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  • Question 1 - Metabolization of many drugs used in anaesthesia involves the cytochrome P450 (CYP) isoenzymes.

    The...

    Incorrect

    • Metabolization of many drugs used in anaesthesia involves the cytochrome P450 (CYP) isoenzymes.

      The CYP enzyme most likely to be subject to genetic variability and thus cause adverse drug reactions is which of these?

      Your Answer: CYP2C19

      Correct Answer: CYP2D6

      Explanation:

      Approximately 25% of phase-1 drug reactions is made responsible by CYP2D6.

      As much as a 1,000-fold difference in the ability to metabolise drugs by CYP2D6 can happen between phenotypes, and this may result in adverse drug reactions (ADRs).

      The metabolism of antiemetics, beta-blockers, codeine, tramadol, oxycodone, hydrocodone, tamoxifen, antidepressants, neuroleptics, and antiarrhythmics is also as a result of CYP2D6.

      Patients who take drugs that are metabolised by CYP2D6 but have poor CYP2D6 metabolism are more likely to have ADRs. People with ultra-rapid CYP2D6 metabolism may have a decreased drug effect due to low plasma concentrations of these drugs.

      All the other CYP enzymes are subject to genetic polymorphism. Variants are less likely to lead to adverse drug reactions.

    • This question is part of the following fields:

      • Physiology
      11.9
      Seconds
  • Question 2 - The following is true about the extracellular fluid (ECF) in a normal adult...

    Incorrect

    • The following is true about the extracellular fluid (ECF) in a normal adult woman weighing 60 kg.

      Your Answer: Is isotonic throughout the body

      Correct Answer: Has a total volume of about 12 litres

      Explanation:

      Total body water (TBW) is about 50% to 70% in adults depending on how much fat is present. ECF is relatively contracted in an obese person.

      The simple rule is 60-40-20. (60% of weight = total body water, 40% of body weight is ICF and 20% is ECF)

      For this woman, the total body water is 36 litres (0.6 × 60). ECF is 12 litres (1/3 of TBW) and 24 litres (2/3 of TBW) is intracellular fluid .

      Sodium concentration is approximately 135-145 mmol/L in the ECF.

      The ECF is made up of both intravascular and extravascular fluid and plasma proteins is found in both.

    • This question is part of the following fields:

      • Physiology
      13
      Seconds
  • Question 3 - A 27-year-old woman is admitted to the emergency room with an ectopic pregnancy...

    Incorrect

    • A 27-year-old woman is admitted to the emergency room with an ectopic pregnancy that has ruptured.

      The following is a description of the clinical examination:

      Anxious
      Capillary refill time of 3 seconds
      Cool peripheries
      Pulse 120 beats per minute
      Blood pressure 120/95 mmHg
      Respiratory rate 22 breaths per minute.

      Which of the following is the most likely explanation for these clinical findings?

      Your Answer: Reduction in blood volume of 30-40%

      Correct Answer: Reduction in blood volume of 15-30%

      Explanation:

      The following is the Advanced Trauma Life Support (ATLS) classification of haemorrhagic shock:

      Class I haemorrhage:
      It has blood loss up to 15%. There is very less tachycardia, and no changes in blood pressure, RR or pulse pressure. Usually, fluid replacement is not required.

      Class II haemorrhage:
      It has 15-30% blood loss, equivalent to 750 – 1500 ml. There is tachycardia, tachypnoea and a decrease in pulse pressure. Patient may be frightened, hostile and anxious. It can be stabilised by crystalloid and blood transfusion.

      Class III haemorrhage:
      There is 30-40% blood loss. It portrays inadequate perfusion, marked tachycardia, tachypnoea, altered mental state and fall in systolic pressure. It requires blood transfusion.

      Class IV haemorrhage:
      There is > 40% blood volume loss. It is a preterminal event, and the patient will die in minutes. It portrays tachycardia, significant depression in systolic pressure and pulse pressure, altered mental state, and cold clammy skin. There is need for rapid transfusion and surgical intervention.

    • This question is part of the following fields:

      • Physiology
      23.4
      Seconds
  • Question 4 - A 25-year old lady is in the operating room and has had general...

    Incorrect

    • A 25-year old lady is in the operating room and has had general anaesthesia for a knee arthroscopy.

      Induction was done with fentanyl 1mcg/kg and propofol 2mg/kg. A supra-glottic airway was inserted and using and air oxygen mixture with 2.5% sevoflurane, her anaesthesia was maintained. The patient is allowed to spontaneously breathe using a Bain circuit, and the fresh gas flow is 9L/min. Over the next 30 minutes, the end-tidal Co2 rises from 4.5kPa to 8.4kPa, and the baseline reading on the capnograph is 0kPa.

      The most appropriate initial action is which of the following?

      Your Answer: Inadequate fresh-gas flow

      Correct Answer: Hypoventilation

      Explanation:

      The commonest and most likely cause of a gradual rise in end-tidal CO2 (EtCO2) occurring during anaesthesia in a spontaneously breathing patient is hypoventilation. This occurs from the respiratory depressant effects of the opioid and sevoflurane.

      Malignant hyperthermia should be sought if the EtCO2 shows further progressive rise.

      Causes of rebreathing and a rise in the baseline of the capnograph can be caused by exhausted soda lime and inadequate fresh gas flow into the Bain circuit.

      A sudden rise in EtCO2 can be caused deflation of the tourniquet.

    • This question is part of the following fields:

      • Physiology
      49.8
      Seconds
  • Question 5 - Pressure volume loop represents the compliance of left ventricle.

    Considering there...

    Incorrect

    • Pressure volume loop represents the compliance of left ventricle.

      Considering there is no change in preload and myocardial contractility, which physiological change may result an increase in left ventricular afterload?

      Your Answer: Reduced end-systolic volume

      Correct Answer: Increased end-systolic volume

      Explanation:

      If there is no change in preload and myocardial contractility, there will be decrease in end-diastolic volume and stroke volume. So there must be increase in end-systolic volume.

    • This question is part of the following fields:

      • Physiology
      17.2
      Seconds
  • Question 6 - Which of the following statement is true regarding hypoxic pulmonary vasoconstriction (HPV)? ...

    Incorrect

    • Which of the following statement is true regarding hypoxic pulmonary vasoconstriction (HPV)?

      Your Answer: Increases ventilation/perfusion mismatch

      Correct Answer: 20 parts per million (ppm) of nitric oxide will reduce hypoxic pulmonary vasoconstriction

      Explanation:

      Hypoxic Pulmonary vasoconstriction (HPV) reflects the constriction of small pulmonary arteries in response to hypoxic alveoli (.i.e.; PO2 below 80-100mmHg or 11-13kPa).

      These blood vessels become independent of the nerve stimulus, when blood with a high PO2 flows through the lung which contains a low alveolar PO2.

      Thus a low PO2 within the alveoli has been shown to impact on hypoxic pulmonary vasoconstriction (HPV) more than a low PO2 within the blood.

      HPV results in the blood flow being directed away from poorly ventilated areas of the lung and helps to reduce the ventilation/perfusion mismatch (not increase).

      In animals, volatile anaesthetic agents can diminish HPV, while in adults, the evidence proves less persuading, in spite of the fact that it certainly doesn’t strengthen the effects.

      HPV response will be suppressed by 20 parts per million (ppm) of nitric oxide.

    • This question is part of the following fields:

      • Physiology
      14.3
      Seconds
  • Question 7 - A human's resting oxygen consumption (VO2) is typically 3.5 ml/kg/minute (one metabolic equivalent...

    Incorrect

    • A human's resting oxygen consumption (VO2) is typically 3.5 ml/kg/minute (one metabolic equivalent or 1 MET).

      Which of the following options is linked to the highest VO2 when a person is at rest?

      Your Answer: Sepsis syndrome

      Correct Answer: Neonate

      Explanation:

      The oxygen consumption rate (VO2) at rest is 3.5 ml/kg/minute (one metabolic equivalent or 1 MET).
      3.86 ml/kg/minute thyrotoxicosis

      Young children consume a lot of oxygen: around 7 ml/kg/min when they are born. The metabolic cost of breathing is higher in children than in adults, and it can account for up to 15% of total oxygen consumption. Similarly, an infant’s metabolic rate is nearly twice that of an adult, resulting in a larger alveolar minute volume and a lower FRC.

      At term, oxygen consumption at rest can increase by as much as 40% (5 ml/kg/minute) and can rise to 60% during labour.

      When compared to normal basal metabolism, sepsis syndrome increases VO2 and resting metabolic rate by 30% (4.55 ml/kg/minute). In septicaemic shock, VO2 decreases.

      Dobutamine hydrochloride was infused into 12 healthy male volunteers at a rate of 2 micrograms per minute per kilogramme, gradually increasing to 4 and 6 micrograms per minute per kilogramme. Dobutamine was infused for 20 minutes for each dose. VO2 increased by 10% to 15%. (3.85-4.0 ml/kg/min).

    • This question is part of the following fields:

      • Physiology
      52.9
      Seconds
  • Question 8 - Which of the following statements is about the measurement of glomerular filtration rate...

    Incorrect

    • Which of the following statements is about the measurement of glomerular filtration rate (GFR) is correct?

      Your Answer: If the clearance of a solute is less than that of inulin, it may be due to tubular secretion of that solute

      Correct Answer: The result matches clearance of the indicator if it is renally inert

      Explanation:

      The measurements of GFR are done using renally inert indicators like inulin, where passive rate of filtration at the glomerulus = rate of excretion. Normal value is about 180 litres per day.

      GFR is altered by renal blood flow but blood flow does not need to be measured.

      The reabsorption of Na leads to a low excretion rate and low urine concentration and therefore its use as an indicator would lead to an erroneously LOW GFR.

      If there is tubular secretion of any solute, the clearance value will be higher than that of inulin. This will be either due to tubular reabsorption or the solute not being freely filtered at the glomerulus.

    • This question is part of the following fields:

      • Physiology
      51.8
      Seconds
  • Question 9 - The passage of glucose into the brain is facilitated by which transport method?...

    Incorrect

    • The passage of glucose into the brain is facilitated by which transport method?

      Your Answer: Na- K pump facilitation

      Correct Answer: Facilitated diffusion

      Explanation:

      Glucose transport is a highly regulated process accomplished mostly by facilitated diffusion using carrier proteins to cross cell membranes.

      There are many transporters, but the most important are known as glucose transporters (GLUTs).

      Stresses in various form of acute and chronic forms affect the activity of glucose transporters.
      They are responsive to many types of metabolic stress, including hypoxia, injury, hypoglycaemia, numerous metabolic inhibitors, stress hormones, and other influences such as growth factors.

      Numerous signalling pathways appear to be involved in transporter regulation.

      New evidence suggests that stresses regulating GLUTs are not only acute biological stresses. In addition, chronic low-grade inflammation, and their associated chronic diseases also lead to altered glucose transport. These include obesity, type 2 diabetes, cardiovascular disease, and the growth and spread of many tumours that are affected by altered glucose transporters. Some of these glucose transport effects are compensatory, while others are pathogenic.

      Ultimately, deliberate manipulation of GLUTs could be used as treatment for some of these chronic diseases.

    • This question is part of the following fields:

      • Physiology
      6.8
      Seconds
  • Question 10 - One of the non-pharmacologic management of COPD is smoking cessation. Given a case...

    Correct

    • One of the non-pharmacologic management of COPD is smoking cessation. Given a case of a 60-year old patient with history of smoking for 30 years and a FEV1 of 70%, what would be the most probable five-year course of his FEV1 if he ceases to smoke?

      Your Answer: The FEV1 will decrease at the same rate as a non-smoker

      Explanation:

      For this patient, his forced expiratory volume in 1 second (FEV1) will decrease at the same rate as a non-smoker.

      There is a notable, but slow, decline in FEV1 when an individual reaches the age of 26. An average reduction of 30 mls every year in non-smokers, while a more significant reduction of 50-70 mls is observed in approximately 20% of smokers.

      Considering the age of the patient, individuals who begin smoking cessation by the age of 60 are far less likely to achieve normal FEV1 levels, even in the next five years. It is expected that their FEV1 will be approximately 14% less than their peers of the same age.

    • This question is part of the following fields:

      • Physiology
      21.7
      Seconds

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Physiology (1/10) 10%
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