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  • Question 1 - A 25 year-old female medical student presents with fever, lack of appetite, rashes,...

    Correct

    • A 25 year-old female medical student presents with fever, lack of appetite, rashes, sore throat and lymphadenopathy. Peripheral smear shows atypical lymphocytes. Which is the most likely organism responsible for this patient's condition?

      Your Answer: Epstein–Barr virus

      Explanation:

      Epstein-Barr virus is in the herpes family of viruses and most people will become infected with EBV sometime during their lives. EBV commonly causes infectious mononucleosis, or mono, a contagious viral illness that initially attacks the lymph nodes in the neck and throat. When these tissues become less effective in fighting infection, sore throats, swelling of the nodes and fever may result.

    • This question is part of the following fields:

      • Microbiology
      • Pathology
      58984.2
      Seconds
  • Question 2 - A 27-year-old HIV patient started on an antifungal agent. Which antifungal agent that...

    Correct

    • A 27-year-old HIV patient started on an antifungal agent. Which antifungal agent that inhibits the biosynthesis of fungal ergosterol was given to the patient?

      Your Answer: Ketoconazole

      Explanation:

      Ketoconazole is a synthetic imidazole antifungal drug used primarily to treat fungal infections. It inhibits the biosynthesis of ergosterol by blocking demethylation at the C14 site of the ergosterol precursor. Amphotericin B and Nystatin impair permeability of the cell membrane. Flucytosine interferes with DNA synthesis, while the target of griseofulvin is the microtubules

    • This question is part of the following fields:

      • Microbiology
      • Pathology
      1.6
      Seconds
  • Question 3 - A 26-year-old female patient had the following blood report: RBC count =...

    Correct

    • A 26-year-old female patient had the following blood report: RBC count = 4. 0 × 106/μl, haematocrit = 27% and haemoglobin = 11 g/dl, mean corpuscular volume (MCV) = 90 fl, mean corpuscular haemoglobin concentration (MCHC) = 41 g/dl. Further examination of blood sample revealed increased osmotic fragility of the erythrocytes. Which of the following is the most likely cause of this patient’s findings?

      Your Answer: Spherocytosis

      Explanation:

      Spherocytes are small rounded RBCs. It is due to an inherited defect of the RBC cytoskeleton membrane tethering proteins. Membrane blebs form that are lost over time and cells become round instead of biconcave. As it is a normochromic anaemia, the MCV is normal. it is diagnosed by osmotic fragility test which reveals increased fragility in a hypotonic solution.

    • This question is part of the following fields:

      • General
      • Physiology
      2
      Seconds
  • Question 4 - A 55 year old man presented with a 4 day history of cough...

    Correct

    • A 55 year old man presented with a 4 day history of cough and fever. His sputum culture showed the presence of Strep pneumoniae. Which of the following substances produced by the inflammatory cells will result in effective clearance of this organism from the lung parenchyma?

      Your Answer: Hydrogen peroxide

      Explanation:

      Hydrogen peroxide is produced by myeloperoxidase to form a potent oxidant that eliminates bacteria, but is not effective in chronic granulomatous diseases.

      Platelet activating factor will lead to the activation, adhesion and aggregation of platelets but will not directly kill bacteria.

      Prostaglandins cause vasodilation but do not activate neutrophils.

      Kallikrein promotes formation of bradykinin that leads to vasodilation.

      Leukreines increase vascular permeability.

      Cytokines are communicating molecules between immune cells but directly will not kill bacteria.

      Interleukins will regulate the immune response.

    • This question is part of the following fields:

      • Inflammation & Immunology; Respiratory
      • Pathology
      4.2
      Seconds
  • Question 5 - What is the result of maltase deficiency in the brush border of the...

    Correct

    • What is the result of maltase deficiency in the brush border of the small intestine?

      Your Answer: Results in increased passage of maltose in stool

      Explanation:

      Maltase is an enzyme produced from the surface cells of the villi, lining the small intestine and aids in hydrolysing the disaccharide maltose, which splits into two molecules of α-glucose. It is done by breaking the glycosidic bond between the ‘first’ carbon of one glucose and the ‘fourth’ carbon of the other (a 1–4 bond). Hence, a deficiency of enzyme maltase will result in the increased passage of maltose in the stool.

    • This question is part of the following fields:

      • Gastroenterology
      • Physiology
      2.5
      Seconds
  • Question 6 - During uterogrowth, the second pharyngeal arch gives rise to which structures? ...

    Correct

    • During uterogrowth, the second pharyngeal arch gives rise to which structures?

      Your Answer: Stylohyoid muscle

      Explanation:

      The second pharyngeal arch or hyoid arch, is the second of six pharyngeal arches that develops in fetal life during the fourth week of development and assists in forming the side and front of the neck. Derivatives:

      Skeletal – From the cartilage of the second arch arises:

      Stapes,

      Temporal styloid process,

      Stylohyoid ligament, and

      Lesser cornu of the hyoid bone.

      Muscles:

      Muscles of face

      Occipitofrontalis muscle

      Platysma

      Stylohyoid muscle

      Posterior belly of Digastric

      Stapedius muscle

      Auricular muscles

      Nerve supply: Facial nerve

    • This question is part of the following fields:

      • Anatomy
      • Embryology
      3.2
      Seconds
  • Question 7 - A 40-year old gentleman, known with a history of peptic ulcer disease, was...

    Correct

    • A 40-year old gentleman, known with a history of peptic ulcer disease, was brought to the clinic in a dehydrated state with persistent vomiting. His blood investigations revealed:
      • sodium = 142 mmol/l
      • potassium = 2.6 mmol/l
      • chloride = 85 mmol/l
      • pH = 7.55
      • p(CO2) = 50 mmHg
      • p(O2) = 107 mmHg
      • standard bicarbonate = 40 mmol/l
      This patient has a:

      Your Answer: Metabolic alkalosis

      Explanation:

      High pH with high standard bicarbonate indicates metabolic alkalosis. The pa(CO2) was appropriately low in compensation. This is hypokalaemic hypochloraemic metabolic acidosis due to prolonged vomiting. Treatment includes treating the cause and intravenous sodium chloride with potassium.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      4.3
      Seconds
  • Question 8 - Bile salt reuptake principally occurs where? ...

    Correct

    • Bile salt reuptake principally occurs where?

      Your Answer: In the ileum

      Explanation:

      90 – 95% of the bile salts are absorbed from the small intestine (mostly terminal ileum and then excreted again from the liver. This is known as the enterohepatic circulation. The entire pool recycles twice per meal and approximately 6 to 8 times per day.

    • This question is part of the following fields:

      • Gastroenterology
      • Physiology
      3.4
      Seconds
  • Question 9 - An infant, 5 weeks and 6 days old born with a large sub-aortic...

    Correct

    • An infant, 5 weeks and 6 days old born with a large sub-aortic ventricular septal defect, is prepared for pulmonary artery banding through a left thoracotomy (the child is not fit for a surgical closure). The surgeon initially passes his index finger immediately behind two great arteries in the pericardial sac to mobilise the great arteries in order to pass the tape around the pulmonary artery. Into which space is the surgeon's finger inserted?

      Your Answer: Transverse pericardial sinus

      Explanation:

      Cardiac notch: is an indentation on the left lung of the heart.

      Coronary sinus: a venous sinus on the surface of the heart (the posterior aspect) that receives blood from the smaller veins that drain the heart.

      Coronary sulcus: a groove on the heart between the atria and ventricles.

      Transverse pericardial sinus: located behind the aorta and pulmonary trunk and anterior to the superior vena cava.

      Oblique pericardial sinus: located behind the left atrium. Accessed from the inferior side (or the apex) of the heart upwards.

      Horizontal pericardial sinus: this is a made-up term.

    • This question is part of the following fields:

      • Anatomy
      • Thorax
      3.2
      Seconds
  • Question 10 - Which statement is correct regarding secretions from the adrenal glands? ...

    Correct

    • Which statement is correct regarding secretions from the adrenal glands?

      Your Answer: Aldosterone is producd by the zona glomerulosa

      Explanation:

      The secretions of the adrenal glands by zone are:

      Zona glomerulosa – aldosterone

      Zona fasciculata – cortisol and testosterone

      Zona reticularis – oestradiol and progesterone

      Adrenal medulia – adrenaline, noradrenaline and dopamine.

    • This question is part of the following fields:

      • Physiology
      • Renal
      5.8
      Seconds
  • Question 11 - Which of the following structures is derived from the dorsal mesogastrium of the...

    Correct

    • Which of the following structures is derived from the dorsal mesogastrium of the stomach during the development of the gut?

      Your Answer: Greater omentum

      Explanation:

      In a developing foetus, the stomach has two mesogastria from which most of the abdominal ligaments develop. These two mesogastria are the; ventral mesogastrium and the dorsal mesogastrium. During the embryological development of the gut, different organs develop in each mesogastrium; the spleen and pancreas in the dorsal mesogastrium while the liver in the ventral mesogastrium (with their associated ligaments). In the dorsal mesogastrium the following structures develop; the greater omentum (containing the gastrophrenic ligament and the gastrocolic ligament), gastrosplenic ligament, mesentery, splenorenal ligament and phrenicocolic ligament. The structures that develop from the ventral mesogastrium include the; lesser omentum (containing the hepatoduodenal ligament and the hepatogastric ligament) in association with the liver; the coronary ligament (left triangular ligament, right triangular ligament and hepatorenal ligament) and the falciform ligament (round ligament of liver and ligamentum venosum within).

      There are also folds that develop from the dorsal mesogastrium which include; umbilical folds, supravesical fossa, medial inguinal fossa, lateral umbilical fold, lateral inguinal fossa and Ileocecal fold.

    • This question is part of the following fields:

      • Abdomen
      • Anatomy
      10.1
      Seconds
  • Question 12 - A patient who has used NSAIDS for many years presents to the A&E...

    Incorrect

    • A patient who has used NSAIDS for many years presents to the A&E with symptoms of acute haemorrhagic shock. An emergency endoscopy is done that shows that a duodenal ulcer has perforated the posterior wall of the first part of the duodenum. Which artery is most likely to be the cause of the haemorrhage?

      Your Answer: Superior mesenteric

      Correct Answer: Gastroduodenal

      Explanation:

      The gastroduodenal artery is a branch of the hepatic artery and descends near the pylorus between the first part of the duodenum and the neck of the pancreas to divide at the lower border of the duodenum into the right gastroepiploic and pancreaticoduodenal arteries. Before it divides, it gives off a few branches to the pyloric end of the stomach and to the pancreas. The artery that is most likely involved in this situation is the gastroduodenal artery since it is posterior to the first part of the duodenum.

    • This question is part of the following fields:

      • Abdomen
      • Anatomy
      4.3
      Seconds
  • Question 13 - Which of the following muscles aid in inspiration? ...

    Correct

    • Which of the following muscles aid in inspiration?

      Your Answer: Diaphragm and external intercostals

      Explanation:

      The diaphragm and external intercostals are muscles of inspiration as they increase the volume of thoracic cavity and reduce the intrathoracic pressure. Muscles of expiration include abdominal muscles and internal intercostals.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      8.6
      Seconds
  • Question 14 - Cervical intraepithelial neoplasia on Pap smear of a 34-year old lady is most...

    Correct

    • Cervical intraepithelial neoplasia on Pap smear of a 34-year old lady is most likely associated with which of the following?

      Your Answer: Human papillomavirus infection

      Explanation:

      CIN (Cervical intraepithelial neoplasia) is considered a precursor of cervical cancer and is likely caused due to infection with human papillomavirus (HPV) types 16, 18, 31, 33, 35 or 39. The risk factors for cervical cancer include multiple sex partners, young age at the time of first intercourse, intercourse with men whose previous partners had cervical cancer. Also, smoking and immunodeficient states are considered contributory. CIN is graded as mild (grade I), moderate (grade II) and severe dysplasia or carcinoma in situ (grade III). CIN III rarely regresses spontaneously and can lead to invasive carcinoma by invading the basement membrane. Squamous cell carcinomas are the commonest cervical cancer seen in 80-85% of all cases. Others are commonly adenocarcinomas. Cervical cancer can spread by direct extension, lymphatic spread to pelvic and para-aortic nodes or by hematogenous route.

    • This question is part of the following fields:

      • Pathology
      • Women's Health
      2.6
      Seconds
  • Question 15 - The most likely cause of prominent U waves on the electrocardiogram (ECG) of...

    Correct

    • The most likely cause of prominent U waves on the electrocardiogram (ECG) of a patient is:

      Your Answer: Hypokalaemia

      Explanation:

      The U-wave, not always visible in ECGs, is thought to represent repolarisation of papillary muscles or Purkinje fibres. When seen, it is very small and occurs after the T-wave. Inverted U-waves indicate myocardial ischaemia or left ventricular volume overload. Prominent U-waves are most commonly seen in hypokalaemia. Other causes include hypercalcaemia, thyrotoxicosis, digitalis exposure, adrenaline and class 1A and 3 anti-arrhythmic agents. It can also be seen in congenital long-QT syndrome and in intracranial haemorrhage.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      3.5
      Seconds
  • Question 16 - During gastrectomy, the operating surgeon ligates the short gastric arteries along the greater...

    Correct

    • During gastrectomy, the operating surgeon ligates the short gastric arteries along the greater curvature of the stomach. Where do the short gastric arteries branch from?

      Your Answer: Splenic artery

      Explanation:

      Short gastric arteries arise from the splenic artery at the end or from its terminal divisions. They are about 5 or 7 in number, passing from the left to the right in between the layers of the gastrosplenic ligament to be distributed along the greater curvature of the stomach.

    • This question is part of the following fields:

      • Abdomen
      • Anatomy
      8.5
      Seconds
  • Question 17 - Which of the following over-the-counter drugs can cause a prolonged bleeding time? ...

    Correct

    • Which of the following over-the-counter drugs can cause a prolonged bleeding time?

      Your Answer: Acetylsalicylic acid

      Explanation:

      Acetylsalicylic acid, or aspirin, is a nonsteroidal anti-inflammatory drug that is widely used as an analgesic and antipyretic. Aspirin is as a cyclo-oxygenase inhibitor that leads to decreased prostaglandin production. Decreased platelet aggregation is another effect of this drug, achieved by long-lasting use of aspirin.

    • This question is part of the following fields:

      • Haematology
      • Pathology
      4.6
      Seconds
  • Question 18 - A victim of mob justice was brought to the A & E with...

    Correct

    • A victim of mob justice was brought to the A & E with a stab wound in the anterior chest 2 cm lateral to the left sternal border. He underwent an emergency thoracotomy that revealed clots in the pericardium, with a puncture wound in the right ventricle. To evacuate the clots from the pericardial cavity the surgeon slipped his hand behind the heart at its apex. He extended his finger upwards until its tip was stopped by a line of pericardial reflection which forms the:

      Your Answer: Oblique pericardial sinus

      Explanation:

      Transverse sinus: part of pericardial cavity that is behind the aorta and pulmonary trunk and in front of the superior vena cava separating the outflow vessels from the inflow vessels.

      Oblique pericardial sinus: is behind the left atrium where the visceral pericardium reflects onto the pulmonary veins and the inferior vena cava. Sliding a finger under the heart will take you to this space.

      Cardiac notch: indentation of the ‘of the heart’ on the superior lobe of the left lung.

      Hilar reflection: the reflection of the pleura onto the root of the lung to continue as mediastinal pleura.

      Costomediastinal recess: part of the pleural sac where the costal pleura transitions to become the mediastinal pleura.

      Sulcus terminalis: a groove between the right atrium and the vena cava

    • This question is part of the following fields:

      • Anatomy
      • Thorax
      9.5
      Seconds
  • Question 19 - An 18 -year-old female is diagnosed with folliculitis in the left axilla. What...

    Correct

    • An 18 -year-old female is diagnosed with folliculitis in the left axilla. What is the most likely organism that could cause this condition?

      Your Answer: Staphylococcus aureus

      Explanation:

      Folliculitis is the inflammation of the hair follicles. It is usually caused by Staphylococcus infection.

    • This question is part of the following fields:

      • Microbiology
      • Pathology
      3.9
      Seconds
  • Question 20 - Which of the following mediators of inflammation requires arachidonic acid for synthesis? ...

    Incorrect

    • Which of the following mediators of inflammation requires arachidonic acid for synthesis?

      Your Answer: Interleukin-1

      Correct Answer: Prostaglandins

      Explanation:

      Arachidonic acid is normally present in the phospholipids that make up the cell membrane and is cleaved by phospholipase A2 from the phospholipid. Arachidonic acid is a precursor for the production of eicosanoids which include: 1) prostaglandins, prostacyclins and thromboxane, 2) leukotrienes and 3) anandamides. The production of these products along with their action on the body is called the arachidonic acid cascade.

    • This question is part of the following fields:

      • Inflammation & Immunology
      • Pathology
      10.8
      Seconds
  • Question 21 - A patient with Paget's disease of the bone is predisposed to developing which...

    Correct

    • A patient with Paget's disease of the bone is predisposed to developing which type of cancer?

      Your Answer: Osteosarcoma

      Explanation:

      Paget’s disease of bone (PDB) is a focal disorder of bone. It is presumed benign in nature and mediated by abnormal osteoclast function. However osteosarcomas may occur in <1% of patients with Paget's disease of the bone. Osteosarcomas are osteogenic in origin, and consistently arise in sites of pagetic bone. This is not to be confused with Paget's disease of the breast.

    • This question is part of the following fields:

      • Neoplasia
      • Pathology
      4.9
      Seconds
  • Question 22 - A 36-year old gentleman with a history of cough for 4 weeks came...

    Correct

    • A 36-year old gentleman with a history of cough for 4 weeks came to the hospital. Examination revealed multiple lymphadenopathy with splenomegaly. Investigations revealed haemoglobin 11 g/dl, haematocrit 32.4%, mean corpuscular volume (MCV) 93 fl, white blood cell count 63 × 109/l, and platelet count 39 × 109/l; along with characteristic Auer rods on peripheral blood smear. What is the likely diagnosis?

      Your Answer: Acute myelogenous leukaemia (AML)

      Explanation:

      AML, or acute myeloid leukaemia is the commonest acute leukaemia affecting adults. increasing in incidence with age. It is a malignancy of the myeloid line of white blood cells. It results in rapid proliferation of abnormal cells, which accumulate in the marrow. Interference with normal cell production leads to a drop in red blood cells, white blood cells and platelets. This causes symptoms such as tiredness, shortness of breath, tendency to bleed or bruise easily and recurrent infections. AML is known to progress quickly and can lead to death in weeks and months if not treated. Leukemic blasts of AML show presence of Auer rods. These are clumps of azurophilic granular material that form needles in the cytoplasm. Composed of fused lysosomes, these contain peroxidase, lysosomal enzymes and crystalline inclusions. Auer rods are classically present in myeloid blasts of M1, M2, M3 and M4 acute leukaemia. They also help to distinguish the preleukemia myelodysplastic syndromes.

    • This question is part of the following fields:

      • Haematology
      • Pathology
      38.3
      Seconds
  • Question 23 - A child presents with hypertension. Serum potassium analysis shows hypokalaemia. What is the...

    Incorrect

    • A child presents with hypertension. Serum potassium analysis shows hypokalaemia. What is the most likely diagnosis?

      Your Answer: Bartter Syndrome

      Correct Answer: Liddle syndrome

      Explanation:

      Liddle’s syndrome,  is an autosomal dominant disorder, that is characterized by early, and frequently severe, high blood pressure associated with low plasma renin activity, metabolic alkalosis, low blood potassium, and normal to low levels of aldosterone. Liddle syndrome involves abnormal kidney function, with excess reabsorption of sodium and loss of potassium from the renal tubule. Bartter Syndrome also presents with hypokalaemia, however blood pressure of these patients is usually low or normal.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Pathology
      21.1
      Seconds
  • Question 24 - A 59-year-old man was brought to the emergency department by his family after...

    Correct

    • A 59-year-old man was brought to the emergency department by his family after complaining of sudden, severe upper back pain and a ripping sensation, that radiated to his neck. On arrival, his pulse was weak in one arm compared with the other however his ECG result was normal. Which of the following is most probably the cause of these findings and symptoms?

      Your Answer: Acute aortic dissection

      Explanation:

      Acute aortic dissection is a serious condition in which the inner layer of the aorta tears and the blood flows in between the inner and middle layers of the aorta causing their separation (dissection). Aortic dissection can lead to rupture or decreased blood flow to organs. Clinical manifestations most often include the sudden onset of severe, tearing or ripping chest pain that can radiate to the shoulder, back or neck; syncope; altered mental status; dyspnoea; pale skin; stroke symptoms etc. The diagnosis of acute aortic dissection is based on clinical findings, imaging studies, electrocardiography and laboratory analysis.

    • This question is part of the following fields:

      • Cardiovascular
      • Pathology
      35.7
      Seconds
  • Question 25 - The inferior palpebral nerve ascends behind the orbicularis oculi. What is the terminal...

    Correct

    • The inferior palpebral nerve ascends behind the orbicularis oculi. What is the terminal branch of the inferior palpebral nerve?

      Your Answer: Infraorbital nerve

      Explanation:

      The inferior palpebral nerve is a branch of the maxillary nerve. It supplies the skin and conjunctiva of the lower eyelid.

    • This question is part of the following fields:

      • Anatomy
      • Head & Neck
      18.9
      Seconds
  • Question 26 - A CT scan of 65 year old male patient at an outpatient clinic...

    Correct

    • A CT scan of 65 year old male patient at an outpatient clinic suggested a bone tumour at the stylomastoid foramen. Which of the following cranial nerves is likely to be affected with this tumour?

      Your Answer: VII

      Explanation:

      Cranial nerve VII, the facial nerve, is found in the internal acoustic canal and runs through this canal into the facial canal before exiting through the stylomastoid foramen. In the case of a bone tumour at the stylomastoid process, the facial nerve is the nerve that will most likely be affected.

    • This question is part of the following fields:

      • Anatomy
      • Head & Neck
      9.8
      Seconds
  • Question 27 - In which of the following conditions will the oxygen-haemoglobin dissociation curve shift to...

    Correct

    • In which of the following conditions will the oxygen-haemoglobin dissociation curve shift to the right?

      Your Answer: Exercise

      Explanation:

      The oxygen-haemoglobin dissociation curve plots saturated haemoglobin against the oxygen tension and is usually a sigmoid plot. Each molecule of haemoglobin can bind to four molecules of oxygen reversibly. Factors that can influence the binding include: pH, concentration of 2,3-diphosphoglycerate (2,3-DPG), temperature, type of haemoglobin molecules, and presence of toxins, especially carbon monoxide. Shape of the curve is due to interaction of bound oxygen molecules with the incoming molecules. The binding of first molecule is difficult, with easier binding of the second and third molecule and increase in difficulty with the fourth molecule – partly as a result of crowding and partly as a natural tendency of oxygen to dissociate.

      Left shift of curve indicates haemoglobin’s increased affinity for oxygen (seen at lungs). Right shift indicates decreased affinity and is seen with an increase in body temperature, hydrogen ions, 2,3-diphosphoglycerate (DPG), carbon dioxide concentration and exercise. Under normal resting conditions in a healthy individual, the normal position of the curve is at a pH of 7.4. A shift in the position of the curve with a change in pH is called the Bohr effect. Left shift occurs in acute alkalosis, decrease in p(CO2), decrease in temperature and decrease in 2,3-DPG. The fetal haemoglobin curve is to the left of the adult haemoglobin to allow for oxygen diffusion across the placenta. The curve for myoglobin is even further to the left. Carbon monoxide has a much higher affinity for haemoglobin than oxygen does. Thus, carbon monoxide poisoning leads to hypoxia.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      12.4
      Seconds
  • Question 28 - Blood supply to the posterior compartment of the thigh is supplied by which...

    Incorrect

    • Blood supply to the posterior compartment of the thigh is supplied by which artery?

      Your Answer: Peroneal

      Correct Answer: Perforating

      Explanation:

      There are usually 3 perforating arteries:

      The first gives branches to the adductor brevis and magnus, biceps femoris and gluteus maximus and anastomoses with the inferior gluteal, medial and lateral femoral circumflex.

      The second artery supplies the posterior femoral muscles and anastomose with the first and third perforating vessels.

      The third supplies the posterior femoral muscles.

    • This question is part of the following fields:

      • Anatomy
      • Lower Limb
      16.6
      Seconds
  • Question 29 - Evaluation of a 60-year old gentleman, who has been a coal miner all...

    Incorrect

    • Evaluation of a 60-year old gentleman, who has been a coal miner all his life and is suspected to have pulmonary fibrosis reveals the following: FEV1 of 75% (normal > 65%), arterial oxygen saturation 92%, alveolar ventilation 6000 ml/min at a tidal volume of 600 ml and a breathing rate of 12 breaths/min. There are also pathological changes in lung compliance and residual volume. Calculate his anatomical dead space.

      Your Answer:

      Correct Answer: 100 ml

      Explanation:

      Dead space refers to inhaled air that does not take part in gas exchange. Because of this dead space, taking deep breaths slowly is more effective for gas exchange than taking quick, shallow breaths where a large proportion is dead space. Use of a snorkel by a diver increases the dead space marginally. Anatomical dead space refers to the gas in conducting areas such as mouth and trachea, and is roughly 150 ml (2.2 ml/kg body weight). This corresponds to a third of the tidal volume (400-500 ml). It can be measured by Fowler’s method, a nitrogen wash-out technique. It is posture-dependent and increases with increase in tidal volume. Physiological dead space is equal to the anatomical dead space plus the alveolar dead space, where alveolar dead space is the area in the alveoli where no effective exchange takes place due to poor blood flow in capillaries. This physiological dead space is very small normally (< 5 ml) but can increase in lung diseases. Physiological dead space can be measured by Bohr’s method. Total ventilation per minute (minute ventilation) is given by the product of tidal volume and the breathing rate. Here, the total ventilation is 600 ml times 12 breaths/min = 7200 ml/min. The problem mentions alveolar ventilation to be 6000 ml/min. Thus, the difference between the alveolar ventilation and total ventilation is 7200 – 6000 ml/min = 1200 ml/min, or 100 ml per breath at 12 breaths per min. This 100 ml is the dead space volume.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      0
      Seconds
  • Question 30 - A 60 year old patient with a history of carcinoma of the head...

    Incorrect

    • A 60 year old patient with a history of carcinoma of the head of the pancreas, and obstructive jaundice presents with a spontaneous nose bleed and easy bruising. What is the most likely reason for this?

      Your Answer:

      Correct Answer: Vitamin-K-dependent clotting factors deficiency

      Explanation:

      Vitamin K is a fat soluble vitamin requiring fat metabolism to function properly to allow for its absorption. People with obstructive jaundice develop vitamin k deficiency as fat digestion is impaired. Vit K causes carboxylation of glutamate residue and hence regulates blood coagulation including: prothrombin (factor II), factors VII, IX, X, protein C, protein S and protein Z.

    • This question is part of the following fields:

      • General
      • Physiology
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Microbiology (3/3) 100%
Pathology (9/11) 82%
General (1/1) 100%
Physiology (8/8) 100%
Inflammation & Immunology; Respiratory (1/1) 100%
Gastroenterology (2/2) 100%
Anatomy (7/9) 78%
Embryology (1/1) 100%
Respiratory (3/3) 100%
Thorax (2/2) 100%
Renal (1/1) 100%
Abdomen (2/3) 67%
Women's Health (1/1) 100%
Cardiovascular (2/2) 100%
Haematology (2/2) 100%
Inflammation & Immunology (0/1) 0%
Neoplasia (1/1) 100%
Fluids & Electrolytes (0/1) 0%
Head & Neck (2/2) 100%
Lower Limb (0/1) 0%
Passmed