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Question 1
Correct
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Which nerve does NOT pass through the posterior triangle of the neck?
Your Answer: Ansa cervicalis
Explanation:The sternocleidomastoid muscle divides the neck into anterior and posterior triangles on both sides of the neck.
The posterior triangle has the following boundaries:
anteriorly – sternocleidomastoid muscle
posteriorly – trapezius
roof – investing layer of deep cervical fascia
floor – prevertebral fascia overlying splenius capitis, levator scapulae, and the scalene musclesThe contents of the posterior triangle are:
1. fat
2. lymph nodes (level V)
3. accessory nerve
4. cutaneous branches of the cervical plexus – greater auricular nerve, transverse cervical nerve, lesser occipital nerve, supraclavicular nerve (A major branch of this plexus is the phrenic nerve, which arises from the anterior divisions of spinal nerves C3-C5)
5. inferior belly of omohyoid
6. branches of the thyrocervical trunk (transverse cervical and suprascapular arteries)
7. third part of the subclavian artery
8. external jugular vein -
This question is part of the following fields:
- Anatomy
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Question 2
Correct
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A previously fit 26-year-old is undergoing surgery to repair an inguinal hernia. He is breathing on his own, and a supraglottic airway is being maintained via a circle system with air/oxygen and sevoflurane.
With a fresh gas flow of 14 L/min, the end-tidal CO2 reading is 8.1 kPa. CO2 pressure is 1.9 kPa. The percentages of oxygen inhaled and exhaled are 38 and 33 percent, respectively.
What do you think is the most likely source for these readings?Your Answer: Incompetent expiratory valve
Explanation:The patient is rebreathing carbon dioxide that has been exhaled.
Exhaustion of the soda lime and failure of the expiratory valve are the two most likely causes. A leak in the inspiratory limb is a less likely cause. Increased inhaled and exhaled carbon dioxide levels may appear with a normal-looking capnogram if the expiratory valve is ineffective.
The patient will exhale into both the inspiratory and expiratory limbs if the inspiratory valve is inoperable. A slanted downstroke inspiratory phase (as the patient inhales carbon dioxide-containing gas from the inspiratory limb) and increased end-tidal carbon dioxide can be seen on the capnogram.
Even if the soda lime were exhausted, a high fresh gas flow would be enough to prevent rebreathing. The difference in oxygen concentrations in inspired and expired breaths would be less pronounced.
Hypercapnia is caused by respiratory obstruction and malignant hyperthermia, but not by rebreathing.
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This question is part of the following fields:
- Pathophysiology
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Question 3
Incorrect
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Which of the following best describes why phenytoin's hepatic extraction ratio is low?
Your Answer: It has an extensive first pass metabolism when given orally
Correct Answer: It has a clearance that is insensitive to changes in liver blood flow
Explanation:The following are the pharmacokinetic properties of drugs with a low hepatic extraction ratio:
Changes in liver blood flow have no effect on drug clearance.
When given orally, drug clearance is extremely sensitive to changes in protein binding, intrinsic metabolism, and excretion, and there is no first-pass metabolism.Warfarin and phenytoin are two drugs with low hepatic extraction ratios.
The following are the pharmacokinetic properties of drugs with a high hepatic extraction ratio:
When taken orally, undergo extensive first-pass metabolism; drug clearance is dependent on liver blood flow, and drug clearance is less sensitive to changes in protein binding and intrinsic metabolism.
Morphine, lidocaine, propranolol, and etomidate are examples of drugs with high hepatic extraction ratios.
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This question is part of the following fields:
- Pharmacology
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Question 4
Correct
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You've been summoned to the paediatric ward after a 4-year-old child was discovered 'collapsed' in bed.
The child had been admitted the day before with febrile convulsions and was scheduled to be discharged. It is safe to approach the child.
What should your first life-saving action be?Your Answer: Apply a gentle stimulus and ask the child if they are alright
Explanation:Paediatric life support differs from adult life support in that hypoxia is the primary cause of deterioration.
After checking for danger, the child should be given a gentle stimulus (such as holding the head and shaking the arm) and asked, Are you alright? according to current advanced paediatric life support (APLS) guidelines. Safety, Stimulate, Shout is a phrase that is frequently remembered. Any airway assessment should be preceded by these actions.
Although the algorithm includes five rescue breaths, they are performed after the airway assessment.
It is not recommended to ask parents to leave unless they are obstructing the resuscitation. A team member should be with them at all times to explain what is going on and answer any questions they may have.
CPR should not begin until the child has been properly assessed and rescue breaths have been administered.
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This question is part of the following fields:
- Pathophysiology
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Question 5
Incorrect
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In a diagnosis of a compensated respiratory acidosis, which of the following arterial blood gas results is likely to be seen?
Your Answer: pH = 7.34
PaCO2 = 7.2 kPa
HCO3 = 29Correct Answer:
Explanation:During normal tissue metabolism, there is production of CO2 (acid) which is then expired by the lungs. If metabolism switches from aerobic to anaerobic due to a lack of oxygen, the tissues are unable to completely oxidise sugars to CO2. As a consequence, the sugars can only be partially oxidised to lactic acid. Since lactic acid cannot be expired by the lungs, it remains in the circulation leading to metabolic acidosis.
Also, normal tissue metabolism leads to the production of some amount of acid from the breakdown of proteins. These acids are excreted from the body by kidney filtration. Renal failure will therefore results in acidosis after several days.
An increased acidosis stimulates the brain’s respiratory centres to increase the respiratory rate. This lowers the CO2 in the blood, leading to a decrease in its acidity. Renal excretion removes the excess acid, resulting in a normal pH, and a reduced PaCO2 and HCO3.
pH PaCO2 (kPa) HCO3
Compensated respiratory acidosis 7.34 7.2 29
Acute respiratory acidosis 7.25 7.3 22
Compensated metabolic acidosis 7.34 3.6 14
Metabolic acidosis 7.21 5.3 15
Metabolic alkalosis 7.51 5.1 30 -
This question is part of the following fields:
- Pathophysiology
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Question 6
Correct
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A surgeon infiltrates the tissue layers with local anaesthetic (bupivacaine 0.125%) with 1 in 120,000 adrenaline in a patient weighing 50 kg as part of an enhanced recovery programme for primary hip replacement surgery.
What is the maximum volume of local anaesthetic that is permissible in this patient?Your Answer: 100 mL
Explanation:The maximum safe amount of bupivacaine is 2mg/kg. Addition of adrenaline slows down absorption of the local anaesthetic and allows a maximum dose of 2.5mg/kg to be used.
The maximum safe dose of bupivacaine for this patient is 125 mg.
A 0.125% solution will contain 0.125g/100mL or 125mg/100 mL.
The maximum volume of local anaesthetic is approximately 80-100 mL.
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This question is part of the following fields:
- Pharmacology
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Question 7
Correct
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Calculation of the left ventricular ejection fraction is determined by which of the following equations?
Your Answer: Stroke volume / end diastolic LV volume
Explanation:Cardiac output = stroke volume x heart rate
Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%
Stroke volume = end diastolic LV volume – end systolic LV volume
Pulse pressure = Systolic Pressure – Diastolic Pressure
Systemic vascular resistance = mean arterial pressure / cardiac output
Factors that increase pulse pressure include:
-a less compliant aorta (this tends to occur with advancing age)
-increased stroke volume -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 8
Incorrect
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With regards to devices for temperature management, all of these are used EXCEPT:
Your Answer: Thermocouple works using the potential difference which is created when dissimilar metals are joined
Correct Answer: Thermistors use the resistance of a semiconductor bead which increases exponentially as the temperature increases
Explanation:There are different types of temperature measurement. These include:
Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially
Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)
Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature
Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output
Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.
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This question is part of the following fields:
- Clinical Measurement
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Question 9
Incorrect
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Regarding anti diuretic hormone (ADH), one of the following statements is correct:
Your Answer: Increases the reabsorption of water in the proximal tubule
Correct Answer: Increases the total amount of electrolyte free water in the body
Explanation:The major action of ADH is to increase reabsorption of osmotically unencumbered water from the glomerular filtrate and decreases the volume of urine passed. The osmolarity of urine is increased to a maximum of four times that of plasma (approx. 1200 mOsm/kg) by Increasing water reabsorption.
Chronic water loading, Lithium, potassium deficiency, cortisol and calcium excess, all blunt the action of ADH. This leads to nephrogenic diabetes insipidus.
ADH’s primary site of action is the distal tubule and collecting duct.
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This question is part of the following fields:
- Physiology
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Question 10
Correct
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All of the following statements about pH electrode are incorrect except:
Your Answer: A semi-permeable membrane reduces protein contamination
Explanation:Pulse oximeters combine the principles of oximetry and plethysmography to noninvasively measure oxygen saturation in arterial blood. A sensor containing two or three light emitting diodes and a photodiode is placed across a perfused body part, commonly a finger, to be transilluminated. Oximetry depends on oxyhaemoglobin and deoxyhaemoglobin, and their ability to absorb the beams of light produced by the light emitting diodes: red light at 660 nm and infrared light at 960 nm.
The isosbestic point is the point wherein two different substances absorb light to the same extent. For oxyhaemoglobin and deoxyhaemoglobin, the points are at 590 nm and 805 nm. These are considered reference points where light absorption is independent of the degree of saturation.
Non-constant absorption of light is often due to the presence of an arterial pulsation, whilst constant absorption of light is seen in non-pulsatile tissues.
Most pulse oximeters are inaccurate at low SpO2, but is accurate at +/- 2% within the range of 70% to 100% SpO2. All pulse oximeters demonstrate a delay in between changes in SaO2 and SpO2, and display average readings every 10 to 20 seconds, hence they are unable to detect acute desaturation episodes.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 11
Correct
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Which of the following, at a given PaO2, increases the oxygen content of arterial blood?
Your Answer: A reduced erythrocyte 2,3-diphosphoglycerate level
Explanation:The oxygen content of arterial blood can be calculated by the following equation:
(10 x haemoglobin x SaO2 x 1.34) + (PaO2 x 0.0225).
This is the sum of the oxygen bound to haemoglobin and the oxygen dissolved in the plasma.Oxygen content x cardiac output = The amount of oxygen delivered to the tissues in unit time which is known as the oxygen flux.
Any factor that increases the metabolic demand will encourage oxygen offloading from the haemoglobin in the tissues and this causes the oxygen dissociation curve (ODC) to shift to the right. This subsequently reduced the oxygen content of arterial blood.
Conditions like fever, metabolic or respiratory acidosis lowers the oxygen content and shifts the ODC to the right.
A low level of 2,3 diphosphoglycerate (2,3-DPG) is usually related to an increased oxygen content as there is less offloading, and so the ODC is shifted to the left.So for a given PaO2, a high blood oxygen content is related to any factors that can shift the ODC to the left and not to the right.
A low haematocrit usually means that there is a decreased haemoglobin concentration, and therefore is associated with decreased oxygen binding to haemoglobin.
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This question is part of the following fields:
- Physiology
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Question 12
Correct
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Which of the following statements is not correct regarding Noradrenaline?
Your Answer: Predominantly work through effects on ?-adrenergic receptors
Explanation:Noradrenaline also called norepinephrine belongs to the catecholamine family that functions in the brain and body as both a hormone and neurotransmitter.
They have sympathomimetic effects acting via adrenoceptors (?1, ?2,?1, ?2, ?3) or dopamine receptors (D1, D2).
May cause reflex bradycardia, reduce cardiac output and increase myocardial oxygen consumption
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This question is part of the following fields:
- Pharmacology
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Question 13
Correct
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Which of these statements is false relating to the posterior cerebral artery?
Your Answer: It is connected to the circle of Willis via the superior cerebellar artery
Explanation:The posterior cerebral arteries are the terminal branches of the basilar artery and are connected to the circle of Willis via the posterior communicating artery. The posterior cerebral artery supplies the visual areas of the cerebral cortex and other structures in the visual pathway.
The posterior cerebral artery is separated from the superior cerebellar artery near its origin by the oculomotor nerve (3rd cranial nerve) and, lateral to the midbrain, by the trochlear nerve.
PCA strokes will primarily cause a visual field loss or homonymous hemianopia to the opposite side. This large occipital or PCA stroke causes people to be “blind” on one side of the visual field. This is the most common symptom of a large occipital lesion or PCA stroke.
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This question is part of the following fields:
- Anatomy
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Question 14
Correct
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Which of the following is the maximum volume of 0.5% bupivacaine that should be administered to a 10kg child?
Your Answer: 5 ml
Explanation:Bupivacaine is used to decrease sensation in a specific area. It is injected around a nerve that supplies the area, or into the spinal canal’s epidural space.
The maximum volume of 0.5% bupivacaine that should be administered to a 10kg child is 5 ml
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This question is part of the following fields:
- Pharmacology
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Question 15
Correct
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The whole water content of the body is calculated by multiplying body mass with 0.6. This water is diffused into distinct compartments.
Which fluid compartment can be measured indirectly?Your Answer: Intracellular volume
Explanation:The total body water content of a 70kg man is (70 × 0.6) = 42 litres. For a woman, the calculation is (70 × 0.55) = 38.5 litres.
For a man, it is subdivided into:
Extracellular fluid (ECF) = 14L (1/3)
Intracellular fluid (ICF) = 28L (2/3).The ECF volume is further divided into:
Interstitial fluid = 10.5 litres
Plasma = 3 litres
Transcellular fluid (CSF/synovial fluid) = 0.5 litres.Directly measured fluid compartments:
Heavy water (deuterium) can be used to measure total body water content, which is freely distributed.
Albumin labelled with a radioactive isotope or using a dye called Evans blue can be used to measure Plasma volume . They do not diffuse into red blood cells.
Radiolabelled (Cr-51) red blood cells can be used to measure total erythrocyte volume.
Inulin as the tracer can be used to measure ECF volume as it circulate freely in the interstitial and plasma volumes.Indirectly measured fluid compartments:
Total blood volume can be calculated with the level of haematocrit and the volume of total circulating red blood cells.
ICF volume can be calculated by subtracting ECF volume from total blood volume. -
This question is part of the following fields:
- Basic Physics
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Question 16
Correct
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The cardiac tissue type that that has the highest conduction velocity is:
Your Answer: Purkinje fibres
Explanation:Potassium maintains the resting potential of cardiac myocytes, with depolarization triggered by a rapid influx of sodium ions, and repolarization due to efflux of potassium. A slow influx of calcium is responsible for the longer duration of a cardiac action potential compared with skeletal muscle.
The cardiac action potential has several phases which have different mechanisms of action as seen below:
Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
These channels automatically deactivate after a few ms.Phase 1: caused by early repolarisation and an efflux of potassium.
Phase 2: Plateau – caused by a slow influx of calcium.
Phase 3 – Final repolarisation – caused by an efflux of potassium.
Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potentialOf note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.
Different sites have different conduction velocities:
1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec2. AV node conduction – 0.05 m/sec
3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 17
Correct
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You've been summoned to the recovery room to examine a 28-year-old man who has had an inguinal hernia repaired.
His vital signs are normal, but you notice that he has developed abnormal upper-limb movements due to muscle contractions that cause repetitive twisting movements.
What do you think is the most likely source for this patient's condition?Your Answer: Prochlorperazine
Explanation:Dystonia is characterised by repetitive twisting movements or abnormal postures. They are classified as either primary or secondary.
Primary dystonia is a genetic disorder that is inherited in an autosomal dominant pattern.
Secondary dystonia can be caused by focal brain lesions, Parkinson’s disease, or certain medications.The following drugs cause the most common drug-induced dystonic reactions:
Antipsychotics, antiemetics (especially prochlorperazine and metoclopramide), and antidepressants.Following the administration of the neuroleptic prochlorperazine, 16 percent of patients experience restlessness (akathisia) and 4% experience dystonia.
Several published reports have linked the anaesthetics thiopentone, fentanyl, and propofol to opisthotonos and other abnormal neurologic sequelae. Dystonias following a general anaesthetic are uncommon. Tramadol has been linked to serotonin syndrome, while remifentanil has been linked to muscle rigidity.
The following are some of the risk factors:
Positive family history
Male
Children
An episode of acute dystonia occurred previously.
Dopamine receptor (D2) antagonists at high doses and recent cocaine useDystonia is treated in a variety of ways, including:
Benztropine (as a first-line therapy):
1-2 mg intravenous injection for adults
Child: 0.02 mg/kg to 1 mg maximumBenzodiazepines are a type of benzodiazepine (second line treatment).
Midazolam:
1-2 mg intravenously, or 5-10 mg IV/PO diazepam
Antihistamines with anticholinergic activity (H1receptor antagonists):
Promethazine 25-50 mg IV/IM, or diphenhydramine 50 mg IV/IM (1 mg/kg in children) are used when benztropine is not available.
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This question is part of the following fields:
- Pharmacology
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Question 18
Correct
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A 66-year-old man, present to the emergency department with dyspepsia. On history taking, he admits to being a heavy smoker, and on testing is noted to be positive for a helicobacter pylori infection. A few evenings later, he suffers from haematemesis and collapses.
What vessel is most likely to be involved?Your Answer: Gastroduodenal artery
Explanation:The most likely of the differential diagnosis in this case is a duodenal ulcer located on the posterior abdominal wall.
These can cause an erosion of the abdominal wall, eventually affecting the gastroduodenal artery and resulting in major bleeding and haematemesis.
Gastroduodenal artery supplies the pylorus, proximal part of the duodenum, and indirectly to the pancreatic head (via the anterior and posterior superior pancreaticoduodenal arteries)
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This question is part of the following fields:
- Anatomy
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Question 19
Correct
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A 77-year-old man, is scheduled for an angiogram to investigate gastro-intestinal bleeding. The radiologist performing the angiogram inserts the catheter into the coeliac axis.
What level of the vertebrae does the coeliac axis normally arise from the aorta?Your Answer: T12
Explanation:The coeliac axis refers to one of the splanchnic arteries located within the abdomen.
It arises from the aorta almost horizontally at the level of the T12 vertebrae
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This question is part of the following fields:
- Anatomy
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Question 20
Correct
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An elective left colectomy is being performed on a 60-year old male for left-sided colon cancer. The upper and lower parts of the descending colon are supplied by the left colic artery.
Which of the following arteries gives rise to the left colic artery?Your Answer: Inferior mesenteric artery
Explanation:The inferior mesenteric artery originates 3-4 cm above the bifurcation of the abdominal aorta. The left colic artery branches off the inferior mesenteric artery, arising close to its origin from the abdominal aorta. Other branches of IMA include the three sigmoid arteries that supply the sigmoid colon.
The left colic artery branches off from IMA to supply the distal 1/3 of the transverse colon and the descending colon. It moves upwards posterior to the left colic mesentery and then travels anteriorly to the psoas major muscle, left ureter, and left internal spermatic vessels, before dividing into ascending and descending branches.
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This question is part of the following fields:
- Anatomy
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Question 21
Correct
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Which of the following statements is true regarding oxygen?
Your Answer: Forms molecules containing either two or three atoms
Explanation:Oxygen is formed by a molecule of oxygen and two molecules of hydrogen with a molecular formula of H2O
The critical temperature is defined as a temperature above which the substance cannot be liquefied, no matter how much pressure is applied.
Water has a critical temperature of -118.6oC. So, it cannot be liquified at room temperature.Medical oxygen cylinder is stored in a cylinder with a white shoulder and black body. Meanwhile, medial air is stored in cylinders with a white and black shoulder and a French grey body.
The partial pressure of air at a high altitude is less but the relative concentration remains constant.
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This question is part of the following fields:
- Basic Physics
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Question 22
Incorrect
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Your manager asks you to inform patients that are suffering from a chronic pain about a trial that is going to be conducted in order to determine the efficacy of a novel analgesic. What phase is the trial currently in?
Your Answer: Phase 0
Correct Answer: Phase 2
Explanation:Phase 0 trials assist the scientists in studying the behaviour of drugs in humans by micro dosing patients. They are used to speed up the developmental process. They have no measurable therapeutic effect and efficiency.
Phase 1 is associated with assessing whether a drug is safe to use or not. The process is extensive and can take up to several months. It also involves healthy participants (less than 100) that are paid to take part in the study. The side effects upon increasing dosage are also addressed by the study. The effects the drug has on humans including how its absorbed, metabolized and excreted are studied. Approximately 70% of the drugs pass this phase.
Phase 2 trials involve patients that are suffering from the disease under study and are associated with determining the efficiency and the optimum dosage of the drug.
Phase 3 also assesses the efficacy but at a higher scale with larger population sample.
Phase 4 trials are involved with the long term effects and side effects of the drug.
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This question is part of the following fields:
- Statistical Methods
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Question 23
Correct
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Transthoracic echocardiogram (TTE) can be used to investigate the function of the heart in patients with suspected heart failure. The aim is to measure the ejection fraction, but to do that, the stroke volume must first be measured. How is stroke volume calculated?
Your Answer: End diastolic volume - end systolic volume
Explanation:Cardiac output = stroke volume x heart rate
Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%
Stroke volume = end diastolic LV volume – end systolic LV volume
Pulse pressure = Systolic Pressure – Diastolic Pressure
Systemic vascular resistance = mean arterial pressure / cardiac output
Factors that increase pulse pressure include:
-a less compliant aorta (this tends to occur with advancing age)
-increased stroke volume -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 24
Correct
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Left ventricular afterload is mostly calculated from systemic vascular resistance.
Which one of the following factors has most impact on systemic vascular resistance?Your Answer: Small arterioles
Explanation:Systemic vascular resistance (SVR), also known as total peripheral resistance (TPR), is the amount of force exerted on circulating blood by the vasculature of the body. Three factors determine the force: the length of the blood vessels in the body, the diameter of the vessels, and the viscosity of the blood within them. The most important factor that determines the systemic vascular resistance (SVR) is the tone of the small arterioles.
These are otherwise known as resistance arterioles. Their diameter ranges between 100 and 450 µm. Smaller resistance vessels, less than 100 µm in diameter (pre-capillary arterioles), play a less significant role in determining SVR. They are subject to autoregulation.
Any change in the viscosity of blood and therefore flow (such as due to a change in haematocrit) might also have a small effect on the measured vascular resistance.
Changes of blood temperature can also affect blood rheology and therefore flow through resistance vessels.
Systemic vascular resistance (SVR) is measured in dynes·s·cm-5
It can be calculated from the following equation:
SVR = (mean arterial pressure − mean right atrial pressure) × 80 cardiac output
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This question is part of the following fields:
- Physiology
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Question 25
Correct
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A patient on admission is given an infusion of 1000 mL of 10% glucose and 500 mL of 20% lipid over a 24 hour period.
Which of these best approximates to the energy input over this time period?Your Answer: 1300 kcal
Explanation:1% solution contains 1 g of substance per 100 mL.
A solution of 10% glucose is 10 g/100mL. Therefore 1000 mL of this glucose solution will contain 100 g.
1 g of glucose yields about 4 kcal of energy. One litre of 10% glucose will therefore release approximately 4x100g = 400 kcal of energy.
A solution of 20% fat is 20 g/100mL. Therefore 1000 mL of this fat solution will have 200 g and 500 mL will contain 100 g.
1 g of fat yields approximately 9 kcal. 500 mL of 20% fat therefore has the potential to yield 900 kcal of energy.
The total energy input over this 24 hour period is approximately 400kcal + 900kcal = 1300 kcal.
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This question is part of the following fields:
- Physiology
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Question 26
Correct
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Regarding the Manley MP3 ventilator, which statement is true?
Your Answer: Is a minute volume divider
Explanation:It’s a minute volume divider – True
The Manley MP3 ventilator is classed as a minute volume divider. The entire fresh gas flow or minute volume is delivered to the patient, having been divided into readily set tidal volumes.Can efficiently ventilate patients with poor pulmonary compliance – False
Ventilating patients with poor pulmonary compliance is not easily achieved, which makes it an unsuitable ventilator for a modern ICU.Can generate tidal volume up to 1500ml – False
It can generate tidal volumes up to 1000 ml (not 1500 ml), and the inflation pressure can be adjusted by sliding a weight along a rail.Functions like a Mapleson A system during spontaneous ventilation – False
The ventilator functions like a Mapleson D breathing system (not Mapleson A) during spontaneous ventilation.Has three sets of bellows – False
The fresh gas flow drives the ventilator which allows rapid detection of gas supply failure. It has two sets of bellows (not three) and three unidirectional valves. -
This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 27
Correct
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Which of these thyroid hormones is considered the most potent and most physiologically active?
Your Answer: T3
Explanation:Triiodothyronine (T3) is more potent than thyroxine (T4). It is able to bind to more receptors (90%) compared to T4 (10%), and the onset of action is more immediate (within 12 hours) than T4 (2 days).
Ninety-three percent of thyroid hormones synthesized is T4, and the remaining 7% is T3. The half-life of T3 is shorter (1 day), and its affinity for thyroxine-binding globulin is lower than T4.
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This question is part of the following fields:
- Pathophysiology
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Question 28
Correct
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You're summoned to the emergency room, where a 39-year-old man has been admitted following a cardiac arrest. He was rescued from a river, but little else is known about him.
CPR is being performed on the patient, who has been intubated. He's received three DC shocks and is still in VF. A rectal temperature of 29.5°C is taken with a low-reading thermometer.
Which of the following statements about his resuscitation is correct?Your Answer: No further DC shocks and no drugs should be given until his core temperature is greater than 30°C
Explanation:The guidelines for the management of cardiac arrest in hypothermic patients published by the UK Resuscitation Council differ slightly from the standard algorithm.
In a patient with a core temperature of less than 30°C, do the following:
If you’re on the shockable side of the algorithm (VF/VT), you should give three DC shocks.
Further shocks are not recommended until the patient has been rewarmed to a temperature of more than 30°C because the rhythm is refractory and unlikely to change.
There should be no drugs given because they will be ineffective.In a patient with a core temperature of 30°C to 35°C, do the following:
DC shocks are used as usual.
Because they are metabolised much more slowly, the time between drug doses should be doubled.Active rewarming and protection against hyperthermia should be given to the patient.
Option e is false because there is insufficient information to determine whether resuscitation should be stopped.
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This question is part of the following fields:
- Physiology
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Question 29
Correct
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Which of the following is the best marker of mast cell degranulation in a patient with suspected anaphylaxis who became hypotensive and developed widespread urticarial rash after administration of Augmentin?
Your Answer: Tryptase
Explanation:Mast cell tryptase is a reliable marker of mast cell degranulation. Tryptase is a protease enzyme that acts via widespread protease-activated receptors (PARs).
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This question is part of the following fields:
- Pharmacology
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Question 30
Correct
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A 70-year-old male presented to an outpatient clinic with a complaint of a lump in his groin. Physical examination reveals the lumps increase in size while coughing and reduces in size after lying down flat. Based on his age and examination, a diagnosis of direct inguinal hernia was made.
Which structures does the bowel pass through in order to be classed as direct inguinal hernia?Your Answer: Hesselbach's triangle
Explanation:A hernia is a protrusion of the abdominal viscera through a defect in the abdominal wall. Inguinal hernias are of two types; Indirect inguinal hernia and Direct inguinal hernia.
– Indirect inguinal hernia is common at young age commonly due to a patent processes vaginalis and bowel passes through the deep inguinal ring lateral to the inferior epigastric artery.
– Direct hernia forms as a result of the weakening of the posterior wall of the inguinal canal more specifically within a region called ‘Hasselbach triangle. It is defined medially by the rectus abdominis muscle, laterally by the epigastric vessels, and inferiorly by the inguinal ligament.Direct and indirect hernias can be differentiated based on their relation to the inferior epigastric artery. Direct inguinal hernia lies medial to it while indirect inguinal hernia lies lateral to the inferior epigastric artery.
The femoral ring is the site of the femoral hernia.
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This question is part of the following fields:
- Anatomy
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Question 31
Correct
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A 27-year-old woman takes part in a study looking into the effects of different dietary substrates on metabolism. She receives a 24-hour ethyl alcohol infusion.
A constant volume, closed system respirometer is used to measure CO2 production and consumption. The production of carbon dioxide is found to be 200 mL/minute.
Which of the following values most closely resembles her anticipated O2 consumption at the conclusion of the trial?Your Answer: 300 mL/minute
Explanation:The respiratory quotient (RQ) is the ratio of CO2 produced by the body to O2 consumed in a given amount of time.
CO2 produced / O2 consumed = RQ
CO2 is produced at a rate of 200 mL per minute, while O2 is consumed at a rate of 250 mL per minute. An RQ of around 0.8 is typical for a mixed diet.
The RQ will change depending on the energy substrates consumed in the diet. Granulated sugar is a refined carbohydrate that contains 99.999 percent carbohydrate and no lipids, proteins, minerals, or vitamins.
Glucose and other hexose sugars (glucose and other hexose sugars):
RQ=1Fats:
RQ = 0.7Proteins:
Approximately 0.9 RQEthyl alcohol is a type of alcohol.
200/300 = 0.67 RQ
For complete oxidation, lipids and alcohol require more oxygen than carbohydrates.
When carbohydrate is converted to fat, the RQ can rise above 1.0. Fat deposition and weight gain are likely to occur in these circumstances.
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This question is part of the following fields:
- Physiology
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Question 32
Correct
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Regarding adrenocorticotropic hormone (ACTH) one of these is true.
Your Answer: Is increased in the maternal plasma in pregnancy
Explanation:ACTH production is stimulated through the secretion of corticotropin-releasing hormone (CRH) from the hypothalamic nuclei.
ACTH secretion has a circadian rhythm. A high level of cortisol in the body stops its production. ACTH is secreted maximally in the morning and concentrations are lowest at midnight.
ACTH can be expressed in the placenta, the pituitary and other tissues.
Conditions where ACTH concentrations rise include: stress, disease and pregnancy.
Glucocorticoids (not mineralocorticoids – aldosterone) switch off ACTH production through a negative feedback loop .
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This question is part of the following fields:
- Pathophysiology
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Question 33
Correct
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All of the following options describes a thermistor for the measurement of temperature except:
Your Answer: Resistance of the bead increases exponentially as the temperature increases
Explanation:There are different types of temperature measurement. These include:
Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially
Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)
Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature
Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output
Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.
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This question is part of the following fields:
- Clinical Measurement
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Question 34
Correct
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Which of the following correctly explains the mechanism of sevoflurane preconditioning?
Your Answer: Opening of mitochondrial KATP channels
Explanation:Sevoflurane is highly fluorinated methyl isopropyl ether widely used as an inhalational anaesthetic. It is suggested that sevoflurane preconditioning occurs via the opening of mitochondrial Potassium ATP dependent channel similar to that of Ischemic Preconditioning protection.
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This question is part of the following fields:
- Pharmacology
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Question 35
Incorrect
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If the speed of an ultrasound in soft tissue is 1540 meters per second, what is the estimated wavelength produced if the frequency of a generated ultrasound is 10 megahertz?
Your Answer: 1.5 millimetres
Correct Answer: 0.15 millimetre
Explanation:Wavelength can be computed as follows:
Wavelength = velocity/frequency
In the given problem, the values stated are:
Frequency = 10 x 10^6
Velocity = 1540 meters per secondWavelength = 1540/(10×10^6)
Wavelength = 1540/10,000,000 meters
Wavelength = 0.15 millimetres -
This question is part of the following fields:
- Clinical Measurement
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Question 36
Correct
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A 70-year-old female is on bisoprolol, amitriptyline, and gabapentin medication and required hemiarthroplasty for a fractured neck of the femur. Spinal anaesthesia using 10 mg of IV ketamine to aid positioning was decided to be used. This resulting block extended to T8 and she required boluses of metaraminol for hypotension.
She became profoundly hypertensive and had multiple ventricular ectopic beats on ECG following positioning in theatre.
Which of the following is the cause for this?Your Answer: Ketamine
Explanation:Ketamine is primarily used for the induction and maintenance of anaesthesia. It induces dissociative anaesthesia. But it is contraindicated in cardiovascular diseases such as unstable angina or poorly controlled hypertension.
Tricyclic antidepressants (TCA) are primarily used as antidepressants which is important for the management of depression. These are second-line drugs next to SSRI. They work by competitively preventing re-uptake of amines (noradrenaline and serotonin) from the synaptic cleft so increasing their concentration. But TCA overdoses are toxic and have cardiovascular effects, central effects, and anticholinergics effects. Cardiovascular effects like prolonged QT and widened QRS at lower doses progressing to ventricular arrhythmias and refractory hypotension at higher doses can be life-threatening. When used in the perioperative period, it can lead to increased sensitivity to circulating catecholamines therefore care is needed perioperatively.
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This question is part of the following fields:
- Pharmacology
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Question 37
Correct
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Glyceryl trinitrate (GTN) used for the acute treatment of angina is best administered via the sublingual route.
Why is this the best route of administration?Your Answer: High first pass metabolism
Explanation:Glyceryl trinitrate (GTN) has a significant first pass metabolism. About 90% of a dose of GTN is metabolised in the liver by the enzyme glutathione organic nitrate reductase.
An INSIGNIFICANT amount of metabolism occurs in the intestinal mucosa.
There is approximately 1% bioavailability after oral administration and 38% after sublingual administration.
GTN does NOT cause gastric irritation and it is well absorbed in the gastrointestinal tract.
The volume of distribution of GTN is 2.1 to 4.5 L/kg. This is HIGH.
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This question is part of the following fields:
- Pharmacology
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Question 38
Correct
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A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise. On urine culture and sensitivity testing, E.coli was detected with resistance to ampicillin.
What is the mechanism of resistance to ampicillin?Your Answer: Beta-lactamase production
Explanation:Ampicillin belongs to the family of penicillin. Resistance to this group of drugs is due to ?-lactamase production which opens the ?-lactam ring and inactivates Penicillin G and some closely related congeners. The majority of Staphylococci and some strains of gonococci, B. subtilis, E. coli, and a few other bacteria produce penicillinase.
Resistance to cephalosporins is due to changes in penicillin-binding proteins.
Resistance to macrolides are due to post-transcriptional methylation of 23s bacterial ribosomal RNA
Resistance to fluoroquinolones is due to mutations in DNA gyrase.
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This question is part of the following fields:
- Pharmacology
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Question 39
Correct
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A balanced general anaesthetic including a muscle relaxant is administered at induction. It is observed that the train-of-four count is two after two hours, with no further doses of the muscle relaxant.
What is most likely reason for this?Your Answer: Mivacurium with plasma cholinesterase deficiency
Explanation:Mivacurium is metabolised primarily by plasma cholinesterase at an In vitro rate of about 70% that of succinylcholine. Mivacurium is contraindicated in patients with genetic and acquired plasma cholinesterase deficiencies.
The clearance of atracurium is by Hoffman degradation and ester hydrolysis in the plasma and is independent of both hepatic and renal function.
Rocuronium is eliminated primarily by the liver after metabolises to a less active metabolite, 17-desacetyl-rocuronium. Its duration of action is not affected much by renal impairment.
Vecuronium undergoes hepatic metabolism into 3-desacetyl-vecuronium which has 50-80% the activity of the parent drug. It undergoes biliary (40%) and renal excretion (30%). The aminoglycoside antibiotics possess additional neuromuscular blocking activity. The potency of gentamicin > streptomycin > amikacin. Calcium can be used to reverse the muscle weakness produced by gentamicin but not neostigmine. When vecuronium and gentamycin are given together the effect on neuromuscular blockade is synergistic.
Significant residual neuromuscular block 2 hours after the administration of these drugs is unlikely In this scenario.
Any recovery from neuromuscular blockade with suxamethonium in a patient with deficiency of plasma cholinesterase demonstrate four twitches on a train of four count.
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This question is part of the following fields:
- Pharmacology
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Question 40
Incorrect
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Which of the following is true regarding correlation coefficient?
Your Answer: It is stated in the same units as the dependent variable
Correct Answer: It can assume any value between -1 and 1
Explanation:The degree of correlation is summarised by the correlation coefficient (r). This indicates how closely the points lie to a line drawn through the plotted data. In parametric data this is called Pearson’s correlation coefficient and can take any value between -1 to +1. A correlation of -1.0 indicates a perfect negative correlation, and a correlation of 1.0 indicates a perfect positive correlation.
For example
r = 1 – strong positive correlation (e.g. systolic blood pressure always increases with age)
r = 0 – no correlation (e.g. there is no correlation between systolic blood pressure and age)
r = – 1 – strong negative correlation (e.g. systolic blood pressure always decreases with age)
Whilst correlation coefficients give information about how one variable may increase or decrease as another variable increases they do not give information about how much the variable will change. They also do not provide information on cause and effect.
In contrast to the correlation coefficient, linear regression may be used to predict how much one variable changes when a second variable is changed.
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This question is part of the following fields:
- Statistical Methods
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Question 41
Incorrect
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A mercury barometer can be used to determine absolute pressure. A mercury manometer can be used to check blood pressure. The SI units of length(mm) are used to measure pressure.
Why is pressure expressed in millimetres of mercury (mmHg)?Your Answer: Pressure is directly proportional to length of the mercury column and is the only constant
Correct Answer: Pressure is directly proportional to length of the mercury column and is variable
Explanation:A mercury barometer can be used to determine absolute pressure. A glass tube with one closed end serves as the barometer. The open end is inserted into a mercury-filled open vessel. The mercury in the container is pushed into the tube by atmospheric pressure exerted on its surface. Absolute pressure is the distance between the tube’s meniscus and the mercury surface.
Pressure is defined as force in newtons per unit area (F) (A).
Mass of mercury = area (A) × density (ρ) × length (L)
Pressure = ((A × ρ × L) × 9.8 m/s2)/A
Pressure = ρ × L x 9.8
Pressure is proportional to LThe numerator and denominator of the above equation, area (A), cancel out. The constants are density and the gravitational acceleration value.
The length is proportional to the applied pressure.
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This question is part of the following fields:
- Physiology
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Question 42
Correct
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A bolus of alfentanil has a faster onset of action than an equal dose of fentanyl.
Which of the following statements most accurately describes the difference?Your Answer: The pKa of alfentanil is less than that of fentanyl
Explanation:Unionised molecules are more likely than ionised molecules to cross membranes (such as the blood-brain barrier).
Because alfentanil and fentanyl are weak bases, the Henderson-Hasselbalch equation says that the ratio of ionised to unionised molecules is determined by the parent compound’s pKa in relation to physiological pH.
Alfentanil has a pKa of 6.5, while fentanyl has a pKa of 8.4.
At a pH of 7.4, 89 percent of alfentanil is unionised, whereas 9% of fentanyl is.As a result, alfentanil has a faster onset than fentanyl.
Fentanyl is 83% plasma protein bound
Alfentanil is 90% plasma protein bound.Alfentanil’s pharmacokinetics are affected by its higher plasma protein binding. Because alfentanil has a low hepatic extraction ratio (0.4), clearance is determined by the degree of protein binding rather than the time it takes to take effect.
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This question is part of the following fields:
- Pharmacology
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Question 43
Incorrect
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Of the following, which is NOT a branch of the subclavian artery?
Your Answer: Internal thoracic artery
Correct Answer: Superior thyroid artery
Explanation:The left subclavian artery originates from the aortic arch, while the right subclavian artery originates from the brachiocephalic artery.
The subclavian artery gives off branches on both sides of the body:
1. Vertebral artery
2. Internal thoracic artery
3. Thyrocervical trunk
4. Costocervical trunk
5. Dorsal scapular arteryThe superior thyroid artery is the first branch of the external carotid artery. The other branches of the external carotid artery are:
1. Superior thyroid artery
2. Ascending pharyngeal artery
3. Lingual artery
4. Facial artery
5. Occipital artery
6. Posterior auricular artery
7. Maxillary artery
8. Superficial temporal artery -
This question is part of the following fields:
- Anatomy
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Question 44
Correct
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A post-operative patient was given paracetamol and pethidine for post-operative analgesia. A few hours later, the patient developed fever of 38°C, hypertension, and agitation.
According to the patient's medical history, he is maintained on Levodopa and Selegiline for Parkinson's disease.
Which of the following is the most probable cause of his manifestation?Your Answer: Pethidine
Explanation:Selegiline is a monoamine oxidase inhibitor. Inhibition of monoamine oxidase leads to increased levels of norepinephrine and serotonin in the central nervous system.
Pethidine, also known as meperidine, is a strong agonist at the mu and kappa receptors. It inhibits pain neurotransmission and blocks muscarinic-specific actions.
Administering opioid analgesic is relatively contraindicated to individuals taking monoamine oxidase inhibitors. This is because of the high incidence of serotonin syndrome, which is characterized by fever, agitation, tremor, clonus, hyperreflexia and diaphoresis. Onset of symptoms is within hours, and the treatment is mainly through sedation, paralysis, intubation and ventilation.
The clinical findings are more consistent with Serotonin syndrome rather than exacerbation of Parkinson’s. Parkinson’s Disease (PD) exacerbations are defined as patient-reported or caregiver-reported episodes of subacute worsening of PD motor function in 1 or more domains (bradykinesia, tremor, rigidity, or PD-related postural instability/gait disturbance) that caused a decline in functional status, developed over a period of < 2 months, did not fluctuate with medication timing, and are not caused by intentional adjustments of PD medications by the treating neurologist. Malignant hyperthermia usually occurs within minutes of administration of a volatile anaesthetic, such as halothane, or succinylcholine. There is massive release of calcium from the sarcoplasmic reticulum, leading to fever, acidosis, rhabdomyolysis, trismus, clonus, and hypertension. In sepsis, it more common for patients to present with hypotension rather than hypertension.
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This question is part of the following fields:
- Pharmacology
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Question 45
Correct
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A 27-year-old woman is admitted to the emergency room with an ectopic pregnancy that has ruptured.
The following is a description of the clinical examination:
Anxious
Capillary refill time of 3 seconds
Cool peripheries
Pulse 120 beats per minute
Blood pressure 120/95 mmHg
Respiratory rate 22 breaths per minute.
Which of the following is the most likely explanation for these clinical findings?Your Answer: Reduction in blood volume of 15-30%
Explanation:The following is the Advanced Trauma Life Support (ATLS) classification of haemorrhagic shock:
Class I haemorrhage:
It has blood loss up to 15%. There is very less tachycardia, and no changes in blood pressure, RR or pulse pressure. Usually, fluid replacement is not required.Class II haemorrhage:
It has 15-30% blood loss, equivalent to 750 – 1500 ml. There is tachycardia, tachypnoea and a decrease in pulse pressure. Patient may be frightened, hostile and anxious. It can be stabilised by crystalloid and blood transfusion.Class III haemorrhage:
There is 30-40% blood loss. It portrays inadequate perfusion, marked tachycardia, tachypnoea, altered mental state and fall in systolic pressure. It requires blood transfusion.Class IV haemorrhage:
There is > 40% blood volume loss. It is a preterminal event, and the patient will die in minutes. It portrays tachycardia, significant depression in systolic pressure and pulse pressure, altered mental state, and cold clammy skin. There is need for rapid transfusion and surgical intervention. -
This question is part of the following fields:
- Physiology
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Question 46
Correct
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Which of the following statement is true or false regarding to the respiratory tract?
Your Answer: The sympathetic innervation of the bronchi is derived from T2 - T4
Explanation:The diaphragm has three opening through which different structures pass from the thoracic cavity to the abdominal cavity:
Inferior vena cava passes at the level of T8.
Oesophagus, oesophageal vessels and vagi at T10.
Aorta, thoracic duct and azygous vein through T12.
Sympathetic trunk and pulmonary branches of vagus nerve form a posterior pulmonary plexus at the root of the lung. Fibres continue posteriorly from superficial cardiac plexus to form Anterior pulmonary plexus. It contains vagi nerves and superficial cardiac plexus. These fibres then follow the blood vessel and bronchi into the lungs.
The lower border of the pleura is at the level of:
8th rib in the midclavicular line
10th rib in the lower level of midaxillary line
T12 at its termination.
Both lungs have oblique fissure while right lung has transverse fissure too.
The trachea expands from the lower edge of the cricoid cartilage (at the level of the 6th cervical vertebra) to the carina.
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This question is part of the following fields:
- Physiology
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Question 47
Incorrect
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A 67-year-old man, presents with an embolus in the lower limbs. He has previous medical history of atrial fibrillation. After examination and diagnostic investigations, he is scheduled for a transpopliteal embolectomy, which will require the surgeons to explore the central region of the popliteal fossa.
What structures will the surgeons come across after incising the deep fascia?Your Answer: Common peroneal nerve
Correct Answer: Tibial nerve
Explanation:The tibial nerve lies on top of the vessels contained within the inferior aspect of the popliteal fossa.
In the superior aspect of the fossa, the tibial nerve runs lateral to the vessels, before then travelling superficial to the vessels, and then finally changing course to lie medial to the vessels.
The popliteal artery is the most deep structure present in the popliteal fossa
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This question is part of the following fields:
- Anatomy
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Question 48
Incorrect
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A 50-year-old female is having her central venous pressure (CVP) measured. A long femoral line was inserted that passes from the common iliac vein into the inferior vena cava.
At which level of vertebra does this occur?Your Answer: L2
Correct Answer: L5
Explanation:The inferior vena cava is formed by the union of the right and left common iliac veins. This occurs at the L5 vertebral level. The IVC courses along the right anterolateral side of the vertebral column and ascends through the central tendon of the diaphragm at the T8 vertebral level.
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This question is part of the following fields:
- Anatomy
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Question 49
Correct
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A 47-year old man and known alcoholic suffered a fall that resulted to a fracture on his right leg. Radiographic imaging showed a fractured tibial shaft. Following surgery, you were instructed to prescribe intravenous paracetamol as an analgesic.
If the patient weighs 49 kg, which of the following would be the best regimen for the patient?Your Answer: 15 mg/kg with a maximum daily dose of 60 mg/kg (not exceeding 3 g)
Explanation:A stock dose of Intravenous paracetamol available in the market is 10mg/ml. There is a recommended dose of IV paracetamol according to the profile of the patient (age, co-morbidities, weight).
Weight Recommended Dose Maximum per day
≤10 kg 7.5 mg/kg 30 mg/kg
>10 kg to ≤33 kg 15 mg/kg 60 mg/kg (not exceeding 2 g)
>33 kg to ≤50 kg 15 mg/kg 60 mg/kg (not exceeding 3 g)
>50 kg with additional risk factors for hepatotoxicity 1g 3 g
>50 kg with no additional risk factors for hepatotoxicity 1g 4 gSpecial precaution must be observed for patients with hepatocellular insufficiency. The maximum dose per day should not exceed 3g.
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This question is part of the following fields:
- Pharmacology
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Question 50
Correct
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Which of the following is the smallest value of pressure?
Your Answer: 14.69 psi
Explanation:The SI unit of pressure is the pascal (Pa) and it is equal to one newton (N) per square meter (m2) or N/m2.
1 atmosphere (atm) is the equivalent of:
101325 Pa760 mmHg
1.01325 bar
1033.23 cmH2O.
14.69 pounds per square inch (psi)
1013.25 millibar (mbar) or hectopascals (hPa), and14.69 psi is equal to one atmosphere. The other values are equal to two atmospheres of pressure.
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This question is part of the following fields:
- Basic Physics
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Question 51
Incorrect
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What structure is most posterior at the porta hepatis?
Your Answer: Cystic artery
Correct Answer: Portal vein
Explanation:The structures in the porta hepatis from anterior to posterior are:
The ducts: Most anterior are the left and right hepatic ducts.
The arteries: Next are the left and right hepatic arteries
The veins: Next is the portal vein
The epiploic foramen of Winslow lies most posterior at the porta hepatis.
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This question is part of the following fields:
- Anatomy
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Question 52
Correct
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Of the following, which option best describes the muscle type that has the fastest twitch response to stimulation?
Your Answer: Type IIb skeletal muscle
Explanation:Human skeletal muscle is composed of a heterogeneous collection of muscle fibre types which differ histologically, biochemically and physiologically.
It can be biochemically classified into 2 groups. This is based on muscle fibre myosin ATPase histochemistry. These are:
Type 1 (slow twitch): Muscle fibres depend upon aerobic glycolytic metabolism and aerobic oxidative metabolism. They are rich in mitochondria, have a good blood supply, rich in myoglobin and are resistant to fatigue.
Type II (fast twitch): Muscle fibres are sub-divided into:
Type IIa – relies on aerobic/oxidative metabolism
Type IIb – relies on anaerobic/glycolytic metabolism.Fast twitch muscle fibres produce short bursts of power but are more easily fatigued.
Cardiac and smooth muscle twitches are relatively slow compared with skeletal muscle.
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This question is part of the following fields:
- Physiology
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Question 53
Incorrect
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Which of the following statements is true regarding sucralfate?
Your Answer: Is a simple compound formed from sulphated sucrose
Correct Answer:
Explanation:Sucralfate is an octasulfate of glucose to which Al(OH)3 has been added. It undergoes extensive cross-linking in an acidic environment and forms a polymer which adheres to the ulcer base for up to 6 hours and protects it from further erosion. Since it is not systemically absorbed it is virtually devoid of side effects. However, it may cause constipation in about 2% of cases due to the Aluminium component in it.
Sucralfate does not have antibacterial action against Helicobacter pylori. However, Bismuth has antibacterial action due to its oligodynamic effect.
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This question is part of the following fields:
- Pharmacology
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Question 54
Incorrect
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What is the order of the anatomical components of the tracheobronchial tree from proximal to distal?
Your Answer: Bronchioles, respiratory bronchioles, terminal bronchioles, alveolar ducts, alveolar sacs
Correct Answer: Bronchioles, terminal bronchioles, respiratory bronchioles, alveolar ducts, alveolar sacs
Explanation:The tracheobronchial tree is subdivided into the conducting and the respiratory zones.
The zones from proximal to distal are:
Trachea
Bronchi
Bronchioles
Terminal bronchioles
Respiratory bronchioles
Alveolar ducts
Alveolar sacsfrom the trachea to terminal bronchioles are the conducting zone while the respiratory zone is from the respiratory bronchioles to the alveola sacs
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This question is part of the following fields:
- Anatomy
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Question 55
Correct
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Which oral hypoglycaemic agent has no effect on insulin sensitivity or secretion?
Your Answer: Alpha glucosidase inhibitors
Explanation:Because alpha glucosidase inhibitors slow starch digestion in the small intestine, glucose from a meal enters the bloodstream more slowly and can be matched more effectively by an impaired insulin response or sensitivity, glucose from a meal enters the bloodstream more slowly and can be matched more effectively by an impaired insulin response or sensitivity.
Biguanides decrease hepatic glucose output while increasing glucose uptake in peripheral cells.
The meglitinides are secretagogues that act on a different site of the KATP receptors.
Insulin secretion is stimulated by sulphonylureas, which stimulate insulin secretion from pancreatic beta cells. The KATP channels are inhibited by these substances.
Insulin-sensitive genes are influenced by thiazolidinediones, which increase the production of mRNAs for insulin-dependent enzymes. As a result, the cells make better use of glucose.
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This question is part of the following fields:
- Pharmacology
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Question 56
Correct
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In asthmatic patients, non-steroidal anti-inflammatory analgesics (NSAIDs) are generally contraindicated.
Which of the following membrane phospholipid metabolism products is most likely to cause NSAID-induced bronchospasm in asthmatic patients who are predisposed to it?Your Answer: Leukotrienes
Explanation:Nonsteroidal anti-inflammatory drugs (NSAIDs) cause bronchospasm, rhinorrhoea, and nasal obstruction in some asthma patients.
The inhibition of cyclooxygenase-1 (Cox-1) appears to be the cause of NSAID-induced reactions. This activates the lipoxygenase pathway, which increases the release of cysteinyl leukotrienes (Cys-LTs), which causes bronchospasm and nasal obstruction.
The following changes in arachidonic acid (AA) metabolism have been observed in NSAID-intolerant asthmatic patients:
Prostaglandin E2 production is low, possibly due to a lack of Cox-2 regulation.
An increase in leukotriene-C4 synthase expression and
A decrease in the production of metabolites (lipoxins) released by AA’s transcellular metabolism.Phospholipase A produces membrane phospholipids, which are converted to arachidonic acid.
TXA2 causes vasoconstriction as well as platelet aggregation and adhesion.
PGI2 causes vasodilation and a reduction in platelet adhesion.
PGE2 is involved in parturition initiation and maintenance, as well as thermoregulation.
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This question is part of the following fields:
- Pharmacology
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Question 57
Incorrect
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A 20-year-old boy is undergoing surgery for indirect inguinal hernia repair. The deep inguinal ring is exposed and held with a retractor at its medial aspect during the procedure.
What structure is most likely to lie under the retractor on the medial side?Your Answer: Lateral border of rectus abdominis
Correct Answer: Inferior epigastric artery
Explanation:The deep inguinal ring is the entrance of the inguinal canal. It is an opening in the transversalis fascia around 1 cm above the inguinal ligament. Therefore, the superolateral wall is made by the transervalis fascia.
The inferior epigastric vessels run medially to the deep inguinal ring forming its inferomedial border.
The inguinal canal extends obliquely from the deep inguinal ring to the superficial inguinal ring.
An indirect inguinal hernia arises through the deep inguinal ring lateral to the inferior epigastric vessels. -
This question is part of the following fields:
- Anatomy
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Question 58
Correct
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An 80-year old female was taken to the emergency room for chest pain. She has a medical history of coronary artery disease and previous episodes of atrial fibrillation. She was immediately attached to the cardiac monitor, which showed tachycardia at 148 beats per minute. The 12-lead ECG revealed atrial fibrillation.
Digoxin was given as an anti-arrhythmic at 500 micrograms, which is higher than the maintenance dose routinely given. Why is this so?Your Answer: It has a high volume of distribution
Explanation:When the loading dose of Digoxin is given, the primary thing to consider is the volume of distribution. The volume of distribution is the proportionality factor that relates the total amount of drug in the body to the concentration. LD is computed as:
LD = Volume of distribution X (desired plasma concentration/bioavailability)
Digoxin is an anti-arrhythmic drug with a large volume of distribution and high bioavailability, and only a small percentage of Digoxin is bound to plasma proteins (,20%).
In the case, since the arrhythmia is not life-threatening, there is no need for the medication to work rapidly.
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This question is part of the following fields:
- Pharmacology
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Question 59
Correct
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Fixed performance devices like high air flow oxygen enrichment (HAFOE) masks have large volumes of air entrained into a flow of 100% oxygen.
The term that best describes the physics behind air entrainment is?Your Answer: Bernoulli's principle
Explanation:Bernoulli’s principle states that as the speed of a moving fluid increases, there is a simultaneously decrease in static pressure or a decrease in the fluid’s potential energy.
This is seen in the simultaneous increase in speed and kinetic energy and fall in pressure that causes entrainment of large volumes of air into a flow of 100% oxygen in the nozzle of HAFOE masks.The reduction in fluid pressure that happens when a fluid flows through a constriction in a tube is the Venturi effect.
When a flow of gas or liquid attaches itself to a nearby surface and remains attached even when the surface curves away from the initial direction of flow, this is the Coanda effect.
The branch of engineering and technology that is concerned with the building of devices that use the flow and pressure of a fluid for functions usually performed by electronic devices is Fluidics . Fluidic logic is used to power some ventilators.
The branch of engineering that utilises pressurised gases is Pneumatics.
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This question is part of the following fields:
- Basic Physics
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Question 60
Incorrect
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A 70-year-old man will have a PICC line inserted as he requires long-term parenteral nutrition. To gain venous access, the line is inserted into the basilic vein at the elbow region.
As the catheter tip advances into the basilic vein, which venous structure will it first encounter?
Your Answer: Cephalic vein
Correct Answer: Axillary vein
Explanation:A peripherally inserted central catheter (PICC) line is a long, thin tube inserted into the vein of a patient’s arm to gain access to the large central veins near the heart. PICC line is indicated for parenteral nutrition or to deliver medications. They can be used for medium-term venous access, defined as anywhere between several weeks to 6 months.
The veins of choice for PICC are:
1. Basilic
2. Brachial
3. Cephalic
4. Medial cubital veinThe vein of choice is the right basilic vein as it has a large circumference and is located superficially. It has the most straight route to the final destination of PICC (SVC or Right atrium). It courses through the axillary vein, then the subclavian, and finally settles into the SVC. It also has the least number of valves and a shallow angle of insertion when compared to the other veins.
The basilic vein drains the medial end of the dorsal arch of the upper limb, passes along the medial aspect of the forearm, and pierces the deep fascia at the elbow. The basilic vein joins the venae comitantes of the brachial artery to form the axillary vein at the elbow.
The posterior circumflex humeral vein is encountered before the axillary vein. However, a PICC line is unlikely to enter this structure because of its entry angle into the basilic vein. -
This question is part of the following fields:
- Anatomy
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Question 61
Correct
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A 60 year old non insulin dependent diabetic on metformin undergoes hip arthroscopy under general anaesthesia.
Her preoperative blood glucose is 6.5mmol/L. Anaesthesia is induced with 200 mg propofol and 100 mcg fentanyl and maintained with sevoflurane and air/oxygen mixture. she is given 8 mg dexamethasone, 40 mg parecoxib, 1 g paracetamol and 500 mL Hartmann's solution Intraoperatively.
The procedure took thirty minutes and her blood glucose in recovery is 14 mmol/L.
What is the most likely cause for her rise in blood sugar?Your Answer: Stress response
Explanation:A significant early feature of the metabolic response to trauma and surgery is hyperglycaemia. It is due to an increased glucose production and decreased glucose utilisation bought on by neuroendocrine stimulation. Catecholamines, Growth hormone, ACTH and cortisol, and Glucagon are all increased.
There is also a decreased insulin sensitivity peripherally and an inhibition of insulin production from the beta cells of the pancreas. These changes lead to hyperglycaemia.
The stress response to endoscopic surgery will only be prevented with use of high dose opioids or central neuraxial block at anaesthesia.
To reduce the risk of inducing hyperchloremic acidosis, Ringer’s lactate/acetate or Hartmann’s solution is preferred to 0.9% sodium chloride as routine maintenance fluids.Though it has been suggested that administration of Hartmann’s solution to patients with type 2 diabetes leads to hyperglycaemia, one Litre of Hartmann’s solution would yield a maximum of 14.5 mmol of glucose. A rapid infusion of this volume would increase the plasma glucose by no more than 1 mmol/L..
Dexamethasone, a glucocorticoid, produces hyperglycaemia by stimulating gluconeogenesis . Glucocorticoids are agonists of intracellular glucocorticoid receptors. Their effects are mainly mediated via altered protein synthesis via gene transcription and so the onset of action is slow. The onset of action of dexamethasone is about one to four hours and therefore would NOT contribute to the hyperglycaemia in this patient in the time given.
0.9% Normal saline with or without adrenaline is the usual irrigation fluid. With this type of surgery, systemic absorption is unlikely to occur.
Fentanyl is not likely the primary cause of hyperglycaemia in this patient. In high doses (50 mcg/Kg) it has been shown to reduce the hyperglycaemic responses to surgery.
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This question is part of the following fields:
- Pathophysiology
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Question 62
Correct
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Which of the following vertebral levels is the site where the oesophagus passes through the diaphragm to enter the abdominal cavity?
Your Answer: T10
Explanation:The diaphragm divides the thoracic cavity from the abdominal cavity. Structures penetrate the diaphragm at different vertebral levels through openings in the diaphragm to communicate between the two cavities. The diaphragm has openings at three vertebral levels:
T8: vena cava, terminal branches of the right phrenic nerve
T10: oesophagus, vagal trunks, left anterior phrenic vessels, oesophageal branches of the left gastric vessels
T12: descending aorta, thoracic duct, azygous and hemi-azygous vein -
This question is part of the following fields:
- Anatomy
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Question 63
Incorrect
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You are given an intravenous induction agent. The following are its characteristics:
A racemic mixture of cyclohexanone rings with one chiral centre
Local anaesthetic properties.
Which of the following statements about its primary mechanism of action is most accurate?Your Answer: Reversible competitive antagonist affecting Na+ channels
Correct Answer: Non-competitive antagonist affecting Ca2+ channels
Explanation:Ketamine is the substance in question. Its structure and pharmacodynamic effects make it a one-of-a-kind intravenous induction agent. The molecule is made up of two cyclohexanone rings (2-(O-chlorophenyl)-2-methylamino cyclohexanone and 2-(O-chlorophenyl)-2-methylamino cyclohexanone). Ketamine has local anaesthetic properties and acts primarily on the brain and spinal cord.
It affects Ca2+ channels as a non-competitive antagonist for the N-D-methyl-aspartate (NMDA) receptor. It also acts as a local anaesthetic by interfering with neuronal Na+ channels.
Ketamine causes profound dissociative anaesthesia (profound amnesia and analgesia) as well as sedation.
Phenoxybenzamine, an alpha-1 adrenoreceptor antagonist, is an example of an irreversible competitive antagonist. It forms a covalent bond with the calcium influx receptor.
Benzodiazepines are GABAA receptor agonists that affect chloride influx.
Flumazenil is an inverse agonist that affects GABAA receptor chloride influx.
Ketamine is a cyclohexanone derivative that acts as a non-competitive Ca2+ channel antagonist.
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This question is part of the following fields:
- Pharmacology
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Question 64
Correct
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A 42 year old lady has acute onset of painless weakness on her left side of the face with a drooping mouth and difficulty speaking. With no significant past medical history and after relevant investigations, you rule out stroke as a possible cause. The lady is suspected to have suffered Bell's palsy, an idiopathic paralysis of the facial nerve.
What symptoms are you most likely to find on examination in a patient with Bell's palsy?Your Answer: Taste impairment of the anterior tongue
Explanation:Bell’s palsy is facial muscle weakness or paralysis that arises from idiopathic damage to the facial nerve. It can occur at any age but is commonly associated with some conditions:
1. pregnancy
2. diabetes
3. upper respiratory ailment
4. GBS
5. ToxinsThe common symptoms of Bell’s palsy are:
1. Abnormal corneal reflex as the facial nerve controls the motor aspect of the corneal reflex.
2. The loss of control of facial muscles and eyelids leads to decreased tear production.
3. mild weakness to total paralysis on one side of the face, occurring within hours to days.
4. Bell’s palsy is a lower motor neuron lesion that usually spares the forehead while the upper motor near lesions, like stroke, involves the entire face.
5. The anterior two-thirds of the tongue is supplied by the chorda tympani branch of the facial nerve, thus resulting in loss of taste.
6. Ptosis can be a feature of Bell’s palsy but Bell’s palsy would typically show unilateral symptoms rather than bilateral. -
This question is part of the following fields:
- Anatomy
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Question 65
Correct
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A 20-year-old man has been diagnosed with mitral regurgitation. He will be treated with mitral valve repair.
What is true regarding the mitral valve?Your Answer: Its closure is marked by the first heart sound
Explanation:The mitral valve is the valve between the left atrium and left ventricle. It opens when the heart is in diastole (relaxation) which allows blood to flow from the left atrium to the left ventricle. In systole (contraction), the mitral valve closes to prevent the backflow of blood from the left ventricle to the left atrium.
The mitral valve is located posterior to the sternum at the level of the 4th costal cartilage. It is best auscultated over the cardiac apex, where its closure marks the first heart sound.
The mitral valve anatomy is composed of five main structures:
1. Left atrial wall – the myocardium of the left atrial wall extends over the posterior leaflet of the mitral valve. (left atrial enlargement is one of the causes for mitral regurgitation)
2. Mitral annulus – a fibrous ring that connects with the anterior and posterior leaflets. It functions as a sphincter that contracts and reduces the surface area of the valve during systole (Annular dilatation can also lead to mitral regurgitation)
3. Mitral valve leaflets (cusps) – The mitral valve is the only valve in the heart with two cusps or leaflets. One anterior and one posterior.
i. The anterior leaflet is located posterior to the aortic root and is also anchored to the aortic root.
ii. The posterior leaflet is located posterior to the two commissural areas.
4. Chordae tendinae – The chordae tendinae connects both the cusps to the papillary muscles.
5. Papillary muscles – These muscles and their cords support the mitral valve, allowing the cusps to resist the pressure developed during contractions (pumping) of the left ventricleThe anterior and posterior cusps are attached to the chordae tendinae which itself is attached to the left ventricle via papillary muscle.
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This question is part of the following fields:
- Anatomy
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Question 66
Correct
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Which of these anaesthetics has the best chance of preventing HPV (hypoxic pulmonary vasoconstriction)?
Your Answer: Desflurane 2 MAC
Explanation:Resistance pulmonary arteries constrict in response to alveolar and airway hypoxia, diverting blood to better-oxygenated alveoli.
In atelectasis, pneumonia, asthma, and adult respiratory distress syndrome, hypoxic pulmonary vasoconstriction optimises O2 uptake. Hypoxic pulmonary vasoconstriction helps maintain systemic oxygenation during single-lung anaesthesia.
A redox-based O2 sensor within pulmonary artery smooth muscle cells is involved in hypoxic pulmonary vasoconstriction. The production of reactive oxygen species by smooth muscle cells in the pulmonary artery varies in proportion to PaO2. Hypoxic removal of these redox second messengers inhibits voltage-gated potassium channels, depolarizing smooth muscle cells in the pulmonary artery.
L-type calcium channels are activated by depolarization, which raises cytosolic calcium and causes hypoxic pulmonary vasoconstriction. Some anaesthetics suppress this response, increasing the risk of further deterioration in ventilation perfusion mismatch.
Agents that inhibit HPV are ether, halothane, and desflurane (>1.6 MAC).
Agents with no effect on HPV include thiopentone, fentanyl, desflurane (1MAC), isoflurane (<1.5MAC), sevoflurane(1MAC), and propofol. -
This question is part of the following fields:
- Pharmacology
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Question 67
Correct
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About the vagus nerve, which one of these is true ?
Your Answer: Gives off the recurrent laryngeal nerve on the right as it passes anteriorly across the subclavian artery
Explanation:The tenth cranial nerve (vagus nerve) has both sensory and motor divisions.
It emerges from the anterolateral surface of the medulla in a groove between the olive and the inferior cerebellar peduncle as a series of 8-10 rootlets . It leaves the skull through the middle compartment of the jugular foramen and descends within the carotid sheath between the internal carotid artery and internal jugular vein. The right vagus crosses in front of the first part of the subclavian artery. It gives off the right recurrent laryngeal nerve at this point.
The left recurrent laryngeal nerve passes around the ligamentum arteriosum.
The external laryngeal nerve supplies the cricothyroid muscle while the recurrent laryngeal nerve supplies the other laryngeal muscles.
The cranial part of the accessory nerve supplies all the muscles of the palate, via the pharyngeal plexus and the pharyngeal branch of the vagus nerve, except the tensor veli palatini which is supplied by the mandibular branch of the trigeminal nerve.
The Sternothyroid, Sternohyoid, and Omohyoid muscles are supplied by the ansa cervicalis while the thyrohyoid muscle is supplied by the hypoglossal nerve.
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This question is part of the following fields:
- Anatomy
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Question 68
Correct
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Over the course of 10 minutes, one litre of 0.9% normal saline is intravenously infused into a normally fit and well 58-year-old male. A catheter is used to measure urine output before and after the infusion. The patient is 70 kg in weight.
The following data on urine output is obtained:
50ml/hour Before the infusion
200 ml/hour 1 hour following infusion
90 ml/hour 2 hours after the infusion
60 ml/hr 3 hours after the infusion
Which of the following physiological responses is most likely to account for the sudden increase in urine output after a fluid bolus?Your Answer: Increased glomerular filtration rate
Explanation:The following are some basic assumptions:
Extracellular fluid (ECF) makes up one-third of total body water (TBW), while intracellular fluid makes up the other two-thirds (ICF).
One-quarter of ECF is plasma, and three-quarters is interstitial fluid (ISF).
The volume receptors have a 7-10% blood volume change threshold. The osmoreceptors are sensitive to changes in osmolality of 1-2 percent.
Prior to the transfusion, the plasma osmolality is normal (between 287 and 290 mOsm/kg).
[Na+] in 0.9 percent N. saline is 154 mmol/L, which is similar to that of extracellular fluid. When given intravenously, this limits its distribution within the extracellular space, resulting in a plasma compartment:ISF volume ratio of 1:3.
In this time frame, one litre of 0.9 percent N. saline will increase plasma volume by about 250 mL, which could be the threshold for activation of the volume receptors in the atria, resulting in the release of atrial natriuretic peptide (ANP).Because 0.9 percent N. saline is isosmotic, after a 1 L infusion, plasma osmolality will not change. No changes in antidiuretic hormone secretion will be detected by the hypothalamic osmoreceptors.
Because normal saline is protein-free, the oncotic pressure in the blood is slightly reduced after the saline infusion. As a result, fluid movement into the ISF is favoured (Starling’s hypothesis), and the lower oncotic pressure causes an immediate increase in the glomerular filtration rate (GFR) and a reduction in water reabsorption in the proximal tubule.
The flow of urine increases. There is no hormonal intermediary in this effect, so it is strictly local. Urine flow immediately increases. The fluid returns to the intravascular compartment, and urine flow continues until all of the transfused fluid has been excreted.
Blood pressure changes associated with a 1 L fluid infusion are unlikely to affect high-pressure baroreceptors in the carotid sinus.
The juxta-glomerular cells of the afferent arteriole are adjacent to the specialised cells (macula densa) of distal tubules. The sodium and chloride ions in the tubular fluid are detected by the macula densa. Renin release is inhibited when the tubular fluid contains too much sodium chloride. Hormonal changes take longer to manifest than physical changes that control glomerulotubular balance.
Hypertonic saline, not 0.9 percent N saline, is an osmotic diuretic. -
This question is part of the following fields:
- Pathophysiology
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Question 69
Correct
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A 74-year-old man presents to a hospital for manipulation of Colles fracture. The patient is 50 kg and the anaesthetic plan is to perform an intravenous regional (Bier's) block.
Which of the following is the appropriate dose of local anaesthetic for the procedure?Your Answer: 0.5% prilocaine (40 ml)
Explanation:Prilocaine is the drug of choice for intravenous regional anaesthesia. 0.5% prilocaine (40 ml) is indicated for this condition.
Lidocaine is another alternative for this condition but volume and dose are likely to be inadequate for the procedure. -
This question is part of the following fields:
- Pharmacology
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Question 70
Correct
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Which of the following is true regarding a laryngoscope?
Your Answer: The Wisconsin and Seward are examples of straight blade laryngoscopes
Explanation:Direct laryngoscopy are performed using laryngoscopes and they can be classed according to the shape of the blade as curved or straight.
Miller, Soper, Wisconsin and Seward are examples of straight blade laryngoscopes. Straight blades are commonly used for intubating neonates and infants but can be used in adults too.
The tip of the miller blade is advanced over the epiglottis to the tracheal entrance then lifted in order to view the vocal cords.
The RIGHT-SIDED Macintosh blade is used in adults while the left-sided blade may be used in conditions that make intubation with standard blade difficult e.g. facial deformities.
The McCoy laryngoscope is based on the STANDARD MACINTOSH blade not Robertshaw’s. It has a lever operated hinged tip, which improves the view during laryngoscopy.
Polio blade is mounted at an angle of 120-135 degrees to the handle. Originally designed for use during the polio epidemic in intubation patients within iron lung ventilators, it is now useful in patients with conditions like breast hypertrophy, barrel chest, and restricted neck mobility.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 71
Correct
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A 60-year old male has anaemia and is being investigated. The most common combination of globin chains in a normal adult is:
Your Answer: α2β2
Explanation:There are 4 different types of globin chains which surround 4 heme molecules in haemoglobin (Hb) – α (alpha), β (beta), γ (gamma), and δ (delta)
α chains are essential.
δ2β2 and β2γ2 are not found in a healthy adult.
97% of the Hb in a healthy adult is made of α2β2 (2 α chains and 2 β chains).
α2δ2 accounts for around 1.5-3% of the adult Hb.
α2γ2 accounts for less than 1%.With respect to oxygen transport in cells, almost all oxygen is transported within erythrocytes. There is limited solubility and only 1% is carried as solution. Thus, the amount of oxygen transported depends upon haemoglobin concentration and its degree of saturation.
Haemoglobin is a globular protein composed of 4 subunits. Haem is made up of a protoporphyrin ring surrounding an iron atom in its ferrous state. The iron can form two additional bonds – one is with oxygen and the other with a polypeptide chain. There are two alpha and two beta subunits to this polypeptide chain in an adult and together these form globin. Globin cannot bind oxygen but can bind to CO2 and hydrogen ions. The beta chains are able to bind to 2,3 diphosphoglycerate. The oxygenation of haemoglobin is a reversible reaction. The molecular shape of haemoglobin is such that binding of one oxygen molecule facilitates the binding of subsequent molecules.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 72
Correct
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A patient visits the radiology department for a magnetic resonance imaging (MRI) scan (MRI). The presence of metal implants must be ruled out prior to the scan.
In a strong magnetic field, which of the following metals is the safest?Your Answer: Chromium
Explanation:Ferromagnetism is the property of a substance that is magnetically attracted and can be magnetised indefinitely. A material is said to be paramagnetic if it is attracted to a magnetic field. A substance is said to be diamagnetic if it is repelled by a magnetic field.
Cobalt, iron, gadolinium, neodymium, and nickel are ferromagnetic.
Gadolinium is a ferromagnetic rare earth metal that is ferromagnetic below 20 degrees Celsius (its Curie temperature). MRI scans are enhanced with gadolinium-based contrast media.
When ferromagnetic materials are exposed to a magnetic field, they can cause a variety of issues like magnetic field interactions, heating, and image artefacts.
Titanium, lead, chromium, copper, aluminium, silver, gold, and tin are non ferromagnetic.
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This question is part of the following fields:
- Clinical Measurement
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Question 73
Correct
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A 68-year-old man is to be operated.
His past history is significant for a stroke, and some residual neurological deficit. The cranial nerves are examined clinically. He is unable to rotate his head to the left side when resistance is applied. Moreover, there is tongue wasting on the right side. There are no unusual sensory signs and symptoms.
The most likely reason for these clinical findings is?Your Answer: Damage to hypoglossal (XII) and spinal accessory (XI) nerves
Explanation:The upper five cervical segments of the spinal cord give rise to the XI cranial nerve. They connect with a few smaller branches before exiting the skull through the jugular foramen. The sternomastoid and trapezius muscles get their motor supply from the accessory root. Except for the palatoglossus, the hypoglossal nerve supplies motor supply to all tongue muscles.
The inability to shrug the shoulder on the affected side and rotate the head to the side against resistance is caused by damage to the spinal accessory nerve. This is due to the trapezius and sternomastoid muscles’ weakness.
The hypoglossal nerve is damaged, resulting in tongue wasting and inability to move from side to side.
The stylopharyngeus receives motor supply from the glossopharyngeal nerve. It also carries taste sensory fibres from the back third of the tongue, as well as the carotid sinus, carotid body, pharynx, and middle ear.
Motor supply to the larynx, pharynx, and palate; parasympathetic innervation to the heart, lung, and gut; and sensory fibres from the epiglottis and valleculae are all provided by the vagus nerve.
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This question is part of the following fields:
- Pathophysiology
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Question 74
Correct
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Prior to rapid sequence induction of anaesthesia, a man with a BMI of 35 is pre-oxygenated.
Which method of pre-oxygenation with a tight-fitting face mask is the most effective?Your Answer: Oxygen 6 litres per minute via a Mapleson A breathing system, with patient sitting up at 30 degrees breathing four vital capacity breaths
Explanation:This patient is morbidly obese and has a high risk of developing hypoxia. This will be exacerbated by the patient’s supine position, as a result of:
Functional residual capacity has been reduced (FRC)
Increased closing capacity (CC)
Reduced tidal volume due to increased airway resistance, decreased thoracic cage compliance, and decreased respiratory muscle strength and endurance
Following induction of general anaesthesia, there is a tendency for atelectasis and increased O2 consumption due to the increased workload of respiratory muscles and the overall increase in metabolism.Pre-oxygenation with 100 percent oxygen via a tight-fitting mask can be done using either tidal volume breaths for three to five minutes or four vital capacity breaths in normal circumstances. In the head-up position, this patient is much more likely to be adequately pre-oxygenated, maximising the FRC and minimising the CC. In spontaneously breathing patients, the Mapleson A and circle systems are both effective, but the Mapleson D requires 160-200 ml/kg/minute to prevent rebreathing.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 75
Correct
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The most abundant intracellular ion is?
Your Answer: Phosphate
Explanation:Phosphate is the principal anion of the intracellular fluid, most of which is bound to either lipids or proteins. They dissociate or associate with different compounds, depending on the enzymatic reaction, thus forming a constantly shifting pool.
Calcium and magnesium are also present intracellularly, however in lesser amounts than phosphate.
Sodium is the most abundant extracellular cation, and Chloride and is the most abundant extracellular anion.
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This question is part of the following fields:
- Physiology
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Question 76
Correct
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Concerning drug dose and response, one of the following statements is correct?
Your Answer: Intrinsic activity determines maximal response
Explanation:Dose response curves are plotted as % response to drug against Logarithm of drug concentration. The graph is usually sigmoid shaped.
Any drug that has high affinity and high intrinsic activity is likely an agonist. A drug with high affinity but no intrinsic activity will act as an antagonist. Displacement of an agonist also depends on the relative concentrations of the two drugs at the receptor sites.
Maximal response may be achieved by activation of a small proportion of receptor sites.
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This question is part of the following fields:
- Pharmacology
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Question 77
Correct
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Prophylactic antibiotics are required for which of the following procedures?
Your Answer: Caesarean section
Explanation:Staphylococcus aureus infection is the most likely cause.
Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.
SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
The organisms are usually derived from the patient’s own body.Measures that may increase the risk of SSI include:
-Shaving the wound using a single use electrical razor with a disposable head
-Using a non iodine impregnated surgical drape if one is needed
-Tissue hypoxia
-Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.Measures that may decrease the risk of SSI include:
1. Intraoperatively
– Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
-Cover surgical site with dressingIn contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.
2. Post operatively
Tissue viability advice for management of surgical wounds healing by secondary intentionUse of diathermy for skin incisions
In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 78
Correct
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A 60-year-old male is being reviewed in the peri-operative assessment before total knee replacement. He had a history of a heart transplant 10 years back. His resting heart rate is 110 beats per minute. On examination, ECG showed sinus tachycardia.
Which of the following explains this tachycardia?Your Answer: Loss of parasympathetic innervation
Explanation:Normally, at rest vagal influence is dominant producing the heart rate of 60-80 beats per minute even if the intrinsic automaticity of Sinoatrial Node is 100-110 beats per minute.
The transplanted heart has no autonomic nervous supply. So, it will respond to endogenous and exogenous catecholamine. This loss of parasympathetic innervation is responsible for the tachycardia in this patient.
Hypokalaemia can cause myocardial excitability and potential for ventricular ectopic and supraventricular arrhythmias. Hypothyroidism is also unlikely to cause tachycardia in this patient.
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This question is part of the following fields:
- Pathophysiology
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Question 79
Incorrect
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The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised by which of the following?
Your Answer: Small diameter to initiate short term intense contractions
Correct Answer: Synthesis of ATP is brought about by anaerobic respiration
Explanation:Muscle fibre myosin ATPase histochemistry is used to divide the biochemical classification into two groups: type 1 and type II.
Type I (slow twitch) muscle fibres rely on aerobic glycolytic and aerobic oxidative metabolism to function. They have a lot of mitochondria, a good blood supply, a lot of myoglobin, and they don’t get tired easily.
Because they contain more motor units, Type II (fast twitch) muscle fibres are thicker. They are more easily fatigued, but produce powerful bursts. The capillary networks and mitochondria are less dense in these white muscle fibres than in type I fibres. They have a low myoglobin content as well.
Muscle fibres of type II (fast twitch) are divided into three types:
Type IIa – aerobic/oxidative metabolism is used.
Type IIb – anaerobic/glycolytic metabolism is used by these fibres.When compared to skeletal muscle, cardiac and smooth muscle twitch at a slower rate.
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This question is part of the following fields:
- Pharmacology
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Question 80
Incorrect
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An experiment is designed to investigate that how three diets having different sugar content affect the body weight to a different level.
Which one of the following test will determine a statistically significant difference among the diets?Your Answer: Students t-test
Correct Answer: ANOVA
Explanation:Chi-square test is used to determine the statistically significant different between categorical variables. It also determines the difference between expected frequencies and the observed frequencies.
Mann Whitney U test is used to determine the statistically significant different between two independent groups.
Wilcoxon’s test is the test of dependency. it determines the statistically significant difference between two dependent groups.
Student t-test is one of the most commonly used method to test the hypothesis. It determines the significant difference between the means of two different groups.
ANOVA (analysis of variance) is similar to student’s t-test.
ANOVA is a statistical method used to determines the statistically significant difference between the mean of more than two group. In this experiment as we are dealing with three different group, ANOVA is most suitable test to determine the difference between each groups.
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This question is part of the following fields:
- Statistical Methods
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Question 81
Correct
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Modified rapid sequence induction with 1mg/kg rocuronium was done is a 42-year-old male for emergency appendicectomy. The patient weight was 70 kg and a failed intubation indicated immediate reversal of neuromuscular blockade.
Which of the following is the correct dose of sugammadex for this patient?Your Answer: 1120 mg
Explanation:Sugammadex is used for immediate reversal of rocuronium-induced neuromuscular blockade.
It is used at a dose of 16 mg/kg.Since the patient in the question is 70 kg, the required dose of sugammadex can be calculated as:
16×70 = 1120 mg.Sugammadex selectively binds rocuronium or vecuronium, thereby reversing their neuromuscular blocking action. Due to its 1:1 binding of rocuronium or vecuronium, it can reverse any depth of neuromuscular block.
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This question is part of the following fields:
- Pharmacology
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Question 82
Correct
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A 72-year old man has presented to the emergency room with sweating, nausea, chest pain, and an ECG that shows ST elevation. The ST segment of the ECG corresponds to a period of slow calcium influx in the cardiac action potential.
This equates to which phase in the cardiac action potential?Your Answer: Phase 2
Explanation:Understanding of the cardiac action potential helps with the understanding of the ECG which measures the electrical activity of the heart. This is reflected in its waveform.
The rapid depolarisation phase is reflected in the QRS complex. After this phase comes the plateau phase which is represented by the ST segment. Lastly, the T wave shows repolarisation, phase 3.The cardiac action potential has several phases which have different mechanisms of action as seen below:
Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
These channels automatically deactivate after a few msPhase 1: caused by early repolarisation and an efflux of potassium.
Phase 2: Plateau – caused by a slow influx of calcium. (ST segment)
Phase 3 – Final repolarisation – caused by an efflux of potassium. (T wave)
Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potentialOf note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.
Different sites have different conduction velocities:
1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec2. AV node conduction – 0.05 m/sec
3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 83
Correct
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Which of the following can be measured directly using spirometry?
Your Answer: Vital capacity
Explanation:Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).
It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.
During spirometry, the following measurements can be determined:
Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
Forced expiratory volume in one second (FEV1)
FEV1/FVC ratio
Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.
Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution
The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.
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This question is part of the following fields:
- Clinical Measurement
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Question 84
Correct
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The following is true about the extracellular fluid (ECF) in a normal adult woman weighing 60 kg.
Your Answer: Has a total volume of about 12 litres
Explanation:Total body water (TBW) is about 50% to 70% in adults depending on how much fat is present. ECF is relatively contracted in an obese person.
The simple rule is 60-40-20. (60% of weight = total body water, 40% of body weight is ICF and 20% is ECF)
For this woman, the total body water is 36 litres (0.6 × 60). ECF is 12 litres (1/3 of TBW) and 24 litres (2/3 of TBW) is intracellular fluid .
Sodium concentration is approximately 135-145 mmol/L in the ECF.
The ECF is made up of both intravascular and extravascular fluid and plasma proteins is found in both.
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This question is part of the following fields:
- Physiology
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Question 85
Correct
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What does therapeutic index in humans mean?
Your Answer: The TD50 divided by the ED50
Explanation:Therapeutic index is a measure which relates the dose of a drug required to produce a desired effect to that which produces an undesired effect.
In humans, it is usually defined as the ratio of the toxic dose for 50% of the population (TD50) to the minimum effective dose for 50% of the population (ED50) for some therapeutically relevant effect. In animal studies, the therapeutic index can be defined as the ratio of the median lethal dose (LD50) to the ED50.
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This question is part of the following fields:
- Pharmacology
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Question 86
Correct
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A 54-year-old lady comes in for a right-sided elective bunionectomy with a realignment osteotomy under local anaesthetic on her first (large) toe.
For the operation, which of the following nerve blocks will be most effective?Your Answer: Superficial peroneal, deep peroneal and posterior tibial nerves
Explanation:An ankle block is commonly used for anaesthesia and postoperative analgesia when operating on bunions. It results in the selective block of the superficial peroneal, deep peroneal, and posterior tibial nerves.
The deep peroneal nerve supplies sensory input to the web space between the first and second toes (L4-5).
The L2-S1 nerve, often known as the superficial peroneal nerve, is a mixed motor and sensory neuron. It gives sensory supply to the anterolateral region of the leg, the anterior aspect of the 1st, 2nd, 3rd, and 4th toes, and innervates the peroneus longus and brevis muscles (with the exception of the web space between 1st and 2nd toes).
The sensory area of the saphenous nerve (L3-4) in the foot stretches from the proximal portion of the midfoot on the medial side to the proximal part of the midfoot on the lateral side.
The lateral side of the little (fifth) toe is innervated by the sural nerve’s sensory supply (S1-2). The heel, medial (medial plantar nerve), and lateral (lateral plantar nerve) soles of the foot are all served by the posterior tibial nerve.
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This question is part of the following fields:
- Pathophysiology
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Question 87
Correct
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Concerning the trachea, which of these is true?
Your Answer: In an adult is approximately 15 cm long
Explanation:In an adult, the trachea is approximately 15 cm long. It extends at the level of the 6th cervical vertebra, from the lower border of the cricoid cartilage.
The trachea terminates between T4 and T6 at the carina or bronchial bifurcation. This variation is because of changes during respiration.
The trachea has 16-20 C-shaped cartilaginous rings that maintain its patency.
The trachea is first of the 23 generations of air passages in the tracheobronchial tree (not 25), from the trachea to the alveoli..
The inferior thyroid arteries which are branches of the thyrocervical trunk, arise from the first part of the subclavian artery and supplies the trachea.
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This question is part of the following fields:
- Anatomy
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Question 88
Correct
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Given the following values:
Expired tidal volume = 800 ml
Plateau pressure = 50 cmH2O
PEEP = 10 cmH2O
Compute for the static pulmonary compliance.Your Answer: 20 ml/cmH2O
Explanation:Compliance of the respiratory system describes the expandability of the lungs and chest wall. There are two types of compliance: dynamic and static.
Dynamic compliance describes the compliance measured during breathing, which involves a combination of lung compliance and airway resistance. Defined as the change in lung volume per unit change in pressure in the presence of flow.
Static compliance describes pulmonary compliance when there is no airflow, like an inspiratory pause. Defined as the change in lung volume per unit change in pressure in the absence of flow.
For example, if a person was to fill the lung with pressure and then not move it, the pressure would eventually decrease; this is the static compliance measurement. Dynamic compliance is measured by dividing the tidal volume, the average volume of air in one breath cycle, by the difference between the pressure of the lungs at full inspiration and full expiration. Static compliance is always a higher value than dynamic
Static compliance can be computed using the formula:
Cstat = Tidal volume/Plateau pressure – PEEP
Substituting the values given,
Cstat = 800/50-10
Cstat = 20 ml/cmH2O -
This question is part of the following fields:
- Physiology
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Question 89
Correct
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During a stabbing incident, a 30-year-old injured his inferior vena cava. What number of functional valves can be usually found in this vessel?
Your Answer: 0
Explanation:The inferior vena cava is formed by the union of the right and left common iliac veins. The inferior vena cava has no functional valves like the one-way valves commonly found in many veins. The forward flow to the heart is driven by the differential pressure created by normal respiration.
The absence of functional valves has an important clinical role when cannulating during cardiopulmonary bypass.
There is a valve that is non-functioning called the eustachian valve that lies at the junction of the IVC and the right atrium. This valve has a role to help direct the flow of oxygen-rich blood through the right atrium to the left atrium via the foramen ovale during fetal life. It has no specific function in adult life.
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This question is part of the following fields:
- Anatomy
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Question 90
Correct
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Of the following, which of these oxygen carrying molecules causes the greatest shift of the oxygen-dissociation curve to the left?
Your Answer: Myoglobin (Mb)
Explanation:Myoglobin is a haemoglobin-like, iron-containing pigment that is found in muscle fibres. It has a high affinity for oxygen and it consists of a single alpha polypeptide chain. It binds only one oxygen molecule, unlike haemoglobin, which binds 4 oxygen molecules.
The myoglobin ODC is a rectangular hyperbola. There is a very low P50 0.37 kPa (2.75 mmHg). This means that it needs a lower P50 to facilitate oxygen offloading from haemoglobin. It is low enough to be able to offload oxygen onto myoglobin where it is stored. Myoglobin releases its oxygen at the very low PO2 values found inside the mitochondria.
P50 is defined as the affinity of haemoglobin for oxygen: It is the PO2 at which the haemoglobin becomes 50% saturated with oxygen. Normally, the P50 of adult haemoglobin is 3.47 kPa(26 mmHg).
Foetal haemoglobin has 2 ? and 2 ?chains. The ODC is left shifted – this means that P50 lies between 2.34-2.67 kPa [18-20 mmHg]) compared with the adult curve and it has a higher affinity for oxygen. Foetal haemoglobin has no ? chains so this means that there is less binding of 2.3 diphosphoglycerate (2,3 DPG).
Carbon monoxide binds to haemoglobin with an affinity more than 200-fold higher than that of oxygen. This therefore decreases the amount of haemoglobin that is available for oxygen transport. Carbon monoxide binding also increases the affinity of haemoglobin for oxygen, which shifts the oxygen-haemoglobin dissociation curve to the left and thus impedes oxygen unloading in the tissues.
In sickle cell disease, (HbSS) has a P50 of 4.53 kPa(34 mmHg).
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This question is part of the following fields:
- Physiology
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Question 91
Correct
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Which of these structures will cause the biggest reduction in hepatic blood flow when occluded surgically?
Your Answer: Portal vein
Explanation:The portal vein arises from the splenic and mesenteric veins, and is the biggest vessel in the portal venous system, accounting for about 75% of the hepatic blood flow.
It is responsible for draining blood from parts of the gastrointestinal system, the spleen, the pancreas and the gallbladder into the liver.
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This question is part of the following fields:
- Anatomy
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Question 92
Incorrect
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A 10-year-old girl complains of right iliac fossa pain, and a provisional diagnosis of appendicitis is made.
Which of the following embryological structures gives rise to the appendix?Your Answer: Hindgut
Correct Answer: Midgut
Explanation:The midgut gives rise to the appendix.
At week 6, the caecal diverticulum appears and is the precursor for the cecum and vermiform appendix. The cecum and appendix undergo rotation and descend into the right lower abdomen. The appendix can take up various positions:
1. Retrocecal appendix: behind the cecum
2. Retrocolic appendix: behind the ascending colon
3. Pelvic appendix: appendix descends into the pelvisThe appendix grows in length so that at birth, it is long and worm-shaped, or vermiform. After birth, the caecal wall grows unequally, and the appendix comes to lie on its medial side.
The midgut develops into the distal duodenum, jejunum, ileum, cecum, appendix, ascending colon, and proximal 2/3 of the transverse colon.
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This question is part of the following fields:
- Anatomy
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Question 93
Correct
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International colour coding is used on medical gas cylinders. Other characteristics also play a role in determining the gas's identity within a cylinder.
Which of the following options best describes a cylinder containing analgesics for obstetrics?Your Answer: Blue body, blue/white shoulder, full cylinder; 13700 KPa, gas mixture, requires a dual stage pressure regulator
Explanation:The body of the Entonox cylinder is usually blue (occasionally white), with blue and white shoulders. Entonox contains a 50:50 mixture of oxygen and nitrous oxide, with a full cylinder pressure of 13700 KPa (137 bar). The cylinder is equipped with a two-stage pressure regulator for safe operation.
The cylinder body and shoulder of nitrous oxide are (French) blue.
In today’s anaesthetic workstations, carbon dioxide cylinders are no longer used.
The body of an oxygen cylinder is black, with a white shoulder.
The white Heliox (21 percent oxygen and 79 percent helium) cylinder has a brown and white shoulder. The administration of this gas mixture, which is less dense than air, is used to reduce turbulence (stridor) of inspiratory flow in patients with upper airway obstruction.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 94
Correct
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Which of the following statements is true regarding the relation to the liver?
Your Answer: The caudate lobe is superior to the porta hepatis
Explanation:Ligamentum venosum is an anterior relation of the liver: The ligamentum venosum, the fibrous remnant of the ductus venosus of the fetal circulation, lies posterior to the liver. It lies in the fossa for ductus venosus that separates the caudate lobe and the left lobe of the liver.
The portal triad contains three important tubes: 1. Proper hepatic artery 2. Hepatic portal vein 3. Bile ductules It also contains lymphatic vessels and a branch of the vagus nerve.
The bare area of the liver is a large triangular area that is devoid of any peritoneal covering. The bare area is attached directly to the diaphragm by loose connective tissue. This nonperitoneal area is created by a wide separation between the coronary ligaments.
The porta hepatis is a fissure in the inferior surface of the liver. All the neurovascular structures (except the hepatic veins) and hepatic ducts enter or leave the liver via the porta hepatis. It contains the sympathetic branch to the liver and gallbladder and the parasympathetic, hepatic branch of the vagus nerve. The caudate lobe (segment I) lies in the lesser sac on the inferior surface of the liver between the IVC on the right, the ligamentum venosum on the left, and the porta hepatis in front
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This question is part of the following fields:
- Anatomy
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Question 95
Correct
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Which of the following drugs would cause the most clinical concern if accidentally administered intravenously to a 4-year-old boy?
Your Answer: 20 mg codeine
Explanation:To begin, one must determine the child’s approximate weight. There are a variety of formulas to choose from. It is acceptable to use the advanced paediatric life support formula:
(age + 4) 2 = weight
A 5-year-old child will weigh around 18 kilogrammes.
The following are the appropriate doses of the drugs listed above:
Gentamicin (once daily) – 5-7 mg/kg = 90-126 mg and subsequent dose modified according to plasma levels
Ondansetron – 0.1 mg/kg, but a maximum of 4 mg as a single dose = 1.8 mg
Codeine should be administered orally at a dose of 1 mg/kg rather than intravenously, as the latter can cause ‘dangerous’ hypotension due to histamine release.
15 mg/kg paracetamol = 270 mg orally or intravenously (a loading dose of 20 mg/kg, or 360 mg, is sometimes recommended, which is not far short of the doses listed above).
Cefuroxime – the initial intravenous dose is 20 mg/kg (360 mg) depending on the indication (again, similar to the dose given in the answer options above). -
This question is part of the following fields:
- Pharmacology
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Question 96
Correct
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Which of the following statements is the most correct about ketamine?
Your Answer: The S (+) isomer is more potent that the R (-) isomer
Explanation:Ketamine, a phencyclidine derivative, is an antagonist at the NMDA receptor. It causes depression of the CNS that is dose dependent and induces a dissociative anaesthetic state with profound analgesia and amnesia.
Ketamine has a chiral centre usually presented as a racemic mixture with two optical isomers, S (+) and R (-) forms. These isomers are in equal proportions. The S (+) isomer is about three times more potent than the R (-) form. The S (+) form is less likely to cause emergence delirium and hallucinations.
Ketamine is extensively metabolised by hepatic microsomal cytochrome P450 enzymes producing norketamine as its main metabolite. Norketamine has a one third to one fifth as potency as its parent compound.
It increases the CMRO2, cerebral blood flow and potentially increase intracranial pressure. -
This question is part of the following fields:
- Pharmacology
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Question 97
Correct
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Calcium homeostasis is regulated by parathormone (PTH).
Which of the following PTH actions is most likely to cause calcium to be released from bone?Your Answer: Indirect stimulation of osteoclasts
Explanation:The hormone parathyroid hormone (PTH) and the receptor parathyroid hormone type 1 (PTH1-Rc) are important regulators of blood calcium homeostasis.
PTH can cause a rapid release of calcium from the matrix in bone, but it also affects long-term calcium metabolism by acting directly on bone-forming osteoblasts (by binding to PTH1-Rc) and indirectly on bone-resorbing osteoclasts.
PTH causes changes in the synthesis and/or activity of several proteins, including osteoclast-differentiating factor, also known as TRANCE or RANKL, when it acts on osteoblasts.
RANK receptors are found on the cell surfaces of osteoclast precursors. The osteoclasts are activated when RANKL binds to the RANK receptors. Osteoclasts lack PTH receptors, whereas osteoblasts do. Osteoclasts are activated indirectly when the RANK receptor binds to the RANKL secreted by osteoblasts, resulting in bone resorption. PTH1 receptors are found in osteoclasts, but they are few.
PTH activates G-protein coupled receptors in all target cells via adenylate cyclase.
The PTH2 receptor is most abundant in the nervous system and pancreas, but it is not a calcium metabolism regulator. It is abundant in the septum, midline thalamic nuclei, several hypothalamic nuclei, and the dorsal horn of the spinal cord, as well as the cerebral cortex and basal ganglia. Expression in pancreatic islet somatostatin cells is the most prominent on the periphery.
The distribution of the receptor is being used to test functional hypotheses. It may play a role in pain modulation and hypothalamic releasing-factor secretion control.
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This question is part of the following fields:
- Pathophysiology
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Question 98
Correct
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A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a 57-year-old woman. Her vision is causing her problems.
A macroadenoma compressing the optic chiasm is visible on MRI.
What is the most likely visual field defect to be discovered during an examination?Your Answer: Bitemporal hemianopia
Explanation:The pituitary gland plays a crucial role in the neuro-endocrine axis. It is located at the base of the skull in the sella turcica of the sphenoid bone. It is connected superiorly to the hypothalamus, third ventricle, and visual pathways, and laterally to the cavernous sinuses, internal carotid arteries, and cranial nerves III, IV, V, and VI.
Pituitary tumours make up about 10-15% of all intracranial tumours. The majority of adenomas are benign. Over-secretion of pituitary hormones (most commonly prolactin, growth hormone, or ACTH), under-secretion of hormones, or localised or generalised pressure effects can all cause symptoms.
Compression of the optic chiasm can result in visual field defects, the most common of which is bitemporal hemianopia. This is caused by compression of the nasal retinal fibres, which carry visual impulses from temporal vision across the optic chiasm to the contralateral sides before continuing to the optic tracts.
The interruption of the visual pathways distal to the optic chiasm causes a homonymous visual field defect. The loss of the right or left halves of each eye’s visual field is referred to as homonymous hemianopia. It’s usually caused by a middle or posterior cerebral artery territory stroke that affects the occipital lobe’s optic radiation or visual cortex.
Binasal hemianopia is a condition in which vision is lost in the inner half of both eyes (nasal or medial). It’s caused by compression of the temporal visual pathways, which don’t cross at the optic chiasm and instead continue to the ipsilateral optic tracts. Binasal hemianopia is a rare complication caused by the internal carotid artery impinging on the temporal (lateral) visual fibres.
A monocular visual loss (that is, loss of vision in only one eye) can be caused by a variety of factors, but if caused by nerve damage, the damage would be proximal to the optic chiasm on the ipsilateral side.
A central scotoma is another name for central visual field loss. Every normal mammalian eye has a scotoma, also known as a blind spot, in its field of vision. The optic disc is a region of the retina that lacks photoreceptor cells and is where the retinal ganglion cell axons that make up the optic nerve exit the retina. When both eyes are open, visual signals that are absent in one eye’s blind spot are provided for the other eye by the opposite visual cortex, even if the other eye is closed.
Scotomata can be caused by a variety of factors, including demyelinating disease such as multiple sclerosis, damage to nerve fibre layer in the retina, methyl alcohol, ethambutol, quinine, nutritional deficiencies, and vascular blockages either in the retina or in the optic nerve.
Bilateral scotoma can occur when a pituitary tumour compresses the optic chiasm, causing a bitemporal paracentral scotoma, which then spreads out to the periphery, causing bitemporal hemianopsia. A central scotoma in a pregnant woman could be a sign of severe pre-eclampsia.
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This question is part of the following fields:
- Pathophysiology
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Question 99
Correct
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With regards to this state of matter which has a volume but no definite shape, particles are not tightly packed together. These are incompressible although there is free movement within the volume.
This statement best describes which one of the following states of matter?Your Answer: Liquid
Explanation:The solid state of matter has a definite volume and shape and particles are packed closely together and are incompressible. Within this tight lattice, there is enough thermal energy to produce vibration of particles.
Liquids however have a volume but no definite shape. These particles are less tightly packed together. Although there is free movement within the volume, they are incompressible.
Gases, however, have no finite shape or volume and particles are free to move rapidly in a state of random motion. They are compressible and are completely shaped by the space in which they are held. Vapours exist as a gas phase in equilibrium with identical liquid or solid matter below its boiling point.
The most prevalent state of matter in the universe is plasma which is formed by heating atoms to very high temperatures to form ions.
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This question is part of the following fields:
- Basic Physics
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Question 100
Correct
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A 21-year-old female was brought to the Emergency department with a ruptured ectopic pregnancy.
On clinical examination, the following were the findings:
Pulse: 120 beats per minute
BP: 120/95 mmHg
Respiratory rate: 22 breaths per minute
Capillary refill time: three seconds
Cool peripheries.
Which of the following best describes the cause for this clinical finding?Your Answer: Reduction in blood volume of 15-30%
Explanation:Classification of hemorrhagic shock according to Advanced Trauma Life Support is as follows:
– Class I haemorrhage (blood loss up to 15%) in which there is no change in blood pressure, RR, or pulse pressure.
– Class II haemorrhage (15-30% blood volume loss) where there is tachycardia, tachypnoea, and a decrease in pulse pressure.
– Class III haemorrhage (30-40% blood volume loss) where clinical signs of inadequate perfusion, marked tachycardia, tachypnoea, significant changes in mental state, and measurable fall in systolic pressure is seen. It almost always requires a blood transfusion.
– Class IV haemorrhage (> 40% blood volume loss) in which marked tachycardia, significant depression in systolic pressure and very narrow pulse pressure, and markedly depressed mental state with cold and pale skin are seen.
Loss of >50% results in loss of consciousness, pulse, and blood pressure.
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This question is part of the following fields:
- Pathophysiology
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Question 101
Correct
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Among the different classes of anti-arrhythmics, which one is the first line treatment for narrow complex AV nodal re-entry tachycardia?
Your Answer: Adenosine
Explanation:Adenosine is the first line for AV nodal re-entry tachycardia. An initial dose of 6 mg is given, and a consequent second dose or third dose of 12 mg is administered if the initial dose fails to terminate the arrhythmia.
Aside from Adenosine, a vagal manoeuvre (e.g. carotid massage) is done to help terminate the supraventricular arrhythmia.
Amiodarone is not a first-line drug for supraventricular tachycardias. Digoxin and Propranolol can be considered if the arrhythmia is of a narrow complex irregular type. Verapamil is an alternative to Adenosine if the latter is contraindicated.
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This question is part of the following fields:
- Pharmacology
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Question 102
Correct
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The clavipectoral fascia is penetrated by the cephalic vein to terminate in which of the listed veins?
Your Answer: Axillary
Explanation:The cephalic vein is a superficial vein that runs through the forearm and the arm, before draining into the axillary vein where it terminates.
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This question is part of the following fields:
- Anatomy
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Question 103
Correct
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A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath and pleuritic chest pain. Her work requires her to travel internationally frequently. The consultant makes a diagnosis and treats her.
Now, the consultant recommends placing a filter that will prevent future incidents. A needle is placed into the femoral vein and passed up into the abdomen to insert the filter.
What is true regarding the organ where the filter is placed for this patient's condition?Your Answer: It is located posteriorly to the peritoneum
Explanation:The patient likely suffers from pulmonary embolism due to her history of frequent international travels. A filter is placed in the inferior vena cava to decrease the risk of future episodes of pulmonary embolism. The IVC filter is a small, wiry device that can catch blood clots and stop them from going into the heart and lungs. Your IVC is a major vessel that brings deoxygenated blood from the lower body to the heart, from where it is pumped into the lungs.
The filter is placed via a thin catheter inserted into the femoral vein in the groin. The catheter is gently moved up into your IVC, and a filter is introduced.
The IVC is a retroperitoneal organ.
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This question is part of the following fields:
- Anatomy
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Question 104
Correct
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One of the following neuromuscular blocking agents is the most potent:
Your Answer: Vecuronium
Explanation:The measure of drug potency or therapeutic response is the ED95. This is defined as the dose of a neuromuscular blocking drug required to produce a 95% depression of muscle twitch height. The ED50 and ED90 describe a depression of twitch height by 50% and 90% respectively.
The ED95 (mg/kg) of the commonly used neuromuscular blocking agents are:
suxamethonium: 0.27
rocuronium: 0.31
vecuronium: 0.04
pancuronium: 0.07
cisatracurium: 0.04
mivacurium: 0.08 -
This question is part of the following fields:
- Pharmacology
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Question 105
Incorrect
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You have always been curious about the effects of statins. While going through a study, something ticks you off and makes you think that they are way more common then the data suggests and are mostly under reported. In search of some concrete evidence, you decide to conduct a study of your own. While doing research, you come across a recent study that highlights the long term effects of statins.
Which of the following types of study could that have been?Your Answer: A double blinded, placebo controlled randomised controlled trial
Correct Answer: Clinical trial, Phase 4
Explanation:In general practice, majority of phase 3 trials and some of the trials conducted in phase 2 are randomized. Because phase 4 trials require a huge sample size, they are not randomized as much. The primal reason behind conducting phase 3 trials is to test the efficiency and safety in a significant sample population. At this point it is assumed that the drug is effective up to a certain extent.
During a case-control study, subjects that exhibit outcomes of interest are compared with those who don’t show the expected outcome. The extent of exposure to a particular risk factor is then matched between cases and controls. If the exposure among cases surpasses controls, it becomes a risk factor for the outcome that is being studied.
Pilot studies are conducted on a lower and much smaller level, to assess if a randomized controlled trial of the crucial components of a study will be plausible.
Phase 4 trials are the ones that are conducted after its established that the drug is effective and is approved by the regulating authority for use. These trials are concerned with the side effects and potential risks associated with the long term usage of the drug.
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This question is part of the following fields:
- Statistical Methods
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Question 106
Correct
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An adult and a 7-year-old child are anatomically and physiologically very different.
Which of the following physiological characteristics of a 5-year-old most closely resembles those of a healthy adult?Your Answer: Dead space ratio
Explanation:Whatever the age, the dead space ratio is 0.3. It’s the dead space (Vd) to tidal volume ratio (Vt).
The glottis is the narrowest point of the upper airway in an adult, while the cricoid ring is the narrowest point in a child.
A child’s airway resistance is much higher than an adult’s. The resistance to airflow increases as the diameter of a paediatric airway shrinks. The radius (r) to the power of 4 is inversely proportional to airway resistance (r4). As a result, paediatric patients are more susceptible to changes in airflow caused by a small reduction in airway diameter, such as caused by oedema.
The compliance of a newborn’s lungs is very low (5 mL/cmH2O), but it gradually improves as lung size and elasticity grow. Lung compliance in an adult is 200 mL/cmH2O.
In children, minute ventilation (mL/kg/minute) is much higher.
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This question is part of the following fields:
- Pathophysiology
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Question 107
Correct
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One litre of water at 0°C and a pressure of 1 bar is in a water-bath. A 1 kW element is used in heating it.
Given that the specific heat capacity of water is 4181 J/(kg°C) or J/(kg K), how long will it take to raise the temperature of the water by 10°C?Your Answer: 42 seconds
Explanation: -
This question is part of the following fields:
- Physiology
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Question 108
Correct
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Regarding anaesthetic breathing circuits, which one would be the best for spontaneous breathing?
Your Answer: Lack circuit
Explanation:Among the breathing circuits, the Lack circuit is the most efficient for spontaneous breathing.
An outer coaxial tube is present to deliver fresh air; exhaust air is routed to an inner tube, which is then delivered to a scavenging system. An expiratory valve is seen at the patient end, which is an advantage over other circuits. Moreover, the Lack circuit prevents rebreathing slightly greater than the alveolar minute ventilation at 4-5 litres per minute.
The Bain circuit prevents rebreathing at 160-200ml/kg per minute, and is a co-axial version of the Mapleson D circuit.
The Mapleson E circuit prevent rebreathing at a fresh gas flow (FGF) of approximately twice the patient’s normal minute volume. A modification of this, the Mapleson F, has a reservoir bag at the opposite end for the FGF. This circuit is appropriate for paediatric patients with a body weight less than 20 kg.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 109
Incorrect
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Which term among the following is used for the proportion of a particular disease that would be eradicated from a population if the rate of disease were to be reduced to that of the group that has not been exposed to it?
Your Answer: Risk ratio
Correct Answer: Attributable proportion
Explanation:The attributable risk is the rate of a disease in an exposed group to that of a group that has not been exposed to it. It involves the measure of association that is pertinent to making decisions for the individuals.
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This question is part of the following fields:
- Statistical Methods
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Question 110
Correct
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Which of the following options will cause an artificial increase in pulse oximeter (SpO2) readings?
Your Answer: Heavy smoker
Explanation:A pulse oximeter is a piece of medical equipment used as a non-invasive method of measuring the oxygen saturation of blood.
It works by measuring the ratio of absorption of red and infrared light in a section of blood flow, as red light is largely absorbed by deoxygenated blood, and infrared light is largely absorbed by oxygenated blood.
Pulse oximetry relies on photoplethysmography (PPG) waveforms. The oximeter has 2 sides, with different functions. One side houses light-emitting diodes which are responsible for transmitting 2 light wavelengths, 660nm for red light and 940nm for near infrared light. The other side is a photodetector. The light emitted travels through the body and the amount that is not absorbed is measured by the photodetector.
Smokers often have increased levels of carboxy haemoglobin (COHb). This leads to artificial increases in pulse oximeter readings as it is unable to differentiate between COHb and oxyhaemoglobin (O2HB) as they both absorb red light at 660nm. Every 1% increase of circulating carboxyhaemoglobin, results in a correlative 1% increase in oximeter readings.
Prilocaine toxicity will cause an artificial decrease in oximeter readings. This is because prilocaine metabolites cause methemoglobinemia (MetHB), which are dysfunctional haemoglobins unable to properly transport oxygen. In this case, a laboratory multiwavelength co-oximeter is recommended for a more accurate reading.
Anaemia will not affect oximeter readings as long as haemoglobins in the blood are normal.
Sickle cell disease does not affect oximeter readings despite its ability to cause hypoxia and shift the oxygen dissociation curve to the right.
Brown-red fingernail polish will cause an underestimation of pulse oximeter readings.
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This question is part of the following fields:
- Clinical Measurement
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Question 111
Correct
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A 55-year-old man with a ventricular rate of 210 beats per minute is admitted to the emergency department with atrial fibrillation. The patient develops ventricular fibrillation shortly after receiving pharmacotherapy to treat his arrhythmia, from which he is successfully resuscitated.
He has a PR interval of 40 Ms, a prominent delta wave in lead I, and a QRS duration of 120 Ms, according to an ECG from a previous admission.
Which of the following drugs is most likely to be involved in this patient's development of ventricular fibrillation?Your Answer: Digoxin
Explanation:The Wolff-Parkinson-White syndrome (WPWS) is linked to an additional electrical conduction pathway between the atria and ventricles. This accessory pathway (bundle of Kent), unlike the atrioventricular (AV) node, is incapable of slowing down a rapid rate of atrial depolarization. In other words, a short circuit bypasses the AV node. Patients with a rapid ventricular response or narrow complex AV re-entry tachycardia are more likely to develop atrial fibrillation or flutter.
Digoxin can promote impulse transmission through this accessory pathway if a patient with WPWS develops atrial fibrillation because it works by blocking the AV node. This can cause ventricular fibrillation and an extremely rapid ventricular rate. As a result, it’s not advised.
Adenosine, beta-blockers, and calcium channel blockers, among other drugs that interfere with AV nodal conduction, are also generally contraindicated.
The class III antiarrhythmic drugs amiodarone and ibutilide (K+ channel block) and procainamide (Na+ channel block) are the drugs of choice.
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This question is part of the following fields:
- Pharmacology
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Question 112
Incorrect
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While inspecting the caecum, what structure will be identified at the point at which all the taeniae coli converge?
Your Answer: Ileocaecal valve
Correct Answer: Appendix base
Explanation:The taeniae coli are the three outer muscular bands of the cecum, ascending colon, transverse colon, and descending colon.
The taeniae coli converge at the base of the appendix in the cecum where they form a complete longitudinal layer. In the ascending and descending colon, the bands are located anteriorly, posteromedially, and posterolateral.
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This question is part of the following fields:
- Anatomy
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Question 113
Correct
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All of the following statements are false regarding salmeterol except:
Your Answer: Is more potent than salbutamol at the beta-2 receptor
Explanation:Salmeterol is a long-acting Beta 2 selective agonist. Therefore it is only used for prophylaxis whereas salbutamol is a short-acting Beta 2 agonist and is thus used for the treatment of acute attacks of asthma.
Salmeterol is 15 times more potent than salbutamol at the Beta 2 receptor but 4 times less potent at the Beta 1 receptor.
Tachyphylaxis to the unwanted side effects commonly occurs, but not to bronchodilation.
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This question is part of the following fields:
- Pharmacology
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Question 114
Incorrect
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A 20-year-old male student is admitted to ER after sustaining a crush injury of the pelvis.
Clinical examination is as follows:
Airway: Patent
Breathing: RR: 25 breaths per minute, breath sounds vesicular, nil added
Circulation: Capillary refill time = 4 seconds, cool peripheries
Pulse: 125 beats per minute
BP: 125/96 mmHg
Disability:
Glasgow coma score 15
Anxious and in pain.
Secondary survey does not reveal any other significant injuries. The patient is given high flow oxygen therapy and intravenous access is established.
Which one of the following options is the most appropriate initial route of intravenous access?Your Answer: Right internal jugular vein
Correct Answer: Left cephalic vein
Explanation:The clinical signs suggest a class II haemorrhage – 15-30% of circulating blood volume has been lost.
Pelvic fractures are associated with significant concealed haemorrhage (>2000 ml) and may require aggressive fluid resuscitation. Other priorities include stabilisation of the fracture(s) and pain relief.
The Advanced Trauma Life Support (ATLS) classification of haemorrhagic shock is as follows:
Class I haemorrhage (blood loss up to 15%):
<750 ml of blood loss
Minimal tachycardia
No changes in blood pressure, RR or pulse pressure
Normally not require fluid replacement as will be restored in 24 hours, but in trauma correct.Class II haemorrhage (15-30% blood volume loss):
Uncomplicated haemorrhage requiring crystalloid resuscitation
Represents about 750 – 1500 ml of blood loss
Tachycardia, tachypnoea and a decrease in pulse pressure (due to a rise in diastolic component due action of catecholamines)
Minimal systolic pressure changes
Anxiety, fright or hostility
Can usually be stabilised by crystalloid, but may later require a blood transfusion.Class III haemorrhage (30-40% blood volume loss):
Complicated haemorrhagic state in which at least crystalloid and probably blood replacement are required
Classical signs of inadequate perfusion, marked tachycardia, tachypnoea, significant changes in mental state and measurable fall in systolic pressure
Almost always require blood transfusion, but decision based on patient initial response to fluid resuscitation.Class IV haemorrhage (> 40% blood volume loss):
Preterminal event patient will die in minutes
Marked tachycardia, significant depression in systolic pressure and very narrow pulse pressure (or unobtainable diastolic pressure)
Mental state is markedly depressed
Skin cold and pale
Need rapid transfusion and immediate surgical intervention.Loss of >50% results in loss of consciousness, pulse and blood pressure.
The route of choice is an arm vein (cephalic) with one or two large bore cannula. This will enable initial aggressive fluid resuscitation. A central line can be inserted at a later stage if central venous monitoring is deemed necessary. If a suitable peripheral vein cannot be cannulated with a large bore cannula then the internal jugular vein could be accessed rapidly (preferably ultrasound guided).
Intravenous access below the diaphragm in this case is inadvisable when other routes are available.
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This question is part of the following fields:
- Anatomy
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Question 115
Correct
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The following statements are about changes that occur at birth. Which is accurate?
Your Answer: The systemic vascular resistance rises
Explanation:The umbilical vein closes once the umbilical cord is clamped following birth. This causes a rise in systemic vascular resistance, closing the ductus venosus.
Upon birth, the pulmonary vascular resistance is decreased as the lungs are aerated.
At birth, there is a rise in oxygen tension which causes the corresponding constriction of the ductus arteriosus. This prevents a left to right shunt as it stops aortic blood and blood from the pulmonary artery from mixing. The ventricles do no have an opening connecting them.
The foramen ovale closes soon after birth. It is the septum opening between the left and right atrium.
An adult’s cardiac output is expected to be 5 L/min
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This question is part of the following fields:
- Pathophysiology
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Question 116
Correct
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Buffers are solutions that resist a change in pH when protons are produced or consumed. They consist of weak acids and their conjugate bases. Buffers are also present in our bodies, and they are known as physiologic buffers.
Which of these is the most effective buffer in the blood?Your Answer: Bicarbonate
Explanation:The first line of defence against acid-base disorder is buffering. The blood mainly utilizes bicarbonate ion (HCO3-) for its buffering capacity (total of 53%, plasma and red blood cells combined).
Strong acids, when acted upon by a buffer, release H+, which then combines to HCO3- and forms carbonic acid (H2CO3). When acted upon by the enzyme carbonic anhydrase, H2CO3 dissociates into H2O and CO.
The rest are the percentage of utilization for the following buffers:
Haemoglobin (by RBCs) – 35%
Plasma proteins (by plasma) – 7%
Organic phosphates (by RBCs) – 3%
Inorganic phosphates (by plasma) – 2% -
This question is part of the following fields:
- Pharmacology
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Question 117
Correct
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Which of the following would most likely explain a failed post-operative analgesia via local anaesthesia of a neck abscess?
Your Answer: pKA
Explanation:For the local anaesthetic base to be stable in solution, it is formulated as a hydrochloride salt. As such, the molecules exist in a quaternary, water-soluble state at the time of injection. However, this form will not penetrate the neuron. The time for onset of local anaesthesia is therefore predicated on the proportion of molecules that convert to the tertiary, lipid-soluble structure when exposed to physiologic pH (7.4).
The ionization constant (pKa) for the anaesthetic predicts the proportion of molecules that exists in each of these states. By definition, the pKa of a molecule represents the pH at which 50% of the molecules exist in the lipid-soluble tertiary form and 50% in the quaternary, water-soluble form. The pKa of all local anaesthetics is >7.4 (physiologic pH), and therefore a greater proportion the molecules exists in the quaternary, water-soluble form when injected into tissue having normal pH of 7.4.
Furthermore, the acidic environment associated with inflamed tissues favours the quaternary, water-soluble configuration even further. Presumably, this accounts for difficulty when attempting to anesthetize inflamed or infected tissues; fewer molecules exist as tertiary lipid-soluble forms that can penetrate nerves.
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This question is part of the following fields:
- Physiology
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Question 118
Incorrect
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A 58-year-old man, visits his general practitioner complaining of a lump in his groin. He explains he is otherwise well and reports no other symptoms. The lump is examined and is found to be soft, and can be reduced without causing the patient pain. The GP diagnoses an inguinal hernia. To determine the nature of the hernia, the GP reduced the lump and applies pressure on the deep inguinal ring.
The deep inguinal ring has what anatomical landmark?Your Answer: Inferior and lateral to the pubic tubercle
Correct Answer: Superior to the midpoint of the inguinal ligament
Explanation:The deep inguinal ring lies approximately 1.5-2cm above the midpoint of the inguinal ligament, the halfway point between the anterior superior iliac spine and the pubic tubercle, next to the epigastric vessels.
It is an important point in determining the nature of an inguinal hernia (direct or indirect). The patient is asked to cough after the hernia is reduced, with pressure applied to the deep inguinal ring. The hernia reappearing indicates it is direct, moving through the posterior wall of the inguinal canal.
Inferior and lateral to the pubic tubercle is the normal anatomical position of the neck of a femoral hernia.
Superior and medial to the pubic tubercle is the site of the superficial inguinal ring, and the normal anatomical position of the neck of an inguinal hernia.
The mid-inguinal point is located halways between the pubic symphysis and the anterior superior iliac spine. It is the surface marking for taking the femoral pulse.
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This question is part of the following fields:
- Anatomy
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Question 119
Correct
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An 81-year old man was admitted to the Pulmonology Ward due to chronic obstructive airway disease (COPD) exacerbation. Upon physical examination, he was hypertensive at 140/90 mmHg, tachycardic at 114 beats per minute, and tachypnoeic at 33 breaths per minute.
Arterial blood gas analysis was obtained and showed the following results:
pH: 7.25 (Reference range: 7.35-7.45)
PaO2: 73 mmHg (9.7 kPa) (Reference range: 11.3-12.6 kPa)
PaCO2: 56 mmHg (7.5 kPa) (Reference range: 4.7-6.0 kPa)
SaO2: 90%
Standard bicarbonate: 29 mmol/L (Reference range: 20-28)
BE: +4 mmol/L (± 2)
Which of the following options has the most significant impact on his respiratory rate?Your Answer: CSF pH
Explanation:The arterial blood gas analysis indicates presence of acute respiratory acidosis.
Central chemoreceptors are located in the ventral medulla and respond directly to presence of hydrogen ions in the CSF. When stimulated, it causes an increase in respiratory rate.
It is believed that hydrogen ions may be the only important direct stimulus for these neurons, however, CO2 is believed to stimulate these neurons secondarily by changing the hydrogen ion concentration.
Changes in O2 concentration have virtually no direct effect on the respiratory centre itself to alter respiratory drive. Although, O2 changes do have an indirect effect by acting through the peripheral chemoreceptors.
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This question is part of the following fields:
- Pathophysiology
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Question 120
Incorrect
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A 63-year old man has palpitations and goes to the emergency room. An ECG shows tall tented T waves, which corresponds to phase 3 of the cardiac action potential.
The shape of the T wave is as a result of which of the following?Your Answer: Fast depolarisation due to influx of potassium
Correct Answer: Repolarisation due to efflux of potassium
Explanation:Cardiac conduction
Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium
Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop
Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period
Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period
Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 121
Incorrect
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A laceration to the upper lateral margin of the popliteal fossa will pose the greatest risk of injury for which nerve?
Your Answer: Tibial nerve
Correct Answer: Common peroneal nerve
Explanation:The common peroneal (fibular) nerve descends obliquely along the lateral side of the popliteal fossa to the fibular head, medial to biceps femoris.
The sural nerve exits at the fossa’s lower inferolateral aspect and is more at risk in short saphenous vein surgery.
The tibial nerve lies more medially and is even less likely to be injured in this location.
The boundaries of the popliteal fossa are:
Superolateral – the biceps femoris tendon
Superomedial – semimembranosus reinforced by semitendinosus
Inferomedial and inferolateral – medial and lateral heads of gastrocnemiusThe contents of the Popliteal fossa are:
1. The popliteal artery
2. The popliteal vein
3. The Tibial nerve and common Fibular nerve
4. Posterior femoral cutaneous nerve: descends and pierces the roof
5. Small saphenous vein
6. popliteal lymph nodes
7. fat -
This question is part of the following fields:
- Anatomy
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Question 122
Correct
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Health workers are at increased risks of anaesthetic exposure. Therefore, The Control of Substances Hazardous to Health (COSHH) regulations require measures implemented to assess and control the risks related to this exposure.
Among the following control measures, which one is most likely to limit potentially harmful exposure to anaesthetic agents within an operating theatre?Your Answer: Total intravenous anaesthesia (TIVA)
Explanation:Exposure to anaesthetic hazards is one among the occupational exposures in manipulating toxic agents or inhaling toxic gases during anaesthetic practices.
Toxic gases mainly nitrous oxide, is one of the most gaseous anaesthetic agents that constitutes an important source of pollution. One of the safe and effective technics used in anaesthesia and reducing the amount of pollution is the Total Intravenous Anaesthesia (TIVA) which consists of using opioids in analgesia and propofol for the induction and the maintenance of anaesthesia. It refers to the administration intravenously of an anaesthetic, sedative, and/or tranquilizer. A less polluting but not the best way to get rid of the toxic aesthetic agents is the scavenger system that collects and expels the gas outside the medical environment. Yet, this technique still represents a hazard for the environment and still increase the risk of exposure for the health workers and clinical staff.
Fume cupboards are also not recommended to use because of their high pollution potency, mainly of the air resulting in a great harm for medical workers.
Supraglottic airways as well as the Air Changes per Hour technics could be harmful for both patients and health workers, increasing the risks of transmitted diseases, namely nosocomial infections.
Therefore, the Total Intravenous Anaesthesia technique (TIVA) is most likely to be safe and recommended to use.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 123
Incorrect
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A 45-year-old man is being operated on for emergency laparotomy as he presented with bowel perforation. During the surgery, the marginal artery of Drummond is encountered and preserved.
Which of the following two arteries fuse to form the marginal artery of Drummond?Your Answer: Superior mesenteric artery and the coeliac trunk
Correct Answer: Superior mesenteric artery and inferior mesenteric artery
Explanation:The arteries of the midgut (superior mesenteric artery) and hindgut (inferior mesenteric artery) give off terminal branches that form an anastomotic vessel called the marginal artery of Drummond. It runs in the inner margins of the colon and gives off short terminal branches to the bowel wall.
The marginal artery is formed by the main branches and arcades arising from the ileocolic, right colic, middle colic, and left colic arteries. It is most apparent in the ascending, transverse, and descending colons and poorly developed in the sigmoid colon.
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This question is part of the following fields:
- Anatomy
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Question 124
Incorrect
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A 35-year-old female, presents to the emergency department via ambulance. The paramedics have noted the patient's symptoms as unilateral left-sided weakness of the upper and lower limbs, homonymous hemianopia and dysphasia.
She has previous personal and family history of deep vein thromboses.
The report of her CT scan suggests a stroke involving the middle cerebral artery.
Post recovery, she undergoes further diagnostic investigations to determine the cause of a stroke at her young age. She is eventually diagnosed with a hypercoagulable state disease called Factor V Leiden thrombophilia.
An emboli in the middle cerebral artery results in dysfunction of which areas of the brain?Your Answer: Frontal, parietal and occipital
Correct Answer: Frontal, temporal and parietal lobes
Explanation:The middle cerebral artery is a part of the circle of Willis system of anastomosis within the brain, and the most often affected by brain pathology.
The primary function of the middle cerebral artery is providing oxygenated blood to related regions of the brain. It achieves this by giving off different branches to supply different brain regions, namely:
The cortical branches: which supplies the primary motor and somatosensory cortical areas of some parts of the face, trunk and upper limbs.
The small central branches: which supply the basal ganglia and internal capsule via the lenticulostriate vessels.
The superior division: which supplies the lateral inferior frontal lobe, including the Broca area which is responsible for production of speech, language comprehension, and writing.
The inferior division: which supplies the superior temporal gyrus, including Wernicke’s area which controls speech comprehension and language development.
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This question is part of the following fields:
- Anatomy
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Question 125
Correct
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The following results were obtained In a new drug trial:
Improved Not improved
Placebo group 36 26
Treatment group 44 16
Regarding the statistical analysis or interpretation of the trial, One of these is trueYour Answer: The data could be evaluated using the chi square test
Explanation:This data is in a 2 × 2 contingency table so a chi square test can be used. There is a special chi squared formula that gives a value that can be looked up in a table giving the p value.
Since we are comparing proportions not means, the Student’s t test CANNOT be used.
There is no linear regression to plot so Pearson’s co-efficient cannot be calculated.
Nothing is so obvious that no statistical analysis is needed.
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This question is part of the following fields:
- Statistical Methods
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Question 126
Incorrect
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Regarding the classification of breathing systems, which of the following is true?
Your Answer: The Mapleson classification of breathing systems is a further description of Conway's semi-open systems
Correct Answer: The Conway classification describes a functional classification based on whether a CO2 absorber is required
Explanation:Breathing system is an assembly of components which connects patient’s airway to anaesthesia machine through which controlled composition of gas mixture is dispensed. It delivers gas to the patient, removes expired gas and controls the temperature and humidity of the inspired mixture. It allows spontaneous, controlled, or assisted respiration. It may also provide ports for gas sampling, airway pressure, flow and volume monitoring.
Breathing systems have been classified by Conway and Mapleson.
Conway suggested a functional classification:
– Circuits requiring a CO2 absorber
– Circuits not requiring a CO2 absorberWilliam Mapleson designated varying arrangements of breathing system components (masks, breathing tubes, fresh gas flow inlets, adjustable pressure-limiting valves, and reservoir bags) as Mapleson A-E circuits.
Mapleson A: Arranged as FGF inlet, reservoir bag, APL valve, mask.
In this circuit, because the reservoir bag is between the FGF inlet valve and the APL valve, expired gas from the patient may re-enter the system and fill the reservoir bag during controlled ventilation. This is the most efficient system for spontaneous breathing as the FGF must only be equal to a patient’s minute ventilation to prevent rebreathing.Mapleson B: Arranged as reservoir bag, FGF inlet, APL valve, mask.
In this circuit, the FGF inlet is closer to the APL valve, which helps prevent the rebreathing concern in the Mapleson A circuit as above during controlled ventilation.Mapleson C: Arranged as reservoir bag, FGF inlet, APL valve, mask.
In this circuit, the arrangement is the same as the Mapleson B circuit. However, this circuit is shorter as it does not contain elongated corrugated tubing. This circuit also has the FGF inlet close to the APL valve to aid in preventing rebreathing.Mapleson D: Arranged as reservoir bag, APL valve, FGF inlet, and mask.
In this circuit, the arrangement interchanges the FGF inlet and APL valve of the Mapleson A circuit. This system prevents rebreathing by directing FGF towards the APL valve rather than towards the patient during exhalation.Mapleson E: Arranged as corrugated tubing, FGF inlet, and mask.
In this circuit, there is no reservoir bag and no APL valve. Given the inability to alter the pressure of the circuit, this is ideal for spontaneously ventilating neonates or paediatric patients where low-pressure ventilation is desired. The system prevents rebreathing, similar to the Mapleson D circuit.Jackson Rees later modified the Mapleson E by adding an open ended bag, which has since become known as the Mapleson F.
Mapleson F: Arranged as APL valve directly connected to reservoir bag, corrugated tubing, FGF inlet, and mask.
The system prevents rebreathing similarly to Mapleson D by directing FGF towards the APL valve. -
This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 127
Incorrect
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It was hypothesized that people that had lower socio economic status were more prone to developing gastric cancer. After 30 years of studying people with lower socio economic status, it was found that they did have a greater tendency to develop cancer. As a result of that the authors got to the conclusion that a strong association existed between the two. Later on another study conducted found that people from lower socio economic back grounds also had a tendency to be smokers.
Which form of potential bias can be associated with this particular study?Your Answer: Measurement bias
Correct Answer: Confounding bias
Explanation:Selection bias is when randomisation is not achieved and is often a result of in efficient recruiting method.
Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.
Measurement bias can be characterized by gathering of information in a manner that is distorted.
When the participants of a research study are recruited from the hospitals rather than the general population, its called Berkson Bias.
Confounding bias is the major player here because in this case the effects of smoking can be masked behind and can be read as outcomes of lower socio economic status. This extraneous factor (Smoking), distorts the founding.
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This question is part of the following fields:
- Statistical Methods
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Question 128
Incorrect
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A 40-year-old obese woman has complaints of heartburn and regurgitation that is worse on lying flat. The doctor suspects gastroesophageal reflux due to a hiatus hernia. Lifestyle modifications to lose weight and antacids are prescribed to her.
At which level of the diaphragm will you find an opening for this problem?Your Answer: T12
Correct Answer: T10
Explanation:Hiatus is an opening in the diaphragm. A hiatal hernia is a protrusion of the upper part of the stomach through an opening in the diaphragm, the oesophageal hiatus, into the thorax. The oesophageal hiatus occurs at the level of T10 in the right crus of the diaphragm.
Other important openings in the diaphragm:
T8: vena cava, terminal branches of the right phrenic nerve
T10: oesophagus, vagal trunks, left anterior phrenic vessels, oesophageal branches of the left gastric vessels
T12: descending aorta, thoracic duct, azygous and hemi-azygous veinAn opening in the diaphragm is called a hiatus. The oesophageal hiatus is at vertebral level T10. A hiatus hernia is where the stomach bulges through the oesophageal hiatus hence the name – hiatus hernia.
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This question is part of the following fields:
- Anatomy
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Question 129
Incorrect
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A study involving 64 patients of diabetes mellitus type 2 was performed. Weight of each patient was recorded and the mean weight of the patients was found to be 81 kg. The data set had a standard deviation of 12 kg.
The value of standard error associated with the mean is:Your Answer: 12-Sep
Correct Answer: 1.5
Explanation:Standard error can be calculated by the following formula:
Standard Error= (Standard Deviation)/√(Sample Size)
= (12) / √(64)
= 12 / 8
= 1.5 -
This question is part of the following fields:
- Statistical Methods
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Question 130
Correct
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Which of the following molecules is closely related to the structure of Oxytocin?
Your Answer: ADH
Explanation:Oxytocin is structurally similar to Antidiuretic Hormone (ADH) and thus oxytocin can cause water intoxication (due to an ADH like action)
Oxytocin is secreted by the posterior pituitary along with ADH. It increases uterine contractions – the contraction of the upper segment (fundus and body) of the uterus whereas the lower segment is relaxed facilitating the expulsion of the foetus
Antidiuretic hormone (ADH) also called vasopressin is released from the posterior pituitary in response to hypertonicity and increases fluid reabsorption from the kidney.
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This question is part of the following fields:
- Pharmacology
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Question 131
Correct
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Which of the following describes the mechanism of action of erythromycin?
Your Answer: Inhibit 50S subunit of ribosomes
Explanation:Erythromycin binds to the 50s subunit of bacterial rRNA complex and inhibits protein synthesis.
Gentamicin is a broad-spectrum antibiotic whose mechanism of action involves inhibition of protein synthesis by binding to 30s ribosomes. Its major adverse effect is nephrotoxicity and ototoxicity
Aminoglycoside bind to 30s subunit of ribosome causing misreading of mRNA
Tetracyclines inhibit protein synthesis through reversible binding to bacterial 30s ribosomal subunits, which prevent binding of new incoming amino acids (aminoacyl-tRNA) and thus interfere with peptide growth.
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This question is part of the following fields:
- Pharmacology
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Question 132
Correct
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A drug with a 2-hour half-life and a first-order kinetics of elimination is administered intravenously. The initial plasma concentration is calculated to be 12 mcg/mL and plasma concentrations is measured hourly.
At 6 hours, how much drug will be left?Your Answer: 1.5 mcg/mL
Explanation:In first order kinetics the rate of elimination is proportional to plasma concentration.
Rate of elimination is described by the following equation:
C = C0. e^-kt
Where:
C=drug concentration,
C0= drug concentration at time zero (extrapolated),
k = rate constant and
t = time.The initial concentration of this drug is 12 mcg/ml therefore:
The plasma concentration will have halved to 6 mcg/ml at 2 hours.
The plasma concentration will have halved to 3 mcg/ml at 4 hours and
The plasma concentration will have halved to 1.5 mcg/ml t 6 hours. -
This question is part of the following fields:
- Pharmacology
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Question 133
Correct
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A 50-year-old female is undergoing a lymph node biopsy from the posterior triangle of his neck.
What structure forms the posterior boundary of the posterior triangle of the neck?Your Answer: Trapezius muscle
Explanation:The sternocleidomastoid muscle divides the neck into anterior and posterior triangles on both sides of the neck.
The posterior triangle has the following boundaries:
anteriorly – sternocleidomastoid muscle
posteriorly – trapezius
roof – investing layer of deep cervical fascia
floor – prevertebral fascia overlying splenius capitis, levator scapulae, and the scalene musclesThe contents of the posterior triangle are:
1. fat
2. lymph nodes (level V)
3. accessory nerve
4. cutaneous branches of the cervical plexus – greater auricular nerve, transverse cervical nerve, lesser occipital nerve, supraclavicular nerve (A major branch of this plexus is the phrenic nerve, which arises from the anterior divisions of spinal nerves C3-C5)
5. inferior belly of omohyoid
6. branches of the thyrocervical trunk (transverse cervical and suprascapular arteries)
7. third part of the subclavian artery
8. external jugular vein -
This question is part of the following fields:
- Anatomy
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Question 134
Correct
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Which of the following statements is true about an acute pulmonary embolism?
Your Answer: Thrombolysis administered through a peripheral vein is as effective as through a pulmonary artery catheter
Explanation:Acute pulmonary embolism occurs when a blood clot becomes embedded in a pulmonary artery and restricts lung blood flow.
Thrombolysis is recommended in patients with extremely compromised circulation rather than reduced oxygen in the blood. It is effective when administered via a peripheral vein or a pulmonary artery catheter.
Anticoagulant therapy (heparin use) decreases the risk of further embolic evens and decreases constriction of pulmonary vessels.
An ECG may be normal in patients with an acute pulmonary embolism.
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This question is part of the following fields:
- Pathophysiology
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Question 135
Correct
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Which of the following antiplatelet drugs would be best for rapid offset action?
Your Answer: Epoprostenol
Explanation:Epoprostenol has a half-life of only 42 seconds and has rapid offset. It is used for the treatment of pulmonary hypertension.
Aspirin inhibits the COX enzyme irreversibly. It inhibits thromboxane synthesis but does not inhibit the enzyme thromboxane synthetase.
Ticlopidine, clopidogrel and prasugrel act as irreversible antagonists of P2 Y12 receptor of Adenosine Diphosphate (ADP). These drugs interfere with the activation of platelets by ADP and fibrinogen. Both aspirin and clopidogrel act irreversibly so they are not correct.
Paclitaxel is a long-acting antiproliferative agent used for the prevention of restenosis (recurrent narrowing) of coronary and peripheral stents and is not the correct answer.
Tirofiban has the next shortest duration of action after epoprostenol. If epoprostenol is not given in the question, it would be the best answer.
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This question is part of the following fields:
- Pharmacology
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Question 136
Correct
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The ED95 of muscle relaxants is the dose required to reduce twitch height by 95% in half of the target population. The dose of non-depolarizing muscle relaxants used for intubation is 2-3 times the ED95.
For procedures that need a short duration of muscle relaxation and abrupt recovery, the short-acting drug Mivacurium is given at less than 2 times the ED95. What is the explanation for Mivacurium being an exception to this rule?Your Answer: Dose related histamine release occurs which frequently leads to tachycardia and hypotension
Explanation:Mivacurium, when administered at doses greater than 0.2 mg/kg,increases the risk for hypotension, tachycardia, and erythema. This is due to the ability of mivacurium to release histamine with increasing dose. Contrary to this fact, anaphylaxis is rare for mivacurium because of the short duration of histamine release.
The effective dose 50 (ED50) of mivacurium is between 0.08-0.15 mg/kg. It is administered slowly to prevent and decrease the risk of developing adverse effects.
Mivacurium has a high potency thus a longer duration of action, however this is not the answer that we are looking for.
Although drug metabolism takes longer for mivacurium than succinylcholine, it has no effect on the dose required for intubation.
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This question is part of the following fields:
- Pharmacology
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Question 137
Incorrect
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During the design phase of a study, which among the given is aimed at addressing confounding factors?
Your Answer: Bias sampling
Correct Answer: Randomisation
Explanation:Randomisation allows for performance of experimental trials in a random order. Using this method gives us control over the confounding variables that are not supposed to be held constant.
For an instance, by employing randomisation we get to control biological differences among individual human beings during experimental trials.
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This question is part of the following fields:
- Statistical Methods
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Question 138
Incorrect
-
Drug A has a 1 L/kg volume of distribution and a 0.1 elimination rate constant (k).
Drug B has a 2 L/kg volume of distribution and a 0.2 elimination rate constant (k).
Which of the following statements best describes the pharmacokinetics of drug A in a single compartment?Your Answer: Drug A has a higher clearance than drug B
Correct Answer: Drug A has a lower clearance than drug B
Explanation:The fall in plasma concentration of a drug with time decreases exponentially in a single compartment pharmacokinetic model (wash-out curve).
A straight line is produced when the logarithm (ln) of a drug’s plasma concentration is plotted against time because a constant proportion of the drug is removed from the plasma per unit time. The line’s gradient or slope can be expressed mathematically as k. (the rate constant). The gradient is related to the half life (T1/2) because it can be used to predict a drug’s plasma concentration at any time.
According to the following formula, clearance (CL), volume of distribution (Vd), and elimination rate constant (k) are mathematically related.
CL = Vd x k
For drug A, CL = 1 x 0.1 = 0.1units per minute
For drug B, Cl = 2 x 0.2 = 0.4 units per minute
Hence, it is proved that Drug A has a lower clearance than drug B.
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This question is part of the following fields:
- Pharmacology
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Question 139
Correct
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The pharmacologically inactive precursor of barbiturates is Barbituric acid. Because the molecule is heterocyclic, small structural changes can alter its pharmacological activity (structure function relationship).
Which of the following modifications to the molecule has the greatest impact on the effectiveness of the barbiturate derivative?Your Answer: Sulphur at C2
Explanation:Barbituric acid is the barbiturates’ pharmacologically inactive precursor. A pyrimidine heterocyclic nucleus is formed by the condensation of urea and malonic acid. Its pharmacological activity can be influenced by minor structural changes (structure function relationship).
The duration of action and potency as a sedative are influenced by the length of the side chains at C5. Barbiturates with three carbon atoms in their chain last longer than those with two. Anticonvulsant properties are enhanced by branched chains.
The addition of a methyl group at N1 causes a faster onset/offset of action, but it also causes excitatory phenomena (twitching/lower convulsive threshold).
The addition of oxygen and sulphur to C2 increases the molecule’s lipid solubility and thus its potency. Thiopentone (thiobarbiturate) has sulphur groups at C2, making it 20-200 times more lipid soluble than oxybarbiturates.
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This question is part of the following fields:
- Pharmacology
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Question 140
Correct
-
Which of the following explains the mode of action of Magnesium sulphate in preventing eclampsia in susceptible patients?
Your Answer: Dilatation of cerebral circulation due to calcium channel antagonism reducing cerebral vascular spasm
Explanation:Magnesium is a unique calcium antagonist as it can act on most types of calcium channels in vascular smooth muscle and as such would be expected to decrease intracellular calcium. One major effect of decreased intracellular calcium would be inactivation of calmodulin-dependent myosin light chain kinase activity and decreased contraction, causing arterial relaxation that may subsequently lower peripheral and cerebral vascular resistance, relieve vasospasm, and decrease arterial blood pressure.
The vasodilatory effect of MgSO4 has been investigated in a wide variety of vessels. For example, both in vivo and in vitro animal studies have shown that it is a vasodilator of large conduit arteries such as the aorta, as well as smaller resistance vessels including mesenteric, skeletal muscle, uterine, and cerebral arteries.
The theory of cerebrovascular vasospasm as the aetiology of eclampsia seemed to be reinforced by transcranial Doppler (TCD) studies which suggested that MgSO4 treatment caused dilation in the cerebral circulation as well as in animal studies that used large cerebral arteries.
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This question is part of the following fields:
- Pathophysiology
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Question 141
Incorrect
-
Which of the following is correct regarding correlation?
Your Answer: Correlation can take any value between 0-10
Correct Answer: Complete absence of correlation is expressed by a value of 0
Explanation:In statistical terms, correlation is used to denote association between two quantitative variables.
The degree of association is measured by a correlation coefficient, denoted by r. The correlation coefficient is measured on a scale that varies from + 1 through 0 to – 1. Complete correlation between two variables is expressed by either + 1 or -1. When one variable increases as the other increases the correlation is positive; when one decreases as the other increases it is negative. Complete absence of correlation is represented by 0.
The two methods are not synonymous as correlation measures the degree of relationship between two variables whereas regression analysis is about how one variable affects another or what changes it has on the other variable. Both are also shown by a different graphical representation.
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This question is part of the following fields:
- Statistical Methods
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Question 142
Correct
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Prophylactic antibiotics are required for which of the following procedures?
Your Answer: Appendicectomy
Explanation:Correctly used, antibiotic prophylaxis can reduce
the total use of antibiotics.
There is strong scientific support that antibiotic
prophylaxis reduces the development of infection after:- Operations and endoscopic procedures in the large intestine,
the rectum, and the stomach (including appendectomies and
penetrating abdominal trauma), and after percutaneous endoscopic gastrostomy (PEG) - Cardiovascular surgery, and insertion of pacemakers
- Breast cancer surgery
- Hysterectomy
- Reduction of simple fractures and prosthetic limb surgery
- Complicated surgery for cancer in the ear, nose, and throat
regions - Transrectal biopsy and resection of the prostate (febrile urinary
tract infection and blood poisoning).
In most cases the scientific evidence is inadequate to determine
which type of antibiotic is most effective for antibiotic prophylaxis. - Operations and endoscopic procedures in the large intestine,
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 143
Incorrect
-
Which among the given choices can be used to describe a persistent and expected level of disease in a particular population?
Your Answer: Epidemic
Correct Answer: Endemic
Explanation:Phase 0 trials assist the scientists in studying the behaviour of drugs in humans by micro dosing patients. They are used to speed up the developmental process. They have no measurable therapeutic effect and efficiency.
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This question is part of the following fields:
- Statistical Methods
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Question 144
Correct
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A 26-year old male patient was admitted to the surgery department for appendectomy. Medical history revealed that he has major depressive disorder and was on Phenelzine. Aside from abdominal pain, initial assessment was unremarkable. However, thirty minutes after, the patient was referred to you for generalized seizures. He was given an analgesic and it was noted that, during the first 15 minutes of administration, he became anxious, with profuse sweating, which later developed into seizures. Upon physical examination, he was febrile at 38.3°C.
Which of the following statements is the best explanation for the patient's symptoms?Your Answer: Drug interaction with pethidine
Explanation:The clinical picture best describes a probable drug interaction with pethidine.
Phenelzine, a monoamine oxidase (MAO) inhibitor, when given with pethidine, an opioid analgesic, may lead to episodes of hypertension, rigidity, excitation, hyperpyrexia, seizures, coma and death. Studies have shown that pethidine reacts more significantly with MAO inhibitors than morphine.
When pethidine is metabolised to normeperidine, it acts as a serotonin reuptake inhibitor and cause an increase in serotonin levels in the brain. MAO inhibitors can also lead to elevated levels of serotonin because of its mechanism of action by inhibiting the enzyme monoamine oxidase that degrades serotonin.
The excess serotonin levels may lead to serotonin syndrome, of which some of the common precipitating drugs are selective serotonin reuptake inhibitors, MAO inhibitors, tricyclic antidepressants, meperidine, and St. John’s Wort. Onset of symptoms is within hours, which includes fever, agitation, tremor, clonus, hyperreflexia and diaphoresis.
Drug interaction between phenelzine and paracetamol do not commonly precipitate serotonin syndrome.
Neuroleptic malignant syndrome is due to dopamine antagonism, precipitated commonly by antipsychotics. Its onset of symptoms occur in 1 to 3 days, and is characterized by fever, encephalopathy, unstable vitals signs, elevated CPK, and rigidity.
Altered mental status is the most common manifestation of sepsis-associated encephalopathy. Patient also exhibit confusional states and inappropriate behaviour. In some cases, this may lead to coma and death.
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This question is part of the following fields:
- Pharmacology
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Question 145
Correct
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A 42 year old man came to the out-patient department with attacks of facial pain. Upon further questioning, he reported that the pain was intermittent, often occurring spontaneously. The quality of the pain was sharp, and severity was moderate to moderately severe. The pain was non-radiating, and often involved the left maxillary and mandibular areas.
Other medical information of the patient, such as allergies and co-morbidities, were unremarkable.
Which of the following is the most probable diagnosis of the patient?Your Answer: Trigeminal neuralgia
Explanation:Trigeminal neuralgia is characterized by excruciating paroxysms of pain in the lips, gums, cheek, or chin and, very rarely, in the distribution of the fifth nerve. The pain seldom lasts more than a few seconds or a minute or two but may be so intense that the patient winces, hence the term tic. The paroxysms, experienced as single jabs or clusters, tend to recur frequently, both day and night, for several weeks at a time. They may occur spontaneously or with movements of affected areas evoked by speaking, chewing, or smiling. Another characteristic feature is the presence of trigger zones, typically on the face, lips, or tongue, that provoke attacks; patients may report that tactile stimuli – e.g., washing the face, brushing the teeth, or exposure to a draft of air – generate excruciating pain. An essential feature of trigeminal neuralgia is that objective signs of sensory loss cannot be demonstrated on examination.
Trigeminal neuralgia is relatively common, with an estimated annual incidence of 4–8 per 100,000 individuals. Middle-aged and elderly persons are affected primarily, and ,60% of cases occur in women. Onset is typically sudden, and bouts tend to persist for weeks or months before remitting spontaneously. Remissions may be long-lasting, but in most patients, the disorder ultimately recurs.
An ESR or CRP is indicated if temporal arteritis is suspected. In typical cases of trigeminal neuralgia, neuroimaging studies are usually unnecessary but may be valuable if MS is a consideration or in assessing overlying vascular lesions in order to plan for decompression surgery.
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This question is part of the following fields:
- Pathophysiology
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Question 146
Incorrect
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A 35-year-old male presents to GP presenting an area of erythema which was around a recent cut on his right forearm. He was prescribed a short course of antibiotics and after 5 days again presented with progressive fatigue, headaches, and fevers.
On clinical examination:
Oxygen saturation: 98% on room air
Respiratory rate: 22 per minute
Heart rate: 100 beats per minute
Blood pressure: 105/76 mmHg
Temperature: 38.2 degree Celsius
On physical examination, a dramatic increase in the area of erythema was noted.
Blood culture was done in the patient and indicated the presence of bacterium containing beta-lactamase. Which of the following antibiotics was likely prescribed to the patient?Your Answer: Co-amoxiclav
Correct Answer: Amoxicillin
Explanation:Ciprofloxacin belongs to the quinolone group of antibiotics, and doxycycline and minocycline are tetracyclines. So, they are not affected by beta-lactamase.
However, amoxicillin is a beta-lactam antibiotic and beta-lactamase cleaves the beta-lactam ring present in amoxicillin. This results in the breakdown of the antibiotic and thus the area of erythema dramatically increased.
Co-amoxiclav contains amoxicillin and clavulanic acid which protects amoxicillin from beta-lactamase. -
This question is part of the following fields:
- Pharmacology
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Question 147
Correct
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A patient is being prepped for major bowel surgery. Alice, a final-year medical student, observes the surgery but is asked to scrub in and assist the anaesthetist during intubation. The anaesthetist inserts the laryngoscope and asks Alex to locate the larynx.
What anatomical landmark corresponds to the position of the larynx?Your Answer: C3-C6
Explanation:The larynx is an air passage, sphincter, and organ of phonation that extends from the tongue to the trachea. It lies in the anterior part of the neck at the vertebral levels C3 to C6.
Important anatomical landmarks:
C1-C2 – Atlas and axis, respectivelyC3-C6 – Larynx
C5 – Thyroid cartilage
T5-T7 – Pulmonary hilum
T12-L1 – Duodenum
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This question is part of the following fields:
- Anatomy
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Question 148
Incorrect
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A 28-year-old man is admitted to the critical care unit. He has been diagnosed with adult respiratory distress syndrome and is being ventilated. His haemodynamic condition is improved using a pulmonary artery flotation.
His readings are listed below:
Haemoglobin concentration: 10 g/dL
Mixed venous oxygen saturation: 70%
Mixed venous oxygen tensions (PvO2): 50 mmHg
Estimate his mixed venous oxygen content (mL/100mL).Your Answer: 9
Correct Answer: 9.5
Explanation:Mixed venous oxygen content (CvO2) is the oxygen concentration in 100mL of mixed venous blood taken from the pulmonary artery. It is usually 12-17 mL/dL (70-75%). It is represented mathematically as:
CvO2 = (1.34 x Hgb x SvO2 x 0.01) + (0.003 x PvO2)
Where,
1.34 = Huffner’s constant
Hgb = Haemoglobin level (g/dL)
SvO2 = % oxyhaemoglobin saturation of mixed venous blood
PvO2 = 0.0225 = mL of O2 dissolved per 100mL plasma per kPa, or 0.003 mL per mmHgTherefore,
CvO2 = (1.34 x 10 x 70 x 0.01) + (0.003 x 50)
CvO2 = 9.38 + 0.15 = 9.53 mL/100mL
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This question is part of the following fields:
- Clinical Measurement
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Question 149
Correct
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A cannula is inserted into the cephalic vein of a 30-year-old man. Which of the following structures does the cephalic vein pass through?
Your Answer: Clavipectoral fascia
Explanation:The cephalic vein is one of the primary superficial veins of the upper limb. The superficial group of upper limb veins begin as an irregular dorsal arch on the back of the hand.
The cephalic vein originates in the anatomical snuffbox from the radial side of the arch and travels laterally up, within the superficial fascia to join the basilic vein via the median cubital vein at the elbow.
Near the shoulder, it passes between the deltoid and pectoralis major muscles. It pierces the coracoid membrane (continuation of the clavipectoral fascia) to terminate in the axillary vein’s first part.
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This question is part of the following fields:
- Anatomy
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Question 150
Correct
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A 25 year-old female came to the out-patient department with complaints of vaginal discharge with a distinct fishy odour. She was later diagnosed with bacterial vaginosis and was prescribed to take metronidazole.
The mechanism of action of metronidazole is?Your Answer: Interferes with bacterial DNA synthesis
Explanation:Metronidazole is a nitroimidazole antiprotozoal drug that is selectively absorbed by anaerobic bacteria and sensitive protozoa. Once taken up be anaerobes, it is nonenzymatically reduced by reacting with reduced ferredoxin. This reduction results in products that accumulate in and are toxic to anaerobic cells. The metabolites of metronidazole are taken up into bacterial DNA, forming unstable molecules. This action occurs only when metronidazole is partially reduced, and, because this reduction usually happens only in anaerobic cells, it has relatively little effect on human cells or aerobic bacteria.
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This question is part of the following fields:
- Pharmacology
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Question 151
Incorrect
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A 48-year-old woman has presented to the emergency with abdominal pain and distension complaints. She is a known case of diabetes mellitus type 2 and has a BMI of 28 kg/m². On investigations, the liver function tests (LFTs) show raised alanine transaminase (ALT).
Liver ultrasound is performed next to visualize the blood flow into and out of the liver.
Which blood vessel supplies approximately one-third of the blood supply to the liver?
Your Answer: Hepatic portal vein
Correct Answer: Hepatic artery proper
Explanation:The liver receives blood supply from two sources.
1. Hepatic artery proper
It arises from the celiac trunk via the common hepatic artery and brings oxygenated blood to the liver.
It contributes to approximately 30% of the blood supply of the liver.
2. Hepatic portal vein – supplies the liver with partially deoxygenated blood, carrying nutrients absorbed from the small intestine. It gets tributaries from the inferior mesenteric vein, splenic vein, and superior mesenteric veinThe inferior mesenteric artery supplies the hindgut.
The superior mesenteric artery supplies the pancreas and intestine up to the proximal two-thirds of the transverse colon.
The inferior phrenic artery supplies the inferior surface of the diaphragm and oesophagus. -
This question is part of the following fields:
- Anatomy
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Question 152
Correct
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Regarding the emergency oxygen flush, which is true?
Your Answer: May lead to awareness if used inappropriately
Explanation:When the emergency oxygen flush is pressed, 100% oxygen is supplied from the common gas outlet. This gas bypasses BOTH flowmeters and vaporisers. The flow of oxygen is usually 45 l/min at a PRESSURE OF 400 kPa.
There is an increased risk of pulmonary barotrauma when the emergency flush is pressed, especially when anaesthetising paediatric patients.
The inappropriate use of the flush causes dilution of anaesthetic gases and this increases the possibility of anaesthetic awareness .
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 153
Incorrect
-
In the United Kingdom, a new breast cancer screening test is being conducted compared to the conventional use of mammography. This test predicts that if the breast cancer is diagnosed at an earlier stage, it could improve the survival rate but the overall results remains constant.
This is an example of what kind of bias?Your Answer: Procedure Bias
Correct Answer: Lead time bias
Explanation:Recall bias introduced when participants in a study are systematically more or less likely to recall and relate information on exposure depending on their outcome status.
In procedure bias, the researcher decides assignment of a treatment versus control and assigns particular patients to one group or the other non-randomly. This is unlikely to have occurred in this case, although it is not mentioned specifically.
Self Selection or volunteer bias occur when those subjects are selected to participate in the study who are not the representative of the entire target population. those subjects may be from high socio-economic status and practice those activities or lifestyle that improves their health.
Lead-time bias occurs when a disease is detected by a screening test at an earlier time point rather than it would have been diagnosed by its clinical appearance. In this bias, earlier detection improves the survival time in the intervention group.
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This question is part of the following fields:
- Statistical Methods
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Question 154
Incorrect
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Which of the following drugs is safe to be used in porphyria?
Your Answer: Phenytoin
Correct Answer:
Explanation:Porphyria is a group of disorders in which there is excess production and excess excretion of porphyrins and their precursors. They are usually genetic and are caused due to defects in the haem metabolic pathway. However, other factors like infection, pregnancy, mensuration, starvation may precipitate the attack.
Sulphonamides, barbiturates (methohexitone and thiopental), and phenytoin are considered to be precipitants so are not safe to use
Chloral hydrate is thought to be safe to use.
Etomidate lacks proper studies and may be used with caution but it is generally advised not to use this drug especially if other alternatives are available. -
This question is part of the following fields:
- Pharmacology
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Question 155
Correct
-
One of the following sets of arterial blood gases best demonstrates compensated respiratory acidosis?
Your Answer: pH=7.36, PaCO2=8.5kPa, PaO2=7.5kPa, HCO3- = 43mmol/L
Explanation:pH=7.36, PaCO2=8.5kPa, PaO2=7.5kPa, HCO3- = 43mmol/L is the correct answer.
Since the pH is the lower limit of normal, it is compensated despite a raised PaCO2. Retention of bicarbonate ions by the renal system suggests this process is chronic.
pH=7.24, PaCO2=3.5kPa, PaO2=8.5kPa, HCO3- =18mmol/L represents an acute uncompensated metabolic acidosis
The remaining stems are degrees of uncompensated respiratory acidosis and therefore incorrect.
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This question is part of the following fields:
- Pathophysiology
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Question 156
Correct
-
Which vessel is the first to branch from the external carotid artery?
Your Answer: Superior thyroid artery
Explanation:The superior thyroid artery is the first branch of the external carotid artery. The other branches of the external carotid artery are:
1. Superior thyroid artery
2. Ascending pharyngeal artery
3. Lingual artery
4. Facial artery
5. Occipital artery
6. Posterior auricular artery
7. Maxillary artery
8. Superficial temporal arteryThe inferior thyroid artery is derived from the thyrocervical trunk.
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This question is part of the following fields:
- Anatomy
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Question 157
Incorrect
-
One of the non-pharmacologic management of COPD is smoking cessation. Given a case of a 60-year old patient with history of smoking for 30 years and a FEV1 of 70%, what would be the most probable five-year course of his FEV1 if he ceases to smoke?
Your Answer: The FEV1 will decrease at the same rate as a smoker
Correct Answer: The FEV1 will decrease at the same rate as a non-smoker
Explanation:For this patient, his forced expiratory volume in 1 second (FEV1) will decrease at the same rate as a non-smoker.
There is a notable, but slow, decline in FEV1 when an individual reaches the age of 26. An average reduction of 30 mls every year in non-smokers, while a more significant reduction of 50-70 mls is observed in approximately 20% of smokers.
Considering the age of the patient, individuals who begin smoking cessation by the age of 60 are far less likely to achieve normal FEV1 levels, even in the next five years. It is expected that their FEV1 will be approximately 14% less than their peers of the same age.
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This question is part of the following fields:
- Physiology
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Question 158
Correct
-
Rocuronium is substituted for succinylcholine during induction of anaesthesia for a caesarean section delivery.
Which of the following feature of rocuronium ensures the neonate shows no clinical signs of muscle relaxation?Your Answer: Highly ionised
Explanation:Drugs cross the placenta by Simple, Ion channel and Facilitated diffusion; Exocytosis and Endocytosis, Osmosis, and Active transport (primary and secondary)
The following factors influence rate of diffusion across the placenta:
Protein binding
Degree of ionisation
Placental blood flow
Maternal and foetal blood pH
Materno-foetal concentration gradient.
Thickness of placental membrane
Molecular weight of drug <600 Daltons cross by diffusion
Lipid solubility (lipid soluble molecules readily diffuse across the placenta)Rocuronium has a F/M ratios of 0.16, a 30% plasma protein binding, low lipid solubility, a low volume of distribution (0.25L/kg), and a high molecular weight (530Da).
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This question is part of the following fields:
- Pharmacology
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Question 159
Correct
-
A common renal adverse effect of non-steroidal anti-inflammatory drugs is?
Your Answer: Haemodynamic renal insufficiency
Explanation:Prostaglandins do not play a major role in regulating RBF in healthy resting individuals. However, during pathophysiological conditions such as haemorrhage and reduced extracellular fluid volume (ECVF), prostaglandins (PGI2, PGE1, and PGE2) are produced locally within the kidneys and serve to increase RBF without changing GFR. Prostaglandins increase RBF by dampening the vasoconstrictor effects of both sympathetic activation and angiotensin II. These effects are important because they prevent severe and potentially harmful vasoconstriction and renal ischemia. Synthesis of prostaglandins is stimulated by ECVF depletion and stress (e.g. surgery, anaesthesia), angiotensin II, and sympathetic nerves.
Non-steroidal anti-inflammatory drugs (NSAIDs), such as ibuprofen and naproxen, potently inhibit prostaglandin synthesis. Thus administration of these drugs during renal ischemia and hemorrhagic shock is contraindicated because, by blocking the production of prostaglandins, they decrease RBF and increase renal ischemia. Prostaglandins also play an increasingly important role in maintaining RBF and GFR as individuals age. Accordingly, NSAIDs can significantly reduce RBF and GFR in the elderly.
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This question is part of the following fields:
- Physiology
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Question 160
Correct
-
Over the course of 10 minutes, a normally fit and well 22-year-old male receives a 1 litre intravenous bolus of 20% albumin.
Which of the following primary physiological responses in this patient has the highest chance to influence a change in urine output?
Your Answer: Stimulation of atrial natriuretic peptide (ANP) secretion
Explanation:The renal effects of atrial natriuretic peptide (ANP) secretion are as follows:
Increased glomerular filtration rate by dilating the afferent glomerular arteriole. Moreover, it constricts the efferent glomerular arteriole, and relaxes the mesangial cells.
Reduces sodium reabsorption in the collecting ducts and distal convoluted tubule.
The renin-angiotensin system (RAS) is inhibited.
Blood flow in the vasa recta is increased.Because plasma osmolality is unlikely to change, hypothalamic osmoreceptors are unaffected.
The plasma protein has a molecular weight of 66 kDa, is not normally filtered into the proximal convoluted tubule, and has no osmotic diuretic effect.
The following are some basic assumptions:
Extracellular fluid (ECF) makes up one-third of total body water (TBW), while intracellular fluid makes up the other two-thirds (ICF)
One-quarter plasma and three-quarters interstitial fluid make up ECF (ISF)
The volume receptors in the atria have a 7-10% blood volume change threshold.
The osmoreceptors are sensitive to changes in osmolality of 1-2 percent.
The normal plasma osmolality before the transfusion is 287-290 mOsm/kg.
The plasma protein solution is a colloid that is only delivered to the intravascular compartment. The tonicity remains unchanged.
The blood volume increases by 20%, from 5,000 mls to 6,000 mls. This is higher than the volume receptor threshold of 7 to 10%. -
This question is part of the following fields:
- Pathophysiology
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Question 161
Incorrect
-
About the mechanism of action of bendroflumethiazide, Which of the following is correct?
Your Answer: Sodium-potassium-chloride symporter activator
Correct Answer: Sodium-chloride symporter inhibitor
Explanation:Sodium-chloride symporter inhibitor.
The thiazide sensitive sodium chloride symporter is inhibited by thiazides at the proximal portion of the distal convoluted tubule leading to increased sodium and water excretion. Increased delivery of sodium to the distal portion of the distal convoluted tubule promotes potassium loss. This is why thiazides are associated with hyponatraemia and hypokalaemia.
Carbonic anhydrase inhibitors are used mainly in the treatment of glaucoma. They act on the proximal convoluted tubule to promote bicarbonate, sodium and potassium loss.
Sodium potassium chloride symporter is inhibited by Loop diuretics.
Epithelial sodium channels are inhibited by Amiloride.
Drugs which lead to nephrogenic diabetes insipidus such as lithium and demeclocycline, are Inhibitors of vasopressin. -
This question is part of the following fields:
- Pharmacology
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Question 162
Correct
-
A 64-year old male has shortness of breath on exertion and presented to the cardiology clinic. He has a transthoracic echo performed to help in assessing the function of his heart.
How can this echo aid in calculating cardiac output?Your Answer: (end diastolic LV volume - end systolic LV volume) x heart rate
Explanation:Cardiac output = stroke volume x heart rate
Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%
Stroke volume = end diastolic LV volume – end systolic LV volume
Pulse pressure = Systolic Pressure – Diastolic Pressure
Systemic vascular resistance = mean arterial pressure / cardiac output
Factors that increase pulse pressure include:
-a less compliant aorta (this tends to occur with advancing age)
-increased stroke volume -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 163
Correct
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The solutions that contains the most sodium is?
Your Answer: 3500 mL 0.9% N saline
Explanation:Sodium concentration for different fluids
3% N saline 513 mmol/L
5% N saline 856 mmol/L
0.9% N saline 154 mmol/L
Hartmann’s solution 131 mmol/L
0.45% N saline with 5% glucose 77 mmol/LThis means that:
500 mL 5% N saline contains 428 mmol of sodium
1000 mL 3% N saline contains 513 mmol of sodium
3500 mL 0.9% N saline contains 539 mmol of sodium
4000 mL Hartmann’s contains 524 mmol of sodium
6000 mL 0.45% N saline with 5% glucose contains 462 mmol of sodium. -
This question is part of the following fields:
- Physiology
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Question 164
Incorrect
-
Which of the following is true about number needed to harm?
Your Answer: The number of patients that must receive a particular treatment for one patient in that group to receive an adverse outcome.
Correct Answer: The number of patients that must receive a particular treatment for one additional patient to experience an adverse outcome.
Explanation:Number needed to harm are a measure of the impact of a treatment or intervention that is often used to communicate results to patients, clinicians, the public and policymakers. It states how many patients need to be treated for one additional patient to experience an adverse outcome (e.g. a death). It is calculated as the inverse of the absolute risk reduction. It can equally well be applied to harmful outcomes as well as beneficial ones, where it becomes numbers needed to treat (NNT) instead.
In this way, they are both calculated the same but NNT usually refers to a therapeutic treatment whereas NNH refers to a risk-factor for disease.
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This question is part of the following fields:
- Statistical Methods
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Question 165
Correct
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A patient under brachial plexus regional block complains of pain under the cuff after the torniquet is inflated.
Which nerve was most probably 'missed' by the local anaesthetic?Your Answer: Intercostobrachial nerve
Explanation:The area described in the question is supplied by the intercostobrachial nerve, which provides sensory innervation to the portions of the axilla, tail of the breast, lateral chest wall and medial side of the arm.
It is a common for it to be ‘missed’ during administration of local anaesthesia because of its very superficial anatomic course. It may be anesthetized by giving an analgesia from the upper border of the biceps at the anterior axillary fold, to the margin of the triceps by the axillary floor.
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This question is part of the following fields:
- Pathophysiology
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Question 166
Incorrect
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A doctor has recorded the number of times the patient did not attend (DNA) the clinic for a study over a 10 month period.
Number of DNAs in 10 Months Number of Patients
1st Month 0
2nd Month 3
3rd Month 1
4th Month 45
5th Month 2
6th Month 0
7th Month 1
8th Month 4
9th Month 4
10th Month 2
Which among the following is the most apt way of summarizing mean value?Your Answer: Mean
Correct Answer: Median
Explanation:Variance and standard deviation indicate the dispersion of the plot from mean value and thus are not really helpful in summarizing the mean.
Range is the difference between maximum and minimum value that is 45 in this case.
The mean in this case is 6.2 due to the presence of an outlier 45. In the presence of outlier mean can be misleading as it is quite sensitive to skewness in data.
Mode is the most frequent value. In this case mode has 4 values: 0,1,2,4.
In case of skewedness, median is the most apt representative of the mean as it is not affected by outliers. In this case since the data set has even values i.e. 10. Median is the average of the 5th & 6th entry after arranging the data in ascending order like that in case of the question (0,0,1,1,2,2,3,4,4,45). This turns out to be 2.
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This question is part of the following fields:
- Statistical Methods
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Question 167
Correct
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This vertebrae can be easily differentiated from the rest because of its prominent spinous process.
Your Answer: C7
Explanation:The spinous process is the part of a vertebrae that is directed posteriorly.
Typical cervical vertebra have spinous processes that are small and bifid, except for C7, which has a long and prominent spinous process.
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This question is part of the following fields:
- Anatomy
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Question 168
Correct
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A 50-year-old man has complained of persistent hoarseness and dry cough. He has a history of smoking 20 cigarettes per day. The examination reveals no significant clinical signs of cranial nerve damage.
Referred to an ENT specialist, the patient is explained how coughing is usually a defence mechanism of the body which is activated more than usual by the chemical irritants in cigarette smoke. However, the ENT doctor suspects a nerve involvement in the cough reflex as the patient also presents with hoarseness with the dry cough.
Which nerves is the ENT doctor suspecting to have been affected in this patient?Your Answer: CN IX and X
Explanation:Cough is an important defensive reflex that helps clear secretions and particulates from the airways. A complex reflex arc generates each cough.
The cough reflex begins with irritation of the cough receptors present in the epithelium of the trachea, main carina, branching points of large airways, and more distal smaller airways. These receptors are responsive to both mechanical and chemical stimuli.
Afferent pathway:
Impulses from stimulated receptors are transmitted via sensory nerve fibres of the vagus nerve (mainly) and glossopharyngeal nerve and travel to the medulla diffusely. CN 5 is also thought to contribute to the afferent limb. However, the vagus is the main nerve.Central pathway:
The cough centre is located in the upper brain stem and ponsEfferent pathway:
Impulses from the centre travel via the vagus, phrenic nerve, and spinal motor nerves to the diaphragm, abdominal wall, and muscles. -
This question is part of the following fields:
- Anatomy
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Question 169
Correct
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Which of the following is true about the patellar reflex?
Your Answer: Is abolished immediately after transection of the spinal cord at T6
Explanation:The patellar (knee jerk) reflex is a monosynaptic stretch reflex arising from L2-L4 nerve roots. It occurs after a tap on the patellar tendon which causes the spindles of the quadriceps muscles to stretch.
The afferent nerve pathway occurred through A gamma fibres.
Wesphal’s sign refers to a reduction, or absence of the patellar reflex. It is often indicated of a neurological disease affecting the PNS.
A transection of the spinal cord results in a degree of shock which causes all reflexes to be reduced or completely absent, and required a period of approximately 6 weeks to recover.
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This question is part of the following fields:
- Pathophysiology
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Question 170
Correct
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Regarding pre-eclampsia with warning signs, which of the following laboratory tests is the most appropriate to establish a platelet dysfunction or disorder?
Your Answer: Platelet count
Explanation:Decreased platelet concentrations with eclampsia were described as early as 1922 by Stancke. The platelet count is routinely measured in women with any form of gestational hypertension. The frequency and intensity of thrombocytopenia vary and are dependent on the severity and duration of the preeclampsia syndrome and the frequency with which platelet counts are performed.
Overt thrombocytopenia defined by a platelet count < 100,000/microliter - indicates severe disease. In general, the lower the platelet count, the higher the rates of maternal and fetal morbidity and mortality. In most cases, delivery is advisable because thrombocytopenia usually continues to worsen. After delivery, the platelet count may continue to decline for the first day or so. It then usually increases progressively to reach a normal level within 3-5 days. In some instances with HELLP syndrome, the platelet count continues to fall after delivery. If these do not reach a nadir until 48 to 72 hours, then preeclampsia syndrome may be incorrectly attributed to one of the thrombotic microangiopathies. The following are other severe features associated with preeclampsia: Proteinuria: >/= 300 mg/24 hours; or urine protein: creatinine ratio >/= 0.3; or dipstick 1+
Renal insufficiency: serum creatinine > 1.1 mg/dL or doubling of creatinine in the absence of other renal disease
Impaired liver function: two times elevated AST/ALT or unexplained right upper quadrant pain or epigastric pain unresponsive to medications
Pulmonary oedema
Cerebral or visual symptoms: headache, visual disturbances
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This question is part of the following fields:
- Pathophysiology
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Question 171
Correct
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A 72-year old farmer is hospitalized with acute respiratory failure and autonomic dysfunction. Suspected organophosphate poisoning.
Which one is the best mechanism for acute toxicity caused by organophosphates?Your Answer: Inhibition of acetylcholinesterase
Explanation:The toxicity of organophosphorus (OP) nerve agents is manifested through irreversible inhibition of acetylcholinesterase (AChE) at the cholinergic synapses, which stops nerve signal transmission, resulting in a cholinergic crisis and eventually death of the poisoned person. Oxime compounds used in nerve agent antidote regimen reactivate nerve agent-inhibited AChE and halt the development of this cholinergic crisis.
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This question is part of the following fields:
- Physiology
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Question 172
Correct
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A 72-year-old long-term rheumatoid arthritis patient is having shoulder replacement surgery.
He has chronic obstructive pulmonary disease with a limited exercise tolerance. He agrees to the procedure being performed with an interscalene brachial plexus block.
Which of the following neurological complications puts this patient at the greatest risk?Your Answer: Phrenic nerve block
Explanation:An ipsilateral phrenic nerve block will result from a successful interscalene block (ISB).
The phrenic nerve is the diaphragm’s sole motor supply, and ipsilateral hemidiaphragmatic paresis affects up to 100% of patients who receive ISBs. Phrenic nerve palsy is usually well tolerated and goes unnoticed by healthy people. However, forced vital capacity decreases by approximately 25%, which can produce ventilatory compromise in patients with limited pulmonary reserve, requiring assisted ventilation.
Vocal cord palsy occurs when the recurrent laryngeal nerve is inadvertently blocked, causing hoarseness and possibly acute respiratory insufficiency. Unless bilateral laryngeal nerve palsy occurs, which can cause severe laryngeal obstruction, this complication is usually of little consequence.
ISB can also cause cranial nerve X and XII palsy (Tapia’s syndrome). One-sided cord paralysis, aphonia, and the patient’s tongue deviating toward the block’s side are all symptoms.
When a local anaesthetic spreads to the stellate ganglion and its cervical sympathetic nerves, Horner’s syndrome can develop. Ptosis of the eyelid, miosis, and anhidrosis of the face are all symptoms. Horner’s syndrome, on the other hand, may not indicate that the brachial plexus is sufficiently blocked.
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This question is part of the following fields:
- Pathophysiology
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Question 173
Correct
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Concerning the pathway of endothelial nitric oxide (eNO), one of the following best describes it.
Your Answer: Stimulation of guanylyl cyclase, increases cGMP concentration leading to vasodilation
Explanation:Nitric oxide (NO), an endothelial-derived relaxant factor (EDRF), is a powerful vasodilator. Its cell-signalling molecule is calcium-dependant and generated endogenous by nitric oxide synthetases from the precursor L-arginine, oxygen and NADPH. Three main isoforms have been isolated and they are inducible (iNO), neuronal (nNO) and endothelial (eNO).
Endothelial NO stimulates intracellular guanylyl cyclase which generates cyclic GMP (cGMP) from its action on guanylyl tri-phosphate (GTP). The cGMP goes on to activate protein kinase G (PKG). PKG phosphorylates cell membrane proteins that regulate intracellular calcium concentrations and level of calcium sensitisation.
Smooth muscle vasodilatation results from:
1. Light chain phosphatase activation.
2. Inhibition of calcium entry into the cell (reducing Ca2+ concentrations) and
3. Hyperpolarisation of cells by activation of H+ channels. -
This question is part of the following fields:
- Pathophysiology
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Question 174
Correct
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A delayed hypersensitivity reaction is type ____?
Your Answer: IV
Explanation:Type I – immediate hypersensitivity reaction
Examples are: Atopy, urticaria, Anaphylaxis, Asthma( IgE mediated).
Type II – Antibody mediated cytotoxic reaction
Examples are: Autoimmune haemolytic anaemia, Thrombocytopenia( IgM or IgG mediated).
Type III – Immune complex mediated reaction
Examples are: Serum sickness,SLE – IgG., Farmers lungs, rheumatoid arthritis
Type IV – Delayed hypersensitivity reaction
Examples are: Contact dermatitis, drug allergies.
Type V – Autoimmune
Graves’
Myasthenia – IgM or IgG. -
This question is part of the following fields:
- Pathophysiology
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Question 175
Incorrect
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When nitrous oxide is stored in cylinders at room temperature, it is a gas.
Which of its property is responsible for this?
Your Answer: Critical pressure
Correct Answer: Critical temperature
Explanation:The temperature above which a gas cannot be liquefied no matter how much pressure is applied is its critical temperature. The critical temperature of nitrous oxide is 36.5°C
The minimum pressure that causes liquefaction is the critical pressure of that gas.
The Poynting effect refers to the phenomenon where mixing of liquid nitrous oxide at low pressure with oxygen at high pressure (in Entonox) leads to formation of gas of nitrous oxide.
There is no relevance of molecular weight to this question. it does not change with phase of a substance.
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This question is part of the following fields:
- Pharmacology
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Question 176
Correct
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Question 177
Correct
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Two different anti-viral treatments are being evaluated for COVID-19 in a clinical study.
Which of the following statistical method should be opted to compare survival time with?Your Answer: Hazard ratio
Explanation:The hazard ratio (HR) is simply a comparison of two hazards in a study. It provides an estimate of the ratio of the hazard rates between the experimental group and a control group over the entire study duration. It is typically used when analysing survival over time, hence is the most suitable statistical method in this case.
An odds ratio is a statistic that quantifies the strength of the association between two events, A and B. It is the “measure of association” for a case-control study.
The Pearson product-moment correlation coefficient (Pearson’s correlation, for short) is a measure of the strength and direction of association that exists between two variables. An example would be if scientists wanted to evaluate the relationship between quality of certain population of rice and their genetic make-up.
Relative risk is the ratio of the risks for an event for the exposure group to the risks for the non-exposure group. Thus relative risk provides an increase or decrease in the likelihood of an event based on some exposure. Relative risk measures the association between the exposure and the outcome.
Absolute risk reduction is the number of percentage points your own risk goes down if you do a preventive act such as stop drinking alcohol. It depends on what your risk factors are to begin with.
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This question is part of the following fields:
- Statistical Methods
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Question 178
Incorrect
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A new volatile anaesthetic agent has been approved for use in clinical testing.
It's a non-irritating, sweet-smelling substance. It has a molecular weight of 170, a 0.6 blood:gas partition coefficient, and a 180 oil:gas partition coefficient. An oxidative pathway converts 2% of the substance to trifluoroacetic acid.
Which of the following statements best describes this agent's pharmacological profile?Your Answer: It has a lower MAC than halothane
Correct Answer: It has a lower molecular weight than isoflurane
Explanation:Because enflurane is much less soluble in blood and has a blood: gas partition coefficient of 1.8, both wash-in and wash-out should be faster.
Sevoflurane’s sweet-smelling, non-irritant nature, combined with a low blood: gas partition coefficient, would result in similar offset and onset characteristics.
Isoflurane and enflurane have a molecular weight of 184.
The oil: gas partition coefficient on a volatile agent is a measure of lipid solubility, potency, and thus MAC. Halothane has an oil: gas partition coefficient of 220 and a MAC of 0.74. One would expect the MAC to be higher with an oil gas partition coefficient of 180 (less lipid soluble).
The conversion of halothane (20%) to trifluoroacetic acid via oxidative metabolism has been linked to the development of hepatitis.
P450 2E1 converts sevoflurane to hexafluoroisopropanol, which results in the release of inorganic fluoride ions. It’s the only fluorinated volatile anaesthetic that doesn’t break down into trifluoracetic acid.
Desflurane is likely to cause airway irritation, which can lead to coughing, apnoea, and laryngospasm, despite its low blood:gas partition coefficient (0.42).
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This question is part of the following fields:
- Pharmacology
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Question 179
Incorrect
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A young male is undergoing inguinal hernia repair. During the procedure, the surgeons approach the inguinal canal and expose the superficial inguinal ring.
Which structure forms the lateral edge of the superficial inguinal ring?Your Answer: Rectus abdominis muscle
Correct Answer: External oblique aponeurosis
Explanation:The superficial inguinal ring is an opening in the aponeurosis of the external oblique muscle, just above and lateral to the pubic crest.
The superficial ring resembles a triangle more than a ring with the base lying on the pubic crest and its apex pointing towards the anterior superior iliac spine. The sides of the triangle are crura of the opening in the external oblique aponeurosis. The lateral crura of the triangle is attached to the pubic tubercle. The medial crura of the triangle is attached to the pubic crest.
The external oblique aponeurosis forms the anterior wall of the inguinal canal and also the lateral edge of the superficial inguinal ring. The rectus abdominis lies posteromedially, and the transversalis posterior to this.
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This question is part of the following fields:
- Anatomy
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Question 180
Incorrect
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A graph was plotted after administration of fentanyl infusion to a patient. The following are the x- and y-axis of the graph:
X-axis: Dose of fentanyl
Y-axis: Mu receptor occupancy, measured using positron emission tomography
Given the data above, what would be the best representation of the graph if the data on the x-axis are converted to logarithms?Your Answer: Wash-out exponential curve to a straight line
Correct Answer: Rectangular hyperbola to sigmoid curve
Explanation:The dose-response curve plots the graph of the dose (drug concentration) versus the response. As doses increase, the response increment diminishes; finally, doses may be reached at which no further increase in response can be achieved. This relation between drug concentration and effect is traditionally described by a hyperbolic curve. When the x-axis is plotted in log scale, the graph yields a sigmoid curve.
Efficacy (Emax) and potency (EC50) can be derived from this curve. Emax is the maximal effect achievable, with increasing concentration of a drug. EC50 is the concentration of the drug, wherein half of the maximal effect is achieved.
When the graph is plotted using a log [response/1-response] against log dose, the sigmoid curve becomes a straight line (Hill plot). A graph that transforms from a straight line to exponential curve is mathematically incorrect. A graph that transforms from either a wash-in or wash-out exponential curve to a straight line comes from an initial set of data plotted against time, to a logarithmic transformation of the initial data set against time.
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This question is part of the following fields:
- Statistical Methods
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Question 181
Correct
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A 5-year old male has ingested a peanut and has developed urticaria, vomiting and hypotension. The pathogenesis of this condition is derived from predominant cells of which cell line?
Your Answer: Common myeloid progenitor
Explanation:A is correct. Common myeloid progenitor cells are involved in the anaphylaxis reaction.
B is incorrect. The common lymphoid lineage gives rise to T-cells, B-cell and NK cells.
C is incorrect as megakaryocytes give rise to platelets.
D is incorrect – Neural crest cells give rise to various cells throughout the body, including melanocytes, enterochromaffin cells and Schwann cells. However, they do not give rise to mast cells.
E is incorrect. Reticulocytes give rise to erythrocytes.This is a classic case of anaphylaxis. In this situation, IgE previously raised against antigens (in this case peanut antigen) bind to mast cells, and this causes them to degranulate.
There is release of vasoactive substances like histamine into the blood, and this is responsible for the symptoms seen. Therefore, the main type of cells involved in the pathogenesis of the disease is mast cells. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 182
Correct
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What can you see within the tunica media of a blood vessel on examination?
Your Answer: Smooth muscle
Explanation:The blood vessel well is divided into 3 parts, namely:
The tunica intima, which is the deepest layer. It contains endothelial cells separated by gap junctions
The tunica media, primarily consisting of the involuntary smooth muscle fibres, laid out in spiral layers with elastic fibres and connective tissue.
The tunica adventitia, which is the most superficial layer. It consists of the vasa vasorum, fibroblast and collagen.
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This question is part of the following fields:
- Anatomy
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Question 183
Incorrect
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Which statement regarding the cardiac action potential is correct?
Your Answer: Phase 2 is the plateau phase with large influx of calcium ions
Correct Answer:
Explanation:Cardiac conduction
Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium
Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop
Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period
Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period
Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 184
Correct
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A 68-year old female is brought to the Emergency Room for abdominal pain. Medical history revealed that she is on long-term warfarin therapy for deep vein thrombosis.
Upon further investigation, the patient is hypotensive at 80/60 mmHg, and an abdominal mass is palpable on the umbilical area. An initial diagnosis of ruptured abdominal aortic aneurysm (AAA) is made. Moreover, blood tests show an international normalised ratio (INR) of 4.2.
Which of the following products should be initially transfused or administered to the patient to reverse the anticoagulation?Your Answer: Prothrombin complex
Explanation:Warfarin prevents reductive metabolism of the inactive vitamin K epoxide back to its active hydroquinone form. Thus, warfarin inhibits the synthesis of vitamin K dependent clotting factors: X, IX, VII, II (prothrombin), and of the anticoagulants protein C and protein S. The therapeutic range for oral anticoagulant therapy is defined in terms of an international normalized ratio (INR). The INR is the prothrombin time ratio (patient prothrombin time/mean of normal prothrombin time for lab)ISI, where the ISI exponent refers to the International Sensitivity Index and is dependent on the specific reagents and instruments used for the determination. A prolonged INR is widely used as an indication of integrity of the coagulation system in liver disease and other disorders, it has been validated only in patients in steady state on chronic warfarin therapy.
Prothrombin complex concentrate (PCC) is used to replace congenital or acquired vitamin-K deficiency warfarin-induced anticoagulant effect, particularly in the emergent setting.
Intravenous vitamin K has a slower onset of action compared to PCC, but is useful for long term therapy.
Fresh frozen plasma (FFP) prepared from freshly donated blood is the usual source of the vitamin K-dependent factors and is the only source of factor V. The factors needed, however, are found in small quantities compared to PCC.
Cryoprecipitate is indicated for hypofibrinogenemia/dysfibrinogenemia, von Willebrand disease, haemophilia A, factor XIII deficiency, and management of bleeding related to thrombolytic therapy.
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This question is part of the following fields:
- Pathophysiology
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Question 185
Correct
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The plateau phase of the myocardial action potential is as a result of:
Your Answer: Slow influx of calcium
Explanation:Cardiac conduction
Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium
Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop
Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period
Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period
Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 186
Correct
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A 65-year-old man has been diagnosed with transitional cell carcinoma of the left kidney. He will be operated on, and as part of the surgery, the left renal artery has to be located and dissected.
Which of the following vertebral levels gives rise to this artery?
Your Answer: L1
Explanation:The renal arteries branch from the abdominal aorta just below the origin of the superior mesenteric artery. The right renal artery is higher and longer than the left renal artery. The left renal artery passes behind the left renal vein, the body of the pancreas, and the splenic vein.
The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:
T10 – oesophageal opening in the diaphragm
T12 – Coeliac trunk, aortic hiatus in the diaphragm
L1 – Left renal artery
L2 – Testicular or ovarian arteries
L3 – Inferior mesenteric artery
L4 – Bifurcation of the abdominal aorta
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This question is part of the following fields:
- Anatomy
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Question 187
Correct
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A 49-year-old woman is admitted to hospital. She is scheduled for surgery and is undergoing preoperative assessment.
As part of the preoperative assessment, her functional capacity is estimated. At 50kg in weight, she is able to cycle along a flat surface at a speed of 10-14 miles/hour (8 metabolic equivalents or METs).
Provide the best estimated value of oxygen consumption (VO2) for eight METs.Your Answer: 1400 mL/minute
Explanation:Oxygen consumption (VO2) refers to the optimal amount of oxygen used by the body during exercise.
It is calculated mathematically by:
VO2 = 3.5 x 50 x 8 = 1400 mL/kg/minute
where,
1 MET = 3.5 mL O2/kg/minute is utilized by the body.
Note:
1 MET Eating
Dressing
Use toilet
Walking slowly on level ground at 2-3 mph
2 METs Playing a musical instrument
Walking indoors around house
Light housework
4 METs Climbing a flight of stairs
Walking up hill
Running a short distance
Heavy housework, scrubbing floors, moving heavy furniture
Walking on level ground at 4 mph
Recreational activity, e.g. golf, bowling, dancing, tennis
6 METs Leisurely swimming
Leisurely cycling along the flat (8-10 mph)
8 METs Cycling along the flat (10-14 mph)
Basketball game
10 METs Moderate to hard swimming
Competitive football
Fast cycling (14-16 mph) -
This question is part of the following fields:
- Clinical Measurement
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Question 188
Correct
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A 89-year old male has hypertension, with a blood pressure of 170/68 mmHg and has been admitted to the hospital. He is on no regular medications. His large pulse pressure can be accounted for by which of the following?
Your Answer: Reduced aortic compliance
Explanation:Cardiac output = stroke volume x heart rate
Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%
Stroke volume = end diastolic LV volume – end systolic LV volume
Pulse pressure = Systolic Pressure – Diastolic Pressure
Systemic vascular resistance = mean arterial pressure / cardiac output
Factors that increase pulse pressure include:
-a less compliant aorta (this tends to occur with advancing age)
-increased stroke volume -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 189
Incorrect
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A double-blinded randomised controlled trial is proposed to assess the effectiveness of a new blood pressure medication.
Which type of bias can be avoided by ensuring the patient and doctor are blinded?Your Answer: Confounding bias
Correct Answer: Expectation bias
Explanation:Observers may subconsciously measure or report data in a way that favours the expected study outcome. Therefore, by blinding the study we can eliminate expectation bias.
Recall bias is a systematic error that occurs when the study participants omit details or do not remember previous events or experiences accurately.
Verification can occur during investigations when there is a difference in testing strategy between groups of individuals, which might lead to biasness due to differing ways of verifying the disease of interest.
Nonresponse bias is the bias that occurs when the people who respond to a survey differ significantly from the people who do not respond to the survey.
A distortion that modifies an association between an exposure and an outcome because a factor is independently associated with the exposure and the outcome. Randomization is the best way to reduce the risk of confounding.
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This question is part of the following fields:
- Statistical Methods
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Question 190
Correct
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The prostate and the rectum are separated by which anatomical plane?
Your Answer: Denonvilliers fascia
Explanation:The prostate is separated from the rectum by the Denonvilliers fascia (rectoprostatic fascia).
Waldeyers fascia functions to separate the rectum and the sacrum.
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This question is part of the following fields:
- Anatomy
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Question 191
Correct
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An intravenous infusion is started with a 500 mL bag of 0.18 percent N. saline and 4% dextrose.
Which of the following best describes its make-up?Your Answer: Osmolarity 284 mOsmol/L, sodium 15 mequivalents and glucose 20 g
Explanation:30 mmol Na+ and 30 mmol Cl- are found in 1 litre of 0.18 percent N. saline with 4% dextrose. Percent (percent) refers to the number of grammes of a compound per 100 mL, so a litre of 4 percent dextrose solution contains 40 grammes.
As a result, a 500 mL bag of 1/5th N. saline and 4% dextrose contains approximately 15 mequivalents of sodium and 20 g of glucose. It is hypotonic due to its osmolarity of 284.
Because of the risk of hyponatraemia, it is no longer considered the crystalloid of choice for fluid maintenance in children.
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This question is part of the following fields:
- Physiology
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Question 192
Correct
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Which compound of ketamine hydrochloride has the most significant anaesthetic property or effect?
Your Answer: (S)-ketamine
Explanation:Ketamine is usually used as a racemic mixture, i.e. (R/S)-ketamine. For over 20 years, use of the more potent (S)-enantiomer by anaesthesiologists has become a preferred option due to the assumption of increased anaesthetic and analgesic properties, a more suitable control of anaesthesia, and of an improved recovery from anaesthesia.
The use of ketamine in anaesthesia and psychiatry may be accompanied by the manifestation of somatic and especially psychomimetic symptoms such as perceptual disturbances, experiences of dissociation, euphoria, and anxiety.
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This question is part of the following fields:
- Pharmacology
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Question 193
Incorrect
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Regarding chest tube insertion, which of the following measurements is utilized when selecting a chest tube drain?
Your Answer: Standard wire gauge (SWG)
Correct Answer: External circumference (mm)
Explanation:Selection of a chest drain will depend on the external circumference.
A cannula, whether intravenous or intra-arterial, are classified according to standard wire gauge, which refers to the number of wires that can fit into the same hole. If a cannula is labelled 22G, then 22 wires will fit into the standard size hole.
A more popular measurement than SWG nowadays is cross sectional area.
When the concern for selecting equipment is the rate of flow, then it is important to consider the diameter and the radius of a parallel sided tube. These, however, are not routinely considered when comparing sizes of a cannula.
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This question is part of the following fields:
- Pathophysiology
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Question 194
Correct
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Which of the following statement is true regarding the mechanism of action of rifampicin?
Your Answer: Inhibit RNA synthesis
Explanation:Rifampicin is a derivative of a rifamycin (other derivatives are rifabutin and rifapentine). It is bactericidal against both dividing and non-dividing mycobacterium and acts by inhibiting DNA-dependent RNA polymerase. Thus this drug inhibits RNA synthesis.
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This question is part of the following fields:
- Pharmacology
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Question 195
Correct
-
Which statement best describes the bispectral index (BIS)?
Your Answer: It decreases during normal sleep
Explanation:The bispectral index (BIS) is one of several systems used in anaesthesiology as of 2003 to measure the effects of specific anaesthetic drugs on the brain and to track changes in the patient’s level of sedation or hypnosis. It is a complex mathematical algorithm that allows a computer inside an anaesthesia monitor to analyse data from a patient’s electroencephalogram (EEG) during surgery. It is a dimensionless number (0-100) that is a summative measurement of time domain, frequency domain and high order spectral parameters derived from electroencephalogram (EEG) signals.
Sleep and anaesthesia have similar behavioural characteristics but are physiologically different but BIS monitors can be used to measure sleep depth. With increasing sleep depth during slow-wave sleep, BIS levels decrease. This correlates with changes in regional cerebral blood flow when measured using positron emission tomography (PET).
BIS shows a dose-response relationship with the intravenous and volatile anaesthetic agents. Opioids produce a clinical change in the depth of sedation or analgesia but fail to produce significant changes in the BIS. Ketamine increases CMRO2 and EEG activity.
BIS is unable to predict movement in response to a surgical stimulus. Some of these are spinal reflexes and not perceived by the cerebral cortex.
BIS is used during cardiopulmonary bypass to measure depth of anaesthesia and an index of cerebral perfusion. However, it cannot predict subtle or significant cerebral damage.
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This question is part of the following fields:
- Physiology
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Question 196
Correct
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A 61-year-old woman with myasthenia gravis is admitted to the ER with type II respiratory failure. There is a suspicion of myasthenic crisis.
She is in a semiconscious state. Her blood pressure is 160/90 mmHg, pulse is 110 beats per minute, temperature is 37°C, and oxygen saturation is 84 percent.
With a PaCO2 of 75 mmHg (10 kPa) breathing air, blood gas analysis confirms she is hypoventilating.
Which of the following values is the most accurate representation of her alveolar oxygen tension (PAO2)?Your Answer: 7.3
Explanation:The following is the alveolar gas equation:
PAO2 = PiO2 − PaCO2/R
Where:
PAO2 is the partial pressure of oxygen in the alveoli.
PiO2 is the partial pressure of oxygen inhaled.
PaCO2 stands for partial pressure of carbon dioxide in the arteries.
The amount of carbon dioxide produced (200 mL/minute) divided by the amount of oxygen consumed (250 mL/minute) equals R = respiratory quotient. With a normal diet, the value is 0.8.By subtracting the partial pressure exerted by water vapour at body temperature, the PiO2 can be calculated:
PiO2 = 0.21 × (100 kPa − 6.3 kPa)
PiO2 = 19.8Substituting:
PAO2 = 19.8 − 10/0.8
PAO2 = 19.8 − 12.5
PAO2 = 7.3k Pa -
This question is part of the following fields:
- Physiology
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Question 197
Correct
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Regarding sine wave damping, which one would approach equilibrium the fastest at zero amplitude, without overshoot?
Your Answer: Critical damping
Explanation:A damped sine wave is a smooth, periodic oscillation with an amplitude that approaches zero as time goes to infinity. In other words, the wave gets flatter as the x-values become larger.
Critical damping is defined as the threshold between overdamping and underdamping. In the case of critical damping, the oscillator returns to the equilibrium position as quickly as possible, without oscillating, and passes it once at most.
In overdamping, the system moves slowly towards the equilibrium. An underdamped system moves quickly to equilibrium, but will oscillate about the equilibrium point as it does so.
Optimal damping has a damping coefficient of around 0.64-0.7. It maximizes frequency response, minimizes overshoot of oscillations, and minimizes phase and amplitude distortion.
In an undamped system, the amplitude of the waves that are being generated remain unchanged and constant over time.
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This question is part of the following fields:
- Clinical Measurement
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Question 198
Correct
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Of the following statements, which is true about the measurements of cardiac output using thermodilution?
Your Answer: Cardiac output should be measured during the end-expiratory pause
Explanation:Thermodilution is the most common dilution method used to measure cardiac output (CO) in a hospital setting.
During the procedure, a Swan-Ganz catheter, which is a specialized catheter with a thermistor-tip, is inserted into the pulmonary artery via the peripheral vein. 5-10mL of a cold saline solution with a known temperature and volume is injected into the right atrium via a proximal catheter port. The solution is cooled as it mixes with the blood during its travel to the pulmonary artery. The temperature of the blood is the measured by the catheter and is profiled using a computer.
The computer also uses the profile to measure cardiac output from the right ventricle, over several measurements until an average is selected.
Cardiac output changes at each point of respiration, therefore to get an accurate measurement, the same point during respiration must be used at each procedure, this is usually the end of expiration, that is the end-expiratory pause.
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This question is part of the following fields:
- Clinical Measurement
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Question 199
Correct
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What vessel is NOT considered a major branch of the descending thoracic aorta?
Your Answer: Inferior thyroid artery
Explanation:The descending thoracic aorta begins at the lower border of T4 near the midline as a continuation of the arch of the aorta. It descends and ends at the level of T12 at the aortic hiatus in the diaphragm, where it becomes the abdominal aorta.
The aorta gives off the following branches: (descending order)
1. Bronchial arteries
2. Mediastinal arteries
3. Oesophageal arteries
4. Pericardial arteries
5. Superior phrenic arteriesThe posterior intercostal arteries are branches that originate throughout the length of the posterior aspect of the descending thoracic aorta.
The inferior thyroid artery is usually derived from the thyrocervical trunk, a branch of the subclavian artery.
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This question is part of the following fields:
- Anatomy
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Question 200
Incorrect
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The child-Pugh scoring system can be used, if risk classifying a patient with chronic liver disorder earlier to anaesthesia.
Which one is the best combination of clinical signs and examinations used within the Child-Pugh scoring system?Your Answer: Ascites, grade of encephalopathy, AST/ALT, bilirubin and INR
Correct Answer: Ascites, grade of encephalopathy, albumin, bilirubin and INR
Explanation:In the Child-Pugh classification system, the following 5 components are determined or calculated in order:
Ascites
Grade of encephalopathy
Serum bilirubin (?mol/L)
Serum Albumin (g/L)
Prothrombin time or INR
Raised liver enzymes are not the component of the classification system.
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This question is part of the following fields:
- Basic Physics
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