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Question 1
Correct
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A 25-year old man needs an emergency appendicectomy and has gone to the operating room. During general anaesthesia, ventilation is achieved using a circle system with a fresh gas flow (FGF) of 1L/min, with and air/oxygen and sevoflurane combination. The capnograph trace is normal.
Changes to the end tidal and baseline CO2 measurements at 10 and 20 mins respectively are seen on the capnograph below:
10 minutes 20 minutes
End-tidal CO2 4.9 kPa 8.4 kPa
Baseline end-tidal CO2 0.2 kPa 2.4 kPa
The other vitals were as follows:
Pulse 100-105 beats per minute
Systolic blood pressure 120-133 mmHg
O2 saturation 99%.
The next most important immediate step is which of the following?Your Answer: Increase the FGF
Explanation:This scenario describes rebreathing management.
Changes is exhaustion of the soda lime and a progressive rise in circuit deadspace is the most likely explanation for the capnograph.
It is important that the soda lime canister is inspected for a change in colour of the granules. Initially fresh gas flow should be increased and then if necessary, replace the soda lime granules. Other strategies include changing to another circuit or bypassing the soda lime canister after the fresh gas flow is increased.
Any other causes of increased equipment deadspace should be excluded.
Intraoperative hypercarbia can be caused by:
1. Hypoventilation – Breathing spontaneously; drugs which include anaesthetic agents, opioids, residual neuromuscular blockade, pre-existing respiratory or neuromuscular disease and cerebrovascular accident.
2. Controlled ventilation- circuit leaks, disconnection, miscalculation of patient’s minute volume.
3. Rebreathing – Soda lime exhaustion with circle, inadequate fresh gas flow into Mapleson circuits, increased breathing system deadspace.
4. Endogenous source – Tourniquet release, hypermetabolic states (MH or thyroid storm) and release of vascular clamps.
5. Exogenous source – Absorption of CO2 absorption from the pneumoperitoneum. -
This question is part of the following fields:
- Physiology
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Question 2
Incorrect
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Post thyroidectomy, a 50-year-old male singer noticed some hoarseness in his voice. Now, he presents to his general physician as it has been the same for the past few weeks.
A complication is noted in the post-thyroidectomy report regarding an injury to the external laryngeal nerve.
Which muscle has been affected due to loss of innervation by the damaged nerve, and whose improper functioning can lead to hoarseness in the patient's voice?Your Answer: Lateral cricoarytenoid
Correct Answer: Cricothyroid
Explanation:All of the muscles of the larynx are innervated by the recurrent laryngeal nerve, except the cricothyroid muscle.
Cricothyroid muscle is located deep in the anterior neck, between the cricoid and thyroid cartilage and is innervated by the external laryngeal nerve. Any injury to this muscle can cause paralysis and lead to hoarseness. When cricothyroid muscle contracts, it leads to tightening, stretching and thinning of the vocal folds. This produces higher-pitched sounds during vocalization.
A patient experiencing hoarseness due to possible injury to the external laryngeal nerve should be reassured that the hoarseness will resolve in time due to increased compensation from the other muscles.
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This question is part of the following fields:
- Anatomy
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Question 3
Correct
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A study designed to examine the benefits of adding a new antiplatelet to aspirin after a myocardial infraction. The recorded results give us the percentage of patients that reported myocardial infraction within a three month period. The percentage was 4% and 3% for aspirin and the combination of drugs respectively.
How many further patients needed to be treated in order for one patient to avoid any more heart attacks during 3 months?Your Answer: 100
Explanation:Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.
It can be found as:
NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).
where ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)
So,
ARR= (0.04-0.03)
ARR= 0.01
NNT= 1/0.01
NNT=100
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This question is part of the following fields:
- Statistical Methods
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Question 4
Correct
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The half-empty cylinder weighs 4.44 kg.
The tare weight of a nitrous oxide cylinder is 4 kg.
The molecular weight of nitrous oxide is 44gm.
Based on the data, how many litres of nitrous oxide remains in the cylinder for use?Your Answer: 224 litres
Explanation:The Tare weight of a cylinder is the weight when it is empty. So,
Weight of cylinder – tare weight = weight of remaining N2O (g).
4.44 kg – 4 kg = 0.44 kg
Here,
0.44 kg of nitrous oxide remains in the cylinderSince the molecular weight of nitrous oxide is 44 g and one mole of an ideal gas will occupy a volume of 22.4 litres at STP
Therefore amount left in the cylinder is several (gN2O/44) x 22.4 litres of N2O.(440/44) x 22.4 = 224 litres.
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This question is part of the following fields:
- Basic Physics
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Question 5
Incorrect
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A common renal adverse effect of non-steroidal anti-inflammatory drugs is?
Your Answer: Interstitial nephritis
Correct Answer: Haemodynamic renal insufficiency
Explanation:Prostaglandins do not play a major role in regulating RBF in healthy resting individuals. However, during pathophysiological conditions such as haemorrhage and reduced extracellular fluid volume (ECVF), prostaglandins (PGI2, PGE1, and PGE2) are produced locally within the kidneys and serve to increase RBF without changing GFR. Prostaglandins increase RBF by dampening the vasoconstrictor effects of both sympathetic activation and angiotensin II. These effects are important because they prevent severe and potentially harmful vasoconstriction and renal ischemia. Synthesis of prostaglandins is stimulated by ECVF depletion and stress (e.g. surgery, anaesthesia), angiotensin II, and sympathetic nerves.
Non-steroidal anti-inflammatory drugs (NSAIDs), such as ibuprofen and naproxen, potently inhibit prostaglandin synthesis. Thus administration of these drugs during renal ischemia and hemorrhagic shock is contraindicated because, by blocking the production of prostaglandins, they decrease RBF and increase renal ischemia. Prostaglandins also play an increasingly important role in maintaining RBF and GFR as individuals age. Accordingly, NSAIDs can significantly reduce RBF and GFR in the elderly.
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This question is part of the following fields:
- Physiology
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Question 6
Incorrect
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One of the non-pharmacologic management of COPD is smoking cessation. Given a case of a 60-year old patient with history of smoking for 30 years and a FEV1 of 70%, what would be the most probable five-year course of his FEV1 if he ceases to smoke?
Your Answer: The FEV1 will decrease at the same rate as a smoker
Correct Answer: The FEV1 will decrease at the same rate as a non-smoker
Explanation:For this patient, his forced expiratory volume in 1 second (FEV1) will decrease at the same rate as a non-smoker.
There is a notable, but slow, decline in FEV1 when an individual reaches the age of 26. An average reduction of 30 mls every year in non-smokers, while a more significant reduction of 50-70 mls is observed in approximately 20% of smokers.
Considering the age of the patient, individuals who begin smoking cessation by the age of 60 are far less likely to achieve normal FEV1 levels, even in the next five years. It is expected that their FEV1 will be approximately 14% less than their peers of the same age.
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This question is part of the following fields:
- Physiology
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Question 7
Incorrect
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Which of the following best describes why phenytoin's hepatic extraction ratio is low?
Your Answer: It has a clearance that is insensitive to changes in binding to plasma proteins
Correct Answer: It has a clearance that is insensitive to changes in liver blood flow
Explanation:The following are the pharmacokinetic properties of drugs with a low hepatic extraction ratio:
Changes in liver blood flow have no effect on drug clearance.
When given orally, drug clearance is extremely sensitive to changes in protein binding, intrinsic metabolism, and excretion, and there is no first-pass metabolism.Warfarin and phenytoin are two drugs with low hepatic extraction ratios.
The following are the pharmacokinetic properties of drugs with a high hepatic extraction ratio:
When taken orally, undergo extensive first-pass metabolism; drug clearance is dependent on liver blood flow, and drug clearance is less sensitive to changes in protein binding and intrinsic metabolism.
Morphine, lidocaine, propranolol, and etomidate are examples of drugs with high hepatic extraction ratios.
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This question is part of the following fields:
- Pharmacology
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Question 8
Incorrect
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With regards to the internal carotid artery, which of these statements is correct.
Your Answer:
Correct Answer: Enters the skull and divides into the anterior and middle cerebral arteries
Explanation:The internal carotid artery passes through the carotid canal in the petrous part of the temporal bone into the cranial cavity. It does NOT groove the sphenoid bone.
The internal carotid artery gives off no branches in the neck and is a terminal branch of the common carotid artery.
These structures pass between the external and internal carotid arteries: the styloglossus and stylopharyngeus muscles, the glossopharyngeal nerve (CN IX), and the pharyngeal branch of the vagus.
Accompanied by its sympathetic plexus, the internal carotid artery, passes through the cavernous sinus and is crossed by the abducent nerve.
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This question is part of the following fields:
- Anatomy
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Question 9
Incorrect
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Concerning the anterior pituitary gland, one of following is true.
Your Answer:
Correct Answer: Produces glycoproteins
Explanation:The posterior pituitary and the hypothalamus are connected by the pituitary stalk. It contains in the pituitary sella and has the optic chiasm and hypothalamus as superior relations.
The anterior pituitary produces thyroid-stimulating hormone (TSH), luteinising hormone (LH) and follicle-stimulating hormone (FSH) . These hormones are Glycoproteins and share a common alpha subunit with unique beta subunits.
The secretion of pituitary hormones are pulsatile. Examples are LH, adrenocorticotropic hormone (ACTH) and growth hormone (GH).
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This question is part of the following fields:
- Pathophysiology
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Question 10
Incorrect
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For a rapid sequence induction of anaesthesia, you are pre-oxygenating a patient using 100% oxygen and a fresh gas flow equal to the patient's minute ventilation.
Which would be the most suitable choice of anaesthetic breathing system in this situation?Your Answer:
Correct Answer: Mapleson A system
Explanation:The Mapleson A (Magill) and coaxial version of the Mapleson A system (Lack circuit) are more efficient for spontaneous breathing than any of the other Mapleson circuits. The fresh gas flow (FGF) required to prevent rebreathing is slightly greater than the alveolar minute ventilation (4-5 litres/minute). This is delivered to the patient through the outer coaxial tube and exhaust gases are moved to the scavenging system through the inner tube. In the Lack circuit, the expiratory valve is located close to the common gas outlet away from the patient end. This is the main advantage of the Lack circuit over the Mapleson A circuit.
The Mapleson E circuit is a modification of the Ayres T piece and the FGF required to prevent rebreathing is 1.5-2 times the patient’s minute volume.
The Bain circuit is the coaxial version of the Mapleson D circuit.
The FGF for spontaneous respiration to avoid rebreathing is 160-200 ml/kg/minute.
The FGF for controlled ventilation to avoid rebreathing is 70-100 ml/kg/min.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 11
Incorrect
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A 43-year-old patient was brought to the emergency department with a traumatic amputation of his leg at mid-thigh level. Resuscitation with 1 L gelofusine was done and four units of packed red blood cells were given before theatre. Thirty minutes following blood transfusion, the patient became flushed, breathless, hypotensive, develops haemoglobinuria, and had a fever of 38oC.
Which one of the following correctly explains the patient signs and symptoms?Your Answer:
Correct Answer: Activation of classic complement pathway
Explanation:This may be the classical case of blood transfusion reaction due to ABO incompatibility.
Here red cells are destroyed in the bloodstream with the release of haemoglobin in circulation (causing haemoglobinuria). Here, IgM or IgG anti-A or anti-B antibody can cause rapid activation of complement cascade usually the classical pathway. This is called intravascular haemolysis.
There may be extravascular haemolysis by cells of the mononuclear phagocyte system situated in the liver and spleen. Extravascular red cell destruction can increase breakdown products of haemoglobin, such as bilirubin and urobilinogen.
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This question is part of the following fields:
- Pathophysiology
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Question 12
Incorrect
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The whole water content of the body is calculated by multiplying body mass with 0.6. This water is diffused into distinct compartments.
Which fluid compartment can be measured indirectly?Your Answer:
Correct Answer: Intracellular volume
Explanation:The total body water content of a 70kg man is (70 × 0.6) = 42 litres. For a woman, the calculation is (70 × 0.55) = 38.5 litres.
For a man, it is subdivided into:
Extracellular fluid (ECF) = 14L (1/3)
Intracellular fluid (ICF) = 28L (2/3).The ECF volume is further divided into:
Interstitial fluid = 10.5 litres
Plasma = 3 litres
Transcellular fluid (CSF/synovial fluid) = 0.5 litres.Directly measured fluid compartments:
Heavy water (deuterium) can be used to measure total body water content, which is freely distributed.
Albumin labelled with a radioactive isotope or using a dye called Evans blue can be used to measure Plasma volume . They do not diffuse into red blood cells.
Radiolabelled (Cr-51) red blood cells can be used to measure total erythrocyte volume.
Inulin as the tracer can be used to measure ECF volume as it circulate freely in the interstitial and plasma volumes.Indirectly measured fluid compartments:
Total blood volume can be calculated with the level of haematocrit and the volume of total circulating red blood cells.
ICF volume can be calculated by subtracting ECF volume from total blood volume. -
This question is part of the following fields:
- Basic Physics
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Question 13
Incorrect
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The spinal cord tracts that transmits the sensations of pain, crude temperature, and light touch is?
Your Answer:
Correct Answer: Spinothalamic
Explanation:Dorsal column (ascending tract) – Proprioception, vibration, discriminative
Spinocerebellar (ascending tract) – Subconscious muscle position and tone
Corticospinal (descending tract) – Voluntary muscle
Rubrospinal (descending tract) – Flexor muscle tone
Vestibulospinal (descending tract) – Reflexes and muscle tone
Reticulospinal(descending tract) – Voluntary movements, head position.-
Autonomic – Descending tract.
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This question is part of the following fields:
- Anatomy
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Question 14
Incorrect
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A young woman presented with a gynaecological related infection and was prescribed a cephalosporin. Which of the following is correct about the mechanism of action of this drug?
Your Answer:
Correct Answer: Bacterial cell wall synthesis inhibition
Explanation:Cephalosporin belongs to a family of beta-lactam antibiotics. All ?-lactam antibiotics interfere with the synthesis of the bacterial cell walls. The ?-lactam antibiotics inhibit the transpeptidases so that cross-linking (which maintains the close-knit structure of the cell wall) does not take place i.e. they inhibit bacterial cell wall formation.
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This question is part of the following fields:
- Pharmacology
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Question 15
Incorrect
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The most sensitive indicator of mild obstructive airway disease is?
Your Answer:
Correct Answer: Forced expiratory flow (FEF25-75%)
Explanation:The volume expired in the first second of maximal expiration after a maximal inspiration is known as forced expiratory volume in one second (FEV1), and it indicates how quickly full lungs can be emptied. It is the most commonly measured parameter for bronchoconstriction assessment.
The maximum volume of air exhaled after a maximal inspiration is known as the ‘slow’ vital capacity (VC). VC is normally equal to FVC after a forced vital capacity (FVC) or slow vital capacity (VC) manoeuvre, unless there is an airflow obstruction, in which case VC is usually higher than FVC.
The FEV1/FVC (Tiffeneau index) is a clinically useful index of airflow restriction that can be used to distinguish between restrictive and obstructive respiratory disorders.
The average expired flow over the middle half (25-75 percent) of the FVC manoeuvre is the forced expiratory volume (FEF25-75). The airflow from the resistance bronchioles corresponds to this. It’s a more sensitive indicator of mild small airway narrowing than FEV1, but it’s difficult to tell if the VC (or FVC) is decreasing or increasing.
The maximum expiratory flow rate achieved is called the peak expiratory flow (PEF), which is usually 8-14 L/second.
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This question is part of the following fields:
- Pathophysiology
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Question 16
Incorrect
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You've been summoned to the recovery room to examine a 28-year-old man who has had an inguinal hernia repaired.
His vital signs are normal, but you notice that he has developed abnormal upper-limb movements due to muscle contractions that cause repetitive twisting movements.
What do you think is the most likely source for this patient's condition?Your Answer:
Correct Answer: Prochlorperazine
Explanation:Dystonia is characterised by repetitive twisting movements or abnormal postures. They are classified as either primary or secondary.
Primary dystonia is a genetic disorder that is inherited in an autosomal dominant pattern.
Secondary dystonia can be caused by focal brain lesions, Parkinson’s disease, or certain medications.The following drugs cause the most common drug-induced dystonic reactions:
Antipsychotics, antiemetics (especially prochlorperazine and metoclopramide), and antidepressants.Following the administration of the neuroleptic prochlorperazine, 16 percent of patients experience restlessness (akathisia) and 4% experience dystonia.
Several published reports have linked the anaesthetics thiopentone, fentanyl, and propofol to opisthotonos and other abnormal neurologic sequelae. Dystonias following a general anaesthetic are uncommon. Tramadol has been linked to serotonin syndrome, while remifentanil has been linked to muscle rigidity.
The following are some of the risk factors:
Positive family history
Male
Children
An episode of acute dystonia occurred previously.
Dopamine receptor (D2) antagonists at high doses and recent cocaine useDystonia is treated in a variety of ways, including:
Benztropine (as a first-line therapy):
1-2 mg intravenous injection for adults
Child: 0.02 mg/kg to 1 mg maximumBenzodiazepines are a type of benzodiazepine (second line treatment).
Midazolam:
1-2 mg intravenously, or 5-10 mg IV/PO diazepam
Antihistamines with anticholinergic activity (H1receptor antagonists):
Promethazine 25-50 mg IV/IM, or diphenhydramine 50 mg IV/IM (1 mg/kg in children) are used when benztropine is not available.
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This question is part of the following fields:
- Pharmacology
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Question 17
Incorrect
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Which of the following statements is true regarding vecuronium?
Your Answer:
Correct Answer: Has a similar structure to rocuronium
Explanation:Vecuronium is used as a part of general anaesthesia to provide skeletal muscle relaxation during surgery or mechanical ventilation. It is a monoquaternary aminosteroid (not quaternary) non- depolarising neuromuscular blocking drug.
It has a structure similar to both rocuronium and pancuronium. The only difference is the substitution of specific groups on the steroid structure.
Vecuronium is not associated with the release of norepinephrine from sympathetic nerve endings. However, Pancuronium has norepinephrine releasing the property.
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This question is part of the following fields:
- Pharmacology
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Question 18
Incorrect
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A study of blood pressure measurements is being performed in patients with chronic kidney disease.
Considering that the results are normally distributed, what percentage of values lie within two standard deviations of the mean blood pressure reading?Your Answer:
Correct Answer: 95.40%
Explanation:Normal distribution, also called Gaussian distribution, the most common distribution function for independent, randomly generated variables, and describes the spread for many biological and clinical measurements.
Properties of the Normal distribution
symmetrical i.e. Mean = mode = median
68.3% of values lie within 1 SD of the mean
95.4% of values lie within 2 SD of the mean
99.7% of values lie within 3 SD of the mean
The empirical rule, or the 68-95-99.7 rule, tells you where most of the values lie in a normal distribution: Around 68% of values are within 1 standard deviation of the mean.
Around 95% of values are within 2 standard deviations of the mean. Around 99.7% of values are within 3 standard deviations of the mean.
the standard deviation (SD) is a measure of how much dispersion exists from the mean.SD = square root (variance)
The empirical rule, or the 68-95-99.7 rule states where most of the values lie in a normal distribution. Around 68% of values fall within 1 S.D of the mean, about 95% within 2 S.D of the mean, and about 99.7% of values within 3 S.D of the mean. Therefore, 95.4% is the most reasonable answer if results are normally distributed.
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This question is part of the following fields:
- Statistical Methods
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Question 19
Incorrect
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Which statement most accurately describes the action of increasing the gain in ultrasound imaging?
Your Answer:
Correct Answer: Amplifies the returning signal
Explanation:A higher frequency ultrasound comes with a better resolution of the digital image. Ultrasound with a frequency of 15 MHz is best used in imaging of superficial organs such as the thyroid gland, muscles, tendons and breasts whereas deep organs are better imaged using a lower frequency of 2-7MHz because of its ability for deeper penetration but lower resolution. These low frequency probes are also used to diagnose ascites, pleural effusions or can be used in echocardiography.
The US probe emits and then absorbs a reflected wave. Similar to brightness control, increasing the gain will amplify the return signal which is then attenuated by the tissue. This increases the signal to noise ratio.
A high frame rate, which basically means the number of times an image is updated onto the screen per second, improves the resolution of a moving 3D image which has become more accurate as the computing power has increased.Widening of the image field can be obtained by altering the penetration depth which is obtained by changing the frequency of the US beam
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 20
Incorrect
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From the following statements, which is true of humidification?
Your Answer:
Correct Answer: Ultrasonic humidifier can achieve greater than 100% relative humidity
Explanation:Increasing temperature increases the amount of water vapour contained in air; for example, at 20°C, air contains about 17 g/m3, and at 37°C, air contains about 44 g/m3. The wet and dry bulb hygrometer, like the hair hygrometer, measures relative humidity.
Under normal operating conditions, Heat and moisture exchangers (HMEs) allows relative humidity of up to 70% to be achieved. Mucus can impair their performance, and they should not be used for longer than 24 hours.
Hot water bath humidifiers might cause scalding, condensed water in the tubing can interfere with gas flow, and there is a danger of infection.
The ultrasonic humidifier operates at roughly 2 MHz and may attain relative humidity levels much above 100%.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 21
Incorrect
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A pulmonary function tests results are:
Measurement Predicted result Test result
Forced vital capacity (FVC) (btps) 3.85 2.36
Forced expiratory volume in 1 second (FEV1) (btps) 3.34 0.97
FEV1/FVC ratio % (btps) 85.1 39.9
Peak expiratory flow (PEF) (L/second) 7.33 2.11
Maximum voluntary ventilation (MVV) (L/minute) 116 44.4
What does this indicate?Your Answer:
Correct Answer: Moderate restrictive and severe obstructive picture
Explanation:Severity of a reduction in restrictive defect (%FVC) or obstructive defect (%FEV1/FVC) predicted are classified as follows:
Mild 70-80%
Moderate 60-69%
Moderately severe 50-59%
Severe 35-49%
Very severe <35% This patient has a mixed deficit with a severe obstructive deficit as %FEV1/FVC predicted is 46.9% and a moderate restrictive deficit as %FVC of predicted is 61.3 FEV1/FVC ratio 80% < predicted and VC < 80% = mixed picture. FEV1/FVC ratio 80% < predicted and VC > 80% = obstructive picture.FEV1/FVC ratio 80% > predicted and VC > 80% = normal picture.
FEV1/FVC ratio 80% > predicted and VC < 80% predicted= restrictive picture.
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This question is part of the following fields:
- Clinical Measurement
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Question 22
Incorrect
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An acidic drug with a pKA of 4.3 is injected intravenously into a patient.
At a normal physiological pH, the approximate ratio of ionised to unionised forms of this drug in the plasma is?Your Answer:
Correct Answer: 1000:01:00
Explanation:The pH at which the drug exists in 50 percent ionised and 50 percent unionised forms is known as the pKa.
To calculate the proportion of ionised to unionised form of an ACID, use the Henderson-Hasselbalch equation.
pH = pKa + log ([A-]/[HA])
or
pH = pKa + log [(salt)/(acid)]
pH = pKa + log ([ionised]/[unionised]).Hence, if the pKa − pH = 0, then 50% of drug is ionised and 50% is unionised.
In this example:
7.4 = 4.3 + log ([ionised]/[unionised])
7.4 − 4.3 = log ([ionised]/[unionised])
log 3.1 = log ([ionised]/[unionised])Simply put, the antilog is the inverse log calculation. In other words, if you know the logarithm of a number, you can use the antilog to find the value of the number. The antilogarithm’s definition is as follows:
y = antilog x = 10x
Antilog to the base 10 of 0 = 1, 1 = 10, 2 =100, 3 = 1000, and 4 = 10,000.
If you want to find the antilogarithm of 3.1, for a number between 3 and 4, the antilogarithm will return a value between 1000 and 10,000. The ratio is 1:1 if pKa = pH, that is, pH pKa = log 0. (50 percent ionised and unionised).
According to the above value, there is only one unionised molecule for every approximately 1000 (1259) ionised molecules of this drug in plasma, implying that this drug is largely ionised in plasma (99.99 percent ).
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This question is part of the following fields:
- Pharmacology
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Question 23
Incorrect
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The immediate physiological response to massive perioperative blood loss is:
Your Answer:
Correct Answer: Stimulation of baroreceptors in carotid sinus and aortic arch
Explanation:With regards to compensatory response to blood loss, the following sequence of events take place:
1. Decrease in venous return, right atrial pressure and cardiac output
2. Baroreceptor reflexes (carotid sinus and aortic arch) are immediately activated
3. There is decreased afferent input to the cardiovascular centre in medulla. This inhibits parasympathetic reflexes and increases sympathetic response
4. This results in an increased cardiac output and increased SVR by direct sympathetic stimulation. There is increased circulating catecholamines and local tissue mediators (adenosine, potassium, NO2)
5. Fluid moves into the intravascular space as a result of decreased capillary hydrostatic pressure absorbing interstitial fluid.A slower response is mounted by the hypothalamus-pituitary-adrenal axis.
6. Reduced renal blood flow is sensed by the intra renal baroreceptors and this stimulates release of renin by the juxta-glomerular apparatus.
7. There is cleavage of circulating Angiotensinogen to Angiotensin I, which is converted to Angiotensin II in the lungs (by Angiotensin Converting Enzyme ACE)Angiotensin II is a powerful vasoconstrictor that sets off other endocrine pathways.
8. The adrenal cortex releases Aldosterone
9. There is antidiuretic hormone release from posterior pituitary (also in response to hypovolaemia being sensed by atrial stretch receptors)
10. This leads to sodium and water retention in the distal convoluted renal tubule to conserve fluid
Fluid conservation is also aided by an increased amount of cortisol which is secreted in response to the increase in circulating catecholamines and sympathetic stimulation. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 24
Incorrect
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Fixed performance devices like high air flow oxygen enrichment (HAFOE) masks have large volumes of air entrained into a flow of 100% oxygen.
The term that best describes the physics behind air entrainment is?Your Answer:
Correct Answer: Bernoulli's principle
Explanation:Bernoulli’s principle states that as the speed of a moving fluid increases, there is a simultaneously decrease in static pressure or a decrease in the fluid’s potential energy.
This is seen in the simultaneous increase in speed and kinetic energy and fall in pressure that causes entrainment of large volumes of air into a flow of 100% oxygen in the nozzle of HAFOE masks.The reduction in fluid pressure that happens when a fluid flows through a constriction in a tube is the Venturi effect.
When a flow of gas or liquid attaches itself to a nearby surface and remains attached even when the surface curves away from the initial direction of flow, this is the Coanda effect.
The branch of engineering and technology that is concerned with the building of devices that use the flow and pressure of a fluid for functions usually performed by electronic devices is Fluidics . Fluidic logic is used to power some ventilators.
The branch of engineering that utilises pressurised gases is Pneumatics.
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This question is part of the following fields:
- Basic Physics
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Question 25
Incorrect
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A double blind placebo control clinical trial is done. Which of these is correct about it?
Your Answer:
Correct Answer: The clinician assessing the effects of the treatment does not know which treatment the patient has been given
Explanation:A ‘double blind crossover study’ happens when every patient receive both treatments.
It is incorrect to say that only half of the patients do not know which treatment they receive because in a double blind placebo control clinical trial ALL of the patients are blind to their treatment choice .
If some of the patients are not treated, they would be aware that they were not being treated and it could not be considered a blind trial.
In a double blind placebo control clinical trial both the clinician and the patient are blind to the treatment choice. The clinician assessing the effects of the treatment, therefore, does not know which treatment the patient has been given.
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This question is part of the following fields:
- Statistical Methods
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Question 26
Incorrect
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Which plasma protein will bind the thyroid hormone triiodothyronine (T3) more readily?
Your Answer:
Correct Answer: Thyroxine binding globulin
Explanation:Secreted T4 and T3 circulate in the bloodstream almost entirely bound to proteins. Normally only about 0.03% of total plasma T4 and 0.3% of total plasma T3 exist in the free state. Free T3 is biologically active and mediates the effects of thyroid hormone on peripheral tissues in addition to exerting negative feedback on the pituitary and hypothalamus. The major binding protein is thyroxine-binding globulin (TBG), which is synthesized in the liver and binds one molecule of T4 or T3. About 70% of circulating T4 and T3 is bound to TBGl 10% to 15% is bound to another specific thyroid-binding protein called transthyretin (TTR). Albumin binds 15% to 20%, and 3% to lipoproteins. Ordinarily only alterations in TBG concentration significantly affect total plasma T4 and T3 levels.
Two important biological functions have been ascribed to TBG. First, it maintains a large circulating reservoir of T4 that buffers any acute changes in thyroid gland function. Second, binding of plasma T4 and T3 to proteins prevents loss of these relatively small hormone molecules in urine and thereby helps conserve iodide. TTR transports T4 in CSF and provides thyroid hormones to the CNS.
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This question is part of the following fields:
- Physiology
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Question 27
Incorrect
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Standard error of the mean can be defined as:
Your Answer:
Correct Answer: Standard deviation / square root (number of patients)
Explanation:The standard error of the mean (SEM) is a measure of the spread expected for the mean of the observations – i.e. how ‘accurate’ the calculated sample mean is from the true population mean. The relationship between the standard error of the mean and the standard deviation is such that, for a given sample size, the standard error of the mean equals the standard deviation divided by the square root of the sample size.
SEM = SD / square root (n)
where SD = standard deviation and n = sample size
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This question is part of the following fields:
- Statistical Methods
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Question 28
Incorrect
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Which nerve does NOT pass through the posterior triangle of the neck?
Your Answer:
Correct Answer: Ansa cervicalis
Explanation:The sternocleidomastoid muscle divides the neck into anterior and posterior triangles on both sides of the neck.
The posterior triangle has the following boundaries:
anteriorly – sternocleidomastoid muscle
posteriorly – trapezius
roof – investing layer of deep cervical fascia
floor – prevertebral fascia overlying splenius capitis, levator scapulae, and the scalene musclesThe contents of the posterior triangle are:
1. fat
2. lymph nodes (level V)
3. accessory nerve
4. cutaneous branches of the cervical plexus – greater auricular nerve, transverse cervical nerve, lesser occipital nerve, supraclavicular nerve (A major branch of this plexus is the phrenic nerve, which arises from the anterior divisions of spinal nerves C3-C5)
5. inferior belly of omohyoid
6. branches of the thyrocervical trunk (transverse cervical and suprascapular arteries)
7. third part of the subclavian artery
8. external jugular vein -
This question is part of the following fields:
- Anatomy
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Question 29
Incorrect
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A 45-year-old woman gives a two-week history of fatigue, muscle cramps, and paraesthesia of her fingers and toes. She has low serum calcium and low serum parathyroid hormone levels on investigations.
She appears slightly confused, likely due to hypocalcaemia, and cannot give a full account of her past medical history, but can recall that she recently was admitted to the hospital.
What is the most likely cause of her hypoparathyroidism?Your Answer:
Correct Answer: Thyroidectomy
Explanation:The most common cause of hypoparathyroidism is injury or removing the parathyroid glands. They can be injured accidentally during surgery to remove the thyroid as they are located posterior to the thyroid gland.
A result of both low parathyroid hormone and low calcium is likely to mean that the parathyroid glands are not responding to hypocalcaemia. The hypocalcaemia can cause confusion, and the stay in the hospital is likely to refer to her surgery.
While a parathyroid adenoma is fairly common and can cause hypoparathyroidism, it much more likely causes hyperparathyroidism.
Chronic kidney disease is likely to cause hypocalcaemia, which would increase parathyroid hormone production in an attempt to increase calcium levels, causing hyperparathyroidism. Vitamin D is activated by the kidneys and then binds to calcium to be absorbed in the terminal ileum so that a deficiency would cause hyperparathyroidism.
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This question is part of the following fields:
- Anatomy
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Question 30
Incorrect
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A graph was plotted after administration of fentanyl infusion to a patient. The following are the x- and y-axis of the graph:
X-axis: Dose of fentanyl
Y-axis: Mu receptor occupancy, measured using positron emission tomography
Given the data above, what would be the best representation of the graph if the data on the x-axis are converted to logarithms?Your Answer:
Correct Answer: Rectangular hyperbola to sigmoid curve
Explanation:The dose-response curve plots the graph of the dose (drug concentration) versus the response. As doses increase, the response increment diminishes; finally, doses may be reached at which no further increase in response can be achieved. This relation between drug concentration and effect is traditionally described by a hyperbolic curve. When the x-axis is plotted in log scale, the graph yields a sigmoid curve.
Efficacy (Emax) and potency (EC50) can be derived from this curve. Emax is the maximal effect achievable, with increasing concentration of a drug. EC50 is the concentration of the drug, wherein half of the maximal effect is achieved.
When the graph is plotted using a log [response/1-response] against log dose, the sigmoid curve becomes a straight line (Hill plot). A graph that transforms from a straight line to exponential curve is mathematically incorrect. A graph that transforms from either a wash-in or wash-out exponential curve to a straight line comes from an initial set of data plotted against time, to a logarithmic transformation of the initial data set against time.
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This question is part of the following fields:
- Statistical Methods
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Question 31
Incorrect
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Which of the following statements is true about an acute pulmonary embolism?
Your Answer:
Correct Answer: Thrombolysis administered through a peripheral vein is as effective as through a pulmonary artery catheter
Explanation:Acute pulmonary embolism occurs when a blood clot becomes embedded in a pulmonary artery and restricts lung blood flow.
Thrombolysis is recommended in patients with extremely compromised circulation rather than reduced oxygen in the blood. It is effective when administered via a peripheral vein or a pulmonary artery catheter.
Anticoagulant therapy (heparin use) decreases the risk of further embolic evens and decreases constriction of pulmonary vessels.
An ECG may be normal in patients with an acute pulmonary embolism.
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This question is part of the following fields:
- Pathophysiology
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Question 32
Incorrect
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The coronary sinus is a collection of veins joined together to form a large vessel that collects blood from the myocardium. Which structure forms the largest tributary of the coronary sinus?
Your Answer:
Correct Answer: Great cardiac vein
Explanation:The coronary sinus is large venous structure located on the posterior aspect of the left atrium, coursing within the left atrioventricular groove. The function of the coronary sinus is to drain the venous blood from the majority of the heart. It opens into the right atrium between the opening of inferior vena cava, the fossa ovalis and the right atrioventricular orifice. The coronary sinus is often guarded by a thin, semicircular endocardial fold, also known as the thebesian valve.
Tributaries include: Great cardiac vein, middle cardiac vein, small cardiac vein, posterior vein of left ventricle, oblique vein of left atrium. The great cardiac vein is the largest tributary of the coronary sinus. -
This question is part of the following fields:
- Anatomy
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Question 33
Incorrect
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Which of the following is true about the pulse oximeter?
Your Answer:
Correct Answer: Is accurate to within +/- 2% in the range of 70% to 100% saturation
Explanation:The pulse oximeter provides a continuous non-invasive measurement of the arterial oxygen saturation. The light emitting diodes (LEDs) produce beams of red and infrared light at 660 nm and 940 nm respectively (not 640 and 960 nm), which travel through a finger (toe, ear lobe or nose) and are then detected by a sensitive photodetector.
The light absorbed by non-pulsatile tissues is constant (DC), and the non-constant absorption (AC) is the result of arterial blood pulsation. The DC and AC components at 660 and 940 nm are then analysed by the microprocessor and the result is related to the arterial saturation.
An isosbestic point is a point at which two substances absorb a wavelength of light to the same degree. In pulse oximetry the different absorption profiles of oxyhaemoglobin and deoxyhaemoglobin are used to quantify the haemoglobin saturation (in %). Isosbestic points occur at 590 and 805 nm (not 490 and 805 nm), where the light absorbed is independent of the degree of saturation, and are used as reference points.
The pulse oximeter is accurate to within +/- 2% in the range of 70% to 100% saturation, and below 70% the readings are extrapolated. Pulse oximeters average their readings every 10 to 20 seconds and thus they cannot detect acute desaturation events. Consequently, they are often referred to as ‘lag’ monitors, due to the time delay in identifying the desaturation episode.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 34
Incorrect
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Campylobacter is which type of bacteria?
Your Answer:
Correct Answer: sdgsdf
Explanation:Campylobacter is the commonest bacterial cause of infectious intestinal disease in the UK. The majority of cases are caused by the Gram-negative bacillus Campylobacter jejuni which is spread by the faecal-oral route. The incubation period is 1-6 days.
Features include a prodrome phase with headaches and malaise, then diarrhoea occurs which is often bloody.
There is often abdominal pain which may mimic appendicitis.It is usually self-limiting but treatment is warranted if the infection is severe or the infection occurs in an immunocompromised patient.
Severe infection comprises of high fever, bloody diarrhoea, or more than eight stools per day or symptoms last for more than one week.
This management would include antibiotics and the first-line antibiotic is clarithromycin.
Ciprofloxacin is an alternative but there are strains with decreased sensitivity to ciprofloxacin which can be frequently isolated.Complications include:
1.Guillain-Barre syndrome may follow Campylobacter
2. Jejuniinfections
3. Reactive arthritis
4. Septicaemia, endocarditis, arthritis -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 35
Incorrect
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Which of the following is true when testing for statistical significance?
Your Answer:
Correct Answer: The probability associated with a type I error is the significance level
Explanation:The null hypothesis states that there is no significant difference between two groups.
The alternative hypothesis states that there is a significant difference between two groups.
A type I error (false positive) occurs when a null hypothesis is rejected when it should be accepted.
A type II error (false negative) occurs when the alternative hypothesis is rejected when it should be accepted.
The probability determines the rejection of a null hypothesis.
The level of significance is set at p <0.05.
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This question is part of the following fields:
- Statistical Methods
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Question 36
Incorrect
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A 72-year old man has presented to the emergency room with sweating, nausea, chest pain, and an ECG that shows ST elevation. The ST segment of the ECG corresponds to a period of slow calcium influx in the cardiac action potential.
This equates to which phase in the cardiac action potential?Your Answer:
Correct Answer: Phase 2
Explanation:Understanding of the cardiac action potential helps with the understanding of the ECG which measures the electrical activity of the heart. This is reflected in its waveform.
The rapid depolarisation phase is reflected in the QRS complex. After this phase comes the plateau phase which is represented by the ST segment. Lastly, the T wave shows repolarisation, phase 3.The cardiac action potential has several phases which have different mechanisms of action as seen below:
Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
These channels automatically deactivate after a few msPhase 1: caused by early repolarisation and an efflux of potassium.
Phase 2: Plateau – caused by a slow influx of calcium. (ST segment)
Phase 3 – Final repolarisation – caused by an efflux of potassium. (T wave)
Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potentialOf note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.
Different sites have different conduction velocities:
1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec2. AV node conduction – 0.05 m/sec
3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 37
Incorrect
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The renal glomerulus is able to filter 180 litres of blood per day, as determined by the starling forces present in the glomerulus. Ninety-nine percent of which is reabsorbed thereafter.
Water is reabsorbed in the highest proportion in which segment of the nephron?Your Answer:
Correct Answer: Proximal convoluted tubule
Explanation:Sixty-seven percent of filtered water is reabsorbed in the proximal tubule. The driving force for water reabsorption is a transtubular osmotic gradient established by reabsorption of solutes (e.g., NaCl, Na+-glucose).
Henle’s loop reabsorbs approximately 25% of filtered NaCl and 15% of filtered water. The thin ascending limb reabsorbs NaCl by a passive mechanism, and is impermeable to water. Reabsorption of water, but not NaCl, in the descending thin limb increases the concentration of NaCl in the tubule fluid entering the ascending thin limb. As the NaCl-rich fluid moves toward the cortex, NaCl diffuses out of the tubule lumen across the ascending thin limb and into the medullary interstitial fluid, down a concentration gradient as directed from the tubule fluid to the interstitium. This mechanism is known as the counter current multiplier.
The distal tubule and collecting duct reabsorb approximately 8% of filtered NaCl, secrete variable amounts of K+ and H+, and reabsorb a variable amount of water (approximately 8%-17%).
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This question is part of the following fields:
- Physiology
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Question 38
Incorrect
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A 50-year-old man, presents to the hospital with bilateral inguinal hernias.
After examination and investigation, the surgical team decides to perform a laparoscopic hernia repair using the extraperitoneal approach. After making an infraumbilical incision, the surgeons perform the repair by placing a prosthetic mesh over the affected area, after shifting the inferior aspect of the rectus abdominis muscle anteriorly.
Name the structure that would like posterior to the mesh?Your Answer:
Correct Answer: Peritoneum
Explanation:This question is asking which structure would lie posterior to the rectus abdominis muscle and not the prosthetic mesh, as only peritoneum lies posterior to mesh during a total extraperitoneal (TEP) hernia repair.
The region of the repair lies below the arcuate line, meaning that the transversalis fascia and peritoneum lie posterior to the rectus abdominis.
The bucks fascia lies within the penis.
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This question is part of the following fields:
- Anatomy
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Question 39
Incorrect
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What does therapeutic index in humans mean?
Your Answer:
Correct Answer: The TD50 divided by the ED50
Explanation:Therapeutic index is a measure which relates the dose of a drug required to produce a desired effect to that which produces an undesired effect.
In humans, it is usually defined as the ratio of the toxic dose for 50% of the population (TD50) to the minimum effective dose for 50% of the population (ED50) for some therapeutically relevant effect. In animal studies, the therapeutic index can be defined as the ratio of the median lethal dose (LD50) to the ED50.
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This question is part of the following fields:
- Pharmacology
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Question 40
Incorrect
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A 60-year-old man had previously been diagnosed with Type 2 diabetes. He had recently started gliclazide, a sulphonyl urea, as his diabetes was not controlled by metformin alone.
Now, he presents to his physician with complaints of anxiety, sweating, and palpitations since the morning. On physical examination, he is pale and clammy and has mydriasis and increased bowel sounds.
Which biological site primarily synthesizes the hormone responsible for this patient's condition?Your Answer:
Correct Answer: Chromaffin cells of the adrenal medulla
Explanation:This patient has been shifted to a sulfonylurea drug whose most common side effect is hypoglycaemia. Similar symptoms can arise in a patient on insulin too. The signs and symptoms are consistent with a hypoglycaemic attack and include tachycardia, altered consciousness, and behaviour. This needs to be treated as an emergency with rapid correction of the blood glucose level using glucose or IV 20% dextrose.
In a hypoglycaemic attack, the body undergoes stress and releases hormones to increase blood glucose levels. These include:
Glucagon
Cortisol
AdrenalineAdrenaline or epinephrine is the hormone responsible for this patient’s condition and is primarily produced in the medulla of the adrenal gland. It functions primarily to raise cardiac output and raise blood glucose levels in the blood.
Alpha-cells of the islets of Langerhans produce the hormone glucagon, which has opposing effects to insulin.
Follicular cells of the thyroid gland produce and secrete thyroid hormones. Thyroid hormones can cause similar symptoms, but it is unlikely with the patient’s medical history.
Post-ganglionic neurons of the sympathetic nervous system use norepinephrine as a neurotransmitter. Adrenaline can be made in these cells, but it is not their primary production site.
Zona fasciculata of the adrenal cortex is the main site for the production of cortisol.
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This question is part of the following fields:
- Anatomy
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Question 41
Incorrect
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A 30-year-old woman admitted following a tonsillectomy has developed stridor with a respiratory rate of 22 breaths per minute and obstructive movements of the chest and abdomen that is in a see-saw pattern .
Her SpO2 is 92% on 60% oxygen with pulse rate 120 beats per minute while her blood pressure is 180/90mmHg. She is repeatedly trying to remove the oxygen mask and appears anxious.
Her pharynx is suctioned and CPAP applied with 100% oxygen via a Mapleson C circuit.
Which of these is the most appropriate next step in her management?Your Answer:
Correct Answer: Administer intravenous propofol 0.5 mg/kg
Explanation:Continuous closure of the vocal cords resulting in partial or complete airway obstruction is called Laryngospasm. It is a reflex that helps protect against pulmonary aspiration.
Predisposing factors include: Hyperactive airway disease, Insufficient depth of anaesthesia, Inexperience of the anaesthetist, Airway irritation, Smoking, Shared airway surgery and Paediatric patients
Its primary treatment includes checking for blood or stomach aspirate in the pharynx, removing any triggering stimulation, relieving any possible supra-glottic component to airway obstruction and application of CPAP with 100% oxygen.
In this patient, all the above has been done and the next treatment of choice is the administration of a rapidly acting intravenous anaesthetic agent such as propofol (0.5 mg/kg) in increments as it has been reported to relieve laryngospasm in approximately 75% of cases. Administering suxamethonium to an awake patient would be inappropriate at this stage.
Magnesium and lidocaine are used for prevention rather than acute treatment of laryngospasm. Superior laryngeal nerve blocks have been reported to successfully treat recurrent laryngospasm but it is not the next logical step in index patient.
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This question is part of the following fields:
- Pathophysiology
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Question 42
Incorrect
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A 25-year -old man, presents with a suspected uretic colic and is placed on admission. An abdominal x-ray of the kidney, ureter and bladder (KUB) is ordered.
Where is the stone most likely to be located on x-ray?Your Answer:
Correct Answer: The tips of the transverse processes between L2 and L5
Explanation:The ureter runs anterior to the vertebrae at the level of L2 to L5, and stones are usually seen at these points on x-ray.
They can also be seen at the level of the sacro-iliac joints.
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This question is part of the following fields:
- Anatomy
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Question 43
Incorrect
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A 25-year-old male has tonsillitis and is in considerable pain.
Which nerve is responsible for the sensory innervation of the tonsillar fossa?Your Answer:
Correct Answer: Glossopharyngeal nerve
Explanation:A tonsillar sinus or fossa is a space that is bordered by the triangular fold of the palatoglossal and palatopharyngeal arches in the lateral wall of the oral cavity. The palatine tonsils are in these sinuses.
The glossopharyngeal nerve is the main sensory nerve for the tonsillar fossa. The tonsillar branches of the glossopharyngeal nerve supply the palatine tonsils forming a plexus around it. Filaments from this plexus are distributed to the soft palate and fauces where they communicate with the palatine nerves. A lesser contribution is made by the lesser palatine nerve. Because of this otalgia may occur following tonsillectomy.
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This question is part of the following fields:
- Anatomy
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Question 44
Incorrect
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Clearance techniques are used to assess renal glomerular function.
Which of the following is the most accurate marker for glomerular filtration rate measurement?Your Answer:
Correct Answer: Inulin
Explanation:The perfect glomerular filtration marker is:
The human body is not harmed by it.
Chemical or physical methods are used to accurately measure
Extracellular fluid (ECF) compartment is freely and evenly diffusible.
Inability to access the intracellular fluid (ICF) compartment
Filtration in the kidney is the only way to remove it from the blood.The ideal marker should not be reabsorbed into the bloodstream by the renal tubules or other urinary system components.
Creatinine is an endogenous substance that is filtered freely by the glomerulus and secreted by the proximal tubule. As a result, creatinine clearance consistently underestimates GFR. In healthy people, this overestimation ranges from 10% to 40%, but it is higher and more unpredictable in patients with chronic kidney disease.
The gold standard method of inulin clearance necessitates an intravenous infusion and several hours of timed urine collection, making it costly and time-consuming. Inulin is hard to come by and is difficult to mix and keep as a solution.
Exogenous filtration markers include the following:
Although plasma clearance of 51chromium EDTA is a widely used method in Europe, tubular reabsorption can occur.
Because 125I-iothalamate can be excreted by renal tubules in the urine, it cannot be used in patients who have an iodine assay.Radioactive substances must be stored, administered, and disposed of according to these methods.
The glomerulus filters para-aminohippuric acid (PAH) freely, and any that remains in the peritubular capillaries is secreted into the proximal convoluted tubules. This marker is used to determine the amount of blood flowing through the kidneys.
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This question is part of the following fields:
- Pathophysiology
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Question 45
Incorrect
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A study of 1500 participants is designed to determine the normal range for a number of parameters in a certain population.
Analysis has revealed that there is a strong positive correlation between height and forced expiratory volume (FEV1).
Which of the following statistical technique can be utilized to predict FEV1 at any given height in this cohort?Your Answer:
Correct Answer: Linear regression
Explanation:A forest plot is a graphical representation that summarizes the findings of several research, such as a meta-analysis of a series of randomized controlled trials.
The Kaplan-Meier estimate shows survival over time, for example, plotting the number of patients still alive seven years after chemotherapy for lung cancer.
Fisher’s exact test similarly uses contingency tables to assess statistical significance, however, it is typically used when sample sizes are small.
Chi-square test assesses whether an association exists between two categorical variables using the observed and expected frequencies. For instance, is social class (I-V) related to body mass index (BMI) category? Using the observed and anticipated frequencies, the Chi-square test determines whether a connection exists between two categorical variables. For example, is socio-economic status related to BMI category?
Linear regression is a technique which attempts to model the relationship between two variables by fitting a linear equation to observed data. Linear regression uses correlation between two continuous variables. As correlation only indicates the strength of an association only, it cannot be used to forecast the change in one variable when a second variable is altered.
This equation takes the form y = mx + c, where ‘y’ is the dependent variable, ‘x’ is the independent variable, ‘m’ is the slope of the line and ‘c’ is the intercept. In this example, for a range of heights, it would be possible to map a line of best fit to a scatter plot and thus predict the forced expiratory volume (FEV1) for an individual.
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This question is part of the following fields:
- Statistical Methods
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Question 46
Incorrect
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A global cerebral blood flow (CBF) of 35 ml/100 g/min (Normal CBF = 54 ml/100 g/min) can lead to which of the following?
Your Answer:
Correct Answer: Poor prognostic EEG
Explanation:CBF is defined as the blood volume that flows per unit mass per unit time in brain tissue and is typically expressed in units of ml blood/100 g tissue/minute. The normal average CBF in adults human is about 50 ml/100 g/min, with lower values in the white matter (,20 ml/100 g/min) and greater values in the gray matter (,80 ml/100 g/min).
Low CBF levels between 30-40 ml/100 g/min may begin to show poor prognostic EEG. EEG findings consistently associated with a poor outcome are isoelectric EEG, low voltage EEG, and burst suppression (specifically burst suppression with identical bursts), as well as the absence of EEG reactivity.
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This question is part of the following fields:
- Physiology
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Question 47
Incorrect
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A 30-year-old woman with a BMI of 24 kg/m2 consumes four glasses of wine on an empty stomach. Her serum alcohol are levels measured over the following five hours. The serum alcohol level of 30-year-old man with the same BMI and alcohol consumption is also measured over the same duration.
The peak concentration of alcohol is found to be greater in the woman than in the man.
Which of these offers best explanation for this observation?Your Answer:
Correct Answer: Lower volume of distribution
Explanation:The blood alcohol concentration depends on:
-The rate of alcohol absorption from the gastrointestinal tract
-The volume of distribution of alcohol in the body, and
-The rate of elimination of alcohol from the body.Total body water is approximately 50% in a female as compared to 60% in a typical male. This means that the volume of distribution of alcohol is lower in female compared with men. This is the principal reason for higher peak in alcohol levels.
About 4% of ingested alcohol is metabolised by the liver accounting for first pass metabolism and 0.4% is metabolised by gastric alcohol dehydrogenase (ADH). The absorbed alcohol is NOT distributed to fat cells but it is distributed throughout the water compartments (plasma, interstitial and intracellular) of the body. Women have very little gastric ADH, which further influences this exaggerated rise.
85-98% of the alcohol is oxidised by the liver to acetaldehyde and then to acetate. The metabolic pathway initially observes first order kinetics and then saturation or zero order kinetics leading to peaks in alcohol levels.
Clearance of ethanol per unit lean body mass is lower in male. The calculated alcohol elimination rate and liver volume per kilogram of lean body mass were 33% and 38% higher in women than in men, respectively.
Available evidence in the literature about the relationship of alcohol metabolism to the phases of the menstrual cycle is conflicting.
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This question is part of the following fields:
- Pathophysiology
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Question 48
Incorrect
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An 82-year old male has shortness of breath which is made worse when he lies down but investigations have revealed a normal ejection fraction. Why might this be?
Your Answer:
Correct Answer: He has diastolic dysfunction
Explanation:Decreased stroke volume causes decreased ejection fraction which results in diastolic dysfunction.
Ejection fraction is not a useful measure in someone with diastolic dysfunction because stroke volume may be reduced whilst end-diastolic volume may be reduced.
Diastolic dysfunction may arise with reduced heart compliance.Ejection fraction measures of the proportion of blood leaving the ventricles with each beat and is calculated as follows:
Stroke volume / end-diastolic volume.A healthy ejection fraction is usually taken as 60% (based on a stroke volume of 70ml and end-diastolic volume of 120ml).
Respiratory inspiration causes a decreased pressure in the thoracic cavity, which in turn causes more blood to flow into the atrium.
Sitting up decreases venous because of the action of gravity on blood in the venous system.
Hypotension also decreases venous return.
A less compliant aorta, like in aortic stenosis increases end systolic left ventricular volume which decreases stroke volume.Systemic vascular resistance = mean arterial pressure / cardiac output.
Increased vascular resistance impedes the flow of blood back to the heart.Increased venous return increases end diastolic LV volume as there is more blood returning to the ventricles.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 49
Incorrect
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A 66-year-old man with a haemorrhagic stroke is admitted to the medical admissions unit.
He has been taking warfarin for a long time because of atrial fibrillation. His INR at the time of admission was 9.1.
Which of the following treatment options is the most effective in managing his condition?Your Answer:
Correct Answer: Prothrombin complex concentrate
Explanation:Haemorrhage, including intracranial bleeding, is a common and potentially fatal side effect of warfarin therapy, and reversing anticoagulation quickly and completely can save lives. When complete and immediate correction of the coagulation defect is required in orally anticoagulated patients with life-threatening haemorrhage, clotting factor concentrates are the only viable option.
For rapid reversal of vitamin K anticoagulants, prothrombin complex concentrates (PCC) are recommended. They contain the vitamin K-dependent clotting factors II, VII, IX, and X and are derived from human plasma. They can be used as an adjunctive therapy in patients with major bleeding because they normalise vitamin K dependent clotting factors and restore haemostasis.
The most common treatments are fresh frozen plasma (FFP) and vitamin K. The efficacy of this approach is questioned due to the variable content of vitamin K-dependent clotting factors in FFP and the effects of dilution. Significant intravascular volume challenge, as well as the possibility of rare complications like transfusion-associated lung injury or blood-borne infection, are all potential issues.
To avoid anaphylactic reactions, vitamin K should be given as a slow intravenous infusion over 30 minutes. Regardless of the route of administration, the reversal of INRs with vitamin K can take up to 24 hours to reach its maximum effect.
Reversal of anticoagulation in patients with warfarin-associated intracranial haemorrhage may be considered with factor VIIa (recombinant), but its use is controversial. There are concerns about thromboembolic events following treatment, as well as questions about assessing efficacy in changes in the INR. If the drug is to be administered, patients should be screened for an increased risk of thrombosis before the drug is given.
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This question is part of the following fields:
- Pathophysiology
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Question 50
Incorrect
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A 20-year-old male student is admitted to ER after sustaining a crush injury of the pelvis.
Clinical examination is as follows:
Airway: Patent
Breathing: RR: 25 breaths per minute, breath sounds vesicular, nil added
Circulation: Capillary refill time = 4 seconds, cool peripheries
Pulse: 125 beats per minute
BP: 125/96 mmHg
Disability:
Glasgow coma score 15
Anxious and in pain.
Secondary survey does not reveal any other significant injuries. The patient is given high flow oxygen therapy and intravenous access is established.
Which one of the following options is the most appropriate initial route of intravenous access?Your Answer:
Correct Answer: Left cephalic vein
Explanation:The clinical signs suggest a class II haemorrhage – 15-30% of circulating blood volume has been lost.
Pelvic fractures are associated with significant concealed haemorrhage (>2000 ml) and may require aggressive fluid resuscitation. Other priorities include stabilisation of the fracture(s) and pain relief.
The Advanced Trauma Life Support (ATLS) classification of haemorrhagic shock is as follows:
Class I haemorrhage (blood loss up to 15%):
<750 ml of blood loss
Minimal tachycardia
No changes in blood pressure, RR or pulse pressure
Normally not require fluid replacement as will be restored in 24 hours, but in trauma correct.Class II haemorrhage (15-30% blood volume loss):
Uncomplicated haemorrhage requiring crystalloid resuscitation
Represents about 750 – 1500 ml of blood loss
Tachycardia, tachypnoea and a decrease in pulse pressure (due to a rise in diastolic component due action of catecholamines)
Minimal systolic pressure changes
Anxiety, fright or hostility
Can usually be stabilised by crystalloid, but may later require a blood transfusion.Class III haemorrhage (30-40% blood volume loss):
Complicated haemorrhagic state in which at least crystalloid and probably blood replacement are required
Classical signs of inadequate perfusion, marked tachycardia, tachypnoea, significant changes in mental state and measurable fall in systolic pressure
Almost always require blood transfusion, but decision based on patient initial response to fluid resuscitation.Class IV haemorrhage (> 40% blood volume loss):
Preterminal event patient will die in minutes
Marked tachycardia, significant depression in systolic pressure and very narrow pulse pressure (or unobtainable diastolic pressure)
Mental state is markedly depressed
Skin cold and pale
Need rapid transfusion and immediate surgical intervention.Loss of >50% results in loss of consciousness, pulse and blood pressure.
The route of choice is an arm vein (cephalic) with one or two large bore cannula. This will enable initial aggressive fluid resuscitation. A central line can be inserted at a later stage if central venous monitoring is deemed necessary. If a suitable peripheral vein cannot be cannulated with a large bore cannula then the internal jugular vein could be accessed rapidly (preferably ultrasound guided).
Intravenous access below the diaphragm in this case is inadvisable when other routes are available.
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This question is part of the following fields:
- Anatomy
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Question 51
Incorrect
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A 60-year-old man, presents to the emergency department with crushing pain in the central chest area, which radiates to his left arm and jaw. He also reports feelings of nausea with no other symptoms. Elevation of the ST-segment is noted in multiple chest leads upon ECG, leading to a diagnosis of ST-elevation MI.
What vessel gives rise to the coronary vessels?Your Answer:
Correct Answer: Ascending aorta
Explanation:The above mentioned patient presentation is one of an acute coronary syndrome.
The elevations noted in the ST-segments of multiple heart leads on ECG is diagnostic of an ST-elevation myocardial infarction.
The pulmonary artery branches to give rise to the right and left pulmonary arteries, which supply deoxygenated blood to the right and left lungs from the right ventricle.
The pulmonary veins do not form any bifurcations, and therefore do not give rise to any vessels. They travel to the left atrium from the lungs, carrying oxygenated blood.
The descending aorta continues from the aortic arch, and bifurcates to give off many branches, including the right and left common iliac arteries.
The coronary sinus is formed from the combination of four coronary veins, receiving blood supply from the great, middle, small and posterior cardiac veins, and transporting this venous blood into the right atrium.
The right and left aortic sinus give rise to the right and left coronary arteries, respectively. They branch of the ascending aorta, in the area just superior to the aortic valve.
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This question is part of the following fields:
- Anatomy
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Question 52
Incorrect
-
Which of the following is true regarding a laryngoscope?
Your Answer:
Correct Answer: The Wisconsin and Seward are examples of straight blade laryngoscopes
Explanation:Direct laryngoscopy are performed using laryngoscopes and they can be classed according to the shape of the blade as curved or straight.
Miller, Soper, Wisconsin and Seward are examples of straight blade laryngoscopes. Straight blades are commonly used for intubating neonates and infants but can be used in adults too.
The tip of the miller blade is advanced over the epiglottis to the tracheal entrance then lifted in order to view the vocal cords.
The RIGHT-SIDED Macintosh blade is used in adults while the left-sided blade may be used in conditions that make intubation with standard blade difficult e.g. facial deformities.
The McCoy laryngoscope is based on the STANDARD MACINTOSH blade not Robertshaw’s. It has a lever operated hinged tip, which improves the view during laryngoscopy.
Polio blade is mounted at an angle of 120-135 degrees to the handle. Originally designed for use during the polio epidemic in intubation patients within iron lung ventilators, it is now useful in patients with conditions like breast hypertrophy, barrel chest, and restricted neck mobility.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 53
Incorrect
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A 25 year-old female came to the out-patient department with complaints of vaginal discharge with a distinct fishy odour. She was later diagnosed with bacterial vaginosis and was prescribed to take metronidazole.
The mechanism of action of metronidazole is?Your Answer:
Correct Answer: Interferes with bacterial DNA synthesis
Explanation:Metronidazole is a nitroimidazole antiprotozoal drug that is selectively absorbed by anaerobic bacteria and sensitive protozoa. Once taken up be anaerobes, it is nonenzymatically reduced by reacting with reduced ferredoxin. This reduction results in products that accumulate in and are toxic to anaerobic cells. The metabolites of metronidazole are taken up into bacterial DNA, forming unstable molecules. This action occurs only when metronidazole is partially reduced, and, because this reduction usually happens only in anaerobic cells, it has relatively little effect on human cells or aerobic bacteria.
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This question is part of the following fields:
- Pharmacology
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Question 54
Incorrect
-
Which of the following is true regarding the dose of propofol?
Your Answer:
Correct Answer: 1-2mg/kg
Explanation:Propofol is a short-acting medication used for starting and maintenance of general anaesthesia, sedation for mechanically ventilated adults, and procedural sedation.
The dose of propofol is 1-2 mg/kg.Dose of some other important drugs are listed below:
Thiopental dose: 3-7 mg/kg
Ketamine dose: 1-2 mg/kg
Etomidate dose: 0.3 mg/kg
Methohexitone dose: 1.0-1.5 mg/kg -
This question is part of the following fields:
- Pharmacology
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Question 55
Incorrect
-
Because this benzodiazepine has a half-life of 2-4 hours, it is preferred for clinical use.
This benzodiazepine has which of the following properties that no other benzodiazepine has?Your Answer:
Correct Answer: It is water soluble at a pH of 3.5 and lipid soluble at a pH of 7.4
Explanation:Midazolam is the benzodiazepine in question. It’s the only benzodiazepine that undergoes tautomeric transformation (dynamic isomerism). The molecule is ionised and water soluble at pH 3.5, but when injected into the body at pH 7.4, it becomes unionised and lipid soluble, allowing it to easily pass through the blood brain barrier.
The half-life of midazolam is only 2-4 hours.
It is a GABAA receptor agonist because it is a benzodiazepine. GABAA receptors are found in abundance throughout the central nervous system, particularly in the cerebral cortex, hippocampus, thalamus, basal ganglia, and limbic system. GABAA receptors are ligand-gated ion channels, with the inhibitory neurotransmitter gamma-aminobutyric acid as the endogenous agonist. It is a pentameric protein (2, 2 and one subunit) that spans the cell membrane, and when the agonist interacts with the alpha subunit, a conformational change occurs, allowing chloride ions to enter the cell, resulting in neuronal hyperpolarization.
For status epilepticus, midazolam is not the drug of choice. Lorazepam is the benzodiazepine of choice for status epilepticus.
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This question is part of the following fields:
- Pharmacology
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Question 56
Incorrect
-
Conclusive evidence suggests that rate for the prevalence of schizophrenia in United Kingdom is around 1%.
Which term can be used to describe that?Your Answer:
Correct Answer: Endemic
Explanation:An epidemic is declared when the increase in a give disease is above a certain level in a specific interval of time.
An endemic is the general, usual level of a disease in a population at a particular time.
A pandemic is an epidemic that is spread across many countries and continents.
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This question is part of the following fields:
- Statistical Methods
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Question 57
Incorrect
-
A 63-year old male who has heart failure has peripheral oedema and goes to the GP's office. The GP notes that he is fluid-overloaded. This causes his atrial myocytes to release atrial natriuretic peptide (ANP). ANP's main action is by which of these mechanisms?
Your Answer:
Correct Answer: Antagonist of angiotensin II
Explanation:Atrial natriuretic peptide (ANP) is secreted mainly from myocytes of right atrium and ventricle in response to increased blood volume.
It is secreted by both the right and left atria (right >> left).It is a 28 amino acid peptide hormone, which acts via cGMP
degraded by endopeptidases.It serves to promote the excretion of sodium, lowers blood pressure, and antagonise the actions of angiotensin II and aldosterone.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 58
Incorrect
-
Which of the following statements is true regarding Entonox?
Your Answer:
Correct Answer: Exists only in gaseous form in a cylinder (under normal working conditions)
Explanation:Entonox is a gas that consists of 50% oxygen and 50% Nitrous oxide. Nitrous oxide is sometimes used for anaesthetics but in this combination, it works as a short-acting painkiller.
Under normal working conditions, it exists only in gaseous form in a cylinder. The gauge pressure of a full Entonox cylinder is 137 bar.
Entonox cylinders should be stored horizontally at a temperature above 0 C. At temperatures below this the nitrous oxide component may separate.
Pseudocritical temperature and pseudocritical pressure can be defined as the molal average critical temperature and pressure of mixture components. In other words, the pseudo-critical temperature is the temperature at which the two gases separate. The pseudo-critical temperature of Entonox is approximately -5.50 C
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This question is part of the following fields:
- Pharmacology
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Question 59
Incorrect
-
A 70-year-old man presents with central crushing chest pain that radiates to the jaw in the emergency department. He has associated symptoms of nausea and diaphoresis.
A 12 lead ECG is performed. ST-elevation is observed in leads V2-V4. The diagnosis of anteroseptal ST-elevation myocardial infarction is made.
Which coronary vessel is responsible for this condition and runs in the interventricular septum on the anterior surface of the heart to reach the apex?Your Answer:
Correct Answer: Left anterior descending artery
Explanation:The heart receives blood supply from coronary arteries. The right and left coronary arteries branch off the aorta and supply oxygenated blood to all heart muscle parts.
The left main coronary artery branches into:
1. Circumflex artery – supplies the left atrium, side, and back of the left ventricle. The left marginal artery arises from the left circumflex artery. It travels along the obtuse margin of the heart.
2. Left Anterior Descending (LAD) artery – supplies the front and bottom of the left ventricle and front of the interventricular septumThe left anterior descending coronary artery is the largest coronary artery. It courses anterior to the interventricular septum in the anterior interventricular groove, extending from the base of the heart to its apex. Around the apex, the LAD anastomosis with the terminal branches of the posterior descending artery (branch of the right coronary artery).
Atherosclerosis or thrombotic occlusion of LAD causes myocardial infarction in large areas of the anterior, septal, and apical portions of the heart muscle. It can lead to a serious deterioration in heart performance.Occlusion of the LAD causes anteroseptal myocardial infarction, which is evident on the ECG with changes in leads V1-V4. Occlusion of the left circumflex artery causes lateral, posterior, or anterolateral MI. However, as it does not run towards the apex in the interventricular septum of the heart, it is not the correct answer for this question.
The right coronary artery branches into:
1. Right marginal artery
2. Posterior descending arteryThe right coronary artery supplies the right atrium, right ventricle, interatrial septum, and the inferior posterior third of the interventricular septum. Occlusion of the right coronary artery causes inferior MI, which is indicated on ECG with changes in leads II, III, and aVF.
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This question is part of the following fields:
- Anatomy
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Question 60
Incorrect
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You decide to conduct research on the normal rates of gastric emptying in healthy people. The strategy is to give a drug orally and measure plasma concentrations at predetermined intervals.
Which of the following drugs would you choose to use?Your Answer:
Correct Answer: Paracetamol
Explanation:Because of the low pH in the stomach, paracetamol absorption is minimal (pKa value is 9.5). Paracetamol is absorbed quickly and completely in the alkaline environment of the small intestine. Oral bioavailability is approaching 100%. As a result, measuring paracetamol levels in plasma after an oral paracetamol dose has been used as a surrogate marker of gastric emptying. This method has been used to investigate the effects of drugs on gastric emptying. At clinically used doses, paracetamol is ideal because it has very few side effects.
Scintigraphic imaging is the gold standard for determining gastric emptying.
Although aspirin (acetyl salicylic acid) is absorbed primarily in the small intestine, some may also be absorbed in the stomach. The oral bioavailability ranges from 70 to 100 percent, making it less reliable than paracetamol.
Propranolol is a lipophilic drug that is rapidly absorbed after administration. However, it is highly metabolised by the liver in the first pass, and only about 25% of propranolol reaches the systemic circulation. It’s not the best indicator of gastric emptying.
Oral bioavailability of gentamicin and vancomycin is low. Only antibiotic-induced pseudomembranous colitis is treated with oral vancomycin.
Erythromycin is a pro-kinetic agent that acts as a motilin receptor agonist.
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This question is part of the following fields:
- Pharmacology
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Question 61
Incorrect
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With regards to oxygen delivery in the body, which of these statements is true?
Your Answer:
Correct Answer: Anaemia will reduce oxygen delivery
Explanation:Oxygen delivery depends on 2 variables.
1) Content of oxygen in blood
2) Cardiac outputOxygen content (arterial) = (Hb (g/dL) x 1.39 x SaO2 (%) ) + (0.023 x PaO2 (kPa))
Oxygen content (mixed venous) = (Hb (g/dL) x 1.39 x mixed venous saturation) + (0.023 x mixed venous partial pressure of oxygen in kPA)
Huffner’s constant = 1.39 = 1g of Hb binds to 1.39 ml of O2
Oxygen delivery DO2 (ml/min) = 10 x Cardiac output (L/min) x Oxygen content
Normally 1000ml/minOxygen consumption VO2 (ml/min) = 10 x Cardiac output (L/min) x Difference in arterial and mixed venous oxygen content
Normally 250 ml/minOxygen extraction ratio (OER) = VO2/DO2
Normally approximately 25% -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 62
Incorrect
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Of the following, which of these oxygen carrying molecules causes the greatest shift of the oxygen-dissociation curve to the left?
Your Answer:
Correct Answer: Myoglobin (Mb)
Explanation:Myoglobin is a haemoglobin-like, iron-containing pigment that is found in muscle fibres. It has a high affinity for oxygen and it consists of a single alpha polypeptide chain. It binds only one oxygen molecule, unlike haemoglobin, which binds 4 oxygen molecules.
The myoglobin ODC is a rectangular hyperbola. There is a very low P50 0.37 kPa (2.75 mmHg). This means that it needs a lower P50 to facilitate oxygen offloading from haemoglobin. It is low enough to be able to offload oxygen onto myoglobin where it is stored. Myoglobin releases its oxygen at the very low PO2 values found inside the mitochondria.
P50 is defined as the affinity of haemoglobin for oxygen: It is the PO2 at which the haemoglobin becomes 50% saturated with oxygen. Normally, the P50 of adult haemoglobin is 3.47 kPa(26 mmHg).
Foetal haemoglobin has 2 ? and 2 ?chains. The ODC is left shifted – this means that P50 lies between 2.34-2.67 kPa [18-20 mmHg]) compared with the adult curve and it has a higher affinity for oxygen. Foetal haemoglobin has no ? chains so this means that there is less binding of 2.3 diphosphoglycerate (2,3 DPG).
Carbon monoxide binds to haemoglobin with an affinity more than 200-fold higher than that of oxygen. This therefore decreases the amount of haemoglobin that is available for oxygen transport. Carbon monoxide binding also increases the affinity of haemoglobin for oxygen, which shifts the oxygen-haemoglobin dissociation curve to the left and thus impedes oxygen unloading in the tissues.
In sickle cell disease, (HbSS) has a P50 of 4.53 kPa(34 mmHg).
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This question is part of the following fields:
- Physiology
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Question 63
Incorrect
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Which of the following is a correctly stated fundamental (base) SI unit?
Your Answer:
Correct Answer: A metre is the unit of length
Explanation:The international system of units, or system international d’unites (SI) is a collection of measurements derived from expanding the metric system.
There are seven base units, which are:
Metre (m): a unit of length
Second (s): a unit of time
Kilogram (kg): a unit of mass
Ampere (A): a unit of electrical current
Kelvin (K): a unit of thermodynamic temperature
Candela (cd): a unit of luminous intensity
Mole (mol): a unit of substance. -
This question is part of the following fields:
- Clinical Measurement
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Question 64
Incorrect
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A study was concerned with finding out the normal reference range of IgE levels in adults was conducted. Presuming that the curve follows a normal distribution, what is the percentage of individuals having IgE levels greater than 2 standard deviations from mean?
Your Answer:
Correct Answer: 2.30%
Explanation:Since the data is normally distributed, 95.4% of the values lie with in 2 standard deviations from mean. The rest of the 4.6% are distributed symmetrically outside of that range which means 2.3% of the values lie above 2 standard deviations of the mean.
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This question is part of the following fields:
- Statistical Methods
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Question 65
Incorrect
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When combined with a general anaesthetic or central neuraxial block, which of the following medications used to treat dementia involves the risk of significant hypotension?
Your Answer:
Correct Answer: Risperidone
Explanation:Atypical antipsychotic drugs include risperidone and quetiapine. They not only inhibit dopamine receptors in the limbic system, but also histamine (H1) and alpha2 adrenoreceptors. When combined with general and/or central neuraxial block, this might result in severe hypotension.
Donepezil (Aricept) is an acetylcholinesterase (AChE) inhibitor that increases the neurotransmitter acetylcholine in the cerebral cortex and hippocampus in a reversible, non-competitive manner. It is used to reduce the advancement of Alzheimer’s disease symptoms (AD). Rivastigmine and galantamine are two more drugs that work in the same way.
Ginkgo Biloba contains anti-oxidant characteristics and is used to treat early-stage Alzheimer’s disease, vascular dementia, and peripheral vascular disease. It lowers platelet adhesiveness and decreases platelet activating factor (PAF) increasing the risk f bleeding, especially in individuals who are also taking anticoagulants and antiplatelet medication.
Memantine is an antagonist of the NMDA receptor. Synaptic plasticity, which is thought to be a critical component of learning and memory, can be inhibited at high doses. The use of ketamine is a relative contraindication since antagonism of this receptor can cause a dissociative state.
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This question is part of the following fields:
- Pharmacology
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Question 66
Incorrect
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After consuming 12 g of paracetamol, a 37-year-old man is admitted to the medical admissions unit. He has hepatocellular necrosis in both clinical and biochemical aspects.
The most significant reason for paracetamol causing toxicity is?Your Answer:
Correct Answer: Glutathione is rapidly exhausted
Explanation:Phase I and phase II metabolism are used by the liver to break down paracetamol.
1st Phase:
Prostaglandin synthetase and cytochrome P450 (CYP1A2, CYP2E2, CYP3A4 and CYP2D6) to N-acetyl-p-benzoquinoneimine (NAPQI) and N-acetylbenzo-semiquinoneimine. NAPQI is a toxic metabolite that binds to the sulfhydryl groups of cellular proteins in hepatocytes, making it toxic. This can result in centrilobular necrosis.
Glutathione and glutathione transferases prevent NAPQI from binding to hepatocytes at low paracetamol doses by preferentially binding to these toxic metabolites. The cysteine and mercapturic acid conjugates are then excreted in the urine. Depletion of glutathione occurs at higher doses of paracetamol, resulting in high levels of NAPQI and the risk of hepatocellular damage. Hepatotoxicity would not be an issue if the body’s glutathione stores were sufficient.
N-acetylcysteine is a precursor for glutathione synthesis and is the drug of choice for the treatment of paracetamol overdose.
Phase II:
Conjugation with glucuronic acid to paracetamol glucuronide is the most common method of metabolism and excretion, accounting for 60% of renally excreted metabolites. Paracetamol sulphate (35%), unchanged paracetamol (5%), and mercapturic acid are among the other renally excreted metabolites (3 percent ). The capacity of conjugation pathways is limited. The capacity of the sulphate conjugation pathway is lower than that of the glucuronidation pathway.
Because of the low pH in the stomach, paracetamol absorption is minimal (pKa value is 9.5). Paracetamol is absorbed quickly and completely in the alkaline environment of the small intestine. Oral bioavailability is extremely high, approaching 100%.
As a result, measuring paracetamol levels in plasma after an injury is important. Peak plasma concentrations are reached after 30-60 minutes, with a volume of distribution of 0.95 L/kg. It binds to plasma proteins at a rate of 10% to 25%.
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This question is part of the following fields:
- Pharmacology
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Question 67
Incorrect
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An elderly man complains of a vague lump near his stomach to his physician. On examination, the lump is visible on coughing and is found within Hesselbach's triangle.
Which of the following is true regarding the borders for this triangle?Your Answer:
Correct Answer: Inguinal ligament inferiorly, inferior epigastric vessels laterally, lateral border of rectus sheath medially
Explanation:The inguinal triangle of Hesselbach is an important clinical landmark on the posterior wall of the inguinal canal. It has the following relations:
Inferiorly – medial third of the inguinal ligament
Medially – lower lateral border of the rectus abdominis
Laterally – inferior epigastric vesselsDirect inguinal hernia is when the bowel bulges directly through the abdominal wall. These hernias usually protrude through Hesselbach’s triangle
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This question is part of the following fields:
- Anatomy
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Question 68
Incorrect
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A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise. On urine culture and sensitivity testing, E.coli was detected with resistance to ampicillin.
What is the mechanism of resistance to ampicillin?Your Answer:
Correct Answer: Beta-lactamase production
Explanation:Ampicillin belongs to the family of penicillin. Resistance to this group of drugs is due to ?-lactamase production which opens the ?-lactam ring and inactivates Penicillin G and some closely related congeners. The majority of Staphylococci and some strains of gonococci, B. subtilis, E. coli, and a few other bacteria produce penicillinase.
Resistance to cephalosporins is due to changes in penicillin-binding proteins.
Resistance to macrolides are due to post-transcriptional methylation of 23s bacterial ribosomal RNA
Resistance to fluoroquinolones is due to mutations in DNA gyrase.
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This question is part of the following fields:
- Pharmacology
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Question 69
Incorrect
-
Which of the following statements is true with regards to acetylcholine?
Your Answer:
Correct Answer: Excess cholinesterase inhibitor medication causes cholinergic crisis
Explanation:Myasthenic and cholinergic crises are two crises which are similar in their clinical presentation.
Myasthenic crisis can be caused by:
-lack of acetylcholine,
-poor compliance with medication,
-infectionCholinergic crisis can be caused by excess cholinesterase inhibitor medication (mimicking organophosphate poisoning) causing excess acetylcholine.
Differentiation between the 2 crises is made by giving incremental doses of the short acting cholinesterase inhibitor, Edrophonium.
This increase acetylcholine levels and will make a myasthenic crisis better and a cholinergic crisis worse. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 70
Incorrect
-
Which of the following statements is true regarding drug dose and response?
Your Answer:
Correct Answer: Intrinsic activity determines maximal response
Explanation:There are two types of drug dose-response relationships, namely, the graded dose-response and the quantal dose-response relationships.
Drug response curves are plotted as percentage response again LOG drug concentration. This graph is sigmoid in shape.
Agonists are drugs with high affinity and high intrinsic activity. Meanwhile, the antagonist is a drug with high affinity but no intrinsic activity. Intrinsic activity determines the maximal response. The maximal response can be achieved even by activation of a small proportion of receptor sites.
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This question is part of the following fields:
- Pharmacology
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Question 71
Incorrect
-
A 57-year old lady is admitted to the Emergency Department with signs of a subarachnoid haemorrhage.
On admission, her GCS was 7. She has been intubated, sedated and is being ventilated and is waiting for a CT scan. Her Blood pressure is 140/70mmHg.
The arterial blood gas analysis shows the following:
pH 7.2 (7.35 - 7.45)
PaO2 70 mmHg (80-100)
9.2 kPa (10.5-13.1)
PaCO2 78 mmHg (35-45)
10.2 kPa (4.6-6.0)
BE -3 mEq/L (-3 +/-3)
Standard bic 27 mmol/L (21-27)
SaO2 94%
The most likely cause of an increase in the patient's global cerebral blood flow (CBF) is which of the following?
Your Answer:
Correct Answer: Hypercapnia
Explanation:PaCO2 is one of the most important factors that regulate cerebral vascular tone. CO2 induces cerebral vasodilatation and as a result, it increases CBF. Between 20 mmHg (2.7 kPa) and 80 mmHg (10.7 kPa), there is a linear increase of PaCO2.
Sometimes, there are areas where auto regulation has failed locally but not globally. Similarly, local vs. systemic acidosis will have similar effects. When the PaO2 falls below 50 mmHg (6.5 kPa), the CBF progressively increases.
An increase in the cerebral metabolic rate for oxygen (CMRO2) and therefore CBF can be caused by hyperthermia.
A late feature of cerebral injury is hyperthermia secondary to hypothalamic injury. Therefore this is not the most likely cause of an increased CBF in this scenario. -
This question is part of the following fields:
- Physiology
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Question 72
Incorrect
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In endurance athletes, which of the following physiological adaptations to exercise is the best predictor of performance?
Your Answer:
Correct Answer: Velocity of blood lactate accumulation
Explanation:Multiple regression analysis revealed that velocity of lactate accumulation (VOBLA) accounted for 92 percent of the variation in marathon running velocity (VM), and VOBLA plus training volume prior to the marathon accounted for 96 percent of the variation. Percent ST muscle fibre distribution (r = 0.55-0.69) and capillary density (r = 052-0.63) were found to be positively correlated with all performance variables. As a result, marathon running performance was linked to VOBLA and the ability to run at a pace close to it during the race. The percent ST, capillary density, and training volume were all related to these properties.
Another metabolic adaptation compared to normal people is the early selection of fat for oxidation by muscle, especially when glucose availability is limited during high-intensity exercise. This helps to delay the onset of muscle fatigue, but it does not prevent VOBLA.
For a given level of exercise, training can also result in cardiovascular adaptation, such as increased heart size, increased contractility, and a slower heart rate. All of these factors contribute to an increase in maximal oxygen consumption (VO2 max), but genetic factors, despite intensive training, play a large role in an athlete’s performance.
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This question is part of the following fields:
- Pathophysiology
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Question 73
Incorrect
-
A 26-year old male patient was admitted to the surgery department for appendectomy. Medical history revealed that he has major depressive disorder and was on Phenelzine. Aside from abdominal pain, initial assessment was unremarkable. However, thirty minutes after, the patient was referred to you for generalized seizures. He was given an analgesic and it was noted that, during the first 15 minutes of administration, he became anxious, with profuse sweating, which later developed into seizures. Upon physical examination, he was febrile at 38.3°C.
Which of the following statements is the best explanation for the patient's symptoms?Your Answer:
Correct Answer: Drug interaction with pethidine
Explanation:The clinical picture best describes a probable drug interaction with pethidine.
Phenelzine, a monoamine oxidase (MAO) inhibitor, when given with pethidine, an opioid analgesic, may lead to episodes of hypertension, rigidity, excitation, hyperpyrexia, seizures, coma and death. Studies have shown that pethidine reacts more significantly with MAO inhibitors than morphine.
When pethidine is metabolised to normeperidine, it acts as a serotonin reuptake inhibitor and cause an increase in serotonin levels in the brain. MAO inhibitors can also lead to elevated levels of serotonin because of its mechanism of action by inhibiting the enzyme monoamine oxidase that degrades serotonin.
The excess serotonin levels may lead to serotonin syndrome, of which some of the common precipitating drugs are selective serotonin reuptake inhibitors, MAO inhibitors, tricyclic antidepressants, meperidine, and St. John’s Wort. Onset of symptoms is within hours, which includes fever, agitation, tremor, clonus, hyperreflexia and diaphoresis.
Drug interaction between phenelzine and paracetamol do not commonly precipitate serotonin syndrome.
Neuroleptic malignant syndrome is due to dopamine antagonism, precipitated commonly by antipsychotics. Its onset of symptoms occur in 1 to 3 days, and is characterized by fever, encephalopathy, unstable vitals signs, elevated CPK, and rigidity.
Altered mental status is the most common manifestation of sepsis-associated encephalopathy. Patient also exhibit confusional states and inappropriate behaviour. In some cases, this may lead to coma and death.
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This question is part of the following fields:
- Pharmacology
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Question 74
Incorrect
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Which of these anaesthetics has the best chance of preventing HPV (hypoxic pulmonary vasoconstriction)?
Your Answer:
Correct Answer: Desflurane 2 MAC
Explanation:Resistance pulmonary arteries constrict in response to alveolar and airway hypoxia, diverting blood to better-oxygenated alveoli.
In atelectasis, pneumonia, asthma, and adult respiratory distress syndrome, hypoxic pulmonary vasoconstriction optimises O2 uptake. Hypoxic pulmonary vasoconstriction helps maintain systemic oxygenation during single-lung anaesthesia.
A redox-based O2 sensor within pulmonary artery smooth muscle cells is involved in hypoxic pulmonary vasoconstriction. The production of reactive oxygen species by smooth muscle cells in the pulmonary artery varies in proportion to PaO2. Hypoxic removal of these redox second messengers inhibits voltage-gated potassium channels, depolarizing smooth muscle cells in the pulmonary artery.
L-type calcium channels are activated by depolarization, which raises cytosolic calcium and causes hypoxic pulmonary vasoconstriction. Some anaesthetics suppress this response, increasing the risk of further deterioration in ventilation perfusion mismatch.
Agents that inhibit HPV are ether, halothane, and desflurane (>1.6 MAC).
Agents with no effect on HPV include thiopentone, fentanyl, desflurane (1MAC), isoflurane (<1.5MAC), sevoflurane(1MAC), and propofol. -
This question is part of the following fields:
- Pharmacology
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Question 75
Incorrect
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Risk stratification is done prior to a major cardiac surgery using cardiopulmonary exercise testing. Given the following options, which one is most likely to have the highest risk for post-operative cardiac morbidity?
Your Answer:
Correct Answer: Anaerobic threshold (AT) of less than 11 mL/kg/minute
Explanation:The ventilatory anaerobic threshold (VAT), formerly referred to as the anaerobic threshold, is an index used to estimate exercise capacity. During the initial (aerobic) phase of CPET, which lasts until 50–60% of Vo2max is reached, expired ventilation (VE) increases linearly with Vo2 and reflects aerobically produced CO2 in the muscles. Blood lactate levels do not change substantially during this phase, since muscle lactic acid production is minimal.
During the latter half of exercise, anaerobic metabolism occurs because oxygen supply cannot keep up with the increasing metabolic requirements of exercising muscles. At this time, there is a significant increase in lactic acid production in the muscles and in the blood lactate concentration. The Vo2 at the onset of blood lactate accumulation is called the lactate threshold or the VAT. The VAT is also defined as the point at which minute ventilation increases disproportionately relative to Vo2, a response that is generally seen at 60–70% of Vo2max.
The VAT is a useful measure as work below this level encompasses most daily living activities. The ability to achieve the VAT can help distinguish cardiac and non‐cardiac (pulmonary or musculoskeletal) causes of exercise limitation, since patients who fatigue before reaching VAT are likely to have a non‐cardiac problem.
When VAT is detected, patients with PVo2 of ⩽10 ml/kg/min have a high event rate.
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This question is part of the following fields:
- Pathophysiology
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Question 76
Incorrect
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A 28-year-old man is admitted to the critical care unit. He has been diagnosed with adult respiratory distress syndrome and is being ventilated. His haemodynamic condition is improved using a pulmonary artery flotation.
His readings are listed below:
Haemoglobin concentration: 10 g/dL
Mixed venous oxygen saturation: 70%
Mixed venous oxygen tensions (PvO2): 50 mmHg
Estimate his mixed venous oxygen content (mL/100mL).Your Answer:
Correct Answer: 9.5
Explanation:Mixed venous oxygen content (CvO2) is the oxygen concentration in 100mL of mixed venous blood taken from the pulmonary artery. It is usually 12-17 mL/dL (70-75%). It is represented mathematically as:
CvO2 = (1.34 x Hgb x SvO2 x 0.01) + (0.003 x PvO2)
Where,
1.34 = Huffner’s constant
Hgb = Haemoglobin level (g/dL)
SvO2 = % oxyhaemoglobin saturation of mixed venous blood
PvO2 = 0.0225 = mL of O2 dissolved per 100mL plasma per kPa, or 0.003 mL per mmHgTherefore,
CvO2 = (1.34 x 10 x 70 x 0.01) + (0.003 x 50)
CvO2 = 9.38 + 0.15 = 9.53 mL/100mL
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This question is part of the following fields:
- Clinical Measurement
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Question 77
Incorrect
-
A 64-year old male has shortness of breath on exertion and presented to the cardiology clinic. He has a transthoracic echo performed to help in assessing the function of his heart.
How can this echo aid in calculating cardiac output?Your Answer:
Correct Answer: (end diastolic LV volume - end systolic LV volume) x heart rate
Explanation:Cardiac output = stroke volume x heart rate
Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%
Stroke volume = end diastolic LV volume – end systolic LV volume
Pulse pressure = Systolic Pressure – Diastolic Pressure
Systemic vascular resistance = mean arterial pressure / cardiac output
Factors that increase pulse pressure include:
-a less compliant aorta (this tends to occur with advancing age)
-increased stroke volume -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 78
Incorrect
-
Many of the processes we deal with in anaesthesia entail a relationship between two or more variables.
Which of the following relationships is a linear relationship?Your Answer:
Correct Answer: The relationship between the junction potential and temperature in a thermocouple
Explanation:Two bonded wires of dissimilar metals, iron/constantan or copper/constantan, make up a thermocouple (constantan is an alloy of copper and nickel). At the tip, a thermojunction voltage is generated that is proportional to temperature (Seebeck effect).
All of the other connections are non-linear.
For a single compartment model, the relationship between a decrease in plasma concentration of an intravenous bolus of a drug and time is a washout exponential.
A sine wave is the relationship between current and degrees or time from a mains power source.
A sigmoid curve represents the relationship between efficacy and log-dose of a pure agonist on mu receptors.
The pressure of a fixed mass of gas and its volume (Boyle’s law) at a fixed temperature are inversely proportional, resulting in a hyperbolic curve.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 79
Incorrect
-
Which of the following statement is true regarding the paediatric airway?
Your Answer:
Correct Answer: The larynx is more anterior than in an adult
Explanation:In the neonatal stage, the tongue is usually large and comes to the normal size at the age of 1 year. The vocal cords lie inverse C4 and as it reaches the grown-up position inverse C5/6 by the age of 4 (not 1 year).
Due to the immature cricoid cartilage, the larynx lies more anterior in newborn children. That’s why the cricoid ring is the narrowest part of the paediatric respiratory tract, while in the adults the tightest portion of the respiratory route is vocal cords. The epiglottis is generally expansive and slants at a point of 45 degrees to the laryngeal opening.
The carina is the ridge of the cartilage in the trachea at the level of T2 in newborn (T4 in adults), that separates the openings of right and left main bronchi.
Neonates have a comparatively low number of alveoli and then this number gradually increases to a most extreme by the age of 8 (not 3 years).
Neonates are obligatory nose breathers and any hindrance can cause respiratory issues (e.g., choanal atresia).
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This question is part of the following fields:
- Physiology
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Question 80
Incorrect
-
All the following statements are false regarding local anaesthetic except
Your Answer:
Correct Answer: Potency is directly related to lipid solubility
Explanation:The potency of local anaesthetics is directly proportional to lipid solubility because they need to penetrate the lipid-soluble membrane to enter the cell.
Protein binding has a direct relationship with the duration of action because the higher the ability of the drug to bind with membrane protein, the higher is the duration of action.
Higher the pKa of a drug, slower the onset of action. Because a drug with higher pKa will be more ionized than the one with lower pKa at a given pH. Local anaesthetics are weak bases, and unionized form diffuses more rapidly across the nerve membrane than the protonated form. As a result drugs with higher pKa will be more ionized will diffuse less across the nerve membrane.
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This question is part of the following fields:
- Pharmacology
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Question 81
Incorrect
-
Which of the following statements is true regarding enantiomers?
Your Answer:
Correct Answer: Desflurane is a chiral compound
Explanation:A compound that contains an asymmetric centre (chiral atom or chiral centre) and thus can occur in two non-superimposable mirror-image forms (enantiomers) are called chiral compounds.
Desflurane, Halothane, and isoflurane are chiral compounds but Sevoflurane is not a chiral compound.
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This question is part of the following fields:
- Pharmacology
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Question 82
Incorrect
-
Which drug, if given to a pregnant woman, can lead to deleterious fetal effects due to its ability to cross the placenta?
Your Answer:
Correct Answer: Atropine
Explanation:It is well known that atropine will cross the placenta and that maternal administration results in an increase in fetal heart rate.
Atropine is highly selective for muscarinic receptors. Its potency at nicotinic receptors is much lower, and actions at non-muscarinic receptors are generally undetectable clinically. Atropine does not distinguish among the M1, M2, and M3 subgroups of muscarinic receptors. In contrast, other antimuscarinic drugs are moderately selective for one or another of these subgroups. Most synthetic antimuscarinic drugs are considerably less selective than atropine in interactions with nonmuscarinic receptors.
A study on glycopyrrolate, a quaternary ammonium salt, was found to have a fetal: maternal serum concentration ratio of 0.4 indicating partial transfer.
Heparin, suxamethonium, and vecuronium do not cross the placenta.
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This question is part of the following fields:
- Pharmacology
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Question 83
Incorrect
-
An air ambulance brought a young boy involved in a fight to the emergency department.
On examination, his blood pressure cannot be recorded. He suffers a stab wound to his chest that has penetrated the left atrium and the artery that supplies it.
Which artery is most likely damaged in this scenario?Your Answer:
Correct Answer: Left coronary artery
Explanation:The left atrium is supplied by the left coronary artery and its major branch the left circumflex.
The heart receives blood supply from coronary arteries. The right and left coronary arteries branch off the aorta and supply oxygenated blood to all heart muscle parts.
The left main coronary artery branches into:
1. Circumflex artery – supplies the left atrium, side, and back of the left ventricle. The left marginal artery arises from the left circumflex artery. It travels along the obtuse margin of the heart.
The left marginal artery, a branch of the circumflex artery, supplies the left ventricle.
2. Left Anterior Descending (LAD) artery – supplies the front and bottom of the left ventricle and front of the interventricular septumThe right coronary artery branches into:
1. Right marginal artery
2. Posterior descending arteryThe right coronary artery supplies the right atrium, right ventricle, interatrial septum, and the inferior posterior third of the interventricular septum. It also supplies the atrioventricular node + sinoatrial node in most patients. The posterior descending artery supplies the posterior third of the interventricular septum.
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This question is part of the following fields:
- Anatomy
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Question 84
Incorrect
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Question 85
Incorrect
-
A patient has a myocardial infarction with anterior ST elevation. There are the following observations:
Cardiac output 2.0 L/min
Blood pressure 80/60 mmHg
CVP 20 mmHg
SpO2 91% on 4 L/min oxygen
What is the most logical physiological explanation for these findings?Your Answer:
Correct Answer: Biventricular failure
Explanation:The occlusion of the left anterior descending (LAD) coronary artery causes anterior ST elevation myocardial infarction (STEMI). It has the worst prognosis of all the infarct locations due to its larger infarct size. It has a higher rate of total mortality (27 percent versus 11 percent), heart failure (41 percent versus 15 percent), and a lower ejection fraction on admission than an inferior myocardial infarction (38 percent versus 55 percent ).
The LAD artery supplies the majority of the interventricular septum, as well as the anterior, lateral, and apical walls of the left ventricle, as well as the majority of the right and left bundle branches and the bicuspid valve’s anterior papillary muscle (left ventricle).
The left or right ventricle’s end-diastolic volume (EDV) is the volume of blood in each chamber at the end of diastole before systole. Preload is synonymous with the EDV.
120 mL is a typical left ventricular EDV (range 65-240 mL). The EDV of the right ventricle in a typical range is (100-160 mL).
With an ejection fraction (EF) of less than 45 percent, the patient is most likely suffering from systolic dysfunction. Increases in right and left ventricular end-diastolic pressures and volumes are likely with a reduced EF because the ventricles are not adequately emptied. The left atrium and the pulmonary vasculature are affected by the increased pressures on the left side of the heart.
By causing an imbalance of the Starling forces acting across the capillaries, increased hydrostatic pressure in the pulmonary circulation favours the development of pulmonary oedema. With cardiogenic pulmonary oedema, capillary permeability is likely to remain unchanged.
Biventricular failure will result as a result of the pressure changes being transmitted to the right side of the circulation. The patient’s systemic vascular resistance is likely to be elevated as well, but it is not the most likely cause of his symptoms. The patient is suffering from cardiogenic shock as a result of biventricular failure. The patient has low cardiac output and is hypotensive. Right ventricular filling pressures are elevated, indicating right ventricular dysfunction.
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This question is part of the following fields:
- Clinical Measurement
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Question 86
Incorrect
-
Substitution at different positions of the barbituric ring give rise to different pharmacologic properties.
Substitution with and at which specific site of the ring affects lipid solubility the most?Your Answer:
Correct Answer: Sulphur atom at position 2
Explanation:Barbiturates are derived from barbituric acid, which itself is nondepressant, but appropriate side-chain substitutions result in CNS depressant activity that varies in potency and duration with carbon chain length, branching, and saturation.
Oxybarbiturates retain an oxygen atom on number 2-carbon atom of the barbituric acid ring.
Thiobarbiturates replace this oxygen atom with a sulphur atom, which confers greater lipid solubility. Generally speaking, a substitution such as sulphuration that increases lipid solubility is associated with greater hypnotic potency and more rapid onset, but shorter duration of action.
Addition of a methyl group to the nitrogen atom of the barbituric acid ring, as with oxybarbiturate methohexital, also results in a compound with a short duration of action.
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This question is part of the following fields:
- Pharmacology
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Question 87
Incorrect
-
What is NOT a feature of Propofol infusion syndrome?
Your Answer:
Correct Answer: Hypotriglyceridaemia
Explanation:Propofol infusion syndrome is a rare but extremely dangerous complication of propofol administration
Common organ systems affected by PRIS include the following:
1. cardiovascular
widening of QRS complex, Brugada syndrome-like patterns (particularly type 1), ventricular tachyarrhythmias, cardiogenic shock, and asystole2. hepatic
Liver enzymes elevation, hepatomegaly, and steatosis3. skeletal muscular
myopathy and overt rhabdomyolysis4. renal
Hyperkalaemia, acute kidney injury5. metabolic
High anion gap metabolic acidosis (due to elevation in lactic acid) -
This question is part of the following fields:
- Anatomy
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Question 88
Incorrect
-
Where should you insert a needle to obtain a femoral artery sample to be used for an arterial blood gas?
Your Answer:
Correct Answer: Mid inguinal point
Explanation:The needle should be inserted just below the skin at the mid inguinal point which is the surface indicator for the femoral artery.
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This question is part of the following fields:
- Anatomy
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Question 89
Incorrect
-
A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath and pleuritic chest pain. Her work requires her to travel internationally frequently. The consultant makes a diagnosis and treats her.
Now, the consultant recommends placing a filter that will prevent future incidents. A needle is placed into the femoral vein and passed up into the abdomen to insert the filter.
What is true regarding the organ where the filter is placed for this patient's condition?Your Answer:
Correct Answer: It is located posteriorly to the peritoneum
Explanation:The patient likely suffers from pulmonary embolism due to her history of frequent international travels. A filter is placed in the inferior vena cava to decrease the risk of future episodes of pulmonary embolism. The IVC filter is a small, wiry device that can catch blood clots and stop them from going into the heart and lungs. Your IVC is a major vessel that brings deoxygenated blood from the lower body to the heart, from where it is pumped into the lungs.
The filter is placed via a thin catheter inserted into the femoral vein in the groin. The catheter is gently moved up into your IVC, and a filter is introduced.
The IVC is a retroperitoneal organ.
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This question is part of the following fields:
- Anatomy
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Question 90
Incorrect
-
Which of the following vertebral levels is the site where the aorta perforates the diaphragm?
Your Answer:
Correct Answer: T12
Explanation:The diaphragm divides the thoracic cavity from the abdominal cavity. Structures penetrate the diaphragm at different vertebral levels through openings in the diaphragm to communicate between the two cavities. The diaphragm has openings at three vertebral levels:
T8: vena cava, terminal branches of the right phrenic nerve
T10: oesophagus, vagal trunks, left anterior phrenic vessels, oesophageal branches of the left gastric vessels
T12: descending aorta, thoracic duct, azygous and hemi-azygous vein -
This question is part of the following fields:
- Anatomy
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Question 91
Incorrect
-
Among the following which one is not a criterion for the assessment of causality?
Your Answer:
Correct Answer: Sensitivity
Explanation:For establishing a cause effect relationship, following criteria must be met:
1. Coherence & Consistency
2. Temporal Precedence
3. Specificity
As can be seen, sensitivity (The probability of a positive test) is not among these deciding factors..
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This question is part of the following fields:
- Statistical Methods
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Question 92
Incorrect
-
A 30 year old male was the victim of an electrocution injury and has been treated. The option that best describes the current levels for this injury is:
Your Answer:
Correct Answer: Tonic muscle contraction - 15 mA
Explanation:There are different effects of electrocution and these can be shown in the table below.
Current Effect
1 mA Tingling
5 mA Pain
15 mA Tonic muscle contraction
50 mA Respiratory arrest
100 mA Ventricular fibrillation and cardiac arrest -
This question is part of the following fields:
- Clinical Measurement
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Question 93
Incorrect
-
A 46-year old man was taken to the emergency room due to slow, laboured breathing. A relative reported that he's maintained on codeine 60 mg, taken orally every 6 hours for severe pain from oesophageal cancer. His creatinine was elevated, and glomerular filtration rate was severely decreased at 27 ml/minute.
Given the scenario above, which of the metabolites of codeine is the culprit for his clinical findings?Your Answer:
Correct Answer: Morphine-6-glucuronide
Explanation:Accumulation of morphine-6-glucuronide is a risk factor for opioid toxicity during morphine treatment. Morphine is metabolized in the liver to morphine-6-glucuronide and morphine-3-glucuronide, both of which are excreted by the kidneys. In the setting of renal failure, these metabolites can accumulate, resulting in a lowering of the seizure threshold. However, it does not occur in all patients with renal insufficiency, which is the most common reason for accumulation of morphine-6-glucuronide; this suggests that other risk factors can contribute to morphine-6-glucuronide toxicity.
The active metabolites of codeine are morphine and the morphine metabolite morphine-6-glucuronide. The enzyme systems responsible for this metabolism are: CYP2D for codeine and UGT2B7 for morphine, codeine-6-gluronide, and morphine-6-glucuronide. Both of these systems are subject to genetic variation. Some patients are ultrarapid metabolizers of codeine and produce higher levels of morphine and active metabolites in a very short period of time after administration. These increased levels will produce increased side effects, especially drowsiness and central nervous system depression.
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This question is part of the following fields:
- Pharmacology
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Question 94
Incorrect
-
An 81-year old man was admitted to the Pulmonology Ward due to chronic obstructive airway disease (COPD) exacerbation. Upon physical examination, he was hypertensive at 140/90 mmHg, tachycardic at 114 beats per minute, and tachypnoeic at 33 breaths per minute.
Arterial blood gas analysis was obtained and showed the following results:
pH: 7.25 (Reference range: 7.35-7.45)
PaO2: 73 mmHg (9.7 kPa) (Reference range: 11.3-12.6 kPa)
PaCO2: 56 mmHg (7.5 kPa) (Reference range: 4.7-6.0 kPa)
SaO2: 90%
Standard bicarbonate: 29 mmol/L (Reference range: 20-28)
BE: +4 mmol/L (± 2)
Which of the following options has the most significant impact on his respiratory rate?Your Answer:
Correct Answer: CSF pH
Explanation:The arterial blood gas analysis indicates presence of acute respiratory acidosis.
Central chemoreceptors are located in the ventral medulla and respond directly to presence of hydrogen ions in the CSF. When stimulated, it causes an increase in respiratory rate.
It is believed that hydrogen ions may be the only important direct stimulus for these neurons, however, CO2 is believed to stimulate these neurons secondarily by changing the hydrogen ion concentration.
Changes in O2 concentration have virtually no direct effect on the respiratory centre itself to alter respiratory drive. Although, O2 changes do have an indirect effect by acting through the peripheral chemoreceptors.
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This question is part of the following fields:
- Pathophysiology
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Question 95
Incorrect
-
The following statements concern the sensory innervation of the nasal passage:
Your Answer:
Correct Answer:
Explanation:The walls of the anterior nasal passage are supplied by the anterior ethmoidal branch of the nasociliary nerve, and the floor is innervated by the superior dental nerve (not the sphenopalatine nerves).
The walls and floor of the posterior nasal passage are innervated by the long and short sphenopalatine nerves and the great palatine nerve (not the superior dental nerves and the nasociliary nerve).
The vestibule is innervated by small branches of the infraorbital branch of the maxillary nerve.
The nasopharynx is innervated by the sensory branches of the trigeminal nerve (not the great palatine nerve).
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This question is part of the following fields:
- Anatomy
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Question 96
Incorrect
-
Left ventricular afterload is mostly calculated from systemic vascular resistance.
Which one of the following factors has most impact on systemic vascular resistance?Your Answer:
Correct Answer: Small arterioles
Explanation:Systemic vascular resistance (SVR), also known as total peripheral resistance (TPR), is the amount of force exerted on circulating blood by the vasculature of the body. Three factors determine the force: the length of the blood vessels in the body, the diameter of the vessels, and the viscosity of the blood within them. The most important factor that determines the systemic vascular resistance (SVR) is the tone of the small arterioles.
These are otherwise known as resistance arterioles. Their diameter ranges between 100 and 450 µm. Smaller resistance vessels, less than 100 µm in diameter (pre-capillary arterioles), play a less significant role in determining SVR. They are subject to autoregulation.
Any change in the viscosity of blood and therefore flow (such as due to a change in haematocrit) might also have a small effect on the measured vascular resistance.
Changes of blood temperature can also affect blood rheology and therefore flow through resistance vessels.
Systemic vascular resistance (SVR) is measured in dynes·s·cm-5
It can be calculated from the following equation:
SVR = (mean arterial pressure − mean right atrial pressure) × 80 cardiac output
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This question is part of the following fields:
- Physiology
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Question 97
Incorrect
-
A 53-year old female with a diagnosis of anaplastic thyroid carcinoma is admitted in the surgery department for an elective total thyroidectomy with radical neck dissection. The operation is expected to last for 10 hours.
Which of the following is the most suitable humidifier to use in an anaesthetic circuit for this case?Your Answer:
Correct Answer: Heat and moisture exchanger (HME)
Explanation:Adequate humidification is vital to maintain homeostasis of the airway. Heat and moisture exchangers conserve some of the exhaled water, heat and return them to inspired gases. Many heat and moisture exchangers also perform bacterial/viral filtration and prevent inhalation of small particles. Heat and moisture exchangers are also called condenser humidifier, artificial nose, etc. Most of them are disposable devices with exchanging medium enclosed in a plastic housing. For adult and paediatric age group different dead space types are available. Heat and moisture exchangers are helpful during anaesthesia and ventilatory breathing system. To reduce the damage of the upper respiratory tract through cooling and dehydration inspiratory air can be heated and humidified, thus preventing the serious complications. Moreover, they are the most appropriate humidification devices used for routine anaesthesia.
Gases can be bubbled through water to increase humidity. Passing gas through water at room temperature causes the gas to cool due to latent heat of vaporisation. The water bath can be heated. This improves the efficiency of the device and also reduces the incidence of bacterial colonisation.
Nebulisers use a venturi system which employs the Bernoulli effect. A gas at high flow passes through a constriction causing the gas to accelerate, reducing its potential energy allowing other gases or liquids to be entrained. This can include medications or in the case of humidification, water vapour. The size of the water droplet produced by nebulisation determines where in the airway it is deposited. Standard nebulisers produced droplets of 4 microns in diameter and these are deposited in the upper airway and trachea. Efficacy can be improved by passing the droplets over an anvil which further reduces particle size. The most efficient form of nebuliser is the ultrasonic nebuliser. Here a transducer immersed in water and vibrated at a frequency of 3MHz produces1-2micron droplets. These particles easily reach the bronchioles and provide excellent humidification.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 98
Incorrect
-
Regarding a drug whose elimination exhibits first-order kinetics, which of the following statements is correct?
Your Answer:
Correct Answer: The rate of elimination is proportional to plasma concentration
Explanation:The elimination of phenytoin follows first order kinetics. Plasma concentrations determine the rate of elimination. The relationship between drug X plasma concentration and time is described by an exponential process in the following equation used to describe the rate of elimination:
C = C0. e-kt
C=drug concentration, C0= drug concentration at time zero (extrapolated), k = rate constant and t=time
As enzyme systems become saturated when phenytoin concentrations are above the usual range, clearance of the medication becomes zero-order. The medication is metabolised at a constant pace, regardless of its plasma levels. Aspirin and ethyl alcohol are two more significant examples of medications that operate in this way.
A plot of drug concentration with time is a washout exponential curve.
A graph of concentration with time is a straight line i.e. Zero-order kinetics
The amount eliminated per unit time is constant defines the point at which zero order kinetics commences.
Elimination involves a rate-limiting reaction operating at its maximal velocity is incorrect.
The half life of the drug is proportional to the drug concentration in the plasma corresponds to a definition of first-order kinetics.
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This question is part of the following fields:
- Pharmacology
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Question 99
Incorrect
-
Regarding the classification of breathing systems, which of the following is true?
Your Answer:
Correct Answer: The Conway classification describes a functional classification based on whether a CO2 absorber is required
Explanation:Breathing system is an assembly of components which connects patient’s airway to anaesthesia machine through which controlled composition of gas mixture is dispensed. It delivers gas to the patient, removes expired gas and controls the temperature and humidity of the inspired mixture. It allows spontaneous, controlled, or assisted respiration. It may also provide ports for gas sampling, airway pressure, flow and volume monitoring.
Breathing systems have been classified by Conway and Mapleson.
Conway suggested a functional classification:
– Circuits requiring a CO2 absorber
– Circuits not requiring a CO2 absorberWilliam Mapleson designated varying arrangements of breathing system components (masks, breathing tubes, fresh gas flow inlets, adjustable pressure-limiting valves, and reservoir bags) as Mapleson A-E circuits.
Mapleson A: Arranged as FGF inlet, reservoir bag, APL valve, mask.
In this circuit, because the reservoir bag is between the FGF inlet valve and the APL valve, expired gas from the patient may re-enter the system and fill the reservoir bag during controlled ventilation. This is the most efficient system for spontaneous breathing as the FGF must only be equal to a patient’s minute ventilation to prevent rebreathing.Mapleson B: Arranged as reservoir bag, FGF inlet, APL valve, mask.
In this circuit, the FGF inlet is closer to the APL valve, which helps prevent the rebreathing concern in the Mapleson A circuit as above during controlled ventilation.Mapleson C: Arranged as reservoir bag, FGF inlet, APL valve, mask.
In this circuit, the arrangement is the same as the Mapleson B circuit. However, this circuit is shorter as it does not contain elongated corrugated tubing. This circuit also has the FGF inlet close to the APL valve to aid in preventing rebreathing.Mapleson D: Arranged as reservoir bag, APL valve, FGF inlet, and mask.
In this circuit, the arrangement interchanges the FGF inlet and APL valve of the Mapleson A circuit. This system prevents rebreathing by directing FGF towards the APL valve rather than towards the patient during exhalation.Mapleson E: Arranged as corrugated tubing, FGF inlet, and mask.
In this circuit, there is no reservoir bag and no APL valve. Given the inability to alter the pressure of the circuit, this is ideal for spontaneously ventilating neonates or paediatric patients where low-pressure ventilation is desired. The system prevents rebreathing, similar to the Mapleson D circuit.Jackson Rees later modified the Mapleson E by adding an open ended bag, which has since become known as the Mapleson F.
Mapleson F: Arranged as APL valve directly connected to reservoir bag, corrugated tubing, FGF inlet, and mask.
The system prevents rebreathing similarly to Mapleson D by directing FGF towards the APL valve. -
This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 100
Incorrect
-
Which compound is secreted only from the adrenal medulla?
Your Answer:
Correct Answer: Adrenaline
Explanation:The adrenal medulla comprises chromaffin cells (pheochromocytes), which are functionally equivalent to postganglionic sympathetic neurons. They synthesize, store and release the catecholamines noradrenaline (norepinephrine) and adrenaline (epinephrine) into the venous sinusoids.
The majority of the chromaffin cells synthesize adrenaline. -
This question is part of the following fields:
- Anatomy
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Question 101
Incorrect
-
Which statement is true with regards to the cardiac action potential?
Your Answer:
Correct Answer: Repolarization due to potassium efflux after calcium channels close causes the relative refractory period to start
Explanation:Cardiac conduction
Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium
Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop
Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period
Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period
Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 102
Incorrect
-
In North America, there have been reports of paediatric patients dying after undergoing adenotonsillectomy for obstructive sleep apnoea.
Respiratory depression/obstruction is thought to be the cause of death. The codeine dose was 0.5-1 mg/kg, given every 4-6 hours.
In this group of patients, which of the following is the most likely cause of respiratory depression and obstruction?Your Answer:
Correct Answer: Exaggerated metabolism of codeine
Explanation:Codeine is easily absorbed from the gastrointestinal tract and converted to morphine and norcodeine in the liver via O- and N-demethylation. Morphine and norcodeine are excreted almost entirely by the kidney, primarily as conjugates with glucuronic acid.
By glucuronidation, phase II metabolism enzyme UDP-glucuronosyl transferase-2B7 converts morphine to morphine-3-glucuronide (M3G) and morphine-6-glucuronide (M6G) (UGT2B7).
Approximately 60% of morphine is converted to M3G, with the remaining 6-10% converted to M6G. M3G is inactive, but M6G is said to be 4 to 650 times more potent on the MOP receptor than morphine.
When codeine is consumed, cytochrome P450 2D6 in the liver converts it to morphine (CYP2D6).
Some people have DNA variations that increase the activity of this enzyme, causing codeine to be converted to morphine more quickly and completely than in others. After taking codeine, these ultra-rapid metabolisers are more likely to have higher than normal levels of morphine in their blood.
Respiratory depression/obstruction can be caused by high levels of morphine and M6G, especially in people who have a history of obstructive sleep apnoea. The estimated number of ultra-rapid metabolisers ranges from 1 to 7 per 100 people, but some ethnic groups may have as many as 28 per 100 people.
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This question is part of the following fields:
- Pathophysiology
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Question 103
Incorrect
-
The production of carbon dioxide and water occurs during cellular respiration, which involves an energy substrate and oxygen. For a patient, the respiratory quotient is calculated as 0.7.
Which of the following energy substrate combinations is the most likely in this patient's diet?Your Answer:
Correct Answer: Low carbohydrate, high fat and low protein
Explanation:The respiratory quotient (RQ) is the proportion of CO2 produced by the body to O2 consumed per unit of time.
CO2 produced / O2 consumed = RQ
CO2 is produced at a rate of 200 mL per minute, while O2 is consumed at a rate of 250 mL per minute. An RQ of around 0.8 is typical for a mixed diet.
The RQ will change depending on the energy substrates consumed in the diet.
Granulated sugar is a refined carbohydrate that contains 99.999 percent carbohydrate and no lipids, proteins, minerals, or vitamins.
Glucose and other hexose sugars – RQ = 1
Fats – RQ = 0.7
Proteins – RQ is 0.9
Ethyl alcohol – RQ = 0.67 -
This question is part of the following fields:
- Pathophysiology
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Question 104
Incorrect
-
Which structure does NOT lie in the posterior triangle of the neck?
Your Answer:
Correct Answer: Internal jugular vein
Explanation:The sternocleidomastoid muscle divides the neck into anterior and posterior triangles on both sides of the neck.
The posterior triangle has the following boundaries:
anteriorly – sternocleidomastoid muscle
posteriorly – trapezius
roof – investing layer of deep cervical fascia
floor – prevertebral fascia overlying splenius capitis, levator scapulae, and the scalene musclesThe contents of the posterior triangle are:
1. fat
2. lymph nodes (level V)
3. accessory nerve
4. cutaneous branches of the cervical plexus (A major branch of this plexus is the phrenic nerve, which arises from the anterior divisions of spinal nerves C3-C5)
5. inferior belly of omohyoid
6. branches of the thyrocervical trunk (transverse cervical and suprascapular arteries)
7. third part of the subclavian artery
8. external jugular vein -
This question is part of the following fields:
- Anatomy
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Question 105
Incorrect
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A 30-year old female was anaesthetically induced for an elective open cholecystectomy. Upon mask ventilation, patient's oxygen saturation level dropped to 90% despite maximal head extension, jaw thrust and two handed mask seal. Intubation was performed twice but failed. Use of bougie also failed to localize the trachea. Oxygen levels continued to drop, but was maintained between 80 and 88% with mask ventilation.
Which of the following options is the best action to take for this patient?Your Answer:
Correct Answer: Insert a supraglottic airway
Explanation:A preplanned preinduction strategy includes the consideration of various interventions designed to facilitate intubation should a difficult airway occur. Non-invasive interventions intended to manage a difficult airway include, but are not limited to: (1) awake intubation, (2) video-assisted laryngoscopy, (3) intubating stylets or tube-changers, (4) SGA for ventilation (e.g., LMA, laryngeal tube), (5) SGA for intubation (e.g., ILMA), (6) rigid laryngoscopic blades of varying design and size, (7) fibreoptic-guided intubation, and (8) lighted stylets or light wands.
Most supraglottic airway devices (SADs) are designed for use during routine anaesthesia, but there are other roles such as airway rescue after failed tracheal intubation, use as a conduit to facilitate tracheal intubation and use by primary responders at cardiac arrest or other out-of-hospital emergencies. Supraglottic airway devices are intrinsically more invasive than use of a facemask for anaesthesia, but less invasive than tracheal intubation. Supraglottic airway devices can usefully be classified as first and second generation SADs and also according to whether they are specifically designed to facilitate tracheal intubation. First generation devices are simply ‘airway tubes’, whereas second generation devices incorporate specific design features to improve safety by protecting against regurgitation and aspiration.
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This question is part of the following fields:
- Physiology
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Question 106
Incorrect
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Which of the following lung parameters can be measured directly using spirometry?
Your Answer:
Correct Answer: Vital capacity
Explanation:Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).
It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.
During spirometry, the following measurements can be determined:
Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
Forced expiratory volume in one second (FEV1)
FEV1/FVC ratio
Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.
Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution
The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.
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This question is part of the following fields:
- Clinical Measurement
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Question 107
Incorrect
-
Which among the given options can be used to find out the number needed to treat?
Your Answer:
Correct Answer: 1 / (Absolute risk reduction)
Explanation:Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.
It can be found as:
NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).
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This question is part of the following fields:
- Statistical Methods
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Question 108
Incorrect
-
A 21-year-old woman presents to ER following the deliberate ingestion of 2 g of amitriptyline. On clinical examination:
Glasgow coma score: 10
Pulse rate: 140 beats per minute
Blood pressure: 80/50 mmHg.
ECG showed a QRS duration of 233 Ms.
Which of the following statement describes the most important initial course of action?Your Answer:
Correct Answer: Give fluid boluses
Explanation:The first line of treatment in case of hypotension is fluid resuscitation.
Activated charcoal can be used within one hour of tricyclic antidepressant ingestion but an intact and secure airway must be checked before intervention. The risk of aspiration should be assessed.
Vasopressors are indicated for the treatment of hypotension following (Tricyclic Antidepressant) TCA overdose when patients fail to respond to fluids and bicarbonate.
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This question is part of the following fields:
- Pharmacology
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Question 109
Incorrect
-
Regarding nerve supply to the vocal cords, which of the following provides sensation to the area above the vocal cords?
Your Answer:
Correct Answer: Internal branch of superior laryngeal nerve
Explanation:The laryngeal folds are comprised of two types of folds; the vestibular fold and the vocal fold. The vocal folds are mobile, and concerned with voice production. They are formed by the mucous membrane covering the vocal ligament. They are avascular, hence, are white in colour.
The internal branch of the superior laryngeal nerve provides sensation above the vocal cords. Lesions to this nerve may lead to loss of sensation above the vocal cords and loss of taste on the epiglottis.
The recurrent laryngeal nerve supplies the lateral and posterior cricoarytenoid, the thyroarytenoid. It also provides sensation below the vocal cords. Lesions to this nerve may cause respiratory obstruction, hoarseness, inability to speak and loss of sensation below the vocal cords.
The external branch of the superior laryngeal nerve supplies the cricothyroid muscle.
The glossopharyngeal nerve contains both sensory and motor components, and provides somatic innervation to the stylopharyngeus muscle, visceral motor innervation to the parotid gland, and carries afferent sensory fibres from the posterior third of the tongue, pharynx and tympanic cavity.
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This question is part of the following fields:
- Anatomy
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Question 110
Incorrect
-
Concerning the trachea, which of these is true?
Your Answer:
Correct Answer: In an adult is approximately 15 cm long
Explanation:In an adult, the trachea is approximately 15 cm long. It extends at the level of the 6th cervical vertebra, from the lower border of the cricoid cartilage.
The trachea terminates between T4 and T6 at the carina or bronchial bifurcation. This variation is because of changes during respiration.
The trachea has 16-20 C-shaped cartilaginous rings that maintain its patency.
The trachea is first of the 23 generations of air passages in the tracheobronchial tree (not 25), from the trachea to the alveoli..
The inferior thyroid arteries which are branches of the thyrocervical trunk, arise from the first part of the subclavian artery and supplies the trachea.
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This question is part of the following fields:
- Anatomy
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Question 111
Incorrect
-
Which of following statements is true regarding the comparison of fentanyl and alfentanil?
Your Answer:
Correct Answer: Fentanyl is more potent than alfentanil
Explanation:Fentanyl is a pethidine congener, 80–100 times more potent than morphine, both in analgesia and respiratory depression. Fentanyl is ten times more potent than alfentanil.
Alfentanil has a more rapid onset than fentanyl even if fentanyl is more lipid-soluble because both are basic compounds and alfentanil has lower pKa, so a greater proportion of alfentanil is unionized and is more available to cross membranes.
Elimination of alfentanil is higher than fentanyl due to its lower volume of distribution.
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This question is part of the following fields:
- Pharmacology
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Question 112
Incorrect
-
In which of the following situations will a regional fall in cerebral blood flow occur, suppose there is no changes in the mean arterial pressure (MAP)?
Your Answer:
Correct Answer: Hyperoxia
Explanation:The response of cerebral blood flow (CBF) to hyperoxia (PaO2 >15 kPa, 113 mmHg), the cerebral oxygen vasoreactivity is less well defined. A study originally described, using a nitrous oxide washout technique, a reduction in CBF of 13% and a moderate increase in cerebrovascular resistance in subjects inhaling 85-100% oxygen. Subsequent human studies, using a variety of differing methods, have also shown CBF reductions with hyperoxia, although the reported extent of this change is variable. Another study assessed how supra-atmospheric pressures influenced CBF, as estimated by changes in middle cerebral artery flow velocity (MCAFV) in healthy individuals. Atmospheric pressure alone had no effect on MCAFV if PaO2 was kept constant. Increases in PaO2 did lead to a significant reduction in MCAFV; however, there were no further reductions in MCAFV when oxygen was increased from 100% at 1 atmosphere of pressure to 100% oxygen at 2 atmospheres of pressure. This suggests that the ability of cerebral vasculature to constrict in response to increasing partial pressure of oxygen is limited.
Increases in arterial blood CO2 tension (PaCO2) elicit marked cerebral vasodilation.
CBF increases with general anaesthesia, ketamine anaesthesia, and hypoviscosity.
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This question is part of the following fields:
- Physiology
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Question 113
Incorrect
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The tissue layer in a patient is infiltrated with local anaesthetic (marcaine 0.125%) with 1 in 120,000 adrenaline as part of an enhanced recovery programme for primary hip replacement surgery. The total volume of solution is 120mL.
What is the appropriate combination of constituents in the final solution?Your Answer:
Correct Answer: 30mL 0.5% bupivacaine, 1mL 1 in 1,000 adrenaline and 89mL 0.9% N. Saline
Explanation:30mL 0.5% bupivacaine, 1mL 1 in 1,000 adrenaline and 89mL 0.9% N. Saline is the correct answer.
Initial concentration of bupivacaine is 0.5% with a volume of 30mLThe volume is doubled (60mL) by the addition of 0.9% N. saline (30mls) and the concentration of bupivacaine is halved to (0.25%).
If the volume is doubled again (120mL) by the addition of further 0.9% N. saline (59mls) the final concentration of bupivacaine is halved again to 0.125%. Total N. saline = 89mls
The 1 mL of 1 in 1000 adrenaline has also been diluted into the final volume of 120 mL making it a 1 in 120000 concentration.
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This question is part of the following fields:
- Pharmacology
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Question 114
Incorrect
-
Of the stated laws, which is correct?
Your Answer:
Correct Answer: Boyle's law states that at constant temperature the volume of a given mass of gas varies inversely with absolute pressure.
Explanation:Boyle’s law is correctly stated as it states that the volume of a gas of known mass is inversely proportional with absolute pressure, at a constant temperature.
Beer’s law states that radiation absorption by a solution of known thickness and concentration is identical to that of a solution of double thickness and half concentration.
Bougner’s (or Lambert’s) law states that every layer with the same thickness will absorb the same amount of radiation as it passes through.
Graham’s law states that the diffusion rate of a gas is inversely related to the square root of its molecular weight.
Raoult’s law states that the reduction of a solvent’s vapour pressure is directly proportional to the solute’s molar concentration.
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This question is part of the following fields:
- Statistical Methods
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Question 115
Incorrect
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Which statement regarding the cardiac action potential is correct?
Your Answer:
Correct Answer:
Explanation:Cardiac conduction
Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium
Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop
Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period
Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period
Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 116
Incorrect
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A 75-year-old man, visits his general practitioner. He complains of changes to his bowel habit and unexpected weight loss in the last 6 months. He is scheduled for a colonoscopy and biopsy where he is diagnosed with a transverse colon malignancy.
The transverse colon is one of many organs tethered to the posterior wall of the abdominal cavity by a double fold of the peritoneum.
Which of the listed organs is also tethered to the peritoneum in a similar way?Your Answer:
Correct Answer: The stomach
Explanation:The peritoneal cavity is made up of the omentum, the ligaments and the mesentery.
The section of the peritoneum responsible for tethering organs to the posterior abdominal wall is the mesentery.
These tethered organs are classified as intraperitoneal, and these include the stomach, spleen, liver, first and fourth parts of the duodenum, jejunum, ileum, transverse, and sigmoid colon.
Retroperitoneal organs are located posterior to the peritoneum and include: the rest of the duodenum, the ascending colon, the descending colon, the middle third of the rectum, and the remainder of the pancreas
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This question is part of the following fields:
- Anatomy
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Question 117
Incorrect
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A radiologist is conducting an arch aortogram. She begins by entering the brachiocephalic artery using the angiography catheter. As she continues to advance the catheter, what vessels will the catheter enter?
Your Answer:
Correct Answer: Right subclavian artery
Explanation:As there is no brachiocephalic artery on the left side, the artery is entered by the catheter on the right side.
The brachiocephalic artery branches into the common carotid and the right subclavian artery, so the catheter is most likely to enter the right subclavian artery, or also possibly the right carotid.
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This question is part of the following fields:
- Anatomy
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Question 118
Incorrect
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The liver plays a major role in drug metabolism.
Which of the following liver cells is most important in phase I of drug metabolism?Your Answer:
Correct Answer: Centrilobular cells
Explanation:The metabolism of drugs in the liver occurs in 3 phases
Phase I: This involves functionalization reactions, which are of 3 types, namely hydrolysis, oxidation and reduction reactions catalysed by the cytochrome P450 (CYP) enzymes.
Phase II: This involves conjugation or acetylation reactions. The goal is to create water soluble metabolites that can be excreted from the body.
The liver is the second largest organ. It’s smallest functional unit is the acinus which is divided into 3 zones:
Zone I (periportal): This zone receives the largest amount of oxygen supply as it is the closest to the blood vessels. It is the site of plasma protein synthesis.
Zone II (mediolobular): This is located between the portal triad and central vein.
Zone III (centrilobular): This is closest to the central vein and receives the least amount of oxygen supply.
Kupffer cells are specialized macrophages found in the periportal zone of the liver, and function to remove foreign particles and breakdown red blood cells via phagocytosis.
Ito cells are fat-storing liver cells found in the space of Disse. Their function is to take-uo, store and secrete retinoids, as well as manufacture and release proteins that make up the extracellular matrix.
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This question is part of the following fields:
- Pathophysiology
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Question 119
Incorrect
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Which of the following statements is true regarding the relation to the liver?
Your Answer:
Correct Answer: The caudate lobe is superior to the porta hepatis
Explanation:Ligamentum venosum is an anterior relation of the liver: The ligamentum venosum, the fibrous remnant of the ductus venosus of the fetal circulation, lies posterior to the liver. It lies in the fossa for ductus venosus that separates the caudate lobe and the left lobe of the liver.
The portal triad contains three important tubes: 1. Proper hepatic artery 2. Hepatic portal vein 3. Bile ductules It also contains lymphatic vessels and a branch of the vagus nerve.
The bare area of the liver is a large triangular area that is devoid of any peritoneal covering. The bare area is attached directly to the diaphragm by loose connective tissue. This nonperitoneal area is created by a wide separation between the coronary ligaments.
The porta hepatis is a fissure in the inferior surface of the liver. All the neurovascular structures (except the hepatic veins) and hepatic ducts enter or leave the liver via the porta hepatis. It contains the sympathetic branch to the liver and gallbladder and the parasympathetic, hepatic branch of the vagus nerve. The caudate lobe (segment I) lies in the lesser sac on the inferior surface of the liver between the IVC on the right, the ligamentum venosum on the left, and the porta hepatis in front
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This question is part of the following fields:
- Anatomy
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Question 120
Incorrect
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Which of the following options will likely play a major role in falling coronary blood flow?
Your Answer:
Correct Answer: Intracoronary artery infusion of endothelin-1
Explanation:Endothelin-1 is considered as a powerful coronary vasoconstrictor, produced by the endothelium. It acts to counter the effects of Nitric oxide (NO).
Neuropeptide-Y, angiotensin1, cocaine, vasopressin, and nicotine are some other coronary vasoconstrictors.Chronotrophy and inotrophy occur after the activation of sympathetic nerve fibres, which in turn results in increasing the myocardial oxygen consumption, leading to increased coronary blood flow via local metabolic processes.
An alpha-receptor mediated coronary vasoconstrictor effect is also initiated that usually competes with vasodilation, resulting in decreased coronary vascular resistance. Some of the other dilators include hydrogen ions, CO2, potassium, and lactic acid. The action of endothelial NO synthase (eNOS) on L-arginine results in the formation of NO. This messenger also plays a vital role in the regulation of coronary blood flow via vasodilation, inhibition of platelet aggression, and decreasing vascular resistance.
Adenosine is considered as purine nucleoside that forms after the breakdown of adenosine triphosphate (ATP). Adenosine binds to adenosine type 2A (A2A) receptors in coronary vascular smooth muscles. These are coupled to the Gs protein. This mechanism leads to hyperpolarisation of muscle cells, resulting in relaxation and increased coronary blood flow.GTN is an veno and arteriolar dilator, which behaves as pro-drug with NO.
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This question is part of the following fields:
- Pathophysiology
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Question 121
Incorrect
-
Bioelectric potentials that have been measured have an optimum bandwidth and typical frequency.
For a standard 12-lead ECG, which of the following bandwidth and voltage combinations is the best?Your Answer:
Correct Answer: Bandwidth 0.05-150 Hz, voltage 100-4000 microvolts
Explanation:The potential difference (amplitude) and bandwidth frequencies of bioelectric signals are typical.
These are the following:
ECG: A bandwidth of 0.5-50 Hz is usually sufficient in monitoring mode, but a typical diagnostic bandwidth is 0.05-150 Hz (up to 200 Hz) with a typical voltage range of 0.1-4 millivolts (100-4000 microvolts).
EEG has a frequency range of 0.5-100 Hz and a voltage range of 0.5-100 microvolts.
EMG has a frequency range of 0.5 to 350 Hz and a voltage range of 0.5 to 30 millivolts.Prior to display, these small signals will need to be amplified and processed further.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 122
Incorrect
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Which of the following statements is correct regarding opioid receptors?
Your Answer:
Correct Answer: Binding with an opioid agonist increases potassium conductance
Explanation:Opioid receptors are a large family of seven transmembrane domain receptors. They are of four types:
1) Delta opioid receptor
2) Mu opioid receptor
3) Kappa opioid receptor
4) Orphan receptor-like 1
They contain about 372-400 amino acids and thus their molecular weight is different.
Opioid receptor activation reduces the intracellular cAMP formation and opens K+ channels (mainly through µ and δ receptors) or suppresses voltage-gated N-type Ca2+ channels (mainly κ receptor). These actions result in neuronal hyperpolarization and reduced availability of intracellular Ca2+ which results in decreased neurotransmitter release by cerebral, spinal, and myenteric neurons (e.g. glutamate from primary nociceptive afferents).
However, other mechanisms and second messengers may also be involved, particularly in the long-term
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This question is part of the following fields:
- Pharmacology
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Question 123
Incorrect
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Which one of the following patients presenting for elective surgery has an American Society of Anaesthesiologists (ASA) preoperative physical status grading of III?
Your Answer:
Correct Answer: A 50-year old man with a BMI of 41 with a reduced exercise tolerance
Explanation:The ASA physical status classification system is a system for assessing the fitness of patients before surgery. It was last updated in October 2014.
ASA I A normal healthy patient
ASA II A patient with mild systemic disease
ASA III A patient with severe systemic disease
ASA IV A patient with severe systemic disease that is a constant threat to life
ASA V A moribund patient who is not expected to survive without the operation
ASA VI A declared brain-dead patient whose organs are being removed for donor purposesA 20-year old woman who is 39-weeks pregnant with no other medical conditions – ASA II
A 35-year-old man with a BMI of 29 with a good exercise tolerance who smokes-ASA II
A 50-year old man with a BMI of 41 with a reduced exercise tolerance -ASA III
A 65-year old woman with a BMI of 34 with treated hypertension with no functional limitations-ASA II
A 73-year old man who has had a TIA ten-weeks ago but has a good exercise tolerance and is a non-smoker-ASA IV
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This question is part of the following fields:
- Clinical Measurement
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Question 124
Incorrect
-
Which of the following intravenous induction agents is best for the patient with acute intermittent porphyria requiring rapid sequence induction for emergency surgery?
Your Answer:
Correct Answer: Propofol
Explanation:Propofol is considered a safe drug to use in porphyria because even if causes mild elevation of porphyrins inpatient, it does not cause any symptoms.
Since barbiturates are inducers of ALA synthetase, they are contraindicated in porphyria patients. So, thiopentone most not be used.
Etomidate is a potent inhibitor of adrenal 11 beta-hydroxylase and 17 alpha-hydroxylase reducing cortisol and aldosterone synthesis in the adrenal cortex and has been associated with exacerbations of porphyria in animal studies and it is advisable not to use it in this condition.
Ketamine should be reserved for the hemodynamically unstable patient, however, it is a safe drug.
Diazepam is safe in porphyria but is not usually used for a rapid sequence induction.
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This question is part of the following fields:
- Pharmacology
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Question 125
Incorrect
-
Venepuncture is being performed on the basilic vein in the cubital fossa. At which of the following points does the basilic vein pass deep under the muscle?
Your Answer:
Correct Answer: Midway up the humerus
Explanation:The basilic vein is one of the primary veins that drain the upper limb, like the cephalic vein. It begins as the dorsal venous arch. The basilic vein originates from the ulnar side of the dorsal arch of the upper limb passes along the posteromedial aspect of the forearm, moving towards the anterior surface of the elbow.
The basilic vein pierces the deep fascia at the elbow and joins the venae commitantes of the brachial vein to form the axillary vein.
The basilic vein passes deep under the muscles as it moves midway up the humerus. At the lower border of the teres major muscle, the anterior and posterior circumflex humeral veins feed into it.
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This question is part of the following fields:
- Anatomy
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Question 126
Incorrect
-
A 70-year-old female presented with a productive cough and is prescribed a bacteriostatic antibiotic?
Which of the following best explains the mechanism of action of bacteriostatic drugs?Your Answer:
Correct Answer: Protein synthesis inhibition
Explanation:Cell membrane pore formation, Bacterial DNA damage, Peptidoglycan cross-linking inhibition, and peptidoglycan synthesis inhibitor are always lethal and such mechanisms are possible only in bactericidal drugs. But Protein synthesis inhibition would only prevent cell replication or cell growth and is responsible for bacteriostatic effects of the drug.
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This question is part of the following fields:
- Pharmacology
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Question 127
Incorrect
-
Which of the following statements is true regarding antibiotics?
Your Answer:
Correct Answer: Staphylococcus aureus colonises the nasopharynx in >20% of the general population
Explanation:Staphylococcus aureus colonizes the nasopharynx in >20% of the general population.
Methicillin-resistant Staphylococcus aureus (MRSA) is resistant to flucloxacillin.
Trimethoprim binds to dihydrofolate reductase and inhibits the reduction of dihydrofolic acid (DHF) to tetrahydrofolic acid (THF). THF is an essential precursor in the thymidine synthesis pathway and interference with this pathway inhibits bacterial DNA synthesis.
All ?-lactam antibiotics like penicillin interfere with the synthesis of the bacterial cell walls. The ?-lactam antibiotics inhibit the transpeptidases so that cross-linking (which maintains the close-knit structure of the cell wall) does not take place
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This question is part of the following fields:
- Pharmacology
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Question 128
Incorrect
-
A 60-year-old male is being reviewed in the peri-operative assessment before total knee replacement. He had a history of a heart transplant 10 years back. His resting heart rate is 110 beats per minute. On examination, ECG showed sinus tachycardia.
Which of the following explains this tachycardia?Your Answer:
Correct Answer: Loss of parasympathetic innervation
Explanation:Normally, at rest vagal influence is dominant producing the heart rate of 60-80 beats per minute even if the intrinsic automaticity of Sinoatrial Node is 100-110 beats per minute.
The transplanted heart has no autonomic nervous supply. So, it will respond to endogenous and exogenous catecholamine. This loss of parasympathetic innervation is responsible for the tachycardia in this patient.
Hypokalaemia can cause myocardial excitability and potential for ventricular ectopic and supraventricular arrhythmias. Hypothyroidism is also unlikely to cause tachycardia in this patient.
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This question is part of the following fields:
- Pathophysiology
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Question 129
Incorrect
-
Which of the following, at a given PaO2, increases the oxygen content of arterial blood?
Your Answer:
Correct Answer: A reduced erythrocyte 2,3-diphosphoglycerate level
Explanation:The oxygen content of arterial blood can be calculated by the following equation:
(10 x haemoglobin x SaO2 x 1.34) + (PaO2 x 0.0225).
This is the sum of the oxygen bound to haemoglobin and the oxygen dissolved in the plasma.Oxygen content x cardiac output = The amount of oxygen delivered to the tissues in unit time which is known as the oxygen flux.
Any factor that increases the metabolic demand will encourage oxygen offloading from the haemoglobin in the tissues and this causes the oxygen dissociation curve (ODC) to shift to the right. This subsequently reduced the oxygen content of arterial blood.
Conditions like fever, metabolic or respiratory acidosis lowers the oxygen content and shifts the ODC to the right.
A low level of 2,3 diphosphoglycerate (2,3-DPG) is usually related to an increased oxygen content as there is less offloading, and so the ODC is shifted to the left.So for a given PaO2, a high blood oxygen content is related to any factors that can shift the ODC to the left and not to the right.
A low haematocrit usually means that there is a decreased haemoglobin concentration, and therefore is associated with decreased oxygen binding to haemoglobin.
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This question is part of the following fields:
- Physiology
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Question 130
Incorrect
-
An 84-year-old woman has a fall. She fractures the neck of her femur and requires emergency surgery.
On history and examination, she appears to also have a possible heart failure for which an echocardiogram is scheduled.
Her measurements are:
End-diastolic volume: 40mL (70-240)
End-systolic volume: 30mL (16-140)
Calculate her approximate ejection fraction.Your Answer:
Correct Answer: 25%
Explanation:An echocardiogram provides real-time visualisation of cardiac structures. The ejection fraction (EF) is normally measured using this system.
The ejection fraction (EF) can be deduced mathematically if the patient’s end-diastolic volume (EDV), end-systolic volume (ESV) and stroke volume (SV) are known, as:
SV = EDV – ESV, and
EF = SV/EDV x 100
The normal range for EF is >55-70%.
For this patient,
SV= 40 – 30 = 10 mL, therefore
EF = 10/40 x 100 = 25%
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This question is part of the following fields:
- Clinical Measurement
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Question 131
Incorrect
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A normal woman at term, not in labour, has her arterial blood gas analysed.
Which set of results is most likely her own?
Option - pH - PaCO2 - HCO3 - PaO2
A - 7.35 - 28 mmHg (3.73 kPa) - 27 mmol/L - 104 mmHg (13.8kPa)
B - 7.43 - 32 mmHg (4.27 kPa) - 21 mmol/L - 104 mmHg (13.8kPa)
C - 7.44 - 36 mmHg (4.8 kPa) - 27 mmol/L - 104 mmHg (13.8kPa)
D - 7.45 - 40 mmHg (5.33 kPa) - 21 mmol/L - 104 mmHg (13.8kPa)
E - 7.46 - 44 mmHg (5.87kPa) - 21 mmol/L - 104 mmHg (13.8kPa)Your Answer:
Correct Answer: B
Explanation:Due to an increased tidal volume with little change or slight increase in respiratory rate, Minute ventilation at term is increased by about 50%. Hypothalamic function are thought to influence by Progesterone, oestradiol and prostaglandins. This causes a mild compensated respiratory alkalosis.
Maternal PaCO2 is usually decreased to about 32 mmHg (4.27 kPa) as a result of this increased alveolar ventilation at term . A compensatory decrease in serum bicarbonate from 27 to 21 mmol/L by renal excretion lessens the impact of maternal alkalosis.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 132
Incorrect
-
The following statements are about burns patients. Which one is true?
Your Answer:
Correct Answer: High protein diets may improve survival
Explanation:Patients who have sustained thermal injuries are at high risk of becoming hypercatabolic with larger cardiac outputs and oxygen consumptions.
The hypermetabolic states increase with an increase in the burn severity and surface area of the skin affected. A patient with thermal injuries affecting 60% of the total surface area of the body will have twice the normal metabolic rate.
The optimal temperature for nursing patients with burn injuries is 30°C to conserve the energy usage. The areas affected by the burn injuries should be covered to reduce loss of fluid via evaporation. Resetting hypothalamic thermoregulation will cause a 1-2°C increase in core temperature.
Burn injuries will have an immediate effect on the intestine, destroying the barrier function and allowing for the movement of bacteria and endotoxins within hours.
Enteral nutrition allows for the delivery of nutrients directly to the stomach or intestine. It has correlation with a dampened hypermetabolic response to a thermal and injury, especially when initiated early as it helps to protect the integrity of the mucosal lining and prevents the movement of bacteria into circulation.
Diet changes have been linked to reduced mortality due to burn injuries. Diets high in protein especially (calorie: nitrogen ratio of 100: 1), have the highest correlation with improved survival rates.
Parenteral feeds may be required alongside enteral nutrition, even with the increased risks of infection.
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This question is part of the following fields:
- Pathophysiology
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Question 133
Incorrect
-
A study involving 64 patients of diabetes mellitus type 2 was performed. Weight of each patient was recorded and the mean weight of the patients was found to be 81 kg. The data set had a standard deviation of 12 kg.
The value of standard error associated with the mean is:Your Answer:
Correct Answer: 1.5
Explanation:Standard error can be calculated by the following formula:
Standard Error= (Standard Deviation)/√(Sample Size)
= (12) / √(64)
= 12 / 8
= 1.5 -
This question is part of the following fields:
- Statistical Methods
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Question 134
Incorrect
-
Which of the following is a feature of a central venous pressure waveform?
Your Answer:
Correct Answer: An a wave due to atrial contraction
Explanation:The central venous pressure (CVP) waveform depicts changes of pressure within the right atrium. Different parts of the waveform are:
A wave: which represents atrial contraction. It is synonymous with the P wave seen during an ECG. It is often eliminated in the presence of atrial fibrillation, and increased tricuspid stenosis, pulmonary stenosis and pulmonary hypertension.
C wave: which represents right ventricle contraction at the point where the tricuspid valve bulges into the right atrium. It is synonymous with the QRS complex seen on ECG.
X descent: which represents relaxation of the atrial diastole and a decrease in atrial pressure, due to the downward movement of the right ventricle as it contracts. It is synonymous with the point before the T wave on ECG.
V wave: which represents an increase in atrial pressure just before the opening of the tricuspid valve. It is synonymous with the point after the T wave on ECG. It is increased in the background of a tricuspid regurgitation.
Y descent: which represents the emptying of the atrium as the tricuspid valve opens to allow for blood flow into the ventricle in early diastole.
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This question is part of the following fields:
- Pathophysiology
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Question 135
Incorrect
-
A 33-year old man was referred to you because of difficulty moving his limbs.
History revealed that he was placed under anaesthesia for a major surgery 12 hours prior to the referral. Other symptoms were noted such as anxiousness, agitation, and fever of 38°C. Upon physical examination, he was tachycardic at 119 beats per minute. Moreover, his medical history showed that he was on Fluoxetine for clinical depression.
The nurses reported that, because of his frequent complaints of axillary pain, he was given tramadol with paracetamol.
Which of the following is responsible for his clinical features?Your Answer:
Correct Answer: Tramadol
Explanation:Tramadol is weak agonist at the mu receptor. It inhibits the neuronal reuptake of serotonin and norepinephrine, and inhibits pain neurotransmission. It is given for moderate pain, chronic pain syndromes, and neuropathic pain.
Fluoxetine is a selective serotonin reuptake inhibitor (SSRI). It inhibits the neuronal reuptake of serotonin by inhibiting the serotonin transporter (SERT). It is the drug of choice for major depressive disorder, and is given for other psychiatric disorders such as anxiety, obsessive-compulsive, post-traumatic stress, and phobias.
When tramadol is given with SSRIs, serotonin syndrome may occur. Serotonin syndrome is characterized by fever, agitation, tremors, clonus, hyperreflexia and diaphoresis. The onset of symptoms may occur within a few hours, and the first-line treatment is sedation, paralysis, intubation and ventilation.
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This question is part of the following fields:
- Pharmacology
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Question 136
Incorrect
-
A 30-year old lady has a sub total thyroidectomy. On the 5th post-operative day, the wound becomes erythematous and there is a purulent discharge. The most likely organism causing this is:
Your Answer:
Correct Answer: Staphylococcus aureus
Explanation:Staphylococcus aureus infection is the most likely cause.
Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.
SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
The organisms are usually derived from the patient’s own body.Measures that may increase the risk of SSI include:
-Shaving the wound using a single use electrical razor with a disposable head
-Using a non iodine impregnated surgical drape if one is needed
-Tissue hypoxia
-Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.Measures that may decrease the risk of SSI include:
1. Intraoperatively
– Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
-Cover surgical site with dressingIn contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.
2. Post operatively
Tissue viability advice for management of surgical wounds healing by secondary intentionUse of diathermy for skin incisions
In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 137
Incorrect
-
Regarding the emergency oxygen flush, which is true?
Your Answer:
Correct Answer: May lead to awareness if used inappropriately
Explanation:When the emergency oxygen flush is pressed, 100% oxygen is supplied from the common gas outlet. This gas bypasses BOTH flowmeters and vaporisers. The flow of oxygen is usually 45 l/min at a PRESSURE OF 400 kPa.
There is an increased risk of pulmonary barotrauma when the emergency flush is pressed, especially when anaesthetising paediatric patients.
The inappropriate use of the flush causes dilution of anaesthetic gases and this increases the possibility of anaesthetic awareness .
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 138
Incorrect
-
A 40-year old farmer came into the emergency room with a chief complaint of 4 episodes of non-bloody diarrhoea. This was associated with frequent urination, vomiting and salivation. History also revealed frequent use of insecticides. Upon physical examination, there was miosis and bradycardia.
Given the different types of bonds, which is the most likely bond formed between insecticide poisoning and receptors?Your Answer:
Correct Answer: Covalent
Explanation:Organophosphate poisoning occurs most often due to accidental exposure to toxic amounts of pesticides. Signs and symptoms include diarrhoea, urination, miosis, bradycardia, emesis, lacrimation, lethargy and salivation.
Organophosphates are classified as indirect acting cholinomimetics, and their mode of action involves: (1) the inhibition of acetylcholinesterase (AChE) by forming a stable covalent bond on the active site serine; and, (2) amplification of endogenously release acetylcholine (ACh), hence the clinical manifestation.
There are 4 types of bonds or interactions: ionic, covalent, hydrogen bonds, and van der Waals interactions. Ionic and covalent bonds are strong interactions that require a larger energy input to break apart. When an element donates an electron from its outer shell, a positive ion is formed. The element accepting the electron is now negatively charged. Because positive and negative charges attract, these ions stay together and form an ionic bond. Covalent bonds form when an electron is shared between two elements and are the strongest and most common form of chemical bond in living organisms. Covalent bonds form between the elements that make up the biological molecules in our cells. Unlike ionic bonds, covalent bonds do not dissociate in water.
When polar covalent bonds containing a hydrogen atom form, the hydrogen atom in that bond has a slightly positive charge. This is because the shared electron is pulled more strongly toward the other element and away from the hydrogen nucleus. Because the hydrogen atom is slightly positive, it will be attracted to neighbouring negative partial charges. When this happens, a weak interaction occurs between the slightly positive charge of the hydrogen atom of one molecule and the slightly negative charge of the other molecule. This interaction is called a hydrogen bond.
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This question is part of the following fields:
- Pathophysiology
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Question 139
Incorrect
-
What statement about endotoxins is true?
Your Answer:
Correct Answer: Can often survive autoclaving
Explanation:Endotoxins are the lipopolysaccharides found in the outer cell wall of Gram-negative bacteria. They are responsible for providing the structure and stability of the cell wall.
They cannot be destroyed by normal sterilisation as they are heat stable molecules. They require the use of certain sterilant such as superoxide, peroxide and hypochlorite to be neutralised.
They stimulate strong immune responses, but can only be destroyed partially by specific antibodies. Repeat infections occur as memory T cells cannot be formed.
It can cause septicaemia and associated symptoms such as fever, shock, hypotension and nausea.
It activates the alternative complement pathway and the coagulation pathway using secreted cytokines.
It is not involved in botulism as clostridium botulinum, the responsible organism, secretes a neurotoxic exotoxin.
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This question is part of the following fields:
- Pathophysiology
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Question 140
Incorrect
-
The following statements are about changes that occur at birth. Which is accurate?
Your Answer:
Correct Answer: The systemic vascular resistance rises
Explanation:The umbilical vein closes once the umbilical cord is clamped following birth. This causes a rise in systemic vascular resistance, closing the ductus venosus.
Upon birth, the pulmonary vascular resistance is decreased as the lungs are aerated.
At birth, there is a rise in oxygen tension which causes the corresponding constriction of the ductus arteriosus. This prevents a left to right shunt as it stops aortic blood and blood from the pulmonary artery from mixing. The ventricles do no have an opening connecting them.
The foramen ovale closes soon after birth. It is the septum opening between the left and right atrium.
An adult’s cardiac output is expected to be 5 L/min
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This question is part of the following fields:
- Pathophysiology
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Question 141
Incorrect
-
A new clinical trial evaluates the effect of a new drug Z on all-cause mortality. The rate of death in the group receiving this drug is 8%, compared with 16% in the control group.
What is the number needed to treat with drug Z to prevent death?Your Answer:
Correct Answer: 13
Explanation:Number needed to treat is a measure of the impact of a treatment or intervention that is often used to communicate results to patients, clinicians, the public and policymakers. It states how many patients need to be treated for one additional patient to experience an adverse outcome (e.g. a death).
It is calculated as the inverse of the absolute risk reduction and is rounded to the next highest whole number.
The absolute risk reduction is 8% (16% – 8%). 100/8 = 12.5, so rounding up the next integer this gives at NNT of 13. i.e. you would need to give the new drug to 13 people to ensure that you prevented one death.
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This question is part of the following fields:
- Statistical Methods
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Question 142
Incorrect
-
A 57-year old woman, presents to her general practitioner. She has a 2 week history of a vaginal hysterectomy for which she was placed under general anaesthesia.
On examination, she has notable weakness of dorsiflexion of her left foot and a high stepping gait.
Which nerve was most likely injured during her surgery?Your Answer:
Correct Answer: Common peroneal nerve
Explanation:The common peroneal (fibular) nerve is a peripheral nerve in the lower limb. It arises of the L4-S2 nerve roots and has sensory and motor innervations:
Sensory: Provides innervation of the lateral leg and foot dorsum.
Motor: Provides innervation of the short head of the biceps femoris, as well as muscles of the anterior and lateral leg compartments.
It is the most commonly damaged nerve in the lower extremity, as it is easily compressed by a plaster cast or injured when the fibula is fractured.
Damage to the common peroneal nerve will result in loss of dorsiflexion at ankle (footdrop, as feet are permanently plantarflexed), with the accompanying high stepping gait.
The saphenous and sural nerve only provide sensory innervation.
The tibial nerve arises from the sciatic nerve (like the common peroneal), but it provides motor innervation to the posterior leg compartments and intrinsic foot muscles. Injury to the tibial nerve will cause loss of plantar flexion, toe flexion and weakened foot inversion.
Extreme hip flexion into the lithotomy or Lloyd-Davies position can result in stretch damage to the neurones (sciatic and obturator nerves) or by applying direct pressure (femoral nerve compression).
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This question is part of the following fields:
- Pathophysiology
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Question 143
Incorrect
-
Which of the following is true about the bispectral index (BIS)?
Your Answer:
Correct Answer: Sevoflurane lowers BIS more than ketamine
Explanation:The bispectral index (BIS) monitors works to determine the level of consciousness of a patient by processing electroencephalographic (EEG) signals to obtain a value between 0 and 100, where 0 reflects no brain activity, and 100 reflects a patient is completely awake.
The general meaning of BIS values are:
>95: Patient is in an awake state.
65-85: Patient is in a sedated state.
40-65: Patient is in a state that is optimal for general surgery.
<40: Patient is in a deep hypnotic state It is important in measuring the depths of anaesthesia to prevent haemodynamic changes or patient awareness during surgery. The nature of anaesthetic agent used is a determinant factor in resultant BIS values. Intravenous agents, such as propofol, thiopental and midazolam, result in a deeper hypnotic state, whilst inhalation agents have a lesser hypnotic effect at the same BIS values. Certain agents result in inaccurate BIS values such as ketamine and nitrous oxide (NO). These two agents appear to increase the BIS value, whilst putting the patient in a deeper hypnotic state, and should therefore not be used with BIS monitoring. Hypothermia also affects the BIS value as it causes a 1.12 per °C decrease in body temperature. -
This question is part of the following fields:
- Clinical Measurement
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Question 144
Incorrect
-
Regarding basal metabolic rate (BMR), which of the following is the most efficient regulator of BMR?
Your Answer:
Correct Answer: Hypothalamus
Explanation:The hypothalamus is primarily responsible for the regulation of the basal metabolic rate. It releases thyrotropin releasing hormones (TRH) in response to low levels of triiodothyronine (T3) and thyroxine (T4). The TRH acts on the pituitary gland to release thyroid stimulating hormone, which will stimulate the thyroid gland to synthesize more T3 and T4.
Basal metabolic rate refers to the energy expended by an individual in a resting, post-absorptive state. It represents the energy required to carry out normal body functions, such as respiration.
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This question is part of the following fields:
- Pathophysiology
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Question 145
Incorrect
-
What can an outbreak of flu that has spread globally be termed as?
Your Answer:
Correct Answer: Pandemic
Explanation:An epidemic is declared when the increase in a give disease is above a certain level in a specific interval of time.
An endemic is the general, usual level of a disease in a population at a particular time.
A pandemic is an epidemic that is spread across many countries and continents.
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This question is part of the following fields:
- Statistical Methods
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Question 146
Incorrect
-
Regarding renal autoregulation, which of the following best describes its process?
Your Answer:
Correct Answer: Reduces the effect of changes in arterial blood pressure on renal Na+ excretion
Explanation:Two mechanisms are responsible for autoregulation of RBF and GFR: one mechanism that responds to changes in arterial pressure and another that responds to changes in [NaCl] in tubular fluid. Both regulate the tone of the afferent arteriole. The pressure-sensitive mechanism, the so-called myogenic mechanism, is related to an intrinsic property of vascular smooth muscle: the tendency to contract when stretched. Accordingly, when arterial pressure rises and the renal afferent arteriole is stretched, the smooth muscle contracts in response. Because the increase in resistance of the arteriole offsets the increase in pressure, RBF, and therefore GFR, remains constant.
The second mechanism responsible for autoregulation of GFR and RBF is the [NaCl]-dependent mechanism known as tubuloglomerular feedback. This mechanism involves a feedback loop in which a change in GFR leads to alteration in the concentration of NaCl in tubular fluid, which is sensed by the macula densa of the juxtaglomerular apparatus and converted into signals that affect afferent arteriolar resistance and thus the GFR (Fig. 33.19). For example, when the GFR increases and causes [NaCl] in tubular fluid in the loop of Henle to rise, more NaCl enters the macula densa cells in this segment (Fig. 33.20). This leads to an increase in formation and release of adenosine triphosphate (ATP) and adenosine (a metabolite of ATP) by macula densa cells, which causes vasoconstriction of the afferent arteriole and normalization of GFR. In contrast, when GFR and [NaCl] in tubule fluid decrease, less NaCl enters the macula densa cells, and both ATP and adenosine production and release decline. The fall in [ATP] and [adenosine] results in afferent arteriolar vasodilation, which returns GFR to normal. NO, a vasodilator produced by the macula densa, attenuates tubuloglomerular feedback, whereas angiotensin II enhances tubuloglomerular feedback. Thus the macula densa may release both vasoconstrictors (e.g., ATP and adenosine) and a vasodilator (e.g., NO) that oppose each other’s action at the level of the afferent arteriole. Production plus release of either vasoconstrictors or vasodilators ensures exquisite control over tubuloglomerular feedback.
Renal autoregulation, thus, reduces the effect of changes in arterial blood pressure on renal sodium excretion.
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This question is part of the following fields:
- Pathophysiology
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Question 147
Incorrect
-
In asthmatic patients, non-steroidal anti-inflammatory analgesics (NSAIDs) are generally contraindicated.
Which of the following membrane phospholipid metabolism products is most likely to cause NSAID-induced bronchospasm in asthmatic patients who are predisposed to it?Your Answer:
Correct Answer: Leukotrienes
Explanation:Nonsteroidal anti-inflammatory drugs (NSAIDs) cause bronchospasm, rhinorrhoea, and nasal obstruction in some asthma patients.
The inhibition of cyclooxygenase-1 (Cox-1) appears to be the cause of NSAID-induced reactions. This activates the lipoxygenase pathway, which increases the release of cysteinyl leukotrienes (Cys-LTs), which causes bronchospasm and nasal obstruction.
The following changes in arachidonic acid (AA) metabolism have been observed in NSAID-intolerant asthmatic patients:
Prostaglandin E2 production is low, possibly due to a lack of Cox-2 regulation.
An increase in leukotriene-C4 synthase expression and
A decrease in the production of metabolites (lipoxins) released by AA’s transcellular metabolism.Phospholipase A produces membrane phospholipids, which are converted to arachidonic acid.
TXA2 causes vasoconstriction as well as platelet aggregation and adhesion.
PGI2 causes vasodilation and a reduction in platelet adhesion.
PGE2 is involved in parturition initiation and maintenance, as well as thermoregulation.
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This question is part of the following fields:
- Pharmacology
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Question 148
Incorrect
-
A 240 volt alternating current (AC) socket from a wall is used to charge a direct current (DC) cardiac defibrillator.
Name the electrical component that converts AC to DC.Your Answer:
Correct Answer: Rectifier
Explanation:There are two types of defibrillators
AC defibrillator
DC defibrillatorAC defibrillator,
consists of a step-up transformer with primary and secondary winding and two switches. Since secondary coil consists of more turns of wire than the primary coil, it induces larger voltage. A voltage value ranging between 250V to 750V is applied for AC external defibrillator. And used to enable the charging of a capacitor.DC defibrillator,
consists of auto transformer T1 that acts as primary of the high voltage transformer T2. Is an iron core that transfers energy between 2 circuits by electromagnetic induction. Transformers are used to isolate circuits, change impedance and alter voltage output. transformers do not convert AC to DC.Diode rectifier composed of 4 diodes made of semiconductor material allows current to flow only in one direction. Alternating current (AC) passing through these diodes produces direct current (DC). Capacitor stores the charge in the form of an electrostatic field.
Capacitor is used to convert the rectified AC voltage to produce DC voltage but capacitors do not directly convert AC to DC.
Inductor induces a counter electromotive force(emf) that reduces the capacitor discharge value.
In step-down transformer primary coils has more turns of wire than secondary coil, so induced voltage is smaller in the secondary coil.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 149
Incorrect
-
All of the following statements about calcium channel antagonists are incorrect except:
Your Answer:
Correct Answer: May cause potentiation of muscle relaxants
Explanation:Calcium channel blocker (CCB) blocks L-type of voltage-gated calcium channels present in blood vessels and the heart. By inhibiting the calcium channels, these agents decrease the frequency of opening of calcium channels activity of the heart, decrease heart rate, AV conduction, and contractility.
Three groups of CCBs include
1) Phenylalkylamines: Verapamil, Norverapamil
2) Benzothiazepines : Diltiazem
3) Dihydropyridine : Nifedipine, Nicardipine, Nimodipine, Nislodipine, Nitrendipine, Isradipine, Lacidipine, Felodipine and Amlodipine.Even though verapamil as good absorption from GIT, its oral bioavailability is low due to high first-pass metabolism.
Nimodipine is a Cerebro-selective CCB, used to reverse the compensatory vasoconstriction after sub-arachnoid haemorrhage and is more lipid soluble analogue of nifedipine
Calcium channel antagonist can potentiate the effect of non-depolarising muscle relaxants.
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This question is part of the following fields:
- Pharmacology
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Question 150
Incorrect
-
A 30-year old male has Von Willebrand's disease and attends the hospital to get an infusion of desmopressin acetate. The way this works is by stimulating the release of von Willebrand factor from cells, which in turn increases factor VIII and platelet plug formation in clotting.
In patients that have no clotting abnormalities, the substance that keeps the blood soluble and prevents platelet activation normally is which of these?Your Answer:
Correct Answer: Prostacyclin
Explanation:Even though aprotinin reduces fibrinolysis and therefore bleeding, there is an associated increased risk of death. It was withdrawn in 2007.
Protein C is dependent upon vitamin K and this may paradoxically increase the risk of thrombosis during the early phases of warfarin treatment.The coagulation cascade include two pathways which lead to fibrin formation:
1. Intrinsic pathway – these components are already present in the blood
Minor role in clotting
Subendothelial damage e.g. collagen
Formation of the primary complex on collagen by high-molecular-weight kininogen (HMWK), prekallikrein, and Factor 12
Prekallikrein is converted to kallikrein and Factor 12 becomes activated
Factor 12 activates Factor 11
Factor 11 activates Factor 9, which with its co-factor Factor 8a form the tenase complex which activates Factor 102. Extrinsic pathway – needs tissue factor that is released by damaged tissue)
In tissue damage:
Factor 7 binds to Tissue factor – this complex activates Factor 9
Activated Factor 9 works with Factor 8 to activate Factor 103. Common pathway
Activated Factor 10 causes the conversion of prothrombin to thrombin and this hydrolyses fibrinogen peptide bonds to form fibrin. It also activates factor 8 to form links between fibrin molecules.4. Fibrinolysis
Plasminogen is converted to plasmin to facilitate clot resorption -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 151
Incorrect
-
Which of the following can be measured directly using spirometry?
Your Answer:
Correct Answer: Vital capacity
Explanation:Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).
It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.
During spirometry, the following measurements can be determined:
Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
Forced expiratory volume in one second (FEV1)
FEV1/FVC ratio
Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.
Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution
The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.
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This question is part of the following fields:
- Clinical Measurement
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Question 152
Incorrect
-
Which of the following statements is true about fluid balance?
Your Answer:
Correct Answer: After intravenous administration of crystalloids, the distribution of these fluids throughout the body depends on its osmotic activity
Explanation:When there is capillary leakage as seen in dependent oedema or ascites, oncotic pressure becomes a problem.
The intracellular sodium concentration is very sensitive to the extracellular sodium concentrations. When there is an imbalance, osmosis occurs resulting in shifts in water between the two compartments.
The microvascular endothelium relies upon osmosis and other processes as it is not freely permeable to water.
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This question is part of the following fields:
- Physiology
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Question 153
Incorrect
-
You performed pelvic ultrasound of Mrs Aciman as she had pelvic bloating and intermittent pain. The ultrasound shows a complex ovarian cyst and the radiologist who reported the results has advised urgent consultation with a gynaecologist. Upon breaking the news to Mrs Aciman you learn that she recently had a blood test done that was normal. You explain it to her that the test performed (Ca-125) is not always perfect and is only able to detect 80% of the cancer cases while the remaining 20% go undetected.
Which statistical term appropriately explains the 80% in this example.Your Answer:
Correct Answer: Sensitivity
Explanation:Tests are used to confirm the presence of a particular disease. However the results can be misleading at times since most of the tests have some limitations associated with them.
Sensitivity is the correct term that refers to the probability of a positive test. The others are explained below:False Positive rates refer to the proportion of the patients who don’t have the condition being detected as positive.
False Negative rates refer to the proportion of the patients who have the condition being detected as negative (like the 20% of the patients that went undetected by the Ca-125 test).
Specificity describes the ability of a test to detect and pick up people without the disease. Absolute risk ratio compares the rate of two separate outcomes.
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This question is part of the following fields:
- Statistical Methods
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Question 154
Incorrect
-
A 30-year-old man has been stabbed in an area of the groin that contains the femoral triangle. He will undergo explorative surgery.
Which of the following makes the lateral wall of the femoral triangle?Your Answer:
Correct Answer: Sartorius
Explanation:The femoral triangle is a wedge-shaped area found within the superomedial aspect of the anterior thigh. It is a passageway for structures to leave and enter the anterior thigh.
Superior: Inguinal ligament
Medial: Adductor longus
Lateral: Sartorius
Floor: Iliopsoas, adductor longus and pectineusThe contents include: (medial to lateral)
Femoral vein
Femoral artery-pulse palpated at the mid inguinal point
Femoral nerve
Deep and superficial inguinal lymph nodes
Lateral cutaneous nerve
Great saphenous vein
Femoral branch of the genitofemoral nerve -
This question is part of the following fields:
- Anatomy
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Question 155
Incorrect
-
An 80-year-old man will be operated on for an arterial bypass procedure to treat claudication and foot ulceration. The anterior tibial artery will be the target for distal arterial anastomosis.
Which structure is NOT closely related to the anterior tibial artery?Your Answer:
Correct Answer: Tibialis posterior
Explanation:The anterior tibial artery originates from the distal border of the popliteus. In the posterior compartment, it passes between the heads of the tibialis posterior and the oval aperture of the interosseous membrane to reach the anterior compartment.
On entry into the anterior compartment, it runs medially along the deep peroneal nerve.
The upper third of the artery courses between the tibialis anterior and extensor digitorum longus muscles, while the middle third runs between the tibialis anterior and extensor hallucis longus muscles.At the ankle, the anterior tibial artery is located approximately midway between the malleoli. It continues on the dorsum of the foot, lateral to extensor hallucis longus, as the dorsalis pedis artery.
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This question is part of the following fields:
- Anatomy
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Question 156
Incorrect
-
A 40-year-old woman was diagnosed with hyperparathyroidism. She is undergoing a parathyroidectomy, and during the surgery, the inferior parathyroid gland is found to be enlarged. There is a vessel adjacent to this gland on its lateral side.
What is this vessel most likely to be?Your Answer:
Correct Answer: Common carotid artery
Explanation:There are four parathyroid glands that lie on the medial half of the posterior surface of each lobe of the thyroid gland, inside its sheath. There are two superior and two inferior parathyroid glands.
The common carotid artery is a lateral relation of the inferior parathyroid.
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This question is part of the following fields:
- Anatomy
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Question 157
Incorrect
-
The following statements are about the conjugation of bilirubin. Which is true?
Your Answer:
Correct Answer: Is catalysed by a glucuronyl transferase
Explanation:Bilirubin is formed by metabolizing heme, mostly from haemoglobin in red blood cells.
Bilirubin is conjugated to glucuronic acid in the hepatocytes by the glucuronyl transferase enzyme in order to enable it to become soluble and allow for its secretion across the canalicular membrane and into bile.
The conjugation process is increased by rifampicin and decreased by valproate.
Gilbert’s syndrome is caused by a decrease in glucuronyl transferase in the hepatic system, decreasing the transport of bilirubin into the hepatocyte, causing unconjugated bilirubinaemia.
Crigler-Najjer syndrome is caused by mutations in the genes responsible for hepatic glucuronyl transferase, decreasing the activity of the enzyme, meaning bilirubin cannot be conjugated, causing unconjugated bilirubinaemia.
Dubin-Johnson syndrome does not cause an impairment in the conjugation of bilirubin, but it blocks the transport of bilirubin out of the hepatocyte resulting in conjugated bilirubinaemia.
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This question is part of the following fields:
- Pathophysiology
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Question 158
Incorrect
-
What is the order of the anatomical components of the tracheobronchial tree from proximal to distal?
Your Answer:
Correct Answer: Bronchioles, terminal bronchioles, respiratory bronchioles, alveolar ducts, alveolar sacs
Explanation:The tracheobronchial tree is subdivided into the conducting and the respiratory zones.
The zones from proximal to distal are:
Trachea
Bronchi
Bronchioles
Terminal bronchioles
Respiratory bronchioles
Alveolar ducts
Alveolar sacsfrom the trachea to terminal bronchioles are the conducting zone while the respiratory zone is from the respiratory bronchioles to the alveola sacs
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This question is part of the following fields:
- Anatomy
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Question 159
Incorrect
-
Regarding oxygen consumption, which of these organs has the highest consumption at rest?
Your Answer:
Correct Answer: Kidney
Explanation:Oxygen delivery is related to blood flow as most of the oxygen binds to haemoglobin in red blood cells, although a small amount is dissolved in the plasma. Blood flow per 100 g of tissue is greatest in the kidneys.
The following is the oxygen consumption rate of different organs in ml/minute/100g
Hepatoportal = 2.2
Kidney = 6.8
Brain = 3.7
Skin = 0.38
Skeletal muscle = 0.18
Heart = 11 -
This question is part of the following fields:
- Pathophysiology
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Question 160
Incorrect
-
A 23-year-old man who is currently on fluoxetine for depression was anaesthetized two hours ago for knee arthroscopy. He seems agitated, confused, with a heart rate of 120 beats per minute, a temperature of 38.2oC, and developed difficulty moving his limbs.
He is on paracetamol and tramadol for analgesia. Which of the following is the most likely cause for his condition?Your Answer:
Correct Answer: Tramadol
Explanation: -
This question is part of the following fields:
- Pharmacology
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Question 161
Incorrect
-
A 70-year-old man presents with bilateral buttock claudication that spreads down the thigh and erectile dysfunction in a vascular clinic.
The left femoral pulse is not palpable on examination, and the right is weakly palpable. Leriche syndrome is diagnosed as the blood flow at the abdominal aortic bifurcation is blocked due to atherosclerosis. He is prepared for aortoiliac bypass surgery.
Which vertebral level will you find the affected artery that requires bypassing?Your Answer:
Correct Answer: L4
Explanation:The bifurcation of the abdominal aorta into common iliac arteries occurs at the level of L4. The bifurcation is a common site for atherosclerotic plaques as it is an area of high turbulence.
Leriche Syndrome is an aortoiliac occlusive disease and affects the distal abdominal aorta, iliac arteries, and femoropopliteal vessels. It has a triad of symptoms:
1. Claudication (cramping lower extremities pain that is reproducible by exercise)
2. Impotence (reduced penile arterial flow)
3. Absent/weak femoral pulses (hallmark)T12 – aorta enters the diaphragm with the thoracic duct and azygous veins
L2 – testicular or ovarian arteries branch off the aorta
L3 – inferior mesenteric artery
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This question is part of the following fields:
- Anatomy
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Question 162
Incorrect
-
Which of the following statements about the central venous pressure (CVP) waveform is true?
Your Answer:
Correct Answer: Third degree heart block causes canon A waves
Explanation:The central venous pressure (CVP) waveform depicts changes of pressure within the right atrium. Different parts of the waveform are:
A wave: which represents atrial contraction. It is synonymous with the P wave seen during an ECG. It is often eliminated in the presence of atrial fibrillation, and increased tricuspid stenosis, pulmonary stenosis and pulmonary hypertension.
C wave: which represents right ventricle contraction at the point where the tricuspid valve bulges into the right atrium. It is synonymous with the QRS complex seen on ECG.
X descent: which represents relaxation of the atrial diastole and a decrease in atrial pressure, due to the downward movement of the right ventricle as it contracts. It is synonymous with the point before the T wave on ECG.
V wave: which represents an increase in atrial pressure just before the opening of the tricuspid valve. It is synonymous with the point after the T wave on ECG. It is increased in the background of a tricuspid regurgitation.
Y descent: which represents the emptying of the atrium as the tricuspid valve opens to allow for blood flow into the ventricle in early diastole.
Canon waves: which refer to large waves present on the trace that do not correspond to the A, V or C waves. They usually occur in a background of complete heart blocks or junctional arrythmias.
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This question is part of the following fields:
- Clinical Measurement
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Question 163
Incorrect
-
A 19-year-old woman presents to the emergency department. She complains of symptoms indicative of an acute exacerbation of known 'brittle' asthma. On history, she reveals her asthma is normally controlled using inhalers and she has never had an acute exacerbation requiring hospitalisation.
On her admission into the ICU, further examination and diagnostic investigations are conducted. Her readings are:
Physical state: Alert, anxious and non-cyanotic.
Respiratory rate: 30 breaths/min
Pulse: 120 beats/min
Blood pressure: 150/90 mmHg
SPO2: 95% on air
Auscultation: Quiet breath sounds at both lung bases
What is the next most important step of investigation?Your Answer:
Correct Answer: Peak expiratory flow rate
Explanation:Peak expiratory flow rate (PEFR) is the maximum speed of air flow generated during a single forced exhaled breath. It is most useful when expressed as a percentage of the best value obtained from the patient.
Forced expiratory volume over 1 second (FEV1) is a lung parameter measured using spirometry. It is the amount of air forced out of the lung in one exhaled breath. It is a more accurate measure of lung obstructions as it doesn’t rely on effort like PEFR
PEFR and FEV1 are usually similar, but become more different in asthmatic patients as airflow becomes increasingly obstructed.
Acute severe asthma is most often diagnosed on history taking and examinations:
Respiratory rate: >25 breaths/min
Heart rate: >110 beats/min
PEFR: 33 – 50% predicted (<200L/min)
Patient state: Unable to complete a sentence in a single breath.A chest x-ray is not routinely required, and is only indicated in specific circumstances, which are:
If a pneumomediastinum or pneumothorax is suspected
Possible life threatening asthma
Possible consolidation
Unresponsive asthma
If ventilation is required.An echocardiograph (ECG) is not necessary in this case
Routine haematological and biochemical investigations are not urgent in this case as any abnormalities they detect will be secondary to the patient’s presentation.
An arterial blood gas (ABG) will only be indicated if SPO2 was <92% or if patient presented with life threatening symptoms.
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This question is part of the following fields:
- Clinical Measurement
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Question 164
Incorrect
-
A double-blinded randomised controlled trial is proposed to assess the effectiveness of a new blood pressure medication.
Which type of bias can be avoided by ensuring the patient and doctor are blinded?Your Answer:
Correct Answer: Expectation bias
Explanation:Observers may subconsciously measure or report data in a way that favours the expected study outcome. Therefore, by blinding the study we can eliminate expectation bias.
Recall bias is a systematic error that occurs when the study participants omit details or do not remember previous events or experiences accurately.
Verification can occur during investigations when there is a difference in testing strategy between groups of individuals, which might lead to biasness due to differing ways of verifying the disease of interest.
Nonresponse bias is the bias that occurs when the people who respond to a survey differ significantly from the people who do not respond to the survey.
A distortion that modifies an association between an exposure and an outcome because a factor is independently associated with the exposure and the outcome. Randomization is the best way to reduce the risk of confounding.
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This question is part of the following fields:
- Statistical Methods
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Question 165
Incorrect
-
Compared to the parasympathetic nervous system (PNS), the sympathetic nervous system (SNS) has:
Your Answer:
Correct Answer: Nicotinic receptors in pre and post ganglionic synapses
Explanation:With regards to the autonomic nervous system (ANS)
1. It is not under voluntary control
2. It uses reflex pathways and different to the somatic nervous system.
3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.With regards to the central nervous system (CNS)
1. There are myelinated preganglionic fibres which lead to the
ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.Most organs are under control of both systems although one system normally predominates.
The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.
There are short pre-ganglionic and long post ganglionic fibres.
Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.
There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.
Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.
The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.
The cranial outflow consists of
1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreasThe sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.
The PNS has long preganglionic and short post ganglionic fibres.
Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.Different types of these muscarinic receptors are present in different organs:
There are:
M1 = pupillary constriction, gastric acid secretion stimulation
M2 = inhibition of cardiac stimulation
M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
M4 = brain and adrenal medulla
M5 = brainThe lacrimal glands are solely under parasympathetic control.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 166
Incorrect
-
Regarding the following induction agents, which one is cleared at the fastest rate from the plasma?
Your Answer:
Correct Answer: Propofol
Explanation:Propofol is cleared at the fastest rate at the rate of 60ml/kg/min.
Clearance rate of other drugs are as follows:
– Thiopental: 3.5 ml/kg/min
– Methohexitone: 11 ml/kg/min
– Ketamine: 17 ml/kg/min
– Etomidate: 10-20 ml/kg/min -
This question is part of the following fields:
- Pharmacology
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Question 167
Incorrect
-
The spinal cord in a neonate terminates at the lower border of:
Your Answer:
Correct Answer: L3
Explanation:The spinal cord and the vertebral canal are as long as each other in early fetal life. The length of the cord increases faster than the growth of the vertebrae during development. By the time of birth, the spinal cord is at the level of the lower border of the 3rd lumbar vertebra, compared to its original position at the level of the 2nd coccygeal vertebra.
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This question is part of the following fields:
- Anatomy
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Question 168
Incorrect
-
A 4-year-old boy with status epilepticus was brought to ER and has already received two doses of intravenous lorazepam but is still continuing to have seizures.
Which of the following drug would be best for his treatment?Your Answer:
Correct Answer: Phenytoin 20 mg/kg IV
Explanation:When the convulsion lasts for five or more than five minutes, or if there are recurrent episodes of convulsions in a 5 minute period without returning to the baseline, it is termed as Status Epilepticus.
The first priority in the patient with seizures is maintaining the airway, breathing, and circulation.Guideline for the management of Status Epilepticus in children by Advanced Life Support Group is as follow:
Step 1 (Five minutes after the start of seizures):
If intravascular access is available start treatment with lorazepam 0.1 mg/kg IV
If no intravascular access then give buccal midazolam 0.5 mg/kg or rectal diazepam 0.5 mg/kg.Step 2 (Ten minutes after the start of seizure):
If the convulsions continue then a second dose of benzodiazepine should be given. Senior should be called on-site and phenytoin should be prepared.
No more than two doses or benzodiazepines should be given (including any doses given before arrival at the hospital)
If still no IV access then obtain intraosseous access (IO).Step 3 (Ten minutes after step 2)
Senior help along with anaesthetic/ICU help should be sought
Phenytoin 20 mg/kg IV over 20 minutes
If the seizure stops before the full dose of phenytoin is given then the infusion should be completed as this provides up to 24 hours of anticonvulsant effect
In children already receiving phenytoin as treatment for epilepsy then an alternative is phenobarbitone 20 mg/kg IV over five minutes
Once the phenytoin is started, senior staff may wish to give rectal paraldehyde 0.4 mg/kg although this is no longer included in the routine algorithm recommended by APLS.Step 4 (20 minutes after step 3)
If 20 minutes after starting phenytoin the child remains in status epilepticus then rapid sequence induction of anaesthesia with thiopentone and a short acting paralysing agent is needed and the child transferred to paediatric intensive care.
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This question is part of the following fields:
- Pathophysiology
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Question 169
Incorrect
-
The muscle that lies behind the first part of the axillary nerve is?
Your Answer:
Correct Answer: Subscapularis
Explanation:The axillary nerve lies behind the axillary artery initially, and in front of the subscapularis. It passes downward to the lower border of the subscapularis muscle.
In company with the posterior humeral circumflex artery and vein, it winds backward through a quadrilateral space bounded above by the subscapularis (anterior) and teres minor (posterior), below by the teres major, medially by the long head of the triceps brachii, and laterally by the humerus (surgical neck).
It then divides into an anterior and a posterior part. The anterior division supplies the deltoid (anterior and middle heads) while the posterior division supplies the teres minor and posterior part of deltoid
The posterior division terminates as the superior lateral cutaneous nerve of the arm -
This question is part of the following fields:
- Anatomy
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Question 170
Incorrect
-
An 82-year-old male has severe abdominal pain that is out of proportion to the examination. He is a known case of atrial fibrillation and diverticulitis. Suspecting mesenteric ischemia, he was thoroughly investigated, and a mesenteric angiography shows ischemia of the left colic flexure.
Which artery gives off branches that supply this region directly?Your Answer:
Correct Answer: Inferior mesenteric artery (IMA)
Explanation:Mesenteric ischemia is ischemia of the blood vessels of the intestines. It can be life-threatening, especially if the small intestine is involved.
The inferior mesenteric artery originates 3-4 cm above the bifurcation of the abdominal aorta.
The left colic artery branches off the inferior mesenteric artery to supply the following:
– distal 1/3 of the transverse colon
– descending colonAt approximately the left colic flexure (splenic flexure), a transition occurs in the blood supply of the GI tract. The SMA supplies the proximal part to the flexure, and the IMA supplies the part distal to the flexure. This is why the left colic flexure is a watershed area and is prone to ischemia exacerbated by atherosclerotic changes or hypotension. The dominant arterial supply of the splenic flexure is usually from the left colic artery, but it may also get collaterals from the left branch of the middle colic artery.
The AMA and PMA do not exist.
The splenic artery directly supplies the spleen and has branches that supply the stomach and the pancreas.
The proximal two-thirds of the transverse colon is supplied by the middle colic artery, a branch of the SMA. -
This question is part of the following fields:
- Anatomy
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Question 171
Incorrect
-
Concerning the pathway of endothelial nitric oxide (eNO), one of the following best describes it.
Your Answer:
Correct Answer: Stimulation of guanylyl cyclase, increases cGMP concentration leading to vasodilation
Explanation:Nitric oxide (NO), an endothelial-derived relaxant factor (EDRF), is a powerful vasodilator. Its cell-signalling molecule is calcium-dependant and generated endogenous by nitric oxide synthetases from the precursor L-arginine, oxygen and NADPH. Three main isoforms have been isolated and they are inducible (iNO), neuronal (nNO) and endothelial (eNO).
Endothelial NO stimulates intracellular guanylyl cyclase which generates cyclic GMP (cGMP) from its action on guanylyl tri-phosphate (GTP). The cGMP goes on to activate protein kinase G (PKG). PKG phosphorylates cell membrane proteins that regulate intracellular calcium concentrations and level of calcium sensitisation.
Smooth muscle vasodilatation results from:
1. Light chain phosphatase activation.
2. Inhibition of calcium entry into the cell (reducing Ca2+ concentrations) and
3. Hyperpolarisation of cells by activation of H+ channels. -
This question is part of the following fields:
- Pathophysiology
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Question 172
Incorrect
-
Which structure has the greatest amount of musculi pectinati?
Your Answer:
Correct Answer: Right atrium
Explanation:The pectinate muscles (musculi pectinati) are parallel muscular ridges that extend anterolaterally on the right atrial walls. The most prominent pectinate muscle, which forms the bridge of the sulcus terminalis internally, is the taenia sagittalis (second crest or septum spurium).
In the left atrium, the pectinate muscles are confined to the inner surface of its atrial appendage. They tend to be fewer and smaller than in the right atrium. This is due to the embryological origin of the auricles, which are the true atria.
Pectinate muscles of the atria are different from the trabeculae carneae, which are found on the inner walls of both ventricles.
The interior of the right atrium has five distinct features:
1. Sinus venarum – smooth, thin-walled posterior part of the right atrium where the SVC, IVC, and coronary sinus open
2. Musculi pectinati – a rough anterior wall of pectinate muscles
3. Tricuspid valve orifice – the opening through which the right atrium empties blood into the right ventricle
4. Crista terminalis – separates the rough (musculi pectinati) from the smooth (sinus venarum) internally
5. Fossa ovalis – a thumbprint size depression in the interatrial septum, which is a remnant of the oval foramen and its valve in the foetus -
This question is part of the following fields:
- Anatomy
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Question 173
Incorrect
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Question 174
Incorrect
-
All of the following options describes a thermistor for the measurement of temperature except:
Your Answer:
Correct Answer: Resistance of the bead increases exponentially as the temperature increases
Explanation:There are different types of temperature measurement. These include:
Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially
Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)
Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature
Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output
Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.
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This question is part of the following fields:
- Clinical Measurement
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Question 175
Incorrect
-
It is safe to perform a central neuraxial block without an increased risk of developing a vertebral canal haematoma in?
Your Answer:
Correct Answer: A patient on clopidogrel 7 days after last dose
Explanation:The incidence of vertebral canal haematoma following neuraxial blockade was reported (third National Audit Project (NAP3)) as 0.85 per 100 000 (95% CI 0-1.8 per 100 000). The incidence following neuraxial blockade in coagulopathic patients is likely to be higher hence coagulopathy remains a relative contraindication for conducting a spinal or epidural. When indicate, risk and benefits are weighed, and it is only performed by experienced personnel in this case.
Acceptable time to perform a block after the last dose of rivaroxaban in a patient with a creatinine clearance of greater than 30mL/minute is 18 hours.
Acceptable time to perform a block after the last dose of subcutaneous LMWH as prophylaxis is 12 hours.
Acceptable time to perform a block after the last dose of subcutaneous UFH as prophylaxis is 4 hours.
Acceptable time to perform a block after the last dose of thrombolytic therapy (streptokinase or alteplase) is 10 days.
Clopidogrel should be stopped 7 days prior to surgery, particularly if a central neuraxial procedure is considered.
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This question is part of the following fields:
- Pathophysiology
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Question 176
Incorrect
-
Which of the following statements is true with regards to the Krebs' cycle (also known as the tricarboxylic acid cycle or citric acid cycle)?
Your Answer:
Correct Answer: Alpha-ketoglutarate is a five carbon molecule
Explanation:Krebs’ cycle (tricarboxylic acid cycle or citric acid cycle) is a sequence of reactions in which acetyl coenzyme A (acetyl-CoA) is metabolised and this results in carbon dioxide and hydrogen atoms production.
This series of reactions occur in the mitochondria of eukaryotic cells, not the cytoplasm. The cycle requires oxygen and so, cannot function under anaerobic conditions.
It is the common pathway for carbohydrate, fat and some amino acids oxidation and is required for high energy phosphate bond formation in adenosine triphosphate (ATP).
When pyruvate enters the mitochondria, it is converted into acetyl-CoA. This represents the formation of a 2 carbon molecule from a 3 carbon molecule. There is loss of one CO2 but formation of one NADH molecule. Acetyl-CoA is condensed with oxaloacetate, the anion of a 4 carbon acid, to form citrate which is a 6 carbon molecule.
Citrate is then converted into isocitrate, alpha-ketoglutarate, succinyl-CoA, succinate, fumarate, malate and finally oxaloacetate.
The only 5 carbon molecule in the cycle is alpha-ketoglutarate.
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This question is part of the following fields:
- Physiology
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Question 177
Incorrect
-
The rapid depolarisation phase of the myocardial action potential is caused by:
Your Answer:
Correct Answer: Rapid sodium influx
Explanation:The cardiac action potential has several phases which have different mechanisms of action as seen below:
Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
These channels automatically deactivate after a few msPhase 1: caused by early repolarisation and an efflux of potassium.
Phase 2: Plateau – caused by a slow influx of calcium.
Phase 3 – Final repolarisation – caused by an efflux of potassium.
Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potentialOf note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.
Different sites have different conduction velocities:
1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec2. AV node conduction – 0.05 m/sec
3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 178
Incorrect
-
A patient in the post-anaesthesia care unit was put on ephedrine for episodes of hypotension. Initial bolus doses were effective and the patient became normotensive, until, a few hours later, there was a noticeable drop in the blood pressure despite administration of another dose of ephedrine.
Which of the following best explains the situation above?Your Answer:
Correct Answer: Tachyphylaxis
Explanation:When responsiveness diminishes rapidly after administration of a drug, the response is said to be subject to tachyphylaxis. This may be due to frequent or continuous exposure to agonists, which often results in short-term diminution of the receptor response.
Many mechanisms may be responsible, such as blocking access of G protein to activated receptor, or receptor molecules internalized by endocytosis to prevent exposure to extracellular molecules.
Tolerance occurs when larger doses are required to produce the same effect. This may be due to changes in receptor number or function due to exposure to the drug.
Desensitization refers to the common situation where the biological response to a drug diminishes when it is given continuously or repeatedly. It is a chronic loss of response, occurring over a longer period than tachyphylaxis. It may be possible to restore the response by increasing the dose (or concentration) of the drug but, in some cases, the tissues may become completely refractory to its effect.
Drug dependence is defined as a psychic and physical state of the person characterized by behavioural and other responses resulting in compulsions to take a drug, on a continuous or periodic basis in order to experience its psychic effect and at times to avoid the discomfort of its absence.
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This question is part of the following fields:
- Pharmacology
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Question 179
Incorrect
-
Concerning drug dose and response, one of the following statements is correct?
Your Answer:
Correct Answer: Intrinsic activity determines maximal response
Explanation:Dose response curves are plotted as % response to drug against Logarithm of drug concentration. The graph is usually sigmoid shaped.
Any drug that has high affinity and high intrinsic activity is likely an agonist. A drug with high affinity but no intrinsic activity will act as an antagonist. Displacement of an agonist also depends on the relative concentrations of the two drugs at the receptor sites.
Maximal response may be achieved by activation of a small proportion of receptor sites.
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This question is part of the following fields:
- Pharmacology
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Question 180
Incorrect
-
Out of the following, which anatomical structure lies within the spiral groove of the humerus?
Your Answer:
Correct Answer: Radial nerve
Explanation:The shaft of the humerus has two prominent features:
1. Deltoid tuberosity – attachment for the deltoid muscle
2. Radial or spiral groove – The radial nerve and profunda brachii artery lie in the grooveMid-shaft fractures of the humerus usually occur after a direct blow to the upper arm, which can occur after a fall or RTAs. The most important clinical significance of a mid-shaft humeral fracture is an injury to the radial nerve. The radial nerve originates from the brachial plexus and has roots of C5-T1. It crosses the spiral groove on the posterior side of the shaft of the humerus.
On examination, the patient may have a wrist drop, loss or weakness of finger extension, and decreased or absent sensation to the posterior forearm, digits 1 to 3, and the radial half of the fourth digit.The following parts of the humerus are in direct contact with the indicated
nerves:
Surgical neck: axillary nerve.
Radial groove: radial nerve.
Distal end of humerus: median nerve.
Medial epicondyle: ulnar nerve. -
This question is part of the following fields:
- Anatomy
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Question 181
Incorrect
-
A 30-year-old man has been diagnosed with a direct inguinal hernia.
A direct inguinal hernia passes through Hesselbach's triangle. What forms the medial edge of this triangle?Your Answer:
Correct Answer: Rectus abdominis muscle
Explanation:The inguinal triangle of Hesselbach’s is an important clinical landmark on the posterior wall of the inguinal canal. It has the following relations:
Inferiorly – medial third of the inguinal ligament
Medially – lower lateral border of the rectus abdominis
Laterally – inferior epigastric vesselsDirect inguinal hernia is when the bowel bulges directly through the abdominal wall. These hernias usually protrude through Hesselbach’s triangle
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This question is part of the following fields:
- Anatomy
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Question 182
Incorrect
-
A 50-year-old man has complained of persistent hoarseness and dry cough. He has a history of smoking 20 cigarettes per day. The examination reveals no significant clinical signs of cranial nerve damage.
Referred to an ENT specialist, the patient is explained how coughing is usually a defence mechanism of the body which is activated more than usual by the chemical irritants in cigarette smoke. However, the ENT doctor suspects a nerve involvement in the cough reflex as the patient also presents with hoarseness with the dry cough.
Which nerves is the ENT doctor suspecting to have been affected in this patient?Your Answer:
Correct Answer: CN IX and X
Explanation:Cough is an important defensive reflex that helps clear secretions and particulates from the airways. A complex reflex arc generates each cough.
The cough reflex begins with irritation of the cough receptors present in the epithelium of the trachea, main carina, branching points of large airways, and more distal smaller airways. These receptors are responsive to both mechanical and chemical stimuli.
Afferent pathway:
Impulses from stimulated receptors are transmitted via sensory nerve fibres of the vagus nerve (mainly) and glossopharyngeal nerve and travel to the medulla diffusely. CN 5 is also thought to contribute to the afferent limb. However, the vagus is the main nerve.Central pathway:
The cough centre is located in the upper brain stem and ponsEfferent pathway:
Impulses from the centre travel via the vagus, phrenic nerve, and spinal motor nerves to the diaphragm, abdominal wall, and muscles. -
This question is part of the following fields:
- Anatomy
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Question 183
Incorrect
-
When the volume of gas is measured, its value should be supported by a suitable abbreviation. From the following options, what does the STPD stand for?
Your Answer:
Correct Answer: Standard Temperature and Pressure, Dry
Explanation:Gas is composed of large numbers of molecules moving in random directions, separated by distances. They undergo perfectly elastic collisions with each other and the walls of a container and transfer kinetic energy in form of heat. These assumptions bring the characteristics of gases within the range and reasonable approximation to a real gas, particularly how any change in temperature and pressure affect the behaviour of gas. According to different theories and laws proposed, mathematical equations are derived to calculate the volume of gas, also different abbreviations are being used according to given conditions. The abbreviations used are ATP, BTPS, and STPD.
ATP stands for ambient temperature and barometric pressure, it is used to describe the conditions under which volume of gas is measured.
BTPS stands for body temperature and pressure saturated with water vapor. These are conditions under which volume of gas exist and all results of lung volume determination should be quoted at BTPS.
STPD stands for standard temperature and pressure, dry (0C and 760 mm Hg). These are the conditions that are used to describe quantities of individual gases exchanged in the lungs. -
This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 184
Incorrect
-
The clavipectoral fascia is penetrated by the cephalic vein to terminate in which of the listed veins?
Your Answer:
Correct Answer: Axillary
Explanation:The cephalic vein is a superficial vein that runs through the forearm and the arm, before draining into the axillary vein where it terminates.
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This question is part of the following fields:
- Anatomy
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Question 185
Incorrect
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A new drug treatment has been developed for Crohn's disease. The pharmaceutical company behind this, is planning to conduct a trial and is looking for hiring around 200 individuals that are suffering from Crohn's disease. The aim would be to determine if there is any decline in the disease activity in response to the drug and compare it with a placebo.
What phase is the trial in?Your Answer:
Correct Answer: Phase 2
Explanation:The study is being conducted on a smaller level with only 200 participants and is determining the effectiveness of the drug in comparison to a placebo. These characteristics are in accordance with the second phase of trial.
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This question is part of the following fields:
- Statistical Methods
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Question 186
Incorrect
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A 68-year old female is brought to the Emergency Room for abdominal pain. Medical history revealed that she is on long-term warfarin therapy for deep vein thrombosis.
Upon further investigation, the patient is hypotensive at 80/60 mmHg, and an abdominal mass is palpable on the umbilical area. An initial diagnosis of ruptured abdominal aortic aneurysm (AAA) is made. Moreover, blood tests show an international normalised ratio (INR) of 4.2.
Which of the following products should be initially transfused or administered to the patient to reverse the anticoagulation?Your Answer:
Correct Answer: Prothrombin complex
Explanation:Warfarin prevents reductive metabolism of the inactive vitamin K epoxide back to its active hydroquinone form. Thus, warfarin inhibits the synthesis of vitamin K dependent clotting factors: X, IX, VII, II (prothrombin), and of the anticoagulants protein C and protein S. The therapeutic range for oral anticoagulant therapy is defined in terms of an international normalized ratio (INR). The INR is the prothrombin time ratio (patient prothrombin time/mean of normal prothrombin time for lab)ISI, where the ISI exponent refers to the International Sensitivity Index and is dependent on the specific reagents and instruments used for the determination. A prolonged INR is widely used as an indication of integrity of the coagulation system in liver disease and other disorders, it has been validated only in patients in steady state on chronic warfarin therapy.
Prothrombin complex concentrate (PCC) is used to replace congenital or acquired vitamin-K deficiency warfarin-induced anticoagulant effect, particularly in the emergent setting.
Intravenous vitamin K has a slower onset of action compared to PCC, but is useful for long term therapy.
Fresh frozen plasma (FFP) prepared from freshly donated blood is the usual source of the vitamin K-dependent factors and is the only source of factor V. The factors needed, however, are found in small quantities compared to PCC.
Cryoprecipitate is indicated for hypofibrinogenemia/dysfibrinogenemia, von Willebrand disease, haemophilia A, factor XIII deficiency, and management of bleeding related to thrombolytic therapy.
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This question is part of the following fields:
- Pathophysiology
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Question 187
Incorrect
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Dinamap is an automated blood pressure monitoring device. Which of these statements best fit its properties?
Your Answer:
Correct Answer: The cuff should be positioned at the same level as the heart
Explanation:Dinamap continuously measures the systolic, diastolic and mean arterial pressure along with pulse rate, thereby providing a continuous monitoring of the blood pressure using the osscillitonometric principle of measurement.
The device loses accuracy towards the extremes of BP and is more accurate with systolic compared with diastolic pressure. In arrhythmias such as AF, the devices are also inaccurate due to the major fluctuations associated with the individual pulse pressure variations.
The manual BP device is still the gold standard for BP measurement and monitoring.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 188
Incorrect
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Which statement is true about the autonomic nervous system?
Your Answer:
Correct Answer: Preganglionic synapse utilise Acetylcholine as the neurotransmitter in both parasympathetic and sympathetic systems
Explanation:With regards to the autonomic nervous system (ANS)
1. It is not under voluntary control
2. It uses reflex pathways and different to the somatic nervous system.
3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.With regards to the central nervous system (CNS)
1. There are myelinated preganglionic fibres which lead to the
ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.Most organs are under control of both systems although one system normally predominates.
The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.
There are short pre-ganglionic and long post ganglionic fibres.
Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.
There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.
Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.
The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.
The cranial outflow consists of
1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreasThe sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.
The PNS has long preganglionic and short post ganglionic fibres.
Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.Different types of these muscarinic receptors are present in different organs:
There are:
M1 = pupillary constriction, gastric acid secretion stimulation
M2 = inhibition of cardiac stimulation
M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
M4 = brain and adrenal medulla
M5 = brainThe lacrimal glands are solely under parasympathetic control.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 189
Incorrect
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Which muscle separates the subclavian artery and the subclavian vein?
Your Answer:
Correct Answer: Scalenus anterior
Explanation:The subclavian artery and vein have a similar path throughout their course, with the subclavian vein running anterior to the subclavian artery. The artery and vein are separated by the insertion of the scalenus anterior muscle.
There are three scalene muscles, found on each side of the neck:
1. Anterior scalene
2. Middle scalene
3. Posterior scaleneThe scalenus anterior muscle is the anterior most of the three scalene muscles. It originates from the transverse processes of vertebrae C3-C6 and is inserted in the first rib.
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This question is part of the following fields:
- Anatomy
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Question 190
Incorrect
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The arterial-venous oxygen (a-vO2) difference is the difference between the oxygen content of arterial blood (CaO2) and mixed-venous blood (CvO2).
At rest, which organ has the greatest a-vO2 difference?Your Answer:
Correct Answer: Heart
Explanation:At rest, the heart has the greatest a-vO2 difference, a high capillary to myocyte ratio, short diffusion distances, and a high mitochondrial density. The flow of blood through the coronary arteries is also tightly controlled. At rest, 70-80 percent of the oxygen available to the cardiac muscle is extracted, increasing to 90 percent during exercise.
The a-vO2 difference indicates the body’s or an individual organ’s ability to extract oxygen from the blood.
CaO2 is influenced by a number of factors, including Hb concentration, PaO2 and pulmonary diffusion capacity.
CvO2 is influenced by a number of factors, including capillary density, regional blood flow, heart, resting skeletal muscle, kidney, intestine and skin.
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This question is part of the following fields:
- Pathophysiology
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Question 191
Incorrect
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Which of the following statement is correct regarding the difference between dabigatran and other anticoagulants?
Your Answer:
Correct Answer: Competitive thrombin inhibitor blocking both free and bound thrombin
Explanation:Dabigatran template is a prodrug and its active metabolite is a direct thrombin inhibitor. It is a synthetic, reversible, non-peptide thrombin inhibitor. This inhibition of thrombin results in a decrease of fibrin and reduces platelet aggregation.
Drugs like warfarin act by inhibiting the activation of vitamin K-dependent clotting factors. These factors are synthesized by the liver and activated by gamma-carboxylation of glutamate residues with the help of vitamin K. Hydroquinone form of vitamin K is converted to epoxide form in this reaction and regeneration of hydroquinone form by enzyme vitamin K epoxide reductase (VKOR) is required for this activity. Oral anticoagulants prevent this regeneration by inhibiting VKOR, thus vitamin K-dependent factors are not activated. These factors include clotting factors II, VII, IX, and X as well as anti-clotting proteins, protein C and protein S.
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This question is part of the following fields:
- Pharmacology
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Question 192
Incorrect
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A paediatric patient was referred to the surgery department after an initial assessment of acute gastroenteritis was proven otherwise to be a case acute appendicitis. History revealed multiple episodes of non-bloody emesis. In the paediatric ward, the patient had already undergone fluid resuscitation and replacement, and electrolytes were already corrected. Other pertinent laboratory studies were the following:
Serum Na: 138 mmol/l
Blood glucose: 6.4 mmol/l
If the patient weighed 25 kg, which intravenous fluid maintenance regimen would be best for the child?
Your Answer:
Correct Answer: 65 ml/hr Hartmann's solution with 0% glucose
Explanation:Maintenance therapy aims to replace water and electrolytes lost under ordinary conditions. In the perioperative period, maintenance fluid administration may not sufficiently account for the increased fluid requirements caused by third-space losses into the interstitium and gut. Specific recommendations vary with the patient, the procedure, and the type and amount of fluid administered during the operation. The fluid for maintenance therapy replaces deficits arising primarily from insensible losses and urinary or gastrointestinal (GI) losses.
The maintenance fluid volume can be computed using the Holliday-Segar method.
Body weight Fluid volume
first 10 kg 4 ml/kg/hr
next 10-20 kg 2 ml/kg/hr
>20 kg 1 ml/kg/hrIn the past few years, there has been growing recognition of the increased risk of hyponatremia in hospitalized children in intensive care and postoperative settings who receive hypotonic maintenance fluids. Several studies, including a randomized controlled trial and a Cochrane analysis, found that the use of isotonic fluids is associated with fewer electrolyte derangements and concluded that isotonic maintenance fluids are preferable to hypotonic solutions in hospitalized children.
A European consensus statement suggests that an intraoperative fluid should have an osmolarity close to the physiologic range in children in order to avoid hyponatremia, an addition of 1-2.5% in order to avoid hypoglycaemia, lipolysis or hyperglycaemia and should also include metabolic anions as bicarbonate precursors to prevent hyperchloremic acidosis.
A rate of 40 ml/hr is suboptimal.
If 0.9% NaCl with 0% glucose is given at a rate of 65 ml/hr, despite of the correct infusion rate, large volumes can lead to hyperchloremic acidosis.
If 0.18% NaCl with 4% glucose is given at a rate of 65 ml/hr, infusion of this fluid regimen can lead to hyponatremia because of its hypotonicity.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 193
Incorrect
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Of the following, which is NOT a branch of the abdominal aorta?
Your Answer:
Correct Answer: Superior phrenic artery
Explanation:The abdominal aorta begins at the level of the body of T12 near the midline, as a continuation of the thoracic aorta. It descends and bifurcates at the level of L4 into the common iliac arteries.
The branches of the abdominal aorta (with their vertebra level) are:
1. Inferior phrenic arteries: T12 (upper border)
2. Coeliac artery: T12
3. Superior mesenteric artery: L1
4. Middle suprarenal arteries: L1
5. Renal arteries: Between L1 and L2
6. Gonadal arteries: L2 (in males, it is the testicular artery, and in females, the ovarian artery)
7. Inferior mesenteric artery: L3
8. Median sacral artery: L4
9. Lumbar arteries: Between L1 and L4The superior phrenic artery branches from the thoracic aorta.
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This question is part of the following fields:
- Anatomy
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Question 194
Incorrect
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Systemic vascular resistance (multiplied by 80) to produce the units of dynes.s.cm-5 is represented by?
Your Answer:
Correct Answer: Mean arterial pressure (MAP) - central venous pressure (CVP)/cardiac output (CO)
Explanation:Systemic vascular resistance (SVR) is a derived value based on:
SVR = (MAP-CVP)/CO x 80
= (60 -10)/5 x 80 = 800 dynes.s.cm-5
A correction factor of 80 is needed in converting mmHg to dynes.s.cm-5
Normal values is between 700 -1600 dynes.s.cm-5Pulmonary resistance (PVR) = (MPAP-PCWP)/CO x 80
= (10 – 5)/5 x 80 = 80 dynes.s.cm-5
To account for body size, cardiac index (CI) can be used instead of CO. CI = CO/body surface area (m2) or mL/minute/m2.
N/B: either MAP and CVP, or MPAP and PCWP are used in calculation to get dynes.s.cm-5 -
This question is part of the following fields:
- Clinical Measurement
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Question 195
Incorrect
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The biochemical assessment of malnutrition can be measured by the amount of plasma proteins.
In acute starvation, which of these plasma proteins is the most sensitive indicator?Your Answer:
Correct Answer: Retinol binding globulin
Explanation:The half life of Retinol binding protein (RBP) is 10-12 hours and therefore reflects more acute changes in protein metabolism than any of these proteins. Therefore it is not commonly used as a parameter for nutritional assessment.
The half life of Transthyretin (thyroxine binding pre-albumin) is only one to two days and so levels are less sensitive and this protein is not an albumin precursor. 15 mg/dL represents early malnutrition and a need for nutritional support.
Albumin levels have been frequently as a marker of nutrition but this is not a very sensitive marker. It’s half life more than 30 days and significant change takes some time to be noticed. Also, synthesis of albumin is decreased with the onset of the stress response after burns. Unrelated to nutritional status, the synthesis of acute phase proteins increases and that of albumin decreases.
A more accurate indicator of protein stores is transferrin. It’s response to acute changes in protein status is much faster. The half life of serum transferrin is shorter (8-10 days) and there are smaller body stores than albumin. A low serum transferrin level is below 200 mg/dL and below 100 mg/dL is considered severe. Serum transferrin levels can also affect serum transferrin level.
Fibronectin is used a nutritional marker but levels decrease after seven days of starvation. It is a glycoprotein which plays a role in enhancing the phagocytosis of foreign particles.
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This question is part of the following fields:
- Physiology
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Question 196
Incorrect
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A 50-year-old man is admitted in hospital. Over four hours, he produces 240 mL of urine and has a plasma creatinine concentration is 10 mcg/mL. The normal concentration of creatinine in urine is 1.25 mg/mL.
Calculate his approximate creatinine clearance.Your Answer:
Correct Answer: 125 ml/minute
Explanation:Creatinine clearance is a test used to approximate the glomerular filtration rate (GFR) as an assessment of kidney function.
Creatinine is formed during the breakdown of dietary sources of meat and skeletal muscle. It is secreted at a consistent concentration and pace into the body’s circulation, and is easily filtered across the glomerulus without being reabsorbed or metabolized by the kidney.
It is represented mathematically as:
Creatinine clearance (CL) = U x V/P
where,
U: Urinary creatinine concentration (mg/mL)
V: Volume of urine (mL/min)
P: Plasma creatinine concentration (mg/mL)Therefore, in this case:
CL: 1.25 x 1 = 125mL/min
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This question is part of the following fields:
- Clinical Measurement
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Question 197
Incorrect
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You've been summoned to the paediatric ward after a 4-year-old child was discovered 'collapsed' in bed.
The child had been admitted the day before with febrile convulsions and was scheduled to be discharged. It is safe to approach the child.
What should your first life-saving action be?Your Answer:
Correct Answer: Apply a gentle stimulus and ask the child if they are alright
Explanation:Paediatric life support differs from adult life support in that hypoxia is the primary cause of deterioration.
After checking for danger, the child should be given a gentle stimulus (such as holding the head and shaking the arm) and asked, Are you alright? according to current advanced paediatric life support (APLS) guidelines. Safety, Stimulate, Shout is a phrase that is frequently remembered. Any airway assessment should be preceded by these actions.
Although the algorithm includes five rescue breaths, they are performed after the airway assessment.
It is not recommended to ask parents to leave unless they are obstructing the resuscitation. A team member should be with them at all times to explain what is going on and answer any questions they may have.
CPR should not begin until the child has been properly assessed and rescue breaths have been administered.
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This question is part of the following fields:
- Pathophysiology
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Question 198
Incorrect
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A 54-year-old lady comes in for a right-sided elective bunionectomy with a realignment osteotomy under local anaesthetic on her first (large) toe.
For the operation, which of the following nerve blocks will be most effective?Your Answer:
Correct Answer: Superficial peroneal, deep peroneal and posterior tibial nerves
Explanation:An ankle block is commonly used for anaesthesia and postoperative analgesia when operating on bunions. It results in the selective block of the superficial peroneal, deep peroneal, and posterior tibial nerves.
The deep peroneal nerve supplies sensory input to the web space between the first and second toes (L4-5).
The L2-S1 nerve, often known as the superficial peroneal nerve, is a mixed motor and sensory neuron. It gives sensory supply to the anterolateral region of the leg, the anterior aspect of the 1st, 2nd, 3rd, and 4th toes, and innervates the peroneus longus and brevis muscles (with the exception of the web space between 1st and 2nd toes).
The sensory area of the saphenous nerve (L3-4) in the foot stretches from the proximal portion of the midfoot on the medial side to the proximal part of the midfoot on the lateral side.
The lateral side of the little (fifth) toe is innervated by the sural nerve’s sensory supply (S1-2). The heel, medial (medial plantar nerve), and lateral (lateral plantar nerve) soles of the foot are all served by the posterior tibial nerve.
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This question is part of the following fields:
- Pathophysiology
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Question 199
Incorrect
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In the adrenal gland:
Your Answer:
Correct Answer: Catecholamine release is mediated by cholinergic nicotinic transmission
Explanation:The adrenal (suprarenal) gland is composed of two main parts: the adrenal cortex, which is the largest and outer part of the gland, and the adrenal medulla. The adrenal cortex consists of three zones: 1. Zona glomerulosa (outermost layer) is responsible for the production of mineralocorticoids, mainly aldosterone, which regulates blood pressure and electrolyte balance. 2. Zona fasciculata (middle layer) is responsible for the production of glucocorticoids, predominantly cortisol, which increases blood sugar levels via gluconeogenesis, suppresses the immune system, and aids in metabolism. It also produces 11-deoxycorticosterone and corticosterone in addition to cortisol. 3. Zona reticularis (innermost layer) is responsible for the production of gonadocorticoids, mainly dehydroepiandrosterone (DHEA), which serves as the starting material for many other important hormones produced by the adrenal gland, such as oestrogen, progesterone, testosterone, and cortisol. It is also responsible for administering these hormones to the reproductive regions of the body.
The adrenal medulla majorly secretes epinephrine (adrenaline), and norepinephrine in small quantity. Both hormones have similar functions and initiate the flight or fight response.
Catecholamine is mediated by cholinergic nicotinic transmission through changes in sympathetic nervous system (T5 – T11), being increased during stress and hypoglycaemia.
Blood supply to the adrenal gland is by these three arteries: superior suprarenal arteries, middle suprarenal artery and inferior suprarenal artery. Venous drainage is via the suprarenal vein to the left renal vein or directly to the inferior vena cava on the right side. There is no portal (venous) system between cortex and medulla.
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This question is part of the following fields:
- Anatomy
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Question 200
Incorrect
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Which of these structures will cause the biggest reduction in hepatic blood flow when occluded surgically?
Your Answer:
Correct Answer: Portal vein
Explanation:The portal vein arises from the splenic and mesenteric veins, and is the biggest vessel in the portal venous system, accounting for about 75% of the hepatic blood flow.
It is responsible for draining blood from parts of the gastrointestinal system, the spleen, the pancreas and the gallbladder into the liver.
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This question is part of the following fields:
- Anatomy
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