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  • Question 1 - For a rapid sequence induction of anaesthesia, you are pre-oxygenating a patient using...

    Incorrect

    • For a rapid sequence induction of anaesthesia, you are pre-oxygenating a patient using 100% oxygen and a fresh gas flow equal to the patient's minute ventilation.

      Which would be the most suitable choice of anaesthetic breathing system in this situation?

      Your Answer: Mapleson E system

      Correct Answer: Mapleson A system

      Explanation:

      The Mapleson A (Magill) and coaxial version of the Mapleson A system (Lack circuit) are more efficient for spontaneous breathing than any of the other Mapleson circuits. The fresh gas flow (FGF) required to prevent rebreathing is slightly greater than the alveolar minute ventilation (4-5 litres/minute). This is delivered to the patient through the outer coaxial tube and exhaust gases are moved to the scavenging system through the inner tube. In the Lack circuit, the expiratory valve is located close to the common gas outlet away from the patient end. This is the main advantage of the Lack circuit over the Mapleson A circuit.

      The Mapleson E circuit is a modification of the Ayres T piece and the FGF required to prevent rebreathing is 1.5-2 times the patient’s minute volume.

      The Bain circuit is the coaxial version of the Mapleson D circuit.

      The FGF for spontaneous respiration to avoid rebreathing is 160-200 ml/kg/minute.

      The FGF for controlled ventilation to avoid rebreathing is 70-100 ml/kg/min.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      36.1
      Seconds
  • Question 2 - In a diagnosis of a compensated respiratory acidosis, which of the following arterial...

    Incorrect

    • In a diagnosis of a compensated respiratory acidosis, which of the following arterial blood gas results is likely to be seen?

      Your Answer: pH = 7.34
      PaCO2 = 3.6 kPa
      HCO3 = 14

      Correct Answer:

      Explanation:

      During normal tissue metabolism, there is production of CO2 (acid) which is then expired by the lungs. If metabolism switches from aerobic to anaerobic due to a lack of oxygen, the tissues are unable to completely oxidise sugars to CO2. As a consequence, the sugars can only be partially oxidised to lactic acid. Since lactic acid cannot be expired by the lungs, it remains in the circulation leading to metabolic acidosis.

      Also, normal tissue metabolism leads to the production of some amount of acid from the breakdown of proteins. These acids are excreted from the body by kidney filtration. Renal failure will therefore results in acidosis after several days.

      An increased acidosis stimulates the brain’s respiratory centres to increase the respiratory rate. This lowers the CO2 in the blood, leading to a decrease in its acidity. Renal excretion removes the excess acid, resulting in a normal pH, and a reduced PaCO2 and HCO3.

      pH PaCO2 (kPa) HCO3
      Compensated respiratory acidosis 7.34 7.2 29
      Acute respiratory acidosis 7.25 7.3 22
      Compensated metabolic acidosis 7.34 3.6 14
      Metabolic acidosis 7.21 5.3 15
      Metabolic alkalosis 7.51 5.1 30

    • This question is part of the following fields:

      • Pathophysiology
      45.6
      Seconds
  • Question 3 - Which of the following statements below would best describe the receptor response to...

    Correct

    • Which of the following statements below would best describe the receptor response to an opioid mu receptor agonist such as fentanyl?

      Your Answer: Intrinsic activity determines maximal response

      Explanation:

      Agonists activate the receptor as a direct result of binding to it with a characteristic affinity. Moreover, intrinsic activity of an agonist to its receptor determines the ability to create a maximal response.

      Responses to low doses of a drug usually increase in direct proportion to dose. As doses increase, however, the response increment diminishes; finally, doses may be reached at which no further increase in response can be achieved. The relationship formed between the dose and response when plotted graphically is hyperbolic. This also shows that even at low receptor occupancy, a maximal response may be produced.

      Antagonists bind to receptors in the same affinity as agonists, but they have no intrinsic efficacy. They do not activate generation of signal. Instead, they interfere with the ability of the agonist to activate the receptor.

      Partial agonists are similar to full agonists in that they have similar affinity to the target receptor, but they produce a lower response than full agonists.

    • This question is part of the following fields:

      • Pharmacology
      36.1
      Seconds
  • Question 4 - A 72-year-old woman with a medical history of ischaemic heart disease, hypertension, and...

    Incorrect

    • A 72-year-old woman with a medical history of ischaemic heart disease, hypertension, and hypothyroidism was brought to ER with a change in her mental state over the past few hours. Medications used by her were hydrochlorothiazide, aspirin, ramipril, and levothyroxine.

      On physical examination, decreased skin turgor, orthostatic hypotension, and disorientation of time and place were found. There were no significant neurological signs.

      Initial biochemical tests are as follows:

      Na: 111 mmol/L (135-145)
      K: 4.1 mmol/L (3.5-5.1)
      Cl: 105 mmol/L (99-101)
      Bic: 29 mmol/L (22-29)
      Urea: 16.4 mmol/L (1.7-8.3)
      Creatinine: 320µmol/L (44-80)
      Glucose: 13.5mmol/L (3.5-5.5)
      Plasma osmolality: 278mOsm/kg
      Urinary osmolality: 450mOsm/kg
      TSH: 6.2 miu/L (0.1-6.0)
      Free T4: 10.1 pmol/L (10-25)
      Free T3: 1.4nm/L (1.0-2.5)

      Which of the following is most likely cause for this condition of the patient?

      Your Answer: Hyperglycaemia

      Correct Answer: Drug idiosyncrasy

      Explanation:

      Based on the laboratory reports, the patient is suffering from significant hyponatremia. The symptoms of hyponatremia are mainly neurological and depend on the severity and rapidity of onset of hyponatremia.

      Patient symptom according to the hyponatremia level is correlated below:

      125 – 130mmol/L – Nausea and malaise
      115 – 125mmol/L – Headache, lethargy, seizures, and coma
      <120mmol/L - Up to 11% present with coma.

    • This question is part of the following fields:

      • Pathophysiology
      81.5
      Seconds
  • Question 5 - Which statement is true of albumin? ...

    Incorrect

    • Which statement is true of albumin?

      Your Answer: Is negatively charged

      Correct Answer: Is synthesised and stored in the liver

      Explanation:

      Major surgery induces the systemic inflammatory response and this causes endothelial leakage and a low albumin level.

      Albumin is a single polypeptide which is made but not stored in the liver. Therefore, levels are a reflection of synthetic activity. It is negatively charged and very soluble.

      Only 40% of albumin is intravascular, and the rest in the in interstitial compartment.

      If there was normal liver function during starvation, albumin will be maintained and proteolysis will occur elsewhere.
      It is not catabolised during starvation.
      Starvation and malnutrition may, however, present as part of other disease processes that are associated with hypalbuminaemia.

      Causes of low albumin are

      1. Decreased production (hepatic dysfunction)
      2. Increased loss (renal dysfunction)
      3. Redistribution (endothelial leak/damage)
      4. Increased catabolism (very rare)

    • This question is part of the following fields:

      • Physiology And Biochemistry
      20.3
      Seconds
  • Question 6 - One of the commonest risks associated with a retrobulbar block for ophthalmic surgery...

    Correct

    • One of the commonest risks associated with a retrobulbar block for ophthalmic surgery is the injury to orbital structures within the tendinous ring.

      The structure which passes through the superior orbital fissure and tendinous ring to enter the orbit is?

      Your Answer: Superior division of oculomotor nerve

      Explanation:

      From superior to inferior, the following structures enter the orbit through the superior orbital fissure:
      1. Lacrimal nerve
      2. Frontal nerve
      3. Superior ophthalmic vein
      4. Trochlear nerve
      5. Superior division of the oculomotor nerve*
      6. Nasociliary nerve*
      7. Inferior division of the oculomotor nerve*
      8. Abducent nerve*
      9. Inferior ophthalmic vein.

      The superior and inferior division of the oculomotor nerve, nasociliary nerve, and abducent nerve are within the tendinous ring.

      The common origin of the four rectus muscles is the tendinous ring (also known as the annulus of Zinn). The tendinous ring’s lateral portion straddles the superior orbital fissure, while the medial portion encloses the optic foramen, through which the optic nerve and ophthalmic artery pass.

    • This question is part of the following fields:

      • Pathophysiology
      22.3
      Seconds
  • Question 7 - Clearance techniques are used to assess renal glomerular function.

    Which of the following is...

    Incorrect

    • Clearance techniques are used to assess renal glomerular function.

      Which of the following is the most accurate marker for glomerular filtration rate measurement?

      Your Answer: Urinary clearance of 125I-iothalamate

      Correct Answer: Inulin

      Explanation:

      The perfect glomerular filtration marker is:

      The human body is not harmed by it.
      Chemical or physical methods are used to accurately measure
      Extracellular fluid (ECF) compartment is freely and evenly diffusible.
      Inability to access the intracellular fluid (ICF) compartment
      Filtration in the kidney is the only way to remove it from the blood.

      The ideal marker should not be reabsorbed into the bloodstream by the renal tubules or other urinary system components.

      Creatinine is an endogenous substance that is filtered freely by the glomerulus and secreted by the proximal tubule. As a result, creatinine clearance consistently underestimates GFR. In healthy people, this overestimation ranges from 10% to 40%, but it is higher and more unpredictable in patients with chronic kidney disease.

      The gold standard method of inulin clearance necessitates an intravenous infusion and several hours of timed urine collection, making it costly and time-consuming. Inulin is hard to come by and is difficult to mix and keep as a solution.

      Exogenous filtration markers include the following:

      Although plasma clearance of 51chromium EDTA is a widely used method in Europe, tubular reabsorption can occur.
      Because 125I-iothalamate can be excreted by renal tubules in the urine, it cannot be used in patients who have an iodine assay.

      Radioactive substances must be stored, administered, and disposed of according to these methods.

      The glomerulus filters para-aminohippuric acid (PAH) freely, and any that remains in the peritubular capillaries is secreted into the proximal convoluted tubules. This marker is used to determine the amount of blood flowing through the kidneys.

    • This question is part of the following fields:

      • Pathophysiology
      14.5
      Seconds
  • Question 8 - A 24-year-old female, presents to the emergency department via ambulance. She has just...

    Correct

    • A 24-year-old female, presents to the emergency department via ambulance. She has just been involved in a car accident. She is examined and undergoes various diagnostic investigations. Her X-ray report states that a fracture was noted on the surgical neck of her humerus.

      What structure is most likely to the damaged as a result of a surgical neck fracture of the humerus?

      Your Answer: Axillary nerve

      Explanation:

      Fractures to the surgical neck of the humerus are common place as it is the weakest point of the proximal humerus bone.

      The structures most likely to be damaged are the axillary nerve and the posterior circumflex humeral artery as they surround the surgical neck.

      The radial nerve runs along the radial groove, so injury to it would likely occur with a mid-shaft fracture of the humerus.

      The brachial artery is most likely to be injured as a result of a supracondylar fracture of the humerus which increases the risk of volkmaan’s ischemic contractures.

      Injury to the musculocutaneous nerve is least likely to happen and it very uncommon.

    • This question is part of the following fields:

      • Anatomy
      40.8
      Seconds
  • Question 9 - Regarding the treatment of bladder cancer, a study concerned with the usage of...

    Incorrect

    • Regarding the treatment of bladder cancer, a study concerned with the usage of a combined or monotherapy was conducted. A forest plot was used for the visual representation of the data.

      Which of the following is true regarding forest plots?

      Your Answer: Forest plots cannot tell you if the outcome is significant

      Correct Answer: Forest plots can present data from multiple studies

      Explanation:

      Being the part of a meta analysis, forest plots are more valued as evidence then randomised control trials.

      The notion that forest plots can only be used if the results are substantial is not true. They are good indicators of the significance of the data. If the diamond intersects the central line, the data is rendered significant. It also aggregates means and confidence intervals from studies conducted in the past which makes the study much more reliable as errors associated with individual studies tend to have less of an impact in this way.

      The suggestion that forest plots are primarily used for qualitative data is factually incorrect. Forest plots require numerical values to function.

      All in all, forest plots help us in determining whether or not there is a significant trend in that particular field of study.

    • This question is part of the following fields:

      • Statistical Methods
      48.9
      Seconds
  • Question 10 - You've been summoned to the recovery room to examine a 28-year-old man who...

    Incorrect

    • You've been summoned to the recovery room to examine a 28-year-old man who has had an inguinal hernia repaired.

      His vital signs are normal, but you notice that he has developed abnormal upper-limb movements due to muscle contractions that cause repetitive twisting movements.

      What do you think is the most likely source for this patient's condition?

      Your Answer: Tramadol

      Correct Answer: Prochlorperazine

      Explanation:

      Dystonia is characterised by repetitive twisting movements or abnormal postures. They are classified as either primary or secondary.

      Primary dystonia is a genetic disorder that is inherited in an autosomal dominant pattern.
      Secondary dystonia can be caused by focal brain lesions, Parkinson’s disease, or certain medications.

      The following drugs cause the most common drug-induced dystonic reactions:
      Antipsychotics, antiemetics (especially prochlorperazine and metoclopramide), and antidepressants.

      Following the administration of the neuroleptic prochlorperazine, 16 percent of patients experience restlessness (akathisia) and 4% experience dystonia.

      Several published reports have linked the anaesthetics thiopentone, fentanyl, and propofol to opisthotonos and other abnormal neurologic sequelae. Dystonias following a general anaesthetic are uncommon. Tramadol has been linked to serotonin syndrome, while remifentanil has been linked to muscle rigidity.

      The following are some of the risk factors:

      Positive family history
      Male
      Children
      An episode of acute dystonia occurred previously.
      Dopamine receptor (D2) antagonists at high doses and recent cocaine use

      Dystonia is treated in a variety of ways, including:

      Benztropine (as a first-line therapy):

      1-2 mg intravenous injection for adults
      Child: 0.02 mg/kg to 1 mg maximum

      Benzodiazepines are a type of benzodiazepine (second line treatment).

      Midazolam:

      1-2 mg intravenously, or 5-10 mg IV/PO diazepam

      Antihistamines with anticholinergic activity (H1receptor antagonists):

      Promethazine 25-50 mg IV/IM, or diphenhydramine 50 mg IV/IM (1 mg/kg in children) are used when benztropine is not available.

    • This question is part of the following fields:

      • Pharmacology
      41.5
      Seconds
  • Question 11 - During a fight, a 20-year-old male is stabbed in the thigh with a...

    Correct

    • During a fight, a 20-year-old male is stabbed in the thigh with a bottle. He is admitted for treatment.

      Which feature, if present, suggests an injury to the femoral nerve?

      Your Answer: Loss of knee reflex

      Explanation:

      Femoral nerve lesion (L2,L3 and L4) is characterised by weakness of the quadriceps femoris muscle. This results in weakness of extension of the knee, loss of sensation over the front of the thigh, and loss of the knee jerk reflex.

      The skin over the lateral aspect of the thigh and knee, and the lower lateral quadrant of the buttock is supplied by the lateral cutaneous nerve of the thigh (L1,2).

      The adductors of the hip are supplied by the obturator nerve (L2-4). This nerve also supplies sensation to the inner thigh.

    • This question is part of the following fields:

      • Anatomy
      31.5
      Seconds
  • Question 12 - Which structure does NOT lie in the posterior triangle of the neck? ...

    Incorrect

    • Which structure does NOT lie in the posterior triangle of the neck?

      Your Answer: Phrenic nerve

      Correct Answer: Internal jugular vein

      Explanation:

      The sternocleidomastoid muscle divides the neck into anterior and posterior triangles on both sides of the neck.

      The posterior triangle has the following boundaries:
      anteriorly – sternocleidomastoid muscle
      posteriorly – trapezius
      roof – investing layer of deep cervical fascia
      floor – prevertebral fascia overlying splenius capitis, levator scapulae, and the scalene muscles

      The contents of the posterior triangle are:
      1. fat
      2. lymph nodes (level V)
      3. accessory nerve
      4. cutaneous branches of the cervical plexus (A major branch of this plexus is the phrenic nerve, which arises from the anterior divisions of spinal nerves C3-C5)
      5. inferior belly of omohyoid
      6. branches of the thyrocervical trunk (transverse cervical and suprascapular arteries)
      7. third part of the subclavian artery
      8. external jugular vein

    • This question is part of the following fields:

      • Anatomy
      24.7
      Seconds
  • Question 13 - Which of the following statements is not correct regarding dopamine? ...

    Correct

    • Which of the following statements is not correct regarding dopamine?

      Your Answer: Crosses the blood brain barrier

      Explanation:

      Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic ? and?1 (but not ?2 ) agonist.

      The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of DA dilates these vessels (by raising intracellular cAMP). This increases g.f.r. In addition, DA exerts a natriuretic effect by D1 receptors on proximal tubular cells.

      Moderately high doses produce a positive inotropic (direct?1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.

      Vasoconstriction (?1 action) occurs only when large doses are infused.

      At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.

      Dopamine is used in patients with cardiogenic or septic shock and severe CHF wherein it increases BP and urine outflow.

      It is administered by i.v. infusion (0.2–1 mg/min) which is regulated by monitoring BP and rate of urine formation

    • This question is part of the following fields:

      • Pharmacology
      41.3
      Seconds
  • Question 14 - The half-empty cylinder weighs 4.44 kg.
    The tare weight of a nitrous...

    Correct

    • The half-empty cylinder weighs 4.44 kg.
      The tare weight of a nitrous oxide cylinder is 4 kg.
      The molecular weight of nitrous oxide is 44gm.

      Based on the data, how many litres of nitrous oxide remains in the cylinder for use?

      Your Answer: 224 litres

      Explanation:

      The Tare weight of a cylinder is the weight when it is empty. So,

      Weight of cylinder – tare weight = weight of remaining N2O (g).
      4.44 kg – 4 kg = 0.44 kg
      Here,
      0.44 kg of nitrous oxide remains in the cylinder

      Since the molecular weight of nitrous oxide is 44 g and one mole of an ideal gas will occupy a volume of 22.4 litres at STP
      Therefore amount left in the cylinder is several (gN2O/44) x 22.4 litres of N2O.

      (440/44) x 22.4 = 224 litres.

    • This question is part of the following fields:

      • Basic Physics
      32.4
      Seconds
  • Question 15 - A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure,...

    Correct

    • A 53-year-old-male is being operated on for a right hemicolectomy. In the procedure, the ileocolic artery is ligated. Which vessel does this artery originate from?

      Your Answer: Superior mesenteric artery

      Explanation:

      The ileocolic artery is the terminal branch of the superior mesenteric artery. It supplies:
      1. terminal ileum
      2. proximal right colon
      3. cecum
      4. appendix (via its branch of the appendicular artery)

      As veins accompany arteries in the mesentery and are lined by lymphatics, high ligation is the norm in cancer resections—the ileocolic artery branches off the SMA near the duodenum.

    • This question is part of the following fields:

      • Anatomy
      22.8
      Seconds
  • Question 16 - A survey aimed at finding out mean glucose level in individuals that took...

    Incorrect

    • A survey aimed at finding out mean glucose level in individuals that took antipsychotics medicines was conducted. The results were as follows:

      Mean Value: 7mmol/L

      Standard Deviation: 6mmol/L

      Sample Size: 9

      Standard Error: 2mmol/L

      For a confidence interval of 95%, which of the option presents the correct range up to the nearest value?

      Your Answer: 1-7 mmol/L

      Correct Answer: 3-11 mmol/L

      Explanation:

      Key Point: While finding out confidence intervals, standard errors are used. Standard error and Standard deviation are two distinct entities and should not be confused.

      For 99.7% confidence interval, you can find the range as follows:

      Multiply the standard error by 3.

      Subtract the answer from mean value to get the lower limit.

      Add the answer obtained in step 1 from the mean value to get the upper limit.

      The range turns out to be 1-13 mmol/L.

      For a confidence interval of 68%, multiply the standard error with 1 and repeat the process. The range found for this interval is 3-11 mmol/L.

      For a 95% confidence interval. Standard Error is multiplied by 1.96 which gives us the limit ranging from 3.08 to 10.92 mmol/L which could be approximated to 3-11 mmol/L.

    • This question is part of the following fields:

      • Statistical Methods
      48.2
      Seconds
  • Question 17 - A 78-year-old man with a previous history of ischaemic heart disease is admitted...

    Correct

    • A 78-year-old man with a previous history of ischaemic heart disease is admitted to hospital. He is scheduled for a cardiopulmonary exercise test (CPX) before he undergoes an elective abdominal aneurysm repair.

      What measurement obtained during a CPX test alone provides the best indication for postoperative mortality?

      Your Answer: Anaerobic threshold

      Explanation:

      Cardiopulmonary exercise testing (CPX, CPEX, CPET) is a non-invasive testing method used to determine the performance of the heart, lungs and skeletal muscle. It measures the exercise tolerance of the patient.

      The parameters measured include:

      ECG and ST-segment analysis and blood pressure
      Oxygen consumption (VO2)
      Carbon dioxide production (VCO2)
      Gas flows and volumes
      Respiratory exchange ratio (RER)
      Respiratory rate
      Anaerobic threshold (AT)

      The anaerobic threshold (AT) is an estimate of exercise ability. Any measurement below 11 ml/kg/min is usually related with an increase in mortality, especially when there is a background of myocardial ischaemia occurring during the test.

      Peak VO2 <20 mL/kg with a low AT have a correlation with postoperative complications and a 30 day mortality. The CPX test is used for risk-testing patients prior to surgery to determine the appropriate postoperative care facilities. The V slope measured in CPX testing represents VO2 versus VCO2 relationship. During AT, the ramp of V slope increases, but does not provide a picture of postoperative mortality.

    • This question is part of the following fields:

      • Clinical Measurement
      25.6
      Seconds
  • Question 18 - At 37 weeks' gestation, a 29-year-old parturient is admitted to the labour ward....

    Correct

    • At 37 weeks' gestation, a 29-year-old parturient is admitted to the labour ward. Her antenatal period was asymptomatic for her.

      The haematological values listed below are available:

      Hb concentration of 100 g/L (115-165)
      200x109/L platelets (150-400)
      MCV 81 fL (80-96)

      Which of the following is the most likely reason for the problem?

      Your Answer: Iron deficiency

      Explanation:

      This patient’s limited haematological profile includes mild normocytic anaemia and a normal platelet count.

      Iron deficiency is the most common cause of anaemia during pregnancy. It affects 75 to 95 percent of patients. A haemoglobin level of less than 110 g/L in the first trimester and less than 105 g/L in the second and third trimesters is considered anaemia. There will usually be a low mean cell volume (MCV), mean cell haemoglobin (MCH), and mean cell haemoglobin concentration in addition to a low haemoglobin (MCHC). The MCV may be normal in mild cases of iron deficiency or coexisting vitamin B12 and folate deficiency.

      To determine whether you have an iron deficiency, you’ll need to take more tests. Low serum ferritin (15 g/L) and less reliable indices like serum iron and total iron binding capacity are among them.

      A number of factors contribute to iron deficiency in pregnancy, including:

      Insufficient dietary iron to meet the mother’s and foetus’ nutritional needs
      Multiple pregnancies
      Blood loss, as well as
      Absorption of iron from the gut is reduced.

      The volume of plasma increases by about 50% during pregnancy, but the mass of red blood cells (RBCs) increases by only 30%. Dilutional anaemia is the result of this situation. From the first trimester to delivery, the RBC mass increases linearly, while the plasma volume plateaus, stabilises, or falls slightly near term. As a result, between 28 and 34 weeks of pregnancy, haemoglobin concentrations are at their lowest. The effects of haemodilution will be negated in this patient because she is 37 weeks pregnant.

      Vitamin B12 and folate deficiency are less common causes of anaemia in pregnancy. The diagnosis could be ruled out if the MVC is normal.

      During pregnancy, the platelet count drops, especially in the third trimester. Gestational thrombocytopenia is the medical term for this condition. It’s due to a combination of factors, including haemodilution and increased platelet activation and clearance. Pre-eclampsia and HELLP syndrome are common causes of thrombocytopenia. Pre-eclampsia isn’t the only cause of anaemia during pregnancy.

      A typical blood picture of a haemoglobinopathy like sickle cell disease shows quantitative and qualitative defects, with the former leading to a severe anaemia exacerbated by haemodilution and other factors that contribute to iron deficiency. Microcytic cells are the most common type.

    • This question is part of the following fields:

      • Pathophysiology
      29.7
      Seconds
  • Question 19 - Which of the following is true about the patellar reflex? ...

    Correct

    • Which of the following is true about the patellar reflex?

      Your Answer: Is abolished immediately after transection of the spinal cord at T6

      Explanation:

      The patellar (knee jerk) reflex is a monosynaptic stretch reflex arising from L2-L4 nerve roots. It occurs after a tap on the patellar tendon which causes the spindles of the quadriceps muscles to stretch.

      The afferent nerve pathway occurred through A gamma fibres.

      Wesphal’s sign refers to a reduction, or absence of the patellar reflex. It is often indicated of a neurological disease affecting the PNS.

      A transection of the spinal cord results in a degree of shock which causes all reflexes to be reduced or completely absent, and required a period of approximately 6 weeks to recover.

    • This question is part of the following fields:

      • Pathophysiology
      24.8
      Seconds
  • Question 20 - All of the following are responses to massive haemorrhage except which of the...

    Incorrect

    • All of the following are responses to massive haemorrhage except which of the following?

      Your Answer: Adrenal cortex releases Aldosterone

      Correct Answer: Decreased cardiac output by increased direct parasympathetic stimulation

      Explanation:

      With regards to compensatory response to blood loss, the following sequence of events take place:

      1. Decrease in venous return, right atrial pressure and cardiac output
      2. Baroreceptor reflexes (carotid sinus and aortic arch) are immediately activated
      3. There is decreased afferent input to the cardiovascular centre in medulla. This inhibits parasympathetic reflexes and increases sympathetic response
      4. This results in an increased cardiac output and increased SVR by direct sympathetic stimulation. There is increased circulating catecholamines and local tissue mediators (adenosine, potassium, NO2)
      5. Fluid moves into the intravascular space as a result of decreased capillary hydrostatic pressure absorbing interstitial fluid.

      A slower response is mounted by the hypothalamus-pituitary-adrenal axis.
      6. Reduced renal blood flow is sensed by the intra renal baroreceptors and this stimulates release of renin by the juxta-glomerular apparatus.
      7. There is cleavage of circulating Angiotensinogen to Angiotensin I, which is converted to Angiotensin II in the lungs (by Angiotensin Converting Enzyme ACE)

      Angiotensin II is a powerful vasoconstrictor that sets off other endocrine pathways.
      8. The adrenal cortex releases Aldosterone
      9. There is antidiuretic hormone release from posterior pituitary (also in response to hypovolaemia being sensed by atrial stretch receptors)
      10. This leads to sodium and water retention in the distal convoluted renal tubule to conserve fluid
      Fluid conservation is also aided by an increased amount of cortisol which is secreted in response to the increase in circulating catecholamines and sympathetic stimulation.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      51
      Seconds
  • Question 21 - A 58-year-old man, visits his general practitioner complaining of a lump in his...

    Correct

    • A 58-year-old man, visits his general practitioner complaining of a lump in his groin. He explains he is otherwise well and reports no other symptoms. The lump is examined and is found to be soft, and can be reduced without causing the patient pain. The GP diagnoses an inguinal hernia. To determine the nature of the hernia, the GP reduced the lump and applies pressure on the deep inguinal ring.

      The deep inguinal ring has what anatomical landmark?

      Your Answer: Superior to the midpoint of the inguinal ligament

      Explanation:

      The deep inguinal ring lies approximately 1.5-2cm above the midpoint of the inguinal ligament, the halfway point between the anterior superior iliac spine and the pubic tubercle, next to the epigastric vessels.

      It is an important point in determining the nature of an inguinal hernia (direct or indirect). The patient is asked to cough after the hernia is reduced, with pressure applied to the deep inguinal ring. The hernia reappearing indicates it is direct, moving through the posterior wall of the inguinal canal.

      Inferior and lateral to the pubic tubercle is the normal anatomical position of the neck of a femoral hernia.

      Superior and medial to the pubic tubercle is the site of the superficial inguinal ring, and the normal anatomical position of the neck of an inguinal hernia.

      The mid-inguinal point is located halways between the pubic symphysis and the anterior superior iliac spine. It is the surface marking for taking the femoral pulse.

    • This question is part of the following fields:

      • Anatomy
      108.9
      Seconds
  • Question 22 - At sea level, Sevoflurane is administered via a plenum vaporiser. 100 mL of...

    Incorrect

    • At sea level, Sevoflurane is administered via a plenum vaporiser. 100 mL of the fresh gas flow is bypassed into the vaporising chamber. Temperature within the vaporising chamber is maintained at 20°C.

      The following fresh gas flows approximates best for the delivery of 1% sevoflurane.

      Your Answer: 270 mL/minute

      Correct Answer: 2.7 L/minute

      Explanation:

      The equation for calculating vaporiser output is:

      Vaporiser output (VO) mL = Carrier gas flow (mL/minute) × SVP of agent (kPa)
      Ambient pressure (kPa) − SVP of agent (kPa)

      The saturated vapour pressure of sevoflurane at 1 atm (100 kPa) and 20°C is 21 kPa.

      VO = (100 mL × 21 kPa)/(100 kPa − 21kPa) for sevoflurane,
      VO = 26.6 mL

      26.6 mL of 100% sevoflurane and 100 mL bypass carrier gas is being added to the fresh gas flow per minute.

      2660 mL of 1% sevoflurane and 100 mL bypass carrier gas is approximately 2.7 L/minute.

    • This question is part of the following fields:

      • Pharmacology
      64.3
      Seconds
  • Question 23 - All of the following are causes of hypalbuminaemia except: ...

    Correct

    • All of the following are causes of hypalbuminaemia except:

      Your Answer: Starvation

      Explanation:

      Major surgery induces the systemic inflammatory response and this causes endothelial leakage and a low albumin level.

      Albumin is a single polypeptide which is made but not stored in the liver. Therefore, levels are a reflection of synthetic activity. It is negatively charged and very soluble.

      Only 40% of albumin is intravascular, and the rest in the in interstitial compartment.

      If there was normal liver function during starvation, albumin will be maintained and proteolysis will occur elsewhere.
      It is not catabolised during starvation.
      Starvation and malnutrition may, however, present as part of other disease processes that are associated with hypalbuminaemia.

      Causes of low albumin are

      1. Decreased production (hepatic dysfunction)
      2. Increased loss (renal dysfunction)
      3. Redistribution (endothelial leak/damage)
      4. Increased catabolism (very rare)

    • This question is part of the following fields:

      • Physiology And Biochemistry
      24.1
      Seconds
  • Question 24 - One litre of water at 0°C and a pressure of 1 bar is...

    Incorrect

    • One litre of water at 0°C and a pressure of 1 bar is in a water-bath. A 1 kW element is used in heating it.

      Given that the specific heat capacity of water is 4181 J/(kg°C) or J/(kg K), how long will it take to raise the temperature of the water by 10°C?

      Your Answer: 7 minutes

      Correct Answer: 42 seconds

      Explanation:

    • This question is part of the following fields:

      • Physiology
      177.1
      Seconds
  • Question 25 - Which of the following statements is true with regards to 2,3-diphosphoglycerate (2,3-DPG)? ...

    Incorrect

    • Which of the following statements is true with regards to 2,3-diphosphoglycerate (2,3-DPG)?

      Your Answer: Production is increased in primary polycythaemia

      Correct Answer: Production is increased in heart failure

      Explanation:

      During glycolysis, 2,3-diphosphoglycerate (2,3-DPG) is
      created in erythrocytes by the Rapoport-Luebering shunt.

      The production of 2,3-DPG increases for several conditions
      in the presence of decreased peripheral tissue O2 availability.
      Some of these conditions include hypoxaemia, chronic lung
      disease anaemia, and congestive heart failure. Thus,
      2,3-DPG production is likely an important adaptive mechanism.

      High levels of 2,3-DPG cause a shift of the curve to the right.
      Low levels of 2,3-DPG cause a shift of the curve to the left,
      as seen in states such as septic shock and hypophosphatemia.

    • This question is part of the following fields:

      • Physiology
      19.5
      Seconds
  • Question 26 - Following an acute appendicectomy, a 6-year-old child is admitted to the recovery unit.

    Your...

    Correct

    • Following an acute appendicectomy, a 6-year-old child is admitted to the recovery unit.

      Your consultant has requested that you prescribe maintenance fluids for the next 12 hours. The child is 21 kg in weight.

      What is the most suitable fluid volume to be prescribed?

      Your Answer: 732 ml

      Explanation:

      After a paediatric case, you’ll frequently have to calculate and prescribe maintenance fluids. The ‘4-2-1 rule’ should be used as a guideline:

      1st 10 kg – 4 ml/kg/hr
      2nd 10 kg – 2 ml/kg/hr
      Subsequent kg – 1 ml/kg/hr

      Hence

      1st 10 kg = 4 × 10 = 40 ml
      2nd 10 kg = 2 × 10 = 20 ml
      Subsequent kg = 1 × 1 = 1 ml
      Total = 61 ml/hr

      61 × 12 = 732 ml over 12 hrs.

    • This question is part of the following fields:

      • Physiology
      46.5
      Seconds
  • Question 27 - A study of blood pressure measurements is being performed in patients with chronic...

    Correct

    • A study of blood pressure measurements is being performed in patients with chronic kidney disease.

      Considering that the results are normally distributed, what percentage of values lie within two standard deviations of the mean blood pressure reading?

      Your Answer: 95.40%

      Explanation:

      Normal distribution, also called Gaussian distribution, the most common distribution function for independent, randomly generated variables, and describes the spread for many biological and clinical measurements.

      Properties of the Normal distribution

      symmetrical i.e. Mean = mode = median

      68.3% of values lie within 1 SD of the mean

      95.4% of values lie within 2 SD of the mean

      99.7% of values lie within 3 SD of the mean

      The empirical rule, or the 68-95-99.7 rule, tells you where most of the values lie in a normal distribution: Around 68% of values are within 1 standard deviation of the mean.

      Around 95% of values are within 2 standard deviations of the mean. Around 99.7% of values are within 3 standard deviations of the mean.
      the standard deviation (SD) is a measure of how much dispersion exists from the mean.

      SD = square root (variance)

      The empirical rule, or the 68-95-99.7 rule states where most of the values lie in a normal distribution. Around 68% of values fall within 1 S.D of the mean, about 95% within 2 S.D of the mean, and about 99.7% of values within 3 S.D of the mean. Therefore, 95.4% is the most reasonable answer if results are normally distributed.

    • This question is part of the following fields:

      • Statistical Methods
      27.7
      Seconds
  • Question 28 - Which statement is correct about the Mapleson anaesthetic breathing circuits? ...

    Correct

    • Which statement is correct about the Mapleson anaesthetic breathing circuits?

      Your Answer: Mapleson A is most efficient for spontaneous ventilation

      Explanation:

      Mapleson breathing system (or circuit) analysed five different arrangements of components of the breathing system:
      Mapleson A – It is the most efficient for spontaneous respiration. The flow of fresh gas required is 70-85 ml/kg/min, i.e., approximately 5-6 lit./min fresh gas flow for an average adult.
      Mapleson B and C – inefficient for both SV and PPV; requires gas flow of two to three times minute volume (100 ml/kg/min). Not commonly used but category C may be used for emergency resuscitation.
      Mapleson D – efficient for PPV at gas flow equivalent to patient’s minute volume; the Bain’s circuit is a coaxial version of the Mapleson D
      Mapleson E and F – for paediatric use; requires gas flow at two to three times the patient’s minute volume. The Mapleson F consists of an open-ended reservoir bag (Jackson-Rees modification).

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      22.9
      Seconds
  • Question 29 - With regards to devices for temperature management, all of these are used EXCEPT:...

    Correct

    • With regards to devices for temperature management, all of these are used EXCEPT:

      Your Answer: Thermistors use the resistance of a semiconductor bead which increases exponentially as the temperature increases

      Explanation:

      There are different types of temperature measurement. These include:

      Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially

      Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)

      Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature

      Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output

      Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.

    • This question is part of the following fields:

      • Clinical Measurement
      34.3
      Seconds
  • Question 30 - Regarding oxygen consumption, which of these organs has the highest consumption at rest?...

    Incorrect

    • Regarding oxygen consumption, which of these organs has the highest consumption at rest?

      Your Answer: Brain

      Correct Answer: Kidney

      Explanation:

      Oxygen delivery is related to blood flow as most of the oxygen binds to haemoglobin in red blood cells, although a small amount is dissolved in the plasma. Blood flow per 100 g of tissue is greatest in the kidneys.

      The following is the oxygen consumption rate of different organs in ml/minute/100g

      Hepatoportal = 2.2
      Kidney = 6.8
      Brain = 3.7
      Skin = 0.38
      Skeletal muscle = 0.18
      Heart = 11

    • This question is part of the following fields:

      • Pathophysiology
      9.2
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Anaesthesia Related Apparatus (1/2) 50%
Pathophysiology (3/7) 43%
Pharmacology (2/4) 50%
Physiology And Biochemistry (1/3) 33%
Anatomy (4/5) 80%
Statistical Methods (1/3) 33%
Basic Physics (1/1) 100%
Clinical Measurement (2/2) 100%
Physiology (1/3) 33%
Passmed