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  • Question 1 - Which of the following is not seen as a complication of wound healing?...

    Correct

    • Which of the following is not seen as a complication of wound healing?

      Your Answer: Malignancy

      Explanation:

      Complications in wound healing can originate due to abnormalities in the repair process. These abnormalities are :

      1) Deficient scar formation: insufficient granulation tissue can lead to wound dehiscence and ulceration. Dehiscence or wound rupture is seen most commonly in abdominal surgery due to increased intraabdominal pressure. Ulcerations are common in extremity wounds due to inadequate vascularization.

      2) Excessive formation of repair components: collagen being laid down may begin normally however later lead to a raised scar also called a hypertrophic scar, which can extend beyond its boundaries to form a keloid and

      3) Formation of contractures.

    • This question is part of the following fields:

      • Cell Injury & Wound Healing
      • Pathology
      12.8
      Seconds
  • Question 2 - Which of the following over-the-counter drugs can cause a prolonged bleeding time? ...

    Correct

    • Which of the following over-the-counter drugs can cause a prolonged bleeding time?

      Your Answer: Acetylsalicylic acid

      Explanation:

      Acetylsalicylic acid, or aspirin, is a nonsteroidal anti-inflammatory drug that is widely used as an analgesic and antipyretic. Aspirin is as a cyclo-oxygenase inhibitor that leads to decreased prostaglandin production. Decreased platelet aggregation is another effect of this drug, achieved by long-lasting use of aspirin.

    • This question is part of the following fields:

      • Haematology
      • Pathology
      21.7
      Seconds
  • Question 3 - Hormones of the anterior pituitary include which of the following? ...

    Correct

    • Hormones of the anterior pituitary include which of the following?

      Your Answer: Prolactin

      Explanation:

      The anterior pituitary gland (adenohypophysis or pars distalis) synthesizes and secretes:

      1. FSH (follicle-stimulating hormone)

      2. LH (luteinizing hormone)

      3. Growth hormone

      4. Prolactin

      5. ACTH (adrenocorticotropic hormone)

      6. TSH (thyroid-stimulating hormone).

      The posterior pituitary gland (neurohypophysis) stores and secretes 2 hormones produced by the hypothalamus:

      1. ADH (antidiuretic hormone or vasopressin)

      2. Oxytocin

    • This question is part of the following fields:

      • Endocrine
      • Physiology
      13.5
      Seconds
  • Question 4 - What is the most likely cause of bilateral gynaecomastia in a 55-year old...

    Incorrect

    • What is the most likely cause of bilateral gynaecomastia in a 55-year old male?

      Your Answer: Increased risk of breast carcinoma

      Correct Answer: Hepatic failure

      Explanation:

      Hypertrophy of breast tissue in males is known as gynaecomastia. It is normally due to proliferation of stroma and not of mammary ducts. Physiological gynaecomastia can occur during puberty and is often transient, bilateral, symmetrical and possibly tender. Gynaecomastia can occur during old age too, but is usually unilateral. Other causes include hepatic or renal failure, endocrinological disorders, drugs (anabolic steroids, antineoplastic drugs, calcium channel blockers, cimetidine, digitalis, oestrogens, isoniazid, ketoconazole, methadone, metronidazole, reserpine, spironolactone, theophylline), and marijuana. It should not be confused with malignancy which is often hard, asymmetric and fixed to the dermis or fascia. Treatment if indicated, includes withdrawal of the causative factor or treatment of the underlying disorder.

    • This question is part of the following fields:

      • Pathology
      • Women's Health
      28.6
      Seconds
  • Question 5 - Endometrial hyperplasia is most likely to be associated with which of the following...

    Correct

    • Endometrial hyperplasia is most likely to be associated with which of the following conditions?

      Your Answer: Fibrothecoma

      Explanation:

      A benign tumour arising from the ovarian stroma, fibrothecoma are bilateral in 10% cases. The thecoma component of the tumour can produce oestrogen leading to endometrial hyperplasia. The thecoma is rich in lipid content and is responsible for the yellowish appearance of the tumour. Meig’s syndrome is the presence of fibrothecoma with a right-sided hydrothorax.

    • This question is part of the following fields:

      • Pathology
      • Women's Health
      54
      Seconds
  • Question 6 - A 34-year-old man is receiving chemotherapy for non-Hodgkin's lymphoma. Which of the following...

    Correct

    • A 34-year-old man is receiving chemotherapy for non-Hodgkin's lymphoma. Which of the following chemotherapy regimens would be used in this case?

      Your Answer: CHOP

      Explanation:

      CHOP is the acronym for a chemotherapy regimen used in the treatment of non-Hodgkin’s lymphoma, comprising cyclophosphamide, hydroxyrubicin (adriamycin), vincristine and prednisone. This regimen can also be combined with the monoclonal antibody rituximab if the lymphoma is of B cell origin; this combination is called R-CHOP.

    • This question is part of the following fields:

      • Pathology
      • Pharmacology
      11.8
      Seconds
  • Question 7 - A 27-year-old female was admitted due to severe dehydration. The patient also complained...

    Incorrect

    • A 27-year-old female was admitted due to severe dehydration. The patient also complained of chest tightness, thus an ECG was requested. The ECG strip showed an isoelectric ST segment, upright T wave, with prominent U waves. What is the most likely electrolyte abnormality responsible for these ECG tracing?

      Your Answer: Hyperkalaemia

      Correct Answer: Hypokalaemia

      Explanation:

      U waves are prominent if it is >1-2mm or 25% of the height of the T wave. Abnormally prominent U waves are characteristically seen in severe hypokalaemia.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Pathology
      122.7
      Seconds
  • Question 8 - A 30 year old female presented in the emergency with an irregular pulse....

    Correct

    • A 30 year old female presented in the emergency with an irregular pulse. Her ECG showed absent P-waves with irregular RR interval. What is the most likely diagnosis?

      Your Answer: Atrial fibrillation

      Explanation:

      Atrial fibrillation is one of the most common cardiac arrhythmias. It is often asymptomatic but may present with symptoms of palpitations, fainting, chest pain and heart failure. Characteristic findings are: absence of P-waves, unorganised electrical activity in their place, irregularity of RR interval due to irregular conduction of impulses to the ventricles and if paroxysmal AF is suspected, episodes may be documented with the use of Holter monitoring

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      70.3
      Seconds
  • Question 9 - Abnormal breathing is noticed in a of victim of a road traffic accident,...

    Correct

    • Abnormal breathing is noticed in a of victim of a road traffic accident, who sustained a head injury. The breathing pattern is characterised by alternate periods of waxing and waning tidal volumes with interspersed periods of apnoea. This breathing pattern is known as:

      Your Answer: Cheyne–Stokes breathing

      Explanation:

      Cheyne-Stokes breathing is an abnormal breathing pattern with breathing periods of gradually waxing and waning tidal volumes, with apnoeic periods interspersed. It is usually the first breathing pattern to be seen with a rise in intracranial pressure and is caused by failure of the respiratory centre in the brain to compensate quickly enough to changes in serum partial pressure of oxygen and carbon dioxide. The aetiology includes strokes, head injuries, brain tumours and congestive heart failure. It is also a sign of altitude sickness in normal people, a symptom of carbon monoxide poisoning or post-morphine administration. Biot’s respiration (cluster breathing) is characterized by cluster of quick, shallow inspirations followed by regular or irregular periods of apnoea. It is different from ataxic respiration, which has completely irregular breaths and pauses. It results due to damage to the medulla oblongata by any reason (stroke, uncal herniation, trauma) and is a poor prognostic indicator. Kussmaul breathing, also known as ‘air hunger’, is basically respiratory compensation for metabolic acidosis and is characterized by quick, deep and laboured breathing. It is most often seen in in diabetic ketoacidosis. Due to forced inspiratory rate, the patients will show a low p(CO2). Ondine’s curse is congenital central hypoventilation syndrome or primary alveolar hypoventilation, which can be fatal and leads to sleep apnoea. It involves an inborn failure to control breathing autonomically during sleep and in severe cases, can affect patients even while awake. It is known to occur in 1 in 200000 liveborn children. Treatment includes tracheostomies and life long mechanical ventilator support.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      13.1
      Seconds
  • Question 10 - A 23-year-old woman decides to donate a kidney through a kidney chain. Which...

    Correct

    • A 23-year-old woman decides to donate a kidney through a kidney chain. Which of the following indices would be expected to be decreased in the donor after full recovery from the operation?

      Your Answer: Creatinine clearance

      Explanation:

      Since medication to prevent rejection is so effective, donors do not need to be similar to their recipient. Most donated kidneys come from deceased donors; however, the utilisation of living donors is on the rise. Most problems encountered with live donation are associated with the donor. Firstly, there are the potentially harmful investigative procedures carried out in the assessment phase, the most hazardous being renal angiography, where there is cannulation of the artery and injection of a radio-opaque dye to determine the blood supply to the kidney. Secondly, there are the short-term risks of nephrectomy surgery. According to the literature, there is a mortality rate of between 1 in 1600 and 1 in 3000, but this is no more than is associated with any anaesthetic. In the initial postoperative period creatinine clearance may be decreased but this recovers fully over a few weeks to months. Long-term complications include prolonged wound pain.

    • This question is part of the following fields:

      • Physiology
      • Renal
      76.4
      Seconds
  • Question 11 - Calculate the stroke volume in an adult male with the following parameters:

    Heart...

    Incorrect

    • Calculate the stroke volume in an adult male with the following parameters:

      Heart rate 70 beats/min

      Arterial [O2] 0.24 ml O2/min

      Venous [O2] 0.16 ml O2/mi

      Whole body O2 consumption 500 ml/min

      Pulmonary diastolic pressure 15 mmHg

      Pulmonary systolic pressure 25 mmHg

      Wedge pressure 5 mmHg.

      Your Answer: 75 ml

      Correct Answer: 90 ml

      Explanation:

      Fick’s principle states that, VO2 = (CO × CAO2) – (CO × CVO2) where VO2 = oxygen consumption, CO = cardiac output, CAO2 = oxygen concentration of arterial blood and CVO2 = oxygen concentration of venous blood. Thus, CO = VO2/CAO2– CVO2, CO = 500/0.24–0.16, CO = 500/0.8, CO = 6.25 l/min. Cardiac output is also given by product of stroke volume and heart rate. Thus, stroke volume = cardiac output / heart rate = 6.25/70 × 1000 stroke volume = 90 ml approximately.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      3.6
      Seconds
  • Question 12 - A 35-year-old woman is in a comatose state following a traumatic head injury,...

    Incorrect

    • A 35-year-old woman is in a comatose state following a traumatic head injury, and is receiving intravenous (IV) antibiotics and IV fluids containing saline and 5% dextrose. A serum biochemistry analysis is performed five days later which shows a low serum potassium level. This is most likely to be due to:

      Your Answer: Repeated vomiting of gastric contents before operation

      Correct Answer: Nothing per oral regimen

      Explanation:

      In this patient the cause for hypokalaemia is insufficient consumption of potassium as she is nil-per mouth with no intravenous supplementation. Parenteral nutrition has been used for comatose patients, although enteral feeding is usually preferable, and less prone to complications.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Physiology
      26.5
      Seconds
  • Question 13 - A suspected recreational drug user was brought to the Emergency department in an...

    Correct

    • A suspected recreational drug user was brought to the Emergency department in an unconscious state, and was found to be hypoventilating. Which of the following set of arterial blood gas analysis report is most consistent with hypoventilation as the primary cause? pH, pa(CO2) (mmHg), pa(O2) (mmHg).

      Your Answer: 7.28, 55, 81

      Explanation:

      Hypoventilation (or respiratory depression) causes an increase in carbon dioxide (hypercapnia) and respiratory acidosis. It can result due to drugs such as alcohol, benzodiazepines, barbiturates, opiates, mechanical conditions or holding ones breath. Strong opioids such as heroin and fentanyl are commonly implicated and can lead to respiratory arrest. In recreational drug overdose, acute respiratory acidosis occurs with an increase in p(CO2) over 45 mm Hg and acidaemia (pH < 7.35)

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      4.4
      Seconds
  • Question 14 - A 68-year-old man underwent sigmoid resection with diverting colostomy for a ruptured sigmoid...

    Correct

    • A 68-year-old man underwent sigmoid resection with diverting colostomy for a ruptured sigmoid diverticulum 10 days ago. He received gentamicin and ampicillin post-op. 2 days after he was discharged from the hospital, he was readmitted because of high grade fever and chills. His blood culture grew Gram-negative bacilli. Which organism is most likely responsible for the patient's infection?

      Your Answer: Bacteroides fragilis

      Explanation:

      Bacteroides fragilis is an anaerobic, Gram-negative, rod-shaped bacterium. It is part of the normal flora of the human colon and is generally a commensal, but can cause infection if displaced into the bloodstream or surrounding tissue following surgery, disease, or trauma.

    • This question is part of the following fields:

      • Microbiology
      • Pathology
      59.9
      Seconds
  • Question 15 - A 34-year-old Asian male presents with cervical lymphadenopathy. The patient is suspected to...

    Correct

    • A 34-year-old Asian male presents with cervical lymphadenopathy. The patient is suspected to have tuberculous lymphadenopathy. Excision biopsy of one of the nodes showed granulomatous inflammation. Which histopathologic feature is most likely consistent with the diagnosis of tuberculosis?

      Your Answer: Caseation necrosis

      Explanation:

      The granulomas of tuberculosis tend to contain necrosis (caseating tubercles), but non-necrotizing granulomas may also be present. Multinucleated giant cells with nuclei arranged like a horseshoe (Langhans giant cells) and foreign body giant cells are often present, but are not specific for tuberculosis. A definitive diagnosis of tuberculosis requires identification of the causative organism by microbiological cultures.

    • This question is part of the following fields:

      • Microbiology
      • Pathology
      26.1
      Seconds
  • Question 16 - In the kidney, the macula densa is an area of closely packed specialized cells lining the wall of...

    Correct

    • In the kidney, the macula densa is an area of closely packed specialized cells lining the wall of the:

      Your Answer: Distal convoluted tubule

      Explanation:

      In the kidney, the macula densa is an area of closely packed specialised cells lining the region of the distal convoluted tubule (DCT) lying next to the glomerular vascular pole. The cells of the macula densa are sensitive to the ionic content and water volume of the fluid in the DCT, producing signals that promote renin secretion by other cells of the juxtaglomerular apparatus.

    • This question is part of the following fields:

      • Physiology
      • Renal
      12.1
      Seconds
  • Question 17 - Which of the following coagulation factors is responsible for the formation of a...

    Incorrect

    • Which of the following coagulation factors is responsible for the formation of a complex with tissue factor to activate factors IX and X?

      Your Answer: Fibrinogen

      Correct Answer: Factor VII

      Explanation:

      Factor VII, also known as proconvertin or stable factor, is a vitamin K–dependent protein that plays a central role in haemostasis and coagulation. Tissue factor is a protein that is normally not exposed on the surface of intact blood vessels. Damage to the vascular lumen leads to tissue factor exposure. The exposed tissue factor binds to factor VII. This facilitates the activation of factor VII to factor VIIa.

    • This question is part of the following fields:

      • Haematology
      • Pathology
      23
      Seconds
  • Question 18 - What is the normal amount of oxygen that is carried in the blood?...

    Incorrect

    • What is the normal amount of oxygen that is carried in the blood?

      Your Answer: 50 ml oxygen/100 ml blood

      Correct Answer: 20 ml oxygen/100 ml blood

      Explanation:

      Normally, 100 ml of blood contains 15g haemoglobin and a single gram of haemoglobin can bind to 1.34 ml oxygen when 100% saturated. Thus, 15 × 1.34 = 20 ml O2/100 ml blood. The haemoglobin in venous blood that is leaving the tissues is about 75% saturated with oxygen, and hence it carries about 15 ml O2/100 ml venous blood. This implies that for each 10 ml of blood, 5 ml oxygen is transported to the tissues. With a p(O2) > 100 mm Hg, only 3 ml of oxygen is dissolved in every one litre of plasma. By increasing the pA(O2) by breathing 100% oxygen, one can add an extra amount of oxygen in the plasma, but the amount of oxygen carried by haemoglobin will not increase significantly as it is already > 95% saturated.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      12.5
      Seconds
  • Question 19 - When a penile tumour invades the subepithelial connective tissue of the penis, what...

    Incorrect

    • When a penile tumour invades the subepithelial connective tissue of the penis, what is its stage?

      Your Answer: T2

      Correct Answer: T1

      Explanation:

      The TNM staging used for penile cancer is as follows:

      TX: primary tumour cannot be assessed

      T0: primary tumour is not evident

      Tis: carcinoma in situ is present

      Ta: non-invasive verrucous carcinoma is present

      T1: tumour is invading subepithelial connective tissue

      T2: tumour is invading the corpora spongiosum or cavernosum

      T3: tumour invading the urethra or prostate

      T4: tumour invading other adjacent structures.

      In this case, the patient has a T1 tumour.

    • This question is part of the following fields:

      • Pathology
      • Urology
      21.2
      Seconds
  • Question 20 - A 34-year-old woman is diagnosed with cerebral oedema after suffering a severe head...

    Correct

    • A 34-year-old woman is diagnosed with cerebral oedema after suffering a severe head trauma. Which of the following conditions is not likely to be associated with the extracellular oedema?

      Your Answer: Increased plasma colloid osmotic pressure

      Explanation:

      Cerebral oedema is extracellular fluid accumulation in the brain. Increased capillary permeability, increased capillary pressure, increased interstitial fluid colloid osmotic pressure and lymphatic blockage would increase fluid movement into the interstitial spaces. Increased plasma colloid osmotic pressure, however, would oppose fluid movement from the capillaries into the interstitial compartment.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Physiology
      31.7
      Seconds
  • Question 21 - A 44-year old gentleman presented to the hospital in congestive cardiac failure. On...

    Incorrect

    • A 44-year old gentleman presented to the hospital in congestive cardiac failure. On further investigation, he was found to have a right-sided retroperitoneal mass. On enquiry, he gave a history of intermittent hypertensive attacks. 24-hour urine specimen revealed raised metanephrine and vanillylmandelic acid levels. What is the likely diagnosis?

      Your Answer: Renal cell carcinoma

      Correct Answer: Pheochromocytoma

      Explanation:

      A neuroendocrine tumour of the chromaffin cells in adrenal medulla, pheochromocytoma secretes excessive catecholamines – adrenaline (epinephrine) and noradrenaline (norepinephrine). Pheochromocytomas are also known as the ‘10% tumour’. This is because 10% of them are bilateral, 10% are malignant, and 10% are extra-adrenal. Extra-adrenal paragangliomas (also known as extra-adrenal pheochromocytomas) are less common than pheochromocytomas and arise in the ganglia of sympathetic nervous system. Around 25% of pheochromocytomas are familial. Symptoms are described as feeling of ‘impending doom’, and include tachycardia, hypertension, palpitations, anxiety, headaches and pallor. Orthostatic hypertension is typically seen where there is a more than 100 mmHg fall in systolic pressure when the patient stands up. Pheochromocytomas can also lead to malignant hypertension. Diagnosis is by measurement of catecholamines and metanephrines in blood or in 24-hour urine, after exclusion of other possible causes such as stress, hypoglycaemia and drugs (methyldopa, dopamine agonists, ganglion-blocking antihypertensive). Imaging is also needed to localize the tumour. Localization of the tumour can also be done by Iodine-131 meta-iodobenzylguanidine (I131-MIBG) imaging.

    • This question is part of the following fields:

      • Endocrine
      • Pathology
      109.1
      Seconds
  • Question 22 - Diffusion is the movement of molecules from a region of high concentration to a...

    Correct

    • Diffusion is the movement of molecules from a region of high concentration to a region of low concentration. Which of these changes will decrease the rate of diffusion of a substance?

      Your Answer: An increase in the molecular weight of the substance

      Explanation:

      Unless given IV, a drug must cross several semipermeable cell membranes before it reaches the systemic circulation. Drugs may cross cell membranes by diffusion, amongst other mechanisms. The rate of diffusion of a substance is proportional to the difference in the concentration of the diffusing substance between the two sides of the membrane, the temperature of the solution, the permeability of the membrane and, in the case of ions, the electrical potential difference between the two sides of the membrane.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Physiology
      34.3
      Seconds
  • Question 23 - Which of the following changes in the histology of the cell is most...

    Incorrect

    • Which of the following changes in the histology of the cell is most likely to be accompanied by disruption of the cell membrane following an injury?

      Your Answer: Apoptosis

      Correct Answer: Coagulative necrosis

      Explanation:

      The process of necrosis ends with the rupture of the cell membrane and the consequent release of the cellular components into the surrounding tissue. Apoptosis, pyknosis and karyorrhexis are not reversible events but the cell membrane remains intact. Cloudy swelling and hydropic changes are also reversible but again the cell membrane remains intact and they are therefore different and distinct from necrosis.

    • This question is part of the following fields:

      • Cell Injury & Wound Healing
      • Pathology
      15.6
      Seconds
  • Question 24 - When at rest, which of the following will be higher in a marathon...

    Correct

    • When at rest, which of the following will be higher in a marathon runner compared to an untrained individual?

      Your Answer: Cardiac stroke volume

      Explanation:

      Cardiac muscle hypertrophy is seen in trained athletes as compared to the normal population. This hypertrophy results in higher stroke volume at rest and increased cardiac reserve (maximum cardiac output during exercise). However, the cardiac output at rest is almost the same in both trained and untrained people. This is because in trained athletes, the heart rate is slower, even up to 40-50 beats/min. There is minimal affect of athletic training on oxygen consumption and respiratory rate.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      36.3
      Seconds
  • Question 25 - Which of the following is most likely to cause hypovolaemic hypernatremia: ...

    Incorrect

    • Which of the following is most likely to cause hypovolaemic hypernatremia:

      Your Answer: Central diabetes insipidus

      Correct Answer: Hyperalimentation

      Explanation:

      Hypernatremia, characterised by a high serum sodium concentration, is rarely associated with volume overload (hypervolemia). A hypovolaemic hypernatremia may be seen during excessive administration of hypertonic sodium bicarbonate, hypertonic saline or hyperalimentation.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Pathology
      21.4
      Seconds
  • Question 26 - A 14-year old girl presented with a 2cm, mobile, cystic mass in the...

    Correct

    • A 14-year old girl presented with a 2cm, mobile, cystic mass in the midline of her neck. Fine needle aspiration of the mass revealed clear fluid. This is most likely a case of:

      Your Answer: Thyroglossal duct cyst

      Explanation:

      Thyroglossal cyst is the most common congenital thyroid anomaly which is clinically significant and affects women more than men. It is a vestigial remnant of developing thyroid. Although the thyroglossal cyst can develop anywhere along the thyroglossal duct, the most common site is in the midline between the isthmus of thyroid and hyoid bone, or just above the hyoid. Thyroglossal cysts are also associated with ectopic thyroid tissue. Clinically, the cyst moves upward with protrusion of the tongue. Rarely, the persistent duct can become malignant (thyroglossal duct carcinoma) where the cancerous cells arise in the ectopic thyroid tissue that are deposited along the duct. Exposure to radiation is a predisposing factor.

    • This question is part of the following fields:

      • Endocrine
      • Pathology
      14.8
      Seconds
  • Question 27 - A 50-year old gentleman who was admitted for elective surgery was found to...

    Incorrect

    • A 50-year old gentleman who was admitted for elective surgery was found to have haemoglobin 9.5 g/dl, white blood cell count of 1.4 × 109/l and a mean corpuscular volume (MCV) of 134 fl. Which of the following is the likely finding on his peripheral blood smear?

      Your Answer: Hypochromic microcytic red blood cells

      Correct Answer: Hypersegmented neutrophils

      Explanation:

      The likely diagnosis is megaloblastic anaemia, which also shows the presence of hypersegmented neutrophils.

    • This question is part of the following fields:

      • Haematology
      • Pathology
      62.6
      Seconds
  • Question 28 - A 56 year old gentleman, who is a chronic smoker presents to the...

    Incorrect

    • A 56 year old gentleman, who is a chronic smoker presents to the clinic with dyspnoea. His Chest X-ray shows intercostal space widening with increased blackening bilaterally. What is the most likely finding on his pulmonary function test?

      Your Answer: Decreased total lung capacity

      Correct Answer: Increased total lung capacity

      Explanation:

      In patients suspected of having chronic obstructive pulmonary disease, pulmonary function testing (PFT) is useful to confirm airway obstruction, to quantify its severity and reversibility, for following disease progression and monitoring response to treatment. These tests include:

      FEV1 – volume of air forcefully expired during the first second after a full breath

      Forced vital capacity (FVC) – total volume of air expired with maximal force and flow-volume loops. The hallmark of airway obstruction is reduction of FEV1, FVC and the ratio of FEV1/FVC, with a concave pattern in expiratory tracing on the flow-volume loop. FEV1 and forced vital capacity (FVC) are easily measured with office spirometry and are useful to assess the severity of disease. Other parameters include increased total lung capacity, functional residual capacity and residual volume, which can help distinguish chronic obstructive pulmonary disease (COPD) from restrictive pulmonary disease where these values are lower than normal. Along with these, other tests are decreased vital capacity; and decreased diffusing capacity for carbon monoxide (DLCO). DLCO is non-specific and can be low in other disorders that affect the pulmonary vascular bed, such as interstitial lung disease. DLCO is however useful to distinguish COPD from asthma, in which DLCO is normal or elevated.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      118.9
      Seconds
  • Question 29 - A 40-year old gentleman, known with a history of peptic ulcer disease, was...

    Correct

    • A 40-year old gentleman, known with a history of peptic ulcer disease, was brought to the clinic in a dehydrated state with persistent vomiting. His blood investigations revealed:
      • sodium = 142 mmol/l
      • potassium = 2.6 mmol/l
      • chloride = 85 mmol/l
      • pH = 7.55
      • p(CO2) = 50 mmHg
      • p(O2) = 107 mmHg
      • standard bicarbonate = 40 mmol/l
      This patient has a:

      Your Answer: Metabolic alkalosis

      Explanation:

      High pH with high standard bicarbonate indicates metabolic alkalosis. The pa(CO2) was appropriately low in compensation. This is hypokalaemic hypochloraemic metabolic acidosis due to prolonged vomiting. Treatment includes treating the cause and intravenous sodium chloride with potassium.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      8.9
      Seconds
  • Question 30 - A 45-year-old pregnant woman develops high blood pressure at 20 weeks. She complains...

    Incorrect

    • A 45-year-old pregnant woman develops high blood pressure at 20 weeks. She complains of headaches and swollen feet, and a test reveals proteinuria (350 mg/day). Which of the following is the most likely diagnosis?

      Your Answer: Polycystic kidney disease

      Correct Answer: Pre-eclampsia

      Explanation:

      Pre-eclampsia (PE) is a disorder of pregnancy characterized by the onset of high blood pressure (two separate readings taken at least 6 h apart of 140/90 or more) and often a significant amount of protein in the urine (>300 mg of protein in a 24-h urine sample). While blood pressure elevation is the most visible sign of the disease, it involves generalised damage to the maternal endothelium of the kidneys and liver, with the release of vasopressive factors only secondary to the original damage. Pre-eclampsia may develop at varying times within pregnancy and its progress differs among patients; most cases present pre-term. It has no known cure apart from ending the pregnancy (induction of labour or abortion). It may also present up to 6 weeks post partum. Risk factors for pre-eclampsia include obesity, prior hypertension, older age, and diabetes mellitus.

    • This question is part of the following fields:

      • Physiology
      • Renal
      41.4
      Seconds
  • Question 31 - Lack of findings in the bladder but presence of atypical epithelial cells in...

    Correct

    • Lack of findings in the bladder but presence of atypical epithelial cells in urinalysis is most often associated with which of the following conditions?

      Your Answer: Transitional cell carcinoma of renal pelvis

      Explanation:

      The presence of atypical cells in urinalysis without findings in the bladder suggests a lesion located higher up, most probably in ureters or renal pelvis. Transitional cell cancer of the renal pelvis is a disease in which malignant cells form in the renal pelvis and is characterised by the presence of abnormal cells in urine cytology.

    • This question is part of the following fields:

      • Pathology
      • Renal
      16.1
      Seconds
  • Question 32 - Arterial blood gas analysis of a man admitted with acute exacerbation of chronic...

    Incorrect

    • Arterial blood gas analysis of a man admitted with acute exacerbation of chronic obstructive pulmonary disease (COPD) showed the following: pH = 7.28, p(CO2) = 65.5 mmHg, p(O2)= 60 mmHg and standard bicarbonate = 30.5 mmol/l. This patient had:

      Your Answer: Metabolic alkalosis

      Correct Answer: Respiratory acidosis

      Explanation:

      Acidosis with high p(CO2) and normal standard bicarbonate indicates respiratory acidosis, commonly seen in acute worsening of COPD patients. Respiratory acidosis occurs due to alveolar hypoventilation which leads to increased arterial carbon dioxide concentration (p(CO2)). This in turn decreases the HCO3 –/p(CO2) and decreases pH. In acute respiratory acidosis, the p(CO2) is raised above the upper limit of normal (over 45 mm Hg) with a low pH. However, in chronic cases, the raised p(CO2) is accompanied with a normal or near-normal pH due to renal compensation and an increased serum bicarbonate (HCO3 – > 30 mmHg).

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      3.1
      Seconds
  • Question 33 - Calculate the total peripheral resistance for a patient with a blood pressure of...

    Incorrect

    • Calculate the total peripheral resistance for a patient with a blood pressure of 130/70 mm HG and cardiac output of 5 litres / min?

      Your Answer: 22 mmHg × min/l

      Correct Answer: 18 mmHg × min/l

      Explanation:

      Total peripheral resistance = Mean arterial pressure/Cardiac output. And the mean arterial pressure = Diastolic pressure + 1/3 (Systolic pressure – Diastolic pressure), i.e., 70 + 1/3 (130-70) = 90 mmHg. Therefore, total peripheral resistance = 90 mmHg/5 l per min = 18 mmHg × min/l.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      140.5
      Seconds
  • Question 34 - The most likely cause of a low p(O2) in arterial blood is: ...

    Incorrect

    • The most likely cause of a low p(O2) in arterial blood is:

      Your Answer:

      Correct Answer: Hypoxic hypoxia

      Explanation:

      Hypoxia is when the whole body or a region is deprived of adequate oxygen supply. Different types of hypoxia include the following:

      – Hypoxic hypoxia, which occurs due to poor oxygen supply, as a result of low partial pressure of oxygen in arterial blood. This could be due to low partial pressure of atmospheric oxygen (e.g., at high altitude), sleep apnoea, poor ventilation because of chronic obstructive pulmonary disease or respiratory arrest, or shunts. The other types of hypoxia have a normal partial pressure of oxygen.

      – Anaemic hypoxia occurs due to low total oxygen content of the blood, with a normal arterial oxygen pressure.

      – Hyperaemic hypoxia occurs due to poor delivery of oxygen to target tissues, such as in carbon monoxide poisoning or methemoglobinemia.

      – Histotoxic hypoxia results due to inability of the cells to use the delivered oxygen due to disabled oxidative phosphorylation enzymes.

      – Ischaemic (or stagnant) hypoxia occurs due to local flow restriction of well-oxygenated blood, seen in cases like cerebral ischaemia, ischaemic heart disease and intrauterine hypoxia.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      0
      Seconds
  • Question 35 - Low molecular weight heparin (LMWH) has less side effects than heparin and is...

    Incorrect

    • Low molecular weight heparin (LMWH) has less side effects than heparin and is used in the prophylaxis and treatment of venous and arterial thrombotic disorders. Which of the following is LMWHs mechanism of action?

      Your Answer:

      Correct Answer: Inhibition of factor Xa

      Explanation:

      Low molecular weight heparin (LMWH) is a anticoagulant that differs from normal heparin in that it has only short chains of polysaccharide. LMWH inhibits thrombin formation by converting antithrombin from a slow to a rapid inactivator of coagulation factor Xa.

    • This question is part of the following fields:

      • Haematology
      • Pathology
      0
      Seconds
  • Question 36 - If a patient takes long-term corticosteroid therapy, which of the following diseases is...

    Incorrect

    • If a patient takes long-term corticosteroid therapy, which of the following diseases is most likely to develop?

      Your Answer:

      Correct Answer: Osteoporosis

      Explanation:

      One of the complications of long-term intake of corticosteroids is osteoporosis. Some guidelines recommend prophylactic calcium and vitamin D supplementation in patients who take more than 30 mg hydrocortisone or 7.5 mg of prednisolone daily.

    • This question is part of the following fields:

      • Orthopaedics
      • Pathology
      0
      Seconds
  • Question 37 - A 40-year old gentleman underwent a computed tomographic scan for the abdomen to...

    Incorrect

    • A 40-year old gentleman underwent a computed tomographic scan for the abdomen to rule out blunt abdominal trauma, after a vehicular accident. The scan revealed no abnormal finding except for a 1 cm-sized cortical mass in the left adrenal gland. The doctor-on-call decided to not intervene for this mass because it was likely to be a:

      Your Answer:

      Correct Answer: Non-functioning adrenal adenoma

      Explanation:

      Adrenal adenomas are common, benign lesions which are asymptomatic and seen in 10% of population. Usually detected incidentally on Computed tomography (‘incidentaloma’), only around 1 in 10,000 are malignant (adenocarcinoma). Adrenal adenomas rarely need to be investigated, especially if they are homogenous and less than 3 cm in diameter. Follow-up imaging can be done after an interval of 3-6 months to assess any change in size. Some adenomas can secrete cortisol (leading to Cushing syndrome), or aldosterone (leads to Conn syndrome) or androgens (leading to hyperandrogenism).

      Haematomas and simple cysts are not usually seen in adrenal gland. Infection due to Histoplasma capsulatum is usually bilateral and leads to multiple granulomas. Adrenal metastasis will usually demonstrate a lung primary and the adrenal lesions will be often multiple and larger than 1 cm.

    • This question is part of the following fields:

      • Endocrine
      • Pathology
      0
      Seconds
  • Question 38 - Which of the following is responsible for the maximum increase in total peripheral...

    Incorrect

    • Which of the following is responsible for the maximum increase in total peripheral resistance on sympathetic stimulation?

      Your Answer:

      Correct Answer: Arterioles

      Explanation:

      Arterioles are also known as the resistance vessels as they are responsible for approximately half the resistance of the entire systemic circulation. They are richly innervated by the autonomic nervous system and hence, will bring about the maximum increase in peripheral resistance on sympathetic stimulation.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      0
      Seconds
  • Question 39 - Which portion of the renal tubule absorbs amino acids and glucose? ...

    Incorrect

    • Which portion of the renal tubule absorbs amino acids and glucose?

      Your Answer:

      Correct Answer: Proximal convoluted tubule

      Explanation:

      In relation to the morphology of the kidney as a whole, the convoluted segments of the proximal tubules are confined entirely to the renal cortex. Glucose, amino acids, inorganic phosphate and some other solutes are reabsorbed via secondary active transport in the proximal renal tubule through co-transport channels driven by the sodium gradient.

    • This question is part of the following fields:

      • Physiology
      • Renal
      0
      Seconds
  • Question 40 - In a cardiac cycle, what event does the opening of the atrioventricular (AV)...

    Incorrect

    • In a cardiac cycle, what event does the opening of the atrioventricular (AV) valves coincide with?

      Your Answer:

      Correct Answer: Beginning of diastole

      Explanation:

      Cardiac diastole refers to the time period when the heart is relaxed after contraction and is preparing to refill with blood. Both ventricular and atrial diastole are together known as complete cardiac diastole. At its beginning, the ventricles relax, causing a drop in the ventricular pressure. As soon as the left ventricular pressure drops below that in left atrium, the mitral valve opens and there is ventricular filling of blood. Similarly, the tricuspid valve opens filling the right atrium.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      0
      Seconds
  • Question 41 - A 29-year-old woman presents to the doctor complaining of cough, shortness of breath,...

    Incorrect

    • A 29-year-old woman presents to the doctor complaining of cough, shortness of breath, fever and weight loss. Chest X-ray revealed bilateral hilar and mediastinal lymph node enlargement and bilateral pulmonary opacities. Non-caseating granulomas were found on histological examination. The most likely diagnosis is:

      Your Answer:

      Correct Answer: Sarcoidosis

      Explanation:

      Sarcoidosis is an inflammatory disease of unknown aetiology that affects multiple organs but predominantly the lungs and intrathoracic lymph nodes. Systemic and pulmonary symptoms may both be present. Pulmonary involvement is confirmed by a chest X-ray and other imaging studies. The main histological finding is the presence of non-caseating granulomas.

    • This question is part of the following fields:

      • Pathology
      • Respiratory
      0
      Seconds
  • Question 42 - A chest X-ray in a healthy, non-smoker, asymptomatic 48-year-old woman reveals a 2cm...

    Incorrect

    • A chest X-ray in a healthy, non-smoker, asymptomatic 48-year-old woman reveals a 2cm left lower lobe well-defined round opacity. Which of the following conditions is most probably responsible for this finding?

      Your Answer:

      Correct Answer: Pulmonary hamartoma

      Explanation:

      An asymptomatic healthy patient with no history of smoking and a lesion of small size most probably has a benign lung lesion. Hamartomas are one of the most common benign tumours of the lung that accounts for approximately 6% of all solitary pulmonary nodules. Pulmonary hamartomas are usually asymptomatic and therefore are found incidentally when performing an imaging test for other reasons.

    • This question is part of the following fields:

      • Pathology
      • Respiratory
      0
      Seconds
  • Question 43 - A 70-year-old female who underwent coronary artery bypass graft developed post-operative acute renal...

    Incorrect

    • A 70-year-old female who underwent coronary artery bypass graft developed post-operative acute renal failure. Her urinary catheter was left in place to monitor urine output. 6 days later she developed fever and chills. She also complained of suprapubic and left flank pain. She is found to have developed acute ascending pyelonephritis. Which of the following organism was most likely isolated during urine culture?

      Your Answer:

      Correct Answer: Escherichia coli with pili

      Explanation:

      The most common cause of urinary tract infection is Escherichia coli. Pilated strains of E. coli ascend the urethra to infect the kidney and the bladder. Catheters have been associated with an increased risk of UTIs.

    • This question is part of the following fields:

      • Microbiology
      • Pathology
      0
      Seconds
  • Question 44 - Increased resistance to flow of blood in cerebral vessels is most likely seen...

    Incorrect

    • Increased resistance to flow of blood in cerebral vessels is most likely seen in:

      Your Answer:

      Correct Answer: Elevation in systemic arterial pressure from 100 to 130 mmHg

      Explanation:

      Constant cerebral blood flow is maintained by autoregulation in the brain, which causes an increase in local vascular resistance to offset an increase in blood pressure. There will be an increase in cerebral blood flow (and decrease in resistance to cerebral blood flow) with a decrease in arterial oxygen or an increase in arterial CO2. Similarly, a decrease in viscosity will also increase the blood flow. Due to increased brain metabolism and activity during a seizure, there will also be an increase in the cerebral blood flow.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      0
      Seconds
  • Question 45 - Hyperplastic arteriosclerosis with fibrinoid necrosis, petechial haemorrhages, microinfarcts in the kidneys and elevated...

    Incorrect

    • Hyperplastic arteriosclerosis with fibrinoid necrosis, petechial haemorrhages, microinfarcts in the kidneys and elevated plasma renin are common findings in which of the following patients?

      Your Answer:

      Correct Answer: A 45-year-old woman with scleroderma

      Explanation:

      Scleroderma, also known as systemic sclerosis, is a chronic disease of the connective tissue. Involvement of the kidneys occurs in patients with diffuse scleroderma, causing rapid onset of high blood pressure with hyperreninemia, thrombotic microangiopathy, and progressive renal failure.

    • This question is part of the following fields:

      • Pathology
      • Renal
      0
      Seconds
  • Question 46 - A 17-year-old female was given an antibiotic for a urinary tract infection. After...

    Incorrect

    • A 17-year-old female was given an antibiotic for a urinary tract infection. After taking the medication the patient developed Steven-Johnson syndrome. Which particular antibiotic usually causes Steven-Johnson syndrome?

      Your Answer:

      Correct Answer: Sulphonamides

      Explanation:

      Stevens–Johnson syndrome (SJS) is a type of severe skin reaction. The most common cause is certain medications such as lamotrigine, carbamazepine, allopurinol, sulphonamide antibiotics, and nevirapine.

    • This question is part of the following fields:

      • Microbiology
      • Pathology
      0
      Seconds
  • Question 47 - A 65 year old man with a history of diabetes and hypertension presented...

    Incorrect

    • A 65 year old man with a history of diabetes and hypertension presented with a stroke a few months ago severely affecting his speech and movement in the right arm and leg. A cerebral angiogram revealed a middle cerebral artery occlusion. A recent CT scan was done which revealed a 5 cm cystic space in his left parietal lobe. This lesion is a result of which of the following forms of resolution?

      Your Answer:

      Correct Answer: Liquefactive necrosis

      Explanation:

      Characteristically, the brain will undergo liquefactive necrosis following ischaemic injury. This leaves a cystic space in that region which would show up on a CT scan. Atrophy would result in a generalized decrease in the brain size. Coagulative necrosis typically occurs in parenchymal organs e.g. the spleen or kidney which have a lower lipid content. Caseous necrosis is typical in granulomatous tuberculosis infection. Apoptosis will not form a cystic area as it is programmed cell death involving a individual cells. Gangrenous necrosis is characteristic of ischaemic injury of the lower limb and GI tract. Fibrinous necrosis results from necrotic damage to the blood vessels with the leaking of proteins into the vessel, appearing bright pink on H & E staining.

    • This question is part of the following fields:

      • Cell Injury & Wound Healing; Neurology
      • Pathology
      0
      Seconds
  • Question 48 - In multiple myeloma, which of these cell types confirms the diagnosis when found...

    Incorrect

    • In multiple myeloma, which of these cell types confirms the diagnosis when found in a smear of bone marrow aspirate?

      Your Answer:

      Correct Answer: Plasma cells

      Explanation:

      A bone marrow aspiration is the diagnostic test for multiple myeloma, which is a malignant bone tumour that usually affects older adults. The smear reveals clusters of plasma cells, while X-rays tend to show circumscribed lytic lesions or diffuse demineralisation.

    • This question is part of the following fields:

      • Orthopaedics
      • Pathology
      0
      Seconds
  • Question 49 - A 36-year old gentleman with a history of cough for 4 weeks came...

    Incorrect

    • A 36-year old gentleman with a history of cough for 4 weeks came to the hospital. Examination revealed multiple lymphadenopathy with splenomegaly. Investigations revealed haemoglobin 11 g/dl, haematocrit 32.4%, mean corpuscular volume (MCV) 93 fl, white blood cell count 63 × 109/l, and platelet count 39 × 109/l; along with characteristic Auer rods on peripheral blood smear. What is the likely diagnosis?

      Your Answer:

      Correct Answer: Acute myelogenous leukaemia (AML)

      Explanation:

      AML, or acute myeloid leukaemia is the commonest acute leukaemia affecting adults. increasing in incidence with age. It is a malignancy of the myeloid line of white blood cells. It results in rapid proliferation of abnormal cells, which accumulate in the marrow. Interference with normal cell production leads to a drop in red blood cells, white blood cells and platelets. This causes symptoms such as tiredness, shortness of breath, tendency to bleed or bruise easily and recurrent infections. AML is known to progress quickly and can lead to death in weeks and months if not treated. Leukemic blasts of AML show presence of Auer rods. These are clumps of azurophilic granular material that form needles in the cytoplasm. Composed of fused lysosomes, these contain peroxidase, lysosomal enzymes and crystalline inclusions. Auer rods are classically present in myeloid blasts of M1, M2, M3 and M4 acute leukaemia. They also help to distinguish the preleukemia myelodysplastic syndromes.

    • This question is part of the following fields:

      • Haematology
      • Pathology
      0
      Seconds
  • Question 50 - A 47-year-old male smoker, who had been self-medicating with oral steroids for the...

    Incorrect

    • A 47-year-old male smoker, who had been self-medicating with oral steroids for the last two years due to persistent breathlessness presented to the doctor complaining of a productive cough, fever and chest pain. A chest X-ray revealed bilateral patchy opacities. He was diagnosed with bilateral bronchopneumonia. Which of these organisms is most probably causing these findings?

      Your Answer:

      Correct Answer: Nocardia asteroides

      Explanation:

      Nocardia is a Gram-positive aerobic actinomycete. Several species have been identified but the most common human pathogen is Nocardia asteroides. The predominant clinical finding in the majority of patients affected by nocardiosis is pulmonary disease. Predisposing factors for pulmonary nocardiosis include leukaemia, human immunodeficiency virus (HIV) infection, organ transplantation, diabetes and receiving prolonged corticosteroids.

    • This question is part of the following fields:

      • Pathology
      • Respiratory
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Cell Injury & Wound Healing (1/2) 50%
Pathology (7/16) 44%
Haematology (1/3) 33%
Endocrine (2/3) 67%
Physiology (11/17) 65%
Women's Health (1/2) 50%
Pharmacology (1/1) 100%
Fluids & Electrolytes (2/5) 40%
Cardiovascular (3/4) 75%
Respiratory (3/7) 43%
Renal (2/3) 67%
Microbiology (2/2) 100%
Urology (0/1) 0%
Passmed