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Question 1
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Which of the following statements is true regarding drug dose and response?
Your Answer: Intrinsic activity determines maximal response
Explanation:There are two types of drug dose-response relationships, namely, the graded dose-response and the quantal dose-response relationships.
Drug response curves are plotted as percentage response again LOG drug concentration. This graph is sigmoid in shape.
Agonists are drugs with high affinity and high intrinsic activity. Meanwhile, the antagonist is a drug with high affinity but no intrinsic activity. Intrinsic activity determines the maximal response. The maximal response can be achieved even by activation of a small proportion of receptor sites.
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This question is part of the following fields:
- Pharmacology
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Question 2
Correct
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A 61-year-old woman with myasthenia gravis is admitted to the ER with type II respiratory failure. There is a suspicion of myasthenic crisis.
She is in a semiconscious state. Her blood pressure is 160/90 mmHg, pulse is 110 beats per minute, temperature is 37°C, and oxygen saturation is 84 percent.
With a PaCO2 of 75 mmHg (10 kPa) breathing air, blood gas analysis confirms she is hypoventilating.
Which of the following values is the most accurate representation of her alveolar oxygen tension (PAO2)?Your Answer: 7.3
Explanation:The following is the alveolar gas equation:
PAO2 = PiO2 − PaCO2/R
Where:
PAO2 is the partial pressure of oxygen in the alveoli.
PiO2 is the partial pressure of oxygen inhaled.
PaCO2 stands for partial pressure of carbon dioxide in the arteries.
The amount of carbon dioxide produced (200 mL/minute) divided by the amount of oxygen consumed (250 mL/minute) equals R = respiratory quotient. With a normal diet, the value is 0.8.By subtracting the partial pressure exerted by water vapour at body temperature, the PiO2 can be calculated:
PiO2 = 0.21 × (100 kPa − 6.3 kPa)
PiO2 = 19.8Substituting:
PAO2 = 19.8 − 10/0.8
PAO2 = 19.8 − 12.5
PAO2 = 7.3k Pa -
This question is part of the following fields:
- Physiology
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Question 3
Correct
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About the mechanism of action of bendroflumethiazide, Which of the following is correct?
Your Answer: Sodium-chloride symporter inhibitor
Explanation:Sodium-chloride symporter inhibitor.
The thiazide sensitive sodium chloride symporter is inhibited by thiazides at the proximal portion of the distal convoluted tubule leading to increased sodium and water excretion. Increased delivery of sodium to the distal portion of the distal convoluted tubule promotes potassium loss. This is why thiazides are associated with hyponatraemia and hypokalaemia.
Carbonic anhydrase inhibitors are used mainly in the treatment of glaucoma. They act on the proximal convoluted tubule to promote bicarbonate, sodium and potassium loss.
Sodium potassium chloride symporter is inhibited by Loop diuretics.
Epithelial sodium channels are inhibited by Amiloride.
Drugs which lead to nephrogenic diabetes insipidus such as lithium and demeclocycline, are Inhibitors of vasopressin. -
This question is part of the following fields:
- Pharmacology
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Question 4
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An elderly man complains of a vague lump near his stomach to his physician. On examination, the lump is visible on coughing and is found within Hesselbach's triangle.
Which of the following is true regarding the borders for this triangle?Your Answer: Inguinal ligament inferiorly, inferior epigastric vessels laterally, lateral border of rectus sheath medially
Explanation:The inguinal triangle of Hesselbach is an important clinical landmark on the posterior wall of the inguinal canal. It has the following relations:
Inferiorly – medial third of the inguinal ligament
Medially – lower lateral border of the rectus abdominis
Laterally – inferior epigastric vesselsDirect inguinal hernia is when the bowel bulges directly through the abdominal wall. These hernias usually protrude through Hesselbach’s triangle
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This question is part of the following fields:
- Anatomy
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Question 5
Correct
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Which of the following options will likely play a major role in falling coronary blood flow?
Your Answer: Intracoronary artery infusion of endothelin-1
Explanation:Endothelin-1 is considered as a powerful coronary vasoconstrictor, produced by the endothelium. It acts to counter the effects of Nitric oxide (NO).
Neuropeptide-Y, angiotensin1, cocaine, vasopressin, and nicotine are some other coronary vasoconstrictors.Chronotrophy and inotrophy occur after the activation of sympathetic nerve fibres, which in turn results in increasing the myocardial oxygen consumption, leading to increased coronary blood flow via local metabolic processes.
An alpha-receptor mediated coronary vasoconstrictor effect is also initiated that usually competes with vasodilation, resulting in decreased coronary vascular resistance. Some of the other dilators include hydrogen ions, CO2, potassium, and lactic acid. The action of endothelial NO synthase (eNOS) on L-arginine results in the formation of NO. This messenger also plays a vital role in the regulation of coronary blood flow via vasodilation, inhibition of platelet aggression, and decreasing vascular resistance.
Adenosine is considered as purine nucleoside that forms after the breakdown of adenosine triphosphate (ATP). Adenosine binds to adenosine type 2A (A2A) receptors in coronary vascular smooth muscles. These are coupled to the Gs protein. This mechanism leads to hyperpolarisation of muscle cells, resulting in relaxation and increased coronary blood flow.GTN is an veno and arteriolar dilator, which behaves as pro-drug with NO.
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This question is part of the following fields:
- Pathophysiology
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Question 6
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A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure, the ileocolic artery is ligated. Which vessel does this artery originate from?
Your Answer: Superior mesenteric artery
Explanation:The ileocolic artery is the terminal branch of the superior mesenteric artery. It supplies:
1. terminal ileum
2. proximal right colon
3. cecum
4. appendix (via its branch of the appendicular artery)As veins accompany arteries in the mesentery and are lined by lymphatics, high ligation is the norm in cancer resections—the ileocolic artery branches off the SMA near the duodenum.
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This question is part of the following fields:
- Anatomy
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Question 7
Correct
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Which of the following causes the right-sided shift of the oxygen haemoglobin dissociation curve?
Your Answer: Chronic iron deficiency anaemia
Explanation:With respect to oxygen transport in cells, almost all oxygen is transported within erythrocytes. There is limited solubility and only 1% is carried as solution. Thus, the amount of oxygen transported depends upon haemoglobin concentration and its degree of saturation.
Haemoglobin is a globular protein composed of 4 subunits. Haem is made up of a protoporphyrin ring surrounding an iron atom in its ferrous state. The iron can form two additional bonds – one is with oxygen and the other with a polypeptide chain.
There are two alpha and two beta subunits to this polypeptide chain in an adult and together these form globin. Globin cannot bind oxygen but can bind to CO2 and hydrogen ions.
The beta chains are able to bind to 2,3 diphosphoglycerate. The oxygenation of haemoglobin is a reversible reaction. The molecular shape of haemoglobin is such that binding of one oxygen molecule facilitates the binding of subsequent molecules.The oxygen dissociation curve (ODC) describes the relationship between the percentage of saturated haemoglobin and partial pressure of oxygen in the blood.
Of note, it is not affected by haemoglobin concentration.Chronic anaemia causes 2, 3 DPG levels to increase, hence shifting the curve to the right
Haldane effect – Causes the ODC to shift to the left. For a given oxygen tension there is increased saturation of Hb with oxygen i.e. Decreased oxygen delivery to tissues.
This can be caused by:
-HbF, methaemoglobin, carboxyhaemoglobin
-low [H+] (alkali)
-low pCO2
-ow 2,3-DPG
-ow temperatureBohr effect – causes the ODC to shifts to the right = for given oxygen tension there is reduced saturation of Hb with oxygen i.e. Enhanced oxygen delivery to tissues. This can be caused by:
– raised [H+] (acidic)
– raised pCO2
-raised 2,3-DPG
-raised temperature -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 8
Correct
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A delayed hypersensitivity reaction is type ____?
Your Answer: IV
Explanation:Type I – immediate hypersensitivity reaction
Examples are: Atopy, urticaria, Anaphylaxis, Asthma( IgE mediated).
Type II – Antibody mediated cytotoxic reaction
Examples are: Autoimmune haemolytic anaemia, Thrombocytopenia( IgM or IgG mediated).
Type III – Immune complex mediated reaction
Examples are: Serum sickness,SLE – IgG., Farmers lungs, rheumatoid arthritis
Type IV – Delayed hypersensitivity reaction
Examples are: Contact dermatitis, drug allergies.
Type V – Autoimmune
Graves’
Myasthenia – IgM or IgG. -
This question is part of the following fields:
- Pathophysiology
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Question 9
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Which among the following is not true regarding disease rates?
Your Answer: The odds ratio is synonymous with the risk ratio
Explanation:The relative risk (also known as risk ratio [RR]) is the ratio of risk of an event in one group (e.g., exposed group) versus the risk of the event in the other group (e.g., nonexposed group).
The odds ratio (OR) is the ratio of odds of an event in one group versus the odds of the event in the other group.
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This question is part of the following fields:
- Statistical Methods
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Question 10
Correct
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At a pH of 7, pure water has an hydrogen ion concentration of?
Your Answer: 100 nanomol/L
Explanation:pH is the negative log to the base 10 of hydrogen ion concentration:
So, what power produces the answer?
pH = – log10 [H+]
Making [H+] the subject:
[H+] = 10-pH
Substituting, [H+] = 10-7
One nanomole = 1 x 10-9 or 0.000000001
10-7 = 1x 0.0000001 or 10 x 0.00000001 or 100 x 0.000000001
100 nanomole
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This question is part of the following fields:
- Basic Physics
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