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  • Question 1 - Which of the following statements is true regarding ketamine? ...

    Correct

    • Which of the following statements is true regarding ketamine?

      Your Answer: Can be used in the management of refractory status epilepticus

      Explanation:

      Ketamine is a phencyclidine (hallucinogenic) derivative that is administered in a dose of 2 mg/kg and acts by blocking NMDA (N-methyl-D-aspartate) receptors of glutamate.

      It is a powerful bronchodilator agent and is, therefore, an intravenous anaesthetic of choice in bronchial asthma (halothane is an inhalational anaesthetic agent of choice for bronchial asthma). It is also used in the management of refractory status epilepticus.

      It is an acid solution with an elimination half-life of three hours.

      It has S (+) enantiomer and R (-) enantiomer. the S(+) enantiomer is two to four times more potent than the R(-) and is less likely to produce hallucinations.

      Its use is contraindicated in patients with ischaemic heart disease because it increased sympathetic outflow leading to tachycardia and increased cardiac output which in turn increases the myocardial oxygen demand.

    • This question is part of the following fields:

      • Pharmacology
      796.5
      Seconds
  • Question 2 - In the adrenal gland: ...

    Correct

    • In the adrenal gland:

      Your Answer: Catecholamine release is mediated by cholinergic nicotinic transmission

      Explanation:

      The adrenal (suprarenal) gland is composed of two main parts: the adrenal cortex, which is the largest and outer part of the gland, and the adrenal medulla. The adrenal cortex consists of three zones: 1. Zona glomerulosa (outermost layer) is responsible for the production of mineralocorticoids, mainly aldosterone, which regulates blood pressure and electrolyte balance. 2. Zona fasciculata (middle layer) is responsible for the production of glucocorticoids, predominantly cortisol, which increases blood sugar levels via gluconeogenesis, suppresses the immune system, and aids in metabolism. It also produces 11-deoxycorticosterone and corticosterone in addition to cortisol. 3. Zona reticularis (innermost layer) is responsible for the production of gonadocorticoids, mainly dehydroepiandrosterone (DHEA), which serves as the starting material for many other important hormones produced by the adrenal gland, such as oestrogen, progesterone, testosterone, and cortisol. It is also responsible for administering these hormones to the reproductive regions of the body.

      The adrenal medulla majorly secretes epinephrine (adrenaline), and norepinephrine in small quantity. Both hormones have similar functions and initiate the flight or fight response.

      Catecholamine is mediated by cholinergic nicotinic transmission through changes in sympathetic nervous system (T5 – T11), being increased during stress and hypoglycaemia.

      Blood supply to the adrenal gland is by these three arteries: superior suprarenal arteries, middle suprarenal artery and inferior suprarenal artery. Venous drainage is via the suprarenal vein to the left renal vein or directly to the inferior vena cava on the right side. There is no portal (venous) system between cortex and medulla.

    • This question is part of the following fields:

      • Anatomy
      87.1
      Seconds
  • Question 3 - Which of the following statements is the most correct about ketamine? ...

    Correct

    • Which of the following statements is the most correct about ketamine?

      Your Answer: The S (+) isomer is more potent that the R (-) isomer

      Explanation:

      Ketamine, a phencyclidine derivative, is an antagonist at the NMDA receptor. It causes depression of the CNS that is dose dependent and induces a dissociative anaesthetic state with profound analgesia and amnesia.

      Ketamine has a chiral centre usually presented as a racemic mixture with two optical isomers, S (+) and R (-) forms. These isomers are in equal proportions. The S (+) isomer is about three times more potent than the R (-) form. The S (+) form is less likely to cause emergence delirium and hallucinations.

      Ketamine is extensively metabolised by hepatic microsomal cytochrome P450 enzymes producing norketamine as its main metabolite. Norketamine has a one third to one fifth as potency as its parent compound.
      It increases the CMRO2, cerebral blood flow and potentially increase intracranial pressure.

    • This question is part of the following fields:

      • Pharmacology
      77.6
      Seconds
  • Question 4 - A 62-year-old woman, presents to emergency department with an ischaemic left colon.

    Multiple...

    Correct

    • A 62-year-old woman, presents to emergency department with an ischaemic left colon.

      Multiple arteries arise from the aorta at the level of the L3 vertebrae, which is most likely to be involved in this pathology?

      Your Answer: Inferior mesenteric artery

      Explanation:

      The inferior mesenteric artery arises from the abdominal aorta at the level of the L3 vertebrae and supplies blood to the final third of the transverse colon, the descending colon, the sigmoid colon and the uppermost part of the rectum.

      It is the artery most likely to affect the left colon.

    • This question is part of the following fields:

      • Anatomy
      373.4
      Seconds
  • Question 5 - A strict diet is mandatory for which of the following drugs for mood...

    Correct

    • A strict diet is mandatory for which of the following drugs for mood disorders?

      Your Answer: Tranylcypromine

      Explanation:

      Tranylcypromine is a monoamine oxidase inhibitor that binds irreversibly to target enzyme.

      Monoamine oxidase inhibitors are responsible for blocking the monoamine oxidase enzyme. The monoamine oxidase enzyme breaks down different types of neurotransmitters from the brain: norepinephrine, serotonin, dopamine, and tyramine. MAOIs inhibit the breakdown of these neurotransmitters thus, increasing their levels and allowing them to continue to influence the cells that have been affected by depression.

      There are two types of monoamine oxidase, A and B. The MAO A is mostly distributed in the placenta, gut, and liver, but MAO B is present in the brain, liver, and platelets. Serotonin and noradrenaline are substrates of MAO A, but phenylethylamine, methylhistamine, and tryptamine are substrates of MAO B. Dopamine and tyramine are metabolized by both MAO A and B. Selegiline and rasagiline are irreversible and selective inhibitors of MAO type B, but safinamide is a reversible and selective MAO B inhibitor.

      MAOIs prevent the breakdown of tyramine found in the body and certain foods, drinks, and other medications. Patients that take MAOIs and consume tyramine-containing foods or drinks will exhibit high serum tyramine level. A high level of tyramine can cause a sudden increase in blood pressure, called the tyramine pressor response. Even though it is rare, a high tyramine level can trigger a cerebral haemorrhage, which can even result in death.

      Eating foods with high tyramine can trigger a reaction that can have serious consequences. Patients should know that tyramine can increase with the aging of food; they should be encouraged to have fresh foods instead of leftovers or food prepared hours earlier. Examples of high levels of tyramine in food are types of fish and types of meat, including sausage, turkey, liver, and salami. Also, certain fruits can contain tyramine, like overripe fruits, avocados, bananas, raisins, or figs. Further examples are cheeses, alcohol, and fava beans; all of these should be avoided even after two weeks of stopping MAOIs. Anyone taking MAOIs is at risk for an adverse hypertensive reaction, with accompanying morbidity. Patients taking reversible MAOIs have fewer dietary restrictions.

      Amitriptyline is a tricyclic antidepressant, and citalopram and escitalopram are selective serotonin reuptake inhibitors.

    • This question is part of the following fields:

      • Pharmacology
      387
      Seconds
  • Question 6 - Which of the following statements is true regarding prazosin? ...

    Correct

    • Which of the following statements is true regarding prazosin?

      Your Answer: Is a selective alpha 1 adrenergic receptor antagonist.

      Explanation:

      Selective ?1 -Blockers like prazosin, terazosin, doxazosin, and alfuzosin cause a decrease in blood pressure with lesser tachycardia than nonselective blockers (due to lack of ?2 blocking action.

      The major adverse effect of these drugs is postural hypotension. It is seen with the first few doses or on-dose escalation (First dose effect).

      Its half-life is approximately three hours.

      It is excreted primarily through bile and faeces (not through kidneys)

    • This question is part of the following fields:

      • Pharmacology
      374.9
      Seconds
  • Question 7 - What is the name of the space between the vocal cords? ...

    Correct

    • What is the name of the space between the vocal cords?

      Your Answer: Rima glottidis

      Explanation:

      The rima glottidis is a narrow, triangle-shaped opening between the true vocal cords.

      The vocal folds (true vocal cords) control sound production. The apex of each fold projects medially into the laryngeal cavity.

      Each vocal fold includes these vocal ligaments:

      Vocalis muscle (most medial part of thyroarytenoid muscle)

      The glottis is composed of the vocal folds, processes and rima glottidis.

      The rima glottidis is the narrowest potential site within the larynx, as the vocal cords may be completely opposed, forming a complete barrier.

    • This question is part of the following fields:

      • Anatomy
      177
      Seconds
  • Question 8 - Which of the following statement is true regarding the mechanism of action of...

    Correct

    • Which of the following statement is true regarding the mechanism of action of doxycycline?

      Your Answer: Inhibit 30S subunit of ribosomes

      Explanation:

      Doxycycline belongs to the family of tetracyclines and inhibits protein synthesis through reversible binding to bacterial 30s ribosomal subunits, which prevent binding of new incoming amino acids (aminoacyl-tRNA) and thus interfere with peptide growth.

    • This question is part of the following fields:

      • Pharmacology
      7.1
      Seconds
  • Question 9 - Of the stated laws, which is correct? ...

    Correct

    • Of the stated laws, which is correct?

      Your Answer: Boyle's law states that at constant temperature the volume of a given mass of gas varies inversely with absolute pressure.

      Explanation:

      Boyle’s law is correctly stated as it states that the volume of a gas of known mass is inversely proportional with absolute pressure, at a constant temperature.

      Beer’s law states that radiation absorption by a solution of known thickness and concentration is identical to that of a solution of double thickness and half concentration.

      Bougner’s (or Lambert’s) law states that every layer with the same thickness will absorb the same amount of radiation as it passes through.

      Graham’s law states that the diffusion rate of a gas is inversely related to the square root of its molecular weight.

      Raoult’s law states that the reduction of a solvent’s vapour pressure is directly proportional to the solute’s molar concentration.

    • This question is part of the following fields:

      • Statistical Methods
      118.7
      Seconds
  • Question 10 - During a squint surgery, a 5-year-old child developed severe bradycardia as a result...

    Correct

    • During a squint surgery, a 5-year-old child developed severe bradycardia as a result of the oculocardiac reflex.

      The afferent limb of this reflex is formed by which nerve?

      Your Answer: Trigeminal nerve

      Explanation:

      When the eye is compressed or the extra-ocular muscles are tractioned, the oculocardiac reflex causes a decrease in heart rate.

      The ophthalmic division of the trigeminal nerve provides the afferent limb. This synapses with the vagus nerve’s visceral motor nucleus in the brainstem. The efferent signal is carried by the vagus nerve to the heart, where increased parasympathetic tone reduces sinoatrial node output and slows heart rate.

      The most common symptom is sinus bradycardia, but junctional rhythm and asystole can also occur.

    • This question is part of the following fields:

      • Pathophysiology
      467.5
      Seconds
  • Question 11 - Which of the following is true in the Kreb's cycle? ...

    Correct

    • Which of the following is true in the Kreb's cycle?

      Your Answer: Alpha-ketoglutarate is a five carbon molecule

      Explanation:

      Krebs’ cycle (tricarboxylic acid cycle or citric acid cycle) is a sequence of reactions to release stored energy through oxidation of acetyl coenzyme A (acetyl-CoA). Some of the products are carbon dioxide and hydrogen atoms.

      The sequence of reactions, known collectively as oxidative phosphorylation, only occurs in the mitochondria (not cytoplasm).

      The Krebs cycle can only take place when oxygen is present, though it does not require oxygen directly, because it relies on the by-products from the electron transport chain, which requires oxygen. It is therefore considered an aerobic process. It is the common pathway for the oxidation of carbohydrate, fat and some amino acids, required for the formation of adenosine triphosphate (ATP).

      Pyruvate enters the mitochondria and is converted into acetyl-CoA. Acetyl-CoA is then condensed with oxaloacetate, to form citrate which is a six carbon molecule. Citrate is subsequently converted into isocitrate, alpha-ketoglutarate, succinyl-CoA, succinate, fumarate, malate and finally oxaloacetate.

      The only five carbon molecule in the cycle is Alpha-ketoglutarate.

    • This question is part of the following fields:

      • Physiology
      72.2
      Seconds
  • Question 12 - A 35-year-old female, presents to the emergency department via ambulance. The paramedics have...

    Correct

    • A 35-year-old female, presents to the emergency department via ambulance. The paramedics have noted the patient's symptoms as unilateral left-sided weakness of the upper and lower limbs, homonymous hemianopia and dysphasia.
      She has previous personal and family history of deep vein thromboses.
      The report of her CT scan suggests a stroke involving the middle cerebral artery.
      Post recovery, she undergoes further diagnostic investigations to determine the cause of a stroke at her young age. She is eventually diagnosed with a hypercoagulable state disease called Factor V Leiden thrombophilia.

      An emboli in the middle cerebral artery results in dysfunction of which areas of the brain?

      Your Answer: Frontal, temporal and parietal lobes

      Explanation:

      The middle cerebral artery is a part of the circle of Willis system of anastomosis within the brain, and the most often affected by brain pathology.

      The primary function of the middle cerebral artery is providing oxygenated blood to related regions of the brain. It achieves this by giving off different branches to supply different brain regions, namely:

      The cortical branches: which supplies the primary motor and somatosensory cortical areas of some parts of the face, trunk and upper limbs.

      The small central branches: which supply the basal ganglia and internal capsule via the lenticulostriate vessels.

      The superior division: which supplies the lateral inferior frontal lobe, including the Broca area which is responsible for production of speech, language comprehension, and writing.

      The inferior division: which supplies the superior temporal gyrus, including Wernicke’s area which controls speech comprehension and language development.

    • This question is part of the following fields:

      • Anatomy
      236.5
      Seconds
  • Question 13 - With regards to the repolarisation phase of the myocardial action potential, which of...

    Correct

    • With regards to the repolarisation phase of the myocardial action potential, which of the following is responsible?

      Your Answer: Efflux of potassium

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
      151.9
      Seconds
  • Question 14 - A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath...

    Correct

    • A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath and pleuritic chest pain. Her work requires her to travel internationally frequently. The consultant makes a diagnosis and treats her.

      Now, the consultant recommends placing a filter that will prevent future incidents. A needle is placed into the femoral vein and passed up into the abdomen to insert the filter.

      What is true regarding the organ where the filter is placed for this patient's condition?

      Your Answer: It is located posteriorly to the peritoneum

      Explanation:

      The patient likely suffers from pulmonary embolism due to her history of frequent international travels. A filter is placed in the inferior vena cava to decrease the risk of future episodes of pulmonary embolism. The IVC filter is a small, wiry device that can catch blood clots and stop them from going into the heart and lungs. Your IVC is a major vessel that brings deoxygenated blood from the lower body to the heart, from where it is pumped into the lungs.

      The filter is placed via a thin catheter inserted into the femoral vein in the groin. The catheter is gently moved up into your IVC, and a filter is introduced.

      The IVC is a retroperitoneal organ.

    • This question is part of the following fields:

      • Anatomy
      438.5
      Seconds
  • Question 15 - What structure lies deepest within the popliteal fossa? ...

    Correct

    • What structure lies deepest within the popliteal fossa?

      Your Answer: Popliteal artery

      Explanation:

      The popliteal fossa is the shallow, diamond-shaped depression located in the back of the knee joint.

      The structures that lie within in from superficial to deep are:

      The tibial and common fibular nerve: Most superficial. They arise from the sciatic nerve.
      The popliteal vein
      The popliteal artery: Lies deepest. It arises from the femoral artery

      Boundaries of the popliteal fossa:

      Laterally
      Biceps femoris above, lateral head of gastrocnemius and plantaris below

      Medially
      Semimembranosus and semitendinosus above, medial head of gastrocnemius below

      Floor
      Popliteal surface of the femur, posterior ligament of knee joint and popliteus muscle

      Roof
      Superficial and deep fascia

    • This question is part of the following fields:

      • Anatomy
      33.5
      Seconds
  • Question 16 - Heights of 100 individuals(adults) who were administered steroids at any stage during childhood...

    Correct

    • Heights of 100 individuals(adults) who were administered steroids at any stage during childhood was studied. The mean height was found to be 169cm with the data having a standard deviation of 16cm. What will be the standard error associated with the mean?

      Your Answer: 1.6

      Explanation:

      Standard error can be calculated by the following formula:
      Standard Error= (Standard Deviation)/√(Sample Size)
      = (16) / √(100)
      = 16 / 10
      = 1.6

    • This question is part of the following fields:

      • Statistical Methods
      189.5
      Seconds
  • Question 17 - Among the following options, which one can not be the value of Pearson's...

    Correct

    • Among the following options, which one can not be the value of Pearson's correlation coefficient?

      Your Answer: 1.5

      Explanation:

      The correlation coefficient gives us the idea about relation between two parameters. i.e. to what extent change in parameter A could prompt a change in parameter B. The numerical value of correlation coefficient could not be greater than 1.

    • This question is part of the following fields:

      • Statistical Methods
      155.2
      Seconds
  • Question 18 - Anaesthetic gas concentrations can be measured using a refractometer. The main principal which...

    Correct

    • Anaesthetic gas concentrations can be measured using a refractometer. The main principal which allows it to be used for this purpose is which of the following?

      Your Answer: Refraction

      Explanation:

      Refractometers measure the degree to which the light changes direction, called the angle of refraction. A refractometer takes the refraction angles and correlates them to refractive index (nD) values that have been established. Using these values, you can determine the concentrations of solutions.

    • This question is part of the following fields:

      • Basic Physics
      10.2
      Seconds
  • Question 19 - A patient has a myocardial infarction with anterior ST elevation. There are the...

    Incorrect

    • A patient has a myocardial infarction with anterior ST elevation. There are the following observations:

      Cardiac output 2.0 L/min
      Blood pressure 80/60 mmHg
      CVP 20 mmHg
      SpO2 91% on 4 L/min oxygen

      What is the most logical physiological explanation for these findings?

      Your Answer:

      Correct Answer: Biventricular failure

      Explanation:

      The occlusion of the left anterior descending (LAD) coronary artery causes anterior ST elevation myocardial infarction (STEMI). It has the worst prognosis of all the infarct locations due to its larger infarct size. It has a higher rate of total mortality (27 percent versus 11 percent), heart failure (41 percent versus 15 percent), and a lower ejection fraction on admission than an inferior myocardial infarction (38 percent versus 55 percent ).

      The LAD artery supplies the majority of the interventricular septum, as well as the anterior, lateral, and apical walls of the left ventricle, as well as the majority of the right and left bundle branches and the bicuspid valve’s anterior papillary muscle (left ventricle).

      The left or right ventricle’s end-diastolic volume (EDV) is the volume of blood in each chamber at the end of diastole before systole. Preload is synonymous with the EDV.

      120 mL is a typical left ventricular EDV (range 65-240 mL). The EDV of the right ventricle in a typical range is (100-160 mL).

      With an ejection fraction (EF) of less than 45 percent, the patient is most likely suffering from systolic dysfunction. Increases in right and left ventricular end-diastolic pressures and volumes are likely with a reduced EF because the ventricles are not adequately emptied. The left atrium and the pulmonary vasculature are affected by the increased pressures on the left side of the heart.

      By causing an imbalance of the Starling forces acting across the capillaries, increased hydrostatic pressure in the pulmonary circulation favours the development of pulmonary oedema. With cardiogenic pulmonary oedema, capillary permeability is likely to remain unchanged.

      Biventricular failure will result as a result of the pressure changes being transmitted to the right side of the circulation. The patient’s systemic vascular resistance is likely to be elevated as well, but it is not the most likely cause of his symptoms. The patient is suffering from cardiogenic shock as a result of biventricular failure. The patient has low cardiac output and is hypotensive. Right ventricular filling pressures are elevated, indicating right ventricular dysfunction.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 20 - Which statement regarding the cardiac action potential is correct? ...

    Incorrect

    • Which statement regarding the cardiac action potential is correct?

      Your Answer:

      Correct Answer:

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 21 - Which statement is correct about the Mapleson anaesthetic breathing circuits? ...

    Incorrect

    • Which statement is correct about the Mapleson anaesthetic breathing circuits?

      Your Answer:

      Correct Answer: Mapleson A is most efficient for spontaneous ventilation

      Explanation:

      Mapleson breathing system (or circuit) analysed five different arrangements of components of the breathing system:
      Mapleson A – It is the most efficient for spontaneous respiration. The flow of fresh gas required is 70-85 ml/kg/min, i.e., approximately 5-6 lit./min fresh gas flow for an average adult.
      Mapleson B and C – inefficient for both SV and PPV; requires gas flow of two to three times minute volume (100 ml/kg/min). Not commonly used but category C may be used for emergency resuscitation.
      Mapleson D – efficient for PPV at gas flow equivalent to patient’s minute volume; the Bain’s circuit is a coaxial version of the Mapleson D
      Mapleson E and F – for paediatric use; requires gas flow at two to three times the patient’s minute volume. The Mapleson F consists of an open-ended reservoir bag (Jackson-Rees modification).

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 22 - Regarding the use of soda lime as part of a modern circle system...

    Incorrect

    • Regarding the use of soda lime as part of a modern circle system with a vaporiser outside the circuit (VOC), which of the following is its most deleterious consequence?

      Your Answer:

      Correct Answer: Carbon monoxide formation

      Explanation:

      When using dry soda lime for VOCs, very high amounts of carbon monoxide may be produced, regardless of the inhalational anaesthetic agent used. The carbon monoxide produced is sufficient enough to cause cytotoxic and anaemic hypoxia. To prevent this, soda lime canisters are shaken well to even out the packing of granules. This can help to evenly distribute gas flow for proper CO2 absorption and ventilation.

      Compound A is formed when dry soda lime, or soda lime in high temperature, reacts with the inhalational anaesthetic Sevoflurane. Animal studies have shown renal toxicity in rats, but renal adverse effects in humans are yet to be observed.

      When monitors are not employed with VOCs, deleterious effects are not for certain. However, monitors not employed with vaporiser inside the circuit (VIC) can lead to significant adverse events.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 23 - A 28-year-old man is admitted to the critical care unit. He has been...

    Incorrect

    • A 28-year-old man is admitted to the critical care unit. He has been diagnosed with adult respiratory distress syndrome and is being ventilated. His haemodynamic condition is improved using a pulmonary artery flotation.

      His readings are listed below:

      Haemoglobin concentration: 10 g/dL
      Mixed venous oxygen saturation: 70%
      Mixed venous oxygen tensions (PvO2): 50 mmHg

      Estimate his mixed venous oxygen content (mL/100mL).

      Your Answer:

      Correct Answer: 9.5

      Explanation:

      Mixed venous oxygen content (CvO2) is the oxygen concentration in 100mL of mixed venous blood taken from the pulmonary artery. It is usually 12-17 mL/dL (70-75%). It is represented mathematically as:

      CvO2 = (1.34 x Hgb x SvO2 x 0.01) + (0.003 x PvO2)

      Where,

      1.34 = Huffner’s constant
      Hgb = Haemoglobin level (g/dL)
      SvO2 = % oxyhaemoglobin saturation of mixed venous blood
      PvO2 = 0.0225 = mL of O2 dissolved per 100mL plasma per kPa, or 0.003 mL per mmHg

      Therefore,

      CvO2 = (1.34 x 10 x 70 x 0.01) + (0.003 x 50)

      CvO2 = 9.38 + 0.15 = 9.53 mL/100mL

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 24 - The statement that best describes the classification of theatre equipment in terms of...

    Incorrect

    • The statement that best describes the classification of theatre equipment in terms of electrical safety is:

      Your Answer:

      Correct Answer: A floating circuit is equipment applied to patient that is isolated from all its other parts

      Explanation:

      There are different classes of electrical equipment that can be classified in the table below:

      Class 1 – provides basic protection only. It must be connected to earth and insulated from the mains supply

      Class II – provides double insulation for all equipment. It does not require an earth.

      Class III – uses safety extra low voltage (SELV) which does not exceed 24 V AC. There is no risk of gross electrocution but risk of microshock exists.

      Type B – All of above with low leakage currents (0.5mA for Class IB, 0.1 mA for Class IIB)

      Type BF – Same as with other equipment but has ‘floating circuit’ which means that the equipment applied to patient is isolated from all its other parts.

      Type CF – Class I or II equipment with ‘floating circuits’ that is considered to be safe for direct connection with the heart. There are extremely low leakage currents (0.05mA for Class I CF and 0.01mA for Class II CF)

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 25 - Following an uneventful laparoscopic right hemicolectomy, a previously fit and well 75-year-old male...

    Incorrect

    • Following an uneventful laparoscopic right hemicolectomy, a previously fit and well 75-year-old male is admitted to the critical care unit.

      You've been summoned to examine the patient because he's become oliguric.

      Which of the following is most likely to indicate that acute kidney injury is caused by a prerenal cause?

      Your Answer:

      Correct Answer: Serum urea: creatinine ratio 200

      Explanation:

      Prerenal failure has a serum urea: creatinine ratio of >100, while acute kidney injury has a ratio of 40.
      In prerenal failure, ADH levels are typically high, resulting in water, urea, and sodium resorption. The fractional sodium excretion is less than 1%, but it is greater than 2% in acute tubular necrosis.
      Prerenal azotaemia has higher serum urea nitrogen/serum creatinine ratios (>20), whereas acute tubular necrosis has lower ratios (10-15). The normal range is between 12 and 20.
      Urinary sodium is less than 20 in prerenal failure and greater than 40 in acute tubular necrosis.
      Prerenal failure has a urine osmolality of >500, while acute tubular necrosis has an osmolality of 350.
      Prerenal failure has a urine/serum creatinine ratio of >40, while acute tubular necrosis has a urine/serum creatinine ratio of 20.

      The concentrations of serum urea or creatinine change in inverse proportion to glomerular filtration. Changes in serum creatinine concentrations are more reliable than changes in serum urea concentrations in predicting GFR. Creatinine is produced at a constant rate from creatine, and blood concentrations are almost entirely determined by GFR.

      A number of factors influence urea formation, including liver function, protein intake, and protein catabolism rate. Urea excretion is also influenced by hydration status, the amount of water reabsorption, and GFR.

      A high serum creatinine level, as well as a urine output of less than 10 mL/hour and the production of concentrated looking urine, do not necessarily indicate a specific cause of oliguria.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 26 - With respect to the peripheral nerve stimulators, which one is used to perform...

    Incorrect

    • With respect to the peripheral nerve stimulators, which one is used to perform nerve blocking?

      Your Answer:

      Correct Answer:

      Explanation:

      The nerve stimulators deliver a stimulus lasting for 1-2 milliseconds (not second) to perform nerve blockage.

      There are just 2 leads (not 3); one for the skin and other for the needle.

      Prior to the administration of the local anaesthesia, a current of 0.25 – 0.5 mA (not 1-2mA) at the frequency of 1-2 Hz is preferred.

      If the needle tip is close to the nerve, muscular contraction could be possible at the lowest possible current.

      Insulated needles have improved the block success rate, as the current is only conducting through needle tip.

      Stimulus to the femoral nerve which is placed in the mid lingual line causes withdrawer of the quadriceps and knee extension, that’s the dancing patella ( not plantar flexion).

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 27 - A 45-year-old man is being operated on for emergency laparotomy as he presented...

    Incorrect

    • A 45-year-old man is being operated on for emergency laparotomy as he presented with bowel perforation. During the surgery, the marginal artery of Drummond is encountered and preserved.
      Which of the following two arteries fuse to form the marginal artery of Drummond?

      Your Answer:

      Correct Answer: Superior mesenteric artery and inferior mesenteric artery

      Explanation:

      The arteries of the midgut (superior mesenteric artery) and hindgut (inferior mesenteric artery) give off terminal branches that form an anastomotic vessel called the marginal artery of Drummond. It runs in the inner margins of the colon and gives off short terminal branches to the bowel wall.

      The marginal artery is formed by the main branches and arcades arising from the ileocolic, right colic, middle colic, and left colic arteries. It is most apparent in the ascending, transverse, and descending colons and poorly developed in the sigmoid colon.

    • This question is part of the following fields:

      • Anatomy
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  • Question 28 - Which of the following is true regarding the mechanism of action of daptomycin?...

    Incorrect

    • Which of the following is true regarding the mechanism of action of daptomycin?

      Your Answer:

      Correct Answer: Interferes with the outer membrane of gram positive bacteria resulting in cell death

      Explanation:

      Daptomycin alters the curvature of the membrane, which creates holes that leak ions. This causes rapid depolarization, resulting in loss of membrane potential. Thus it interferes with the outer membrane of gram-positive bacteria resulting in cell death.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 29 - All of the following statements are false regarding propranolol except: ...

    Incorrect

    • All of the following statements are false regarding propranolol except:

      Your Answer:

      Correct Answer: Has a plasma half life of 3-6 hours.

      Explanation:

      Propranolol is a nonselective beta-blocker with a half-life of 3 to 6 hours.

      Since it is lipid-soluble it crosses the blood-brain barrier and causes Central Nervous System side effects like sedation, nightmares, and depression.

      They are contraindicated in asthma, Congestive heart failure, and diabetes.

      It has a large volume of distribution with no intrinsic sympathomimetic action.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 30 - A 30-year old male has Von Willebrand's disease and attends the hospital to...

    Incorrect

    • A 30-year old male has Von Willebrand's disease and attends the hospital to get an infusion of desmopressin acetate. The way this works is by stimulating the release of von Willebrand factor from cells, which in turn increases factor VIII and platelet plug formation in clotting.

      In patients that have no clotting abnormalities, the substance that keeps the blood soluble and prevents platelet activation normally is which of these?

      Your Answer:

      Correct Answer: Prostacyclin

      Explanation:

      Even though aprotinin reduces fibrinolysis and therefore bleeding, there is an associated increased risk of death. It was withdrawn in 2007.
      Protein C is dependent upon vitamin K and this may paradoxically increase the risk of thrombosis during the early phases of warfarin treatment.

      The coagulation cascade include two pathways which lead to fibrin formation:
      1. Intrinsic pathway – these components are already present in the blood
      Minor role in clotting
      Subendothelial damage e.g. collagen
      Formation of the primary complex on collagen by high-molecular-weight kininogen (HMWK), prekallikrein, and Factor 12
      Prekallikrein is converted to kallikrein and Factor 12 becomes activated
      Factor 12 activates Factor 11
      Factor 11 activates Factor 9, which with its co-factor Factor 8a form the tenase complex which activates Factor 10

      2. Extrinsic pathway – needs tissue factor that is released by damaged tissue)
      In tissue damage:
      Factor 7 binds to Tissue factor – this complex activates Factor 9
      Activated Factor 9 works with Factor 8 to activate Factor 10

      3. Common pathway
      Activated Factor 10 causes the conversion of prothrombin to thrombin and this hydrolyses fibrinogen peptide bonds to form fibrin. It also activates factor 8 to form links between fibrin molecules.

      4. Fibrinolysis
      Plasminogen is converted to plasmin to facilitate clot resorption

    • This question is part of the following fields:

      • Physiology And Biochemistry
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SESSION STATS - PERFORMANCE PER SPECIALTY

Pharmacology (5/5) 100%
Anatomy (6/6) 100%
Statistical Methods (3/3) 100%
Pathophysiology (1/1) 100%
Physiology (1/1) 100%
Physiology And Biochemistry (1/1) 100%
Basic Physics (1/1) 100%
Passmed