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  • Question 1 - In the United Kingdom, a new breast cancer screening test is being conducted...

    Incorrect

    • In the United Kingdom, a new breast cancer screening test is being conducted compared to the conventional use of mammography. This test predicts that if the breast cancer is diagnosed at an earlier stage, it could improve the survival rate but the overall results remains constant.

      This is an example of what kind of bias?

      Your Answer: Length time bias

      Correct Answer: Lead time bias

      Explanation:

      Recall bias introduced when participants in a study are systematically more or less likely to recall and relate information on exposure depending on their outcome status.

      In procedure bias, the researcher decides assignment of a treatment versus control and assigns particular patients to one group or the other non-randomly. This is unlikely to have occurred in this case, although it is not mentioned specifically.

      Self Selection or volunteer bias occur when those subjects are selected to participate in the study who are not the representative of the entire target population. those subjects may be from high socio-economic status and practice those activities or lifestyle that improves their health.

      Lead-time bias occurs when a disease is detected by a screening test at an earlier time point rather than it would have been diagnosed by its clinical appearance. In this bias, earlier detection improves the survival time in the intervention group.

    • This question is part of the following fields:

      • Statistical Methods
      32.5
      Seconds
  • Question 2 - At a pH of 7, pure water has an hydrogen ion concentration of?...

    Correct

    • At a pH of 7, pure water has an hydrogen ion concentration of?

      Your Answer: 100 nanomol/L

      Explanation:

      pH is the negative log to the base 10 of hydrogen ion concentration:

      So, what power produces the answer?

      pH = – log10 [H+]

      Making [H+] the subject:

      [H+] = 10-pH

      Substituting, [H+] = 10-7

      One nanomole = 1 x 10-9 or 0.000000001

      10-7 = 1x 0.0000001 or 10 x 0.00000001 or 100 x 0.000000001

      100 nanomole

    • This question is part of the following fields:

      • Basic Physics
      19.5
      Seconds
  • Question 3 - A 28-year-old girl, Sam, has suffered a road traffic accident. She is brought...

    Correct

    • A 28-year-old girl, Sam, has suffered a road traffic accident. She is brought to the emergency department and undergoes investigations and treatment.

      On X-ray of the humerus, she has a mid-shaft fracture.

      What structure is at the highest risk of damage with a mid-shaft humeral fracture?

      Your Answer: Radial nerve

      Explanation:

      Mid-shaft fractures of the humerus usually occur after a direct blow to the upper arm, which can occur after a fall or RTAs.
      The most important clinical significance of a mid-shaft humeral fracture is an injury to the radial nerve. The radial nerve originates from the brachial plexus and has roots of C5-T1. It crosses the spiral groove on the posterior side of the shaft of the humerus.
      On examination, the patient may have a wrist drop, loss or weakness of finger extension, and decreased or absent sensation to the posterior forearm, digits 1 to 3, and the radial half of the fourth digit.

      The humeral shaft has two compartments:
      1. Anterior:
      Brachial artery and vein
      Biceps brachii, brachialis, coracobrachialis
      Musculocutaneous, median, and ulnar nerves
      2. Posterior:
      Radial nerve
      Triceps

      Other significant nerve injuries are:
      1. Axillary nerve – surgical neck fracture of the humerus
      2. Brachial Artery – supracondylar fracture of the humerus
      3. Axillary artery – surgical neck fracture of the humerus, but is relatively uncommon

    • This question is part of the following fields:

      • Anatomy
      27.1
      Seconds
  • Question 4 - Following a near drowning accident, a 5-year-old child is admitted to the emergency...

    Incorrect

    • Following a near drowning accident, a 5-year-old child is admitted to the emergency department and advanced paediatric life support is started.

      What is the child's approximate weight, according to the preferred formulae of the Resuscitation Council (UK), the European Resuscitation Council, and the Royal College of Anaesthetists?

      Your Answer: 15-19 kg

      Correct Answer: 20-25kg

      Explanation:

      For estimating a child’s weight, the Resuscitation Council (UK) and European Resuscitation Council teach the following formula:

      Weight = (age + 4) × 2

      The weight of the child will be around 20 kg.

      This formula is used in the Primary FRCA exam by the Royal College of Anaesthetists.

      In ‘developed’ countries, the traditional ‘APLS formula’ for estimating weight in children based on age (wt in kg = [age+4] x 2) is acknowledged as underestimating weight by 33.4 percent on average, with the degree of underestimation increasing with increasing age.

      However, more recently, the APLS formula ‘Weight=3(age)+7’ has been found to provide a mean underestimate of only 6.9%. This formula is applicable to children aged 1 to 13 years.

      The estimated weight based on age using this formula is 25 kg.

    • This question is part of the following fields:

      • Physiology
      36.5
      Seconds
  • Question 5 - A 71-year-old man, presents with central crushing pain in his chest to the...

    Correct

    • A 71-year-old man, presents with central crushing pain in his chest to the emergency department. On examination, he complains of nausea and is notably sweating. On ECG, elevation in the ST-segment is noted in multiple chest leads, as well as sinus bradycardia. A myocardial infarction can cause a sinus bradycardia.

      The sinoatrial (SA) node and the atrioventricular (AV) node receive arterial supply from which vessel?

      Your Answer: Right coronary artery

      Explanation:

      The left marginal artery comes off the left circumflex artery, and runs alongside the heart.

      The left circumflex artery is one of the bifurcations of the left coronary artery, and eventually forms the left marginal artery.

      An occlusion in the left circumflex artery often results in a lateral MI.

      The right marginal artery originates from the right coronary artery.

      The left anterior descending artery (LAD) is another bifurcation of the left coronary artery. An occlusion in the LAD would often result in an anteroseptal MI as is diagnosed on ECG by noting changes in leads V1-V4.

      The right coronary artery originates from the right aortic sinus of the ascending aorta, and bifurcates to give rise to many branches, including the sinoatrial artery which supplies the sinoatrial (SA) node in 50-70% of cases, the artery of the atrioventricular (AV) node in 50-60% of cases, the right acute marginal artery which supplies the right ventricle. It also supplies the right atrium, interatrial septum and the posterior inferior third of the interventricular septum.

      Arrhythmias and inferior MI often occurs as a result of an occlusion in the right coronary artery, and can be diagnosed by ECG changes in leads II, III and aVF.

    • This question is part of the following fields:

      • Anatomy
      50
      Seconds
  • Question 6 - You are preparing to anaesthetize a 27-year-old woman for an acute diagnostic laparoscopy...

    Incorrect

    • You are preparing to anaesthetize a 27-year-old woman for an acute diagnostic laparoscopy to rule out appendicitis.

      She has no medical history and does not take any medications on a regular basis. You're going to do a quick sequence induction.

      Which method of preoxygenation is the most effective and efficient?

      Your Answer: Hudson mask with a fresh gas flow of 15 L/min

      Correct Answer: Mapleson A circuit with a fresh gas flow of 100 ml/kg

      Explanation:

      Professor Mapleson classified non-rebreathing circuits based on the position of the APL valve, which controls fresh gas flow.

      The Mapleson A (Magill) circuit is most effective in spontaneous breathing, requiring only 70-100 ml/kg (the patient’s minute volume) of fresh gas flow. The patient inhales fresh gas from the reservoir bag and tubing during inspiration. During expiration, the patient adds dead space gas (gas that hasn’t been exchanged) to the tubing and reservoir bag in addition to the fresh gas flow. At the patient’s end, alveolar gas is vented through the APL valve. During the expiratory pause, the fresh gas flow causes more gas to be released.

      The Mapleson A is inefficient during controlled ventilation. Venting occurs during inspiration rather than during the expiratory phase, as it does during spontaneous ventilation. As a result, unless a high fresh gas flow of >20 L/minute is used, alveolar gas is rebreathed.

      During spontaneous ventilation, the Mapleson D circuit is inefficient.

      The oxygen concentration in a Hudson mask is insufficient to allow for adequate pre-oxygenation.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      56
      Seconds
  • Question 7 - In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five...

    Correct

    • In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five minutes is indicated during in-hospital cardiac arrest due to ventricular fibrillation (VF) following three DC shocks.

      Which of the following indicates the most important reason for using epinephrine?

      Your Answer: Preferential distribution of blood to the coronary and cerebral circulation

      Explanation:

      Epinephrine is used for the treatment of cardiac arrest because it causes vasoconstriction via the alpha-adrenergic (?1) receptor. This vasoconstriction increases cerebral and coronary blood flow by increasing mean arterial, aortic diastolic, and cerebral pressures. Furthermore, epinephrine is also a?1 and ?2 adrenoreceptor agonist which shows inotrope, chronotrope, and bronchodilator effects.
      – Adrenaline is also used to prolong the duration of action and decrease the systemic toxicity of local anaesthetics.
      – Preferred route of adrenaline in patients with cardiac arrest is i.v. followed by intra-osseous and endotracheal

    • This question is part of the following fields:

      • Pathophysiology
      101.7
      Seconds
  • Question 8 - An 81-year old man was admitted to the Pulmonology Ward due to chronic...

    Correct

    • An 81-year old man was admitted to the Pulmonology Ward due to chronic obstructive airway disease (COPD) exacerbation. Upon physical examination, he was hypertensive at 140/90 mmHg, tachycardic at 114 beats per minute, and tachypnoeic at 33 breaths per minute.

      Arterial blood gas analysis was obtained and showed the following results:

      pH: 7.25 (Reference range: 7.35-7.45)
      PaO2: 73 mmHg (9.7 kPa) (Reference range: 11.3-12.6 kPa)
      PaCO2: 56 mmHg (7.5 kPa) (Reference range: 4.7-6.0 kPa)
      SaO2: 90%
      Standard bicarbonate: 29 mmol/L (Reference range: 20-28)
      BE: +4 mmol/L (± 2)

      Which of the following options has the most significant impact on his respiratory rate?

      Your Answer: CSF pH

      Explanation:

      The arterial blood gas analysis indicates presence of acute respiratory acidosis.

      Central chemoreceptors are located in the ventral medulla and respond directly to presence of hydrogen ions in the CSF. When stimulated, it causes an increase in respiratory rate.

      It is believed that hydrogen ions may be the only important direct stimulus for these neurons, however, CO2 is believed to stimulate these neurons secondarily by changing the hydrogen ion concentration.

      Changes in O2 concentration have virtually no direct effect on the respiratory centre itself to alter respiratory drive. Although, O2 changes do have an indirect effect by acting through the peripheral chemoreceptors.

    • This question is part of the following fields:

      • Pathophysiology
      88.7
      Seconds
  • Question 9 - Regarding the anatomical relations of the scalenus muscles, which of these is true?...

    Incorrect

    • Regarding the anatomical relations of the scalenus muscles, which of these is true?

      Your Answer: The phrenic nerve passes behind scalenus anterior

      Correct Answer: The trunks of the brachial plexus emerge from the lateral border of scalenus anterior

      Explanation:

      The ascending cervical artery lies media the phrenic nerve on scalenus anterior and can easily be mistaken for the phrenic nerve at operation.

      The phrenic nerve passes across scalenus anterior and medius inferiorly.

      The subclavian artery is separated from the vein by the scalenus anterior.

      The brachiocephalic vein is formed at the medial border of scalenus anterior by the subclavian vein and the internal jugular vein.

      Emerging from the lateral border of scalenus anterior are the trunks of the brachial plexus .

    • This question is part of the following fields:

      • Anatomy
      95.9
      Seconds
  • Question 10 - A 72-year-old female is diagnosed with acute mesenteric ischemia.

    On CT angiogram, the...

    Incorrect

    • A 72-year-old female is diagnosed with acute mesenteric ischemia.

      On CT angiogram, the origin of the superior mesenteric artery is stenosed.

      At which vertebra level does the superior mesenteric artery branch from the aorta?

      Your Answer: L3

      Correct Answer: L1

      Explanation:

      The superior mesenteric artery branches from the abdominal aorta just 1-2 cm below the origin of the celiac trunk. It lies posterior to the body of the pancreas and splenic vein and is separated from the aorta by the left renal vein. It passes forwards and inferiorly, anterior to the uncinate process of the pancreas and the third part of the duodenum, to enter the root of the small bowel mesentery and supply the midgut.

      The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:

      T10 – oesophageal opening in the diaphragm

      T12 – Coeliac trunk, aortic hiatus in the diaphragm

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta

    • This question is part of the following fields:

      • Anatomy
      13.1
      Seconds
  • Question 11 - Calcium homeostasis is regulated by parathormone (PTH).

    Which of the following PTH actions is...

    Incorrect

    • Calcium homeostasis is regulated by parathormone (PTH).

      Which of the following PTH actions is most likely to cause calcium to be released from bone?

      Your Answer: Direct simulation of osteoblasts

      Correct Answer: Indirect stimulation of osteoclasts

      Explanation:

      The hormone parathyroid hormone (PTH) and the receptor parathyroid hormone type 1 (PTH1-Rc) are important regulators of blood calcium homeostasis.

      PTH can cause a rapid release of calcium from the matrix in bone, but it also affects long-term calcium metabolism by acting directly on bone-forming osteoblasts (by binding to PTH1-Rc) and indirectly on bone-resorbing osteoclasts.

      PTH causes changes in the synthesis and/or activity of several proteins, including osteoclast-differentiating factor, also known as TRANCE or RANKL, when it acts on osteoblasts.

      RANK receptors are found on the cell surfaces of osteoclast precursors. The osteoclasts are activated when RANKL binds to the RANK receptors. Osteoclasts lack PTH receptors, whereas osteoblasts do. Osteoclasts are activated indirectly when the RANK receptor binds to the RANKL secreted by osteoblasts, resulting in bone resorption. PTH1 receptors are found in osteoclasts, but they are few.

      PTH activates G-protein coupled receptors in all target cells via adenylate cyclase.

      The PTH2 receptor is most abundant in the nervous system and pancreas, but it is not a calcium metabolism regulator. It is abundant in the septum, midline thalamic nuclei, several hypothalamic nuclei, and the dorsal horn of the spinal cord, as well as the cerebral cortex and basal ganglia. Expression in pancreatic islet somatostatin cells is the most prominent on the periphery.

      The distribution of the receptor is being used to test functional hypotheses. It may play a role in pain modulation and hypothalamic releasing-factor secretion control.

    • This question is part of the following fields:

      • Pathophysiology
      40.4
      Seconds
  • Question 12 - Which of these statements is true about spirometry? ...

    Correct

    • Which of these statements is true about spirometry?

      Your Answer: A capacity is the sum of two or more volumes

      Explanation:

      Functional residual capacity (FRC) is 1.7 to 3.5L/kg

      A capacity is the sum of two or more volumes. The total lung capacity (TLC) is total sum of the volume of gas present in all lung compartments upon maximum inspiration. It is represented mathematically as:

      Total lung capacity (TLC) = Vital capacity (VC) + Residual volume (RV)

      The residual volume (RV) is the volume of gas still present within the lung post maximum exhalation. It cannot be measured by spirometry, but can be using a body plethysmograph and also with the helium dilution technique.

      Closing capacity (CC) is the volume of gas within the lungs at which small airways close upon expiration. It increases with age and is especially important when it surpasses the FRC as it causes changes in ventilation/perfusion mismatch and hypoxia.
      In the supine position, a patient with a normal body mass index and no history of lung pathology, the CC equals the FRC at approximately 44, and at approximately 66 at standing position.

    • This question is part of the following fields:

      • Clinical Measurement
      66.7
      Seconds
  • Question 13 - Blood pressure monitoring is a requirement for in-patient care. Different factors can result...

    Correct

    • Blood pressure monitoring is a requirement for in-patient care. Different factors can result in an inaccurate blood pressure reading, including the damping of an arterial waveform.

      How does a damped arterial waveform affect blood pressure measurements?

      Your Answer: The systolic pressure is lower and the diastolic pressure higher with the same mean

      Explanation:

      Damping is the reduction of energy in a system achieved by reducing the amplitude of oscillations. It is necessary to some degree to prevent wave overshoots.

      Critical damping usually causes the system to be slow, so optimal damping is normally applied to provide a balance between speed and distortion.

      Damping can cause errors if excessive (overdamping) or inadequate (Underdamping). The amount of damping in a system can be determined using the damping coefficient (D), where:

      Undamped: 0
      Critically damped: 1
      Optimally damped: 0.64

      An overdamped system will cause an artificial decrease in the systolic blood pressure, and an artificial increase in the diastolic blood pressure.

      An underdamped system will cause an artificial increase in systolic blood pressure and an artificial decrease in diastolic blood pressure.

      Damping can be caused by a number of factors affecting different parts of the system, including:

      The tubing/cannula: The presence of air bubbles, increased blood viscosity or formation of blood clots.
      The diaphragm/tubing: Increased malleability/compliance
      The tubing: Presence of kinks, narrowing or too many ports of injection.

      The answer here is a damped system will have a low systolic pressure, a high diastolic pressure with a normal mean pressure.

    • This question is part of the following fields:

      • Clinical Measurement
      55
      Seconds
  • Question 14 - Which of the statements below best describe the total cerebral flow (CBF) in...

    Correct

    • Which of the statements below best describe the total cerebral flow (CBF) in an adult?

      Your Answer: Accounts for 15% of the cardiac output

      Explanation:

      While the brain only weighs 3% of the body weight, 15% of the cardiac output goes towards the brain.

      Between mean arterial pressures (MAP) of 60-130 mmHg, autoregulation of cerebral blood flow (CBF) occurs. Exceeding this, the CBF is maintained at a constant level. This is controlled mainly by the PaCO2 level, and the autonomic nervous system has minimal role.

      Beyond these limits, the CBF is directly proportional to the MAP, not the systolic blood pressure.

    • This question is part of the following fields:

      • Physiology
      40.4
      Seconds
  • Question 15 - The Fick principle can be used to determine the blood flow to any...

    Incorrect

    • The Fick principle can be used to determine the blood flow to any organ of the body.

      At rest, which one of these organs has the highest blood flow (ml/min/100g)?

      Your Answer: Brain

      Correct Answer: Thyroid gland

      Explanation:

      After the carotid body, the thyroid gland is the second most richly vascular organ in the body.

      The global blood flow to the thyroid gland can be measured using:
      1. Colour ultrasound sonography
      2. Quantitative perfusion maps using MRI of the thyroid gland using an arterial spin labelling (ASL) method.

      This table shows the blood flow to various organs of the body at rest:
      Organ Blood Flow(ml/minute/100g)
      Hepatoportal 58
      Kidney 420
      Brain 54
      Skin 13
      Skeletal muscle 2.7
      Heart 87
      Carotid body 2000
      Thyroid gland 560

    • This question is part of the following fields:

      • Physiology
      24.9
      Seconds
  • Question 16 - Which of the following statements is true regarding sucralfate? ...

    Incorrect

    • Which of the following statements is true regarding sucralfate?

      Your Answer: Is a simple compound formed from sulphated sucrose

      Correct Answer:

      Explanation:

      Sucralfate is an octasulfate of glucose to which Al(OH)3 has been added. It undergoes extensive cross-linking in an acidic environment and forms a polymer which adheres to the ulcer base for up to 6 hours and protects it from further erosion. Since it is not systemically absorbed it is virtually devoid of side effects. However, it may cause constipation in about 2% of cases due to the Aluminium component in it.

      Sucralfate does not have antibacterial action against Helicobacter pylori. However, Bismuth has antibacterial action due to its oligodynamic effect.

    • This question is part of the following fields:

      • Pharmacology
      64.9
      Seconds
  • Question 17 - This vertebrae can be easily differentiated from the rest because of its prominent...

    Correct

    • This vertebrae can be easily differentiated from the rest because of its prominent spinous process.

      Your Answer: C7

      Explanation:

      The spinous process is the part of a vertebrae that is directed posteriorly.

      Typical cervical vertebra have spinous processes that are small and bifid, except for C7, which has a long and prominent spinous process.

    • This question is part of the following fields:

      • Anatomy
      9.8
      Seconds
  • Question 18 - A 35-year old male is found to be bradycardic in the emergency room....

    Correct

    • A 35-year old male is found to be bradycardic in the emergency room. His cardiac muscle will most likely stay in a prolonged phase 4 state of the cardiac action potential. During phase 4 of the cardiac action potential, which of these occurs?

      Your Answer: Na+/K+ ATPase acts

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
      34.5
      Seconds
  • Question 19 - Which of the following best explains the association between smoking and lower oxygen...

    Incorrect

    • Which of the following best explains the association between smoking and lower oxygen delivery to tissues?

      Your Answer:

      Correct Answer: Left shift of the oxygen dissociation curve

      Explanation:

      Smoking is a major risk factor associated with perioperative respiratory and cardiovascular complications. Evidence also suggests that cigarette smoking causes imbalance in the prostaglandins and promotes vasoconstriction and excessive platelet aggregation. Two of the constituents of cigarette smoke, nicotine and carbon monoxide, have adverse cardiovascular effects. Carbon monoxide increases the incidence of arrhythmias and has a negative ionotropic effect both in animals and humans.

      Smoking causes an increase in carboxyhaemoglobin levels, resulting in a leftward shift in which appears to represent a risk factor for some of these cardiovascular complications.

      There are two mechanisms responsible for the leftward shift of oxyhaemoglobin dissociation curve when carbon monoxide is present in the blood. Carbon monoxide has a direct effect on oxyhaemoglobin, causing a leftward shift of the oxygen dissociation curve, and carbon monoxide also reduces the formation of 2,3-DPG by inhibiting glycolysis in the erythrocyte. Nicotine, on the other hand, has a stimulatory effect on the autonomic nervous system. The effects of nicotine on the cardiovascular system last less than 30 min.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 20 - One of the following neuromuscular blocking agents is the most potent: ...

    Incorrect

    • One of the following neuromuscular blocking agents is the most potent:

      Your Answer:

      Correct Answer: Vecuronium

      Explanation:

      The measure of drug potency or therapeutic response is the ED95. This is defined as the dose of a neuromuscular blocking drug required to produce a 95% depression of muscle twitch height. The ED50 and ED90 describe a depression of twitch height by 50% and 90% respectively.

      The ED95 (mg/kg) of the commonly used neuromuscular blocking agents are:

      suxamethonium: 0.27
      rocuronium: 0.31
      vecuronium: 0.04
      pancuronium: 0.07
      cisatracurium: 0.04
      mivacurium: 0.08

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 21 - A 5-year-old child is scheduled for squint surgery requiring general anaesthesia.

    To begin, she...

    Incorrect

    • A 5-year-old child is scheduled for squint surgery requiring general anaesthesia.

      To begin, she is given sevoflurane for the inhalation induction, then intravenous access is established along with the insertion of a supraglottic airway. Anaesthesia is maintained with fentanyl 1 mcg/kg, with an air/oxygen/sevoflurane mix with spontaneous respirations.

      Once the surgery begins, her pulse rate drastically reduces from 120 beats/min to 8 beats/min.

      What is the most appropriate next step for this patient?

      Your Answer:

      Correct Answer: Tell surgeon to stop surgical retraction

      Explanation:

      This sudden change in pulse rate is due to the oculocardiac reflex. It is a >20% reduction in pulse rate as a result of placing pressure directly on the eyeball. The reflex arc has an afferent and efferent arm:

      The afferent (sensory) arm: The trigeminal nerve (CN V)

      The efferent arm: The vagus nerve (CN X)

      The most appropriate action is to ask the surgeon to stop retraction of the extraocular muscles, Assess for hypoxia, and give 100% oxygen if indicated.

      Atropine of glycopyrrolate can be administered to counteract the reflex, and also prevent any further vagal reflexes.

      Administration of fentanyl may increase patient’s risk of bradycardia and sinus arrest in this case.

      Adrenaline is not indicated here as other treatment options will provide sufficient relief from arrhythmia.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 22 - A 68-year old man, is admitted in hospital. He is scheduled to undergo...

    Incorrect

    • A 68-year old man, is admitted in hospital. He is scheduled to undergo a femoro-popliteal bypass graft, for which he has been administered a spinal-epidural anaesthetic. Intrathecal heavy bupivacaine (0.5%) was injected at L3-4 with good effect. On insertion of the epidural catheter, he remained asymptomatic.

      During surgery, 5000 I.U. of IV heparin was given. The surgery is successful and required no epidural top-ups.

      Six hours later, he complains of a severe back pain with weakness in his lower limbs.

      What is the most important first step?

      Your Answer:

      Correct Answer: A full neurological examination to establish the nature of the problem

      Explanation:

      The most likely diagnosis is a spinal epidural haematoma, a neurological emergency. A full examination must be carried out to determine the nature of the neurological problem before conducting any investigations or imaging.

      The effects of spinal anaesthesia should have worn off by this time point, and the severe back pain is a red flag.

      The patient will also require an urgent neurological team referral as a spinal epidural haematoma requires immediate evacuation for spinal decompression. Analgesics may be prescribed for pain management.

      Heparin would have been fully metabolised and so a reversal is unnecessary.

      A spinal epidural haematoma is a pooling of blood in the epidural space, which can cause compression of the spinal cord. Its presenting symptoms are:

      Usually begins with severe backpain and percussion tenderness
      Cauda equina syndrome
      Paralysis of the lower extremities.
      If infected, a fever occurs in 66% of cases
      Lower limb weakness developing after stopping an epidural infusion or weakness of the lower limbs which does not resolve within four hours of cessation of infusion of epidural local anaesthetic
      Meningism.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 23 - Which of the following statement is true regarding the paediatric airway? ...

    Incorrect

    • Which of the following statement is true regarding the paediatric airway?

      Your Answer:

      Correct Answer: The larynx is more anterior than in an adult

      Explanation:

      In the neonatal stage, the tongue is usually large and comes to the normal size at the age of 1 year. The vocal cords lie inverse C4 and as it reaches the grown-up position inverse C5/6 by the age of 4 (not 1 year).

      Due to the immature cricoid cartilage, the larynx lies more anterior in newborn children. That’s why the cricoid ring is the narrowest part of the paediatric respiratory tract, while in the adults the tightest portion of the respiratory route is vocal cords. The epiglottis is generally expansive and slants at a point of 45 degrees to the laryngeal opening.

      The carina is the ridge of the cartilage in the trachea at the level of T2 in newborn (T4 in adults), that separates the openings of right and left main bronchi.

      Neonates have a comparatively low number of alveoli and then this number gradually increases to a most extreme by the age of 8 (not 3 years).

      Neonates are obligatory nose breathers and any hindrance can cause respiratory issues (e.g., choanal atresia).

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 24 - Which of the following options is correct regarding the coagulation pathway? ...

    Incorrect

    • Which of the following options is correct regarding the coagulation pathway?

      Your Answer:

      Correct Answer: Tissue factor released by damaged tissue initiates the extrinsic pathway

      Explanation:

      The extrinsic pathway is considered as the main pathway of coagulation cascade.

      Heparin is known to inhibit the activation of coagulation factors 2,9,10, and 11.

      The extrinsic and intrinsic pathways meet at the activation of coagulation factor 10.

      Fibrinogen is converted into Fibrin in the presence of Thrombin. Plasminogen is converted into plasmin during fibrinolysis to breakdown fibrin clot.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 25 - The mandibular division of the trigeminal nerve passes through which anatomic structure? ...

    Incorrect

    • The mandibular division of the trigeminal nerve passes through which anatomic structure?

      Your Answer:

      Correct Answer: Foramen ovale

      Explanation:

      The mandibular branch of the trigeminal nerve passes through the foramen ovale. Other structures that pass through this foramen are the accessory meningeal artery, and occasionally, the lesser petrosal nerve.

      These are the structures that pass through the other openings in the cranial fossa:

      Foramen rotundum – Maxillary branch of the trigeminal nerve

      Foramen lacerum – Greater petrosal nerve, traversed by the internal carotid artery

      Superior orbital fissure – Oculomotor nerve; trochlear nerve; lacrimal, frontal and nasociliary branches of the ophthalmic branch of the trigeminal nerve; abducens nerve, superior ophthalmic vein

      Stylomastoid foramen – facial nerve

    • This question is part of the following fields:

      • Anatomy
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  • Question 26 - Which compound is secreted only from the adrenal medulla? ...

    Incorrect

    • Which compound is secreted only from the adrenal medulla?

      Your Answer:

      Correct Answer: Adrenaline

      Explanation:

      The adrenal medulla comprises chromaffin cells (pheochromocytes), which are functionally equivalent to postganglionic sympathetic neurons. They synthesize, store and release the catecholamines noradrenaline (norepinephrine) and adrenaline (epinephrine) into the venous sinusoids.
      The majority of the chromaffin cells synthesize adrenaline.

    • This question is part of the following fields:

      • Anatomy
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  • Question 27 - Because this benzodiazepine has a half-life of 2-4 hours, it is preferred for...

    Incorrect

    • Because this benzodiazepine has a half-life of 2-4 hours, it is preferred for clinical use.

      This benzodiazepine has which of the following properties that no other benzodiazepine has?

      Your Answer:

      Correct Answer: It is water soluble at a pH of 3.5 and lipid soluble at a pH of 7.4

      Explanation:

      Midazolam is the benzodiazepine in question. It’s the only benzodiazepine that undergoes tautomeric transformation (dynamic isomerism). The molecule is ionised and water soluble at pH 3.5, but when injected into the body at pH 7.4, it becomes unionised and lipid soluble, allowing it to easily pass through the blood brain barrier.

      The half-life of midazolam is only 2-4 hours.

      It is a GABAA receptor agonist because it is a benzodiazepine. GABAA receptors are found in abundance throughout the central nervous system, particularly in the cerebral cortex, hippocampus, thalamus, basal ganglia, and limbic system. GABAA receptors are ligand-gated ion channels, with the inhibitory neurotransmitter gamma-aminobutyric acid as the endogenous agonist. It is a pentameric protein (2, 2 and one subunit) that spans the cell membrane, and when the agonist interacts with the alpha subunit, a conformational change occurs, allowing chloride ions to enter the cell, resulting in neuronal hyperpolarization.

      For status epilepticus, midazolam is not the drug of choice. Lorazepam is the benzodiazepine of choice for status epilepticus.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 28 - Which of the following descriptions best describes enflurane and isoflurane? ...

    Incorrect

    • Which of the following descriptions best describes enflurane and isoflurane?

      Your Answer:

      Correct Answer: Have the same molecular formula but different structural formulae

      Explanation:

      Structural isomers have a similar molecular formula, but they have a different structural formula as their atoms are arranged in a different manner. Such small changes lead to the differential pharmacological activity. Enflurane and isoflurane are two prime examples of structural isomers.

      Stereoisomers are those substances that have a similar molecular and structural formula, but the arrangement spatially of atoms are different and have optical activity.

      Enantiomers are a pair of stereoisomers, which are non-superimposable mirror images of each other. They also have chiral centres of molecular symmetry. Ketamine is considered as an example of racemic mixture (contain 50% R and 50% S enantiomers)

      Geometric isomers contain a carbon-carbon double bond (i.e. C=C) or a rigid carbon-carbon single bond in a heterocyclic ring. Cis-atracurium is one example.

      Dynamic isomers or Tautomers are a pait of unstable structural isomers, which are present in equilibrium. One isomer can easily change after the change in pH. Midazolam and thiopentone are their examples.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 29 - Which of the given statements is true about standard error of the mean?...

    Incorrect

    • Which of the given statements is true about standard error of the mean?

      Your Answer:

      Correct Answer: Gets smaller as the sample size increases

      Explanation:

      The standard error of the mean (SEM) is a measure of the spread expected for the mean of the observations – i.e. how ‘accurate’ the calculated sample mean is from the true population mean. The relationship between the standard error of the mean and the standard deviation is such that, for a given sample size, the standard error of the mean equals the standard deviation divided by the square root of the sample size.

      SEM = SD / square root (n)

      where SD = standard deviation and n = sample size

      Therefore, the SEM gets smaller as the sample size (n) increases.

      If we want to depict how widely scattered some measurements are, we use the standard deviation. For indicating the uncertainty around the estimate of the mean, we use the standard error of the mean. The standard error is most useful as a means of calculating a confidence interval. For a large sample, a 95% confidence interval is obtained as the values 1.96×SE either side of the mean.

      A 95% confidence interval:

      lower limit = mean – (1.96 * SEM)

      upper limit = mean + (1.96 * SEM)

      Results such as mean value are often presented along with a confidence interval. For example, in a study the mean height in a sample taken from a population is 183cm. You know that the standard error (SE) (the standard deviation of the mean) is 2cm. This gives a 95% confidence interval of 179-187cm (+/- 2 SE).

      Hence, it would be wrong to say that confidence levels do not apply to standard error of the mean.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 30 - A 30-year-old man has been diagnosed with a direct inguinal hernia.

    A direct...

    Incorrect

    • A 30-year-old man has been diagnosed with a direct inguinal hernia.

      A direct inguinal hernia passes through Hesselbach's triangle. What forms the medial edge of this triangle?

      Your Answer:

      Correct Answer: Rectus abdominis muscle

      Explanation:

      The inguinal triangle of Hesselbach’s is an important clinical landmark on the posterior wall of the inguinal canal. It has the following relations:
      Inferiorly – medial third of the inguinal ligament
      Medially – lower lateral border of the rectus abdominis
      Laterally – inferior epigastric vessels

      Direct inguinal hernia is when the bowel bulges directly through the abdominal wall. These hernias usually protrude through Hesselbach’s triangle

    • This question is part of the following fields:

      • Anatomy
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SESSION STATS - PERFORMANCE PER SPECIALTY

Statistical Methods (0/1) 0%
Basic Physics (1/1) 100%
Anatomy (3/5) 60%
Physiology (1/3) 33%
Anaesthesia Related Apparatus (0/1) 0%
Pathophysiology (2/3) 67%
Clinical Measurement (2/2) 100%
Pharmacology (0/1) 0%
Physiology And Biochemistry (1/1) 100%
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