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  • Question 1 - The Kappa statistic (aka Cohen's kappa coefficient) can be used to measure which...

    Correct

    • The Kappa statistic (aka Cohen's kappa coefficient) can be used to measure which of the following?

      Your Answer: Inter-rater reliability

      Explanation:

      The Kappa Statistic or Cohen’s Kappa is a statistical measure of inter-rater reliability for categorical variables. It is used when two raters both apply a criterion based on a tool to assess whether or not some condition occur. A good example can be two doctors rating individuals for diabetes occurrence on the basis of symptoms.

      It gives a quantitative measure of the magnitude of agreement between observers.

      Kappa can take any value between 0 and 1. 0 implies the observers are in complete disagreement and a value of 1 implies complete agreement.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 2 - An experiment is designed to investigate that how three diets having different sugar...

    Incorrect

    • An experiment is designed to investigate that how three diets having different sugar content affect the body weight to a different level.

      Which one of the following test will determine a statistically significant difference among the diets?

      Your Answer: Chi squared test

      Correct Answer: ANOVA

      Explanation:

      Chi-square test is used to determine the statistically significant different between categorical variables. It also determines the difference between expected frequencies and the observed frequencies.

      Mann Whitney U test is used to determine the statistically significant different between two independent groups.

      Wilcoxon’s test is the test of dependency. it determines the statistically significant difference between two dependent groups.

      Student t-test is one of the most commonly used method to test the hypothesis. It determines the significant difference between the means of two different groups.

      ANOVA (analysis of variance) is similar to student’s t-test.

      ANOVA is a statistical method used to determines the statistically significant difference between the mean of more than two group. In this experiment as we are dealing with three different group, ANOVA is most suitable test to determine the difference between each groups.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 3 - Work is underway to devise a new breast cancer screen testing method that...

    Incorrect

    • Work is underway to devise a new breast cancer screen testing method that doesn’t involve mammography which is in contrast to the prevailing standard. The initial numbers look promising and are indicating that the new testing method is better able to pick up early stage cancer. There, however, is not substantial difference in survival rates.

      Which of the following term can be used to describe this?

      Your Answer:

      Correct Answer: Lead-time bias

      Explanation:

      Work up bias involves comparing the novel diagnostic test with the current standard test. A portion of the patients undergo the standard test while others undergo the new test as the standard test is costly. The result can be alteration in specify and sensitivity.

      Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.

      Not publishing the results of a valid study just because they are negative or uninteresting can be termed as publication bias.

      When information gathering is ill suited with respect to time i.e. collecting the data regarding a fatal disease many years after the death of its patients, it is termed as Late – look bias.

      The case in point is an instance of lead time bias when upon comparing two tests, one is able to detect the condition earlier than the other but the overall outcome doesn’t change. There is a possibility that this will make the survival rates for the newer test look more promising.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 4 - Your manager asks you to inform patients that are suffering from a chronic...

    Incorrect

    • Your manager asks you to inform patients that are suffering from a chronic pain about a trial that is going to be conducted in order to determine the efficacy of a novel analgesic. What phase is the trial currently in?

      Your Answer:

      Correct Answer: Phase 2

      Explanation:

      Phase 0 trials assist the scientists in studying the behaviour of drugs in humans by micro dosing patients. They are used to speed up the developmental process. They have no measurable therapeutic effect and efficiency.

      Phase 1 is associated with assessing whether a drug is safe to use or not. The process is extensive and can take up to several months. It also involves healthy participants (less than 100) that are paid to take part in the study. The side effects upon increasing dosage are also addressed by the study. The effects the drug has on humans including how its absorbed, metabolized and excreted are studied. Approximately 70% of the drugs pass this phase.

      Phase 2 trials involve patients that are suffering from the disease under study and are associated with determining the efficiency and the optimum dosage of the drug.

      Phase 3 also assesses the efficacy but at a higher scale with larger population sample.

      Phase 4 trials are involved with the long term effects and side effects of the drug.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 5 - Two different anti-viral treatments are being evaluated for COVID-19 in a clinical study....

    Incorrect

    • Two different anti-viral treatments are being evaluated for COVID-19 in a clinical study.

      Which of the following statistical method should be opted to compare survival time with?

      Your Answer:

      Correct Answer: Hazard ratio

      Explanation:

      The hazard ratio (HR) is simply a comparison of two hazards in a study. It provides an estimate of the ratio of the hazard rates between the experimental group and a control group over the entire study duration. It is typically used when analysing survival over time, hence is the most suitable statistical method in this case.

      An odds ratio is a statistic that quantifies the strength of the association between two events, A and B. It is the “measure of association” for a case-control study.

      The Pearson product-moment correlation coefficient (Pearson’s correlation, for short) is a measure of the strength and direction of association that exists between two variables. An example would be if scientists wanted to evaluate the relationship between quality of certain population of rice and their genetic make-up.

      Relative risk is the ratio of the risks for an event for the exposure group to the risks for the non-exposure group. Thus relative risk provides an increase or decrease in the likelihood of an event based on some exposure. Relative risk measures the association between the exposure and the outcome.

      Absolute risk reduction is the number of percentage points your own risk goes down if you do a preventive act such as stop drinking alcohol. It depends on what your risk factors are to begin with.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 6 - A trail has analysed that a new screening test may increase the survival...

    Incorrect

    • A trail has analysed that a new screening test may increase the survival time of ovarian cancer patients. But analyst say that the apparent increase in the patients survival time is just because of earlier detection instead of actual improvement.

      What kind of bias is in this experiment?

      Your Answer:

      Correct Answer: Lead time bias

      Explanation:

      Observation bias occurs when the behaviour of an individual changes that results from their awareness of being observed.

      Recall bias introduced when participants in a study are systematically more or less likely to recall and relate information on exposure depending on their outcome status.

      Attrition bias is a systematic error caused by unequal loss of participants from a randomized controlled trial (RCT). In clinical trials, participants might dropout due to unsatisfactory treatment or efficacy, intolerable adverse events, or even death.

      Selection bias introduced when the individuals are not chosen randomly to take a part in the study. It usually occurs when the research decides who is going to be studied, they are not the representative of the population.

      Lead-time bias occurs when a disease is detected by a screening test at an earlier time point rather than it would have been diagnosed by its clinical appearance. In this bias, earlier detection improves the survival time in the intervention group.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 7 - Which among the given options can be used to find out the number...

    Incorrect

    • Which among the given options can be used to find out the number needed to treat?

      Your Answer:

      Correct Answer: 1 / (Absolute risk reduction)

      Explanation:

      Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.

      It can be found as:

      NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 8 - In the United Kingdom, a new breast cancer screening test is being conducted...

    Incorrect

    • In the United Kingdom, a new breast cancer screening test is being conducted compared to the conventional use of mammography. This test predicts that if the breast cancer is diagnosed at an earlier stage, it could improve the survival rate but the overall results remains constant.

      This is an example of what kind of bias?

      Your Answer:

      Correct Answer: Lead time bias

      Explanation:

      Recall bias introduced when participants in a study are systematically more or less likely to recall and relate information on exposure depending on their outcome status.

      In procedure bias, the researcher decides assignment of a treatment versus control and assigns particular patients to one group or the other non-randomly. This is unlikely to have occurred in this case, although it is not mentioned specifically.

      Self Selection or volunteer bias occur when those subjects are selected to participate in the study who are not the representative of the entire target population. those subjects may be from high socio-economic status and practice those activities or lifestyle that improves their health.

      Lead-time bias occurs when a disease is detected by a screening test at an earlier time point rather than it would have been diagnosed by its clinical appearance. In this bias, earlier detection improves the survival time in the intervention group.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 9 - A 68-year-old man presents worried about his risk of motor neurone disease. No...

    Incorrect

    • A 68-year-old man presents worried about his risk of motor neurone disease. No symptoms have developed, but his father suffered from motor neurone disease. Recently, his cousin has also been diagnosed with amyotrophic lateral sclerosis. He searched the internet for screening tests for motor neurone disease and found a blood test called ‘neuron’, and requests to have it done. You search this blood test and find a prospective study going on evaluating the potential benefits of this blood test. On average, this test diagnosed patients with the disease 8 months earlier than the patients who are diagnosed on the basis of their clinical symptoms. The patients diagnosed using this neuron test also survived, on average, 48 months from the diagnosis, whereas the patients diagnosed clinically survived an average of 39 months from the diagnosis. Considering the clear benefits, you decide to have it done on the patient.

      Which of the following options best relate to the above scenario?

      Your Answer:

      Correct Answer: Lead-time bias

      Explanation:

      Hypochondriasis is an illness anxiety disorder, and describes excessively worriedness about the presence of a disease. While the woman is concerned about her possibility of developing motor neurone disease, she understands that no symptoms have yet appeared. Hypochondriasis involves patients who refuse to accept that they don’t have the disease, even if the results come back negative.

      Late Look Bias occurs when the data is gathered or analysed at an inappropriate time e.g. when many of the subjects suffering from a fatal disease have died. This type of biasness might occur in some retrospective studies of motor neurone disease, but is not applicable to this prospective study.

      In procedure bias, the researcher decides assignment of a treatment versus control and assigns particular patients to one group or the other non-randomly. This is unlikely to have occurred in this case, although it is not mentioned specifically. Of all the options, lead time-bias is a better answer.

      The Hawthorne Effect refers to groups modifying their behaviour simply because they are aware of being observed. Any differences in the behaviour have not been mentioned in the question, and it is highly unlikely that a change in patient’s behaviour would have affected their length of survival in this case.

      The correct option is lead-time bias. Even if the new blood test diagnoses the disease earlier, it doesn’t affect the outcome, as the survival time was still on average 43 months from the onset of symptoms in both groups. With the help of blood test, the disease was only detected 8 months earlier.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 10 - Which of the given statements is true about standard error of the mean?...

    Incorrect

    • Which of the given statements is true about standard error of the mean?

      Your Answer:

      Correct Answer: Gets smaller as the sample size increases

      Explanation:

      The standard error of the mean (SEM) is a measure of the spread expected for the mean of the observations – i.e. how ‘accurate’ the calculated sample mean is from the true population mean. The relationship between the standard error of the mean and the standard deviation is such that, for a given sample size, the standard error of the mean equals the standard deviation divided by the square root of the sample size.

      SEM = SD / square root (n)

      where SD = standard deviation and n = sample size

      Therefore, the SEM gets smaller as the sample size (n) increases.

      If we want to depict how widely scattered some measurements are, we use the standard deviation. For indicating the uncertainty around the estimate of the mean, we use the standard error of the mean. The standard error is most useful as a means of calculating a confidence interval. For a large sample, a 95% confidence interval is obtained as the values 1.96×SE either side of the mean.

      A 95% confidence interval:

      lower limit = mean – (1.96 * SEM)

      upper limit = mean + (1.96 * SEM)

      Results such as mean value are often presented along with a confidence interval. For example, in a study the mean height in a sample taken from a population is 183cm. You know that the standard error (SE) (the standard deviation of the mean) is 2cm. This gives a 95% confidence interval of 179-187cm (+/- 2 SE).

      Hence, it would be wrong to say that confidence levels do not apply to standard error of the mean.

    • This question is part of the following fields:

      • Statistical Methods
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Statistical Methods (1/2) 50%
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