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  • Question 1 - Which of the following statements is true about fluid balance? ...

    Incorrect

    • Which of the following statements is true about fluid balance?

      Your Answer: In patients with pathological capillary leakage, the oncotic pressure becomes decreasingly important in determining fluid fluxes

      Correct Answer: After intravenous administration of crystalloids, the distribution of these fluids throughout the body depends on its osmotic activity

      Explanation:

      When there is capillary leakage as seen in dependent oedema or ascites, oncotic pressure becomes a problem.

      The intracellular sodium concentration is very sensitive to the extracellular sodium concentrations. When there is an imbalance, osmosis occurs resulting in shifts in water between the two compartments.

      The microvascular endothelium relies upon osmosis and other processes as it is not freely permeable to water.

    • This question is part of the following fields:

      • Physiology
      75.2
      Seconds
  • Question 2 - A 57-year old lady is admitted to the Emergency Department with signs of...

    Incorrect

    • A 57-year old lady is admitted to the Emergency Department with signs of a subarachnoid haemorrhage.

      On admission, her GCS was 7. She has been intubated, sedated and is being ventilated and is waiting for a CT scan. Her Blood pressure is 140/70mmHg.

      The arterial blood gas analysis shows the following:

      pH 7.2 (7.35 - 7.45)
      PaO2 70 mmHg (80-100)
      9.2 kPa (10.5-13.1)
      PaCO2 78 mmHg (35-45)
      10.2 kPa (4.6-6.0)
      BE -3 mEq/L (-3 +/-3)
      Standard bic 27 mmol/L (21-27)
      SaO2 94%

      The most likely cause of an increase in the patient's global cerebral blood flow (CBF) is which of the following?


      Your Answer: Acidosis

      Correct Answer: Hypercapnia

      Explanation:

      PaCO2 is one of the most important factors that regulate cerebral vascular tone. CO2 induces cerebral vasodilatation and as a result, it increases CBF. Between 20 mmHg (2.7 kPa) and 80 mmHg (10.7 kPa), there is a linear increase of PaCO2.

      Sometimes, there are areas where auto regulation has failed locally but not globally. Similarly, local vs. systemic acidosis will have similar effects. When the PaO2 falls below 50 mmHg (6.5 kPa), the CBF progressively increases.

      An increase in the cerebral metabolic rate for oxygen (CMRO2) and therefore CBF can be caused by hyperthermia.
      A late feature of cerebral injury is hyperthermia secondary to hypothalamic injury. Therefore this is not the most likely cause of an increased CBF in this scenario.

    • This question is part of the following fields:

      • Physiology
      79.1
      Seconds
  • Question 3 - The statement that best describes lactic acidosis is: ...

    Incorrect

    • The statement that best describes lactic acidosis is:

      Your Answer: Skeletal muscles are important sites of lactate metabolism

      Correct Answer: It can be precipitated by intravenous fructose

      Explanation:

      An elevated arterial blood lactate level and an increase anion gap ([Na + K] – [Cl + HCO3]) of >20mmol gives rise to lactic acidosis. It can also be a result of overproduction and/or reduced metabolism of lactic acid.

      The liver and kidney are the main sites of lactate metabolism, not skeletal muscle.

      The two types of lactic acidosis that are known are:

      Type A – due to tissue hypoxia, inadequate tissue perfusion and anaerobic glycolysis. These may be seen in cardiac arrest, shock, hypoxaemia and anaemia. The management of type A lactic acidosis involves reversing the underlying cause of the tissue hypoxia.

      Type B – occurs in the absence of tissue hypoxia. Some of the causes of this include hepatic failure, renal failure, diabetes mellitus, pancreatitis and infection. Some drugs can also cause this lie aspirin, ethanol, methanol, biguanides and intravenous fructose.

      The mainstay of treatment involves:
      1. Optimising tissue oxygen delivery
      2. Correcting the cause
      3. Intravenous sodium bicarbonate

      In resistant cases, peritoneal dialysis can be performed.

    • This question is part of the following fields:

      • Physiology
      22.2
      Seconds
  • Question 4 - The following statement is true with regards to the Nernst equation: ...

    Correct

    • The following statement is true with regards to the Nernst equation:

      Your Answer: It is used to calculate the potential difference across a membrane when the individual ions are in equilibrium

      Explanation:

      The Nernst equation is used to calculate the membrane potential at which the ions are in equilibrium across the cell membrane.

      The normal resting membrane potential is -70 mV (not + 70 mV).

      The equation is:
      E = RT/FZ ln {[X]o
      /[X]i}

      Where:
      E is the equilibrium potential
      R is the universal gas constant
      T is the absolute temperature
      F is the Faraday constant
      Z is the valency of the ion
      [X]o is the extracellular concentration of ion X
      [X]i is the intracellular concentration of ion X.

    • This question is part of the following fields:

      • Physiology
      12.2
      Seconds
  • Question 5 - Which of the following statement is true or false regarding to the respiratory...

    Correct

    • Which of the following statement is true or false regarding to the respiratory tract?

      Your Answer: The sympathetic innervation of the bronchi is derived from T2 - T4

      Explanation:

      The diaphragm has three opening through which different structures pass from the thoracic cavity to the abdominal cavity:

      Inferior vena cava passes at the level of T8.

      Oesophagus, oesophageal vessels and vagi at T10.

      Aorta, thoracic duct and azygous vein through T12.

      Sympathetic trunk and pulmonary branches of vagus nerve form a posterior pulmonary plexus at the root of the lung. Fibres continue posteriorly from superficial cardiac plexus to form Anterior pulmonary plexus. It contains vagi nerves and superficial cardiac plexus. These fibres then follow the blood vessel and bronchi into the lungs.

      The lower border of the pleura is at the level of:

      8th rib in the midclavicular line

      10th rib in the lower level of midaxillary line

      T12 at its termination.

      Both lungs have oblique fissure while right lung has transverse fissure too.

      The trachea expands from the lower edge of the cricoid cartilage (at the level of the 6th cervical vertebra) to the carina.

    • This question is part of the following fields:

      • Physiology
      7.8
      Seconds
  • Question 6 - An orthopaedic surgery is scheduled for a 68-year-old man. He is normally in...

    Correct

    • An orthopaedic surgery is scheduled for a 68-year-old man. He is normally in good shape. His routine biochemistry results are checked and found to be within normal limits.

      Which of the following pairs has the greatest impact on his plasma osmolarity?

      Your Answer: Sodium and potassium cations

      Explanation:

      The number of osmoles (Osm) of solute per litre (L) of solution (Osmol/L) is the unit of measurement for solute concentration. The calculated serum osmolality assumes that the primary solutes in the serum are sodium salts (chloride and bicarbonate), glucose, and urea nitrogen.

      2 (Na + K) + Glucose + Urea (all in mmol/L) = calculated osmolarity

      313 mOsm/L = 2 (144 + 6) + 9.5 + 3.5

      Sodium and potassium ions clearly contribute the most to plasma osmolarity. Glucose and urea, on the other hand, are less so.

      The osmolarity of normal serum is 285-295 mOsm/L. Temperature and pressure affect osmolality, and this calculated variable is less than osmolality for a given solution.

      The number of osmoles (Osm) of solute per kilogramme (Osm/kg) is a measure of osmolality, which is also a measure of solute concentration. Temperature and pressure have no effect on the value. An osmometer is used to measure it in the lab. Osmometers rely on a solution’s colligative properties, such as a decrease in freezing point or a rise in vapour pressure.

      The osmolar gap (OG) is calculated as follows:

      OG = osmolaRity calculated from measured serum osmolaLity

      Excess alcohols, lipids, and proteins in the blood can all contribute to the difference.

    • This question is part of the following fields:

      • Physiology
      47.3
      Seconds
  • Question 7 - A 30-year old female athlete was brought to the Emergency Room for complaints...

    Incorrect

    • A 30-year old female athlete was brought to the Emergency Room for complaints of light-headedness and nausea. Clinical chemistry studies were done and the results were the following:

      Na: 144 mmol/L (Reference: 137-144 mmol/L)
      K: 6 mmol/L (Reference: 3.5-4.9 mmol/L)
      Cl: 115 mmol/L (Reference: 95-107 mmol/L)
      HCO3: 24 mmol/L (Reference: 20-28 mmol/L)
      BUN: 9.5 mmol/L (Reference: 2.5-7.5 mmol/L)
      Crea: 301 µmol/l (Reference: 60 - 110 µmol/L)
      Glucose: 3.5 mmol/L (Reference: 3.0-6.0 mmol/L)

      Taking into consideration the values above, in which of the following ranges will his osmolarity fall into?

      Your Answer: 288-294

      Correct Answer: 300-313

      Explanation:

      Osmolarity refers to the osmotic pressure generated by the dissolved solute molecules in 1 L of solvent. Measurements of osmolarity are temperature dependent because the volume of the solvent varies with temperature. The higher the osmolarity of a solution, the more it attracts water from an opposite compartment.

      Osmolarity can be computed using the following formulas:

      Osmolarity = Concentration x number of dissociable particles; OR
      Plasma osmolarity (Posm) = 2([Na+]) + (glucose in mmol/L) + (BUN in mmol/L)

      Posm = 2 (144) + 3.5 + 9.5 = 301 mOsm/L

      Suppose there is electrical neutrality, the formula will double the cation activity to account for the anions.

      Plasma osmolarity (Posm) = 2([Na+] + [K+]) + (glucose in mmol/L) + (BUN in mmol/L)

      Posm = 2 (144 + 6) + 3.5 + 9.5 = 313 mOsm/L

    • This question is part of the following fields:

      • Physiology
      59
      Seconds
  • Question 8 - Which statement is true when describing carbonic anhydrase? ...

    Incorrect

    • Which statement is true when describing carbonic anhydrase?

      Your Answer: Is present in the plasma

      Correct Answer: Isoenzyme IV is found in the brush border of the proximal convoluted tubule

      Explanation:

      Carbonic anhydrase is an enzyme which contains zinc and can be found in:
      1. Erythrocytes
      2. Pulmonary endothelium
      3. The intestine
      4. Pancreas
      5. Cardiac muscle and skeletal muscle.

      To date, there have been seven isoenzymes identified. Of note, isoenzyme IV is found in the brush border of the proximal convoluted tubule and isoenzyme II is found within the luminal cells.

      Acetazolamides a carbonic anhydrase inhibitor and is used as prophylaxis against mountain sickness and in glaucoma management.

      Spironolactone is a potassium diuretic and is an aldosterone antagonist.

    • This question is part of the following fields:

      • Physiology
      18.6
      Seconds
  • Question 9 - Which of the following statement is true regarding hypoxic pulmonary vasoconstriction (HPV)? ...

    Incorrect

    • Which of the following statement is true regarding hypoxic pulmonary vasoconstriction (HPV)?

      Your Answer: The predominant stimulus is a low PO2 in the pulmonary arterial blood

      Correct Answer: 20 parts per million (ppm) of nitric oxide will reduce hypoxic pulmonary vasoconstriction

      Explanation:

      Hypoxic Pulmonary vasoconstriction (HPV) reflects the constriction of small pulmonary arteries in response to hypoxic alveoli (.i.e.; PO2 below 80-100mmHg or 11-13kPa).

      These blood vessels become independent of the nerve stimulus, when blood with a high PO2 flows through the lung which contains a low alveolar PO2.

      Thus a low PO2 within the alveoli has been shown to impact on hypoxic pulmonary vasoconstriction (HPV) more than a low PO2 within the blood.

      HPV results in the blood flow being directed away from poorly ventilated areas of the lung and helps to reduce the ventilation/perfusion mismatch (not increase).

      In animals, volatile anaesthetic agents can diminish HPV, while in adults, the evidence proves less persuading, in spite of the fact that it certainly doesn’t strengthen the effects.

      HPV response will be suppressed by 20 parts per million (ppm) of nitric oxide.

    • This question is part of the following fields:

      • Physiology
      23.7
      Seconds
  • Question 10 - Which one of the following factor affects the minimal alveolar concentration (MAC)? ...

    Incorrect

    • Which one of the following factor affects the minimal alveolar concentration (MAC)?

      Your Answer:

      Correct Answer: Hypoxaemia

      Explanation:

      The minimal alveolar concentration (MAC) is the concentration of an inhalation anaesthetic agent in the lung alveoli required to stop a response to the surgical stimulus in 50% of the patient.

      Following factors don’t affect the MAC of the inhaled anaesthetic agents:

      Gender, acidosis, alkalosis, hypothyroidism, hyperthyroidism, body weight, serum potassium level, and the duration of the anaesthesia.

      MAC increase in children, elevated temperature, high metabolic rate, sympathetic increase and chronic alcoholism.

      MAC decrease in low temperature, low oxygen level, old age, hypotension (<40 mmHg), depressant drugs e.g. opioids and low level of catecholamines; alpha methyl dopa. Carbon dioxide O2 at the pressure > 120mmHg is being used in anesthetic-Hinkman as an additive effect to decrease MAC, however, increase concentration of CO2 activates the sympathetic system resulting the MAC increases.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 11 - Concerning forced alkaline diuresis, which of the following statements is true? ...

    Incorrect

    • Concerning forced alkaline diuresis, which of the following statements is true?

      Your Answer:

      Correct Answer: Can be used in a barbiturate overdose

      Explanation:

      In situations of poisoning or drug overdose with acid dugs like salicylates and barbiturates, forced alkaline diuresis may be used.

      With regards to overdose with alkaline drugs, forced acid diuresis is used.

      By changing the pH of the urine, the ionised portion of the drug stays in the urine, and this prevents its diffusion back into the blood. Charged molecules do not readily cross biological membranes.

      The process involves the infusion of specific fluids at a rate of about 500ml per hour. This requires monitoring of the central venous pressure, urine output, plasma electrolytes, especially potassium, and blood gas analysis.

      The fluid regimen recommended is:
      500ml of 1.26% sodium bicarbonate (not 200ml of 8.4%)
      500ml of 5% dextrose and
      500ml of 0.9% sodium chloride.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 12 - Which of the following best explains the association between smoking and lower oxygen...

    Incorrect

    • Which of the following best explains the association between smoking and lower oxygen delivery to tissues?

      Your Answer:

      Correct Answer: Left shift of the oxygen dissociation curve

      Explanation:

      Smoking is a major risk factor associated with perioperative respiratory and cardiovascular complications. Evidence also suggests that cigarette smoking causes imbalance in the prostaglandins and promotes vasoconstriction and excessive platelet aggregation. Two of the constituents of cigarette smoke, nicotine and carbon monoxide, have adverse cardiovascular effects. Carbon monoxide increases the incidence of arrhythmias and has a negative ionotropic effect both in animals and humans.

      Smoking causes an increase in carboxyhaemoglobin levels, resulting in a leftward shift in which appears to represent a risk factor for some of these cardiovascular complications.

      There are two mechanisms responsible for the leftward shift of oxyhaemoglobin dissociation curve when carbon monoxide is present in the blood. Carbon monoxide has a direct effect on oxyhaemoglobin, causing a leftward shift of the oxygen dissociation curve, and carbon monoxide also reduces the formation of 2,3-DPG by inhibiting glycolysis in the erythrocyte. Nicotine, on the other hand, has a stimulatory effect on the autonomic nervous system. The effects of nicotine on the cardiovascular system last less than 30 min.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 13 - In the fetal circulation, the cerebral and coronary circulations are preferentially supplied by...

    Incorrect

    • In the fetal circulation, the cerebral and coronary circulations are preferentially supplied by oxygen-rich blood over other organs. This is possible because of which phenomenon?

      Your Answer:

      Correct Answer: Well oxygenated blood from the inferior vena cava is preferentially streamed across the patent foramen ovale

      Explanation:

      During fetal development, blood oxygenated by the placenta flows to the foetus through the umbilical vein, bypasses the fetal liver through the ductus venosus, and returns to the fetal heart through the inferior vena cava.

      Blood returning from the inferior vena cava then enters the right atrium and is preferentially shunted to the left atrium through the patent foramen ovale. Blood in the left atrium is then pumped from the left ventricle to the aorta. The oxygenated blood ejected through the ascending aorta is preferentially directed to the fetal coronary and cerebral circulations.

      Deoxygenated blood returns from the superior vena cava to the right atrium and ventricle to be pumped into the pulmonary artery. Fetal pulmonary vascular resistance (PVR), however, is higher than fetal systemic vascular resistance (SVR); this forces deoxygenated blood to mostly bypass the fetal lungs. This poorly oxygenated blood enters the aorta through the patent ductus arteriosus and mixes with the well-oxygenated blood in the descending aorta. The mixed blood in the descending aorta then returns to the placenta for oxygenation through the two umbilical arteries.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 14 - The fluids with the highest osmolarity is? ...

    Incorrect

    • The fluids with the highest osmolarity is?

      Your Answer:

      Correct Answer: 0.45% N. Saline with 5% glucose

      Explanation:

      The concentration of solute particles per litre (mosm/L) = the osmolarity of a solution. Changes in water content, ambient temperature, and pressure affects osmolarity. The osmolarity of any solution can be calculated by adding the concentration of key solutes in it.

      Individual manufacturers of crystalloids and colloids may have different absolute values but they are similar to these.

      0.45% N. Saline with 5% glucose:
      Tonicity – hypertonic
      Osmolarity – 405 mosm/L
      Kilocalories (kCal) – 107

      0.9% N. Saline:
      Tonicity – isotonic
      Osmolarity – 308 mosm/L
      Kilocalories (kCal) – 0

      5% Dextrose:
      Tonicity – isotonic
      Osmolarity – 253 mosm/L
      Kilocalories (kCal) – 170

      Gelofusine (154 mmol/L Na, 120 mmol/L Cl):
      Tonicity – isotonic
      Osmolarity – 274 mosm/L
      Kilocalories (kCal) – 0

      Hartmann’s solution:
      Tonicity – isotonic
      Osmolarity – 273 mosm/L
      Kilocalories (kCal) – 9

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 15 - A 72-year old farmer is hospitalized with acute respiratory failure and autonomic dysfunction....

    Incorrect

    • A 72-year old farmer is hospitalized with acute respiratory failure and autonomic dysfunction. Suspected organophosphate poisoning.

      Which one is the best mechanism for acute toxicity caused by organophosphates?

      Your Answer:

      Correct Answer: Inhibition of acetylcholinesterase

      Explanation:

      The toxicity of organophosphorus (OP) nerve agents is manifested through irreversible inhibition of acetylcholinesterase (AChE) at the cholinergic synapses, which stops nerve signal transmission, resulting in a cholinergic crisis and eventually death of the poisoned person. Oxime compounds used in nerve agent antidote regimen reactivate nerve agent-inhibited AChE and halt the development of this cholinergic crisis.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 16 - Comparing pressure-volume curves in patients during an asthma attack with that of healthy...

    Incorrect

    • Comparing pressure-volume curves in patients during an asthma attack with that of healthy subjects.

      The increased resistive work of breathing in the patients with asthma is best indicated by?

      Your Answer:

      Correct Answer: Larger hysteresis loop

      Explanation:

      A major source of caloric expenditure and oxygen consumption in the body is work of breathing (WOB) and 70% of this is to overcome elastic forces. The remaining 30% is for flow-resistive work

      In a normal patient breathing normally, the total area of hysteresis pressure volume curve represents the flow-resistive WOB.

      The area of the expiratory resistive work increases during an asthma attack making the compliance curve larger in area. The larger the area the greater the work required to breathe.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 17 - All of the statements describing the blood brain barrier are false EXCEPT:...

    Incorrect

    • All of the statements describing the blood brain barrier are false EXCEPT:

      Your Answer:

      Correct Answer: Inflammation alters its permeability

      Explanation:

      The blood brain barrier (BBB) consists of the ultrafiltration barrier in the choroid plexus and the barrier around cerebral capillaries. The barrier is made by endothelial cells which line the interior of all blood vessels. In the capillaries that form the blood–brain barrier, endothelial cells are wedged extremely close to each other, forming so-called tight junctions.

      Outside of the BBB lies the hypothalamus, third and fourth ventricles and the chemoreceptor trigger zone (CTZ).

      Water, oxygen and carbon dioxide cross the BBB freely but glucose is controlled. The ability of chemicals to cross the barrier is proportional to their lipid solubility, not their water solubility. It’s ability to cross is inversely proportional to their molecular size and charge.

      In neonates, the BBB is less effective than in adults. This is why there is increased passage of opioids and bile salts (kernicterus) into the neonatal brain.

      In meningitis, the effectiveness and permeability of the BBB is affected, and as a result, this effect helps the passage of antibiotics which would otherwise not normally be able to cross.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 18 - In which of the following situations will a regional fall in cerebral blood...

    Incorrect

    • In which of the following situations will a regional fall in cerebral blood flow occur, suppose there is no changes in the mean arterial pressure (MAP)?

      Your Answer:

      Correct Answer: Hyperoxia

      Explanation:

      The response of cerebral blood flow (CBF) to hyperoxia (PaO2 >15 kPa, 113 mmHg), the cerebral oxygen vasoreactivity is less well defined. A study originally described, using a nitrous oxide washout technique, a reduction in CBF of 13% and a moderate increase in cerebrovascular resistance in subjects inhaling 85-100% oxygen. Subsequent human studies, using a variety of differing methods, have also shown CBF reductions with hyperoxia, although the reported extent of this change is variable. Another study assessed how supra-atmospheric pressures influenced CBF, as estimated by changes in middle cerebral artery flow velocity (MCAFV) in healthy individuals. Atmospheric pressure alone had no effect on MCAFV if PaO2 was kept constant. Increases in PaO2 did lead to a significant reduction in MCAFV; however, there were no further reductions in MCAFV when oxygen was increased from 100% at 1 atmosphere of pressure to 100% oxygen at 2 atmospheres of pressure. This suggests that the ability of cerebral vasculature to constrict in response to increasing partial pressure of oxygen is limited.

      Increases in arterial blood CO2 tension (PaCO2) elicit marked cerebral vasodilation.

      CBF increases with general anaesthesia, ketamine anaesthesia, and hypoviscosity.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 19 - Which of the statements below best describe the total cerebral flow (CBF) in...

    Incorrect

    • Which of the statements below best describe the total cerebral flow (CBF) in an adult?

      Your Answer:

      Correct Answer: Accounts for 15% of the cardiac output

      Explanation:

      While the brain only weighs 3% of the body weight, 15% of the cardiac output goes towards the brain.

      Between mean arterial pressures (MAP) of 60-130 mmHg, autoregulation of cerebral blood flow (CBF) occurs. Exceeding this, the CBF is maintained at a constant level. This is controlled mainly by the PaCO2 level, and the autonomic nervous system has minimal role.

      Beyond these limits, the CBF is directly proportional to the MAP, not the systolic blood pressure.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 20 - The SI unit of measurement is kgm2s-2 in the System international d'unités (SI).

    Which...

    Incorrect

    • The SI unit of measurement is kgm2s-2 in the System international d'unités (SI).

      Which of the following derived units of measurement has this format?

      Your Answer:

      Correct Answer: Energy

      Explanation:

      The derived SI unit of force is Newton.
      F = m·a (where a is acceleration)
      F = 1 kg·m/s2

      The joule (J) is a converted unit of energy, work, or heat. When a force of one newton (N) is applied over a distance of one metre (Nm), the following amount of energy is expended:

      J = 1 kg·m/s2·m =
      J = 1 kg·m2/s2 or 1 kg·m2·s-2

      The unit of velocity is metres per second (m/s or ms-1).

      The watt (W), or number of joules expended per second, is the SI unit of power:

      J/s = kg·m2·s-2/s
      J/s = kg·m2·s-3

      Pressure is measured in pascal (Pa) and is defined as force (N) per unit area (m2):
      Pa = kg·m·s-2/m2
      Pa = kg·m-1·s-2

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 21 - A patient was brought to the emergency room after passing black tarry stools....

    Incorrect

    • A patient was brought to the emergency room after passing black tarry stools. The initial diagnosis was upper gastrointestinal bleeding. The patient was placed on temporary nil per os (NPO) for the next 24 hours, his weight was 110 kg, and the required volume of intravenous fluid for the him was 3 litres. His electrolytes and other biochemistry studies were normal.

      If you were to choose the intravenous fluid regimen that would closely mimic his basic electrolyte and caloric requirements, which one would be the best answer?

      Your Answer:

      Correct Answer: 3000 mL 0.45% N. saline with 5% dextrose, each bag with 40 mmol of potassium

      Explanation:

      The patient in the case has a fluid volume requirement of 30 mL/kg/day. His basic electrolyte requirement per day is:

      Sodium at 2 mmol/kg/day x 110 = 220 mmol/day
      Potassium at 1 mmol/kg/day x 110 = 110 mmol/day

      His energy requirement per day is:

      35 kcal/kg/day x 110 kg = 3850 kcal/day

      One gram of glucose in fluid can provide approximately 4 kilocalories.

      The following are the electrolyte components of the different intravenous fluids:

      Fluid Na (mmol/L) K (mmol/L)
      0.9% Normal saline (NSS) 154 0
      0.45% NSS + 5% dextrose 77 0
      0.18% NSS + 4% dextrose 30 0
      Hartmann’s 131 5
      5% dextrose 0 0

      1000 mL of 5% dextrose has 50 g of glucose

      Option B is inadequate for his sodium and caloric requirements (30 mmol of Na+ and 560 kcal). It is adequate for his K+ requirement (120 mmol of K+).

      Option C is in excess of his Na+ requirement (462 mmol of Na+). Moreover, it does not provide any K+ replacement.

      Option D is inadequate for his caloric requirement (600 kcal) and K+ requirement (60 mmol of K+). Moreover it does not provide any Na+ replacement.

      Option E is in excess of his Na+ requirement (393 mmol of Na+), and is inadequate for his potassium requirement (15 mmol of K+)

      Option A has adequate amounts for his Na+ (231 mmol of Na+) and K+ (120 mmol of K+) requirements. It is inadequate for his caloric requirement (600 kcal).

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 22 - A participant of a metabolism study is to be fed only granulated sugar...

    Incorrect

    • A participant of a metabolism study is to be fed only granulated sugar and water for 48 hours. What would be his expected respiratory quotient at the end of the study?

      Your Answer:

      Correct Answer: 1

      Explanation:

      The respiratory quotient is the ratio of CO2 produced to O2 consumed while food is being metabolized:

      RQ = CO2 eliminated/O2 consumed

      Most energy sources are food containing carbon, hydrogen and oxygen. Examples include fat, carbohydrates, protein, and ethanol. The normal range of respiratory coefficients for organisms in metabolic balance usually ranges from 1.0-0.7.

      Granulated sugar is a refined carbohydrate with no significant fat, protein or ethanol content.

      The RQ for carbohydrates is = 1.0

      The RQ for the rest of the compounds are:

      Fats RQ = 0.7
      The chemical composition of fats differs from that of carbohydrates in that fats contain considerably fewer oxygen atoms in proportion to atoms of carbon and hydrogen.

      Protein RQ = 0.8
      Due to the complexity of various ways in which different amino acids can be metabolized, no single RQ can be assigned to the oxidation of protein in the diet; however, 0.8 is a frequently utilized estimate.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 23 - Which of the following statement is true regarding the paediatric airway? ...

    Incorrect

    • Which of the following statement is true regarding the paediatric airway?

      Your Answer:

      Correct Answer: The larynx is more anterior than in an adult

      Explanation:

      In the neonatal stage, the tongue is usually large and comes to the normal size at the age of 1 year. The vocal cords lie inverse C4 and as it reaches the grown-up position inverse C5/6 by the age of 4 (not 1 year).

      Due to the immature cricoid cartilage, the larynx lies more anterior in newborn children. That’s why the cricoid ring is the narrowest part of the paediatric respiratory tract, while in the adults the tightest portion of the respiratory route is vocal cords. The epiglottis is generally expansive and slants at a point of 45 degrees to the laryngeal opening.

      The carina is the ridge of the cartilage in the trachea at the level of T2 in newborn (T4 in adults), that separates the openings of right and left main bronchi.

      Neonates have a comparatively low number of alveoli and then this number gradually increases to a most extreme by the age of 8 (not 3 years).

      Neonates are obligatory nose breathers and any hindrance can cause respiratory issues (e.g., choanal atresia).

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 24 - The single most important prerequisite for accuracy in measuring basal metabolic rate (BMR)...

    Incorrect

    • The single most important prerequisite for accuracy in measuring basal metabolic rate (BMR) using indirect calorimetry is performing the test:

      Your Answer:

      Correct Answer: In a neutral thermal environment

      Explanation:

      The basal metabolic rate (BMR) is the amount of energy required to maintain basic bodily functions in the resting state. The unit is Watt (Joule/second) or calories per unit time.

      Indirect calorimetry measures O2 consumption and CO2 production where gases are collected in a canopy which is the gold standard, Douglas bag, face-mask dilution technique or interfaced with a ventilator.

      The BMR can be calculated using the Weir formula:

      Metabolic rate (kcal per day) = 1.44 (3.94 VO2 + 1.11 VCO2)

      The BMR should be measured while lying down and at rest with the following conditions met:

      It should follow a 12 -hour fast
      No stimulants ingested within a 12-hour period
      It should be done in a neutral thermal environment (between 20°C-25°C)

    • This question is part of the following fields:

      • Physiology
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  • Question 25 - A mercury barometer can be used to determine absolute pressure. A mercury manometer...

    Incorrect

    • A mercury barometer can be used to determine absolute pressure. A mercury manometer can be used to check blood pressure. The SI units of length(mm) are used to measure pressure.

      Why is pressure expressed in millimetres of mercury (mmHg)?

      Your Answer:

      Correct Answer: Pressure is directly proportional to length of the mercury column and is variable

      Explanation:

      A mercury barometer can be used to determine absolute pressure. A glass tube with one closed end serves as the barometer. The open end is inserted into a mercury-filled open vessel. The mercury in the container is pushed into the tube by atmospheric pressure exerted on its surface. Absolute pressure is the distance between the tube’s meniscus and the mercury surface.

      Pressure is defined as force in newtons per unit area (F) (A). 

      Mass of mercury = area (A) × density (ρ) × length (L)
      Pressure = ((A × ρ × L) × 9.8 m/s2)/A
      Pressure = ρ × L x 9.8
      Pressure is proportional to L

      The numerator and denominator of the above equation, area (A), cancel out. The constants are density and the gravitational acceleration value.

      The length is proportional to the applied pressure.

    • This question is part of the following fields:

      • Physiology
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  • Question 26 - Regarding bilirubin, which one of the following statement is true? ...

    Incorrect

    • Regarding bilirubin, which one of the following statement is true?

      Your Answer:

      Correct Answer: Conjugated bilirubin is stored in the gall bladder

      Explanation:

      Bilirubin is the tetrapyrrole and a catabolic product of heme. 70-90% of bilirubin is end product of haemoglobin degradation in the liver.

      Bilirubin circulates in the blood in 2 forms; unconjugated and conjugated bilirubin.

      Unconjugated bilirubin is insoluble in water. It travels through the bloodstream to the liver, where it changes from insoluble into a soluble form (i.e.; unconjugated into conjugated form).

      This conjugated bilirubin travels from the liver into the small intestine and the gut bacteria convert bilirubin into urobilinogen and then into urobilin (not urobilin to urobilinogen). A very small amount passes into the kidneys and is excreted in urine.

    • This question is part of the following fields:

      • Physiology
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  • Question 27 - Useful diagnostic information can be obtained from measuring the osmolality of biological fluids....

    Incorrect

    • Useful diagnostic information can be obtained from measuring the osmolality of biological fluids.

      Of the following physical principles, which is the most accurate and reliable method of measuring osmolality?

      Your Answer:

      Correct Answer: Depression of freezing point

      Explanation:

      Colligative properties are properties of solutions that depend on the number of dissolved particles in solution. They do not depend on the identities of the solutes.

      All of the above have colligative properties with the exception of depression of melting point.

      The osmolality from the concentration of a substance in a solution is measured by an osmometer. The freezing point of a solution can determines concentration of a solution and this can be measured by using a freezing point osmometer. This is applicable as depression of freezing point is directly correlated to concentration.

      Vapour pressure osmometers, which measure vapour pressure, may miss certain volatiles such as CO2, ammonia and alcohol that are in the solution

      The use of a freezing point osmometer provides the most accurate and reliable results for the majority of applications.

      Colligative properties does not include melting point depression . Mixtures of substances in which the liquid phase components are insoluble, display a melting point depression and a melting range or interval instead of a fixed melting point.

      The magnitude of the melting point depression depends on the mixture composition.

      The melting point depression is used to determine the purity and identity of compounds. EMLA (eutectic mixture of local anaesthetics) cream is a mixture of lidocaine and prilocaine and is used as a topical local anaesthetic. The melting point of the combined drugs is lower than that individually and is below room temperature (18°C).

    • This question is part of the following fields:

      • Physiology
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  • Question 28 - In a normal healthy adult breathing 100 percent oxygen, which of the following...

    Incorrect

    • In a normal healthy adult breathing 100 percent oxygen, which of the following is the most likely cause of an alveolar-arterial (A-a) oxygen difference of 30 kPa?

      Your Answer:

      Correct Answer: Atelectasis

      Explanation:

      The ‘ideal’ alveolar PO2 minus arterial PO2 is the alveolar-arterial (A-a) oxygen difference.

      The ‘ideal’ alveolar PO2 is derived from the alveolar air equation and is the PO2 that the lung would have if there was no ventilation-perfusion (V/Q) inequality and it was exchanging gas at the same respiratory exchange ratio as real lung.

      The amount of oxygen in the blood is measured directly in the arteries.

      The A-a oxygen difference (or gradient) is a useful measure of shunt and V/Q mismatch, and it is less than 2 kPa in normal adults breathing air (15 mmHg). Because the shunt component is not corrected, the A-a difference increases when breathing 100 percent oxygen, and it can be up to 15 kPa (115 mmHg).

      An abnormally low or abnormally high V/Q ratio within the lung can cause an increased A-a difference, though the former is more common. Atelectasis, which results in a low V/Q ratio, is the most likely cause of an A-a difference in a healthy adult breathing 100 percent oxygen.

      Hypoventilation may cause an increase in alveolar (and thus arterial) CO2, lowering alveolar PO2 according to the alveolar air equation.

      The alveolar PO2 is also reduced at high altitude.

      Healthy people are unlikely to have a right-to-left shunt or an oxygen transport diffusion defect.

    • This question is part of the following fields:

      • Physiology
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  • Question 29 - Regarding the plateau phase of the cardiac potential, which electrolyte is the main...

    Incorrect

    • Regarding the plateau phase of the cardiac potential, which electrolyte is the main determinant?

      Your Answer:

      Correct Answer: Ca2+

      Explanation:

      The cardiac action potential has several phases which have different mechanisms of action as seen below:
      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology
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  • Question 30 - A patient on admission is given an infusion of 1000 mL of 10%...

    Incorrect

    • A patient on admission is given an infusion of 1000 mL of 10% glucose and 500 mL of 20% lipid over a 24 hour period.

      Which of these best approximates to the energy input over this time period?

      Your Answer:

      Correct Answer: 1300 kcal

      Explanation:

      1% solution contains 1 g of substance per 100 mL.

      A solution of 10% glucose is 10 g/100mL. Therefore 1000 mL of this glucose solution will contain 100 g.

      1 g of glucose yields about 4 kcal of energy. One litre of 10% glucose will therefore release approximately 4x100g = 400 kcal of energy.

      A solution of 20% fat is 20 g/100mL. Therefore 1000 mL of this fat solution will have 200 g and 500 mL will contain 100 g.

      1 g of fat yields approximately 9 kcal. 500 mL of 20% fat therefore has the potential to yield 900 kcal of energy.

      The total energy input over this 24 hour period is approximately 400kcal + 900kcal = 1300 kcal.

    • This question is part of the following fields:

      • Physiology
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