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  • Question 1 - A 70-year-old man presents with bilateral buttock claudication that spreads down the thigh...

    Correct

    • A 70-year-old man presents with bilateral buttock claudication that spreads down the thigh and erectile dysfunction in a vascular clinic.

      The left femoral pulse is not palpable on examination, and the right is weakly palpable. Leriche syndrome is diagnosed as the blood flow at the abdominal aortic bifurcation is blocked due to atherosclerosis. He is prepared for aortoiliac bypass surgery.

      Which vertebral level will you find the affected artery that requires bypassing?

      Your Answer: L4

      Explanation:

      The bifurcation of the abdominal aorta into common iliac arteries occurs at the level of L4. The bifurcation is a common site for atherosclerotic plaques as it is an area of high turbulence.

      Leriche Syndrome is an aortoiliac occlusive disease and affects the distal abdominal aorta, iliac arteries, and femoropopliteal vessels. It has a triad of symptoms:
      1. Claudication (cramping lower extremities pain that is reproducible by exercise)
      2. Impotence (reduced penile arterial flow)
      3. Absent/weak femoral pulses (hallmark)

      T12 – aorta enters the diaphragm with the thoracic duct and azygous veins

      L2 – testicular or ovarian arteries branch off the aorta

      L3 – inferior mesenteric artery

    • This question is part of the following fields:

      • Anatomy
      17.4
      Seconds
  • Question 2 - Which statement is true when describing carbonic anhydrase? ...

    Correct

    • Which statement is true when describing carbonic anhydrase?

      Your Answer: Isoenzyme IV is found in the brush border of the proximal convoluted tubule

      Explanation:

      Carbonic anhydrase is an enzyme which contains zinc and can be found in:
      1. Erythrocytes
      2. Pulmonary endothelium
      3. The intestine
      4. Pancreas
      5. Cardiac muscle and skeletal muscle.

      To date, there have been seven isoenzymes identified. Of note, isoenzyme IV is found in the brush border of the proximal convoluted tubule and isoenzyme II is found within the luminal cells.

      Acetazolamides a carbonic anhydrase inhibitor and is used as prophylaxis against mountain sickness and in glaucoma management.

      Spironolactone is a potassium diuretic and is an aldosterone antagonist.

    • This question is part of the following fields:

      • Physiology
      2.8
      Seconds
  • Question 3 - Infrared radiation is absorbed by asymmetric, polyatomic polar molecules like carbon dioxide (CO2).

    When...

    Correct

    • Infrared radiation is absorbed by asymmetric, polyatomic polar molecules like carbon dioxide (CO2).

      When measuring CO2 in gas samples, mainstream capnography uses this physical principle.

      Which of the following gases is most likely to interfere with carbon dioxide's absorption spectrum?

      Your Answer: Nitrous oxide

      Explanation:

      Carbon dioxide absorbs the most infrared (IR) light between the wavelengths of 4.2-4.4m (4.26m is ideal).

      Nitrous oxide absorbs infrared light at wavelengths of 4.4-4.6m (very similar to CO2) and less so at 3.9m.

      At a frequency of 4.7m, carbon monoxide absorbs the most IR light.

      At 3.3 m and throughout the ranges 8-12 m, the volatile agents have strong absorption bands.

      Although oxygen does not absorb infrared light, it collides with CO2 molecules, interfering with absorption. The absorption band is widened as a result of this (so called collision or pressure broadening). A drop of 0.5 percent in measured CO2 can be caused by 95% oxygen.

      Nitrous oxide causes a greater inaccuracy of 0.1 percent per ten percent of nitrous oxide.

      Water vapour absorbs infrared light as well, resulting in absorption band overlap, collision broadening, and partial pressure dilution. Water traps and water permeable tubing are used to reduce inaccuracies.

      Collision broadening is compensated for in modern gas multi-gas analysers.

    • This question is part of the following fields:

      • Pharmacology
      19.8
      Seconds
  • Question 4 - Which of the following nerves is responsible for carrying taste sensation from the...

    Correct

    • Which of the following nerves is responsible for carrying taste sensation from the given part of the tongue?

      Your Answer: Anterior two thirds of tongue - facial nerve

      Explanation:

      Taste sensation from the anterior two-thirds of the tongue is carried by chorda tympani, a branch of the facial nerve.

      The general somatic sensation of the anterior two-third of the tongue is supplied by the lingual nerve, a branch of the mandibular nerve.

      Both general somatic sensation and taste from the posterior third of the tongue are carried by the glossopharyngeal nerve.

      All the muscles of the tongue except palatoglossus are supplied by the hypoglossal nerve whereas palatoglossus is supplied by the vagus nerve. (This is because palatoglossus is the only tongue muscle derived from the fourth branchial arch)

    • This question is part of the following fields:

      • Pathophysiology
      6.8
      Seconds
  • Question 5 - A 70-year-old man presents to hospital complaining of dysphagia. He is scheduled for...

    Correct

    • A 70-year-old man presents to hospital complaining of dysphagia. He is scheduled for a rigid oesophagoscopy.

      On examination, He is noted to have severe osteoarthritis in his cervical spine resulting in limited rotation and flexion-extension. He has no other neurological signs or symptoms.

      He is given anaesthesia for the procedure, which is complicated by a difficult intubation (Cormack-Lehane 3), but was eventually achieved using a gum elastic bougie.

      After recovering from anaesthesia, he is examined and found to have severe motor weakness of upper limbs, and mild motor weakness of lower limbs, bladder dysfunction and sensory loss of varying degrees below the level of C5.

      What incomplete spinal cord lesion is most likely to be responsible for his symptoms?

      Your Answer: Central cord syndrome

      Explanation:

      Central cord syndrome is the most commonly occurring type of partial spinal cord lesion. It is more likely to occur in older patients with cervical spondylosis and a hyperextension injury. The injury to the spinal cord occurs in the grey matter causing the following symptoms:

      Disproportionally higher motor function weakness in the upper limbs than in lower limbs
      Dysfunction of the bladder
      Degrees of sensory loss below the level of the lesion

      An anterior spinal artery infarction will interrupt the corticospinal tract resulting in paralysis of motor function, loss of pain and temperature sensation, all occurring below the level of the injury.

      Brown-Sequard syndrome occurs as a result of the hemisection of the spinal cord. Its symptoms include ipsilateral upper motor neurone paralysis and loss of proprioception, with contralateral loss of pain and temperature sensation.

      Spinal cord infarctions rarely occur in the posterior spinal artery.

      Cauda equina syndrome occurs as a result of compression of the lumbosacral spinal nerve roots below the level of the conus medullaris. Injury to these nerves will cause partial or complete loss of movement and sensation in this distribution.

    • This question is part of the following fields:

      • Pathophysiology
      2.5
      Seconds
  • Question 6 - Regarding amide local anaesthetics, which one factor has the most significant effect on...

    Correct

    • Regarding amide local anaesthetics, which one factor has the most significant effect on its duration of action?

      Your Answer: Protein binding

      Explanation:

      When drugs are bound to proteins, drugs cannot cross membranes and exert their effect. Only the free (unbound) drug can be absorbed, distributed, metabolized, excreted and exert pharmacologic effect. Thus, when amide local anaesthetics are bound to ?1-glycoproteins, their duration of action are reduced.

      The potency of local anaesthetics are affected by lipid solubility. Solubility influences the concentration of the drug in the extracellular fluid surrounding blood vessels. The brain, which is high in lipid content, will dissolve high concentration of lipid soluble drugs. When drugs are non-ionized and non-polarized, they are more lipid-soluble and undergo more extensive distribution. Hence allowing these drugs to penetrate the membrane of the target cells and exert their effect.

      Tissue pKa and pH will determine the degree of ionization.

    • This question is part of the following fields:

      • Physiology
      5.9
      Seconds
  • Question 7 - Which of the following best describes why phenytoin's hepatic extraction ratio is low? ...

    Correct

    • Which of the following best describes why phenytoin's hepatic extraction ratio is low?

      Your Answer: It has a clearance that is insensitive to changes in liver blood flow

      Explanation:

      The following are the pharmacokinetic properties of drugs with a low hepatic extraction ratio:

      Changes in liver blood flow have no effect on drug clearance.
      When given orally, drug clearance is extremely sensitive to changes in protein binding, intrinsic metabolism, and excretion, and there is no first-pass metabolism.

      Warfarin and phenytoin are two drugs with low hepatic extraction ratios.

      The following are the pharmacokinetic properties of drugs with a high hepatic extraction ratio:

      When taken orally, undergo extensive first-pass metabolism; drug clearance is dependent on liver blood flow, and drug clearance is less sensitive to changes in protein binding and intrinsic metabolism.

      Morphine, lidocaine, propranolol, and etomidate are examples of drugs with high hepatic extraction ratios.

    • This question is part of the following fields:

      • Pharmacology
      7.4
      Seconds
  • Question 8 - A pharmaceutical company has developed a new drug considered a breakthrough in treating...

    Incorrect

    • A pharmaceutical company has developed a new drug considered a breakthrough in treating ovarian cancer.

      The efficacy of this drug can be assessed by which phase of a clinical trial?

      Your Answer: Phase I

      Correct Answer: Phase IIa

      Explanation:

      Phase IIa studies are usually pilot studies designed to demonstrate clinical efficacy or biological activity (‘proof of concept’ studies) whereas phase IIb studies determine the optimal dose at which the drug shows biological activity with minimal side-effects (definite dose-finding studies).

      Phase III and Phase IV studies are performed on larger set of participants (usually hundreds to thousands) when safety and efficacy have been established.

    • This question is part of the following fields:

      • Statistical Methods
      15.9
      Seconds
  • Question 9 - When compared to unipolar diathermy, which of the following is more specific to...

    Correct

    • When compared to unipolar diathermy, which of the following is more specific to bipolar diathermy?

      Your Answer: Has a power output of up to 140 joules per second

      Explanation:

      Electrocautery, also known as diathermy, is a technique for coagulation, tissue cutting, and fulguration that uses a high-frequency current to generate heat (cell destruction from dehydration).

      The two electrodes in bipolar diathermy are the tips of forceps, and current passes between the tips rather than through the patient. Bipolar diathermy’s power output (40-140 W) is lower than unipolar diathermy’s typical output (400 W). There is no earthing in the bipolar circuit.

      A cutting electrode and a indifferent electrode in the form of a metal plate are used in unipolar diathermy. The high-frequency current completes a circuit by passing through the patient from the active electrode to the metal plate. When used correctly, the current density at the indifferent electrode is low, and the patient is unlikely to be burned. Between the patient plate and the earth is placed an isolating capacitor. This has a low impedance to a high frequency current, such as diathermy current, and is used in modern diathermy machines. The capacitor has a high impedance to current at 50 Hz, which protects the patient from electrical shock.

      High frequency currents (500 KHz – 1 MHz) are used in both unipolar and bipolar diathermy, which can cause tissue damage and interfere with pacemaker function (less so with bipolar diathermy).

      The effect of diathermy is determined by the current density and waveform employed. The current is a pulsed square wave pattern in coagulation mode and a continuous square wave pattern in cutting mode.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      182.9
      Seconds
  • Question 10 - Which of the given statements is true about standard error of the mean?...

    Correct

    • Which of the given statements is true about standard error of the mean?

      Your Answer: Gets smaller as the sample size increases

      Explanation:

      The standard error of the mean (SEM) is a measure of the spread expected for the mean of the observations – i.e. how ‘accurate’ the calculated sample mean is from the true population mean. The relationship between the standard error of the mean and the standard deviation is such that, for a given sample size, the standard error of the mean equals the standard deviation divided by the square root of the sample size.

      SEM = SD / square root (n)

      where SD = standard deviation and n = sample size

      Therefore, the SEM gets smaller as the sample size (n) increases.

      If we want to depict how widely scattered some measurements are, we use the standard deviation. For indicating the uncertainty around the estimate of the mean, we use the standard error of the mean. The standard error is most useful as a means of calculating a confidence interval. For a large sample, a 95% confidence interval is obtained as the values 1.96×SE either side of the mean.

      A 95% confidence interval:

      lower limit = mean – (1.96 * SEM)

      upper limit = mean + (1.96 * SEM)

      Results such as mean value are often presented along with a confidence interval. For example, in a study the mean height in a sample taken from a population is 183cm. You know that the standard error (SE) (the standard deviation of the mean) is 2cm. This gives a 95% confidence interval of 179-187cm (+/- 2 SE).

      Hence, it would be wrong to say that confidence levels do not apply to standard error of the mean.

    • This question is part of the following fields:

      • Statistical Methods
      5.8
      Seconds
  • Question 11 - A 26-year old male patient was admitted to the surgery department for appendectomy....

    Correct

    • A 26-year old male patient was admitted to the surgery department for appendectomy. Medical history revealed that he has major depressive disorder and was on Phenelzine. Aside from abdominal pain, initial assessment was unremarkable. However, thirty minutes after, the patient was referred to you for generalized seizures. He was given an analgesic and it was noted that, during the first 15 minutes of administration, he became anxious, with profuse sweating, which later developed into seizures. Upon physical examination, he was febrile at 38.3°C.

      Which of the following statements is the best explanation for the patient's symptoms?

      Your Answer: Drug interaction with pethidine

      Explanation:

      The clinical picture best describes a probable drug interaction with pethidine.

      Phenelzine, a monoamine oxidase (MAO) inhibitor, when given with pethidine, an opioid analgesic, may lead to episodes of hypertension, rigidity, excitation, hyperpyrexia, seizures, coma and death. Studies have shown that pethidine reacts more significantly with MAO inhibitors than morphine.

      When pethidine is metabolised to normeperidine, it acts as a serotonin reuptake inhibitor and cause an increase in serotonin levels in the brain. MAO inhibitors can also lead to elevated levels of serotonin because of its mechanism of action by inhibiting the enzyme monoamine oxidase that degrades serotonin.

      The excess serotonin levels may lead to serotonin syndrome, of which some of the common precipitating drugs are selective serotonin reuptake inhibitors, MAO inhibitors, tricyclic antidepressants, meperidine, and St. John’s Wort. Onset of symptoms is within hours, which includes fever, agitation, tremor, clonus, hyperreflexia and diaphoresis.

      Drug interaction between phenelzine and paracetamol do not commonly precipitate serotonin syndrome.

      Neuroleptic malignant syndrome is due to dopamine antagonism, precipitated commonly by antipsychotics. Its onset of symptoms occur in 1 to 3 days, and is characterized by fever, encephalopathy, unstable vitals signs, elevated CPK, and rigidity.

      Altered mental status is the most common manifestation of sepsis-associated encephalopathy. Patient also exhibit confusional states and inappropriate behaviour. In some cases, this may lead to coma and death.

    • This question is part of the following fields:

      • Pharmacology
      5.8
      Seconds
  • Question 12 - An intravenous infusion is started with a 500 mL bag of 0.18 percent...

    Incorrect

    • An intravenous infusion is started with a 500 mL bag of 0.18 percent N. saline and 4% dextrose.

      Which of the following best describes its make-up?

      Your Answer: Osmolarity 293 mOsmol/L, sodium 15 mequivalents and glucose 40 g

      Correct Answer: Osmolarity 284 mOsmol/L, sodium 15 mequivalents and glucose 20 g

      Explanation:

      30 mmol Na+ and 30 mmol Cl- are found in 1 litre of 0.18 percent N. saline with 4% dextrose. Percent (percent) refers to the number of grammes of a compound per 100 mL, so a litre of 4 percent dextrose solution contains 40 grammes.

      As a result, a 500 mL bag of 1/5th N. saline and 4% dextrose contains approximately 15 mequivalents of sodium and 20 g of glucose. It is hypotonic due to its osmolarity of 284.

      Because of the risk of hyponatraemia, it is no longer considered the crystalloid of choice for fluid maintenance in children.

    • This question is part of the following fields:

      • Physiology
      14.3
      Seconds
  • Question 13 - Two different anti-viral treatments are being evaluated for COVID-19 in a clinical study....

    Correct

    • Two different anti-viral treatments are being evaluated for COVID-19 in a clinical study.

      Which of the following statistical method should be opted to compare survival time with?

      Your Answer: Hazard ratio

      Explanation:

      The hazard ratio (HR) is simply a comparison of two hazards in a study. It provides an estimate of the ratio of the hazard rates between the experimental group and a control group over the entire study duration. It is typically used when analysing survival over time, hence is the most suitable statistical method in this case.

      An odds ratio is a statistic that quantifies the strength of the association between two events, A and B. It is the “measure of association” for a case-control study.

      The Pearson product-moment correlation coefficient (Pearson’s correlation, for short) is a measure of the strength and direction of association that exists between two variables. An example would be if scientists wanted to evaluate the relationship between quality of certain population of rice and their genetic make-up.

      Relative risk is the ratio of the risks for an event for the exposure group to the risks for the non-exposure group. Thus relative risk provides an increase or decrease in the likelihood of an event based on some exposure. Relative risk measures the association between the exposure and the outcome.

      Absolute risk reduction is the number of percentage points your own risk goes down if you do a preventive act such as stop drinking alcohol. It depends on what your risk factors are to begin with.

    • This question is part of the following fields:

      • Statistical Methods
      16.7
      Seconds
  • Question 14 - Which of the following can be evaluated by the Delphi method? ...

    Correct

    • Which of the following can be evaluated by the Delphi method?

      Your Answer: Expert consensus

      Explanation:

      The Delphi method relies on expert consensus. This method kicks off with an open ended questionnaire and uses its responses as a survey instrument for the next round in which each of the participants is asked to rate the items that the investigators have summarized on the basis of the data collected in the first round. Any disagreement is further discussed in phases to come on the basis of information obtained from previous phases.

    • This question is part of the following fields:

      • Statistical Methods
      6.1
      Seconds
  • Question 15 - What feature is found in the flowmeters of modern anaesthetic machines ? ...

    Incorrect

    • What feature is found in the flowmeters of modern anaesthetic machines ?

      Your Answer: Oxygen is the first gas to be added to the mixture delivered to the back bar

      Correct Answer: The use of stannic oxide increases the accuracy of flowmeters

      Explanation:

      Flowmeters measure the rate at which a specific gas, that the flowmeter has been calibrated for, passes through. This calibration is done at room temperature and standard atmospheric pressure with an accuracy of +/- 2%.

      Reading the flowmeter is done from the top of a bobbin (the midpoint of a ball). Oxygen is the last gas to be added downstream to the mixture delivered to the back bar as a safety feature. This prevents delivery of a hypoxic mixture.

      Inaccurate flow measurements occur when the bobbin sticks to the inside wall of the flowmeter. Stannic oxide has been used as a successful antistatic substance thus, reducing the aforementioned risk.

      Carbon dioxide being easily delivered is found on some older machines, but those attached flowmeters are limited by a maximum flow of 500 ml /min. Thus avoiding the delivery of a hypercarbic mixture.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      18.8
      Seconds
  • Question 16 - Which one of the following pharmacokinetic models is most suitable for target-controlled infusion...

    Correct

    • Which one of the following pharmacokinetic models is most suitable for target-controlled infusion (TCI) of propofol in paediatric patients?

      Your Answer: Kataria

      Explanation:

      Marsh (adult) model, when used with children caused over-estimation of plasma concentration. To address this issue Kataria et al developed a three-compartmental model for propofol in children. The pharmacokinetic models used by Target controlled infusion (TCI) systems are used to calculate the relative sizes of the central (vascular), vessel-rich peripheral, and vessel-poor peripheral compartments. The relative volumes of these compartments are different in young children when compared to adults.

      Kataria, therefore, is the correct option as described above.

      The Maitre model is a three-compartmental model for alfentanil TCI.

      The Marsh model describes a propofol TCI model for adults

      The Minto model applies to TCI remifentanil.

      The Schnider model is also an adult model for propofol that incorporates age and lean body mass as covariates.

    • This question is part of the following fields:

      • Pharmacology
      1.8
      Seconds
  • Question 17 - Very large SI units are easily expressed using mathematical prefixes.

    One terabyte is equal...

    Incorrect

    • Very large SI units are easily expressed using mathematical prefixes.

      One terabyte is equal to which of the following numbers?

      Your Answer: 1,000,000,000 bytes

      Correct Answer: 1,000,000,000,000 bytes

      Explanation:

      To denote large measured units, the following SI mathematical prefixes are used:

      1 deca = 10 bytes (101)
      1 hecto (h) = 100 bytes
      1 kilo (k)= 1,000 bytes
      1 mega (M) = 1,000,000 bytes
      1 giga (G) = 1,000,000,000 bytes
      1 Tera (T) = 1,000,000,000,000 bytes
      1 Peta (P) = 1,000,000,000,000,000 bytes

    • This question is part of the following fields:

      • Basic Physics
      8.7
      Seconds
  • Question 18 - A 50-year old man for septoplasty has a BMI of 32kg/m2 and neck...

    Incorrect

    • A 50-year old man for septoplasty has a BMI of 32kg/m2 and neck circumference of 44 cm. He is troubled by intermittent nasal obstruction which causes his partner sleeps in a separate bedroom because of snoring. He currently on ramipril for hypertension.

      Which of the following best approximates to his STOP-BANG score from the information above?

      Your Answer: 4

      Correct Answer: 5

      Explanation:

      The STOP-BANG questionnaire is used to screen patients for obstructive sleep apnoea (OSA).

      The scoring system assigns one point for each feature.

      S: Snoring (louder than talking or loud enough to be heard through closed doors)
      T: Feeling tired, fatigued, or sleepy during daytime
      O: Observed apnoeas during sleep
      P: Hypertension
      B: BMI more than 35 kg/m2
      A: Age 50-years of age or greater
      N: Neck circumference (male 17 inches / 43cm or greater and female 16 inches / 41 or greater)
      G: Gender: Male

      Our patient has a score of 5 ( O, P, A, N, G)

      The score helps clinicians stratify patients for unrecognized OSA and target appropriate clinical management. It can also help triage patients for further investigation. A STOP-BANG score of 5-8 will identify patients with high probability of moderate to severe OSA in the surgical population.

    • This question is part of the following fields:

      • Clinical Measurement
      15.5
      Seconds
  • Question 19 - A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure,...

    Incorrect

    • A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure, the ileocolic artery is ligated. Which vessel does this artery originate from?

      Your Answer: Inferior mesenteric artery

      Correct Answer: Superior mesenteric artery

      Explanation:

      The ileocolic artery is the terminal branch of the superior mesenteric artery. It supplies:
      1. terminal ileum
      2. proximal right colon
      3. cecum
      4. appendix (via its branch of the appendicular artery)

      As veins accompany arteries in the mesentery and are lined by lymphatics, high ligation is the norm in cancer resections—the ileocolic artery branches off the SMA near the duodenum.

    • This question is part of the following fields:

      • Anatomy
      2349
      Seconds
  • Question 20 - A 55-year-old man with a ventricular rate of 210 beats per minute is...

    Correct

    • A 55-year-old man with a ventricular rate of 210 beats per minute is admitted to the emergency department with atrial fibrillation. The patient develops ventricular fibrillation shortly after receiving pharmacotherapy to treat his arrhythmia, from which he is successfully resuscitated.

      He has a PR interval of 40 Ms, a prominent delta wave in lead I, and a QRS duration of 120 Ms, according to an ECG from a previous admission.

      Which of the following drugs is most likely to be involved in this patient's development of ventricular fibrillation?

      Your Answer: Digoxin

      Explanation:

      The Wolff-Parkinson-White syndrome (WPWS) is linked to an additional electrical conduction pathway between the atria and ventricles. This accessory pathway (bundle of Kent), unlike the atrioventricular (AV) node, is incapable of slowing down a rapid rate of atrial depolarization. In other words, a short circuit bypasses the AV node. Patients with a rapid ventricular response or narrow complex AV re-entry tachycardia are more likely to develop atrial fibrillation or flutter.

      Digoxin can promote impulse transmission through this accessory pathway if a patient with WPWS develops atrial fibrillation because it works by blocking the AV node. This can cause ventricular fibrillation and an extremely rapid ventricular rate. As a result, it’s not advised.

      Adenosine, beta-blockers, and calcium channel blockers, among other drugs that interfere with AV nodal conduction, are also generally contraindicated.

      The class III antiarrhythmic drugs amiodarone and ibutilide (K+ channel block) and procainamide (Na+ channel block) are the drugs of choice.

    • This question is part of the following fields:

      • Pharmacology
      42.1
      Seconds
  • Question 21 - A patient's ECG is abnormal, with an abnormal broad complex QRS complexes. This...

    Correct

    • A patient's ECG is abnormal, with an abnormal broad complex QRS complexes. This means either a ventricular origin problem or aberrant conduction. The normal resting membrane potential of the heart's ventricular contractile fibres is which of the following?

      Your Answer: -90mV

      Explanation:

      The cardiac muscle’s contractile fibres have a much more stable resting potential than its conductive fibres. In the ventricular fibres it is -90mV and in the atrial fibres it is -80mV.

      The cardiac action potential has several phases which have different mechanisms of action as seen below:

      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms. (QRS complex)

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology And Biochemistry
      151.8
      Seconds
  • Question 22 - About the mechanism of action of bendroflumethiazide, Which of the following is correct?...

    Correct

    • About the mechanism of action of bendroflumethiazide, Which of the following is correct?

      Your Answer: Sodium-chloride symporter inhibitor

      Explanation:

      Sodium-chloride symporter inhibitor.

      The thiazide sensitive sodium chloride symporter is inhibited by thiazides at the proximal portion of the distal convoluted tubule leading to increased sodium and water excretion. Increased delivery of sodium to the distal portion of the distal convoluted tubule promotes potassium loss. This is why thiazides are associated with hyponatraemia and hypokalaemia.

      Carbonic anhydrase inhibitors are used mainly in the treatment of glaucoma. They act on the proximal convoluted tubule to promote bicarbonate, sodium and potassium loss.

      Sodium potassium chloride symporter is inhibited by Loop diuretics.
      Epithelial sodium channels are inhibited by Amiloride.
      Drugs which lead to nephrogenic diabetes insipidus such as lithium and demeclocycline, are Inhibitors of vasopressin.

    • This question is part of the following fields:

      • Pharmacology
      23.7
      Seconds
  • Question 23 - All the following statements are false regarding nitrous oxide except: ...

    Correct

    • All the following statements are false regarding nitrous oxide except:

      Your Answer: Maintains carbon dioxide reactivity

      Explanation:

      Nitrous oxide increases cerebral blood flow by direct cerebral stimulation and tends to elevate intracranial pressure (ICP)

      It increases the cerebral metabolic rate of oxygen consumption (CMRO2)

      It is not an NMDA agonist as it antagonizes NMDA receptors.

      Cerebral autoregulation is impaired with the use of nitrous oxide but when used with propofol, it is maintained.

      Carbon dioxide reactivity is not affected by it.

    • This question is part of the following fields:

      • Pharmacology
      248.1
      Seconds
  • Question 24 - An elective left colectomy is being performed on a 60-year old male for...

    Correct

    • An elective left colectomy is being performed on a 60-year old male for left-sided colon cancer. The upper and lower parts of the descending colon are supplied by the left colic artery.

      Which of the following arteries gives rise to the left colic artery?

      Your Answer: Inferior mesenteric artery

      Explanation:

      The inferior mesenteric artery originates 3-4 cm above the bifurcation of the abdominal aorta. The left colic artery branches off the inferior mesenteric artery, arising close to its origin from the abdominal aorta. Other branches of IMA include the three sigmoid arteries that supply the sigmoid colon.

      The left colic artery branches off from IMA to supply the distal 1/3 of the transverse colon and the descending colon. It moves upwards posterior to the left colic mesentery and then travels anteriorly to the psoas major muscle, left ureter, and left internal spermatic vessels, before dividing into ascending and descending branches.

    • This question is part of the following fields:

      • Anatomy
      6.8
      Seconds
  • Question 25 - Which of the following is a correctly stated fundamental (base) SI unit? ...

    Incorrect

    • Which of the following is a correctly stated fundamental (base) SI unit?

      Your Answer: A watt is the unit of energy

      Correct Answer: A metre is the unit of length

      Explanation:

      The international system of units, or system international d’unites (SI) is a collection of measurements derived from expanding the metric system.

      There are seven base units, which are:

      Metre (m): a unit of length
      Second (s): a unit of time
      Kilogram (kg): a unit of mass
      Ampere (A): a unit of electrical current
      Kelvin (K): a unit of thermodynamic temperature
      Candela (cd): a unit of luminous intensity
      Mole (mol): a unit of substance.

    • This question is part of the following fields:

      • Clinical Measurement
      10.8
      Seconds
  • Question 26 - Which of following statements is true regarding the comparison of fentanyl and alfentanil?...

    Correct

    • Which of following statements is true regarding the comparison of fentanyl and alfentanil?

      Your Answer: Fentanyl is more potent than alfentanil

      Explanation:

      Fentanyl is a pethidine congener, 80–100 times more potent than morphine, both in analgesia and respiratory depression. Fentanyl is ten times more potent than alfentanil.

      Alfentanil has a more rapid onset than fentanyl even if fentanyl is more lipid-soluble because both are basic compounds and alfentanil has lower pKa, so a greater proportion of alfentanil is unionized and is more available to cross membranes.

      Elimination of alfentanil is higher than fentanyl due to its lower volume of distribution.

    • This question is part of the following fields:

      • Pharmacology
      17.8
      Seconds
  • Question 27 - A 55-year-old male is diagnosed with superior vena cava obstruction. What is the...

    Incorrect

    • A 55-year-old male is diagnosed with superior vena cava obstruction. What is the number of collateral circulations that exist for alternate pathways for venous return?

      Your Answer: None

      Correct Answer: Four

      Explanation:

      Superior vena cava is the main vein bringing blood back to the heart. It can get partially or completely blocked by various causes, the most common being due to malignant tumours of the mediastinum.

      There are collateral pathways that form in long-standing cases with 60% or more stenosis and continue venous drainage in cases of superior vena obstruction. The collaterals are classified into four as follows:

      1. The azygos-hemiazygos pathway
      Azygos, hemiazygos, intercostal, and lumbar veins.

      2. The internal and external mammary pathway
      internal mammary, superior epigastric, and inferior epigastric veins and superficial veins of the thorax.

      3. The lateral thoracic pathway
      Lateral thoracic, thoracoepigastric, superficial circumflex, long saphenous, and femoral veins to collateralize to the IVC.

      4. The vertebral pathway
      Innominate, vertebral, intercostal, lumbar, and sacral veins to collateralize to the azygos and internal mammary pathways.

    • This question is part of the following fields:

      • Anatomy
      8.2
      Seconds
  • Question 28 - Regarding the emergency oxygen flush, which is true? ...

    Correct

    • Regarding the emergency oxygen flush, which is true?

      Your Answer: May lead to awareness if used inappropriately

      Explanation:

      When the emergency oxygen flush is pressed, 100% oxygen is supplied from the common gas outlet. This gas bypasses BOTH flowmeters and vaporisers. The flow of oxygen is usually 45 l/min at a PRESSURE OF 400 kPa.

      There is an increased risk of pulmonary barotrauma when the emergency flush is pressed, especially when anaesthetising paediatric patients.

      The inappropriate use of the flush causes dilution of anaesthetic gases and this increases the possibility of anaesthetic awareness .

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      56.3
      Seconds
  • Question 29 - Which of the following statements is false when considering the electrical safety of...

    Incorrect

    • Which of the following statements is false when considering the electrical safety of equipment?

      Your Answer: Type CF equipment is considered to safe for direct connection with the heart

      Correct Answer: The low leakage currents limit is 0.01mA for Class I CF

      Explanation:

      There are different classes of electrical equipment that can be classified in the table below:

      Class 1 – provides basic protection only. It must be connected to earth and insulated from the mains supply

      Class II – provides double insulation for all equipment. It does not require an earth.

      Class III – uses safety extra low voltage (SELV) which does not exceed 24 V AC. There is no risk of gross electrocution but risk of microshock exists.

      Type B – All of above with low leakage currents (0.5mA for Class IB, 0.1 mA for Class IIB)

      Type BF – Same as with other equipment but has ‘floating circuit’ which means that the equipment applied to patient is isolated from all its other parts.

      Type CF – Class I or II equipment with ‘floating circuits’ that is considered to be safe for direct connection with the heart. There are extremely low leakage currents (0.05mA for Class I CF and 0.01mA for Class II CF)

    • This question is part of the following fields:

      • Clinical Measurement
      23.3
      Seconds
  • Question 30 - At sea level, Sevoflurane is administered via a plenum vaporiser. 100 mL of...

    Incorrect

    • At sea level, Sevoflurane is administered via a plenum vaporiser. 100 mL of the fresh gas flow is bypassed into the vaporising chamber. Temperature within the vaporising chamber is maintained at 20°C.

      The following fresh gas flows approximates best for the delivery of 1% sevoflurane.

      Your Answer: 27 L/minute

      Correct Answer: 2.7 L/minute

      Explanation:

      The equation for calculating vaporiser output is:

      Vaporiser output (VO) mL = Carrier gas flow (mL/minute) × SVP of agent (kPa)
      Ambient pressure (kPa) − SVP of agent (kPa)

      The saturated vapour pressure of sevoflurane at 1 atm (100 kPa) and 20°C is 21 kPa.

      VO = (100 mL × 21 kPa)/(100 kPa − 21kPa) for sevoflurane,
      VO = 26.6 mL

      26.6 mL of 100% sevoflurane and 100 mL bypass carrier gas is being added to the fresh gas flow per minute.

      2660 mL of 1% sevoflurane and 100 mL bypass carrier gas is approximately 2.7 L/minute.

    • This question is part of the following fields:

      • Pharmacology
      21.1
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Anatomy (2/4) 50%
Physiology (2/3) 67%
Pharmacology (8/9) 89%
Pathophysiology (2/2) 100%
Statistical Methods (3/4) 75%
Anaesthesia Related Apparatus (2/3) 67%
Basic Physics (0/1) 0%
Clinical Measurement (0/3) 0%
Physiology And Biochemistry (1/1) 100%
Passmed