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  • Question 1 - A 68-year-old man is to be operated.
     
    His past history is significant for a...

    Correct

    • A 68-year-old man is to be operated.
       
      His past history is significant for a stroke, and some residual neurological deficit. The cranial nerves are examined clinically. He is unable to rotate his head to the left side when resistance is applied. Moreover, there is tongue wasting on the right side. There are no unusual sensory signs and symptoms.

      The most likely reason for these clinical findings is?

      Your Answer: Damage to hypoglossal (XII) and spinal accessory (XI) nerves

      Explanation:

      The upper five cervical segments of the spinal cord give rise to the XI cranial nerve. They connect with a few smaller branches before exiting the skull through the jugular foramen. The sternomastoid and trapezius muscles get their motor supply from the accessory root. Except for the palatoglossus, the hypoglossal nerve supplies motor supply to all tongue muscles.

      The inability to shrug the shoulder on the affected side and rotate the head to the side against resistance is caused by damage to the spinal accessory nerve. This is due to the trapezius and sternomastoid muscles’ weakness.

      The hypoglossal nerve is damaged, resulting in tongue wasting and inability to move from side to side.

      The stylopharyngeus receives motor supply from the glossopharyngeal nerve. It also carries taste sensory fibres from the back third of the tongue, as well as the carotid sinus, carotid body, pharynx, and middle ear.

      Motor supply to the larynx, pharynx, and palate; parasympathetic innervation to the heart, lung, and gut; and sensory fibres from the epiglottis and valleculae are all provided by the vagus nerve.

    • This question is part of the following fields:

      • Pathophysiology
      267.5
      Seconds
  • Question 2 - A 27-year old man loses 1000ml blood after being stabbed on his thigh....

    Incorrect

    • A 27-year old man loses 1000ml blood after being stabbed on his thigh.

      The most impactful physiological response occurring at the start to combat the decline in the intravascular blood volume of this man is?

      Your Answer: Transcapillary absorption of interstitial fluid

      Correct Answer: Venoconstriction

      Explanation:

      In contrast to the arterial system, which contains 15% of the circulating blood volume, the body’s veins contain 70% of it.

      In severe haemorrhage, when sympathetic stimulation causes venoconstriction, venous tone is important in maintaining the return of blood to the heart.

      Because the liver receives about 30% of the resting cardiac output, it is a very vascular organ. The hepatic vascular system is dynamic, which means it can store and release blood in large amounts – it acts as a reservoir within the general circulation.

      In a normal situation, the liver contains 10-15% of total blood volume, with the sinusoids accounting for roughly 60% of that. The liver dynamically adjusts its blood volume when blood is lost and can eject enough blood to compensate for a moderate amount of haemorrhage.

      In the portal venous and hepatic arterial systems, sympathetic nerves constrict the presinusoidal resistance vessels. More importantly, sympathetic stimulation lowers the portal system’s capacitance, allowing blood to flow more efficiently to the heart.

      Net transcapillary absorption of interstitial fluid from skeletal muscle into the intravascular space compensates for blood loss effectively during haemorrhage. The decrease in capillary hydrostatic pressure (Pc), caused by reflex adrenergic readjustment of the ratio of pre- to postcapillary resistance, is primarily responsible for fluid absorption. Within a few hours of blood loss, these fluid shifts become significant, further diluting haemoglobin and plasma proteins.

      Albumin synthesis begins to increase after 48 hours.

      The juxtamedullary complex releases renin in response to a drop in mean arterial pressure, which causes an increase in aldosterone level and, eventually, sodium and water resorption. Increased antidiuretic hormone (ADH) levels also contribute to water retention.

    • This question is part of the following fields:

      • Physiology
      175.3
      Seconds
  • Question 3 - A 48-year-old woman has presented to the emergency with abdominal pain and distension...

    Correct

    • A 48-year-old woman has presented to the emergency with abdominal pain and distension complaints. She is a known case of diabetes mellitus type 2 and has a BMI of 28 kg/m². On investigations, the liver function tests (LFTs) show raised alanine transaminase (ALT).

      Liver ultrasound is performed next to visualize the blood flow into and out of the liver.

      Which blood vessel supplies approximately one-third of the blood supply to the liver?

      Your Answer: Hepatic artery proper

      Explanation:

      The liver receives blood supply from two sources.
      1. Hepatic artery proper
      It arises from the celiac trunk via the common hepatic artery and brings oxygenated blood to the liver.
      It contributes to approximately 30% of the blood supply of the liver.
      2. Hepatic portal vein – supplies the liver with partially deoxygenated blood, carrying nutrients absorbed from the small intestine. It gets tributaries from the inferior mesenteric vein, splenic vein, and superior mesenteric vein

      The inferior mesenteric artery supplies the hindgut.
      The superior mesenteric artery supplies the pancreas and intestine up to the proximal two-thirds of the transverse colon.
      The inferior phrenic artery supplies the inferior surface of the diaphragm and oesophagus.

    • This question is part of the following fields:

      • Anatomy
      984
      Seconds
  • Question 4 - Given the following hormones, which of these will stimulate glycogenesis and gluconeogenesis? ...

    Correct

    • Given the following hormones, which of these will stimulate glycogenesis and gluconeogenesis?

      Your Answer: Corticosteroids

      Explanation:

      Insulin is the primary anabolic hormone that dominates regulation of metabolism during digestive phase. It promotes glucose uptake in skeletal myocytes and adipocytes, and other insulin-target cells. It promotes glycogenesis and inhibits gluconeogenesis.

      Glucagon is the primary counterregulatory hormone that increases blood glucose levels, primarily through its effects on liver glucose output.

      Similar to glucagon, growth hormone, catecholamines and corticosteroids are also counterregulatory factors released in response to decreased glucose concentrations. Growth hormone promotes glycogenolysis and inhibits gluconeogenesis; catecholamines stimulate glycogenolysis and gluconeogenesis; while corticosteroids stimulate glycogenesis and gluconeogenesis.

    • This question is part of the following fields:

      • Pathophysiology
      89.9
      Seconds
  • Question 5 - Which of the following statements is true regarding enantiomers? ...

    Incorrect

    • Which of the following statements is true regarding enantiomers?

      Your Answer: Sevoflurane is a chiral compound

      Correct Answer: Desflurane is a chiral compound

      Explanation:

      A compound that contains an asymmetric centre (chiral atom or chiral centre) and thus can occur in two non-superimposable mirror-image forms (enantiomers) are called chiral compounds.

      Desflurane, Halothane, and isoflurane are chiral compounds but Sevoflurane is not a chiral compound.

    • This question is part of the following fields:

      • Pharmacology
      2001.4
      Seconds
  • Question 6 - Regarding management of chronic pain, which of the following describes the mode of...

    Incorrect

    • Regarding management of chronic pain, which of the following describes the mode of action of gabapentin?

      Your Answer:

      Correct Answer: Modulation of voltage dependent calcium channels and NMDA receptor transmission

      Explanation:

      Gabapentin is an amino acid-like molecules that was originally synthesized as an analogue of GABA but is now known not to act through GABA mechanisms. It is used in the treatment of focal seizures and various nonepilepsy indications, such as neuropathic pain, restless legs syndrome, and anxiety disorders.

      Despite its close structural resemblance to GABA, gabapentin does not act through effects on GABA receptors or any other mechanism related to GABA-mediated neurotransmission. Rather gabapentin binds avidly to ?2?, a protein that serves as an auxiliary subunit of voltage-gated calcium channels. Moreover, it binds to NMDA receptor to modulate its transmission.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 7 - Which of the following antiplatelet drugs would be best for rapid offset action?...

    Incorrect

    • Which of the following antiplatelet drugs would be best for rapid offset action?

      Your Answer:

      Correct Answer: Epoprostenol

      Explanation:

      Epoprostenol has a half-life of only 42 seconds and has rapid offset. It is used for the treatment of pulmonary hypertension.

      Aspirin inhibits the COX enzyme irreversibly. It inhibits thromboxane synthesis but does not inhibit the enzyme thromboxane synthetase.

      Ticlopidine, clopidogrel and prasugrel act as irreversible antagonists of P2 Y12 receptor of Adenosine Diphosphate (ADP). These drugs interfere with the activation of platelets by ADP and fibrinogen. Both aspirin and clopidogrel act irreversibly so they are not correct.

      Paclitaxel is a long-acting antiproliferative agent used for the prevention of restenosis (recurrent narrowing) of coronary and peripheral stents and is not the correct answer.

      Tirofiban has the next shortest duration of action after epoprostenol. If epoprostenol is not given in the question, it would be the best answer.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 8 - With a 10-day history of severe vomiting, a 71-year-old man with a gastric...

    Incorrect

    • With a 10-day history of severe vomiting, a 71-year-old man with a gastric outlet obstruction is admitted to the surgical ward.

      The serum biochemical results listed below are available:

      Sodium 128 mmol/L (137-144)
      Potassium 2.6 mmol/L (3.5-4.9)
      Chloride 50 mmol/L (95-107)
      Urea 12 mmol/L (2.5-7.5)
      Creatinine 180 µmol/L (60-110)

      Which of the following do you think you are most likely to encounter?

      Your Answer:

      Correct Answer: The standard base excess will be higher than actual base excess

      Explanation:

      Hydrochloric acid is lost when you vomit for a long time (HCl). As a result, the following can be expected, in varying degrees of severity:

      Hypokalaemia
      Hypochloraemia
      Increased bicarbonate to compensate for chloride loss and metabolic alkalosis

      The alkalosis causes potassium to move from the intracellular to the extracellular compartment at first. Long-term vomiting and dehydration cause potassium to be excreted by the kidneys in order to conserve sodium. Dehydration can cause urea and creatinine levels to rise.

      The actual base excess is always greater than the standard base excess.

      The actual base excess (BE) is a measurement of a base’s contribution to a blood gas picture’s metabolic component. It’s the amount of base that needs to be added to a blood sample to bring the pH back to 7.4 after the respiratory component of a blood gas picture has been corrected (PaCO2 of 40 mmHg or 5.3 kPa). The BE has a normal range of +2 to 2. A large positive BE indicates a severe metabolic alkalosis, while a large negative BE indicates a severe metabolic acidosis. As a result, the actual BE in vitro is unaffected by CO2.

      In vivo, however, standard BE is not independent of pCO2 because blood with haemoglobin acts as a better buffer than total ECF.

      As a result, it is impossible to tell the difference between compensating for a respiratory disorder and compensating for the presence of a primary metabolic disorder.

      The differences between in vitro and in vivo behaviour can be mostly eliminated if the BE is calculated for a haemoglobin concentration of 50 g/L (the ‘effective’ or virtual value of Hb if it was distributed throughout the extracellular space) rather than the actual haemoglobin. Because haemoglobin has a lower buffering capacity, the standard BE is higher than the actual BE. It reflects the BE better in the extracellular space rather than just the intravascular compartment.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 9 - Among the following options which one compares variance within the group and variance...

    Incorrect

    • Among the following options which one compares variance within the group and variance between groups?

      Your Answer:

      Correct Answer: ANOVA

      Explanation:

      ANOVA is based upon within group variance (i.e. the variance of the mean of a sample) and between group variance (i.e. the variance between means of different samples). The test works by finding out the ratio of the two variances mentioned above. (Commonly known as F statistic).

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 10 - A 27-year-old woman presents to emergency department. She is experiencing generalised seizures.

    She is...

    Incorrect

    • A 27-year-old woman presents to emergency department. She is experiencing generalised seizures.

      She is given emergency management of her symptoms before being referred to the neurologist who diagnoses her with new onset of tonic-clonic epilepsy.

      What is the most appropriate first line of treatment?

      Your Answer:

      Correct Answer: Lamotrigine should be offered as first line of treatment

      Explanation:

      Tonic-clonic (Grand mal) epilepsy is characterised by a general loss of consciousness with violent involuntary muscle contractions.

      The NICE guidelines for treatment indicates the use of sodium valproate and lamotrigine, but sodium valproate unsuitable in this case and she is a woman of reproductive age and it is known to have teratogenic effects. Lamotrigine is a more suitable choice, prescribed as 800mg daily.

      NICE guidelines also advice an additional prescription of 5mg of folic acid daily for women on anticonvulsant therapy looking to get pregnant. It also warns of the need for extra contraceptive precaution as there is a possibly that the anticonvulsant agent can reduce levels of contraceptive agents.

      Stimulation of the vagal nerve stimulation is only necessary in patients who are refractory to medical treatment and not candidates for surgical resection.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 11 - A 41-year-old man, with symptomatic tracheal compression is scheduled for a thyroidectomy. He...

    Incorrect

    • A 41-year-old man, with symptomatic tracheal compression is scheduled for a thyroidectomy. He has previous personal history of hyperthyroidism, controlled by a carbimazole prescription.
      He has previously presented to the emergency department with dyspnoea and stridor, for which the surgery is indicated. Prior to his thyroidectomy, excessive bleeding is controlled for by ligation of the superior thyroid artery.
      The superior thyroid artery branches into the superior laryngeal artery which is closely related to a structure which upon injury will cause loss of sensation in the laryngeal mucosa.

      What is the name of this structure?

      Your Answer:

      Correct Answer: Internal laryngeal nerve

      Explanation:

      The internal laryngeal nerve provides sensory innervation to the laryngeal mucosa, and injury to it will cause loss of sensation.

      The internal laryngeal nerve lies inferior to the piriform recess mucous membrane, placing it at high risk of irritation or damage by objects which become lodged in the recess.

      The internal laryngeal artery branches off the superior laryngeal artery accompanied by the superior laryngeal nerve, inferior to the thyroid artery which branches off the superior thyroid artery close to its bifurcation from the external carotid artery.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 12 - A graph is created to show the exponential relationship between bacterial growth (y-axis)...

    Incorrect

    • A graph is created to show the exponential relationship between bacterial growth (y-axis) and time (x-axis).

      Which of the following statements is most true about this kind of exponential relationship?

      Your Answer:

      Correct Answer: y = ex

      Explanation:

      The relationship between bacterial growth and time is a tear-away exponential. The mathematical relationship between y and x in this case is:

      y = ex

      Where: the power is x, and the base is e.

      Euler’s number (e) is a mathematical constant that is the base for all logarithms occurring naturally. Its value is 2.718.

      The statement X increasing with an increase in Y is proportional to Y refers to the change in y in terms of x when considering any exponential relationship.

      This is not a build-up exponential, and that is mathematically stated as y = 1-e-kt.

      The negative x axis being a horizontal asymptote and the y intercept being 0, 1 are examples of tearaway exponentials , but do not describe an exponential process.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 13 - Which of the following antibiotics inhibits protein synthesis in bacteria? ...

    Incorrect

    • Which of the following antibiotics inhibits protein synthesis in bacteria?

      Your Answer:

      Correct Answer: Erythromycin

      Explanation:

      Erythromycin binds to the 50s subunit of bacterial rRNA complex and inhibits protein synthesis.

      Vancomycin binds to the acyl-D-ala-D-ala portion of the growing cell wall in a susceptible gram-positive bacterium. After binding, it prevents the cell wall from forming the cross-linking.

      Trimethoprim binds to dihydrofolate reductase and inhibits the reduction of dihydrofolic acid to tetrahydrofolic acid. Tetrahydrofolic acid is an essential precursor in the thymidine synthesis pathway and interference with this pathway inhibits bacterial DNA synthesis.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 14 - The following foetal anatomical features functionally closes earliest at birth? ...

    Incorrect

    • The following foetal anatomical features functionally closes earliest at birth?

      Your Answer:

      Correct Answer: Foramen ovale

      Explanation:

      Foramen ovale, ductus arteriosus (DA) and ductus venosus (DV) are the three important cardiac shunts in-utero.

      At birth the umbilical vessels constrict in response to stretch as they are clamped. Blood flow through the ductus venosus (DV) decreases but the DV closes passively in 3-10 days.

      As the pulmonary circulation is established, there is a drastic fall in pulmonary vascular resistance and an increased pulmonary blood flow. This increases flow and pressure in the Left Atrium that exceeds that of the right atrium. The difference in pressure usually leads to the IMMEDIATE closure of the foramen ovale.

      The DA is functionally closed within the first 36-hours of birth in a healthy full-term newborn. Subsequent endothelial and fibroblast proliferation leads to permanent anatomical closure within 2 – 3 weeks.

      Oxygenated blood from the placenta passes via the umbilical vein to the liver. Blood also bypasses the liver via the ductus venosus into the inferior vena cava (IVC). The Crista dividens is a tissue flap situated at the junction of the IVC and the right atrium (RA). This flap directs the oxygen-rich blood, along the posterior aspect of the IVC, through the foramen ovale into the left atrium (LA).

      The Eustachian valve also known as the valve of The IVC is a remnant of the crista dividens.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 15 - An adult and a 7-year-old child are anatomically and physiologically very different.

    Which of...

    Incorrect

    • An adult and a 7-year-old child are anatomically and physiologically very different.

      Which of the following physiological characteristics of a 5-year-old most closely resembles those of a healthy adult?

      Your Answer:

      Correct Answer: Dead space ratio

      Explanation:

      Whatever the age, the dead space ratio is 0.3. It’s the dead space (Vd) to tidal volume ratio (Vt).

      The glottis is the narrowest point of the upper airway in an adult, while the cricoid ring is the narrowest point in a child.

      A child’s airway resistance is much higher than an adult’s. The resistance to airflow increases as the diameter of a paediatric airway shrinks. The radius (r) to the power of 4 is inversely proportional to airway resistance (r4). As a result, paediatric patients are more susceptible to changes in airflow caused by a small reduction in airway diameter, such as caused by oedema.

      The compliance of a newborn’s lungs is very low (5 mL/cmH2O), but it gradually improves as lung size and elasticity grow. Lung compliance in an adult is 200 mL/cmH2O.

      In children, minute ventilation (mL/kg/minute) is much higher.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 16 - The outer muscular layer of the oesophagus is covered by? ...

    Incorrect

    • The outer muscular layer of the oesophagus is covered by?

      Your Answer:

      Correct Answer: Loose connective tissue

      Explanation:

      The oesophagus has four layers namely; 1. the mucosal layer, 2. the submucosal layer, 3. the muscular layer and 4. the layer of loose connective tissue which binds to the outer mucosal layer. The oesophagus lacks the serosal layer and therefore holds sutures poorly.

      The mucosal layer consists of muscularis mucosa and the lamina propria and is made up of non keratinised stratified squamous epithelium. The mucosal layer is the innermost layer of the oesophagus.

      The submucosal layer being the strongest layer of all has mucous glands which are called as the tuboalveolar mucous glands.

      The outer muscular layer has two types of muscle layers of which one is the circular layer and the other the longitudinal layer. The Auerbach’s and Meissner’s nerve plexuses lie in between the longitudinal and circular muscle layers and submucosally. The muscle fibres present in the upper 1/3rd part of the oesophagus are skeletal muscle fibres, the middle 1/3rd layer has both smooth and skeletal muscle fibres, but the lower 1/3rd only has smooth muscle fibres.

      The loose connective tissue layer or the adventitious layer has dense fibrous tissue.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 17 - Which of the following statements is false when considering the electrical safety of...

    Incorrect

    • Which of the following statements is false when considering the electrical safety of equipment?

      Your Answer:

      Correct Answer: The low leakage currents limit is 0.01mA for Class I CF

      Explanation:

      There are different classes of electrical equipment that can be classified in the table below:

      Class 1 – provides basic protection only. It must be connected to earth and insulated from the mains supply

      Class II – provides double insulation for all equipment. It does not require an earth.

      Class III – uses safety extra low voltage (SELV) which does not exceed 24 V AC. There is no risk of gross electrocution but risk of microshock exists.

      Type B – All of above with low leakage currents (0.5mA for Class IB, 0.1 mA for Class IIB)

      Type BF – Same as with other equipment but has ‘floating circuit’ which means that the equipment applied to patient is isolated from all its other parts.

      Type CF – Class I or II equipment with ‘floating circuits’ that is considered to be safe for direct connection with the heart. There are extremely low leakage currents (0.05mA for Class I CF and 0.01mA for Class II CF)

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 18 - An 80-year-old presents to the emergency department with symptoms raising suspicion of mesenteric...

    Incorrect

    • An 80-year-old presents to the emergency department with symptoms raising suspicion of mesenteric ischemia. To diagnose the condition, an angiogram is performed. The radiologist needs to cannulate the coeliac axis from the aorta for the angiogram.

      What vertebral level does the coeliac axis originate from the aorta?



      Your Answer:

      Correct Answer: T12

      Explanation:

      Mesenteric ischemia is ischemia of the blood vessels of the intestines. It can be life-threatening especially if the small intestine is involved.

      A critical factor for survival of acute mesenteric ischemia is early diagnosis and intervention. Angiography uses X-ray and contrast dye to image arteries and identify the severity of ischemia or obstruction.

      The celiac axis is the first branch of the abdominal aorta and supplies the entire foregut (mouth to the major duodenal papilla). It arises at the level of vertebra T12. It has three major branches:
      1. Left gastric
      2. Common hepatic
      3. Splenic arteries

      There are some important landmarks of vessels at different levels of vertebrae that need to be memorized.

      T12 – Coeliac trunk

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 19 - A patient admitted to the hospital is on oxygen via a venturi mask....

    Incorrect

    • A patient admitted to the hospital is on oxygen via a venturi mask.
      The air entrainment ratio is 1:9 i.e. 1 litre of 100% oxygen from the source entrains 9 litres of air from the atmosphere). The flow rate of 100% oxygen is 6L/minute.

      Based on the given data which of the following value approximates the oxygen concentration delivered to the patient?

      Your Answer:

      Correct Answer: 28%

      Explanation:

      The formula for calculating air: oxygen entrainment ratio is given as :
      100% − FiO2 = air/oxygen entrainment ratio
      Since FiO2 − 21% and the entrainment ratio is already known. Substituting the values in the equation: x = FiO2.

      100 − x = 9
      x − 21
      100 − x = 9(x − 21)
      100 − x = 9x − 189
      10x = 289
      x = 289/10
      x = 28.9%

    • This question is part of the following fields:

      • Basic Physics
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  • Question 20 - A young male is operated on for an open inguinal hernia repair. During...

    Incorrect

    • A young male is operated on for an open inguinal hernia repair. During the procedure, the cord is mobilized, and the deep inguinal ring is located.

      What structure forms the lateral wall of the deep inguinal ring?

      Your Answer:

      Correct Answer: Transversalis fascia

      Explanation:

      The deep inguinal ring is the entrance of the inguinal canal. It is an opening in the transversalis fascia around 1 cm above the inguinal ligament. Therefore, the superolateral wall is made by the transervalis fascia.

      The inferior epigastric vessels run medially to the deep inguinal ring forming its inferomedial border.

      The inguinal canal extends obliquely from the deep inguinal ring to the superficial inguinal ring.
      An indirect inguinal hernia arises through the deep inguinal ring lateral to the inferior epigastric vessels.

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 21 - A 64-year old lady has been diagnosed with hypertension. Her GP explains how...

    Incorrect

    • A 64-year old lady has been diagnosed with hypertension. Her GP explains how this occurs, and that blood pressure is determined by multiple factors which include action by the heart, nervous system and the diameter of the blood vessels. This lady's cardiac output (CO) is 4L/min. Her exam today revealed a mean arterial pressure (MAP) of 140 mmHg.
      Using these values, her systemic vascular resistance (SVR) is which of these?

      Your Answer:

      Correct Answer: 35mmHg⋅min⋅mL-1

      Explanation:

      Impaired ventricular relaxation reduces diastolic filling and therefore preload.

      Decreased blood volume decreases preload due to reduced venous return.

      Heart failure is characterized by reduced ejection fraction and therefore stroke volume.

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure (is increased by stroke volume) = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume
      Aortic stenosis would decrease stroke volume as end systolic volume would increase.
      This is because of an increase in afterload, an increase in resistance that the heart must pump against due to a hard stenotic valve.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 22 - Which one of the following patients presenting for elective surgery has an American...

    Incorrect

    • Which one of the following patients presenting for elective surgery has an American Society of Anaesthesiologists (ASA) preoperative physical status grading of III?

      Your Answer:

      Correct Answer: A 50-year old man with a BMI of 41 with a reduced exercise tolerance

      Explanation:

      The ASA physical status classification system is a system for assessing the fitness of patients before surgery. It was last updated in October 2014.

      ASA I A normal healthy patient
      ASA II A patient with mild systemic disease
      ASA III A patient with severe systemic disease
      ASA IV A patient with severe systemic disease that is a constant threat to life
      ASA V A moribund patient who is not expected to survive without the operation
      ASA VI A declared brain-dead patient whose organs are being removed for donor purposes

      A 20-year old woman who is 39-weeks pregnant with no other medical conditions – ASA II

      A 35-year-old man with a BMI of 29 with a good exercise tolerance who smokes-ASA II

      A 50-year old man with a BMI of 41 with a reduced exercise tolerance -ASA III

      A 65-year old woman with a BMI of 34 with treated hypertension with no functional limitations-ASA II

      A 73-year old man who has had a TIA ten-weeks ago but has a good exercise tolerance and is a non-smoker-ASA IV

    • This question is part of the following fields:

      • Clinical Measurement
      0
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  • Question 23 - A patient was brought to the emergency room after passing black tarry stools....

    Incorrect

    • A patient was brought to the emergency room after passing black tarry stools. The initial diagnosis was upper gastrointestinal bleeding. The patient was placed on temporary nil per os (NPO) for the next 24 hours, his weight was 110 kg, and the required volume of intravenous fluid for the him was 3 litres. His electrolytes and other biochemistry studies were normal.

      If you were to choose the intravenous fluid regimen that would closely mimic his basic electrolyte and caloric requirements, which one would be the best answer?

      Your Answer:

      Correct Answer: 3000 mL 0.45% N. saline with 5% dextrose, each bag with 40 mmol of potassium

      Explanation:

      The patient in the case has a fluid volume requirement of 30 mL/kg/day. His basic electrolyte requirement per day is:

      Sodium at 2 mmol/kg/day x 110 = 220 mmol/day
      Potassium at 1 mmol/kg/day x 110 = 110 mmol/day

      His energy requirement per day is:

      35 kcal/kg/day x 110 kg = 3850 kcal/day

      One gram of glucose in fluid can provide approximately 4 kilocalories.

      The following are the electrolyte components of the different intravenous fluids:

      Fluid Na (mmol/L) K (mmol/L)
      0.9% Normal saline (NSS) 154 0
      0.45% NSS + 5% dextrose 77 0
      0.18% NSS + 4% dextrose 30 0
      Hartmann’s 131 5
      5% dextrose 0 0

      1000 mL of 5% dextrose has 50 g of glucose

      Option B is inadequate for his sodium and caloric requirements (30 mmol of Na+ and 560 kcal). It is adequate for his K+ requirement (120 mmol of K+).

      Option C is in excess of his Na+ requirement (462 mmol of Na+). Moreover, it does not provide any K+ replacement.

      Option D is inadequate for his caloric requirement (600 kcal) and K+ requirement (60 mmol of K+). Moreover it does not provide any Na+ replacement.

      Option E is in excess of his Na+ requirement (393 mmol of Na+), and is inadequate for his potassium requirement (15 mmol of K+)

      Option A has adequate amounts for his Na+ (231 mmol of Na+) and K+ (120 mmol of K+) requirements. It is inadequate for his caloric requirement (600 kcal).

    • This question is part of the following fields:

      • Physiology
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  • Question 24 - A 65-year-old man got operated on for carotid endarterectomy for his carotid artery...

    Incorrect

    • A 65-year-old man got operated on for carotid endarterectomy for his carotid artery disease. He is recovering well post-surgery. However, on follow-up in the ward, he has hoarseness of his voice.

      Which of the following explains the hoarseness?

      Your Answer:

      Correct Answer: Damage to the vagus

      Explanation:

      During carotid endarterectomy, injury to the vagus nerve or its branches can cause hoarseness. Injury to the vagus nerve can result in adductor vocal cord paralysis. It can also cause other symptoms like dysphagia or even vocal cord immobility.

      Carotid endarterectomy is the procedure to relieve an obstruction in the carotid artery by opening the artery at its origin and stripping off the atherosclerotic plaque with the intima. Because of the internal carotid artery relations, there is a risk of cranial nerve injury during the procedure involving one or more of the following nerves: CN IX, CN X (or its branch, the superior laryngeal nerve), CN XI, or CN XII.

      However, only damage to the vagus would account for speech difficulties.

    • This question is part of the following fields:

      • Anatomy
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  • Question 25 - Many of the processes we deal with in anaesthesia entail a relationship between...

    Incorrect

    • Many of the processes we deal with in anaesthesia entail a relationship between two or more variables.

      Which of the following relationships is a linear relationship?

      Your Answer:

      Correct Answer: The relationship between the junction potential and temperature in a thermocouple

      Explanation:

      Two bonded wires of dissimilar metals, iron/constantan or copper/constantan, make up a thermocouple (constantan is an alloy of copper and nickel). At the tip, a thermojunction voltage is generated that is proportional to temperature (Seebeck effect).

      All of the other connections are non-linear.

      For a single compartment model, the relationship between a decrease in plasma concentration of an intravenous bolus of a drug and time is a washout exponential.

      A sine wave is the relationship between current and degrees or time from a mains power source.

      A sigmoid curve represents the relationship between efficacy and log-dose of a pure agonist on mu receptors.

      The pressure of a fixed mass of gas and its volume (Boyle’s law) at a fixed temperature are inversely proportional, resulting in a hyperbolic curve.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 26 - A 60-year-old male is being reviewed in the peri-operative assessment before total knee...

    Incorrect

    • A 60-year-old male is being reviewed in the peri-operative assessment before total knee replacement. He had a history of a heart transplant 10 years back. His resting heart rate is 110 beats per minute. On examination, ECG showed sinus tachycardia.

      Which of the following explains this tachycardia?

      Your Answer:

      Correct Answer: Loss of parasympathetic innervation

      Explanation:

      Normally, at rest vagal influence is dominant producing the heart rate of 60-80 beats per minute even if the intrinsic automaticity of Sinoatrial Node is 100-110 beats per minute.

      The transplanted heart has no autonomic nervous supply. So, it will respond to endogenous and exogenous catecholamine. This loss of parasympathetic innervation is responsible for the tachycardia in this patient.

      Hypokalaemia can cause myocardial excitability and potential for ventricular ectopic and supraventricular arrhythmias. Hypothyroidism is also unlikely to cause tachycardia in this patient.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 27 - The following statements concern the sensory innervation of the nasal passage: ...

    Incorrect

    • The following statements concern the sensory innervation of the nasal passage:

      Your Answer:

      Correct Answer:

      Explanation:

      The walls of the anterior nasal passage are supplied by the anterior ethmoidal branch of the nasociliary nerve, and the floor is innervated by the superior dental nerve (not the sphenopalatine nerves).

      The walls and floor of the posterior nasal passage are innervated by the long and short sphenopalatine nerves and the great palatine nerve (not the superior dental nerves and the nasociliary nerve).

      The vestibule is innervated by small branches of the infraorbital branch of the maxillary nerve.

      The nasopharynx is innervated by the sensory branches of the trigeminal nerve (not the great palatine nerve).

    • This question is part of the following fields:

      • Anatomy
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  • Question 28 - During the design phase of a study, which among the given is aimed...

    Incorrect

    • During the design phase of a study, which among the given is aimed at addressing confounding factors?

      Your Answer:

      Correct Answer: Randomisation

      Explanation:

      Randomisation allows for performance of experimental trials in a random order. Using this method gives us control over the confounding variables that are not supposed to be held constant.

      For an instance, by employing randomisation we get to control biological differences among individual human beings during experimental trials.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 29 - In North America, there have been reports of paediatric patients dying after undergoing...

    Incorrect

    • In North America, there have been reports of paediatric patients dying after undergoing adenotonsillectomy for obstructive sleep apnoea.

      Respiratory depression/obstruction is thought to be the cause of death. The codeine dose was 0.5-1 mg/kg, given every 4-6 hours.

      In this group of patients, which of the following is the most likely cause of respiratory depression and obstruction?

      Your Answer:

      Correct Answer: Exaggerated metabolism of codeine

      Explanation:

      Codeine is easily absorbed from the gastrointestinal tract and converted to morphine and norcodeine in the liver via O- and N-demethylation. Morphine and norcodeine are excreted almost entirely by the kidney, primarily as conjugates with glucuronic acid.

      By glucuronidation, phase II metabolism enzyme UDP-glucuronosyl transferase-2B7 converts morphine to morphine-3-glucuronide (M3G) and morphine-6-glucuronide (M6G) (UGT2B7).

      Approximately 60% of morphine is converted to M3G, with the remaining 6-10% converted to M6G. M3G is inactive, but M6G is said to be 4 to 650 times more potent on the MOP receptor than morphine.

      When codeine is consumed, cytochrome P450 2D6 in the liver converts it to morphine (CYP2D6).

      Some people have DNA variations that increase the activity of this enzyme, causing codeine to be converted to morphine more quickly and completely than in others. After taking codeine, these ultra-rapid metabolisers are more likely to have higher than normal levels of morphine in their blood.

      Respiratory depression/obstruction can be caused by high levels of morphine and M6G, especially in people who have a history of obstructive sleep apnoea. The estimated number of ultra-rapid metabolisers ranges from 1 to 7 per 100 people, but some ethnic groups may have as many as 28 per 100 people.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 30 - The prospects of setting up a health facility to help patients with ischaemic...

    Incorrect

    • The prospects of setting up a health facility to help patients with ischaemic heart disease in a remote area are under consideration and you have been asked to look into it.

      What's the crucial factor in finding out the amount of resources needed to go ahead with the idea?

      Your Answer:

      Correct Answer: Prevalence

      Explanation:

      Both incidence and prevalence are indicators of the disease frequency. While incidence tells us about the number of cases reported per population in a provided time period, prevalence is the factor you should be vigilant about as it tells us about the total number of cases that have been reported in a population at a particular point of time.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 31 - The renal glomerulus is able to filter 180 litres of blood per day,...

    Incorrect

    • The renal glomerulus is able to filter 180 litres of blood per day, as determined by the starling forces present in the glomerulus. Ninety-nine percent of which is reabsorbed thereafter.

      Water is reabsorbed in the highest proportion in which segment of the nephron?

      Your Answer:

      Correct Answer: Proximal convoluted tubule

      Explanation:

      Sixty-seven percent of filtered water is reabsorbed in the proximal tubule. The driving force for water reabsorption is a transtubular osmotic gradient established by reabsorption of solutes (e.g., NaCl, Na+-glucose).

      Henle’s loop reabsorbs approximately 25% of filtered NaCl and 15% of filtered water. The thin ascending limb reabsorbs NaCl by a passive mechanism, and is impermeable to water. Reabsorption of water, but not NaCl, in the descending thin limb increases the concentration of NaCl in the tubule fluid entering the ascending thin limb. As the NaCl-rich fluid moves toward the cortex, NaCl diffuses out of the tubule lumen across the ascending thin limb and into the medullary interstitial fluid, down a concentration gradient as directed from the tubule fluid to the interstitium. This mechanism is known as the counter current multiplier.

      The distal tubule and collecting duct reabsorb approximately 8% of filtered NaCl, secrete variable amounts of K+ and H+, and reabsorb a variable amount of water (approximately 8%-17%).

    • This question is part of the following fields:

      • Physiology
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  • Question 32 - Regarding metal wires, which of the following is the most important determinant of...

    Incorrect

    • Regarding metal wires, which of the following is the most important determinant of their resistance?

      Your Answer:

      Correct Answer: Resistivity

      Explanation:

    • This question is part of the following fields:

      • Basic Physics
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  • Question 33 - If a large volume of 0.9% N. saline is administered during resuscitation, it...

    Incorrect

    • If a large volume of 0.9% N. saline is administered during resuscitation, it is most likely to cause?

      Your Answer:

      Correct Answer: Hyperchloremic metabolic acidosis

      Explanation:

      Crystalloids recommended for fluid resuscitation include 0.9% N saline and Hartmann’s solution(a physiological solution). 0.9% N. saline is not a physiological solution for the following reasons:

      Compared with the normal range of 98-102 mmol/L, its chloride concentration is high (154 mmol/L)
      It lacks calcium, magnesium, glucose and potassium
      It does not have bicarbonate or bicarbonate precursor buffer necessary to maintain plasma pH within normal limits

      There is a difference in the activity (concentration) of strong ions at a physiological pH. This imbalance can explain abnormalities of acid base balance. A normal strong ion difference (SID) is in the order of 40.

      SID = ([Na+] + [K+] + [Ca2+] + [Mg2+]) – ([Cl-] + [lactate] + [SO42-])

      This imbalance is made up with the weaker anions to maintain electrical neutrality.
      Administration of a large volume of 0.9% normal saline during resuscitation results in excessive chloride administration and this impairs renal bicarbonate reabsorption. The SID of 0.9% normal saline is 0 (Na+ = 154mmol/L and Cl- = 154mmol/L = 154 – 154 = 0). A large volume of NS will decrease the plasma SID causing an acidosis.

      Other causes of a hyperchloremic acidosis are:

      Diabetic ketoacidosis
      Total Parenteral Nutrition
      Overdose of ammonium chloride and hydrochloric acid
      Gastrointestinal losses of bicarbonate like in diarrhoea and pancreatic fistula
      Proximal renal tubular acidosis with failure of bicarbonate reabsorption

    • This question is part of the following fields:

      • Physiology
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  • Question 34 - Which of the following statement is true or false regarding to the respiratory...

    Incorrect

    • Which of the following statement is true or false regarding to the respiratory tract?

      Your Answer:

      Correct Answer: The sympathetic innervation of the bronchi is derived from T2 - T4

      Explanation:

      The diaphragm has three opening through which different structures pass from the thoracic cavity to the abdominal cavity:

      Inferior vena cava passes at the level of T8.

      Oesophagus, oesophageal vessels and vagi at T10.

      Aorta, thoracic duct and azygous vein through T12.

      Sympathetic trunk and pulmonary branches of vagus nerve form a posterior pulmonary plexus at the root of the lung. Fibres continue posteriorly from superficial cardiac plexus to form Anterior pulmonary plexus. It contains vagi nerves and superficial cardiac plexus. These fibres then follow the blood vessel and bronchi into the lungs.

      The lower border of the pleura is at the level of:

      8th rib in the midclavicular line

      10th rib in the lower level of midaxillary line

      T12 at its termination.

      Both lungs have oblique fissure while right lung has transverse fissure too.

      The trachea expands from the lower edge of the cricoid cartilage (at the level of the 6th cervical vertebra) to the carina.

    • This question is part of the following fields:

      • Physiology
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  • Question 35 - A 28-year male patient presents to the GP with a 2-day history of...

    Incorrect

    • A 28-year male patient presents to the GP with a 2-day history of abdominal pain and bloody diarrhoea. He reports that he was completely fine until one week ago when headache and general tiredness appeared. After further questioning, he revealed eating at a dodgy takeaway 3 days before the start of his symptoms.

      Which of the following diagnosis is most likely?

      Your Answer:

      Correct Answer: Campylobacter

      Explanation:

      Giardiasis is known to have a longer incubation time and doesn’t cause bloody diarrhoea.

      Cholera usually doesn’t cause bloody diarrhoea.

      Generally, most of the E.coli strains do not cause bloody diarrhoea.

      Diverticulitis can be a cause of bloody stool but the history here points out to an infectious cause.

      Campylobacter infection is the most probable cause as it is characterized by a prodrome, abdominal pain and bloody diarrhoea

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 36 - A 60-year-old man, presents to the emergency department with crushing pain in the...

    Incorrect

    • A 60-year-old man, presents to the emergency department with crushing pain in the central chest area, which radiates to his left arm and jaw. He also reports feelings of nausea with no other symptoms. Elevation of the ST-segment is noted in multiple chest leads upon ECG, leading to a diagnosis of ST-elevation MI.

      What vessel gives rise to the coronary vessels?

      Your Answer:

      Correct Answer: Ascending aorta

      Explanation:

      The above mentioned patient presentation is one of an acute coronary syndrome.

      The elevations noted in the ST-segments of multiple heart leads on ECG is diagnostic of an ST-elevation myocardial infarction.

      The pulmonary artery branches to give rise to the right and left pulmonary arteries, which supply deoxygenated blood to the right and left lungs from the right ventricle.

      The pulmonary veins do not form any bifurcations, and therefore do not give rise to any vessels. They travel to the left atrium from the lungs, carrying oxygenated blood.

      The descending aorta continues from the aortic arch, and bifurcates to give off many branches, including the right and left common iliac arteries.

      The coronary sinus is formed from the combination of four coronary veins, receiving blood supply from the great, middle, small and posterior cardiac veins, and transporting this venous blood into the right atrium.

      The right and left aortic sinus give rise to the right and left coronary arteries, respectively. They branch of the ascending aorta, in the area just superior to the aortic valve.

    • This question is part of the following fields:

      • Anatomy
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  • Question 37 - Regarding the anatomical relations of the first rib, one of the following is...

    Incorrect

    • Regarding the anatomical relations of the first rib, one of the following is right

      Your Answer:

      Correct Answer: The subclavius muscle attaches to the upper surface

      Explanation:

      The first rib is an atypical rib. It is short, wide, and flattened and lies in an oblique plane.

      It has a small scalene tubercle on its medial border which marks the point of attachment of scalenus anterior. The lower surface lies on the pleura and is smooth.

      The tubercle on the upper surface separates an anterior groove for the subclavian vein and a posterior groove for the subclavian artery and lower trunk of the brachial plexus.

      Scalenus medius is attached to a roughened area posterior to the groove for the subclavian artery.

      The upper surface gives attachment anteriorly to the subclavius muscle and costoclavicular ligament.

    • This question is part of the following fields:

      • Anatomy
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  • Question 38 - When compared to unipolar diathermy, which of the following is more specific to...

    Incorrect

    • When compared to unipolar diathermy, which of the following is more specific to bipolar diathermy?

      Your Answer:

      Correct Answer: Has a power output of up to 140 joules per second

      Explanation:

      Electrocautery, also known as diathermy, is a technique for coagulation, tissue cutting, and fulguration that uses a high-frequency current to generate heat (cell destruction from dehydration).

      The two electrodes in bipolar diathermy are the tips of forceps, and current passes between the tips rather than through the patient. Bipolar diathermy’s power output (40-140 W) is lower than unipolar diathermy’s typical output (400 W). There is no earthing in the bipolar circuit.

      A cutting electrode and a indifferent electrode in the form of a metal plate are used in unipolar diathermy. The high-frequency current completes a circuit by passing through the patient from the active electrode to the metal plate. When used correctly, the current density at the indifferent electrode is low, and the patient is unlikely to be burned. Between the patient plate and the earth is placed an isolating capacitor. This has a low impedance to a high frequency current, such as diathermy current, and is used in modern diathermy machines. The capacitor has a high impedance to current at 50 Hz, which protects the patient from electrical shock.

      High frequency currents (500 KHz – 1 MHz) are used in both unipolar and bipolar diathermy, which can cause tissue damage and interfere with pacemaker function (less so with bipolar diathermy).

      The effect of diathermy is determined by the current density and waveform employed. The current is a pulsed square wave pattern in coagulation mode and a continuous square wave pattern in cutting mode.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 39 - A 33-year-old woman known to be hypothyroid and taking 150 mcg l-thyroxine daily...

    Incorrect

    • A 33-year-old woman known to be hypothyroid and taking 150 mcg l-thyroxine daily is reviewed in the preoperative assessment clinic prior to a laparoscopic cholecystectomy.

      She has required three increases in her thyroid replacement therapy in the last six months.

      Her thyroid function tests are as follows:

      TSH 11 (normal range 0.4-4mU/L)
      T3 20 (normal range 9-25mU/L)
      T4 6.2 (normal range 3.5-7.8mU/L)

      What will explain this biochemical picture?

      Your Answer:

      Correct Answer: Poor compliance with medication

      Explanation:

      In patients with an intact hypothalamic-pituitary axis, serial TSH measurements are used to determine the adequacy of treatment with thyroid hormones . changes in TSH levels becoming apparent after approximately eight weeks of therapy with thyroid hormone replacement. Change in T3/T4 levels are seen before changes in TSH .

      In patients taking thyroid replacement therapy, the most frequent reason for persistent elevation of serum TSH is poor compliance. Patients who do not regularly take their L-thyroxine try and catch up just before a visit to a clinician for blood test.

      Tissue-level unresponsiveness to thyroid hormone is caused by mutation in the gene controlling a receptor for T3 and is rare.

      Reduced responsiveness of target tissues to thyroid hormone aka resistance to thyroid hormones (rTH) occurs when there is a mutation in the thyroid hormone receptor ? gene. It is a rare autosomal dominant inherited syndrome of reduced end-organ responsiveness to thyroid hormone and has two types:

      Generalised resistance (GrTH)
      Pituitary resistance (PrTH)

      Patients with rTH have normal or slightly elevated serum thyroid stimulating hormone (TSH) level, elevated serum free thyroxine (FT4) and free triiodothyronine (FT3) concentrations.

      Drugs that increase metabolism of thyroxine include:

      Warfarin
      Rifampin
      Phenytoin
      Phenobarbital
      St John’s Wort
      Carbamazepine

      These drugs lower circulating thyroid hormones and would be associated with a raised TSH but low T3/T4.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 40 - A 23-year-old man who is currently on fluoxetine for depression was anaesthetized two...

    Incorrect

    • A 23-year-old man who is currently on fluoxetine for depression was anaesthetized two hours ago for knee arthroscopy. He seems agitated, confused, with a heart rate of 120 beats per minute, a temperature of 38.2oC, and developed difficulty moving his limbs.

      He is on paracetamol and tramadol for analgesia. Which of the following is the most likely cause for his condition?

      Your Answer:

      Correct Answer: Tramadol

      Explanation:

    • This question is part of the following fields:

      • Pharmacology
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  • Question 41 - Which among the following is not true regarding disease rates? ...

    Incorrect

    • Which among the following is not true regarding disease rates?

      Your Answer:

      Correct Answer: The odds ratio is synonymous with the risk ratio

      Explanation:

      The relative risk (also known as risk ratio [RR]) is the ratio of risk of an event in one group (e.g., exposed group) versus the risk of the event in the other group (e.g., nonexposed group).

      The odds ratio (OR) is the ratio of odds of an event in one group versus the odds of the event in the other group.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 42 - A 56-year old man, presents to emergency department following a cardiac arrest. On...

    Incorrect

    • A 56-year old man, presents to emergency department following a cardiac arrest. On history and examination, he is found to be suffering from both metabolic and respiratory acidosis as a result of his cardiac arrest.

      What is the best way to reduce the risk of acidaemia during cardiac arrest

      Your Answer:

      Correct Answer: Chest compressions

      Explanation:

      Chest compressions are an essential part of cardiopulmonary resuscitation (CPR) which helps restore spontaneous circulation (ROSC).

      Sodium bicarbonate is only prescribed in patients with cardiac arrests as a result of an overdose of tricyclic antidepressants or hyperkalaemia. Its use causes the body to produce more CO2 which causes:

      Exacerbation of intracellular acidosis
      Negative inotropy to ischaemic myocardium
      Increased osmotic load of sodium into failing brain and body
      Shift of oxygen dissociation curve to the left.

      THAM is often used to treat metabolic acidosis as a result of cardiac bypass surgery and also cardiac arrest, when other standard methods have failed.

      Carbicarb (Na2CO3 0.33 molar NaHCO3 0.33 molar) has only mild effects on acidosis. It also causes an increase in arterial CO2 pressure and lactate concentration.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 43 - A 55-year-old man with a ventricular rate of 210 beats per minute is...

    Incorrect

    • A 55-year-old man with a ventricular rate of 210 beats per minute is admitted to the emergency department with atrial fibrillation. The patient develops ventricular fibrillation shortly after receiving pharmacotherapy to treat his arrhythmia, from which he is successfully resuscitated.

      He has a PR interval of 40 Ms, a prominent delta wave in lead I, and a QRS duration of 120 Ms, according to an ECG from a previous admission.

      Which of the following drugs is most likely to be involved in this patient's development of ventricular fibrillation?

      Your Answer:

      Correct Answer: Digoxin

      Explanation:

      The Wolff-Parkinson-White syndrome (WPWS) is linked to an additional electrical conduction pathway between the atria and ventricles. This accessory pathway (bundle of Kent), unlike the atrioventricular (AV) node, is incapable of slowing down a rapid rate of atrial depolarization. In other words, a short circuit bypasses the AV node. Patients with a rapid ventricular response or narrow complex AV re-entry tachycardia are more likely to develop atrial fibrillation or flutter.

      Digoxin can promote impulse transmission through this accessory pathway if a patient with WPWS develops atrial fibrillation because it works by blocking the AV node. This can cause ventricular fibrillation and an extremely rapid ventricular rate. As a result, it’s not advised.

      Adenosine, beta-blockers, and calcium channel blockers, among other drugs that interfere with AV nodal conduction, are also generally contraindicated.

      The class III antiarrhythmic drugs amiodarone and ibutilide (K+ channel block) and procainamide (Na+ channel block) are the drugs of choice.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 44 - Which of the following may indicate an inadequate reversal of non-depolarising neuromuscular blockade?...

    Incorrect

    • Which of the following may indicate an inadequate reversal of non-depolarising neuromuscular blockade?

      Your Answer:

      Correct Answer: Post tetanic count of 5

      Explanation:

      A post-tetanic count of 5 denotes a deep neuromuscular blockade.

      Post tetanic count (PTC) is a well-established method of evaluating neuromuscular recovery during intense neuromuscular blockade. It cam ne used when there is no response to single twitch, tetanic, or train-of-four (TOF) stimulation to assess the intensity of neuromuscular blockade and to estimate the duration after which the first twitch in the TOF (T1) is likely to reappear.

      During a nondepolarizing block, the high frequency of tetanic stimulation will induce a transient increase in the amount of acetylcholine released from the presynaptic nerve ending, such that the intensity of subsequent muscle contractions will be increased (potentiated) briefly (period of post-tetanic potentiation, which may last 2 to 5 min. The neuromuscular response to stimulation during post tetanic potentiation can be used to gauge the depth of block when TOF stimulation otherwise evokes no responses. The number of post tetanic responses is inversely proportional to the depth of block: fewer post tetanic contractions denote a deeper block. When the post tetanic count (PTC) is 6 to 8, recovery to TOF count = 1 is likely imminent from an intermediate-duration blocking agent; when the PTC is 0, the depth of block is profound, and no additional NMBA should be administered.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 45 - A 31-year old Caucasian female came into the emergency department due to difficulty...

    Incorrect

    • A 31-year old Caucasian female came into the emergency department due to difficulty of breathing. History revealed exposure to room odorizes that are rich in alkyl nitrites. Upon physical examination, patient is tachypnoeic at 32 breaths per minute, desaturated at 88% while on a non-rebreather mask at 15 litres per minute oxygen. She was also noted to be cyanotic, however with clear breath sounds.

      Considering the history, what is the most probable cause of her difficulty of breathing?

      Your Answer:

      Correct Answer: Increased affinity of bound oxygen to haemoglobin

      Explanation:

      Amyl nitrate is part of the treatment of cyanide poisoning. The short acting nitrate causes oxidation of Fe2+ in haemoglobin to Fe3+ in methaemoglobin. Methaemoglobin combines with cyanide (cyanmethemoglobin), which reacts with sodium thiosulfate to convert nontoxic thiocyanate and methaemoglobin.

      Methaemoglobin is formed when the iron in haemoglobin is converted from the reduced state (Fe2+) to the oxidized state (Fe3+). The oxidized form of haemoglobin (Fe3+) does not bind oxygen as readily as Fe2+, but has high affinity for cyanide. It also results to high affinity of bound oxygen to haemoglobin, thus leading to tissue hypoxia. Arterial oxygen tension is normal despite observations of cyanosis and dyspnoea. Methemoglobinemia can be treated with methylene blue and vitamin C.

      Carboxyhaemoglobin can be due to carbon monoxide poisoning. In such cases, patients experience headache and dizziness, but do not develop cyanosis.

      2,3-diphosphoglycerate causes a shift in the oxygen dissociation curve to the right, decreasing haemoglobin’s affinity to oxygen to facilitate unloading of oxygen to the tissues.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 46 - The passage of glucose into the brain is facilitated by which transport method?...

    Incorrect

    • The passage of glucose into the brain is facilitated by which transport method?

      Your Answer:

      Correct Answer: Facilitated diffusion

      Explanation:

      Glucose transport is a highly regulated process accomplished mostly by facilitated diffusion using carrier proteins to cross cell membranes.

      There are many transporters, but the most important are known as glucose transporters (GLUTs).

      Stresses in various form of acute and chronic forms affect the activity of glucose transporters.
      They are responsive to many types of metabolic stress, including hypoxia, injury, hypoglycaemia, numerous metabolic inhibitors, stress hormones, and other influences such as growth factors.

      Numerous signalling pathways appear to be involved in transporter regulation.

      New evidence suggests that stresses regulating GLUTs are not only acute biological stresses. In addition, chronic low-grade inflammation, and their associated chronic diseases also lead to altered glucose transport. These include obesity, type 2 diabetes, cardiovascular disease, and the growth and spread of many tumours that are affected by altered glucose transporters. Some of these glucose transport effects are compensatory, while others are pathogenic.

      Ultimately, deliberate manipulation of GLUTs could be used as treatment for some of these chronic diseases.

    • This question is part of the following fields:

      • Physiology
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  • Question 47 - A 46-year-old woman is listed for clipping of a cerebral aneurysm, following a...

    Incorrect

    • A 46-year-old woman is listed for clipping of a cerebral aneurysm, following a diagnosis of surgical third nerve palsy.

      Which of the following clinical findings correlate with surgical third nerve palsy?

      Your Answer:

      Correct Answer: Ptosis, inferolateral rotation of globe and mydriasis

      Explanation:

      Ptosis and mydriasis are visible in surgical third nerve palsy, and the eye looks ‘down and out.’ The loss of innervation to all of the major structures supplied by the oculomotor nerve is reflected in these characteristics.

      Ptosis is caused by the paralysis of the levator palpebrae superioris in oculomotor nerve palsy. Due to the unopposed actions of the superior oblique and lateral rectus muscles, the eye rotates down and out.

      Mydriasis is caused by surgical (compressive) causes of third nerve palsy, which disrupt the parasympathetic pupillomotor fibres on the nerve’s periphery.

      Medical (ischaemic) causes of a third nerve palsy, on the other hand, leave the superficial parasympathetic fibres relatively unaffected and the pupil unaffected.

      Horner’s syndrome is characterised by ptosis, anhidrosis, and miosis, which are caused by a loss of sympathetic innervation to the tarsal muscle of the upper lid, facial skin, and dilator pupillae, respectively.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 48 - An 80-year old female was taken to the emergency room for chest pain....

    Incorrect

    • An 80-year old female was taken to the emergency room for chest pain. She has a medical history of coronary artery disease and previous episodes of atrial fibrillation. She was immediately attached to the cardiac monitor, which showed tachycardia at 148 beats per minute. The 12-lead ECG revealed atrial fibrillation.

      Digoxin was given as an anti-arrhythmic at 500 micrograms, which is higher than the maintenance dose routinely given. Why is this so?

      Your Answer:

      Correct Answer: It has a high volume of distribution

      Explanation:

      When the loading dose of Digoxin is given, the primary thing to consider is the volume of distribution. The volume of distribution is the proportionality factor that relates the total amount of drug in the body to the concentration. LD is computed as:

      LD = Volume of distribution X (desired plasma concentration/bioavailability)

      Digoxin is an anti-arrhythmic drug with a large volume of distribution and high bioavailability, and only a small percentage of Digoxin is bound to plasma proteins (,20%).

      In the case, since the arrhythmia is not life-threatening, there is no need for the medication to work rapidly.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 49 - Drug toxicity when using bupivacaine is most likely to occur when this local...

    Incorrect

    • Drug toxicity when using bupivacaine is most likely to occur when this local anaesthetic technique is performed.

      Your Answer:

      Correct Answer: Intercostal nerve block

      Explanation:

      An intercostal nerve block is used for therapeutic and diagnostic purposes. Intercostal nerve blocks manage acute and chronic pain in the chest area. Common indications are chest wall surgery and shingles or postherpetic neuralgia.

      An intercostal nerve block is also an effective option for the management of pain associated with chest trauma and rib fractures. These blocks have been shown to improve oxygenation and respiratory mechanics, and offer pain relief that is comparable to that of epidural analgesia.

      This technique, however, is limited by the relatively large doses of local anaesthetic required, and relatively high intravascular uptake from the intercostal space, increasing risk of local anaesthetic toxicity.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 50 - A patient in the post-anaesthesia care unit was put on ephedrine for episodes...

    Incorrect

    • A patient in the post-anaesthesia care unit was put on ephedrine for episodes of hypotension. Initial bolus doses were effective and the patient became normotensive, until, a few hours later, there was a noticeable drop in the blood pressure despite administration of another dose of ephedrine.

      Which of the following best explains the situation above?

      Your Answer:

      Correct Answer: Tachyphylaxis

      Explanation:

      When responsiveness diminishes rapidly after administration of a drug, the response is said to be subject to tachyphylaxis. This may be due to frequent or continuous exposure to agonists, which often results in short-term diminution of the receptor response.

      Many mechanisms may be responsible, such as blocking access of G protein to activated receptor, or receptor molecules internalized by endocytosis to prevent exposure to extracellular molecules.

      Tolerance occurs when larger doses are required to produce the same effect. This may be due to changes in receptor number or function due to exposure to the drug.

      Desensitization refers to the common situation where the biological response to a drug diminishes when it is given continuously or repeatedly. It is a chronic loss of response, occurring over a longer period than tachyphylaxis. It may be possible to restore the response by increasing the dose (or concentration) of the drug but, in some cases, the tissues may become completely refractory to its effect.

      Drug dependence is defined as a psychic and physical state of the person characterized by behavioural and other responses resulting in compulsions to take a drug, on a continuous or periodic basis in order to experience its psychic effect and at times to avoid the discomfort of its absence.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 51 - The following is normally higher in concentration extracellularly than intracellularly ...

    Incorrect

    • The following is normally higher in concentration extracellularly than intracellularly

      Your Answer:

      Correct Answer: Sodium

      Explanation:

      The ions found in higher concentrations intracellularly than outside the cells are:

      ATP
      AMP
      Potassium
      Phosphate, and
      Magnesium Adenosine diphosphate (ADP)

      Sodium is a primarily extracellular ion.

    • This question is part of the following fields:

      • Physiology
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  • Question 52 - The following results were obtained In a new drug trial:

    Improved Not improved
    Placebo...

    Incorrect

    • The following results were obtained In a new drug trial:

      Improved Not improved
      Placebo group 36 26
      Treatment group 44 16

      Regarding the statistical analysis or interpretation of the trial, One of these is true

      Your Answer:

      Correct Answer: The data could be evaluated using the chi square test

      Explanation:

      This data is in a 2 × 2 contingency table so a chi square test can be used. There is a special chi squared formula that gives a value that can be looked up in a table giving the p value.

      Since we are comparing proportions not means, the Student’s t test CANNOT be used.

      There is no linear regression to plot so Pearson’s co-efficient cannot be calculated.

      Nothing is so obvious that no statistical analysis is needed.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 53 - You've been summoned to the paediatric ward after a 4-year-old child was discovered...

    Incorrect

    • You've been summoned to the paediatric ward after a 4-year-old child was discovered 'collapsed' in bed.

      The child had been admitted the day before with febrile convulsions and was scheduled to be discharged. It is safe to approach the child.

      What should your first life-saving action be?

      Your Answer:

      Correct Answer: Apply a gentle stimulus and ask the child if they are alright

      Explanation:

      Paediatric life support differs from adult life support in that hypoxia is the primary cause of deterioration.

      After checking for danger, the child should be given a gentle stimulus (such as holding the head and shaking the arm) and asked, Are you alright? according to current advanced paediatric life support (APLS) guidelines. Safety, Stimulate, Shout is a phrase that is frequently remembered. Any airway assessment should be preceded by these actions.

      Although the algorithm includes five rescue breaths, they are performed after the airway assessment.

      It is not recommended to ask parents to leave unless they are obstructing the resuscitation. A team member should be with them at all times to explain what is going on and answer any questions they may have.

      CPR should not begin until the child has been properly assessed and rescue breaths have been administered.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 54 - In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five...

    Incorrect

    • In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five minutes is indicated during in-hospital cardiac arrest due to ventricular fibrillation (VF) following three DC shocks.

      Which of the following indicates the most important reason for using epinephrine?

      Your Answer:

      Correct Answer: Preferential distribution of blood to the coronary and cerebral circulation

      Explanation:

      Epinephrine is used for the treatment of cardiac arrest because it causes vasoconstriction via the alpha-adrenergic (?1) receptor. This vasoconstriction increases cerebral and coronary blood flow by increasing mean arterial, aortic diastolic, and cerebral pressures. Furthermore, epinephrine is also a?1 and ?2 adrenoreceptor agonist which shows inotrope, chronotrope, and bronchodilator effects.
      – Adrenaline is also used to prolong the duration of action and decrease the systemic toxicity of local anaesthetics.
      – Preferred route of adrenaline in patients with cardiac arrest is i.v. followed by intra-osseous and endotracheal

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 55 - A 40-year old female comes to the GP's office with unexplained weight gain,...

    Incorrect

    • A 40-year old female comes to the GP's office with unexplained weight gain, cold intolerance and fatigue. Her thyroid function tests are performed as there is a suspicion of hypothyroidism. A negative feedback mechanism is incorporated in the control of thyroid hormone release. All of choices below are also controlled by a negative feedback loop except:

      Your Answer:

      Correct Answer: Clotting cascade

      Explanation:

      The correct answer is the clotting cascade, which occurs via a positive feedback mechanism. As clotting factors are attracted to a site, their presence attracts further clotting factors. This continues until a functioning clot is formed.

      This patient has presented with symptoms of hypothyroidism and symptoms include weight gain, lethargy, cold intolerance, dry skin, coarse hair and constipation. It can be treated by replacing the missing thyroid hormone with levothyroxine which is a synthetic version of thyroxine (T4).

      Serum carbon dioxide (CO2) is controlled via a negative feedback mechanism as well. Chemoreceptors can detect when the serum CO2 is high, and send an impulse to the respiratory centre of the brain to increase the respiratory rate. As a result, more CO2 is exhaled which lowers the serum concentration.

      Cortisol is also released according to a negative feedback mechanism. Cortisol acts on both the hypothalamus and the anterior pituitary. Its action serve to decrease the formation of corticotrophin releasing hormone (CRH) and adrenocorticotropic hormone (ACTH), respectively. CRH acts on the anterior pituitary to release ACTH. This then acts on the adrenal gland to cause the release of cortisol. Thus, inhibition of CRH and ACTH formation results in high levels of cortisol which inhibit its further release.

      Blood pressure (BP) is controlled via a negative feedback mechanism. Low BP results in renin-angiotensin-aldosterone system (RAAS) activation. This leads to vasoconstriction and retention of salt and water which increased BP.
      Blood sugar is controlled via a negative feedback mechanism. A rise in blood sugar causes insulin to be released. Insulin acts to transport glucose into the cell which lowers blood sugar.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 56 - Out of the following, which is NOT true regarding the external carotid? ...

    Incorrect

    • Out of the following, which is NOT true regarding the external carotid?

      Your Answer:

      Correct Answer: It ends by bifurcating into the superficial temporal and ascending pharyngeal artery

      Explanation:

      The external carotid artery has eight important branches:
      Anterior surface:
      1. Superior thyroid artery (first branch)
      2. Lingual artery
      3. Facial artery
      Medial branch
      4. Ascending pharyngeal artery
      Posterior branches
      5. Occipital artery
      6. Posterior auricular artery
      Terminal branches
      7. Maxillary artery
      8. Superficial temporal artery

      The external carotid has eight branches, 3 from its anterior surface ; thyroid, lingual and facial. The pharyngeal artery is a medial branch. The posterior auricular and occipital are posterior branches.

    • This question is part of the following fields:

      • Anatomy
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  • Question 57 - Which of the following statements is true with regards to acetylcholine? ...

    Incorrect

    • Which of the following statements is true with regards to acetylcholine?

      Your Answer:

      Correct Answer: Excess cholinesterase inhibitor medication causes cholinergic crisis

      Explanation:

      Myasthenic and cholinergic crises are two crises which are similar in their clinical presentation.

      Myasthenic crisis can be caused by:
      -lack of acetylcholine,
      -poor compliance with medication,
      -infection

      Cholinergic crisis can be caused by excess cholinesterase inhibitor medication (mimicking organophosphate poisoning) causing excess acetylcholine.

      Differentiation between the 2 crises is made by giving incremental doses of the short acting cholinesterase inhibitor, Edrophonium.
      This increase acetylcholine levels and will make a myasthenic crisis better and a cholinergic crisis worse.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 58 - Radical prostatectomy is being performed on a 60-year-old man for carcinoma of the...

    Incorrect

    • Radical prostatectomy is being performed on a 60-year-old man for carcinoma of the prostate gland.

      What is the direct blood supply of the prostate?

      Your Answer:

      Correct Answer: Inferior vesical artery

      Explanation:

      The prostate gland is primarily supplied by the inferior vesical artery, which branches off from the anterior division of the internal iliac artery. The inferior vesical artery supplies the base of the bladder, the distal ureters, and the prostate. The branches to the prostate communicate with the corresponding vessels of the opposite side.

      The inferior vesical artery branches into two main arteries:
      1. Urethral artery – supplies the transition zone and is the main arterial supply for the adenomas in BPH
      2. Capsular artery – supplies the glandular tissue

      The venous drainage of the prostate is from the prostatic venous plexus, which drains into the paravertebral veins.

    • This question is part of the following fields:

      • Anatomy
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  • Question 59 - The following are pairs of neurotransmitters with their corresponding synthesising enzymes.

    Which pair...

    Incorrect

    • The following are pairs of neurotransmitters with their corresponding synthesising enzymes.

      Which pair is correct?

      Your Answer:

      Correct Answer: Glutamic acid decarboxylase and gamma-aminobutyric acid (GABA)

      Explanation:

      Glutamic acid decarboxylase is responsible for the catalyses of glutamate to gamma-aminobutyric acid (GABA)

      Catechol-o-methyl transferase catalyses the degradation and inactivation of dopamine into 3-methoxytyramine, epinephrine into metanephrine, and norepinephrine into normetanephrine and vanylmethylmandelic acid (VMA).

      Monoamine oxidase catalyses the oxidation of norepinephrine to vanylmethylmandelic acid (VMA) and serotonin to 5-hydeoxyindole acetic acid (5-HIAA).

      Cholinesterase functions to catalyse the split of acetylcholine into choline and acetic acid.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 60 - The leading cause of perioperative anaphylaxis per hundred thousand administrations is? ...

    Incorrect

    • The leading cause of perioperative anaphylaxis per hundred thousand administrations is?

      Your Answer:

      Correct Answer: Teicoplanin

      Explanation:

      The leading cause of perioperative anaphylaxis in the UK currently are antibiotics. They account for 46% of cases with identified causative agents. Co-amoxiclav and teicoplanin between them account for 89% of antibiotic-induced perioperative anaphylaxis

      Neuromuscular blocking agents (NMBAs) are the second leading cause and account for 33% of case.

      Chlorhexidine (0.78/100,000 administrations)
      Co-amoxiclav (8.7/100,000 administrations)Suxamethonium (11.1/100,000 administrations)
      Patent blue dye (14.6/100,000 administrations)
      Teicoplanin (16.4/100,000 administrations)

      Anaphylaxis to chlorhexidine periop poses a significant risk in the healthcare setting because of its widespread use with some being fatal.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 61 - The immediate physiological response to massive perioperative blood loss is: ...

    Incorrect

    • The immediate physiological response to massive perioperative blood loss is:

      Your Answer:

      Correct Answer: Stimulation of baroreceptors in carotid sinus and aortic arch

      Explanation:

      With regards to compensatory response to blood loss, the following sequence of events take place:

      1. Decrease in venous return, right atrial pressure and cardiac output
      2. Baroreceptor reflexes (carotid sinus and aortic arch) are immediately activated
      3. There is decreased afferent input to the cardiovascular centre in medulla. This inhibits parasympathetic reflexes and increases sympathetic response
      4. This results in an increased cardiac output and increased SVR by direct sympathetic stimulation. There is increased circulating catecholamines and local tissue mediators (adenosine, potassium, NO2)
      5. Fluid moves into the intravascular space as a result of decreased capillary hydrostatic pressure absorbing interstitial fluid.

      A slower response is mounted by the hypothalamus-pituitary-adrenal axis.
      6. Reduced renal blood flow is sensed by the intra renal baroreceptors and this stimulates release of renin by the juxta-glomerular apparatus.
      7. There is cleavage of circulating Angiotensinogen to Angiotensin I, which is converted to Angiotensin II in the lungs (by Angiotensin Converting Enzyme ACE)

      Angiotensin II is a powerful vasoconstrictor that sets off other endocrine pathways.
      8. The adrenal cortex releases Aldosterone
      9. There is antidiuretic hormone release from posterior pituitary (also in response to hypovolaemia being sensed by atrial stretch receptors)
      10. This leads to sodium and water retention in the distal convoluted renal tubule to conserve fluid
      Fluid conservation is also aided by an increased amount of cortisol which is secreted in response to the increase in circulating catecholamines and sympathetic stimulation.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 62 - Which one is true with respect to the first rib? ...

    Incorrect

    • Which one is true with respect to the first rib?

      Your Answer:

      Correct Answer: Scalenus anterior is inserted onto the scalene tubercle

      Explanation:

      Specific knowledge of the anatomical relationship is required to address this examination question.

      The first rib is small and thick and contains a single facet that articulates at the costovertebral joint. It consist of a head, neck and shaft but a discrete angle is deficit. Along the side the shaft is indented with a groove for the subclavian artery and the lower brachial plexus trunk. Front to the scalene tubercle is a space for the subclavian vein.

      The first rib has the scalenus front muscle joined to the scalene tubercle, isolating the subclavian vein (anteriorly) from the subclavian artery (posteriorly). This anatomical relationship is of major significance with respect to subclavian vein cannulation.

      The 1st rib has the following relationships:

      superior: lower trunk of the brachial plexus, subclavian vessels, clavicle.

      inferior: intercostal vessels and nerves

      posterior and inferior: pleura

      anterior: sympathetic trunk (over neck)

      superior intercostal artery, ventral T1 nerve root

    • This question is part of the following fields:

      • Anatomy
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  • Question 63 - All of the following are part of the endocrine response to uncontrolled bleeding...

    Incorrect

    • All of the following are part of the endocrine response to uncontrolled bleeding except:

      Your Answer:

      Correct Answer: Increased secretion of insulin

      Explanation:

      With regards to compensatory response to blood loss, the following sequence of events take place:

      1. Decrease in venous return, right atrial pressure and cardiac output
      2. Baroreceptor reflexes (carotid sinus and aortic arch) are immediately activated
      3. There is decreased afferent input to the cardiovascular centre in medulla. This inhibits parasympathetic reflexes and increases sympathetic response
      4. This results in an increased cardiac output and increased SVR by direct sympathetic stimulation. There is increased circulating catecholamines and local tissue mediators (adenosine, potassium, NO2)
      5. Fluid moves into the intravascular space as a result of decreased capillary hydrostatic pressure absorbing interstitial fluid.

      A slower response is mounted by the hypothalamus-pituitary-adrenal axis.
      6. Reduced renal blood flow is sensed by the intra renal baroreceptors and this stimulates release of renin by the juxta-glomerular apparatus.
      7. There is cleavage of circulating Angiotensinogen to Angiotensin I, which is converted to Angiotensin II in the lungs (by Angiotensin Converting Enzyme ACE)

      Angiotensin II is a powerful vasoconstrictor that sets off other endocrine pathways.
      8. The adrenal cortex releases Aldosterone
      9. There is antidiuretic hormone release from posterior pituitary (also in response to hypovolaemia being sensed by atrial stretch receptors)
      10. This leads to sodium and water retention in the distal convoluted renal tubule to conserve fluid
      Fluid conservation is also aided by an increased amount of cortisol which is secreted in response to the increase in circulating catecholamines and sympathetic stimulation.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 64 - The external urethral sphincter arises from which nerve root? ...

    Incorrect

    • The external urethral sphincter arises from which nerve root?

      Your Answer:

      Correct Answer: S2, S3, S4

      Explanation:

      The external urethral sphincter functions to provide voluntary control of urine flow from the bladder to the urethra.

      It receives its innervation from the branches of the pudendal nerve which originate from S2, S3 and S4.

    • This question is part of the following fields:

      • Anatomy
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  • Question 65 - A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a...

    Incorrect

    • A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a 57-year-old woman. Her vision is causing her problems.

      A macroadenoma compressing the optic chiasm is visible on MRI.

      What is the most likely visual field defect to be discovered during an examination?

      Your Answer:

      Correct Answer: Bitemporal hemianopia

      Explanation:

      The pituitary gland plays a crucial role in the neuro-endocrine axis. It is located at the base of the skull in the sella turcica of the sphenoid bone. It is connected superiorly to the hypothalamus, third ventricle, and visual pathways, and laterally to the cavernous sinuses, internal carotid arteries, and cranial nerves III, IV, V, and VI.

      Pituitary tumours make up about 10-15% of all intracranial tumours. The majority of adenomas are benign. Over-secretion of pituitary hormones (most commonly prolactin, growth hormone, or ACTH), under-secretion of hormones, or localised or generalised pressure effects can all cause symptoms.

      Compression of the optic chiasm can result in visual field defects, the most common of which is bitemporal hemianopia. This is caused by compression of the nasal retinal fibres, which carry visual impulses from temporal vision across the optic chiasm to the contralateral sides before continuing to the optic tracts.

      The interruption of the visual pathways distal to the optic chiasm causes a homonymous visual field defect. The loss of the right or left halves of each eye’s visual field is referred to as homonymous hemianopia. It’s usually caused by a middle or posterior cerebral artery territory stroke that affects the occipital lobe’s optic radiation or visual cortex.

      Binasal hemianopia is a condition in which vision is lost in the inner half of both eyes (nasal or medial). It’s caused by compression of the temporal visual pathways, which don’t cross at the optic chiasm and instead continue to the ipsilateral optic tracts. Binasal hemianopia is a rare complication caused by the internal carotid artery impinging on the temporal (lateral) visual fibres.

      A monocular visual loss (that is, loss of vision in only one eye) can be caused by a variety of factors, but if caused by nerve damage, the damage would be proximal to the optic chiasm on the ipsilateral side.

      A central scotoma is another name for central visual field loss. Every normal mammalian eye has a scotoma, also known as a blind spot, in its field of vision. The optic disc is a region of the retina that lacks photoreceptor cells and is where the retinal ganglion cell axons that make up the optic nerve exit the retina. When both eyes are open, visual signals that are absent in one eye’s blind spot are provided for the other eye by the opposite visual cortex, even if the other eye is closed.

      Scotomata can be caused by a variety of factors, including demyelinating disease such as multiple sclerosis, damage to nerve fibre layer in the retina, methyl alcohol, ethambutol, quinine, nutritional deficiencies, and vascular blockages either in the retina or in the optic nerve.

      Bilateral scotoma can occur when a pituitary tumour compresses the optic chiasm, causing a bitemporal paracentral scotoma, which then spreads out to the periphery, causing bitemporal hemianopsia. A central scotoma in a pregnant woman could be a sign of severe pre-eclampsia.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 66 - In a diagnosis of a compensated respiratory acidosis, which of the following arterial...

    Incorrect

    • In a diagnosis of a compensated respiratory acidosis, which of the following arterial blood gas results is likely to be seen?

      Your Answer:

      Correct Answer:

      Explanation:

      During normal tissue metabolism, there is production of CO2 (acid) which is then expired by the lungs. If metabolism switches from aerobic to anaerobic due to a lack of oxygen, the tissues are unable to completely oxidise sugars to CO2. As a consequence, the sugars can only be partially oxidised to lactic acid. Since lactic acid cannot be expired by the lungs, it remains in the circulation leading to metabolic acidosis.

      Also, normal tissue metabolism leads to the production of some amount of acid from the breakdown of proteins. These acids are excreted from the body by kidney filtration. Renal failure will therefore results in acidosis after several days.

      An increased acidosis stimulates the brain’s respiratory centres to increase the respiratory rate. This lowers the CO2 in the blood, leading to a decrease in its acidity. Renal excretion removes the excess acid, resulting in a normal pH, and a reduced PaCO2 and HCO3.

      pH PaCO2 (kPa) HCO3
      Compensated respiratory acidosis 7.34 7.2 29
      Acute respiratory acidosis 7.25 7.3 22
      Compensated metabolic acidosis 7.34 3.6 14
      Metabolic acidosis 7.21 5.3 15
      Metabolic alkalosis 7.51 5.1 30

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 67 - A 20-year-old boy is undergoing surgery for indirect inguinal hernia repair. The deep...

    Incorrect

    • A 20-year-old boy is undergoing surgery for indirect inguinal hernia repair. The deep inguinal ring is exposed and held with a retractor at its medial aspect during the procedure.

      What structure is most likely to lie under the retractor on the medial side?

      Your Answer:

      Correct Answer: Inferior epigastric artery

      Explanation:

      The deep inguinal ring is the entrance of the inguinal canal. It is an opening in the transversalis fascia around 1 cm above the inguinal ligament. Therefore, the superolateral wall is made by the transervalis fascia.

      The inferior epigastric vessels run medially to the deep inguinal ring forming its inferomedial border.

      The inguinal canal extends obliquely from the deep inguinal ring to the superficial inguinal ring.
      An indirect inguinal hernia arises through the deep inguinal ring lateral to the inferior epigastric vessels.

    • This question is part of the following fields:

      • Anatomy
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  • Question 68 - The ED95 of muscle relaxants is the dose required to reduce twitch height...

    Incorrect

    • The ED95 of muscle relaxants is the dose required to reduce twitch height by 95% in half of the target population. The dose of non-depolarizing muscle relaxants used for intubation is 2-3 times the ED95.

      For procedures that need a short duration of muscle relaxation and abrupt recovery, the short-acting drug Mivacurium is given at less than 2 times the ED95. What is the explanation for Mivacurium being an exception to this rule?

      Your Answer:

      Correct Answer: Dose related histamine release occurs which frequently leads to tachycardia and hypotension

      Explanation:

      Mivacurium, when administered at doses greater than 0.2 mg/kg,increases the risk for hypotension, tachycardia, and erythema. This is due to the ability of mivacurium to release histamine with increasing dose. Contrary to this fact, anaphylaxis is rare for mivacurium because of the short duration of histamine release.

      The effective dose 50 (ED50) of mivacurium is between 0.08-0.15 mg/kg. It is administered slowly to prevent and decrease the risk of developing adverse effects.

      Mivacurium has a high potency thus a longer duration of action, however this is not the answer that we are looking for.

      Although drug metabolism takes longer for mivacurium than succinylcholine, it has no effect on the dose required for intubation.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 69 - Which one of the following factor affects the minimal alveolar concentration (MAC)? ...

    Incorrect

    • Which one of the following factor affects the minimal alveolar concentration (MAC)?

      Your Answer:

      Correct Answer: Hypoxaemia

      Explanation:

      The minimal alveolar concentration (MAC) is the concentration of an inhalation anaesthetic agent in the lung alveoli required to stop a response to the surgical stimulus in 50% of the patient.

      Following factors don’t affect the MAC of the inhaled anaesthetic agents:

      Gender, acidosis, alkalosis, hypothyroidism, hyperthyroidism, body weight, serum potassium level, and the duration of the anaesthesia.

      MAC increase in children, elevated temperature, high metabolic rate, sympathetic increase and chronic alcoholism.

      MAC decrease in low temperature, low oxygen level, old age, hypotension (<40 mmHg), depressant drugs e.g. opioids and low level of catecholamines; alpha methyl dopa. Carbon dioxide O2 at the pressure > 120mmHg is being used in anesthetic-Hinkman as an additive effect to decrease MAC, however, increase concentration of CO2 activates the sympathetic system resulting the MAC increases.

    • This question is part of the following fields:

      • Physiology
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  • Question 70 - The biochemical assessment of malnutrition can be measured by the amount of plasma...

    Incorrect

    • The biochemical assessment of malnutrition can be measured by the amount of plasma proteins.

      In acute starvation, which of these plasma proteins is the most sensitive indicator?

      Your Answer:

      Correct Answer: Retinol binding globulin

      Explanation:

      The half life of Retinol binding protein (RBP) is 10-12 hours and therefore reflects more acute changes in protein metabolism than any of these proteins. Therefore it is not commonly used as a parameter for nutritional assessment.

      The half life of Transthyretin (thyroxine binding pre-albumin) is only one to two days and so levels are less sensitive and this protein is not an albumin precursor. 15 mg/dL represents early malnutrition and a need for nutritional support.

      Albumin levels have been frequently as a marker of nutrition but this is not a very sensitive marker. It’s half life more than 30 days and significant change takes some time to be noticed. Also, synthesis of albumin is decreased with the onset of the stress response after burns. Unrelated to nutritional status, the synthesis of acute phase proteins increases and that of albumin decreases.

      A more accurate indicator of protein stores is transferrin. It’s response to acute changes in protein status is much faster. The half life of serum transferrin is shorter (8-10 days) and there are smaller body stores than albumin. A low serum transferrin level is below 200 mg/dL and below 100 mg/dL is considered severe. Serum transferrin levels can also affect serum transferrin level.

      Fibronectin is used a nutritional marker but levels decrease after seven days of starvation. It is a glycoprotein which plays a role in enhancing the phagocytosis of foreign particles.

    • This question is part of the following fields:

      • Physiology
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  • Question 71 - The SI unit of energy is the joule. Energy can be kinetic, potential,...

    Incorrect

    • The SI unit of energy is the joule. Energy can be kinetic, potential, electrical or chemical energy.

      Which of these correlates with the most energy?

      Your Answer:

      Correct Answer: Energy released when 1 kg fat is metabolised to CO2 and water (the energy content of fat is 37 kJ/g)

      Explanation:

      The derived unit of energy, work or amount of heat is joule (J). It is defined as the amount of energy expended if a force of one newton (N) is applied through a distance of one metre (N·m)

      J = 1 kg·m/s2·m = 1 kg·m2/s2 or 1 kg·m2·s-2

      Kinetic energy (KE) = ½ MV2

      An object with a mass of 1500 kg moving at 30 m/s correlates to 675 kJ:

      KE = ½ (1500) × (30)2 = 750 × 900 = 675 kJ

      Total energy released when 1 kg fat is metabolised to CO2 and water is 37 MJ. 1 g fat produces 37 kJ/g, therefore 1 kg fat produces 37,000 × 1000 = 37 MJ.

      Raising the temperature of 1 kg water from 0°C to 100°C correlates to 420 kJ. The amount of energy needed to change the temperature of 1 kg of the substance by 1°C is the specific heat capacity. We have 1 kg water therefore:

      4,200 J × 100 = 420,000 J = 420 kJ

      In order to calculate the energy involved in raising a 100 kg mass to a height of 1 km against gravity, we need to calculate the potential energy (PE) of the mass:

      PE = mass × height attained × acceleration due to gravity
      PE = 100 kg × 1000 m × 10 m/s2 = 1 MJ

      The heat generated when a direct current of 10 amps flows through a heating element for 10 seconds when the potential difference across the element is 1000 volts can be calculated by applying Joule’s law of heating:

      Work done (WD) = V (potential difference) × I (current) × t (time)
      WD = 10 × 10 × 1000 = 100 kJ

    • This question is part of the following fields:

      • Physiology
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  • Question 72 - All of the following statements about intravenous induction agents are false except: ...

    Incorrect

    • All of the following statements about intravenous induction agents are false except:

      Your Answer:

      Correct Answer:

      Explanation:

      Thiopental is a new British Approved Name for thiopentone and is thio-barbiturate.
      Methohexitone is an oxy- barbiturate. Both thiopental and methohexitone are intravenous induction agents.

      Ketamine cannot cause loss of consciousness in less than 30 seconds. At least 30 seconds is needed to cause loss of consciousness following intravenous administration.

      Etomidate is an imidazole but it is not used in the Intensive Care unit for sedation because it has an antidepressant effect on the steroid axis.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 73 - A caudal anaesthetic block is planned for a 3-year-old girl presenting for inguinal...

    Incorrect

    • A caudal anaesthetic block is planned for a 3-year-old girl presenting for inguinal hernia repair. Choose the best answer that explains why the caudal epidural space is accessed via the sacral hiatus.

      Your Answer:

      Correct Answer: The failure of fusion of the laminae of S4 and S5 provides a suitable point of entry

      Explanation:

      The sacral hiatus is shaped by incomplete midline fusion of the posterior elements of the distal portion of S4 and S5. This inverted U shaped space is covered by the posterior aspect of the sacrococcygeal membrane and is an important landmark in caudal anaesthetic block. Distal most portion of the dural sac and the sacral hiatus usually terminate between levels S1 and S3. The dural sac ends at the level of S2 in adults and S3 in children.

      An equilateral triangle is formed between the apex of the sacral hiatus and the posterior superior iliac spines. This triangle is used to determine the location of the sacral hiatus during caudal anaesthetic block.

    • This question is part of the following fields:

      • Anatomy
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  • Question 74 - Which of the following drugs is safe to be used in porphyria? ...

    Incorrect

    • Which of the following drugs is safe to be used in porphyria?

      Your Answer:

      Correct Answer:

      Explanation:

      Porphyria is a group of disorders in which there is excess production and excess excretion of porphyrins and their precursors. They are usually genetic and are caused due to defects in the haem metabolic pathway. However, other factors like infection, pregnancy, mensuration, starvation may precipitate the attack.

      Sulphonamides, barbiturates (methohexitone and thiopental), and phenytoin are considered to be precipitants so are not safe to use
      Chloral hydrate is thought to be safe to use.
      Etomidate lacks proper studies and may be used with caution but it is generally advised not to use this drug especially if other alternatives are available.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 75 - A 32-year-old male is admitted to the critical care unit. He has suffered...

    Incorrect

    • A 32-year-old male is admitted to the critical care unit. He has suffered a heroin overdose and requires intubation and ventilatory support.

      What would be his predicted total static compliance (lung and chest wall) measurements.

      Your Answer:

      Correct Answer: 100 ml/cmH2O

      Explanation:

      Static lung compliance refers to the change in volume within the lung per given change in unit pressure. It is usually measured when air flow is absent, such as during pauses in inhalation and exhalation.

      It is a combination of:

      Chest wall compliance: normal value is 200 mL/cmH2O
      Lung tissue compliance: normal value is 200 mL/ cmH2O

      It is represented mathematically as:

      1/Crs = 1/Cl + 1/Ccw

      Where,

      Crs = total compliance of the respiratory system
      Cl = compliance of the lung
      Ccw = compliance of the chest wall

      Therefore in this case:

      1/Crs = 1/200 + 1/200

      1/Crs = 0.005 + 0.005 = 0.01

      1/Ct = 0.01

      Rearranging equation gives:

      Ct = 1/0.01 = 100 mL/cmH2O.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 76 - Regarding the anatomical relations of the scalenus muscles, which of these is true?...

    Incorrect

    • Regarding the anatomical relations of the scalenus muscles, which of these is true?

      Your Answer:

      Correct Answer: The trunks of the brachial plexus emerge from the lateral border of scalenus anterior

      Explanation:

      The ascending cervical artery lies media the phrenic nerve on scalenus anterior and can easily be mistaken for the phrenic nerve at operation.

      The phrenic nerve passes across scalenus anterior and medius inferiorly.

      The subclavian artery is separated from the vein by the scalenus anterior.

      The brachiocephalic vein is formed at the medial border of scalenus anterior by the subclavian vein and the internal jugular vein.

      Emerging from the lateral border of scalenus anterior are the trunks of the brachial plexus .

    • This question is part of the following fields:

      • Anatomy
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  • Question 77 - All of the following statements about calcium channel antagonists are incorrect except: ...

    Incorrect

    • All of the following statements about calcium channel antagonists are incorrect except:

      Your Answer:

      Correct Answer: May cause potentiation of muscle relaxants

      Explanation:

      Calcium channel blocker (CCB) blocks L-type of voltage-gated calcium channels present in blood vessels and the heart. By inhibiting the calcium channels, these agents decrease the frequency of opening of calcium channels activity of the heart, decrease heart rate, AV conduction, and contractility.

      Three groups of CCBs include
      1) Phenylalkylamines: Verapamil, Norverapamil
      2) Benzothiazepines : Diltiazem
      3) Dihydropyridine : Nifedipine, Nicardipine, Nimodipine, Nislodipine, Nitrendipine, Isradipine, Lacidipine, Felodipine and Amlodipine.

      Even though verapamil as good absorption from GIT, its oral bioavailability is low due to high first-pass metabolism.

      Nimodipine is a Cerebro-selective CCB, used to reverse the compensatory vasoconstriction after sub-arachnoid haemorrhage and is more lipid soluble analogue of nifedipine

      Calcium channel antagonist can potentiate the effect of non-depolarising muscle relaxants.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 78 - What is the most sensitive method of detecting an intra-operative air embolism? ...

    Incorrect

    • What is the most sensitive method of detecting an intra-operative air embolism?

      Your Answer:

      Correct Answer: Transoesophageal echocardiogram

      Explanation:

      An intra-operative air embolism occurs when air becomes trapped in the blood vessels during surgery.

      A transoesophageal echocardiography (OE) uses invasive echocardiography to monitor the integrity and performance of the heart. It is the gold standard as it provides real-time imaging of the heart to enable early diagnosis and treatment.

      Precordial doppler ultrasonography can also be used to detect into-operative air emboli. It is non-invasive and more practical, but is less sensitive.

      A change in end-tidal CO2 could be indicative of and increase in physiological dead-space, but could also be indicative of any processes that reduces the excretion or increases the production of CO2, making it non-specific.

      A transoesophageal stethoscope can be used to listen for the classic mill-wheel murmur produced by a large air embolus.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 79 - The following statements are about capnography. Which of them is true? ...

    Incorrect

    • The following statements are about capnography. Which of them is true?

      Your Answer:

      Correct Answer: Collision broadening is due to presence of other polyatomic molecules

      Explanation:

      Capnography is the non-invasive measurement and pictorial display of inhaled and exhaled carbon dioxide (CO2) partial pressure.

      It is depicted graphically as the concentration of CO2 over time.

      It is used in disease diagnosis, determining disease severity, assessing response to treatment and is the best method to for indicating when an endotracheal tube is placed in the trachea after intubation.

      The wavelength of IR light usually absorbed by nitrous oxide is between 4.4-4.6?m (very close to that of CO2). Its absorption of wavelengths at 3.9 ?m is much weaker. It causes a measurable deficit of 0.1% for every 10% of nitrous oxide. The maximal wavelength of infrared (IR) light absorbed by carbon monoxide is 4.7 ?m. The volatile agents have strong absorption bands at 3.3 ?m and throughout the ranges 8-12 ?m.

      IR light is not absorbed by oxygen (O2), but O2 and CO2 molecules are constantly colliding which interrupts the absorption of IR light by CO2. This increases the band of absorption, that is the Collison or pressure broadening). An oxygen percentage of 95 will result in a 0.5 percentage fall in CO2 measure.

      IR light is also absorbed by water vapour which will result in an overlap of the absorption band, collision broadening and a dilution of partial pressure. This is why water trap and water permeable tubing is recommended for use as it reduces measurement inaccuracies.

      The use of multi-gas analysers of modern gases also help reduce the effects of collision broadening.

      Beer’s law is also applied in this system as an increase in the concentrations of CO2 causes a decrease in the amount of IR able to pass through the gas. This IR light is what generated the signal that is analysed for display.

      The capnograph can indicate oesophageal intubation, but cannot determine if it is endotracheal or endobronchial. For this, auscultation is used.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 80 - Which of the following descriptions best describes enflurane and isoflurane? ...

    Incorrect

    • Which of the following descriptions best describes enflurane and isoflurane?

      Your Answer:

      Correct Answer: Have the same molecular formula but different structural formulae

      Explanation:

      Structural isomers have a similar molecular formula, but they have a different structural formula as their atoms are arranged in a different manner. Such small changes lead to the differential pharmacological activity. Enflurane and isoflurane are two prime examples of structural isomers.

      Stereoisomers are those substances that have a similar molecular and structural formula, but the arrangement spatially of atoms are different and have optical activity.

      Enantiomers are a pair of stereoisomers, which are non-superimposable mirror images of each other. They also have chiral centres of molecular symmetry. Ketamine is considered as an example of racemic mixture (contain 50% R and 50% S enantiomers)

      Geometric isomers contain a carbon-carbon double bond (i.e. C=C) or a rigid carbon-carbon single bond in a heterocyclic ring. Cis-atracurium is one example.

      Dynamic isomers or Tautomers are a pait of unstable structural isomers, which are present in equilibrium. One isomer can easily change after the change in pH. Midazolam and thiopentone are their examples.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 81 - The child-Pugh scoring system can be used, if risk classifying a patient with...

    Incorrect

    • The child-Pugh scoring system can be used, if risk classifying a patient with chronic liver disorder earlier to anaesthesia.

      Which one is the best combination of clinical signs and examinations used within the Child-Pugh scoring system?

      Your Answer:

      Correct Answer: Ascites, grade of encephalopathy, albumin, bilirubin and INR

      Explanation:

      In the Child-Pugh classification system, the following 5 components are determined or calculated in order:

      Ascites

      Grade of encephalopathy

      Serum bilirubin (?mol/L)

      Serum Albumin (g/L)

      Prothrombin time or INR

      Raised liver enzymes are not the component of the classification system.

    • This question is part of the following fields:

      • Basic Physics
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  • Question 82 - An arterial pressure transducer is supposedly in direct correlation to change, thus it...

    Incorrect

    • An arterial pressure transducer is supposedly in direct correlation to change, thus it is dependent on zero gradient drift and zero offset. Which of the following values will best compensate for the gradient drift?

      Your Answer:

      Correct Answer: 0 mmHg and 200 mmHg

      Explanation:

      Since an arterial pressure transducer, and every other measuring apparatus, is prone to errors due to offset and gradient drifts, regular calibration is required to maintain accuracy of the instrument. The two-point calibration pressure values of 0 mmHg and 200 mmHg are within the physiologic range and can best compensate for the gradient drift.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 83 - A patient on admission is given an infusion of 1000 mL of 10%...

    Incorrect

    • A patient on admission is given an infusion of 1000 mL of 10% glucose and 500 mL of 20% lipid over a 24 hour period.

      Which of these best approximates to the energy input over this time period?

      Your Answer:

      Correct Answer: 1300 kcal

      Explanation:

      1% solution contains 1 g of substance per 100 mL.

      A solution of 10% glucose is 10 g/100mL. Therefore 1000 mL of this glucose solution will contain 100 g.

      1 g of glucose yields about 4 kcal of energy. One litre of 10% glucose will therefore release approximately 4x100g = 400 kcal of energy.

      A solution of 20% fat is 20 g/100mL. Therefore 1000 mL of this fat solution will have 200 g and 500 mL will contain 100 g.

      1 g of fat yields approximately 9 kcal. 500 mL of 20% fat therefore has the potential to yield 900 kcal of energy.

      The total energy input over this 24 hour period is approximately 400kcal + 900kcal = 1300 kcal.

    • This question is part of the following fields:

      • Physiology
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  • Question 84 - You are given an intravenous induction agent. The following are its characteristics:

    A racemic mixture...

    Incorrect

    • You are given an intravenous induction agent. The following are its characteristics:

      A racemic mixture of cyclohexanone rings with one chiral centre
      Local anaesthetic properties.

      Which of the following statements about its primary mechanism of action is most accurate?

      Your Answer:

      Correct Answer: Non-competitive antagonist affecting Ca2+ channels

      Explanation:

      Ketamine is the substance in question. Its structure and pharmacodynamic effects make it a one-of-a-kind intravenous induction agent. The molecule is made up of two cyclohexanone rings (2-(O-chlorophenyl)-2-methylamino cyclohexanone and 2-(O-chlorophenyl)-2-methylamino cyclohexanone). Ketamine has local anaesthetic properties and acts primarily on the brain and spinal cord.

      It affects Ca2+ channels as a non-competitive antagonist for the N-D-methyl-aspartate (NMDA) receptor. It also acts as a local anaesthetic by interfering with neuronal Na+ channels.

      Ketamine causes profound dissociative anaesthesia (profound amnesia and analgesia) as well as sedation.

      Phenoxybenzamine, an alpha-1 adrenoreceptor antagonist, is an example of an irreversible competitive antagonist. It forms a covalent bond with the calcium influx receptor.

      Benzodiazepines are GABAA receptor agonists that affect chloride influx.

      Flumazenil is an inverse agonist that affects GABAA receptor chloride influx.

      Ketamine is a cyclohexanone derivative that acts as a non-competitive Ca2+ channel antagonist.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 85 - A post-operative patient was brought to the recovery room after completion of dilation...

    Incorrect

    • A post-operative patient was brought to the recovery room after completion of dilation and curettage. Her medical history revealed that she was maintained on levodopa for Parkinson's disease. The nurses administered ondansetron 4 mg and dexamethasone 8 mg prior to transfer from the operating room to the recovery room. However, an additional antiemetic agent is warranted.

      Which of the following agents should be prescribed to the patient?

      Your Answer:

      Correct Answer: Cyclizine 50 mg IV

      Explanation:

      The Beers criteria, a US set of criteria for good prescribing in the older patient, preclude the use of metoclopramide in Parkinson’s disease. The Adverse Reactions Register of the UK Committee on Safety of Medicines (CSM) for the years 1967 to 1982 contained 479 reports of extrapyramidal reactions in which metoclopramide was the suspected drug; 455 were for dystonic-dyskinetic reactions, 20 for parkinsonism and four for tardive dyskinesia. Effects can occur within days of initiation of treatment and may take months to wear off.

      Other antiemetics are available, such as cyclizine (Valoid), domperidone and ondansetron, which would be more appropriate to use in those with Parkinson’s disease.

      Cyclizine is a piperazine derivative with histamine H1 receptor antagonist and anticholinergic activity. It is used for the treatment of nausea, vomiting, (particularly opioid-induced vomiting), vertigo, motion sickness, and labyrinthine disorders.

      Prochlorperazine is an antipsychotic known to cause tardive dyskinesia, tremor and parkinsonian symptoms and is therefore likely to exacerbate Parkinson’s disease. Prochlorperazine is not favoured for older patients because of the increased risk of stroke and transient ischaemic attack (TIA).

      Droperidol and phenothiazine are also potent antagonists on D2 receptors and must also be avoided.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 86 - Which muscle separates the subclavian artery and the subclavian vein? ...

    Incorrect

    • Which muscle separates the subclavian artery and the subclavian vein?

      Your Answer:

      Correct Answer: Scalenus anterior

      Explanation:

      The subclavian artery and vein have a similar path throughout their course, with the subclavian vein running anterior to the subclavian artery. The artery and vein are separated by the insertion of the scalenus anterior muscle.

      There are three scalene muscles, found on each side of the neck:
      1. Anterior scalene
      2. Middle scalene
      3. Posterior scalene

      The scalenus anterior muscle is the anterior most of the three scalene muscles. It originates from the transverse processes of vertebrae C3-C6 and is inserted in the first rib.

    • This question is part of the following fields:

      • Anatomy
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  • Question 87 - Which of the following statements is the most correct about ketamine? ...

    Incorrect

    • Which of the following statements is the most correct about ketamine?

      Your Answer:

      Correct Answer: The S (+) isomer is more potent that the R (-) isomer

      Explanation:

      Ketamine, a phencyclidine derivative, is an antagonist at the NMDA receptor. It causes depression of the CNS that is dose dependent and induces a dissociative anaesthetic state with profound analgesia and amnesia.

      Ketamine has a chiral centre usually presented as a racemic mixture with two optical isomers, S (+) and R (-) forms. These isomers are in equal proportions. The S (+) isomer is about three times more potent than the R (-) form. The S (+) form is less likely to cause emergence delirium and hallucinations.

      Ketamine is extensively metabolised by hepatic microsomal cytochrome P450 enzymes producing norketamine as its main metabolite. Norketamine has a one third to one fifth as potency as its parent compound.
      It increases the CMRO2, cerebral blood flow and potentially increase intracranial pressure.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 88 - Considering research studies, which of the following is considered as a limitation of...

    Incorrect

    • Considering research studies, which of the following is considered as a limitation of the Delphi method?

      Your Answer:

      Correct Answer: Potential low response rates

      Explanation:

      The Delphi technique was developed in the 1950s and is a widely used and accepted method for achieving convergence of opinion concerning real-world knowledge solicited from experts within certain topic areas. Choosing the appropriate subjects is the most important step in the entire process because it directly relates to the quality of the results generated, despite this, there is no exact criterion currently listed in the literature concerning the selection of Delphi participants.

      Therefore, due to the potential scarcity of qualified participants and the relatively small number of subjects used in a Delphi study, the ability to achieve and maintain an ideal response rate can either ensure or jeopardize the validity of a Delphi study.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 89 - A 58-year-old man, visits his general practitioner complaining of a lump in his...

    Incorrect

    • A 58-year-old man, visits his general practitioner complaining of a lump in his groin. He explains he is otherwise well and reports no other symptoms. The lump is examined and is found to be soft, and can be reduced without causing the patient pain. The GP diagnoses an inguinal hernia. To determine the nature of the hernia, the GP reduced the lump and applies pressure on the deep inguinal ring.

      The deep inguinal ring has what anatomical landmark?

      Your Answer:

      Correct Answer: Superior to the midpoint of the inguinal ligament

      Explanation:

      The deep inguinal ring lies approximately 1.5-2cm above the midpoint of the inguinal ligament, the halfway point between the anterior superior iliac spine and the pubic tubercle, next to the epigastric vessels.

      It is an important point in determining the nature of an inguinal hernia (direct or indirect). The patient is asked to cough after the hernia is reduced, with pressure applied to the deep inguinal ring. The hernia reappearing indicates it is direct, moving through the posterior wall of the inguinal canal.

      Inferior and lateral to the pubic tubercle is the normal anatomical position of the neck of a femoral hernia.

      Superior and medial to the pubic tubercle is the site of the superficial inguinal ring, and the normal anatomical position of the neck of an inguinal hernia.

      The mid-inguinal point is located halways between the pubic symphysis and the anterior superior iliac spine. It is the surface marking for taking the femoral pulse.

    • This question is part of the following fields:

      • Anatomy
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  • Question 90 - Volunteers are being recruited for a new clinical trial of a novel drug...

    Incorrect

    • Volunteers are being recruited for a new clinical trial of a novel drug treatment for Ulcerative colitis. The proposed study will enrol about 2000 people with ulcerative colitis. Testing will be performed to assess any reduction in disease severity with the new drug as compared to the current treatment available in the industry.

      Which phase of clinical trial will this be?

      Your Answer:

      Correct Answer: Phase 3

      Explanation:

      This clinical trial consists over 1000 patients being evaluated for the response to a new treatment against a currently licensed treatment for ulcerative colitis. Therefore, it is comparing its efficacy to an established therapeutic or control in a larger population of volunteers. These are the characteristics of a phase III clinical trial.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 91 - The cardiac tissue type that that has the highest conduction velocity is: ...

    Incorrect

    • The cardiac tissue type that that has the highest conduction velocity is:

      Your Answer:

      Correct Answer: Purkinje fibres

      Explanation:

      Potassium maintains the resting potential of cardiac myocytes, with depolarization triggered by a rapid influx of sodium ions, and repolarization due to efflux of potassium. A slow influx of calcium is responsible for the longer duration of a cardiac action potential compared with skeletal muscle.

      The cardiac action potential has several phases which have different mechanisms of action as seen below:

      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms.

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 92 - Which of the following best explains the association between smoking and lower oxygen...

    Incorrect

    • Which of the following best explains the association between smoking and lower oxygen delivery to tissues?

      Your Answer:

      Correct Answer: Left shift of the oxygen dissociation curve

      Explanation:

      Smoking is a major risk factor associated with perioperative respiratory and cardiovascular complications. Evidence also suggests that cigarette smoking causes imbalance in the prostaglandins and promotes vasoconstriction and excessive platelet aggregation. Two of the constituents of cigarette smoke, nicotine and carbon monoxide, have adverse cardiovascular effects. Carbon monoxide increases the incidence of arrhythmias and has a negative ionotropic effect both in animals and humans.

      Smoking causes an increase in carboxyhaemoglobin levels, resulting in a leftward shift in which appears to represent a risk factor for some of these cardiovascular complications.

      There are two mechanisms responsible for the leftward shift of oxyhaemoglobin dissociation curve when carbon monoxide is present in the blood. Carbon monoxide has a direct effect on oxyhaemoglobin, causing a leftward shift of the oxygen dissociation curve, and carbon monoxide also reduces the formation of 2,3-DPG by inhibiting glycolysis in the erythrocyte. Nicotine, on the other hand, has a stimulatory effect on the autonomic nervous system. The effects of nicotine on the cardiovascular system last less than 30 min.

    • This question is part of the following fields:

      • Physiology
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  • Question 93 - Which of the following factors significantly increases the risk of hepatotoxicity and fulminant...

    Incorrect

    • Which of the following factors significantly increases the risk of hepatotoxicity and fulminant hepatic failure in halothane administration?

      Your Answer:

      Correct Answer: Multiple exposure

      Explanation:

      Hepatotoxicity due to halothane administration is relatively common and is a major factor in its rapidly declining use. Type 1 hepatotoxicity has an incidence of 20% to 30%. A comprehensive report in 1969 demonstrated an incidence of type 2 hepatotoxicity (hepatitis) of 1 case per 6000 to 20000 cases, with fatal cases occurring approximately once in 35000 patients following a single exposure to the anaesthetic. This incidence of fatal cases increases to approximately 1 in 1000 patients following multiple exposures. Following this study was a large-scale review in the United Kingdom, which showed similar results. To put this into perspective, there is only a single case of hepatotoxicity confirmed after the administration of desflurane and 2 cases per 1 million after enflurane. By the 1970s, halothane was the most common cause of drug-induced liver failure.

      Halothane-induced hepatotoxicity has a female to male ratio of two to one. Younger patients are less likely to be affected; 80% of the cases are typically in patients 40 years or older. Other risk factors include obesity and underlying liver dysfunction. Medications such as phenobarbital, alcohol, and isoniazid may play a role in affecting CYP2E1 metabolism, increasing one’s risk.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 94 - The Control of Substances Hazardous to Health (COSHH) regulations recommend air supply rates...

    Incorrect

    • The Control of Substances Hazardous to Health (COSHH) regulations recommend air supply rates to specific environments. Which of the following statements is true?

      Your Answer:

      Correct Answer: Preparation rooms receive a volume of 0.1 m3 of air per second

      Explanation:

      Control of Substances Hazardous to Health (COSHH) was established by government under the Health and Safety at Work act in 1989. Their employers work on identification and management of those substances that are dangerous to health. The implications for anaesthetists include gas scavenging, equipment contamination and environmental safety. Adequate ventilation is required in areas where anaesthetic gases are present. The minimum air supply that is legally required in each specific area is: Operating theatres: 0.65 m3/second. Anaesthetic rooms: 0.15 m3/s. Preparation rooms: 0.1 m3/s. Recovery rooms need 15 air changes per hour

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 95 - You decide to conduct research on the normal rates of gastric emptying in...

    Incorrect

    • You decide to conduct research on the normal rates of gastric emptying in healthy people. The strategy is to give a drug orally and measure plasma concentrations at predetermined intervals.

      Which of the following drugs would you choose to use?

      Your Answer:

      Correct Answer: Paracetamol

      Explanation:

      Because of the low pH in the stomach, paracetamol absorption is minimal (pKa value is 9.5). Paracetamol is absorbed quickly and completely in the alkaline environment of the small intestine. Oral bioavailability is approaching 100%. As a result, measuring paracetamol levels in plasma after an oral paracetamol dose has been used as a surrogate marker of gastric emptying. This method has been used to investigate the effects of drugs on gastric emptying. At clinically used doses, paracetamol is ideal because it has very few side effects.

      Scintigraphic imaging is the gold standard for determining gastric emptying.

      Although aspirin (acetyl salicylic acid) is absorbed primarily in the small intestine, some may also be absorbed in the stomach. The oral bioavailability ranges from 70 to 100 percent, making it less reliable than paracetamol.

      Propranolol is a lipophilic drug that is rapidly absorbed after administration. However, it is highly metabolised by the liver in the first pass, and only about 25% of propranolol reaches the systemic circulation. It’s not the best indicator of gastric emptying.

      Oral bioavailability of gentamicin and vancomycin is low. Only antibiotic-induced pseudomembranous colitis is treated with oral vancomycin.

      Erythromycin is a pro-kinetic agent that acts as a motilin receptor agonist.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 96 - A randomized controlled trail has been conducted to compare two drugs used for...

    Incorrect

    • A randomized controlled trail has been conducted to compare two drugs used for the early management of acute severe asthma in the emergency department. After being allocated to the randomized groups, many patients have been excluded due to deleterious effect to the drugs.

      How the data would be analysed?

      Your Answer:

      Correct Answer: Include the patients who drop out in the final data set

      Explanation:

      Randomized controlled trails will be analysed by the intention-to-treat (ITT) approach. It provides unbiased comparisons among the treatment groups. ITT analyses are done to avoid the effects of dropout, which may break the random assignment to the treatment groups in a study.

      ITT analysis is a comparison of the treatment groups that includes all patients as originally allocated after randomization.

      In order to include such participants in an analysis, outcome data could be imputed which involves making assumptions about the outcomes in the lost participants.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 97 - About low molecular weight (LMW) heparin, Which of these is true? ...

    Incorrect

    • About low molecular weight (LMW) heparin, Which of these is true?

      Your Answer:

      Correct Answer: Is excreted in the urine

      Explanation:

      Low molecular weight heparin (LMWH) creates a complex by binding to antithrombin. This complex binds with and inactivates factor Xa.

      There is less risk of bleeding with LMWH because it binds less to platelets, endothelium and von Willebrand factor.

      LMW binds Xa more readily. The shorter chains are less likely to bind both antithrombin and thrombin.

      There is need for monitoring in renal impairment because LMHW is excreted in the urine (and partly by hepatic metabolism)

      LMWH have been shown to be as efficacious as unfractionated heparin. It is also safer and have improved inpatient stay and reduced hospital cost.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 98 - Which of the following is true regarding the mechanism of action of daptomycin?...

    Incorrect

    • Which of the following is true regarding the mechanism of action of daptomycin?

      Your Answer:

      Correct Answer: Interferes with the outer membrane of gram positive bacteria resulting in cell death

      Explanation:

      Daptomycin alters the curvature of the membrane, which creates holes that leak ions. This causes rapid depolarization, resulting in loss of membrane potential. Thus it interferes with the outer membrane of gram-positive bacteria resulting in cell death.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 99 - Which of the following is a correct match for reflex and their root...

    Incorrect

    • Which of the following is a correct match for reflex and their root value?

      Your Answer:

      Correct Answer: Knee reflex: L3/L4

      Explanation:

      Reflexes are a routine part of clinical examination. Hyperreflexia (abnormally brisk reflexes) is the sign of upper motor neuron damage whereas diminished or absent jerks are most commonly due to lower motor neuron lesions. Reflexes may be Monosynaptic (deep tendon reflexes) or polysynaptic (superficial reflexes)

      Here are deep tendon reflexes with their nerve root
      Biceps = C5, C6
      Supinator (Brachioradialis) = C5, C6
      Triceps = C6, C7
      Knee reflex = L3,L4
      Ankle reflex = S1

      Polysynaptic superficial reflexes with their nerve root are listed below
      Planter response = S1-2
      Abdominal reflexes = T8-12
      Cremasteric reflex = L1-2

    • This question is part of the following fields:

      • Anatomy
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  • Question 100 - A 20-year-old woman, presented to her GP after swallowing a tiny, sharp bone...

    Incorrect

    • A 20-year-old woman, presented to her GP after swallowing a tiny, sharp bone and is referred to an ENT. She explains that the bone feels stuck in her throat. A laryngoscopy is performed and it shows the bone is lodged in the piriform recess.

      Name the nerve at highest risk of damage by the bone?

      Your Answer:

      Correct Answer: Internal laryngeal nerve

      Explanation:

      The internal laryngeal nerve lies inferior to the piriform recess mucous membrane, placing it at high risk of irritation or damage by sharp foreign objects which become lodged in the recess.

      Any attempt to retrieve lodged foreign objects must be done careful as there is also a high risk of damage during this process.

      The other mentioned nerves are not at risk of being affected.

    • This question is part of the following fields:

      • Anatomy
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  • Question 101 - A 16-year-old female presented to the hospital with a chief complaint of headache,...

    Incorrect

    • A 16-year-old female presented to the hospital with a chief complaint of headache, photophobia, fever, and confusion. She is treated empirically with antibiotics. Which of the following represents the correct mechanism of action of the most commonly used first-line antibiotic class?

      Your Answer:

      Correct Answer: Inhibition of cell wall synthesis

      Explanation:

      Based on the presenting symptoms, this is the case of bacterial meningitis. The treatment of choice for bacterial meningitis is a cephalosporin. Cephalosporin acts by inhibiting bacterial cell wall synthesis.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 102 - Which of the following is correct about the action of bile salts? ...

    Incorrect

    • Which of the following is correct about the action of bile salts?

      Your Answer:

      Correct Answer: Emulsification of lipids

      Explanation:

      The emulsification and absorption of fats requires Bile salts.

      Absorption of fats is associated with the activation of lipases in the intestine.

      Bile salts are involved in fat soluble vitamin absorption and are reabsorbed in the terminal ileum (B12 is NOT fat soluble).

      Although Vitamin B12 is also absorbed in the terminal ileum, it is a water soluble vitamin (as are B1, nicotinic acid, folic acid and vitamin C) .

      The gastric parietal cells secretes Intrinsic factor that is essential for the absorption of B12.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 103 - A 68-year old man, is admitted in hospital. He is scheduled to undergo...

    Incorrect

    • A 68-year old man, is admitted in hospital. He is scheduled to undergo a femoro-popliteal bypass graft, for which he has been administered a spinal-epidural anaesthetic. Intrathecal heavy bupivacaine (0.5%) was injected at L3-4 with good effect. On insertion of the epidural catheter, he remained asymptomatic.

      During surgery, 5000 I.U. of IV heparin was given. The surgery is successful and required no epidural top-ups.

      Six hours later, he complains of a severe back pain with weakness in his lower limbs.

      What is the most important first step?

      Your Answer:

      Correct Answer: A full neurological examination to establish the nature of the problem

      Explanation:

      The most likely diagnosis is a spinal epidural haematoma, a neurological emergency. A full examination must be carried out to determine the nature of the neurological problem before conducting any investigations or imaging.

      The effects of spinal anaesthesia should have worn off by this time point, and the severe back pain is a red flag.

      The patient will also require an urgent neurological team referral as a spinal epidural haematoma requires immediate evacuation for spinal decompression. Analgesics may be prescribed for pain management.

      Heparin would have been fully metabolised and so a reversal is unnecessary.

      A spinal epidural haematoma is a pooling of blood in the epidural space, which can cause compression of the spinal cord. Its presenting symptoms are:

      Usually begins with severe backpain and percussion tenderness
      Cauda equina syndrome
      Paralysis of the lower extremities.
      If infected, a fever occurs in 66% of cases
      Lower limb weakness developing after stopping an epidural infusion or weakness of the lower limbs which does not resolve within four hours of cessation of infusion of epidural local anaesthetic
      Meningism.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 104 - The following is true about the extracellular fluid (ECF) in a normal adult...

    Incorrect

    • The following is true about the extracellular fluid (ECF) in a normal adult woman weighing 60 kg.

      Your Answer:

      Correct Answer: Has a total volume of about 12 litres

      Explanation:

      Total body water (TBW) is about 50% to 70% in adults depending on how much fat is present. ECF is relatively contracted in an obese person.

      The simple rule is 60-40-20. (60% of weight = total body water, 40% of body weight is ICF and 20% is ECF)

      For this woman, the total body water is 36 litres (0.6 × 60). ECF is 12 litres (1/3 of TBW) and 24 litres (2/3 of TBW) is intracellular fluid .

      Sodium concentration is approximately 135-145 mmol/L in the ECF.

      The ECF is made up of both intravascular and extravascular fluid and plasma proteins is found in both.

    • This question is part of the following fields:

      • Physiology
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  • Question 105 - A new volatile anaesthetic agent has been approved for use in clinical testing.

    It's...

    Incorrect

    • A new volatile anaesthetic agent has been approved for use in clinical testing.

      It's a non-irritating, sweet-smelling substance. It has a molecular weight of 170, a 0.6 blood:gas partition coefficient, and a 180 oil:gas partition coefficient. An oxidative pathway converts 2% of the substance to trifluoroacetic acid.

      Which of the following statements best describes this agent's pharmacological profile?

      Your Answer:

      Correct Answer: It has a lower molecular weight than isoflurane

      Explanation:

      Because enflurane is much less soluble in blood and has a blood: gas partition coefficient of 1.8, both wash-in and wash-out should be faster.

      Sevoflurane’s sweet-smelling, non-irritant nature, combined with a low blood: gas partition coefficient, would result in similar offset and onset characteristics.

      Isoflurane and enflurane have a molecular weight of 184.

      The oil: gas partition coefficient on a volatile agent is a measure of lipid solubility, potency, and thus MAC. Halothane has an oil: gas partition coefficient of 220 and a MAC of 0.74. One would expect the MAC to be higher with an oil gas partition coefficient of 180 (less lipid soluble).

      The conversion of halothane (20%) to trifluoroacetic acid via oxidative metabolism has been linked to the development of hepatitis.

      P450 2E1 converts sevoflurane to hexafluoroisopropanol, which results in the release of inorganic fluoride ions. It’s the only fluorinated volatile anaesthetic that doesn’t break down into trifluoracetic acid.

      Desflurane is likely to cause airway irritation, which can lead to coughing, apnoea, and laryngospasm, despite its low blood:gas partition coefficient (0.42).

    • This question is part of the following fields:

      • Pharmacology
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  • Question 106 - A 4-year-old boy with status epilepticus was brought to ER and has already...

    Incorrect

    • A 4-year-old boy with status epilepticus was brought to ER and has already received two doses of intravenous lorazepam but is still continuing to have seizures.

      Which of the following drug would be best for his treatment?

      Your Answer:

      Correct Answer: Phenytoin 20 mg/kg IV

      Explanation:

      When the convulsion lasts for five or more than five minutes, or if there are recurrent episodes of convulsions in a 5 minute period without returning to the baseline, it is termed as Status Epilepticus.
      The first priority in the patient with seizures is maintaining the airway, breathing, and circulation.

      Guideline for the management of Status Epilepticus in children by Advanced Life Support Group is as follow:

      Step 1 (Five minutes after the start of seizures):

      If intravascular access is available start treatment with lorazepam 0.1 mg/kg IV
      If no intravascular access then give buccal midazolam 0.5 mg/kg or rectal diazepam 0.5 mg/kg.

      Step 2 (Ten minutes after the start of seizure):

      If the convulsions continue then a second dose of benzodiazepine should be given. Senior should be called on-site and phenytoin should be prepared.
      No more than two doses or benzodiazepines should be given (including any doses given before arrival at the hospital)
      If still no IV access then obtain intraosseous access (IO).

      Step 3 (Ten minutes after step 2)

      Senior help along with anaesthetic/ICU help should be sought
      Phenytoin 20 mg/kg IV over 20 minutes
      If the seizure stops before the full dose of phenytoin is given then the infusion should be completed as this provides up to 24 hours of anticonvulsant effect
      In children already receiving phenytoin as treatment for epilepsy then an alternative is phenobarbitone 20 mg/kg IV over five minutes
      Once the phenytoin is started, senior staff may wish to give rectal paraldehyde 0.4 mg/kg although this is no longer included in the routine algorithm recommended by APLS.

      Step 4 (20 minutes after step 3)

      If 20 minutes after starting phenytoin the child remains in status epilepticus then rapid sequence induction of anaesthesia with thiopentone and a short acting paralysing agent is needed and the child transferred to paediatric intensive care.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 107 - At sea level, Sevoflurane is administered via a plenum vaporiser. 100 mL of...

    Incorrect

    • At sea level, Sevoflurane is administered via a plenum vaporiser. 100 mL of the fresh gas flow is bypassed into the vaporising chamber. Temperature within the vaporising chamber is maintained at 20°C.

      The following fresh gas flows approximates best for the delivery of 1% sevoflurane.

      Your Answer:

      Correct Answer: 2.7 L/minute

      Explanation:

      The equation for calculating vaporiser output is:

      Vaporiser output (VO) mL = Carrier gas flow (mL/minute) × SVP of agent (kPa)
      Ambient pressure (kPa) − SVP of agent (kPa)

      The saturated vapour pressure of sevoflurane at 1 atm (100 kPa) and 20°C is 21 kPa.

      VO = (100 mL × 21 kPa)/(100 kPa − 21kPa) for sevoflurane,
      VO = 26.6 mL

      26.6 mL of 100% sevoflurane and 100 mL bypass carrier gas is being added to the fresh gas flow per minute.

      2660 mL of 1% sevoflurane and 100 mL bypass carrier gas is approximately 2.7 L/minute.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 108 - Out of the following, which therapy for acute severe asthma or life-threatening asthma...

    Incorrect

    • Out of the following, which therapy for acute severe asthma or life-threatening asthma has been NOT been approved in recent guidelines?

      Your Answer:

      Correct Answer: Heliox

      Explanation:

      Recommendations from the British Thoracic Society for acute severe asthma or life-threatening asthma are:

      1. Give controlled supplementary oxygen to all hypoxemic patients with acute severe asthma titrated to maintain a SpO₂ level of 94 98%.
      2. Use high-dose inhaled ?₂ agonists as first-line agents in patients with acute asthma and administer them as early as possible. Reserve
      intravenous ?₂ agonists for those patients in whom inhaled therapy cannot be used reliably.
      3. Give steroids in adequate doses to all patients with an acute asthma attack.
      4. Add nebulized ipratropium bromide (0.5 mg 4–6 hourly) to ?₂ agonist treatment for acute severe or life-threatening asthma or those with a poor initial response to ?₂ agonist therapy.
      5. Consider aminophylline for children with severe or life-threatening asthma unresponsive to maximal doses of bronchodilators and steroids.

      A review (including 12 case reports, three RCTs, and five other observational studies) of ketamine use in adults and children in status asthmaticus reported that ketamine is a potential bronchodilator. Still, prospective trials are needed before conclusions about effectiveness can be drawn.

      Heliox has no place in the current guidelines issued by the British Thoracic Society.

    • This question is part of the following fields:

      • Anatomy
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  • Question 109 - A 50-year-old man, presents to the hospital with bilateral inguinal hernias.
    After examination...

    Incorrect

    • A 50-year-old man, presents to the hospital with bilateral inguinal hernias.
      After examination and investigation, the surgical team decides to perform a laparoscopic hernia repair using the extraperitoneal approach. After making an infraumbilical incision, the surgeons perform the repair by placing a prosthetic mesh over the affected area, after shifting the inferior aspect of the rectus abdominis muscle anteriorly.

      Name the structure that would like posterior to the mesh?

      Your Answer:

      Correct Answer: Peritoneum

      Explanation:

      This question is asking which structure would lie posterior to the rectus abdominis muscle and not the prosthetic mesh, as only peritoneum lies posterior to mesh during a total extraperitoneal (TEP) hernia repair.

      The region of the repair lies below the arcuate line, meaning that the transversalis fascia and peritoneum lie posterior to the rectus abdominis.

      The bucks fascia lies within the penis.

    • This question is part of the following fields:

      • Anatomy
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  • Question 110 - The statement that best describes the classification of theatre equipment in terms of...

    Incorrect

    • The statement that best describes the classification of theatre equipment in terms of electrical safety is:

      Your Answer:

      Correct Answer: A floating circuit is equipment applied to patient that is isolated from all its other parts

      Explanation:

      There are different classes of electrical equipment that can be classified in the table below:

      Class 1 – provides basic protection only. It must be connected to earth and insulated from the mains supply

      Class II – provides double insulation for all equipment. It does not require an earth.

      Class III – uses safety extra low voltage (SELV) which does not exceed 24 V AC. There is no risk of gross electrocution but risk of microshock exists.

      Type B – All of above with low leakage currents (0.5mA for Class IB, 0.1 mA for Class IIB)

      Type BF – Same as with other equipment but has ‘floating circuit’ which means that the equipment applied to patient is isolated from all its other parts.

      Type CF – Class I or II equipment with ‘floating circuits’ that is considered to be safe for direct connection with the heart. There are extremely low leakage currents (0.05mA for Class I CF and 0.01mA for Class II CF)

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 111 - During positive pressure ventilation using positive end-expiratory pressure (PEEP), there is usually an...

    Incorrect

    • During positive pressure ventilation using positive end-expiratory pressure (PEEP), there is usually an associated reduction in cardiac output

      Which of the following is responsible?

      Your Answer:

      Correct Answer: Reduced venous return to the heart

      Explanation:

      The option that is most responsible is the progressive decrease in venous return of blood to the right atrium. The heart rate does not usually change with PEEP so the fall in cardiac output is due to a reduction in left ventricular (LV) stroke volume (SV).

      Note that the interventricular septum does shift toward the left and there is an increased pulmonary vascular resistance (PVR) from overdistention of alveolar air sacs that contribute to the reduction in cardiac output. Any increase in PVR will be associated with reduced pulmonary vascular capacitance.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 112 - Suppose a diabetic patient is to undergo an elective surgery under general anaesthesia,...

    Incorrect

    • Suppose a diabetic patient is to undergo an elective surgery under general anaesthesia, which of the following will most effectively prevent a hyperglycaemic stress response during the surgical procedure?

      Your Answer:

      Correct Answer: Spinal block to T4

      Explanation:

      Every surgical procedure is associated with a stress response which comprises a number of endocrine, metabolic, and immunological changes triggered by neuronal activation of the hypothalamic-pituitary-adrenal axis. The overall metabolic effect of the stress response to surgery includes an increase in secretion of catabolic hormones, such as cortisol and catecholamine, and a decrease in secretion of anabolic hormones, such as insulin and testosterone. The increase in levels of catabolic hormones in plasma stimulates glucose production, and there is a relative lack of insulin together with impaired tissue insulin sensitivity and glucose utilization, which is called insulin resistance. Consequently, blood glucose concentrations will increase, even in the absence of pre-existing diabetes.

      A study compared the effects of spinal and general anaesthesia on changes in blood glucose concentrations during surgery in nondiabetic patients. Although mean blood glucose concentrations showed a significant proportional increase during surgery in both groups, this effect was much more significant with general anaesthesia than with spinal anaesthesia. These results indicate that spinal anaesthesia is more effective than general anaesthesia in attenuating the hyperglycaemic response to surgery.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 113 - A 40-year old gentleman has palpitations and has gone to the emergency department....

    Incorrect

    • A 40-year old gentleman has palpitations and has gone to the emergency department. He is found to have monomorphic ventricular tachycardia. The resting potential of ventricular monocytes is maintained by which electrolyte?

      Your Answer:

      Correct Answer: Potassium

      Explanation:

      Potassium maintains the resting potential of cardiac myocytes, with depolarization triggered by a rapid influx of sodium ions, and repolarization due to efflux of potassium. A slow influx of calcium is responsible for the longer duration of a cardiac action potential compared with skeletal muscle.

      The cardiac action potential has several phases which have different mechanisms of action as seen below:

      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms.

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 114 - Which of the following options will best reflect the adequacy of preoxygenation prior...

    Incorrect

    • Which of the following options will best reflect the adequacy of preoxygenation prior to rapid sequence induction of a patient?

      Your Answer:

      Correct Answer: Expired fraction of oxygen (FEO2)

      Explanation:

      The most important determinant of preoxygenation adequacy is expired fraction of oxygen. Denitrogenating of the functional residual capacity is the purpose of preoxygenation. This is dependent on three vital factors: (1) respiratory rate; (2) inspired volume, and; (3) inspired oxygen concentration (FiO2).

      Arterial oxygen saturation does not efficiently determine adequacy of preoxygenation because of its inability to measure tissue reserves. Arterial partial pressure of oxygen is also unsuitable for determining preoxygenation adequacy. Moreover, the absence of central cyanosis is a very crude sign of low tissue oxygenation.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 115 - Concerning platelets one of the following is true ...

    Incorrect

    • Concerning platelets one of the following is true

      Your Answer:

      Correct Answer: Are formed in the bone marrow from megakaryocytes

      Explanation:

      Platelets are fragments of megakaryocytes and they are encapsulated by membrane.

      They have no nucleus but are metabolically active and are able to express membrane receptors and release stored substances when triggered. adenosine diphosphate and serotonin are 2 of its content.

      Because they have no nucleus, they are not able to produce new proteins. This is why aspirin and other drugs affect function for their entire lifespan after exposure. Its lifespan is approximately 9-10 days in normal individuals.

      Platelets does NOT PRODUCE prostacyclin but are able to produce nitric oxide, prostaglandins and thromboxane.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 116 - A patient is evaluated for persistent dysphonia six months after undergoing a subtotal...

    Incorrect

    • A patient is evaluated for persistent dysphonia six months after undergoing a subtotal thyroidectomy.

      Which of the following is the most likely reason for the change in this patient's voice?

      Your Answer:

      Correct Answer: Damage to recurrent laryngeal nerve

      Explanation:

      After thyroid surgery, about 10-15% of patients experience a temporary subjective voice change of varying degrees. A frog in the throat or cracking of the voice, or a weak voice, are common descriptions. These modifications are only temporary, lasting a few days to a few weeks.

      Swelling of the muscles in the area of the dissection, as well as inflammation and oedema of the larynx due to the dissection, or minor trauma from the tracheal tube, are all suspected causes.

      On both sides of the thyroid gland, the superior laryngeal nerve (EBSLN) runs along the upper part. The muscles that fine-tune the vocal cords are innervated by these nerves. The quality of their voice is usually normal if they are injured, but making high-pitched sounds may be difficult. Injury to the EBSLN occurs in about 2% of the population.

      Injuries to the recurrent laryngeal nerve (RLN) have been reported to occur in 1 percent to 14 percent of people. Except for the cricothyroid muscle, the RLN supplies all of the laryngeal intrinsic muscles.

      This complication is usually unilateral and temporary, but it can also be bilateral and permanent, and it can be intentional or unintentional. The most common complication following thyroid surgery is a permanent lesion of damaged RLN, which manifests as an irreversible phonation dysfunction.

      The crico-arytenoid joint dislocation is a relatively uncommon complication of tracheal intubation and blunt neck trauma. The probability is less than one in a thousand.

      Vocal cord polyps affect 0.8 percent of people.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 117 - A radiologist is conducting an arch aortogram. She begins by entering the brachiocephalic...

    Incorrect

    • A radiologist is conducting an arch aortogram. She begins by entering the brachiocephalic artery using the angiography catheter. As she continues to advance the catheter, what vessels will the catheter enter?

      Your Answer:

      Correct Answer: Right subclavian artery

      Explanation:

      As there is no brachiocephalic artery on the left side, the artery is entered by the catheter on the right side.

      The brachiocephalic artery branches into the common carotid and the right subclavian artery, so the catheter is most likely to enter the right subclavian artery, or also possibly the right carotid.

    • This question is part of the following fields:

      • Anatomy
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  • Question 118 - Regarding the classification of breathing systems, which of the following is true? ...

    Incorrect

    • Regarding the classification of breathing systems, which of the following is true?

      Your Answer:

      Correct Answer: The Conway classification describes a functional classification based on whether a CO2 absorber is required

      Explanation:

      Breathing system is an assembly of components which connects patient’s airway to anaesthesia machine through which controlled composition of gas mixture is dispensed. It delivers gas to the patient, removes expired gas and controls the temperature and humidity of the inspired mixture. It allows spontaneous, controlled, or assisted respiration. It may also provide ports for gas sampling, airway pressure, flow and volume monitoring.

      Breathing systems have been classified by Conway and Mapleson.
      Conway suggested a functional classification:
      – Circuits requiring a CO2 absorber
      – Circuits not requiring a CO2 absorber

      William Mapleson designated varying arrangements of breathing system components (masks, breathing tubes, fresh gas flow inlets, adjustable pressure-limiting valves, and reservoir bags) as Mapleson A-E circuits.
      Mapleson A: Arranged as FGF inlet, reservoir bag, APL valve, mask.
      In this circuit, because the reservoir bag is between the FGF inlet valve and the APL valve, expired gas from the patient may re-enter the system and fill the reservoir bag during controlled ventilation. This is the most efficient system for spontaneous breathing as the FGF must only be equal to a patient’s minute ventilation to prevent rebreathing.

      Mapleson B: Arranged as reservoir bag, FGF inlet, APL valve, mask.
      In this circuit, the FGF inlet is closer to the APL valve, which helps prevent the rebreathing concern in the Mapleson A circuit as above during controlled ventilation.

      Mapleson C: Arranged as reservoir bag, FGF inlet, APL valve, mask.
      In this circuit, the arrangement is the same as the Mapleson B circuit. However, this circuit is shorter as it does not contain elongated corrugated tubing. This circuit also has the FGF inlet close to the APL valve to aid in preventing rebreathing.

      Mapleson D: Arranged as reservoir bag, APL valve, FGF inlet, and mask.
      In this circuit, the arrangement interchanges the FGF inlet and APL valve of the Mapleson A circuit. This system prevents rebreathing by directing FGF towards the APL valve rather than towards the patient during exhalation.

      Mapleson E: Arranged as corrugated tubing, FGF inlet, and mask.
      In this circuit, there is no reservoir bag and no APL valve. Given the inability to alter the pressure of the circuit, this is ideal for spontaneously ventilating neonates or paediatric patients where low-pressure ventilation is desired. The system prevents rebreathing, similar to the Mapleson D circuit.

      Jackson Rees later modified the Mapleson E by adding an open ended bag, which has since become known as the Mapleson F.
      Mapleson F: Arranged as APL valve directly connected to reservoir bag, corrugated tubing, FGF inlet, and mask.
      The system prevents rebreathing similarly to Mapleson D by directing FGF towards the APL valve.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 119 - Which of following statements is true regarding the comparison of fentanyl and alfentanil?...

    Incorrect

    • Which of following statements is true regarding the comparison of fentanyl and alfentanil?

      Your Answer:

      Correct Answer: Fentanyl is more potent than alfentanil

      Explanation:

      Fentanyl is a pethidine congener, 80–100 times more potent than morphine, both in analgesia and respiratory depression. Fentanyl is ten times more potent than alfentanil.

      Alfentanil has a more rapid onset than fentanyl even if fentanyl is more lipid-soluble because both are basic compounds and alfentanil has lower pKa, so a greater proportion of alfentanil is unionized and is more available to cross membranes.

      Elimination of alfentanil is higher than fentanyl due to its lower volume of distribution.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 120 - Dinamap is an automated blood pressure monitoring device. Which of these statements best...

    Incorrect

    • Dinamap is an automated blood pressure monitoring device. Which of these statements best fit its properties?

      Your Answer:

      Correct Answer: The cuff should be positioned at the same level as the heart

      Explanation:

      Dinamap continuously measures the systolic, diastolic and mean arterial pressure along with pulse rate, thereby providing a continuous monitoring of the blood pressure using the osscillitonometric principle of measurement.

      The device loses accuracy towards the extremes of BP and is more accurate with systolic compared with diastolic pressure. In arrhythmias such as AF, the devices are also inaccurate due to the major fluctuations associated with the individual pulse pressure variations.

      The manual BP device is still the gold standard for BP measurement and monitoring.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 121 - Concerning calcium metabolism and its control, which of these is correct? ...

    Incorrect

    • Concerning calcium metabolism and its control, which of these is correct?

      Your Answer:

      Correct Answer: Cholecalciferol is 25-hydroxylated in the liver

      Explanation:

      When there is a fall in ionised plasma calcium levels, the chief cells of the parathyroid glands are stimulated to secrete parathyroid hormone (PTH).

      50% of extracellular calcium occurs as non-ionised, protein- (albumin-)bound calcium.

      The degree of ionisation increases with low ph and decreases with high pH.

      There is increased renal calcium excretion with secretion of calcitonin.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 122 - A 5-year old male has ingested a peanut and has developed urticaria, vomiting...

    Incorrect

    • A 5-year old male has ingested a peanut and has developed urticaria, vomiting and hypotension. The pathogenesis of this condition is derived from predominant cells of which cell line?

      Your Answer:

      Correct Answer: Common myeloid progenitor

      Explanation:

      A is correct. Common myeloid progenitor cells are involved in the anaphylaxis reaction.
      B is incorrect. The common lymphoid lineage gives rise to T-cells, B-cell and NK cells.
      C is incorrect as megakaryocytes give rise to platelets.
      D is incorrect – Neural crest cells give rise to various cells throughout the body, including melanocytes, enterochromaffin cells and Schwann cells. However, they do not give rise to mast cells.
      E is incorrect. Reticulocytes give rise to erythrocytes.

      This is a classic case of anaphylaxis. In this situation, IgE previously raised against antigens (in this case peanut antigen) bind to mast cells, and this causes them to degranulate.
      There is release of vasoactive substances like histamine into the blood, and this is responsible for the symptoms seen. Therefore, the main type of cells involved in the pathogenesis of the disease is mast cells.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 123 - You are preparing to anaesthetize a 27-year-old woman for an acute diagnostic laparoscopy...

    Incorrect

    • You are preparing to anaesthetize a 27-year-old woman for an acute diagnostic laparoscopy to rule out appendicitis.

      She has no medical history and does not take any medications on a regular basis. You're going to do a quick sequence induction.

      Which method of preoxygenation is the most effective and efficient?

      Your Answer:

      Correct Answer: Mapleson A circuit with a fresh gas flow of 100 ml/kg

      Explanation:

      Professor Mapleson classified non-rebreathing circuits based on the position of the APL valve, which controls fresh gas flow.

      The Mapleson A (Magill) circuit is most effective in spontaneous breathing, requiring only 70-100 ml/kg (the patient’s minute volume) of fresh gas flow. The patient inhales fresh gas from the reservoir bag and tubing during inspiration. During expiration, the patient adds dead space gas (gas that hasn’t been exchanged) to the tubing and reservoir bag in addition to the fresh gas flow. At the patient’s end, alveolar gas is vented through the APL valve. During the expiratory pause, the fresh gas flow causes more gas to be released.

      The Mapleson A is inefficient during controlled ventilation. Venting occurs during inspiration rather than during the expiratory phase, as it does during spontaneous ventilation. As a result, unless a high fresh gas flow of >20 L/minute is used, alveolar gas is rebreathed.

      During spontaneous ventilation, the Mapleson D circuit is inefficient.

      The oxygen concentration in a Hudson mask is insufficient to allow for adequate pre-oxygenation.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 124 - With a cervical dilation of 9 cm, a 23-year-old term primigravida is in...

    Incorrect

    • With a cervical dilation of 9 cm, a 23-year-old term primigravida is in labour. She is otherwise in good health. She's been in labour for 14 hours and counting.

      Early foetal pulse decelerations can be seen on the cardiotocograph, and a recent foetal scalp blood sample revealed a pH of 7.25.

      Which of the following is true about this patient's care and management?

      Your Answer:

      Correct Answer: Monitor for downward trend in fetal scalp blood pH as caesarean section is not indicated at the present time

      Explanation:

      Once the decision to deliver a baby by caesarean section has been made, it should be carried out with a level of urgency commensurate with the risk to the baby and the mother’s safety.

      There are four types of caesarean section urgency:

      Category 1 – Endangering the life of the mother or the foetus
      Category 2 – Maternal or foetal compromise that is not immediately life threatening
      Category 3 – Early delivery is required, but there is no risk to the mother or the foetus.
      Category 4: Elective delivery at a time that is convenient for both the mother and the maternity staff.

      Caesarean sections for categories 1 and 2 should be performed as soon as possible after the decision is made, especially for category 1. For category 1 caesarean sections, a decision to deliver time of 30 minutes is currently used.

      In most cases, Category 2 caesarean sections should be performed within 75 minutes of making the decision.

      The condition of the woman and the unborn baby should be considered when making a decision for a quick delivery, as it may be harmful in some cases.

      There is no evidence of foetal compromise in the example above (early foetal pulse decelerations and a pH of less than 7.25). Early foetal pulse decelerations are most likely caused by the uterus compressing the foetal head. The foetus is not harmed by these. A spinal anaesthetic is preferred over a general anaesthetic whenever possible.

      If the foetal scalp blood pH is greater than 7.25, it’s a good idea to repeat the test later and look for any changes. When a foetus decelerates, the mother should be given oxygen, kept in a left lateral position, and kept hydrated to avoid the need for a caesarean section.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 125 - A 60-year old male has anaemia and is being investigated. The most common...

    Incorrect

    • A 60-year old male has anaemia and is being investigated. The most common combination of globin chains in a normal adult is:

      Your Answer:

      Correct Answer: α2β2

      Explanation:

      There are 4 different types of globin chains which surround 4 heme molecules in haemoglobin (Hb) – α (alpha), β (beta), γ (gamma), and δ (delta)
      α chains are essential.
      δ2β2 and β2γ2 are not found in a healthy adult.
      97% of the Hb in a healthy adult is made of α2β2 (2 α chains and 2 β chains).
      α2δ2 accounts for around 1.5-3% of the adult Hb.
      α2γ2 accounts for less than 1%.

      With respect to oxygen transport in cells, almost all oxygen is transported within erythrocytes. There is limited solubility and only 1% is carried as solution. Thus, the amount of oxygen transported depends upon haemoglobin concentration and its degree of saturation.

      Haemoglobin is a globular protein composed of 4 subunits. Haem is made up of a protoporphyrin ring surrounding an iron atom in its ferrous state. The iron can form two additional bonds – one is with oxygen and the other with a polypeptide chain. There are two alpha and two beta subunits to this polypeptide chain in an adult and together these form globin. Globin cannot bind oxygen but can bind to CO2 and hydrogen ions. The beta chains are able to bind to 2,3 diphosphoglycerate. The oxygenation of haemoglobin is a reversible reaction. The molecular shape of haemoglobin is such that binding of one oxygen molecule facilitates the binding of subsequent molecules.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 126 - According to the statements given which one is most correct concerning the spinal...

    Incorrect

    • According to the statements given which one is most correct concerning the spinal cord?

      Your Answer:

      Correct Answer: There are 31 pairs of spinal roots

      Explanation:

      The cylindrical structure(spine), starts from the foramen magnum in medulla oblongata at the skull’s base. Its length varies in gender with men having 45cm and women having up to 43 cm. The spine contains 31 pairs of spinal nerves, named according to the spinal region:
      – 8 cervical nerve pairs ( C1-C8)
      – 12 thoracic nerve pairs ( T1-T12)
      – 5 lumbar nerve pairs (L1-L5)
      – 5 sacral nerves (S1-S5) and
      – 1 coccygeal nerve pair.
      These spinal nerves are classified as the peripheral nervous system though they branch from the spinal cord and central nervous system. They interact directly with the spinal cord to modulate the motor and sensory information from the peripheral’s region. As the nerves emerges form the spinal cords they are known as rootlets. They join to form nerve roots, and depending on their position, we have anterior nerve roots and posterior.

      The spinal cord is supplied by two posterior and one anterior spinal arteries which anastomoses caudally, at the conus medullaris.

      The anterior spinal artery supplies the anterior two-thirds of the spinal cord and medulla. Disruption of the anterior spinal artery supply is characterised by ischaemia or infarction of motor tracts (corticospinal) and loss of pain and temperature sensation below the level of the lesion.

      The posterior spinal arteries supply the posterior columns (posterior third of the spinal cord). Infarction of the posterior columns results in the loss of proprioceptive, vibration and two-point discrimination.

      The spinal cord normally ends at the level of L1 or L2 in an adult and L3 in a newborn.

    • This question is part of the following fields:

      • Anatomy
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  • Question 127 - A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise....

    Incorrect

    • A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise. On urine culture and sensitivity testing, E.coli was detected with resistance to ampicillin.
      What is the mechanism of resistance to ampicillin?

      Your Answer:

      Correct Answer: Beta-lactamase production

      Explanation:

      Ampicillin belongs to the family of penicillin. Resistance to this group of drugs is due to ?-lactamase production which opens the ?-lactam ring and inactivates Penicillin G and some closely related congeners. The majority of Staphylococci and some strains of gonococci, B. subtilis, E. coli, and a few other bacteria produce penicillinase.

      Resistance to cephalosporins is due to changes in penicillin-binding proteins.

      Resistance to macrolides are due to post-transcriptional methylation of 23s bacterial ribosomal RNA

      Resistance to fluoroquinolones is due to mutations in DNA gyrase.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 128 - An experiment is designed to investigate that how three diets having different sugar...

    Incorrect

    • An experiment is designed to investigate that how three diets having different sugar content affect the body weight to a different level.

      Which one of the following test will determine a statistically significant difference among the diets?

      Your Answer:

      Correct Answer: ANOVA

      Explanation:

      Chi-square test is used to determine the statistically significant different between categorical variables. It also determines the difference between expected frequencies and the observed frequencies.

      Mann Whitney U test is used to determine the statistically significant different between two independent groups.

      Wilcoxon’s test is the test of dependency. it determines the statistically significant difference between two dependent groups.

      Student t-test is one of the most commonly used method to test the hypothesis. It determines the significant difference between the means of two different groups.

      ANOVA (analysis of variance) is similar to student’s t-test.

      ANOVA is a statistical method used to determines the statistically significant difference between the mean of more than two group. In this experiment as we are dealing with three different group, ANOVA is most suitable test to determine the difference between each groups.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 129 - Out of the following, which artery is NOT a branch of the hepatic...

    Incorrect

    • Out of the following, which artery is NOT a branch of the hepatic artery?

      Your Answer:

      Correct Answer: Pancreatic artery

      Explanation:

      The common hepatic artery arises from the celiac artery and has the following branches:
      1. hepatic artery proper that branches into –
      a. cystic artery to supply the gallbladder
      b. left and right hepatic arteries to supply the liver
      2. gastroduodenal artery that branches into
      a. right gastroepiploic artery
      b. superior pancreaticoduodenal artery
      3. right gastric artery

      The pancreatic artery is a branch of the splenic artery.

    • This question is part of the following fields:

      • Anatomy
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  • Question 130 - Which of the following statement is true regarding the mechanism of action of...

    Incorrect

    • Which of the following statement is true regarding the mechanism of action of doxycycline?

      Your Answer:

      Correct Answer: Inhibit 30S subunit of ribosomes

      Explanation:

      Doxycycline belongs to the family of tetracyclines and inhibits protein synthesis through reversible binding to bacterial 30s ribosomal subunits, which prevent binding of new incoming amino acids (aminoacyl-tRNA) and thus interfere with peptide growth.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 131 - Which vessel is the first to branch from the external carotid artery? ...

    Incorrect

    • Which vessel is the first to branch from the external carotid artery?

      Your Answer:

      Correct Answer: Superior thyroid artery

      Explanation:

      The superior thyroid artery is the first branch of the external carotid artery. The other branches of the external carotid artery are:
      1. Superior thyroid artery
      2. Ascending pharyngeal artery
      3. Lingual artery
      4. Facial artery
      5. Occipital artery
      6. Posterior auricular artery
      7. Maxillary artery
      8. Superficial temporal artery

      The inferior thyroid artery is derived from the thyrocervical trunk.

    • This question is part of the following fields:

      • Anatomy
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  • Question 132 - The cardiac muscle will primarily utilize which metabolic substrate to produce energy when...

    Incorrect

    • The cardiac muscle will primarily utilize which metabolic substrate to produce energy when at rest?

      Your Answer:

      Correct Answer: Fatty acids

      Explanation:

      Approximately 70% of the heart’s ATP requirement is met by cardiac mitochondria through beta-oxidation of fatty acids at rest. The remaining 30% is supplied by glucose.

      Amino acids and ketones, in the presence of ketoacidosis, may supply at most 10% of the ATP requirement. And, when in high levels, lactate may also contribute to the ATP requirement of the heart, particularly during moments of high muscular activity.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 133 - A 59-year-old smoker booked for an emergency laparotomy is in the anaesthetic room...

    Incorrect

    • A 59-year-old smoker booked for an emergency laparotomy is in the anaesthetic room prior to intubation. He is breathing room air and an arterial blood gas is obtained on insertion of an arterial cannula and sent for analysis.

      The following results are available:

      Haemoglobin 75 g/L
      PaO2 10.7 kPa
      PaCO2 5.2 kPa

      After intravenous induction, intubation is difficult and he rapidly begins to de-saturate.

      Which of the following is most effective in prolonging the oxygen de-saturation time?

      Your Answer:

      Correct Answer: Pre-oxygenation with 100% O2 for three minutes

      Explanation:

      Breathing 100% oxygen for three minutes will provide the best reservoir of oxygen during apnoea by oxygenating the functional residual capacity (FRC).

      Sitting at 45 degrees might increase the FRC and improve oxygen reserve but not compared with 100% oxygenation.

      The following table compares the oxygen reserves in the body following pre-oxygenation with room air and 100% oxygen:

      Compartment Factors Room air (mL) 100% O2 (mL)
      Lung FAO2, FRC 630 2850
      Plasma PaO2, DF, PV 7 45
      Red blood cells Hb, TGV, SaO2 788 805
      Myoglobin – 200 200
      Interstitial space – 25 160

      FAO2 = alveolar fraction of oxygen.
      FRC = Functional residual capacity.
      PaO2 = partial pressure of oxygen dissolved in arterial blood
      DF = dissolved form.
      PV = plasma volume.
      TG = total globular volume .
      Hb = haemoglobin concentration.
      SaO2 = arterial oxygen saturation

      Stopping smoking one month prior to surgery will not be more effective than pre-oxygenation with 100% oxygen though it may reduce postoperative pulmonary complications. Note that both long term and short term abstinence reduces pulse rate and blood pressure thus reducing oxygen consumption and also reduce carboxyhaemoglobin levels.

      Blood transfusion will not make a big difference in oxygen reserve, particularly if a blood transfusion is administered within 12-24-hours before surgery.

      Heliox (79% helium and 21% oxygen) despite its lower viscosity is unlikely to be more effective than 100% oxygen .

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 134 - Out of the following, which anatomical structure lies within the spiral groove of...

    Incorrect

    • Out of the following, which anatomical structure lies within the spiral groove of the humerus?

      Your Answer:

      Correct Answer: Radial nerve

      Explanation:

      The shaft of the humerus has two prominent features:
      1. Deltoid tuberosity – attachment for the deltoid muscle
      2. Radial or spiral groove – The radial nerve and profunda brachii artery lie in the groove

      Mid-shaft fractures of the humerus usually occur after a direct blow to the upper arm, which can occur after a fall or RTAs. The most important clinical significance of a mid-shaft humeral fracture is an injury to the radial nerve. The radial nerve originates from the brachial plexus and has roots of C5-T1. It crosses the spiral groove on the posterior side of the shaft of the humerus.
      On examination, the patient may have a wrist drop, loss or weakness of finger extension, and decreased or absent sensation to the posterior forearm, digits 1 to 3, and the radial half of the fourth digit.

      The following parts of the humerus are in direct contact with the indicated
      nerves:
      Surgical neck: axillary nerve.
      Radial groove: radial nerve.
      Distal end of humerus: median nerve.
      Medial epicondyle: ulnar nerve.

    • This question is part of the following fields:

      • Anatomy
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  • Question 135 - An orthopaedic surgery is scheduled for a 68-year-old man. He is normally in...

    Incorrect

    • An orthopaedic surgery is scheduled for a 68-year-old man. He is normally in good shape. His routine biochemistry results are checked and found to be within normal limits.

      Which of the following pairs has the greatest impact on his plasma osmolarity?

      Your Answer:

      Correct Answer: Sodium and potassium cations

      Explanation:

      The number of osmoles (Osm) of solute per litre (L) of solution (Osmol/L) is the unit of measurement for solute concentration. The calculated serum osmolality assumes that the primary solutes in the serum are sodium salts (chloride and bicarbonate), glucose, and urea nitrogen.

      2 (Na + K) + Glucose + Urea (all in mmol/L) = calculated osmolarity

      313 mOsm/L = 2 (144 + 6) + 9.5 + 3.5

      Sodium and potassium ions clearly contribute the most to plasma osmolarity. Glucose and urea, on the other hand, are less so.

      The osmolarity of normal serum is 285-295 mOsm/L. Temperature and pressure affect osmolality, and this calculated variable is less than osmolality for a given solution.

      The number of osmoles (Osm) of solute per kilogramme (Osm/kg) is a measure of osmolality, which is also a measure of solute concentration. Temperature and pressure have no effect on the value. An osmometer is used to measure it in the lab. Osmometers rely on a solution’s colligative properties, such as a decrease in freezing point or a rise in vapour pressure.

      The osmolar gap (OG) is calculated as follows:

      OG = osmolaRity calculated from measured serum osmolaLity

      Excess alcohols, lipids, and proteins in the blood can all contribute to the difference.

    • This question is part of the following fields:

      • Physiology
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  • Question 136 - A 35-year-old female, presents to the emergency department via ambulance. The paramedics have...

    Incorrect

    • A 35-year-old female, presents to the emergency department via ambulance. The paramedics have noted the patient's symptoms as unilateral left-sided weakness of the upper and lower limbs, homonymous hemianopia and dysphasia.
      She has previous personal and family history of deep vein thromboses.
      The report of her CT scan suggests a stroke involving the middle cerebral artery.
      Post recovery, she undergoes further diagnostic investigations to determine the cause of a stroke at her young age. She is eventually diagnosed with a hypercoagulable state disease called Factor V Leiden thrombophilia.

      An emboli in the middle cerebral artery results in dysfunction of which areas of the brain?

      Your Answer:

      Correct Answer: Frontal, temporal and parietal lobes

      Explanation:

      The middle cerebral artery is a part of the circle of Willis system of anastomosis within the brain, and the most often affected by brain pathology.

      The primary function of the middle cerebral artery is providing oxygenated blood to related regions of the brain. It achieves this by giving off different branches to supply different brain regions, namely:

      The cortical branches: which supplies the primary motor and somatosensory cortical areas of some parts of the face, trunk and upper limbs.

      The small central branches: which supply the basal ganglia and internal capsule via the lenticulostriate vessels.

      The superior division: which supplies the lateral inferior frontal lobe, including the Broca area which is responsible for production of speech, language comprehension, and writing.

      The inferior division: which supplies the superior temporal gyrus, including Wernicke’s area which controls speech comprehension and language development.

    • This question is part of the following fields:

      • Anatomy
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  • Question 137 - Which of these anaesthetics has the best chance of preventing HPV (hypoxic pulmonary...

    Incorrect

    • Which of these anaesthetics has the best chance of preventing HPV (hypoxic pulmonary vasoconstriction)?

      Your Answer:

      Correct Answer: Desflurane 2 MAC

      Explanation:

      Resistance pulmonary arteries constrict in response to alveolar and airway hypoxia, diverting blood to better-oxygenated alveoli.

      In atelectasis, pneumonia, asthma, and adult respiratory distress syndrome, hypoxic pulmonary vasoconstriction optimises O2 uptake. Hypoxic pulmonary vasoconstriction helps maintain systemic oxygenation during single-lung anaesthesia.

      A redox-based O2 sensor within pulmonary artery smooth muscle cells is involved in hypoxic pulmonary vasoconstriction. The production of reactive oxygen species by smooth muscle cells in the pulmonary artery varies in proportion to PaO2. Hypoxic removal of these redox second messengers inhibits voltage-gated potassium channels, depolarizing smooth muscle cells in the pulmonary artery.

      L-type calcium channels are activated by depolarization, which raises cytosolic calcium and causes hypoxic pulmonary vasoconstriction. Some anaesthetics suppress this response, increasing the risk of further deterioration in ventilation perfusion mismatch.

      Agents that inhibit HPV are ether, halothane, and desflurane (>1.6 MAC).
      Agents with no effect on HPV include thiopentone, fentanyl, desflurane (1MAC), isoflurane (<1.5MAC), sevoflurane(1MAC), and propofol.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 138 - A 76-year-old female, presents to her GP. She complains of fatigue and increased...

    Incorrect

    • A 76-year-old female, presents to her GP. She complains of fatigue and increased shortness of breath. On examination, she is noted to have pallor, an increased respiratory and heart rate. Her GP requests further diagnostic investigations, including a full blood count (FBC) which finds decreased MCV and MCHC.

      What is the most likely cause of her symptoms?

      Your Answer:

      Correct Answer: Iron deficiency

      Explanation:

      The patient’s diagnosis is microcytic hypochromic anaemia which is often as a result of iron deficiency and thalassaemia.

      Macrocytic anaemia is often caused by folate and B12 deficiencies and alcohol abuse.

      Normocytic normochromic anaemia is often caused by acute blood loss, haemolytic anaemia, anaemia of chronic disease and leucoerythroblastic anaemias.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 139 - You are approached by a drug rep who tells you about a new...

    Incorrect

    • You are approached by a drug rep who tells you about a new drug. The dosage and side effects of the drug are being determined in a trial. The representative asks you to refer participants for the trial.

      What type of participants should you refer? In which phase of trials is the drug currently in?

      Your Answer:

      Correct Answer: Healthy participants, Phase 1

      Explanation:

      Phase 2 trials involve patients that are suffering from the disease under study and are associated with determining the efficiency and the optimum dosage of the drug.

      Phase 0 trials assist the scientists in studying the behaviour of drugs in humans by micro dosing patients. They are used to speed up the developmental process. They have no measurable therapeutic effect and efficiency.

      Phase 1 is associated with assessing whether a drug is safe to use or not. The process is extensive and can take up to several months. It also involves healthy participants (less than 100) that are paid to take part in the study. The side effects upon increasing dosage are also addressed by the study. The effects the drug has on humans including how its absorbed, metabolized and excreted are studied. Approximately 70% of the drugs pass this phase.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 140 - An 85-year old female is being investigated and treated for pancytopenia of unknown...

    Incorrect

    • An 85-year old female is being investigated and treated for pancytopenia of unknown origin. Her most recent blood test is shown below which shows that he has a low platelet count.

      Hb-102 g/l
      WBC - 2.9* 109/l
      Platelets - 7 * 109/l

      Which of the following normally stimulates platelet production?


      Your Answer:

      Correct Answer: Thrombopoietin

      Explanation:

      Interleukin-4 is a cytokine which acts to regulate the responses of B and T cells.

      Erythropoietin is responsible for the signal that initiated red blood cell production.

      Granulocyte-colony stimulating factor stimulates the bone marrow to produce granulocytes.

      Interleukin-5 is a cytokine that stimulates the proliferation and activation of eosinophils.

      Thrombopoietin is the primary signal responsible for megakaryocyte and thus platelet production.
      Platelets are also called thrombocytes. They, like red blood cells, are also derived from myeloid stem cells. The process involves a megakaryocyte developing from a common myeloid progenitor cell. A megakaryocyte is a large cell with a multilobulated nucleus, this grows to become massive where it will then break up to form platelets.

      Immune cells are generated from haematopoietic stem cells in bone marrow. They generate two main types of progenitors, myeloid and lymphoid progenitor cells, from which all immune cells are derived.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 141 - A 20-year-old man has been diagnosed with mitral regurgitation. He will be treated...

    Incorrect

    • A 20-year-old man has been diagnosed with mitral regurgitation. He will be treated with mitral valve repair.

      What is true regarding the mitral valve?

      Your Answer:

      Correct Answer: Its closure is marked by the first heart sound

      Explanation:

      The mitral valve is the valve between the left atrium and left ventricle. It opens when the heart is in diastole (relaxation) which allows blood to flow from the left atrium to the left ventricle. In systole (contraction), the mitral valve closes to prevent the backflow of blood from the left ventricle to the left atrium.

      The mitral valve is located posterior to the sternum at the level of the 4th costal cartilage. It is best auscultated over the cardiac apex, where its closure marks the first heart sound.

      The mitral valve anatomy is composed of five main structures:
      1. Left atrial wall – the myocardium of the left atrial wall extends over the posterior leaflet of the mitral valve. (left atrial enlargement is one of the causes for mitral regurgitation)
      2. Mitral annulus – a fibrous ring that connects with the anterior and posterior leaflets. It functions as a sphincter that contracts and reduces the surface area of the valve during systole (Annular dilatation can also lead to mitral regurgitation)
      3. Mitral valve leaflets (cusps) – The mitral valve is the only valve in the heart with two cusps or leaflets. One anterior and one posterior.
      i. The anterior leaflet is located posterior to the aortic root and is also anchored to the aortic root.
      ii. The posterior leaflet is located posterior to the two commissural areas.
      4. Chordae tendinae – The chordae tendinae connects both the cusps to the papillary muscles.
      5. Papillary muscles – These muscles and their cords support the mitral valve, allowing the cusps to resist the pressure developed during contractions (pumping) of the left ventricle

      The anterior and posterior cusps are attached to the chordae tendinae which itself is attached to the left ventricle via papillary muscle.

    • This question is part of the following fields:

      • Anatomy
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  • Question 142 - The most abundant intracellular ion is? ...

    Incorrect

    • The most abundant intracellular ion is?

      Your Answer:

      Correct Answer: Phosphate

      Explanation:

      Phosphate is the principal anion of the intracellular fluid, most of which is bound to either lipids or proteins. They dissociate or associate with different compounds, depending on the enzymatic reaction, thus forming a constantly shifting pool.

      Calcium and magnesium are also present intracellularly, however in lesser amounts than phosphate.

      Sodium is the most abundant extracellular cation, and Chloride and is the most abundant extracellular anion.

    • This question is part of the following fields:

      • Physiology
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  • Question 143 - Which of the following is included in monosynaptic reflexes? ...

    Incorrect

    • Which of the following is included in monosynaptic reflexes?

      Your Answer:

      Correct Answer: The patellar or knee jerk reflex.

      Explanation:

      Monosynaptic reflexes is a type of reflex arc providing direct communication between motor and sensory innervation in a muscle. It occurs very quickly as it arises and ends in the same muscle. Examples include: biceps reflex, brachioradialis reflex, extensor digitorum reflex, triceps reflex, Achilles reflex and patellar reflex.

      Polysynaptic reflexes facilitates contraction and inhibition in muscle by providing communication between multiple muscles.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 144 - Infrared radiation is absorbed by asymmetric, polyatomic polar molecules like carbon dioxide (CO2).

    When...

    Incorrect

    • Infrared radiation is absorbed by asymmetric, polyatomic polar molecules like carbon dioxide (CO2).

      When measuring CO2 in gas samples, mainstream capnography uses this physical principle.

      Which of the following gases is most likely to interfere with carbon dioxide's absorption spectrum?

      Your Answer:

      Correct Answer: Nitrous oxide

      Explanation:

      Carbon dioxide absorbs the most infrared (IR) light between the wavelengths of 4.2-4.4m (4.26m is ideal).

      Nitrous oxide absorbs infrared light at wavelengths of 4.4-4.6m (very similar to CO2) and less so at 3.9m.

      At a frequency of 4.7m, carbon monoxide absorbs the most IR light.

      At 3.3 m and throughout the ranges 8-12 m, the volatile agents have strong absorption bands.

      Although oxygen does not absorb infrared light, it collides with CO2 molecules, interfering with absorption. The absorption band is widened as a result of this (so called collision or pressure broadening). A drop of 0.5 percent in measured CO2 can be caused by 95% oxygen.

      Nitrous oxide causes a greater inaccuracy of 0.1 percent per ten percent of nitrous oxide.

      Water vapour absorbs infrared light as well, resulting in absorption band overlap, collision broadening, and partial pressure dilution. Water traps and water permeable tubing are used to reduce inaccuracies.

      Collision broadening is compensated for in modern gas multi-gas analysers.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 145 - Concerning forced alkaline diuresis, which of the following statements is true? ...

    Incorrect

    • Concerning forced alkaline diuresis, which of the following statements is true?

      Your Answer:

      Correct Answer: Can be used in a barbiturate overdose

      Explanation:

      In situations of poisoning or drug overdose with acid dugs like salicylates and barbiturates, forced alkaline diuresis may be used.

      With regards to overdose with alkaline drugs, forced acid diuresis is used.

      By changing the pH of the urine, the ionised portion of the drug stays in the urine, and this prevents its diffusion back into the blood. Charged molecules do not readily cross biological membranes.

      The process involves the infusion of specific fluids at a rate of about 500ml per hour. This requires monitoring of the central venous pressure, urine output, plasma electrolytes, especially potassium, and blood gas analysis.

      The fluid regimen recommended is:
      500ml of 1.26% sodium bicarbonate (not 200ml of 8.4%)
      500ml of 5% dextrose and
      500ml of 0.9% sodium chloride.

    • This question is part of the following fields:

      • Physiology
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  • Question 146 - A 63-year old male who has heart failure has peripheral oedema and goes...

    Incorrect

    • A 63-year old male who has heart failure has peripheral oedema and goes to the GP's office. The GP notes that he is fluid-overloaded. This causes his atrial myocytes to release atrial natriuretic peptide (ANP). ANP's main action is by which of these mechanisms?

      Your Answer:

      Correct Answer: Antagonist of angiotensin II

      Explanation:

      Atrial natriuretic peptide (ANP) is secreted mainly from myocytes of right atrium and ventricle in response to increased blood volume.
      It is secreted by both the right and left atria (right >> left).

      It is a 28 amino acid peptide hormone, which acts via cGMP
      degraded by endopeptidases.

      It serves to promote the excretion of sodium, lowers blood pressure, and antagonise the actions of angiotensin II and aldosterone.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 147 - In an experimental study, a healthy subject was given one litre of 5%...

    Incorrect

    • In an experimental study, a healthy subject was given one litre of 5% dextrose within a 15-minute period. Which of the following mechanisms is expected to affect the urine output?

      Your Answer:

      Correct Answer: Inhibition of arginine vasopressin (AVP) secretion

      Explanation:

      Changes in the osmolality of body fluids (changes as minor as 1% are sufficient) play the most important role in regulating AVP secretion. The receptors that monitor changes in osmolality of body fluids (termed osmoreceptors) are distinct from the cells that synthesize and secrete AVP, and are located in the organum vasculosum of the lamina terminalis (OVLT) of the hypothalamus. The osmoreceptors sense changes in body osmolality by either shrinking or swelling. When the effective osmolality of the plasma increases, the osmoreceptors send signals to the AVP synthesizing/secreting cells located in the supraoptic and paraventricular nuclei of the hypothalamus, and AVP synthesis and secretion are stimulated. Conversely, when the effective osmolality of the plasma is reduced, secretion is inhibited. Because AVP is rapidly degraded in the plasma, circulating levels can be reduced to zero within minutes after secretion is inhibited.

      In this scenario, the osmolality of the plasma will decrease to an estimate of 2.5%, hence inhibition of AVP.

      Stimulation of atrial stretch receptors is incorrect because the increase in plasma volume is still below the threshold for its activation.

      Osmotic diuresis is incorrect because 5% dextrose is isotonic, hence osmotic diuresis is not probable.

      Renin is inhibited when an excess of NaCl in the tubular fluid is sensed by the macula densa.

    • This question is part of the following fields:

      • Physiology
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  • Question 148 - Patient’s having disease (Test Positive: 60, Test Negative:40)


    Patient’s not having...

    Incorrect

    • Patient’s having disease (Test Positive: 60, Test Negative:40)


      Patient’s not having the disease (Test Positive:20, Test Negative: 80)

      This is a result of a new tumour marker blood test, that was performed on 200 women for breast cancer screening. The director of the screening programme ask you to evaluate the observations and inform them the specificity of this new test.

      Which one of the following figure you will relay to the programme director?

      Your Answer:

      Correct Answer: 80%

      Explanation:

      The positive predictive value is the ratio of patients truly diagnosed as positive to all those who had positive test results. In this case, this is 60/(60+20)=75%.

      The negative predictive value is the ratio of patients truly diagnosed as negative to all those who had negative test results. In this case, this is 80/(80+40)=67%.

      The sensitivity is the ratio of patients with the disease who test positive i.e. true positive patients to the total number of people with the disease. In this case, this is 60/(60+40)=60%.

      The specificity is the ratio of people who don’t have the disease who test negative i.e. true negatives to the total number of people without the disease. In this case, this is 80/(20+80)=80%.

      70% is not the result of any screening measurements

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 149 - All the following statements are false regarding local anaesthetic except ...

    Incorrect

    • All the following statements are false regarding local anaesthetic except

      Your Answer:

      Correct Answer: Potency is directly related to lipid solubility

      Explanation:

      The potency of local anaesthetics is directly proportional to lipid solubility because they need to penetrate the lipid-soluble membrane to enter the cell.

      Protein binding has a direct relationship with the duration of action because the higher the ability of the drug to bind with membrane protein, the higher is the duration of action.

      Higher the pKa of a drug, slower the onset of action. Because a drug with higher pKa will be more ionized than the one with lower pKa at a given pH. Local anaesthetics are weak bases, and unionized form diffuses more rapidly across the nerve membrane than the protonated form. As a result drugs with higher pKa will be more ionized will diffuse less across the nerve membrane.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 150 - Gag reflex was assessed as a part of brain stem death in a...

    Incorrect

    • Gag reflex was assessed as a part of brain stem death in a 22-year-old man with severe traumatic brain injury.

      Which of the following nerves forms the afferent limb of this reflex?

      Your Answer:

      Correct Answer: Glossopharyngeal nerve

      Explanation:

      The gag reflex is a protective mechanism that prevents any foreign material to enter the aerodigestive tract.

      This reflex has afferent (sensory) and effect (motor) components.
      – Glossopharyngeal nerve form the afferent limb
      – Vagus nerve form the efferent limb

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 151 - A 52-year old man was placed under general anaesthesia for an emergent open...

    Incorrect

    • A 52-year old man was placed under general anaesthesia for an emergent open cholecystectomy. As part of the induction, suxamethonium was administered at 1.5mg/kg. Post-operatively, there was failure to restore muscle twitch responses over a course of five hours.

      Clinical chemistry studies were obtained and showed the following results:
      Butrylcholinesterase (BChE) activity: 49 U/L (Reference range: 3300-10,300 U/L)
      Dibucaine number: <4% (Reference range: 83-88%)

      The attending physician gave an initial diagnosis of Suxamethonium Apnoea.

      What is the most probable phenotype of BChE of the patient?

      Your Answer:

      Correct Answer: S (silent)

      Explanation:

      Silent (S) is the most probable phenotype of the patient. In S phenotype, patients have significantly reduced levels of BChE, the lowest among the four phenotypes. Because of this, individuals with S phenotype are subjected to long periods of apnoea. In addition, their dibucaine number is very low.

      Other BChE phenotypes are the following:

      Usual (U)
      Atypical (A)
      Fluoride-resistant (F)

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 152 - All the following statements are false regarding gabapentin except: ...

    Incorrect

    • All the following statements are false regarding gabapentin except:

      Your Answer:

      Correct Answer: Requires dose adjustment in renal disease

      Explanation:

      Therapy with gabapentin requires dose adjustment with renal diseases. However, plasma monitoring of the drug is not necessary.

      Gabapentin is not a liver enzyme inducer unlike other anticonvulsants like phenytoin and phenobarbitone

      Gabapentin has not been shown to be associated with visual disturbances.

      Gabapentin is used for add-on therapy in partial or generalized seizures and used in the management of chronic pain conditions but is of no use in petit mal.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 153 - A 45-year-old woman complains of pain in her upper abdomen to her physician....

    Incorrect

    • A 45-year-old woman complains of pain in her upper abdomen to her physician. The pain comes intermittently in waves and gets worse after eating food. There are no associated complaints of fever or bowel problems.

      The pain intensity is 6/10, and paracetamol relieves it a little. There is suspicion that part of the biliary tree is blocked.

      Which area of the duodenum does this blocked tube open into?

      Your Answer:

      Correct Answer: 2nd part of the duodenum

      Explanation:

      The patient is likely suffering from biliary colic since her pain is intermittent and comes and goes in waves. Biliary colic pain gets worse after eating, especially fatty food as bile helps digest fats. Gallstones are the most common cause of biliary colic and are usually located in the cystic duct or common bile duct. But since this patient has no signs of jaundice or steatorrhea, the duct most likely blocked is the cystic duct.

      The cystic duct drains the gallbladder and combines with the common hepatic duct to form the common bile duct. The common bile duct then merges with the pancreatic duct and opens into the second part of the duodenum (major duodenal papilla).

      The duodenojejunal flexure is attached to the diaphragm by the ligament of Treitz and is not associated with any common pathology.
      The fourth part of the duodenum passes very close to the abdominal aorta and can be compressed by an abdominal aortic aneurysm.
      The third part of the duodenum can be affected by superior mesenteric artery syndrome, where the duodenum is compressed between the SMA and the aorta, often in cases of reduced body fat.
      The first part of the duodenum is the most common location for peptic ulcers affecting this organ.

    • This question is part of the following fields:

      • Anatomy
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  • Question 154 - The thyroid gland: ...

    Incorrect

    • The thyroid gland:

      Your Answer:

      Correct Answer: Internalises iodine through active transport

      Explanation:

      The thyroid gland is a gland shaped like a butterfly which lies at the base of the anterior neck. It controls metabolism using hormone secretion.

      Iodine is extremely important for the synthesis of hormones within the thyroid. It is internalised into the thyroid follicular cells via the sodium/iodide symporter (NIS).

      The parathyroid glands are found posterior to the thyroid gland, with the recurrent laryngeal nerves running posteromedially.

      The expected weight of a normal thyroid gland is about 30 grams.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 155 - A human's resting oxygen consumption (VO2) is typically 3.5 ml/kg/minute (one metabolic equivalent...

    Incorrect

    • A human's resting oxygen consumption (VO2) is typically 3.5 ml/kg/minute (one metabolic equivalent or 1 MET).

      Which of the following options is linked to the highest VO2 when a person is at rest?

      Your Answer:

      Correct Answer: Neonate

      Explanation:

      The oxygen consumption rate (VO2) at rest is 3.5 ml/kg/minute (one metabolic equivalent or 1 MET).
      3.86 ml/kg/minute thyrotoxicosis

      Young children consume a lot of oxygen: around 7 ml/kg/min when they are born. The metabolic cost of breathing is higher in children than in adults, and it can account for up to 15% of total oxygen consumption. Similarly, an infant’s metabolic rate is nearly twice that of an adult, resulting in a larger alveolar minute volume and a lower FRC.

      At term, oxygen consumption at rest can increase by as much as 40% (5 ml/kg/minute) and can rise to 60% during labour.

      When compared to normal basal metabolism, sepsis syndrome increases VO2 and resting metabolic rate by 30% (4.55 ml/kg/minute). In septicaemic shock, VO2 decreases.

      Dobutamine hydrochloride was infused into 12 healthy male volunteers at a rate of 2 micrograms per minute per kilogramme, gradually increasing to 4 and 6 micrograms per minute per kilogramme. Dobutamine was infused for 20 minutes for each dose. VO2 increased by 10% to 15%. (3.85-4.0 ml/kg/min).

    • This question is part of the following fields:

      • Physiology
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  • Question 156 - A 50-year-old woman's blood pressure readings in the clinic are 170/109 mmHg, 162/100...

    Incorrect

    • A 50-year-old woman's blood pressure readings in the clinic are 170/109 mmHg, 162/100 mmHg and 175/107 mmHg and her routine haematology, biochemistry, and 12-lead ECG are normal.

      She is assessed on the day of surgery prior to laparoscopic inguinal hernia repair and is found to be normally fit and well. Documentation of previous blood pressure measurements from her general practitioner in the primary healthcare setting are not available.

      What is your next course of action?

      Your Answer:

      Correct Answer: Proceed with scheduled surgery without treatment

      Explanation:

      The AAGBI and the British Hypertension Society has published guidelines for the measurement of adult blood pressure and management of hypertension before elective surgery.

      The objective is to ensure that patients admitted for elective surgery have a known systolic blood pressure below 160 mmHg and diastolic blood pressures below 100 mmHg. The primary health care teams, if possible, should ensure that this is the case and provide evidence to the pre-assessment clinic staff or on admission.

      Avoiding cancellation on the day of surgery because of white coat hypertension is a secondary objective.

      Patients with blood pressures below 180 mmHg systolic and 110 mmHg diastolic (measured in the preop assessment clinic), who present to pre-operative assessment clinics without documented evidence of primary care blood pressures should proceed to elective surgery.

      In this question, the history/assessment does not appear to point to obvious end-organ damage so there is no indication for further investigation for secondary causes of hypertension or an echocardiogram at this point. Further review and treatment at this point is not required.

      However, you should write to the patient’s GP and encourage serial blood pressure measurements in the primary health care setting.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 157 - A 70-year-old male is brought to the Emergency department with:
    Pulse rate:...

    Incorrect

    • A 70-year-old male is brought to the Emergency department with:
      Pulse rate: 32 beats per minute
      Blood pressure: 82/35 mmHg
      12 lead ECG shows a sinus bradycardia of 35 beats per minute with no evidence of myocardial ischemia or infarction. There was no chest pain but the patient feels light-headed.

      Which of the following would be the best initial treatment for this condition?

      Your Answer:

      Correct Answer: Atropine

      Explanation:

      Based on the presenting symptoms and clinical examination, it is a case of an adult sinus bradycardia with adverse signs. The first pharmacological treatment for this condition is atropine 500mcg intravenously and if necessary repeat every three to five minutes up to a maximum of 3 mg.

      If the bradycardia does not subside even after the administration of atropine, cardiac pacing should be considered. If pacing cannot be achieved promptly, we should consider the use of second-line drugs like adrenaline, dobutamine, or isoprenaline.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 158 - A 52-year-old patient is brought to ER with a chief complaint of chest...

    Incorrect

    • A 52-year-old patient is brought to ER with a chief complaint of chest pain for two hours. Chest pain was tightness in nature, located in the centre of the chest and radiate into the neck and left arm. The patient otherwise looks fit and well.

      Just after admitting the patient, he suffered VF cardiac arrest and is immediately defibrillated with the return of spontaneous circulation (ROSC).

      On clinical examination following was the finding:
      BP: 82/45 mmHg
      Heart rate: 120 beats/min
      Oxygen saturation on air: 25%
      Heart sounds: Normal
      There is no sign of pulmonary oedema. The patient is anxious, cold, and clammy.

      A 12 lead ECG was done which revealed a sinus rhythm of 120 with ST-segment depression and T wave inversion in leads II, III, and aVF. Which of the following is considered best for the initial treatment of the patient?

      Your Answer:

      Correct Answer: Oral aspirin

      Explanation:

      This is a classical case of unstable angina or NSTEMI (Non-ST-elevation myocardial infarction). As soon as the diagnosis of unstable angina or NSTEMI is made the initial treatment is Aspirin and antithrombin therapy.

      Betablocker is known to reduce mortality from acute myocardial infarction by reducing oxygen demand. If there is no contraindication (heart block, bradycardia, hypotension, severe left ventricular dysfunction, and asthma), a beta-blocker should be given early. This patient has hypotension and therefore metoprolol is contraindicated.

      If three doses of nitroglycerine tablets or Nitrolingual sprays and intravenous beta-blockers too cannot relieve the symptoms intravenous Glyceryl Trinitrate (GTN) should be considered provided that there is no hypotension. But in this case, the patient is hypotensive, and therefore, it is contraindicated.

      If the symptoms are not relieved after three serial doses of nitroglycerine or if symptoms recur despite adequate anti-anginal treatment morphine sulphate is indicated.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 159 - A weakly acidic drug with a pKa of 8.4 is injected intravenously into...

    Incorrect

    • A weakly acidic drug with a pKa of 8.4 is injected intravenously into a patient.

      At a normal physiological pH, the percentage of this drug unionised in the plasma is?

      Your Answer:

      Correct Answer: 90

      Explanation:

      Primary FRCA is concerned with two issues. The first is a working knowledge of the Henderson-Hasselbalch equation, and the second is a working knowledge of logarithms and antilogarithms.

      The pH at which the drug exists in 50 percent ionised and 50 percent unionised forms is known as the pKa.

      To calculate the proportion of ionised to unionised form of a drug, use the Henderson-Hasselbalch equation.

      pH = pKa + log ([A-]/[HA])

      or

      pH = pKa + log [(salt)/(acid)]
      pH = pKa + log ([ionised]/[unionised])

      Hence, if the pKa − pH = 0, then 50% of drug is ionised and 50% is unionised.

      In this example:
      7.4 = 8.4 + log ([ionised]/[unionised])
      7.4 − 8.4 = log ([ionised]/[unionised])
      log −1 = log ([ionised]/[unionised])

      Simply put, the antilog is the inverse log calculation. In other words, if you know the logarithm of a number, you can use the antilog to find the value of the number. The antilogarithm’s definition is as follows:

      y = antilog x = 10x

      Antilog to the base 10 of 0 = 1, −1 = 0.1, −2 = 0.01, −3 = 0.001 and, −4 = 0.0001.

      [A-]/[HA] = 0.1

      Assuming that we can apply the approximation [A-] << [HA} then this means the acid is 0.1 x 100% = 10% ionised so the percentage of (non-ionized) acid will be 100% – 10% = 90%

    • This question is part of the following fields:

      • Pharmacology
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  • Question 160 - Health workers are at increased risks of anaesthetic exposure. Therefore, The Control of...

    Incorrect

    • Health workers are at increased risks of anaesthetic exposure. Therefore, The Control of Substances Hazardous to Health (COSHH) regulations require measures implemented to assess and control the risks related to this exposure.

      Among the following control measures, which one is most likely to limit potentially harmful exposure to anaesthetic agents within an operating theatre?

      Your Answer:

      Correct Answer: Total intravenous anaesthesia (TIVA)

      Explanation:

      Exposure to anaesthetic hazards is one among the occupational exposures in manipulating toxic agents or inhaling toxic gases during anaesthetic practices.

      Toxic gases mainly nitrous oxide, is one of the most gaseous anaesthetic agents that constitutes an important source of pollution. One of the safe and effective technics used in anaesthesia and reducing the amount of pollution is the Total Intravenous Anaesthesia (TIVA) which consists of using opioids in analgesia and propofol for the induction and the maintenance of anaesthesia. It refers to the administration intravenously of an anaesthetic, sedative, and/or tranquilizer. A less polluting but not the best way to get rid of the toxic aesthetic agents is the scavenger system that collects and expels the gas outside the medical environment. Yet, this technique still represents a hazard for the environment and still increase the risk of exposure for the health workers and clinical staff.

      Fume cupboards are also not recommended to use because of their high pollution potency, mainly of the air resulting in a great harm for medical workers.

      Supraglottic airways as well as the Air Changes per Hour technics could be harmful for both patients and health workers, increasing the risks of transmitted diseases, namely nosocomial infections.

      Therefore, the Total Intravenous Anaesthesia technique (TIVA) is most likely to be safe and recommended to use.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 161 - Useful diagnostic information can be obtained from measuring the osmolality of biological fluids....

    Incorrect

    • Useful diagnostic information can be obtained from measuring the osmolality of biological fluids.

      Of the following physical principles, which is the most accurate and reliable method of measuring osmolality?

      Your Answer:

      Correct Answer: Depression of freezing point

      Explanation:

      Colligative properties are properties of solutions that depend on the number of dissolved particles in solution. They do not depend on the identities of the solutes.

      All of the above have colligative properties with the exception of depression of melting point.

      The osmolality from the concentration of a substance in a solution is measured by an osmometer. The freezing point of a solution can determines concentration of a solution and this can be measured by using a freezing point osmometer. This is applicable as depression of freezing point is directly correlated to concentration.

      Vapour pressure osmometers, which measure vapour pressure, may miss certain volatiles such as CO2, ammonia and alcohol that are in the solution

      The use of a freezing point osmometer provides the most accurate and reliable results for the majority of applications.

      Colligative properties does not include melting point depression . Mixtures of substances in which the liquid phase components are insoluble, display a melting point depression and a melting range or interval instead of a fixed melting point.

      The magnitude of the melting point depression depends on the mixture composition.

      The melting point depression is used to determine the purity and identity of compounds. EMLA (eutectic mixture of local anaesthetics) cream is a mixture of lidocaine and prilocaine and is used as a topical local anaesthetic. The melting point of the combined drugs is lower than that individually and is below room temperature (18°C).

    • This question is part of the following fields:

      • Physiology
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  • Question 162 - A 79-year-old female complains of painful legs, especially in her thigh region. The...

    Incorrect

    • A 79-year-old female complains of painful legs, especially in her thigh region. The pain starts after walking and settles with rest. She occasionally has to take paracetamol to relieve the pain. She is a known case of hyperlipidaemia, type 2 diabetes mellitus, hypertension, and depression.

      Her physician makes a provisional diagnosis of claudication of the femoral artery, which is a continuation of the external iliac artery.
      Which of the following anatomical landmarks does the external iliac artery cross to become the femoral artery?

      Your Answer:

      Correct Answer: Inguinal ligament

      Explanation:

      The external iliac artery is the larger of the two branches of the common iliac artery. It forms the main blood supply to the lower limbs. The common iliac bifurcates into the internal and external iliac artery anterior to the sacroiliac joint.

      The external iliac artery courses on the medial border of the psoas major muscles and exits the pelvic girdle posterior to the inguinal ligament. Here, midway between the anterior superior iliac spine and the pubic symphysis, the external iliac artery becomes the femoral artery and descends along the anteromedial part of the thigh in the femoral triangle.

      The pectineus forms the posterior border of the femoral canal.
      The femoral vein forms the lateral border of the femoral canal.
      The medial border of the adductor longus muscle forms the medial wall of the femoral triangle.
      The medial border of the sartorius muscle forms the lateral wall of the femoral triangle.

    • This question is part of the following fields:

      • Anatomy
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  • Question 163 - One of the following neuromuscular blocking agents is the most potent: ...

    Incorrect

    • One of the following neuromuscular blocking agents is the most potent:

      Your Answer:

      Correct Answer: Vecuronium

      Explanation:

      The measure of drug potency or therapeutic response is the ED95. This is defined as the dose of a neuromuscular blocking drug required to produce a 95% depression of muscle twitch height. The ED50 and ED90 describe a depression of twitch height by 50% and 90% respectively.

      The ED95 (mg/kg) of the commonly used neuromuscular blocking agents are:

      suxamethonium: 0.27
      rocuronium: 0.31
      vecuronium: 0.04
      pancuronium: 0.07
      cisatracurium: 0.04
      mivacurium: 0.08

    • This question is part of the following fields:

      • Pharmacology
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  • Question 164 - An otherwise fit 7-year-old boy for an elective tonsillectomy is seen holding a...

    Incorrect

    • An otherwise fit 7-year-old boy for an elective tonsillectomy is seen holding a bottle of sugared orange squash at anaesthetic assessment . He appears to have consumed 120 mL of the bottle's contents.

      What is the minimal safe fasting time prior to proceeding with a general anaesthetic in this patient?

      Your Answer:

      Correct Answer: 1 hour

      Explanation:

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 165 - A laceration to the upper lateral margin of the popliteal fossa will pose...

    Incorrect

    • A laceration to the upper lateral margin of the popliteal fossa will pose the greatest risk of injury for which nerve?

      Your Answer:

      Correct Answer: Common peroneal nerve

      Explanation:

      The common peroneal (fibular) nerve descends obliquely along the lateral side of the popliteal fossa to the fibular head, medial to biceps femoris.

      The sural nerve exits at the fossa’s lower inferolateral aspect and is more at risk in short saphenous vein surgery.

      The tibial nerve lies more medially and is even less likely to be injured in this location.

      The boundaries of the popliteal fossa are:
      Superolateral – the biceps femoris tendon
      Superomedial – semimembranosus reinforced by semitendinosus
      Inferomedial and inferolateral – medial and lateral heads of gastrocnemius

      The contents of the Popliteal fossa are:

      1. The popliteal artery
      2. The popliteal vein
      3. The Tibial nerve and common Fibular nerve
      4. Posterior femoral cutaneous nerve: descends and pierces the roof
      5. Small saphenous vein
      6. popliteal lymph nodes
      7. fat

    • This question is part of the following fields:

      • Anatomy
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  • Question 166 - A patient visits the radiology department for a magnetic resonance imaging (MRI) scan...

    Incorrect

    • A patient visits the radiology department for a magnetic resonance imaging (MRI) scan (MRI). The presence of metal implants must be ruled out prior to the scan.

      In a strong magnetic field, which of the following metals is the safest?

      Your Answer:

      Correct Answer: Chromium

      Explanation:

      Ferromagnetism is the property of a substance that is magnetically attracted and can be magnetised indefinitely. A material is said to be paramagnetic if it is attracted to a magnetic field. A substance is said to be diamagnetic if it is repelled by a magnetic field.

      Cobalt, iron, gadolinium, neodymium, and nickel are ferromagnetic.

      Gadolinium is a ferromagnetic rare earth metal that is ferromagnetic below 20 degrees Celsius (its Curie temperature). MRI scans are enhanced with gadolinium-based contrast media.

      When ferromagnetic materials are exposed to a magnetic field, they can cause a variety of issues like magnetic field interactions, heating, and image artefacts.

      Titanium, lead, chromium, copper, aluminium, silver, gold, and tin are non ferromagnetic.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 167 - Which of the following options is correct regarding the coagulation pathway? ...

    Incorrect

    • Which of the following options is correct regarding the coagulation pathway?

      Your Answer:

      Correct Answer: Tissue factor released by damaged tissue initiates the extrinsic pathway

      Explanation:

      The extrinsic pathway is considered as the main pathway of coagulation cascade.

      Heparin is known to inhibit the activation of coagulation factors 2,9,10, and 11.

      The extrinsic and intrinsic pathways meet at the activation of coagulation factor 10.

      Fibrinogen is converted into Fibrin in the presence of Thrombin. Plasminogen is converted into plasmin during fibrinolysis to breakdown fibrin clot.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 168 - A 63-year old man has palpitations and goes to the emergency room. An...

    Incorrect

    • A 63-year old man has palpitations and goes to the emergency room. An ECG shows tall tented T waves, which corresponds to phase 3 of the cardiac action potential.
      The shape of the T wave is as a result of which of the following?

      Your Answer:

      Correct Answer: Repolarisation due to efflux of potassium

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 169 - A 21-year-old woman presents to ER following the deliberate ingestion of 2 g...

    Incorrect

    • A 21-year-old woman presents to ER following the deliberate ingestion of 2 g of amitriptyline. On clinical examination:
      Glasgow coma score: 10
      Pulse rate: 140 beats per minute
      Blood pressure: 80/50 mmHg.
      ECG showed a QRS duration of 233 Ms.

      Which of the following statement describes the most important initial course of action?

      Your Answer:

      Correct Answer: Give fluid boluses

      Explanation:

      The first line of treatment in case of hypotension is fluid resuscitation.

      Activated charcoal can be used within one hour of tricyclic antidepressant ingestion but an intact and secure airway must be checked before intervention. The risk of aspiration should be assessed.

      Vasopressors are indicated for the treatment of hypotension following (Tricyclic Antidepressant) TCA overdose when patients fail to respond to fluids and bicarbonate.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 170 - From the following electromagnetic waves, which one has the shortest wavelength? ...

    Incorrect

    • From the following electromagnetic waves, which one has the shortest wavelength?

      Your Answer:

      Correct Answer: X rays

      Explanation:

      Electromagnetic waves are categorized according to their frequency or equivalently according to their wavelength. Visible light makes up a small part of the full electromagnetic spectrum.

      Electromagnetic waves with shorter wavelengths and higher frequencies include ultraviolet light, X-rays, and gamma rays. Electromagnetic waves with longer wavelengths and lower frequencies include infrared light, microwaves, and radio and televisions waves.

      Different electromagnetic waves according to their wavelength from shorter to longer are X-rays, ultraviolet radiations, visible light, infrared radiation, radio waves. X-ray among electromagnetic waves has the shortest wavelength and higher frequency with wavelengths ranging from 10*-8 to 10* -12 and corresponding frequencies.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 171 - An intravenous infusion is started with a 500 mL bag of 0.18 percent...

    Incorrect

    • An intravenous infusion is started with a 500 mL bag of 0.18 percent N. saline and 4% dextrose.

      Which of the following best describes its make-up?

      Your Answer:

      Correct Answer: Osmolarity 284 mOsmol/L, sodium 15 mequivalents and glucose 20 g

      Explanation:

      30 mmol Na+ and 30 mmol Cl- are found in 1 litre of 0.18 percent N. saline with 4% dextrose. Percent (percent) refers to the number of grammes of a compound per 100 mL, so a litre of 4 percent dextrose solution contains 40 grammes.

      As a result, a 500 mL bag of 1/5th N. saline and 4% dextrose contains approximately 15 mequivalents of sodium and 20 g of glucose. It is hypotonic due to its osmolarity of 284.

      Because of the risk of hyponatraemia, it is no longer considered the crystalloid of choice for fluid maintenance in children.

    • This question is part of the following fields:

      • Physiology
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  • Question 172 - A 68-year-old man presents worried about his risk of motor neurone disease. No...

    Incorrect

    • A 68-year-old man presents worried about his risk of motor neurone disease. No symptoms have developed, but his father suffered from motor neurone disease. Recently, his cousin has also been diagnosed with amyotrophic lateral sclerosis. He searched the internet for screening tests for motor neurone disease and found a blood test called ‘neuron’, and requests to have it done. You search this blood test and find a prospective study going on evaluating the potential benefits of this blood test. On average, this test diagnosed patients with the disease 8 months earlier than the patients who are diagnosed on the basis of their clinical symptoms. The patients diagnosed using this neuron test also survived, on average, 48 months from the diagnosis, whereas the patients diagnosed clinically survived an average of 39 months from the diagnosis. Considering the clear benefits, you decide to have it done on the patient.

      Which of the following options best relate to the above scenario?

      Your Answer:

      Correct Answer: Lead-time bias

      Explanation:

      Hypochondriasis is an illness anxiety disorder, and describes excessively worriedness about the presence of a disease. While the woman is concerned about her possibility of developing motor neurone disease, she understands that no symptoms have yet appeared. Hypochondriasis involves patients who refuse to accept that they don’t have the disease, even if the results come back negative.

      Late Look Bias occurs when the data is gathered or analysed at an inappropriate time e.g. when many of the subjects suffering from a fatal disease have died. This type of biasness might occur in some retrospective studies of motor neurone disease, but is not applicable to this prospective study.

      In procedure bias, the researcher decides assignment of a treatment versus control and assigns particular patients to one group or the other non-randomly. This is unlikely to have occurred in this case, although it is not mentioned specifically. Of all the options, lead time-bias is a better answer.

      The Hawthorne Effect refers to groups modifying their behaviour simply because they are aware of being observed. Any differences in the behaviour have not been mentioned in the question, and it is highly unlikely that a change in patient’s behaviour would have affected their length of survival in this case.

      The correct option is lead-time bias. Even if the new blood test diagnoses the disease earlier, it doesn’t affect the outcome, as the survival time was still on average 43 months from the onset of symptoms in both groups. With the help of blood test, the disease was only detected 8 months earlier.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 173 - Which of the following statements is correct regarding hypomagnesaemia? ...

    Incorrect

    • Which of the following statements is correct regarding hypomagnesaemia?

      Your Answer:

      Correct Answer: Causes tetany

      Explanation:

      The ECG changes seen in hypomagnesaemia include:

      Prolonged PR interval
      Prolonged QT interval
      Flattening of T waves
      ST segment depression
      Prominent U waves

      These changes are almost the same as those of hypokalaemia.

      There is an increased risk of digoxin toxicity and a risk of atrial and ventricular ectopic and ventricular arrhythmias.

      There is impaired synthesis and release of parathyroid hormone (PTH) in chronic hypomagnesaemia leading to impaired target organ response to PTH. This produces secondary hypocalcaemia.

      The use of potassium ‘wasting’ diuretics (e.g. loop diuretics like furosemide) may lead to Hypomagnesaemia.

      A tall T wave is seen in hypermagnesemia.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 174 - Which among the following is summed up by F statistic? ...

    Incorrect

    • Which among the following is summed up by F statistic?

      Your Answer:

      Correct Answer: ANOVA

      Explanation:

      ANOVA is based upon within group variance (i.e. the variance of the mean of a sample) and between group variance (i.e. the variance between means of different samples). The test works by finding out the ratio of the two variances mentioned above. (Commonly known as F statistic).

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 175 - A 55-year-old man has complaints of severe tearing chest pain. A preliminary diagnosis...

    Incorrect

    • A 55-year-old man has complaints of severe tearing chest pain. A preliminary diagnosis of aortic dissection is made in the emergency department. In aortic dissection, which layers have blood flowing in between them?

      Your Answer:

      Correct Answer: Tunica intima and tunica media

      Explanation:

      The wall of an artery has three layers: (innermost to outermost)
      1. Tunica intima – in direct contact with the blood inside the vessel and contains endothelial cells separated by gap junctions.
      2. Tunica media – contains smooth muscle cells and is separated from the intima by the internal elastic lamina and the adventitia by the external elastic lamina.
      3. Tunica adventitia – contains the vasa vasorum, fibroblast, and collagen.

      Aortic dissection is when a tear arises in the innermost layer of the aorta and penetrates through the tear, entering the media layer. The inner and middle layers of the aorta split (dissect).

    • This question is part of the following fields:

      • Anatomy
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  • Question 176 - Glyceryl trinitrate (GTN) used for the acute treatment of angina is best administered...

    Incorrect

    • Glyceryl trinitrate (GTN) used for the acute treatment of angina is best administered via the sublingual route.

      Why is this the best route of administration?

      Your Answer:

      Correct Answer: High first pass metabolism

      Explanation:

      Glyceryl trinitrate (GTN) has a significant first pass metabolism. About 90% of a dose of GTN is metabolised in the liver by the enzyme glutathione organic nitrate reductase.

      An INSIGNIFICANT amount of metabolism occurs in the intestinal mucosa.

      There is approximately 1% bioavailability after oral administration and 38% after sublingual administration.

      GTN does NOT cause gastric irritation and it is well absorbed in the gastrointestinal tract.

      The volume of distribution of GTN is 2.1 to 4.5 L/kg. This is HIGH.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 177 - Which statement is true with regards to the cardiac action potential? ...

    Incorrect

    • Which statement is true with regards to the cardiac action potential?

      Your Answer:

      Correct Answer: Repolarization due to potassium efflux after calcium channels close causes the relative refractory period to start

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 178 - A 2-year old male is admitted to the surgery ward for repair of...

    Incorrect

    • A 2-year old male is admitted to the surgery ward for repair of an inguinal hernia. He weighs 10 kg. To provide post-operative analgesia, levobupivacaine was administered into the epidural space.

      Given the information above, what is the most appropriate dose for the hernia repair?

      Your Answer:

      Correct Answer: 0.25% 7.5 ml

      Explanation:

      Caudal analgesia using bupivacaine is a widely employed technique for achieving both intraoperative and early postoperative pain relief. 0.5 ml/kg of 0.25% plain bupivacaine is favoured by many practitioners who employ this fixed scheme for procedures involving sacral dermatomes (circumcision, hypospadias repair) as well as lower thoracic dermatomes (orchidopexy). However, there are other dosing regimens for caudal blocks with variable analgesic success rates: These include 0.75 ml/kg, 1.0 ml/kg and 1.25 ml/kg.

      A study indicated that plain bupivacaine 0.25% at a dose of 0.75 ml/kg compared to a dose of 0.5 ml/kg when administered for herniotomies provided improved quality of caudal analgesia with a low side effects profile. There were consistently more patients with favourable objective pain scale (OPS) scores at all timelines, increased the time to the analgesic request with similar postoperative consumption of paracetamol in the group of patients who received 0.75 ml/kg of 0.25% bupivacaine.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 179 - A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure,...

    Incorrect

    • A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure, the ileocolic artery is ligated. Which vessel does this artery originate from?

      Your Answer:

      Correct Answer: Superior mesenteric artery

      Explanation:

      The ileocolic artery is the terminal branch of the superior mesenteric artery. It supplies:
      1. terminal ileum
      2. proximal right colon
      3. cecum
      4. appendix (via its branch of the appendicular artery)

      As veins accompany arteries in the mesentery and are lined by lymphatics, high ligation is the norm in cancer resections—the ileocolic artery branches off the SMA near the duodenum.

    • This question is part of the following fields:

      • Anatomy
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  • Question 180 - The Kappa statistic (aka Cohen's kappa coefficient) can be used to measure which...

    Incorrect

    • The Kappa statistic (aka Cohen's kappa coefficient) can be used to measure which of the following?

      Your Answer:

      Correct Answer: Inter-rater reliability

      Explanation:

      The Kappa Statistic or Cohen’s Kappa is a statistical measure of inter-rater reliability for categorical variables. It is used when two raters both apply a criterion based on a tool to assess whether or not some condition occur. A good example can be two doctors rating individuals for diabetes occurrence on the basis of symptoms.

      It gives a quantitative measure of the magnitude of agreement between observers.

      Kappa can take any value between 0 and 1. 0 implies the observers are in complete disagreement and a value of 1 implies complete agreement.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 181 - The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised...

    Incorrect

    • The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised by which of the following?

      Your Answer:

      Correct Answer: Synthesis of ATP is brought about by anaerobic respiration

      Explanation:

      Muscle fibre myosin ATPase histochemistry is used to divide the biochemical classification into two groups: type 1 and type II.

      Type I (slow twitch) muscle fibres rely on aerobic glycolytic and aerobic oxidative metabolism to function. They have a lot of mitochondria, a good blood supply, a lot of myoglobin, and they don’t get tired easily.

      Because they contain more motor units, Type II (fast twitch) muscle fibres are thicker. They are more easily fatigued, but produce powerful bursts. The capillary networks and mitochondria are less dense in these white muscle fibres than in type I fibres. They have a low myoglobin content as well.

      Muscle fibres of type II (fast twitch) are divided into three types:

      Type IIa – aerobic/oxidative metabolism is used.
      Type IIb – anaerobic/glycolytic metabolism is used by these fibres.

      When compared to skeletal muscle, cardiac and smooth muscle twitch at a slower rate.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 182 - Which statement is true of albumin? ...

    Incorrect

    • Which statement is true of albumin?

      Your Answer:

      Correct Answer: Is synthesised and stored in the liver

      Explanation:

      Major surgery induces the systemic inflammatory response and this causes endothelial leakage and a low albumin level.

      Albumin is a single polypeptide which is made but not stored in the liver. Therefore, levels are a reflection of synthetic activity. It is negatively charged and very soluble.

      Only 40% of albumin is intravascular, and the rest in the in interstitial compartment.

      If there was normal liver function during starvation, albumin will be maintained and proteolysis will occur elsewhere.
      It is not catabolised during starvation.
      Starvation and malnutrition may, however, present as part of other disease processes that are associated with hypalbuminaemia.

      Causes of low albumin are

      1. Decreased production (hepatic dysfunction)
      2. Increased loss (renal dysfunction)
      3. Redistribution (endothelial leak/damage)
      4. Increased catabolism (very rare)

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 183 - Which structure does NOT lie in the posterior triangle of the neck? ...

    Incorrect

    • Which structure does NOT lie in the posterior triangle of the neck?

      Your Answer:

      Correct Answer: Internal jugular vein

      Explanation:

      The sternocleidomastoid muscle divides the neck into anterior and posterior triangles on both sides of the neck.

      The posterior triangle has the following boundaries:
      anteriorly – sternocleidomastoid muscle
      posteriorly – trapezius
      roof – investing layer of deep cervical fascia
      floor – prevertebral fascia overlying splenius capitis, levator scapulae, and the scalene muscles

      The contents of the posterior triangle are:
      1. fat
      2. lymph nodes (level V)
      3. accessory nerve
      4. cutaneous branches of the cervical plexus (A major branch of this plexus is the phrenic nerve, which arises from the anterior divisions of spinal nerves C3-C5)
      5. inferior belly of omohyoid
      6. branches of the thyrocervical trunk (transverse cervical and suprascapular arteries)
      7. third part of the subclavian artery
      8. external jugular vein

    • This question is part of the following fields:

      • Anatomy
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  • Question 184 - Which of the following statements is true regarding Entonox? ...

    Incorrect

    • Which of the following statements is true regarding Entonox?

      Your Answer:

      Correct Answer: Exists only in gaseous form in a cylinder (under normal working conditions)

      Explanation:

      Entonox is a gas that consists of 50% oxygen and 50% Nitrous oxide. Nitrous oxide is sometimes used for anaesthetics but in this combination, it works as a short-acting painkiller.

      Under normal working conditions, it exists only in gaseous form in a cylinder. The gauge pressure of a full Entonox cylinder is 137 bar.

      Entonox cylinders should be stored horizontally at a temperature above 0 C. At temperatures below this the nitrous oxide component may separate.

      Pseudocritical temperature and pseudocritical pressure can be defined as the molal average critical temperature and pressure of mixture components. In other words, the pseudo-critical temperature is the temperature at which the two gases separate. The pseudo-critical temperature of Entonox is approximately -5.50 C

    • This question is part of the following fields:

      • Pharmacology
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  • Question 185 - It was hypothesized that people that had lower socio economic status were more...

    Incorrect

    • It was hypothesized that people that had lower socio economic status were more prone to developing gastric cancer. After 30 years of studying people with lower socio economic status, it was found that they did have a greater tendency to develop cancer. As a result of that the authors got to the conclusion that a strong association existed between the two. Later on another study conducted found that people from lower socio economic back grounds also had a tendency to be smokers.


      Which form of potential bias can be associated with this particular study?

      Your Answer:

      Correct Answer: Confounding bias

      Explanation:

      Selection bias is when randomisation is not achieved and is often a result of in efficient recruiting method.

      Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.

      Measurement bias can be characterized by gathering of information in a manner that is distorted.

      When the participants of a research study are recruited from the hospitals rather than the general population, its called Berkson Bias.

      Confounding bias is the major player here because in this case the effects of smoking can be masked behind and can be read as outcomes of lower socio economic status. This extraneous factor (Smoking), distorts the founding.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 186 - Which of the following statement is not true regarding the effects of Dopamine...

    Incorrect

    • Which of the following statement is not true regarding the effects of Dopamine in CNS?

      Your Answer:

      Correct Answer: Most of the administered dose is converted to Noradrenaline in sympathetic nerve terminals

      Explanation:

      Nausea and vomiting occur commonly due to Chemoreceptor Trigger Zone (CTZ) stimulation by dopamine (Domperidone but not metoclopramide can be used for the treatment of this vomiting)

      Dopamine itself cannot cross the blood-brain barrier (BBB) but its precursor levodopa can cross BBB.

      Dopamine can modulate extrapyramidal symptoms like acute dyskinesia, tardive dyskinesia, Parkinsonism, and Neuroleptic malignant syndrome.

      Dopamine inhibits the secretion of prolactin from the pituitary gland.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 187 - Which of the following anaesthetic agent is most potent with the lowest Minimal...

    Incorrect

    • Which of the following anaesthetic agent is most potent with the lowest Minimal Alveolar Concentration (MAC)?

      Your Answer:

      Correct Answer: Isoflurane

      Explanation:

      The clinical potency of the anaesthetic agent is measured using minimal alveolar concentration(MAC).

      MAC and oil: gas partition coefficient is inversely related. Anaesthetic agent Oil/gas partition coefficient and Minimal alveolar concentration (MAC) is given respectively as

      Desflurane 18 6
      Isoflurane 90 1.2
      Nitrous oxide 1.4 104
      Sevoflurane 53.4 2
      Xenon 1.9 71

      With these data, we can conclude Isoflurane is the most potent with the highest oil/gas partition coefficient of 90 and the lowest MAC of 1.2

    • This question is part of the following fields:

      • Pharmacology
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  • Question 188 - Substitution at different positions of the barbituric ring give rise to different pharmacologic...

    Incorrect

    • Substitution at different positions of the barbituric ring give rise to different pharmacologic properties.

      Substitution with and at which specific site of the ring affects lipid solubility the most?

      Your Answer:

      Correct Answer: Sulphur atom at position 2

      Explanation:

      Barbiturates are derived from barbituric acid, which itself is nondepressant, but appropriate side-chain substitutions result in CNS depressant activity that varies in potency and duration with carbon chain length, branching, and saturation.

      Oxybarbiturates retain an oxygen atom on number 2-carbon atom of the barbituric acid ring.

      Thiobarbiturates replace this oxygen atom with a sulphur atom, which confers greater lipid solubility. Generally speaking, a substitution such as sulphuration that increases lipid solubility is associated with greater hypnotic potency and more rapid onset, but shorter duration of action.

      Addition of a methyl group to the nitrogen atom of the barbituric acid ring, as with oxybarbiturate methohexital, also results in a compound with a short duration of action.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 189 - Which compound is secreted only from the adrenal medulla? ...

    Incorrect

    • Which compound is secreted only from the adrenal medulla?

      Your Answer:

      Correct Answer: Adrenaline

      Explanation:

      The adrenal medulla comprises chromaffin cells (pheochromocytes), which are functionally equivalent to postganglionic sympathetic neurons. They synthesize, store and release the catecholamines noradrenaline (norepinephrine) and adrenaline (epinephrine) into the venous sinusoids.
      The majority of the chromaffin cells synthesize adrenaline.

    • This question is part of the following fields:

      • Anatomy
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  • Question 190 - Among the following options, which one can not be the value of Pearson's...

    Incorrect

    • Among the following options, which one can not be the value of Pearson's correlation coefficient?

      Your Answer:

      Correct Answer: 1.5

      Explanation:

      The correlation coefficient gives us the idea about relation between two parameters. i.e. to what extent change in parameter A could prompt a change in parameter B. The numerical value of correlation coefficient could not be greater than 1.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 191 - A young male is undergoing inguinal hernia repair. During the procedure, the surgeons...

    Incorrect

    • A young male is undergoing inguinal hernia repair. During the procedure, the surgeons approach the inguinal canal and expose the superficial inguinal ring.

      Which structure forms the lateral edge of the superficial inguinal ring?

      Your Answer:

      Correct Answer: External oblique aponeurosis

      Explanation:

      The superficial inguinal ring is an opening in the aponeurosis of the external oblique muscle, just above and lateral to the pubic crest.

      The superficial ring resembles a triangle more than a ring with the base lying on the pubic crest and its apex pointing towards the anterior superior iliac spine. The sides of the triangle are crura of the opening in the external oblique aponeurosis. The lateral crura of the triangle is attached to the pubic tubercle. The medial crura of the triangle is attached to the pubic crest.

      The external oblique aponeurosis forms the anterior wall of the inguinal canal and also the lateral edge of the superficial inguinal ring. The rectus abdominis lies posteromedially, and the transversalis posterior to this.

    • This question is part of the following fields:

      • Anatomy
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  • Question 192 - A medical student performed a case control study for her final dissertation. It...

    Incorrect

    • A medical student performed a case control study for her final dissertation. It involved examining marijuana exposure in a group of patients with and without COPD.

      What form of bias is the study most susceptible to?

      Your Answer:

      Correct Answer: Recall bias

      Explanation:

      Case control studies in particular are prone to recall bias, people who are suffering from COPD might sometimes relate the ailment to marijuana usage in past and hence contrary to the control group, they are more able to describe to what extent they have been using the drug in the past.

      As recommended, all the doctors should make sure that there practice is based on evidence and thus it is paramount that the doctors learn to appraise the paper in a critical manner i.e. ability to detect any potential source of bias.

      Detection Bias: Outcomes are more looked for in one group than the other.

      Observer Bias: Subjectivity of observers regarding the outcome.

      Publication bias: Not publishing the results of a valid study just because they are negative or uninteresting can be termed as publication bias.

      Recall bias: Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.

      Response Bias: The participants that filled out the response forms containing information that was going to be used for a trial, don’t represent the target population.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 193 - The spinal cord tracts that transmits the sensations of pain, crude temperature, and...

    Incorrect

    • The spinal cord tracts that transmits the sensations of pain, crude temperature, and light touch is?

      Your Answer:

      Correct Answer: Spinothalamic

      Explanation:

      Dorsal column (ascending tract) – Proprioception, vibration, discriminative

      Spinocerebellar (ascending tract) – Subconscious muscle position and tone

      Corticospinal (descending tract) – Voluntary muscle

      Rubrospinal (descending tract) – Flexor muscle tone

      Vestibulospinal (descending tract) – Reflexes and muscle tone

      Reticulospinal(descending tract) – Voluntary movements, head position.-

      Autonomic – Descending tract.

    • This question is part of the following fields:

      • Anatomy
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  • Question 194 - A 54-year-old man weighing 70kg, underwent mesh repair for inguinal hernia under general...

    Incorrect

    • A 54-year-old man weighing 70kg, underwent mesh repair for inguinal hernia under general anaesthesia. He was given intravenous co-amoxiclav (Augmentin) following which the patient developed widespread urticarial ras, became hypotensive (61/30 mmHg), and showed clinical signs of bronchospasm. Anaphylaxis is suspected in this patient.

      Which one of the following is considered as best initial pharmacological treatment for this condition?

      Your Answer:

      Correct Answer: Intravenous adrenaline 50 mcg

      Explanation:

      The drug of choice for the treatment of anaphylaxis is adrenaline. It has an intravenous route of administration. Since the patient already has intravenous access, the intramuscular route is not appropriate.

      Second-line pharmacological intervention includes the use of chlorpheniramine 10mg intravenous, Hydrocortisone 200mg.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 195 - Which of the following correctly explains the mechanism of lowering blood pressure by...

    Incorrect

    • Which of the following correctly explains the mechanism of lowering blood pressure by nitroglycerine?

      Your Answer:

      Correct Answer: Nitric oxide

      Explanation:

      Nitroglycerine is rapidly denitrated enzymatically in the smooth muscle cell to release the free radical nitric oxide (NO).

      Released NO activated cytosolic guanylyl cyclase which increases cGMP (cyclin guanosine monophosphate) which causes dephosphorylation of myosin light chain kinase (MLCK) through a cGMP-dependent protein kinase.

      Reduced availability of phosphorylated (active) MLCK interferes with activation of myosin and in turn, it fails to interact with actin to cause contraction. Consequently, relaxation occurs.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 196 - A 77-year-old woman is scheduled for day case cataract surgery under local anaesthesia....

    Incorrect

    • A 77-year-old woman is scheduled for day case cataract surgery under local anaesthesia. She has no cardiac or respiratory problems. Lisinopril is being used to treat her hypertension, which is under control.

      Which of the following preoperative investigations are the most appropriate for this patient?

      Your Answer:

      Correct Answer: No investigations

      Explanation:

      Because the patient has mild systemic disease, he is ASA 2 and the procedure will be performed under local anaesthesia.

      The following factors should be considered when requesting preoperative investigations:

      Indications derived from a preliminary clinical examination
      Whether or not a general anaesthetic will be used, the possibility of asymptomatic abnormalities, and the scope of the surgery.

      No special investigations are needed if the patient has no history of significant systemic disease and no abnormal findings on examination during the nurse-led assessment.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 197 - Left ventricular afterload is mostly calculated from systemic vascular resistance.

    Which...

    Incorrect

    • Left ventricular afterload is mostly calculated from systemic vascular resistance.

      Which one of the following factors has most impact on systemic vascular resistance?

      Your Answer:

      Correct Answer: Small arterioles

      Explanation:

      Systemic vascular resistance (SVR), also known as total peripheral resistance (TPR), is the amount of force exerted on circulating blood by the vasculature of the body. Three factors determine the force: the length of the blood vessels in the body, the diameter of the vessels, and the viscosity of the blood within them. The most important factor that determines the systemic vascular resistance (SVR) is the tone of the small arterioles.

      These are otherwise known as resistance arterioles. Their diameter ranges between 100 and 450 µm. Smaller resistance vessels, less than 100 µm in diameter (pre-capillary arterioles), play a less significant role in determining SVR. They are subject to autoregulation.

      Any change in the viscosity of blood and therefore flow (such as due to a change in haematocrit) might also have a small effect on the measured vascular resistance.

      Changes of blood temperature can also affect blood rheology and therefore flow through resistance vessels.

      Systemic vascular resistance (SVR) is measured in dynes·s·cm-5

      It can be calculated from the following equation:

      SVR = (mean arterial pressure − mean right atrial pressure) × 80 cardiac output

    • This question is part of the following fields:

      • Physiology
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  • Question 198 - Which statement most accurately describes the action of increasing the gain in ultrasound...

    Incorrect

    • Which statement most accurately describes the action of increasing the gain in ultrasound imaging?

      Your Answer:

      Correct Answer: Amplifies the returning signal

      Explanation:

      A higher frequency ultrasound comes with a better resolution of the digital image. Ultrasound with a frequency of 15 MHz is best used in imaging of superficial organs such as the thyroid gland, muscles, tendons and breasts whereas deep organs are better imaged using a lower frequency of 2-7MHz because of its ability for deeper penetration but lower resolution. These low frequency probes are also used to diagnose ascites, pleural effusions or can be used in echocardiography.

      The US probe emits and then absorbs a reflected wave. Similar to brightness control, increasing the gain will amplify the return signal which is then attenuated by the tissue. This increases the signal to noise ratio.
      A high frame rate, which basically means the number of times an image is updated onto the screen per second, improves the resolution of a moving 3D image which has become more accurate as the computing power has increased.

      Widening of the image field can be obtained by altering the penetration depth which is obtained by changing the frequency of the US beam

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 199 - A 70-year old male has diverticular disease and is undergoing a sigmoid colectomy....

    Incorrect

    • A 70-year old male has diverticular disease and is undergoing a sigmoid colectomy. His risk of developing a post operative would infection can be minimized by which of the following interventions?

      Your Answer:

      Correct Answer: Administration of single dose of broad spectrum antibiotics prior to the procedure

      Explanation:

      Staphylococcus aureus infection is the most likely cause.

      Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.

      SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
      The organisms are usually derived from the patient’s own body.

      Measures that may increase the risk of SSI include:
      -Shaving the wound using a single use electrical razor with a disposable head
      -Using a non iodine impregnated surgical drape if one is needed
      -Tissue hypoxia
      -Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.

      Measures that may decrease the risk of SSI include:
      1. Intraoperatively
      – Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
      -Cover surgical site with dressing

      In contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.

      2. Post operatively
      Tissue viability advice for management of surgical wounds healing by secondary intention

      Use of diathermy for skin incisions
      In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 200 - Regarding bilirubin, which one of the following statement is true? ...

    Incorrect

    • Regarding bilirubin, which one of the following statement is true?

      Your Answer:

      Correct Answer: Conjugated bilirubin is stored in the gall bladder

      Explanation:

      Bilirubin is the tetrapyrrole and a catabolic product of heme. 70-90% of bilirubin is end product of haemoglobin degradation in the liver.

      Bilirubin circulates in the blood in 2 forms; unconjugated and conjugated bilirubin.

      Unconjugated bilirubin is insoluble in water. It travels through the bloodstream to the liver, where it changes from insoluble into a soluble form (i.e.; unconjugated into conjugated form).

      This conjugated bilirubin travels from the liver into the small intestine and the gut bacteria convert bilirubin into urobilinogen and then into urobilin (not urobilin to urobilinogen). A very small amount passes into the kidneys and is excreted in urine.

    • This question is part of the following fields:

      • Physiology
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Pathophysiology (2/2) 100%
Physiology (0/1) 0%
Anatomy (1/1) 100%
Pharmacology (0/1) 0%
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