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Question 1
Correct
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What is the name of the space between the vocal cords?
Your Answer: Rima glottidis
Explanation:The rima glottidis is a narrow, triangle-shaped opening between the true vocal cords.
The vocal folds (true vocal cords) control sound production. The apex of each fold projects medially into the laryngeal cavity.
Each vocal fold includes these vocal ligaments:
Vocalis muscle (most medial part of thyroarytenoid muscle)
The glottis is composed of the vocal folds, processes and rima glottidis.
The rima glottidis is the narrowest potential site within the larynx, as the vocal cords may be completely opposed, forming a complete barrier.
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This question is part of the following fields:
- Anatomy
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Question 2
Correct
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Regarding amide local anaesthetics, which one factor has the most significant effect on its duration of action?
Your Answer: Protein binding
Explanation:When drugs are bound to proteins, drugs cannot cross membranes and exert their effect. Only the free (unbound) drug can be absorbed, distributed, metabolized, excreted and exert pharmacologic effect. Thus, when amide local anaesthetics are bound to ?1-glycoproteins, their duration of action are reduced.
The potency of local anaesthetics are affected by lipid solubility. Solubility influences the concentration of the drug in the extracellular fluid surrounding blood vessels. The brain, which is high in lipid content, will dissolve high concentration of lipid soluble drugs. When drugs are non-ionized and non-polarized, they are more lipid-soluble and undergo more extensive distribution. Hence allowing these drugs to penetrate the membrane of the target cells and exert their effect.
Tissue pKa and pH will determine the degree of ionization.
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This question is part of the following fields:
- Physiology
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Question 3
Incorrect
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A graph is created to show the exponential relationship between bacterial growth (y-axis) and time (x-axis).
Which of the following statements is most true about this kind of exponential relationship?Your Answer: The negative x axis is a horizontal asymptote
Correct Answer: y = ex
Explanation:The relationship between bacterial growth and time is a tear-away exponential. The mathematical relationship between y and x in this case is:
y = ex
Where: the power is x, and the base is e.
Euler’s number (e) is a mathematical constant that is the base for all logarithms occurring naturally. Its value is 2.718.
The statement X increasing with an increase in Y is proportional to Y refers to the change in y in terms of x when considering any exponential relationship.
This is not a build-up exponential, and that is mathematically stated as y = 1-e-kt.
The negative x axis being a horizontal asymptote and the y intercept being 0, 1 are examples of tearaway exponentials , but do not describe an exponential process.
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This question is part of the following fields:
- Statistical Methods
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Question 4
Correct
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Which of the following is a correctly stated fundamental (base) SI unit?
Your Answer: A metre is the unit of length
Explanation:The international system of units, or system international d’unites (SI) is a collection of measurements derived from expanding the metric system.
There are seven base units, which are:
Metre (m): a unit of length
Second (s): a unit of time
Kilogram (kg): a unit of mass
Ampere (A): a unit of electrical current
Kelvin (K): a unit of thermodynamic temperature
Candela (cd): a unit of luminous intensity
Mole (mol): a unit of substance. -
This question is part of the following fields:
- Clinical Measurement
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Question 5
Correct
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All of the following statements about calcium channel antagonists are incorrect except:
Your Answer: May cause potentiation of muscle relaxants
Explanation:Calcium channel blocker (CCB) blocks L-type of voltage-gated calcium channels present in blood vessels and the heart. By inhibiting the calcium channels, these agents decrease the frequency of opening of calcium channels activity of the heart, decrease heart rate, AV conduction, and contractility.
Three groups of CCBs include
1) Phenylalkylamines: Verapamil, Norverapamil
2) Benzothiazepines : Diltiazem
3) Dihydropyridine : Nifedipine, Nicardipine, Nimodipine, Nislodipine, Nitrendipine, Isradipine, Lacidipine, Felodipine and Amlodipine.Even though verapamil as good absorption from GIT, its oral bioavailability is low due to high first-pass metabolism.
Nimodipine is a Cerebro-selective CCB, used to reverse the compensatory vasoconstriction after sub-arachnoid haemorrhage and is more lipid soluble analogue of nifedipine
Calcium channel antagonist can potentiate the effect of non-depolarising muscle relaxants.
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This question is part of the following fields:
- Pharmacology
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Question 6
Correct
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A 20-year-old man has been diagnosed with mitral regurgitation. He will be treated with mitral valve repair.
What is true regarding the mitral valve?Your Answer: Its closure is marked by the first heart sound
Explanation:The mitral valve is the valve between the left atrium and left ventricle. It opens when the heart is in diastole (relaxation) which allows blood to flow from the left atrium to the left ventricle. In systole (contraction), the mitral valve closes to prevent the backflow of blood from the left ventricle to the left atrium.
The mitral valve is located posterior to the sternum at the level of the 4th costal cartilage. It is best auscultated over the cardiac apex, where its closure marks the first heart sound.
The mitral valve anatomy is composed of five main structures:
1. Left atrial wall – the myocardium of the left atrial wall extends over the posterior leaflet of the mitral valve. (left atrial enlargement is one of the causes for mitral regurgitation)
2. Mitral annulus – a fibrous ring that connects with the anterior and posterior leaflets. It functions as a sphincter that contracts and reduces the surface area of the valve during systole (Annular dilatation can also lead to mitral regurgitation)
3. Mitral valve leaflets (cusps) – The mitral valve is the only valve in the heart with two cusps or leaflets. One anterior and one posterior.
i. The anterior leaflet is located posterior to the aortic root and is also anchored to the aortic root.
ii. The posterior leaflet is located posterior to the two commissural areas.
4. Chordae tendinae – The chordae tendinae connects both the cusps to the papillary muscles.
5. Papillary muscles – These muscles and their cords support the mitral valve, allowing the cusps to resist the pressure developed during contractions (pumping) of the left ventricleThe anterior and posterior cusps are attached to the chordae tendinae which itself is attached to the left ventricle via papillary muscle.
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This question is part of the following fields:
- Anatomy
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Question 7
Incorrect
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Regarding laminar gas flow, which of the following options has the most influence on laminar flow?
Your Answer: Coefficient of viscosity
Correct Answer: Diameter of tube
Explanation:Laminar flow can be defined as the motion of a fluid where every particle in the fluid follows the same path of its previous particles. The following are properties of laminar flow of gas or fluids:
1. Smooth unobstructed flow of gas through a tube of relatively uniform diameter
2. Few directional changes
3. Slow, steady flow through straight smooth, rigid, large calibre, cylindrical tube
4. Outer layer flow slower than the centre due to friction, results in discrete cylindrical layers, or streamlines
5. Double flow by doubling pressure as long as the flow pattern remains laminarPoiseuille’s Law relates the factors that determine laminar flow. It indicates the degree of resistance to fluid flow through a tube. The resistance to fluid flow through a tube is directly related to the length, flow and viscosity; and inversely related to the radius of the tube to the fourth power. This means that, when the radius is doubled, there is increase in flow by a factor of 16.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 8
Correct
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The statement that best describes lactic acidosis is:
Your Answer: It can be precipitated by intravenous fructose
Explanation:An elevated arterial blood lactate level and an increase anion gap ([Na + K] – [Cl + HCO3]) of >20mmol gives rise to lactic acidosis. It can also be a result of overproduction and/or reduced metabolism of lactic acid.
The liver and kidney are the main sites of lactate metabolism, not skeletal muscle.
The two types of lactic acidosis that are known are:
Type A – due to tissue hypoxia, inadequate tissue perfusion and anaerobic glycolysis. These may be seen in cardiac arrest, shock, hypoxaemia and anaemia. The management of type A lactic acidosis involves reversing the underlying cause of the tissue hypoxia.
Type B – occurs in the absence of tissue hypoxia. Some of the causes of this include hepatic failure, renal failure, diabetes mellitus, pancreatitis and infection. Some drugs can also cause this lie aspirin, ethanol, methanol, biguanides and intravenous fructose.
The mainstay of treatment involves:
1. Optimising tissue oxygen delivery
2. Correcting the cause
3. Intravenous sodium bicarbonateIn resistant cases, peritoneal dialysis can be performed.
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This question is part of the following fields:
- Physiology
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Question 9
Incorrect
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The statement that best describes temperature management is:
Your Answer: Thermocouples use the principle that resistance in metals show a linear increase with temperature
Correct Answer: Gauge thermometers use coils of different metals with different co-efficients of expansion which either tighten or relax with changes in temperature
Explanation:There are different types of temperature measurement. These include:
Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially
Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)
Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature
Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output
Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.
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This question is part of the following fields:
- Clinical Measurement
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Question 10
Correct
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Which type of epithelium lines the luminal surface of the oesophagus?
Your Answer: Non keratinised stratified squamous epithelium
Explanation:Normally, the oesophagus is lined by non-keratinized stratified squamous epithelium. This epithelium can undergo metaplasia and convert to the columnar epithelium (stomach’s lining) in long-standing GERD that leads to Barret’s oesophagus.
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This question is part of the following fields:
- Anatomy
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Question 11
Correct
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A 68-year-old woman is a known case of acute myeloid leukaemia and was treated with chemotherapy as a child. She now presents in casualty, and you are called in to attend this patient as it is getting difficult to gain vascular access in her arms. The medical registrar asks you to site a cannula during the arrest call as intraosseous access is delayed. The intern wants to assist you in performing a venous cutdown of one of the veins in the patients ankle that passes anterior to the medial malleolus. Which vessel is this?
Your Answer: Long saphenous vein
Explanation:Venous cutdown is a surgical procedure when venous access is difficult, and other procedures like the Seldinger technique, ultrasound-guided venous access, and intraosseous vascular access have failed.
The vein of choice for venous cutdown is the long/great saphenous vein. It is part of the superficial venous collecting system of the lower extremity. It is the preferred vein as the long saphenous vein has anatomic consistency and is superficially located at the ankle anterior to the medial malleolus. It is also the most commonly used conduit for cardiovascular bypass operations.
Origin- in the foot at the confluence of the dorsal vein of the first digit and the dorsal venous arch of the foot
Route- runs ANTERIOR to the medial malleolus and travels up in the medial leg and upper thigh.
Termination: in the femoral vein within the femoral triangleRegarding the other options:
The short saphenous vein passes posterior to the lateral malleolus.
The dorsalis pedis vein accompanies the dorsalis pedis artery on the anterior foot.
The posterior tibial vein is part of the deep venous system accompanying the posterior tibial artery. There is no significant sural vein (there is a sural nerve), but the sural veins accompany the sural arteries and drain to the popliteal vein. -
This question is part of the following fields:
- Anatomy
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Question 12
Incorrect
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A 68-year old man, is admitted in hospital. He is scheduled to undergo a femoro-popliteal bypass graft, for which he has been administered a spinal-epidural anaesthetic. Intrathecal heavy bupivacaine (0.5%) was injected at L3-4 with good effect. On insertion of the epidural catheter, he remained asymptomatic.
During surgery, 5000 I.U. of IV heparin was given. The surgery is successful and required no epidural top-ups.
Six hours later, he complains of a severe back pain with weakness in his lower limbs.
What is the most important first step?Your Answer: Arrange an MRI scan
Correct Answer: A full neurological examination to establish the nature of the problem
Explanation:The most likely diagnosis is a spinal epidural haematoma, a neurological emergency. A full examination must be carried out to determine the nature of the neurological problem before conducting any investigations or imaging.
The effects of spinal anaesthesia should have worn off by this time point, and the severe back pain is a red flag.
The patient will also require an urgent neurological team referral as a spinal epidural haematoma requires immediate evacuation for spinal decompression. Analgesics may be prescribed for pain management.
Heparin would have been fully metabolised and so a reversal is unnecessary.
A spinal epidural haematoma is a pooling of blood in the epidural space, which can cause compression of the spinal cord. Its presenting symptoms are:
Usually begins with severe backpain and percussion tenderness
Cauda equina syndrome
Paralysis of the lower extremities.
If infected, a fever occurs in 66% of cases
Lower limb weakness developing after stopping an epidural infusion or weakness of the lower limbs which does not resolve within four hours of cessation of infusion of epidural local anaesthetic
Meningism. -
This question is part of the following fields:
- Pathophysiology
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Question 13
Incorrect
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A 42-year-old man presented with a bitemporal hemianopia with enlarged hands and feet. On examination, he was found to be hypertensive.
Which of the following correctly explains the cause of his visual field defect?Your Answer: Pituitary microadenoma secreting growth hormone (GH)
Correct Answer: Pituitary macroadenoma secreting growth hormone (GH)
Explanation:Pituitary macroadenoma is a benign tumour with growth larger than 10mm (those under 10mm are called microadenoma)
Compression of optic chiasm by pituitary adenoma is responsible for causing visual field defects like bitemporal hemianopia, optic neuropathy.
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This question is part of the following fields:
- Pathophysiology
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Question 14
Incorrect
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Which of the following statement is true regarding the mechanism of action of doxycycline?
Your Answer: Inhibit protein wall synthesis
Correct Answer: Inhibit 30S subunit of ribosomes
Explanation:Doxycycline belongs to the family of tetracyclines and inhibits protein synthesis through reversible binding to bacterial 30s ribosomal subunits, which prevent binding of new incoming amino acids (aminoacyl-tRNA) and thus interfere with peptide growth.
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This question is part of the following fields:
- Pharmacology
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Question 15
Correct
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Compared to the parasympathetic nervous system (PNS), the sympathetic nervous system (SNS) has:
Your Answer: Nicotinic receptors in pre and post ganglionic synapses
Explanation:With regards to the autonomic nervous system (ANS)
1. It is not under voluntary control
2. It uses reflex pathways and different to the somatic nervous system.
3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.With regards to the central nervous system (CNS)
1. There are myelinated preganglionic fibres which lead to the
ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.Most organs are under control of both systems although one system normally predominates.
The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.
There are short pre-ganglionic and long post ganglionic fibres.
Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.
There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.
Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.
The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.
The cranial outflow consists of
1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreasThe sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.
The PNS has long preganglionic and short post ganglionic fibres.
Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.Different types of these muscarinic receptors are present in different organs:
There are:
M1 = pupillary constriction, gastric acid secretion stimulation
M2 = inhibition of cardiac stimulation
M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
M4 = brain and adrenal medulla
M5 = brainThe lacrimal glands are solely under parasympathetic control.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 16
Incorrect
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One of the non-pharmacologic management of COPD is smoking cessation. Given a case of a 60-year old patient with history of smoking for 30 years and a FEV1 of 70%, what would be the most probable five-year course of his FEV1 if he ceases to smoke?
Your Answer: The FEV1 will return to normal within 6 months
Correct Answer: The FEV1 will decrease at the same rate as a non-smoker
Explanation:For this patient, his forced expiratory volume in 1 second (FEV1) will decrease at the same rate as a non-smoker.
There is a notable, but slow, decline in FEV1 when an individual reaches the age of 26. An average reduction of 30 mls every year in non-smokers, while a more significant reduction of 50-70 mls is observed in approximately 20% of smokers.
Considering the age of the patient, individuals who begin smoking cessation by the age of 60 are far less likely to achieve normal FEV1 levels, even in the next five years. It is expected that their FEV1 will be approximately 14% less than their peers of the same age.
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This question is part of the following fields:
- Physiology
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Question 17
Incorrect
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Dinamap is an automated blood pressure monitoring device. Which of these statements best fit its properties?
Your Answer: Utilises a double cuff oscillotonometric system
Correct Answer: The cuff should be positioned at the same level as the heart
Explanation:Dinamap continuously measures the systolic, diastolic and mean arterial pressure along with pulse rate, thereby providing a continuous monitoring of the blood pressure using the osscillitonometric principle of measurement.
The device loses accuracy towards the extremes of BP and is more accurate with systolic compared with diastolic pressure. In arrhythmias such as AF, the devices are also inaccurate due to the major fluctuations associated with the individual pulse pressure variations.
The manual BP device is still the gold standard for BP measurement and monitoring.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 18
Correct
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A 89-year old male has hypertension, with a blood pressure of 170/68 mmHg and has been admitted to the hospital. He is on no regular medications. His large pulse pressure can be accounted for by which of the following?
Your Answer: Reduced aortic compliance
Explanation:Cardiac output = stroke volume x heart rate
Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%
Stroke volume = end diastolic LV volume – end systolic LV volume
Pulse pressure = Systolic Pressure – Diastolic Pressure
Systemic vascular resistance = mean arterial pressure / cardiac output
Factors that increase pulse pressure include:
-a less compliant aorta (this tends to occur with advancing age)
-increased stroke volume -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 19
Correct
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Regarding the plateau phase of the cardiac potential, which electrolyte is the main determinant?
Your Answer: Ca2+
Explanation:The cardiac action potential has several phases which have different mechanisms of action as seen below:
Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
These channels automatically deactivate after a few msPhase 1: caused by early repolarisation and an efflux of potassium.
Phase 2: Plateau – caused by a slow influx of calcium.
Phase 3 – Final repolarisation – caused by an efflux of potassium.
Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potentialOf note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.
Different sites have different conduction velocities:
1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec2. AV node conduction – 0.05 m/sec
3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles
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This question is part of the following fields:
- Physiology
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Question 20
Correct
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A 43-year old woman, presented to the emergency department. She has suffered trauma to her right orbital floor.
On examination, it is noted that her right eye is deviated upwards when compared to her left. She also has a deliberate tilt in her head to the left in an attempt to compensate for loss of intorsion.
This clinical sign is caused by damage to which of the following cranial nerves?Your Answer: Trochlear nerve
Explanation:The trochlear nerve (CN IV) is the fourth and smallest cranial nerve. It’s role is to provide somatic motor innervation of the superior oblique muscle which is responsible for oculomotion.
Injury to the trochlear nerve will result in vertical diplopia, which worsens when looking downwards or inwards. This diplopia presents as an upward deviation of the eye with a head tilt away from the site of the lesion.
The abducens nerve (CN VI) provides somatic motor innervation for the lateral rectus muscle which functions to abduct the eye. Injury to this nerve will cause diplopia and an inability to abduct the eye, causing the patient to have to rotate their head to look sideways.
The facial nerve (CN VII) provides sensory, motor and parasympathetic innervations. It’s motor aspect controls the muscles of facial expression. Damage will cause paralysis of facial expression.
The oculomotor nerve (CN III) provides motor and parasympathetic innervations. Its motor component controls most of the other extraocular muscles. Damage to it will result in ptosis, dilatation of the pupil and a down and out eye position.
The ophthalmic division of the trigeminal nerve (CN VI) is responsible for sensory innervation of skin, mucous membranes and sinuses of the upper face and scalp.
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This question is part of the following fields:
- Pathophysiology
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Question 21
Correct
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When compared to unipolar diathermy, which of the following is more specific to bipolar diathermy?
Your Answer: Has a power output of up to 140 joules per second
Explanation:Electrocautery, also known as diathermy, is a technique for coagulation, tissue cutting, and fulguration that uses a high-frequency current to generate heat (cell destruction from dehydration).
The two electrodes in bipolar diathermy are the tips of forceps, and current passes between the tips rather than through the patient. Bipolar diathermy’s power output (40-140 W) is lower than unipolar diathermy’s typical output (400 W). There is no earthing in the bipolar circuit.
A cutting electrode and a indifferent electrode in the form of a metal plate are used in unipolar diathermy. The high-frequency current completes a circuit by passing through the patient from the active electrode to the metal plate. When used correctly, the current density at the indifferent electrode is low, and the patient is unlikely to be burned. Between the patient plate and the earth is placed an isolating capacitor. This has a low impedance to a high frequency current, such as diathermy current, and is used in modern diathermy machines. The capacitor has a high impedance to current at 50 Hz, which protects the patient from electrical shock.
High frequency currents (500 KHz – 1 MHz) are used in both unipolar and bipolar diathermy, which can cause tissue damage and interfere with pacemaker function (less so with bipolar diathermy).
The effect of diathermy is determined by the current density and waveform employed. The current is a pulsed square wave pattern in coagulation mode and a continuous square wave pattern in cutting mode.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 22
Correct
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Which measure of central tendency is most useful for a continuous, non-skewed data?
Your Answer: Mean
Explanation:Mean, also known as the average, is the most common measure of central tendency. It is the sum of all observed values divided by the number of observation. It is not useful for skewed data, which has an abnormal distribution. It is useful, instead, for numerical data that have symmetric distribution. It reflects the contributions of each data in the group, and are sensitive to outliers.
The median is the value that falls in the middle position when the observations are ranked in order from the smallest to the largest. If the number of observations is odd, the median is the middle number. If it is even, the median is the average of the two middle numbers. Unlike the mean, the median is useful on skewed data, and can be used for ordinal or numerical data if skewed.
The mode is the value that occurs with the greatest frequency in a set of observations, and is utilized for bimodal distribution.
The variance and the standard deviation are not measures of central tendency, but of dispersion.
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This question is part of the following fields:
- Statistical Methods
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Question 23
Incorrect
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Prior to rapid sequence induction of anaesthesia, a man with a BMI of 35 is pre-oxygenated.
Which method of pre-oxygenation with a tight-fitting face mask is the most effective?Your Answer: Oxygen 6 litres per minute via a Mapleson A breathing system, with patient supine breathing tidal volume breaths for three minutes
Correct Answer: Oxygen 6 litres per minute via a Mapleson A breathing system, with patient sitting up at 30 degrees breathing four vital capacity breaths
Explanation:This patient is morbidly obese and has a high risk of developing hypoxia. This will be exacerbated by the patient’s supine position, as a result of:
Functional residual capacity has been reduced (FRC)
Increased closing capacity (CC)
Reduced tidal volume due to increased airway resistance, decreased thoracic cage compliance, and decreased respiratory muscle strength and endurance
Following induction of general anaesthesia, there is a tendency for atelectasis and increased O2 consumption due to the increased workload of respiratory muscles and the overall increase in metabolism.Pre-oxygenation with 100 percent oxygen via a tight-fitting mask can be done using either tidal volume breaths for three to five minutes or four vital capacity breaths in normal circumstances. In the head-up position, this patient is much more likely to be adequately pre-oxygenated, maximising the FRC and minimising the CC. In spontaneously breathing patients, the Mapleson A and circle systems are both effective, but the Mapleson D requires 160-200 ml/kg/minute to prevent rebreathing.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 24
Incorrect
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A common renal adverse effect of non-steroidal anti-inflammatory drugs is?
Your Answer: Renal papillary necrosis
Correct Answer: Haemodynamic renal insufficiency
Explanation:Prostaglandins do not play a major role in regulating RBF in healthy resting individuals. However, during pathophysiological conditions such as haemorrhage and reduced extracellular fluid volume (ECVF), prostaglandins (PGI2, PGE1, and PGE2) are produced locally within the kidneys and serve to increase RBF without changing GFR. Prostaglandins increase RBF by dampening the vasoconstrictor effects of both sympathetic activation and angiotensin II. These effects are important because they prevent severe and potentially harmful vasoconstriction and renal ischemia. Synthesis of prostaglandins is stimulated by ECVF depletion and stress (e.g. surgery, anaesthesia), angiotensin II, and sympathetic nerves.
Non-steroidal anti-inflammatory drugs (NSAIDs), such as ibuprofen and naproxen, potently inhibit prostaglandin synthesis. Thus administration of these drugs during renal ischemia and hemorrhagic shock is contraindicated because, by blocking the production of prostaglandins, they decrease RBF and increase renal ischemia. Prostaglandins also play an increasingly important role in maintaining RBF and GFR as individuals age. Accordingly, NSAIDs can significantly reduce RBF and GFR in the elderly.
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This question is part of the following fields:
- Physiology
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Question 25
Correct
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The phenomenon that the patients behaved in a different manner when they know that they are being observed is termed as?
Your Answer: Hawthorne effect
Explanation:Hawthorne effect explains the change in any behavioural aspect owing to the awareness that the person is being observed.
Simpson’s Paradox explains the association developed when the data from several groups is combined to form a single larger group.The remaining terms are made up.
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This question is part of the following fields:
- Statistical Methods
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Question 26
Correct
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Monitoring of which of the following is indicated in the prevention of propofol infusion syndrome?
Your Answer: Lactate
Explanation:Propofol infusion syndrome (PRIS) is characterized by lactic acidosis, bradyarrhythmia, rhabdomyolysis, cardiac and renal failure, and often leads to death. So, lactate monitoring is advised in patients with propofol infusion syndrome.
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This question is part of the following fields:
- Pharmacology
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Question 27
Incorrect
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Which of the following can be evaluated by the Delphi method?
Your Answer: Confounding
Correct Answer: Expert consensus
Explanation:The Delphi method relies on expert consensus. This method kicks off with an open ended questionnaire and uses its responses as a survey instrument for the next round in which each of the participants is asked to rate the items that the investigators have summarized on the basis of the data collected in the first round. Any disagreement is further discussed in phases to come on the basis of information obtained from previous phases.
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This question is part of the following fields:
- Statistical Methods
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Question 28
Correct
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Very large SI units are easily expressed using mathematical prefixes.
One terabyte is equal to which of the following numbers?Your Answer: 1,000,000,000,000 bytes
Explanation:To denote large measured units, the following SI mathematical prefixes are used:
1 deca = 10 bytes (101)
1 hecto (h) = 100 bytes
1 kilo (k)= 1,000 bytes
1 mega (M) = 1,000,000 bytes
1 giga (G) = 1,000,000,000 bytes
1 Tera (T) = 1,000,000,000,000 bytes
1 Peta (P) = 1,000,000,000,000,000 bytes -
This question is part of the following fields:
- Basic Physics
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Question 29
Correct
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Which of the following anaesthetic agents is most suitable for inhalational induction in an 8-year-old child for inhalational induction of anaesthesia before routine surgery?
Your Answer: Sevoflurane at 4%
Explanation:The ideal agent for this case should have low blood: gas coefficient, pleasant smell, and high oil: gas coefficient (potent with a low Minimum alveolar coefficient (MAC)). Among the given options, Sevoflurane is perfect with 0.692 blood: gas partition coefficient and is low pungency, and is sweet.
Other drugs with their blood: gas partition coefficient and their smell are given as:
Blood/gas partition coefficient MAC Smell
Enflurane 1.8 1.68 Pungent, ethereal
Desflurane 0.42 7 Pungent, ethereal
Halothane 2.54 0.71 Sweet
Isoflurane 1.4 1.15 Pungent, ethereal -
This question is part of the following fields:
- Pharmacology
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Question 30
Correct
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Which of the following ionic changes is associated with the ventricular myocyte action potential's initial repolarization phase?
Your Answer: Ceased Na+ and increase K+ conductances
Explanation:The Purkinje system, as well as the action potentials of ventricular and atrial myocytes, have the same ionic changes. It lasts about 200 milliseconds and has a resting membrane potential, as well as fast depolarisation and plateau phases.
There are five stages to the process:
Increased Na+ and decreased K+ conductance in Phase 0 (rapid depolarisation).
1st phase (initial repolarisation) : Na+ conductance decreased, while K+ conductance increased.
Phase two (plateau phase) : Ca2+ conductance increased
Phase three (repolarisation phase) : Lower Ca2+ conductance and higher K+ conductance
4th Phase (resting membrane potential) : K+ conductance increased, Na+ conductance decreased, and Ca2+ conductance decreased. -
This question is part of the following fields:
- Pathophysiology
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Question 31
Correct
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Heights of 100 individuals(adults) who were administered steroids at any stage during childhood was studied. The mean height was found to be 169cm with the data having a standard deviation of 16cm. What will be the standard error associated with the mean?
Your Answer: 1.6
Explanation:Standard error can be calculated by the following formula:
Standard Error= (Standard Deviation)/√(Sample Size)
= (16) / √(100)
= 16 / 10
= 1.6 -
This question is part of the following fields:
- Statistical Methods
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Question 32
Incorrect
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An adult and a 7-year-old child are anatomically and physiologically very different.
Which of the following physiological characteristics of a 5-year-old most closely resembles those of a healthy adult?Your Answer: Lung compliance mL/cmH2O
Correct Answer: Dead space ratio
Explanation:Whatever the age, the dead space ratio is 0.3. It’s the dead space (Vd) to tidal volume ratio (Vt).
The glottis is the narrowest point of the upper airway in an adult, while the cricoid ring is the narrowest point in a child.
A child’s airway resistance is much higher than an adult’s. The resistance to airflow increases as the diameter of a paediatric airway shrinks. The radius (r) to the power of 4 is inversely proportional to airway resistance (r4). As a result, paediatric patients are more susceptible to changes in airflow caused by a small reduction in airway diameter, such as caused by oedema.
The compliance of a newborn’s lungs is very low (5 mL/cmH2O), but it gradually improves as lung size and elasticity grow. Lung compliance in an adult is 200 mL/cmH2O.
In children, minute ventilation (mL/kg/minute) is much higher.
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This question is part of the following fields:
- Pathophysiology
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Question 33
Incorrect
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In a normal healthy adult breathing 100 percent oxygen, which of the following is the most likely cause of an alveolar-arterial (A-a) oxygen difference of 30 kPa?
Your Answer: High altitude
Correct Answer: Atelectasis
Explanation:The ‘ideal’ alveolar PO2 minus arterial PO2 is the alveolar-arterial (A-a) oxygen difference.
The ‘ideal’ alveolar PO2 is derived from the alveolar air equation and is the PO2 that the lung would have if there was no ventilation-perfusion (V/Q) inequality and it was exchanging gas at the same respiratory exchange ratio as real lung.
The amount of oxygen in the blood is measured directly in the arteries.
The A-a oxygen difference (or gradient) is a useful measure of shunt and V/Q mismatch, and it is less than 2 kPa in normal adults breathing air (15 mmHg). Because the shunt component is not corrected, the A-a difference increases when breathing 100 percent oxygen, and it can be up to 15 kPa (115 mmHg).
An abnormally low or abnormally high V/Q ratio within the lung can cause an increased A-a difference, though the former is more common. Atelectasis, which results in a low V/Q ratio, is the most likely cause of an A-a difference in a healthy adult breathing 100 percent oxygen.
Hypoventilation may cause an increase in alveolar (and thus arterial) CO2, lowering alveolar PO2 according to the alveolar air equation.
The alveolar PO2 is also reduced at high altitude.
Healthy people are unlikely to have a right-to-left shunt or an oxygen transport diffusion defect.
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This question is part of the following fields:
- Physiology
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Question 34
Incorrect
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A 66-year-old man, present to the emergency department with dyspepsia. On history taking, he admits to being a heavy smoker, and on testing is noted to be positive for a helicobacter pylori infection. A few evenings later, he suffers from haematemesis and collapses.
What vessel is most likely to be involved?Your Answer: Portal vein
Correct Answer: Gastroduodenal artery
Explanation:The most likely of the differential diagnosis in this case is a duodenal ulcer located on the posterior abdominal wall.
These can cause an erosion of the abdominal wall, eventually affecting the gastroduodenal artery and resulting in major bleeding and haematemesis.
Gastroduodenal artery supplies the pylorus, proximal part of the duodenum, and indirectly to the pancreatic head (via the anterior and posterior superior pancreaticoduodenal arteries)
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This question is part of the following fields:
- Anatomy
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Question 35
Correct
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Which one of the following patients presenting for elective surgery has an American Society of Anaesthesiologists (ASA) preoperative physical status grading of III?
Your Answer: A 50-year old man with a BMI of 41 with a reduced exercise tolerance
Explanation:The ASA physical status classification system is a system for assessing the fitness of patients before surgery. It was last updated in October 2014.
ASA I A normal healthy patient
ASA II A patient with mild systemic disease
ASA III A patient with severe systemic disease
ASA IV A patient with severe systemic disease that is a constant threat to life
ASA V A moribund patient who is not expected to survive without the operation
ASA VI A declared brain-dead patient whose organs are being removed for donor purposesA 20-year old woman who is 39-weeks pregnant with no other medical conditions – ASA II
A 35-year-old man with a BMI of 29 with a good exercise tolerance who smokes-ASA II
A 50-year old man with a BMI of 41 with a reduced exercise tolerance -ASA III
A 65-year old woman with a BMI of 34 with treated hypertension with no functional limitations-ASA II
A 73-year old man who has had a TIA ten-weeks ago but has a good exercise tolerance and is a non-smoker-ASA IV
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This question is part of the following fields:
- Clinical Measurement
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Question 36
Incorrect
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The following are pairs of neurotransmitters with their corresponding synthesising enzymes.
Which pair is correct?Your Answer: Catechol-O-methyl transferase and norepinephrine
Correct Answer: Glutamic acid decarboxylase and gamma-aminobutyric acid (GABA)
Explanation:Glutamic acid decarboxylase is responsible for the catalyses of glutamate to gamma-aminobutyric acid (GABA)
Catechol-o-methyl transferase catalyses the degradation and inactivation of dopamine into 3-methoxytyramine, epinephrine into metanephrine, and norepinephrine into normetanephrine and vanylmethylmandelic acid (VMA).
Monoamine oxidase catalyses the oxidation of norepinephrine to vanylmethylmandelic acid (VMA) and serotonin to 5-hydeoxyindole acetic acid (5-HIAA).
Cholinesterase functions to catalyse the split of acetylcholine into choline and acetic acid.
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This question is part of the following fields:
- Pathophysiology
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Question 37
Incorrect
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When describing the surface anatomy of the sacrum, which of the following anatomical landmarks refers to the base of an equilateral triangle is formed by the sacral hiatus?
Your Answer: A line connecting the processes of S5
Correct Answer: A line connecting the posterior superior iliac spines
Explanation:The apex of an equilateral triangle completed by the posterior superior iliac spines is where the sacral hiatus or sacrococcygeal membrane can normally located. The failure of posterior fusion of the laminae of the fourth and fifth sacral vertebrae allows the sacral canal to be accessible via the membrane.
In adults, the spine of L4 usually lies on a line drawn between the highest points of the iliac crests (Tuffier’s line). A line connecting each anterior iliac spine, approximates to the L3/4 interspace in the sitting position. Both of these options are incorrect.
A line connecting the greater trochanters is also incorrect.
A line connecting the posterior superior iliac spines is correct, but in adults the presence of a sacral fat pad can still make identification of this landmark less straightforward.
The processes of S5 are remnants only and form the sacral cornua, which are also used to help identify the sacral hiatus.
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This question is part of the following fields:
- Anatomy
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Question 38
Incorrect
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A 70-year-old man will have a PICC line inserted as he requires long-term parenteral nutrition. To gain venous access, the line is inserted into the basilic vein at the elbow region.
As the catheter tip advances into the basilic vein, which venous structure will it first encounter?
Your Answer: Cephalic vein
Correct Answer: Axillary vein
Explanation:A peripherally inserted central catheter (PICC) line is a long, thin tube inserted into the vein of a patient’s arm to gain access to the large central veins near the heart. PICC line is indicated for parenteral nutrition or to deliver medications. They can be used for medium-term venous access, defined as anywhere between several weeks to 6 months.
The veins of choice for PICC are:
1. Basilic
2. Brachial
3. Cephalic
4. Medial cubital veinThe vein of choice is the right basilic vein as it has a large circumference and is located superficially. It has the most straight route to the final destination of PICC (SVC or Right atrium). It courses through the axillary vein, then the subclavian, and finally settles into the SVC. It also has the least number of valves and a shallow angle of insertion when compared to the other veins.
The basilic vein drains the medial end of the dorsal arch of the upper limb, passes along the medial aspect of the forearm, and pierces the deep fascia at the elbow. The basilic vein joins the venae comitantes of the brachial artery to form the axillary vein at the elbow.
The posterior circumflex humeral vein is encountered before the axillary vein. However, a PICC line is unlikely to enter this structure because of its entry angle into the basilic vein. -
This question is part of the following fields:
- Anatomy
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Question 39
Correct
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A 64-year old male has shortness of breath on exertion and presented to the cardiology clinic. He has a transthoracic echo performed to help in assessing the function of his heart.
How can this echo aid in calculating cardiac output?Your Answer: (end diastolic LV volume - end systolic LV volume) x heart rate
Explanation:Cardiac output = stroke volume x heart rate
Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%
Stroke volume = end diastolic LV volume – end systolic LV volume
Pulse pressure = Systolic Pressure – Diastolic Pressure
Systemic vascular resistance = mean arterial pressure / cardiac output
Factors that increase pulse pressure include:
-a less compliant aorta (this tends to occur with advancing age)
-increased stroke volume -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 40
Correct
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Which of the following is true regarding the dose of propofol?
Your Answer: 1-2mg/kg
Explanation:Propofol is a short-acting medication used for starting and maintenance of general anaesthesia, sedation for mechanically ventilated adults, and procedural sedation.
The dose of propofol is 1-2 mg/kg.Dose of some other important drugs are listed below:
Thiopental dose: 3-7 mg/kg
Ketamine dose: 1-2 mg/kg
Etomidate dose: 0.3 mg/kg
Methohexitone dose: 1.0-1.5 mg/kg -
This question is part of the following fields:
- Pharmacology
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Question 41
Correct
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Which of the following statements is true with regards to acetylcholine?
Your Answer: Excess cholinesterase inhibitor medication causes cholinergic crisis
Explanation:Myasthenic and cholinergic crises are two crises which are similar in their clinical presentation.
Myasthenic crisis can be caused by:
-lack of acetylcholine,
-poor compliance with medication,
-infectionCholinergic crisis can be caused by excess cholinesterase inhibitor medication (mimicking organophosphate poisoning) causing excess acetylcholine.
Differentiation between the 2 crises is made by giving incremental doses of the short acting cholinesterase inhibitor, Edrophonium.
This increase acetylcholine levels and will make a myasthenic crisis better and a cholinergic crisis worse. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 42
Correct
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A 54-year-old lady comes in for a right-sided elective bunionectomy with a realignment osteotomy under local anaesthetic on her first (large) toe.
For the operation, which of the following nerve blocks will be most effective?Your Answer: Superficial peroneal, deep peroneal and posterior tibial nerves
Explanation:An ankle block is commonly used for anaesthesia and postoperative analgesia when operating on bunions. It results in the selective block of the superficial peroneal, deep peroneal, and posterior tibial nerves.
The deep peroneal nerve supplies sensory input to the web space between the first and second toes (L4-5).
The L2-S1 nerve, often known as the superficial peroneal nerve, is a mixed motor and sensory neuron. It gives sensory supply to the anterolateral region of the leg, the anterior aspect of the 1st, 2nd, 3rd, and 4th toes, and innervates the peroneus longus and brevis muscles (with the exception of the web space between 1st and 2nd toes).
The sensory area of the saphenous nerve (L3-4) in the foot stretches from the proximal portion of the midfoot on the medial side to the proximal part of the midfoot on the lateral side.
The lateral side of the little (fifth) toe is innervated by the sural nerve’s sensory supply (S1-2). The heel, medial (medial plantar nerve), and lateral (lateral plantar nerve) soles of the foot are all served by the posterior tibial nerve.
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This question is part of the following fields:
- Pathophysiology
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Question 43
Correct
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Which of the following statements is not true regarding Adrenaline?
Your Answer: Exerts its effect by decreasing intracellular calcium
Explanation:Noradrenaline also called norepinephrine belongs to the catecholamine family that functions in the brain and body as both a hormone and neurotransmitter.
They have sympathomimetic effects acting via adrenoceptors (?1, ?2,?1, ?2, ?3) or dopamine receptors (D1, D2).
May cause reflex bradycardia, reduce cardiac output and increase myocardial oxygen consumption
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This question is part of the following fields:
- Pharmacology
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Question 44
Incorrect
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Question 45
Incorrect
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A mercury barometer can be used to determine absolute pressure. A mercury manometer can be used to check blood pressure. The SI units of length(mm) are used to measure pressure.
Why is pressure expressed in millimetres of mercury (mmHg)?Your Answer: Pressure is directly proportional to the weight of the mercury column
Correct Answer: Pressure is directly proportional to length of the mercury column and is variable
Explanation:A mercury barometer can be used to determine absolute pressure. A glass tube with one closed end serves as the barometer. The open end is inserted into a mercury-filled open vessel. The mercury in the container is pushed into the tube by atmospheric pressure exerted on its surface. Absolute pressure is the distance between the tube’s meniscus and the mercury surface.
Pressure is defined as force in newtons per unit area (F) (A).
Mass of mercury = area (A) × density (ρ) × length (L)
Pressure = ((A × ρ × L) × 9.8 m/s2)/A
Pressure = ρ × L x 9.8
Pressure is proportional to LThe numerator and denominator of the above equation, area (A), cancel out. The constants are density and the gravitational acceleration value.
The length is proportional to the applied pressure.
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This question is part of the following fields:
- Physiology
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Question 46
Correct
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Which of the following antiplatelet drugs would be best for rapid offset action?
Your Answer: Epoprostenol
Explanation:Epoprostenol has a half-life of only 42 seconds and has rapid offset. It is used for the treatment of pulmonary hypertension.
Aspirin inhibits the COX enzyme irreversibly. It inhibits thromboxane synthesis but does not inhibit the enzyme thromboxane synthetase.
Ticlopidine, clopidogrel and prasugrel act as irreversible antagonists of P2 Y12 receptor of Adenosine Diphosphate (ADP). These drugs interfere with the activation of platelets by ADP and fibrinogen. Both aspirin and clopidogrel act irreversibly so they are not correct.
Paclitaxel is a long-acting antiproliferative agent used for the prevention of restenosis (recurrent narrowing) of coronary and peripheral stents and is not the correct answer.
Tirofiban has the next shortest duration of action after epoprostenol. If epoprostenol is not given in the question, it would be the best answer.
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This question is part of the following fields:
- Pharmacology
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Question 47
Correct
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A 20-year-old boy is undergoing surgery for indirect inguinal hernia repair. The deep inguinal ring is exposed and held with a retractor at its medial aspect during the procedure.
What structure is most likely to lie under the retractor on the medial side?Your Answer: Inferior epigastric artery
Explanation:The deep inguinal ring is the entrance of the inguinal canal. It is an opening in the transversalis fascia around 1 cm above the inguinal ligament. Therefore, the superolateral wall is made by the transervalis fascia.
The inferior epigastric vessels run medially to the deep inguinal ring forming its inferomedial border.
The inguinal canal extends obliquely from the deep inguinal ring to the superficial inguinal ring.
An indirect inguinal hernia arises through the deep inguinal ring lateral to the inferior epigastric vessels. -
This question is part of the following fields:
- Anatomy
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Question 48
Incorrect
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Following a physical assault, a 28-year-old man is admitted to the emergency room. A golf club has struck him in the head.
There is a large haematoma on the scalp, as well as a bleeding wound. In response to painful stimuli, he opens his eyes and makes deliberate movements. Because of inappropriate responses, a history is impossible to construct, but words can be discerned.
Which of the options below best describes his current Glasgow Coma Scale (GCS)?Your Answer: E3V2M5=10
Correct Answer: E2V3M5=10
Explanation:The Glasgow Coma Scale (GCS) has been used in outcome models as a measure of physiological derangement and as a tool for assessing head trauma.
Eye opening (E):
4 Spontaneously
3 Responds to voice
2 Responds to painful stimulus
1 No response.Best verbal response (V):
5 Orientated, converses normally
4 Confused, disoriented conversation, but able to answer basic questions
3 Inappropriate responses, words discernible
2 Incomprehensible speech
1 Makes no sounds.Best motor response (M):
6 Obeys commands for movement
5 Purposeful movement to painful stimulus
4 Withdraws from pain
3 Abnormal (spastic) flexor response to painful stimuli, decorticate posture
2 Extensor response to painful stimuli, decerebrate posture
1 No response.In this case, GCS = 2+3+5 = 10.
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This question is part of the following fields:
- Pathophysiology
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Question 49
Correct
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The lung volume that is commonly measured indirectly is?
Your Answer: Functional residual capacity
Explanation:The functional residual capacity (FRC) is the volume in the lungs at the end of passive expiration. It is determined by opposing forces of the expanding chest wall and the elastic recoil of the lung. A normal FRC = 1.7 to 3.5 L. It a marker for lung function, and, during this time, the alveolar pressure is equal to the atmospheric pressure.
FRC cannot be measured by spirometry because it contains the residual volume.
Tidal volume, inspiratory reserve volume, forced expiratory volume in 1 second, and vital capacity can be measured directly.
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This question is part of the following fields:
- Pathophysiology
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Question 50
Correct
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Which one of the following factor affects the minimal alveolar concentration (MAC)?
Your Answer: Hypoxaemia
Explanation:The minimal alveolar concentration (MAC) is the concentration of an inhalation anaesthetic agent in the lung alveoli required to stop a response to the surgical stimulus in 50% of the patient.
Following factors don’t affect the MAC of the inhaled anaesthetic agents:
Gender, acidosis, alkalosis, hypothyroidism, hyperthyroidism, body weight, serum potassium level, and the duration of the anaesthesia.
MAC increase in children, elevated temperature, high metabolic rate, sympathetic increase and chronic alcoholism.
MAC decrease in low temperature, low oxygen level, old age, hypotension (<40 mmHg), depressant drugs e.g. opioids and low level of catecholamines; alpha methyl dopa. Carbon dioxide O2 at the pressure > 120mmHg is being used in anesthetic-Hinkman as an additive effect to decrease MAC, however, increase concentration of CO2 activates the sympathetic system resulting the MAC increases.
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This question is part of the following fields:
- Physiology
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Question 51
Correct
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Left ventricular afterload is mostly calculated from systemic vascular resistance.
Which one of the following factors has most impact on systemic vascular resistance?Your Answer: Small arterioles
Explanation:Systemic vascular resistance (SVR), also known as total peripheral resistance (TPR), is the amount of force exerted on circulating blood by the vasculature of the body. Three factors determine the force: the length of the blood vessels in the body, the diameter of the vessels, and the viscosity of the blood within them. The most important factor that determines the systemic vascular resistance (SVR) is the tone of the small arterioles.
These are otherwise known as resistance arterioles. Their diameter ranges between 100 and 450 µm. Smaller resistance vessels, less than 100 µm in diameter (pre-capillary arterioles), play a less significant role in determining SVR. They are subject to autoregulation.
Any change in the viscosity of blood and therefore flow (such as due to a change in haematocrit) might also have a small effect on the measured vascular resistance.
Changes of blood temperature can also affect blood rheology and therefore flow through resistance vessels.
Systemic vascular resistance (SVR) is measured in dynes·s·cm-5
It can be calculated from the following equation:
SVR = (mean arterial pressure − mean right atrial pressure) × 80 cardiac output
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This question is part of the following fields:
- Physiology
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Question 52
Incorrect
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A 26-year old man is admitted to the high dependency unit following an external fixation of a pelvic fracture sustained in a road traffic accident earlier in the day. Additionally, he has stable L2/L4 vertebral fractures but no other injuries.
He is a known intravenous drug abuser currently on 200 mg heroin per day. He has been admitted for observations postop and pain control. He has regular paracetamol and NSAIDs prescribed.
Which is the most appropriate postoperative pain regimen?Your Answer: Epidural with 20 mL 0.5% bupivacaine and 2 mcg/mL fentanyl and PCA morphine
Correct Answer: PCA morphine alone with background infusion
Explanation:With a history of drug abuse, the patient is likely dependent on and tolerant to opioids. He is also likely to experience significant pain from his injuries. Providing adequate pain relief with regular paracetamol and NSAIDs in combination with a pure opioid agonist while at the same time avoiding occurrence of acute withdrawal syndrome is the goal.
Administering a baseline dose of opioid corresponding to the patient’s usual opioid use plus an opioid dose required to address the level of pain the patient experience can help prevent opioid withdrawal. The best approach is by empowering the patient to use patient controlled analgesia (PCA). The infusion rate, bolus dose and lock-out time are adjusted accordingly. Using PCA helps in avoiding staff/patient confrontations about dose and dosing interval.
2.5 mg heroin is equivalent to 3.3 mg morphine. This patient is usually on 200 mg of heroin per 24 hours. The equivalent dose of morphine is 80 × 3.3 =254 mg per 24 hours (11 mg/hour).
Epidural or spinal opioids might be the best choice for providing a systemic dose of opioids when patients are in remission to avoid withdrawal. Lumbar vertebral fractures is a contraindication to this route of analgesia.
The long half life of Oral methadone make titration to response difficult. Also, absorption of methadone by the gastrointestinal tract is variable. It is therefore NOT the best choice for acute pain management.
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This question is part of the following fields:
- Pharmacology
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Question 53
Correct
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Regarding anti diuretic hormone (ADH), one of the following statements is correct:
Your Answer: Increases the total amount of electrolyte free water in the body
Explanation:The major action of ADH is to increase reabsorption of osmotically unencumbered water from the glomerular filtrate and decreases the volume of urine passed. The osmolarity of urine is increased to a maximum of four times that of plasma (approx. 1200 mOsm/kg) by Increasing water reabsorption.
Chronic water loading, Lithium, potassium deficiency, cortisol and calcium excess, all blunt the action of ADH. This leads to nephrogenic diabetes insipidus.
ADH’s primary site of action is the distal tubule and collecting duct.
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This question is part of the following fields:
- Physiology
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Question 54
Incorrect
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A 50-year-old woman is brought into the emergency department in an ambulance. She was found collapsed on the street. She has visual and oculomotor deficits on examination, but her motor function is intact.
A digital subtraction angiography is performed that shows occlusion of the basilar artery at the site where the vertebral arteries fuse to form the basilar artery.
Which anatomical landmark corresponds to this site of occlusion?Your Answer: The base of the medulla
Correct Answer: The base of the pons
Explanation:The basilar artery is a large vessel that is formed by the union of the vertebral arteries at the junction of the medulla and pons. It lies in the pontine cistern and follows a shallow groove on the ventral pontine surface, extending to the upper border of the pons.
The basilar artery then bifurcates into the two posterior cerebral arteries that form part of the Circle of Willis.
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This question is part of the following fields:
- Anatomy
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Question 55
Incorrect
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A peripheral nerve stimulator is used to stimulate the ulnar nerve at the wrist to indicate the degree of neuromuscular blockade.
Which single muscle or group of muscles of the hand supplied by the ulnar nerve is best for monitoring the twitch function during neuromuscular blockade?Your Answer: Abductor digiti minimi
Correct Answer: Adductor pollicis
Explanation:In anaesthesia, adductor pollicis neuromuscular monitoring with ulnar nerve stimulation is commonly used. It is the gold standard for measuring the degree of block and comparing neuromuscular blocking drugs and their effects on other muscles.
Electrodes are usually placed over the ulnar nerve at the wrist to monitor the adductor pollicis.
Neuromuscular blocking drugs have different sensitivity levels in different muscle groups.
To achieve the same level of blockade, the diaphragm requires 1.4 to 2 times the amount of neuromuscular blocking agent as the adductor pollicis muscle. The small muscles of the larynx and the ocular muscles are two other respiratory muscles that are less resistant than the diaphragm (especially corrugator supercilii).
The abdominal muscles, Orbicularis oculi, peripheral muscles of the limbs, Geniohyoid, Masseter, and Upper airway muscles are the most sensitive to neuromuscular blocking agents.
The C8-T1 nerve roots, which are part of the medial cord of the brachial plexus, form the ulnar nerve. It enters the hand via the ulnar canal, superficial to the flexor retinaculum, after following the ulnar artery at the wrist.
The nerve then splits into two branches: superficial and deep. The palmaris brevis is supplied by the superficial branch, which also provides palmar digital nerves to one and a half fingers. The dorsal surface of the medial/ulnar 1.5 fingers, as well as the corresponding skin over the hand, are also supplied by it (as well as the palmar surface).
The ulnar nerve’s deep branch runs between the abductor and flexor digiti minimi, which it supplies. It also innervates the opponens, and with the deep palmar arch, it curves around the hook of the hamate and laterally across the palm. All of the interossei, the medial two lumbricals, the adductor pollicis, and, in most cases, the flexor pollicis brevis are supplied there.
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This question is part of the following fields:
- Anatomy
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Question 56
Incorrect
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A patient under brachial plexus regional block complains of pain under the cuff after the torniquet is inflated.
Which nerve was most probably 'missed' by the local anaesthetic?Your Answer: Axillary nerve
Correct Answer: Intercostobrachial nerve
Explanation:The area described in the question is supplied by the intercostobrachial nerve, which provides sensory innervation to the portions of the axilla, tail of the breast, lateral chest wall and medial side of the arm.
It is a common for it to be ‘missed’ during administration of local anaesthesia because of its very superficial anatomic course. It may be anesthetized by giving an analgesia from the upper border of the biceps at the anterior axillary fold, to the margin of the triceps by the axillary floor.
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This question is part of the following fields:
- Pathophysiology
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Question 57
Correct
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A randomized controlled trail has been conducted to compare two drugs used for the early management of acute severe asthma in the emergency department. After being allocated to the randomized groups, many patients have been excluded due to deleterious effect to the drugs.
How the data would be analysed?Your Answer: Include the patients who drop out in the final data set
Explanation:Randomized controlled trails will be analysed by the intention-to-treat (ITT) approach. It provides unbiased comparisons among the treatment groups. ITT analyses are done to avoid the effects of dropout, which may break the random assignment to the treatment groups in a study.
ITT analysis is a comparison of the treatment groups that includes all patients as originally allocated after randomization.
In order to include such participants in an analysis, outcome data could be imputed which involves making assumptions about the outcomes in the lost participants.
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This question is part of the following fields:
- Statistical Methods
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Question 58
Correct
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A 61-year-old woman, present to her general practitioner. She complains of a severe lancinating pain in her forehead that only last a few seconds, possibly triggered by washing her face, occurring over the previous six weeks.
On examination, she is normal with no other signs or symptoms.
Which nerve is the most likely cause of her pain?Your Answer: Sensory branches of the ophthalmic division of the trigeminal nerve
Explanation:Her symptoms are suggestive of trigeminal neuralgia which is a short, sudden, severe sharp unilateral pain in the facial region. The pain often follows the sensory distribution of the trigeminal nerve (CN V).
The trigeminal nerve gives rise to 3 sensory and 1 motor nuclei. Neuralgia can arise from any of the 3 sensory divisions.
The ophthalmic division gives rise to 3 further sensory branches, which are the frontal, lacrimal and nasociliary.
The frontal branch of the ophthalmic division of the trigeminal nerve is responsible for the innervation of the area in question.
The superior alveolar dental, zygomatic and sphenopalatine nerves are all branches arising from the maxillary division of the trigeminal nerve.
The mandibular division of the trigeminal nerve provides sensory and motor innervation. The sensory innervation is carried out by the auriculotemporal nerve which supplies the lower third of the face, while the motor fibres are responsible for controlling the muscles of mastication.
The somatic sensory branches of the vagus nerve are responsible for sensory innervation of the external acoustic meatus and tympanic membrane.
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This question is part of the following fields:
- Pathophysiology
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Question 59
Incorrect
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All of the following statements about cerebrospinal fluid are incorrect except:
Your Answer: Has approximately 100 red cells/ml
Correct Answer: Has a glucose concentration 2/3 that of the plasma glucose
Explanation:The pH of CSF is 7.31 which is lower than plasma.
Compared to plasma, it has a lower concentration of potassium, calcium, and protein and a higher concentration of sodium, chloride, bicarbonate and magnesium.
CSF usually has no cells present but if white cells are present, there should be no more than 4/ml.
The pressure of CSF should be less than 20 cm of water.
The concentration of glucose is approximately two-thirds of that of plasma, and it has a concentration of approximately 3.3-4 mmol/L.
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This question is part of the following fields:
- Physiology
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Question 60
Correct
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What structure is most posterior at the porta hepatis?
Your Answer: Portal vein
Explanation:The structures in the porta hepatis from anterior to posterior are:
The ducts: Most anterior are the left and right hepatic ducts.
The arteries: Next are the left and right hepatic arteries
The veins: Next is the portal vein
The epiploic foramen of Winslow lies most posterior at the porta hepatis.
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This question is part of the following fields:
- Anatomy
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Question 61
Incorrect
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Levels of serum potassium in around 1000 patients that were on ACE inhibitor were measured. The mean value was calculated to be 4.6mmol/L and a standard deviation of 0.3mmol/L was recorded.
Which among the given options is correct?Your Answer: 95% of values lie between 4.5 and 4.75 mmol/l
Correct Answer: 68.3% of values lie between 4.3 and 4.9 mmol/l
Explanation:Its known that 68.3% of the total values of a normally distributed variable are found within a range of 1 standard deviation from the mean which makes the range to be 4.3 to 4.9 mmol/L.
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This question is part of the following fields:
- Statistical Methods
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Question 62
Correct
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The pharmacologically inactive precursor of barbiturates is Barbituric acid. Because the molecule is heterocyclic, small structural changes can alter its pharmacological activity (structure function relationship).
Which of the following modifications to the molecule has the greatest impact on the effectiveness of the barbiturate derivative?Your Answer: Sulphur at C2
Explanation:Barbituric acid is the barbiturates’ pharmacologically inactive precursor. A pyrimidine heterocyclic nucleus is formed by the condensation of urea and malonic acid. Its pharmacological activity can be influenced by minor structural changes (structure function relationship).
The duration of action and potency as a sedative are influenced by the length of the side chains at C5. Barbiturates with three carbon atoms in their chain last longer than those with two. Anticonvulsant properties are enhanced by branched chains.
The addition of a methyl group at N1 causes a faster onset/offset of action, but it also causes excitatory phenomena (twitching/lower convulsive threshold).
The addition of oxygen and sulphur to C2 increases the molecule’s lipid solubility and thus its potency. Thiopentone (thiobarbiturate) has sulphur groups at C2, making it 20-200 times more lipid soluble than oxybarbiturates.
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This question is part of the following fields:
- Pharmacology
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Question 63
Correct
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The biochemical assessment of malnutrition can be measured by the amount of plasma proteins.
In acute starvation, which of these plasma proteins is the most sensitive indicator?Your Answer: Retinol binding globulin
Explanation:The half life of Retinol binding protein (RBP) is 10-12 hours and therefore reflects more acute changes in protein metabolism than any of these proteins. Therefore it is not commonly used as a parameter for nutritional assessment.
The half life of Transthyretin (thyroxine binding pre-albumin) is only one to two days and so levels are less sensitive and this protein is not an albumin precursor. 15 mg/dL represents early malnutrition and a need for nutritional support.
Albumin levels have been frequently as a marker of nutrition but this is not a very sensitive marker. It’s half life more than 30 days and significant change takes some time to be noticed. Also, synthesis of albumin is decreased with the onset of the stress response after burns. Unrelated to nutritional status, the synthesis of acute phase proteins increases and that of albumin decreases.
A more accurate indicator of protein stores is transferrin. It’s response to acute changes in protein status is much faster. The half life of serum transferrin is shorter (8-10 days) and there are smaller body stores than albumin. A low serum transferrin level is below 200 mg/dL and below 100 mg/dL is considered severe. Serum transferrin levels can also affect serum transferrin level.
Fibronectin is used a nutritional marker but levels decrease after seven days of starvation. It is a glycoprotein which plays a role in enhancing the phagocytosis of foreign particles.
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This question is part of the following fields:
- Physiology
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Question 64
Incorrect
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Out of the following, which is NOT true regarding the external carotid?
Your Answer: The ascending pharyngeal artery is a medial branch
Correct Answer: It ends by bifurcating into the superficial temporal and ascending pharyngeal artery
Explanation:The external carotid artery has eight important branches:
Anterior surface:
1. Superior thyroid artery (first branch)
2. Lingual artery
3. Facial artery
Medial branch
4. Ascending pharyngeal artery
Posterior branches
5. Occipital artery
6. Posterior auricular artery
Terminal branches
7. Maxillary artery
8. Superficial temporal arteryThe external carotid has eight branches, 3 from its anterior surface ; thyroid, lingual and facial. The pharyngeal artery is a medial branch. The posterior auricular and occipital are posterior branches.
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This question is part of the following fields:
- Anatomy
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Question 65
Correct
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A 25-year old man needs an emergency appendicectomy and has gone to the operating room. During general anaesthesia, ventilation is achieved using a circle system with a fresh gas flow (FGF) of 1L/min, with and air/oxygen and sevoflurane combination. The capnograph trace is normal.
Changes to the end tidal and baseline CO2 measurements at 10 and 20 mins respectively are seen on the capnograph below:
10 minutes 20 minutes
End-tidal CO2 4.9 kPa 8.4 kPa
Baseline end-tidal CO2 0.2 kPa 2.4 kPa
The other vitals were as follows:
Pulse 100-105 beats per minute
Systolic blood pressure 120-133 mmHg
O2 saturation 99%.
The next most important immediate step is which of the following?Your Answer: Increase the FGF
Explanation:This scenario describes rebreathing management.
Changes is exhaustion of the soda lime and a progressive rise in circuit deadspace is the most likely explanation for the capnograph.
It is important that the soda lime canister is inspected for a change in colour of the granules. Initially fresh gas flow should be increased and then if necessary, replace the soda lime granules. Other strategies include changing to another circuit or bypassing the soda lime canister after the fresh gas flow is increased.
Any other causes of increased equipment deadspace should be excluded.
Intraoperative hypercarbia can be caused by:
1. Hypoventilation – Breathing spontaneously; drugs which include anaesthetic agents, opioids, residual neuromuscular blockade, pre-existing respiratory or neuromuscular disease and cerebrovascular accident.
2. Controlled ventilation- circuit leaks, disconnection, miscalculation of patient’s minute volume.
3. Rebreathing – Soda lime exhaustion with circle, inadequate fresh gas flow into Mapleson circuits, increased breathing system deadspace.
4. Endogenous source – Tourniquet release, hypermetabolic states (MH or thyroid storm) and release of vascular clamps.
5. Exogenous source – Absorption of CO2 absorption from the pneumoperitoneum. -
This question is part of the following fields:
- Physiology
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Question 66
Correct
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One of the following neuromuscular blocking agents is the most potent:
Your Answer: Vecuronium
Explanation:The measure of drug potency or therapeutic response is the ED95. This is defined as the dose of a neuromuscular blocking drug required to produce a 95% depression of muscle twitch height. The ED50 and ED90 describe a depression of twitch height by 50% and 90% respectively.
The ED95 (mg/kg) of the commonly used neuromuscular blocking agents are:
suxamethonium: 0.27
rocuronium: 0.31
vecuronium: 0.04
pancuronium: 0.07
cisatracurium: 0.04
mivacurium: 0.08 -
This question is part of the following fields:
- Pharmacology
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Question 67
Correct
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The following results were obtained In a new drug trial:
Improved Not improved
Placebo group 36 26
Treatment group 44 16
Regarding the statistical analysis or interpretation of the trial, One of these is trueYour Answer: The data could be evaluated using the chi square test
Explanation:This data is in a 2 × 2 contingency table so a chi square test can be used. There is a special chi squared formula that gives a value that can be looked up in a table giving the p value.
Since we are comparing proportions not means, the Student’s t test CANNOT be used.
There is no linear regression to plot so Pearson’s co-efficient cannot be calculated.
Nothing is so obvious that no statistical analysis is needed.
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This question is part of the following fields:
- Statistical Methods
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Question 68
Incorrect
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A new drug treatment has been developed for Crohn's disease. The pharmaceutical company behind this, is planning to conduct a trial and is looking for hiring around 200 individuals that are suffering from Crohn's disease. The aim would be to determine if there is any decline in the disease activity in response to the drug and compare it with a placebo.
What phase is the trial in?Your Answer: Phase 1
Correct Answer: Phase 2
Explanation:The study is being conducted on a smaller level with only 200 participants and is determining the effectiveness of the drug in comparison to a placebo. These characteristics are in accordance with the second phase of trial.
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This question is part of the following fields:
- Statistical Methods
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Question 69
Correct
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Question 70
Incorrect
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All of the following statements about that parasympathetic nervous system (PNS) are true except:
Your Answer: Facial nerve supplies the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
Correct Answer: The PNS has nicotinic receptors throughout the system
Explanation:With regards to the autonomic nervous system (ANS)
1. It is not under voluntary control
2. It uses reflex pathways and different to the somatic nervous system.
3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.With regards to the central nervous system (CNS)
1. There are myelinated preganglionic fibres which lead to the
ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.Most organs are under control of both systems although one system normally predominates.
The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.
There are short pre-ganglionic and long post ganglionic fibres.
Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.
There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.
Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.
The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.
The cranial outflow consists of
1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreasThe sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.
The PNS has long preganglionic and short post ganglionic fibres.
Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.Different types of these muscarinic receptors are present in different organs:
There are:
M1 = pupillary constriction, gastric acid secretion stimulation
M2 = inhibition of cardiac stimulation
M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
M4 = brain and adrenal medulla
M5 = brainThe lacrimal glands are solely under parasympathetic control.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 71
Incorrect
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A 63-year-old woman, is admitted into hospital. She has undergone a thoracoscopic sympathectomy.
To enable ease of access during surgery, her right arm has been abducted.
On examination, immediately after surgery, she is noted to have lost the ability to abduct her right arm, with the presence a weak lateral rotation in the same arm. She has also lost sensation in the outer aspect of the lower deltoid area of the skin.
Her symptoms are as a result of injury to a nerve during surgery. What nerve is it?Your Answer: Thoracodorsal nerve
Correct Answer: Axillary nerve
Explanation:The axillary nerve arises from spinal roots C5-C6. It has both sensory and motor functions:
Sensory: Provides innervation to the skin over the lower deltoid area
Motor: Provides innervation to the teres minor (responsible for stabilisation of glenohumeral joint and external rotation of shoulder joint) and deltoid muscles (responsible for abduction of arms glenohumeral joint).
Injury to the axillary nerve will result in the patient being unable to abduct the arm beyond 15 degrees and a loss of sensory feeling over lower deltoid area.
These symptoms could also be a result of over-abduction of the arm (>90°) which would cause the head of the humerus to become dislocated.
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This question is part of the following fields:
- Pathophysiology
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Question 72
Correct
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A 21-year-old woman presents to ER following the deliberate ingestion of 2 g of amitriptyline. On clinical examination:
Glasgow coma score: 10
Pulse rate: 140 beats per minute
Blood pressure: 80/50 mmHg.
ECG showed a QRS duration of 233 Ms.
Which of the following statement describes the most important initial course of action?Your Answer: Give fluid boluses
Explanation:The first line of treatment in case of hypotension is fluid resuscitation.
Activated charcoal can be used within one hour of tricyclic antidepressant ingestion but an intact and secure airway must be checked before intervention. The risk of aspiration should be assessed.
Vasopressors are indicated for the treatment of hypotension following (Tricyclic Antidepressant) TCA overdose when patients fail to respond to fluids and bicarbonate.
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This question is part of the following fields:
- Pharmacology
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Question 73
Correct
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You are given an intravenous induction agent. The following are its characteristics:
A racemic mixture of cyclohexanone rings with one chiral centre
Local anaesthetic properties.
Which of the following statements about its primary mechanism of action is most accurate?Your Answer: Non-competitive antagonist affecting Ca2+ channels
Explanation:Ketamine is the substance in question. Its structure and pharmacodynamic effects make it a one-of-a-kind intravenous induction agent. The molecule is made up of two cyclohexanone rings (2-(O-chlorophenyl)-2-methylamino cyclohexanone and 2-(O-chlorophenyl)-2-methylamino cyclohexanone). Ketamine has local anaesthetic properties and acts primarily on the brain and spinal cord.
It affects Ca2+ channels as a non-competitive antagonist for the N-D-methyl-aspartate (NMDA) receptor. It also acts as a local anaesthetic by interfering with neuronal Na+ channels.
Ketamine causes profound dissociative anaesthesia (profound amnesia and analgesia) as well as sedation.
Phenoxybenzamine, an alpha-1 adrenoreceptor antagonist, is an example of an irreversible competitive antagonist. It forms a covalent bond with the calcium influx receptor.
Benzodiazepines are GABAA receptor agonists that affect chloride influx.
Flumazenil is an inverse agonist that affects GABAA receptor chloride influx.
Ketamine is a cyclohexanone derivative that acts as a non-competitive Ca2+ channel antagonist.
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This question is part of the following fields:
- Pharmacology
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Question 74
Incorrect
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A 30-year-old woman admitted following a tonsillectomy has developed stridor with a respiratory rate of 22 breaths per minute and obstructive movements of the chest and abdomen that is in a see-saw pattern .
Her SpO2 is 92% on 60% oxygen with pulse rate 120 beats per minute while her blood pressure is 180/90mmHg. She is repeatedly trying to remove the oxygen mask and appears anxious.
Her pharynx is suctioned and CPAP applied with 100% oxygen via a Mapleson C circuit.
Which of these is the most appropriate next step in her management?Your Answer: Perform a superior laryngeal nerve block
Correct Answer: Administer intravenous propofol 0.5 mg/kg
Explanation:Continuous closure of the vocal cords resulting in partial or complete airway obstruction is called Laryngospasm. It is a reflex that helps protect against pulmonary aspiration.
Predisposing factors include: Hyperactive airway disease, Insufficient depth of anaesthesia, Inexperience of the anaesthetist, Airway irritation, Smoking, Shared airway surgery and Paediatric patients
Its primary treatment includes checking for blood or stomach aspirate in the pharynx, removing any triggering stimulation, relieving any possible supra-glottic component to airway obstruction and application of CPAP with 100% oxygen.
In this patient, all the above has been done and the next treatment of choice is the administration of a rapidly acting intravenous anaesthetic agent such as propofol (0.5 mg/kg) in increments as it has been reported to relieve laryngospasm in approximately 75% of cases. Administering suxamethonium to an awake patient would be inappropriate at this stage.
Magnesium and lidocaine are used for prevention rather than acute treatment of laryngospasm. Superior laryngeal nerve blocks have been reported to successfully treat recurrent laryngospasm but it is not the next logical step in index patient.
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This question is part of the following fields:
- Pathophysiology
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Question 75
Incorrect
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A 77-year-old man is admitted to hospital for colorectal surgery. He is scheduled to undergo a preoperative assessment, which includes cardiopulmonary exercise test (CPX).
During the CPX, his maximum oxygen consumption (VO2 max) is determined to be 2,100 mL/minute. His weight is measured to be 100 kg.
Calculate the metabolic equivalent (MET) that is the best estimate for his VO2 max.Your Answer: 8 METs
Correct Answer: 6 METs
Explanation:Metabolic equivalent (MET) measures the energy expenditure of an individual.
It is calculated mathematically by:
MET = (VO2 max/weight)/3.5 = 21/3.5 = 6 METs
Where 1 MET = 3.5 mL O2/kg/minute is utilized by the body.
Note:
1 MET Eating
Dressing
Use toilet
Walking slowly on level ground at 2-3 mph
2 METs Playing a musical instrument
Walking indoors around house
Light housework
4 METs Climbing a flight of stairs
Walking up hill
Running a short distance
Heavy housework, scrubbing floors, moving heavy furniture
Walking on level ground at 4 mph
Recreational activity, e.g. golf, bowling, dancing, tennis
6 METs Leisurely swimming
Leisurely cycling along the flat (8-10 mph)
8 METs Cycling along the flat (10-14 mph)
Basketball game
10 METs Moderate to hard swimming
Competitive football
Fast cycling (14-16 mph) -
This question is part of the following fields:
- Clinical Measurement
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Question 76
Correct
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The Fick principle can be used to determine the blood flow to any organ of the body.
At rest, which one of these organs has the highest blood flow (ml/min/100g)?Your Answer: Thyroid gland
Explanation:After the carotid body, the thyroid gland is the second most richly vascular organ in the body.
The global blood flow to the thyroid gland can be measured using:
1. Colour ultrasound sonography
2. Quantitative perfusion maps using MRI of the thyroid gland using an arterial spin labelling (ASL) method.This table shows the blood flow to various organs of the body at rest:
Organ Blood Flow(ml/minute/100g)
Hepatoportal 58
Kidney 420
Brain 54
Skin 13
Skeletal muscle 2.7
Heart 87
Carotid body 2000
Thyroid gland 560 -
This question is part of the following fields:
- Physiology
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Question 77
Correct
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A new study is being carried out on the measurement of a new cardiovascular disease biomarker, and its applications in preoperative screening. The data for this study is expected to be normally distributed.
Which of the following statements is true about normal distributions?Your Answer: The mean, median and mode are the same value
Explanation:The correct answer is the mean, median and mode of normally distributed data are the same value. This is as a result of the bell shaped curve which is equal on both sides.
The bell-shape indicates that values around the mean are more frequent in occurrence than the values farther away.
In a normal distribution:
1) +/- one standard deviation of the mean accounts for 68% of the data.
2) +/- two standard deviations of the mean accounts for 95% of the data.
3) +/- three standard deviations of the mean accounts for 99.7% of the data. -
This question is part of the following fields:
- Statistical Methods
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Question 78
Correct
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At what site would you palpate to assess the posterior tibial pulse?
Your Answer: Behind and below the medial ankle
Explanation:The posterior tibial artery originates from the popliteal artery in the popliteal fossa. It passes posterior to the popliteus muscle to pierce the soleus muscle. It descends between the tibialis posterior and flexor digitorum longus muscles.
The posterior tibial artery supplies blood to the posterior compartment of the lower limb. The artery can be palpated posterior to the medial malleolus.
There are 4 main pulse points for the lower limb:
1. Femoral pulse 2-3 cm below the mid-inguinal point
2. Popliteal partially flexed knee to loosen the popliteal fascia
3. Posterior tibial behind and below the medial ankle
4. Dorsal pedis dorsum of the foot over the navicular bone -
This question is part of the following fields:
- Anatomy
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Question 79
Correct
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With regards to the repolarisation phase of the myocardial action potential, which of the following is responsible?
Your Answer: Efflux of potassium
Explanation:Cardiac conduction
Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium
Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop
Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period
Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period
Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 80
Correct
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A post-operative patient was given paracetamol and pethidine for post-operative analgesia. A few hours later, the patient developed fever of 38°C, hypertension, and agitation.
According to the patient's medical history, he is maintained on Levodopa and Selegiline for Parkinson's disease.
Which of the following is the most probable cause of his manifestation?Your Answer: Pethidine
Explanation:Selegiline is a monoamine oxidase inhibitor. Inhibition of monoamine oxidase leads to increased levels of norepinephrine and serotonin in the central nervous system.
Pethidine, also known as meperidine, is a strong agonist at the mu and kappa receptors. It inhibits pain neurotransmission and blocks muscarinic-specific actions.
Administering opioid analgesic is relatively contraindicated to individuals taking monoamine oxidase inhibitors. This is because of the high incidence of serotonin syndrome, which is characterized by fever, agitation, tremor, clonus, hyperreflexia and diaphoresis. Onset of symptoms is within hours, and the treatment is mainly through sedation, paralysis, intubation and ventilation.
The clinical findings are more consistent with Serotonin syndrome rather than exacerbation of Parkinson’s. Parkinson’s Disease (PD) exacerbations are defined as patient-reported or caregiver-reported episodes of subacute worsening of PD motor function in 1 or more domains (bradykinesia, tremor, rigidity, or PD-related postural instability/gait disturbance) that caused a decline in functional status, developed over a period of < 2 months, did not fluctuate with medication timing, and are not caused by intentional adjustments of PD medications by the treating neurologist. Malignant hyperthermia usually occurs within minutes of administration of a volatile anaesthetic, such as halothane, or succinylcholine. There is massive release of calcium from the sarcoplasmic reticulum, leading to fever, acidosis, rhabdomyolysis, trismus, clonus, and hypertension. In sepsis, it more common for patients to present with hypotension rather than hypertension.
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This question is part of the following fields:
- Pharmacology
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Question 81
Incorrect
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Concerning the trachea, which of these is true?
Your Answer: Is made up of 12 C-shaped cartilaginous rings
Correct Answer: In an adult is approximately 15 cm long
Explanation:In an adult, the trachea is approximately 15 cm long. It extends at the level of the 6th cervical vertebra, from the lower border of the cricoid cartilage.
The trachea terminates between T4 and T6 at the carina or bronchial bifurcation. This variation is because of changes during respiration.
The trachea has 16-20 C-shaped cartilaginous rings that maintain its patency.
The trachea is first of the 23 generations of air passages in the tracheobronchial tree (not 25), from the trachea to the alveoli..
The inferior thyroid arteries which are branches of the thyrocervical trunk, arise from the first part of the subclavian artery and supplies the trachea.
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This question is part of the following fields:
- Anatomy
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Question 82
Incorrect
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A 66-year-old man with a haemorrhagic stroke is admitted to the medical admissions unit.
He has been taking warfarin for a long time because of atrial fibrillation. His INR at the time of admission was 9.1.
Which of the following treatment options is the most effective in managing his condition?Your Answer: Fresh frozen plasma
Correct Answer: Prothrombin complex concentrate
Explanation:Haemorrhage, including intracranial bleeding, is a common and potentially fatal side effect of warfarin therapy, and reversing anticoagulation quickly and completely can save lives. When complete and immediate correction of the coagulation defect is required in orally anticoagulated patients with life-threatening haemorrhage, clotting factor concentrates are the only viable option.
For rapid reversal of vitamin K anticoagulants, prothrombin complex concentrates (PCC) are recommended. They contain the vitamin K-dependent clotting factors II, VII, IX, and X and are derived from human plasma. They can be used as an adjunctive therapy in patients with major bleeding because they normalise vitamin K dependent clotting factors and restore haemostasis.
The most common treatments are fresh frozen plasma (FFP) and vitamin K. The efficacy of this approach is questioned due to the variable content of vitamin K-dependent clotting factors in FFP and the effects of dilution. Significant intravascular volume challenge, as well as the possibility of rare complications like transfusion-associated lung injury or blood-borne infection, are all potential issues.
To avoid anaphylactic reactions, vitamin K should be given as a slow intravenous infusion over 30 minutes. Regardless of the route of administration, the reversal of INRs with vitamin K can take up to 24 hours to reach its maximum effect.
Reversal of anticoagulation in patients with warfarin-associated intracranial haemorrhage may be considered with factor VIIa (recombinant), but its use is controversial. There are concerns about thromboembolic events following treatment, as well as questions about assessing efficacy in changes in the INR. If the drug is to be administered, patients should be screened for an increased risk of thrombosis before the drug is given.
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This question is part of the following fields:
- Pathophysiology
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Question 83
Incorrect
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It was hypothesized that people that had lower socio economic status were more prone to developing gastric cancer. After 30 years of studying people with lower socio economic status, it was found that they did have a greater tendency to develop cancer. As a result of that the authors got to the conclusion that a strong association existed between the two. Later on another study conducted found that people from lower socio economic back grounds also had a tendency to be smokers.
Which form of potential bias can be associated with this particular study?Your Answer: Sampling bias
Correct Answer: Confounding bias
Explanation:Selection bias is when randomisation is not achieved and is often a result of in efficient recruiting method.
Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.
Measurement bias can be characterized by gathering of information in a manner that is distorted.
When the participants of a research study are recruited from the hospitals rather than the general population, its called Berkson Bias.
Confounding bias is the major player here because in this case the effects of smoking can be masked behind and can be read as outcomes of lower socio economic status. This extraneous factor (Smoking), distorts the founding.
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This question is part of the following fields:
- Statistical Methods
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Question 84
Correct
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A 26-year-old male was diagnosed with hypovolaemic shock following a road traffic accident. On clinical examination:
Heart rate: 125 beats/min
Blood pressure: 120/105 mmHg.
On physical examination, his abdomen was found to be tense and tender. Which of the following receptors is responsible for the compensation of blood loss?Your Answer: Alpha 1 adrenergic
Explanation:Alpha 1 adrenergic receptor stimulation results in vasoconstriction of peripheral arteries mainly of those of skin, gut and kidney arterioles. This would cause and increase in total peripheral resistance and mean arterial pressure and as a result the perfusion of vital organs i.e. brain, heart and lungs are maintained.
Muscarinic M2 receptor also known as cholinergic receptor are located in heart, where they act to slow the heart rate down to normal sinus rhythm after negative stimulatory actions of parasympathetic nervous system. They also reduce contractile forces of the atrial cardiac muscle, and reduce conduction velocity of AV node. This could worsen the compensation.
Stimulation of beta 2 adrenergic receptor result in dilation of smooth muscle as in bronchodilation.
Beta 3 adrenergic receptors are present on cell surface f both white and brown adipocytes and are responsible for lipolysis, thermogenesis, and relaxation of intestinal smooth muscle.
Alpha 2 adrenergic receptor stimulation results in inhibition of the release of noradrenaline in a form of negative feedback.
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This question is part of the following fields:
- Pharmacology
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Question 85
Correct
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Buffers are solutions that resist a change in pH when protons are produced or consumed. They consist of weak acids and their conjugate bases. Buffers are also present in our bodies, and they are known as physiologic buffers.
Which of these is the most effective buffer in the blood?Your Answer: Bicarbonate
Explanation:The first line of defence against acid-base disorder is buffering. The blood mainly utilizes bicarbonate ion (HCO3-) for its buffering capacity (total of 53%, plasma and red blood cells combined).
Strong acids, when acted upon by a buffer, release H+, which then combines to HCO3- and forms carbonic acid (H2CO3). When acted upon by the enzyme carbonic anhydrase, H2CO3 dissociates into H2O and CO.
The rest are the percentage of utilization for the following buffers:
Haemoglobin (by RBCs) – 35%
Plasma proteins (by plasma) – 7%
Organic phosphates (by RBCs) – 3%
Inorganic phosphates (by plasma) – 2% -
This question is part of the following fields:
- Pharmacology
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Question 86
Incorrect
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A 58-year-old man, visits his general practitioner complaining of a lump in his groin. He explains he is otherwise well and reports no other symptoms. The lump is examined and is found to be soft, and can be reduced without causing the patient pain. The GP diagnoses an inguinal hernia. To determine the nature of the hernia, the GP reduced the lump and applies pressure on the deep inguinal ring.
The deep inguinal ring has what anatomical landmark?Your Answer: Superior to the mid inguinal point
Correct Answer: Superior to the midpoint of the inguinal ligament
Explanation:The deep inguinal ring lies approximately 1.5-2cm above the midpoint of the inguinal ligament, the halfway point between the anterior superior iliac spine and the pubic tubercle, next to the epigastric vessels.
It is an important point in determining the nature of an inguinal hernia (direct or indirect). The patient is asked to cough after the hernia is reduced, with pressure applied to the deep inguinal ring. The hernia reappearing indicates it is direct, moving through the posterior wall of the inguinal canal.
Inferior and lateral to the pubic tubercle is the normal anatomical position of the neck of a femoral hernia.
Superior and medial to the pubic tubercle is the site of the superficial inguinal ring, and the normal anatomical position of the neck of an inguinal hernia.
The mid-inguinal point is located halways between the pubic symphysis and the anterior superior iliac spine. It is the surface marking for taking the femoral pulse.
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This question is part of the following fields:
- Anatomy
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Question 87
Incorrect
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A balanced general anaesthetic including a muscle relaxant is administered at induction. It is observed that the train-of-four count is two after two hours, with no further doses of the muscle relaxant.
What is most likely reason for this?Your Answer: Suxamethonium with plasma cholinesterase deficiency
Correct Answer: Mivacurium with plasma cholinesterase deficiency
Explanation:Mivacurium is metabolised primarily by plasma cholinesterase at an In vitro rate of about 70% that of succinylcholine. Mivacurium is contraindicated in patients with genetic and acquired plasma cholinesterase deficiencies.
The clearance of atracurium is by Hoffman degradation and ester hydrolysis in the plasma and is independent of both hepatic and renal function.
Rocuronium is eliminated primarily by the liver after metabolises to a less active metabolite, 17-desacetyl-rocuronium. Its duration of action is not affected much by renal impairment.
Vecuronium undergoes hepatic metabolism into 3-desacetyl-vecuronium which has 50-80% the activity of the parent drug. It undergoes biliary (40%) and renal excretion (30%). The aminoglycoside antibiotics possess additional neuromuscular blocking activity. The potency of gentamicin > streptomycin > amikacin. Calcium can be used to reverse the muscle weakness produced by gentamicin but not neostigmine. When vecuronium and gentamycin are given together the effect on neuromuscular blockade is synergistic.
Significant residual neuromuscular block 2 hours after the administration of these drugs is unlikely In this scenario.
Any recovery from neuromuscular blockade with suxamethonium in a patient with deficiency of plasma cholinesterase demonstrate four twitches on a train of four count.
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This question is part of the following fields:
- Pharmacology
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Question 88
Incorrect
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Which of the following is true when testing for statistical significance?
Your Answer: The significance level (p) is always set to 5%
Correct Answer: The probability associated with a type I error is the significance level
Explanation:The null hypothesis states that there is no significant difference between two groups.
The alternative hypothesis states that there is a significant difference between two groups.
A type I error (false positive) occurs when a null hypothesis is rejected when it should be accepted.
A type II error (false negative) occurs when the alternative hypothesis is rejected when it should be accepted.
The probability determines the rejection of a null hypothesis.
The level of significance is set at p <0.05.
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This question is part of the following fields:
- Statistical Methods
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Question 89
Incorrect
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Which of these statements regarding the basilar artery and its branches is not true?
Your Answer: The superior cerebellar artery may be decompressed to treat trigeminal neuralgia
Correct Answer: The posterior inferior cerebellar artery is the largest of the cerebellar arteries arising from the basilar artery
Explanation:The posterior inferior cerebellar artery is the largest branch arising from the distal portion of the vertebral artery which forms the basilar artery. It is one of the arteries responsible for providing blood supply to the brain’s cerebellum.
The labyrinthine artery (auditory artery) is a long and slender artery which arises from the basilar artery and runs alongside the facial and vestibulocochlear nerves into the internal auditory meatus.
The posterior cerebellar artery is one of two cerebral arteries supplying the occipital lobe with oxygenated blood. It is usually bigger than the superior cerebellar artery. It is separated from the vessel near its origin by the oculomotor nerve.
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This question is part of the following fields:
- Anatomy
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Question 90
Correct
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A 79-year-old female complains of painful legs, especially in her thigh region. The pain starts after walking and settles with rest. She occasionally has to take paracetamol to relieve the pain. She is a known case of hyperlipidaemia, type 2 diabetes mellitus, hypertension, and depression.
Her physician makes a provisional diagnosis of claudication of the femoral artery, which is a continuation of the external iliac artery.
Which of the following anatomical landmarks does the external iliac artery cross to become the femoral artery?Your Answer: Inguinal ligament
Explanation:The external iliac artery is the larger of the two branches of the common iliac artery. It forms the main blood supply to the lower limbs. The common iliac bifurcates into the internal and external iliac artery anterior to the sacroiliac joint.
The external iliac artery courses on the medial border of the psoas major muscles and exits the pelvic girdle posterior to the inguinal ligament. Here, midway between the anterior superior iliac spine and the pubic symphysis, the external iliac artery becomes the femoral artery and descends along the anteromedial part of the thigh in the femoral triangle.
The pectineus forms the posterior border of the femoral canal.
The femoral vein forms the lateral border of the femoral canal.
The medial border of the adductor longus muscle forms the medial wall of the femoral triangle.
The medial border of the sartorius muscle forms the lateral wall of the femoral triangle. -
This question is part of the following fields:
- Anatomy
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Question 91
Correct
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Which of the following statements about the cricoid cartilage is true?
Your Answer: The lower border is attached to the first tracheal ring
Explanation:The cricoid cartilage is a hyaline cartilage ring surrounding the trachea. It provides support for key phonation muscles.
The inferior border of the cricoid cartilage is attached to the thyroid cartilage and the inferior border is attached to the first tracheal ring through the cricotracheal ligament.
Application of pressure to the cricoid cartilage to reduce risk of aspiration of gastric contents (Sellick manoeuvre) does not stop tracheal aspiration and cannot stop regurgitation into the oesophagus.
A force of 44 newtons to the cricoid cartilage is needed to control regurgitation.
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This question is part of the following fields:
- Antomy
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Question 92
Correct
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An individual who recently moved his residence from the plains to the mountains will experience immediately which physiologic response to high altitude and hypoxia?
Your Answer: Increased cardiac output
Explanation:A person remaining at high altitudes for days, weeks, or years becomes more and more acclimatized to the low PO2, so it causes fewer deleterious effects on the body.
After acclimatization, it becomes possible for the person to work harder without hypoxic effects or to ascend to still higher altitudes. The principal means by which acclimatization comes about are (1) a great increase in pulmonary ventilation, (2) increased numbers of red blood cells, (3) diffusing capacity of the lungs, (4) increased vascularity of the peripheral tissues, and (5) increased ability of the tissue cells to use oxygen despite low PO2.
The cardiac output often increases as much as 30% immediately after a person ascends to high altitude but then decreases back toward normal over a period of weeks as the blood haematocrit increases, so the amount of oxygen transported to the peripheral body tissues remains about normal.
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This question is part of the following fields:
- Pathophysiology
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Question 93
Correct
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An inguinal hernia repair under general anaesthesia is scheduled for a fit 36-year-old man (75 kg). For perioperative and postoperative analgesia, you decide to perform an inguinal field block.
Which of the following local anaesthetic solutions is the most appropriate?Your Answer: 30 mL bupivacaine 0.5%
Explanation:Perioperative and postoperative analgesia can both be provided by an inguinal hernia field block. The Iliohypogastric and ilioinguinal nerves, as well as the skin, superficial fascia, and deeper structures, must be blocked for maximum effectiveness. The local anaesthetic should ideally have a long duration of action, be highly concentrated, and have a volume of at least 30 mL.
Plain bupivacaine has a maximum safe dose of 2 mg/kg body weight.
Because the patient weighs 75 kg, 150 mg bupivacaine can be safely administered. Both 30 mL 0.5 percent bupivacaine (150 mg) and 60 mL 0.25 percent bupivacaine (150 mg) are acceptable doses, but 30 mL 0.5 percent bupivacaine represents the optimal volume and strength, potentially providing a denser and longer block.
The maximum safe dose of plain lidocaine has been estimated to be between 3.5 and 5 mg/kg. The patient weighs 75 kg and can receive a maximum of 375 mg using the higher dosage regimen:
There are 200 mg of lidocaine in 10 mL of 2% lidocaine (and therefore 11 mL contains 220 mg)
200 mg of lidocaine is contained in 20 mL of 1% lidocaine.While alternatives are available, Although the doses of 11 mL lidocaine 2% and 20 mL lidocaine 1% are well within the dose limit, the volumes used are insufficient for effective field block for this surgery.
With 1 in 200,000 epinephrine, the maximum safe dose of lidocaine is 7 mg/kg. The patient can be given 525 mg in this case. Even with epinephrine, 60 mL of 1% lidocaine is 600 mg, which could be considered an overdose.
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This question is part of the following fields:
- Pharmacology
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Question 94
Correct
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Of the following, which is NOT a branch of the subclavian artery?
Your Answer: Superior thyroid artery
Explanation:The left subclavian artery originates from the aortic arch, while the right subclavian artery originates from the brachiocephalic artery.
The subclavian artery gives off branches on both sides of the body:
1. Vertebral artery
2. Internal thoracic artery
3. Thyrocervical trunk
4. Costocervical trunk
5. Dorsal scapular arteryThe superior thyroid artery is the first branch of the external carotid artery. The other branches of the external carotid artery are:
1. Superior thyroid artery
2. Ascending pharyngeal artery
3. Lingual artery
4. Facial artery
5. Occipital artery
6. Posterior auricular artery
7. Maxillary artery
8. Superficial temporal artery -
This question is part of the following fields:
- Anatomy
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Question 95
Correct
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Of the stated laws, which is correct?
Your Answer: Boyle's law states that at constant temperature the volume of a given mass of gas varies inversely with absolute pressure.
Explanation:Boyle’s law is correctly stated as it states that the volume of a gas of known mass is inversely proportional with absolute pressure, at a constant temperature.
Beer’s law states that radiation absorption by a solution of known thickness and concentration is identical to that of a solution of double thickness and half concentration.
Bougner’s (or Lambert’s) law states that every layer with the same thickness will absorb the same amount of radiation as it passes through.
Graham’s law states that the diffusion rate of a gas is inversely related to the square root of its molecular weight.
Raoult’s law states that the reduction of a solvent’s vapour pressure is directly proportional to the solute’s molar concentration.
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This question is part of the following fields:
- Statistical Methods
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Question 96
Correct
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A 28-year-old man is admitted to the critical care unit. He has been diagnosed with adult respiratory distress syndrome and is being ventilated. His haemodynamic condition is improved using a pulmonary artery flotation.
His readings are listed below:
Haemoglobin concentration: 10 g/dL
Mixed venous oxygen saturation: 70%
Mixed venous oxygen tensions (PvO2): 50 mmHg
Estimate his mixed venous oxygen content (mL/100mL).Your Answer: 9.5
Explanation:Mixed venous oxygen content (CvO2) is the oxygen concentration in 100mL of mixed venous blood taken from the pulmonary artery. It is usually 12-17 mL/dL (70-75%). It is represented mathematically as:
CvO2 = (1.34 x Hgb x SvO2 x 0.01) + (0.003 x PvO2)
Where,
1.34 = Huffner’s constant
Hgb = Haemoglobin level (g/dL)
SvO2 = % oxyhaemoglobin saturation of mixed venous blood
PvO2 = 0.0225 = mL of O2 dissolved per 100mL plasma per kPa, or 0.003 mL per mmHgTherefore,
CvO2 = (1.34 x 10 x 70 x 0.01) + (0.003 x 50)
CvO2 = 9.38 + 0.15 = 9.53 mL/100mL
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This question is part of the following fields:
- Clinical Measurement
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Question 97
Correct
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If a patient is to be placed under general anaesthesia using total intravenous technique with target-controlled infusions of propofol and remifentanil, what safety precaution is the most vital in this a scenario?
Your Answer: Cannula access site clearly visible and regularly checked
Explanation:According to the Safe Anaesthesia Liaison Group, the most important factor to consider the cannula access, and if the patient is properly receiving the total intravenous anaesthesia. The cannula access must be regularly checked for kinks, leaks and disconnections.
Below are the safety precautions and policies to be followed for total intravenous anaesthesia among children and adults:
When administering TIVA, a non-return valve must be used on any intravenous fluid line;
When using equipment, it is essential that clinical staff know its limitations and uses;
Sites of intravenous infusions should be visible so they may be monitored for disconnection, leaks or perivenous infusion into the subcutaneous tissues; and,
Organisations must give preference to clearly labelled intravenous connectors and valves. -
This question is part of the following fields:
- Pathophysiology
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Question 98
Correct
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A 70-year-old man presents with bilateral buttock claudication that spreads down the thigh and erectile dysfunction in a vascular clinic.
The left femoral pulse is not palpable on examination, and the right is weakly palpable. Leriche syndrome is diagnosed as the blood flow at the abdominal aortic bifurcation is blocked due to atherosclerosis. He is prepared for aortoiliac bypass surgery.
Which vertebral level will you find the affected artery that requires bypassing?Your Answer: L4
Explanation:The bifurcation of the abdominal aorta into common iliac arteries occurs at the level of L4. The bifurcation is a common site for atherosclerotic plaques as it is an area of high turbulence.
Leriche Syndrome is an aortoiliac occlusive disease and affects the distal abdominal aorta, iliac arteries, and femoropopliteal vessels. It has a triad of symptoms:
1. Claudication (cramping lower extremities pain that is reproducible by exercise)
2. Impotence (reduced penile arterial flow)
3. Absent/weak femoral pulses (hallmark)T12 – aorta enters the diaphragm with the thoracic duct and azygous veins
L2 – testicular or ovarian arteries branch off the aorta
L3 – inferior mesenteric artery
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This question is part of the following fields:
- Anatomy
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Question 99
Correct
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A drug with a 2-hour half-life and a first-order kinetics of elimination is administered intravenously. The initial plasma concentration is calculated to be 12 mcg/mL and plasma concentrations is measured hourly.
At 6 hours, how much drug will be left?Your Answer: 1.5 mcg/mL
Explanation:In first order kinetics the rate of elimination is proportional to plasma concentration.
Rate of elimination is described by the following equation:
C = C0. e^-kt
Where:
C=drug concentration,
C0= drug concentration at time zero (extrapolated),
k = rate constant and
t = time.The initial concentration of this drug is 12 mcg/ml therefore:
The plasma concentration will have halved to 6 mcg/ml at 2 hours.
The plasma concentration will have halved to 3 mcg/ml at 4 hours and
The plasma concentration will have halved to 1.5 mcg/ml t 6 hours. -
This question is part of the following fields:
- Pharmacology
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Question 100
Correct
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Regarding the treatment of bladder cancer, a study concerned with the usage of a combined or monotherapy was conducted. A forest plot was used for the visual representation of the data.
Which of the following is true regarding forest plots?Your Answer: Forest plots can present data from multiple studies
Explanation:Being the part of a meta analysis, forest plots are more valued as evidence then randomised control trials.
The notion that forest plots can only be used if the results are substantial is not true. They are good indicators of the significance of the data. If the diamond intersects the central line, the data is rendered significant. It also aggregates means and confidence intervals from studies conducted in the past which makes the study much more reliable as errors associated with individual studies tend to have less of an impact in this way.
The suggestion that forest plots are primarily used for qualitative data is factually incorrect. Forest plots require numerical values to function.
All in all, forest plots help us in determining whether or not there is a significant trend in that particular field of study.
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This question is part of the following fields:
- Statistical Methods
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