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  • Question 1 - A 60-year-old man, presents to the emergency department with crushing pain in the...

    Correct

    • A 60-year-old man, presents to the emergency department with crushing pain in the central chest area, which radiates to his left arm and jaw. He also reports feelings of nausea with no other symptoms. Elevation of the ST-segment is noted in multiple chest leads upon ECG, leading to a diagnosis of ST-elevation MI.

      What vessel gives rise to the coronary vessels?

      Your Answer: Ascending aorta

      Explanation:

      The above mentioned patient presentation is one of an acute coronary syndrome.

      The elevations noted in the ST-segments of multiple heart leads on ECG is diagnostic of an ST-elevation myocardial infarction.

      The pulmonary artery branches to give rise to the right and left pulmonary arteries, which supply deoxygenated blood to the right and left lungs from the right ventricle.

      The pulmonary veins do not form any bifurcations, and therefore do not give rise to any vessels. They travel to the left atrium from the lungs, carrying oxygenated blood.

      The descending aorta continues from the aortic arch, and bifurcates to give off many branches, including the right and left common iliac arteries.

      The coronary sinus is formed from the combination of four coronary veins, receiving blood supply from the great, middle, small and posterior cardiac veins, and transporting this venous blood into the right atrium.

      The right and left aortic sinus give rise to the right and left coronary arteries, respectively. They branch of the ascending aorta, in the area just superior to the aortic valve.

    • This question is part of the following fields:

      • Anatomy
      101.5
      Seconds
  • Question 2 - A 68-year-old man is to be operated.
     
    His past history is significant for a...

    Incorrect

    • A 68-year-old man is to be operated.
       
      His past history is significant for a stroke, and some residual neurological deficit. The cranial nerves are examined clinically. He is unable to rotate his head to the left side when resistance is applied. Moreover, there is tongue wasting on the right side. There are no unusual sensory signs and symptoms.

      The most likely reason for these clinical findings is?

      Your Answer: Damage to glossopharyngeal (IX) and hypoglossal (XII) nerves

      Correct Answer: Damage to hypoglossal (XII) and spinal accessory (XI) nerves

      Explanation:

      The upper five cervical segments of the spinal cord give rise to the XI cranial nerve. They connect with a few smaller branches before exiting the skull through the jugular foramen. The sternomastoid and trapezius muscles get their motor supply from the accessory root. Except for the palatoglossus, the hypoglossal nerve supplies motor supply to all tongue muscles.

      The inability to shrug the shoulder on the affected side and rotate the head to the side against resistance is caused by damage to the spinal accessory nerve. This is due to the trapezius and sternomastoid muscles’ weakness.

      The hypoglossal nerve is damaged, resulting in tongue wasting and inability to move from side to side.

      The stylopharyngeus receives motor supply from the glossopharyngeal nerve. It also carries taste sensory fibres from the back third of the tongue, as well as the carotid sinus, carotid body, pharynx, and middle ear.

      Motor supply to the larynx, pharynx, and palate; parasympathetic innervation to the heart, lung, and gut; and sensory fibres from the epiglottis and valleculae are all provided by the vagus nerve.

    • This question is part of the following fields:

      • Pathophysiology
      90.9
      Seconds
  • Question 3 - A 59-year-old smoker booked for an emergency laparotomy is in the anaesthetic room...

    Incorrect

    • A 59-year-old smoker booked for an emergency laparotomy is in the anaesthetic room prior to intubation. He is breathing room air and an arterial blood gas is obtained on insertion of an arterial cannula and sent for analysis.

      The following results are available:

      Haemoglobin 75 g/L
      PaO2 10.7 kPa
      PaCO2 5.2 kPa

      After intravenous induction, intubation is difficult and he rapidly begins to de-saturate.

      Which of the following is most effective in prolonging the oxygen de-saturation time?

      Your Answer:

      Correct Answer: Pre-oxygenation with 100% O2 for three minutes

      Explanation:

      Breathing 100% oxygen for three minutes will provide the best reservoir of oxygen during apnoea by oxygenating the functional residual capacity (FRC).

      Sitting at 45 degrees might increase the FRC and improve oxygen reserve but not compared with 100% oxygenation.

      The following table compares the oxygen reserves in the body following pre-oxygenation with room air and 100% oxygen:

      Compartment Factors Room air (mL) 100% O2 (mL)
      Lung FAO2, FRC 630 2850
      Plasma PaO2, DF, PV 7 45
      Red blood cells Hb, TGV, SaO2 788 805
      Myoglobin – 200 200
      Interstitial space – 25 160

      FAO2 = alveolar fraction of oxygen.
      FRC = Functional residual capacity.
      PaO2 = partial pressure of oxygen dissolved in arterial blood
      DF = dissolved form.
      PV = plasma volume.
      TG = total globular volume .
      Hb = haemoglobin concentration.
      SaO2 = arterial oxygen saturation

      Stopping smoking one month prior to surgery will not be more effective than pre-oxygenation with 100% oxygen though it may reduce postoperative pulmonary complications. Note that both long term and short term abstinence reduces pulse rate and blood pressure thus reducing oxygen consumption and also reduce carboxyhaemoglobin levels.

      Blood transfusion will not make a big difference in oxygen reserve, particularly if a blood transfusion is administered within 12-24-hours before surgery.

      Heliox (79% helium and 21% oxygen) despite its lower viscosity is unlikely to be more effective than 100% oxygen .

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 4 - Which statement most accurately describes the action of increasing the gain in ultrasound...

    Incorrect

    • Which statement most accurately describes the action of increasing the gain in ultrasound imaging?

      Your Answer:

      Correct Answer: Amplifies the returning signal

      Explanation:

      A higher frequency ultrasound comes with a better resolution of the digital image. Ultrasound with a frequency of 15 MHz is best used in imaging of superficial organs such as the thyroid gland, muscles, tendons and breasts whereas deep organs are better imaged using a lower frequency of 2-7MHz because of its ability for deeper penetration but lower resolution. These low frequency probes are also used to diagnose ascites, pleural effusions or can be used in echocardiography.

      The US probe emits and then absorbs a reflected wave. Similar to brightness control, increasing the gain will amplify the return signal which is then attenuated by the tissue. This increases the signal to noise ratio.
      A high frame rate, which basically means the number of times an image is updated onto the screen per second, improves the resolution of a moving 3D image which has become more accurate as the computing power has increased.

      Widening of the image field can be obtained by altering the penetration depth which is obtained by changing the frequency of the US beam

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 5 - A pharmaceutical company has developed a new drug considered a breakthrough in treating...

    Incorrect

    • A pharmaceutical company has developed a new drug considered a breakthrough in treating ovarian cancer.

      The efficacy of this drug can be assessed by which phase of a clinical trial?

      Your Answer:

      Correct Answer: Phase IIa

      Explanation:

      Phase IIa studies are usually pilot studies designed to demonstrate clinical efficacy or biological activity (‘proof of concept’ studies) whereas phase IIb studies determine the optimal dose at which the drug shows biological activity with minimal side-effects (definite dose-finding studies).

      Phase III and Phase IV studies are performed on larger set of participants (usually hundreds to thousands) when safety and efficacy have been established.

    • This question is part of the following fields:

      • Statistical Methods
      0
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  • Question 6 - Which of the following is true when testing for statistical significance? ...

    Incorrect

    • Which of the following is true when testing for statistical significance?

      Your Answer:

      Correct Answer: The probability associated with a type I error is the significance level

      Explanation:

      The null hypothesis states that there is no significant difference between two groups.

      The alternative hypothesis states that there is a significant difference between two groups.

      A type I error (false positive) occurs when a null hypothesis is rejected when it should be accepted.

      A type II error (false negative) occurs when the alternative hypothesis is rejected when it should be accepted.

      The probability determines the rejection of a null hypothesis.

      The level of significance is set at p <0.05.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 7 - The cardiac tissue type that that has the highest conduction velocity is: ...

    Incorrect

    • The cardiac tissue type that that has the highest conduction velocity is:

      Your Answer:

      Correct Answer: Purkinje fibres

      Explanation:

      Potassium maintains the resting potential of cardiac myocytes, with depolarization triggered by a rapid influx of sodium ions, and repolarization due to efflux of potassium. A slow influx of calcium is responsible for the longer duration of a cardiac action potential compared with skeletal muscle.

      The cardiac action potential has several phases which have different mechanisms of action as seen below:

      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms.

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 8 - An 81-year old man was admitted to the Pulmonology Ward due to chronic...

    Incorrect

    • An 81-year old man was admitted to the Pulmonology Ward due to chronic obstructive airway disease (COPD) exacerbation. Upon physical examination, he was hypertensive at 140/90 mmHg, tachycardic at 114 beats per minute, and tachypnoeic at 33 breaths per minute.

      Arterial blood gas analysis was obtained and showed the following results:

      pH: 7.25 (Reference range: 7.35-7.45)
      PaO2: 73 mmHg (9.7 kPa) (Reference range: 11.3-12.6 kPa)
      PaCO2: 56 mmHg (7.5 kPa) (Reference range: 4.7-6.0 kPa)
      SaO2: 90%
      Standard bicarbonate: 29 mmol/L (Reference range: 20-28)
      BE: +4 mmol/L (± 2)

      Which of the following options has the most significant impact on his respiratory rate?

      Your Answer:

      Correct Answer: CSF pH

      Explanation:

      The arterial blood gas analysis indicates presence of acute respiratory acidosis.

      Central chemoreceptors are located in the ventral medulla and respond directly to presence of hydrogen ions in the CSF. When stimulated, it causes an increase in respiratory rate.

      It is believed that hydrogen ions may be the only important direct stimulus for these neurons, however, CO2 is believed to stimulate these neurons secondarily by changing the hydrogen ion concentration.

      Changes in O2 concentration have virtually no direct effect on the respiratory centre itself to alter respiratory drive. Although, O2 changes do have an indirect effect by acting through the peripheral chemoreceptors.

    • This question is part of the following fields:

      • Pathophysiology
      0
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  • Question 9 - A breakthrough lipid-lowering therapy for stroke had a number needed to treat (NNT)...

    Incorrect

    • A breakthrough lipid-lowering therapy for stroke had a number needed to treat (NNT) of 20 for the prevention of the primary end-point. These results can be best described as:

      Your Answer:

      Correct Answer: For 1000 patients treated with active therapy, there would be 50 fewer strokes

      Explanation:

      Number needed to treat (NNT) is a time specific epidemiological measure that indicates how many patients would be require for an intervention to prevent one additional bad outcome. A perfect NNT would be 1, where everyone improves with treatment, thus the higher the NNT, the less effective the treatment.

      Thus if you treat 1000 patients then you will expect to have 50 fewer strokes.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 10 - A 47-year old man and known alcoholic suffered a fall that resulted to...

    Incorrect

    • A 47-year old man and known alcoholic suffered a fall that resulted to a fracture on his right leg. Radiographic imaging showed a fractured tibial shaft. Following surgery, you were instructed to prescribe intravenous paracetamol as an analgesic.

      If the patient weighs 49 kg, which of the following would be the best regimen for the patient?

      Your Answer:

      Correct Answer: 15 mg/kg with a maximum daily dose of 60 mg/kg (not exceeding 3 g)

      Explanation:

      A stock dose of Intravenous paracetamol available in the market is 10mg/ml. There is a recommended dose of IV paracetamol according to the profile of the patient (age, co-morbidities, weight).

      Weight Recommended Dose Maximum per day
      ≤10 kg 7.5 mg/kg 30 mg/kg
      >10 kg to ≤33 kg 15 mg/kg 60 mg/kg (not exceeding 2 g)
      >33 kg to ≤50 kg 15 mg/kg 60 mg/kg (not exceeding 3 g)
      >50 kg with additional risk factors for hepatotoxicity 1g 3 g
      >50 kg with no additional risk factors for hepatotoxicity 1g 4 g

      Special precaution must be observed for patients with hepatocellular insufficiency. The maximum dose per day should not exceed 3g.

    • This question is part of the following fields:

      • Pharmacology
      0
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  • Question 11 - A post-operative patient was brought to the recovery room after completion of dilation...

    Incorrect

    • A post-operative patient was brought to the recovery room after completion of dilation and curettage. Her medical history revealed that she was maintained on levodopa for Parkinson's disease. The nurses administered ondansetron 4 mg and dexamethasone 8 mg prior to transfer from the operating room to the recovery room. However, an additional antiemetic agent is warranted.

      Which of the following agents should be prescribed to the patient?

      Your Answer:

      Correct Answer: Cyclizine 50 mg IV

      Explanation:

      The Beers criteria, a US set of criteria for good prescribing in the older patient, preclude the use of metoclopramide in Parkinson’s disease. The Adverse Reactions Register of the UK Committee on Safety of Medicines (CSM) for the years 1967 to 1982 contained 479 reports of extrapyramidal reactions in which metoclopramide was the suspected drug; 455 were for dystonic-dyskinetic reactions, 20 for parkinsonism and four for tardive dyskinesia. Effects can occur within days of initiation of treatment and may take months to wear off.

      Other antiemetics are available, such as cyclizine (Valoid), domperidone and ondansetron, which would be more appropriate to use in those with Parkinson’s disease.

      Cyclizine is a piperazine derivative with histamine H1 receptor antagonist and anticholinergic activity. It is used for the treatment of nausea, vomiting, (particularly opioid-induced vomiting), vertigo, motion sickness, and labyrinthine disorders.

      Prochlorperazine is an antipsychotic known to cause tardive dyskinesia, tremor and parkinsonian symptoms and is therefore likely to exacerbate Parkinson’s disease. Prochlorperazine is not favoured for older patients because of the increased risk of stroke and transient ischaemic attack (TIA).

      Droperidol and phenothiazine are also potent antagonists on D2 receptors and must also be avoided.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 12 - Concerning the trachea, which of these is true? ...

    Incorrect

    • Concerning the trachea, which of these is true?

      Your Answer:

      Correct Answer: In an adult is approximately 15 cm long

      Explanation:

      In an adult, the trachea is approximately 15 cm long. It extends at the level of the 6th cervical vertebra, from the lower border of the cricoid cartilage.

      The trachea terminates between T4 and T6 at the carina or bronchial bifurcation. This variation is because of changes during respiration.

      The trachea has 16-20 C-shaped cartilaginous rings that maintain its patency.

      The trachea is first of the 23 generations of air passages in the tracheobronchial tree (not 25), from the trachea to the alveoli..

      The inferior thyroid arteries which are branches of the thyrocervical trunk, arise from the first part of the subclavian artery and supplies the trachea.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 13 - Which of the following statements is not correct regarding Noradrenaline? ...

    Incorrect

    • Which of the following statements is not correct regarding Noradrenaline?

      Your Answer:

      Correct Answer: Predominantly work through effects on ?-adrenergic receptors

      Explanation:

      Noradrenaline also called norepinephrine belongs to the catecholamine family that functions in the brain and body as both a hormone and neurotransmitter.

      They have sympathomimetic effects acting via adrenoceptors (?1, ?2,?1, ?2, ?3) or dopamine receptors (D1, D2).

      May cause reflex bradycardia, reduce cardiac output and increase myocardial oxygen consumption

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 14 - A 40-year-old obese woman has complaints of heartburn and regurgitation that is worse...

    Incorrect

    • A 40-year-old obese woman has complaints of heartburn and regurgitation that is worse on lying flat. The doctor suspects gastroesophageal reflux due to a hiatus hernia. Lifestyle modifications to lose weight and antacids are prescribed to her.

      At which level of the diaphragm will you find an opening for this problem?

      Your Answer:

      Correct Answer: T10

      Explanation:

      Hiatus is an opening in the diaphragm. A hiatal hernia is a protrusion of the upper part of the stomach through an opening in the diaphragm, the oesophageal hiatus, into the thorax. The oesophageal hiatus occurs at the level of T10 in the right crus of the diaphragm.

      Other important openings in the diaphragm:
      T8: vena cava, terminal branches of the right phrenic nerve
      T10: oesophagus, vagal trunks, left anterior phrenic vessels, oesophageal branches of the left gastric vessels
      T12: descending aorta, thoracic duct, azygous and hemi-azygous vein

      An opening in the diaphragm is called a hiatus. The oesophageal hiatus is at vertebral level T10. A hiatus hernia is where the stomach bulges through the oesophageal hiatus hence the name – hiatus hernia.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 15 - Which of the following statements is true regarding drug dose and response? ...

    Incorrect

    • Which of the following statements is true regarding drug dose and response?

      Your Answer:

      Correct Answer: Intrinsic activity determines maximal response

      Explanation:

      There are two types of drug dose-response relationships, namely, the graded dose-response and the quantal dose-response relationships.

      Drug response curves are plotted as percentage response again LOG drug concentration. This graph is sigmoid in shape.

      Agonists are drugs with high affinity and high intrinsic activity. Meanwhile, the antagonist is a drug with high affinity but no intrinsic activity. Intrinsic activity determines the maximal response. The maximal response can be achieved even by activation of a small proportion of receptor sites.

    • This question is part of the following fields:

      • Pharmacology
      0
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  • Question 16 - Which of the following statements is true regarding the relation to the liver?...

    Incorrect

    • Which of the following statements is true regarding the relation to the liver?

      Your Answer:

      Correct Answer: The caudate lobe is superior to the porta hepatis

      Explanation:

      Ligamentum venosum is an anterior relation of the liver: The ligamentum venosum, the fibrous remnant of the ductus venosus of the fetal circulation, lies posterior to the liver. It lies in the fossa for ductus venosus that separates the caudate lobe and the left lobe of the liver.

      The portal triad contains three important tubes: 1. Proper hepatic artery 2. Hepatic portal vein 3. Bile ductules It also contains lymphatic vessels and a branch of the vagus nerve.

      The bare area of the liver is a large triangular area that is devoid of any peritoneal covering. The bare area is attached directly to the diaphragm by loose connective tissue. This nonperitoneal area is created by a wide separation between the coronary ligaments.

      The porta hepatis is a fissure in the inferior surface of the liver. All the neurovascular structures (except the hepatic veins) and hepatic ducts enter or leave the liver via the porta hepatis. It contains the sympathetic branch to the liver and gallbladder and the parasympathetic, hepatic branch of the vagus nerve. The caudate lobe (segment I) lies in the lesser sac on the inferior surface of the liver between the IVC on the right, the ligamentum venosum on the left, and the porta hepatis in front

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 17 - A 48-year-old woman has presented to the emergency with abdominal pain and distension...

    Incorrect

    • A 48-year-old woman has presented to the emergency with abdominal pain and distension complaints. She is a known case of diabetes mellitus type 2 and has a BMI of 28 kg/m². On investigations, the liver function tests (LFTs) show raised alanine transaminase (ALT).

      Liver ultrasound is performed next to visualize the blood flow into and out of the liver.

      Which blood vessel supplies approximately one-third of the blood supply to the liver?

      Your Answer:

      Correct Answer: Hepatic artery proper

      Explanation:

      The liver receives blood supply from two sources.
      1. Hepatic artery proper
      It arises from the celiac trunk via the common hepatic artery and brings oxygenated blood to the liver.
      It contributes to approximately 30% of the blood supply of the liver.
      2. Hepatic portal vein – supplies the liver with partially deoxygenated blood, carrying nutrients absorbed from the small intestine. It gets tributaries from the inferior mesenteric vein, splenic vein, and superior mesenteric vein

      The inferior mesenteric artery supplies the hindgut.
      The superior mesenteric artery supplies the pancreas and intestine up to the proximal two-thirds of the transverse colon.
      The inferior phrenic artery supplies the inferior surface of the diaphragm and oesophagus.

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 18 - Regarding the information about kidney, which of the following is true? ...

    Incorrect

    • Regarding the information about kidney, which of the following is true?

      Your Answer:

      Correct Answer: Each kidney contains approximately 1.2 million nephrons

      Explanation:

      Each kidney is composed of about 1.2 million uriniferous tubules. Each tubule consists of two parts that are embryologically distinct from each other. They are as follows:
      a) Excretory part, called the nephron, which elaborates urine
      b) Collecting part which begins as a junctional tubule from the distal convoluted tubule.

      There are two types of nephrons in the kidney:
      The cortical nephron comprises 80% of the total nephron and its major function is the excretion of waste products in urine whereas the juxtamedullary nephron comprises 20% of the total nephron and its major function is the concentration of urine by counter current mechanism.
      In the superficial (cortical) nephrons, peritubular capillaries branch off the efferent arterioles and deliver nutrients to epithelial cells as well as serve as a blood supply for reabsorption and secretion. In juxtamedullary nephrons, the peritubular capillaries have a specialization called the vasa recta, which are long, hairpin-shaped blood vessels that follow the same course as a loop of Henle. The vasa recta serve as osmotic exchangers for the production of concentrated urine.

      The kidney receives about 25% of cardiac output and about 20% of this is filtered at the glomeruli of the kidney. Thus, renal blood flow is 1200 ml/minute and renal plasma flow is 650 ml/minute

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 19 - Which of these statements is true about spirometry? ...

    Incorrect

    • Which of these statements is true about spirometry?

      Your Answer:

      Correct Answer: A capacity is the sum of two or more volumes

      Explanation:

      Functional residual capacity (FRC) is 1.7 to 3.5L/kg

      A capacity is the sum of two or more volumes. The total lung capacity (TLC) is total sum of the volume of gas present in all lung compartments upon maximum inspiration. It is represented mathematically as:

      Total lung capacity (TLC) = Vital capacity (VC) + Residual volume (RV)

      The residual volume (RV) is the volume of gas still present within the lung post maximum exhalation. It cannot be measured by spirometry, but can be using a body plethysmograph and also with the helium dilution technique.

      Closing capacity (CC) is the volume of gas within the lungs at which small airways close upon expiration. It increases with age and is especially important when it surpasses the FRC as it causes changes in ventilation/perfusion mismatch and hypoxia.
      In the supine position, a patient with a normal body mass index and no history of lung pathology, the CC equals the FRC at approximately 44, and at approximately 66 at standing position.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 20 - When there is a relation between two variables due to the existence of...

    Incorrect

    • When there is a relation between two variables due to the existence of a confounding factor, this association is termed as:

      Your Answer:

      Correct Answer: Indirect

      Explanation:

      When the association among any two classes of object is defined by the presence of a third entity it is termed as indirect association. For an instance, the age of the employee may affect the rate of pay, which would have implications on job satisfaction. So, in this example, an indirect relationship between age and job satisfaction exists due to a third party i.e. rate of pay.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 21 - A 46-year old man was taken to the emergency room due to slow,...

    Incorrect

    • A 46-year old man was taken to the emergency room due to slow, laboured breathing. A relative reported that he's maintained on codeine 60 mg, taken orally every 6 hours for severe pain from oesophageal cancer. His creatinine was elevated, and glomerular filtration rate was severely decreased at 27 ml/minute.

      Given the scenario above, which of the metabolites of codeine is the culprit for his clinical findings?

      Your Answer:

      Correct Answer: Morphine-6-glucuronide

      Explanation:

      Accumulation of morphine-6-glucuronide is a risk factor for opioid toxicity during morphine treatment. Morphine is metabolized in the liver to morphine-6-glucuronide and morphine-3-glucuronide, both of which are excreted by the kidneys. In the setting of renal failure, these metabolites can accumulate, resulting in a lowering of the seizure threshold. However, it does not occur in all patients with renal insufficiency, which is the most common reason for accumulation of morphine-6-glucuronide; this suggests that other risk factors can contribute to morphine-6-glucuronide toxicity.

      The active metabolites of codeine are morphine and the morphine metabolite morphine-6-glucuronide. The enzyme systems responsible for this metabolism are: CYP2D for codeine and UGT2B7 for morphine, codeine-6-gluronide, and morphine-6-glucuronide. Both of these systems are subject to genetic variation. Some patients are ultrarapid metabolizers of codeine and produce higher levels of morphine and active metabolites in a very short period of time after administration. These increased levels will produce increased side effects, especially drowsiness and central nervous system depression.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 22 - A randomized study aimed at finding out the efficacy of a novel anticoagulant,...

    Incorrect

    • A randomized study aimed at finding out the efficacy of a novel anticoagulant, in preventing stroke in patients suffering from atrial fibrillation, relative to those already available in the market was performed. A 59 year old woman volunteered for it and was randomised to the treatment arm. A year later, following findings were reported:

      165 out of 1050 patients who were prescribed the already prevalent medicine had a stroke while the number of patients who had a single stroke after using the new drug was 132 out of 1044.

      In order to avoid one stroke case, what is the number of patients that need to be treated?

      Your Answer:

      Correct Answer: 32

      Explanation:

      Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.

      It can be found as:

      NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).

      where ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)

      So,

      ARR= (165/1050)-(132/1044)

      ARR= (0.157-0.126)

      ARR= 0.031

      NNT= 1/0.031

      NNT=32.3

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 23 - Which statement is true when describing carbonic anhydrase? ...

    Incorrect

    • Which statement is true when describing carbonic anhydrase?

      Your Answer:

      Correct Answer: Isoenzyme IV is found in the brush border of the proximal convoluted tubule

      Explanation:

      Carbonic anhydrase is an enzyme which contains zinc and can be found in:
      1. Erythrocytes
      2. Pulmonary endothelium
      3. The intestine
      4. Pancreas
      5. Cardiac muscle and skeletal muscle.

      To date, there have been seven isoenzymes identified. Of note, isoenzyme IV is found in the brush border of the proximal convoluted tubule and isoenzyme II is found within the luminal cells.

      Acetazolamides a carbonic anhydrase inhibitor and is used as prophylaxis against mountain sickness and in glaucoma management.

      Spironolactone is a potassium diuretic and is an aldosterone antagonist.

    • This question is part of the following fields:

      • Physiology
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  • Question 24 - Which of the given statements is true about standard error of the mean?...

    Incorrect

    • Which of the given statements is true about standard error of the mean?

      Your Answer:

      Correct Answer: Gets smaller as the sample size increases

      Explanation:

      The standard error of the mean (SEM) is a measure of the spread expected for the mean of the observations – i.e. how ‘accurate’ the calculated sample mean is from the true population mean. The relationship between the standard error of the mean and the standard deviation is such that, for a given sample size, the standard error of the mean equals the standard deviation divided by the square root of the sample size.

      SEM = SD / square root (n)

      where SD = standard deviation and n = sample size

      Therefore, the SEM gets smaller as the sample size (n) increases.

      If we want to depict how widely scattered some measurements are, we use the standard deviation. For indicating the uncertainty around the estimate of the mean, we use the standard error of the mean. The standard error is most useful as a means of calculating a confidence interval. For a large sample, a 95% confidence interval is obtained as the values 1.96×SE either side of the mean.

      A 95% confidence interval:

      lower limit = mean – (1.96 * SEM)

      upper limit = mean + (1.96 * SEM)

      Results such as mean value are often presented along with a confidence interval. For example, in a study the mean height in a sample taken from a population is 183cm. You know that the standard error (SE) (the standard deviation of the mean) is 2cm. This gives a 95% confidence interval of 179-187cm (+/- 2 SE).

      Hence, it would be wrong to say that confidence levels do not apply to standard error of the mean.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 25 - A participant of a metabolism study is to be fed only granulated sugar...

    Incorrect

    • A participant of a metabolism study is to be fed only granulated sugar and water for 48 hours. What would be his expected respiratory quotient at the end of the study?

      Your Answer:

      Correct Answer: 1

      Explanation:

      The respiratory quotient is the ratio of CO2 produced to O2 consumed while food is being metabolized:

      RQ = CO2 eliminated/O2 consumed

      Most energy sources are food containing carbon, hydrogen and oxygen. Examples include fat, carbohydrates, protein, and ethanol. The normal range of respiratory coefficients for organisms in metabolic balance usually ranges from 1.0-0.7.

      Granulated sugar is a refined carbohydrate with no significant fat, protein or ethanol content.

      The RQ for carbohydrates is = 1.0

      The RQ for the rest of the compounds are:

      Fats RQ = 0.7
      The chemical composition of fats differs from that of carbohydrates in that fats contain considerably fewer oxygen atoms in proportion to atoms of carbon and hydrogen.

      Protein RQ = 0.8
      Due to the complexity of various ways in which different amino acids can be metabolized, no single RQ can be assigned to the oxidation of protein in the diet; however, 0.8 is a frequently utilized estimate.

    • This question is part of the following fields:

      • Physiology
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  • Question 26 - Which of the following statement is correct regarding the difference between dabigatran and...

    Incorrect

    • Which of the following statement is correct regarding the difference between dabigatran and other anticoagulants?

      Your Answer:

      Correct Answer: Competitive thrombin inhibitor blocking both free and bound thrombin

      Explanation:

      Dabigatran template is a prodrug and its active metabolite is a direct thrombin inhibitor. It is a synthetic, reversible, non-peptide thrombin inhibitor. This inhibition of thrombin results in a decrease of fibrin and reduces platelet aggregation.

      Drugs like warfarin act by inhibiting the activation of vitamin K-dependent clotting factors. These factors are synthesized by the liver and activated by gamma-carboxylation of glutamate residues with the help of vitamin K. Hydroquinone form of vitamin K is converted to epoxide form in this reaction and regeneration of hydroquinone form by enzyme vitamin K epoxide reductase (VKOR) is required for this activity. Oral anticoagulants prevent this regeneration by inhibiting VKOR, thus vitamin K-dependent factors are not activated. These factors include clotting factors II, VII, IX, and X as well as anti-clotting proteins, protein C and protein S.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 27 - The phenomenon that the patients behaved in a different manner when they know...

    Incorrect

    • The phenomenon that the patients behaved in a different manner when they know that they are being observed is termed as?

      Your Answer:

      Correct Answer: Hawthorne effect

      Explanation:

      Hawthorne effect explains the change in any behavioural aspect owing to the awareness that the person is being observed.
      Simpson’s Paradox explains the association developed when the data from several groups is combined to form a single larger group.

      The remaining terms are made up.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 28 - A 49-year-old female has presented to her physician with complaints of a lump...

    Incorrect

    • A 49-year-old female has presented to her physician with complaints of a lump in her groin area. The lump is painless and is more prominent in coughing.
      On examination, the lump's location is inferior and lateral to the pubic tubercle. This points towards the diagnosis of femoral hernia, where part of her intestines has entered the femoral canal, causing a bulge in the femoral triangle. The femoral triangle is an anatomical region in the upper thigh.

      Name the structures found in the femoral triangle, laterally to medially.

      Your Answer:

      Correct Answer: Femoral nerve, femoral artery, femoral vein, empty space, lymphatics

      Explanation:

      The femoral triangle is a wedge-shaped area found within the superomedial aspect of the anterior thigh. It is a passageway for structures to leave and enter the anterior thigh.

      Superior: Inguinal ligament
      Medial: Adductor longus
      Lateral: Sartorius
      Floor: Iliopsoas, adductor longus and pectineus

      The contents include: (medial to lateral)
      Femoral vein
      Femoral artery-pulse palpated at the mid inguinal point
      Femoral nerve
      Deep and superficial inguinal lymph nodes
      Lateral cutaneous nerve
      Great saphenous vein
      Femoral branch of the genitofemoral nerve

    • This question is part of the following fields:

      • Anatomy
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  • Question 29 - Infrared radiation is absorbed by asymmetric, polyatomic polar molecules like carbon dioxide (CO2).

    When...

    Incorrect

    • Infrared radiation is absorbed by asymmetric, polyatomic polar molecules like carbon dioxide (CO2).

      When measuring CO2 in gas samples, mainstream capnography uses this physical principle.

      Which of the following gases is most likely to interfere with carbon dioxide's absorption spectrum?

      Your Answer:

      Correct Answer: Nitrous oxide

      Explanation:

      Carbon dioxide absorbs the most infrared (IR) light between the wavelengths of 4.2-4.4m (4.26m is ideal).

      Nitrous oxide absorbs infrared light at wavelengths of 4.4-4.6m (very similar to CO2) and less so at 3.9m.

      At a frequency of 4.7m, carbon monoxide absorbs the most IR light.

      At 3.3 m and throughout the ranges 8-12 m, the volatile agents have strong absorption bands.

      Although oxygen does not absorb infrared light, it collides with CO2 molecules, interfering with absorption. The absorption band is widened as a result of this (so called collision or pressure broadening). A drop of 0.5 percent in measured CO2 can be caused by 95% oxygen.

      Nitrous oxide causes a greater inaccuracy of 0.1 percent per ten percent of nitrous oxide.

      Water vapour absorbs infrared light as well, resulting in absorption band overlap, collision broadening, and partial pressure dilution. Water traps and water permeable tubing are used to reduce inaccuracies.

      Collision broadening is compensated for in modern gas multi-gas analysers.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 30 - Dinamap is an automated blood pressure monitoring device. Which of these statements best...

    Incorrect

    • Dinamap is an automated blood pressure monitoring device. Which of these statements best fit its properties?

      Your Answer:

      Correct Answer: The cuff should be positioned at the same level as the heart

      Explanation:

      Dinamap continuously measures the systolic, diastolic and mean arterial pressure along with pulse rate, thereby providing a continuous monitoring of the blood pressure using the osscillitonometric principle of measurement.

      The device loses accuracy towards the extremes of BP and is more accurate with systolic compared with diastolic pressure. In arrhythmias such as AF, the devices are also inaccurate due to the major fluctuations associated with the individual pulse pressure variations.

      The manual BP device is still the gold standard for BP measurement and monitoring.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 31 - Which of the following drug can be the first-line drug for both broad...

    Incorrect

    • Which of the following drug can be the first-line drug for both broad and narrow complex tachyarrhythmia?

      Your Answer:

      Correct Answer: Amiodarone

      Explanation:

      Amiodarone is the longest-acting anti-arrhythmic drug. It possesses the action of all classes of antiarrhythmic drugs (Sodium channel blockade, Beta blockade, Potassium channel blockade, and Calcium channel blockade). Due to this property, it has the widest anti-arrhythmic spectrum and thus can be used in both broad and narrow complex tachyarrhythmia.

      Adenosine is shortest acting anti-arrhythmic drug.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 32 - A double blind placebo control clinical trial is done. Which of these is...

    Incorrect

    • A double blind placebo control clinical trial is done. Which of these is correct about it?

      Your Answer:

      Correct Answer: The clinician assessing the effects of the treatment does not know which treatment the patient has been given

      Explanation:

      A ‘double blind crossover study’ happens when every patient receive both treatments.

      It is incorrect to say that only half of the patients do not know which treatment they receive because in a double blind placebo control clinical trial ALL of the patients are blind to their treatment choice .

      If some of the patients are not treated, they would be aware that they were not being treated and it could not be considered a blind trial.

      In a double blind placebo control clinical trial both the clinician and the patient are blind to the treatment choice. The clinician assessing the effects of the treatment, therefore, does not know which treatment the patient has been given.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 33 - A 32-year-old male is admitted to the critical care unit. He has suffered...

    Incorrect

    • A 32-year-old male is admitted to the critical care unit. He has suffered a heroin overdose and requires intubation and ventilatory support.

      What would be his predicted total static compliance (lung and chest wall) measurements.

      Your Answer:

      Correct Answer: 100 ml/cmH2O

      Explanation:

      Static lung compliance refers to the change in volume within the lung per given change in unit pressure. It is usually measured when air flow is absent, such as during pauses in inhalation and exhalation.

      It is a combination of:

      Chest wall compliance: normal value is 200 mL/cmH2O
      Lung tissue compliance: normal value is 200 mL/ cmH2O

      It is represented mathematically as:

      1/Crs = 1/Cl + 1/Ccw

      Where,

      Crs = total compliance of the respiratory system
      Cl = compliance of the lung
      Ccw = compliance of the chest wall

      Therefore in this case:

      1/Crs = 1/200 + 1/200

      1/Crs = 0.005 + 0.005 = 0.01

      1/Ct = 0.01

      Rearranging equation gives:

      Ct = 1/0.01 = 100 mL/cmH2O.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 34 - A 60-year-old male is being reviewed in the peri-operative assessment before total knee...

    Incorrect

    • A 60-year-old male is being reviewed in the peri-operative assessment before total knee replacement. He had a history of a heart transplant 10 years back. His resting heart rate is 110 beats per minute. On examination, ECG showed sinus tachycardia.

      Which of the following explains this tachycardia?

      Your Answer:

      Correct Answer: Loss of parasympathetic innervation

      Explanation:

      Normally, at rest vagal influence is dominant producing the heart rate of 60-80 beats per minute even if the intrinsic automaticity of Sinoatrial Node is 100-110 beats per minute.

      The transplanted heart has no autonomic nervous supply. So, it will respond to endogenous and exogenous catecholamine. This loss of parasympathetic innervation is responsible for the tachycardia in this patient.

      Hypokalaemia can cause myocardial excitability and potential for ventricular ectopic and supraventricular arrhythmias. Hypothyroidism is also unlikely to cause tachycardia in this patient.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 35 - An 80 year old woman is due for cataract surgery.

    There are no...

    Incorrect

    • An 80 year old woman is due for cataract surgery.

      There are no contraindications to regional anaesthesia so a peribulbar block was performed. 8mls of 2% lidocaine was injected using an infratemporal approach. However, there is still movement of the globe after 5 mins.

      The least likely extraocular muscle to develop akinesia is:

      Your Answer:

      Correct Answer: Superior oblique

      Explanation:

      The fibrotendinous ring formed by the congregation of the rectus muscles at the apex of the orbit does not include superior oblique. This muscle is completely outside the ring and so it is the most difficult muscle to anaesthetise completely. A good grasp of the anatomy of the area being anaesthetised is important with all regional anaesthetic techniques so that potential problems and complications with a block can be anticipated.

      The borders of this pyramid whose apex points upwards and outwards of the bony orbit are as follows:
      Floor – Zygoma and Maxilla
      Roof – frontal bone
      Medial wall – maxilla, ethmoid, sphenoid and lacrimal bones.
      Lateral wall – greater wing of the sphenoid and the zygoma.

      The four recti muscles (superior, medial, lateral and inferior) originate from a tendinous ring (the annulus of Zinn) and extend anteriorly to insert beyond the equator of the globe. Bands of connective tissue are present between the rectus muscles forming a conical structure and hinder the passage of local anaesthetic.

      The superior oblique muscle is situated outside this ring and is the most difficult muscle to anaesthetise completely, particularly with a single inferotemporal peribulbar injection. An additional medial injection may help to prevent this.

      The cranial nerve supply to the extraocular muscles are:
      3rd (inferior oblique, inferior recti, medial and superior)
      4th (superior oblique), and
      6th (lateral rectus).

      The long and short ciliary nerves provide the sensory supply to the globe and these are branches of the nasociliary nerve, (which is itself a branch of the ophthalmic division of the trigeminal nerve).

      To achieve anaesthesia for the eye, these nerves which enter the fibrotendinous ring need to be fully blocked to anaesthetise the eye for surgery.

    • This question is part of the following fields:

      • Anatomy
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  • Question 36 - Which statement is true about the autonomic nervous system? ...

    Incorrect

    • Which statement is true about the autonomic nervous system?

      Your Answer:

      Correct Answer: Preganglionic synapse utilise Acetylcholine as the neurotransmitter in both parasympathetic and sympathetic systems

      Explanation:

      With regards to the autonomic nervous system (ANS)

      1. It is not under voluntary control
      2. It uses reflex pathways and different to the somatic nervous system.
      3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.

      With regards to the central nervous system (CNS)
      1. There are myelinated preganglionic fibres which lead to the
      ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
      2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.

      Most organs are under control of both systems although one system normally predominates.

      The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.

      There are short pre-ganglionic and long post ganglionic fibres.
      Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
      Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
      However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.

      The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.

      There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.

      Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.

      The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.

      The cranial outflow consists of
      1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
      2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
      3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
      4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreas

      The sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.

      The PNS has long preganglionic and short post ganglionic fibres.
      Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
      Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.

      Different types of these muscarinic receptors are present in different organs:
      There are:
      M1 = pupillary constriction, gastric acid secretion stimulation
      M2 = inhibition of cardiac stimulation
      M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
      M4 = brain and adrenal medulla
      M5 = brain

      The lacrimal glands are solely under parasympathetic control.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 37 - The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised...

    Incorrect

    • The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised by which of the following?

      Your Answer:

      Correct Answer: Synthesis of ATP is brought about by anaerobic respiration

      Explanation:

      Muscle fibre myosin ATPase histochemistry is used to divide the biochemical classification into two groups: type 1 and type II.

      Type I (slow twitch) muscle fibres rely on aerobic glycolytic and aerobic oxidative metabolism to function. They have a lot of mitochondria, a good blood supply, a lot of myoglobin, and they don’t get tired easily.

      Because they contain more motor units, Type II (fast twitch) muscle fibres are thicker. They are more easily fatigued, but produce powerful bursts. The capillary networks and mitochondria are less dense in these white muscle fibres than in type I fibres. They have a low myoglobin content as well.

      Muscle fibres of type II (fast twitch) are divided into three types:

      Type IIa – aerobic/oxidative metabolism is used.
      Type IIb – anaerobic/glycolytic metabolism is used by these fibres.

      When compared to skeletal muscle, cardiac and smooth muscle twitch at a slower rate.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 38 - A 31-year old Caucasian female came into the emergency department due to difficulty...

    Incorrect

    • A 31-year old Caucasian female came into the emergency department due to difficulty of breathing. History revealed exposure to room odorizes that are rich in alkyl nitrites. Upon physical examination, patient is tachypnoeic at 32 breaths per minute, desaturated at 88% while on a non-rebreather mask at 15 litres per minute oxygen. She was also noted to be cyanotic, however with clear breath sounds.

      Considering the history, what is the most probable cause of her difficulty of breathing?

      Your Answer:

      Correct Answer: Increased affinity of bound oxygen to haemoglobin

      Explanation:

      Amyl nitrate is part of the treatment of cyanide poisoning. The short acting nitrate causes oxidation of Fe2+ in haemoglobin to Fe3+ in methaemoglobin. Methaemoglobin combines with cyanide (cyanmethemoglobin), which reacts with sodium thiosulfate to convert nontoxic thiocyanate and methaemoglobin.

      Methaemoglobin is formed when the iron in haemoglobin is converted from the reduced state (Fe2+) to the oxidized state (Fe3+). The oxidized form of haemoglobin (Fe3+) does not bind oxygen as readily as Fe2+, but has high affinity for cyanide. It also results to high affinity of bound oxygen to haemoglobin, thus leading to tissue hypoxia. Arterial oxygen tension is normal despite observations of cyanosis and dyspnoea. Methemoglobinemia can be treated with methylene blue and vitamin C.

      Carboxyhaemoglobin can be due to carbon monoxide poisoning. In such cases, patients experience headache and dizziness, but do not develop cyanosis.

      2,3-diphosphoglycerate causes a shift in the oxygen dissociation curve to the right, decreasing haemoglobin’s affinity to oxygen to facilitate unloading of oxygen to the tissues.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 39 - A 74-year-old with a VVI pacemaker is undergoing a hip replacement.

    Which of the...

    Incorrect

    • A 74-year-old with a VVI pacemaker is undergoing a hip replacement.

      Which of the following is most likely to predispose him to an electrical hazard?

      Your Answer:

      Correct Answer: Use of cutting unipolar diathermy

      Explanation:

      A single chamber pacemaker was implanted in the patient. In VVI mode, a pacemaker paces and senses the ventricle while being inhibited by a perceived ventricular event. The most likely electrical hazard from diathermy is electromagnetic interference (EMI).

      EMI has the potential to cause the following: Inhibition of pacing
      Asynchronous pacing
      Reset to backup mode
      Myocardial burns, and
      Trigger VF.

      Diathermy entails the implementation of high-frequency electrical currents to produce heat and either make incisions or induce coagulation. Monopolar cautery involves disposable cautery pencils and electrosurgical diathermy units. In typical monopolar cautery, an electrical plate is placed on the patient’s skin and acts as an electrode, while the current passes between the instrument and the plate. Monopolar diathermy can therefore interfere with implanted metal devices and pacemaker function.

      Bipolar diathermy, where the current passes between the forceps tips and not through the patient and is less likely to generate EMI.

      Whilst the presence of a CVP line may in theory predispose the patient to microshock, the use of prerequisite CF electrical equipment makes this very unlikely. The presence of a CVP line and pacemaker does not therefore unduly increase the risk of an electrical hazard.

      Isolating transformers are used to protect secondary circuits and individuals from electrical shocks. There is no step-up or step-down voltage (i.e. there is a ratio of 1 to 1 between the primary and secondary windings).

      A ground (or earth) wire is normally connected to the metal case of an operating table to protect patients from accidental electrocution. In the event that a fault allows a live wire to make contact with the metal table (broken cable, loose connection etc.) it becomes live. The earth will provide an immediate path for current to safely flow through and so the table remains safe to touch. Being a low resistance path, the earth lets a large current flow through it when the fault occurs ensuring that the fuse or RCD will quickly blow. Without an operating table earth, the patient is not at more risk of an electrical hazard because of the pacemaker.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 40 - A 70-year-old man presents to hospital complaining of dysphagia. He is scheduled for...

    Incorrect

    • A 70-year-old man presents to hospital complaining of dysphagia. He is scheduled for a rigid oesophagoscopy.

      On examination, He is noted to have severe osteoarthritis in his cervical spine resulting in limited rotation and flexion-extension. He has no other neurological signs or symptoms.

      He is given anaesthesia for the procedure, which is complicated by a difficult intubation (Cormack-Lehane 3), but was eventually achieved using a gum elastic bougie.

      After recovering from anaesthesia, he is examined and found to have severe motor weakness of upper limbs, and mild motor weakness of lower limbs, bladder dysfunction and sensory loss of varying degrees below the level of C5.

      What incomplete spinal cord lesion is most likely to be responsible for his symptoms?

      Your Answer:

      Correct Answer: Central cord syndrome

      Explanation:

      Central cord syndrome is the most commonly occurring type of partial spinal cord lesion. It is more likely to occur in older patients with cervical spondylosis and a hyperextension injury. The injury to the spinal cord occurs in the grey matter causing the following symptoms:

      Disproportionally higher motor function weakness in the upper limbs than in lower limbs
      Dysfunction of the bladder
      Degrees of sensory loss below the level of the lesion

      An anterior spinal artery infarction will interrupt the corticospinal tract resulting in paralysis of motor function, loss of pain and temperature sensation, all occurring below the level of the injury.

      Brown-Sequard syndrome occurs as a result of the hemisection of the spinal cord. Its symptoms include ipsilateral upper motor neurone paralysis and loss of proprioception, with contralateral loss of pain and temperature sensation.

      Spinal cord infarctions rarely occur in the posterior spinal artery.

      Cauda equina syndrome occurs as a result of compression of the lumbosacral spinal nerve roots below the level of the conus medullaris. Injury to these nerves will cause partial or complete loss of movement and sensation in this distribution.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 41 - How data is collected for the Delphi survey technique? ...

    Incorrect

    • How data is collected for the Delphi survey technique?

      Your Answer:

      Correct Answer: Questionnaires

      Explanation:

      The Delphi is a group facilitation technique that seeks to obtain consensus on the opinions of `experts’ through a series of structured questionnaires (commonly referred to as rounds). By using successive questionnaires, opinions are considered in a non-adversarial manner, with the current status of the groups’ collective opinion being repeatedly fed back. Studies employing the Delphi make use of individuals who have knowledge of the topic being investigated

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 42 - From the following electromagnetic waves, which one has the shortest wavelength? ...

    Incorrect

    • From the following electromagnetic waves, which one has the shortest wavelength?

      Your Answer:

      Correct Answer: X rays

      Explanation:

      Electromagnetic waves are categorized according to their frequency or equivalently according to their wavelength. Visible light makes up a small part of the full electromagnetic spectrum.

      Electromagnetic waves with shorter wavelengths and higher frequencies include ultraviolet light, X-rays, and gamma rays. Electromagnetic waves with longer wavelengths and lower frequencies include infrared light, microwaves, and radio and televisions waves.

      Different electromagnetic waves according to their wavelength from shorter to longer are X-rays, ultraviolet radiations, visible light, infrared radiation, radio waves. X-ray among electromagnetic waves has the shortest wavelength and higher frequency with wavelengths ranging from 10*-8 to 10* -12 and corresponding frequencies.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 43 - With regards to the repolarisation phase of the myocardial action potential, which of...

    Incorrect

    • With regards to the repolarisation phase of the myocardial action potential, which of the following is responsible?

      Your Answer:

      Correct Answer: Efflux of potassium

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 44 - The single most important prerequisite for accuracy in measuring basal metabolic rate (BMR)...

    Incorrect

    • The single most important prerequisite for accuracy in measuring basal metabolic rate (BMR) using indirect calorimetry is performing the test:

      Your Answer:

      Correct Answer: In a neutral thermal environment

      Explanation:

      The basal metabolic rate (BMR) is the amount of energy required to maintain basic bodily functions in the resting state. The unit is Watt (Joule/second) or calories per unit time.

      Indirect calorimetry measures O2 consumption and CO2 production where gases are collected in a canopy which is the gold standard, Douglas bag, face-mask dilution technique or interfaced with a ventilator.

      The BMR can be calculated using the Weir formula:

      Metabolic rate (kcal per day) = 1.44 (3.94 VO2 + 1.11 VCO2)

      The BMR should be measured while lying down and at rest with the following conditions met:

      It should follow a 12 -hour fast
      No stimulants ingested within a 12-hour period
      It should be done in a neutral thermal environment (between 20°C-25°C)

    • This question is part of the following fields:

      • Physiology
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  • Question 45 - Regarding the use of soda lime as part of a modern circle system...

    Incorrect

    • Regarding the use of soda lime as part of a modern circle system with a vaporiser outside the circuit (VOC), which of the following is its most deleterious consequence?

      Your Answer:

      Correct Answer: Carbon monoxide formation

      Explanation:

      When using dry soda lime for VOCs, very high amounts of carbon monoxide may be produced, regardless of the inhalational anaesthetic agent used. The carbon monoxide produced is sufficient enough to cause cytotoxic and anaemic hypoxia. To prevent this, soda lime canisters are shaken well to even out the packing of granules. This can help to evenly distribute gas flow for proper CO2 absorption and ventilation.

      Compound A is formed when dry soda lime, or soda lime in high temperature, reacts with the inhalational anaesthetic Sevoflurane. Animal studies have shown renal toxicity in rats, but renal adverse effects in humans are yet to be observed.

      When monitors are not employed with VOCs, deleterious effects are not for certain. However, monitors not employed with vaporiser inside the circuit (VIC) can lead to significant adverse events.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 46 - Following an acute appendicectomy, a 6-year-old child is admitted to the recovery unit.

    Your...

    Incorrect

    • Following an acute appendicectomy, a 6-year-old child is admitted to the recovery unit.

      Your consultant has requested that you prescribe maintenance fluids for the next 12 hours. The child is 21 kg in weight.

      What is the most suitable fluid volume to be prescribed?

      Your Answer:

      Correct Answer: 732 ml

      Explanation:

      After a paediatric case, you’ll frequently have to calculate and prescribe maintenance fluids. The ‘4-2-1 rule’ should be used as a guideline:

      1st 10 kg – 4 ml/kg/hr
      2nd 10 kg – 2 ml/kg/hr
      Subsequent kg – 1 ml/kg/hr

      Hence

      1st 10 kg = 4 × 10 = 40 ml
      2nd 10 kg = 2 × 10 = 20 ml
      Subsequent kg = 1 × 1 = 1 ml
      Total = 61 ml/hr

      61 × 12 = 732 ml over 12 hrs.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 47 - Activation of which of the following GABA A receptor subunit leads to anxiolytic...

    Incorrect

    • Activation of which of the following GABA A receptor subunit leads to anxiolytic effects of Benzodiazepines?

      Your Answer:

      Correct Answer: Alpha

      Explanation:

    • This question is part of the following fields:

      • Pharmacology
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      Seconds
  • Question 48 - A 77-year-old man, is scheduled for an angiogram to investigate gastro-intestinal bleeding. The...

    Incorrect

    • A 77-year-old man, is scheduled for an angiogram to investigate gastro-intestinal bleeding. The radiologist performing the angiogram inserts the catheter into the coeliac axis.

      What level of the vertebrae does the coeliac axis normally arise from the aorta?

      Your Answer:

      Correct Answer: T12

      Explanation:

      The coeliac axis refers to one of the splanchnic arteries located within the abdomen.

      It arises from the aorta almost horizontally at the level of the T12 vertebrae

    • This question is part of the following fields:

      • Anatomy
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  • Question 49 - A 71-year-old woman will undergo surgery for a fractured femur neck.

    1 mg midazolam...

    Incorrect

    • A 71-year-old woman will undergo surgery for a fractured femur neck.

      1 mg midazolam is used to induce anaesthesia, followed by 75 mg propofol.

      Which of the following options best describes how these two drugs interact pharmacologically?

      Your Answer:

      Correct Answer: Synergism

      Explanation:

      Drug interactions can be seen in the following examples:

      Additive interaction (summation).

      Additive effects are described for intravenous drug combinations such as ketamine and thiopentone or ketamine and midazolam. Different mechanisms of action are used by them. Thiopentone and midazolam are GABAA receptor agonists, whereas ketamine is an NMDA receptor antagonist. Nitrous oxide and halothane are two other examples.

      Synergism is a supra-additive interaction.

      Refers to the administration of two drugs with similar pharmacological properties and closely related sites of action, resulting in a combined effect that is greater than the sum of the contributions of each component. The construction of an isobologram can be used to interpret and understand these. The best example is the hypnotic effect of benzodiazepines and intravenous induction agents like propofol. As part of a co-induction technique, midazolam is frequently given before propofol.

      Potentiation

      In a dose-dependent manner, volatile agents enhance the effects of neuromuscular blocking agents. Electrolyte disturbance (hypomagnesaemia), Penicillin, and probenecid can all increase the effects of neuromuscular blocking agents (the latter has no similar pharmacological activity).

      Infra-additive interaction (antagonism).

      This can be subdivided into the following categories:

      -Pharmacokinetic interference occurs when one drug affects the absorption of another through the gastrointestinal tract or when hepatic microsomal enzyme induction influences metabolism.
      -Heparin and protamine, for example, or heavy metals and chelating agents, are examples of chemical antagonists.
      -Competitive reversible antagonistic antagonism of receptors, such as opioids and naloxone, and irreversible antagonistic antagonism of receptors

    • This question is part of the following fields:

      • Pharmacology
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  • Question 50 - An study on post-operative nausea and vomiting (PONV) among paediatric patients who underwent...

    Incorrect

    • An study on post-operative nausea and vomiting (PONV) among paediatric patients who underwent tonsillectomy showed a decrease in incidence from 10% to 5% following a new management protocol.

      Which of the following best estimates the numbers needed to treat (NNT) for one additional patient to benefit from the new management of PONV?

      Your Answer:

      Correct Answer: 20

      Explanation:

      The Number Needed to Treat (NNT) is the number of patients you need to treat to prevent one additional bad outcome. For example, if a drug has an NNT of 5, it means you have to treat 5 people with the drug to prevent one additional bad outcome.

      To calculate the NNT, you need to know the Absolute Risk Reduction (ARR); the NNT is the inverse of the ARR:

      NNT = 1/ARR

      Where ARR = CER (Control Event Rate) – EER (Experimental Event Rate).

      NNTs are always rounded up to the nearest whole number.

      In this case, the NNT can be computed as follows:

      ARR = 10% – 5% = 0.05

      NNT = 1/0.05 = 20

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 51 - Regarding aldosterone, one of the following is true. ...

    Incorrect

    • Regarding aldosterone, one of the following is true.

      Your Answer:

      Correct Answer: Secretion is increased following haematemesis

      Explanation:

      Aldosterone is produced in the zona glomerulosa of the adrenal cortex and acts to increase sodium reabsorption via intracellular mineralocorticoid receptors in the distal tubules and collecting ducts of the nephron.

      Its release is stimulated by hypovolaemia, blood loss ,and low plasma sodium and is inhibited by hypertension and increased sodium. It is regulated by the renin-angiotensin system.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 52 - Which muscle separates the subclavian artery and the subclavian vein? ...

    Incorrect

    • Which muscle separates the subclavian artery and the subclavian vein?

      Your Answer:

      Correct Answer: Scalenus anterior

      Explanation:

      The subclavian artery and vein have a similar path throughout their course, with the subclavian vein running anterior to the subclavian artery. The artery and vein are separated by the insertion of the scalenus anterior muscle.

      There are three scalene muscles, found on each side of the neck:
      1. Anterior scalene
      2. Middle scalene
      3. Posterior scalene

      The scalenus anterior muscle is the anterior most of the three scalene muscles. It originates from the transverse processes of vertebrae C3-C6 and is inserted in the first rib.

    • This question is part of the following fields:

      • Anatomy
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  • Question 53 - If a large volume of 0.9% N. saline is administered during resuscitation, it...

    Incorrect

    • If a large volume of 0.9% N. saline is administered during resuscitation, it is most likely to cause?

      Your Answer:

      Correct Answer: Hyperchloremic metabolic acidosis

      Explanation:

      Crystalloids recommended for fluid resuscitation include 0.9% N saline and Hartmann’s solution(a physiological solution). 0.9% N. saline is not a physiological solution for the following reasons:

      Compared with the normal range of 98-102 mmol/L, its chloride concentration is high (154 mmol/L)
      It lacks calcium, magnesium, glucose and potassium
      It does not have bicarbonate or bicarbonate precursor buffer necessary to maintain plasma pH within normal limits

      There is a difference in the activity (concentration) of strong ions at a physiological pH. This imbalance can explain abnormalities of acid base balance. A normal strong ion difference (SID) is in the order of 40.

      SID = ([Na+] + [K+] + [Ca2+] + [Mg2+]) – ([Cl-] + [lactate] + [SO42-])

      This imbalance is made up with the weaker anions to maintain electrical neutrality.
      Administration of a large volume of 0.9% normal saline during resuscitation results in excessive chloride administration and this impairs renal bicarbonate reabsorption. The SID of 0.9% normal saline is 0 (Na+ = 154mmol/L and Cl- = 154mmol/L = 154 – 154 = 0). A large volume of NS will decrease the plasma SID causing an acidosis.

      Other causes of a hyperchloremic acidosis are:

      Diabetic ketoacidosis
      Total Parenteral Nutrition
      Overdose of ammonium chloride and hydrochloric acid
      Gastrointestinal losses of bicarbonate like in diarrhoea and pancreatic fistula
      Proximal renal tubular acidosis with failure of bicarbonate reabsorption

    • This question is part of the following fields:

      • Physiology
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  • Question 54 - The external laryngeal nerve is responsible for the innervation of which of the...

    Incorrect

    • The external laryngeal nerve is responsible for the innervation of which of the following muscles?

      Your Answer:

      Correct Answer: Cricothyroid

      Explanation:

      The external laryngeal nerve arises from the superior laryngeal nerve and provides innervation to the cricothyroid muscle.

      The other muscles mentioned receive their innervations from the recurrent laryngeal nerve.

    • This question is part of the following fields:

      • Anatomy
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  • Question 55 - The average diastolic blood pressure of a control group was found out to...

    Incorrect

    • The average diastolic blood pressure of a control group was found out to be 80 with a standard deviation of 5 in a study aimed at exploring the efficiency of a novel anti-hypertensive drug. The trial was randomised.

      Making an assumption that the data is normally distributed, find out the number of patients that had diastolic blood pressure over 90.

      Your Answer:

      Correct Answer: 3%

      Explanation:

      Since the data is normally distributed, 95% of the values lie with in the interval 70 to 90. This can be calculated as follows:

      Interval= Mean ± ( 2 times standard deviation)
      = 80 ± 2(5)
      = 80 ± 10
      = 70 & 90

      The rest of the 5% are distributed symmetrically beyond 90 and below 70 which means 2.5% of the values lie above 90.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 56 - The following results were obtained In a new drug trial:

    Improved Not improved
    Placebo...

    Incorrect

    • The following results were obtained In a new drug trial:

      Improved Not improved
      Placebo group 36 26
      Treatment group 44 16

      Regarding the statistical analysis or interpretation of the trial, One of these is true

      Your Answer:

      Correct Answer: The data could be evaluated using the chi square test

      Explanation:

      This data is in a 2 × 2 contingency table so a chi square test can be used. There is a special chi squared formula that gives a value that can be looked up in a table giving the p value.

      Since we are comparing proportions not means, the Student’s t test CANNOT be used.

      There is no linear regression to plot so Pearson’s co-efficient cannot be calculated.

      Nothing is so obvious that no statistical analysis is needed.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 57 - How many unpaired branches leave the abdominal aorta to supply the abdominal viscera?...

    Incorrect

    • How many unpaired branches leave the abdominal aorta to supply the abdominal viscera?

      Your Answer:

      Correct Answer: Three

      Explanation:

      The abdominal arteries are divided into 3 branches;
      – 3 main unpaired trunks (celiac trunk, superior mesenteric, inferior mesenteric arteries)
      – 6 paired branches
      – unpaired median sacral artery.

      We can group the abdominal aorta as follows;
      -Ventral which includes: Coeliac trunk, superior mesenteric and inferior mesenteric arteries
      -Lateral: Inferior phrenic, middle suprarenal, renal and gonadal arteries
      -Dorsal: Lumbar and median sacral arteries
      -Terminal : Right and left common iliac arteries

      The celiac trunk (L1) takes blood the foregut and its found posterior to the stomach. The unpaired superior mesenteric artery supplies blood to the mid-gut.

      The paired renal arteries form the inferior suprarenal arteries. The renal arteries arise around L1/L2 and takes blood to either side of the kidneys.

      The median sacral artery supplies blood to the lumbar vertebrae the L4 and L5.

    • This question is part of the following fields:

      • Anatomy
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  • Question 58 - One of two divisions of the autonomic nervous system is the sympathetic nervous...

    Incorrect

    • One of two divisions of the autonomic nervous system is the sympathetic nervous system. It is both anatomically and physiologically different from the parasympathetic nervous system.

      Which best describes the anatomical layout of the sympathetic nervous system?

      Your Answer:

      Correct Answer: Short myelinated preganglionic neurones from T1-L5 in lateral horns of grey matter of spinal cord, synapse in sympathetic ganglia (neurotransmitter - acetyl choline), long unmyelinated postganglionic neurones, synapse with effector organ (neurotransmitter - adrenaline or noradrenaline)

      Explanation:

      The autonomic nervous system is divided into the sympathetic and parasympathetic nervous system. They are anatomically and physiologically different.

      The sympathetic nervous system arises from the thoracolumbar outflow (T1-L5 ) at the lateral horns of grey matter of the spinal cord. Their preganglionic neurones are usually short myelinated and synapse in ganglia lateral to the vertebral column and have acetyl choline (Ach) as the neurotransmitter. Their postganglionic neurones are longer and unmyelinated and synapse with effector organ where the neurotransmitter is either adrenaline or noradrenaline.

      The outflow of the parasympathetic nervous system is craniosacral. The cranial part originates from the midbrain and medulla (cranial nerves III, VII, IX and X) and the sacral outflow is from S2, S3 and S4. Their preganglionic neurones are usually long myelinated and synapse in ganglia close to the target organ and has Ach as its neurotransmitter. The unmyelinated postganglionic neurones is shorter and they synapse with effector organ. The neurotransmitter here is also Ach.

      Both sympathetic and parasympathetic preganglionic neurons are cholinergic. Only the postganglionic parasympathetic neurons are cholinergic.

    • This question is part of the following fields:

      • Anatomy
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  • Question 59 - Of the following, which is NOT a branch of the abdominal aorta? ...

    Incorrect

    • Of the following, which is NOT a branch of the abdominal aorta?

      Your Answer:

      Correct Answer: Superior phrenic artery

      Explanation:

      The abdominal aorta begins at the level of the body of T12 near the midline, as a continuation of the thoracic aorta. It descends and bifurcates at the level of L4 into the common iliac arteries.

      The branches of the abdominal aorta (with their vertebra level) are:
      1. Inferior phrenic arteries: T12 (upper border)
      2. Coeliac artery: T12
      3. Superior mesenteric artery: L1
      4. Middle suprarenal arteries: L1
      5. Renal arteries: Between L1 and L2
      6. Gonadal arteries: L2 (in males, it is the testicular artery, and in females, the ovarian artery)
      7. Inferior mesenteric artery: L3
      8. Median sacral artery: L4
      9. Lumbar arteries: Between L1 and L4

      The superior phrenic artery branches from the thoracic aorta.

    • This question is part of the following fields:

      • Anatomy
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  • Question 60 - Which of the following closely estimates the interstitial oncotic pressure acting on a...

    Incorrect

    • Which of the following closely estimates the interstitial oncotic pressure acting on a pulmonary capillary?

      Your Answer:

      Correct Answer: 17 mmHg

      Explanation:

      The starling forces operate to maintain a homeostatic flow across the pulmonary capillary bed.

      The outward driving force comprises of the capillary hydrostatic pressure (13 mmHg), negative interstitial fluid pressure (zero to slightly negative), and interstitial colloid osmotic pressure (17 mmHg). The inward driving force is controlled by the plasma colloid osmotic pressure (25 mmHg).

    • This question is part of the following fields:

      • Basic Physics
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  • Question 61 - A log-dose response curve is plotted after drug A is given. The shape...

    Incorrect

    • A log-dose response curve is plotted after drug A is given. The shape of this curve is sigmoid, with a maximum response of 100%.

      The log-dose response curve of drug A shifts to the right with a maximum response of 100 percent when drug B is administered.

      What does this mean in terms of drug B?

      Your Answer:

      Correct Answer: Drug B has affinity for the receptor but has no intrinsic efficacy

      Explanation:

      Drug A is a pure agonist for the receptor, with high intrinsic efficacy and affinity, according to the log-dose response curve.

      Drug B, on the other hand, works as a competitive antagonist. It binds to the receptor but has no inherent efficacy. Drug A’s efficacy will not change, but its potency will be reduced.

      A partial agonist is a drug with partial intrinsic efficacy and affinity for the receptor. Giving a partial agonist after a pure agonist will not increase receptor occupancy or decrease receptor activity, and thus will not affect drug A’s efficacy. The inverse agonist flumazenil can reverse all benzodiazepines.

      An inverse agonist is a drug that binds to the receptor but has the opposite pharmacological effect.

      A non-competitive antagonist is a drug that has affinity for a receptor but has different pharmacological effects and reduces the efficacy of an agonist for that receptor.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 62 - Which of the following statements is true regarding oxytocin? ...

    Incorrect

    • Which of the following statements is true regarding oxytocin?

      Your Answer:

      Correct Answer: Reduces the threshold for depolarisation of the uterine smooth muscle

      Explanation:

      Oxytocin is secreted by the posterior pituitary along with Antidiuretic Hormone (ADH). It increases the contraction of the upper segment (fundus and body) of the uterus whereas the lower segment is relaxed facilitating the expulsion of the foetus.

      Oxytocin acts through G protein-coupled receptor and phosphoinositide-calcium second messenger system to contract uterine smooth muscle.

      It has 0.5 to 1 % ADH activity introducing possibilities of water intoxication when used in high doses.

      The sensitivity of the uterus to oxytocin increases as the pregnancy progresses.

      It is used for induction of labour in post maturity and uterine inertia.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 63 - A 70-year-old male is brought to the Emergency department with:
    Pulse rate:...

    Incorrect

    • A 70-year-old male is brought to the Emergency department with:
      Pulse rate: 32 beats per minute
      Blood pressure: 82/35 mmHg
      12 lead ECG shows a sinus bradycardia of 35 beats per minute with no evidence of myocardial ischemia or infarction. There was no chest pain but the patient feels light-headed.

      Which of the following would be the best initial treatment for this condition?

      Your Answer:

      Correct Answer: Atropine

      Explanation:

      Based on the presenting symptoms and clinical examination, it is a case of an adult sinus bradycardia with adverse signs. The first pharmacological treatment for this condition is atropine 500mcg intravenously and if necessary repeat every three to five minutes up to a maximum of 3 mg.

      If the bradycardia does not subside even after the administration of atropine, cardiac pacing should be considered. If pacing cannot be achieved promptly, we should consider the use of second-line drugs like adrenaline, dobutamine, or isoprenaline.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 64 - Following a near drowning accident, a 5-year-old child is admitted to the emergency...

    Incorrect

    • Following a near drowning accident, a 5-year-old child is admitted to the emergency department and advanced paediatric life support is started.

      What is the child's approximate weight, according to the preferred formulae of the Resuscitation Council (UK), the European Resuscitation Council, and the Royal College of Anaesthetists?

      Your Answer:

      Correct Answer: 20-25kg

      Explanation:

      For estimating a child’s weight, the Resuscitation Council (UK) and European Resuscitation Council teach the following formula:

      Weight = (age + 4) × 2

      The weight of the child will be around 20 kg.

      This formula is used in the Primary FRCA exam by the Royal College of Anaesthetists.

      In ‘developed’ countries, the traditional ‘APLS formula’ for estimating weight in children based on age (wt in kg = [age+4] x 2) is acknowledged as underestimating weight by 33.4 percent on average, with the degree of underestimation increasing with increasing age.

      However, more recently, the APLS formula ‘Weight=3(age)+7’ has been found to provide a mean underestimate of only 6.9%. This formula is applicable to children aged 1 to 13 years.

      The estimated weight based on age using this formula is 25 kg.

    • This question is part of the following fields:

      • Physiology
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  • Question 65 - Which one of the following statement is true regarding United Kingdom gas cylinders?...

    Incorrect

    • Which one of the following statement is true regarding United Kingdom gas cylinders?

      Your Answer:

      Correct Answer: Tensile tests are performed on sections of one cylinder in every hundred

      Explanation:

      Medical gas cylinders are made up of molybdenum steel but not cast iron. They are checked and assessed at a regular interval.

      At least one cylinder in each hundred are tested for tensile, pressure, smash, twist and straightening.

      Nitrous Oxide cylinders contain a mixture of liquid and vapour at a pressure of approx. 4500 kPa or 45 Bar. Carbon dioxide cylinder contain gas at the pressure of 5000kPa.

      The filling ratio is the ratio of mass of liquified gas in the cylinder to the mass of water required to fill the cylinder at the temperature of 15ºC. In the united kingdom, filling ratio of liquid nitrous oxide is 0.75. The cylinders are usually attached to the anaesthetic machine. As nitrous oxide is an N-methyl-d-aspartate receptor antagonist that may reduce the incidence of chronic post-surgical pain.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 66 - The spinal cord tracts that transmits the sensations of pain, crude temperature, and...

    Incorrect

    • The spinal cord tracts that transmits the sensations of pain, crude temperature, and light touch is?

      Your Answer:

      Correct Answer: Spinothalamic

      Explanation:

      Dorsal column (ascending tract) – Proprioception, vibration, discriminative

      Spinocerebellar (ascending tract) – Subconscious muscle position and tone

      Corticospinal (descending tract) – Voluntary muscle

      Rubrospinal (descending tract) – Flexor muscle tone

      Vestibulospinal (descending tract) – Reflexes and muscle tone

      Reticulospinal(descending tract) – Voluntary movements, head position.-

      Autonomic – Descending tract.

    • This question is part of the following fields:

      • Anatomy
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  • Question 67 - Regarding the classification of breathing systems, which of the following is true? ...

    Incorrect

    • Regarding the classification of breathing systems, which of the following is true?

      Your Answer:

      Correct Answer: The Conway classification describes a functional classification based on whether a CO2 absorber is required

      Explanation:

      Breathing system is an assembly of components which connects patient’s airway to anaesthesia machine through which controlled composition of gas mixture is dispensed. It delivers gas to the patient, removes expired gas and controls the temperature and humidity of the inspired mixture. It allows spontaneous, controlled, or assisted respiration. It may also provide ports for gas sampling, airway pressure, flow and volume monitoring.

      Breathing systems have been classified by Conway and Mapleson.
      Conway suggested a functional classification:
      – Circuits requiring a CO2 absorber
      – Circuits not requiring a CO2 absorber

      William Mapleson designated varying arrangements of breathing system components (masks, breathing tubes, fresh gas flow inlets, adjustable pressure-limiting valves, and reservoir bags) as Mapleson A-E circuits.
      Mapleson A: Arranged as FGF inlet, reservoir bag, APL valve, mask.
      In this circuit, because the reservoir bag is between the FGF inlet valve and the APL valve, expired gas from the patient may re-enter the system and fill the reservoir bag during controlled ventilation. This is the most efficient system for spontaneous breathing as the FGF must only be equal to a patient’s minute ventilation to prevent rebreathing.

      Mapleson B: Arranged as reservoir bag, FGF inlet, APL valve, mask.
      In this circuit, the FGF inlet is closer to the APL valve, which helps prevent the rebreathing concern in the Mapleson A circuit as above during controlled ventilation.

      Mapleson C: Arranged as reservoir bag, FGF inlet, APL valve, mask.
      In this circuit, the arrangement is the same as the Mapleson B circuit. However, this circuit is shorter as it does not contain elongated corrugated tubing. This circuit also has the FGF inlet close to the APL valve to aid in preventing rebreathing.

      Mapleson D: Arranged as reservoir bag, APL valve, FGF inlet, and mask.
      In this circuit, the arrangement interchanges the FGF inlet and APL valve of the Mapleson A circuit. This system prevents rebreathing by directing FGF towards the APL valve rather than towards the patient during exhalation.

      Mapleson E: Arranged as corrugated tubing, FGF inlet, and mask.
      In this circuit, there is no reservoir bag and no APL valve. Given the inability to alter the pressure of the circuit, this is ideal for spontaneously ventilating neonates or paediatric patients where low-pressure ventilation is desired. The system prevents rebreathing, similar to the Mapleson D circuit.

      Jackson Rees later modified the Mapleson E by adding an open ended bag, which has since become known as the Mapleson F.
      Mapleson F: Arranged as APL valve directly connected to reservoir bag, corrugated tubing, FGF inlet, and mask.
      The system prevents rebreathing similarly to Mapleson D by directing FGF towards the APL valve.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 68 - Of the following, which of these oxygen carrying molecules causes the greatest shift...

    Incorrect

    • Of the following, which of these oxygen carrying molecules causes the greatest shift of the oxygen-dissociation curve to the left?

      Your Answer:

      Correct Answer: Myoglobin (Mb)

      Explanation:

      Myoglobin is a haemoglobin-like, iron-containing pigment that is found in muscle fibres. It has a high affinity for oxygen and it consists of a single alpha polypeptide chain. It binds only one oxygen molecule, unlike haemoglobin, which binds 4 oxygen molecules.

      The myoglobin ODC is a rectangular hyperbola. There is a very low P50 0.37 kPa (2.75 mmHg). This means that it needs a lower P50 to facilitate oxygen offloading from haemoglobin. It is low enough to be able to offload oxygen onto myoglobin where it is stored. Myoglobin releases its oxygen at the very low PO2 values found inside the mitochondria.

      P50 is defined as the affinity of haemoglobin for oxygen: It is the PO2 at which the haemoglobin becomes 50% saturated with oxygen. Normally, the P50 of adult haemoglobin is 3.47 kPa(26 mmHg).

      Foetal haemoglobin has 2 ? and 2 ?chains. The ODC is left shifted – this means that P50 lies between 2.34-2.67 kPa [18-20 mmHg]) compared with the adult curve and it has a higher affinity for oxygen. Foetal haemoglobin has no ? chains so this means that there is less binding of 2.3 diphosphoglycerate (2,3 DPG).

      Carbon monoxide binds to haemoglobin with an affinity more than 200-fold higher than that of oxygen. This therefore decreases the amount of haemoglobin that is available for oxygen transport. Carbon monoxide binding also increases the affinity of haemoglobin for oxygen, which shifts the oxygen-haemoglobin dissociation curve to the left and thus impedes oxygen unloading in the tissues.

      In sickle cell disease, (HbSS) has a P50 of 4.53 kPa(34 mmHg).

    • This question is part of the following fields:

      • Physiology
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  • Question 69 - A 28-year-old girl, Sam, has suffered a road traffic accident. She is brought...

    Incorrect

    • A 28-year-old girl, Sam, has suffered a road traffic accident. She is brought to the emergency department and undergoes investigations and treatment.

      On X-ray of the humerus, she has a mid-shaft fracture.

      What structure is at the highest risk of damage with a mid-shaft humeral fracture?

      Your Answer:

      Correct Answer: Radial nerve

      Explanation:

      Mid-shaft fractures of the humerus usually occur after a direct blow to the upper arm, which can occur after a fall or RTAs.
      The most important clinical significance of a mid-shaft humeral fracture is an injury to the radial nerve. The radial nerve originates from the brachial plexus and has roots of C5-T1. It crosses the spiral groove on the posterior side of the shaft of the humerus.
      On examination, the patient may have a wrist drop, loss or weakness of finger extension, and decreased or absent sensation to the posterior forearm, digits 1 to 3, and the radial half of the fourth digit.

      The humeral shaft has two compartments:
      1. Anterior:
      Brachial artery and vein
      Biceps brachii, brachialis, coracobrachialis
      Musculocutaneous, median, and ulnar nerves
      2. Posterior:
      Radial nerve
      Triceps

      Other significant nerve injuries are:
      1. Axillary nerve – surgical neck fracture of the humerus
      2. Brachial Artery – supracondylar fracture of the humerus
      3. Axillary artery – surgical neck fracture of the humerus, but is relatively uncommon

    • This question is part of the following fields:

      • Anatomy
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  • Question 70 - You performed pelvic ultrasound of Mrs Aciman as she had pelvic bloating and...

    Incorrect

    • You performed pelvic ultrasound of Mrs Aciman as she had pelvic bloating and intermittent pain. The ultrasound shows a complex ovarian cyst and the radiologist who reported the results has advised urgent consultation with a gynaecologist. Upon breaking the news to Mrs Aciman you learn that she recently had a blood test done that was normal. You explain it to her that the test performed (Ca-125) is not always perfect and is only able to detect 80% of the cancer cases while the remaining 20% go undetected.

      Which statistical term appropriately explains the 80% in this example.

      Your Answer:

      Correct Answer: Sensitivity

      Explanation:

      Tests are used to confirm the presence of a particular disease. However the results can be misleading at times since most of the tests have some limitations associated with them.
      Sensitivity is the correct term that refers to the probability of a positive test. The others are explained below:

      False Positive rates refer to the proportion of the patients who don’t have the condition being detected as positive.

      False Negative rates refer to the proportion of the patients who have the condition being detected as negative (like the 20% of the patients that went undetected by the Ca-125 test).

      Specificity describes the ability of a test to detect and pick up people without the disease. Absolute risk ratio compares the rate of two separate outcomes.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 71 - Which of the following can be measured directly using spirometry? ...

    Incorrect

    • Which of the following can be measured directly using spirometry?

      Your Answer:

      Correct Answer: Vital capacity

      Explanation:

      Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).

      It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.

      During spirometry, the following measurements can be determined:
      Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
      Forced expiratory volume in one second (FEV1)
      FEV1/FVC ratio
      Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
      Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
      Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.

      Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.

      Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution

      The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 72 - Which of the following statement is not true regarding Adrenaline or Epinephrine? ...

    Incorrect

    • Which of the following statement is not true regarding Adrenaline or Epinephrine?

      Your Answer:

      Correct Answer: Inhibits Glucagon secretion in the pancreas

      Explanation:

      Adrenaline acts on ?1, ?2,?1, and ?2 receptors and also on dopamine receptors (D1, D2) and have sympathomimetic effects.

      Natural catecholamines are Adrenaline, Noradrenaline, and Dopamine

      Adrenaline is a sympathomimetic amine with both alpha and beta-adrenergic stimulating properties.
      Adrenaline is the drug of choice for anaphylactic shock
      Adrenaline is also used in patients with cardiac arrest. The preferred route is i.v. followed by the intra-osseous and endotracheal route.

      Adrenaline is released by the adrenal glands, acts on ? 1 and 2, ? 1 and 2 receptors, and is responsible for fight or flight response.

      It acts on ? 2 receptors in skeletal muscle vessels-causing vasodilation.

      It acts on ? adrenergic receptors to inhibit insulin secretion by the pancreas. It also stimulates glycogenolysis in the liver and muscle, stimulates glycolysis in muscle.

      It acts on ? adrenergic receptors to stimulate glucagon secretion in the pancreas. It also stimulates Adrenocorticotrophic Hormone (ACTH) and stimulates lipolysis by adipose tissue

    • This question is part of the following fields:

      • Pharmacology
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  • Question 73 - Monitoring of which of the following is indicated in the prevention of propofol...

    Incorrect

    • Monitoring of which of the following is indicated in the prevention of propofol infusion syndrome?

      Your Answer:

      Correct Answer: Lactate

      Explanation:

      Propofol infusion syndrome (PRIS) is characterized by lactic acidosis, bradyarrhythmia, rhabdomyolysis, cardiac and renal failure, and often leads to death. So, lactate monitoring is advised in patients with propofol infusion syndrome.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 74 - Anaesthetic gas concentrations can be measured using a refractometer. The main principal which...

    Incorrect

    • Anaesthetic gas concentrations can be measured using a refractometer. The main principal which allows it to be used for this purpose is which of the following?

      Your Answer:

      Correct Answer: Refraction

      Explanation:

      Refractometers measure the degree to which the light changes direction, called the angle of refraction. A refractometer takes the refraction angles and correlates them to refractive index (nD) values that have been established. Using these values, you can determine the concentrations of solutions.

    • This question is part of the following fields:

      • Basic Physics
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  • Question 75 - A common renal adverse effect of non-steroidal anti-inflammatory drugs is? ...

    Incorrect

    • A common renal adverse effect of non-steroidal anti-inflammatory drugs is?

      Your Answer:

      Correct Answer: Haemodynamic renal insufficiency

      Explanation:

      Prostaglandins do not play a major role in regulating RBF in healthy resting individuals. However, during pathophysiological conditions such as haemorrhage and reduced extracellular fluid volume (ECVF), prostaglandins (PGI2, PGE1, and PGE2) are produced locally within the kidneys and serve to increase RBF without changing GFR. Prostaglandins increase RBF by dampening the vasoconstrictor effects of both sympathetic activation and angiotensin II. These effects are important because they prevent severe and potentially harmful vasoconstriction and renal ischemia. Synthesis of prostaglandins is stimulated by ECVF depletion and stress (e.g. surgery, anaesthesia), angiotensin II, and sympathetic nerves.

      Non-steroidal anti-inflammatory drugs (NSAIDs), such as ibuprofen and naproxen, potently inhibit prostaglandin synthesis. Thus administration of these drugs during renal ischemia and hemorrhagic shock is contraindicated because, by blocking the production of prostaglandins, they decrease RBF and increase renal ischemia. Prostaglandins also play an increasingly important role in maintaining RBF and GFR as individuals age. Accordingly, NSAIDs can significantly reduce RBF and GFR in the elderly.

    • This question is part of the following fields:

      • Physiology
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  • Question 76 - A strain gauge operates on which of the following principles? ...

    Incorrect

    • A strain gauge operates on which of the following principles?

      Your Answer:

      Correct Answer: Varying resistance of a wire when stretched

      Explanation:

      The principle by which a strain gauge works is that when a wire is stretched, it becomes longer and thinner, and as a result, its resistance increases.

      A strain gauge, which is used in pressure transducers, acts as a resistor. When the pressure in a pressure transducer changes, the diaphragm moves, changing the tension in the resistance wire and thus changing the resistance.

      Changes in current flow through the resistor are amplified and displayed as a pressure change measure.

      A Wheatstone bridge, on the other hand, is frequently used to measure or monitor these changes in resistance.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 77 - Which among the following is not true regarding disease rates? ...

    Incorrect

    • Which among the following is not true regarding disease rates?

      Your Answer:

      Correct Answer: The odds ratio is synonymous with the risk ratio

      Explanation:

      The relative risk (also known as risk ratio [RR]) is the ratio of risk of an event in one group (e.g., exposed group) versus the risk of the event in the other group (e.g., nonexposed group).

      The odds ratio (OR) is the ratio of odds of an event in one group versus the odds of the event in the other group.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 78 - An orthopaedic surgery is scheduled for a 68-year-old man. He is normally in...

    Incorrect

    • An orthopaedic surgery is scheduled for a 68-year-old man. He is normally in good shape. His routine biochemistry results are checked and found to be within normal limits.

      Which of the following pairs has the greatest impact on his plasma osmolarity?

      Your Answer:

      Correct Answer: Sodium and potassium cations

      Explanation:

      The number of osmoles (Osm) of solute per litre (L) of solution (Osmol/L) is the unit of measurement for solute concentration. The calculated serum osmolality assumes that the primary solutes in the serum are sodium salts (chloride and bicarbonate), glucose, and urea nitrogen.

      2 (Na + K) + Glucose + Urea (all in mmol/L) = calculated osmolarity

      313 mOsm/L = 2 (144 + 6) + 9.5 + 3.5

      Sodium and potassium ions clearly contribute the most to plasma osmolarity. Glucose and urea, on the other hand, are less so.

      The osmolarity of normal serum is 285-295 mOsm/L. Temperature and pressure affect osmolality, and this calculated variable is less than osmolality for a given solution.

      The number of osmoles (Osm) of solute per kilogramme (Osm/kg) is a measure of osmolality, which is also a measure of solute concentration. Temperature and pressure have no effect on the value. An osmometer is used to measure it in the lab. Osmometers rely on a solution’s colligative properties, such as a decrease in freezing point or a rise in vapour pressure.

      The osmolar gap (OG) is calculated as follows:

      OG = osmolaRity calculated from measured serum osmolaLity

      Excess alcohols, lipids, and proteins in the blood can all contribute to the difference.

    • This question is part of the following fields:

      • Physiology
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  • Question 79 - A new clinical trial evaluates the effect of a new drug Z on...

    Incorrect

    • A new clinical trial evaluates the effect of a new drug Z on all-cause mortality. The rate of death in the group receiving this drug is 8%, compared with 16% in the control group.

      What is the number needed to treat with drug Z to prevent death?

      Your Answer:

      Correct Answer: 13

      Explanation:

      Number needed to treat is a measure of the impact of a treatment or intervention that is often used to communicate results to patients, clinicians, the public and policymakers. It states how many patients need to be treated for one additional patient to experience an adverse outcome (e.g. a death).

      It is calculated as the inverse of the absolute risk reduction and is rounded to the next highest whole number.

      The absolute risk reduction is 8% (16% – 8%). 100/8 = 12.5, so rounding up the next integer this gives at NNT of 13. i.e. you would need to give the new drug to 13 people to ensure that you prevented one death.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 80 - Which of the following statements is true about data analysed from a new...

    Incorrect

    • Which of the following statements is true about data analysed from a new drug trial?

      Your Answer:

      Correct Answer: The data could be evaluated using the chi square test

      Explanation:

      The data is ideal for chi square test evaluation as it will help determine if observed outcomes are in line with expected outcomes, and also if results are significant or due to chance.

      The student’s t test is not ideal as it requires comparison of means from different populations, rather than proportions.

      Pearson’s coefficient of linear regression is not ideal as it requires the plotting of a linear regression.

      The numbers should be analysed before determining if there are any statistical conclusions that can be drawn from the population.

      Statistical analysis is always required to determine the performance of any treatment during a clinical drug trial. Conclusions cannot be drawn simply by looking at the data.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 81 - A post-operative patient was given paracetamol and pethidine for post-operative analgesia. A few...

    Incorrect

    • A post-operative patient was given paracetamol and pethidine for post-operative analgesia. A few hours later, the patient developed fever of 38°C, hypertension, and agitation.

      According to the patient's medical history, he is maintained on Levodopa and Selegiline for Parkinson's disease.

      Which of the following is the most probable cause of his manifestation?

      Your Answer:

      Correct Answer: Pethidine

      Explanation:

      Selegiline is a monoamine oxidase inhibitor. Inhibition of monoamine oxidase leads to increased levels of norepinephrine and serotonin in the central nervous system.

      Pethidine, also known as meperidine, is a strong agonist at the mu and kappa receptors. It inhibits pain neurotransmission and blocks muscarinic-specific actions.

      Administering opioid analgesic is relatively contraindicated to individuals taking monoamine oxidase inhibitors. This is because of the high incidence of serotonin syndrome, which is characterized by fever, agitation, tremor, clonus, hyperreflexia and diaphoresis. Onset of symptoms is within hours, and the treatment is mainly through sedation, paralysis, intubation and ventilation.

      The clinical findings are more consistent with Serotonin syndrome rather than exacerbation of Parkinson’s. Parkinson’s Disease (PD) exacerbations are defined as patient-reported or caregiver-reported episodes of subacute worsening of PD motor function in 1 or more domains (bradykinesia, tremor, rigidity, or PD-related postural instability/gait disturbance) that caused a decline in functional status, developed over a period of < 2 months, did not fluctuate with medication timing, and are not caused by intentional adjustments of PD medications by the treating neurologist. Malignant hyperthermia usually occurs within minutes of administration of a volatile anaesthetic, such as halothane, or succinylcholine. There is massive release of calcium from the sarcoplasmic reticulum, leading to fever, acidosis, rhabdomyolysis, trismus, clonus, and hypertension. In sepsis, it more common for patients to present with hypotension rather than hypertension.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 82 - Of the following, which option best describes the muscle type that has the...

    Incorrect

    • Of the following, which option best describes the muscle type that has the fastest twitch response to stimulation?

      Your Answer:

      Correct Answer: Type IIb skeletal muscle

      Explanation:

      Human skeletal muscle is composed of a heterogeneous collection of muscle fibre types which differ histologically, biochemically and physiologically.

      It can be biochemically classified into 2 groups. This is based on muscle fibre myosin ATPase histochemistry. These are:

      Type 1 (slow twitch): Muscle fibres depend upon aerobic glycolytic metabolism and aerobic oxidative metabolism. They are rich in mitochondria, have a good blood supply, rich in myoglobin and are resistant to fatigue.

      Type II (fast twitch): Muscle fibres are sub-divided into:
      Type IIa – relies on aerobic/oxidative metabolism
      Type IIb – relies on anaerobic/glycolytic metabolism.

      Fast twitch muscle fibres produce short bursts of power but are more easily fatigued.

      Cardiac and smooth muscle twitches are relatively slow compared with skeletal muscle.

    • This question is part of the following fields:

      • Physiology
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  • Question 83 - Which statement is false in regards to the Circle of Willis? ...

    Incorrect

    • Which statement is false in regards to the Circle of Willis?

      Your Answer:

      Correct Answer: Majority of blood passing through the vessels mix together

      Explanation:

      There is minimum mixing of blood passing through the vessels.

      The cerebral hemispheres are supplied by arteries that make up the Circle of Willis. The Circle of Willis is formed by the anastomosis of the two internal carotid arteries and two vertebral arteries. It lies in the subarachnoid space within the basal cisterns that surround the optic chiasma and infundibulum.

      Each half of the circle is formed by:
      1. Anterior communicating artery
      2. Anterior cerebral artery
      3. Internal carotid artery
      4. Posterior communicating artery
      5. Posterior cerebral arteries and the termination of the basilar artery

      The circle and its branches supply; the corpus striatum, internal capsule, diencephalon, and midbrain

    • This question is part of the following fields:

      • Anatomy
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  • Question 84 - A patient visits the radiology department for a magnetic resonance imaging (MRI) scan...

    Incorrect

    • A patient visits the radiology department for a magnetic resonance imaging (MRI) scan (MRI). The presence of metal implants must be ruled out prior to the scan.

      In a strong magnetic field, which of the following metals is the safest?

      Your Answer:

      Correct Answer: Chromium

      Explanation:

      Ferromagnetism is the property of a substance that is magnetically attracted and can be magnetised indefinitely. A material is said to be paramagnetic if it is attracted to a magnetic field. A substance is said to be diamagnetic if it is repelled by a magnetic field.

      Cobalt, iron, gadolinium, neodymium, and nickel are ferromagnetic.

      Gadolinium is a ferromagnetic rare earth metal that is ferromagnetic below 20 degrees Celsius (its Curie temperature). MRI scans are enhanced with gadolinium-based contrast media.

      When ferromagnetic materials are exposed to a magnetic field, they can cause a variety of issues like magnetic field interactions, heating, and image artefacts.

      Titanium, lead, chromium, copper, aluminium, silver, gold, and tin are non ferromagnetic.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 85 - Useful diagnostic information can be obtained from measuring the osmolality of biological fluids....

    Incorrect

    • Useful diagnostic information can be obtained from measuring the osmolality of biological fluids.

      Of the following physical principles, which is the most accurate and reliable method of measuring osmolality?

      Your Answer:

      Correct Answer: Depression of freezing point

      Explanation:

      Colligative properties are properties of solutions that depend on the number of dissolved particles in solution. They do not depend on the identities of the solutes.

      All of the above have colligative properties with the exception of depression of melting point.

      The osmolality from the concentration of a substance in a solution is measured by an osmometer. The freezing point of a solution can determines concentration of a solution and this can be measured by using a freezing point osmometer. This is applicable as depression of freezing point is directly correlated to concentration.

      Vapour pressure osmometers, which measure vapour pressure, may miss certain volatiles such as CO2, ammonia and alcohol that are in the solution

      The use of a freezing point osmometer provides the most accurate and reliable results for the majority of applications.

      Colligative properties does not include melting point depression . Mixtures of substances in which the liquid phase components are insoluble, display a melting point depression and a melting range or interval instead of a fixed melting point.

      The magnitude of the melting point depression depends on the mixture composition.

      The melting point depression is used to determine the purity and identity of compounds. EMLA (eutectic mixture of local anaesthetics) cream is a mixture of lidocaine and prilocaine and is used as a topical local anaesthetic. The melting point of the combined drugs is lower than that individually and is below room temperature (18°C).

    • This question is part of the following fields:

      • Physiology
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  • Question 86 - About the vagus nerve, which one of these is true ? ...

    Incorrect

    • About the vagus nerve, which one of these is true ?

      Your Answer:

      Correct Answer: Gives off the recurrent laryngeal nerve on the right as it passes anteriorly across the subclavian artery

      Explanation:

      The tenth cranial nerve (vagus nerve) has both sensory and motor divisions.

      It emerges from the anterolateral surface of the medulla in a groove between the olive and the inferior cerebellar peduncle as a series of 8-10 rootlets . It leaves the skull through the middle compartment of the jugular foramen and descends within the carotid sheath between the internal carotid artery and internal jugular vein. The right vagus crosses in front of the first part of the subclavian artery. It gives off the right recurrent laryngeal nerve at this point.

      The left recurrent laryngeal nerve passes around the ligamentum arteriosum.

      The external laryngeal nerve supplies the cricothyroid muscle while the recurrent laryngeal nerve supplies the other laryngeal muscles.

      The cranial part of the accessory nerve supplies all the muscles of the palate, via the pharyngeal plexus and the pharyngeal branch of the vagus nerve, except the tensor veli palatini which is supplied by the mandibular branch of the trigeminal nerve.

      The Sternothyroid, Sternohyoid, and Omohyoid muscles are supplied by the ansa cervicalis while the thyrohyoid muscle is supplied by the hypoglossal nerve.

    • This question is part of the following fields:

      • Anatomy
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  • Question 87 - You are asked about the relative risk associated with a drug. You happened...

    Incorrect

    • You are asked about the relative risk associated with a drug. You happened to have read a report in which the same drug was compared with a placebo and your initial thoughts after reading the study were that the drug will have significant side effects.

      What do you expect the value of relative risk to be?

      Your Answer:

      Correct Answer: Greater than 1

      Explanation:

      Risk ratio (relative risk) compares the probability of an event in an exposed (experimental) group to that of an event in the unexposed (control) group.

      A relative risk of 1 suggests that there is no discernible difference in the outcome whether or not it has been exposed.

      A relative risk of less than 1 indicates that probability of occurrence of an event is less if there is exposure.

      A relative risk of greater than 1 highlights that an event is most likely to occur if it was provided exposure. Since you believe that exposure (the new drug) would have side effects, the value should be greater than 1.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 88 - Under general anaesthesia, a 48-year-old patient is scheduled for some dental extractions. He...

    Incorrect

    • Under general anaesthesia, a 48-year-old patient is scheduled for some dental extractions. He tells you that he has a heart murmur and that he has always received antibiotic prophylaxis at the dentist. There are no allergies that he is aware of.

      Which antibiotic prophylaxis strategy is most appropriate for this patient?

      Your Answer:

      Correct Answer: Prophylactic antibiotics are unnecessary for this patient

      Explanation:

      The National Institute for Health and Care Excellence (NICE) has published guidelines on infective endocarditis prophylaxis (IE). The goal was to create clear guidelines for antibiotic prophylaxis in patients undergoing dental procedures as well as certain non-dental interventional procedures. A number of studies have found an inconsistent link between recent interventional procedures and the development of infective endocarditis in both dental and non-dental procedures.

      Antibiotic prophylaxis against infective endocarditis is not advised or required in the following situations:

      Dental patients undergoing procedures
      Patients undergoing procedures involving the upper and lower gastrointestinal tracts, the genitourinary tract (including urological, gynaecological, and obstetric procedures, as well as childbirth), and the upper and lower respiratory tract (including ear, nose and throat procedures and bronchoscopy).

      Antibiotic resistance can be exacerbated by the indiscriminate use of prophylactic antibiotics, but this is not the primary reason for avoiding their use in these situations.

      To reduce the risk of endocarditis, any patient who is at risk of developing IE should be investigated and treated as soon as possible. Patients with the following conditions are at risk of developing IE:
      acquired valvular heart disease with regurgitation or stenosis
      previous valve replacement
      structural congenital heart disease
      past history of IE, or
      hypertrophic cardiomyopathy (HOCM)

      It would also be appropriate for high-risk dental procedures and those with severe gingival disease.

      Although this patient may not have structural heart disease, ABs should be administered on a case-by-case basis.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 89 - Which of the following statement is true about Loop diuretics? ...

    Incorrect

    • Which of the following statement is true about Loop diuretics?

      Your Answer:

      Correct Answer: Are useful in the treatment of acute heart failure

      Explanation:

      Loop diuretics act by causing inhibition of Na+ K+ 2Cl– symporter present at the luminal membrane of the ascending limb of the loop of Henle.

      Furosemide, torsemide, bumetanide, ethacrynic acid, furosemide, piretanide, tripamide, and mersalyl are the important members of this group

      The main use of loop diuretics is to remove the oedema fluid in renal, hepatic, or cardiac diseases. Thus they are useful in the treatment of acute heart failure. These can be administered i.v. for prompt relief of acute pulmonary oedema (due to vasodilatory action).

      Hypokalaemia, hypomagnesemia, hyponatremia, alkalosis, hyperglycaemia, hyperuricemia, and dyslipidaemia are seen with both thiazides as well as loop diuretics

    • This question is part of the following fields:

      • Pharmacology
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  • Question 90 - Which of the following drugs is an enzyme inducer? ...

    Incorrect

    • Which of the following drugs is an enzyme inducer?

      Your Answer:

      Correct Answer: Rifampicin

      Explanation:

      Rifampicin is a potent inducer of liver cytochrome enzymes. Other enzyme inducers are:
      Carbamazepine
      Sodium valproate
      Phenytoin
      Phenobarbitone

    • This question is part of the following fields:

      • Pharmacology
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  • Question 91 - Which of the following statement is true regarding hypoxic pulmonary vasoconstriction (HPV)? ...

    Incorrect

    • Which of the following statement is true regarding hypoxic pulmonary vasoconstriction (HPV)?

      Your Answer:

      Correct Answer: 20 parts per million (ppm) of nitric oxide will reduce hypoxic pulmonary vasoconstriction

      Explanation:

      Hypoxic Pulmonary vasoconstriction (HPV) reflects the constriction of small pulmonary arteries in response to hypoxic alveoli (.i.e.; PO2 below 80-100mmHg or 11-13kPa).

      These blood vessels become independent of the nerve stimulus, when blood with a high PO2 flows through the lung which contains a low alveolar PO2.

      Thus a low PO2 within the alveoli has been shown to impact on hypoxic pulmonary vasoconstriction (HPV) more than a low PO2 within the blood.

      HPV results in the blood flow being directed away from poorly ventilated areas of the lung and helps to reduce the ventilation/perfusion mismatch (not increase).

      In animals, volatile anaesthetic agents can diminish HPV, while in adults, the evidence proves less persuading, in spite of the fact that it certainly doesn’t strengthen the effects.

      HPV response will be suppressed by 20 parts per million (ppm) of nitric oxide.

    • This question is part of the following fields:

      • Physiology
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  • Question 92 - Regarding oxygen consumption, which of these organs has the highest consumption at rest?...

    Incorrect

    • Regarding oxygen consumption, which of these organs has the highest consumption at rest?

      Your Answer:

      Correct Answer: Kidney

      Explanation:

      Oxygen delivery is related to blood flow as most of the oxygen binds to haemoglobin in red blood cells, although a small amount is dissolved in the plasma. Blood flow per 100 g of tissue is greatest in the kidneys.

      The following is the oxygen consumption rate of different organs in ml/minute/100g

      Hepatoportal = 2.2
      Kidney = 6.8
      Brain = 3.7
      Skin = 0.38
      Skeletal muscle = 0.18
      Heart = 11

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 93 - In the United Kingdom, a new breast cancer screening test is being conducted...

    Incorrect

    • In the United Kingdom, a new breast cancer screening test is being conducted compared to the conventional use of mammography. This test predicts that if the breast cancer is diagnosed at an earlier stage, it could improve the survival rate but the overall results remains constant.

      This is an example of what kind of bias?

      Your Answer:

      Correct Answer: Lead time bias

      Explanation:

      Recall bias introduced when participants in a study are systematically more or less likely to recall and relate information on exposure depending on their outcome status.

      In procedure bias, the researcher decides assignment of a treatment versus control and assigns particular patients to one group or the other non-randomly. This is unlikely to have occurred in this case, although it is not mentioned specifically.

      Self Selection or volunteer bias occur when those subjects are selected to participate in the study who are not the representative of the entire target population. those subjects may be from high socio-economic status and practice those activities or lifestyle that improves their health.

      Lead-time bias occurs when a disease is detected by a screening test at an earlier time point rather than it would have been diagnosed by its clinical appearance. In this bias, earlier detection improves the survival time in the intervention group.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 94 - A 20-year-old woman, presented to her GP after swallowing a tiny, sharp bone...

    Incorrect

    • A 20-year-old woman, presented to her GP after swallowing a tiny, sharp bone and is referred to an ENT. She explains that the bone feels stuck in her throat. A laryngoscopy is performed and it shows the bone is lodged in the piriform recess.

      Name the nerve at highest risk of damage by the bone?

      Your Answer:

      Correct Answer: Internal laryngeal nerve

      Explanation:

      The internal laryngeal nerve lies inferior to the piriform recess mucous membrane, placing it at high risk of irritation or damage by sharp foreign objects which become lodged in the recess.

      Any attempt to retrieve lodged foreign objects must be done careful as there is also a high risk of damage during this process.

      The other mentioned nerves are not at risk of being affected.

    • This question is part of the following fields:

      • Anatomy
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  • Question 95 - A 30-year old female was anaesthetically induced for an elective open cholecystectomy. Upon...

    Incorrect

    • A 30-year old female was anaesthetically induced for an elective open cholecystectomy. Upon mask ventilation, patient's oxygen saturation level dropped to 90% despite maximal head extension, jaw thrust and two handed mask seal. Intubation was performed twice but failed. Use of bougie also failed to localize the trachea. Oxygen levels continued to drop, but was maintained between 80 and 88% with mask ventilation.

      Which of the following options is the best action to take for this patient?

      Your Answer:

      Correct Answer: Insert a supraglottic airway

      Explanation:

      A preplanned preinduction strategy includes the consideration of various interventions designed to facilitate intubation should a difficult airway occur. Non-invasive interventions intended to manage a difficult airway include, but are not limited to: (1) awake intubation, (2) video-assisted laryngoscopy, (3) intubating stylets or tube-changers, (4) SGA for ventilation (e.g., LMA, laryngeal tube), (5) SGA for intubation (e.g., ILMA), (6) rigid laryngoscopic blades of varying design and size, (7) fibreoptic-guided intubation, and (8) lighted stylets or light wands.

      Most supraglottic airway devices (SADs) are designed for use during routine anaesthesia, but there are other roles such as airway rescue after failed tracheal intubation, use as a conduit to facilitate tracheal intubation and use by primary responders at cardiac arrest or other out-of-hospital emergencies. Supraglottic airway devices are intrinsically more invasive than use of a facemask for anaesthesia, but less invasive than tracheal intubation. Supraglottic airway devices can usefully be classified as first and second generation SADs and also according to whether they are specifically designed to facilitate tracheal intubation. First generation devices are simply ‘airway tubes’, whereas second generation devices incorporate specific design features to improve safety by protecting against regurgitation and aspiration.

    • This question is part of the following fields:

      • Physiology
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  • Question 96 - Many of the processes we deal with in anaesthesia entail a relationship between...

    Incorrect

    • Many of the processes we deal with in anaesthesia entail a relationship between two or more variables.

      Which of the following relationships is a linear relationship?

      Your Answer:

      Correct Answer: The relationship between the junction potential and temperature in a thermocouple

      Explanation:

      Two bonded wires of dissimilar metals, iron/constantan or copper/constantan, make up a thermocouple (constantan is an alloy of copper and nickel). At the tip, a thermojunction voltage is generated that is proportional to temperature (Seebeck effect).

      All of the other connections are non-linear.

      For a single compartment model, the relationship between a decrease in plasma concentration of an intravenous bolus of a drug and time is a washout exponential.

      A sine wave is the relationship between current and degrees or time from a mains power source.

      A sigmoid curve represents the relationship between efficacy and log-dose of a pure agonist on mu receptors.

      The pressure of a fixed mass of gas and its volume (Boyle’s law) at a fixed temperature are inversely proportional, resulting in a hyperbolic curve.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 97 - What is factually correct regarding correlation and regression? ...

    Incorrect

    • What is factually correct regarding correlation and regression?

      Your Answer:

      Correct Answer: Regression allows one variable to be predicted from another variable

      Explanation:

      Linear regression, using a technique called curve fitting, allows us to make predictions regarding a certain variable.

      Correlation coefficient gives us an idea whether or not the two parameters provide have any relation of some sort or not i.e. does change in one prompt any change in other?

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 98 - After a bariatric surgery, average weight loss observed in patients is 18 kg....

    Incorrect

    • After a bariatric surgery, average weight loss observed in patients is 18 kg. The standard deviation was found to be 3 kg. What is the percentage of patients that lie between 9 and 27 kg?

      Note: Assume that the curve is normally distributed.

      Your Answer:

      Correct Answer: 99.70%

      Explanation:

      9 & 27 can be obtained by subtracting and adding 9 from the mean. 9 is three times the standard deviation and we know that 99.7% values lie within 3 standard deviations from the mean. We can find the interval for 99.7% to verify in the following way:

      For 99.7% confidence interval, you can find the range as follows:

      1. Multiply the standard error by 3.

      2. Subtract the answer from mean value to get the lower limit.

      3. Add the answer obtained in step 1 from the mean value to get the upper limit.

      4. The range turns out to be 9-27 kg.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 99 - Among the following options which one compares variance within the group and variance...

    Incorrect

    • Among the following options which one compares variance within the group and variance between groups?

      Your Answer:

      Correct Answer: ANOVA

      Explanation:

      ANOVA is based upon within group variance (i.e. the variance of the mean of a sample) and between group variance (i.e. the variance between means of different samples). The test works by finding out the ratio of the two variances mentioned above. (Commonly known as F statistic).

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 100 - A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a...

    Incorrect

    • A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a 57-year-old woman. Her vision is causing her problems.

      A macroadenoma compressing the optic chiasm is visible on MRI.

      What is the most likely visual field defect to be discovered during an examination?

      Your Answer:

      Correct Answer: Bitemporal hemianopia

      Explanation:

      The pituitary gland plays a crucial role in the neuro-endocrine axis. It is located at the base of the skull in the sella turcica of the sphenoid bone. It is connected superiorly to the hypothalamus, third ventricle, and visual pathways, and laterally to the cavernous sinuses, internal carotid arteries, and cranial nerves III, IV, V, and VI.

      Pituitary tumours make up about 10-15% of all intracranial tumours. The majority of adenomas are benign. Over-secretion of pituitary hormones (most commonly prolactin, growth hormone, or ACTH), under-secretion of hormones, or localised or generalised pressure effects can all cause symptoms.

      Compression of the optic chiasm can result in visual field defects, the most common of which is bitemporal hemianopia. This is caused by compression of the nasal retinal fibres, which carry visual impulses from temporal vision across the optic chiasm to the contralateral sides before continuing to the optic tracts.

      The interruption of the visual pathways distal to the optic chiasm causes a homonymous visual field defect. The loss of the right or left halves of each eye’s visual field is referred to as homonymous hemianopia. It’s usually caused by a middle or posterior cerebral artery territory stroke that affects the occipital lobe’s optic radiation or visual cortex.

      Binasal hemianopia is a condition in which vision is lost in the inner half of both eyes (nasal or medial). It’s caused by compression of the temporal visual pathways, which don’t cross at the optic chiasm and instead continue to the ipsilateral optic tracts. Binasal hemianopia is a rare complication caused by the internal carotid artery impinging on the temporal (lateral) visual fibres.

      A monocular visual loss (that is, loss of vision in only one eye) can be caused by a variety of factors, but if caused by nerve damage, the damage would be proximal to the optic chiasm on the ipsilateral side.

      A central scotoma is another name for central visual field loss. Every normal mammalian eye has a scotoma, also known as a blind spot, in its field of vision. The optic disc is a region of the retina that lacks photoreceptor cells and is where the retinal ganglion cell axons that make up the optic nerve exit the retina. When both eyes are open, visual signals that are absent in one eye’s blind spot are provided for the other eye by the opposite visual cortex, even if the other eye is closed.

      Scotomata can be caused by a variety of factors, including demyelinating disease such as multiple sclerosis, damage to nerve fibre layer in the retina, methyl alcohol, ethambutol, quinine, nutritional deficiencies, and vascular blockages either in the retina or in the optic nerve.

      Bilateral scotoma can occur when a pituitary tumour compresses the optic chiasm, causing a bitemporal paracentral scotoma, which then spreads out to the periphery, causing bitemporal hemianopsia. A central scotoma in a pregnant woman could be a sign of severe pre-eclampsia.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 101 - A patient was brought to the emergency room after passing black tarry stools....

    Incorrect

    • A patient was brought to the emergency room after passing black tarry stools. The initial diagnosis was upper gastrointestinal bleeding. The patient was placed on temporary nil per os (NPO) for the next 24 hours, his weight was 110 kg, and the required volume of intravenous fluid for the him was 3 litres. His electrolytes and other biochemistry studies were normal.

      If you were to choose the intravenous fluid regimen that would closely mimic his basic electrolyte and caloric requirements, which one would be the best answer?

      Your Answer:

      Correct Answer: 3000 mL 0.45% N. saline with 5% dextrose, each bag with 40 mmol of potassium

      Explanation:

      The patient in the case has a fluid volume requirement of 30 mL/kg/day. His basic electrolyte requirement per day is:

      Sodium at 2 mmol/kg/day x 110 = 220 mmol/day
      Potassium at 1 mmol/kg/day x 110 = 110 mmol/day

      His energy requirement per day is:

      35 kcal/kg/day x 110 kg = 3850 kcal/day

      One gram of glucose in fluid can provide approximately 4 kilocalories.

      The following are the electrolyte components of the different intravenous fluids:

      Fluid Na (mmol/L) K (mmol/L)
      0.9% Normal saline (NSS) 154 0
      0.45% NSS + 5% dextrose 77 0
      0.18% NSS + 4% dextrose 30 0
      Hartmann’s 131 5
      5% dextrose 0 0

      1000 mL of 5% dextrose has 50 g of glucose

      Option B is inadequate for his sodium and caloric requirements (30 mmol of Na+ and 560 kcal). It is adequate for his K+ requirement (120 mmol of K+).

      Option C is in excess of his Na+ requirement (462 mmol of Na+). Moreover, it does not provide any K+ replacement.

      Option D is inadequate for his caloric requirement (600 kcal) and K+ requirement (60 mmol of K+). Moreover it does not provide any Na+ replacement.

      Option E is in excess of his Na+ requirement (393 mmol of Na+), and is inadequate for his potassium requirement (15 mmol of K+)

      Option A has adequate amounts for his Na+ (231 mmol of Na+) and K+ (120 mmol of K+) requirements. It is inadequate for his caloric requirement (600 kcal).

    • This question is part of the following fields:

      • Physiology
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  • Question 102 - What is the most sensitive method of detecting an intra-operative air embolism? ...

    Incorrect

    • What is the most sensitive method of detecting an intra-operative air embolism?

      Your Answer:

      Correct Answer: Transoesophageal echocardiogram

      Explanation:

      An intra-operative air embolism occurs when air becomes trapped in the blood vessels during surgery.

      A transoesophageal echocardiography (OE) uses invasive echocardiography to monitor the integrity and performance of the heart. It is the gold standard as it provides real-time imaging of the heart to enable early diagnosis and treatment.

      Precordial doppler ultrasonography can also be used to detect into-operative air emboli. It is non-invasive and more practical, but is less sensitive.

      A change in end-tidal CO2 could be indicative of and increase in physiological dead-space, but could also be indicative of any processes that reduces the excretion or increases the production of CO2, making it non-specific.

      A transoesophageal stethoscope can be used to listen for the classic mill-wheel murmur produced by a large air embolus.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 103 - All of the following statements about intravenous induction agents are false except: ...

    Incorrect

    • All of the following statements about intravenous induction agents are false except:

      Your Answer:

      Correct Answer:

      Explanation:

      Thiopental is a new British Approved Name for thiopentone and is thio-barbiturate.
      Methohexitone is an oxy- barbiturate. Both thiopental and methohexitone are intravenous induction agents.

      Ketamine cannot cause loss of consciousness in less than 30 seconds. At least 30 seconds is needed to cause loss of consciousness following intravenous administration.

      Etomidate is an imidazole but it is not used in the Intensive Care unit for sedation because it has an antidepressant effect on the steroid axis.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 104 - Very large SI units are easily expressed using mathematical prefixes.

    One terabyte is equal...

    Incorrect

    • Very large SI units are easily expressed using mathematical prefixes.

      One terabyte is equal to which of the following numbers?

      Your Answer:

      Correct Answer: 1,000,000,000,000 bytes

      Explanation:

      To denote large measured units, the following SI mathematical prefixes are used:

      1 deca = 10 bytes (101)
      1 hecto (h) = 100 bytes
      1 kilo (k)= 1,000 bytes
      1 mega (M) = 1,000,000 bytes
      1 giga (G) = 1,000,000,000 bytes
      1 Tera (T) = 1,000,000,000,000 bytes
      1 Peta (P) = 1,000,000,000,000,000 bytes

    • This question is part of the following fields:

      • Basic Physics
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  • Question 105 - The spinal cord in a neonate terminates at the lower border of: ...

    Incorrect

    • The spinal cord in a neonate terminates at the lower border of:

      Your Answer:

      Correct Answer: L3

      Explanation:

      The spinal cord and the vertebral canal are as long as each other in early fetal life. The length of the cord increases faster than the growth of the vertebrae during development. By the time of birth, the spinal cord is at the level of the lower border of the 3rd lumbar vertebra, compared to its original position at the level of the 2nd coccygeal vertebra.

    • This question is part of the following fields:

      • Anatomy
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  • Question 106 - When administered as an infusion, which of the following medicines causes a reflex...

    Incorrect

    • When administered as an infusion, which of the following medicines causes a reflex tachycardia?

      Your Answer:

      Correct Answer: Phentolamine

      Explanation:

      The ?-2 adrenoceptor has three subtypes (2a, 2b and 2c). The receptors are generally presynaptic, meaning they prevent noradrenaline from being released at nerve endings. Both the central and peripheral nerve systems are affected by the ?-2 agonists. ?-2 agonists cause drowsiness, analgesia, and euphoria centrally in the locus coeruleus (in the brainstem), lower the MAC of volatile anaesthetic drugs, and are used to treat acute withdrawal symptoms in chronic opioid addicts.

      The most common impact of ?-2 agonists on heart rate is bradycardia. The adrenoreceptors ?-1 and ?-2 are blocked by phenoxybenzamine.

      Clonidine is a selective agonist for the ? -2 receptor, having a 200:1 affinity ratio for the ?-2: ?-1 receptors, respectively.

      Tizanidine is similar to clonidine but has a few key variances. It has the same sedative, anxiolytic, and analgesic characteristics as clonidine, although for a shorter period of time and with less effect on heart rate and blood pressure.

      Dexmedetomidine, like clonidine, is a highly selective ?-2 adrenoreceptor agonist having a higher affinity for the ?-2 receptor. In the case of ?-2: ?-1 receptors, the affinity ratio is 1620:1. It has a biphasic blood pressure impact and induces a brief rise in blood pressure and reflex bradycardia (activation of ?-2b subtypes of receptors in vascular smooth muscles), followed by a reduction in sympathetic outflow from the brainstem and hypotension/bradycardia.

      A prodrug is methyldopa. It blocks the enzyme dopa-decarboxylase, which converts L-dopa to dopamine (a precursor of noradrenaline and adrenaline). It is also converted to alpha-methyl noradrenaline, a centrally active agonist of the ?-2 adrenoreceptor. These two processes contribute to its blood pressure-lowering effect. Without a rise in heart rate, cardiac output is generally maintained. The heart rate of certain patients is slowed.

      Phentolamine is a short-acting antagonist of peripheral ?-1 and ?-2 receptors that causes peripheral vascular resistance to reduce and vasodilation to increase. It’s used to treat hypertensive situations that aren’t life threatening (e.g. hypertension from phaeochromocytoma).

      A baroreceptor reflex commonly causes reflex tachycardia when systemic vascular resistance drops.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 107 - Which medical gas cylinders have the correct colour codes? ...

    Incorrect

    • Which medical gas cylinders have the correct colour codes?

      Your Answer:

      Correct Answer: Oxygen cylinders have a black body with white shoulders

      Explanation:

      The following are the colour codes for medical gas cylinders:

      Oxygen cylinder has a dark body with white shoulders.

      Nitrous oxide is French blue. Air encompasses a grey body with dark and white quarters on the shoulders.

      Entonox contains a French blue body with white and blue quarters on the shoulders.

      Carbon dioxide barrels are grey in colour.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 108 - A transport ventilator connected to a size CD oxygen cylinder has a setting...

    Incorrect

    • A transport ventilator connected to a size CD oxygen cylinder has a setting of air/oxygen entrainment ratio of 1:1 and a minute volume set at 10 litres/minute.

      Which value best approximates to the FiO2?

      Your Answer:

      Correct Answer: 0.6

      Explanation:

      A nominal volume of 2 litres is contained in a CD cylinder. It has a pressure of 230 bar when full and contains litres 460 L of useable oxygen at STP.

      For every 1000 mL 100% oxygen there will be an entrainment of 1000 mL or air (20% oxygen) in an air/oxygen mix.

      The average concentration is, therefore, 120/2=60% or 0.6.

    • This question is part of the following fields:

      • Physiology
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  • Question 109 - Prophylactic antibiotics are required for which of the following procedures? ...

    Incorrect

    • Prophylactic antibiotics are required for which of the following procedures?

      Your Answer:

      Correct Answer: Appendicectomy

      Explanation:

      Correctly used, antibiotic prophylaxis can reduce
      the total use of antibiotics.
      There is strong scientific support that antibiotic
      prophylaxis reduces the development of infection after:

      • Operations and endoscopic procedures in the large intestine,
        the rectum, and the stomach (including appendectomies and
        penetrating abdominal trauma), and after percutaneous endoscopic gastrostomy (PEG)
      • Cardiovascular surgery, and insertion of pacemakers
      • Breast cancer surgery
      • Hysterectomy
      • Reduction of simple fractures and prosthetic limb surgery
      • Complicated surgery for cancer in the ear, nose, and throat
        regions
      • Transrectal biopsy and resection of the prostate (febrile urinary
        tract infection and blood poisoning).

      In most cases the scientific evidence is inadequate to determine
      which type of antibiotic is most effective for antibiotic prophylaxis.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 110 - A 67-year-old man, presents with an embolus in the lower limbs. He has...

    Incorrect

    • A 67-year-old man, presents with an embolus in the lower limbs. He has previous medical history of atrial fibrillation. After examination and diagnostic investigations, he is scheduled for a transpopliteal embolectomy, which will require the surgeons to explore the central region of the popliteal fossa.

      What structures will the surgeons come across after incising the deep fascia?

      Your Answer:

      Correct Answer: Tibial nerve

      Explanation:

      The tibial nerve lies on top of the vessels contained within the inferior aspect of the popliteal fossa.

      In the superior aspect of the fossa, the tibial nerve runs lateral to the vessels, before then travelling superficial to the vessels, and then finally changing course to lie medial to the vessels.

      The popliteal artery is the most deep structure present in the popliteal fossa

    • This question is part of the following fields:

      • Anatomy
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  • Question 111 - All of the following statements are false regarding tetracyclines except: ...

    Incorrect

    • All of the following statements are false regarding tetracyclines except:

      Your Answer:

      Correct Answer:

      Explanation:

      Tetracyclines inhibit protein synthesis through reversible binding to bacterial 30s ribosomal subunits (not 50s) which prevent binding of new incoming amino acids (aminoacyl-tRNA) and thus interfere with peptide growth.

      They penetrate macrophages and are thus a drug of choice for treating infections due to intracellular organisms.

      Tetracycline does not inhibit transpeptidation. Meanwhile, it is chloramphenicol which is responsible for inhibiting transpeptidation.

      Tetracycline can get deposited in growing bone and teeth due to its calcium-binding effect and thus causes dental discoloration and dental hypoplasia. Due to this reason, they should be avoided in pregnant or lactating mothers.

      Simultaneous administration of aluminium hydroxide can impede the absorption of tetracyclines.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 112 - Arrythmias can develop from abnormal conduction, which may be as a result of...

    Incorrect

    • Arrythmias can develop from abnormal conduction, which may be as a result of impaired blood flow in the coronary arteries which causes hypoxia. Phase 0 depolarisation can be slowed, and this leads to slower conduction speeds.
      Rapid depolarisation in the cardiac action potential is caused by which movement of ions?

      Your Answer:

      Correct Answer: Sodium influx

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 113 - A 60-year-old man, with a history of excessive alcohol intake, presents for the...

    Incorrect

    • A 60-year-old man, with a history of excessive alcohol intake, presents for the first time in the emergency department with acute abdominal pain in the epigastric region.

      On examination, the man is sweating and has a high-grade fever. His heart rate is 140/min and a BP of 92/59 mmHg.

      The patient is diagnosed with acute pancreatitis. Which of the following is a complication you are most likely to see in this patient?

      Your Answer:

      Correct Answer: Blue discolouration of the flank regions

      Explanation:

      Bulky, greasy stools are associated with improper digestion that can be expected if the pancreas loses its exocrine function. This is common in long-term chronic pancreatitis but since this is the patient’s first presentation with such symptoms, this complication is unlikely.

      Peripheral neuropathy is a common complication of chronic diabetes but has been reported with cases of chronic pancreatitis too.

      Abdominal distention with shifting dullness is a classic symptom of underlying ascites. Ascites is a complication of many diseases but it is not common with the acute first-time presentation of pancreatitis.

      Option E: This points towards abdominal obstruction but in the absence of the more common symptoms, nausea and bilious vomiting, this is unlikely.

      Option A: Grey Turner’s sign is the pooling of blood in the retroperitoneal space between the last rib and the top of the hip. The pancreas is a retroperitoneal organ and inflammation of the pancreas can cause retroperitoneal haemorrhage. The sign takes 24-48 hours to develop and can predict a severe attack of acute pancreatitis. The patient has presented with acute pancreatitis due to his history of high alcohol intake, and acute on chronic is unlikely as this is his first presentation. He also has low blood pressure and an increased heart rate, which suggest blood loss with acute pancreatitis.

    • This question is part of the following fields:

      • Anatomy
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  • Question 114 - Which measurements is the most accurate for predicting fluid responsiveness? ...

    Incorrect

    • Which measurements is the most accurate for predicting fluid responsiveness?

      Your Answer:

      Correct Answer: Change in stroke volume following passive straight leg raise

      Explanation:

      The passive leg raising (PLR) manoeuvre is a method of altering left and right ventricular preload and it is done with real-time measurement of stroke volume. It is a simple, quick, relatively unbiased, and accurate bedside test to guide fluid management and avoid fluid overload.

      Pulse pressure variation (PPV), Stroke volume variation (SVV), superior vena cava diameter variation (threshold 36%) and end-expiratory occlusion test are used for dynamic tests of fluid responsiveness.

      PPV is derived peripherally from the arterial pressure waveform.

      Stroke volume variation (SVV) can be derived peripherally through pulse contour analysis of the arterial waveform. PPV and SVV have a threshold of 12% but since they are not used in patients who have cardiac arrhythmias, are spontaneous breathing, and in ventilated patients with low lung compliance and tidal volumes, they are of limited value.

      The tests of fluid responsiveness’ accuracy is determined by calculating the area under the receiver operating characteristic curve (UROC) obtained by plotting the sensitivity of the parameter in predicting fluid responsiveness vs. 1-specificity.

      Under optimal conditions, the ability to determine the need for fluid is best with PPV>SVV>LVEDA>CVP.

      Central venous pressure (CVP) is a static test of preload (not preload responsiveness) and a key determinant of cardiac function. The left ventricular end-diastolic area (LVEDA) a static test of fluid responsiveness, is derived using echocardiography

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 115 - Lisa is a 75-year-old female rushed into the emergency department by first-aid responders....

    Incorrect

    • Lisa is a 75-year-old female rushed into the emergency department by first-aid responders. The ambulance team give a history of vomiting, homonymous hemianopia, weakness of the left upper and lower limb, and dysphasia. Lisa adds that she has a headache that keeps worsening.

      Lisa takes Warfarin as she is a known case of atrial fibrillation. Her INR is 4.3 despite the ideal target being 2-3.
      CT scan of the head suggests anterior cerebral artery haemorrhage.

      What areas of the brain are affected by an anterior cerebral artery stroke?

      Your Answer:

      Correct Answer: Frontal and parietal lobes

      Explanation:

      The anterior cerebral artery supplies the midline portion of the frontal lobe and the superior medial parietal lobe of the brain. It also supplies the front four-fifths of the corpus callosum and provides blood to deep structures such as the anterior limb of the internal capsule, part of the caudate nucleus, and the anterior part of the globus pallidus.

      The cerebral hemispheres are supplied by arteries that make up the Circle of Willis. The Circle of Willis is formed by the anastomosis of the two internal carotid arteries and two vertebral arteries.

      Clinically, the internal carotid arteries and their branches are often referred to as the anterior circulation of the brain. The anterior cerebral arteries are connected by the anterior communicating artery. Near their termination, the internal carotid arteries are joined to the posterior cerebral arteries by the posterior communicating arteries, completing the cerebral arterial circle around the interpeduncular fossa, the deep depression on the inferior surface of the midbrain between the cerebral peduncles.

      The middle cerebral artery supplies part of the frontal, temporal and parietal lobes.

      The posterior cerebral artery supplies the occipital lobe.

    • This question is part of the following fields:

      • Anatomy
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  • Question 116 - During a squint surgery, a 5-year-old child developed severe bradycardia as a result...

    Incorrect

    • During a squint surgery, a 5-year-old child developed severe bradycardia as a result of the oculocardiac reflex.

      The afferent limb of this reflex is formed by which nerve?

      Your Answer:

      Correct Answer: Trigeminal nerve

      Explanation:

      When the eye is compressed or the extra-ocular muscles are tractioned, the oculocardiac reflex causes a decrease in heart rate.

      The ophthalmic division of the trigeminal nerve provides the afferent limb. This synapses with the vagus nerve’s visceral motor nucleus in the brainstem. The efferent signal is carried by the vagus nerve to the heart, where increased parasympathetic tone reduces sinoatrial node output and slows heart rate.

      The most common symptom is sinus bradycardia, but junctional rhythm and asystole can also occur.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 117 - A 42 year old man came to the out-patient department with attacks of...

    Incorrect

    • A 42 year old man came to the out-patient department with attacks of facial pain. Upon further questioning, he reported that the pain was intermittent, often occurring spontaneously. The quality of the pain was sharp, and severity was moderate to moderately severe. The pain was non-radiating, and often involved the left maxillary and mandibular areas.

      Other medical information of the patient, such as allergies and co-morbidities, were unremarkable.

      Which of the following is the most probable diagnosis of the patient?

      Your Answer:

      Correct Answer: Trigeminal neuralgia

      Explanation:

      Trigeminal neuralgia is characterized by excruciating paroxysms of pain in the lips, gums, cheek, or chin and, very rarely, in the distribution of the fifth nerve. The pain seldom lasts more than a few seconds or a minute or two but may be so intense that the patient winces, hence the term tic. The paroxysms, experienced as single jabs or clusters, tend to recur frequently, both day and night, for several weeks at a time. They may occur spontaneously or with movements of affected areas evoked by speaking, chewing, or smiling. Another characteristic feature is the presence of trigger zones, typically on the face, lips, or tongue, that provoke attacks; patients may report that tactile stimuli – e.g., washing the face, brushing the teeth, or exposure to a draft of air – generate excruciating pain. An essential feature of trigeminal neuralgia is that objective signs of sensory loss cannot be demonstrated on examination.

      Trigeminal neuralgia is relatively common, with an estimated annual incidence of 4–8 per 100,000 individuals. Middle-aged and elderly persons are affected primarily, and ,60% of cases occur in women. Onset is typically sudden, and bouts tend to persist for weeks or months before remitting spontaneously. Remissions may be long-lasting, but in most patients, the disorder ultimately recurs.

      An ESR or CRP is indicated if temporal arteritis is suspected. In typical cases of trigeminal neuralgia, neuroimaging studies are usually unnecessary but may be valuable if MS is a consideration or in assessing overlying vascular lesions in order to plan for decompression surgery.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 118 - A 65-year-old man, presents to the emergency department. He explains that an hour...

    Incorrect

    • A 65-year-old man, presents to the emergency department. He explains that an hour ago, he experienced central chest pain, which moved down his left arm.
      On ECG, elevation in the ST-segment was noted in the anterior leads. He undergoes emergency percutaneous coronary intervention (PCI) which requires the cardiologist to access the heart via the femoral artery.

      Where is the surface marking for identifying the femoral artery?

      Your Answer:

      Correct Answer: Midway between the ASIS and the pubic symphysis

      Explanation:

      The surface marking for locating the femoral artery is the mid-inguinal point, which is the halfway point between the anterior superior iliac spine (ASIS) and the pubic symphysis.

      The other mentioned options are not specific for any landmark.

      However, it is important to note the difference between the mid inguinal point and the midpoint of the inguinal ligament, which is travels from the ASIS to the pubic tubercle.

    • This question is part of the following fields:

      • Anatomy
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  • Question 119 - A previously fit 26-year-old is undergoing surgery to repair an inguinal hernia. He...

    Incorrect

    • A previously fit 26-year-old is undergoing surgery to repair an inguinal hernia. He is breathing on his own, and a supraglottic airway is being maintained via a circle system with air/oxygen and sevoflurane.

      With a fresh gas flow of 14 L/min, the end-tidal CO2 reading is 8.1 kPa. CO2 pressure is 1.9 kPa. The percentages of oxygen inhaled and exhaled are 38 and 33 percent, respectively.

      What do you think is the most likely source for these readings?

      Your Answer:

      Correct Answer: Incompetent expiratory valve

      Explanation:

      The patient is rebreathing carbon dioxide that has been exhaled.

      Exhaustion of the soda lime and failure of the expiratory valve are the two most likely causes. A leak in the inspiratory limb is a less likely cause. Increased inhaled and exhaled carbon dioxide levels may appear with a normal-looking capnogram if the expiratory valve is ineffective.

      The patient will exhale into both the inspiratory and expiratory limbs if the inspiratory valve is inoperable. A slanted downstroke inspiratory phase (as the patient inhales carbon dioxide-containing gas from the inspiratory limb) and increased end-tidal carbon dioxide can be seen on the capnogram.

      Even if the soda lime were exhausted, a high fresh gas flow would be enough to prevent rebreathing. The difference in oxygen concentrations in inspired and expired breaths would be less pronounced.

      Hypercapnia is caused by respiratory obstruction and malignant hyperthermia, but not by rebreathing.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 120 - A balanced general anaesthetic including a muscle relaxant is administered at induction. It...

    Incorrect

    • A balanced general anaesthetic including a muscle relaxant is administered at induction. It is observed that the train-of-four count is two after two hours, with no further doses of the muscle relaxant.

      What is most likely reason for this?

      Your Answer:

      Correct Answer: Mivacurium with plasma cholinesterase deficiency

      Explanation:

      Mivacurium is metabolised primarily by plasma cholinesterase at an In vitro rate of about 70% that of succinylcholine. Mivacurium is contraindicated in patients with genetic and acquired plasma cholinesterase deficiencies.

      The clearance of atracurium is by Hoffman degradation and ester hydrolysis in the plasma and is independent of both hepatic and renal function.

      Rocuronium is eliminated primarily by the liver after metabolises to a less active metabolite, 17-desacetyl-rocuronium. Its duration of action is not affected much by renal impairment.

      Vecuronium undergoes hepatic metabolism into 3-desacetyl-vecuronium which has 50-80% the activity of the parent drug. It undergoes biliary (40%) and renal excretion (30%). The aminoglycoside antibiotics possess additional neuromuscular blocking activity. The potency of gentamicin > streptomycin > amikacin. Calcium can be used to reverse the muscle weakness produced by gentamicin but not neostigmine. When vecuronium and gentamycin are given together the effect on neuromuscular blockade is synergistic.

      Significant residual neuromuscular block 2 hours after the administration of these drugs is unlikely In this scenario.

      Any recovery from neuromuscular blockade with suxamethonium in a patient with deficiency of plasma cholinesterase demonstrate four twitches on a train of four count.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 121 - A 49-year-old woman is admitted to hospital. She is scheduled for surgery and...

    Incorrect

    • A 49-year-old woman is admitted to hospital. She is scheduled for surgery and is undergoing preoperative assessment.

      As part of the preoperative assessment, her functional capacity is estimated. At 50kg in weight, she is able to cycle along a flat surface at a speed of 10-14 miles/hour (8 metabolic equivalents or METs).

      Provide the best estimated value of oxygen consumption (VO2) for eight METs.

      Your Answer:

      Correct Answer: 1400 mL/minute

      Explanation:

      Oxygen consumption (VO2) refers to the optimal amount of oxygen used by the body during exercise.

      It is calculated mathematically by:

      VO2 = 3.5 x 50 x 8 = 1400 mL/kg/minute

      where,

      1 MET = 3.5 mL O2/kg/minute is utilized by the body.

      Note:

      1 MET Eating
      Dressing
      Use toilet
      Walking slowly on level ground at 2-3 mph
      2 METs Playing a musical instrument
      Walking indoors around house
      Light housework
      4 METs Climbing a flight of stairs
      Walking up hill
      Running a short distance
      Heavy housework, scrubbing floors, moving heavy furniture
      Walking on level ground at 4 mph
      Recreational activity, e.g. golf, bowling, dancing, tennis
      6 METs Leisurely swimming
      Leisurely cycling along the flat (8-10 mph)
      8 METs Cycling along the flat (10-14 mph)
      Basketball game
      10 METs Moderate to hard swimming
      Competitive football
      Fast cycling (14-16 mph)

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 122 - Which of the following statements about a cervical rib is correct? ...

    Incorrect

    • Which of the following statements about a cervical rib is correct?

      Your Answer:

      Correct Answer: It originates from the 7th cervical vertebra

      Explanation:

      The costal elements of the seventh cervical vertebrae form projections known as cervical ribs, which are present in approximately 0.5% – 1 % individuals.

      A cervical rib commonly comprises of a head, neck and tubercle. The body of the rib varies from person to person. It extends into the posterior triangle of the neck, where it is either free anteriorly, or attached to the first rib / sternum.

      Patients with a cervical rib mostly are asymptomatic and it is usually diagnosed as an incidental finding on chest x-ray. However, in some cases, the subclavian artery and the lower trunk of the brachial plexus are compressed where they pass over the cervical rib. This leads to a condition known as ”neurovascular compression syndrome,” in which these neurovascular structures are compressed between the cervical rib and scalenus anterior.

      The most common cause of neurogenic symptoms in approximately 80% of the patients with cervical rib is neck trauma.

      In most cases, the tingling, numbness and impaired circulation to the upper limb appears only after puberty. This is because the neck elongates, and the shoulders droop slightly.

    • This question is part of the following fields:

      • Anatomy
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  • Question 123 - If a patient is to be placed under general anaesthesia using total intravenous...

    Incorrect

    • If a patient is to be placed under general anaesthesia using total intravenous technique with target-controlled infusions of propofol and remifentanil, what safety precaution is the most vital in this a scenario?

      Your Answer:

      Correct Answer: Cannula access site clearly visible and regularly checked

      Explanation:

      According to the Safe Anaesthesia Liaison Group, the most important factor to consider the cannula access, and if the patient is properly receiving the total intravenous anaesthesia. The cannula access must be regularly checked for kinks, leaks and disconnections.

      Below are the safety precautions and policies to be followed for total intravenous anaesthesia among children and adults:

      When administering TIVA, a non-return valve must be used on any intravenous fluid line;
      When using equipment, it is essential that clinical staff know its limitations and uses;
      Sites of intravenous infusions should be visible so they may be monitored for disconnection, leaks or perivenous infusion into the subcutaneous tissues; and,
      Organisations must give preference to clearly labelled intravenous connectors and valves.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 124 - Following a physical assault, a 28-year-old man is admitted to the emergency room....

    Incorrect

    • Following a physical assault, a 28-year-old man is admitted to the emergency room. A golf club has struck him in the head.

      There is a large haematoma on the scalp, as well as a bleeding wound. In response to painful stimuli, he opens his eyes and makes deliberate movements. Because of inappropriate responses, a history is impossible to construct, but words can be discerned.

      Which of the options below best describes his current Glasgow Coma Scale (GCS)?

      Your Answer:

      Correct Answer: E2V3M5=10

      Explanation:

      The Glasgow Coma Scale (GCS) has been used in outcome models as a measure of physiological derangement and as a tool for assessing head trauma.

      Eye opening (E):

      4 Spontaneously
      3 Responds to voice
      2 Responds to painful stimulus
      1 No response.

      Best verbal response (V):

      5 Orientated, converses normally
      4 Confused, disoriented conversation, but able to answer basic questions
      3 Inappropriate responses, words discernible
      2 Incomprehensible speech
      1 Makes no sounds.

      Best motor response (M):

      6 Obeys commands for movement
      5 Purposeful movement to painful stimulus
      4 Withdraws from pain
      3 Abnormal (spastic) flexor response to painful stimuli, decorticate posture
      2 Extensor response to painful stimuli, decerebrate posture
      1 No response.

      In this case, GCS = 2+3+5 = 10.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 125 - Of the following, which is NOT a branch of the subclavian artery? ...

    Incorrect

    • Of the following, which is NOT a branch of the subclavian artery?

      Your Answer:

      Correct Answer: Superior thyroid artery

      Explanation:

      The left subclavian artery originates from the aortic arch, while the right subclavian artery originates from the brachiocephalic artery.

      The subclavian artery gives off branches on both sides of the body:
      1. Vertebral artery
      2. Internal thoracic artery
      3. Thyrocervical trunk
      4. Costocervical trunk
      5. Dorsal scapular artery

      The superior thyroid artery is the first branch of the external carotid artery. The other branches of the external carotid artery are:
      1. Superior thyroid artery
      2. Ascending pharyngeal artery
      3. Lingual artery
      4. Facial artery
      5. Occipital artery
      6. Posterior auricular artery
      7. Maxillary artery
      8. Superficial temporal artery

    • This question is part of the following fields:

      • Anatomy
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  • Question 126 - An 80-year old female was taken to the emergency room for chest pain....

    Incorrect

    • An 80-year old female was taken to the emergency room for chest pain. She has a medical history of coronary artery disease and previous episodes of atrial fibrillation. She was immediately attached to the cardiac monitor, which showed tachycardia at 148 beats per minute. The 12-lead ECG revealed atrial fibrillation.

      Digoxin was given as an anti-arrhythmic at 500 micrograms, which is higher than the maintenance dose routinely given. Why is this so?

      Your Answer:

      Correct Answer: It has a high volume of distribution

      Explanation:

      When the loading dose of Digoxin is given, the primary thing to consider is the volume of distribution. The volume of distribution is the proportionality factor that relates the total amount of drug in the body to the concentration. LD is computed as:

      LD = Volume of distribution X (desired plasma concentration/bioavailability)

      Digoxin is an anti-arrhythmic drug with a large volume of distribution and high bioavailability, and only a small percentage of Digoxin is bound to plasma proteins (,20%).

      In the case, since the arrhythmia is not life-threatening, there is no need for the medication to work rapidly.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 127 - All of the following statements about cerebrospinal fluid are incorrect except: ...

    Incorrect

    • All of the following statements about cerebrospinal fluid are incorrect except:

      Your Answer:

      Correct Answer: Has a glucose concentration 2/3 that of the plasma glucose

      Explanation:

      The pH of CSF is 7.31 which is lower than plasma.

      Compared to plasma, it has a lower concentration of potassium, calcium, and protein and a higher concentration of sodium, chloride, bicarbonate and magnesium.

      CSF usually has no cells present but if white cells are present, there should be no more than 4/ml.

      The pressure of CSF should be less than 20 cm of water.

      The concentration of glucose is approximately two-thirds of that of plasma, and it has a concentration of approximately 3.3-4 mmol/L.

    • This question is part of the following fields:

      • Physiology
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  • Question 128 - Buffers are solutions that resist a change in pH when protons are produced...

    Incorrect

    • Buffers are solutions that resist a change in pH when protons are produced or consumed. They consist of weak acids and their conjugate bases. Buffers are also present in our bodies, and they are known as physiologic buffers.

      Which of these is the most effective buffer in the blood?

      Your Answer:

      Correct Answer: Bicarbonate

      Explanation:

      The first line of defence against acid-base disorder is buffering. The blood mainly utilizes bicarbonate ion (HCO3-) for its buffering capacity (total of 53%, plasma and red blood cells combined).

      Strong acids, when acted upon by a buffer, release H+, which then combines to HCO3- and forms carbonic acid (H2CO3). When acted upon by the enzyme carbonic anhydrase, H2CO3 dissociates into H2O and CO.

      The rest are the percentage of utilization for the following buffers:
      Haemoglobin (by RBCs) – 35%
      Plasma proteins (by plasma) – 7%
      Organic phosphates (by RBCs) – 3%
      Inorganic phosphates (by plasma) – 2%

    • This question is part of the following fields:

      • Pharmacology
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  • Question 129 - You are shown the summary of a publication recommending use of their company's...

    Incorrect

    • You are shown the summary of a publication recommending use of their company's antiemetic to prevent postoperative nausea and vomiting by a pharmaceutical representative. You read the article, which is in a peer reviewed journal, and consider whether to change your current practice of using cyclizine intraoperatively.

      Which type of publication will provide the best evidence on which to base changes to your practice?

      Your Answer:

      Correct Answer: A prospective randomised double blind controlled trial against cyclizine in multiple centres

      Explanation:

      A prospective randomised double blind controlled trial against cyclizine in multiple centres is the most likely to change your practice.

      Case controlled studies are efficient in identifying an association between a drug treatment and outcome and are usually conducted retrospectively. They are generally less valued than prospective randomised trials. They cannot generate incidence data, are subject to bias, have difficult selection of controls and can be made more difficult if note keeping is not reliable.

      The gold standard in intervention-based studies is randomised controlled double blind trials. Its features are:

      Treating all intervention groups identically
      Reduction of bias by random allocation to intervention groups
      Patients and researchers unaware of which treatment was given until at completion of study
      Patients analysed within the group to which they were allocated, and
      Analysis focused on estimating the size of the difference in predefined outcomes between intervention groups.

      New healthcare interventions should be evaluated through properly designed randomised controlled trials (though there are some potential ethical disadvantages)

      Conducting trials in multiple centres is an accepted way of evaluating a new drug as it may be the only way of recruiting sufficient number of patients within a reasonable time frame to satisfy the objectives of the trial. Type II statistical errors will occur if a small numbers of patients is used in study group.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 130 - In endurance athletes, which of the following physiological adaptations to exercise is the...

    Incorrect

    • In endurance athletes, which of the following physiological adaptations to exercise is the best predictor of performance?

      Your Answer:

      Correct Answer: Velocity of blood lactate accumulation

      Explanation:

      Multiple regression analysis revealed that velocity of lactate accumulation (VOBLA) accounted for 92 percent of the variation in marathon running velocity (VM), and VOBLA plus training volume prior to the marathon accounted for 96 percent of the variation. Percent ST muscle fibre distribution (r = 0.55-0.69) and capillary density (r = 052-0.63) were found to be positively correlated with all performance variables. As a result, marathon running performance was linked to VOBLA and the ability to run at a pace close to it during the race. The percent ST, capillary density, and training volume were all related to these properties.

      Another metabolic adaptation compared to normal people is the early selection of fat for oxidation by muscle, especially when glucose availability is limited during high-intensity exercise. This helps to delay the onset of muscle fatigue, but it does not prevent VOBLA.

      For a given level of exercise, training can also result in cardiovascular adaptation, such as increased heart size, increased contractility, and a slower heart rate. All of these factors contribute to an increase in maximal oxygen consumption (VO2 max), but genetic factors, despite intensive training, play a large role in an athlete’s performance.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 131 - Which of the following is a correctly stated fundamental (base) SI unit? ...

    Incorrect

    • Which of the following is a correctly stated fundamental (base) SI unit?

      Your Answer:

      Correct Answer: A metre is the unit of length

      Explanation:

      The international system of units, or system international d’unites (SI) is a collection of measurements derived from expanding the metric system.

      There are seven base units, which are:

      Metre (m): a unit of length
      Second (s): a unit of time
      Kilogram (kg): a unit of mass
      Ampere (A): a unit of electrical current
      Kelvin (K): a unit of thermodynamic temperature
      Candela (cd): a unit of luminous intensity
      Mole (mol): a unit of substance.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 132 - A 50-year old man for septoplasty has a BMI of 32kg/m2 and neck...

    Incorrect

    • A 50-year old man for septoplasty has a BMI of 32kg/m2 and neck circumference of 44 cm. He is troubled by intermittent nasal obstruction which causes his partner sleeps in a separate bedroom because of snoring. He currently on ramipril for hypertension.

      Which of the following best approximates to his STOP-BANG score from the information above?

      Your Answer:

      Correct Answer: 5

      Explanation:

      The STOP-BANG questionnaire is used to screen patients for obstructive sleep apnoea (OSA).

      The scoring system assigns one point for each feature.

      S: Snoring (louder than talking or loud enough to be heard through closed doors)
      T: Feeling tired, fatigued, or sleepy during daytime
      O: Observed apnoeas during sleep
      P: Hypertension
      B: BMI more than 35 kg/m2
      A: Age 50-years of age or greater
      N: Neck circumference (male 17 inches / 43cm or greater and female 16 inches / 41 or greater)
      G: Gender: Male

      Our patient has a score of 5 ( O, P, A, N, G)

      The score helps clinicians stratify patients for unrecognized OSA and target appropriate clinical management. It can also help triage patients for further investigation. A STOP-BANG score of 5-8 will identify patients with high probability of moderate to severe OSA in the surgical population.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 133 - A chain smoker is interested in knowing how many years of his life...

    Incorrect

    • A chain smoker is interested in knowing how many years of his life would be lessened by smoking. You tell him explicitly that precise determination is impossible but you can tell him the proportion of people who died due to smoking. Which of the following epidemiological term is apt in this regard?

      Your Answer:

      Correct Answer: Attributable risk - the rate in the exposed group minus the rate in the unexposed group

      Explanation:

      Attributable proportion is the proportion of disease that is caused due to exposure. It refers to the proportion of disease that would be eradicated from a particular population if the disease rate was diminished to match that of the unexposed group.

      Risk ratio (relative risk) compares the probability of an event in an exposed (experimental) group to that of an event in the unexposed (control) group. Thus two are not the same.

      The attributable risk is the rate of a disease in an exposed group to that of a group that has not been exposed to it i.e. how many deaths did the exposure cause.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 134 - Which of the following statement is true regarding the paediatric airway? ...

    Incorrect

    • Which of the following statement is true regarding the paediatric airway?

      Your Answer:

      Correct Answer: The larynx is more anterior than in an adult

      Explanation:

      In the neonatal stage, the tongue is usually large and comes to the normal size at the age of 1 year. The vocal cords lie inverse C4 and as it reaches the grown-up position inverse C5/6 by the age of 4 (not 1 year).

      Due to the immature cricoid cartilage, the larynx lies more anterior in newborn children. That’s why the cricoid ring is the narrowest part of the paediatric respiratory tract, while in the adults the tightest portion of the respiratory route is vocal cords. The epiglottis is generally expansive and slants at a point of 45 degrees to the laryngeal opening.

      The carina is the ridge of the cartilage in the trachea at the level of T2 in newborn (T4 in adults), that separates the openings of right and left main bronchi.

      Neonates have a comparatively low number of alveoli and then this number gradually increases to a most extreme by the age of 8 (not 3 years).

      Neonates are obligatory nose breathers and any hindrance can cause respiratory issues (e.g., choanal atresia).

    • This question is part of the following fields:

      • Physiology
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  • Question 135 - A 24-year-old female, presents to the emergency department via ambulance. She has just...

    Incorrect

    • A 24-year-old female, presents to the emergency department via ambulance. She has just been involved in a car accident. She is examined and undergoes various diagnostic investigations. Her X-ray report states that a fracture was noted on the surgical neck of her humerus.

      What structure is most likely to the damaged as a result of a surgical neck fracture of the humerus?

      Your Answer:

      Correct Answer: Axillary nerve

      Explanation:

      Fractures to the surgical neck of the humerus are common place as it is the weakest point of the proximal humerus bone.

      The structures most likely to be damaged are the axillary nerve and the posterior circumflex humeral artery as they surround the surgical neck.

      The radial nerve runs along the radial groove, so injury to it would likely occur with a mid-shaft fracture of the humerus.

      The brachial artery is most likely to be injured as a result of a supracondylar fracture of the humerus which increases the risk of volkmaan’s ischemic contractures.

      Injury to the musculocutaneous nerve is least likely to happen and it very uncommon.

    • This question is part of the following fields:

      • Anatomy
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  • Question 136 - Sugammadex binds to certain drugs that affect neuromuscular function during anaesthesia in a...

    Incorrect

    • Sugammadex binds to certain drugs that affect neuromuscular function during anaesthesia in a stereospecific, non-covalent, and irreversible manner.

      It has the greatest impact on the activity of which of the following drugs?

      Your Answer:

      Correct Answer: Vecuronium

      Explanation:

      Sugammadex is a modified cyclodextrin that works as an aminosteroid neuromuscular blocking (nmb) reversal agent. By encapsulating each molecule in the plasma, it rapidly reverses rocuronium and, to a lesser extent, vecuronium-induced neuromuscular blockade. Consequently, a  concentration gradient favours the movement of these nmb agents away from the neuromuscular junction.  Pancuronium-induced neuromuscular blockade at low levels has also been reversed.

      By inhibiting voltage-dependent calcium channels at the neuromuscular junction, antibiotics in the aminoglycoside group potentiate neuromuscular blocking agents. This can be reversed by giving calcium but not neostigmine or sugammadex.

      Sugammadex will not reverse the effects of mivacurium, which belongs to the benzylisoquinolinium class of drugs.

      A phase II or desensitisation block occurs when the motor end-plate becomes less sensitive to acetylcholine as a result of an overdose or repeated administration of suxamethonium. The use of neostigmine has been shown to be effective in reversing this weakness.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 137 - Concerning the pathway of endothelial nitric oxide (eNO), one of the following best...

    Incorrect

    • Concerning the pathway of endothelial nitric oxide (eNO), one of the following best describes it.

      Your Answer:

      Correct Answer: Stimulation of guanylyl cyclase, increases cGMP concentration leading to vasodilation

      Explanation:

      Nitric oxide (NO), an endothelial-derived relaxant factor (EDRF), is a powerful vasodilator. Its cell-signalling molecule is calcium-dependant and generated endogenous by nitric oxide synthetases from the precursor L-arginine, oxygen and NADPH. Three main isoforms have been isolated and they are inducible (iNO), neuronal (nNO) and endothelial (eNO).

      Endothelial NO stimulates intracellular guanylyl cyclase which generates cyclic GMP (cGMP) from its action on guanylyl tri-phosphate (GTP). The cGMP goes on to activate protein kinase G (PKG). PKG phosphorylates cell membrane proteins that regulate intracellular calcium concentrations and level of calcium sensitisation.

      Smooth muscle vasodilatation results from:

      1. Light chain phosphatase activation.
      2. Inhibition of calcium entry into the cell (reducing Ca2+ concentrations) and
      3. Hyperpolarisation of cells by activation of H+ channels.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 138 - A 42-year-old man presented with a bitemporal hemianopia with enlarged hands and feet....

    Incorrect

    • A 42-year-old man presented with a bitemporal hemianopia with enlarged hands and feet. On examination, he was found to be hypertensive.

      Which of the following correctly explains the cause of his visual field defect?

      Your Answer:

      Correct Answer: Pituitary macroadenoma secreting growth hormone (GH)

      Explanation:

      Pituitary macroadenoma is a benign tumour with growth larger than 10mm (those under 10mm are called microadenoma)

      Compression of optic chiasm by pituitary adenoma is responsible for causing visual field defects like bitemporal hemianopia, optic neuropathy.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 139 - A 5-year-old child is scheduled for squint surgery requiring general anaesthesia.

    To begin, she...

    Incorrect

    • A 5-year-old child is scheduled for squint surgery requiring general anaesthesia.

      To begin, she is given sevoflurane for the inhalation induction, then intravenous access is established along with the insertion of a supraglottic airway. Anaesthesia is maintained with fentanyl 1 mcg/kg, with an air/oxygen/sevoflurane mix with spontaneous respirations.

      Once the surgery begins, her pulse rate drastically reduces from 120 beats/min to 8 beats/min.

      What is the most appropriate next step for this patient?

      Your Answer:

      Correct Answer: Tell surgeon to stop surgical retraction

      Explanation:

      This sudden change in pulse rate is due to the oculocardiac reflex. It is a >20% reduction in pulse rate as a result of placing pressure directly on the eyeball. The reflex arc has an afferent and efferent arm:

      The afferent (sensory) arm: The trigeminal nerve (CN V)

      The efferent arm: The vagus nerve (CN X)

      The most appropriate action is to ask the surgeon to stop retraction of the extraocular muscles, Assess for hypoxia, and give 100% oxygen if indicated.

      Atropine of glycopyrrolate can be administered to counteract the reflex, and also prevent any further vagal reflexes.

      Administration of fentanyl may increase patient’s risk of bradycardia and sinus arrest in this case.

      Adrenaline is not indicated here as other treatment options will provide sufficient relief from arrhythmia.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 140 - A 71-year-old man, presents with central crushing pain in his chest to the...

    Incorrect

    • A 71-year-old man, presents with central crushing pain in his chest to the emergency department. On examination, he complains of nausea and is notably sweating. On ECG, elevation in the ST-segment is noted in multiple chest leads, as well as sinus bradycardia. A myocardial infarction can cause a sinus bradycardia.

      The sinoatrial (SA) node and the atrioventricular (AV) node receive arterial supply from which vessel?

      Your Answer:

      Correct Answer: Right coronary artery

      Explanation:

      The left marginal artery comes off the left circumflex artery, and runs alongside the heart.

      The left circumflex artery is one of the bifurcations of the left coronary artery, and eventually forms the left marginal artery.

      An occlusion in the left circumflex artery often results in a lateral MI.

      The right marginal artery originates from the right coronary artery.

      The left anterior descending artery (LAD) is another bifurcation of the left coronary artery. An occlusion in the LAD would often result in an anteroseptal MI as is diagnosed on ECG by noting changes in leads V1-V4.

      The right coronary artery originates from the right aortic sinus of the ascending aorta, and bifurcates to give rise to many branches, including the sinoatrial artery which supplies the sinoatrial (SA) node in 50-70% of cases, the artery of the atrioventricular (AV) node in 50-60% of cases, the right acute marginal artery which supplies the right ventricle. It also supplies the right atrium, interatrial septum and the posterior inferior third of the interventricular septum.

      Arrhythmias and inferior MI often occurs as a result of an occlusion in the right coronary artery, and can be diagnosed by ECG changes in leads II, III and aVF.

    • This question is part of the following fields:

      • Anatomy
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  • Question 141 - In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five...

    Incorrect

    • In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five minutes is indicated during in-hospital cardiac arrest due to ventricular fibrillation (VF) following three DC shocks.

      Which of the following indicates the most important reason for using epinephrine?

      Your Answer:

      Correct Answer: Preferential distribution of blood to the coronary and cerebral circulation

      Explanation:

      Epinephrine is used for the treatment of cardiac arrest because it causes vasoconstriction via the alpha-adrenergic (?1) receptor. This vasoconstriction increases cerebral and coronary blood flow by increasing mean arterial, aortic diastolic, and cerebral pressures. Furthermore, epinephrine is also a?1 and ?2 adrenoreceptor agonist which shows inotrope, chronotrope, and bronchodilator effects.
      – Adrenaline is also used to prolong the duration of action and decrease the systemic toxicity of local anaesthetics.
      – Preferred route of adrenaline in patients with cardiac arrest is i.v. followed by intra-osseous and endotracheal

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 142 - A 56-year-old man, presents to his general practitioner with a lump in his...

    Incorrect

    • A 56-year-old man, presents to his general practitioner with a lump in his groin area. He is diagnosed with an indirect inguinal hernia and is scheduled for a laparoscopic inguinal hernia repair. During the repair, the surgeon sees several structures surrounding the inguinal canal.

      Name the structure that forms the anterior borders of the inguinal canal.

      Your Answer:

      Correct Answer: Aponeurosis of external oblique

      Explanation:

      The inguinal canal is the pathway leading from the wall of the abdomen to the external genitalia.

      The borders of the inguinal canal are:

      Anterior wall: formed by the aponeurosis of the external oblique, supported by the internal oblique muscle laterally.

      Posterior wall: formed laterally by the transversalis fascia, and medially by the conjoint tendon

      Roof: formed by the internal oblique and transversus abdominis muscles

      Floor: formed by the inguinal ligament and supported medially by the lacunar ligament

    • This question is part of the following fields:

      • Anatomy
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  • Question 143 - Which of the following options will likely play a major role in falling...

    Incorrect

    • Which of the following options will likely play a major role in falling coronary blood flow?

      Your Answer:

      Correct Answer: Intracoronary artery infusion of endothelin-1

      Explanation:

      Endothelin-1 is considered as a powerful coronary vasoconstrictor, produced by the endothelium. It acts to counter the effects of Nitric oxide (NO).
      Neuropeptide-Y, angiotensin1, cocaine, vasopressin, and nicotine are some other coronary vasoconstrictors.

      Chronotrophy and inotrophy occur after the activation of sympathetic nerve fibres, which in turn results in increasing the myocardial oxygen consumption, leading to increased coronary blood flow via local metabolic processes.

      An alpha-receptor mediated coronary vasoconstrictor effect is also initiated that usually competes with vasodilation, resulting in decreased coronary vascular resistance. Some of the other dilators include hydrogen ions, CO2, potassium, and lactic acid. The action of endothelial NO synthase (eNOS) on L-arginine results in the formation of NO. This messenger also plays a vital role in the regulation of coronary blood flow via vasodilation, inhibition of platelet aggression, and decreasing vascular resistance.
      Adenosine is considered as purine nucleoside that forms after the breakdown of adenosine triphosphate (ATP). Adenosine binds to adenosine type 2A (A2A) receptors in coronary vascular smooth muscles. These are coupled to the Gs protein. This mechanism leads to hyperpolarisation of muscle cells, resulting in relaxation and increased coronary blood flow.

      GTN is an veno and arteriolar dilator, which behaves as pro-drug with NO.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 144 - A 28-year-old woman who is 36 weeks pregnant presented with significant proteinuria and...

    Incorrect

    • A 28-year-old woman who is 36 weeks pregnant presented with significant proteinuria and severe headache. On examination, the blood pressure recorded was consistently raised at 190/110. Subsequently, she was admitted to the labour ward as a case of pre-eclampsia.

      A loading dose of IV magnesium sulphate 4g is given, followed by a 1g/hour infusion.

      The most suitable parameter to access magnesium toxicity is?

      Your Answer:

      Correct Answer: Tendon reflexes

      Explanation:

      Magnesium is a very important cation due to its various physiological roles in the body. This includes:
      – playing the role of a cofactor in many enzymatic reactions
      – influencing hormone receptor binding
      – affecting calcium channels
      – impact on cardiac, vascular and neural cells

      Magnesium sulphate is used as first line in the treatment of eclampsia. Moreover, it has some preventive role in patients with severe pre-eclampsia. All the clinical effects of magnesium are in line with its plasma concentration.

      The first sign of magnesium toxicity in obstetric patients is the loss of patellar reflex, which is regularly monitored during treatment. The other options are all late signs of magnesium toxicity.

      Whenever there is a doubt, serum magnesium levels should always be monitored.

      The table below correlates the effects of increased levels of magnesium on the body:

      Plasma Concentration
      (mmol/L) Effect
      0.7-1.2 Normal
      4-8 Decreased deep tendon reflexes, nausea, headache, weakness, malaise, lethargy and facial flushing
      5-10 ECG changes (prolonged PR, prolonged QT, and widened QRS)
      10 Muscle weakness, loss of deep tendon reflexes, hypotension
      15 SA/AV nodal block, respiratory paralysis and depression
      20 Cardiac arrest

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 145 - From the following statements, which is true of humidification? ...

    Incorrect

    • From the following statements, which is true of humidification?

      Your Answer:

      Correct Answer: Ultrasonic humidifier can achieve greater than 100% relative humidity

      Explanation:

      Increasing temperature increases the amount of water vapour contained in air; for example, at 20°C, air contains about 17 g/m3, and at 37°C, air contains about 44 g/m3. The wet and dry bulb hygrometer, like the hair hygrometer, measures relative humidity.

      Under normal operating conditions, Heat and moisture exchangers (HMEs) allows relative humidity of up to 70% to be achieved. Mucus can impair their performance, and they should not be used for longer than 24 hours.

      Hot water bath humidifiers might cause scalding, condensed water in the tubing can interfere with gas flow, and there is a danger of infection.

      The ultrasonic humidifier operates at roughly 2 MHz and may attain relative humidity levels much above 100%.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 146 - Which of the following is the smallest value of pressure? ...

    Incorrect

    • Which of the following is the smallest value of pressure?

      Your Answer:

      Correct Answer: 14.69 psi

      Explanation:

      The SI unit of pressure is the pascal (Pa) and it is equal to one newton (N) per square meter (m2) or N/m2.

      1 atmosphere (atm) is the equivalent of:

      101325 Pa760 mmHg
      1.01325 bar
      1033.23 cmH2O.
      14.69 pounds per square inch (psi)
      1013.25 millibar (mbar) or hectopascals (hPa), and

      14.69 psi is equal to one atmosphere. The other values are equal to two atmospheres of pressure.

    • This question is part of the following fields:

      • Basic Physics
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  • Question 147 - Which of the following vertebral levels is the site where the aorta perforates...

    Incorrect

    • Which of the following vertebral levels is the site where the aorta perforates the diaphragm?

      Your Answer:

      Correct Answer: T12

      Explanation:

      The diaphragm divides the thoracic cavity from the abdominal cavity. Structures penetrate the diaphragm at different vertebral levels through openings in the diaphragm to communicate between the two cavities. The diaphragm has openings at three vertebral levels:

      T8: vena cava, terminal branches of the right phrenic nerve
      T10: oesophagus, vagal trunks, left anterior phrenic vessels, oesophageal branches of the left gastric vessels
      T12: descending aorta, thoracic duct, azygous and hemi-azygous vein

    • This question is part of the following fields:

      • Anatomy
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  • Question 148 - A 45-year-old woman gives a two-week history of fatigue, muscle cramps, and paraesthesia...

    Incorrect

    • A 45-year-old woman gives a two-week history of fatigue, muscle cramps, and paraesthesia of her fingers and toes. She has low serum calcium and low serum parathyroid hormone levels on investigations.

      She appears slightly confused, likely due to hypocalcaemia, and cannot give a full account of her past medical history, but can recall that she recently was admitted to the hospital.

      What is the most likely cause of her hypoparathyroidism?

      Your Answer:

      Correct Answer: Thyroidectomy

      Explanation:

      The most common cause of hypoparathyroidism is injury or removing the parathyroid glands. They can be injured accidentally during surgery to remove the thyroid as they are located posterior to the thyroid gland.

      A result of both low parathyroid hormone and low calcium is likely to mean that the parathyroid glands are not responding to hypocalcaemia. The hypocalcaemia can cause confusion, and the stay in the hospital is likely to refer to her surgery.

      While a parathyroid adenoma is fairly common and can cause hypoparathyroidism, it much more likely causes hyperparathyroidism.

      Chronic kidney disease is likely to cause hypocalcaemia, which would increase parathyroid hormone production in an attempt to increase calcium levels, causing hyperparathyroidism. Vitamin D is activated by the kidneys and then binds to calcium to be absorbed in the terminal ileum so that a deficiency would cause hyperparathyroidism.

    • This question is part of the following fields:

      • Anatomy
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  • Question 149 - All of the following statements about that parasympathetic nervous system (PNS) are true...

    Incorrect

    • All of the following statements about that parasympathetic nervous system (PNS) are true except:

      Your Answer:

      Correct Answer: The PNS has nicotinic receptors throughout the system

      Explanation:

      With regards to the autonomic nervous system (ANS)

      1. It is not under voluntary control
      2. It uses reflex pathways and different to the somatic nervous system.
      3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.

      With regards to the central nervous system (CNS)
      1. There are myelinated preganglionic fibres which lead to the
      ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
      2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.

      Most organs are under control of both systems although one system normally predominates.

      The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.

      There are short pre-ganglionic and long post ganglionic fibres.
      Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
      Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
      However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.

      The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.

      There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.

      Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.

      The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.

      The cranial outflow consists of
      1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
      2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
      3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
      4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreas

      The sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.

      The PNS has long preganglionic and short post ganglionic fibres.
      Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
      Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.

      Different types of these muscarinic receptors are present in different organs:
      There are:
      M1 = pupillary constriction, gastric acid secretion stimulation
      M2 = inhibition of cardiac stimulation
      M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
      M4 = brain and adrenal medulla
      M5 = brain

      The lacrimal glands are solely under parasympathetic control.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 150 - Which drug, if given to a pregnant woman, can lead to deleterious fetal...

    Incorrect

    • Which drug, if given to a pregnant woman, can lead to deleterious fetal effects due to its ability to cross the placenta?

      Your Answer:

      Correct Answer: Atropine

      Explanation:

      It is well known that atropine will cross the placenta and that maternal administration results in an increase in fetal heart rate.

      Atropine is highly selective for muscarinic receptors. Its potency at nicotinic receptors is much lower, and actions at non-muscarinic receptors are generally undetectable clinically. Atropine does not distinguish among the M1, M2, and M3 subgroups of muscarinic receptors. In contrast, other antimuscarinic drugs are moderately selective for one or another of these subgroups. Most synthetic antimuscarinic drugs are considerably less selective than atropine in interactions with nonmuscarinic receptors.

      A study on glycopyrrolate, a quaternary ammonium salt, was found to have a fetal: maternal serum concentration ratio of 0.4 indicating partial transfer.

      Heparin, suxamethonium, and vecuronium do not cross the placenta.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 151 - Regarding laminar gas flow, which of the following options has the most influence...

    Incorrect

    • Regarding laminar gas flow, which of the following options has the most influence on laminar flow?

      Your Answer:

      Correct Answer: Diameter of tube

      Explanation:

      Laminar flow can be defined as the motion of a fluid where every particle in the fluid follows the same path of its previous particles. The following are properties of laminar flow of gas or fluids:

      1. Smooth unobstructed flow of gas through a tube of relatively uniform diameter
      2. Few directional changes
      3. Slow, steady flow through straight smooth, rigid, large calibre, cylindrical tube
      4. Outer layer flow slower than the centre due to friction, results in discrete cylindrical layers, or streamlines
      5. Double flow by doubling pressure as long as the flow pattern remains laminar

      Poiseuille’s Law relates the factors that determine laminar flow. It indicates the degree of resistance to fluid flow through a tube. The resistance to fluid flow through a tube is directly related to the length, flow and viscosity; and inversely related to the radius of the tube to the fourth power. This means that, when the radius is doubled, there is increase in flow by a factor of 16.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 152 - Which of the following statements is true regarding prazosin? ...

    Incorrect

    • Which of the following statements is true regarding prazosin?

      Your Answer:

      Correct Answer: Is a selective alpha 1 adrenergic receptor antagonist.

      Explanation:

      Selective ?1 -Blockers like prazosin, terazosin, doxazosin, and alfuzosin cause a decrease in blood pressure with lesser tachycardia than nonselective blockers (due to lack of ?2 blocking action.

      The major adverse effect of these drugs is postural hypotension. It is seen with the first few doses or on-dose escalation (First dose effect).

      Its half-life is approximately three hours.

      It is excreted primarily through bile and faeces (not through kidneys)

    • This question is part of the following fields:

      • Pharmacology
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  • Question 153 - Which of the following is true regarding correlation coefficient? ...

    Incorrect

    • Which of the following is true regarding correlation coefficient?

      Your Answer:

      Correct Answer: It can assume any value between -1 and 1

      Explanation:

      The degree of correlation is summarised by the correlation coefficient (r). This indicates how closely the points lie to a line drawn through the plotted data. In parametric data this is called Pearson’s correlation coefficient and can take any value between -1 to +1. A correlation of -1.0 indicates a perfect negative correlation, and a correlation of 1.0 indicates a perfect positive correlation.

      For example

      r = 1 – strong positive correlation (e.g. systolic blood pressure always increases with age)

      r = 0 – no correlation (e.g. there is no correlation between systolic blood pressure and age)

      r = – 1 – strong negative correlation (e.g. systolic blood pressure always decreases with age)

      Whilst correlation coefficients give information about how one variable may increase or decrease as another variable increases they do not give information about how much the variable will change. They also do not provide information on cause and effect.

      In contrast to the correlation coefficient, linear regression may be used to predict how much one variable changes when a second variable is changed.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 154 - The child-Pugh scoring system can be used, if risk classifying a patient with...

    Incorrect

    • The child-Pugh scoring system can be used, if risk classifying a patient with chronic liver disorder earlier to anaesthesia.

      Which one is the best combination of clinical signs and examinations used within the Child-Pugh scoring system?

      Your Answer:

      Correct Answer: Ascites, grade of encephalopathy, albumin, bilirubin and INR

      Explanation:

      In the Child-Pugh classification system, the following 5 components are determined or calculated in order:

      Ascites

      Grade of encephalopathy

      Serum bilirubin (?mol/L)

      Serum Albumin (g/L)

      Prothrombin time or INR

      Raised liver enzymes are not the component of the classification system.

    • This question is part of the following fields:

      • Basic Physics
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  • Question 155 - An elderly man complains of a vague lump near his stomach to his...

    Incorrect

    • An elderly man complains of a vague lump near his stomach to his physician. On examination, the lump is visible on coughing and is found within Hesselbach's triangle.

      Which of the following is true regarding the borders for this triangle?

      Your Answer:

      Correct Answer: Inguinal ligament inferiorly, inferior epigastric vessels laterally, lateral border of rectus sheath medially

      Explanation:

      The inguinal triangle of Hesselbach is an important clinical landmark on the posterior wall of the inguinal canal. It has the following relations:
      Inferiorly – medial third of the inguinal ligament
      Medially – lower lateral border of the rectus abdominis
      Laterally – inferior epigastric vessels

      Direct inguinal hernia is when the bowel bulges directly through the abdominal wall. These hernias usually protrude through Hesselbach’s triangle

    • This question is part of the following fields:

      • Anatomy
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  • Question 156 - Drug A has a 1 L/kg volume of distribution and a 0.1 elimination...

    Incorrect

    • Drug A has a 1 L/kg volume of distribution and a 0.1 elimination rate constant (k).

      Drug B has a 2 L/kg volume of distribution and a 0.2 elimination rate constant (k).

      Which of the following statements best describes the pharmacokinetics of drug A in a single compartment?

      Your Answer:

      Correct Answer: Drug A has a lower clearance than drug B

      Explanation:

      The fall in plasma concentration of a drug with time decreases exponentially in a single compartment pharmacokinetic model (wash-out curve).

      A straight line is produced when the logarithm (ln) of a drug’s plasma concentration is plotted against time because a constant proportion of the drug is removed from the plasma per unit time. The line’s gradient or slope can be expressed mathematically as k. (the rate constant). The gradient is related to the half life (T1/2) because it can be used to predict a drug’s plasma concentration at any time.

      According to the following formula, clearance (CL), volume of distribution (Vd), and elimination rate constant (k) are mathematically related.

      CL = Vd x k

      For drug A, CL = 1 x 0.1 = 0.1units per minute

      For drug B, Cl = 2 x 0.2 = 0.4 units per minute

      Hence, it is proved that Drug A has a lower clearance than drug B.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 157 - This vertebrae can be easily differentiated from the rest because of its prominent...

    Incorrect

    • This vertebrae can be easily differentiated from the rest because of its prominent spinous process.

      Your Answer:

      Correct Answer: C7

      Explanation:

      The spinous process is the part of a vertebrae that is directed posteriorly.

      Typical cervical vertebra have spinous processes that are small and bifid, except for C7, which has a long and prominent spinous process.

    • This question is part of the following fields:

      • Anatomy
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  • Question 158 - A 27-year-old woman takes part in a study looking into the effects of...

    Incorrect

    • A 27-year-old woman takes part in a study looking into the effects of different dietary substrates on metabolism. She receives a 24-hour ethyl alcohol infusion.

      A constant volume, closed system respirometer is used to measure CO2 production and consumption. The production of carbon dioxide is found to be 200 mL/minute.

      Which of the following values most closely resembles her anticipated O2 consumption at the conclusion of the trial?

      Your Answer:

      Correct Answer: 300 mL/minute

      Explanation:

      The respiratory quotient (RQ) is the ratio of CO2 produced by the body to O2 consumed in a given amount of time.

      CO2 produced / O2 consumed = RQ

      CO2 is produced at a rate of 200 mL per minute, while O2 is consumed at a rate of 250 mL per minute. An RQ of around 0.8 is typical for a mixed diet.

      The RQ will change depending on the energy substrates consumed in the diet. Granulated sugar is a refined carbohydrate that contains 99.999 percent carbohydrate and no lipids, proteins, minerals, or vitamins.

      Glucose and other hexose sugars (glucose and other hexose sugars):
      RQ=1

      Fats:
      RQ = 0.7

      Proteins:
      Approximately 0.9 RQ

      Ethyl alcohol is a type of alcohol.

      200/300 = 0.67 RQ

      For complete oxidation, lipids and alcohol require more oxygen than carbohydrates.

      When carbohydrate is converted to fat, the RQ can rise above 1.0. Fat deposition and weight gain are likely to occur in these circumstances.

    • This question is part of the following fields:

      • Physiology
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  • Question 159 - Which of the following anaesthetic is the least powerful trigger of malignant hyperthermia?...

    Incorrect

    • Which of the following anaesthetic is the least powerful trigger of malignant hyperthermia?

      Your Answer:

      Correct Answer: Desflurane

      Explanation:

      Desflurane is a highly fluorinated methyl ethyl ether used for the maintenance of general anaesthesia. It has been identified as a weak triggering anaesthetic of malignant hyperthermia. That, in the absence of succinylcholine, may produce a delayed onset of symptoms.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 160 - A 28-year-old man is admitted to the critical care unit. He has been...

    Incorrect

    • A 28-year-old man is admitted to the critical care unit. He has been diagnosed with adult respiratory distress syndrome and is being ventilated. His haemodynamic condition is improved using a pulmonary artery flotation.

      His readings are listed below:

      Haemoglobin concentration: 10 g/dL
      Mixed venous oxygen saturation: 70%
      Mixed venous oxygen tensions (PvO2): 50 mmHg

      Estimate his mixed venous oxygen content (mL/100mL).

      Your Answer:

      Correct Answer: 9.5

      Explanation:

      Mixed venous oxygen content (CvO2) is the oxygen concentration in 100mL of mixed venous blood taken from the pulmonary artery. It is usually 12-17 mL/dL (70-75%). It is represented mathematically as:

      CvO2 = (1.34 x Hgb x SvO2 x 0.01) + (0.003 x PvO2)

      Where,

      1.34 = Huffner’s constant
      Hgb = Haemoglobin level (g/dL)
      SvO2 = % oxyhaemoglobin saturation of mixed venous blood
      PvO2 = 0.0225 = mL of O2 dissolved per 100mL plasma per kPa, or 0.003 mL per mmHg

      Therefore,

      CvO2 = (1.34 x 10 x 70 x 0.01) + (0.003 x 50)

      CvO2 = 9.38 + 0.15 = 9.53 mL/100mL

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 161 - Of the following statements, which is true about the measurements of cardiac output...

    Incorrect

    • Of the following statements, which is true about the measurements of cardiac output using thermodilution?

      Your Answer:

      Correct Answer: Cardiac output should be measured during the end-expiratory pause

      Explanation:

      Thermodilution is the most common dilution method used to measure cardiac output (CO) in a hospital setting.

      During the procedure, a Swan-Ganz catheter, which is a specialized catheter with a thermistor-tip, is inserted into the pulmonary artery via the peripheral vein. 5-10mL of a cold saline solution with a known temperature and volume is injected into the right atrium via a proximal catheter port. The solution is cooled as it mixes with the blood during its travel to the pulmonary artery. The temperature of the blood is the measured by the catheter and is profiled using a computer.

      The computer also uses the profile to measure cardiac output from the right ventricle, over several measurements until an average is selected.

      Cardiac output changes at each point of respiration, therefore to get an accurate measurement, the same point during respiration must be used at each procedure, this is usually the end of expiration, that is the end-expiratory pause.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 162 - The following statements are about the cervical plexus. Which one is true? ...

    Incorrect

    • The following statements are about the cervical plexus. Which one is true?

      Your Answer:

      Correct Answer: Recurrent laryngeal nerve block is a complication of a cervical plexus block

      Explanation:

      The cervical plexus is a complex network of nerves within the head and neck region, providing nerve innervation to regions within the head, neck and trunk.

      It is comprised of nerves arising from the anterior primary rami of the C1-C4 nerve roots.

      The cervical plexus gives off superficial and deep branches. The superficial branches penetrate through the deep fascia at the centre point of the posterior border of the sternocleidomastoid. It provides sensory innervation from the lower border of the mandible to the 2nd rib. The deep branches provide motor innervation to the neck and diaphragmatic muscles.

      Cervical plexus block is surgically relevant as it is used to provide regional anaesthesia for procedures in the neck region. The anaesthesia should be injected into the centre point of the posterior border of the sternocleidomastoid. Complications arise when anaesthesia is instead injected into the wrong point, including into the vertebral artery, subarachnoid and epidural spaces, blockade of phrenic and recurrent laryngeal nerves, and the cervical sympathetic plexus.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 163 - An 80-year old lady has a background history of a previous myocardial infarction...

    Incorrect

    • An 80-year old lady has a background history of a previous myocardial infarction which has left permanent damage to her heart's conduction system. The part of the conduction system with the highest velocities is damaged, and this has resulted in desynchronisation of the ventricles. The part of the heart that conducts the fastest is which of the following?

      Your Answer:

      Correct Answer: Purkinje fibres

      Explanation:

      The electrical conduction system of the heart starts with the SA node which generates spontaneous action potentials.

      This is conducted across both atria by cell to cell conduction, and occurs at around 1 m/s. The only pathway for the action potential to enter the ventricles is through the AV node in a normal heart.
      At this site, conduction is very slow at 0.05ms, which allows for the atria to completely contract and fill the ventricles with blood before the ventricles depolarise and contract.

      The action potentials are conducted through the Bundle of His from the AV node which then splits into the left and right bundle branches. This conduction is very fast, (,2m/s), and brings the action potential to the Purkinje fibres.

      Purkinje fibres are specialised conducting cells which allow for a faster conduction speed of the action potential (,2-4m/s). This allows for a strong synchronized contraction from the ventricle and thus efficient generation of pressure in systole.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 164 - An 80-year-old man has a swelling in his left groin with moderate pain...

    Incorrect

    • An 80-year-old man has a swelling in his left groin with moderate pain and discomfort complaints. Diagnosed with an inguinal hernia, he is scheduled for elective surgery to repair the defect.

      Of the following, which nerve runs in the inguinal canal and is at risk of being damaged during surgery?

      Your Answer:

      Correct Answer: Ilioinguinal nerve

      Explanation:

      The inguinal canal is a passage in the lower anterior abdominal wall just above the inguinal ligament. It transmits the following structures:
      1. genital branch of genitofemoral nerve
      2. ilioinguinal nerve
      3. spermatic cord (males only)
      4. round ligament of the uterus (females only)

      The ilioinguinal is a direct branch of the first lumbar nerve. The ilioinguinal nerve enters the inguinal canal via the abdominal musculature (and not through the deep (internal) inguinal ring) and exits through the superficial (or external) inguinal ring.

      The openings for the other nerves in the answer options are:
      Sciatic nerve – exits the pelvis via the greater sciatic foramen
      Obturator nerve – descends into pelvis via the obturator foramen
      Femoral nerve – descends from the abdomen through the pelvis behind the inguinal canal

      The Iliohypogastric nerve also arises from the first lumbar root with the ilioinguinal nerve but pierces the transversus abdominis muscle posteriorly, just above the iliac crest, and continues anteriorly between the transversus abdominis and the internal abdominal oblique muscles.

    • This question is part of the following fields:

      • Anatomy
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  • Question 165 - Which of the following is true about number needed to harm? ...

    Incorrect

    • Which of the following is true about number needed to harm?

      Your Answer:

      Correct Answer: The number of patients that must receive a particular treatment for one additional patient to experience an adverse outcome.

      Explanation:

      Number needed to harm are a measure of the impact of a treatment or intervention that is often used to communicate results to patients, clinicians, the public and policymakers. It states how many patients need to be treated for one additional patient to experience an adverse outcome (e.g. a death). It is calculated as the inverse of the absolute risk reduction. It can equally well be applied to harmful outcomes as well as beneficial ones, where it becomes numbers needed to treat (NNT) instead.

      In this way, they are both calculated the same but NNT usually refers to a therapeutic treatment whereas NNH refers to a risk-factor for disease.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 166 - Which of the following does Lidocaine 1% solution equate to? ...

    Incorrect

    • Which of the following does Lidocaine 1% solution equate to?

      Your Answer:

      Correct Answer: 1000 mg per 100 ml

      Explanation:

      Lidocaine 1% is formulated as 1000 mg/100 mL.

      % solution is based on (grams of medicine) / 100 ml

      % solution ~ (1000 mg) / 100 ml

      % solution ~ 10 mg/ml

      Examples:

        • Lidocaine 4% = 40 mg/ml of Lidocaine
        • Lidocaine 2% = 20 mg/ml of Lidocaine
        • Lidocaine 1% = 10 mg/ml of Lidocaine

    • This question is part of the following fields:

      • Pharmacology
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  • Question 167 - Which of the following statement is not true regarding the effects of Dopamine...

    Incorrect

    • Which of the following statement is not true regarding the effects of Dopamine infusions?

      Your Answer:

      Correct Answer: Decreasing gastric transit time

      Explanation:

      Moderately high doses of dopamine produce a positive inotropic (direct?1 and D1 action + that due to Noradrenaline release), but the little chronotropic effect on the heart.

      Vasoconstriction (?1 action) occurs only when large doses are infused.

      At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 168 - With regards to oxygen delivery in the body, which of these statements is...

    Incorrect

    • With regards to oxygen delivery in the body, which of these statements is true?

      Your Answer:

      Correct Answer: Anaemia will reduce oxygen delivery

      Explanation:

      Oxygen delivery depends on 2 variables.
      1) Content of oxygen in blood
      2) Cardiac output

      Oxygen content (arterial) = (Hb (g/dL) x 1.39 x SaO2 (%) ) + (0.023 x PaO2 (kPa))

      Oxygen content (mixed venous) = (Hb (g/dL) x 1.39 x mixed venous saturation) + (0.023 x mixed venous partial pressure of oxygen in kPA)

      Huffner’s constant = 1.39 = 1g of Hb binds to 1.39 ml of O2

      Oxygen delivery DO2 (ml/min) = 10 x Cardiac output (L/min) x Oxygen content
      Normally 1000ml/min

      Oxygen consumption VO2 (ml/min) = 10 x Cardiac output (L/min) x Difference in arterial and mixed venous oxygen content
      Normally 250 ml/min

      Oxygen extraction ratio (OER) = VO2/DO2
      Normally approximately 25%

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 169 - A 63-year old male who has heart failure has peripheral oedema and goes...

    Incorrect

    • A 63-year old male who has heart failure has peripheral oedema and goes to the GP's office. The GP notes that he is fluid-overloaded. This causes his atrial myocytes to release atrial natriuretic peptide (ANP). ANP's main action is by which of these mechanisms?

      Your Answer:

      Correct Answer: Antagonist of angiotensin II

      Explanation:

      Atrial natriuretic peptide (ANP) is secreted mainly from myocytes of right atrium and ventricle in response to increased blood volume.
      It is secreted by both the right and left atria (right >> left).

      It is a 28 amino acid peptide hormone, which acts via cGMP
      degraded by endopeptidases.

      It serves to promote the excretion of sodium, lowers blood pressure, and antagonise the actions of angiotensin II and aldosterone.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 170 - A 60 year old non insulin dependent diabetic on metformin undergoes hip arthroscopy...

    Incorrect

    • A 60 year old non insulin dependent diabetic on metformin undergoes hip arthroscopy under general anaesthesia.

      Her preoperative blood glucose is 6.5mmol/L. Anaesthesia is induced with 200 mg propofol and 100 mcg fentanyl and maintained with sevoflurane and air/oxygen mixture. she is given 8 mg dexamethasone, 40 mg parecoxib, 1 g paracetamol and 500 mL Hartmann's solution Intraoperatively.

      The procedure took thirty minutes and her blood glucose in recovery is 14 mmol/L.

      What is the most likely cause for her rise in blood sugar?

      Your Answer:

      Correct Answer: Stress response

      Explanation:

      A significant early feature of the metabolic response to trauma and surgery is hyperglycaemia. It is due to an increased glucose production and decreased glucose utilisation bought on by neuroendocrine stimulation. Catecholamines, Growth hormone, ACTH and cortisol, and Glucagon are all increased.

      There is also a decreased insulin sensitivity peripherally and an inhibition of insulin production from the beta cells of the pancreas. These changes lead to hyperglycaemia.

      The stress response to endoscopic surgery will only be prevented with use of high dose opioids or central neuraxial block at anaesthesia.
      To reduce the risk of inducing hyperchloremic acidosis, Ringer’s lactate/acetate or Hartmann’s solution is preferred to 0.9% sodium chloride as routine maintenance fluids.

      Though it has been suggested that administration of Hartmann’s solution to patients with type 2 diabetes leads to hyperglycaemia, one Litre of Hartmann’s solution would yield a maximum of 14.5 mmol of glucose. A rapid infusion of this volume would increase the plasma glucose by no more than 1 mmol/L..

      Dexamethasone, a glucocorticoid, produces hyperglycaemia by stimulating gluconeogenesis . Glucocorticoids are agonists of intracellular glucocorticoid receptors. Their effects are mainly mediated via altered protein synthesis via gene transcription and so the onset of action is slow. The onset of action of dexamethasone is about one to four hours and therefore would NOT contribute to the hyperglycaemia in this patient in the time given.

      0.9% Normal saline with or without adrenaline is the usual irrigation fluid. With this type of surgery, systemic absorption is unlikely to occur.

      Fentanyl is not likely the primary cause of hyperglycaemia in this patient. In high doses (50 mcg/Kg) it has been shown to reduce the hyperglycaemic responses to surgery.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 171 - Regarding bilirubin, which one of the following statement is true? ...

    Incorrect

    • Regarding bilirubin, which one of the following statement is true?

      Your Answer:

      Correct Answer: Conjugated bilirubin is stored in the gall bladder

      Explanation:

      Bilirubin is the tetrapyrrole and a catabolic product of heme. 70-90% of bilirubin is end product of haemoglobin degradation in the liver.

      Bilirubin circulates in the blood in 2 forms; unconjugated and conjugated bilirubin.

      Unconjugated bilirubin is insoluble in water. It travels through the bloodstream to the liver, where it changes from insoluble into a soluble form (i.e.; unconjugated into conjugated form).

      This conjugated bilirubin travels from the liver into the small intestine and the gut bacteria convert bilirubin into urobilinogen and then into urobilin (not urobilin to urobilinogen). A very small amount passes into the kidneys and is excreted in urine.

    • This question is part of the following fields:

      • Physiology
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  • Question 172 - A new volatile anaesthetic agent has been approved for use in clinical testing.

    It's...

    Incorrect

    • A new volatile anaesthetic agent has been approved for use in clinical testing.

      It's a non-irritating, sweet-smelling substance. It has a molecular weight of 170, a 0.6 blood:gas partition coefficient, and a 180 oil:gas partition coefficient. An oxidative pathway converts 2% of the substance to trifluoroacetic acid.

      Which of the following statements best describes this agent's pharmacological profile?

      Your Answer:

      Correct Answer: It has a lower molecular weight than isoflurane

      Explanation:

      Because enflurane is much less soluble in blood and has a blood: gas partition coefficient of 1.8, both wash-in and wash-out should be faster.

      Sevoflurane’s sweet-smelling, non-irritant nature, combined with a low blood: gas partition coefficient, would result in similar offset and onset characteristics.

      Isoflurane and enflurane have a molecular weight of 184.

      The oil: gas partition coefficient on a volatile agent is a measure of lipid solubility, potency, and thus MAC. Halothane has an oil: gas partition coefficient of 220 and a MAC of 0.74. One would expect the MAC to be higher with an oil gas partition coefficient of 180 (less lipid soluble).

      The conversion of halothane (20%) to trifluoroacetic acid via oxidative metabolism has been linked to the development of hepatitis.

      P450 2E1 converts sevoflurane to hexafluoroisopropanol, which results in the release of inorganic fluoride ions. It’s the only fluorinated volatile anaesthetic that doesn’t break down into trifluoracetic acid.

      Desflurane is likely to cause airway irritation, which can lead to coughing, apnoea, and laryngospasm, despite its low blood:gas partition coefficient (0.42).

    • This question is part of the following fields:

      • Pharmacology
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  • Question 173 - A 53-year old female with a diagnosis of anaplastic thyroid carcinoma is admitted...

    Incorrect

    • A 53-year old female with a diagnosis of anaplastic thyroid carcinoma is admitted in the surgery department for an elective total thyroidectomy with radical neck dissection. The operation is expected to last for 10 hours.

      Which of the following is the most suitable humidifier to use in an anaesthetic circuit for this case?

      Your Answer:

      Correct Answer: Heat and moisture exchanger (HME)

      Explanation:

      Adequate humidification is vital to maintain homeostasis of the airway. Heat and moisture exchangers conserve some of the exhaled water, heat and return them to inspired gases. Many heat and moisture exchangers also perform bacterial/viral filtration and prevent inhalation of small particles. Heat and moisture exchangers are also called condenser humidifier, artificial nose, etc. Most of them are disposable devices with exchanging medium enclosed in a plastic housing. For adult and paediatric age group different dead space types are available. Heat and moisture exchangers are helpful during anaesthesia and ventilatory breathing system. To reduce the damage of the upper respiratory tract through cooling and dehydration inspiratory air can be heated and humidified, thus preventing the serious complications. Moreover, they are the most appropriate humidification devices used for routine anaesthesia.

      Gases can be bubbled through water to increase humidity. Passing gas through water at room temperature causes the gas to cool due to latent heat of vaporisation. The water bath can be heated. This improves the efficiency of the device and also reduces the incidence of bacterial colonisation.

      Nebulisers use a venturi system which employs the Bernoulli effect. A gas at high flow passes through a constriction causing the gas to accelerate, reducing its potential energy allowing other gases or liquids to be entrained. This can include medications or in the case of humidification, water vapour. The size of the water droplet produced by nebulisation determines where in the airway it is deposited. Standard nebulisers produced droplets of 4 microns in diameter and these are deposited in the upper airway and trachea. Efficacy can be improved by passing the droplets over an anvil which further reduces particle size. The most efficient form of nebuliser is the ultrasonic nebuliser. Here a transducer immersed in water and vibrated at a frequency of 3MHz produces1-2micron droplets. These particles easily reach the bronchioles and provide excellent humidification.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 174 - A 72-year-old man complains of severe, central abdominal pain that radiates to the...

    Incorrect

    • A 72-year-old man complains of severe, central abdominal pain that radiates to the back. He has a past medical history of an abdominal aortic aneurysm.

      A focused abdominal ultrasonography test (FAST) is performed, revealing diffuse dilatation of the abdominal aorta. The most prominent dilatation is at the bifurcation site of abdominal aorta into the iliac arteries.

      What vertebra level corresponds to the site of the most prominent dilatation as evident on the FAST scan?

      Your Answer:

      Correct Answer: L4

      Explanation:

      The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:

      T12 – Coeliac trunk

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta

    • This question is part of the following fields:

      • Anatomy
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  • Question 175 - A 20-year-old man has been diagnosed with mitral regurgitation. He will be treated...

    Incorrect

    • A 20-year-old man has been diagnosed with mitral regurgitation. He will be treated with mitral valve repair.

      What is true regarding the mitral valve?

      Your Answer:

      Correct Answer: Its closure is marked by the first heart sound

      Explanation:

      The mitral valve is the valve between the left atrium and left ventricle. It opens when the heart is in diastole (relaxation) which allows blood to flow from the left atrium to the left ventricle. In systole (contraction), the mitral valve closes to prevent the backflow of blood from the left ventricle to the left atrium.

      The mitral valve is located posterior to the sternum at the level of the 4th costal cartilage. It is best auscultated over the cardiac apex, where its closure marks the first heart sound.

      The mitral valve anatomy is composed of five main structures:
      1. Left atrial wall – the myocardium of the left atrial wall extends over the posterior leaflet of the mitral valve. (left atrial enlargement is one of the causes for mitral regurgitation)
      2. Mitral annulus – a fibrous ring that connects with the anterior and posterior leaflets. It functions as a sphincter that contracts and reduces the surface area of the valve during systole (Annular dilatation can also lead to mitral regurgitation)
      3. Mitral valve leaflets (cusps) – The mitral valve is the only valve in the heart with two cusps or leaflets. One anterior and one posterior.
      i. The anterior leaflet is located posterior to the aortic root and is also anchored to the aortic root.
      ii. The posterior leaflet is located posterior to the two commissural areas.
      4. Chordae tendinae – The chordae tendinae connects both the cusps to the papillary muscles.
      5. Papillary muscles – These muscles and their cords support the mitral valve, allowing the cusps to resist the pressure developed during contractions (pumping) of the left ventricle

      The anterior and posterior cusps are attached to the chordae tendinae which itself is attached to the left ventricle via papillary muscle.

    • This question is part of the following fields:

      • Anatomy
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  • Question 176 - You decide to conduct research on the normal rates of gastric emptying in...

    Incorrect

    • You decide to conduct research on the normal rates of gastric emptying in healthy people. The strategy is to give a drug orally and measure plasma concentrations at predetermined intervals.

      Which of the following drugs would you choose to use?

      Your Answer:

      Correct Answer: Paracetamol

      Explanation:

      Because of the low pH in the stomach, paracetamol absorption is minimal (pKa value is 9.5). Paracetamol is absorbed quickly and completely in the alkaline environment of the small intestine. Oral bioavailability is approaching 100%. As a result, measuring paracetamol levels in plasma after an oral paracetamol dose has been used as a surrogate marker of gastric emptying. This method has been used to investigate the effects of drugs on gastric emptying. At clinically used doses, paracetamol is ideal because it has very few side effects.

      Scintigraphic imaging is the gold standard for determining gastric emptying.

      Although aspirin (acetyl salicylic acid) is absorbed primarily in the small intestine, some may also be absorbed in the stomach. The oral bioavailability ranges from 70 to 100 percent, making it less reliable than paracetamol.

      Propranolol is a lipophilic drug that is rapidly absorbed after administration. However, it is highly metabolised by the liver in the first pass, and only about 25% of propranolol reaches the systemic circulation. It’s not the best indicator of gastric emptying.

      Oral bioavailability of gentamicin and vancomycin is low. Only antibiotic-induced pseudomembranous colitis is treated with oral vancomycin.

      Erythromycin is a pro-kinetic agent that acts as a motilin receptor agonist.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 177 - Which of the following, at a given PaO2, increases the oxygen content of...

    Incorrect

    • Which of the following, at a given PaO2, increases the oxygen content of arterial blood?

      Your Answer:

      Correct Answer: A reduced erythrocyte 2,3-diphosphoglycerate level

      Explanation:

      The oxygen content of arterial blood can be calculated by the following equation:
      (10 x haemoglobin x SaO2 x 1.34) + (PaO2 x 0.0225).
      This is the sum of the oxygen bound to haemoglobin and the oxygen dissolved in the plasma.

      Oxygen content x cardiac output = The amount of oxygen delivered to the tissues in unit time which is known as the oxygen flux.

      Any factor that increases the metabolic demand will encourage oxygen offloading from the haemoglobin in the tissues and this causes the oxygen dissociation curve (ODC) to shift to the right. This subsequently reduced the oxygen content of arterial blood.

      Conditions like fever, metabolic or respiratory acidosis lowers the oxygen content and shifts the ODC to the right.
      A low level of 2,3 diphosphoglycerate (2,3-DPG) is usually related to an increased oxygen content as there is less offloading, and so the ODC is shifted to the left.

      So for a given PaO2, a high blood oxygen content is related to any factors that can shift the ODC to the left and not to the right.

      A low haematocrit usually means that there is a decreased haemoglobin concentration, and therefore is associated with decreased oxygen binding to haemoglobin.

    • This question is part of the following fields:

      • Physiology
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  • Question 178 - While administering a general anaesthetic to a 65-year-old man booked for a hip...

    Incorrect

    • While administering a general anaesthetic to a 65-year-old man booked for a hip hemiarthroplasty, with a weight 70 kg, and an ASA 1 score, you give 1 g of paracetamol IV but notice that he had received the same dose on the ward one hour prior.

      What is the most appropriate subsequent management of this patient?

      Your Answer:

      Correct Answer: Do nothing and give the next doses of paracetamol at standard 6 hour intervals

      Explanation:

      After ingestion of more than 150 mg/kg paracetamol within 24 hours, hepatotoxicity can occur but can also develop rarely after ingestion of doses as low as 75 mg/kg within 24 hours. Hepatocellular damage will not occur in this patient and therefore no need to engage management pathway for paracetamol overdose. If his weight was <33 kg or he already had a history of impaired liver function, then the management would bde different. Subsequent post-operative doses will be a standard dose of 1 g 6 hourly. This is a drug administration error and should be reported as an incident even though the patient will not be harmed.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 179 - Which of the following statements is true with regards to the Krebs' cycle...

    Incorrect

    • Which of the following statements is true with regards to the Krebs' cycle (also known as the tricarboxylic acid cycle or citric acid cycle)?

      Your Answer:

      Correct Answer: Alpha-ketoglutarate is a five carbon molecule

      Explanation:

      Krebs’ cycle (tricarboxylic acid cycle or citric acid cycle) is a sequence of reactions in which acetyl coenzyme A (acetyl-CoA) is metabolised and this results in carbon dioxide and hydrogen atoms production.

      This series of reactions occur in the mitochondria of eukaryotic cells, not the cytoplasm. The cycle requires oxygen and so, cannot function under anaerobic conditions.

      It is the common pathway for carbohydrate, fat and some amino acids oxidation and is required for high energy phosphate bond formation in adenosine triphosphate (ATP).

      When pyruvate enters the mitochondria, it is converted into acetyl-CoA. This represents the formation of a 2 carbon molecule from a 3 carbon molecule. There is loss of one CO2 but formation of one NADH molecule. Acetyl-CoA is condensed with oxaloacetate, the anion of a 4 carbon acid, to form citrate which is a 6 carbon molecule.

      Citrate is then converted into isocitrate, alpha-ketoglutarate, succinyl-CoA, succinate, fumarate, malate and finally oxaloacetate.

      The only 5 carbon molecule in the cycle is alpha-ketoglutarate.

    • This question is part of the following fields:

      • Physiology
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  • Question 180 - A caudal epidural block is planned for a 6-year-old child scheduled for...

    Incorrect

    • A caudal epidural block is planned for a 6-year-old child scheduled for an inguinoscrotal hernia repair under general anaesthesia. The weight of the child is 20kg.

      The most important safety aspect the anaesthetist must keep in mind while performing the block is?

      Your Answer:

      Correct Answer: Limiting the bupivacaine dose to no more than 40 mg

      Explanation:

      Choosing an appropriate dose of local anaesthetic to reduce the chance of toxicity is the most important safety aspect in performing a caudal block.

      The caudal will have to be inserted following induction of anaesthesia as performing it in an awake child is not a viable option.

      The patient is placed in the lateral position and the sacral hiatus is identified. Under strict asepsis, a needle ( usually a 21-23FG needle) is advanced at an angle of approximately 55-65° to the coronal plane at the apex of the sacrococcygeal membrane. When there is loss of resistance, thats the endpoint. The needle must first be aspirated before anaesthetic agent is injected because there is a risk (1 in 2000) of perforating the dura or vascular puncture.

      Alternatively, a 22-gauge plastic cannula can be used. Following perforation of the sacrococcygeal membrane, the stilette is removed and only the blunter plastic cannula is advanced. This reduces the risk of intravascular perforation.

      Eliciting an appropriate end motor response at an appropriate current strength when the caudal and epidural spaces are stimulated helps in improving the efficacy and safety of neural blockade. A 22G insulated needle is advanced in the caudal canal until a pop is felt. If the needle is placed correctly, an anal sphincter contractions (S2 to S4) is seen when an electrical stimulation of 1-10 mA is applied.

      The application of ultrasound guidance in identification of the caudal epidural space has been shown to prevent inadvertent dural puncture and to increase the safety and efficacy of the block in children.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 181 - The liver plays a major role in drug metabolism.

    Which of the following...

    Incorrect

    • The liver plays a major role in drug metabolism.

      Which of the following liver cells is most important in phase I of drug metabolism?

      Your Answer:

      Correct Answer: Centrilobular cells

      Explanation:

      The metabolism of drugs in the liver occurs in 3 phases

      Phase I: This involves functionalization reactions, which are of 3 types, namely hydrolysis, oxidation and reduction reactions catalysed by the cytochrome P450 (CYP) enzymes.

      Phase II: This involves conjugation or acetylation reactions. The goal is to create water soluble metabolites that can be excreted from the body.

      The liver is the second largest organ. It’s smallest functional unit is the acinus which is divided into 3 zones:

      Zone I (periportal): This zone receives the largest amount of oxygen supply as it is the closest to the blood vessels. It is the site of plasma protein synthesis.

      Zone II (mediolobular): This is located between the portal triad and central vein.

      Zone III (centrilobular): This is closest to the central vein and receives the least amount of oxygen supply.

      Kupffer cells are specialized macrophages found in the periportal zone of the liver, and function to remove foreign particles and breakdown red blood cells via phagocytosis.

      Ito cells are fat-storing liver cells found in the space of Disse. Their function is to take-uo, store and secrete retinoids, as well as manufacture and release proteins that make up the extracellular matrix.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 182 - One of the following neuromuscular blocking agents is the most potent: ...

    Incorrect

    • One of the following neuromuscular blocking agents is the most potent:

      Your Answer:

      Correct Answer: Vecuronium

      Explanation:

      The measure of drug potency or therapeutic response is the ED95. This is defined as the dose of a neuromuscular blocking drug required to produce a 95% depression of muscle twitch height. The ED50 and ED90 describe a depression of twitch height by 50% and 90% respectively.

      The ED95 (mg/kg) of the commonly used neuromuscular blocking agents are:

      suxamethonium: 0.27
      rocuronium: 0.31
      vecuronium: 0.04
      pancuronium: 0.07
      cisatracurium: 0.04
      mivacurium: 0.08

    • This question is part of the following fields:

      • Pharmacology
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  • Question 183 - A 72-year-old female is diagnosed with acute mesenteric ischemia.

    On CT angiogram, the...

    Incorrect

    • A 72-year-old female is diagnosed with acute mesenteric ischemia.

      On CT angiogram, the origin of the superior mesenteric artery is stenosed.

      At which vertebra level does the superior mesenteric artery branch from the aorta?

      Your Answer:

      Correct Answer: L1

      Explanation:

      The superior mesenteric artery branches from the abdominal aorta just 1-2 cm below the origin of the celiac trunk. It lies posterior to the body of the pancreas and splenic vein and is separated from the aorta by the left renal vein. It passes forwards and inferiorly, anterior to the uncinate process of the pancreas and the third part of the duodenum, to enter the root of the small bowel mesentery and supply the midgut.

      The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:

      T10 – oesophageal opening in the diaphragm

      T12 – Coeliac trunk, aortic hiatus in the diaphragm

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta

    • This question is part of the following fields:

      • Anatomy
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  • Question 184 - Which one of the following pharmacokinetic models is most suitable for target-controlled infusion...

    Incorrect

    • Which one of the following pharmacokinetic models is most suitable for target-controlled infusion (TCI) of propofol in paediatric patients?

      Your Answer:

      Correct Answer: Kataria

      Explanation:

      Marsh (adult) model, when used with children caused over-estimation of plasma concentration. To address this issue Kataria et al developed a three-compartmental model for propofol in children. The pharmacokinetic models used by Target controlled infusion (TCI) systems are used to calculate the relative sizes of the central (vascular), vessel-rich peripheral, and vessel-poor peripheral compartments. The relative volumes of these compartments are different in young children when compared to adults.

      Kataria, therefore, is the correct option as described above.

      The Maitre model is a three-compartmental model for alfentanil TCI.

      The Marsh model describes a propofol TCI model for adults

      The Minto model applies to TCI remifentanil.

      The Schnider model is also an adult model for propofol that incorporates age and lean body mass as covariates.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 185 - Which of the following is correct about the action of bile salts? ...

    Incorrect

    • Which of the following is correct about the action of bile salts?

      Your Answer:

      Correct Answer: Emulsification of lipids

      Explanation:

      The emulsification and absorption of fats requires Bile salts.

      Absorption of fats is associated with the activation of lipases in the intestine.

      Bile salts are involved in fat soluble vitamin absorption and are reabsorbed in the terminal ileum (B12 is NOT fat soluble).

      Although Vitamin B12 is also absorbed in the terminal ileum, it is a water soluble vitamin (as are B1, nicotinic acid, folic acid and vitamin C) .

      The gastric parietal cells secretes Intrinsic factor that is essential for the absorption of B12.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 186 - A 30-year-old man has been stabbed in an area of the groin that...

    Incorrect

    • A 30-year-old man has been stabbed in an area of the groin that contains the femoral triangle. He will undergo explorative surgery.

      Which of the following makes the lateral wall of the femoral triangle?

      Your Answer:

      Correct Answer: Sartorius

      Explanation:

      The femoral triangle is a wedge-shaped area found within the superomedial aspect of the anterior thigh. It is a passageway for structures to leave and enter the anterior thigh.

      Superior: Inguinal ligament
      Medial: Adductor longus
      Lateral: Sartorius
      Floor: Iliopsoas, adductor longus and pectineus

      The contents include: (medial to lateral)
      Femoral vein
      Femoral artery-pulse palpated at the mid inguinal point
      Femoral nerve
      Deep and superficial inguinal lymph nodes
      Lateral cutaneous nerve
      Great saphenous vein
      Femoral branch of the genitofemoral nerve

    • This question is part of the following fields:

      • Anatomy
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  • Question 187 - Which of the following statements is true about fluid balance? ...

    Incorrect

    • Which of the following statements is true about fluid balance?

      Your Answer:

      Correct Answer: After intravenous administration of crystalloids, the distribution of these fluids throughout the body depends on its osmotic activity

      Explanation:

      When there is capillary leakage as seen in dependent oedema or ascites, oncotic pressure becomes a problem.

      The intracellular sodium concentration is very sensitive to the extracellular sodium concentrations. When there is an imbalance, osmosis occurs resulting in shifts in water between the two compartments.

      The microvascular endothelium relies upon osmosis and other processes as it is not freely permeable to water.

    • This question is part of the following fields:

      • Physiology
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  • Question 188 - At what site would you palpate to assess the posterior tibial pulse? ...

    Incorrect

    • At what site would you palpate to assess the posterior tibial pulse?

      Your Answer:

      Correct Answer: Behind and below the medial ankle

      Explanation:

      The posterior tibial artery originates from the popliteal artery in the popliteal fossa. It passes posterior to the popliteus muscle to pierce the soleus muscle. It descends between the tibialis posterior and flexor digitorum longus muscles.

      The posterior tibial artery supplies blood to the posterior compartment of the lower limb. The artery can be palpated posterior to the medial malleolus.

      There are 4 main pulse points for the lower limb:

      1. Femoral pulse 2-3 cm below the mid-inguinal point
      2. Popliteal partially flexed knee to loosen the popliteal fascia
      3. Posterior tibial behind and below the medial ankle
      4. Dorsal pedis dorsum of the foot over the navicular bone

    • This question is part of the following fields:

      • Anatomy
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  • Question 189 - A 74-year-old man presents to a hospital for manipulation of Colles fracture. The...

    Incorrect

    • A 74-year-old man presents to a hospital for manipulation of Colles fracture. The patient is 50 kg and the anaesthetic plan is to perform an intravenous regional (Bier's) block.

      Which of the following is the appropriate dose of local anaesthetic for the procedure?

      Your Answer:

      Correct Answer: 0.5% prilocaine (40 ml)

      Explanation:

      Prilocaine is the drug of choice for intravenous regional anaesthesia. 0.5% prilocaine (40 ml) is indicated for this condition.
      Lidocaine is another alternative for this condition but volume and dose are likely to be inadequate for the procedure.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 190 - Which of the following is the maximum volume of 0.5% bupivacaine that should...

    Incorrect

    • Which of the following is the maximum volume of 0.5% bupivacaine that should be administered to a 10kg child?

      Your Answer:

      Correct Answer: 5 ml

      Explanation:

      Bupivacaine is used to decrease sensation in a specific area. It is injected around a nerve that supplies the area, or into the spinal canal’s epidural space.

      The maximum volume of 0.5% bupivacaine that should be administered to a 10kg child is 5 ml

    • This question is part of the following fields:

      • Pharmacology
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  • Question 191 - A 68-year-old woman is a known case of acute myeloid leukaemia and was...

    Incorrect

    • A 68-year-old woman is a known case of acute myeloid leukaemia and was treated with chemotherapy as a child. She now presents in casualty, and you are called in to attend this patient as it is getting difficult to gain vascular access in her arms. The medical registrar asks you to site a cannula during the arrest call as intraosseous access is delayed. The intern wants to assist you in performing a venous cutdown of one of the veins in the patients ankle that passes anterior to the medial malleolus. Which vessel is this?

      Your Answer:

      Correct Answer: Long saphenous vein

      Explanation:

      Venous cutdown is a surgical procedure when venous access is difficult, and other procedures like the Seldinger technique, ultrasound-guided venous access, and intraosseous vascular access have failed.

      The vein of choice for venous cutdown is the long/great saphenous vein. It is part of the superficial venous collecting system of the lower extremity. It is the preferred vein as the long saphenous vein has anatomic consistency and is superficially located at the ankle anterior to the medial malleolus. It is also the most commonly used conduit for cardiovascular bypass operations.

      Origin- in the foot at the confluence of the dorsal vein of the first digit and the dorsal venous arch of the foot
      Route- runs ANTERIOR to the medial malleolus and travels up in the medial leg and upper thigh.
      Termination: in the femoral vein within the femoral triangle

      Regarding the other options:
      The short saphenous vein passes posterior to the lateral malleolus.
      The dorsalis pedis vein accompanies the dorsalis pedis artery on the anterior foot.
      The posterior tibial vein is part of the deep venous system accompanying the posterior tibial artery. There is no significant sural vein (there is a sural nerve), but the sural veins accompany the sural arteries and drain to the popliteal vein.

    • This question is part of the following fields:

      • Anatomy
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  • Question 192 - The cardiac muscle will primarily utilize which metabolic substrate to produce energy when...

    Incorrect

    • The cardiac muscle will primarily utilize which metabolic substrate to produce energy when at rest?

      Your Answer:

      Correct Answer: Fatty acids

      Explanation:

      Approximately 70% of the heart’s ATP requirement is met by cardiac mitochondria through beta-oxidation of fatty acids at rest. The remaining 30% is supplied by glucose.

      Amino acids and ketones, in the presence of ketoacidosis, may supply at most 10% of the ATP requirement. And, when in high levels, lactate may also contribute to the ATP requirement of the heart, particularly during moments of high muscular activity.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 193 - A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise....

    Incorrect

    • A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise. On urine culture and sensitivity testing, E.coli was detected with resistance to ampicillin.
      What is the mechanism of resistance to ampicillin?

      Your Answer:

      Correct Answer: Beta-lactamase production

      Explanation:

      Ampicillin belongs to the family of penicillin. Resistance to this group of drugs is due to ?-lactamase production which opens the ?-lactam ring and inactivates Penicillin G and some closely related congeners. The majority of Staphylococci and some strains of gonococci, B. subtilis, E. coli, and a few other bacteria produce penicillinase.

      Resistance to cephalosporins is due to changes in penicillin-binding proteins.

      Resistance to macrolides are due to post-transcriptional methylation of 23s bacterial ribosomal RNA

      Resistance to fluoroquinolones is due to mutations in DNA gyrase.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 194 - What makes the ultrasound nebulizer efficient? ...

    Incorrect

    • What makes the ultrasound nebulizer efficient?

      Your Answer:

      Correct Answer: Reduction in gas flow resistance

      Explanation:

      Smallest drops reach not only the upper but also the lower respiratory tracks. As a result, the ultrasonic nebulizer is most efficient for the therapy of pulmonary diseases and stands out as a robust and reliable support within the clinical setting.

    • This question is part of the following fields:

      • Basic Physics
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  • Question 195 - Which of the following bias is more prone to case-control studies? ...

    Incorrect

    • Which of the following bias is more prone to case-control studies?

      Your Answer:

      Correct Answer: Recall bias

      Explanation:

      Omitted variable bias occurs when a statistician passes over one or more relevant variables from the study.

      Publication bias occurs in publish academic research. it occurs when the results of the study effect the decision whether to publish or not.

      Expectation bias occurs when the expectation of a researcher about the results effect the behaviour of the participants. Expectations may come from communication and experiences.

      Work up bias occurs in the study of diagnostic test validity, whether a gold standard procedure has been used. work up bias can seriously affect the specificity of the test.

      Recall bias introduced when participants in a study are systematically more or less likely to recall and relate information on exposure depending on their outcome status. Recall bias is more potential for Case-control studies.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 196 - A 58-year-old man, visits his general practitioner complaining of a lump in his...

    Incorrect

    • A 58-year-old man, visits his general practitioner complaining of a lump in his groin. He explains he is otherwise well and reports no other symptoms. The lump is examined and is found to be soft, and can be reduced without causing the patient pain. The GP diagnoses an inguinal hernia. To determine the nature of the hernia, the GP reduced the lump and applies pressure on the deep inguinal ring.

      The deep inguinal ring has what anatomical landmark?

      Your Answer:

      Correct Answer: Superior to the midpoint of the inguinal ligament

      Explanation:

      The deep inguinal ring lies approximately 1.5-2cm above the midpoint of the inguinal ligament, the halfway point between the anterior superior iliac spine and the pubic tubercle, next to the epigastric vessels.

      It is an important point in determining the nature of an inguinal hernia (direct or indirect). The patient is asked to cough after the hernia is reduced, with pressure applied to the deep inguinal ring. The hernia reappearing indicates it is direct, moving through the posterior wall of the inguinal canal.

      Inferior and lateral to the pubic tubercle is the normal anatomical position of the neck of a femoral hernia.

      Superior and medial to the pubic tubercle is the site of the superficial inguinal ring, and the normal anatomical position of the neck of an inguinal hernia.

      The mid-inguinal point is located halways between the pubic symphysis and the anterior superior iliac spine. It is the surface marking for taking the femoral pulse.

    • This question is part of the following fields:

      • Anatomy
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  • Question 197 - A 25-year-old man, has been scheduled for a splenectomy. For this procedure, he...

    Incorrect

    • A 25-year-old man, has been scheduled for a splenectomy. For this procedure, he requires a urethral catheter.

      Where does resistance first occur during the insertion of a catheter?

      Your Answer:

      Correct Answer: Membranous urethra

      Explanation:

      The membranous urethra is the shortest part of the urethra and the least dilatable part of it.

      This is as a result of it being surrounded by the external urethral sphincter which is made up of striated muscle and controls voluntary urine flow from the bladder to the urethra.

    • This question is part of the following fields:

      • Anatomy
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  • Question 198 - Which of the following is a feature of a central venous pressure waveform?...

    Incorrect

    • Which of the following is a feature of a central venous pressure waveform?

      Your Answer:

      Correct Answer: An a wave due to atrial contraction

      Explanation:

      The central venous pressure (CVP) waveform depicts changes of pressure within the right atrium. Different parts of the waveform are:

      A wave: which represents atrial contraction. It is synonymous with the P wave seen during an ECG. It is often eliminated in the presence of atrial fibrillation, and increased tricuspid stenosis, pulmonary stenosis and pulmonary hypertension.

      C wave: which represents right ventricle contraction at the point where the tricuspid valve bulges into the right atrium. It is synonymous with the QRS complex seen on ECG.

      X descent: which represents relaxation of the atrial diastole and a decrease in atrial pressure, due to the downward movement of the right ventricle as it contracts. It is synonymous with the point before the T wave on ECG.

      V wave: which represents an increase in atrial pressure just before the opening of the tricuspid valve. It is synonymous with the point after the T wave on ECG. It is increased in the background of a tricuspid regurgitation.

      Y descent: which represents the emptying of the atrium as the tricuspid valve opens to allow for blood flow into the ventricle in early diastole.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 199 - An 82-year old male has shortness of breath which is made worse when...

    Incorrect

    • An 82-year old male has shortness of breath which is made worse when he lies down but investigations have revealed a normal ejection fraction. Why might this be?

      Your Answer:

      Correct Answer: He has diastolic dysfunction

      Explanation:

      Decreased stroke volume causes decreased ejection fraction which results in diastolic dysfunction.
      Ejection fraction is not a useful measure in someone with diastolic dysfunction because stroke volume may be reduced whilst end-diastolic volume may be reduced.
      Diastolic dysfunction may arise with reduced heart compliance.

      Ejection fraction measures of the proportion of blood leaving the ventricles with each beat and is calculated as follows:
      Stroke volume / end-diastolic volume.

      A healthy ejection fraction is usually taken as 60% (based on a stroke volume of 70ml and end-diastolic volume of 120ml).

      Respiratory inspiration causes a decreased pressure in the thoracic cavity, which in turn causes more blood to flow into the atrium.

      Sitting up decreases venous because of the action of gravity on blood in the venous system.
      Hypotension also decreases venous return.
      A less compliant aorta, like in aortic stenosis increases end systolic left ventricular volume which decreases stroke volume.

      Systemic vascular resistance = mean arterial pressure / cardiac output.
      Increased vascular resistance impedes the flow of blood back to the heart.

      Increased venous return increases end diastolic LV volume as there is more blood returning to the ventricles.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 200 - All the following statements are false regarding nitrous oxide except: ...

    Incorrect

    • All the following statements are false regarding nitrous oxide except:

      Your Answer:

      Correct Answer: Maintains carbon dioxide reactivity

      Explanation:

      Nitrous oxide increases cerebral blood flow by direct cerebral stimulation and tends to elevate intracranial pressure (ICP)

      It increases the cerebral metabolic rate of oxygen consumption (CMRO2)

      It is not an NMDA agonist as it antagonizes NMDA receptors.

      Cerebral autoregulation is impaired with the use of nitrous oxide but when used with propofol, it is maintained.

      Carbon dioxide reactivity is not affected by it.

    • This question is part of the following fields:

      • Pharmacology
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