00
Correct
00
Incorrect
00 : 00 : 00
Session Time
00 : 00
Average Question Time ( Mins)
  • Question 1 - Which of the following drugs is an enzyme inducer? ...

    Correct

    • Which of the following drugs is an enzyme inducer?

      Your Answer: Rifampicin

      Explanation:

      Rifampicin is a potent inducer of liver cytochrome enzymes. Other enzyme inducers are:
      Carbamazepine
      Sodium valproate
      Phenytoin
      Phenobarbitone

    • This question is part of the following fields:

      • Pharmacology
      15.6
      Seconds
  • Question 2 - Among the following options, which one can not be the value of Pearson's...

    Correct

    • Among the following options, which one can not be the value of Pearson's correlation coefficient?

      Your Answer: 1.5

      Explanation:

      The correlation coefficient gives us the idea about relation between two parameters. i.e. to what extent change in parameter A could prompt a change in parameter B. The numerical value of correlation coefficient could not be greater than 1.

    • This question is part of the following fields:

      • Statistical Methods
      313.1
      Seconds
  • Question 3 - Comparing pressure-volume curves in patients during an asthma attack with that of healthy...

    Incorrect

    • Comparing pressure-volume curves in patients during an asthma attack with that of healthy subjects.

      The increased resistive work of breathing in the patients with asthma is best indicated by?

      Your Answer: Slope of the inspiratory limb is initially less steep

      Correct Answer: Larger hysteresis loop

      Explanation:

      A major source of caloric expenditure and oxygen consumption in the body is work of breathing (WOB) and 70% of this is to overcome elastic forces. The remaining 30% is for flow-resistive work

      In a normal patient breathing normally, the total area of hysteresis pressure volume curve represents the flow-resistive WOB.

      The area of the expiratory resistive work increases during an asthma attack making the compliance curve larger in area. The larger the area the greater the work required to breathe.

    • This question is part of the following fields:

      • Physiology
      1066.2
      Seconds
  • Question 4 - A 89-year old male has hypertension, with a blood pressure of 170/68 mmHg...

    Correct

    • A 89-year old male has hypertension, with a blood pressure of 170/68 mmHg and has been admitted to the hospital. He is on no regular medications. His large pulse pressure can be accounted for by which of the following?

      Your Answer: Reduced aortic compliance

      Explanation:

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume

    • This question is part of the following fields:

      • Physiology And Biochemistry
      17.8
      Seconds
  • Question 5 - Which of the following can be measured directly using spirometry? ...

    Correct

    • Which of the following can be measured directly using spirometry?

      Your Answer: Vital capacity

      Explanation:

      Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).

      It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.

      During spirometry, the following measurements can be determined:
      Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
      Forced expiratory volume in one second (FEV1)
      FEV1/FVC ratio
      Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
      Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
      Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.

      Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.

      Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution

      The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.

    • This question is part of the following fields:

      • Clinical Measurement
      13.9
      Seconds
  • Question 6 - A 64-year-old man is admitted to the critical care unit. He has a...

    Incorrect

    • A 64-year-old man is admitted to the critical care unit. He has a recent medical history of faecal peritonitis for which a laparotomy was performed. His vitals have been monitored using an invasive pulmonary artery flotation catheter.

      His vital readings are:

      Temperature: 38.1°C
      Blood pressure: 79/51 mmHg (mean 58 mmHg)
      Pulmonary artery pressure: 19/6 mmHg (mean 10 mmHg)
      Pulmonary capillary occlusion pressure: 5 mmHg
      Central venous pressure: 12 mmHg
      Cardiac output: 5 L/min
      Mixed venous oxygen saturation: 82%

      Calculate his approximate pulmonary vascular resistance.

      Note: A correction factor of 80 is require to convert mmHg to dynes·s·cm-5

      Your Answer: 40 dynes·s·cm-5

      Correct Answer: 80 dynes·s·cm-5

      Explanation:

      Pulmonary vascular resistance (PVR) refers to the resistance to blood flow to the left atrium from the pulmonary artery.
      It is derived mathematically by:

      PVR = MPAP – PCWP
      CO
      where,
      MPAP: Mean pulmonary artery pressure
      PCWP: Pulmonary capillary occlusion pressure
      CO: Cardiac output

      For this patient:
      PVR = 10 – 5 = 1mmHg
      5

      Remember, multiply by correction factor 80 to change units:

      PVR = 1mmHg x 80 = 80 dynes·s·cm-5

      Normal values range between 20-130 dynes·s·cm-5

    • This question is part of the following fields:

      • Clinical Measurement
      5288.8
      Seconds
  • Question 7 - A 60-year-old man had previously been diagnosed with Type 2 diabetes. He had...

    Incorrect

    • A 60-year-old man had previously been diagnosed with Type 2 diabetes. He had recently started gliclazide, a sulphonyl urea, as his diabetes was not controlled by metformin alone.

      Now, he presents to his physician with complaints of anxiety, sweating, and palpitations since the morning. On physical examination, he is pale and clammy and has mydriasis and increased bowel sounds.

      Which biological site primarily synthesizes the hormone responsible for this patient's condition?

      Your Answer: Follicular cells of the thyroid gland

      Correct Answer: Chromaffin cells of the adrenal medulla

      Explanation:

      This patient has been shifted to a sulfonylurea drug whose most common side effect is hypoglycaemia. Similar symptoms can arise in a patient on insulin too. The signs and symptoms are consistent with a hypoglycaemic attack and include tachycardia, altered consciousness, and behaviour. This needs to be treated as an emergency with rapid correction of the blood glucose level using glucose or IV 20% dextrose.

      In a hypoglycaemic attack, the body undergoes stress and releases hormones to increase blood glucose levels. These include:
      Glucagon
      Cortisol
      Adrenaline

      Adrenaline or epinephrine is the hormone responsible for this patient’s condition and is primarily produced in the medulla of the adrenal gland. It functions primarily to raise cardiac output and raise blood glucose levels in the blood.

      Alpha-cells of the islets of Langerhans produce the hormone glucagon, which has opposing effects to insulin.

      Follicular cells of the thyroid gland produce and secrete thyroid hormones. Thyroid hormones can cause similar symptoms, but it is unlikely with the patient’s medical history.

      Post-ganglionic neurons of the sympathetic nervous system use norepinephrine as a neurotransmitter. Adrenaline can be made in these cells, but it is not their primary production site.

      Zona fasciculata of the adrenal cortex is the main site for the production of cortisol.

    • This question is part of the following fields:

      • Anatomy
      230
      Seconds
  • Question 8 - Which of the following statement is true regarding hypoxic pulmonary vasoconstriction (HPV)? ...

    Correct

    • Which of the following statement is true regarding hypoxic pulmonary vasoconstriction (HPV)?

      Your Answer: 20 parts per million (ppm) of nitric oxide will reduce hypoxic pulmonary vasoconstriction

      Explanation:

      Hypoxic Pulmonary vasoconstriction (HPV) reflects the constriction of small pulmonary arteries in response to hypoxic alveoli (.i.e.; PO2 below 80-100mmHg or 11-13kPa).

      These blood vessels become independent of the nerve stimulus, when blood with a high PO2 flows through the lung which contains a low alveolar PO2.

      Thus a low PO2 within the alveoli has been shown to impact on hypoxic pulmonary vasoconstriction (HPV) more than a low PO2 within the blood.

      HPV results in the blood flow being directed away from poorly ventilated areas of the lung and helps to reduce the ventilation/perfusion mismatch (not increase).

      In animals, volatile anaesthetic agents can diminish HPV, while in adults, the evidence proves less persuading, in spite of the fact that it certainly doesn’t strengthen the effects.

      HPV response will be suppressed by 20 parts per million (ppm) of nitric oxide.

    • This question is part of the following fields:

      • Physiology
      13.9
      Seconds
  • Question 9 - Which of the following is included in monosynaptic reflexes? ...

    Incorrect

    • Which of the following is included in monosynaptic reflexes?

      Your Answer: The cremasteric reflex.

      Correct Answer: The patellar or knee jerk reflex.

      Explanation:

      Monosynaptic reflexes is a type of reflex arc providing direct communication between motor and sensory innervation in a muscle. It occurs very quickly as it arises and ends in the same muscle. Examples include: biceps reflex, brachioradialis reflex, extensor digitorum reflex, triceps reflex, Achilles reflex and patellar reflex.

      Polysynaptic reflexes facilitates contraction and inhibition in muscle by providing communication between multiple muscles.

    • This question is part of the following fields:

      • Pathophysiology
      2186.9
      Seconds
  • Question 10 - An 85-year old female is being investigated and treated for pancytopenia of unknown...

    Incorrect

    • An 85-year old female is being investigated and treated for pancytopenia of unknown origin. Her most recent blood test is shown below which shows that he has a low platelet count.

      Hb-102 g/l
      WBC - 2.9* 109/l
      Platelets - 7 * 109/l

      Which of the following normally stimulates platelet production?


      Your Answer: Interleukin-5

      Correct Answer: Thrombopoietin

      Explanation:

      Interleukin-4 is a cytokine which acts to regulate the responses of B and T cells.

      Erythropoietin is responsible for the signal that initiated red blood cell production.

      Granulocyte-colony stimulating factor stimulates the bone marrow to produce granulocytes.

      Interleukin-5 is a cytokine that stimulates the proliferation and activation of eosinophils.

      Thrombopoietin is the primary signal responsible for megakaryocyte and thus platelet production.
      Platelets are also called thrombocytes. They, like red blood cells, are also derived from myeloid stem cells. The process involves a megakaryocyte developing from a common myeloid progenitor cell. A megakaryocyte is a large cell with a multilobulated nucleus, this grows to become massive where it will then break up to form platelets.

      Immune cells are generated from haematopoietic stem cells in bone marrow. They generate two main types of progenitors, myeloid and lymphoid progenitor cells, from which all immune cells are derived.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      17
      Seconds
  • Question 11 - The thyroid gland: ...

    Incorrect

    • The thyroid gland:

      Your Answer: Is closely related to the internal carotid artery

      Correct Answer: Internalises iodine through active transport

      Explanation:

      The thyroid gland is a gland shaped like a butterfly which lies at the base of the anterior neck. It controls metabolism using hormone secretion.

      Iodine is extremely important for the synthesis of hormones within the thyroid. It is internalised into the thyroid follicular cells via the sodium/iodide symporter (NIS).

      The parathyroid glands are found posterior to the thyroid gland, with the recurrent laryngeal nerves running posteromedially.

      The expected weight of a normal thyroid gland is about 30 grams.

    • This question is part of the following fields:

      • Pathophysiology
      1411.3
      Seconds
  • Question 12 - A 68-year-old woman is a known case of acute myeloid leukaemia and was...

    Incorrect

    • A 68-year-old woman is a known case of acute myeloid leukaemia and was treated with chemotherapy as a child. She now presents in casualty, and you are called in to attend this patient as it is getting difficult to gain vascular access in her arms. The medical registrar asks you to site a cannula during the arrest call as intraosseous access is delayed. The intern wants to assist you in performing a venous cutdown of one of the veins in the patients ankle that passes anterior to the medial malleolus. Which vessel is this?

      Your Answer:

      Correct Answer: Long saphenous vein

      Explanation:

      Venous cutdown is a surgical procedure when venous access is difficult, and other procedures like the Seldinger technique, ultrasound-guided venous access, and intraosseous vascular access have failed.

      The vein of choice for venous cutdown is the long/great saphenous vein. It is part of the superficial venous collecting system of the lower extremity. It is the preferred vein as the long saphenous vein has anatomic consistency and is superficially located at the ankle anterior to the medial malleolus. It is also the most commonly used conduit for cardiovascular bypass operations.

      Origin- in the foot at the confluence of the dorsal vein of the first digit and the dorsal venous arch of the foot
      Route- runs ANTERIOR to the medial malleolus and travels up in the medial leg and upper thigh.
      Termination: in the femoral vein within the femoral triangle

      Regarding the other options:
      The short saphenous vein passes posterior to the lateral malleolus.
      The dorsalis pedis vein accompanies the dorsalis pedis artery on the anterior foot.
      The posterior tibial vein is part of the deep venous system accompanying the posterior tibial artery. There is no significant sural vein (there is a sural nerve), but the sural veins accompany the sural arteries and drain to the popliteal vein.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 13 - Buffers are solutions that resist a change in pH when protons are produced...

    Incorrect

    • Buffers are solutions that resist a change in pH when protons are produced or consumed. They consist of weak acids and their conjugate bases. Buffers are also present in our bodies, and they are known as physiologic buffers.

      Which of these is the most effective buffer in the blood?

      Your Answer:

      Correct Answer: Bicarbonate

      Explanation:

      The first line of defence against acid-base disorder is buffering. The blood mainly utilizes bicarbonate ion (HCO3-) for its buffering capacity (total of 53%, plasma and red blood cells combined).

      Strong acids, when acted upon by a buffer, release H+, which then combines to HCO3- and forms carbonic acid (H2CO3). When acted upon by the enzyme carbonic anhydrase, H2CO3 dissociates into H2O and CO.

      The rest are the percentage of utilization for the following buffers:
      Haemoglobin (by RBCs) – 35%
      Plasma proteins (by plasma) – 7%
      Organic phosphates (by RBCs) – 3%
      Inorganic phosphates (by plasma) – 2%

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 14 - Lisa is a 75-year-old female rushed into the emergency department by first-aid responders....

    Incorrect

    • Lisa is a 75-year-old female rushed into the emergency department by first-aid responders. The ambulance team give a history of vomiting, homonymous hemianopia, weakness of the left upper and lower limb, and dysphasia. Lisa adds that she has a headache that keeps worsening.

      Lisa takes Warfarin as she is a known case of atrial fibrillation. Her INR is 4.3 despite the ideal target being 2-3.
      CT scan of the head suggests anterior cerebral artery haemorrhage.

      What areas of the brain are affected by an anterior cerebral artery stroke?

      Your Answer:

      Correct Answer: Frontal and parietal lobes

      Explanation:

      The anterior cerebral artery supplies the midline portion of the frontal lobe and the superior medial parietal lobe of the brain. It also supplies the front four-fifths of the corpus callosum and provides blood to deep structures such as the anterior limb of the internal capsule, part of the caudate nucleus, and the anterior part of the globus pallidus.

      The cerebral hemispheres are supplied by arteries that make up the Circle of Willis. The Circle of Willis is formed by the anastomosis of the two internal carotid arteries and two vertebral arteries.

      Clinically, the internal carotid arteries and their branches are often referred to as the anterior circulation of the brain. The anterior cerebral arteries are connected by the anterior communicating artery. Near their termination, the internal carotid arteries are joined to the posterior cerebral arteries by the posterior communicating arteries, completing the cerebral arterial circle around the interpeduncular fossa, the deep depression on the inferior surface of the midbrain between the cerebral peduncles.

      The middle cerebral artery supplies part of the frontal, temporal and parietal lobes.

      The posterior cerebral artery supplies the occipital lobe.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 15 - At sea level, Sevoflurane is administered via a plenum vaporiser. 100 mL of...

    Incorrect

    • At sea level, Sevoflurane is administered via a plenum vaporiser. 100 mL of the fresh gas flow is bypassed into the vaporising chamber. Temperature within the vaporising chamber is maintained at 20°C.

      The following fresh gas flows approximates best for the delivery of 1% sevoflurane.

      Your Answer:

      Correct Answer: 2.7 L/minute

      Explanation:

      The equation for calculating vaporiser output is:

      Vaporiser output (VO) mL = Carrier gas flow (mL/minute) × SVP of agent (kPa)
      Ambient pressure (kPa) − SVP of agent (kPa)

      The saturated vapour pressure of sevoflurane at 1 atm (100 kPa) and 20°C is 21 kPa.

      VO = (100 mL × 21 kPa)/(100 kPa − 21kPa) for sevoflurane,
      VO = 26.6 mL

      26.6 mL of 100% sevoflurane and 100 mL bypass carrier gas is being added to the fresh gas flow per minute.

      2660 mL of 1% sevoflurane and 100 mL bypass carrier gas is approximately 2.7 L/minute.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 16 - The incidence and prevalence of a diabetes in a locality are being measured...

    Incorrect

    • The incidence and prevalence of a diabetes in a locality are being measured by a health care professional. This is what he found:


      Year People with Diabetes New Cases
      2017 150,000 2000
      2018 150,000 4000


      What can be stated regarding the incidence and prevalence of the disease in that area?

      Your Answer:

      Correct Answer: Incidence increasing, prevalence equal

      Explanation:

      Incidence tells us about the number of new cases that have been reported while prevalence gives us the idea of existing cases.

      In this particular instance, the parameter of the study i.e. the total number of cases has not changed thus the prevalence of the disease remains same. Although, more cases have been reported in the second instance as a result of which incidence has increased.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 17 - Regarding the Manley MP3 ventilator, which statement is true? ...

    Incorrect

    • Regarding the Manley MP3 ventilator, which statement is true?

      Your Answer:

      Correct Answer: Is a minute volume divider

      Explanation:

      It’s a minute volume divider – True
      The Manley MP3 ventilator is classed as a minute volume divider. The entire fresh gas flow or minute volume is delivered to the patient, having been divided into readily set tidal volumes.

      Can efficiently ventilate patients with poor pulmonary compliance – False
      Ventilating patients with poor pulmonary compliance is not easily achieved, which makes it an unsuitable ventilator for a modern ICU.

      Can generate tidal volume up to 1500ml – False
      It can generate tidal volumes up to 1000 ml (not 1500 ml), and the inflation pressure can be adjusted by sliding a weight along a rail.

      Functions like a Mapleson A system during spontaneous ventilation – False
      The ventilator functions like a Mapleson D breathing system (not Mapleson A) during spontaneous ventilation.

      Has three sets of bellows – False
      The fresh gas flow drives the ventilator which allows rapid detection of gas supply failure. It has two sets of bellows (not three) and three unidirectional valves.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 18 - Following an uneventful laparoscopic right hemicolectomy, a previously fit and well 75-year-old male...

    Incorrect

    • Following an uneventful laparoscopic right hemicolectomy, a previously fit and well 75-year-old male is admitted to the critical care unit.

      You've been summoned to examine the patient because he's become oliguric.

      Which of the following is most likely to indicate that acute kidney injury is caused by a prerenal cause?

      Your Answer:

      Correct Answer: Serum urea: creatinine ratio 200

      Explanation:

      Prerenal failure has a serum urea: creatinine ratio of >100, while acute kidney injury has a ratio of 40.
      In prerenal failure, ADH levels are typically high, resulting in water, urea, and sodium resorption. The fractional sodium excretion is less than 1%, but it is greater than 2% in acute tubular necrosis.
      Prerenal azotaemia has higher serum urea nitrogen/serum creatinine ratios (>20), whereas acute tubular necrosis has lower ratios (10-15). The normal range is between 12 and 20.
      Urinary sodium is less than 20 in prerenal failure and greater than 40 in acute tubular necrosis.
      Prerenal failure has a urine osmolality of >500, while acute tubular necrosis has an osmolality of 350.
      Prerenal failure has a urine/serum creatinine ratio of >40, while acute tubular necrosis has a urine/serum creatinine ratio of 20.

      The concentrations of serum urea or creatinine change in inverse proportion to glomerular filtration. Changes in serum creatinine concentrations are more reliable than changes in serum urea concentrations in predicting GFR. Creatinine is produced at a constant rate from creatine, and blood concentrations are almost entirely determined by GFR.

      A number of factors influence urea formation, including liver function, protein intake, and protein catabolism rate. Urea excretion is also influenced by hydration status, the amount of water reabsorption, and GFR.

      A high serum creatinine level, as well as a urine output of less than 10 mL/hour and the production of concentrated looking urine, do not necessarily indicate a specific cause of oliguria.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 19 - A 40-year old female comes to the GP's office with unexplained weight gain,...

    Incorrect

    • A 40-year old female comes to the GP's office with unexplained weight gain, cold intolerance and fatigue. Her thyroid function tests are performed as there is a suspicion of hypothyroidism. A negative feedback mechanism is incorporated in the control of thyroid hormone release. All of choices below are also controlled by a negative feedback loop except:

      Your Answer:

      Correct Answer: Clotting cascade

      Explanation:

      The correct answer is the clotting cascade, which occurs via a positive feedback mechanism. As clotting factors are attracted to a site, their presence attracts further clotting factors. This continues until a functioning clot is formed.

      This patient has presented with symptoms of hypothyroidism and symptoms include weight gain, lethargy, cold intolerance, dry skin, coarse hair and constipation. It can be treated by replacing the missing thyroid hormone with levothyroxine which is a synthetic version of thyroxine (T4).

      Serum carbon dioxide (CO2) is controlled via a negative feedback mechanism as well. Chemoreceptors can detect when the serum CO2 is high, and send an impulse to the respiratory centre of the brain to increase the respiratory rate. As a result, more CO2 is exhaled which lowers the serum concentration.

      Cortisol is also released according to a negative feedback mechanism. Cortisol acts on both the hypothalamus and the anterior pituitary. Its action serve to decrease the formation of corticotrophin releasing hormone (CRH) and adrenocorticotropic hormone (ACTH), respectively. CRH acts on the anterior pituitary to release ACTH. This then acts on the adrenal gland to cause the release of cortisol. Thus, inhibition of CRH and ACTH formation results in high levels of cortisol which inhibit its further release.

      Blood pressure (BP) is controlled via a negative feedback mechanism. Low BP results in renin-angiotensin-aldosterone system (RAAS) activation. This leads to vasoconstriction and retention of salt and water which increased BP.
      Blood sugar is controlled via a negative feedback mechanism. A rise in blood sugar causes insulin to be released. Insulin acts to transport glucose into the cell which lowers blood sugar.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 20 - A 25-year old male with palpitations and dizziness presents to the emergency room....

    Incorrect

    • A 25-year old male with palpitations and dizziness presents to the emergency room. In the triage process, cardiac monitoring shows supraventricular tachycardia with a heart rate of 200 beats per minute. This high heart rate arises as a result of different specialised cells and nerve fibres in the heart which are responsible for conducting that action potential which is generated in the event of systole.
      The fastest conduction velocity is carried out by which of the following?

      Your Answer:

      Correct Answer: Purkinje fibres

      Explanation:

      The correct answer is the Purkinje fibres, which conducts at a velocity of about 4m/sec.

      The electrical conduction system of the heart starts with the SA node which generates spontaneous action potentials.

      This is conducted across both atria by cell to cell conduction, and occurs at around 1 m/s. The only pathway for the action potential to enter the ventricles is through the AV node in a normal heart.
      At this site, conduction is very slow at 0.05ms, which allows for the atria to completely contract and fill the ventricles with blood before the ventricles depolarise and contract.

      The action potentials are conducted through the Bundle of His from the AV node which then splits into the left and right bundle branches. This conduction is very fast, (,2m/s), and brings the action potential to the Purkinje fibres.

      Purkinje fibres are specialised conducting cells which allow for a faster conduction speed of the action potential (,2-4m/s). This allows for a strong synchronized contraction from the ventricle and thus efficient generation of pressure in systole.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 21 - The phenomenon that the patients behaved in a different manner when they know...

    Incorrect

    • The phenomenon that the patients behaved in a different manner when they know that they are being observed is termed as?

      Your Answer:

      Correct Answer: Hawthorne effect

      Explanation:

      Hawthorne effect explains the change in any behavioural aspect owing to the awareness that the person is being observed.
      Simpson’s Paradox explains the association developed when the data from several groups is combined to form a single larger group.

      The remaining terms are made up.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 22 - The Fick principle can be used to determine the blood flow to any...

    Incorrect

    • The Fick principle can be used to determine the blood flow to any organ of the body.

      At rest, which one of these organs has the highest blood flow (ml/min/100g)?

      Your Answer:

      Correct Answer: Thyroid gland

      Explanation:

      After the carotid body, the thyroid gland is the second most richly vascular organ in the body.

      The global blood flow to the thyroid gland can be measured using:
      1. Colour ultrasound sonography
      2. Quantitative perfusion maps using MRI of the thyroid gland using an arterial spin labelling (ASL) method.

      This table shows the blood flow to various organs of the body at rest:
      Organ Blood Flow(ml/minute/100g)
      Hepatoportal 58
      Kidney 420
      Brain 54
      Skin 13
      Skeletal muscle 2.7
      Heart 87
      Carotid body 2000
      Thyroid gland 560

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 23 - A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath...

    Incorrect

    • A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath and pleuritic chest pain. Her work requires her to travel internationally frequently. The consultant makes a diagnosis and treats her.

      Now, the consultant recommends placing a filter that will prevent future incidents. A needle is placed into the femoral vein and passed up into the abdomen to insert the filter.

      What is true regarding the organ where the filter is placed for this patient's condition?

      Your Answer:

      Correct Answer: It is located posteriorly to the peritoneum

      Explanation:

      The patient likely suffers from pulmonary embolism due to her history of frequent international travels. A filter is placed in the inferior vena cava to decrease the risk of future episodes of pulmonary embolism. The IVC filter is a small, wiry device that can catch blood clots and stop them from going into the heart and lungs. Your IVC is a major vessel that brings deoxygenated blood from the lower body to the heart, from where it is pumped into the lungs.

      The filter is placed via a thin catheter inserted into the femoral vein in the groin. The catheter is gently moved up into your IVC, and a filter is introduced.

      The IVC is a retroperitoneal organ.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 24 - A radical neck dissection is being performed. The ENT surgeon wishes to expose...

    Incorrect

    • A radical neck dissection is being performed. The ENT surgeon wishes to expose the external carotid artery fully. He inserts a self-retaining retractor close to the origin of the external carotid artery.

      What structure lies posterolaterally to the external carotid at this point?

      Your Answer:

      Correct Answer: Internal carotid artery

      Explanation:

      External carotid artery originates at the upper border of the thyroid cartilage. It ascends and lies anterior to the internal carotid arteries and posterior to the posterior belly of the digastric muscle and stylohyoid muscle.

      The external carotid artery has eight important branches:
      Anterior surface:
      1. Superior thyroid artery (first branch)
      2. Lingual artery
      3. Facial artery
      Medial branch
      4. Ascending pharyngeal artery
      Posterior branches
      5. Occipital artery
      6. Posterior auricular artery
      Terminal branches
      7. Maxillary artery
      8. Superficial temporal artery

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 25 - All of the following statements are false regarding propranolol except: ...

    Incorrect

    • All of the following statements are false regarding propranolol except:

      Your Answer:

      Correct Answer: Has a plasma half life of 3-6 hours.

      Explanation:

      Propranolol is a nonselective beta-blocker with a half-life of 3 to 6 hours.

      Since it is lipid-soluble it crosses the blood-brain barrier and causes Central Nervous System side effects like sedation, nightmares, and depression.

      They are contraindicated in asthma, Congestive heart failure, and diabetes.

      It has a large volume of distribution with no intrinsic sympathomimetic action.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 26 - One of two divisions of the autonomic nervous system is the sympathetic nervous...

    Incorrect

    • One of two divisions of the autonomic nervous system is the sympathetic nervous system. It is both anatomically and physiologically different from the parasympathetic nervous system.

      Which best describes the anatomical layout of the sympathetic nervous system?

      Your Answer:

      Correct Answer: Short myelinated preganglionic neurones from T1-L5 in lateral horns of grey matter of spinal cord, synapse in sympathetic ganglia (neurotransmitter - acetyl choline), long unmyelinated postganglionic neurones, synapse with effector organ (neurotransmitter - adrenaline or noradrenaline)

      Explanation:

      The autonomic nervous system is divided into the sympathetic and parasympathetic nervous system. They are anatomically and physiologically different.

      The sympathetic nervous system arises from the thoracolumbar outflow (T1-L5 ) at the lateral horns of grey matter of the spinal cord. Their preganglionic neurones are usually short myelinated and synapse in ganglia lateral to the vertebral column and have acetyl choline (Ach) as the neurotransmitter. Their postganglionic neurones are longer and unmyelinated and synapse with effector organ where the neurotransmitter is either adrenaline or noradrenaline.

      The outflow of the parasympathetic nervous system is craniosacral. The cranial part originates from the midbrain and medulla (cranial nerves III, VII, IX and X) and the sacral outflow is from S2, S3 and S4. Their preganglionic neurones are usually long myelinated and synapse in ganglia close to the target organ and has Ach as its neurotransmitter. The unmyelinated postganglionic neurones is shorter and they synapse with effector organ. The neurotransmitter here is also Ach.

      Both sympathetic and parasympathetic preganglionic neurons are cholinergic. Only the postganglionic parasympathetic neurons are cholinergic.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 27 - Which of the following statement is correct regarding the difference between dabigatran and...

    Incorrect

    • Which of the following statement is correct regarding the difference between dabigatran and other anticoagulants?

      Your Answer:

      Correct Answer: Competitive thrombin inhibitor blocking both free and bound thrombin

      Explanation:

      Dabigatran template is a prodrug and its active metabolite is a direct thrombin inhibitor. It is a synthetic, reversible, non-peptide thrombin inhibitor. This inhibition of thrombin results in a decrease of fibrin and reduces platelet aggregation.

      Drugs like warfarin act by inhibiting the activation of vitamin K-dependent clotting factors. These factors are synthesized by the liver and activated by gamma-carboxylation of glutamate residues with the help of vitamin K. Hydroquinone form of vitamin K is converted to epoxide form in this reaction and regeneration of hydroquinone form by enzyme vitamin K epoxide reductase (VKOR) is required for this activity. Oral anticoagulants prevent this regeneration by inhibiting VKOR, thus vitamin K-dependent factors are not activated. These factors include clotting factors II, VII, IX, and X as well as anti-clotting proteins, protein C and protein S.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 28 - Regarding laminar gas flow, which of the following options has the most influence...

    Incorrect

    • Regarding laminar gas flow, which of the following options has the most influence on laminar flow?

      Your Answer:

      Correct Answer: Diameter of tube

      Explanation:

      Laminar flow can be defined as the motion of a fluid where every particle in the fluid follows the same path of its previous particles. The following are properties of laminar flow of gas or fluids:

      1. Smooth unobstructed flow of gas through a tube of relatively uniform diameter
      2. Few directional changes
      3. Slow, steady flow through straight smooth, rigid, large calibre, cylindrical tube
      4. Outer layer flow slower than the centre due to friction, results in discrete cylindrical layers, or streamlines
      5. Double flow by doubling pressure as long as the flow pattern remains laminar

      Poiseuille’s Law relates the factors that determine laminar flow. It indicates the degree of resistance to fluid flow through a tube. The resistance to fluid flow through a tube is directly related to the length, flow and viscosity; and inversely related to the radius of the tube to the fourth power. This means that, when the radius is doubled, there is increase in flow by a factor of 16.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 29 - Prophylactic antibiotics are required for which of the following procedures? ...

    Incorrect

    • Prophylactic antibiotics are required for which of the following procedures?

      Your Answer:

      Correct Answer: Appendicectomy

      Explanation:

      Correctly used, antibiotic prophylaxis can reduce
      the total use of antibiotics.
      There is strong scientific support that antibiotic
      prophylaxis reduces the development of infection after:

      • Operations and endoscopic procedures in the large intestine,
        the rectum, and the stomach (including appendectomies and
        penetrating abdominal trauma), and after percutaneous endoscopic gastrostomy (PEG)
      • Cardiovascular surgery, and insertion of pacemakers
      • Breast cancer surgery
      • Hysterectomy
      • Reduction of simple fractures and prosthetic limb surgery
      • Complicated surgery for cancer in the ear, nose, and throat
        regions
      • Transrectal biopsy and resection of the prostate (febrile urinary
        tract infection and blood poisoning).

      In most cases the scientific evidence is inadequate to determine
      which type of antibiotic is most effective for antibiotic prophylaxis.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 30 - The solutions that contains the most sodium is? ...

    Incorrect

    • The solutions that contains the most sodium is?

      Your Answer:

      Correct Answer: 3500 mL 0.9% N saline

      Explanation:

      Sodium concentration for different fluids
      3% N saline 513 mmol/L
      5% N saline 856 mmol/L
      0.9% N saline 154 mmol/L
      Hartmann’s solution 131 mmol/L
      0.45% N saline with 5% glucose 77 mmol/L

      This means that:

      500 mL 5% N saline contains 428 mmol of sodium
      1000 mL 3% N saline contains 513 mmol of sodium
      3500 mL 0.9% N saline contains 539 mmol of sodium
      4000 mL Hartmann’s contains 524 mmol of sodium
      6000 mL 0.45% N saline with 5% glucose contains 462 mmol of sodium.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 31 - Which of the following statements is not correct regarding dopamine? ...

    Incorrect

    • Which of the following statements is not correct regarding dopamine?

      Your Answer:

      Correct Answer: Crosses the blood brain barrier

      Explanation:

      Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic ? and?1 (but not ?2 ) agonist.

      The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of DA dilates these vessels (by raising intracellular cAMP). This increases g.f.r. In addition, DA exerts a natriuretic effect by D1 receptors on proximal tubular cells.

      Moderately high doses produce a positive inotropic (direct?1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.

      Vasoconstriction (?1 action) occurs only when large doses are infused.

      At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.

      Dopamine is used in patients with cardiogenic or septic shock and severe CHF wherein it increases BP and urine outflow.

      It is administered by i.v. infusion (0.2–1 mg/min) which is regulated by monitoring BP and rate of urine formation

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 32 - A 26-year old man is admitted to the high dependency unit following an...

    Incorrect

    • A 26-year old man is admitted to the high dependency unit following an external fixation of a pelvic fracture sustained in a road traffic accident earlier in the day. Additionally, he has stable L2/L4 vertebral fractures but no other injuries.

      He is a known intravenous drug abuser currently on 200 mg heroin per day. He has been admitted for observations postop and pain control. He has regular paracetamol and NSAIDs prescribed.

      Which is the most appropriate postoperative pain regimen?

      Your Answer:

      Correct Answer: PCA morphine alone with background infusion

      Explanation:

      With a history of drug abuse, the patient is likely dependent on and tolerant to opioids. He is also likely to experience significant pain from his injuries. Providing adequate pain relief with regular paracetamol and NSAIDs in combination with a pure opioid agonist while at the same time avoiding occurrence of acute withdrawal syndrome is the goal.

      Administering a baseline dose of opioid corresponding to the patient’s usual opioid use plus an opioid dose required to address the level of pain the patient experience can help prevent opioid withdrawal. The best approach is by empowering the patient to use patient controlled analgesia (PCA). The infusion rate, bolus dose and lock-out time are adjusted accordingly. Using PCA helps in avoiding staff/patient confrontations about dose and dosing interval.

      2.5 mg heroin is equivalent to 3.3 mg morphine. This patient is usually on 200 mg of heroin per 24 hours. The equivalent dose of morphine is 80 × 3.3 =254 mg per 24 hours (11 mg/hour).

      Epidural or spinal opioids might be the best choice for providing a systemic dose of opioids when patients are in remission to avoid withdrawal. Lumbar vertebral fractures is a contraindication to this route of analgesia.

      The long half life of Oral methadone make titration to response difficult. Also, absorption of methadone by the gastrointestinal tract is variable. It is therefore NOT the best choice for acute pain management.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 33 - Given the following values:

    Expired tidal volume = 800 ml
    Plateau pressure = 50 cmH2O
    PEEP...

    Incorrect

    • Given the following values:

      Expired tidal volume = 800 ml
      Plateau pressure = 50 cmH2O
      PEEP = 10 cmH2O

      Compute for the static pulmonary compliance.

      Your Answer:

      Correct Answer: 20 ml/cmH2O

      Explanation:

      Compliance of the respiratory system describes the expandability of the lungs and chest wall. There are two types of compliance: dynamic and static.

      Dynamic compliance describes the compliance measured during breathing, which involves a combination of lung compliance and airway resistance. Defined as the change in lung volume per unit change in pressure in the presence of flow.

      Static compliance describes pulmonary compliance when there is no airflow, like an inspiratory pause. Defined as the change in lung volume per unit change in pressure in the absence of flow.

      For example, if a person was to fill the lung with pressure and then not move it, the pressure would eventually decrease; this is the static compliance measurement. Dynamic compliance is measured by dividing the tidal volume, the average volume of air in one breath cycle, by the difference between the pressure of the lungs at full inspiration and full expiration. Static compliance is always a higher value than dynamic

      Static compliance can be computed using the formula:

      Cstat = Tidal volume/Plateau pressure – PEEP

      Substituting the values given,

      Cstat = 800/50-10
      Cstat = 20 ml/cmH2O

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 34 - You performed pelvic ultrasound of Mrs Aciman as she had pelvic bloating and...

    Incorrect

    • You performed pelvic ultrasound of Mrs Aciman as she had pelvic bloating and intermittent pain. The ultrasound shows a complex ovarian cyst and the radiologist who reported the results has advised urgent consultation with a gynaecologist. Upon breaking the news to Mrs Aciman you learn that she recently had a blood test done that was normal. You explain it to her that the test performed (Ca-125) is not always perfect and is only able to detect 80% of the cancer cases while the remaining 20% go undetected.

      Which statistical term appropriately explains the 80% in this example.

      Your Answer:

      Correct Answer: Sensitivity

      Explanation:

      Tests are used to confirm the presence of a particular disease. However the results can be misleading at times since most of the tests have some limitations associated with them.
      Sensitivity is the correct term that refers to the probability of a positive test. The others are explained below:

      False Positive rates refer to the proportion of the patients who don’t have the condition being detected as positive.

      False Negative rates refer to the proportion of the patients who have the condition being detected as negative (like the 20% of the patients that went undetected by the Ca-125 test).

      Specificity describes the ability of a test to detect and pick up people without the disease. Absolute risk ratio compares the rate of two separate outcomes.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 35 - Which of the following statements is NOT true regarding the internal jugular vein?...

    Incorrect

    • Which of the following statements is NOT true regarding the internal jugular vein?

      Your Answer:

      Correct Answer: The terminal part of the thoracic duct crosses anterior to it to insert into the right subclavian vein

      Explanation:

      The internal jugular vein is found on both sides of the neck and collects blood from the brain, superficial regions of the face, and neck. It drains into the right atrium.

      It is a continuation of the sigmoid sinus and begins in the posterior cranial fossa and exits the skull via the jugular foramen.
      It runs within the carotid sheath as it descends in the neck and is accompanied by the vagus nerve posteriorly and the common carotid anteromedially.

      The hypoglossal nerve emerges from the hypoglossal canal medial to the internal carotid artery and the internal jugular vein and ninth, tenth, and eleventh cranial nerves.

      The internal jugular vein crosses anterior to the thoracic duct on the left side.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 36 - Of the following, which is NOT a branch of the external carotid artery?...

    Incorrect

    • Of the following, which is NOT a branch of the external carotid artery?

      Your Answer:

      Correct Answer: Mandibular artery

      Explanation:

      The external carotid artery has eight important branches:
      1. Superior thyroid artery
      2. Ascending pharyngeal artery
      3. Lingual artery
      4. Facial artery
      5. Occipital artery
      6. Posterior auricular artery
      7. Maxillary artery (terminal branch)
      8. Superficial temporal artery (terminal branch)

      There is no mandibular artery but the first part of the maxillary artery is called the mandibular part as it is posterior to the lateral pterygoid muscle.
      The maxillary artery is divided into three portions by its relation to the lateral pterygoid muscle:
      first (mandibular) part: posterior to the lateral pterygoid muscle
      second (pterygoid or muscular) part: within the lateral pterygoid muscle
      third (pterygopalatine) part: anterior to the lateral pterygoid muscle

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 37 - About low molecular weight (LMW) heparin, Which of these is true? ...

    Incorrect

    • About low molecular weight (LMW) heparin, Which of these is true?

      Your Answer:

      Correct Answer: Is excreted in the urine

      Explanation:

      Low molecular weight heparin (LMWH) creates a complex by binding to antithrombin. This complex binds with and inactivates factor Xa.

      There is less risk of bleeding with LMWH because it binds less to platelets, endothelium and von Willebrand factor.

      LMW binds Xa more readily. The shorter chains are less likely to bind both antithrombin and thrombin.

      There is need for monitoring in renal impairment because LMHW is excreted in the urine (and partly by hepatic metabolism)

      LMWH have been shown to be as efficacious as unfractionated heparin. It is also safer and have improved inpatient stay and reduced hospital cost.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 38 - A 27-year-old woman presents to emergency department. She is experiencing generalised seizures.

    She is...

    Incorrect

    • A 27-year-old woman presents to emergency department. She is experiencing generalised seizures.

      She is given emergency management of her symptoms before being referred to the neurologist who diagnoses her with new onset of tonic-clonic epilepsy.

      What is the most appropriate first line of treatment?

      Your Answer:

      Correct Answer: Lamotrigine should be offered as first line of treatment

      Explanation:

      Tonic-clonic (Grand mal) epilepsy is characterised by a general loss of consciousness with violent involuntary muscle contractions.

      The NICE guidelines for treatment indicates the use of sodium valproate and lamotrigine, but sodium valproate unsuitable in this case and she is a woman of reproductive age and it is known to have teratogenic effects. Lamotrigine is a more suitable choice, prescribed as 800mg daily.

      NICE guidelines also advice an additional prescription of 5mg of folic acid daily for women on anticonvulsant therapy looking to get pregnant. It also warns of the need for extra contraceptive precaution as there is a possibly that the anticonvulsant agent can reduce levels of contraceptive agents.

      Stimulation of the vagal nerve stimulation is only necessary in patients who are refractory to medical treatment and not candidates for surgical resection.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 39 - Heights of 100 individuals(adults) who were administered steroids at any stage during childhood...

    Incorrect

    • Heights of 100 individuals(adults) who were administered steroids at any stage during childhood was studied. The mean height was found to be 169cm with the data having a standard deviation of 16cm. What will be the standard error associated with the mean?

      Your Answer:

      Correct Answer: 1.6

      Explanation:

      Standard error can be calculated by the following formula:
      Standard Error= (Standard Deviation)/√(Sample Size)
      = (16) / √(100)
      = 16 / 10
      = 1.6

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 40 - A caudal anaesthetic block is planned for a 3-year-old girl presenting for inguinal...

    Incorrect

    • A caudal anaesthetic block is planned for a 3-year-old girl presenting for inguinal hernia repair. Choose the best answer that explains why the caudal epidural space is accessed via the sacral hiatus.

      Your Answer:

      Correct Answer: The failure of fusion of the laminae of S4 and S5 provides a suitable point of entry

      Explanation:

      The sacral hiatus is shaped by incomplete midline fusion of the posterior elements of the distal portion of S4 and S5. This inverted U shaped space is covered by the posterior aspect of the sacrococcygeal membrane and is an important landmark in caudal anaesthetic block. Distal most portion of the dural sac and the sacral hiatus usually terminate between levels S1 and S3. The dural sac ends at the level of S2 in adults and S3 in children.

      An equilateral triangle is formed between the apex of the sacral hiatus and the posterior superior iliac spines. This triangle is used to determine the location of the sacral hiatus during caudal anaesthetic block.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 41 - What is the order of the anatomical components of the tracheobronchial tree from...

    Incorrect

    • What is the order of the anatomical components of the tracheobronchial tree from proximal to distal?

      Your Answer:

      Correct Answer: Bronchioles, terminal bronchioles, respiratory bronchioles, alveolar ducts, alveolar sacs

      Explanation:

      The tracheobronchial tree is subdivided into the conducting and the respiratory zones.

      The zones from proximal to distal are:

      Trachea
      Bronchi
      Bronchioles
      Terminal bronchioles
      Respiratory bronchioles
      Alveolar ducts
      Alveolar sacs

      from the trachea to terminal bronchioles are the conducting zone while the respiratory zone is from the respiratory bronchioles to the alveola sacs

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 42 - A man suffers damage to his vagus nerve during surgery on his neck....

    Incorrect

    • A man suffers damage to his vagus nerve during surgery on his neck. The vagus nerve is cut near its exit from the skull. The man loses his parasympathetic tone raising his heart rate and blood pressure.

      What other feature will be likely present with a vagus nerve injury?

      Your Answer:

      Correct Answer: Hoarse voice

      Explanation:

      The vagus nerve is a mixed nerve with both autonomic and somatic effects. Its most important somatic effect is the motor supply to the larynx via recurrent laryngeal nerves. If one vagus nerve is damaged, the result will be the same as damage to a single recurrent laryngeal nerve, leading to hoarseness of voice.

      The vagus exits the skull via the jugular foramen, accompanied by the accessory nerve.

      Anal tone, erections, and urination are all controlled by the sacral parasympathetic and would not be affected by the loss of the vagus. Parasympathetic controlled pupillary constriction is via the oculomotor nerve and would not be affected by the loss of the vagus.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 43 - A 60-year-old man, presents to the emergency department with crushing pain in the...

    Incorrect

    • A 60-year-old man, presents to the emergency department with crushing pain in the central chest area, which radiates to his left arm and jaw. He also reports feelings of nausea with no other symptoms. Elevation of the ST-segment is noted in multiple chest leads upon ECG, leading to a diagnosis of ST-elevation MI.

      What vessel gives rise to the coronary vessels?

      Your Answer:

      Correct Answer: Ascending aorta

      Explanation:

      The above mentioned patient presentation is one of an acute coronary syndrome.

      The elevations noted in the ST-segments of multiple heart leads on ECG is diagnostic of an ST-elevation myocardial infarction.

      The pulmonary artery branches to give rise to the right and left pulmonary arteries, which supply deoxygenated blood to the right and left lungs from the right ventricle.

      The pulmonary veins do not form any bifurcations, and therefore do not give rise to any vessels. They travel to the left atrium from the lungs, carrying oxygenated blood.

      The descending aorta continues from the aortic arch, and bifurcates to give off many branches, including the right and left common iliac arteries.

      The coronary sinus is formed from the combination of four coronary veins, receiving blood supply from the great, middle, small and posterior cardiac veins, and transporting this venous blood into the right atrium.

      The right and left aortic sinus give rise to the right and left coronary arteries, respectively. They branch of the ascending aorta, in the area just superior to the aortic valve.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 44 - A 55-year-old male is diagnosed with superior vena cava obstruction. What is the...

    Incorrect

    • A 55-year-old male is diagnosed with superior vena cava obstruction. What is the number of collateral circulations that exist for alternate pathways for venous return?

      Your Answer:

      Correct Answer: Four

      Explanation:

      Superior vena cava is the main vein bringing blood back to the heart. It can get partially or completely blocked by various causes, the most common being due to malignant tumours of the mediastinum.

      There are collateral pathways that form in long-standing cases with 60% or more stenosis and continue venous drainage in cases of superior vena obstruction. The collaterals are classified into four as follows:

      1. The azygos-hemiazygos pathway
      Azygos, hemiazygos, intercostal, and lumbar veins.

      2. The internal and external mammary pathway
      internal mammary, superior epigastric, and inferior epigastric veins and superficial veins of the thorax.

      3. The lateral thoracic pathway
      Lateral thoracic, thoracoepigastric, superficial circumflex, long saphenous, and femoral veins to collateralize to the IVC.

      4. The vertebral pathway
      Innominate, vertebral, intercostal, lumbar, and sacral veins to collateralize to the azygos and internal mammary pathways.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 45 - The thebesian veins contribute to the venous drainage of the heart. Into which...

    Incorrect

    • The thebesian veins contribute to the venous drainage of the heart. Into which of the following structures do they primarily drain?

      Your Answer:

      Correct Answer: Atrium

      Explanation:

      The heart has two venous drainage systems:
      1. Greater venous system – it parallels the coronary arterial circulation and provides 70% venous drainage to the heart
      2. Lesser venous system – includes the thebasian veins and provides up to 30% of the venous drainage to the heart

      Thebasian veins (also called venae cordis minimae) are the smallest coronary veins and run in the myocardial layer of the heart. They serve to drain the myocardium and are present in all four heart chambers. They are more abundant on the right side of the heart and, more specifically, are most abundant in the right atrium. Thebesian veins drain the subendocardial myocardium either directly, via connecting intramural arteries and veins, or indirectly, via subendocardial sinusoidal spaces.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 46 - Tubes for vascular access and body cavity drainage are available in a variety...

    Incorrect

    • Tubes for vascular access and body cavity drainage are available in a variety of sizes.

      When choosing an intravenous or intra-arterial cannula, which of the following measurements is used?

      Your Answer:

      Correct Answer: Standard wire gauge (SWG)

      Explanation:

      Standard wire gauge cannulas for intravenous and intraarterial use are available (SWG or G). The SWG is a former imperial unit (which requires metric conversion). The cross sectional area of wires is becoming more popular as a size measurement.

      The number of wires that will fit into a standard hole template is referred to as SWG.

      This standard sized hole can accommodate 22 thin wires side by side (each wire the diameter of a 22 gauge cannula)
      In the same hole, 14 thicker wires would fit (each wire the diameter of a 14 gauge cannula)

      While the diameter and thus radius of a parallel sided tube are the most important determinants of fluid flow rate, they are not commonly used to compare cannula sizes.

      The circumference of French gauge (FG) catheters (urinary or chest drains) is measured. Sizes of double lumen tracheal tubes are FG. Internal diameter is used to measure single lumen tubes.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 47 - Which of the following, at a given PaO2, increases the oxygen content of...

    Incorrect

    • Which of the following, at a given PaO2, increases the oxygen content of arterial blood?

      Your Answer:

      Correct Answer: A reduced erythrocyte 2,3-diphosphoglycerate level

      Explanation:

      The oxygen content of arterial blood can be calculated by the following equation:
      (10 x haemoglobin x SaO2 x 1.34) + (PaO2 x 0.0225).
      This is the sum of the oxygen bound to haemoglobin and the oxygen dissolved in the plasma.

      Oxygen content x cardiac output = The amount of oxygen delivered to the tissues in unit time which is known as the oxygen flux.

      Any factor that increases the metabolic demand will encourage oxygen offloading from the haemoglobin in the tissues and this causes the oxygen dissociation curve (ODC) to shift to the right. This subsequently reduced the oxygen content of arterial blood.

      Conditions like fever, metabolic or respiratory acidosis lowers the oxygen content and shifts the ODC to the right.
      A low level of 2,3 diphosphoglycerate (2,3-DPG) is usually related to an increased oxygen content as there is less offloading, and so the ODC is shifted to the left.

      So for a given PaO2, a high blood oxygen content is related to any factors that can shift the ODC to the left and not to the right.

      A low haematocrit usually means that there is a decreased haemoglobin concentration, and therefore is associated with decreased oxygen binding to haemoglobin.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 48 - An study on post-operative nausea and vomiting (PONV) among paediatric patients who underwent...

    Incorrect

    • An study on post-operative nausea and vomiting (PONV) among paediatric patients who underwent tonsillectomy showed a decrease in incidence from 10% to 5% following a new management protocol.

      Which of the following best estimates the numbers needed to treat (NNT) for one additional patient to benefit from the new management of PONV?

      Your Answer:

      Correct Answer: 20

      Explanation:

      The Number Needed to Treat (NNT) is the number of patients you need to treat to prevent one additional bad outcome. For example, if a drug has an NNT of 5, it means you have to treat 5 people with the drug to prevent one additional bad outcome.

      To calculate the NNT, you need to know the Absolute Risk Reduction (ARR); the NNT is the inverse of the ARR:

      NNT = 1/ARR

      Where ARR = CER (Control Event Rate) – EER (Experimental Event Rate).

      NNTs are always rounded up to the nearest whole number.

      In this case, the NNT can be computed as follows:

      ARR = 10% – 5% = 0.05

      NNT = 1/0.05 = 20

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 49 - Regarding the classification of breathing systems, which of the following is true? ...

    Incorrect

    • Regarding the classification of breathing systems, which of the following is true?

      Your Answer:

      Correct Answer: The Conway classification describes a functional classification based on whether a CO2 absorber is required

      Explanation:

      Breathing system is an assembly of components which connects patient’s airway to anaesthesia machine through which controlled composition of gas mixture is dispensed. It delivers gas to the patient, removes expired gas and controls the temperature and humidity of the inspired mixture. It allows spontaneous, controlled, or assisted respiration. It may also provide ports for gas sampling, airway pressure, flow and volume monitoring.

      Breathing systems have been classified by Conway and Mapleson.
      Conway suggested a functional classification:
      – Circuits requiring a CO2 absorber
      – Circuits not requiring a CO2 absorber

      William Mapleson designated varying arrangements of breathing system components (masks, breathing tubes, fresh gas flow inlets, adjustable pressure-limiting valves, and reservoir bags) as Mapleson A-E circuits.
      Mapleson A: Arranged as FGF inlet, reservoir bag, APL valve, mask.
      In this circuit, because the reservoir bag is between the FGF inlet valve and the APL valve, expired gas from the patient may re-enter the system and fill the reservoir bag during controlled ventilation. This is the most efficient system for spontaneous breathing as the FGF must only be equal to a patient’s minute ventilation to prevent rebreathing.

      Mapleson B: Arranged as reservoir bag, FGF inlet, APL valve, mask.
      In this circuit, the FGF inlet is closer to the APL valve, which helps prevent the rebreathing concern in the Mapleson A circuit as above during controlled ventilation.

      Mapleson C: Arranged as reservoir bag, FGF inlet, APL valve, mask.
      In this circuit, the arrangement is the same as the Mapleson B circuit. However, this circuit is shorter as it does not contain elongated corrugated tubing. This circuit also has the FGF inlet close to the APL valve to aid in preventing rebreathing.

      Mapleson D: Arranged as reservoir bag, APL valve, FGF inlet, and mask.
      In this circuit, the arrangement interchanges the FGF inlet and APL valve of the Mapleson A circuit. This system prevents rebreathing by directing FGF towards the APL valve rather than towards the patient during exhalation.

      Mapleson E: Arranged as corrugated tubing, FGF inlet, and mask.
      In this circuit, there is no reservoir bag and no APL valve. Given the inability to alter the pressure of the circuit, this is ideal for spontaneously ventilating neonates or paediatric patients where low-pressure ventilation is desired. The system prevents rebreathing, similar to the Mapleson D circuit.

      Jackson Rees later modified the Mapleson E by adding an open ended bag, which has since become known as the Mapleson F.
      Mapleson F: Arranged as APL valve directly connected to reservoir bag, corrugated tubing, FGF inlet, and mask.
      The system prevents rebreathing similarly to Mapleson D by directing FGF towards the APL valve.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 50 - Which of the following statement is true about Loop diuretics? ...

    Incorrect

    • Which of the following statement is true about Loop diuretics?

      Your Answer:

      Correct Answer: Are useful in the treatment of acute heart failure

      Explanation:

      Loop diuretics act by causing inhibition of Na+ K+ 2Cl– symporter present at the luminal membrane of the ascending limb of the loop of Henle.

      Furosemide, torsemide, bumetanide, ethacrynic acid, furosemide, piretanide, tripamide, and mersalyl are the important members of this group

      The main use of loop diuretics is to remove the oedema fluid in renal, hepatic, or cardiac diseases. Thus they are useful in the treatment of acute heart failure. These can be administered i.v. for prompt relief of acute pulmonary oedema (due to vasodilatory action).

      Hypokalaemia, hypomagnesemia, hyponatremia, alkalosis, hyperglycaemia, hyperuricemia, and dyslipidaemia are seen with both thiazides as well as loop diuretics

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 51 - Which of the following correctly explains the mechanism of lowering blood pressure by...

    Incorrect

    • Which of the following correctly explains the mechanism of lowering blood pressure by nitroglycerine?

      Your Answer:

      Correct Answer: Nitric oxide

      Explanation:

      Nitroglycerine is rapidly denitrated enzymatically in the smooth muscle cell to release the free radical nitric oxide (NO).

      Released NO activated cytosolic guanylyl cyclase which increases cGMP (cyclin guanosine monophosphate) which causes dephosphorylation of myosin light chain kinase (MLCK) through a cGMP-dependent protein kinase.

      Reduced availability of phosphorylated (active) MLCK interferes with activation of myosin and in turn, it fails to interact with actin to cause contraction. Consequently, relaxation occurs.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 52 - During positive pressure ventilation using positive end-expiratory pressure (PEEP), there is usually an...

    Incorrect

    • During positive pressure ventilation using positive end-expiratory pressure (PEEP), there is usually an associated reduction in cardiac output

      Which of the following is responsible?

      Your Answer:

      Correct Answer: Reduced venous return to the heart

      Explanation:

      The option that is most responsible is the progressive decrease in venous return of blood to the right atrium. The heart rate does not usually change with PEEP so the fall in cardiac output is due to a reduction in left ventricular (LV) stroke volume (SV).

      Note that the interventricular septum does shift toward the left and there is an increased pulmonary vascular resistance (PVR) from overdistention of alveolar air sacs that contribute to the reduction in cardiac output. Any increase in PVR will be associated with reduced pulmonary vascular capacitance.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 53 - A 40 year old female is planned for an critical appendicectomy. A rapid...

    Incorrect

    • A 40 year old female is planned for an critical appendicectomy. A rapid sequence induction is organised. The patient has had a preoperative respiratory tract evaluation and there are no adverse features. The patient is optimally positioned and preoxygenated. The anaesthetic assistant applies 10 N of cricoid pressure. Induction of anaesthesia is then carried out with 250 mg thiopentone and 100 mg suxamethonium with 30 N of cricoid pressure. Initial laryngoscopy reveals a grade 4 view. Three attempts are made at placing a size 7 mm ID tracheal tube two with a standard laryngoscope and one with a McCoy blade and bougie and one further attempt is made using a videolaryngoscope. At this point the suxamethonium is begins to "wear off". Oxygen saturation is 95%. Which one of the following options is the next most appropriate plan of action?

      Your Answer:

      Correct Answer: Maintain oxygenation and anaesthesia and declare a failed intubation

      Explanation:

      Always call for help early. This patient is at risk of gastro-oesophageal reflux, which is why a rapid sequence induction has been chosen. The patient is not pregnant, and the surgery is not urgent.

      Plan A is to perform a rapid sequence induction under optimal conditions and secure the airway with a tracheal tube.

      No more than three attempts with a direct laryngoscope (plus one attempt with a videolaryngoscope) should be made to intubate the trachea. Keep in mind that suxamethonium is wearing off. Ensuring adequate neuromuscular blockade at this stage is crucial; this might include administering a non-depolarizing relaxant if oxygenation can be maintained with bag-mask ventilation. Given the non-immediate nature of the surgery, there should be a low threshold to abandon intubation attempts and resort to Plan B.

      An alternative strategy can then be planned.

      The most important initial step is to declare a “failed intubation.” This will prevent further intubation attempts and alert your assistant that Plan A has failed. Maintaining oxygenation and anesthesia is also critical before implementing Plan B.

      Do not administer another dose of suxamethonium. Insert a supraglottic airway if oxygenation fails and adequate ventilation cannot be maintained.

      Plan D follows the declaration of a CICO (Cannot Intubate, Cannot Oxygenate) situation.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 54 - Which compound is secreted only from the adrenal medulla? ...

    Incorrect

    • Which compound is secreted only from the adrenal medulla?

      Your Answer:

      Correct Answer: Adrenaline

      Explanation:

      The adrenal medulla comprises chromaffin cells (pheochromocytes), which are functionally equivalent to postganglionic sympathetic neurons. They synthesize, store and release the catecholamines noradrenaline (norepinephrine) and adrenaline (epinephrine) into the venous sinusoids.
      The majority of the chromaffin cells synthesize adrenaline.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 55 - A 40-year old gentleman has palpitations and has gone to the emergency department....

    Incorrect

    • A 40-year old gentleman has palpitations and has gone to the emergency department. He is found to have monomorphic ventricular tachycardia. The resting potential of ventricular monocytes is maintained by which electrolyte?

      Your Answer:

      Correct Answer: Potassium

      Explanation:

      Potassium maintains the resting potential of cardiac myocytes, with depolarization triggered by a rapid influx of sodium ions, and repolarization due to efflux of potassium. A slow influx of calcium is responsible for the longer duration of a cardiac action potential compared with skeletal muscle.

      The cardiac action potential has several phases which have different mechanisms of action as seen below:

      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms.

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 56 - A 43-year-old patient was brought to the emergency department with a traumatic amputation...

    Incorrect

    • A 43-year-old patient was brought to the emergency department with a traumatic amputation of his leg at mid-thigh level. Resuscitation with 1 L gelofusine was done and four units of packed red blood cells were given before theatre. Thirty minutes following blood transfusion, the patient became flushed, breathless, hypotensive, develops haemoglobinuria, and had a fever of 38oC.

      Which one of the following correctly explains the patient signs and symptoms?

      Your Answer:

      Correct Answer: Activation of classic complement pathway

      Explanation:

      This may be the classical case of blood transfusion reaction due to ABO incompatibility.

      Here red cells are destroyed in the bloodstream with the release of haemoglobin in circulation (causing haemoglobinuria). Here, IgM or IgG anti-A or anti-B antibody can cause rapid activation of complement cascade usually the classical pathway. This is called intravascular haemolysis.

      There may be extravascular haemolysis by cells of the mononuclear phagocyte system situated in the liver and spleen. Extravascular red cell destruction can increase breakdown products of haemoglobin, such as bilirubin and urobilinogen.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 57 - Concerning the physical principles of temperature measurement by a thermocouple, which of the...

    Incorrect

    • Concerning the physical principles of temperature measurement by a thermocouple, which of the following best describes it?

      Your Answer:

      Correct Answer: The bimetallic strip has a junction potential proportional to temperature

      Explanation:

      A thermocouple, or a thermal junction, is temperature measuring device consisting of a pair of dissimilar metal (bimetallic) wires or strips joined together. Typically, copper and constantan (an alloy of 55% copper and 45% nickel) are used. When there is contact between these metals, a small voltage is generated in the order of millivolts. The magnitude of the thermojunction electromotive force (emf) is proportional to applied temperature (the Seebeck effect). This physical principle is applied in the measurement of temperature. The electromotive force at the measuring junction is proportional to temperature.

      Two wires with different coefficients of expansion, joined together, can be used as a switch for thermostatic control.

      Semiconductors are NOT used in thermocouple. The resistance of the measuring junction of a thermocouple is irrelevant.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 58 - Which type of epithelium lines the luminal surface of the oesophagus? ...

    Incorrect

    • Which type of epithelium lines the luminal surface of the oesophagus?

      Your Answer:

      Correct Answer: Non keratinised stratified squamous epithelium

      Explanation:

      Normally, the oesophagus is lined by non-keratinized stratified squamous epithelium. This epithelium can undergo metaplasia and convert to the columnar epithelium (stomach’s lining) in long-standing GERD that leads to Barret’s oesophagus.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 59 - Prior to an urgent appendicectomy, a 49-year-old man requires a rapid sequence induction.

    His...

    Incorrect

    • Prior to an urgent appendicectomy, a 49-year-old man requires a rapid sequence induction.

      His BMI is equal to 50.

      Which of the following formulas is the most appropriate for calculating a suxamethonium dose in order to achieve optimal intubating conditions?

      Your Answer:

      Correct Answer: 1-1.5 × actual body weight (mg)

      Explanation:

      The usual method of calculating the dose of a drug to be given to patients of normal weight is to use total body weight (TBW). This is because the lean body weight (LBW) and ideal body weight (IBW) dosing scalars are similar in these patients.

      Because the LBW and fat mass do not increase in proportion in patients with morbid obesity, this is not the case. Drugs that are lipid soluble, such as propofol or thiopentone, can cause a relative overdose. Lean body mass is a better scalar in these situations.

      Suxamethonium has a small volume of distribution, so the dose is best calculated using the TBW to ensure optimal and deep intubating conditions. The higher dose was justified because these patients’ plasma cholinesterase activity was elevated.

      Other scalars include:

      The dose of highly lipid soluble drugs like benzodiazepines, thiopentone, and propofol can be calculated using lean body weight (LBW). The formula LBW = IBW + 20% can be used on occasion.

      Fentanyl, rocuronium, atracurium, vecuronium, morphine, paracetamol, bupivacaine, and lidocaine are all administered with LBW.

      Formulas can be used to calculate the ideal body weight (IBW). There are a number of drawbacks, including the fact that patients of the same height receive the same dose, and the formulae do not account for changes in body composition associated with obesity. Because IBW is typically lower than LBW, administering a drug based on IBW may result in underdosing. The body mass index (BMI) isn’t used to calculate drug dosage directly.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 60 - Which of the following is true regarding a laryngoscope? ...

    Incorrect

    • Which of the following is true regarding a laryngoscope?

      Your Answer:

      Correct Answer: The Wisconsin and Seward are examples of straight blade laryngoscopes

      Explanation:

      Direct laryngoscopy are performed using laryngoscopes and they can be classed according to the shape of the blade as curved or straight.

      Miller, Soper, Wisconsin and Seward are examples of straight blade laryngoscopes. Straight blades are commonly used for intubating neonates and infants but can be used in adults too.

      The tip of the miller blade is advanced over the epiglottis to the tracheal entrance then lifted in order to view the vocal cords.

      The RIGHT-SIDED Macintosh blade is used in adults while the left-sided blade may be used in conditions that make intubation with standard blade difficult e.g. facial deformities.

      The McCoy laryngoscope is based on the STANDARD MACINTOSH blade not Robertshaw’s. It has a lever operated hinged tip, which improves the view during laryngoscopy.

      Polio blade is mounted at an angle of 120-135 degrees to the handle. Originally designed for use during the polio epidemic ​in intubation patients within iron lung ventilators, it is now useful in patients with conditions like breast hypertrophy, barrel chest, and restricted neck mobility.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 61 - All of the following statements are true about blood clotting except: ...

    Incorrect

    • All of the following statements are true about blood clotting except:

      Your Answer:

      Correct Answer: Administration of aprotinin during liver transplantation surgery prolongs survival

      Explanation:

      Even though aprotinin reduces fibrinolysis and therefore bleeding, there is an associated increased risk of death. It was withdrawn in 2007.
      Protein C is dependent upon vitamin K and this may paradoxically increase the risk of thrombosis during the early phases of warfarin treatment.

      The coagulation cascade include two pathways which lead to fibrin formation:
      1. Intrinsic pathway – these components are already present in the blood
      Minor role in clotting
      Subendothelial damage e.g. collagen
      Formation of the primary complex on collagen by high-molecular-weight kininogen (HMWK), prekallikrein, and Factor 12
      Prekallikrein is converted to kallikrein and Factor 12 becomes activated
      Factor 12 activates Factor 11
      Factor 11 activates Factor 9, which with its co-factor Factor 8a form the tenase complex which activates Factor 10

      2. Extrinsic pathway – needs tissue factor that is released by damaged tissue)
      In tissue damage:
      Factor 7 binds to Tissue factor – this complex activates Factor 9
      Activated Factor 9 works with Factor 8 to activate Factor 10

      3. Common pathway
      Activated Factor 10 causes the conversion of prothrombin to thrombin and this hydrolyses fibrinogen peptide bonds to form fibrin. It also activates factor 8 to form links between fibrin molecules.

      4. Fibrinolysis
      Plasminogen is converted to plasmin to facilitate clot resorption

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 62 - According to the statements given which one is most correct concerning the spinal...

    Incorrect

    • According to the statements given which one is most correct concerning the spinal cord?

      Your Answer:

      Correct Answer: There are 31 pairs of spinal roots

      Explanation:

      The cylindrical structure(spine), starts from the foramen magnum in medulla oblongata at the skull’s base. Its length varies in gender with men having 45cm and women having up to 43 cm. The spine contains 31 pairs of spinal nerves, named according to the spinal region:
      – 8 cervical nerve pairs ( C1-C8)
      – 12 thoracic nerve pairs ( T1-T12)
      – 5 lumbar nerve pairs (L1-L5)
      – 5 sacral nerves (S1-S5) and
      – 1 coccygeal nerve pair.
      These spinal nerves are classified as the peripheral nervous system though they branch from the spinal cord and central nervous system. They interact directly with the spinal cord to modulate the motor and sensory information from the peripheral’s region. As the nerves emerges form the spinal cords they are known as rootlets. They join to form nerve roots, and depending on their position, we have anterior nerve roots and posterior.

      The spinal cord is supplied by two posterior and one anterior spinal arteries which anastomoses caudally, at the conus medullaris.

      The anterior spinal artery supplies the anterior two-thirds of the spinal cord and medulla. Disruption of the anterior spinal artery supply is characterised by ischaemia or infarction of motor tracts (corticospinal) and loss of pain and temperature sensation below the level of the lesion.

      The posterior spinal arteries supply the posterior columns (posterior third of the spinal cord). Infarction of the posterior columns results in the loss of proprioceptive, vibration and two-point discrimination.

      The spinal cord normally ends at the level of L1 or L2 in an adult and L3 in a newborn.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 63 - What is the most sensitive method of detecting an intra-operative air embolism? ...

    Incorrect

    • What is the most sensitive method of detecting an intra-operative air embolism?

      Your Answer:

      Correct Answer: Transoesophageal echocardiogram

      Explanation:

      An intra-operative air embolism occurs when air becomes trapped in the blood vessels during surgery.

      A transoesophageal echocardiography (OE) uses invasive echocardiography to monitor the integrity and performance of the heart. It is the gold standard as it provides real-time imaging of the heart to enable early diagnosis and treatment.

      Precordial doppler ultrasonography can also be used to detect into-operative air emboli. It is non-invasive and more practical, but is less sensitive.

      A change in end-tidal CO2 could be indicative of and increase in physiological dead-space, but could also be indicative of any processes that reduces the excretion or increases the production of CO2, making it non-specific.

      A transoesophageal stethoscope can be used to listen for the classic mill-wheel murmur produced by a large air embolus.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 64 - A graph is created to show the exponential relationship between bacterial growth (y-axis)...

    Incorrect

    • A graph is created to show the exponential relationship between bacterial growth (y-axis) and time (x-axis).

      Which of the following statements is most true about this kind of exponential relationship?

      Your Answer:

      Correct Answer: y = ex

      Explanation:

      The relationship between bacterial growth and time is a tear-away exponential. The mathematical relationship between y and x in this case is:

      y = ex

      Where: the power is x, and the base is e.

      Euler’s number (e) is a mathematical constant that is the base for all logarithms occurring naturally. Its value is 2.718.

      The statement X increasing with an increase in Y is proportional to Y refers to the change in y in terms of x when considering any exponential relationship.

      This is not a build-up exponential, and that is mathematically stated as y = 1-e-kt.

      The negative x axis being a horizontal asymptote and the y intercept being 0, 1 are examples of tearaway exponentials , but do not describe an exponential process.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 65 - Substitution at different positions of the barbituric ring give rise to different pharmacologic...

    Incorrect

    • Substitution at different positions of the barbituric ring give rise to different pharmacologic properties.

      Substitution with and at which specific site of the ring affects lipid solubility the most?

      Your Answer:

      Correct Answer: Sulphur atom at position 2

      Explanation:

      Barbiturates are derived from barbituric acid, which itself is nondepressant, but appropriate side-chain substitutions result in CNS depressant activity that varies in potency and duration with carbon chain length, branching, and saturation.

      Oxybarbiturates retain an oxygen atom on number 2-carbon atom of the barbituric acid ring.

      Thiobarbiturates replace this oxygen atom with a sulphur atom, which confers greater lipid solubility. Generally speaking, a substitution such as sulphuration that increases lipid solubility is associated with greater hypnotic potency and more rapid onset, but shorter duration of action.

      Addition of a methyl group to the nitrogen atom of the barbituric acid ring, as with oxybarbiturate methohexital, also results in a compound with a short duration of action.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 66 - A 52-year-old man was referred for investigation of malignant hyperthermia following general anaesthesia...

    Incorrect

    • A 52-year-old man was referred for investigation of malignant hyperthermia following general anaesthesia for a micro laryngoscopy and biopsy for a suspected laryngeal tumour. The patient was found to be a heavy smoker and the only presenting symptom is a hoarse voice.

      A sample of muscle (vastus lateralis) needs to be taken to establish a diagnosis of malignant hyperthermia in this patient.

      Which one of the following is the best anaesthetic technique for muscle biopsy in this patient?

      Your Answer:

      Correct Answer: Spinal anaesthesia

      Explanation:

      According to European Group protocol for the investigation of MH susceptibility, muscle biopsy should be performed on quadriceps muscle (either vastus medialis or vastus lateralis), using regional anaesthesia (avoiding local anaesthetic infiltration) or general anaesthetic techniques. Local anaesthetic solution within muscle fibres may affect in vitro contraction testing.

      Desflurane is a weak triggering anaesthetic of malignant hyperthermia so is avoided in MH susceptible patients. This includes all volatile inhalational agents and suxamethonium.

      General anaesthetic with the volatile free anaesthetic machine may be considered but spinal anaesthesia is a better choice due to the possibility of airway problems.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 67 - The child-Pugh scoring system can be used, if risk classifying a patient with...

    Incorrect

    • The child-Pugh scoring system can be used, if risk classifying a patient with chronic liver disorder earlier to anaesthesia.

      Which one is the best combination of clinical signs and examinations used within the Child-Pugh scoring system?

      Your Answer:

      Correct Answer: Ascites, grade of encephalopathy, albumin, bilirubin and INR

      Explanation:

      In the Child-Pugh classification system, the following 5 components are determined or calculated in order:

      Ascites

      Grade of encephalopathy

      Serum bilirubin (?mol/L)

      Serum Albumin (g/L)

      Prothrombin time or INR

      Raised liver enzymes are not the component of the classification system.

    • This question is part of the following fields:

      • Basic Physics
      0
      Seconds
  • Question 68 - A 65-year-old man has been diagnosed with transitional cell carcinoma of the left...

    Incorrect

    • A 65-year-old man has been diagnosed with transitional cell carcinoma of the left kidney. He will be operated on, and as part of the surgery, the left renal artery has to be located and dissected.

      Which of the following vertebral levels gives rise to this artery?

      Your Answer:

      Correct Answer: L1

      Explanation:

      The renal arteries branch from the abdominal aorta just below the origin of the superior mesenteric artery. The right renal artery is higher and longer than the left renal artery. The left renal artery passes behind the left renal vein, the body of the pancreas, and the splenic vein.

      The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:

      T10 – oesophageal opening in the diaphragm

      T12 – Coeliac trunk, aortic hiatus in the diaphragm

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 69 - The whole water content of the body is calculated by multiplying body mass...

    Incorrect

    • The whole water content of the body is calculated by multiplying body mass with 0.6. This water is diffused into distinct compartments.

      Which fluid compartment can be measured indirectly?

      Your Answer:

      Correct Answer: Intracellular volume

      Explanation:

      The total body water content of a 70kg man is (70 × 0.6) = 42 litres. For a woman, the calculation is (70 × 0.55) = 38.5 litres.

      For a man, it is subdivided into:

      Extracellular fluid (ECF) = 14L (1/3)
      Intracellular fluid (ICF) = 28L (2/3).

      The ECF volume is further divided into:

      Interstitial fluid = 10.5 litres
      Plasma = 3 litres
      Transcellular fluid (CSF/synovial fluid) = 0.5 litres.

      Directly measured fluid compartments:

      Heavy water (deuterium) can be used to measure total body water content, which is freely distributed.
      Albumin labelled with a radioactive isotope or using a dye called Evans blue can be used to measure Plasma volume . They do not diffuse into red blood cells.
      Radiolabelled (Cr-51) red blood cells can be used to measure total erythrocyte volume.
      Inulin as the tracer can be used to measure ECF volume as it circulate freely in the interstitial and plasma volumes.

      Indirectly measured fluid compartments:

      Total blood volume can be calculated with the level of haematocrit and the volume of total circulating red blood cells.
      ICF volume can be calculated by subtracting ECF volume from total blood volume.

    • This question is part of the following fields:

      • Basic Physics
      0
      Seconds
  • Question 70 - The diaphragm is a muscle that is relatively resistant to non-depolarizing neuromuscular blockade's...

    Incorrect

    • The diaphragm is a muscle that is relatively resistant to non-depolarizing neuromuscular blockade's effects.

      When these muscle relaxants are used, which of the following peripheral nerve stimulator twitch patterns is best for monitoring the return of diaphragmatic function?

      Your Answer:

      Correct Answer: Post-tetanic count stimulation

      Explanation:

      Certain skeletal muscles are more resistant to the effects of neuromuscular blocking agents, both non-depolarizing and depolarizing. The diaphragm is the most resistant. The muscles of the larynx and the corrugator supercilii are less resistant. The abdominal, orbicularis oris, and limb peripheral muscles are the most sensitive muscles.

      Twitch stimulation patterns:

      Supramaximal single stimulus:

      The frequency ranges from 1 Hz to 0.1 Hz (one every second to one every 10 seconds)
      The response is proportional to the frequency of the event.
      It has limited clinical utility because it only tells you whether or not a patient is paralysed (no information on degree of paralysis).

      Over the course of 0.5 seconds (2 Hz), four supramaximal stimulate were applied:

      It is possible to see ‘fade’ and use it as a basis for evaluation.
      This stimulation pattern is used to determine the degree of blockade (1-2 twitches is appropriate for abdominal surgery)
      If the train of four (TOF) count is 1-2, reversal agents can be used in conjunction with medium-acting neuromuscular blocking agents.

      Ratio of TOF:

      This is the ratio of the 4th twitch amplitude to the 1st twitch amplitude.
      The ratio decreases with non-depolarising block and is inversely proportional to the degree of block, allowing objective measurement of residual neuromuscular blockade.
      To achieve adequate reversal, the ratio (as measured by accelerography) must be between 0.7 and 0.9.

      Count of twitches after a tetanic experience(PTC):

      50 Hz for 5 seconds, then a 3 second pause, followed by a single 1 Hz twitch stimulus.
      When the TOF count is zero, this stimulation pattern is used to assess deep blockade (that is, in neurosurgery, microsurgery or ophthalmic surgery when even small movements of a patient will disturb the surgical field)
      It gives an estimate of how long it will take for the response to return to single twitches, allowing assessment of blocks that are too deep for any other technique.
      A palpable post-tetanic count (PTC) of 2 indicates no twitch response for about 20-30 minutes, and a PTC of 5 indicates no twitch response for about 10-15 minutes.

      This is without a doubt the best way to keep track of paralysis in patients who need to avoid diaphragmatic movement. It’s best to use drug infusions and aim for a PTC of 2. After a tetanic stimulus, acetylcholine is mobilised, causing post-tetanic potentiation.

      Stimulation in Two Bursts:

      750 milliseconds between two short bursts of 50 Hz
      This stimulation pattern is used to assess small amounts of residual blockade manually (tactile).

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 71 - Desflurane has which of the following characteristics when compared with halothane? ...

    Incorrect

    • Desflurane has which of the following characteristics when compared with halothane?

      Your Answer:

      Correct Answer: Less biodegradation

      Explanation:

      Approximately 20% of halothane and 0.02% desflurane undergo hepatic biotransformation. Desflurane, halothane, and isoflurane are metabolised in the liver by cytochrome p450 to trifluoroacetate. Through an immunological mechanism involving trifluoroacetyl hapten formation, trifluoroacetate is thought to be responsible for hepatotoxicity.

      Potency of inhaled anaesthetic agents is measured using the minimal alveolar concentration (MAC). The MAC of halothane is 0.74% while that of desflurane is 6.3%. The potency can also be compared using the oil: gas partition coefficient (224 and 18.7 for halothane and desflurane respectively).

      Onset of action of volatile agents depends on the blood:gas partition coefficient. A lower blood:gas partition coefficient and insolubility in blood means faster onset and offset of action. The blood gas coefficient for halothane is 2.4 while that of desflurane is 0.42. Desflurane is less soluble than halothane in blood. Halothane has a pungent smell that can irritate the airway which limits its use for a gaseous induction especially in paediatric anaesthesia. desflurane is not pungent.

      Desfluranes boiling point is only slightly above normal room temperature (22.8°C) making it extremely volatile while the boiling point of halothane is approximately 50.2°C.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 72 - The main site of storage of thyroid hormones in the thyroid gland is?...

    Incorrect

    • The main site of storage of thyroid hormones in the thyroid gland is?

      Your Answer:

      Correct Answer: Thyroglobulin

      Explanation:

      The follicle is the functional unit of the thyroid gland. The follicular cells surround the follicle which is filled with colloid. Suspended within the colloid is the is a pro-hormone complex thyroglobulin.

      The synthesis and storage of thyroid hormones is done by follicular cells and the thyroglobulin within the colloid.

      Iodide ions (I−) are actively transported against a concentration gradient into the follicular cell under the influence of thyroid stimulating hormone (TSH). It then undergoes oxidation to active iodine catalysed by thyroid peroxidase (TPO). The synthesis of thyroglobulin is in the follicular cells and it contains up to 140 tyrosine residues. The tyrosine residues of thyroglobulin and active iodine are merged to form mono- and di-iodotyrosines (MIT and DIT). The iodinated thyroglobulin is then taken up into the colloid where it is stored and dimerised. Two DIT molecules are joined to produce thyroxine (T4) while one MIT and one DIT molecule are joined to produce tri-iodotyrosine (T3) by a process catalysed by TPO.

      Thyroglobulin droplets are taken up as vesicles into follicular cells by pinocytosis. This process is stimulated by TSH. When these vesicles fuse with lysosomes, hydrolysis of the thyroglobulin molecules and subsequent release of T4 and T3 into the circulation occurs.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 73 - An 80-year-old female suffered a TIA 2 weeks ago. She has been admitted...

    Incorrect

    • An 80-year-old female suffered a TIA 2 weeks ago. She has been admitted to the vascular ward as she will be undergoing carotid endarterectomy tomorrow morning. To explain the procedure and its complications, the surgeon gives her information about the procedure, telling her the artery will be tied during the operation.

      She inquires about the areas supplied by the different arteries. You explain that the internal carotid artery supplies the brain while the external carotid artery ascends the neck and bifurcates into two arteries. One of these arteries is the superficial temporal artery. Which of the following is the second branch?

      Your Answer:

      Correct Answer: Maxillary artery

      Explanation:

      Carotid endarterectomy is the procedure to relieve an obstruction in the carotid artery by opening the artery at its origin and stripping off the atherosclerotic plaque with the intima. This procedure is performed to prevent further episodes, especially in patients who have suffered ischemic strokes or transient ischemic attacks.

      The external carotid artery terminates by dividing into the superficial temporal and maxillary branches. The maxillary artery is the larger of the two terminal branches and arises posterior to the neck of the mandible.

      The other arteries mentioned in the answer options branch off from the following:
      Temporal arteries from the maxillary artery
      Middle meningeal artery from the maxillary artery
      Lingual artery from the anterior aspect of the external carotid artery
      Facial artery from the anterior aspect of the external carotid artery

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 74 - A 2-year old male is admitted to the surgery ward for repair of...

    Incorrect

    • A 2-year old male is admitted to the surgery ward for repair of an inguinal hernia. He weighs 10 kg. To provide post-operative analgesia, levobupivacaine was administered into the epidural space.

      Given the information above, what is the most appropriate dose for the hernia repair?

      Your Answer:

      Correct Answer: 0.25% 7.5 ml

      Explanation:

      Caudal analgesia using bupivacaine is a widely employed technique for achieving both intraoperative and early postoperative pain relief. 0.5 ml/kg of 0.25% plain bupivacaine is favoured by many practitioners who employ this fixed scheme for procedures involving sacral dermatomes (circumcision, hypospadias repair) as well as lower thoracic dermatomes (orchidopexy). However, there are other dosing regimens for caudal blocks with variable analgesic success rates: These include 0.75 ml/kg, 1.0 ml/kg and 1.25 ml/kg.

      A study indicated that plain bupivacaine 0.25% at a dose of 0.75 ml/kg compared to a dose of 0.5 ml/kg when administered for herniotomies provided improved quality of caudal analgesia with a low side effects profile. There were consistently more patients with favourable objective pain scale (OPS) scores at all timelines, increased the time to the analgesic request with similar postoperative consumption of paracetamol in the group of patients who received 0.75 ml/kg of 0.25% bupivacaine.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 75 - A young male is undergoing inguinal hernia repair. During the procedure, the surgeons...

    Incorrect

    • A young male is undergoing inguinal hernia repair. During the procedure, the surgeons approach the inguinal canal and expose the superficial inguinal ring.

      Which structure forms the lateral edge of the superficial inguinal ring?

      Your Answer:

      Correct Answer: External oblique aponeurosis

      Explanation:

      The superficial inguinal ring is an opening in the aponeurosis of the external oblique muscle, just above and lateral to the pubic crest.

      The superficial ring resembles a triangle more than a ring with the base lying on the pubic crest and its apex pointing towards the anterior superior iliac spine. The sides of the triangle are crura of the opening in the external oblique aponeurosis. The lateral crura of the triangle is attached to the pubic tubercle. The medial crura of the triangle is attached to the pubic crest.

      The external oblique aponeurosis forms the anterior wall of the inguinal canal and also the lateral edge of the superficial inguinal ring. The rectus abdominis lies posteromedially, and the transversalis posterior to this.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 76 - A study was concerned with finding out the normal reference range of IgE...

    Incorrect

    • A study was concerned with finding out the normal reference range of IgE levels in adults was conducted. Presuming that the curve follows a normal distribution, what is the percentage of individuals having IgE levels greater than 2 standard deviations from mean?

      Your Answer:

      Correct Answer: 2.30%

      Explanation:

      Since the data is normally distributed, 95.4% of the values lie with in 2 standard deviations from mean. The rest of the 4.6% are distributed symmetrically outside of that range which means 2.3% of the values lie above 2 standard deviations of the mean.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 77 - Useful diagnostic information can be obtained from measuring the osmolality of biological fluids....

    Incorrect

    • Useful diagnostic information can be obtained from measuring the osmolality of biological fluids.

      Of the following physical principles, which is the most accurate and reliable method of measuring osmolality?

      Your Answer:

      Correct Answer: Depression of freezing point

      Explanation:

      Colligative properties are properties of solutions that depend on the number of dissolved particles in solution. They do not depend on the identities of the solutes.

      All of the above have colligative properties with the exception of depression of melting point.

      The osmolality from the concentration of a substance in a solution is measured by an osmometer. The freezing point of a solution can determines concentration of a solution and this can be measured by using a freezing point osmometer. This is applicable as depression of freezing point is directly correlated to concentration.

      Vapour pressure osmometers, which measure vapour pressure, may miss certain volatiles such as CO2, ammonia and alcohol that are in the solution

      The use of a freezing point osmometer provides the most accurate and reliable results for the majority of applications.

      Colligative properties does not include melting point depression . Mixtures of substances in which the liquid phase components are insoluble, display a melting point depression and a melting range or interval instead of a fixed melting point.

      The magnitude of the melting point depression depends on the mixture composition.

      The melting point depression is used to determine the purity and identity of compounds. EMLA (eutectic mixture of local anaesthetics) cream is a mixture of lidocaine and prilocaine and is used as a topical local anaesthetic. The melting point of the combined drugs is lower than that individually and is below room temperature (18°C).

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 78 - The Kappa statistic (aka Cohen's kappa coefficient) can be used to measure which...

    Incorrect

    • The Kappa statistic (aka Cohen's kappa coefficient) can be used to measure which of the following?

      Your Answer:

      Correct Answer: Inter-rater reliability

      Explanation:

      The Kappa Statistic or Cohen’s Kappa is a statistical measure of inter-rater reliability for categorical variables. It is used when two raters both apply a criterion based on a tool to assess whether or not some condition occur. A good example can be two doctors rating individuals for diabetes occurrence on the basis of symptoms.

      It gives a quantitative measure of the magnitude of agreement between observers.

      Kappa can take any value between 0 and 1. 0 implies the observers are in complete disagreement and a value of 1 implies complete agreement.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 79 - Which of the following statements is true about fluid balance? ...

    Incorrect

    • Which of the following statements is true about fluid balance?

      Your Answer:

      Correct Answer: After intravenous administration of crystalloids, the distribution of these fluids throughout the body depends on its osmotic activity

      Explanation:

      When there is capillary leakage as seen in dependent oedema or ascites, oncotic pressure becomes a problem.

      The intracellular sodium concentration is very sensitive to the extracellular sodium concentrations. When there is an imbalance, osmosis occurs resulting in shifts in water between the two compartments.

      The microvascular endothelium relies upon osmosis and other processes as it is not freely permeable to water.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 80 - Which structure does NOT lie in the posterior triangle of the neck? ...

    Incorrect

    • Which structure does NOT lie in the posterior triangle of the neck?

      Your Answer:

      Correct Answer: Internal jugular vein

      Explanation:

      The sternocleidomastoid muscle divides the neck into anterior and posterior triangles on both sides of the neck.

      The posterior triangle has the following boundaries:
      anteriorly – sternocleidomastoid muscle
      posteriorly – trapezius
      roof – investing layer of deep cervical fascia
      floor – prevertebral fascia overlying splenius capitis, levator scapulae, and the scalene muscles

      The contents of the posterior triangle are:
      1. fat
      2. lymph nodes (level V)
      3. accessory nerve
      4. cutaneous branches of the cervical plexus (A major branch of this plexus is the phrenic nerve, which arises from the anterior divisions of spinal nerves C3-C5)
      5. inferior belly of omohyoid
      6. branches of the thyrocervical trunk (transverse cervical and suprascapular arteries)
      7. third part of the subclavian artery
      8. external jugular vein

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 81 - Which of the following would most likely explain a failed post-operative analgesia via...

    Incorrect

    • Which of the following would most likely explain a failed post-operative analgesia via local anaesthesia of a neck abscess?

      Your Answer:

      Correct Answer: pKA

      Explanation:

      For the local anaesthetic base to be stable in solution, it is formulated as a hydrochloride salt. As such, the molecules exist in a quaternary, water-soluble state at the time of injection. However, this form will not penetrate the neuron. The time for onset of local anaesthesia is therefore predicated on the proportion of molecules that convert to the tertiary, lipid-soluble structure when exposed to physiologic pH (7.4).

      The ionization constant (pKa) for the anaesthetic predicts the proportion of molecules that exists in each of these states. By definition, the pKa of a molecule represents the pH at which 50% of the molecules exist in the lipid-soluble tertiary form and 50% in the quaternary, water-soluble form. The pKa of all local anaesthetics is >7.4 (physiologic pH), and therefore a greater proportion the molecules exists in the quaternary, water-soluble form when injected into tissue having normal pH of 7.4.

      Furthermore, the acidic environment associated with inflamed tissues favours the quaternary, water-soluble configuration even further. Presumably, this accounts for difficulty when attempting to anesthetize inflamed or infected tissues; fewer molecules exist as tertiary lipid-soluble forms that can penetrate nerves.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 82 - Among the different classes of anti-arrhythmics, which one is the first line treatment...

    Incorrect

    • Among the different classes of anti-arrhythmics, which one is the first line treatment for narrow complex AV nodal re-entry tachycardia?

      Your Answer:

      Correct Answer: Adenosine

      Explanation:

      Adenosine is the first line for AV nodal re-entry tachycardia. An initial dose of 6 mg is given, and a consequent second dose or third dose of 12 mg is administered if the initial dose fails to terminate the arrhythmia.

      Aside from Adenosine, a vagal manoeuvre (e.g. carotid massage) is done to help terminate the supraventricular arrhythmia.

      Amiodarone is not a first-line drug for supraventricular tachycardias. Digoxin and Propranolol can be considered if the arrhythmia is of a narrow complex irregular type. Verapamil is an alternative to Adenosine if the latter is contraindicated.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 83 - A 68-year-old man has suffered a myocardial infarction. He has a heart rate...

    Incorrect

    • A 68-year-old man has suffered a myocardial infarction. He has a heart rate of 40 beats per minute currently.
      Your senior attending explains that the slow heart rate is due to the damage to the conduction pathways between the sinoatrial and atrioventricular nodes. His ventricles are being paced by the AV node alone.

      What artery supplies the AV node in the majority of patients?

      Your Answer:

      Correct Answer: Right coronary artery

      Explanation:

      The AV node has an intrinsic firing rate of 40-60 beats per minute which is clinically significant in cases of damage to the conducting pathways as patients continue to have a ventricular rate of 40-60. Patients who have an AV node supplied by the right coronary are said to be right dominant. The remaining 10% are left dominant and supplied by the left circumflex.

      The right coronary artery supplies the right atrium, right ventricle, interatrial septum, and the inferior posterior third of the interventricular septum. It also supplies the atrioventricular node + sinoatrial node in most patients. The posterior descending artery supplies the posterior third of the interventricular septum.

      The heart receives blood supply from coronary arteries. The right and left coronary arteries branch off the aorta and supply oxygenated blood to all heart muscle parts.

      The left main coronary artery branches into:
      1. Circumflex artery – supplies the left atrium, side, and back of the left ventricle. The left marginal artery arises from the left circumflex artery. It travels along the obtuse margin of the heart.
      The left marginal artery, a branch of the circumflex artery, supplies the left ventricle.
      2. Left Anterior Descending (LAD) artery – supplies the front and bottom of the left ventricle and front of the interventricular septum

      The right coronary artery branches into:
      1. Right marginal artery
      2. Posterior descending artery

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 84 - Which of the following statements is correct about a characteristic that is normally...

    Incorrect

    • Which of the following statements is correct about a characteristic that is normally distributed in a population?

      Your Answer:

      Correct Answer: There will be approximately equal numbers who have more or less of the characteristic than the mean

      Explanation:

      68% of the population will be found in one standard deviation (SD) above plus one SD below the mean. Two SDs above plus two SDs below the mean will include 95% of the population.

      The median can be greater or less than the mean as it is simply the mid point of the data after the data is arranged. Half the data are above and half below the median .

      The mode is a true score, unlike the mean or the median. It is the most common score or the score obtained from the largest number of subjects in any given data.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 85 - Which of the following statements is true regarding the Wrights Respirometer? ...

    Incorrect

    • Which of the following statements is true regarding the Wrights Respirometer?

      Your Answer:

      Correct Answer: Measures the minute volume to within an accuracy of +/- 10%

      Explanation:

      A Wrights Respirometer measures the volume of air exhaled over the course of one minute of normal breathing

      It is unidirectional and measures tidal volume and minute volume of gas flow in one direction. It is placed at the expiratory side (lower pressure than inspiratory side therefore lower chances of gas leaks)

      Slits are arranged such that incoming gas will rotate the vane at a rate of 150 revolutions per litre of flowing gas

      The Wright respirometer tends to over-read at high flow rates and under-read at low flows because of mechanical causes like friction and inertia and the accumulation of water vapour

      The ideal flow for accurate readings is 2 L/min for the respirometer. The respirometer reads the tidal volume and minute volume with a ±5–10% accuracy within the range of 4–24 L/min.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 86 - An elderly man complains of a vague lump near his stomach to his...

    Incorrect

    • An elderly man complains of a vague lump near his stomach to his physician. On examination, the lump is visible on coughing and is found within Hesselbach's triangle.

      Which of the following is true regarding the borders for this triangle?

      Your Answer:

      Correct Answer: Inguinal ligament inferiorly, inferior epigastric vessels laterally, lateral border of rectus sheath medially

      Explanation:

      The inguinal triangle of Hesselbach is an important clinical landmark on the posterior wall of the inguinal canal. It has the following relations:
      Inferiorly – medial third of the inguinal ligament
      Medially – lower lateral border of the rectus abdominis
      Laterally – inferior epigastric vessels

      Direct inguinal hernia is when the bowel bulges directly through the abdominal wall. These hernias usually protrude through Hesselbach’s triangle

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 87 - Which of the following best describes why phenytoin's hepatic extraction ratio is low? ...

    Incorrect

    • Which of the following best describes why phenytoin's hepatic extraction ratio is low?

      Your Answer:

      Correct Answer: It has a clearance that is insensitive to changes in liver blood flow

      Explanation:

      The following are the pharmacokinetic properties of drugs with a low hepatic extraction ratio:

      Changes in liver blood flow have no effect on drug clearance.
      When given orally, drug clearance is extremely sensitive to changes in protein binding, intrinsic metabolism, and excretion, and there is no first-pass metabolism.

      Warfarin and phenytoin are two drugs with low hepatic extraction ratios.

      The following are the pharmacokinetic properties of drugs with a high hepatic extraction ratio:

      When taken orally, undergo extensive first-pass metabolism; drug clearance is dependent on liver blood flow, and drug clearance is less sensitive to changes in protein binding and intrinsic metabolism.

      Morphine, lidocaine, propranolol, and etomidate are examples of drugs with high hepatic extraction ratios.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 88 - Which of the following statements is not true regarding Adrenaline? ...

    Incorrect

    • Which of the following statements is not true regarding Adrenaline?

      Your Answer:

      Correct Answer: Exerts its effect by decreasing intracellular calcium

      Explanation:

      Noradrenaline also called norepinephrine belongs to the catecholamine family that functions in the brain and body as both a hormone and neurotransmitter.

      They have sympathomimetic effects acting via adrenoceptors (?1, ?2,?1, ?2, ?3) or dopamine receptors (D1, D2).

      May cause reflex bradycardia, reduce cardiac output and increase myocardial oxygen consumption

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 89 - A 71-year-old man, presents with central crushing pain in his chest to the...

    Incorrect

    • A 71-year-old man, presents with central crushing pain in his chest to the emergency department. On examination, he complains of nausea and is notably sweating. On ECG, elevation in the ST-segment is noted in multiple chest leads, as well as sinus bradycardia. A myocardial infarction can cause a sinus bradycardia.

      The sinoatrial (SA) node and the atrioventricular (AV) node receive arterial supply from which vessel?

      Your Answer:

      Correct Answer: Right coronary artery

      Explanation:

      The left marginal artery comes off the left circumflex artery, and runs alongside the heart.

      The left circumflex artery is one of the bifurcations of the left coronary artery, and eventually forms the left marginal artery.

      An occlusion in the left circumflex artery often results in a lateral MI.

      The right marginal artery originates from the right coronary artery.

      The left anterior descending artery (LAD) is another bifurcation of the left coronary artery. An occlusion in the LAD would often result in an anteroseptal MI as is diagnosed on ECG by noting changes in leads V1-V4.

      The right coronary artery originates from the right aortic sinus of the ascending aorta, and bifurcates to give rise to many branches, including the sinoatrial artery which supplies the sinoatrial (SA) node in 50-70% of cases, the artery of the atrioventricular (AV) node in 50-60% of cases, the right acute marginal artery which supplies the right ventricle. It also supplies the right atrium, interatrial septum and the posterior inferior third of the interventricular septum.

      Arrhythmias and inferior MI often occurs as a result of an occlusion in the right coronary artery, and can be diagnosed by ECG changes in leads II, III and aVF.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 90 - Regarding sine wave damping, which one would approach equilibrium the fastest at zero...

    Incorrect

    • Regarding sine wave damping, which one would approach equilibrium the fastest at zero amplitude, without overshoot?

      Your Answer:

      Correct Answer: Critical damping

      Explanation:

      A damped sine wave is a smooth, periodic oscillation with an amplitude that approaches zero as time goes to infinity. In other words, the wave gets flatter as the x-values become larger.

      Critical damping is defined as the threshold between overdamping and underdamping. In the case of critical damping, the oscillator returns to the equilibrium position as quickly as possible, without oscillating, and passes it once at most.

      In overdamping, the system moves slowly towards the equilibrium. An underdamped system moves quickly to equilibrium, but will oscillate about the equilibrium point as it does so.

      Optimal damping has a damping coefficient of around 0.64-0.7. It maximizes frequency response, minimizes overshoot of oscillations, and minimizes phase and amplitude distortion.

      In an undamped system, the amplitude of the waves that are being generated remain unchanged and constant over time.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 91 - Suppose a diabetic patient is to undergo an elective surgery under general anaesthesia,...

    Incorrect

    • Suppose a diabetic patient is to undergo an elective surgery under general anaesthesia, which of the following will most effectively prevent a hyperglycaemic stress response during the surgical procedure?

      Your Answer:

      Correct Answer: Spinal block to T4

      Explanation:

      Every surgical procedure is associated with a stress response which comprises a number of endocrine, metabolic, and immunological changes triggered by neuronal activation of the hypothalamic-pituitary-adrenal axis. The overall metabolic effect of the stress response to surgery includes an increase in secretion of catabolic hormones, such as cortisol and catecholamine, and a decrease in secretion of anabolic hormones, such as insulin and testosterone. The increase in levels of catabolic hormones in plasma stimulates glucose production, and there is a relative lack of insulin together with impaired tissue insulin sensitivity and glucose utilization, which is called insulin resistance. Consequently, blood glucose concentrations will increase, even in the absence of pre-existing diabetes.

      A study compared the effects of spinal and general anaesthesia on changes in blood glucose concentrations during surgery in nondiabetic patients. Although mean blood glucose concentrations showed a significant proportional increase during surgery in both groups, this effect was much more significant with general anaesthesia than with spinal anaesthesia. These results indicate that spinal anaesthesia is more effective than general anaesthesia in attenuating the hyperglycaemic response to surgery.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 92 - A surgeon infiltrates the tissue layers with local anaesthetic (bupivacaine 0.125%) with 1...

    Incorrect

    • A surgeon infiltrates the tissue layers with local anaesthetic (bupivacaine 0.125%) with 1 in 120,000 adrenaline in a patient weighing 50 kg as part of an enhanced recovery programme for primary hip replacement surgery.

      What is the maximum volume of local anaesthetic that is permissible in this patient?

      Your Answer:

      Correct Answer: 100 mL

      Explanation:

      The maximum safe amount of bupivacaine is 2mg/kg. Addition of adrenaline slows down absorption of the local anaesthetic and allows a maximum dose of 2.5mg/kg to be used.

      The maximum safe dose of bupivacaine for this patient is 125 mg.

      A 0.125% solution will contain 0.125g/100mL or 125mg/100 mL.

      The maximum volume of local anaesthetic is approximately 80-100 mL.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 93 - An otherwise fit 7-year-old boy for an elective tonsillectomy is seen holding a...

    Incorrect

    • An otherwise fit 7-year-old boy for an elective tonsillectomy is seen holding a bottle of sugared orange squash at anaesthetic assessment . He appears to have consumed 120 mL of the bottle's contents.

      What is the minimal safe fasting time prior to proceeding with a general anaesthetic in this patient?

      Your Answer:

      Correct Answer: 1 hour

      Explanation:

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 94 - A current flows through a simple electric circuit.

    Which of the following electrical component...

    Incorrect

    • A current flows through a simple electric circuit.

      Which of the following electrical component configurations has the greatest potential difference?

      Your Answer:

      Correct Answer: Two 5 ohm resistors in series with a passing current of 10 ampere

      Explanation:

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 95 - What is the mechanism of the pupillary reflex arc? ...

    Incorrect

    • What is the mechanism of the pupillary reflex arc?

      Your Answer:

      Correct Answer: Oculomotor nerve fibres from the Edinger-Westphal nuclei

      Explanation:

      Pupil size is reduced by the pupillary light reflex and during accommodation for near vision. In the pupillary light reflex, light that strikes the retina is processed by retinal circuits that excite W-type retinal ganglion cells. These cells respond to diffuse illumination. The axons of some of the W-type cells project through the optic nerve and tract to the pretectal area, where they synapse in the olivary pretectal nucleus. This nucleus contains neurons that also respond to diffuse illumination. Activity of neurons of the olivary pretectal nucleus causes pupillary constriction by means of bilateral connections with parasympathetic preganglionic neurons in the Edinger-Westphal nuclei. The reflex results in contraction of the pupillary sphincter muscles in both eyes, even when light is shone into only one eye.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 96 - The statement that best describes temperature management is: ...

    Incorrect

    • The statement that best describes temperature management is:

      Your Answer:

      Correct Answer: Gauge thermometers use coils of different metals with different co-efficients of expansion which either tighten or relax with changes in temperature

      Explanation:

      There are different types of temperature measurement. These include:

      Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially

      Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)

      Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature

      Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output

      Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 97 - The rapid depolarisation phase of the myocardial action potential is caused by: ...

    Incorrect

    • The rapid depolarisation phase of the myocardial action potential is caused by:

      Your Answer:

      Correct Answer: Rapid sodium influx

      Explanation:

      The cardiac action potential has several phases which have different mechanisms of action as seen below:
      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 98 - A 28-year-old girl complained of severe abdominal pain and hematemesis and was rushed...

    Incorrect

    • A 28-year-old girl complained of severe abdominal pain and hematemesis and was rushed into the emergency department. She has an increased heart rate of 120 beats per minute and blood pressure of 90/65. She has a history of taking Naproxen for her Achilles tendinopathy. On urgent endoscopy, she is diagnosed with a bleeding peptic ulcer.

      The immediate treatment is to permanently stop the bleeding by performing embolization of the left gastric artery via an angiogram.

      What level of the vertebra will be used as a radiological marker for the origin of the artery that supplies the left gastric artery during the angiogram?

      Your Answer:

      Correct Answer: T12

      Explanation:

      The left gastric artery is the smallest branch that originates from the coeliac trunk—the coeliac trunk branches of the abdominal aorta at the vertebral level of T12.

      The left gastric artery runs along the superior portion of the lesser curvature of the stomach. A peptic ulcer that is serious enough to erode through the stomach mucosa into a branch of the left gastric artery can cause massive blood loss in the stomach, leading to hematemesis. The patient also takes Naproxen, a non-steroidal anti-inflammatory drug that is a common cause for peptic ulcers in otherwise healthy patients.

      The left gastric artery is responsible for 85% of upper GI bleeds. In cases refractory to initial treatment, angiography is sometimes needed to embolise the vessel at its origin and stop bleeding. During an angiogram, the radiologist will enter the aorta via the femoral artery, ascend to the level of the 12th vertebrae and then enter the left gastric artery via the coeliac trunk.

      The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:

      T12 – Coeliac trunk

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 99 - Noradrenaline is used as an infusion to increase blood pressure in a 43-year-old...

    Incorrect

    • Noradrenaline is used as an infusion to increase blood pressure in a 43-year-old woman with pneumonia admitted to ICU.
      Which of the following statements is true regarding Noradrenaline?

      Your Answer:

      Correct Answer: Has a short half life about 2 minutes

      Explanation:

      Noradrenaline has a short half-life of about 2 minutes. It is rapidly cleared from plasma by a combination of cellular reuptake and metabolism.

      It acts as sympathomimetics by acting on ?1 receptors and also on ? receptors.

      It decreases renal and hepatic blood flow.

      Norepinephrine is metabolized by the enzymes monoamine oxidase and catechol-O-methyltransferase to 3-methoxy-4-hydroxymandelic acid and 3-methoxy-4-hydroxyphenylglycol (MHPG).

      Natural catecholamines are Adrenaline, Noradrenaline, and Dopamine

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 100 - An emergency appendicectomy is being performed on a 20 year old man. For...

    Incorrect

    • An emergency appendicectomy is being performed on a 20 year old man. For maintenance of anaesthesia, he is being ventilated using a circle system with a fresh gas flow (FGF) of 1 L/min (air/oxygen and sevoflurane). The trace on the capnograph shows a normal shape.

      The table below demonstrates the changes in the end-tidal and baseline carbon dioxide measurements of the capnograph at 10 and 20 minutes of anaesthesia maintenance.  
      End-tidal CO2: 4.9 kPa vs 8.4kPa (10 minutes vs 20 minutes)
      Baseline end-tidal CO2: 0.2 kPa vs 2.4kPa

      Pulse 100-107 beats per minute, systolic blood pressure 125-133 mmHg and oxygen saturation 98-99%. 

      Which of the following is the single most important immediate course of action?

      Your Answer:

      Correct Answer: Increase the FGF

      Explanation:

      End-tidal carbon dioxide (ETCO2) monitoring has been an important factor in reducing anaesthesia-related mortality and morbidity. Hypercarbia, or hypercapnia, occurs when levels of CO2 in the blood become abnormally high (Paco2 >45 mm Hg). Hypercarbia is confirmed by arterial blood gas analysis. When using capnography to approximate Paco2, remember that the normal arterial–end-tidal carbon dioxide gradient is roughly 5 mm Hg. Hypercarbia, therefore, occurs when PETco2 is greater than 40 mm Hg.

      The most likely explanation for the changes in capnograph is either exhaustion of the soda lime and a progressive rise in circuit dead space.

      Inspect the soda lime canister for a change in colour of the granules. To overcome soda lime exhaustion, the first step is to increase the fresh gas flow (FGF) (Option A). Then, if need arises, replace the soda lime granules. Other strategies that can work are changing to another circuit or bypassing the soda lime canister, but remember that both these strategies are employed only after increasing FGF first. Exclude other causes of equipment deadspace too.

      There are also other causes for hypercarbia to develop intraoperatively:
      1. Hypoventilation is the most common cause of hypercapnia. A. Inadequate ventilation can occur with spontaneous breathing due to drugs like anaesthetic agents, opioids, residual NMDs, chronic respiratory or neuromuscular disease, cerebrovascular accident.
      B. In controlled ventilation, hypercapnia due to circuit leaks, disconnection or miscalculation of patient’s minute volume.
      2. Rebreathing – Soda lime exhaustion with circle, inadequate fresh gas flow into Mapleson circuits and increased breathing system deadspace.
      3. Endogenous source – Tourniquet release, hypermetabolic states (MH or thyroid storm) and release of vascular clamps.
      4. Exogenous source – Absorption of CO2 from pneumoperitoneum.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 101 - After a bariatric surgery, average weight loss observed in patients is 18 kg....

    Incorrect

    • After a bariatric surgery, average weight loss observed in patients is 18 kg. The standard deviation was found to be 3 kg. What is the percentage of patients that lie between 9 and 27 kg?

      Note: Assume that the curve is normally distributed.

      Your Answer:

      Correct Answer: 99.70%

      Explanation:

      9 & 27 can be obtained by subtracting and adding 9 from the mean. 9 is three times the standard deviation and we know that 99.7% values lie within 3 standard deviations from the mean. We can find the interval for 99.7% to verify in the following way:

      For 99.7% confidence interval, you can find the range as follows:

      1. Multiply the standard error by 3.

      2. Subtract the answer from mean value to get the lower limit.

      3. Add the answer obtained in step 1 from the mean value to get the upper limit.

      4. The range turns out to be 9-27 kg.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 102 - All of the statements describing the blood brain barrier are false EXCEPT:...

    Incorrect

    • All of the statements describing the blood brain barrier are false EXCEPT:

      Your Answer:

      Correct Answer: Inflammation alters its permeability

      Explanation:

      The blood brain barrier (BBB) consists of the ultrafiltration barrier in the choroid plexus and the barrier around cerebral capillaries. The barrier is made by endothelial cells which line the interior of all blood vessels. In the capillaries that form the blood–brain barrier, endothelial cells are wedged extremely close to each other, forming so-called tight junctions.

      Outside of the BBB lies the hypothalamus, third and fourth ventricles and the chemoreceptor trigger zone (CTZ).

      Water, oxygen and carbon dioxide cross the BBB freely but glucose is controlled. The ability of chemicals to cross the barrier is proportional to their lipid solubility, not their water solubility. It’s ability to cross is inversely proportional to their molecular size and charge.

      In neonates, the BBB is less effective than in adults. This is why there is increased passage of opioids and bile salts (kernicterus) into the neonatal brain.

      In meningitis, the effectiveness and permeability of the BBB is affected, and as a result, this effect helps the passage of antibiotics which would otherwise not normally be able to cross.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 103 - Regarding pre-eclampsia with warning signs, which of the following laboratory tests is the...

    Incorrect

    • Regarding pre-eclampsia with warning signs, which of the following laboratory tests is the most appropriate to establish a platelet dysfunction or disorder?

      Your Answer:

      Correct Answer: Platelet count

      Explanation:

      Decreased platelet concentrations with eclampsia were described as early as 1922 by Stancke. The platelet count is routinely measured in women with any form of gestational hypertension. The frequency and intensity of thrombocytopenia vary and are dependent on the severity and duration of the preeclampsia syndrome and the frequency with which platelet counts are performed.

      Overt thrombocytopenia defined by a platelet count < 100,000/microliter - indicates severe disease. In general, the lower the platelet count, the higher the rates of maternal and fetal morbidity and mortality. In most cases, delivery is advisable because thrombocytopenia usually continues to worsen. After delivery, the platelet count may continue to decline for the first day or so. It then usually increases progressively to reach a normal level within 3-5 days. In some instances with HELLP syndrome, the platelet count continues to fall after delivery. If these do not reach a nadir until 48 to 72 hours, then preeclampsia syndrome may be incorrectly attributed to one of the thrombotic microangiopathies. The following are other severe features associated with preeclampsia: Proteinuria: >/= 300 mg/24 hours; or urine protein: creatinine ratio >/= 0.3; or dipstick 1+

      Renal insufficiency: serum creatinine > 1.1 mg/dL or doubling of creatinine in the absence of other renal disease

      Impaired liver function: two times elevated AST/ALT or unexplained right upper quadrant pain or epigastric pain unresponsive to medications

      Pulmonary oedema

      Cerebral or visual symptoms: headache, visual disturbances

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 104 - Regarding the treatment of bladder cancer, a study concerned with the usage of...

    Incorrect

    • Regarding the treatment of bladder cancer, a study concerned with the usage of a combined or monotherapy was conducted. A forest plot was used for the visual representation of the data.

      Which of the following is true regarding forest plots?

      Your Answer:

      Correct Answer: Forest plots can present data from multiple studies

      Explanation:

      Being the part of a meta analysis, forest plots are more valued as evidence then randomised control trials.

      The notion that forest plots can only be used if the results are substantial is not true. They are good indicators of the significance of the data. If the diamond intersects the central line, the data is rendered significant. It also aggregates means and confidence intervals from studies conducted in the past which makes the study much more reliable as errors associated with individual studies tend to have less of an impact in this way.

      The suggestion that forest plots are primarily used for qualitative data is factually incorrect. Forest plots require numerical values to function.

      All in all, forest plots help us in determining whether or not there is a significant trend in that particular field of study.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 105 - A double blind placebo control clinical trial is done. Which of these is...

    Incorrect

    • A double blind placebo control clinical trial is done. Which of these is correct about it?

      Your Answer:

      Correct Answer: The clinician assessing the effects of the treatment does not know which treatment the patient has been given

      Explanation:

      A ‘double blind crossover study’ happens when every patient receive both treatments.

      It is incorrect to say that only half of the patients do not know which treatment they receive because in a double blind placebo control clinical trial ALL of the patients are blind to their treatment choice .

      If some of the patients are not treated, they would be aware that they were not being treated and it could not be considered a blind trial.

      In a double blind placebo control clinical trial both the clinician and the patient are blind to the treatment choice. The clinician assessing the effects of the treatment, therefore, does not know which treatment the patient has been given.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 106 - An 80-year old lady has a background history of a previous myocardial infarction...

    Incorrect

    • An 80-year old lady has a background history of a previous myocardial infarction which has left permanent damage to her heart's conduction system. The part of the conduction system with the highest velocities is damaged, and this has resulted in desynchronisation of the ventricles. The part of the heart that conducts the fastest is which of the following?

      Your Answer:

      Correct Answer: Purkinje fibres

      Explanation:

      The electrical conduction system of the heart starts with the SA node which generates spontaneous action potentials.

      This is conducted across both atria by cell to cell conduction, and occurs at around 1 m/s. The only pathway for the action potential to enter the ventricles is through the AV node in a normal heart.
      At this site, conduction is very slow at 0.05ms, which allows for the atria to completely contract and fill the ventricles with blood before the ventricles depolarise and contract.

      The action potentials are conducted through the Bundle of His from the AV node which then splits into the left and right bundle branches. This conduction is very fast, (,2m/s), and brings the action potential to the Purkinje fibres.

      Purkinje fibres are specialised conducting cells which allow for a faster conduction speed of the action potential (,2-4m/s). This allows for a strong synchronized contraction from the ventricle and thus efficient generation of pressure in systole.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 107 - Which of the following statements is TRUE regarding an epidural set? ...

    Incorrect

    • Which of the following statements is TRUE regarding an epidural set?

      Your Answer:

      Correct Answer: 19G Tuohy needles have 0.5 cm markings

      Explanation:

      A paediatric 19G Tuohy catheter is available that is 5cm in length and has 0.5cm markings

      18G Tuohy catheters are generally 9 to 10cm to hub

      Distal end of catheter is angled (15 to 30 degrees) and closed to avoid puncturing the dura

      Epidural mesh are usually 0.2 microns and are used to filter bacteria and viruses to ensure sterility of procedure

      Transparent catheters are 90cm long with diameters depending on gauge size. It has 1cm graduations from 5 to 20cm to ensure they have been inserted amply and removed completely. Distal end is smooth which can be open or closed (with lateral openings)

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 108 - Which of the following statements about intra-arterial blood pressure monitoring is true? ...

    Incorrect

    • Which of the following statements about intra-arterial blood pressure monitoring is true?

      Your Answer:

      Correct Answer: Fluid-filled tubing conducts the intravascular pressure wave from the catheter tip to the transducer

      Explanation:

      Intra-arterial blood pressure monitoring is a common place procedure in the ICU. It is used to provide accurate beat-to-beat information using a pressure wave displayed on a monitor.

      It involves catheter insertion in a peripheral artery (most commonly the radial, brachial and dorsalis pedis arteries). Each subsequent contraction of cardiac muscles results in pressure wave which induces a mechanical motion of flow in the catheter. This mechanical motion is then passed on to a transducer through a rigid fluid-filled tubing. The transducer is the able to process this mechanical motion into electrical signals which are displayed as arterial waves and pressure represented numerically on the monitor.

      The transducer should be placed at the same level as the heart on the phlebostatic axis, and at the level of the atria (the 4th intercostal space, in the mid-axillary line).

      Air bubbles and catheter tubing with longer lengths result in wave dampening (rounding of the resulting pressure waves). This dampening causes a decrease in systolic pressure, and an increase in diastolic pressure.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 109 - Which of the following does Lidocaine 1% solution equate to? ...

    Incorrect

    • Which of the following does Lidocaine 1% solution equate to?

      Your Answer:

      Correct Answer: 1000 mg per 100 ml

      Explanation:

      Lidocaine 1% is formulated as 1000 mg/100 mL.

      % solution is based on (grams of medicine) / 100 ml

      % solution ~ (1000 mg) / 100 ml

      % solution ~ 10 mg/ml

      Examples:

        • Lidocaine 4% = 40 mg/ml of Lidocaine
        • Lidocaine 2% = 20 mg/ml of Lidocaine
        • Lidocaine 1% = 10 mg/ml of Lidocaine

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 110 - Radical prostatectomy is being performed on a 60-year-old man for carcinoma of the...

    Incorrect

    • Radical prostatectomy is being performed on a 60-year-old man for carcinoma of the prostate gland.

      What is the direct blood supply of the prostate?

      Your Answer:

      Correct Answer: Inferior vesical artery

      Explanation:

      The prostate gland is primarily supplied by the inferior vesical artery, which branches off from the anterior division of the internal iliac artery. The inferior vesical artery supplies the base of the bladder, the distal ureters, and the prostate. The branches to the prostate communicate with the corresponding vessels of the opposite side.

      The inferior vesical artery branches into two main arteries:
      1. Urethral artery – supplies the transition zone and is the main arterial supply for the adenomas in BPH
      2. Capsular artery – supplies the glandular tissue

      The venous drainage of the prostate is from the prostatic venous plexus, which drains into the paravertebral veins.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 111 - A 53-year old female with a diagnosis of anaplastic thyroid carcinoma is admitted...

    Incorrect

    • A 53-year old female with a diagnosis of anaplastic thyroid carcinoma is admitted in the surgery department for an elective total thyroidectomy with radical neck dissection. The operation is expected to last for 10 hours.

      Which of the following is the most suitable humidifier to use in an anaesthetic circuit for this case?

      Your Answer:

      Correct Answer: Heat and moisture exchanger (HME)

      Explanation:

      Adequate humidification is vital to maintain homeostasis of the airway. Heat and moisture exchangers conserve some of the exhaled water, heat and return them to inspired gases. Many heat and moisture exchangers also perform bacterial/viral filtration and prevent inhalation of small particles. Heat and moisture exchangers are also called condenser humidifier, artificial nose, etc. Most of them are disposable devices with exchanging medium enclosed in a plastic housing. For adult and paediatric age group different dead space types are available. Heat and moisture exchangers are helpful during anaesthesia and ventilatory breathing system. To reduce the damage of the upper respiratory tract through cooling and dehydration inspiratory air can be heated and humidified, thus preventing the serious complications. Moreover, they are the most appropriate humidification devices used for routine anaesthesia.

      Gases can be bubbled through water to increase humidity. Passing gas through water at room temperature causes the gas to cool due to latent heat of vaporisation. The water bath can be heated. This improves the efficiency of the device and also reduces the incidence of bacterial colonisation.

      Nebulisers use a venturi system which employs the Bernoulli effect. A gas at high flow passes through a constriction causing the gas to accelerate, reducing its potential energy allowing other gases or liquids to be entrained. This can include medications or in the case of humidification, water vapour. The size of the water droplet produced by nebulisation determines where in the airway it is deposited. Standard nebulisers produced droplets of 4 microns in diameter and these are deposited in the upper airway and trachea. Efficacy can be improved by passing the droplets over an anvil which further reduces particle size. The most efficient form of nebuliser is the ultrasonic nebuliser. Here a transducer immersed in water and vibrated at a frequency of 3MHz produces1-2micron droplets. These particles easily reach the bronchioles and provide excellent humidification.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 112 - A transport ventilator connected to a size CD oxygen cylinder has a setting...

    Incorrect

    • A transport ventilator connected to a size CD oxygen cylinder has a setting of air/oxygen entrainment ratio of 1:1 and a minute volume set at 10 litres/minute.

      Which value best approximates to the FiO2?

      Your Answer:

      Correct Answer: 0.6

      Explanation:

      A nominal volume of 2 litres is contained in a CD cylinder. It has a pressure of 230 bar when full and contains litres 460 L of useable oxygen at STP.

      For every 1000 mL 100% oxygen there will be an entrainment of 1000 mL or air (20% oxygen) in an air/oxygen mix.

      The average concentration is, therefore, 120/2=60% or 0.6.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 113 - Which of the following statements is true regarding ketamine? ...

    Incorrect

    • Which of the following statements is true regarding ketamine?

      Your Answer:

      Correct Answer: Can be used in the management of refractory status epilepticus

      Explanation:

      Ketamine is a phencyclidine (hallucinogenic) derivative that is administered in a dose of 2 mg/kg and acts by blocking NMDA (N-methyl-D-aspartate) receptors of glutamate.

      It is a powerful bronchodilator agent and is, therefore, an intravenous anaesthetic of choice in bronchial asthma (halothane is an inhalational anaesthetic agent of choice for bronchial asthma). It is also used in the management of refractory status epilepticus.

      It is an acid solution with an elimination half-life of three hours.

      It has S (+) enantiomer and R (-) enantiomer. the S(+) enantiomer is two to four times more potent than the R(-) and is less likely to produce hallucinations.

      Its use is contraindicated in patients with ischaemic heart disease because it increased sympathetic outflow leading to tachycardia and increased cardiac output which in turn increases the myocardial oxygen demand.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 114 - The following results were obtained In a new drug trial:

    Improved Not improved
    Placebo...

    Incorrect

    • The following results were obtained In a new drug trial:

      Improved Not improved
      Placebo group 36 26
      Treatment group 44 16

      Regarding the statistical analysis or interpretation of the trial, One of these is true

      Your Answer:

      Correct Answer: The data could be evaluated using the chi square test

      Explanation:

      This data is in a 2 × 2 contingency table so a chi square test can be used. There is a special chi squared formula that gives a value that can be looked up in a table giving the p value.

      Since we are comparing proportions not means, the Student’s t test CANNOT be used.

      There is no linear regression to plot so Pearson’s co-efficient cannot be calculated.

      Nothing is so obvious that no statistical analysis is needed.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 115 - The structure most likely to be damaged during cannulation of the subclavian vein...

    Incorrect

    • The structure most likely to be damaged during cannulation of the subclavian vein is?

      Your Answer:

      Correct Answer: Subclavian artery

      Explanation:

      The subclavian artery lies behind and partly above the subclavian vein. 3-4% of the time, it can be inadvertently cannulated during cannulation of the subclavian vein

      Because of its anatomical position, putting pressure on the subclavian artery is impossible so arresting bleeding with pressure when it is punctured is not viable.

      One of the consequences of subclavian vein cannulation (1%) is pleural puncture leading to a pneumothorax. This is because the apical pleura is inferior and caudal to the subclavian vein.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 116 - Because this benzodiazepine has a half-life of 2-4 hours, it is preferred for...

    Incorrect

    • Because this benzodiazepine has a half-life of 2-4 hours, it is preferred for clinical use.

      This benzodiazepine has which of the following properties that no other benzodiazepine has?

      Your Answer:

      Correct Answer: It is water soluble at a pH of 3.5 and lipid soluble at a pH of 7.4

      Explanation:

      Midazolam is the benzodiazepine in question. It’s the only benzodiazepine that undergoes tautomeric transformation (dynamic isomerism). The molecule is ionised and water soluble at pH 3.5, but when injected into the body at pH 7.4, it becomes unionised and lipid soluble, allowing it to easily pass through the blood brain barrier.

      The half-life of midazolam is only 2-4 hours.

      It is a GABAA receptor agonist because it is a benzodiazepine. GABAA receptors are found in abundance throughout the central nervous system, particularly in the cerebral cortex, hippocampus, thalamus, basal ganglia, and limbic system. GABAA receptors are ligand-gated ion channels, with the inhibitory neurotransmitter gamma-aminobutyric acid as the endogenous agonist. It is a pentameric protein (2, 2 and one subunit) that spans the cell membrane, and when the agonist interacts with the alpha subunit, a conformational change occurs, allowing chloride ions to enter the cell, resulting in neuronal hyperpolarization.

      For status epilepticus, midazolam is not the drug of choice. Lorazepam is the benzodiazepine of choice for status epilepticus.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 117 - Of the following statements, which is true about the measurements of cardiac output...

    Incorrect

    • Of the following statements, which is true about the measurements of cardiac output using thermodilution?

      Your Answer:

      Correct Answer: Cardiac output should be measured during the end-expiratory pause

      Explanation:

      Thermodilution is the most common dilution method used to measure cardiac output (CO) in a hospital setting.

      During the procedure, a Swan-Ganz catheter, which is a specialized catheter with a thermistor-tip, is inserted into the pulmonary artery via the peripheral vein. 5-10mL of a cold saline solution with a known temperature and volume is injected into the right atrium via a proximal catheter port. The solution is cooled as it mixes with the blood during its travel to the pulmonary artery. The temperature of the blood is the measured by the catheter and is profiled using a computer.

      The computer also uses the profile to measure cardiac output from the right ventricle, over several measurements until an average is selected.

      Cardiac output changes at each point of respiration, therefore to get an accurate measurement, the same point during respiration must be used at each procedure, this is usually the end of expiration, that is the end-expiratory pause.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 118 - Which of the following facts about IgE is true? ...

    Incorrect

    • Which of the following facts about IgE is true?

      Your Answer:

      Correct Answer: Is increased in the serum of atopic individuals

      Explanation:

      Immunoglobulin E (IgE) are an antibody subtype produced by the immune system. They are the least abundant type and function in parasitic infections and allergy responses.

      The most predominant type of immunoglobulin is IgG. It is able to be transmitted across the placenta to provide immunity to the foetus.

      IgE is involved in the type I hypersensitivity reaction as it stimulates mast cells to release histamine. It has no role in type 2 hypersensitivity.

      Its concentration in the serum is normally the least abundant, however certain reactions cause a rise in its concentration, such as atopy, but not in acute asthma.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 119 - A 56-year old man, presents to emergency department following a cardiac arrest. On...

    Incorrect

    • A 56-year old man, presents to emergency department following a cardiac arrest. On history and examination, he is found to be suffering from both metabolic and respiratory acidosis as a result of his cardiac arrest.

      What is the best way to reduce the risk of acidaemia during cardiac arrest

      Your Answer:

      Correct Answer: Chest compressions

      Explanation:

      Chest compressions are an essential part of cardiopulmonary resuscitation (CPR) which helps restore spontaneous circulation (ROSC).

      Sodium bicarbonate is only prescribed in patients with cardiac arrests as a result of an overdose of tricyclic antidepressants or hyperkalaemia. Its use causes the body to produce more CO2 which causes:

      Exacerbation of intracellular acidosis
      Negative inotropy to ischaemic myocardium
      Increased osmotic load of sodium into failing brain and body
      Shift of oxygen dissociation curve to the left.

      THAM is often used to treat metabolic acidosis as a result of cardiac bypass surgery and also cardiac arrest, when other standard methods have failed.

      Carbicarb (Na2CO3 0.33 molar NaHCO3 0.33 molar) has only mild effects on acidosis. It also causes an increase in arterial CO2 pressure and lactate concentration.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 120 - The prospects of setting up a health facility to help patients with ischaemic...

    Incorrect

    • The prospects of setting up a health facility to help patients with ischaemic heart disease in a remote area are under consideration and you have been asked to look into it.

      What's the crucial factor in finding out the amount of resources needed to go ahead with the idea?

      Your Answer:

      Correct Answer: Prevalence

      Explanation:

      Both incidence and prevalence are indicators of the disease frequency. While incidence tells us about the number of cases reported per population in a provided time period, prevalence is the factor you should be vigilant about as it tells us about the total number of cases that have been reported in a population at a particular point of time.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 121 - Regarding the use of soda lime as part of a modern circle system...

    Incorrect

    • Regarding the use of soda lime as part of a modern circle system with a vaporiser outside the circuit (VOC), which of the following is its most deleterious consequence?

      Your Answer:

      Correct Answer: Carbon monoxide formation

      Explanation:

      When using dry soda lime for VOCs, very high amounts of carbon monoxide may be produced, regardless of the inhalational anaesthetic agent used. The carbon monoxide produced is sufficient enough to cause cytotoxic and anaemic hypoxia. To prevent this, soda lime canisters are shaken well to even out the packing of granules. This can help to evenly distribute gas flow for proper CO2 absorption and ventilation.

      Compound A is formed when dry soda lime, or soda lime in high temperature, reacts with the inhalational anaesthetic Sevoflurane. Animal studies have shown renal toxicity in rats, but renal adverse effects in humans are yet to be observed.

      When monitors are not employed with VOCs, deleterious effects are not for certain. However, monitors not employed with vaporiser inside the circuit (VIC) can lead to significant adverse events.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 122 - In asthmatic patients, non-steroidal anti-inflammatory analgesics (NSAIDs) are generally contraindicated.

    Which of the following...

    Incorrect

    • In asthmatic patients, non-steroidal anti-inflammatory analgesics (NSAIDs) are generally contraindicated.

      Which of the following membrane phospholipid metabolism products is most likely to cause NSAID-induced bronchospasm in asthmatic patients who are predisposed to it?

      Your Answer:

      Correct Answer: Leukotrienes

      Explanation:

      Nonsteroidal anti-inflammatory drugs (NSAIDs) cause bronchospasm, rhinorrhoea, and nasal obstruction in some asthma patients.

      The inhibition of cyclooxygenase-1 (Cox-1) appears to be the cause of NSAID-induced reactions. This activates the lipoxygenase pathway, which increases the release of cysteinyl leukotrienes (Cys-LTs), which causes bronchospasm and nasal obstruction.

      The following changes in arachidonic acid (AA) metabolism have been observed in NSAID-intolerant asthmatic patients:

      Prostaglandin E2 production is low, possibly due to a lack of Cox-2 regulation.
      An increase in leukotriene-C4 synthase expression and
      A decrease in the production of metabolites (lipoxins) released by AA’s transcellular metabolism.

      Phospholipase A produces membrane phospholipids, which are converted to arachidonic acid.

      TXA2 causes vasoconstriction as well as platelet aggregation and adhesion.

      PGI2 causes vasodilation and a reduction in platelet adhesion.

      PGE2 is involved in parturition initiation and maintenance, as well as thermoregulation.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 123 - If the speed of an ultrasound in soft tissue is 1540 meters per...

    Incorrect

    • If the speed of an ultrasound in soft tissue is 1540 meters per second, what is the estimated wavelength produced if the frequency of a generated ultrasound is 10 megahertz?

      Your Answer:

      Correct Answer: 0.15 millimetre

      Explanation:

      Wavelength can be computed as follows:

      Wavelength = velocity/frequency

      In the given problem, the values stated are:

      Frequency = 10 x 10^6
      Velocity = 1540 meters per second

      Wavelength = 1540/(10×10^6)
      Wavelength = 1540/10,000,000 meters
      Wavelength = 0.15 millimetres

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 124 - A drug with a 2-hour half-life and a first-order kinetics of elimination is...

    Incorrect

    • A drug with a 2-hour half-life and a first-order kinetics of elimination is administered intravenously. The initial plasma concentration is calculated to be 12 mcg/mL and plasma concentrations is measured hourly.

      At 6 hours, how much drug will be left?

      Your Answer:

      Correct Answer: 1.5 mcg/mL

      Explanation:

      In first order kinetics the rate of elimination is proportional to plasma concentration.

      Rate of elimination is described by the following equation:

      C = C0. e^-kt

      Where:
      C=drug concentration,
      C0= drug concentration at time zero (extrapolated),
      k = rate constant and
      t = time.

      The initial concentration of this drug is 12 mcg/ml therefore:

      The plasma concentration will have halved to 6 mcg/ml at 2 hours.
      The plasma concentration will have halved to 3 mcg/ml at 4 hours and
      The plasma concentration will have halved to 1.5 mcg/ml t 6 hours.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 125 - A 65-year-old man, presents to the emergency department. He explains that an hour...

    Incorrect

    • A 65-year-old man, presents to the emergency department. He explains that an hour ago, he experienced central chest pain, which moved down his left arm.
      On ECG, elevation in the ST-segment was noted in the anterior leads. He undergoes emergency percutaneous coronary intervention (PCI) which requires the cardiologist to access the heart via the femoral artery.

      Where is the surface marking for identifying the femoral artery?

      Your Answer:

      Correct Answer: Midway between the ASIS and the pubic symphysis

      Explanation:

      The surface marking for locating the femoral artery is the mid-inguinal point, which is the halfway point between the anterior superior iliac spine (ASIS) and the pubic symphysis.

      The other mentioned options are not specific for any landmark.

      However, it is important to note the difference between the mid inguinal point and the midpoint of the inguinal ligament, which is travels from the ASIS to the pubic tubercle.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 126 - After establishing a cardiopulmonary bypass, the right atrium is opened to repair the...

    Incorrect

    • After establishing a cardiopulmonary bypass, the right atrium is opened to repair the tricuspid valve.

      Out of the following, which is NOT a part of the right atrium?

      Your Answer:

      Correct Answer: Trabeculae carnae

      Explanation:

      The right atrium receives blood supply from the SVC, IVC, and coronary sinus. It forms the right border of the heart.

      The interior of the right atrium has 5 distinct features:
      1. Sinus venarum – smooth, thin-walled posterior part of the right atrium where the SVC, IVC, and coronary sinus open
      2. Musculi pectinati – an anterior rough, wall of pectinate muscles
      3. Tricuspid valve orifice – the opening through which the right atrium empties blood into the right ventricle
      4. Crista terminalis – separates the rough (musculi pectinati) from the smooth (sinus venarum) internally
      5. Fossa ovalis – a thumbprint size depression in the interatrial septum which is a remnant of the oval foramen and its valve in the foetus

      The trabeculae carneae are irregular muscular elevations that form the interior of the right ventricle.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 127 - At which of the following location is there no physiological oesophageal constriction? ...

    Incorrect

    • At which of the following location is there no physiological oesophageal constriction?

      Your Answer:

      Correct Answer: Lower oesophageal sphincter

      Explanation:

      The oesophagus is a muscular tube that connects the pharynx to the stomach. It begins at the lower border of the cricoid cartilage and C6 vertebra. It ends at T11.

      The oesophagus has physiological constrictions at the following levels:
      1. Cervical constriction: Pharyngo-oesophageal junction (15 cm from the incisor teeth) produced by the cricopharyngeal part of the inferior pharyngeal constrictor muscle
      2. Thoracic constrictions:
      i. where the oesophagus is first crossed by the arch of the aorta (22.5 cm from the incisor teeth)
      ii. where the oesophagus is crossed by the left main bronchus (27.5 cm from the incisor teeth)
      3. Diaphragmatic constriction: where the oesophagus passes through the oesophageal hiatus of the diaphragm (40 cm from the incisor teeth)

      Awareness of these constrictions is important for clinical purposes when it is required to pass instruments through the oesophagus into the stomach or when viewing radiographs of patients’ oesophagus.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 128 - A doctor has recorded the number of times the patient did not attend...

    Incorrect

    • A doctor has recorded the number of times the patient did not attend (DNA) the clinic for a study over a 10 month period.

      Number of DNAs in 10 Months Number of Patients
      1st Month 0
      2nd Month 3
      3rd Month 1
      4th Month 45
      5th Month 2
      6th Month 0
      7th Month 1
      8th Month 4
      9th Month 4
      10th Month 2

      Which among the following is the most apt way of summarizing mean value?

      Your Answer:

      Correct Answer: Median

      Explanation:

      Variance and standard deviation indicate the dispersion of the plot from mean value and thus are not really helpful in summarizing the mean.

      Range is the difference between maximum and minimum value that is 45 in this case.

      The mean in this case is 6.2 due to the presence of an outlier 45. In the presence of outlier mean can be misleading as it is quite sensitive to skewness in data.

      Mode is the most frequent value. In this case mode has 4 values: 0,1,2,4.

      In case of skewedness, median is the most apt representative of the mean as it is not affected by outliers. In this case since the data set has even values i.e. 10. Median is the average of the 5th & 6th entry after arranging the data in ascending order like that in case of the question (0,0,1,1,2,2,3,4,4,45). This turns out to be 2.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 129 - A 33-year-old woman known to be hypothyroid and taking 150 mcg l-thyroxine daily...

    Incorrect

    • A 33-year-old woman known to be hypothyroid and taking 150 mcg l-thyroxine daily is reviewed in the preoperative assessment clinic prior to a laparoscopic cholecystectomy.

      She has required three increases in her thyroid replacement therapy in the last six months.

      Her thyroid function tests are as follows:

      TSH 11 (normal range 0.4-4mU/L)
      T3 20 (normal range 9-25mU/L)
      T4 6.2 (normal range 3.5-7.8mU/L)

      What will explain this biochemical picture?

      Your Answer:

      Correct Answer: Poor compliance with medication

      Explanation:

      In patients with an intact hypothalamic-pituitary axis, serial TSH measurements are used to determine the adequacy of treatment with thyroid hormones . changes in TSH levels becoming apparent after approximately eight weeks of therapy with thyroid hormone replacement. Change in T3/T4 levels are seen before changes in TSH .

      In patients taking thyroid replacement therapy, the most frequent reason for persistent elevation of serum TSH is poor compliance. Patients who do not regularly take their L-thyroxine try and catch up just before a visit to a clinician for blood test.

      Tissue-level unresponsiveness to thyroid hormone is caused by mutation in the gene controlling a receptor for T3 and is rare.

      Reduced responsiveness of target tissues to thyroid hormone aka resistance to thyroid hormones (rTH) occurs when there is a mutation in the thyroid hormone receptor ? gene. It is a rare autosomal dominant inherited syndrome of reduced end-organ responsiveness to thyroid hormone and has two types:

      Generalised resistance (GrTH)
      Pituitary resistance (PrTH)

      Patients with rTH have normal or slightly elevated serum thyroid stimulating hormone (TSH) level, elevated serum free thyroxine (FT4) and free triiodothyronine (FT3) concentrations.

      Drugs that increase metabolism of thyroxine include:

      Warfarin
      Rifampin
      Phenytoin
      Phenobarbital
      St John’s Wort
      Carbamazepine

      These drugs lower circulating thyroid hormones and would be associated with a raised TSH but low T3/T4.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 130 - A weakly acidic drug with a pKa of 8.4 is injected intravenously into...

    Incorrect

    • A weakly acidic drug with a pKa of 8.4 is injected intravenously into a patient.

      At a normal physiological pH, the percentage of this drug unionised in the plasma is?

      Your Answer:

      Correct Answer: 90

      Explanation:

      Primary FRCA is concerned with two issues. The first is a working knowledge of the Henderson-Hasselbalch equation, and the second is a working knowledge of logarithms and antilogarithms.

      The pH at which the drug exists in 50 percent ionised and 50 percent unionised forms is known as the pKa.

      To calculate the proportion of ionised to unionised form of a drug, use the Henderson-Hasselbalch equation.

      pH = pKa + log ([A-]/[HA])

      or

      pH = pKa + log [(salt)/(acid)]
      pH = pKa + log ([ionised]/[unionised])

      Hence, if the pKa − pH = 0, then 50% of drug is ionised and 50% is unionised.

      In this example:
      7.4 = 8.4 + log ([ionised]/[unionised])
      7.4 − 8.4 = log ([ionised]/[unionised])
      log −1 = log ([ionised]/[unionised])

      Simply put, the antilog is the inverse log calculation. In other words, if you know the logarithm of a number, you can use the antilog to find the value of the number. The antilogarithm’s definition is as follows:

      y = antilog x = 10x

      Antilog to the base 10 of 0 = 1, −1 = 0.1, −2 = 0.01, −3 = 0.001 and, −4 = 0.0001.

      [A-]/[HA] = 0.1

      Assuming that we can apply the approximation [A-] << [HA} then this means the acid is 0.1 x 100% = 10% ionised so the percentage of (non-ionized) acid will be 100% – 10% = 90%

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 131 - A study aimed at assessing the validity of a novel diagnostic test for...

    Incorrect

    • A study aimed at assessing the validity of a novel diagnostic test for heart failure is being performed. The curators are worried that not all the patients will get the prevalent gold standard test.

      Which type of bias is that?

      Your Answer:

      Correct Answer: Work-up bias

      Explanation:

      Work up bias involves comparing the novel diagnostic test with the current standard test. A portion of the patients undergo the standard test while others undergo the new test as the standard test is costly. The result can be alteration in specify and sensitivity.

      Selection bias is when randomisation is not achieved.

      Attention bias refers to the person’s failure to consider various alternatives when he pre occupied by some other thoughts.

      Instrument bias is related to the experience and extent of familiarization of the participating individuals with the test.

      Co intervention bias is characterized by the groups receiving different co interventions.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 132 - The muscle that lies behind the first part of the axillary nerve is?...

    Incorrect

    • The muscle that lies behind the first part of the axillary nerve is?

      Your Answer:

      Correct Answer: Subscapularis

      Explanation:

      The axillary nerve lies behind the axillary artery initially, and in front of the subscapularis. It passes downward to the lower border of the subscapularis muscle.

      In company with the posterior humeral circumflex artery and vein, it winds backward through a quadrilateral space bounded above by the subscapularis (anterior) and teres minor (posterior), below by the teres major, medially by the long head of the triceps brachii, and laterally by the humerus (surgical neck).

      It then divides into an anterior and a posterior part. The anterior division supplies the deltoid (anterior and middle heads) while the posterior division supplies the teres minor and posterior part of deltoid
      The posterior division terminates as the superior lateral cutaneous nerve of the arm

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 133 - Regarding the Valsalva manoeuvre, which of the following describes the cardiovascular changes in...

    Incorrect

    • Regarding the Valsalva manoeuvre, which of the following describes the cardiovascular changes in phase III in a normal patient?

      Your Answer:

      Correct Answer: Normal intrathoracic pressure, decrease in blood pressure, and increase in heart rate

      Explanation:

      When a person forcefully expires against a closed glottis, changes occur in intrathoracic pressure that dramatically affect venous return, cardiac output, arterial pressure, and heart rate. This forced expiratory effort is called a Valsalva maneuver.

      Initially during a Valsalva, intrathoracic (intrapleural) pressure becomes very positive due to compression of the thoracic organs by the contracting rib cage. This increased external pressure on the heart and thoracic blood vessels compresses the vessels and cardiac chambers by decreasing the transmural pressure across their walls. Venous compression, and the accompanying large increase in right atrial pressure, impedes venous return into the thorax. This reduced venous return, and along with compression of the cardiac chambers, reduces cardiac filling and preload despite a large increase in intrachamber pressures. Reduced filling and preload leads to a fall in cardiac output by the Frank-Starling mechanism. At the same time, compression of the thoracic aorta transiently increases aortic pressure (phase I); however, aortic pressure begins to fall (phase II) after a few seconds because cardiac output falls. Changes in heart rate are reciprocal to the changes in aortic pressure due to the operation of the baroreceptor reflex. During phase I, heart rate decreases because aortic pressure is elevated; during phase II, heart rate increases as the aortic pressure falls.

      When the person starts to breathe normally again, the intrathoracic pressure declines to normal levels, the aortic pressure briefly decreases as the external compression on the aorta is removed, and heart rate briefly increases reflexively (phase III). This is followed by an increase in aortic pressure (and reflex decrease in heart rate) as the cardiac output suddenly increases in response to a rapid increase in cardiac filling (phase IV). Aortic pressure also rises above normal because of a baroreceptor, sympathetic-mediated increase in systemic vascular resistance that occurred during the Valsava.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 134 - Dinamap is an automated blood pressure monitoring device. Which of these statements best...

    Incorrect

    • Dinamap is an automated blood pressure monitoring device. Which of these statements best fit its properties?

      Your Answer:

      Correct Answer: The cuff should be positioned at the same level as the heart

      Explanation:

      Dinamap continuously measures the systolic, diastolic and mean arterial pressure along with pulse rate, thereby providing a continuous monitoring of the blood pressure using the osscillitonometric principle of measurement.

      The device loses accuracy towards the extremes of BP and is more accurate with systolic compared with diastolic pressure. In arrhythmias such as AF, the devices are also inaccurate due to the major fluctuations associated with the individual pulse pressure variations.

      The manual BP device is still the gold standard for BP measurement and monitoring.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 135 - It was hypothesized that people that had lower socio economic status were more...

    Incorrect

    • It was hypothesized that people that had lower socio economic status were more prone to developing gastric cancer. After 30 years of studying people with lower socio economic status, it was found that they did have a greater tendency to develop cancer. As a result of that the authors got to the conclusion that a strong association existed between the two. Later on another study conducted found that people from lower socio economic back grounds also had a tendency to be smokers.


      Which form of potential bias can be associated with this particular study?

      Your Answer:

      Correct Answer: Confounding bias

      Explanation:

      Selection bias is when randomisation is not achieved and is often a result of in efficient recruiting method.

      Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.

      Measurement bias can be characterized by gathering of information in a manner that is distorted.

      When the participants of a research study are recruited from the hospitals rather than the general population, its called Berkson Bias.

      Confounding bias is the major player here because in this case the effects of smoking can be masked behind and can be read as outcomes of lower socio economic status. This extraneous factor (Smoking), distorts the founding.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 136 - A 28-year-old man is admitted to the critical care unit. He has been...

    Incorrect

    • A 28-year-old man is admitted to the critical care unit. He has been diagnosed with adult respiratory distress syndrome and is being ventilated. His haemodynamic condition is improved using a pulmonary artery flotation.

      His readings are listed below:

      Haemoglobin concentration: 10 g/dL
      Mixed venous oxygen saturation: 70%
      Mixed venous oxygen tensions (PvO2): 50 mmHg

      Estimate his mixed venous oxygen content (mL/100mL).

      Your Answer:

      Correct Answer: 9.5

      Explanation:

      Mixed venous oxygen content (CvO2) is the oxygen concentration in 100mL of mixed venous blood taken from the pulmonary artery. It is usually 12-17 mL/dL (70-75%). It is represented mathematically as:

      CvO2 = (1.34 x Hgb x SvO2 x 0.01) + (0.003 x PvO2)

      Where,

      1.34 = Huffner’s constant
      Hgb = Haemoglobin level (g/dL)
      SvO2 = % oxyhaemoglobin saturation of mixed venous blood
      PvO2 = 0.0225 = mL of O2 dissolved per 100mL plasma per kPa, or 0.003 mL per mmHg

      Therefore,

      CvO2 = (1.34 x 10 x 70 x 0.01) + (0.003 x 50)

      CvO2 = 9.38 + 0.15 = 9.53 mL/100mL

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 137 - Which of the following statement is false regarding dopamine? ...

    Incorrect

    • Which of the following statement is false regarding dopamine?

      Your Answer:

      Correct Answer: Urine output decreases due to inhibition of proximal tubule Na+ reabsorption

      Explanation:

      Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic ? and?1 (but not ?2 ) agonist.

      The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of Dopamine dilates these vessels (by raising intracellular cAMP). This increases g.f.r. In addition, DA exerts a natriuretic effect by D1 receptors on proximal tubular cells.

      Moderately high doses produce a positive inotropic (direct?1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.

      Vasoconstriction (?1 action) occurs only when large doses are infused.

      At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.

      Dopamine is less arrhythmogenic than adrenaline

      Regarding dopamine part of the dose is converted to Noradrenaline in sympathetic nerve terminals.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 138 - Out of the following, which is NOT true regarding the external carotid? ...

    Incorrect

    • Out of the following, which is NOT true regarding the external carotid?

      Your Answer:

      Correct Answer: It ends by bifurcating into the superficial temporal and ascending pharyngeal artery

      Explanation:

      The external carotid artery has eight important branches:
      Anterior surface:
      1. Superior thyroid artery (first branch)
      2. Lingual artery
      3. Facial artery
      Medial branch
      4. Ascending pharyngeal artery
      Posterior branches
      5. Occipital artery
      6. Posterior auricular artery
      Terminal branches
      7. Maxillary artery
      8. Superficial temporal artery

      The external carotid has eight branches, 3 from its anterior surface ; thyroid, lingual and facial. The pharyngeal artery is a medial branch. The posterior auricular and occipital are posterior branches.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 139 - Which nerve does NOT pass through the posterior triangle of the neck? ...

    Incorrect

    • Which nerve does NOT pass through the posterior triangle of the neck?

      Your Answer:

      Correct Answer: Ansa cervicalis

      Explanation:

      The sternocleidomastoid muscle divides the neck into anterior and posterior triangles on both sides of the neck.

      The posterior triangle has the following boundaries:
      anteriorly – sternocleidomastoid muscle
      posteriorly – trapezius
      roof – investing layer of deep cervical fascia
      floor – prevertebral fascia overlying splenius capitis, levator scapulae, and the scalene muscles

      The contents of the posterior triangle are:
      1. fat
      2. lymph nodes (level V)
      3. accessory nerve
      4. cutaneous branches of the cervical plexus – greater auricular nerve, transverse cervical nerve, lesser occipital nerve, supraclavicular nerve (A major branch of this plexus is the phrenic nerve, which arises from the anterior divisions of spinal nerves C3-C5)
      5. inferior belly of omohyoid
      6. branches of the thyrocervical trunk (transverse cervical and suprascapular arteries)
      7. third part of the subclavian artery
      8. external jugular vein

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 140 - A 50-year-old woman's blood pressure readings in the clinic are 170/109 mmHg, 162/100...

    Incorrect

    • A 50-year-old woman's blood pressure readings in the clinic are 170/109 mmHg, 162/100 mmHg and 175/107 mmHg and her routine haematology, biochemistry, and 12-lead ECG are normal.

      She is assessed on the day of surgery prior to laparoscopic inguinal hernia repair and is found to be normally fit and well. Documentation of previous blood pressure measurements from her general practitioner in the primary healthcare setting are not available.

      What is your next course of action?

      Your Answer:

      Correct Answer: Proceed with scheduled surgery without treatment

      Explanation:

      The AAGBI and the British Hypertension Society has published guidelines for the measurement of adult blood pressure and management of hypertension before elective surgery.

      The objective is to ensure that patients admitted for elective surgery have a known systolic blood pressure below 160 mmHg and diastolic blood pressures below 100 mmHg. The primary health care teams, if possible, should ensure that this is the case and provide evidence to the pre-assessment clinic staff or on admission.

      Avoiding cancellation on the day of surgery because of white coat hypertension is a secondary objective.

      Patients with blood pressures below 180 mmHg systolic and 110 mmHg diastolic (measured in the preop assessment clinic), who present to pre-operative assessment clinics without documented evidence of primary care blood pressures should proceed to elective surgery.

      In this question, the history/assessment does not appear to point to obvious end-organ damage so there is no indication for further investigation for secondary causes of hypertension or an echocardiogram at this point. Further review and treatment at this point is not required.

      However, you should write to the patient’s GP and encourage serial blood pressure measurements in the primary health care setting.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 141 - Which of the following lung parameters can be measured directly using spirometry? ...

    Incorrect

    • Which of the following lung parameters can be measured directly using spirometry?

      Your Answer:

      Correct Answer: Vital capacity

      Explanation:

      Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).

      It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.

      During spirometry, the following measurements can be determined:
      Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
      Forced expiratory volume in one second (FEV1)
      FEV1/FVC ratio
      Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
      Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
      Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.

      Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.

      Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution

      The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 142 - The average diastolic blood pressure of a control group was found out to...

    Incorrect

    • The average diastolic blood pressure of a control group was found out to be 80 with a standard deviation of 5 in a study aimed at exploring the efficiency of a novel anti-hypertensive drug. The trial was randomised.

      Making an assumption that the data is normally distributed, find out the number of patients that had diastolic blood pressure over 90.

      Your Answer:

      Correct Answer: 3%

      Explanation:

      Since the data is normally distributed, 95% of the values lie with in the interval 70 to 90. This can be calculated as follows:

      Interval= Mean ± ( 2 times standard deviation)
      = 80 ± 2(5)
      = 80 ± 10
      = 70 & 90

      The rest of the 5% are distributed symmetrically beyond 90 and below 70 which means 2.5% of the values lie above 90.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 143 - Regarding the emergency oxygen flush, which is true? ...

    Incorrect

    • Regarding the emergency oxygen flush, which is true?

      Your Answer:

      Correct Answer: May lead to awareness if used inappropriately

      Explanation:

      When the emergency oxygen flush is pressed, 100% oxygen is supplied from the common gas outlet. This gas bypasses BOTH flowmeters and vaporisers. The flow of oxygen is usually 45 l/min at a PRESSURE OF 400 kPa.

      There is an increased risk of pulmonary barotrauma when the emergency flush is pressed, especially when anaesthetising paediatric patients.

      The inappropriate use of the flush causes dilution of anaesthetic gases and this increases the possibility of anaesthetic awareness .

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 144 - A 64-year old male has shortness of breath on exertion and presented to...

    Incorrect

    • A 64-year old male has shortness of breath on exertion and presented to the cardiology clinic. He has a transthoracic echo performed to help in assessing the function of his heart.
      How can this echo aid in calculating cardiac output?

      Your Answer:

      Correct Answer: (end diastolic LV volume - end systolic LV volume) x heart rate

      Explanation:

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 145 - During a squint surgery, a 5-year-old child developed severe bradycardia as a result...

    Incorrect

    • During a squint surgery, a 5-year-old child developed severe bradycardia as a result of the oculocardiac reflex.

      The afferent limb of this reflex is formed by which nerve?

      Your Answer:

      Correct Answer: Trigeminal nerve

      Explanation:

      When the eye is compressed or the extra-ocular muscles are tractioned, the oculocardiac reflex causes a decrease in heart rate.

      The ophthalmic division of the trigeminal nerve provides the afferent limb. This synapses with the vagus nerve’s visceral motor nucleus in the brainstem. The efferent signal is carried by the vagus nerve to the heart, where increased parasympathetic tone reduces sinoatrial node output and slows heart rate.

      The most common symptom is sinus bradycardia, but junctional rhythm and asystole can also occur.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 146 - A 21-year-old woman presents to ER following the deliberate ingestion of 2 g...

    Incorrect

    • A 21-year-old woman presents to ER following the deliberate ingestion of 2 g of amitriptyline. On clinical examination:
      Glasgow coma score: 10
      Pulse rate: 140 beats per minute
      Blood pressure: 80/50 mmHg.
      ECG showed a QRS duration of 233 Ms.

      Which of the following statement describes the most important initial course of action?

      Your Answer:

      Correct Answer: Give fluid boluses

      Explanation:

      The first line of treatment in case of hypotension is fluid resuscitation.

      Activated charcoal can be used within one hour of tricyclic antidepressant ingestion but an intact and secure airway must be checked before intervention. The risk of aspiration should be assessed.

      Vasopressors are indicated for the treatment of hypotension following (Tricyclic Antidepressant) TCA overdose when patients fail to respond to fluids and bicarbonate.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 147 - Left ventricular afterload is mostly calculated from systemic vascular resistance.

    Which...

    Incorrect

    • Left ventricular afterload is mostly calculated from systemic vascular resistance.

      Which one of the following factors has most impact on systemic vascular resistance?

      Your Answer:

      Correct Answer: Small arterioles

      Explanation:

      Systemic vascular resistance (SVR), also known as total peripheral resistance (TPR), is the amount of force exerted on circulating blood by the vasculature of the body. Three factors determine the force: the length of the blood vessels in the body, the diameter of the vessels, and the viscosity of the blood within them. The most important factor that determines the systemic vascular resistance (SVR) is the tone of the small arterioles.

      These are otherwise known as resistance arterioles. Their diameter ranges between 100 and 450 µm. Smaller resistance vessels, less than 100 µm in diameter (pre-capillary arterioles), play a less significant role in determining SVR. They are subject to autoregulation.

      Any change in the viscosity of blood and therefore flow (such as due to a change in haematocrit) might also have a small effect on the measured vascular resistance.

      Changes of blood temperature can also affect blood rheology and therefore flow through resistance vessels.

      Systemic vascular resistance (SVR) is measured in dynes·s·cm-5

      It can be calculated from the following equation:

      SVR = (mean arterial pressure − mean right atrial pressure) × 80 cardiac output

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 148 - Which of the following statements is NOT true regarding soda lime? ...

    Incorrect

    • Which of the following statements is NOT true regarding soda lime?

      Your Answer:

      Correct Answer: It mostly contains sodium hydroxide

      Explanation:

      Soda-lime contains mostly calcium hydroxide (about 94%) and remaining sodium hydroxide.

      CO2 + Ca(OH)2 → CaCO3 + H2O + heat
      Here in this exothermic reaction, we can see that the production of calcium carbonate does not require heat.

      When soda lime is allowed to dry with subsequent use of desflurane, isoflurane, and enflurane, it can lead to the generation of carbon monoxide.

      Silica hardens the granules and can thus prevent disintegration.

      The size of soda-lime granules is 4-8 mesh because it allows sufficient surface area for chemical reaction to occur without critically increasing the resistance to airflow.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 149 - Which of the following factors significantly increases the risk of hepatotoxicity and fulminant...

    Incorrect

    • Which of the following factors significantly increases the risk of hepatotoxicity and fulminant hepatic failure in halothane administration?

      Your Answer:

      Correct Answer: Multiple exposure

      Explanation:

      Hepatotoxicity due to halothane administration is relatively common and is a major factor in its rapidly declining use. Type 1 hepatotoxicity has an incidence of 20% to 30%. A comprehensive report in 1969 demonstrated an incidence of type 2 hepatotoxicity (hepatitis) of 1 case per 6000 to 20000 cases, with fatal cases occurring approximately once in 35000 patients following a single exposure to the anaesthetic. This incidence of fatal cases increases to approximately 1 in 1000 patients following multiple exposures. Following this study was a large-scale review in the United Kingdom, which showed similar results. To put this into perspective, there is only a single case of hepatotoxicity confirmed after the administration of desflurane and 2 cases per 1 million after enflurane. By the 1970s, halothane was the most common cause of drug-induced liver failure.

      Halothane-induced hepatotoxicity has a female to male ratio of two to one. Younger patients are less likely to be affected; 80% of the cases are typically in patients 40 years or older. Other risk factors include obesity and underlying liver dysfunction. Medications such as phenobarbital, alcohol, and isoniazid may play a role in affecting CYP2E1 metabolism, increasing one’s risk.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 150 - All of the following statements about intravenous induction agents are false except: ...

    Incorrect

    • All of the following statements about intravenous induction agents are false except:

      Your Answer:

      Correct Answer:

      Explanation:

      Thiopental is a new British Approved Name for thiopentone and is thio-barbiturate.
      Methohexitone is an oxy- barbiturate. Both thiopental and methohexitone are intravenous induction agents.

      Ketamine cannot cause loss of consciousness in less than 30 seconds. At least 30 seconds is needed to cause loss of consciousness following intravenous administration.

      Etomidate is an imidazole but it is not used in the Intensive Care unit for sedation because it has an antidepressant effect on the steroid axis.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 151 - A 61-year-old woman with myasthenia gravis is admitted to the ER with type...

    Incorrect

    • A 61-year-old woman with myasthenia gravis is admitted to the ER with type II respiratory failure. There is a suspicion of myasthenic crisis.

      She is in a semiconscious state. Her blood pressure is 160/90 mmHg, pulse is 110 beats per minute, temperature is 37°C, and oxygen saturation is 84 percent.

      With a PaCO2 of 75 mmHg (10 kPa) breathing air, blood gas analysis confirms she is hypoventilating.

      Which of the following values is the most accurate representation of her alveolar oxygen tension (PAO2)?

      Your Answer:

      Correct Answer: 7.3

      Explanation:

      The following is the alveolar gas equation:

      PAO2 = PiO2 − PaCO2/R

      Where:

      PAO2 is the partial pressure of oxygen in the alveoli.
      PiO2 is the partial pressure of oxygen inhaled.
      PaCO2 stands for partial pressure of carbon dioxide in the arteries.
      The amount of carbon dioxide produced (200 mL/minute) divided by the amount of oxygen consumed (250 mL/minute) equals R = respiratory quotient. With a normal diet, the value is 0.8.

      By subtracting the partial pressure exerted by water vapour at body temperature, the PiO2 can be calculated:

      PiO2 = 0.21 × (100 kPa − 6.3 kPa)
      PiO2 = 19.8

      Substituting:
      PAO2 = 19.8 − 10/0.8
      PAO2 = 19.8 − 12.5
      PAO2 = 7.3k Pa

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 152 - Which of the following statement regarding Adrenaline (Epinephrine) is not true? ...

    Incorrect

    • Which of the following statement regarding Adrenaline (Epinephrine) is not true?

      Your Answer:

      Correct Answer: Inhibits glycolysis in muscle

      Explanation:

      Adrenaline acts on ?1, ?2,?1, and ?2 receptors and also on dopamine receptors (D1, D2) and have sympathomimetic effects.

      Natural catecholamines are Adrenaline, Noradrenaline, and Dopamine

      Adrenaline is a sympathomimetic amine with both alpha and beta-adrenergic stimulating properties.
      Adrenaline is the drug of choice for anaphylactic shock
      Adrenaline is also used in patients with cardiac arrest. The preferred route is i.v. followed by the intra-osseous and endotracheal route.

      Adrenaline is released by the adrenal glands, acts on ? 1 and 2, ? 1 and 2 receptors, and is responsible for fight or flight response.

      It acts on ? 2 receptors in skeletal muscle vessels-causing vasodilation.

      It acts on ? adrenergic receptors to inhibit insulin secretion by the pancreas. It also stimulates glycogenolysis in the liver and muscle, stimulates glycolysis in muscle.

      It acts on ? adrenergic receptors to stimulate glucagon secretion in the pancreas
      It also stimulates Adrenocorticotrophic Hormone (ACTH) and stimulates lipolysis by adipose tissue

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 153 - Which of the following statements about a cervical rib is correct? ...

    Incorrect

    • Which of the following statements about a cervical rib is correct?

      Your Answer:

      Correct Answer: It originates from the 7th cervical vertebra

      Explanation:

      The costal elements of the seventh cervical vertebrae form projections known as cervical ribs, which are present in approximately 0.5% – 1 % individuals.

      A cervical rib commonly comprises of a head, neck and tubercle. The body of the rib varies from person to person. It extends into the posterior triangle of the neck, where it is either free anteriorly, or attached to the first rib / sternum.

      Patients with a cervical rib mostly are asymptomatic and it is usually diagnosed as an incidental finding on chest x-ray. However, in some cases, the subclavian artery and the lower trunk of the brachial plexus are compressed where they pass over the cervical rib. This leads to a condition known as ”neurovascular compression syndrome,” in which these neurovascular structures are compressed between the cervical rib and scalenus anterior.

      The most common cause of neurogenic symptoms in approximately 80% of the patients with cervical rib is neck trauma.

      In most cases, the tingling, numbness and impaired circulation to the upper limb appears only after puberty. This is because the neck elongates, and the shoulders droop slightly.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 154 - A new drug treatment has been developed for Crohn's disease. The pharmaceutical company...

    Incorrect

    • A new drug treatment has been developed for Crohn's disease. The pharmaceutical company behind this, is planning to conduct a trial and is looking for hiring around 200 individuals that are suffering from Crohn's disease. The aim would be to determine if there is any decline in the disease activity in response to the drug and compare it with a placebo.

      What phase is the trial in?

      Your Answer:

      Correct Answer: Phase 2

      Explanation:

      The study is being conducted on a smaller level with only 200 participants and is determining the effectiveness of the drug in comparison to a placebo. These characteristics are in accordance with the second phase of trial.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 155 - What structure is most critical in providing support for the duodenojejunal flexure? ...

    Incorrect

    • What structure is most critical in providing support for the duodenojejunal flexure?

      Your Answer:

      Correct Answer: Ligament of Treitz

      Explanation:

      The duodenojejunal flexure is the point where the duodenum becomes the jejunum.

      The ligament of Treitz, which arises from the right crus of diaphragm, provides suspension for support.

      Between the ileum and the caecum is the ligament of Treves.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 156 - When describing the surface anatomy of the sacrum, which of the following anatomical...

    Incorrect

    • When describing the surface anatomy of the sacrum, which of the following anatomical landmarks refers to the base of an equilateral triangle is formed by the sacral hiatus?

      Your Answer:

      Correct Answer: A line connecting the posterior superior iliac spines

      Explanation:

      The apex of an equilateral triangle completed by the posterior superior iliac spines is where the sacral hiatus or sacrococcygeal membrane can normally located. The failure of posterior fusion of the laminae of the fourth and fifth sacral vertebrae allows the sacral canal to be accessible via the membrane.

      In adults, the spine of L4 usually lies on a line drawn between the highest points of the iliac crests (Tuffier’s line). A line connecting each anterior iliac spine, approximates to the L3/4 interspace in the sitting position. Both of these options are incorrect.

      A line connecting the greater trochanters is also incorrect.

      A line connecting the posterior superior iliac spines is correct, but in adults the presence of a sacral fat pad can still make identification of this landmark less straightforward.

      The processes of S5 are remnants only and form the sacral cornua, which are also used to help identify the sacral hiatus.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 157 - The liver plays a major role in drug metabolism.

    Which of the following...

    Incorrect

    • The liver plays a major role in drug metabolism.

      Which of the following liver cells is most important in phase I of drug metabolism?

      Your Answer:

      Correct Answer: Centrilobular cells

      Explanation:

      The metabolism of drugs in the liver occurs in 3 phases

      Phase I: This involves functionalization reactions, which are of 3 types, namely hydrolysis, oxidation and reduction reactions catalysed by the cytochrome P450 (CYP) enzymes.

      Phase II: This involves conjugation or acetylation reactions. The goal is to create water soluble metabolites that can be excreted from the body.

      The liver is the second largest organ. It’s smallest functional unit is the acinus which is divided into 3 zones:

      Zone I (periportal): This zone receives the largest amount of oxygen supply as it is the closest to the blood vessels. It is the site of plasma protein synthesis.

      Zone II (mediolobular): This is located between the portal triad and central vein.

      Zone III (centrilobular): This is closest to the central vein and receives the least amount of oxygen supply.

      Kupffer cells are specialized macrophages found in the periportal zone of the liver, and function to remove foreign particles and breakdown red blood cells via phagocytosis.

      Ito cells are fat-storing liver cells found in the space of Disse. Their function is to take-uo, store and secrete retinoids, as well as manufacture and release proteins that make up the extracellular matrix.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 158 - With regards to oxygen delivery in the body, which of these statements is...

    Incorrect

    • With regards to oxygen delivery in the body, which of these statements is true?

      Your Answer:

      Correct Answer: Anaemia will reduce oxygen delivery

      Explanation:

      Oxygen delivery depends on 2 variables.
      1) Content of oxygen in blood
      2) Cardiac output

      Oxygen content (arterial) = (Hb (g/dL) x 1.39 x SaO2 (%) ) + (0.023 x PaO2 (kPa))

      Oxygen content (mixed venous) = (Hb (g/dL) x 1.39 x mixed venous saturation) + (0.023 x mixed venous partial pressure of oxygen in kPA)

      Huffner’s constant = 1.39 = 1g of Hb binds to 1.39 ml of O2

      Oxygen delivery DO2 (ml/min) = 10 x Cardiac output (L/min) x Oxygen content
      Normally 1000ml/min

      Oxygen consumption VO2 (ml/min) = 10 x Cardiac output (L/min) x Difference in arterial and mixed venous oxygen content
      Normally 250 ml/min

      Oxygen extraction ratio (OER) = VO2/DO2
      Normally approximately 25%

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 159 - Which drug, if given to a pregnant woman, can lead to deleterious fetal...

    Incorrect

    • Which drug, if given to a pregnant woman, can lead to deleterious fetal effects due to its ability to cross the placenta?

      Your Answer:

      Correct Answer: Atropine

      Explanation:

      It is well known that atropine will cross the placenta and that maternal administration results in an increase in fetal heart rate.

      Atropine is highly selective for muscarinic receptors. Its potency at nicotinic receptors is much lower, and actions at non-muscarinic receptors are generally undetectable clinically. Atropine does not distinguish among the M1, M2, and M3 subgroups of muscarinic receptors. In contrast, other antimuscarinic drugs are moderately selective for one or another of these subgroups. Most synthetic antimuscarinic drugs are considerably less selective than atropine in interactions with nonmuscarinic receptors.

      A study on glycopyrrolate, a quaternary ammonium salt, was found to have a fetal: maternal serum concentration ratio of 0.4 indicating partial transfer.

      Heparin, suxamethonium, and vecuronium do not cross the placenta.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 160 - An inguinal hernia repair under general anaesthesia is scheduled for a fit 36-year-old...

    Incorrect

    • An inguinal hernia repair under general anaesthesia is scheduled for a fit 36-year-old man (75 kg). For perioperative and postoperative analgesia, you decide to perform an inguinal field block.

      Which of the following local anaesthetic solutions is the most appropriate?

      Your Answer:

      Correct Answer: 30 mL bupivacaine 0.5%

      Explanation:

      Perioperative and postoperative analgesia can both be provided by an inguinal hernia field block. The Iliohypogastric and ilioinguinal nerves, as well as the skin, superficial fascia, and deeper structures, must be blocked for maximum effectiveness. The local anaesthetic should ideally have a long duration of action, be highly concentrated, and have a volume of at least 30 mL.

      Plain bupivacaine has a maximum safe dose of 2 mg/kg body weight.

      Because the patient weighs 75 kg, 150 mg bupivacaine can be safely administered. Both 30 mL 0.5 percent bupivacaine (150 mg) and 60 mL 0.25 percent bupivacaine (150 mg) are acceptable doses, but 30 mL 0.5 percent bupivacaine represents the optimal volume and strength, potentially providing a denser and longer block.

      The maximum safe dose of plain lidocaine has been estimated to be between 3.5 and 5 mg/kg. The patient weighs 75 kg and can receive a maximum of 375 mg using the higher dosage regimen:

      There are 200 mg of lidocaine in 10 mL of 2% lidocaine (and therefore 11 mL contains 220 mg)
      200 mg of lidocaine is contained in 20 mL of 1% lidocaine.

      While alternatives are available, Although the doses of 11 mL lidocaine 2% and 20 mL lidocaine 1% are well within the dose limit, the volumes used are insufficient for effective field block for this surgery.

      With 1 in 200,000 epinephrine, the maximum safe dose of lidocaine is 7 mg/kg. The patient can be given 525 mg in this case. Even with epinephrine, 60 mL of 1% lidocaine is 600 mg, which could be considered an overdose.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 161 - One of the following neuromuscular blocking agents is the most potent: ...

    Incorrect

    • One of the following neuromuscular blocking agents is the most potent:

      Your Answer:

      Correct Answer: Vecuronium

      Explanation:

      The measure of drug potency or therapeutic response is the ED95. This is defined as the dose of a neuromuscular blocking drug required to produce a 95% depression of muscle twitch height. The ED50 and ED90 describe a depression of twitch height by 50% and 90% respectively.

      The ED95 (mg/kg) of the commonly used neuromuscular blocking agents are:

      suxamethonium: 0.27
      rocuronium: 0.31
      vecuronium: 0.04
      pancuronium: 0.07
      cisatracurium: 0.04
      mivacurium: 0.08

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 162 - A 60-year-old man, with a history of excessive alcohol intake, presents for the...

    Incorrect

    • A 60-year-old man, with a history of excessive alcohol intake, presents for the first time in the emergency department with acute abdominal pain in the epigastric region.

      On examination, the man is sweating and has a high-grade fever. His heart rate is 140/min and a BP of 92/59 mmHg.

      The patient is diagnosed with acute pancreatitis. Which of the following is a complication you are most likely to see in this patient?

      Your Answer:

      Correct Answer: Blue discolouration of the flank regions

      Explanation:

      Bulky, greasy stools are associated with improper digestion that can be expected if the pancreas loses its exocrine function. This is common in long-term chronic pancreatitis but since this is the patient’s first presentation with such symptoms, this complication is unlikely.

      Peripheral neuropathy is a common complication of chronic diabetes but has been reported with cases of chronic pancreatitis too.

      Abdominal distention with shifting dullness is a classic symptom of underlying ascites. Ascites is a complication of many diseases but it is not common with the acute first-time presentation of pancreatitis.

      Option E: This points towards abdominal obstruction but in the absence of the more common symptoms, nausea and bilious vomiting, this is unlikely.

      Option A: Grey Turner’s sign is the pooling of blood in the retroperitoneal space between the last rib and the top of the hip. The pancreas is a retroperitoneal organ and inflammation of the pancreas can cause retroperitoneal haemorrhage. The sign takes 24-48 hours to develop and can predict a severe attack of acute pancreatitis. The patient has presented with acute pancreatitis due to his history of high alcohol intake, and acute on chronic is unlikely as this is his first presentation. He also has low blood pressure and an increased heart rate, which suggest blood loss with acute pancreatitis.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 163 - Given the following hormones, which of these will stimulate glycogenesis and gluconeogenesis? ...

    Incorrect

    • Given the following hormones, which of these will stimulate glycogenesis and gluconeogenesis?

      Your Answer:

      Correct Answer: Corticosteroids

      Explanation:

      Insulin is the primary anabolic hormone that dominates regulation of metabolism during digestive phase. It promotes glucose uptake in skeletal myocytes and adipocytes, and other insulin-target cells. It promotes glycogenesis and inhibits gluconeogenesis.

      Glucagon is the primary counterregulatory hormone that increases blood glucose levels, primarily through its effects on liver glucose output.

      Similar to glucagon, growth hormone, catecholamines and corticosteroids are also counterregulatory factors released in response to decreased glucose concentrations. Growth hormone promotes glycogenolysis and inhibits gluconeogenesis; catecholamines stimulate glycogenolysis and gluconeogenesis; while corticosteroids stimulate glycogenesis and gluconeogenesis.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 164 - Fixed performance devices like high air flow oxygen enrichment (HAFOE) masks have large...

    Incorrect

    • Fixed performance devices like high air flow oxygen enrichment (HAFOE) masks have large volumes of air entrained into a flow of 100% oxygen.

      The term that best describes the physics behind air entrainment is?

      Your Answer:

      Correct Answer: Bernoulli's principle

      Explanation:

      Bernoulli’s principle states that as the speed of a moving fluid increases, there is a simultaneously decrease in static pressure or a decrease in the fluid’s potential energy.
      This is seen in the simultaneous increase in speed and kinetic energy and fall in pressure that causes entrainment of large volumes of air into a flow of 100% oxygen in the nozzle of HAFOE masks.

      The reduction in fluid pressure that happens when a fluid flows through a constriction in a tube is the Venturi effect.

      When a flow of gas or liquid attaches itself to a nearby surface and remains attached even when the surface curves away from the initial direction of flow, this is the Coanda effect.

      The branch of engineering and technology that is concerned with the building of devices that use the flow and pressure of a fluid for functions usually performed by electronic devices is Fluidics . Fluidic logic is used to power some ventilators.

      The branch of engineering that utilises pressurised gases is Pneumatics.

    • This question is part of the following fields:

      • Basic Physics
      0
      Seconds
  • Question 165 - A young woman presented with a gynaecological related infection and was prescribed a...

    Incorrect

    • A young woman presented with a gynaecological related infection and was prescribed a cephalosporin. Which of the following is correct about the mechanism of action of this drug?

      Your Answer:

      Correct Answer: Bacterial cell wall synthesis inhibition

      Explanation:

      Cephalosporin belongs to a family of beta-lactam antibiotics. All ?-lactam antibiotics interfere with the synthesis of the bacterial cell walls. The ?-lactam antibiotics inhibit the transpeptidases so that cross-linking (which maintains the close-knit structure of the cell wall) does not take place i.e. they inhibit bacterial cell wall formation.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 166 - A 20-year-old man has been diagnosed with mitral regurgitation. He will be treated...

    Incorrect

    • A 20-year-old man has been diagnosed with mitral regurgitation. He will be treated with mitral valve repair.

      What is true regarding the mitral valve?

      Your Answer:

      Correct Answer: Its closure is marked by the first heart sound

      Explanation:

      The mitral valve is the valve between the left atrium and left ventricle. It opens when the heart is in diastole (relaxation) which allows blood to flow from the left atrium to the left ventricle. In systole (contraction), the mitral valve closes to prevent the backflow of blood from the left ventricle to the left atrium.

      The mitral valve is located posterior to the sternum at the level of the 4th costal cartilage. It is best auscultated over the cardiac apex, where its closure marks the first heart sound.

      The mitral valve anatomy is composed of five main structures:
      1. Left atrial wall – the myocardium of the left atrial wall extends over the posterior leaflet of the mitral valve. (left atrial enlargement is one of the causes for mitral regurgitation)
      2. Mitral annulus – a fibrous ring that connects with the anterior and posterior leaflets. It functions as a sphincter that contracts and reduces the surface area of the valve during systole (Annular dilatation can also lead to mitral regurgitation)
      3. Mitral valve leaflets (cusps) – The mitral valve is the only valve in the heart with two cusps or leaflets. One anterior and one posterior.
      i. The anterior leaflet is located posterior to the aortic root and is also anchored to the aortic root.
      ii. The posterior leaflet is located posterior to the two commissural areas.
      4. Chordae tendinae – The chordae tendinae connects both the cusps to the papillary muscles.
      5. Papillary muscles – These muscles and their cords support the mitral valve, allowing the cusps to resist the pressure developed during contractions (pumping) of the left ventricle

      The anterior and posterior cusps are attached to the chordae tendinae which itself is attached to the left ventricle via papillary muscle.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 167 - Which of the following statement is not true regarding Adrenaline or Epinephrine? ...

    Incorrect

    • Which of the following statement is not true regarding Adrenaline or Epinephrine?

      Your Answer:

      Correct Answer: Inhibits Glucagon secretion in the pancreas

      Explanation:

      Adrenaline acts on ?1, ?2,?1, and ?2 receptors and also on dopamine receptors (D1, D2) and have sympathomimetic effects.

      Natural catecholamines are Adrenaline, Noradrenaline, and Dopamine

      Adrenaline is a sympathomimetic amine with both alpha and beta-adrenergic stimulating properties.
      Adrenaline is the drug of choice for anaphylactic shock
      Adrenaline is also used in patients with cardiac arrest. The preferred route is i.v. followed by the intra-osseous and endotracheal route.

      Adrenaline is released by the adrenal glands, acts on ? 1 and 2, ? 1 and 2 receptors, and is responsible for fight or flight response.

      It acts on ? 2 receptors in skeletal muscle vessels-causing vasodilation.

      It acts on ? adrenergic receptors to inhibit insulin secretion by the pancreas. It also stimulates glycogenolysis in the liver and muscle, stimulates glycolysis in muscle.

      It acts on ? adrenergic receptors to stimulate glucagon secretion in the pancreas. It also stimulates Adrenocorticotrophic Hormone (ACTH) and stimulates lipolysis by adipose tissue

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 168 - An experiment is designed to investigate that how three diets having different sugar...

    Incorrect

    • An experiment is designed to investigate that how three diets having different sugar content affect the body weight to a different level.

      Which one of the following test will determine a statistically significant difference among the diets?

      Your Answer:

      Correct Answer: ANOVA

      Explanation:

      Chi-square test is used to determine the statistically significant different between categorical variables. It also determines the difference between expected frequencies and the observed frequencies.

      Mann Whitney U test is used to determine the statistically significant different between two independent groups.

      Wilcoxon’s test is the test of dependency. it determines the statistically significant difference between two dependent groups.

      Student t-test is one of the most commonly used method to test the hypothesis. It determines the significant difference between the means of two different groups.

      ANOVA (analysis of variance) is similar to student’s t-test.

      ANOVA is a statistical method used to determines the statistically significant difference between the mean of more than two group. In this experiment as we are dealing with three different group, ANOVA is most suitable test to determine the difference between each groups.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 169 - The Medical Admissions unit receives a 71-year-old woman. She has type 2 diabetes,...

    Incorrect

    • The Medical Admissions unit receives a 71-year-old woman. She has type 2 diabetes, which she manages with diet, but she has been feeling ill for the past 48 hours.

      Her pulse rate is 110 beats per minute, her blood pressure is 90/50 mmHg, and she is clinically dehydrated. Her respiratory rate is 20 breaths per minute, and chest auscultation reveals no focal signs.

      The following are the lab results:

      Glucose 27.4 mmol/L (3.5-5.5)
      Ketones 2.5 mmol/L (<0.1)
      Urinary glucose is zero (dipstick) with ketones

      A random blood glucose of 15.3 mmol/L was measured during a visit to the diabetic clinic one month prior to admission, according to her notes, and a urinary dipstick registered a high glucose and ketones++.

      The discrepancy between plasma and urinary glucose measurements is best explained by which of the following physiological mechanisms?

      Your Answer:

      Correct Answer: The glomerular filtration rate is abnormally low

      Explanation:

      The glucose molecule enters the Bowman’s capsule freely and becomes part of the filtrate.

      All glucose is reabsorbed in the proximal convoluted tubule when blood glucose concentrations are below a certain threshold (approximately 11 mmol/L) (PCT). Active transportation makes this possible. In the proximal tubular cells, sodium/glucose cotransporters (SGLT1 and SGLT2) are the proteins responsible.

      Glucose does not normally appear in the urine below the renal threshold.

      The renal glucose threshold is not set in stone and is affected by a variety of factors, including GFR, TmG, and the quantity of splay.

      The different absorptive and filtering capacities of individual nephrons cause splay, which is the rounding of a glucose reabsorption curve.

      The SGLT proteins have a high affinity for glucose, but not an infinite affinity. As a result, some glucose may escape reabsorption before the TmG. A decrease in renal threshold may be caused by an increase in splay.

      Because the filtered glucose load is reduced and the PCT can reabsorb all of the filtered glucose despite hyperglycaemia, a low GFR causes an increase in TmG. In contrast, lowering the TmG lowers the threshold because the tubules’ ability to reabsorb glucose is reduced.

      A reduction in GFR caused by severe dehydration and reduced perfusion pressure is the most obvious cause of the discrepancy between plasma and urinary glucose in this scenario.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 170 - A 70-year-old male is brought to the Emergency department with:
    Pulse rate:...

    Incorrect

    • A 70-year-old male is brought to the Emergency department with:
      Pulse rate: 32 beats per minute
      Blood pressure: 82/35 mmHg
      12 lead ECG shows a sinus bradycardia of 35 beats per minute with no evidence of myocardial ischemia or infarction. There was no chest pain but the patient feels light-headed.

      Which of the following would be the best initial treatment for this condition?

      Your Answer:

      Correct Answer: Atropine

      Explanation:

      Based on the presenting symptoms and clinical examination, it is a case of an adult sinus bradycardia with adverse signs. The first pharmacological treatment for this condition is atropine 500mcg intravenously and if necessary repeat every three to five minutes up to a maximum of 3 mg.

      If the bradycardia does not subside even after the administration of atropine, cardiac pacing should be considered. If pacing cannot be achieved promptly, we should consider the use of second-line drugs like adrenaline, dobutamine, or isoprenaline.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 171 - A 50-year old man for septoplasty has a BMI of 32kg/m2 and neck...

    Incorrect

    • A 50-year old man for septoplasty has a BMI of 32kg/m2 and neck circumference of 44 cm. He is troubled by intermittent nasal obstruction which causes his partner sleeps in a separate bedroom because of snoring. He currently on ramipril for hypertension.

      Which of the following best approximates to his STOP-BANG score from the information above?

      Your Answer:

      Correct Answer: 5

      Explanation:

      The STOP-BANG questionnaire is used to screen patients for obstructive sleep apnoea (OSA).

      The scoring system assigns one point for each feature.

      S: Snoring (louder than talking or loud enough to be heard through closed doors)
      T: Feeling tired, fatigued, or sleepy during daytime
      O: Observed apnoeas during sleep
      P: Hypertension
      B: BMI more than 35 kg/m2
      A: Age 50-years of age or greater
      N: Neck circumference (male 17 inches / 43cm or greater and female 16 inches / 41 or greater)
      G: Gender: Male

      Our patient has a score of 5 ( O, P, A, N, G)

      The score helps clinicians stratify patients for unrecognized OSA and target appropriate clinical management. It can also help triage patients for further investigation. A STOP-BANG score of 5-8 will identify patients with high probability of moderate to severe OSA in the surgical population.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 172 - Which statement is true with regards to the cardiac action potential? ...

    Incorrect

    • Which statement is true with regards to the cardiac action potential?

      Your Answer:

      Correct Answer: Repolarization due to potassium efflux after calcium channels close causes the relative refractory period to start

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 173 - All of the following statements about calcium channel antagonists are incorrect except: ...

    Incorrect

    • All of the following statements about calcium channel antagonists are incorrect except:

      Your Answer:

      Correct Answer: May cause potentiation of muscle relaxants

      Explanation:

      Calcium channel blocker (CCB) blocks L-type of voltage-gated calcium channels present in blood vessels and the heart. By inhibiting the calcium channels, these agents decrease the frequency of opening of calcium channels activity of the heart, decrease heart rate, AV conduction, and contractility.

      Three groups of CCBs include
      1) Phenylalkylamines: Verapamil, Norverapamil
      2) Benzothiazepines : Diltiazem
      3) Dihydropyridine : Nifedipine, Nicardipine, Nimodipine, Nislodipine, Nitrendipine, Isradipine, Lacidipine, Felodipine and Amlodipine.

      Even though verapamil as good absorption from GIT, its oral bioavailability is low due to high first-pass metabolism.

      Nimodipine is a Cerebro-selective CCB, used to reverse the compensatory vasoconstriction after sub-arachnoid haemorrhage and is more lipid soluble analogue of nifedipine

      Calcium channel antagonist can potentiate the effect of non-depolarising muscle relaxants.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 174 - A 72-year old man is experiencing a cardiac risk evaluation for the management...

    Incorrect

    • A 72-year old man is experiencing a cardiac risk evaluation for the management of obstructive umbilical hernia. Echocardiogram demonstrates an aortic valve area=0.59cm with a pressure of 70mmHg. Five years ago, he had mild myocardial infarction complicated with pulmonary oedema. Now he encounters angina with little exertion.

      Which of the following factor is the foremost profoundly weighted using Deysky's cardiac risk scoring system in this case?

      Your Answer:

      Correct Answer: Aortic stenosis

      Explanation:

      Detsky’s Modified cardiac risk classification system in patients undergoing non-cardiac surgery:

      Age more than 70: 05 points

      History of myocardial infarction:

      Less than 6 months: 10 points
      More than 6 months: 5 points

      Angina Pectoris:

      Angina with minimal exertion: 10 points

      Angina at any level of exertion: 20 points

      Pulmonary Oedema:

      Within 7 days: 10 points
      At any time: 5 points

      Suspected aortic valve stenosis with valve area <0.6cm2: 20 points Arrhythmia: Any rhythm other than sinus or sinus with premature atrial complexes (PACs): 5 points More than 5 premature ventricular contractions: 5 points
      Emergency Surgery: 10 points
      Deficient general medical condition: 5 points

      Risk classification:

      Grade I: 0-15 points = low risk
      Grade II: 15-30 points = moderate risk
      Grade III: >30 points = high risk

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 175 - A 25 year-old female came to the out-patient department with complaints of vaginal...

    Incorrect

    • A 25 year-old female came to the out-patient department with complaints of vaginal discharge with a distinct fishy odour. She was later diagnosed with bacterial vaginosis and was prescribed to take metronidazole.

      The mechanism of action of metronidazole is?

      Your Answer:

      Correct Answer: Interferes with bacterial DNA synthesis

      Explanation:

      Metronidazole is a nitroimidazole antiprotozoal drug that is selectively absorbed by anaerobic bacteria and sensitive protozoa. Once taken up be anaerobes, it is nonenzymatically reduced by reacting with reduced ferredoxin. This reduction results in products that accumulate in and are toxic to anaerobic cells. The metabolites of metronidazole are taken up into bacterial DNA, forming unstable molecules. This action occurs only when metronidazole is partially reduced, and, because this reduction usually happens only in anaerobic cells, it has relatively little effect on human cells or aerobic bacteria.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 176 - An aged patient that has been suffering from diabetes criticised the health minister...

    Incorrect

    • An aged patient that has been suffering from diabetes criticised the health minister for his comments on incidence and prevalence. The minister had said that they both are two separate entities. It can be therefore inferred that the patient thinks that prevalence and incidence are the same thing.

      Is he right?

      Your Answer:

      Correct Answer: No. In chronic disease prevalence is greater than incidence.

      Explanation:

      Only on rare occasions has it been found that the prevalence and incidence were same. Incidence can be greater than prevalence in acute cases only. In case of chronic diseases prevalence is far greater than incidence. One needs to have a deeper understanding of both the concepts to understand the health literature.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 177 - How many unpaired branches leave the abdominal aorta to supply the abdominal viscera?...

    Incorrect

    • How many unpaired branches leave the abdominal aorta to supply the abdominal viscera?

      Your Answer:

      Correct Answer: Three

      Explanation:

      The abdominal arteries are divided into 3 branches;
      – 3 main unpaired trunks (celiac trunk, superior mesenteric, inferior mesenteric arteries)
      – 6 paired branches
      – unpaired median sacral artery.

      We can group the abdominal aorta as follows;
      -Ventral which includes: Coeliac trunk, superior mesenteric and inferior mesenteric arteries
      -Lateral: Inferior phrenic, middle suprarenal, renal and gonadal arteries
      -Dorsal: Lumbar and median sacral arteries
      -Terminal : Right and left common iliac arteries

      The celiac trunk (L1) takes blood the foregut and its found posterior to the stomach. The unpaired superior mesenteric artery supplies blood to the mid-gut.

      The paired renal arteries form the inferior suprarenal arteries. The renal arteries arise around L1/L2 and takes blood to either side of the kidneys.

      The median sacral artery supplies blood to the lumbar vertebrae the L4 and L5.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 178 - You are asked about the relative risk associated with a drug. You happened...

    Incorrect

    • You are asked about the relative risk associated with a drug. You happened to have read a report in which the same drug was compared with a placebo and your initial thoughts after reading the study were that the drug will have significant side effects.

      What do you expect the value of relative risk to be?

      Your Answer:

      Correct Answer: Greater than 1

      Explanation:

      Risk ratio (relative risk) compares the probability of an event in an exposed (experimental) group to that of an event in the unexposed (control) group.

      A relative risk of 1 suggests that there is no discernible difference in the outcome whether or not it has been exposed.

      A relative risk of less than 1 indicates that probability of occurrence of an event is less if there is exposure.

      A relative risk of greater than 1 highlights that an event is most likely to occur if it was provided exposure. Since you believe that exposure (the new drug) would have side effects, the value should be greater than 1.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 179 - Of the stated laws, which is correct? ...

    Incorrect

    • Of the stated laws, which is correct?

      Your Answer:

      Correct Answer: Boyle's law states that at constant temperature the volume of a given mass of gas varies inversely with absolute pressure.

      Explanation:

      Boyle’s law is correctly stated as it states that the volume of a gas of known mass is inversely proportional with absolute pressure, at a constant temperature.

      Beer’s law states that radiation absorption by a solution of known thickness and concentration is identical to that of a solution of double thickness and half concentration.

      Bougner’s (or Lambert’s) law states that every layer with the same thickness will absorb the same amount of radiation as it passes through.

      Graham’s law states that the diffusion rate of a gas is inversely related to the square root of its molecular weight.

      Raoult’s law states that the reduction of a solvent’s vapour pressure is directly proportional to the solute’s molar concentration.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 180 - A patient admitted to the hospital is on oxygen via a venturi mask....

    Incorrect

    • A patient admitted to the hospital is on oxygen via a venturi mask.
      The air entrainment ratio is 1:9 i.e. 1 litre of 100% oxygen from the source entrains 9 litres of air from the atmosphere). The flow rate of 100% oxygen is 6L/minute.

      Based on the given data which of the following value approximates the oxygen concentration delivered to the patient?

      Your Answer:

      Correct Answer: 28%

      Explanation:

      The formula for calculating air: oxygen entrainment ratio is given as :
      100% − FiO2 = air/oxygen entrainment ratio
      Since FiO2 − 21% and the entrainment ratio is already known. Substituting the values in the equation: x = FiO2.

      100 − x = 9
      x − 21
      100 − x = 9(x − 21)
      100 − x = 9x − 189
      10x = 289
      x = 289/10
      x = 28.9%

    • This question is part of the following fields:

      • Basic Physics
      0
      Seconds
  • Question 181 - A 68-year old female is brought to the Emergency Room for abdominal pain....

    Incorrect

    • A 68-year old female is brought to the Emergency Room for abdominal pain. Medical history revealed that she is on long-term warfarin therapy for deep vein thrombosis.

      Upon further investigation, the patient is hypotensive at 80/60 mmHg, and an abdominal mass is palpable on the umbilical area. An initial diagnosis of ruptured abdominal aortic aneurysm (AAA) is made. Moreover, blood tests show an international normalised ratio (INR) of 4.2.

      Which of the following products should be initially transfused or administered to the patient to reverse the anticoagulation?

      Your Answer:

      Correct Answer: Prothrombin complex

      Explanation:

      Warfarin prevents reductive metabolism of the inactive vitamin K epoxide back to its active hydroquinone form. Thus, warfarin inhibits the synthesis of vitamin K dependent clotting factors: X, IX, VII, II (prothrombin), and of the anticoagulants protein C and protein S. The therapeutic range for oral anticoagulant therapy is defined in terms of an international normalized ratio (INR). The INR is the prothrombin time ratio (patient prothrombin time/mean of normal prothrombin time for lab)ISI, where the ISI exponent refers to the International Sensitivity Index and is dependent on the specific reagents and instruments used for the determination. A prolonged INR is widely used as an indication of integrity of the coagulation system in liver disease and other disorders, it has been validated only in patients in steady state on chronic warfarin therapy.

      Prothrombin complex concentrate (PCC) is used to replace congenital or acquired vitamin-K deficiency warfarin-induced anticoagulant effect, particularly in the emergent setting.

      Intravenous vitamin K has a slower onset of action compared to PCC, but is useful for long term therapy.

      Fresh frozen plasma (FFP) prepared from freshly donated blood is the usual source of the vitamin K-dependent factors and is the only source of factor V. The factors needed, however, are found in small quantities compared to PCC.

      Cryoprecipitate is indicated for hypofibrinogenemia/dysfibrinogenemia, von Willebrand disease, haemophilia A, factor XIII deficiency, and management of bleeding related to thrombolytic therapy.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 182 - The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised...

    Incorrect

    • The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised by which of the following?

      Your Answer:

      Correct Answer: Synthesis of ATP is brought about by anaerobic respiration

      Explanation:

      Muscle fibre myosin ATPase histochemistry is used to divide the biochemical classification into two groups: type 1 and type II.

      Type I (slow twitch) muscle fibres rely on aerobic glycolytic and aerobic oxidative metabolism to function. They have a lot of mitochondria, a good blood supply, a lot of myoglobin, and they don’t get tired easily.

      Because they contain more motor units, Type II (fast twitch) muscle fibres are thicker. They are more easily fatigued, but produce powerful bursts. The capillary networks and mitochondria are less dense in these white muscle fibres than in type I fibres. They have a low myoglobin content as well.

      Muscle fibres of type II (fast twitch) are divided into three types:

      Type IIa – aerobic/oxidative metabolism is used.
      Type IIb – anaerobic/glycolytic metabolism is used by these fibres.

      When compared to skeletal muscle, cardiac and smooth muscle twitch at a slower rate.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 183 - During a fight, a 20-year-old male is stabbed in the thigh with a...

    Incorrect

    • During a fight, a 20-year-old male is stabbed in the thigh with a bottle. He is admitted for treatment.

      Which feature, if present, suggests an injury to the femoral nerve?

      Your Answer:

      Correct Answer: Loss of knee reflex

      Explanation:

      Femoral nerve lesion (L2,L3 and L4) is characterised by weakness of the quadriceps femoris muscle. This results in weakness of extension of the knee, loss of sensation over the front of the thigh, and loss of the knee jerk reflex.

      The skin over the lateral aspect of the thigh and knee, and the lower lateral quadrant of the buttock is supplied by the lateral cutaneous nerve of the thigh (L1,2).

      The adductors of the hip are supplied by the obturator nerve (L2-4). This nerve also supplies sensation to the inner thigh.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 184 - Over the course of 10 minutes, a normally fit and well 22-year-old male...

    Incorrect

    • Over the course of 10 minutes, a normally fit and well 22-year-old male receives a 1 litre intravenous bolus of 20% albumin.

      Which of the following primary physiological responses in this patient has the highest chance to influence a change in urine output?

      Your Answer:

      Correct Answer: Stimulation of atrial natriuretic peptide (ANP) secretion

      Explanation:

      The renal effects of atrial natriuretic peptide (ANP) secretion are as follows:

      Increased glomerular filtration rate by dilating the afferent glomerular arteriole. Moreover, it constricts the efferent glomerular arteriole, and relaxes the mesangial cells.
      Reduces sodium reabsorption in the collecting ducts and distal convoluted tubule.
      The renin-angiotensin system (RAS) is inhibited.
      Blood flow in the vasa recta is increased.

      Because plasma osmolality is unlikely to change, hypothalamic osmoreceptors are unaffected.

      The plasma protein has a molecular weight of 66 kDa, is not normally filtered into the proximal convoluted tubule, and has no osmotic diuretic effect.

      The following are some basic assumptions:

      Extracellular fluid (ECF) makes up one-third of total body water (TBW), while intracellular fluid makes up the other two-thirds (ICF)
      One-quarter plasma and three-quarters interstitial fluid make up ECF (ISF)
      The volume receptors in the atria have a 7-10% blood volume change threshold.
      The osmoreceptors are sensitive to changes in osmolality of 1-2 percent.
      The normal plasma osmolality before the transfusion is 287-290 mOsm/kg.
      The plasma protein solution is a colloid that is only delivered to the intravascular compartment. The tonicity remains unchanged.
      The blood volume increases by 20%, from 5,000 mls to 6,000 mls. This is higher than the volume receptor threshold of 7 to 10%.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 185 - Volunteers are being recruited for a new clinical trial of a novel drug...

    Incorrect

    • Volunteers are being recruited for a new clinical trial of a novel drug treatment for Ulcerative colitis. The proposed study will enrol about 2000 people with ulcerative colitis. Testing will be performed to assess any reduction in disease severity with the new drug as compared to the current treatment available in the industry.

      Which phase of clinical trial will this be?

      Your Answer:

      Correct Answer: Phase 3

      Explanation:

      This clinical trial consists over 1000 patients being evaluated for the response to a new treatment against a currently licensed treatment for ulcerative colitis. Therefore, it is comparing its efficacy to an established therapeutic or control in a larger population of volunteers. These are the characteristics of a phase III clinical trial.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 186 - A 55-year-old woman presents for transsphenoidal surgery following a diagnosis of pituitary macroadenoma.

    Which...

    Incorrect

    • A 55-year-old woman presents for transsphenoidal surgery following a diagnosis of pituitary macroadenoma.

      Which of the following is the most common visual field defect caused by such lesions?

      Your Answer:

      Correct Answer: Bitemporal hemianopia

      Explanation:

      Pituitary tumours that compress the optic chiasma primarily affect the neurones that decussate at this location. Bitemporal hemianopia is caused by neurones that emerge from the nasal half of the retina and transmit the temporal half of the visual field.

      The axons of ganglion cells in the retina form the optic nerve.

      It exits the orbit through the optic foramen and projects to the thalamic lateral geniculate body. The optic chiasma forms above the sella turcica as the nasal fibres decussate along the way. The optic radiation travels from the lateral geniculate body to the occipital cortex.

      Lesions at various points along this pathway cause the following visual field defects:

      Scotoma implies partial retinal or optic nerve damage.
      Monocular vision loss occurs when the optic nerve is completely damaged.
      Pathology at the optic chiasma causes bitemporal hemianopia.
      Cortical blindness with occipital cortex pathology and homonymous hemianopia with lesions compromising the optic radiation.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 187 - Venepuncture is being performed on the basilic vein in the cubital fossa. At...

    Incorrect

    • Venepuncture is being performed on the basilic vein in the cubital fossa. At which of the following points does the basilic vein pass deep under the muscle?

      Your Answer:

      Correct Answer: Midway up the humerus

      Explanation:

      The basilic vein is one of the primary veins that drain the upper limb, like the cephalic vein. It begins as the dorsal venous arch. The basilic vein originates from the ulnar side of the dorsal arch of the upper limb passes along the posteromedial aspect of the forearm, moving towards the anterior surface of the elbow.

      The basilic vein pierces the deep fascia at the elbow and joins the venae commitantes of the brachial vein to form the axillary vein.

      The basilic vein passes deep under the muscles as it moves midway up the humerus. At the lower border of the teres major muscle, the anterior and posterior circumflex humeral veins feed into it.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 188 - Following a traumatic head injury, you are summoned to the emergency department to...

    Incorrect

    • Following a traumatic head injury, you are summoned to the emergency department to transfer a patient to the CT scanner. With a Glasgow coma score of 3, he has already been intubated and ventilated.

      It is important to ensure that cerebral protection strategies are implemented during the transfer.

      Which of the following methods is the most effective for reducing venous obstruction?

      Your Answer:

      Correct Answer: Position with a head-up tilt of 30°

      Explanation:

      ICP is significant because it influences cerebral perfusion pressure and cerebral blood flow. The normal ICP ranges from 5 to 13 mmHg.

      The components within the skull include the brain (80%/1400 ml), blood (10%/150 ml), and cerebrospinal fluid (CSF) (10%/150 ml).

      Because the skull is a rigid box, if one of the three components increases in volume, one or more of the remaining components must decrease in volume to compensate, or the ICP will rise (Monroe-Kellie hypothesis).

      Primary brain injury occurs as a result of a head injury and is unavoidable unless precautions are taken to reduce the risk of head injury. A reduction in oxygen delivery due to hypoxemia (low arterial PaO2) or anaemia, a reduction in cerebral blood flow due to hypotension or reduced cardiac output, and factors that cause a raised ICP and reduced CPP are all causes of secondary brain injury. Secondary brain injury can be avoided with proper management.

      The most important initial management task is to make certain that:

      There is protection of the airway and the cervical spine
      There is proper ventilation and oxygenation
      Blood pressure and cerebral perfusion pressure are both adequate (CPP).

      Following the implementation of these management principles, additional strategies to reduce ICP and preserve cerebral perfusion are required. The volume of one or more of the contents of the skull can be reduced using techniques that can be used to reduce ICP.

      Reduce the volume of brain tissue
      Blood volume should be reduced.
      CSF volume should be reduced.

      The following are some methods for reducing the volume of brain tissue:
      Abscess removal or tumour resection
      Steroids (especially dexamethasone) are used to treat oedema in the brain.
      To reduce intracellular volume, use mannitol/furosemide or hypertonic saline.
      To increase intracranial volume, a decompressive craniectomy is performed.

      The following are some methods for reducing blood volume:

      Haematomas must be evacuated.
      Barbiturate coma reduces cerebral metabolic rate and oxygen consumption, lowering cerebral blood volume as a result.
      Hypoxemia, hypercarbia, hyperthermia, vasodilator drugs, and hypotension should all be avoided in the arterial system.
      PEEP/airway obstruction/CVP lines in neck: patient positioning with 30° head up, avoid neck compression with ties/excessive rotation, avoid PEEP/airway obstruction/CVP lines in neck

      The following are some methods for reducing CSF volume:

      To reduce CSF volume, an external ventricular drain or a ventriculoperitoneal shunt is inserted (although more a long term measure).

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 189 - The action potential in a muscle fibre is initiated by which of these...

    Incorrect

    • The action potential in a muscle fibre is initiated by which of these ions?

      Your Answer:

      Correct Answer: Sodium ions

      Explanation:

      The cardiac action potential has several phases which have different mechanisms of action as seen below:
      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 190 - What statement about endotoxins is true? ...

    Incorrect

    • What statement about endotoxins is true?

      Your Answer:

      Correct Answer: Can often survive autoclaving

      Explanation:

      Endotoxins are the lipopolysaccharides found in the outer cell wall of Gram-negative bacteria. They are responsible for providing the structure and stability of the cell wall.

      They cannot be destroyed by normal sterilisation as they are heat stable molecules. They require the use of certain sterilant such as superoxide, peroxide and hypochlorite to be neutralised.

      They stimulate strong immune responses, but can only be destroyed partially by specific antibodies. Repeat infections occur as memory T cells cannot be formed.

      It can cause septicaemia and associated symptoms such as fever, shock, hypotension and nausea.

      It activates the alternative complement pathway and the coagulation pathway using secreted cytokines.

      It is not involved in botulism as clostridium botulinum, the responsible organism, secretes a neurotoxic exotoxin.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 191 - Which of the following correctly explains the mechanism of sevoflurane preconditioning? ...

    Incorrect

    • Which of the following correctly explains the mechanism of sevoflurane preconditioning?

      Your Answer:

      Correct Answer: Opening of mitochondrial KATP channels

      Explanation:

      Sevoflurane is highly fluorinated methyl isopropyl ether widely used as an inhalational anaesthetic. It is suggested that sevoflurane preconditioning occurs via the opening of mitochondrial Potassium ATP dependent channel similar to that of Ischemic Preconditioning protection.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 192 - A 28-year-old girl, Sam, has suffered a road traffic accident. She is brought...

    Incorrect

    • A 28-year-old girl, Sam, has suffered a road traffic accident. She is brought to the emergency department and undergoes investigations and treatment.

      On X-ray of the humerus, she has a mid-shaft fracture.

      What structure is at the highest risk of damage with a mid-shaft humeral fracture?

      Your Answer:

      Correct Answer: Radial nerve

      Explanation:

      Mid-shaft fractures of the humerus usually occur after a direct blow to the upper arm, which can occur after a fall or RTAs.
      The most important clinical significance of a mid-shaft humeral fracture is an injury to the radial nerve. The radial nerve originates from the brachial plexus and has roots of C5-T1. It crosses the spiral groove on the posterior side of the shaft of the humerus.
      On examination, the patient may have a wrist drop, loss or weakness of finger extension, and decreased or absent sensation to the posterior forearm, digits 1 to 3, and the radial half of the fourth digit.

      The humeral shaft has two compartments:
      1. Anterior:
      Brachial artery and vein
      Biceps brachii, brachialis, coracobrachialis
      Musculocutaneous, median, and ulnar nerves
      2. Posterior:
      Radial nerve
      Triceps

      Other significant nerve injuries are:
      1. Axillary nerve – surgical neck fracture of the humerus
      2. Brachial Artery – supracondylar fracture of the humerus
      3. Axillary artery – surgical neck fracture of the humerus, but is relatively uncommon

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 193 - Which muscle separates the subclavian artery and the subclavian vein? ...

    Incorrect

    • Which muscle separates the subclavian artery and the subclavian vein?

      Your Answer:

      Correct Answer: Scalenus anterior

      Explanation:

      The subclavian artery and vein have a similar path throughout their course, with the subclavian vein running anterior to the subclavian artery. The artery and vein are separated by the insertion of the scalenus anterior muscle.

      There are three scalene muscles, found on each side of the neck:
      1. Anterior scalene
      2. Middle scalene
      3. Posterior scalene

      The scalenus anterior muscle is the anterior most of the three scalene muscles. It originates from the transverse processes of vertebrae C3-C6 and is inserted in the first rib.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 194 - A 28-year male patient presents to the GP with a 2-day history of...

    Incorrect

    • A 28-year male patient presents to the GP with a 2-day history of abdominal pain and bloody diarrhoea. He reports that he was completely fine until one week ago when headache and general tiredness appeared. After further questioning, he revealed eating at a dodgy takeaway 3 days before the start of his symptoms.

      Which of the following diagnosis is most likely?

      Your Answer:

      Correct Answer: Campylobacter

      Explanation:

      Giardiasis is known to have a longer incubation time and doesn’t cause bloody diarrhoea.

      Cholera usually doesn’t cause bloody diarrhoea.

      Generally, most of the E.coli strains do not cause bloody diarrhoea.

      Diverticulitis can be a cause of bloody stool but the history here points out to an infectious cause.

      Campylobacter infection is the most probable cause as it is characterized by a prodrome, abdominal pain and bloody diarrhoea

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 195 - What part of the male urethra is completely surrounded by Bucks fascia? ...

    Incorrect

    • What part of the male urethra is completely surrounded by Bucks fascia?

      Your Answer:

      Correct Answer: Spongiosa part

      Explanation:

      Bucks fascia refers to the layer of loose connective tissue, nerves and blood vessels that encapsulates the penile erectile bodies, the corpa cavernosa and the anterior part of the urethra, including the entirety of the spongiose part of the urethra.

      It runs with the external spermatic fascia and the penile suspensory ligament.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 196 - After consuming 12 g of paracetamol, a 37-year-old man is admitted to the...

    Incorrect

    • After consuming 12 g of paracetamol, a 37-year-old man is admitted to the medical admissions unit. He has hepatocellular necrosis in both clinical and biochemical aspects.

      The most significant reason for paracetamol causing toxicity is?

      Your Answer:

      Correct Answer: Glutathione is rapidly exhausted

      Explanation:

      Phase I and phase II metabolism are used by the liver to break down paracetamol.

      1st Phase:

      Prostaglandin synthetase and cytochrome P450 (CYP1A2, CYP2E2, CYP3A4 and CYP2D6) to N-acetyl-p-benzoquinoneimine (NAPQI) and N-acetylbenzo-semiquinoneimine. NAPQI is a toxic metabolite that binds to the sulfhydryl groups of cellular proteins in hepatocytes, making it toxic. This can result in centrilobular necrosis.

      Glutathione and glutathione transferases prevent NAPQI from binding to hepatocytes at low paracetamol doses by preferentially binding to these toxic metabolites. The cysteine and mercapturic acid conjugates are then excreted in the urine. Depletion of glutathione occurs at higher doses of paracetamol, resulting in high levels of NAPQI and the risk of hepatocellular damage. Hepatotoxicity would not be an issue if the body’s glutathione stores were sufficient.

      N-acetylcysteine is a precursor for glutathione synthesis and is the drug of choice for the treatment of paracetamol overdose.

      Phase II:

      Conjugation with glucuronic acid to paracetamol glucuronide is the most common method of metabolism and excretion, accounting for 60% of renally excreted metabolites. Paracetamol sulphate (35%), unchanged paracetamol (5%), and mercapturic acid are among the other renally excreted metabolites (3 percent ). The capacity of conjugation pathways is limited. The capacity of the sulphate conjugation pathway is lower than that of the glucuronidation pathway.

      Because of the low pH in the stomach, paracetamol absorption is minimal (pKa value is 9.5). Paracetamol is absorbed quickly and completely in the alkaline environment of the small intestine. Oral bioavailability is extremely high, approaching 100%.

      As a result, measuring paracetamol levels in plasma after an injury is important. Peak plasma concentrations are reached after 30-60 minutes, with a volume of distribution of 0.95 L/kg. It binds to plasma proteins at a rate of 10% to 25%.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 197 - A 77-year-old woman is scheduled for day case cataract surgery under local anaesthesia....

    Incorrect

    • A 77-year-old woman is scheduled for day case cataract surgery under local anaesthesia. She has no cardiac or respiratory problems. Lisinopril is being used to treat her hypertension, which is under control.

      Which of the following preoperative investigations are the most appropriate for this patient?

      Your Answer:

      Correct Answer: No investigations

      Explanation:

      Because the patient has mild systemic disease, he is ASA 2 and the procedure will be performed under local anaesthesia.

      The following factors should be considered when requesting preoperative investigations:

      Indications derived from a preliminary clinical examination
      Whether or not a general anaesthetic will be used, the possibility of asymptomatic abnormalities, and the scope of the surgery.

      No special investigations are needed if the patient has no history of significant systemic disease and no abnormal findings on examination during the nurse-led assessment.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 198 - The spinal cord in a neonate terminates at the lower border of: ...

    Incorrect

    • The spinal cord in a neonate terminates at the lower border of:

      Your Answer:

      Correct Answer: L3

      Explanation:

      The spinal cord and the vertebral canal are as long as each other in early fetal life. The length of the cord increases faster than the growth of the vertebrae during development. By the time of birth, the spinal cord is at the level of the lower border of the 3rd lumbar vertebra, compared to its original position at the level of the 2nd coccygeal vertebra.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 199 - All of the following are causes of hypalbuminaemia except: ...

    Incorrect

    • All of the following are causes of hypalbuminaemia except:

      Your Answer:

      Correct Answer: Starvation

      Explanation:

      Major surgery induces the systemic inflammatory response and this causes endothelial leakage and a low albumin level.

      Albumin is a single polypeptide which is made but not stored in the liver. Therefore, levels are a reflection of synthetic activity. It is negatively charged and very soluble.

      Only 40% of albumin is intravascular, and the rest in the in interstitial compartment.

      If there was normal liver function during starvation, albumin will be maintained and proteolysis will occur elsewhere.
      It is not catabolised during starvation.
      Starvation and malnutrition may, however, present as part of other disease processes that are associated with hypalbuminaemia.

      Causes of low albumin are

      1. Decreased production (hepatic dysfunction)
      2. Increased loss (renal dysfunction)
      3. Redistribution (endothelial leak/damage)
      4. Increased catabolism (very rare)

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 200 - If a patient is to be placed under general anaesthesia using total intravenous...

    Incorrect

    • If a patient is to be placed under general anaesthesia using total intravenous technique with target-controlled infusions of propofol and remifentanil, what safety precaution is the most vital in this a scenario?

      Your Answer:

      Correct Answer: Cannula access site clearly visible and regularly checked

      Explanation:

      According to the Safe Anaesthesia Liaison Group, the most important factor to consider the cannula access, and if the patient is properly receiving the total intravenous anaesthesia. The cannula access must be regularly checked for kinks, leaks and disconnections.

      Below are the safety precautions and policies to be followed for total intravenous anaesthesia among children and adults:

      When administering TIVA, a non-return valve must be used on any intravenous fluid line;
      When using equipment, it is essential that clinical staff know its limitations and uses;
      Sites of intravenous infusions should be visible so they may be monitored for disconnection, leaks or perivenous infusion into the subcutaneous tissues; and,
      Organisations must give preference to clearly labelled intravenous connectors and valves.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Pharmacology (1/1) 100%
Statistical Methods (1/1) 100%
Physiology (1/3) 33%
Physiology And Biochemistry (2/2) 100%
Clinical Measurement (2/2) 100%
Anaesthesia Related Apparatus (0/1) 0%
Anatomy (1/1) 100%
Passmed