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  • Question 1 - An study on post-operative nausea and vomiting (PONV) among paediatric patients who underwent...

    Correct

    • An study on post-operative nausea and vomiting (PONV) among paediatric patients who underwent tonsillectomy showed a decrease in incidence from 10% to 5% following a new management protocol.

      Which of the following best estimates the numbers needed to treat (NNT) for one additional patient to benefit from the new management of PONV?

      Your Answer: 20

      Explanation:

      The Number Needed to Treat (NNT) is the number of patients you need to treat to prevent one additional bad outcome. For example, if a drug has an NNT of 5, it means you have to treat 5 people with the drug to prevent one additional bad outcome.

      To calculate the NNT, you need to know the Absolute Risk Reduction (ARR); the NNT is the inverse of the ARR:

      NNT = 1/ARR

      Where ARR = CER (Control Event Rate) – EER (Experimental Event Rate).

      NNTs are always rounded up to the nearest whole number.

      In this case, the NNT can be computed as follows:

      ARR = 10% – 5% = 0.05

      NNT = 1/0.05 = 20

    • This question is part of the following fields:

      • Statistical Methods
      5.8
      Seconds
  • Question 2 - The production of carbon dioxide and water occurs during cellular respiration, which involves...

    Correct

    • The production of carbon dioxide and water occurs during cellular respiration, which involves an energy substrate and oxygen. For a patient, the respiratory quotient is calculated as 0.7.

      Which of the following energy substrate combinations is the most likely in this patient's diet?

      Your Answer: Low carbohydrate, high fat and low protein

      Explanation:

      The respiratory quotient (RQ) is the proportion of CO2 produced by the body to O2 consumed per unit of time.

      CO2 produced / O2 consumed = RQ

      CO2 is produced at a rate of 200 mL per minute, while O2 is consumed at a rate of 250 mL per minute. An RQ of around 0.8 is typical for a mixed diet.

      The RQ will change depending on the energy substrates consumed in the diet.

      Granulated sugar is a refined carbohydrate that contains 99.999 percent carbohydrate and no lipids, proteins, minerals, or vitamins.

      Glucose and other hexose sugars – RQ = 1
      Fats – RQ = 0.7
      Proteins – RQ is 0.9
      Ethyl alcohol – RQ = 0.67

    • This question is part of the following fields:

      • Pathophysiology
      35.6
      Seconds
  • Question 3 - A pulmonary function tests results are:

    Measurement Predicted result Test result
    Forced vital capacity (FVC)...

    Incorrect

    • A pulmonary function tests results are:

      Measurement Predicted result Test result
      Forced vital capacity (FVC) (btps) 3.85 2.36
      Forced expiratory volume in 1 second (FEV1) (btps) 3.34 0.97
      FEV1/FVC ratio % (btps) 85.1 39.9
      Peak expiratory flow (PEF) (L/second) 7.33 2.11
      Maximum voluntary ventilation (MVV) (L/minute) 116 44.4

      What does this indicate?

      Your Answer: Moderate obstructive picture

      Correct Answer: Moderate restrictive and severe obstructive picture

      Explanation:

      Severity of a reduction in restrictive defect (%FVC) or obstructive defect (%FEV1/FVC) predicted are classified as follows:

      Mild 70-80%
      Moderate 60-69%
      Moderately severe 50-59%
      Severe 35-49%
      Very severe <35% This patient has a mixed deficit with a severe obstructive deficit as %FEV1/FVC predicted is 46.9% and a moderate restrictive deficit as %FVC of predicted is 61.3 FEV1/FVC ratio 80% < predicted and VC < 80% = mixed picture. FEV1/FVC ratio 80% < predicted and VC > 80% = obstructive picture.

      FEV1/FVC ratio 80% > predicted and VC > 80% = normal picture.

      FEV1/FVC ratio 80% > predicted and VC < 80% predicted= restrictive picture.

    • This question is part of the following fields:

      • Clinical Measurement
      27.2
      Seconds
  • Question 4 - A weakly acidic drug with a pKa of 8.4 is injected intravenously into...

    Incorrect

    • A weakly acidic drug with a pKa of 8.4 is injected intravenously into a patient.

      At a normal physiological pH, the percentage of this drug unionised in the plasma is?

      Your Answer: 1

      Correct Answer: 90

      Explanation:

      Primary FRCA is concerned with two issues. The first is a working knowledge of the Henderson-Hasselbalch equation, and the second is a working knowledge of logarithms and antilogarithms.

      The pH at which the drug exists in 50 percent ionised and 50 percent unionised forms is known as the pKa.

      To calculate the proportion of ionised to unionised form of a drug, use the Henderson-Hasselbalch equation.

      pH = pKa + log ([A-]/[HA])

      or

      pH = pKa + log [(salt)/(acid)]
      pH = pKa + log ([ionised]/[unionised])

      Hence, if the pKa − pH = 0, then 50% of drug is ionised and 50% is unionised.

      In this example:
      7.4 = 8.4 + log ([ionised]/[unionised])
      7.4 − 8.4 = log ([ionised]/[unionised])
      log −1 = log ([ionised]/[unionised])

      Simply put, the antilog is the inverse log calculation. In other words, if you know the logarithm of a number, you can use the antilog to find the value of the number. The antilogarithm’s definition is as follows:

      y = antilog x = 10x

      Antilog to the base 10 of 0 = 1, −1 = 0.1, −2 = 0.01, −3 = 0.001 and, −4 = 0.0001.

      [A-]/[HA] = 0.1

      Assuming that we can apply the approximation [A-] << [HA} then this means the acid is 0.1 x 100% = 10% ionised so the percentage of (non-ionized) acid will be 100% – 10% = 90%

    • This question is part of the following fields:

      • Pharmacology
      24.5
      Seconds
  • Question 5 - A 59-year-old smoker booked for an emergency laparotomy is in the anaesthetic room...

    Incorrect

    • A 59-year-old smoker booked for an emergency laparotomy is in the anaesthetic room prior to intubation. He is breathing room air and an arterial blood gas is obtained on insertion of an arterial cannula and sent for analysis.

      The following results are available:

      Haemoglobin 75 g/L
      PaO2 10.7 kPa
      PaCO2 5.2 kPa

      After intravenous induction, intubation is difficult and he rapidly begins to de-saturate.

      Which of the following is most effective in prolonging the oxygen de-saturation time?

      Your Answer: Sat up at 45 degrees breathing air

      Correct Answer: Pre-oxygenation with 100% O2 for three minutes

      Explanation:

      Breathing 100% oxygen for three minutes will provide the best reservoir of oxygen during apnoea by oxygenating the functional residual capacity (FRC).

      Sitting at 45 degrees might increase the FRC and improve oxygen reserve but not compared with 100% oxygenation.

      The following table compares the oxygen reserves in the body following pre-oxygenation with room air and 100% oxygen:

      Compartment Factors Room air (mL) 100% O2 (mL)
      Lung FAO2, FRC 630 2850
      Plasma PaO2, DF, PV 7 45
      Red blood cells Hb, TGV, SaO2 788 805
      Myoglobin – 200 200
      Interstitial space – 25 160

      FAO2 = alveolar fraction of oxygen.
      FRC = Functional residual capacity.
      PaO2 = partial pressure of oxygen dissolved in arterial blood
      DF = dissolved form.
      PV = plasma volume.
      TG = total globular volume .
      Hb = haemoglobin concentration.
      SaO2 = arterial oxygen saturation

      Stopping smoking one month prior to surgery will not be more effective than pre-oxygenation with 100% oxygen though it may reduce postoperative pulmonary complications. Note that both long term and short term abstinence reduces pulse rate and blood pressure thus reducing oxygen consumption and also reduce carboxyhaemoglobin levels.

      Blood transfusion will not make a big difference in oxygen reserve, particularly if a blood transfusion is administered within 12-24-hours before surgery.

      Heliox (79% helium and 21% oxygen) despite its lower viscosity is unlikely to be more effective than 100% oxygen .

    • This question is part of the following fields:

      • Pathophysiology
      34.1
      Seconds
  • Question 6 - Out of the following, which is NOT true regarding the external carotid? ...

    Correct

    • Out of the following, which is NOT true regarding the external carotid?

      Your Answer: It ends by bifurcating into the superficial temporal and ascending pharyngeal artery

      Explanation:

      The external carotid artery has eight important branches:
      Anterior surface:
      1. Superior thyroid artery (first branch)
      2. Lingual artery
      3. Facial artery
      Medial branch
      4. Ascending pharyngeal artery
      Posterior branches
      5. Occipital artery
      6. Posterior auricular artery
      Terminal branches
      7. Maxillary artery
      8. Superficial temporal artery

      The external carotid has eight branches, 3 from its anterior surface ; thyroid, lingual and facial. The pharyngeal artery is a medial branch. The posterior auricular and occipital are posterior branches.

    • This question is part of the following fields:

      • Anatomy
      25.4
      Seconds
  • Question 7 - An 80-year-old man will be operated on for an arterial bypass procedure to...

    Incorrect

    • An 80-year-old man will be operated on for an arterial bypass procedure to treat claudication and foot ulceration. The anterior tibial artery will be the target for distal arterial anastomosis.

      Which structure is NOT closely related to the anterior tibial artery?

      Your Answer: Dorsalis pedis artery

      Correct Answer: Tibialis posterior

      Explanation:

      The anterior tibial artery originates from the distal border of the popliteus. In the posterior compartment, it passes between the heads of the tibialis posterior and the oval aperture of the interosseous membrane to reach the anterior compartment.

      On entry into the anterior compartment, it runs medially along the deep peroneal nerve.
      The upper third of the artery courses between the tibialis anterior and extensor digitorum longus muscles, while the middle third runs between the tibialis anterior and extensor hallucis longus muscles.

      At the ankle, the anterior tibial artery is located approximately midway between the malleoli. It continues on the dorsum of the foot, lateral to extensor hallucis longus, as the dorsalis pedis artery.

    • This question is part of the following fields:

      • Anatomy
      21.2
      Seconds
  • Question 8 - Health workers are at increased risks of anaesthetic exposure. Therefore, The Control of...

    Incorrect

    • Health workers are at increased risks of anaesthetic exposure. Therefore, The Control of Substances Hazardous to Health (COSHH) regulations require measures implemented to assess and control the risks related to this exposure.

      Among the following control measures, which one is most likely to limit potentially harmful exposure to anaesthetic agents within an operating theatre?

      Your Answer: Maintenance of 15-20 air changes per hour

      Correct Answer: Total intravenous anaesthesia (TIVA)

      Explanation:

      Exposure to anaesthetic hazards is one among the occupational exposures in manipulating toxic agents or inhaling toxic gases during anaesthetic practices.

      Toxic gases mainly nitrous oxide, is one of the most gaseous anaesthetic agents that constitutes an important source of pollution. One of the safe and effective technics used in anaesthesia and reducing the amount of pollution is the Total Intravenous Anaesthesia (TIVA) which consists of using opioids in analgesia and propofol for the induction and the maintenance of anaesthesia. It refers to the administration intravenously of an anaesthetic, sedative, and/or tranquilizer. A less polluting but not the best way to get rid of the toxic aesthetic agents is the scavenger system that collects and expels the gas outside the medical environment. Yet, this technique still represents a hazard for the environment and still increase the risk of exposure for the health workers and clinical staff.

      Fume cupboards are also not recommended to use because of their high pollution potency, mainly of the air resulting in a great harm for medical workers.

      Supraglottic airways as well as the Air Changes per Hour technics could be harmful for both patients and health workers, increasing the risks of transmitted diseases, namely nosocomial infections.

      Therefore, the Total Intravenous Anaesthesia technique (TIVA) is most likely to be safe and recommended to use.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      33.7
      Seconds
  • Question 9 - The following is true about the extracellular fluid (ECF) in a normal adult...

    Incorrect

    • The following is true about the extracellular fluid (ECF) in a normal adult woman weighing 60 kg.

      Your Answer: Has a sodium concentration of 125-135 mmol/L

      Correct Answer: Has a total volume of about 12 litres

      Explanation:

      Total body water (TBW) is about 50% to 70% in adults depending on how much fat is present. ECF is relatively contracted in an obese person.

      The simple rule is 60-40-20. (60% of weight = total body water, 40% of body weight is ICF and 20% is ECF)

      For this woman, the total body water is 36 litres (0.6 × 60). ECF is 12 litres (1/3 of TBW) and 24 litres (2/3 of TBW) is intracellular fluid .

      Sodium concentration is approximately 135-145 mmol/L in the ECF.

      The ECF is made up of both intravascular and extravascular fluid and plasma proteins is found in both.

    • This question is part of the following fields:

      • Physiology
      62.6
      Seconds
  • Question 10 - A 41-year-old man, with symptomatic tracheal compression is scheduled for a thyroidectomy. He...

    Incorrect

    • A 41-year-old man, with symptomatic tracheal compression is scheduled for a thyroidectomy. He has previous personal history of hyperthyroidism, controlled by a carbimazole prescription.
      He has previously presented to the emergency department with dyspnoea and stridor, for which the surgery is indicated. Prior to his thyroidectomy, excessive bleeding is controlled for by ligation of the superior thyroid artery.
      The superior thyroid artery branches into the superior laryngeal artery which is closely related to a structure which upon injury will cause loss of sensation in the laryngeal mucosa.

      What is the name of this structure?

      Your Answer: Inferior laryngeal artery

      Correct Answer: Internal laryngeal nerve

      Explanation:

      The internal laryngeal nerve provides sensory innervation to the laryngeal mucosa, and injury to it will cause loss of sensation.

      The internal laryngeal nerve lies inferior to the piriform recess mucous membrane, placing it at high risk of irritation or damage by objects which become lodged in the recess.

      The internal laryngeal artery branches off the superior laryngeal artery accompanied by the superior laryngeal nerve, inferior to the thyroid artery which branches off the superior thyroid artery close to its bifurcation from the external carotid artery.

    • This question is part of the following fields:

      • Anatomy
      33.2
      Seconds
  • Question 11 - Drug A has a 1 L/kg volume of distribution and a 0.1 elimination...

    Incorrect

    • Drug A has a 1 L/kg volume of distribution and a 0.1 elimination rate constant (k).

      Drug B has a 2 L/kg volume of distribution and a 0.2 elimination rate constant (k).

      Which of the following statements best describes the pharmacokinetics of drug A in a single compartment?

      Your Answer: Drug A has the same half life than drug B

      Correct Answer: Drug A has a lower clearance than drug B

      Explanation:

      The fall in plasma concentration of a drug with time decreases exponentially in a single compartment pharmacokinetic model (wash-out curve).

      A straight line is produced when the logarithm (ln) of a drug’s plasma concentration is plotted against time because a constant proportion of the drug is removed from the plasma per unit time. The line’s gradient or slope can be expressed mathematically as k. (the rate constant). The gradient is related to the half life (T1/2) because it can be used to predict a drug’s plasma concentration at any time.

      According to the following formula, clearance (CL), volume of distribution (Vd), and elimination rate constant (k) are mathematically related.

      CL = Vd x k

      For drug A, CL = 1 x 0.1 = 0.1units per minute

      For drug B, Cl = 2 x 0.2 = 0.4 units per minute

      Hence, it is proved that Drug A has a lower clearance than drug B.

    • This question is part of the following fields:

      • Pharmacology
      14.9
      Seconds
  • Question 12 - All the following statements are false regarding nitrous oxide except: ...

    Correct

    • All the following statements are false regarding nitrous oxide except:

      Your Answer: Maintains carbon dioxide reactivity

      Explanation:

      Nitrous oxide increases cerebral blood flow by direct cerebral stimulation and tends to elevate intracranial pressure (ICP)

      It increases the cerebral metabolic rate of oxygen consumption (CMRO2)

      It is not an NMDA agonist as it antagonizes NMDA receptors.

      Cerebral autoregulation is impaired with the use of nitrous oxide but when used with propofol, it is maintained.

      Carbon dioxide reactivity is not affected by it.

    • This question is part of the following fields:

      • Pharmacology
      7.2
      Seconds
  • Question 13 - Of the following, which of these oxygen carrying molecules causes the greatest shift...

    Incorrect

    • Of the following, which of these oxygen carrying molecules causes the greatest shift of the oxygen-dissociation curve to the left?

      Your Answer: Haemoglobin (HbSS)

      Correct Answer: Myoglobin (Mb)

      Explanation:

      Myoglobin is a haemoglobin-like, iron-containing pigment that is found in muscle fibres. It has a high affinity for oxygen and it consists of a single alpha polypeptide chain. It binds only one oxygen molecule, unlike haemoglobin, which binds 4 oxygen molecules.

      The myoglobin ODC is a rectangular hyperbola. There is a very low P50 0.37 kPa (2.75 mmHg). This means that it needs a lower P50 to facilitate oxygen offloading from haemoglobin. It is low enough to be able to offload oxygen onto myoglobin where it is stored. Myoglobin releases its oxygen at the very low PO2 values found inside the mitochondria.

      P50 is defined as the affinity of haemoglobin for oxygen: It is the PO2 at which the haemoglobin becomes 50% saturated with oxygen. Normally, the P50 of adult haemoglobin is 3.47 kPa(26 mmHg).

      Foetal haemoglobin has 2 ? and 2 ?chains. The ODC is left shifted – this means that P50 lies between 2.34-2.67 kPa [18-20 mmHg]) compared with the adult curve and it has a higher affinity for oxygen. Foetal haemoglobin has no ? chains so this means that there is less binding of 2.3 diphosphoglycerate (2,3 DPG).

      Carbon monoxide binds to haemoglobin with an affinity more than 200-fold higher than that of oxygen. This therefore decreases the amount of haemoglobin that is available for oxygen transport. Carbon monoxide binding also increases the affinity of haemoglobin for oxygen, which shifts the oxygen-haemoglobin dissociation curve to the left and thus impedes oxygen unloading in the tissues.

      In sickle cell disease, (HbSS) has a P50 of 4.53 kPa(34 mmHg).

    • This question is part of the following fields:

      • Physiology
      13
      Seconds
  • Question 14 - Which of the following is true in the Kreb's cycle? ...

    Correct

    • Which of the following is true in the Kreb's cycle?

      Your Answer: Alpha-ketoglutarate is a five carbon molecule

      Explanation:

      Krebs’ cycle (tricarboxylic acid cycle or citric acid cycle) is a sequence of reactions to release stored energy through oxidation of acetyl coenzyme A (acetyl-CoA). Some of the products are carbon dioxide and hydrogen atoms.

      The sequence of reactions, known collectively as oxidative phosphorylation, only occurs in the mitochondria (not cytoplasm).

      The Krebs cycle can only take place when oxygen is present, though it does not require oxygen directly, because it relies on the by-products from the electron transport chain, which requires oxygen. It is therefore considered an aerobic process. It is the common pathway for the oxidation of carbohydrate, fat and some amino acids, required for the formation of adenosine triphosphate (ATP).

      Pyruvate enters the mitochondria and is converted into acetyl-CoA. Acetyl-CoA is then condensed with oxaloacetate, to form citrate which is a six carbon molecule. Citrate is subsequently converted into isocitrate, alpha-ketoglutarate, succinyl-CoA, succinate, fumarate, malate and finally oxaloacetate.

      The only five carbon molecule in the cycle is Alpha-ketoglutarate.

    • This question is part of the following fields:

      • Physiology
      20.8
      Seconds
  • Question 15 - The phenomenon that the patients behaved in a different manner when they know...

    Incorrect

    • The phenomenon that the patients behaved in a different manner when they know that they are being observed is termed as?

      Your Answer: Ainsley's viewing fallacy

      Correct Answer: Hawthorne effect

      Explanation:

      Hawthorne effect explains the change in any behavioural aspect owing to the awareness that the person is being observed.
      Simpson’s Paradox explains the association developed when the data from several groups is combined to form a single larger group.

      The remaining terms are made up.

    • This question is part of the following fields:

      • Statistical Methods
      28.8
      Seconds
  • Question 16 - Which of the following drugs is safe to be used in porphyria? ...

    Incorrect

    • Which of the following drugs is safe to be used in porphyria?

      Your Answer: Phenytoin

      Correct Answer:

      Explanation:

      Porphyria is a group of disorders in which there is excess production and excess excretion of porphyrins and their precursors. They are usually genetic and are caused due to defects in the haem metabolic pathway. However, other factors like infection, pregnancy, mensuration, starvation may precipitate the attack.

      Sulphonamides, barbiturates (methohexitone and thiopental), and phenytoin are considered to be precipitants so are not safe to use
      Chloral hydrate is thought to be safe to use.
      Etomidate lacks proper studies and may be used with caution but it is generally advised not to use this drug especially if other alternatives are available.

    • This question is part of the following fields:

      • Pharmacology
      6
      Seconds
  • Question 17 - During the analysis phase, which of the provided options serves to control confounding...

    Incorrect

    • During the analysis phase, which of the provided options serves to control confounding factors?

      Your Answer: Blinding

      Correct Answer: Stratification

      Explanation:

      During analytical stage a technique called stratification is used for controlling confounding variables. This technique involves sorting out the data into discernible groups.

    • This question is part of the following fields:

      • Statistical Methods
      28.6
      Seconds
  • Question 18 - The most sensitive indicator of mild obstructive airway disease is? ...

    Incorrect

    • The most sensitive indicator of mild obstructive airway disease is?

      Your Answer: FEV1/FVC ratio

      Correct Answer: Forced expiratory flow (FEF25-75%)

      Explanation:

      The volume expired in the first second of maximal expiration after a maximal inspiration is known as forced expiratory volume in one second (FEV1), and it indicates how quickly full lungs can be emptied. It is the most commonly measured parameter for bronchoconstriction assessment.

      The maximum volume of air exhaled after a maximal inspiration is known as the ‘slow’ vital capacity (VC). VC is normally equal to FVC after a forced vital capacity (FVC) or slow vital capacity (VC) manoeuvre, unless there is an airflow obstruction, in which case VC is usually higher than FVC.

      The FEV1/FVC (Tiffeneau index) is a clinically useful index of airflow restriction that can be used to distinguish between restrictive and obstructive respiratory disorders.

      The average expired flow over the middle half (25-75 percent) of the FVC manoeuvre is the forced expiratory volume (FEF25-75). The airflow from the resistance bronchioles corresponds to this. It’s a more sensitive indicator of mild small airway narrowing than FEV1, but it’s difficult to tell if the VC (or FVC) is decreasing or increasing.

      The maximum expiratory flow rate achieved is called the peak expiratory flow (PEF), which is usually 8-14 L/second.

    • This question is part of the following fields:

      • Pathophysiology
      82.1
      Seconds
  • Question 19 - Which of the following statements is true regarding ketamine? ...

    Incorrect

    • Which of the following statements is true regarding ketamine?

      Your Answer: Has an R (-) enantiomer which is less psychoactive

      Correct Answer: Can be used in the management of refractory status epilepticus

      Explanation:

      Ketamine is a phencyclidine (hallucinogenic) derivative that is administered in a dose of 2 mg/kg and acts by blocking NMDA (N-methyl-D-aspartate) receptors of glutamate.

      It is a powerful bronchodilator agent and is, therefore, an intravenous anaesthetic of choice in bronchial asthma (halothane is an inhalational anaesthetic agent of choice for bronchial asthma). It is also used in the management of refractory status epilepticus.

      It is an acid solution with an elimination half-life of three hours.

      It has S (+) enantiomer and R (-) enantiomer. the S(+) enantiomer is two to four times more potent than the R(-) and is less likely to produce hallucinations.

      Its use is contraindicated in patients with ischaemic heart disease because it increased sympathetic outflow leading to tachycardia and increased cardiac output which in turn increases the myocardial oxygen demand.

    • This question is part of the following fields:

      • Pharmacology
      660.3
      Seconds
  • Question 20 - According to the statements given which one is most correct concerning the spinal...

    Incorrect

    • According to the statements given which one is most correct concerning the spinal cord?

      Your Answer: The spinal cord ends at the level of L3 in the adult

      Correct Answer: There are 31 pairs of spinal roots

      Explanation:

      The cylindrical structure(spine), starts from the foramen magnum in medulla oblongata at the skull’s base. Its length varies in gender with men having 45cm and women having up to 43 cm. The spine contains 31 pairs of spinal nerves, named according to the spinal region:
      – 8 cervical nerve pairs ( C1-C8)
      – 12 thoracic nerve pairs ( T1-T12)
      – 5 lumbar nerve pairs (L1-L5)
      – 5 sacral nerves (S1-S5) and
      – 1 coccygeal nerve pair.
      These spinal nerves are classified as the peripheral nervous system though they branch from the spinal cord and central nervous system. They interact directly with the spinal cord to modulate the motor and sensory information from the peripheral’s region. As the nerves emerges form the spinal cords they are known as rootlets. They join to form nerve roots, and depending on their position, we have anterior nerve roots and posterior.

      The spinal cord is supplied by two posterior and one anterior spinal arteries which anastomoses caudally, at the conus medullaris.

      The anterior spinal artery supplies the anterior two-thirds of the spinal cord and medulla. Disruption of the anterior spinal artery supply is characterised by ischaemia or infarction of motor tracts (corticospinal) and loss of pain and temperature sensation below the level of the lesion.

      The posterior spinal arteries supply the posterior columns (posterior third of the spinal cord). Infarction of the posterior columns results in the loss of proprioceptive, vibration and two-point discrimination.

      The spinal cord normally ends at the level of L1 or L2 in an adult and L3 in a newborn.

    • This question is part of the following fields:

      • Anatomy
      21.4
      Seconds
  • Question 21 - A 60 year old non insulin dependent diabetic on metformin undergoes hip arthroscopy...

    Incorrect

    • A 60 year old non insulin dependent diabetic on metformin undergoes hip arthroscopy under general anaesthesia.

      Her preoperative blood glucose is 6.5mmol/L. Anaesthesia is induced with 200 mg propofol and 100 mcg fentanyl and maintained with sevoflurane and air/oxygen mixture. she is given 8 mg dexamethasone, 40 mg parecoxib, 1 g paracetamol and 500 mL Hartmann's solution Intraoperatively.

      The procedure took thirty minutes and her blood glucose in recovery is 14 mmol/L.

      What is the most likely cause for her rise in blood sugar?

      Your Answer: Irrigation fluid

      Correct Answer: Stress response

      Explanation:

      A significant early feature of the metabolic response to trauma and surgery is hyperglycaemia. It is due to an increased glucose production and decreased glucose utilisation bought on by neuroendocrine stimulation. Catecholamines, Growth hormone, ACTH and cortisol, and Glucagon are all increased.

      There is also a decreased insulin sensitivity peripherally and an inhibition of insulin production from the beta cells of the pancreas. These changes lead to hyperglycaemia.

      The stress response to endoscopic surgery will only be prevented with use of high dose opioids or central neuraxial block at anaesthesia.
      To reduce the risk of inducing hyperchloremic acidosis, Ringer’s lactate/acetate or Hartmann’s solution is preferred to 0.9% sodium chloride as routine maintenance fluids.

      Though it has been suggested that administration of Hartmann’s solution to patients with type 2 diabetes leads to hyperglycaemia, one Litre of Hartmann’s solution would yield a maximum of 14.5 mmol of glucose. A rapid infusion of this volume would increase the plasma glucose by no more than 1 mmol/L..

      Dexamethasone, a glucocorticoid, produces hyperglycaemia by stimulating gluconeogenesis . Glucocorticoids are agonists of intracellular glucocorticoid receptors. Their effects are mainly mediated via altered protein synthesis via gene transcription and so the onset of action is slow. The onset of action of dexamethasone is about one to four hours and therefore would NOT contribute to the hyperglycaemia in this patient in the time given.

      0.9% Normal saline with or without adrenaline is the usual irrigation fluid. With this type of surgery, systemic absorption is unlikely to occur.

      Fentanyl is not likely the primary cause of hyperglycaemia in this patient. In high doses (50 mcg/Kg) it has been shown to reduce the hyperglycaemic responses to surgery.

    • This question is part of the following fields:

      • Pathophysiology
      9
      Seconds
  • Question 22 - Regarding the emergency oxygen flush, which is true? ...

    Incorrect

    • Regarding the emergency oxygen flush, which is true?

      Your Answer: Delivers a flow of oxygen at 45 litres per minute at a pressure of 700 kPa

      Correct Answer: May lead to awareness if used inappropriately

      Explanation:

      When the emergency oxygen flush is pressed, 100% oxygen is supplied from the common gas outlet. This gas bypasses BOTH flowmeters and vaporisers. The flow of oxygen is usually 45 l/min at a PRESSURE OF 400 kPa.

      There is an increased risk of pulmonary barotrauma when the emergency flush is pressed, especially when anaesthetising paediatric patients.

      The inappropriate use of the flush causes dilution of anaesthetic gases and this increases the possibility of anaesthetic awareness .

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      26.8
      Seconds
  • Question 23 - A 39-year old man came to the Out-Patient department for symptoms of gastroesophageal...

    Incorrect

    • A 39-year old man came to the Out-Patient department for symptoms of gastroesophageal reflux disease. Medical history revealed he is on anti-epileptic medication Phenytoin. His plasma phenytoin levels are maintained between 10-12 mcg/mL (Therapeutic range: 10-20 mcg/mL). He is given a H2 antagonist receptor agent (Cimetidine) for his GERD symptoms.

      Upon follow-up, his plasma phenytoin levels increased to 38 mcg/mL.

      Regarding metabolism and elimination, which of the following best explains the pharmacokinetics of phenytoin at higher plasma levels?

      Your Answer: Change in plasma concentration is not linear

      Correct Answer: Plasma concentration plotted against time is linear

      Explanation:

      Drug elimination is the termination of drug action, and may involve metabolism into inactive state and excretion out of the body. Duration of drug action is determined by the dose administered and the rate of elimination following the last dose.

      There are two types of elimination: first-order and zero-order elimination.

      In first-order elimination, the rate of elimination is proportionate to the concentration; the concentration decreases exponentially over time. It observes the characteristic half-life elimination, where the concentration decreases by 50% for every half-life.

      In zero-order elimination, the rate of elimination is constant regardless of concentration; the concentration decreases linearly over time. A constant amount of the drug being excreted over time, and it occurs when drugs have saturated their elimination mechanisms.

      Since phenytoin is observed in elevated levels, the elimination mechanisms for it has been saturated and, thus, will have to undergo zero-order elimination.

    • This question is part of the following fields:

      • Pharmacology
      26.8
      Seconds
  • Question 24 - Regarding aldosterone, one of the following is true. ...

    Incorrect

    • Regarding aldosterone, one of the following is true.

      Your Answer: Secretion is increased in phaeochromocytoma

      Correct Answer: Secretion is increased following haematemesis

      Explanation:

      Aldosterone is produced in the zona glomerulosa of the adrenal cortex and acts to increase sodium reabsorption via intracellular mineralocorticoid receptors in the distal tubules and collecting ducts of the nephron.

      Its release is stimulated by hypovolaemia, blood loss ,and low plasma sodium and is inhibited by hypertension and increased sodium. It is regulated by the renin-angiotensin system.

    • This question is part of the following fields:

      • Pathophysiology
      15
      Seconds
  • Question 25 - Which of the following statement is true regarding the paediatric airway? ...

    Incorrect

    • Which of the following statement is true regarding the paediatric airway?

      Your Answer: Neonates are not obligate nose breathers

      Correct Answer: The larynx is more anterior than in an adult

      Explanation:

      In the neonatal stage, the tongue is usually large and comes to the normal size at the age of 1 year. The vocal cords lie inverse C4 and as it reaches the grown-up position inverse C5/6 by the age of 4 (not 1 year).

      Due to the immature cricoid cartilage, the larynx lies more anterior in newborn children. That’s why the cricoid ring is the narrowest part of the paediatric respiratory tract, while in the adults the tightest portion of the respiratory route is vocal cords. The epiglottis is generally expansive and slants at a point of 45 degrees to the laryngeal opening.

      The carina is the ridge of the cartilage in the trachea at the level of T2 in newborn (T4 in adults), that separates the openings of right and left main bronchi.

      Neonates have a comparatively low number of alveoli and then this number gradually increases to a most extreme by the age of 8 (not 3 years).

      Neonates are obligatory nose breathers and any hindrance can cause respiratory issues (e.g., choanal atresia).

    • This question is part of the following fields:

      • Physiology
      37.5
      Seconds
  • Question 26 - The following are pairs of neurotransmitters with their corresponding synthesising enzymes.

    Which pair...

    Correct

    • The following are pairs of neurotransmitters with their corresponding synthesising enzymes.

      Which pair is correct?

      Your Answer: Glutamic acid decarboxylase and gamma-aminobutyric acid (GABA)

      Explanation:

      Glutamic acid decarboxylase is responsible for the catalyses of glutamate to gamma-aminobutyric acid (GABA)

      Catechol-o-methyl transferase catalyses the degradation and inactivation of dopamine into 3-methoxytyramine, epinephrine into metanephrine, and norepinephrine into normetanephrine and vanylmethylmandelic acid (VMA).

      Monoamine oxidase catalyses the oxidation of norepinephrine to vanylmethylmandelic acid (VMA) and serotonin to 5-hydeoxyindole acetic acid (5-HIAA).

      Cholinesterase functions to catalyse the split of acetylcholine into choline and acetic acid.

    • This question is part of the following fields:

      • Pathophysiology
      6.8
      Seconds
  • Question 27 - In asthmatic patients, non-steroidal anti-inflammatory analgesics (NSAIDs) are generally contraindicated.

    Which of the following...

    Incorrect

    • In asthmatic patients, non-steroidal anti-inflammatory analgesics (NSAIDs) are generally contraindicated.

      Which of the following membrane phospholipid metabolism products is most likely to cause NSAID-induced bronchospasm in asthmatic patients who are predisposed to it?

      Your Answer:

      Correct Answer: Leukotrienes

      Explanation:

      Nonsteroidal anti-inflammatory drugs (NSAIDs) cause bronchospasm, rhinorrhoea, and nasal obstruction in some asthma patients.

      The inhibition of cyclooxygenase-1 (Cox-1) appears to be the cause of NSAID-induced reactions. This activates the lipoxygenase pathway, which increases the release of cysteinyl leukotrienes (Cys-LTs), which causes bronchospasm and nasal obstruction.

      The following changes in arachidonic acid (AA) metabolism have been observed in NSAID-intolerant asthmatic patients:

      Prostaglandin E2 production is low, possibly due to a lack of Cox-2 regulation.
      An increase in leukotriene-C4 synthase expression and
      A decrease in the production of metabolites (lipoxins) released by AA’s transcellular metabolism.

      Phospholipase A produces membrane phospholipids, which are converted to arachidonic acid.

      TXA2 causes vasoconstriction as well as platelet aggregation and adhesion.

      PGI2 causes vasodilation and a reduction in platelet adhesion.

      PGE2 is involved in parturition initiation and maintenance, as well as thermoregulation.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 28 - A 70-year-old female presented with a productive cough and is prescribed a bacteriostatic...

    Incorrect

    • A 70-year-old female presented with a productive cough and is prescribed a bacteriostatic antibiotic?
      Which of the following best explains the mechanism of action of bacteriostatic drugs?

      Your Answer:

      Correct Answer: Protein synthesis inhibition

      Explanation:

      Cell membrane pore formation, Bacterial DNA damage, Peptidoglycan cross-linking inhibition, and peptidoglycan synthesis inhibitor are always lethal and such mechanisms are possible only in bactericidal drugs. But Protein synthesis inhibition would only prevent cell replication or cell growth and is responsible for bacteriostatic effects of the drug.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 29 - Regarding the use of soda lime as part of a modern circle system...

    Incorrect

    • Regarding the use of soda lime as part of a modern circle system with a vaporiser outside the circuit (VOC), which of the following is its most deleterious consequence?

      Your Answer:

      Correct Answer: Carbon monoxide formation

      Explanation:

      When using dry soda lime for VOCs, very high amounts of carbon monoxide may be produced, regardless of the inhalational anaesthetic agent used. The carbon monoxide produced is sufficient enough to cause cytotoxic and anaemic hypoxia. To prevent this, soda lime canisters are shaken well to even out the packing of granules. This can help to evenly distribute gas flow for proper CO2 absorption and ventilation.

      Compound A is formed when dry soda lime, or soda lime in high temperature, reacts with the inhalational anaesthetic Sevoflurane. Animal studies have shown renal toxicity in rats, but renal adverse effects in humans are yet to be observed.

      When monitors are not employed with VOCs, deleterious effects are not for certain. However, monitors not employed with vaporiser inside the circuit (VIC) can lead to significant adverse events.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 30 - Which structure does NOT lie in the posterior triangle of the neck? ...

    Incorrect

    • Which structure does NOT lie in the posterior triangle of the neck?

      Your Answer:

      Correct Answer: Internal jugular vein

      Explanation:

      The sternocleidomastoid muscle divides the neck into anterior and posterior triangles on both sides of the neck.

      The posterior triangle has the following boundaries:
      anteriorly – sternocleidomastoid muscle
      posteriorly – trapezius
      roof – investing layer of deep cervical fascia
      floor – prevertebral fascia overlying splenius capitis, levator scapulae, and the scalene muscles

      The contents of the posterior triangle are:
      1. fat
      2. lymph nodes (level V)
      3. accessory nerve
      4. cutaneous branches of the cervical plexus (A major branch of this plexus is the phrenic nerve, which arises from the anterior divisions of spinal nerves C3-C5)
      5. inferior belly of omohyoid
      6. branches of the thyrocervical trunk (transverse cervical and suprascapular arteries)
      7. third part of the subclavian artery
      8. external jugular vein

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Statistical Methods (2/3) 67%
Pathophysiology (5/6) 83%
Clinical Measurement (0/1) 0%
Pharmacology (2/6) 33%
Anatomy (2/5) 40%
Anaesthesia Related Apparatus (1/2) 50%
Physiology (1/3) 33%
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