidity and mortality. Being familiar with the causes of respiratory compromise in DKA, and how to treat them, may represent better outcomes for patients with DKA.
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This question is part of the following fields:
- Endocrinology
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Question 21
Correct
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Which of the following produces the maximum levels of cortisol in the body?
Your Answer: Zona fasciculata of the adrenal
Explanation:Zona fasciculata of the adrenal produces the maximum levels of cortisol in the body.Functions of cortisol:- Increases blood pressure: permits normal response to angiotensin II and catecholamines by up-regulating alpha-1 receptors on arterioles.- Inhibits bone formation: decreases osteoblasts, type 1 collagen and absorption of calcium from the gut, and increases osteoclastic activity.- Increases insulin resistance.- Increases gluconeogenesis, lipolysis and proteolysis.- Inhibits inflammatory and immune responses.- Maintains function of skeletal and cardiac muscle.An excess of corticosteroids in the body causes various symptoms that are a part of Cushing’s syndrome.
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This question is part of the following fields:
- Endocrinology
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Question 22
Incorrect
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Which of the following is true regarding female puberty?
Your Answer: Adrenarche is responsible for acne
Correct Answer: Adrenarche occurs before thelarche
Explanation:Puberty is the general term for the transition from sexual immaturity to sexual maturity. There are two main physiological events in puberty:- Gonadarche is the activation of the gonads by the pituitary hormones follicle-stimulating hormone (FSH) and luteinizing hormone (LH).- Adrenarche is the increase in production of androgens by the adrenal cortex. It is the term for the maturational increase in adrenal androgen production that normally becomes biochemically apparent at approximately six years of age in both girls and boysA number of other terms describe specific components of puberty:- Thelarche is the appearance of breast tissue, which is primarily due to the action of oestradiol from the ovaries. – Menarche is the time of first menstrual bleed. – Pubarche is the appearance of pubic hair, which is primarily due to the effects of androgens from the adrenal gland. The term is also applied to first appearance of axillary hair, apocrine body odour, and acne.The earliest detectable secondary sexual characteristic on physical examination in most girls is breast/areolar development (thelarche). Ovarian enlargement and growth acceleration typically precede breast development but are not apparent on a single physical examination. Oestrogen stimulation of the vaginal mucosa causes a physiologic leukorrhea, which is a thin, white, non-foul-smelling vaginal discharge that typically begins 6 to 12 months before menarche. Menarche occurs, on average, 2 to 2.5 years after the onset of puberty
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This question is part of the following fields:
- Endocrinology
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Question 23
Correct
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A 17-year-old boy is brought to the endocrinologist by his parents who are worried that he might have delayed growth as all his friends are taller than him. On examination, he has a preadolescent body habitus and no evidence of development of secondary sexual characteristics. Serum LH, FSH, and testosterone all match prepubertal range. Following an injection of GnRH, the LH and FSH concentrations increase only slightly. However, when the GnRH is given daily for 7 days, a normal response is elicited. Which of the following is the most likely causing this boy's delayed puberty?
Your Answer: A hypothalamic disorder
Explanation:Hypogonadotropic hypogonadismIn Kallmann syndrome: impaired migration of GnRH cells and defective olfactory bulb → ↓ GnRH in hypothalamus → ↓ FSH and ↓ LH → ↓ testosterone and ↓ oestrogenIn hypothalamic and/or pituitary lesions: ↓ pituitary gonadotropins (↓ FSH and ↓ LH) → ↓ testosterone and ↓ oestrogen
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This question is part of the following fields:
- Endocrinology
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Question 24
Incorrect
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Bone age would be delayed in which of the following conditions?
Your Answer: Beckwith-Wiedemann syndrome in a 7 year old boy
Correct Answer: Trisomy 21 in a 10 year old boy
Explanation:Bone age is used to determine the maturation of a child’s bones’ and is used to detect pathological growth. This is done using the X-ray of the wrist. Several conditions can either advance or delay the bone age such that they may not match the child’s chronological age. Bone age is advanced in conditions where there are prolonged or elevated sex hormone levels such as precocious puberty, or in genetic overgrowth conditions such as Beckwith-Wiedemann syndrome. Bone age is delayed in constitutional growth delay, chronic ill health, endocrine disorders such as growth hormone deficiencies or hypothyroidism, genetic disorders such as Trisomy 21, Trisomy 18, and Turner’s syndrome. Obesity is unlikely to cause growth delay.
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This question is part of the following fields:
- Endocrinology
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Question 25
Incorrect
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A 16-year-old boy is brought to the clinic by his parents, who are concerned that he is shorter than the other boys at school, despite having attained puberty. His father is 1.70 m tall, and his mother is 1.50 m tall. Given his parents height, what is his adult height potential?
Your Answer: 1.53 m
Correct Answer: 1.67 m
Explanation:The adult height potential may be calculated for a male child by (father’s height in cm + mother’s height in cm) / 2 then add 7 cm.In the scenario provided: (170 + 150)/2 + 7 = 167 cm = 1.67 m.For a female child by (father’s height in cm + mother’s height in cm) / 2 then minus 7 cm.This can then be plotted on a height centile chart to find the mid-parental centile.Causes of short stature include:- Normal variant (often familial)- Constitutional delay of growth and puberty- Chronic illness, e.g. cystic fibrosis, inflammatory bowel disease- Endocrine: growth hormone deficiency, hypothyroidism, steroid excess syndromes: Turner’s, Down’s, Prader-Willi- Skeletal dysplasias, e.g. achondroplasia
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This question is part of the following fields:
- Endocrinology
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Question 26
Correct
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Which of the given electrolyte imbalances is a clinical feature of adrenal insufficiency?
Your Answer: Hyponatraemia
Explanation:Adrenal insufficiency is a serious medical condition that leads to inadequate secretion of corticosteroids. The consequences of this deficiency are numerous electrolyte and acid-base imbalances, which include hyponatremia, hyperkalaemia, hypercalcemia, hypoglycaemia, metabolic alkalosis, and dehydration.
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This question is part of the following fields:
- Endocrinology
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Question 27
Correct
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A 16-year-old boy presents with poor development of secondary sex characteristics, colour blindness and a decreased sense of smell. On examination, his testes are located in the scrotum and are small and soft. What is the most likely diagnosis for this boy?
Your Answer: Kallmann’s syndrome
Explanation:Based on the clinical scenario, the most probable diagnosis in this patient is Kallmann’s syndrome.Kallmann’s syndrome is due to isolated gonadotrophin-releasing hormone (GnRH) deficiency. It is often inherited in an X-linked recessive manner. Other options:- While Klinefelter’s syndrome is also associated with hypogonadism, the other clinical features of Klinefelter’s are not seen. – Cryptorchidism is ruled out by the presence of testes in the scrotum. – The presentation of the child is not suggestive of mumps orchitis or hyperprolactinaemia.
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This question is part of the following fields:
- Endocrinology
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Question 28
Correct
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A 6 year old female presents with an increase in the size of her breasts and light hair on the border of the labia majora. Her mother worries she might be having premature puberty. What is her Tanner stage?
Your Answer: II
Explanation:Tanner stage two presents with the following: Downy hair, Breast bud palpable under areola (1st pubertal sign in females).Stage 1 (prepubertal) – elevation of papilla only – no pubic hairStage 2 – breast bud forms – sparse, slightly pigmented hair on labia majoraStage 3 – Breast begins to become elevated, extends beyond areola borders – hair becomes more coarse and curlyStage 4 – increased size and elevation. Areola and papilla form secondary mound – adult like, but sparing medial thighsStage 5 – final size, areola returns but papilla remains projected – hair extends to medial thighs
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This question is part of the following fields:
- Endocrinology
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Question 29
Correct
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A 40-week-old baby presented with a weak cry and failure to thrive. The mother gives a history of prolonged neonatal jaundice and says it is common in her family. On examination, a large tongue was noticed. What is the most likely diagnosis?
Your Answer: Congenital hypothyroidism
Explanation:Congenital hypothyroidism is associated with failure to thrive, macroglossia, prolonged jaundice of a new-born and constipation.
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This question is part of the following fields:
- Endocrinology
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Question 30
Correct
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Which of the following statements is MOST appropriate for Turner Syndrome?
Your Answer: Fetal loss in the first trimester is common
Explanation:Turners syndrome is a chromosomal syndrome affecting the development of females. In this condition, all or part of the X chromosome gets deleted, producing the Karyotype 45 XO or 45XO/46XX. Spontaneous foetal loss is common in the first trimester, but foetuses which survive are born small for date, and may have lymphedema, and poor feeding in the neonatal period. These patients face numerous medical and developmental problems throughout their lifetimes including growth and puberty failure due to premature ovarian failure/ hypergonadotropic hypogonadism. However spontaneous puberty can be seen in up to 20% of females with Turner’s syndrome.
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This question is part of the following fields:
- Endocrinology
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