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  • Question 1 - A 16-year-old female presents to the physician with nausea, vomiting and abdominal swelling....

    Incorrect

    • A 16-year-old female presents to the physician with nausea, vomiting and abdominal swelling. Physical examination also reveals digital clubbing and linea nigra on her abdomen. Which of the following is the most likely diagnosis?

      Your Answer: Cirrhosis

      Correct Answer: Pregnancy

      Explanation:

      Clinical signs of early pregnancy-Amenorrhoea-Nausea and vomiting -Breast enlargement and tenderness -Hyperpigmentation of the areola and formation of linea nigra: Most likely due to increased levels of melanocyte-stimulating hormone produced by the placenta -Increased urinary frequency-Fatigue-Cravings for or aversions to certain foods-Abdominal bloating and constipation

    • This question is part of the following fields:

      • Adolescent Health
      18.8
      Seconds
  • Question 2 - A 14-year-old uncontrolled asthmatic is started on a steroid inhaler. Which of the...

    Correct

    • A 14-year-old uncontrolled asthmatic is started on a steroid inhaler. Which of the following is the most common adverse effect he might complain about?

      Your Answer: Dysphonia

      Explanation:

      Usage of inhaled corticosteroids are less associated with systemic adverse effects. However they are associated with local complications including dental caries and most commonly dysphonia.

    • This question is part of the following fields:

      • Respiratory
      17.2
      Seconds
  • Question 3 - A 13-year-old girl presents to the hospital with a body mass index (BMI)...

    Incorrect

    • A 13-year-old girl presents to the hospital with a body mass index (BMI) of 13. On examination, she was found to have cold peripheries. Her vitals were:Pulse rate: 130 bpmTemperature: 37°CCapillary blood glucose: 1.8 mmol/LAfter drawing blood for a full blood panel, you immediately give a bolus of glucose at a dose of 2 ml/kg. Her sugar levels improve to 4 mmol/L.What is the next step in the management of this child?

      Your Answer: Correct any electrolyte abnormalities

      Correct Answer: Normal saline fluid bolus| send blood culture, lactate and C-reactive protein

      Explanation:

      The next step in the management of this patient is starting a normal saline fluid bolus, following which we should send samples for blood culture, lactate and C-reactive protein. The patient is probably a case of anorexia nervosa (AN).Note:Children with AN are at higher risk of developing infections, and this needs to be considered in this case. Patients with AN may not respond in the usual fashion to sepsis as they may not mount a fever in response to infection. Hypoglycaemia (especially when severe or persistent despite correction) should raise the alarm for an infection as should tachycardia and cool peripheries. Children with severe AN are more likely to be bradycardic. Therefore, a tachycardia should cause the clinician to consider that another process is going on.Other options:- Correcting electrolyte abnormalities is, of course, very important. However, while these are awaited, one needs to consider that this patient is septic and managed accordingly. Children with anorexia nervosa (AN) may have a whole host of electrolyte abnormalities, some of which can be treated with oral or nutritional supplementation although sometimes intravenous correction is required. Electrolytes need to be checked frequently during admission because of the risk of refeeding syndrome, and dietetic input is required to advise on appropriate starting intake.- While maintenance fluids like dextrose are likely to be needed in this case, consideration needs to be given to the underlying cause of the hypoglycaemia. As the sugar has come up following a glucose bolus, a 10% dextrose infusion would be excessive.- An ECG should form a part of any assessment of a child with AN. In this case, it would not be the first thing| however, as part of the acute management of this child, cardiac monitoring should be commenced. One would usually expect a child with AN to be bradycardic so a tachycardia should raise suspicion that another process is going on.- Dietary input will be vital for this child’s ongoing management. However, their acute issues take precedence in this case. Nevertheless, a dietician should be informed and involved from an early stage.

    • This question is part of the following fields:

      • Nutrition
      38.4
      Seconds
  • Question 4 - A 16 year old female has been admitted to hospital after overdosing on...

    Incorrect

    • A 16 year old female has been admitted to hospital after overdosing on paracetamol 4 hours ago. She has also consumed a large amount of alcohol. Her plasma paracetamol concentration is only just below a level which requires treatment. From the list of options, choose the most appropriate treatment option for this patient.

      Your Answer: N-acetylcysteine

      Correct Answer: Refer to psychiatry ward

      Explanation:

      As her paracetamol level is under the required treatment threshold, she requires no medical treatment. However, she has taken a simultaneous drug overdose and excessive alcohol consumption. These two factors together require psychiatric evaluation and so she should be referred to the psychiatry ward.

    • This question is part of the following fields:

      • Adolescent Health
      36.4
      Seconds
  • Question 5 - A 6 month old baby presents with uncontrollable movements of her hands and...

    Correct

    • A 6 month old baby presents with uncontrollable movements of her hands and feet, shortly after being unconscious for a while. What is the most likely diagnosis?

      Your Answer: Infantile spasm

      Explanation:

      Infantile spasm belongs to the spectrum of seizure disorders. Infantile spasm manifests itself with loss of consciousness and jerky movements. The peak age of onset is between 4 and 6 months. Approximately 90% of infantile spasms begin before 12 months of age. It is rare for infantile spasms to begin during the first 2 weeks of life or after 18 months.

    • This question is part of the following fields:

      • Neurology
      26.4
      Seconds
  • Question 6 - A new treatment reduces blood pressure for hypertensive patients by 10 mmHg more...

    Incorrect

    • A new treatment reduces blood pressure for hypertensive patients by 10 mmHg more than the current standard treatment (95% confidence interval minus 2 to 22).Which of the following statements is most accurate?

      Your Answer: The difference is clinically significant

      Correct Answer: The difference is not statistically significant

      Explanation:

      If the 95% confidence interval contains zero (more precisely, the parameter value specified in the null hypothesis), then the effect will not be significant at the 0.05 level.If the 95% CI for the DIFFERENCE between the 2 groups contains the value 0, this means that the p-value will be greater than 0.05. Conversely, if the 95% CI does not contain the value 0, then the p-value will be strictly less than 0.05. The same applies when comparing groups using a ratio, such as an odds ratio or risk ratio. When using a RATIO instead of a DIFFERENCE, the situation of no difference between the 2 groups will be indicated by a value of 1 instead of 0. If the ratio equals to 1, the 2 groups are equal. Hence, if the 95% CI of the ratio contains the value 1, the p-value will be greater than 0.05. Alternatively, if the 95% CI does not contain the value 1, the p-value is strictly less than 0.05.

    • This question is part of the following fields:

      • Epidemiology And Statistics
      194
      Seconds
  • Question 7 - A 15-year-old rugby player is brought to the emergency by his teammates after...

    Incorrect

    • A 15-year-old rugby player is brought to the emergency by his teammates after suffering a blow to the face. He is applying pressure on his nose with a towel which is saturated with blood. Direct compression results in cessation of bleeding. On examination, a pink/blue mass can be seen occupying the right nostril. The rest of the ENT examination is not significant. The patient reports a blocked nose for the past few weeks. The boy is most likely suffering from which of the following conditions?

      Your Answer: Hereditary haemorrhagic telangiectasia

      Correct Answer: Juvenile Angiofibroma

      Explanation:

      Juvenile angiofibroma (JA) is a rare benign vascular lesion of the skull base that affects young adolescent males. The management of JA is challenged by the abundant vascular blood supply of the lesion, along with the complex anatomy of the skull base and the young age of the affected population. JA typically affects the male population, most commonly between 9 and 19 years of age. The most frequent symptoms are nasal obstruction and epistaxis. Nasal obstruction may be bilateral despite the unilaterality of the lesion, due to nasopharyngeal extension as well as deviation of the nasal septum by the expansile lesion. Epistaxis is usually brisk and intermittent. Purulent nasal discharge and facial pain can be due to sinus drainage pathway obstruction, and conductive hearing loss indicates obstruction of the eustachian tube.

    • This question is part of the following fields:

      • ENT
      47.8
      Seconds
  • Question 8 - A routine vitamin D screening test reveals low calcium levels in a 3-year-old...

    Correct

    • A routine vitamin D screening test reveals low calcium levels in a 3-year-old child.Which of the following could cause low calcium levels due to an artefact?

      Your Answer: Albumin

      Explanation:

      The accuracy of the test for calcium levels in the blood is affected by the blood level of albumin. If albumin levels are low, the calcium level can also appear low.This is termed as pseudohypocalcemia.Hypocalcaemia usually presents with muscle spams. These can include spasms of voluntary muscle but also smooth muscle such as in the airways (causing bronchospasm) and in the heart (causing angina).

    • This question is part of the following fields:

      • Gastroenterology And Hepatology
      13.9
      Seconds
  • Question 9 - Advanced paternal age is NOT a risk factor for which of the following...

    Correct

    • Advanced paternal age is NOT a risk factor for which of the following diseases?

      Your Answer: Turner syndrome

      Explanation:

      Advanced paternal age is associated with poor quality sperm leading to a reduction in overall fertility along with an increase in the occurrence of various medical disorders in the fetus. Advanced paternal age has been implicated as a risk factor for diseases like retinoblastoma, Marfan’s syndrome, neurofibromatosis, achondroplasia, autism spectrum disorders, schizophrenia, and acute lymphoblastic leukaemia. Down’s syndrome is mostly considered a consequence of advanced maternal age, but advanced paternal age has also been implicated as a risk factor. Turner syndrome is not found to be caused by advanced paternal age.

    • This question is part of the following fields:

      • Genetics And Dysmorphology
      4.1
      Seconds
  • Question 10 - An infant, 5 weeks and 6 days old born with a large sub-aortic...

    Correct

    • An infant, 5 weeks and 6 days old born with a large sub-aortic ventricular septal defect, is prepared for pulmonary artery banding through a left thoracotomy (the child is not fit for a surgical closure). The surgeon initially passes his index finger immediately behind two great arteries in the pericardial sac to mobilise the great arteries in order to pass the tape around the pulmonary artery. Into which space is the surgeon's finger inserted?

      Your Answer: Transverse pericardial sinus

      Explanation:

      Cardiac notch: is an indentation on the left lung of the heart.
      Coronary sinus: a venous sinus on the surface of the heart (the posterior aspect) that receives blood from the smaller veins that drain the heart.
      Coronary sulcus: a groove on the heart between the atria and ventricles.
      Transverse pericardial sinus: located behind the aorta and pulmonary trunk and anterior to the superior vena cava.
      Oblique pericardial sinus: located behind the left atrium. Accessed from the inferior side (or the apex) of the heart upwards.
      Horizontal pericardial sinus: this is a made-up term.

    • This question is part of the following fields:

      • Paediatric Surgery
      62.4
      Seconds
  • Question 11 - Congenital hypothyroidism is associated with which of the following clinical features? ...

    Correct

    • Congenital hypothyroidism is associated with which of the following clinical features?

      Your Answer: Cardiomegaly

      Explanation:

      Congenital hypothyroidism results from insufficient levels of thyroid hormone in the body since birth, which is either due to dysgenesis of the thyroid gland or dyshormonogenesis. The important features of this disease include coarse facial features (macroglossia, large fontanelles, depressed nasal bridge, hypertelorism, etc.), failure to thrive, cardiomegaly, hypotonia, umbilical hernia, and low core body temperature among many others. Frontal bossing is the usual feature of rickets and acromegaly. Mitral regurgitation is not usually associated with congenital hypothyroidism.

    • This question is part of the following fields:

      • Neonatology
      29.3
      Seconds
  • Question 12 - An 18-year-old male presents to his family physician after a sexual encounter with...

    Correct

    • An 18-year-old male presents to his family physician after a sexual encounter with his new girlfriend during which they had sexual intercourse around ten days ago. The girlfriend's HIV status is unknown, and the patient is concerned that he might have acquired HIV. He has a blood test for a 4th generation assay, testing for HIV antibody and a p24 antigen. The results come out negative, however, HIV infection cannot be ruled out as he may be presenting in the window period. Which of the following most likely explains the pathology of the window period?

      Your Answer: Antibodies to HIV undetectable

      Explanation:

      Any blood test used to detect HIV infection must have a high degree of sensitivity (the probability that the test will be positive if the patient is infected) and specificity (the probability that the test will be negative if the patient is uninfected). Unfortunately, no antibody test is ever 100 % sensitive and specific. Therefore, if available, all positive test results should be confirmed by retesting, preferably by a different test method. HIV antibody tests usually become positive within 3 months of the individual being infected with the virus (the window period). In some individuals, the test may not be positive until 6 months or longer (considered unusual). In some countries, home testing kits are available. These tests are not very reliable, and support such as pre and post test counselling is not available.

    • This question is part of the following fields:

      • HIV
      15.6
      Seconds
  • Question 13 - What post-birth event encourages closure of the ductus venosus in a new-born baby?...

    Incorrect

    • What post-birth event encourages closure of the ductus venosus in a new-born baby?

      Your Answer: First breath and fall in pulmonary vascular resistance

      Correct Answer: Umbilical cord clamping and separation from mother

      Explanation:

      After birth, the infant takes its first breath and is exposed to a myriad of stimuli. The pulmonary vessels dilate, and pulmonary vascular resistance (PVR) decreases remarkably while the systemic vascular pressure rises above the PVR. This allows blood from the right ventricle to enter the lungs for oxygenation. In most cases, this increased oxygenation, along with other factors, causes the ductal wall to constrict and the ductus arteriosus to close functionally. As left-sided pressures rise higher than right-sided pressures, the foramen ovale functionally closes. With the clamping of the umbilical cord and the cessation of blood flow, pressures in the portal sinus decrease. This causes the muscle in the sinus wall near the ductus venosus to contract. The lumen of the duct becomes filled with connective tissue, and, in two months, the ductus venosus becomes a fibrous strand embedded in the wall of the liver, thus establishing adult circulation.

    • This question is part of the following fields:

      • Neonatology
      34.9
      Seconds
  • Question 14 - A 15-day old baby was brought to the emergency department with constipation for...

    Incorrect

    • A 15-day old baby was brought to the emergency department with constipation for 4 days. On examination, the abdomen of the baby was found to be distended and tender all over. No bowel sounds were heard. A sigmoid colon biopsy was carried out, which showed absent ganglion cells. What is the diagnosis?

      Your Answer: Rectal atresia

      Correct Answer: Hirschsprung’s disease

      Explanation:

      Hirschsprung’s disease is characterized by congenital absence of the autonomic plexus (Meissner’s and Auerbach’s plexus) in the intestinal wall. Usually limited to the distal colon, it can occasionally involve the entire colon or even the small bowel. There is abnormal or absent peristalsis in the affected segment, resulting in continuous spasm of smooth muscle and partial/complete obstruction. This causes accumulation of intestinal contents and dilatation of proximal segment. Skip lesions are highly uncommon. This disease is seen early in life with 15% patients presenting in first month, 60% by 1 year of age and 85% by the age of 4 years. Symptoms include severe and complete constipation, abdominal distension and vomiting. Patients with involvement of ultra-short segments might have mild constipation with intervening diarrhoea. In older children, symptoms include failure to thrive, anorexia, and lack of an urge to defecate. On examination, an empty rectum is revealed with stool palpable high up in the colon. If not diagnosed in time, it can lead to Hirschsprung’s enterocolitis (toxic megacolon), which can be fulminant and lead to death. Diagnosis involves a barium enema or a rectal suction biopsy. Barium enema shows a transition in diameter between the dilated, normal colon proximal to the narrowed, affected distal segment. It is to be noted that barium enema should be done without prior preparation, which can dilate the abnormal segment, leading to a false-negative result. A 24-hour post-evacuation film can be obtained in the neonatal period – if the colon is still filled with barium, there is a high likelihood of Hirschsprung’s disease. Full-thickness rectal biopsy is diagnostic by showing the absence of ganglion cells. Acetylcholinesterase staining can be done to highlight the enlarged nerve trunks. Abnormal innervation can also be demonstrated by rectal manometry.

    • This question is part of the following fields:

      • Gastroenterology And Hepatology
      9325.6
      Seconds
  • Question 15 - A 6 year old child presents with a history of headache and a...

    Incorrect

    • A 6 year old child presents with a history of headache and a tonic-clonic seizure that lasted for three minutes. The doctor measures the blood pressure in all four limbs which is 180 mmHg. His creatinine is 60 μmol/l and he looks dehydrated. The kidneys look small and echogenic on ultrasound. Which of the following steps is most appropriate?

      Your Answer: Four-hourly blood pressure measurement should be requested

      Correct Answer: Ophthalmology assessment is indicated

      Explanation:

      The child requires frequent BP evaluation every 15 to 30 minutes. Normalisation of his BP should be achieved in a 48h interval. An ophthalmology assessment is indicated to check for acute injury of the blood vessels in the eye due to the elevated blood pressure.

    • This question is part of the following fields:

      • Nephro-urology
      60.2
      Seconds
  • Question 16 - Which of the following dermatological conditions is not recognised to be associated with...

    Incorrect

    • Which of the following dermatological conditions is not recognised to be associated with Crohn's disease?

      Your Answer: Pyoderma gangrenosum

      Correct Answer: Xanthomas

      Explanation:

      CUTANEOUS DISORDERS OR DERMATOSIS ASSOCIATED WITH IBD- Psoriasis- Secondary amyloidosis- Vitiligo- Acquired epidermolysis bullosaIn some cases, non-granulomatous skin disorders occur as a reaction to the intestinal disease. These include:- Pyoderma gangrenosum- Neutrophilic dermatosis / Sweet syndrome, typically with pustules- Pyodermatitis-pyostomatitis vegetans, a purulent erosive dermatosis characterised by snail-track ulcers- Erythema multiforme- Erythema nodosum- Acneiform eruptions including nodulocystic acne, hidradenitis suppurativa and folliculitis- Palisaded neutrophilic and granulomatous dermatitis- Necrotizing and granulomatous small vessel vasculitis.

    • This question is part of the following fields:

      • Gastroenterology And Hepatology
      33.7
      Seconds
  • Question 17 - During the fetal stage, the mesonephric tubules gives rise to the? ...

    Incorrect

    • During the fetal stage, the mesonephric tubules gives rise to the?

      Your Answer: Vas deferens

      Correct Answer: Wolffian duct

      Explanation:

      The development of the kidney proceeds through a series of successive phases, each marked by the development of a more advanced kidney: the pronephros, mesonephros, and metanephros. The development of the pronephric duct proceeds in a cranial-to-caudal direction. As it elongates caudally, the pronephric duct induces nearby intermediate mesoderm in the thoracolumbar area to become epithelial tubules called mesonephric tubules. Each mesonephric tubule receives a blood supply from a branch of the aorta, ending in a capillary tuft analogous to the glomerulus of the definitive nephron. The mesonephric tubule forms a capsule around the capillary tuft, allowing for filtration of blood. This filtrate flows through the mesonephric tubule and is drained into the continuation of the pronephric duct, now called the mesonephric duct or Wolffian duct. The nephrotomes of the pronephros degenerate while the mesonephric duct extends towards the most caudal end of the embryo, ultimately attaching to the cloaca.

    • This question is part of the following fields:

      • Embryology
      65.3
      Seconds
  • Question 18 - A 16-year-old girl is diagnosed with Chlamydia trachomatis infection. This infection can possibly...

    Incorrect

    • A 16-year-old girl is diagnosed with Chlamydia trachomatis infection. This infection can possibly result in which of the following complications?

      Your Answer: Isosporiasis

      Correct Answer: Fitz- Hugh- Curtis syndrome

      Explanation:

      Fitz-Hugh-Curtis syndrome (FHCS), or perihepatitis, is a chronic manifestation of pelvic inflammatory disease (PID). It is described as an inflammation of the liver capsule, without the involvement of the liver parenchyma, with adhesion formation accompanied by right upper quadrant pain. A final diagnosis can be made through laparoscopy or laparotomy via direct visualization of violin string-like adhesions or through hepatic capsular biopsy and culture. FHCS is a complication of PID. Microorganisms associated with PID are thought to spread in one of three ways:-Through spontaneous ascending infection, microbes from the cervix or vagina travel to the endometrium, through the fallopian tubes, and into the peritoneal cavity. Complications include endometritis, salpingitis, tubo-ovarian abscess, pelvic peritonitis, and perihepatitis.-Microbes can also spread via lymphatic channels such as an infection of the parametrium from an intrauterine device.-Finally, the hematogenous spread is also possible such as with tuberculosis.

    • This question is part of the following fields:

      • Adolescent Health
      37.3
      Seconds
  • Question 19 - An 16 year old boy from Middle East presented with a 1 month...

    Correct

    • An 16 year old boy from Middle East presented with a 1 month history of a yellowish, crusted plaque over his scalp, along with some scarring alopecia. What will the likely diagnosis be?

      Your Answer: Favus

      Explanation:

      Favus is a fungal infection of the scalp, resulting in the formation of a yellowish crusted plaque over the scalp and leads to scar formation with alopecia. Tinea capitus is a fungal infection of the scalp resulting in scaling and non scarring hair loss. Folliculitis presents with multiple perifollicular papules which can be caused by both bacteria and fungi. Cradle cap usually affects infants where the whole scalp is involved. It can lead to hair loss and responds to topical antifungals and keratolytics.

    • This question is part of the following fields:

      • Dermatology
      14.7
      Seconds
  • Question 20 - An 18-year-old girl presents with complaints of easy fatiguability and severe headaches. She...

    Incorrect

    • An 18-year-old girl presents with complaints of easy fatiguability and severe headaches. She also complains of irregular and sporadic periods. During the examination, you notice behavioural traits that suggest a deterioration in peripheral vision. An eye exam confirms bitemporal hemianopia. Magnetic resonance imaging of the brain reveals a large non-functional pituitary tumour. Which structure does the tumour exert pressure on to cause her visual symptoms?

      Your Answer: Edinger-Westphal nucleus

      Correct Answer: Optic chiasm

      Explanation:

      Bitemporal hemianopia is a characteristic finding seen in patients with optic chiasm lesion.The pituitary gland is situated within the pituitary fossa. Just above the pituitary fossa is the optic chiasm and so any expanding masses from the pituitary gland commonly press on it, causing bitemporal hemianopia.Other options:- Compression of the optic nerve would not cause more severe, generalised visual loss. Also, the optic nerve is not anatomically related to the pituitary gland and so is unlikely to be directly compressed in the presence of a pituitary tumour.- The optic tract is again not closely anatomically related with the pituitary gland and so is unlikely to be directly compressed in the presence of a pituitary tumour. Also, damage to the optic tract on one side would cause homonymous hemianopia.- The lateral geniculate nucleus is a centre of cells in the thalamus and is unlikely to be compressed by a pituitary tumour. Its function is to convey sensory information from the optic tract to more central parts of the visual pathway.- The Edinger-Westphal nucleus is located at the level of the superior colliculus in the midbrain and so may not be compressed by an enlarging pituitary tumour.Other visual defects:- Left homonymous hemianopia: It is the visual field defect to the left, due to the lesion of the right optic tract.- Homonymous quadrantanopias are seen in parietal (inferior homonymous quadrantopia) and temporal lobe lesions (superior homonymous quadrantopia). Mnemonic: PITS (Parietal-Inferior, Temporal-Superior)A congruous defect means complete or symmetrical visual field loss, and conversely, an incongruous defect is incomplete or asymmetric.Incongruous defects suggest an optic tract lesion, while congruous defects suggest optic radiation or occipital cortex lesion.

    • This question is part of the following fields:

      • Ophthalmology
      103
      Seconds
  • Question 21 - The ophthalmic branch exits the skull from which of the following foramina? ...

    Incorrect

    • The ophthalmic branch exits the skull from which of the following foramina?

      Your Answer: Foramen rotundum

      Correct Answer: Superior orbital fissure

      Explanation:

      The trigeminal nerve is responsible for the sensory innervation of the head, and the muscles of mastication. The nerve is divided into three branches, the ophthalmic nerve (V1) the mandibular nerve (V2) and the maxillary nerve (V3) which all exit the skull through their respective foramina. An easy way to remember these foramina is with the following mnemonic:Standing Room Only, for V1-V3 respectivelyV1- Superior orbital FissureV2- foramen RotundumV3 foramen Ovale

    • This question is part of the following fields:

      • Neurology And Neurodisability
      36.5
      Seconds
  • Question 22 - During the excision of the submandibular salivary gland, which one of the following...

    Incorrect

    • During the excision of the submandibular salivary gland, which one of the following nerves is at risk of injury as the duct is mobilised?

      Your Answer:

      Correct Answer: Lingual nerve

      Explanation:

      The lingual nerve wraps around Wharton’s duct, and thus, is at risk of injury as the submandibular gland is mobilised. The lingual nerve provides sensory supply to the anterior 2/3 of the tongue.Note:- Submandibular duct (Wharton’s duct): It opens lateral to the lingual frenulum on the anterior floor of the mouth. It is around 5 cm in length.- Lingual nerve wraps around Wharton’s duct. As the duct passes forwards, it crosses medial to the nerve, above it and then crosses back, lateral to it, to reach a position below the nerve.

    • This question is part of the following fields:

      • ENT
      0
      Seconds
  • Question 23 - A 1 year old child presents with barking cough, coryza and shortness of...

    Incorrect

    • A 1 year old child presents with barking cough, coryza and shortness of breath. What will be the most likely outcome associated with this condition?

      Your Answer:

      Correct Answer: Natural resolution

      Explanation:

      Croup is the most common aetiology for hoarseness, cough, and onset of acute stridor in febrile children. Symptoms of coryza may be absent, mild, or marked. The vast majority of children with croup recover without consequences or sequelae.

    • This question is part of the following fields:

      • Respiratory
      0
      Seconds
  • Question 24 - A 15-year-old boy with type 1 DM is recently started on an insulin...

    Incorrect

    • A 15-year-old boy with type 1 DM is recently started on an insulin pump. There has been better glycaemic control and he now subsequently enjoys a healthy, active lifestyle. During the consultation, he seems to acknowledge the risks of missing out his dose and says that he is comfortable with his new pump. he mentions that he changes his site after every 4 days. However, a random blood sugar analysis reveals it to be 22.3 mmol/L. Which of the following is the most likely reason for the raised RBS level?

      Your Answer:

      Correct Answer: Site change is overdue

      Explanation:

      Insertion sites and sensor sites should be rotated each time the infusion set or glucose sensor is changed. This keeps the tissue healthy and allows previous sites to completely heal before reusing them. Change infusion set every 2 to 3 days to help prevent infection.

    • This question is part of the following fields:

      • Endocrinology
      0
      Seconds
  • Question 25 - A 5 week old baby presents with failure to thrive, falling from the...

    Incorrect

    • A 5 week old baby presents with failure to thrive, falling from the 50th to the 9th percentile on the growth chart for weight. History reveals the baby vomits after each meal. Gestation and delivery were normal without any perinatal or postnatal complications. The baby was healthy at the new-born examination. What is the most probable diagnosis?

      Your Answer:

      Correct Answer: Pyloric stenosis

      Explanation:

      Pyloric stenosis affects infants, typically in the second to fourth weeks of life and is caused most commonly by hypertrophy and thickening of the pylorus. It usually presents with projectile vomiting and failure to thrive. The infant usually has a normal appetite. Features include: ‘projectile’ vomiting, typically 30 minutes after a feed, constipation and dehydration may also be present and a palpable mass may be present in the upper abdomen.

    • This question is part of the following fields:

      • Gastroenterology And Hepatology
      0
      Seconds
  • Question 26 - A 14-year-old girl, in diabetic ketoacidosis, is brought to the emergency room with...

    Incorrect

    • A 14-year-old girl, in diabetic ketoacidosis, is brought to the emergency room with abdominal pain and vomiting. Arterial blood gases show:pH 7.01, pC02: 2.6, HC03:6, BE-19. The ketones are found to be 4.8. Which of the following most likely explains her blood gas analysis?

      Your Answer:

      Correct Answer: Metabolic acidosis with respiratory compensation

      Explanation:

      Diabetes ketoacidosis is one of the most serious and acute complications of diabetes. At the time of presentation and during treatment of diabetic ketoacidosis (DKA), several metabolic and electrolyte derangements can ultimately result in respiratory compromise. Most commonly, hypokalaemia, hypomagnesemia and hypophosphatemia can eventually lead to respiratory muscles failure. Furthermore, tachypnoea, hyperpnea and more severely, Kussmaul breathing pattern can develop. Also, hydrostatic and non-hydrostatic pulmonary oedema can occur secondary to volume shifts into the extracellular space and secondary to increased permeability of the pulmonary capillaries. The presence of respiratory failure in patients with DKA is associated with higher morbidity and mortality. Being familiar with the causes of respiratory compromise in DKA, and how to treat them, may represent better outcomes for patients with DKA.

    • This question is part of the following fields:

      • Endocrinology
      0
      Seconds
  • Question 27 - A 1 day old baby girl is born with severe respiratory compromise. She...

    Incorrect

    • A 1 day old baby girl is born with severe respiratory compromise. She is seen to have a scaphoid abdomen and an absent apex beat. Which anomaly does this baby have?

      Your Answer:

      Correct Answer: Bochdalek hernia

      Explanation:

      Answer: Bochdalek herniaA Bochdalek hernia is one of two forms of a congenital diaphragmatic hernia, the other form being Morgagni hernia. A Bochdalek hernia is a congenital abnormality in which an opening exists in the infant’s diaphragm, allowing normally intra-abdominal organs (particularly the stomach and intestines) to protrude into the thoracic cavity. In the majority of patients, the affected lung will be deformed, and the resulting lung compression can be life-threatening. Bochdalek hernias occur more commonly on the posterior left side (85%, versus right side 15%).In normal Bochdalek hernia cases, the symptoms are often observable simultaneously with the baby’s birth. A few of the symptoms of a Bochdalek Hernia include difficulty breathing, fast respiration and increased heart rate. Also, if the baby appears to have cyanosis (blue-tinted skin) this can also be a sign. Another way to differentiate a healthy baby from a baby with Bochdalek Hernia, is to look at the chest immediately after birth. If the baby has a Bochdalek Hernia it may appear that one side of the chest cavity is larger than the other and or the abdomen seems to be scaphoid (caved in).Situs inversus (also called situs transversus or oppositus) is a congenital condition in which the major visceral organs are reversed or mirrored from their normal positions. The normal arrangement of internal organs is known as situs solitus while situs inversus is generally the mirror image of situs solitus. Although cardiac problems are more common than in the general population, most people with situs inversus have no medical symptoms or complications resulting from the condition, and until the advent of modern medicine it was usually undiagnosed. In the absence of congenital heart defects, individuals with situs inversus are homeostatically normal, and can live standard healthy lives, without any complications related to their medical condition. There is a 5–10% prevalence of congenital heart disease in individuals with situs inversus totalis, most commonly transposition of the great vessels. The incidence of congenital heart disease is 95% in situs inversus with levocardia.Cystic fibrosis is a progressive, genetic disease that causes persistent lung infections and limits the ability to breathe over time. In people with CF, mutations in the cystic fibrosis transmembrane conductance regulator (CFTR) gene cause the CFTR protein to become dysfunctional. When the protein is not working correctly, it’s unable to help move chloride — a component of salt — to the cell surface. Without the chloride to attract water to the cell surface, the mucus in various organs becomes thick and sticky. In the lungs, the mucus clogs the airways and traps germs, like bacteria, leading to infections, inflammation, respiratory failure, and other complications. Necrotizing enterocolitis (NEC) is a medical condition where a portion of the bowel dies. It typically occurs in new-borns that are either premature or otherwise unwell. Symptoms may include poor feeding, bloating, decreased activity, blood in the stool, or vomiting of bile.The exact cause is unclear. Risk factors include congenital heart disease, birth asphyxia, exchange transfusion, and premature rupture of membranes. The underlying mechanism is believed to involve a combination of poor blood flow and infection of the intestines. Diagnosis is based on symptoms and confirmed with medical imaging.Morgagni hernias are one of the congenital diaphragmatic hernias (CDH), and is characterized by herniation through the foramen of Morgagni. When compared to Bochdalek hernias, Morgagni hernias are:-anterior-more often right-sided (,90%)-small-rare (,2% of CDH)-at low risk of prolapseOnly ,30% of patients are symptomatic. New-borns may present with respiratory distress at birth similar to a Bochdalek hernia. Additionally, recurrent chest infections and gastrointestinal symptoms have been reported in those with previously undiagnosed Morgagni hernia.The image of the transverse colon is herniated into the thoracic cavity, through a mid line defect and this indicates that it is a Morgagni hernia since the foramen of a Morgagni hernia occurs in the anterior midline through the sternocostal hiatus of the diaphragm, with 90% of cases occurring on the right side.Clinical manifestations of congenital diaphragmatic hernia (CDH) include the following:Early diagnosis – Right-side heart| decreased breath sounds on the affected side| scaphoid abdomen| bowel sounds in the thorax, respiratory distress, and/or cyanosis on auscultation| CDH can often be diagnosed in utero with ultrasonography (US), magnetic resonance imaging (MRI), or bothLate diagnosis – Chest mass on chest radiography, gastric volvulus, splenic volvulus, or large-bowel obstructionCongenital hernias (neonatal onset) – Respiratory distress and/or cyanosis occurs within the first 24 hours of life| CDH may not be diagnosed for several years if the defect is small enough that it does not cause significant pulmonary dysfunctionCongenital hernias (childhood or adult onset) – Obstructive symptoms from protrusion of the colon, chest pain, tightness or fullness the in chest, sepsis following strangulation or perforation, and many respiratory symptoms occur.

    • This question is part of the following fields:

      • Paediatric Surgery
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  • Question 28 - Which of the following is the gold standard laboratory investigation for diagnosing central...

    Incorrect

    • Which of the following is the gold standard laboratory investigation for diagnosing central precocious puberty?

      Your Answer:

      Correct Answer: GnRH stimulation test

      Explanation:

      Precocious puberty is the attainment of normal pubertal biochemical and physical features at an abnormally early age. The age cut-offs commonly used to define precocious puberty are 8 years for females and 9 years for males. Precocious puberty may be central (true) or peripheral (false) based on the aetiology. Central precocious puberty is due to the premature activation of the hypothalamic-pituitary-gonadal axis, which in turn leads to the development of secondary sexual characteristics at an earlier than usual age. The best laboratory investigation to diagnose central precocious puberty is a gonadotropin-releasing hormone stimulation test, which is regarded as the gold standard. It requires the collection of multiple blood samples at different time points to measure FSH and LH levels. If the LH levels increase to >8IU/L after stimulation with GnRH, then the diagnosis of central precocious puberty is confirmed.

    • This question is part of the following fields:

      • Endocrinology
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  • Question 29 - A healthy male who has a brother with cystic fibrosis. His wife, who...

    Incorrect

    • A healthy male who has a brother with cystic fibrosis. His wife, who has no family history of cystic fibrosis, wants to know their chance of having a child affected by cystic fibrosis.What is the best estimate of the risk if the population carrier rate of cystic fibrosis is 1 in 25?

      Your Answer:

      Correct Answer: 1 in 150

      Explanation:

      CF is inherited in an autosomal recessive manner.This means that to have CF, a person must have a mutation in both copies of the CFTR gene in each cell. People with CF inherit one mutated copy of the gene from each parent, who is referred to as a carrier.CF carriers can pass their copy of the CFTR gene mutation to their children. Each time two CF carriers have a child together, the chances are: 25 percent (1 in 4) the child will have CF50 percent (1 in 2) the child will be a carrier but will not have CF25 percent (1 in 4) the child will not be a carrier of the gene and will not have CFThis male’s parents are obligate carrier because he has a sibling with CFSo the chances he is a carrier too are 2 in 3The risk of having an affected child is the chance of both himself and his partner being carriers: (2/3 × 1/25 = 2/75) × 1/4 = 1/150.

    • This question is part of the following fields:

      • Genetics And Dysmorphology
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  • Question 30 - A case-control study is developed to assess passive smoking as a risk factor...

    Incorrect

    • A case-control study is developed to assess passive smoking as a risk factor for the development of asthma in children. The total number of patients recruited for this study is 200. 40 out of the 200 patients report at least one parent smoking in the house when they were younger. 200 more people without asthma are recruited and 20 out of them report that at least one parent smoked in the house when they were younger. What is the odds ratio of patients with asthma having been exposed to passive smoking during their childhood?

      Your Answer:

      Correct Answer: 2.25

      Explanation:

      An odds ratio (OR) is a measure of association between an exposure and an outcome. The OR represents the odds that an outcome will occur given a particular exposure, compared to the odds of the outcome occurring in the absence of that exposure. Odds ratios are most commonly used in case-control studies, however they can also be used in cross-sectional and cohort study designs as well (with some modifications and/or assumptions). Wherea = Number of exposed casesb = Number of exposed non-casesc = Number of unexposed casesd = Number of unexposed non-casesOR=(a/c) / (b/d) = ad/bc

    • This question is part of the following fields:

      • Epidemiology And Statistics
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SESSION STATS - PERFORMANCE PER SPECIALTY

Adolescent Health (0/2) 0%
Respiratory (2/2) 100%
Nutrition (0/1) 0%
Neurology (1/1) 100%
Epidemiology And Statistics (1/2) 50%
ENT (0/1) 0%
Gastroenterology And Hepatology (2/2) 100%
Genetics And Dysmorphology (1/2) 50%
Paediatric Surgery (1/2) 50%
Neonatology (1/2) 50%
HIV (1/1) 100%
Endocrinology (2/3) 67%
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