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  • Question 1 - A 54-year-old lady comes in for a right-sided elective bunionectomy with a realignment...

    Incorrect

    • A 54-year-old lady comes in for a right-sided elective bunionectomy with a realignment osteotomy under local anaesthetic on her first (large) toe.

      For the operation, which of the following nerve blocks will be most effective?

      Your Answer: Saphenous, posterior tibial and superficial peroneal nerves

      Correct Answer: Superficial peroneal, deep peroneal and posterior tibial nerves

      Explanation:

      An ankle block is commonly used for anaesthesia and postoperative analgesia when operating on bunions. It results in the selective block of the superficial peroneal, deep peroneal, and posterior tibial nerves.

      The deep peroneal nerve supplies sensory input to the web space between the first and second toes (L4-5).

      The L2-S1 nerve, often known as the superficial peroneal nerve, is a mixed motor and sensory neuron. It gives sensory supply to the anterolateral region of the leg, the anterior aspect of the 1st, 2nd, 3rd, and 4th toes, and innervates the peroneus longus and brevis muscles (with the exception of the web space between 1st and 2nd toes).

      The sensory area of the saphenous nerve (L3-4) in the foot stretches from the proximal portion of the midfoot on the medial side to the proximal part of the midfoot on the lateral side.

      The lateral side of the little (fifth) toe is innervated by the sural nerve’s sensory supply (S1-2). The heel, medial (medial plantar nerve), and lateral (lateral plantar nerve) soles of the foot are all served by the posterior tibial nerve.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 2 - An emergency appendicectomy is being performed on a 20 year old man. For...

    Incorrect

    • An emergency appendicectomy is being performed on a 20 year old man. For maintenance of anaesthesia, he is being ventilated using a circle system with a fresh gas flow (FGF) of 1 L/min (air/oxygen and sevoflurane). The trace on the capnograph shows a normal shape.

      The table below demonstrates the changes in the end-tidal and baseline carbon dioxide measurements of the capnograph at 10 and 20 minutes of anaesthesia maintenance.  
      End-tidal CO2: 4.9 kPa vs 8.4kPa (10 minutes vs 20 minutes)
      Baseline end-tidal CO2: 0.2 kPa vs 2.4kPa

      Pulse 100-107 beats per minute, systolic blood pressure 125-133 mmHg and oxygen saturation 98-99%. 

      Which of the following is the single most important immediate course of action?

      Your Answer:

      Correct Answer: Increase the FGF

      Explanation:

      End-tidal carbon dioxide (ETCO2) monitoring has been an important factor in reducing anaesthesia-related mortality and morbidity. Hypercarbia, or hypercapnia, occurs when levels of CO2 in the blood become abnormally high (Paco2 >45 mm Hg). Hypercarbia is confirmed by arterial blood gas analysis. When using capnography to approximate Paco2, remember that the normal arterial–end-tidal carbon dioxide gradient is roughly 5 mm Hg. Hypercarbia, therefore, occurs when PETco2 is greater than 40 mm Hg.

      The most likely explanation for the changes in capnograph is either exhaustion of the soda lime and a progressive rise in circuit dead space.

      Inspect the soda lime canister for a change in colour of the granules. To overcome soda lime exhaustion, the first step is to increase the fresh gas flow (FGF) (Option A). Then, if need arises, replace the soda lime granules. Other strategies that can work are changing to another circuit or bypassing the soda lime canister, but remember that both these strategies are employed only after increasing FGF first. Exclude other causes of equipment deadspace too.

      There are also other causes for hypercarbia to develop intraoperatively:
      1. Hypoventilation is the most common cause of hypercapnia. A. Inadequate ventilation can occur with spontaneous breathing due to drugs like anaesthetic agents, opioids, residual NMDs, chronic respiratory or neuromuscular disease, cerebrovascular accident.
      B. In controlled ventilation, hypercapnia due to circuit leaks, disconnection or miscalculation of patient’s minute volume.
      2. Rebreathing – Soda lime exhaustion with circle, inadequate fresh gas flow into Mapleson circuits and increased breathing system deadspace.
      3. Endogenous source – Tourniquet release, hypermetabolic states (MH or thyroid storm) and release of vascular clamps.
      4. Exogenous source – Absorption of CO2 from pneumoperitoneum.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 3 - A 68-year old man, is admitted in hospital. He is scheduled to undergo...

    Incorrect

    • A 68-year old man, is admitted in hospital. He is scheduled to undergo a femoro-popliteal bypass graft, for which he has been administered a spinal-epidural anaesthetic. Intrathecal heavy bupivacaine (0.5%) was injected at L3-4 with good effect. On insertion of the epidural catheter, he remained asymptomatic.

      During surgery, 5000 I.U. of IV heparin was given. The surgery is successful and required no epidural top-ups.

      Six hours later, he complains of a severe back pain with weakness in his lower limbs.

      What is the most important first step?

      Your Answer:

      Correct Answer: A full neurological examination to establish the nature of the problem

      Explanation:

      The most likely diagnosis is a spinal epidural haematoma, a neurological emergency. A full examination must be carried out to determine the nature of the neurological problem before conducting any investigations or imaging.

      The effects of spinal anaesthesia should have worn off by this time point, and the severe back pain is a red flag.

      The patient will also require an urgent neurological team referral as a spinal epidural haematoma requires immediate evacuation for spinal decompression. Analgesics may be prescribed for pain management.

      Heparin would have been fully metabolised and so a reversal is unnecessary.

      A spinal epidural haematoma is a pooling of blood in the epidural space, which can cause compression of the spinal cord. Its presenting symptoms are:

      Usually begins with severe backpain and percussion tenderness
      Cauda equina syndrome
      Paralysis of the lower extremities.
      If infected, a fever occurs in 66% of cases
      Lower limb weakness developing after stopping an epidural infusion or weakness of the lower limbs which does not resolve within four hours of cessation of infusion of epidural local anaesthetic
      Meningism.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 4 - Which of the following intravenous induction agents is best for the patient with...

    Incorrect

    • Which of the following intravenous induction agents is best for the patient with acute intermittent porphyria requiring rapid sequence induction for emergency surgery?

      Your Answer:

      Correct Answer: Propofol

      Explanation:

      Propofol is considered a safe drug to use in porphyria because even if causes mild elevation of porphyrins inpatient, it does not cause any symptoms.

      Since barbiturates are inducers of ALA synthetase, they are contraindicated in porphyria patients. So, thiopentone most not be used.

      Etomidate is a potent inhibitor of adrenal 11 beta-hydroxylase and 17 alpha-hydroxylase reducing cortisol and aldosterone synthesis in the adrenal cortex and has been associated with exacerbations of porphyria in animal studies and it is advisable not to use it in this condition.

      Ketamine should be reserved for the hemodynamically unstable patient, however, it is a safe drug.

      Diazepam is safe in porphyria but is not usually used for a rapid sequence induction.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 5 - Which of the following is the best marker of mast cell degranulation in...

    Incorrect

    • Which of the following is the best marker of mast cell degranulation in a patient with suspected anaphylaxis who became hypotensive and developed widespread urticarial rash after administration of Augmentin?

      Your Answer:

      Correct Answer: Tryptase

      Explanation:

      Mast cell tryptase is a reliable marker of mast cell degranulation. Tryptase is a protease enzyme that acts via widespread protease-activated receptors (PARs).

    • This question is part of the following fields:

      • Pharmacology
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  • Question 6 - Which of the following is not used in the treatment of Neuroleptic Malignant...

    Incorrect

    • Which of the following is not used in the treatment of Neuroleptic Malignant Syndrome?

      Your Answer:

      Correct Answer: Olanzapine

      Explanation:

      The neuroleptic malignant syndrome (NMS) is a rare complication in response to neuroleptic or antipsychotic medication.

      The main features are:
      – Elevated creatinine kinase
      – Hyperthermia and tachycardia
      – Altered mental state
      – Increased white cell count
      – Insidious onset over 1-3 days
      – Extrapyramidal dysfunction (muscle rigidity, tremor, dystonia)
      – Autonomic dysfunction (Labile blood pressure, sweating, salivation, urinary incontinence)

      Management is supportive of ICU care, anticholinergic drugs, increasing dopaminergic activity with Amantadine, L-dopa, and dantrolene, and non- depolarising neuromuscular blockade drugs.

      Since Olanzapine is a potential cause of NMS it is not a treatment.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 7 - A 42-year-old man presented with a bitemporal hemianopia with enlarged hands and feet....

    Incorrect

    • A 42-year-old man presented with a bitemporal hemianopia with enlarged hands and feet. On examination, he was found to be hypertensive.

      Which of the following correctly explains the cause of his visual field defect?

      Your Answer:

      Correct Answer: Pituitary macroadenoma secreting growth hormone (GH)

      Explanation:

      Pituitary macroadenoma is a benign tumour with growth larger than 10mm (those under 10mm are called microadenoma)

      Compression of optic chiasm by pituitary adenoma is responsible for causing visual field defects like bitemporal hemianopia, optic neuropathy.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 8 - Which of the following is incorrect with regards to atrial natriuretic peptide? ...

    Incorrect

    • Which of the following is incorrect with regards to atrial natriuretic peptide?

      Your Answer:

      Correct Answer: Secreted mainly by the left atrium

      Explanation:

      Atrial natriuretic peptide (ANP) is secreted mainly from myocytes of right atrium and ventricle in response to increased blood volume.
      It is secreted by both the right and left atria (right >> left).

      It is a 28 amino acid peptide hormone, which acts via cGMP
      degraded by endopeptidases.

      It serves to promote the excretion of sodium, lowers blood pressure, and antagonise the actions of angiotensin II and aldosterone.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 9 - A 70-year-old man presents with central crushing chest pain that radiates to the...

    Incorrect

    • A 70-year-old man presents with central crushing chest pain that radiates to the jaw in the emergency department. He has associated symptoms of nausea and diaphoresis.

      A 12 lead ECG is performed. ST-elevation is observed in leads V2-V4. The diagnosis of anteroseptal ST-elevation myocardial infarction is made.

      Which coronary vessel is responsible for this condition and runs in the interventricular septum on the anterior surface of the heart to reach the apex?

      Your Answer:

      Correct Answer: Left anterior descending artery

      Explanation:

      The heart receives blood supply from coronary arteries. The right and left coronary arteries branch off the aorta and supply oxygenated blood to all heart muscle parts.

      The left main coronary artery branches into:
      1. Circumflex artery – supplies the left atrium, side, and back of the left ventricle. The left marginal artery arises from the left circumflex artery. It travels along the obtuse margin of the heart.
      2. Left Anterior Descending (LAD) artery – supplies the front and bottom of the left ventricle and front of the interventricular septum

      The left anterior descending coronary artery is the largest coronary artery. It courses anterior to the interventricular septum in the anterior interventricular groove, extending from the base of the heart to its apex. Around the apex, the LAD anastomosis with the terminal branches of the posterior descending artery (branch of the right coronary artery).
      Atherosclerosis or thrombotic occlusion of LAD causes myocardial infarction in large areas of the anterior, septal, and apical portions of the heart muscle. It can lead to a serious deterioration in heart performance.

      Occlusion of the LAD causes anteroseptal myocardial infarction, which is evident on the ECG with changes in leads V1-V4. Occlusion of the left circumflex artery causes lateral, posterior, or anterolateral MI. However, as it does not run towards the apex in the interventricular septum of the heart, it is not the correct answer for this question.

      The right coronary artery branches into:
      1. Right marginal artery
      2. Posterior descending artery

      The right coronary artery supplies the right atrium, right ventricle, interatrial septum, and the inferior posterior third of the interventricular septum. Occlusion of the right coronary artery causes inferior MI, which is indicated on ECG with changes in leads II, III, and aVF.

    • This question is part of the following fields:

      • Anatomy
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  • Question 10 - A 4-year-old boy with status epilepticus was brought to ER and has already...

    Incorrect

    • A 4-year-old boy with status epilepticus was brought to ER and has already received two doses of intravenous lorazepam but is still continuing to have seizures.

      Which of the following drug would be best for his treatment?

      Your Answer:

      Correct Answer: Phenytoin 20 mg/kg IV

      Explanation:

      When the convulsion lasts for five or more than five minutes, or if there are recurrent episodes of convulsions in a 5 minute period without returning to the baseline, it is termed as Status Epilepticus.
      The first priority in the patient with seizures is maintaining the airway, breathing, and circulation.

      Guideline for the management of Status Epilepticus in children by Advanced Life Support Group is as follow:

      Step 1 (Five minutes after the start of seizures):

      If intravascular access is available start treatment with lorazepam 0.1 mg/kg IV
      If no intravascular access then give buccal midazolam 0.5 mg/kg or rectal diazepam 0.5 mg/kg.

      Step 2 (Ten minutes after the start of seizure):

      If the convulsions continue then a second dose of benzodiazepine should be given. Senior should be called on-site and phenytoin should be prepared.
      No more than two doses or benzodiazepines should be given (including any doses given before arrival at the hospital)
      If still no IV access then obtain intraosseous access (IO).

      Step 3 (Ten minutes after step 2)

      Senior help along with anaesthetic/ICU help should be sought
      Phenytoin 20 mg/kg IV over 20 minutes
      If the seizure stops before the full dose of phenytoin is given then the infusion should be completed as this provides up to 24 hours of anticonvulsant effect
      In children already receiving phenytoin as treatment for epilepsy then an alternative is phenobarbitone 20 mg/kg IV over five minutes
      Once the phenytoin is started, senior staff may wish to give rectal paraldehyde 0.4 mg/kg although this is no longer included in the routine algorithm recommended by APLS.

      Step 4 (20 minutes after step 3)

      If 20 minutes after starting phenytoin the child remains in status epilepticus then rapid sequence induction of anaesthesia with thiopentone and a short acting paralysing agent is needed and the child transferred to paediatric intensive care.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 11 - At which of the following location is there no physiological oesophageal constriction? ...

    Incorrect

    • At which of the following location is there no physiological oesophageal constriction?

      Your Answer:

      Correct Answer: Lower oesophageal sphincter

      Explanation:

      The oesophagus is a muscular tube that connects the pharynx to the stomach. It begins at the lower border of the cricoid cartilage and C6 vertebra. It ends at T11.

      The oesophagus has physiological constrictions at the following levels:
      1. Cervical constriction: Pharyngo-oesophageal junction (15 cm from the incisor teeth) produced by the cricopharyngeal part of the inferior pharyngeal constrictor muscle
      2. Thoracic constrictions:
      i. where the oesophagus is first crossed by the arch of the aorta (22.5 cm from the incisor teeth)
      ii. where the oesophagus is crossed by the left main bronchus (27.5 cm from the incisor teeth)
      3. Diaphragmatic constriction: where the oesophagus passes through the oesophageal hiatus of the diaphragm (40 cm from the incisor teeth)

      Awareness of these constrictions is important for clinical purposes when it is required to pass instruments through the oesophagus into the stomach or when viewing radiographs of patients’ oesophagus.

    • This question is part of the following fields:

      • Anatomy
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  • Question 12 - A 43-year-old patient was brought to the emergency department with a traumatic amputation...

    Incorrect

    • A 43-year-old patient was brought to the emergency department with a traumatic amputation of his leg at mid-thigh level. Resuscitation with 1 L gelofusine was done and four units of packed red blood cells were given before theatre. Thirty minutes following blood transfusion, the patient became flushed, breathless, hypotensive, develops haemoglobinuria, and had a fever of 38oC.

      Which one of the following correctly explains the patient signs and symptoms?

      Your Answer:

      Correct Answer: Activation of classic complement pathway

      Explanation:

      This may be the classical case of blood transfusion reaction due to ABO incompatibility.

      Here red cells are destroyed in the bloodstream with the release of haemoglobin in circulation (causing haemoglobinuria). Here, IgM or IgG anti-A or anti-B antibody can cause rapid activation of complement cascade usually the classical pathway. This is called intravascular haemolysis.

      There may be extravascular haemolysis by cells of the mononuclear phagocyte system situated in the liver and spleen. Extravascular red cell destruction can increase breakdown products of haemoglobin, such as bilirubin and urobilinogen.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 13 - A caudal anaesthetic block is planned for a 3-year-old girl presenting for inguinal...

    Incorrect

    • A caudal anaesthetic block is planned for a 3-year-old girl presenting for inguinal hernia repair. Choose the best answer that explains why the caudal epidural space is accessed via the sacral hiatus.

      Your Answer:

      Correct Answer: The failure of fusion of the laminae of S4 and S5 provides a suitable point of entry

      Explanation:

      The sacral hiatus is shaped by incomplete midline fusion of the posterior elements of the distal portion of S4 and S5. This inverted U shaped space is covered by the posterior aspect of the sacrococcygeal membrane and is an important landmark in caudal anaesthetic block. Distal most portion of the dural sac and the sacral hiatus usually terminate between levels S1 and S3. The dural sac ends at the level of S2 in adults and S3 in children.

      An equilateral triangle is formed between the apex of the sacral hiatus and the posterior superior iliac spines. This triangle is used to determine the location of the sacral hiatus during caudal anaesthetic block.

    • This question is part of the following fields:

      • Anatomy
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  • Question 14 - It was hypothesized that people that had lower socio economic status were more...

    Incorrect

    • It was hypothesized that people that had lower socio economic status were more prone to developing gastric cancer. After 30 years of studying people with lower socio economic status, it was found that they did have a greater tendency to develop cancer. As a result of that the authors got to the conclusion that a strong association existed between the two. Later on another study conducted found that people from lower socio economic back grounds also had a tendency to be smokers.


      Which form of potential bias can be associated with this particular study?

      Your Answer:

      Correct Answer: Confounding bias

      Explanation:

      Selection bias is when randomisation is not achieved and is often a result of in efficient recruiting method.

      Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.

      Measurement bias can be characterized by gathering of information in a manner that is distorted.

      When the participants of a research study are recruited from the hospitals rather than the general population, its called Berkson Bias.

      Confounding bias is the major player here because in this case the effects of smoking can be masked behind and can be read as outcomes of lower socio economic status. This extraneous factor (Smoking), distorts the founding.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 15 - A survey aimed at finding out mean glucose level in individuals that took...

    Incorrect

    • A survey aimed at finding out mean glucose level in individuals that took antipsychotics medicines was conducted. The results were as follows:

      Mean Value: 7mmol/L

      Standard Deviation: 6mmol/L

      Sample Size: 9

      Standard Error: 2mmol/L

      For a confidence interval of 95%, which of the option presents the correct range up to the nearest value?

      Your Answer:

      Correct Answer: 3-11 mmol/L

      Explanation:

      Key Point: While finding out confidence intervals, standard errors are used. Standard error and Standard deviation are two distinct entities and should not be confused.

      For 99.7% confidence interval, you can find the range as follows:

      Multiply the standard error by 3.

      Subtract the answer from mean value to get the lower limit.

      Add the answer obtained in step 1 from the mean value to get the upper limit.

      The range turns out to be 1-13 mmol/L.

      For a confidence interval of 68%, multiply the standard error with 1 and repeat the process. The range found for this interval is 3-11 mmol/L.

      For a 95% confidence interval. Standard Error is multiplied by 1.96 which gives us the limit ranging from 3.08 to 10.92 mmol/L which could be approximated to 3-11 mmol/L.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 16 - Which of the following is a correct match for reflex and their root...

    Incorrect

    • Which of the following is a correct match for reflex and their root value?

      Your Answer:

      Correct Answer: Knee reflex: L3/L4

      Explanation:

      Reflexes are a routine part of clinical examination. Hyperreflexia (abnormally brisk reflexes) is the sign of upper motor neuron damage whereas diminished or absent jerks are most commonly due to lower motor neuron lesions. Reflexes may be Monosynaptic (deep tendon reflexes) or polysynaptic (superficial reflexes)

      Here are deep tendon reflexes with their nerve root
      Biceps = C5, C6
      Supinator (Brachioradialis) = C5, C6
      Triceps = C6, C7
      Knee reflex = L3,L4
      Ankle reflex = S1

      Polysynaptic superficial reflexes with their nerve root are listed below
      Planter response = S1-2
      Abdominal reflexes = T8-12
      Cremasteric reflex = L1-2

    • This question is part of the following fields:

      • Anatomy
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  • Question 17 - Prophylactic antibiotics are required for which of the following procedures? ...

    Incorrect

    • Prophylactic antibiotics are required for which of the following procedures?

      Your Answer:

      Correct Answer: Caesarean section

      Explanation:

      Staphylococcus aureus infection is the most likely cause.

      Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.

      SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
      The organisms are usually derived from the patient’s own body.

      Measures that may increase the risk of SSI include:
      -Shaving the wound using a single use electrical razor with a disposable head
      -Using a non iodine impregnated surgical drape if one is needed
      -Tissue hypoxia
      -Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.

      Measures that may decrease the risk of SSI include:
      1. Intraoperatively
      – Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
      -Cover surgical site with dressing

      In contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.

      2. Post operatively
      Tissue viability advice for management of surgical wounds healing by secondary intention

      Use of diathermy for skin incisions
      In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 18 - Following an acute appendicectomy, a 6-year-old child is admitted to the recovery unit.

    Your...

    Incorrect

    • Following an acute appendicectomy, a 6-year-old child is admitted to the recovery unit.

      Your consultant has requested that you prescribe maintenance fluids for the next 12 hours. The child is 21 kg in weight.

      What is the most suitable fluid volume to be prescribed?

      Your Answer:

      Correct Answer: 732 ml

      Explanation:

      After a paediatric case, you’ll frequently have to calculate and prescribe maintenance fluids. The ‘4-2-1 rule’ should be used as a guideline:

      1st 10 kg – 4 ml/kg/hr
      2nd 10 kg – 2 ml/kg/hr
      Subsequent kg – 1 ml/kg/hr

      Hence

      1st 10 kg = 4 × 10 = 40 ml
      2nd 10 kg = 2 × 10 = 20 ml
      Subsequent kg = 1 × 1 = 1 ml
      Total = 61 ml/hr

      61 × 12 = 732 ml over 12 hrs.

    • This question is part of the following fields:

      • Physiology
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  • Question 19 - A 61-year-old woman, present to her general practitioner. She complains of a severe...

    Incorrect

    • A 61-year-old woman, present to her general practitioner. She complains of a severe lancinating pain in her forehead that only last a few seconds, possibly triggered by washing her face, occurring over the previous six weeks.

      On examination, she is normal with no other signs or symptoms.

      Which nerve is the most likely cause of her pain?

      Your Answer:

      Correct Answer: Sensory branches of the ophthalmic division of the trigeminal nerve

      Explanation:

      Her symptoms are suggestive of trigeminal neuralgia which is a short, sudden, severe sharp unilateral pain in the facial region. The pain often follows the sensory distribution of the trigeminal nerve (CN V).

      The trigeminal nerve gives rise to 3 sensory and 1 motor nuclei. Neuralgia can arise from any of the 3 sensory divisions.

      The ophthalmic division gives rise to 3 further sensory branches, which are the frontal, lacrimal and nasociliary.

      The frontal branch of the ophthalmic division of the trigeminal nerve is responsible for the innervation of the area in question.

      The superior alveolar dental, zygomatic and sphenopalatine nerves are all branches arising from the maxillary division of the trigeminal nerve.

      The mandibular division of the trigeminal nerve provides sensory and motor innervation. The sensory innervation is carried out by the auriculotemporal nerve which supplies the lower third of the face, while the motor fibres are responsible for controlling the muscles of mastication.

      The somatic sensory branches of the vagus nerve are responsible for sensory innervation of the external acoustic meatus and tympanic membrane.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 20 - An 85-year old female is being investigated and treated for pancytopenia of unknown...

    Incorrect

    • An 85-year old female is being investigated and treated for pancytopenia of unknown origin. Her most recent blood test is shown below which shows that he has a low platelet count.

      Hb-102 g/l
      WBC - 2.9* 109/l
      Platelets - 7 * 109/l

      Which of the following normally stimulates platelet production?


      Your Answer:

      Correct Answer: Thrombopoietin

      Explanation:

      Interleukin-4 is a cytokine which acts to regulate the responses of B and T cells.

      Erythropoietin is responsible for the signal that initiated red blood cell production.

      Granulocyte-colony stimulating factor stimulates the bone marrow to produce granulocytes.

      Interleukin-5 is a cytokine that stimulates the proliferation and activation of eosinophils.

      Thrombopoietin is the primary signal responsible for megakaryocyte and thus platelet production.
      Platelets are also called thrombocytes. They, like red blood cells, are also derived from myeloid stem cells. The process involves a megakaryocyte developing from a common myeloid progenitor cell. A megakaryocyte is a large cell with a multilobulated nucleus, this grows to become massive where it will then break up to form platelets.

      Immune cells are generated from haematopoietic stem cells in bone marrow. They generate two main types of progenitors, myeloid and lymphoid progenitor cells, from which all immune cells are derived.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 21 - Which of the following statements about closing capacity is true? ...

    Incorrect

    • Which of the following statements about closing capacity is true?

      Your Answer:

      Correct Answer: It is less than the functional residual capacity in a 30-year-old

      Explanation:

      Closing capacity refers to volume of gas within the lungs at which the conducting small airways begin to close, that is, the point during expiration when small airways close.

      It is calculated mathematically as:

      Closing capacity = Closing volume (CV) + Residual volume (RV)

      Functional residual capacity (FRC) is the volume of gas still present within the lungs post expiration.

      Closing capacity is lower than the functional residual capacity in younger adults, but begins to rise to eventually equal, and then exceed it with increasing age (at about middle age), increasing intrabdominal pressure, decreasing blood flow in the pulmonary system and parenchymal disease within the pulmonary system.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 22 - Which of the given statements is true about standard error of the mean?...

    Incorrect

    • Which of the given statements is true about standard error of the mean?

      Your Answer:

      Correct Answer: Gets smaller as the sample size increases

      Explanation:

      The standard error of the mean (SEM) is a measure of the spread expected for the mean of the observations – i.e. how ‘accurate’ the calculated sample mean is from the true population mean. The relationship between the standard error of the mean and the standard deviation is such that, for a given sample size, the standard error of the mean equals the standard deviation divided by the square root of the sample size.

      SEM = SD / square root (n)

      where SD = standard deviation and n = sample size

      Therefore, the SEM gets smaller as the sample size (n) increases.

      If we want to depict how widely scattered some measurements are, we use the standard deviation. For indicating the uncertainty around the estimate of the mean, we use the standard error of the mean. The standard error is most useful as a means of calculating a confidence interval. For a large sample, a 95% confidence interval is obtained as the values 1.96×SE either side of the mean.

      A 95% confidence interval:

      lower limit = mean – (1.96 * SEM)

      upper limit = mean + (1.96 * SEM)

      Results such as mean value are often presented along with a confidence interval. For example, in a study the mean height in a sample taken from a population is 183cm. You know that the standard error (SE) (the standard deviation of the mean) is 2cm. This gives a 95% confidence interval of 179-187cm (+/- 2 SE).

      Hence, it would be wrong to say that confidence levels do not apply to standard error of the mean.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 23 - The average diastolic blood pressure of a control group was found out to...

    Incorrect

    • The average diastolic blood pressure of a control group was found out to be 80 with a standard deviation of 5 in a study aimed at exploring the efficiency of a novel anti-hypertensive drug. The trial was randomised.

      Making an assumption that the data is normally distributed, find out the number of patients that had diastolic blood pressure over 90.

      Your Answer:

      Correct Answer: 3%

      Explanation:

      Since the data is normally distributed, 95% of the values lie with in the interval 70 to 90. This can be calculated as follows:

      Interval= Mean ± ( 2 times standard deviation)
      = 80 ± 2(5)
      = 80 ± 10
      = 70 & 90

      The rest of the 5% are distributed symmetrically beyond 90 and below 70 which means 2.5% of the values lie above 90.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 24 - Which of these statements regarding the basilar artery and its branches is not...

    Incorrect

    • Which of these statements regarding the basilar artery and its branches is not true?

      Your Answer:

      Correct Answer: The posterior inferior cerebellar artery is the largest of the cerebellar arteries arising from the basilar artery

      Explanation:

      The posterior inferior cerebellar artery is the largest branch arising from the distal portion of the vertebral artery which forms the basilar artery. It is one of the arteries responsible for providing blood supply to the brain’s cerebellum.

      The labyrinthine artery (auditory artery) is a long and slender artery which arises from the basilar artery and runs alongside the facial and vestibulocochlear nerves into the internal auditory meatus.

      The posterior cerebellar artery is one of two cerebral arteries supplying the occipital lobe with oxygenated blood. It is usually bigger than the superior cerebellar artery. It is separated from the vessel near its origin by the oculomotor nerve.

    • This question is part of the following fields:

      • Anatomy
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  • Question 25 - Regarding the classification of breathing systems, which of the following is true? ...

    Incorrect

    • Regarding the classification of breathing systems, which of the following is true?

      Your Answer:

      Correct Answer: The Conway classification describes a functional classification based on whether a CO2 absorber is required

      Explanation:

      Breathing system is an assembly of components which connects patient’s airway to anaesthesia machine through which controlled composition of gas mixture is dispensed. It delivers gas to the patient, removes expired gas and controls the temperature and humidity of the inspired mixture. It allows spontaneous, controlled, or assisted respiration. It may also provide ports for gas sampling, airway pressure, flow and volume monitoring.

      Breathing systems have been classified by Conway and Mapleson.
      Conway suggested a functional classification:
      – Circuits requiring a CO2 absorber
      – Circuits not requiring a CO2 absorber

      William Mapleson designated varying arrangements of breathing system components (masks, breathing tubes, fresh gas flow inlets, adjustable pressure-limiting valves, and reservoir bags) as Mapleson A-E circuits.
      Mapleson A: Arranged as FGF inlet, reservoir bag, APL valve, mask.
      In this circuit, because the reservoir bag is between the FGF inlet valve and the APL valve, expired gas from the patient may re-enter the system and fill the reservoir bag during controlled ventilation. This is the most efficient system for spontaneous breathing as the FGF must only be equal to a patient’s minute ventilation to prevent rebreathing.

      Mapleson B: Arranged as reservoir bag, FGF inlet, APL valve, mask.
      In this circuit, the FGF inlet is closer to the APL valve, which helps prevent the rebreathing concern in the Mapleson A circuit as above during controlled ventilation.

      Mapleson C: Arranged as reservoir bag, FGF inlet, APL valve, mask.
      In this circuit, the arrangement is the same as the Mapleson B circuit. However, this circuit is shorter as it does not contain elongated corrugated tubing. This circuit also has the FGF inlet close to the APL valve to aid in preventing rebreathing.

      Mapleson D: Arranged as reservoir bag, APL valve, FGF inlet, and mask.
      In this circuit, the arrangement interchanges the FGF inlet and APL valve of the Mapleson A circuit. This system prevents rebreathing by directing FGF towards the APL valve rather than towards the patient during exhalation.

      Mapleson E: Arranged as corrugated tubing, FGF inlet, and mask.
      In this circuit, there is no reservoir bag and no APL valve. Given the inability to alter the pressure of the circuit, this is ideal for spontaneously ventilating neonates or paediatric patients where low-pressure ventilation is desired. The system prevents rebreathing, similar to the Mapleson D circuit.

      Jackson Rees later modified the Mapleson E by adding an open ended bag, which has since become known as the Mapleson F.
      Mapleson F: Arranged as APL valve directly connected to reservoir bag, corrugated tubing, FGF inlet, and mask.
      The system prevents rebreathing similarly to Mapleson D by directing FGF towards the APL valve.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 26 - A 65-year-old man got operated on for carotid endarterectomy for his carotid artery...

    Incorrect

    • A 65-year-old man got operated on for carotid endarterectomy for his carotid artery disease. He is recovering well post-surgery. However, on follow-up in the ward, he has hoarseness of his voice.

      Which of the following explains the hoarseness?

      Your Answer:

      Correct Answer: Damage to the vagus

      Explanation:

      During carotid endarterectomy, injury to the vagus nerve or its branches can cause hoarseness. Injury to the vagus nerve can result in adductor vocal cord paralysis. It can also cause other symptoms like dysphagia or even vocal cord immobility.

      Carotid endarterectomy is the procedure to relieve an obstruction in the carotid artery by opening the artery at its origin and stripping off the atherosclerotic plaque with the intima. Because of the internal carotid artery relations, there is a risk of cranial nerve injury during the procedure involving one or more of the following nerves: CN IX, CN X (or its branch, the superior laryngeal nerve), CN XI, or CN XII.

      However, only damage to the vagus would account for speech difficulties.

    • This question is part of the following fields:

      • Anatomy
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  • Question 27 - The pharmacologically inactive precursor of barbiturates is Barbituric acid. Because the molecule is...

    Incorrect

    • The pharmacologically inactive precursor of barbiturates is Barbituric acid. Because the molecule is heterocyclic, small structural changes can alter its pharmacological activity (structure function relationship).

      Which of the following modifications to the molecule has the greatest impact on the effectiveness of the barbiturate derivative?

      Your Answer:

      Correct Answer: Sulphur at C2

      Explanation:

      Barbituric acid is the barbiturates’ pharmacologically inactive precursor. A pyrimidine heterocyclic nucleus is formed by the condensation of urea and malonic acid. Its pharmacological activity can be influenced by minor structural changes (structure function relationship).

      The duration of action and potency as a sedative are influenced by the length of the side chains at C5. Barbiturates with three carbon atoms in their chain last longer than those with two. Anticonvulsant properties are enhanced by branched chains.

      The addition of a methyl group at N1 causes a faster onset/offset of action, but it also causes excitatory phenomena (twitching/lower convulsive threshold).

      The addition of oxygen and sulphur to C2 increases the molecule’s lipid solubility and thus its potency. Thiopentone (thiobarbiturate) has sulphur groups at C2, making it 20-200 times more lipid soluble than oxybarbiturates.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 28 - Which of the following antibiotics inhibits protein synthesis in bacteria? ...

    Incorrect

    • Which of the following antibiotics inhibits protein synthesis in bacteria?

      Your Answer:

      Correct Answer: Erythromycin

      Explanation:

      Erythromycin binds to the 50s subunit of bacterial rRNA complex and inhibits protein synthesis.

      Vancomycin binds to the acyl-D-ala-D-ala portion of the growing cell wall in a susceptible gram-positive bacterium. After binding, it prevents the cell wall from forming the cross-linking.

      Trimethoprim binds to dihydrofolate reductase and inhibits the reduction of dihydrofolic acid to tetrahydrofolic acid. Tetrahydrofolic acid is an essential precursor in the thymidine synthesis pathway and interference with this pathway inhibits bacterial DNA synthesis.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 29 - A 49-year-old woman is admitted to hospital. She is scheduled for surgery and...

    Incorrect

    • A 49-year-old woman is admitted to hospital. She is scheduled for surgery and is undergoing preoperative assessment.

      As part of the preoperative assessment, her functional capacity is estimated. At 50kg in weight, she is able to cycle along a flat surface at a speed of 10-14 miles/hour (8 metabolic equivalents or METs).

      Provide the best estimated value of oxygen consumption (VO2) for eight METs.

      Your Answer:

      Correct Answer: 1400 mL/minute

      Explanation:

      Oxygen consumption (VO2) refers to the optimal amount of oxygen used by the body during exercise.

      It is calculated mathematically by:

      VO2 = 3.5 x 50 x 8 = 1400 mL/kg/minute

      where,

      1 MET = 3.5 mL O2/kg/minute is utilized by the body.

      Note:

      1 MET Eating
      Dressing
      Use toilet
      Walking slowly on level ground at 2-3 mph
      2 METs Playing a musical instrument
      Walking indoors around house
      Light housework
      4 METs Climbing a flight of stairs
      Walking up hill
      Running a short distance
      Heavy housework, scrubbing floors, moving heavy furniture
      Walking on level ground at 4 mph
      Recreational activity, e.g. golf, bowling, dancing, tennis
      6 METs Leisurely swimming
      Leisurely cycling along the flat (8-10 mph)
      8 METs Cycling along the flat (10-14 mph)
      Basketball game
      10 METs Moderate to hard swimming
      Competitive football
      Fast cycling (14-16 mph)

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 30 - The leading cause of perioperative anaphylaxis per hundred thousand administrations is? ...

    Incorrect

    • The leading cause of perioperative anaphylaxis per hundred thousand administrations is?

      Your Answer:

      Correct Answer: Teicoplanin

      Explanation:

      The leading cause of perioperative anaphylaxis in the UK currently are antibiotics. They account for 46% of cases with identified causative agents. Co-amoxiclav and teicoplanin between them account for 89% of antibiotic-induced perioperative anaphylaxis

      Neuromuscular blocking agents (NMBAs) are the second leading cause and account for 33% of case.

      Chlorhexidine (0.78/100,000 administrations)
      Co-amoxiclav (8.7/100,000 administrations)Suxamethonium (11.1/100,000 administrations)
      Patent blue dye (14.6/100,000 administrations)
      Teicoplanin (16.4/100,000 administrations)

      Anaphylaxis to chlorhexidine periop poses a significant risk in the healthcare setting because of its widespread use with some being fatal.

    • This question is part of the following fields:

      • Pharmacology
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