00
Correct
00
Incorrect
00 : 00 : 00
Session Time
00 : 00
Average Question Time ( Mins)
  • Question 1 - A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure,...

    Correct

    • A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure, the ileocolic artery is ligated. Which vessel does this artery originate from?

      Your Answer: Superior mesenteric artery

      Explanation:

      The ileocolic artery is the terminal branch of the superior mesenteric artery. It supplies:
      1. terminal ileum
      2. proximal right colon
      3. cecum
      4. appendix (via its branch of the appendicular artery)

      As veins accompany arteries in the mesentery and are lined by lymphatics, high ligation is the norm in cancer resections—the ileocolic artery branches off the SMA near the duodenum.

    • This question is part of the following fields:

      • Anatomy
      23.1
      Seconds
  • Question 2 - Which of the following statement is true about Loop diuretics? ...

    Incorrect

    • Which of the following statement is true about Loop diuretics?

      Your Answer: May lead to hyperkalaemia

      Correct Answer: Are useful in the treatment of acute heart failure

      Explanation:

      Loop diuretics act by causing inhibition of Na+ K+ 2Cl– symporter present at the luminal membrane of the ascending limb of the loop of Henle.

      Furosemide, torsemide, bumetanide, ethacrynic acid, furosemide, piretanide, tripamide, and mersalyl are the important members of this group

      The main use of loop diuretics is to remove the oedema fluid in renal, hepatic, or cardiac diseases. Thus they are useful in the treatment of acute heart failure. These can be administered i.v. for prompt relief of acute pulmonary oedema (due to vasodilatory action).

      Hypokalaemia, hypomagnesemia, hyponatremia, alkalosis, hyperglycaemia, hyperuricemia, and dyslipidaemia are seen with both thiazides as well as loop diuretics

    • This question is part of the following fields:

      • Pharmacology
      14.5
      Seconds
  • Question 3 - The following statements are about the conjugation of bilirubin. Which is true? ...

    Incorrect

    • The following statements are about the conjugation of bilirubin. Which is true?

      Your Answer: Is impaired in Dubin-Johnson syndrome

      Correct Answer: Is catalysed by a glucuronyl transferase

      Explanation:

      Bilirubin is formed by metabolizing heme, mostly from haemoglobin in red blood cells.

      Bilirubin is conjugated to glucuronic acid in the hepatocytes by the glucuronyl transferase enzyme in order to enable it to become soluble and allow for its secretion across the canalicular membrane and into bile.

      The conjugation process is increased by rifampicin and decreased by valproate.

      Gilbert’s syndrome is caused by a decrease in glucuronyl transferase in the hepatic system, decreasing the transport of bilirubin into the hepatocyte, causing unconjugated bilirubinaemia.

      Crigler-Najjer syndrome is caused by mutations in the genes responsible for hepatic glucuronyl transferase, decreasing the activity of the enzyme, meaning bilirubin cannot be conjugated, causing unconjugated bilirubinaemia.

      Dubin-Johnson syndrome does not cause an impairment in the conjugation of bilirubin, but it blocks the transport of bilirubin out of the hepatocyte resulting in conjugated bilirubinaemia.

    • This question is part of the following fields:

      • Pathophysiology
      36.2
      Seconds
  • Question 4 - Which statement best describes the bispectral index (BIS)? ...

    Incorrect

    • Which statement best describes the bispectral index (BIS)?

      Your Answer: It predicts the response to surgical incision

      Correct Answer: It decreases during normal sleep

      Explanation:

      The bispectral index (BIS) is one of several systems used in anaesthesiology as of 2003 to measure the effects of specific anaesthetic drugs on the brain and to track changes in the patient’s level of sedation or hypnosis. It is a complex mathematical algorithm that allows a computer inside an anaesthesia monitor to analyse data from a patient’s electroencephalogram (EEG) during surgery. It is a dimensionless number (0-100) that is a summative measurement of time domain, frequency domain and high order spectral parameters derived from electroencephalogram (EEG) signals.

      Sleep and anaesthesia have similar behavioural characteristics but are physiologically different but BIS monitors can be used to measure sleep depth. With increasing sleep depth during slow-wave sleep, BIS levels decrease. This correlates with changes in regional cerebral blood flow when measured using positron emission tomography (PET).

      BIS shows a dose-response relationship with the intravenous and volatile anaesthetic agents. Opioids produce a clinical change in the depth of sedation or analgesia but fail to produce significant changes in the BIS. Ketamine increases CMRO2 and EEG activity.

      BIS is unable to predict movement in response to a surgical stimulus. Some of these are spinal reflexes and not perceived by the cerebral cortex.

      BIS is used during cardiopulmonary bypass to measure depth of anaesthesia and an index of cerebral perfusion. However, it cannot predict subtle or significant cerebral damage.

    • This question is part of the following fields:

      • Physiology
      17.4
      Seconds
  • Question 5 - A 49-year-old woman is admitted to hospital. She is scheduled for surgery and...

    Incorrect

    • A 49-year-old woman is admitted to hospital. She is scheduled for surgery and is undergoing preoperative assessment.

      As part of the preoperative assessment, her functional capacity is estimated. At 50kg in weight, she is able to cycle along a flat surface at a speed of 10-14 miles/hour (8 metabolic equivalents or METs).

      Provide the best estimated value of oxygen consumption (VO2) for eight METs.

      Your Answer: 1050 mL/minute

      Correct Answer: 1400 mL/minute

      Explanation:

      Oxygen consumption (VO2) refers to the optimal amount of oxygen used by the body during exercise.

      It is calculated mathematically by:

      VO2 = 3.5 x 50 x 8 = 1400 mL/kg/minute

      where,

      1 MET = 3.5 mL O2/kg/minute is utilized by the body.

      Note:

      1 MET Eating
      Dressing
      Use toilet
      Walking slowly on level ground at 2-3 mph
      2 METs Playing a musical instrument
      Walking indoors around house
      Light housework
      4 METs Climbing a flight of stairs
      Walking up hill
      Running a short distance
      Heavy housework, scrubbing floors, moving heavy furniture
      Walking on level ground at 4 mph
      Recreational activity, e.g. golf, bowling, dancing, tennis
      6 METs Leisurely swimming
      Leisurely cycling along the flat (8-10 mph)
      8 METs Cycling along the flat (10-14 mph)
      Basketball game
      10 METs Moderate to hard swimming
      Competitive football
      Fast cycling (14-16 mph)

    • This question is part of the following fields:

      • Clinical Measurement
      85.5
      Seconds
  • Question 6 - The pharmacologically inactive precursor of barbiturates is Barbituric acid. Because the molecule is...

    Incorrect

    • The pharmacologically inactive precursor of barbiturates is Barbituric acid. Because the molecule is heterocyclic, small structural changes can alter its pharmacological activity (structure function relationship).

      Which of the following modifications to the molecule has the greatest impact on the effectiveness of the barbiturate derivative?

      Your Answer: Short aryl and alkyl groups at C5

      Correct Answer: Sulphur at C2

      Explanation:

      Barbituric acid is the barbiturates’ pharmacologically inactive precursor. A pyrimidine heterocyclic nucleus is formed by the condensation of urea and malonic acid. Its pharmacological activity can be influenced by minor structural changes (structure function relationship).

      The duration of action and potency as a sedative are influenced by the length of the side chains at C5. Barbiturates with three carbon atoms in their chain last longer than those with two. Anticonvulsant properties are enhanced by branched chains.

      The addition of a methyl group at N1 causes a faster onset/offset of action, but it also causes excitatory phenomena (twitching/lower convulsive threshold).

      The addition of oxygen and sulphur to C2 increases the molecule’s lipid solubility and thus its potency. Thiopentone (thiobarbiturate) has sulphur groups at C2, making it 20-200 times more lipid soluble than oxybarbiturates.

    • This question is part of the following fields:

      • Pharmacology
      52.3
      Seconds
  • Question 7 - The following are results of some pulmonary function tests:

    Measurement - Predicted result -...

    Correct

    • The following are results of some pulmonary function tests:

      Measurement - Predicted result - Test result
      Forced vital capacity (FVC) (btps) - 3.21 - 1.94
      Forced expiratory volume in 1 second (FEV1) (btps) - 2.77 - 1.82
      FEV1/FVC ratio % (btps) - 81.9 - 93.5
      Peak expiratory flow (PEF) (L/second) - 6.55 - 3.62
      Maximum voluntary ventilation (MVV) (L/minute) - 103 - 87.1

      Which statement applies to the results?

      Your Answer: The patient has a moderate restrictive pulmonary defect

      Explanation:

      Severity of a reduction in restrictive defect (%FVC) or obstructive defect (%FEV1/FVC) predicted are classified as follows:

      Mild 70-80%
      Moderate 60-69%
      Moderately severe 50-59%
      Severe 35-49%
      Very severe <35% This patient has a %FVC predicted of 60.4% and this corresponds to a moderate restrictive deficit. %FEV1/FVC ratio is 93.5%. FEV1/FVC ratio 80% < predicted and VC < 80% = mixed picture. FEV1/FVC ratio 80% < predicted and VC > 80% = obstructive picture.

      FEV1/FVC ratio 80% > predicted and VC > 80% = normal picture.

      FEV1/FVC ratio 80% > predicted and VC < 80% predicted= restrictive picture. The integrity of the alveolar-capillary barrier is measured by carbon monoxide transfer factor (TLCO) and carbon monoxide transfer coefficient (KCO). These values are seen to be reduced in emphysema, interstitial lung diseases and in pulmonary vascular pathology. However, the KCO (as % predicted) is high in extrapulmonary restriction (pleural, chest wall and respiratory neuromuscular disease), and in loss of lung units provided the structure of the lung remaining is normal. The KCO distinguishes extrapulmonary (high KCO) causes of ‘restriction’ from intrapulmonary causes (low KCO).

    • This question is part of the following fields:

      • Clinical Measurement
      698.6
      Seconds
  • Question 8 - Lisa is a 75-year-old female rushed into the emergency department by first-aid responders....

    Incorrect

    • Lisa is a 75-year-old female rushed into the emergency department by first-aid responders. The ambulance team give a history of vomiting, homonymous hemianopia, weakness of the left upper and lower limb, and dysphasia. Lisa adds that she has a headache that keeps worsening.

      Lisa takes Warfarin as she is a known case of atrial fibrillation. Her INR is 4.3 despite the ideal target being 2-3.
      CT scan of the head suggests anterior cerebral artery haemorrhage.

      What areas of the brain are affected by an anterior cerebral artery stroke?

      Your Answer: Frontal, temporal and parietal lobes

      Correct Answer: Frontal and parietal lobes

      Explanation:

      The anterior cerebral artery supplies the midline portion of the frontal lobe and the superior medial parietal lobe of the brain. It also supplies the front four-fifths of the corpus callosum and provides blood to deep structures such as the anterior limb of the internal capsule, part of the caudate nucleus, and the anterior part of the globus pallidus.

      The cerebral hemispheres are supplied by arteries that make up the Circle of Willis. The Circle of Willis is formed by the anastomosis of the two internal carotid arteries and two vertebral arteries.

      Clinically, the internal carotid arteries and their branches are often referred to as the anterior circulation of the brain. The anterior cerebral arteries are connected by the anterior communicating artery. Near their termination, the internal carotid arteries are joined to the posterior cerebral arteries by the posterior communicating arteries, completing the cerebral arterial circle around the interpeduncular fossa, the deep depression on the inferior surface of the midbrain between the cerebral peduncles.

      The middle cerebral artery supplies part of the frontal, temporal and parietal lobes.

      The posterior cerebral artery supplies the occipital lobe.

    • This question is part of the following fields:

      • Anatomy
      85
      Seconds
  • Question 9 - A 25-year-old man, has been scheduled for a splenectomy. For this procedure, he...

    Incorrect

    • A 25-year-old man, has been scheduled for a splenectomy. For this procedure, he requires a urethral catheter.

      Where does resistance first occur during the insertion of a catheter?

      Your Answer: Bladder neck

      Correct Answer: Membranous urethra

      Explanation:

      The membranous urethra is the shortest part of the urethra and the least dilatable part of it.

      This is as a result of it being surrounded by the external urethral sphincter which is made up of striated muscle and controls voluntary urine flow from the bladder to the urethra.

    • This question is part of the following fields:

      • Anatomy
      27.1
      Seconds
  • Question 10 - Which of the following options will best reflect the adequacy of preoxygenation prior...

    Correct

    • Which of the following options will best reflect the adequacy of preoxygenation prior to rapid sequence induction of a patient?

      Your Answer: Expired fraction of oxygen (FEO2)

      Explanation:

      The most important determinant of preoxygenation adequacy is expired fraction of oxygen. Denitrogenating of the functional residual capacity is the purpose of preoxygenation. This is dependent on three vital factors: (1) respiratory rate; (2) inspired volume, and; (3) inspired oxygen concentration (FiO2).

      Arterial oxygen saturation does not efficiently determine adequacy of preoxygenation because of its inability to measure tissue reserves. Arterial partial pressure of oxygen is also unsuitable for determining preoxygenation adequacy. Moreover, the absence of central cyanosis is a very crude sign of low tissue oxygenation.

    • This question is part of the following fields:

      • Pathophysiology
      2.9
      Seconds
  • Question 11 - If the speed of an ultrasound in soft tissue is 1540 meters per...

    Incorrect

    • If the speed of an ultrasound in soft tissue is 1540 meters per second, what is the estimated wavelength produced if the frequency of a generated ultrasound is 10 megahertz?

      Your Answer: 0.15 centimetre

      Correct Answer: 0.15 millimetre

      Explanation:

      Wavelength can be computed as follows:

      Wavelength = velocity/frequency

      In the given problem, the values stated are:

      Frequency = 10 x 10^6
      Velocity = 1540 meters per second

      Wavelength = 1540/(10×10^6)
      Wavelength = 1540/10,000,000 meters
      Wavelength = 0.15 millimetres

    • This question is part of the following fields:

      • Clinical Measurement
      92.3
      Seconds
  • Question 12 - A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath...

    Incorrect

    • A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath and pleuritic chest pain. Her work requires her to travel internationally frequently. The consultant makes a diagnosis and treats her.

      Now, the consultant recommends placing a filter that will prevent future incidents. A needle is placed into the femoral vein and passed up into the abdomen to insert the filter.

      What is true regarding the organ where the filter is placed for this patient's condition?

      Your Answer: It is wrapped in a double fold of peritoneal fat

      Correct Answer: It is located posteriorly to the peritoneum

      Explanation:

      The patient likely suffers from pulmonary embolism due to her history of frequent international travels. A filter is placed in the inferior vena cava to decrease the risk of future episodes of pulmonary embolism. The IVC filter is a small, wiry device that can catch blood clots and stop them from going into the heart and lungs. Your IVC is a major vessel that brings deoxygenated blood from the lower body to the heart, from where it is pumped into the lungs.

      The filter is placed via a thin catheter inserted into the femoral vein in the groin. The catheter is gently moved up into your IVC, and a filter is introduced.

      The IVC is a retroperitoneal organ.

    • This question is part of the following fields:

      • Anatomy
      103.5
      Seconds
  • Question 13 - Concerning the intercostal nerves, which one of the following is true? ...

    Correct

    • Concerning the intercostal nerves, which one of the following is true?

      Your Answer: Each is connected to a ganglion of the sympathetic trunk

      Explanation:

      The intercostal nerves arise from the ventral rami of the first 11 thoracic spinal nerves. they course along the costal groove on the lower margin of the rib.

      The twelfth intercoastal nerve is called the subcostal nerve. This is because it is below the 12th rib.

      Each intercostal nerve is connected to a ganglion of the sympathetic trunk from which it carries preganglionic and postganglionic fibres that innervate blood vessels, sweat glands, and muscles.

      The lateral and medial pectoral nerves innervates pectoralis major muscle.

    • This question is part of the following fields:

      • Anatomy
      105.5
      Seconds
  • Question 14 - An 80-year-old man will be operated on for an arterial bypass procedure to...

    Correct

    • An 80-year-old man will be operated on for an arterial bypass procedure to treat claudication and foot ulceration. The anterior tibial artery will be the target for distal arterial anastomosis.

      Which structure is NOT closely related to the anterior tibial artery?

      Your Answer: Tibialis posterior

      Explanation:

      The anterior tibial artery originates from the distal border of the popliteus. In the posterior compartment, it passes between the heads of the tibialis posterior and the oval aperture of the interosseous membrane to reach the anterior compartment.

      On entry into the anterior compartment, it runs medially along the deep peroneal nerve.
      The upper third of the artery courses between the tibialis anterior and extensor digitorum longus muscles, while the middle third runs between the tibialis anterior and extensor hallucis longus muscles.

      At the ankle, the anterior tibial artery is located approximately midway between the malleoli. It continues on the dorsum of the foot, lateral to extensor hallucis longus, as the dorsalis pedis artery.

    • This question is part of the following fields:

      • Anatomy
      62.1
      Seconds
  • Question 15 - A 2-year old male is admitted to the surgery ward for repair of...

    Correct

    • A 2-year old male is admitted to the surgery ward for repair of an inguinal hernia. He weighs 10 kg. To provide post-operative analgesia, levobupivacaine was administered into the epidural space.

      Given the information above, what is the most appropriate dose for the hernia repair?

      Your Answer: 0.25% 7.5 ml

      Explanation:

      Caudal analgesia using bupivacaine is a widely employed technique for achieving both intraoperative and early postoperative pain relief. 0.5 ml/kg of 0.25% plain bupivacaine is favoured by many practitioners who employ this fixed scheme for procedures involving sacral dermatomes (circumcision, hypospadias repair) as well as lower thoracic dermatomes (orchidopexy). However, there are other dosing regimens for caudal blocks with variable analgesic success rates: These include 0.75 ml/kg, 1.0 ml/kg and 1.25 ml/kg.

      A study indicated that plain bupivacaine 0.25% at a dose of 0.75 ml/kg compared to a dose of 0.5 ml/kg when administered for herniotomies provided improved quality of caudal analgesia with a low side effects profile. There were consistently more patients with favourable objective pain scale (OPS) scores at all timelines, increased the time to the analgesic request with similar postoperative consumption of paracetamol in the group of patients who received 0.75 ml/kg of 0.25% bupivacaine.

    • This question is part of the following fields:

      • Pharmacology
      120
      Seconds
  • Question 16 - A 56-year-old man, presents to his general practitioner with a lump in his...

    Incorrect

    • A 56-year-old man, presents to his general practitioner with a lump in his groin area. He is diagnosed with an indirect inguinal hernia and is scheduled for a laparoscopic inguinal hernia repair. During the repair, the surgeon sees several structures surrounding the inguinal canal.

      Name the structure that forms the anterior borders of the inguinal canal.

      Your Answer:

      Correct Answer: Aponeurosis of external oblique

      Explanation:

      The inguinal canal is the pathway leading from the wall of the abdomen to the external genitalia.

      The borders of the inguinal canal are:

      Anterior wall: formed by the aponeurosis of the external oblique, supported by the internal oblique muscle laterally.

      Posterior wall: formed laterally by the transversalis fascia, and medially by the conjoint tendon

      Roof: formed by the internal oblique and transversus abdominis muscles

      Floor: formed by the inguinal ligament and supported medially by the lacunar ligament

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 17 - A study was concerned with finding out the normal reference range of IgE...

    Incorrect

    • A study was concerned with finding out the normal reference range of IgE levels in adults was conducted. Presuming that the curve follows a normal distribution, what is the percentage of individuals having IgE levels greater than 2 standard deviations from mean?

      Your Answer:

      Correct Answer: 2.30%

      Explanation:

      Since the data is normally distributed, 95.4% of the values lie with in 2 standard deviations from mean. The rest of the 4.6% are distributed symmetrically outside of that range which means 2.3% of the values lie above 2 standard deviations of the mean.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 18 - An inguinal hernia repair under general anaesthesia is scheduled for a fit 36-year-old...

    Incorrect

    • An inguinal hernia repair under general anaesthesia is scheduled for a fit 36-year-old man (75 kg). For perioperative and postoperative analgesia, you decide to perform an inguinal field block.

      Which of the following local anaesthetic solutions is the most appropriate?

      Your Answer:

      Correct Answer: 30 mL bupivacaine 0.5%

      Explanation:

      Perioperative and postoperative analgesia can both be provided by an inguinal hernia field block. The Iliohypogastric and ilioinguinal nerves, as well as the skin, superficial fascia, and deeper structures, must be blocked for maximum effectiveness. The local anaesthetic should ideally have a long duration of action, be highly concentrated, and have a volume of at least 30 mL.

      Plain bupivacaine has a maximum safe dose of 2 mg/kg body weight.

      Because the patient weighs 75 kg, 150 mg bupivacaine can be safely administered. Both 30 mL 0.5 percent bupivacaine (150 mg) and 60 mL 0.25 percent bupivacaine (150 mg) are acceptable doses, but 30 mL 0.5 percent bupivacaine represents the optimal volume and strength, potentially providing a denser and longer block.

      The maximum safe dose of plain lidocaine has been estimated to be between 3.5 and 5 mg/kg. The patient weighs 75 kg and can receive a maximum of 375 mg using the higher dosage regimen:

      There are 200 mg of lidocaine in 10 mL of 2% lidocaine (and therefore 11 mL contains 220 mg)
      200 mg of lidocaine is contained in 20 mL of 1% lidocaine.

      While alternatives are available, Although the doses of 11 mL lidocaine 2% and 20 mL lidocaine 1% are well within the dose limit, the volumes used are insufficient for effective field block for this surgery.

      With 1 in 200,000 epinephrine, the maximum safe dose of lidocaine is 7 mg/kg. The patient can be given 525 mg in this case. Even with epinephrine, 60 mL of 1% lidocaine is 600 mg, which could be considered an overdose.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 19 - Weight of all of your patients in the ICU is analysed, and shows...

    Incorrect

    • Weight of all of your patients in the ICU is analysed, and shows that your date set is skewed.

      Which of the following will correctly show the average weight of your patients?

      Your Answer:

      Correct Answer: Median

      Explanation:

      The question mentions a quantitative, ratio scale data set. The use of mean would be ideal under normal circumstances, however, in this situation median is preferred as it is less sensitive to the skewness of data. The median is usually preferred to other measures of central tendency when your data set is skewed (i.e., forms a skewed distribution)

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 20 - Which of the following antihypertensive drugs is an alpha-blocker? ...

    Incorrect

    • Which of the following antihypertensive drugs is an alpha-blocker?

      Your Answer:

      Correct Answer: Doxazosin

      Explanation:

      Doxazosin is selective alpha 1 blocker (it causes less tachycardia than a non-selective alpha-blocker) and is the drug of choice for a patient with hypertension and benign hyperplasia of the prostate (BHP).

      The major adverse effect of an alpha-blocker is first-dose hypotension.

      Atenolol and Labetalol are beta blockers. It works by relaxing blood vessels and slowing heart rate to improve blood flow and decrease blood pressure.

      Clonidine is an α2A-adrenergic agonist used to treat high blood pressure, ADHD, drug withdrawal (alcohol, opioids, or nicotine), menopausal flushing, diarrhea, spasticity, and certain pain conditions.

      Methyldopa is a centrally-acting alpha-2 adrenergic agonist used to manage hypertension alone or in combination with hydrochlorothiazide, and to treat hypertensive crises.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 21 - Which of the following statements about closing capacity is true? ...

    Incorrect

    • Which of the following statements about closing capacity is true?

      Your Answer:

      Correct Answer: It is less than the functional residual capacity in a 30-year-old

      Explanation:

      Closing capacity refers to volume of gas within the lungs at which the conducting small airways begin to close, that is, the point during expiration when small airways close.

      It is calculated mathematically as:

      Closing capacity = Closing volume (CV) + Residual volume (RV)

      Functional residual capacity (FRC) is the volume of gas still present within the lungs post expiration.

      Closing capacity is lower than the functional residual capacity in younger adults, but begins to rise to eventually equal, and then exceed it with increasing age (at about middle age), increasing intrabdominal pressure, decreasing blood flow in the pulmonary system and parenchymal disease within the pulmonary system.

    • This question is part of the following fields:

      • Clinical Measurement
      0
      Seconds
  • Question 22 - A 4-year-old boy with status epilepticus was brought to ER and has already...

    Incorrect

    • A 4-year-old boy with status epilepticus was brought to ER and has already received two doses of intravenous lorazepam but is still continuing to have seizures.

      Which of the following drug would be best for his treatment?

      Your Answer:

      Correct Answer: Phenytoin 20 mg/kg IV

      Explanation:

      When the convulsion lasts for five or more than five minutes, or if there are recurrent episodes of convulsions in a 5 minute period without returning to the baseline, it is termed as Status Epilepticus.
      The first priority in the patient with seizures is maintaining the airway, breathing, and circulation.

      Guideline for the management of Status Epilepticus in children by Advanced Life Support Group is as follow:

      Step 1 (Five minutes after the start of seizures):

      If intravascular access is available start treatment with lorazepam 0.1 mg/kg IV
      If no intravascular access then give buccal midazolam 0.5 mg/kg or rectal diazepam 0.5 mg/kg.

      Step 2 (Ten minutes after the start of seizure):

      If the convulsions continue then a second dose of benzodiazepine should be given. Senior should be called on-site and phenytoin should be prepared.
      No more than two doses or benzodiazepines should be given (including any doses given before arrival at the hospital)
      If still no IV access then obtain intraosseous access (IO).

      Step 3 (Ten minutes after step 2)

      Senior help along with anaesthetic/ICU help should be sought
      Phenytoin 20 mg/kg IV over 20 minutes
      If the seizure stops before the full dose of phenytoin is given then the infusion should be completed as this provides up to 24 hours of anticonvulsant effect
      In children already receiving phenytoin as treatment for epilepsy then an alternative is phenobarbitone 20 mg/kg IV over five minutes
      Once the phenytoin is started, senior staff may wish to give rectal paraldehyde 0.4 mg/kg although this is no longer included in the routine algorithm recommended by APLS.

      Step 4 (20 minutes after step 3)

      If 20 minutes after starting phenytoin the child remains in status epilepticus then rapid sequence induction of anaesthesia with thiopentone and a short acting paralysing agent is needed and the child transferred to paediatric intensive care.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 23 - An experiment is designed to investigate that how three diets having different sugar...

    Incorrect

    • An experiment is designed to investigate that how three diets having different sugar content affect the body weight to a different level.

      Which one of the following test will determine a statistically significant difference among the diets?

      Your Answer:

      Correct Answer: ANOVA

      Explanation:

      Chi-square test is used to determine the statistically significant different between categorical variables. It also determines the difference between expected frequencies and the observed frequencies.

      Mann Whitney U test is used to determine the statistically significant different between two independent groups.

      Wilcoxon’s test is the test of dependency. it determines the statistically significant difference between two dependent groups.

      Student t-test is one of the most commonly used method to test the hypothesis. It determines the significant difference between the means of two different groups.

      ANOVA (analysis of variance) is similar to student’s t-test.

      ANOVA is a statistical method used to determines the statistically significant difference between the mean of more than two group. In this experiment as we are dealing with three different group, ANOVA is most suitable test to determine the difference between each groups.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 24 - Regarding laminar gas flow, which of the following options has the most influence...

    Incorrect

    • Regarding laminar gas flow, which of the following options has the most influence on laminar flow?

      Your Answer:

      Correct Answer: Diameter of tube

      Explanation:

      Laminar flow can be defined as the motion of a fluid where every particle in the fluid follows the same path of its previous particles. The following are properties of laminar flow of gas or fluids:

      1. Smooth unobstructed flow of gas through a tube of relatively uniform diameter
      2. Few directional changes
      3. Slow, steady flow through straight smooth, rigid, large calibre, cylindrical tube
      4. Outer layer flow slower than the centre due to friction, results in discrete cylindrical layers, or streamlines
      5. Double flow by doubling pressure as long as the flow pattern remains laminar

      Poiseuille’s Law relates the factors that determine laminar flow. It indicates the degree of resistance to fluid flow through a tube. The resistance to fluid flow through a tube is directly related to the length, flow and viscosity; and inversely related to the radius of the tube to the fourth power. This means that, when the radius is doubled, there is increase in flow by a factor of 16.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 25 - You performed pelvic ultrasound of Mrs Aciman as she had pelvic bloating and...

    Incorrect

    • You performed pelvic ultrasound of Mrs Aciman as she had pelvic bloating and intermittent pain. The ultrasound shows a complex ovarian cyst and the radiologist who reported the results has advised urgent consultation with a gynaecologist. Upon breaking the news to Mrs Aciman you learn that she recently had a blood test done that was normal. You explain it to her that the test performed (Ca-125) is not always perfect and is only able to detect 80% of the cancer cases while the remaining 20% go undetected.

      Which statistical term appropriately explains the 80% in this example.

      Your Answer:

      Correct Answer: Sensitivity

      Explanation:

      Tests are used to confirm the presence of a particular disease. However the results can be misleading at times since most of the tests have some limitations associated with them.
      Sensitivity is the correct term that refers to the probability of a positive test. The others are explained below:

      False Positive rates refer to the proportion of the patients who don’t have the condition being detected as positive.

      False Negative rates refer to the proportion of the patients who have the condition being detected as negative (like the 20% of the patients that went undetected by the Ca-125 test).

      Specificity describes the ability of a test to detect and pick up people without the disease. Absolute risk ratio compares the rate of two separate outcomes.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 26 - Which among the given options can be used to find out the number...

    Incorrect

    • Which among the given options can be used to find out the number needed to treat?

      Your Answer:

      Correct Answer: 1 / (Absolute risk reduction)

      Explanation:

      Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.

      It can be found as:

      NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 27 - A 33-year old man was referred to you because of difficulty moving his...

    Incorrect

    • A 33-year old man was referred to you because of difficulty moving his limbs.

      History revealed that he was placed under anaesthesia for a major surgery 12 hours prior to the referral. Other symptoms were noted such as anxiousness, agitation, and fever of 38°C. Upon physical examination, he was tachycardic at 119 beats per minute. Moreover, his medical history showed that he was on Fluoxetine for clinical depression.

      The nurses reported that, because of his frequent complaints of axillary pain, he was given tramadol with paracetamol.

      Which of the following is responsible for his clinical features?

      Your Answer:

      Correct Answer: Tramadol

      Explanation:

      Tramadol is weak agonist at the mu receptor. It inhibits the neuronal reuptake of serotonin and norepinephrine, and inhibits pain neurotransmission. It is given for moderate pain, chronic pain syndromes, and neuropathic pain.

      Fluoxetine is a selective serotonin reuptake inhibitor (SSRI). It inhibits the neuronal reuptake of serotonin by inhibiting the serotonin transporter (SERT). It is the drug of choice for major depressive disorder, and is given for other psychiatric disorders such as anxiety, obsessive-compulsive, post-traumatic stress, and phobias.

      When tramadol is given with SSRIs, serotonin syndrome may occur. Serotonin syndrome is characterized by fever, agitation, tremors, clonus, hyperreflexia and diaphoresis. The onset of symptoms may occur within a few hours, and the first-line treatment is sedation, paralysis, intubation and ventilation.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 28 - Transthoracic echocardiogram (TTE) can be used to investigate the function of the heart...

    Incorrect

    • Transthoracic echocardiogram (TTE) can be used to investigate the function of the heart in patients with suspected heart failure. The aim is to measure the ejection fraction, but to do that, the stroke volume must first be measured. How is stroke volume calculated?

      Your Answer:

      Correct Answer: End diastolic volume - end systolic volume

      Explanation:

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 29 - A bolus of alfentanil has a faster onset of action than an equal...

    Incorrect

    • A bolus of alfentanil has a faster onset of action than an equal dose of fentanyl.

      Which of the following statements most accurately describes the difference?

      Your Answer:

      Correct Answer: The pKa of alfentanil is less than that of fentanyl

      Explanation:

      Unionised molecules are more likely than ionised molecules to cross membranes (such as the blood-brain barrier).

      Because alfentanil and fentanyl are weak bases, the Henderson-Hasselbalch equation says that the ratio of ionised to unionised molecules is determined by the parent compound’s pKa in relation to physiological pH.

      Alfentanil has a pKa of 6.5, while fentanyl has a pKa of 8.4.
      At a pH of 7.4, 89 percent of alfentanil is unionised, whereas 9% of fentanyl is.

      As a result, alfentanil has a faster onset than fentanyl.

      Fentanyl is 83% plasma protein bound
      Alfentanil is 90% plasma protein bound.

      Alfentanil’s pharmacokinetics are affected by its higher plasma protein binding. Because alfentanil has a low hepatic extraction ratio (0.4), clearance is determined by the degree of protein binding rather than the time it takes to take effect.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 30 - A 48-year-old woman has presented to the emergency with abdominal pain and distension...

    Incorrect

    • A 48-year-old woman has presented to the emergency with abdominal pain and distension complaints. She is a known case of diabetes mellitus type 2 and has a BMI of 28 kg/m². On investigations, the liver function tests (LFTs) show raised alanine transaminase (ALT).

      Liver ultrasound is performed next to visualize the blood flow into and out of the liver.

      Which blood vessel supplies approximately one-third of the blood supply to the liver?

      Your Answer:

      Correct Answer: Hepatic artery proper

      Explanation:

      The liver receives blood supply from two sources.
      1. Hepatic artery proper
      It arises from the celiac trunk via the common hepatic artery and brings oxygenated blood to the liver.
      It contributes to approximately 30% of the blood supply of the liver.
      2. Hepatic portal vein – supplies the liver with partially deoxygenated blood, carrying nutrients absorbed from the small intestine. It gets tributaries from the inferior mesenteric vein, splenic vein, and superior mesenteric vein

      The inferior mesenteric artery supplies the hindgut.
      The superior mesenteric artery supplies the pancreas and intestine up to the proximal two-thirds of the transverse colon.
      The inferior phrenic artery supplies the inferior surface of the diaphragm and oesophagus.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Anatomy (3/6) 50%
Pharmacology (1/3) 33%
Pathophysiology (1/2) 50%
Physiology (0/1) 0%
Clinical Measurement (1/3) 33%
Passmed