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  • Question 1 - A human's resting oxygen consumption (VO2) is typically 3.5 ml/kg/minute (one metabolic equivalent...

    Incorrect

    • A human's resting oxygen consumption (VO2) is typically 3.5 ml/kg/minute (one metabolic equivalent or 1 MET).

      Which of the following options is linked to the highest VO2 when a person is at rest?

      Your Answer: Term pregnancy

      Correct Answer: Neonate

      Explanation:

      The oxygen consumption rate (VO2) at rest is 3.5 ml/kg/minute (one metabolic equivalent or 1 MET).
      3.86 ml/kg/minute thyrotoxicosis

      Young children consume a lot of oxygen: around 7 ml/kg/min when they are born. The metabolic cost of breathing is higher in children than in adults, and it can account for up to 15% of total oxygen consumption. Similarly, an infant’s metabolic rate is nearly twice that of an adult, resulting in a larger alveolar minute volume and a lower FRC.

      At term, oxygen consumption at rest can increase by as much as 40% (5 ml/kg/minute) and can rise to 60% during labour.

      When compared to normal basal metabolism, sepsis syndrome increases VO2 and resting metabolic rate by 30% (4.55 ml/kg/minute). In septicaemic shock, VO2 decreases.

      Dobutamine hydrochloride was infused into 12 healthy male volunteers at a rate of 2 micrograms per minute per kilogramme, gradually increasing to 4 and 6 micrograms per minute per kilogramme. Dobutamine was infused for 20 minutes for each dose. VO2 increased by 10% to 15%. (3.85-4.0 ml/kg/min).

    • This question is part of the following fields:

      • Physiology
      25.9
      Seconds
  • Question 2 - With regards to oxygen delivery in the body, which of these statements is...

    Correct

    • With regards to oxygen delivery in the body, which of these statements is true?

      Your Answer: Anaemia will reduce oxygen delivery

      Explanation:

      Oxygen delivery depends on 2 variables.
      1) Content of oxygen in blood
      2) Cardiac output

      Oxygen content (arterial) = (Hb (g/dL) x 1.39 x SaO2 (%) ) + (0.023 x PaO2 (kPa))

      Oxygen content (mixed venous) = (Hb (g/dL) x 1.39 x mixed venous saturation) + (0.023 x mixed venous partial pressure of oxygen in kPA)

      Huffner’s constant = 1.39 = 1g of Hb binds to 1.39 ml of O2

      Oxygen delivery DO2 (ml/min) = 10 x Cardiac output (L/min) x Oxygen content
      Normally 1000ml/min

      Oxygen consumption VO2 (ml/min) = 10 x Cardiac output (L/min) x Difference in arterial and mixed venous oxygen content
      Normally 250 ml/min

      Oxygen extraction ratio (OER) = VO2/DO2
      Normally approximately 25%

    • This question is part of the following fields:

      • Physiology And Biochemistry
      30.5
      Seconds
  • Question 3 - Ondansetron is serotonin antagonist indicated for post-operative nausea and vomiting.

    In which of the...

    Incorrect

    • Ondansetron is serotonin antagonist indicated for post-operative nausea and vomiting.

      In which of the following anatomic structures does ondansetron produce its effects?

      Your Answer: Hippocampus

      Correct Answer: Nucleus tractus solitarius

      Explanation:

      Ondansetron is a serotonin antagonist at the 5HT3 receptor. 5HT3 receptors in the gastrointestinal tract and in the vomiting centre of the medulla participate in the vomiting reflex. They are particularly important in vomiting caused by chemical triggers such as cancer chemotherapy drugs.

      The nucleus solitarius is the recipient of all visceral afferents, and an essential part of the regulatory centres of the internal homeostasis, through its multiple projections with cardiorespiratory and gastrointestinal regulatory centres. It participates in the reflexes of the nerves innervating the nucleus, so it mediates cough reflex, carotid sinus reflex, gag reflex, and vomiting reflex.

    • This question is part of the following fields:

      • Pharmacology
      16.2
      Seconds
  • Question 4 - One of the following sets of arterial blood gases best demonstrates compensated respiratory...

    Incorrect

    • One of the following sets of arterial blood gases best demonstrates compensated respiratory acidosis?

      Your Answer: pH=7.24, PaCO2=3.5kPa, PaO2=8.5kPa, HCO3- =18mmol/L

      Correct Answer: pH=7.36, PaCO2=8.5kPa, PaO2=7.5kPa, HCO3- = 43mmol/L

      Explanation:

      pH=7.36, PaCO2=8.5kPa, PaO2=7.5kPa, HCO3- = 43mmol/L is the correct answer.

      Since the pH is the lower limit of normal, it is compensated despite a raised PaCO2. Retention of bicarbonate ions by the renal system suggests this process is chronic.

      pH=7.24, PaCO2=3.5kPa, PaO2=8.5kPa, HCO3- =18mmol/L represents an acute uncompensated metabolic acidosis

      The remaining stems are degrees of uncompensated respiratory acidosis and therefore incorrect.

    • This question is part of the following fields:

      • Pathophysiology
      53.1
      Seconds
  • Question 5 - Regarding laminar gas flow, which of the following options has the most influence...

    Incorrect

    • Regarding laminar gas flow, which of the following options has the most influence on laminar flow?

      Your Answer: Length of tube

      Correct Answer: Diameter of tube

      Explanation:

      Laminar flow can be defined as the motion of a fluid where every particle in the fluid follows the same path of its previous particles. The following are properties of laminar flow of gas or fluids:

      1. Smooth unobstructed flow of gas through a tube of relatively uniform diameter
      2. Few directional changes
      3. Slow, steady flow through straight smooth, rigid, large calibre, cylindrical tube
      4. Outer layer flow slower than the centre due to friction, results in discrete cylindrical layers, or streamlines
      5. Double flow by doubling pressure as long as the flow pattern remains laminar

      Poiseuille’s Law relates the factors that determine laminar flow. It indicates the degree of resistance to fluid flow through a tube. The resistance to fluid flow through a tube is directly related to the length, flow and viscosity; and inversely related to the radius of the tube to the fourth power. This means that, when the radius is doubled, there is increase in flow by a factor of 16.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      8.4
      Seconds
  • Question 6 - A 49-year-old woman is admitted to hospital. She is scheduled for surgery and...

    Incorrect

    • A 49-year-old woman is admitted to hospital. She is scheduled for surgery and is undergoing preoperative assessment.

      As part of the preoperative assessment, her functional capacity is estimated. At 50kg in weight, she is able to cycle along a flat surface at a speed of 10-14 miles/hour (8 metabolic equivalents or METs).

      Provide the best estimated value of oxygen consumption (VO2) for eight METs.

      Your Answer:

      Correct Answer: 1400 mL/minute

      Explanation:

      Oxygen consumption (VO2) refers to the optimal amount of oxygen used by the body during exercise.

      It is calculated mathematically by:

      VO2 = 3.5 x 50 x 8 = 1400 mL/kg/minute

      where,

      1 MET = 3.5 mL O2/kg/minute is utilized by the body.

      Note:

      1 MET Eating
      Dressing
      Use toilet
      Walking slowly on level ground at 2-3 mph
      2 METs Playing a musical instrument
      Walking indoors around house
      Light housework
      4 METs Climbing a flight of stairs
      Walking up hill
      Running a short distance
      Heavy housework, scrubbing floors, moving heavy furniture
      Walking on level ground at 4 mph
      Recreational activity, e.g. golf, bowling, dancing, tennis
      6 METs Leisurely swimming
      Leisurely cycling along the flat (8-10 mph)
      8 METs Cycling along the flat (10-14 mph)
      Basketball game
      10 METs Moderate to hard swimming
      Competitive football
      Fast cycling (14-16 mph)

    • This question is part of the following fields:

      • Clinical Measurement
      0
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  • Question 7 - Sugammadex binds to certain drugs that affect neuromuscular function during anaesthesia in a...

    Incorrect

    • Sugammadex binds to certain drugs that affect neuromuscular function during anaesthesia in a stereospecific, non-covalent, and irreversible manner.

      It has the greatest impact on the activity of which of the following drugs?

      Your Answer:

      Correct Answer: Vecuronium

      Explanation:

      Sugammadex is a modified cyclodextrin that works as an aminosteroid neuromuscular blocking (nmb) reversal agent. By encapsulating each molecule in the plasma, it rapidly reverses rocuronium and, to a lesser extent, vecuronium-induced neuromuscular blockade. Consequently, a  concentration gradient favours the movement of these nmb agents away from the neuromuscular junction.  Pancuronium-induced neuromuscular blockade at low levels has also been reversed.

      By inhibiting voltage-dependent calcium channels at the neuromuscular junction, antibiotics in the aminoglycoside group potentiate neuromuscular blocking agents. This can be reversed by giving calcium but not neostigmine or sugammadex.

      Sugammadex will not reverse the effects of mivacurium, which belongs to the benzylisoquinolinium class of drugs.

      A phase II or desensitisation block occurs when the motor end-plate becomes less sensitive to acetylcholine as a result of an overdose or repeated administration of suxamethonium. The use of neostigmine has been shown to be effective in reversing this weakness.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 8 - Over the course of 10 minutes, a normally fit and well 22-year-old male...

    Incorrect

    • Over the course of 10 minutes, a normally fit and well 22-year-old male receives a 1 litre intravenous bolus of 20% albumin.

      Which of the following primary physiological responses in this patient has the highest chance to influence a change in urine output?

      Your Answer:

      Correct Answer: Stimulation of atrial natriuretic peptide (ANP) secretion

      Explanation:

      The renal effects of atrial natriuretic peptide (ANP) secretion are as follows:

      Increased glomerular filtration rate by dilating the afferent glomerular arteriole. Moreover, it constricts the efferent glomerular arteriole, and relaxes the mesangial cells.
      Reduces sodium reabsorption in the collecting ducts and distal convoluted tubule.
      The renin-angiotensin system (RAS) is inhibited.
      Blood flow in the vasa recta is increased.

      Because plasma osmolality is unlikely to change, hypothalamic osmoreceptors are unaffected.

      The plasma protein has a molecular weight of 66 kDa, is not normally filtered into the proximal convoluted tubule, and has no osmotic diuretic effect.

      The following are some basic assumptions:

      Extracellular fluid (ECF) makes up one-third of total body water (TBW), while intracellular fluid makes up the other two-thirds (ICF)
      One-quarter plasma and three-quarters interstitial fluid make up ECF (ISF)
      The volume receptors in the atria have a 7-10% blood volume change threshold.
      The osmoreceptors are sensitive to changes in osmolality of 1-2 percent.
      The normal plasma osmolality before the transfusion is 287-290 mOsm/kg.
      The plasma protein solution is a colloid that is only delivered to the intravascular compartment. The tonicity remains unchanged.
      The blood volume increases by 20%, from 5,000 mls to 6,000 mls. This is higher than the volume receptor threshold of 7 to 10%.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 9 - Regarding a drug whose elimination exhibits first-order kinetics, which of the following statements...

    Incorrect

    • Regarding a drug whose elimination exhibits first-order kinetics, which of the following statements is correct?

      Your Answer:

      Correct Answer: The rate of elimination is proportional to plasma concentration

      Explanation:

      The elimination of phenytoin follows first order kinetics. Plasma concentrations determine the rate of elimination. The relationship between drug X plasma concentration and time is described by an exponential process in the following equation used to describe the rate of elimination:

      C = C0. e-kt

      C=drug concentration, C0= drug concentration at time zero (extrapolated), k = rate constant and t=time

      As enzyme systems become saturated when phenytoin concentrations are above the usual range, clearance of the medication becomes zero-order. The medication is metabolised at a constant pace, regardless of its plasma levels. Aspirin and ethyl alcohol are two more significant examples of medications that operate in this way.

      A plot of drug concentration with time is a washout exponential curve.

      A graph of concentration with time is a straight line i.e. Zero-order kinetics

      The amount eliminated per unit time is constant defines the point at which zero order kinetics commences.

      Elimination involves a rate-limiting reaction operating at its maximal velocity is incorrect.

      The half life of the drug is proportional to the drug concentration in the plasma corresponds to a definition of first-order kinetics.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 10 - Which nerve does NOT pass through the posterior triangle of the neck? ...

    Incorrect

    • Which nerve does NOT pass through the posterior triangle of the neck?

      Your Answer:

      Correct Answer: Ansa cervicalis

      Explanation:

      The sternocleidomastoid muscle divides the neck into anterior and posterior triangles on both sides of the neck.

      The posterior triangle has the following boundaries:
      anteriorly – sternocleidomastoid muscle
      posteriorly – trapezius
      roof – investing layer of deep cervical fascia
      floor – prevertebral fascia overlying splenius capitis, levator scapulae, and the scalene muscles

      The contents of the posterior triangle are:
      1. fat
      2. lymph nodes (level V)
      3. accessory nerve
      4. cutaneous branches of the cervical plexus – greater auricular nerve, transverse cervical nerve, lesser occipital nerve, supraclavicular nerve (A major branch of this plexus is the phrenic nerve, which arises from the anterior divisions of spinal nerves C3-C5)
      5. inferior belly of omohyoid
      6. branches of the thyrocervical trunk (transverse cervical and suprascapular arteries)
      7. third part of the subclavian artery
      8. external jugular vein

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 11 - A 25-year-old male has tonsillitis and is in considerable pain.

    Which nerve is responsible...

    Incorrect

    • A 25-year-old male has tonsillitis and is in considerable pain.

      Which nerve is responsible for the sensory innervation of the tonsillar fossa?

      Your Answer:

      Correct Answer: Glossopharyngeal nerve

      Explanation:

      A tonsillar sinus or fossa is a space that is bordered by the triangular fold of the palatoglossal and palatopharyngeal arches in the lateral wall of the oral cavity. The palatine tonsils are in these sinuses.

      The glossopharyngeal nerve is the main sensory nerve for the tonsillar fossa. The tonsillar branches of the glossopharyngeal nerve supply the palatine tonsils forming a plexus around it. Filaments from this plexus are distributed to the soft palate and fauces where they communicate with the palatine nerves. A lesser contribution is made by the lesser palatine nerve. Because of this otalgia may occur following tonsillectomy.

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 12 - Diagnosis of the neuroleptic malignant syndrome is best supported by which of the...

    Incorrect

    • Diagnosis of the neuroleptic malignant syndrome is best supported by which of the following statement?

      Your Answer:

      Correct Answer: Increased Creatine Kinase

      Explanation:

      The neuroleptic malignant syndrome is a rare complication in response to neuroleptic or antipsychotic medication.

      The main features are:
      – Elevated creatinine kinase
      – Hyperthermia and tachycardia
      – Altered mental state
      – Increased white cell count
      – Insidious onset over 1-3 days
      – Extrapyramidal dysfunction (muscle rigidity, tremor, dystonia)
      – Autonomic dysfunction (Labile blood pressure, sweating, salivation, urinary incontinence)

      Management is supportive ICU care, anticholinergic drugs, increasing dopaminergic activity with Amantadine, L-dopa, and dantrolene, and non- depolarising neuromuscular blockade drugs

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 13 - A 30-year old female athlete was brought to the Emergency Room for complaints...

    Incorrect

    • A 30-year old female athlete was brought to the Emergency Room for complaints of light-headedness and nausea. Clinical chemistry studies were done and the results were the following:

      Na: 144 mmol/L (Reference: 137-144 mmol/L)
      K: 6 mmol/L (Reference: 3.5-4.9 mmol/L)
      Cl: 115 mmol/L (Reference: 95-107 mmol/L)
      HCO3: 24 mmol/L (Reference: 20-28 mmol/L)
      BUN: 9.5 mmol/L (Reference: 2.5-7.5 mmol/L)
      Crea: 301 µmol/l (Reference: 60 - 110 µmol/L)
      Glucose: 3.5 mmol/L (Reference: 3.0-6.0 mmol/L)

      Taking into consideration the values above, in which of the following ranges will his osmolarity fall into?

      Your Answer:

      Correct Answer: 300-313

      Explanation:

      Osmolarity refers to the osmotic pressure generated by the dissolved solute molecules in 1 L of solvent. Measurements of osmolarity are temperature dependent because the volume of the solvent varies with temperature. The higher the osmolarity of a solution, the more it attracts water from an opposite compartment.

      Osmolarity can be computed using the following formulas:

      Osmolarity = Concentration x number of dissociable particles; OR
      Plasma osmolarity (Posm) = 2([Na+]) + (glucose in mmol/L) + (BUN in mmol/L)

      Posm = 2 (144) + 3.5 + 9.5 = 301 mOsm/L

      Suppose there is electrical neutrality, the formula will double the cation activity to account for the anions.

      Plasma osmolarity (Posm) = 2([Na+] + [K+]) + (glucose in mmol/L) + (BUN in mmol/L)

      Posm = 2 (144 + 6) + 3.5 + 9.5 = 313 mOsm/L

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 14 - Which of the following bias is more prone to case-control studies? ...

    Incorrect

    • Which of the following bias is more prone to case-control studies?

      Your Answer:

      Correct Answer: Recall bias

      Explanation:

      Omitted variable bias occurs when a statistician passes over one or more relevant variables from the study.

      Publication bias occurs in publish academic research. it occurs when the results of the study effect the decision whether to publish or not.

      Expectation bias occurs when the expectation of a researcher about the results effect the behaviour of the participants. Expectations may come from communication and experiences.

      Work up bias occurs in the study of diagnostic test validity, whether a gold standard procedure has been used. work up bias can seriously affect the specificity of the test.

      Recall bias introduced when participants in a study are systematically more or less likely to recall and relate information on exposure depending on their outcome status. Recall bias is more potential for Case-control studies.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 15 - How many unpaired branches leave the abdominal aorta to supply the abdominal viscera?...

    Incorrect

    • How many unpaired branches leave the abdominal aorta to supply the abdominal viscera?

      Your Answer:

      Correct Answer: Three

      Explanation:

      The abdominal arteries are divided into 3 branches;
      – 3 main unpaired trunks (celiac trunk, superior mesenteric, inferior mesenteric arteries)
      – 6 paired branches
      – unpaired median sacral artery.

      We can group the abdominal aorta as follows;
      -Ventral which includes: Coeliac trunk, superior mesenteric and inferior mesenteric arteries
      -Lateral: Inferior phrenic, middle suprarenal, renal and gonadal arteries
      -Dorsal: Lumbar and median sacral arteries
      -Terminal : Right and left common iliac arteries

      The celiac trunk (L1) takes blood the foregut and its found posterior to the stomach. The unpaired superior mesenteric artery supplies blood to the mid-gut.

      The paired renal arteries form the inferior suprarenal arteries. The renal arteries arise around L1/L2 and takes blood to either side of the kidneys.

      The median sacral artery supplies blood to the lumbar vertebrae the L4 and L5.

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 16 - A 25-year-old man, has been scheduled for a splenectomy. For this procedure, he...

    Incorrect

    • A 25-year-old man, has been scheduled for a splenectomy. For this procedure, he requires a urethral catheter.

      Where does resistance first occur during the insertion of a catheter?

      Your Answer:

      Correct Answer: Membranous urethra

      Explanation:

      The membranous urethra is the shortest part of the urethra and the least dilatable part of it.

      This is as a result of it being surrounded by the external urethral sphincter which is made up of striated muscle and controls voluntary urine flow from the bladder to the urethra.

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 17 - Which of the following descriptions best describes enflurane and isoflurane? ...

    Incorrect

    • Which of the following descriptions best describes enflurane and isoflurane?

      Your Answer:

      Correct Answer: Have the same molecular formula but different structural formulae

      Explanation:

      Structural isomers have a similar molecular formula, but they have a different structural formula as their atoms are arranged in a different manner. Such small changes lead to the differential pharmacological activity. Enflurane and isoflurane are two prime examples of structural isomers.

      Stereoisomers are those substances that have a similar molecular and structural formula, but the arrangement spatially of atoms are different and have optical activity.

      Enantiomers are a pair of stereoisomers, which are non-superimposable mirror images of each other. They also have chiral centres of molecular symmetry. Ketamine is considered as an example of racemic mixture (contain 50% R and 50% S enantiomers)

      Geometric isomers contain a carbon-carbon double bond (i.e. C=C) or a rigid carbon-carbon single bond in a heterocyclic ring. Cis-atracurium is one example.

      Dynamic isomers or Tautomers are a pait of unstable structural isomers, which are present in equilibrium. One isomer can easily change after the change in pH. Midazolam and thiopentone are their examples.

    • This question is part of the following fields:

      • Pharmacology
      0
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  • Question 18 - Which of the following, at a given PaO2, increases the oxygen content of...

    Incorrect

    • Which of the following, at a given PaO2, increases the oxygen content of arterial blood?

      Your Answer:

      Correct Answer: A reduced erythrocyte 2,3-diphosphoglycerate level

      Explanation:

      The oxygen content of arterial blood can be calculated by the following equation:
      (10 x haemoglobin x SaO2 x 1.34) + (PaO2 x 0.0225).
      This is the sum of the oxygen bound to haemoglobin and the oxygen dissolved in the plasma.

      Oxygen content x cardiac output = The amount of oxygen delivered to the tissues in unit time which is known as the oxygen flux.

      Any factor that increases the metabolic demand will encourage oxygen offloading from the haemoglobin in the tissues and this causes the oxygen dissociation curve (ODC) to shift to the right. This subsequently reduced the oxygen content of arterial blood.

      Conditions like fever, metabolic or respiratory acidosis lowers the oxygen content and shifts the ODC to the right.
      A low level of 2,3 diphosphoglycerate (2,3-DPG) is usually related to an increased oxygen content as there is less offloading, and so the ODC is shifted to the left.

      So for a given PaO2, a high blood oxygen content is related to any factors that can shift the ODC to the left and not to the right.

      A low haematocrit usually means that there is a decreased haemoglobin concentration, and therefore is associated with decreased oxygen binding to haemoglobin.

    • This question is part of the following fields:

      • Physiology
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  • Question 19 - A 68-year old female is brought to the Emergency Room for abdominal pain....

    Incorrect

    • A 68-year old female is brought to the Emergency Room for abdominal pain. Medical history revealed that she is on long-term warfarin therapy for deep vein thrombosis.

      Upon further investigation, the patient is hypotensive at 80/60 mmHg, and an abdominal mass is palpable on the umbilical area. An initial diagnosis of ruptured abdominal aortic aneurysm (AAA) is made. Moreover, blood tests show an international normalised ratio (INR) of 4.2.

      Which of the following products should be initially transfused or administered to the patient to reverse the anticoagulation?

      Your Answer:

      Correct Answer: Prothrombin complex

      Explanation:

      Warfarin prevents reductive metabolism of the inactive vitamin K epoxide back to its active hydroquinone form. Thus, warfarin inhibits the synthesis of vitamin K dependent clotting factors: X, IX, VII, II (prothrombin), and of the anticoagulants protein C and protein S. The therapeutic range for oral anticoagulant therapy is defined in terms of an international normalized ratio (INR). The INR is the prothrombin time ratio (patient prothrombin time/mean of normal prothrombin time for lab)ISI, where the ISI exponent refers to the International Sensitivity Index and is dependent on the specific reagents and instruments used for the determination. A prolonged INR is widely used as an indication of integrity of the coagulation system in liver disease and other disorders, it has been validated only in patients in steady state on chronic warfarin therapy.

      Prothrombin complex concentrate (PCC) is used to replace congenital or acquired vitamin-K deficiency warfarin-induced anticoagulant effect, particularly in the emergent setting.

      Intravenous vitamin K has a slower onset of action compared to PCC, but is useful for long term therapy.

      Fresh frozen plasma (FFP) prepared from freshly donated blood is the usual source of the vitamin K-dependent factors and is the only source of factor V. The factors needed, however, are found in small quantities compared to PCC.

      Cryoprecipitate is indicated for hypofibrinogenemia/dysfibrinogenemia, von Willebrand disease, haemophilia A, factor XIII deficiency, and management of bleeding related to thrombolytic therapy.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 20 - A 30-year-old man has been stabbed in an area of the groin that...

    Incorrect

    • A 30-year-old man has been stabbed in an area of the groin that contains the femoral triangle. He will undergo explorative surgery.

      Which of the following makes the lateral wall of the femoral triangle?

      Your Answer:

      Correct Answer: Sartorius

      Explanation:

      The femoral triangle is a wedge-shaped area found within the superomedial aspect of the anterior thigh. It is a passageway for structures to leave and enter the anterior thigh.

      Superior: Inguinal ligament
      Medial: Adductor longus
      Lateral: Sartorius
      Floor: Iliopsoas, adductor longus and pectineus

      The contents include: (medial to lateral)
      Femoral vein
      Femoral artery-pulse palpated at the mid inguinal point
      Femoral nerve
      Deep and superficial inguinal lymph nodes
      Lateral cutaneous nerve
      Great saphenous vein
      Femoral branch of the genitofemoral nerve

    • This question is part of the following fields:

      • Anatomy
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  • Question 21 - All of the following statements about cerebrospinal fluid are incorrect except: ...

    Incorrect

    • All of the following statements about cerebrospinal fluid are incorrect except:

      Your Answer:

      Correct Answer: Has a glucose concentration 2/3 that of the plasma glucose

      Explanation:

      The pH of CSF is 7.31 which is lower than plasma.

      Compared to plasma, it has a lower concentration of potassium, calcium, and protein and a higher concentration of sodium, chloride, bicarbonate and magnesium.

      CSF usually has no cells present but if white cells are present, there should be no more than 4/ml.

      The pressure of CSF should be less than 20 cm of water.

      The concentration of glucose is approximately two-thirds of that of plasma, and it has a concentration of approximately 3.3-4 mmol/L.

    • This question is part of the following fields:

      • Physiology
      0
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  • Question 22 - A 66-year-old man, present to the emergency department with dyspepsia. On history taking,...

    Incorrect

    • A 66-year-old man, present to the emergency department with dyspepsia. On history taking, he admits to being a heavy smoker, and on testing is noted to be positive for a helicobacter pylori infection. A few evenings later, he suffers from haematemesis and collapses.

      What vessel is most likely to be involved?

      Your Answer:

      Correct Answer: Gastroduodenal artery

      Explanation:

      The most likely of the differential diagnosis in this case is a duodenal ulcer located on the posterior abdominal wall.

      These can cause an erosion of the abdominal wall, eventually affecting the gastroduodenal artery and resulting in major bleeding and haematemesis.

      Gastroduodenal artery supplies the pylorus, proximal part of the duodenum, and indirectly to the pancreatic head (via the anterior and posterior superior pancreaticoduodenal arteries)

    • This question is part of the following fields:

      • Anatomy
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  • Question 23 - What structure is most posterior at the porta hepatis? ...

    Incorrect

    • What structure is most posterior at the porta hepatis?

      Your Answer:

      Correct Answer: Portal vein

      Explanation:

      The structures in the porta hepatis from anterior to posterior are:

      The ducts: Most anterior are the left and right hepatic ducts.

      The arteries: Next are the left and right hepatic arteries

      The veins: Next is the portal vein

      The epiploic foramen of Winslow lies most posterior at the porta hepatis.

    • This question is part of the following fields:

      • Anatomy
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  • Question 24 - One litre of water at 0°C and a pressure of 1 bar is...

    Incorrect

    • One litre of water at 0°C and a pressure of 1 bar is in a water-bath. A 1 kW element is used in heating it.

      Given that the specific heat capacity of water is 4181 J/(kg°C) or J/(kg K), how long will it take to raise the temperature of the water by 10°C?

      Your Answer:

      Correct Answer: 42 seconds

      Explanation:

    • This question is part of the following fields:

      • Physiology
      0
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  • Question 25 - The SI unit of measurement is kgm2s-2 in the System international d'unités (SI).

    Which...

    Incorrect

    • The SI unit of measurement is kgm2s-2 in the System international d'unités (SI).

      Which of the following derived units of measurement has this format?

      Your Answer:

      Correct Answer: Energy

      Explanation:

      The derived SI unit of force is Newton.
      F = m·a (where a is acceleration)
      F = 1 kg·m/s2

      The joule (J) is a converted unit of energy, work, or heat. When a force of one newton (N) is applied over a distance of one metre (Nm), the following amount of energy is expended:

      J = 1 kg·m/s2·m =
      J = 1 kg·m2/s2 or 1 kg·m2·s-2

      The unit of velocity is metres per second (m/s or ms-1).

      The watt (W), or number of joules expended per second, is the SI unit of power:

      J/s = kg·m2·s-2/s
      J/s = kg·m2·s-3

      Pressure is measured in pascal (Pa) and is defined as force (N) per unit area (m2):
      Pa = kg·m·s-2/m2
      Pa = kg·m-1·s-2

    • This question is part of the following fields:

      • Physiology
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  • Question 26 - The half-empty cylinder weighs 4.44 kg.
    The tare weight of a nitrous...

    Incorrect

    • The half-empty cylinder weighs 4.44 kg.
      The tare weight of a nitrous oxide cylinder is 4 kg.
      The molecular weight of nitrous oxide is 44gm.

      Based on the data, how many litres of nitrous oxide remains in the cylinder for use?

      Your Answer:

      Correct Answer: 224 litres

      Explanation:

      The Tare weight of a cylinder is the weight when it is empty. So,

      Weight of cylinder – tare weight = weight of remaining N2O (g).
      4.44 kg – 4 kg = 0.44 kg
      Here,
      0.44 kg of nitrous oxide remains in the cylinder

      Since the molecular weight of nitrous oxide is 44 g and one mole of an ideal gas will occupy a volume of 22.4 litres at STP
      Therefore amount left in the cylinder is several (gN2O/44) x 22.4 litres of N2O.

      (440/44) x 22.4 = 224 litres.

    • This question is part of the following fields:

      • Basic Physics
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  • Question 27 - Regarding thyroid hormones, one of the following is true. ...

    Incorrect

    • Regarding thyroid hormones, one of the following is true.

      Your Answer:

      Correct Answer: Thyroid binding globulin (TBG) is increased in pregnancy

      Explanation:

      T3 is produced by peripheral de-iodination of T4. It is more active than T4.

      TBG, like most binding proteins, is increased in pregnancy. Because of this, measurement of free thyroid hormone concentration is more important than total.

      T4 and T3 concentrations are decreased in Illness and starvation.

      L-T4 that is the active molecule while D-T4 is inactive.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 28 - Which of the following statements is true regarding the relation to the liver?...

    Incorrect

    • Which of the following statements is true regarding the relation to the liver?

      Your Answer:

      Correct Answer: The caudate lobe is superior to the porta hepatis

      Explanation:

      Ligamentum venosum is an anterior relation of the liver: The ligamentum venosum, the fibrous remnant of the ductus venosus of the fetal circulation, lies posterior to the liver. It lies in the fossa for ductus venosus that separates the caudate lobe and the left lobe of the liver.

      The portal triad contains three important tubes: 1. Proper hepatic artery 2. Hepatic portal vein 3. Bile ductules It also contains lymphatic vessels and a branch of the vagus nerve.

      The bare area of the liver is a large triangular area that is devoid of any peritoneal covering. The bare area is attached directly to the diaphragm by loose connective tissue. This nonperitoneal area is created by a wide separation between the coronary ligaments.

      The porta hepatis is a fissure in the inferior surface of the liver. All the neurovascular structures (except the hepatic veins) and hepatic ducts enter or leave the liver via the porta hepatis. It contains the sympathetic branch to the liver and gallbladder and the parasympathetic, hepatic branch of the vagus nerve. The caudate lobe (segment I) lies in the lesser sac on the inferior surface of the liver between the IVC on the right, the ligamentum venosum on the left, and the porta hepatis in front

    • This question is part of the following fields:

      • Anatomy
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  • Question 29 - A 56-year old man, presents to emergency department following a cardiac arrest. On...

    Incorrect

    • A 56-year old man, presents to emergency department following a cardiac arrest. On history and examination, he is found to be suffering from both metabolic and respiratory acidosis as a result of his cardiac arrest.

      What is the best way to reduce the risk of acidaemia during cardiac arrest

      Your Answer:

      Correct Answer: Chest compressions

      Explanation:

      Chest compressions are an essential part of cardiopulmonary resuscitation (CPR) which helps restore spontaneous circulation (ROSC).

      Sodium bicarbonate is only prescribed in patients with cardiac arrests as a result of an overdose of tricyclic antidepressants or hyperkalaemia. Its use causes the body to produce more CO2 which causes:

      Exacerbation of intracellular acidosis
      Negative inotropy to ischaemic myocardium
      Increased osmotic load of sodium into failing brain and body
      Shift of oxygen dissociation curve to the left.

      THAM is often used to treat metabolic acidosis as a result of cardiac bypass surgery and also cardiac arrest, when other standard methods have failed.

      Carbicarb (Na2CO3 0.33 molar NaHCO3 0.33 molar) has only mild effects on acidosis. It also causes an increase in arterial CO2 pressure and lactate concentration.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 30 - An elderly man complains of a vague lump near his stomach to his...

    Incorrect

    • An elderly man complains of a vague lump near his stomach to his physician. On examination, the lump is visible on coughing and is found within Hesselbach's triangle.

      Which of the following is true regarding the borders for this triangle?

      Your Answer:

      Correct Answer: Inguinal ligament inferiorly, inferior epigastric vessels laterally, lateral border of rectus sheath medially

      Explanation:

      The inguinal triangle of Hesselbach is an important clinical landmark on the posterior wall of the inguinal canal. It has the following relations:
      Inferiorly – medial third of the inguinal ligament
      Medially – lower lateral border of the rectus abdominis
      Laterally – inferior epigastric vessels

      Direct inguinal hernia is when the bowel bulges directly through the abdominal wall. These hernias usually protrude through Hesselbach’s triangle

    • This question is part of the following fields:

      • Anatomy
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  • Question 31 - Which of the following is true about the pulse oximeter? ...

    Incorrect

    • Which of the following is true about the pulse oximeter?

      Your Answer:

      Correct Answer: Is accurate to within +/- 2% in the range of 70% to 100% saturation

      Explanation:

      The pulse oximeter provides a continuous non-invasive measurement of the arterial oxygen saturation. The light emitting diodes (LEDs) produce beams of red and infrared light at 660 nm and 940 nm respectively (not 640 and 960 nm), which travel through a finger (toe, ear lobe or nose) and are then detected by a sensitive photodetector.

      The light absorbed by non-pulsatile tissues is constant (DC), and the non-constant absorption (AC) is the result of arterial blood pulsation. The DC and AC components at 660 and 940 nm are then analysed by the microprocessor and the result is related to the arterial saturation.

      An isosbestic point is a point at which two substances absorb a wavelength of light to the same degree. In pulse oximetry the different absorption profiles of oxyhaemoglobin and deoxyhaemoglobin are used to quantify the haemoglobin saturation (in %). Isosbestic points occur at 590 and 805 nm (not 490 and 805 nm), where the light absorbed is independent of the degree of saturation, and are used as reference points.

      The pulse oximeter is accurate to within +/- 2% in the range of 70% to 100% saturation, and below 70% the readings are extrapolated. Pulse oximeters average their readings every 10 to 20 seconds and thus they cannot detect acute desaturation events. Consequently, they are often referred to as ‘lag’ monitors, due to the time delay in identifying the desaturation episode.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 32 - In the adrenal gland: ...

    Incorrect

    • In the adrenal gland:

      Your Answer:

      Correct Answer: Catecholamine release is mediated by cholinergic nicotinic transmission

      Explanation:

      The adrenal (suprarenal) gland is composed of two main parts: the adrenal cortex, which is the largest and outer part of the gland, and the adrenal medulla. The adrenal cortex consists of three zones: 1. Zona glomerulosa (outermost layer) is responsible for the production of mineralocorticoids, mainly aldosterone, which regulates blood pressure and electrolyte balance. 2. Zona fasciculata (middle layer) is responsible for the production of glucocorticoids, predominantly cortisol, which increases blood sugar levels via gluconeogenesis, suppresses the immune system, and aids in metabolism. It also produces 11-deoxycorticosterone and corticosterone in addition to cortisol. 3. Zona reticularis (innermost layer) is responsible for the production of gonadocorticoids, mainly dehydroepiandrosterone (DHEA), which serves as the starting material for many other important hormones produced by the adrenal gland, such as oestrogen, progesterone, testosterone, and cortisol. It is also responsible for administering these hormones to the reproductive regions of the body.

      The adrenal medulla majorly secretes epinephrine (adrenaline), and norepinephrine in small quantity. Both hormones have similar functions and initiate the flight or fight response.

      Catecholamine is mediated by cholinergic nicotinic transmission through changes in sympathetic nervous system (T5 – T11), being increased during stress and hypoglycaemia.

      Blood supply to the adrenal gland is by these three arteries: superior suprarenal arteries, middle suprarenal artery and inferior suprarenal artery. Venous drainage is via the suprarenal vein to the left renal vein or directly to the inferior vena cava on the right side. There is no portal (venous) system between cortex and medulla.

    • This question is part of the following fields:

      • Anatomy
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  • Question 33 - All of the following statements are true about blood clotting except: ...

    Incorrect

    • All of the following statements are true about blood clotting except:

      Your Answer:

      Correct Answer: Administration of aprotinin during liver transplantation surgery prolongs survival

      Explanation:

      Even though aprotinin reduces fibrinolysis and therefore bleeding, there is an associated increased risk of death. It was withdrawn in 2007.
      Protein C is dependent upon vitamin K and this may paradoxically increase the risk of thrombosis during the early phases of warfarin treatment.

      The coagulation cascade include two pathways which lead to fibrin formation:
      1. Intrinsic pathway – these components are already present in the blood
      Minor role in clotting
      Subendothelial damage e.g. collagen
      Formation of the primary complex on collagen by high-molecular-weight kininogen (HMWK), prekallikrein, and Factor 12
      Prekallikrein is converted to kallikrein and Factor 12 becomes activated
      Factor 12 activates Factor 11
      Factor 11 activates Factor 9, which with its co-factor Factor 8a form the tenase complex which activates Factor 10

      2. Extrinsic pathway – needs tissue factor that is released by damaged tissue)
      In tissue damage:
      Factor 7 binds to Tissue factor – this complex activates Factor 9
      Activated Factor 9 works with Factor 8 to activate Factor 10

      3. Common pathway
      Activated Factor 10 causes the conversion of prothrombin to thrombin and this hydrolyses fibrinogen peptide bonds to form fibrin. It also activates factor 8 to form links between fibrin molecules.

      4. Fibrinolysis
      Plasminogen is converted to plasmin to facilitate clot resorption

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 34 - What is the most sensitive method of detecting an intra-operative air embolism? ...

    Incorrect

    • What is the most sensitive method of detecting an intra-operative air embolism?

      Your Answer:

      Correct Answer: Transoesophageal echocardiogram

      Explanation:

      An intra-operative air embolism occurs when air becomes trapped in the blood vessels during surgery.

      A transoesophageal echocardiography (OE) uses invasive echocardiography to monitor the integrity and performance of the heart. It is the gold standard as it provides real-time imaging of the heart to enable early diagnosis and treatment.

      Precordial doppler ultrasonography can also be used to detect into-operative air emboli. It is non-invasive and more practical, but is less sensitive.

      A change in end-tidal CO2 could be indicative of and increase in physiological dead-space, but could also be indicative of any processes that reduces the excretion or increases the production of CO2, making it non-specific.

      A transoesophageal stethoscope can be used to listen for the classic mill-wheel murmur produced by a large air embolus.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 35 - A controlled retrospective study's level of evidence is? ...

    Incorrect

    • A controlled retrospective study's level of evidence is?

      Your Answer:

      Correct Answer: Level 3

      Explanation:

      Level 1 – High-quality randomised controlled trial with statistically significant difference or no statistically significant difference but narrow confidence intervals (prospective controlled)

      Level 2 – Prospective comparative study (prospective uncontrolled)

      Level 3 – Case-control study, retrospective comparative study (retrospective controlled)

      Level 4 – Case series (retrospective uncontrolled)

      Level 5 – Expert opinion.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 36 - The external laryngeal nerve is responsible for the innervation of which of the...

    Incorrect

    • The external laryngeal nerve is responsible for the innervation of which of the following muscles?

      Your Answer:

      Correct Answer: Cricothyroid

      Explanation:

      The external laryngeal nerve arises from the superior laryngeal nerve and provides innervation to the cricothyroid muscle.

      The other muscles mentioned receive their innervations from the recurrent laryngeal nerve.

    • This question is part of the following fields:

      • Anatomy
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  • Question 37 - Which statement is true when describing carbonic anhydrase? ...

    Incorrect

    • Which statement is true when describing carbonic anhydrase?

      Your Answer:

      Correct Answer: Isoenzyme IV is found in the brush border of the proximal convoluted tubule

      Explanation:

      Carbonic anhydrase is an enzyme which contains zinc and can be found in:
      1. Erythrocytes
      2. Pulmonary endothelium
      3. The intestine
      4. Pancreas
      5. Cardiac muscle and skeletal muscle.

      To date, there have been seven isoenzymes identified. Of note, isoenzyme IV is found in the brush border of the proximal convoluted tubule and isoenzyme II is found within the luminal cells.

      Acetazolamides a carbonic anhydrase inhibitor and is used as prophylaxis against mountain sickness and in glaucoma management.

      Spironolactone is a potassium diuretic and is an aldosterone antagonist.

    • This question is part of the following fields:

      • Physiology
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  • Question 38 - A 30-year-old woman with a BMI of 24 kg/m2 consumes four glasses of...

    Incorrect

    • A 30-year-old woman with a BMI of 24 kg/m2 consumes four glasses of wine on an empty stomach. Her serum alcohol are levels measured over the following five hours. The serum alcohol level of 30-year-old man with the same BMI and alcohol consumption is also measured over the same duration.

      The peak concentration of alcohol is found to be greater in the woman than in the man.

      Which of these offers best explanation for this observation?

      Your Answer:

      Correct Answer: Lower volume of distribution

      Explanation:

      The blood alcohol concentration depends on:

      -The rate of alcohol absorption from the gastrointestinal tract
      -The volume of distribution of alcohol in the body, and
      -The rate of elimination of alcohol from the body.

      Total body water is approximately 50% in a female as compared to 60% in a typical male. This means that the volume of distribution of alcohol is lower in female compared with men. This is the principal reason for higher peak in alcohol levels.

      About 4% of ingested alcohol is metabolised by the liver accounting for first pass metabolism and 0.4% is metabolised by gastric alcohol dehydrogenase (ADH). The absorbed alcohol is NOT distributed to fat cells but it is distributed throughout the water compartments (plasma, interstitial and intracellular) of the body. Women have very little gastric ADH, which further influences this exaggerated rise.

      85-98% of the alcohol is oxidised by the liver to acetaldehyde and then to acetate. The metabolic pathway initially observes first order kinetics and then saturation or zero order kinetics leading to peaks in alcohol levels.

      Clearance of ethanol per unit lean body mass is lower in male. The calculated alcohol elimination rate and liver volume per kilogram of lean body mass were 33% and 38% higher in women than in men, respectively.

      Available evidence in the literature about the relationship of alcohol metabolism to the phases of the menstrual cycle is conflicting.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 39 - A 61-year-old woman, present to her general practitioner. She complains of a severe...

    Incorrect

    • A 61-year-old woman, present to her general practitioner. She complains of a severe lancinating pain in her forehead that only last a few seconds, possibly triggered by washing her face, occurring over the previous six weeks.

      On examination, she is normal with no other signs or symptoms.

      Which nerve is the most likely cause of her pain?

      Your Answer:

      Correct Answer: Sensory branches of the ophthalmic division of the trigeminal nerve

      Explanation:

      Her symptoms are suggestive of trigeminal neuralgia which is a short, sudden, severe sharp unilateral pain in the facial region. The pain often follows the sensory distribution of the trigeminal nerve (CN V).

      The trigeminal nerve gives rise to 3 sensory and 1 motor nuclei. Neuralgia can arise from any of the 3 sensory divisions.

      The ophthalmic division gives rise to 3 further sensory branches, which are the frontal, lacrimal and nasociliary.

      The frontal branch of the ophthalmic division of the trigeminal nerve is responsible for the innervation of the area in question.

      The superior alveolar dental, zygomatic and sphenopalatine nerves are all branches arising from the maxillary division of the trigeminal nerve.

      The mandibular division of the trigeminal nerve provides sensory and motor innervation. The sensory innervation is carried out by the auriculotemporal nerve which supplies the lower third of the face, while the motor fibres are responsible for controlling the muscles of mastication.

      The somatic sensory branches of the vagus nerve are responsible for sensory innervation of the external acoustic meatus and tympanic membrane.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 40 - Conclusive evidence suggests that rate for the prevalence of schizophrenia in United Kingdom...

    Incorrect

    • Conclusive evidence suggests that rate for the prevalence of schizophrenia in United Kingdom is around 1%.

      Which term can be used to describe that?

      Your Answer:

      Correct Answer: Endemic

      Explanation:

      An epidemic is declared when the increase in a give disease is above a certain level in a specific interval of time.

      An endemic is the general, usual level of a disease in a population at a particular time.

      A pandemic is an epidemic that is spread across many countries and continents.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 41 - Which statement regarding the cardiac action potential is correct? ...

    Incorrect

    • Which statement regarding the cardiac action potential is correct?

      Your Answer:

      Correct Answer:

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 42 - An aged patient that has been suffering from diabetes criticised the health minister...

    Incorrect

    • An aged patient that has been suffering from diabetes criticised the health minister for his comments on incidence and prevalence. The minister had said that they both are two separate entities. It can be therefore inferred that the patient thinks that prevalence and incidence are the same thing.

      Is he right?

      Your Answer:

      Correct Answer: No. In chronic disease prevalence is greater than incidence.

      Explanation:

      Only on rare occasions has it been found that the prevalence and incidence were same. Incidence can be greater than prevalence in acute cases only. In case of chronic diseases prevalence is far greater than incidence. One needs to have a deeper understanding of both the concepts to understand the health literature.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 43 - What is the percentage of values that lie within 3 standard deviations of...

    Incorrect

    • What is the percentage of values that lie within 3 standard deviations of the mean?

      Your Answer:

      Correct Answer: 99.70%

      Explanation:

      99.7% of the values within 3 standard deviations of the mean.

      For 99.7% confidence interval, you can find the range as follows:

      1. Multiply the standard error by 3.

      2. Subtract the answer from mean value to get the lower limit.

      3. Add the answer obtained in step 1 from the mean value to get the upper limit.

      For a confidence interval of 68%, multiply the standard error with 1 and repeat the process. For a 95% confidence interval, Standard Error is multiplied by 1.96 to get the interval.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 44 - Which of the following is included in monosynaptic reflexes? ...

    Incorrect

    • Which of the following is included in monosynaptic reflexes?

      Your Answer:

      Correct Answer: The patellar or knee jerk reflex.

      Explanation:

      Monosynaptic reflexes is a type of reflex arc providing direct communication between motor and sensory innervation in a muscle. It occurs very quickly as it arises and ends in the same muscle. Examples include: biceps reflex, brachioradialis reflex, extensor digitorum reflex, triceps reflex, Achilles reflex and patellar reflex.

      Polysynaptic reflexes facilitates contraction and inhibition in muscle by providing communication between multiple muscles.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 45 - Which of the following statements is true regarding enantiomers? ...

    Incorrect

    • Which of the following statements is true regarding enantiomers?

      Your Answer:

      Correct Answer: Desflurane is a chiral compound

      Explanation:

      A compound that contains an asymmetric centre (chiral atom or chiral centre) and thus can occur in two non-superimposable mirror-image forms (enantiomers) are called chiral compounds.

      Desflurane, Halothane, and isoflurane are chiral compounds but Sevoflurane is not a chiral compound.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 46 - A 50-year-old man is admitted in hospital. Over four hours, he produces 240...

    Incorrect

    • A 50-year-old man is admitted in hospital. Over four hours, he produces 240 mL of urine and has a plasma creatinine concentration is 10 mcg/mL. The normal concentration of creatinine in urine is 1.25 mg/mL.

      Calculate his approximate creatinine clearance.

      Your Answer:

      Correct Answer: 125 ml/minute

      Explanation:

      Creatinine clearance is a test used to approximate the glomerular filtration rate (GFR) as an assessment of kidney function.

      Creatinine is formed during the breakdown of dietary sources of meat and skeletal muscle. It is secreted at a consistent concentration and pace into the body’s circulation, and is easily filtered across the glomerulus without being reabsorbed or metabolized by the kidney.

      It is represented mathematically as:
      Creatinine clearance (CL) = U x V/P
      where,
      U: Urinary creatinine concentration (mg/mL)
      V: Volume of urine (mL/min)
      P: Plasma creatinine concentration (mg/mL)

      Therefore, in this case:
      CL: 1.25 x 1 = 125mL/min
      0.1

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 47 - Which term among the following is used for the proportion of a particular...

    Incorrect

    • Which term among the following is used for the proportion of a particular disease that would be eradicated from a population if the rate of disease were to be reduced to that of the group that has not been exposed to it?

      Your Answer:

      Correct Answer: Attributable proportion

      Explanation:

      The attributable risk is the rate of a disease in an exposed group to that of a group that has not been exposed to it. It involves the measure of association that is pertinent to making decisions for the individuals.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 48 - Volunteers are being recruited for a new clinical trial of a novel drug...

    Incorrect

    • Volunteers are being recruited for a new clinical trial of a novel drug treatment for Ulcerative colitis. The proposed study will enrol about 2000 people with ulcerative colitis. Testing will be performed to assess any reduction in disease severity with the new drug as compared to the current treatment available in the industry.

      Which phase of clinical trial will this be?

      Your Answer:

      Correct Answer: Phase 3

      Explanation:

      This clinical trial consists over 1000 patients being evaluated for the response to a new treatment against a currently licensed treatment for ulcerative colitis. Therefore, it is comparing its efficacy to an established therapeutic or control in a larger population of volunteers. These are the characteristics of a phase III clinical trial.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 49 - The following statement is true with regards to the Nernst equation: ...

    Incorrect

    • The following statement is true with regards to the Nernst equation:

      Your Answer:

      Correct Answer: It is used to calculate the potential difference across a membrane when the individual ions are in equilibrium

      Explanation:

      The Nernst equation is used to calculate the membrane potential at which the ions are in equilibrium across the cell membrane.

      The normal resting membrane potential is -70 mV (not + 70 mV).

      The equation is:
      E = RT/FZ ln {[X]o
      /[X]i}

      Where:
      E is the equilibrium potential
      R is the universal gas constant
      T is the absolute temperature
      F is the Faraday constant
      Z is the valency of the ion
      [X]o is the extracellular concentration of ion X
      [X]i is the intracellular concentration of ion X.

    • This question is part of the following fields:

      • Physiology
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  • Question 50 - The equipment used for patient monitoring in theatre and intensive care settings have...

    Incorrect

    • The equipment used for patient monitoring in theatre and intensive care settings have electrical safety requirements for the protection of hospital staff and patients.
      Of the different classes of electrical equipment listed, which is least likely to cause a patient to suffer a microshock?

      Your Answer:

      Correct Answer: II (CF)

      Explanation:

      Microshock refers to ventricular fibrillation caused by miniscule amounts of currents or voltages (100-150 microamperes) passing through the myocardial tissue from external cables arising from electrical components within the cardiac muscle, for example, pacemaker electrodes or saline filled venous catheters.
      The risk of shock changes with the construction of electrical equipment in question. The main classes of electrical equipment include: I: Appliances have a protective earth connected to an outer casing which prevents live elements from coming in contact with conductive elements. A fault in this equipment class will result in live elements coming in contact with the outer casing and allowing electrical flow into the protective earth. This triggers the protective fuse to disconnect the electric supply to the appliance.
      II: These appliances have reinforced insulation. In the event of a fault which causes the first layer of insulation to fail, the second layer is able to prevent contact of live elements with outer casing.
      III: These appliances have no insulation to provide safety, and rely solely on the use of separated extra low voltage source (SELV) which limits voltage to 25V AC or 60V DC allowing for a person to come in contact with it without risk of a shock under normal dry conditions. Under wet conditions, voltage supply should be lowered to reduce risk of shock. These devices have no risk of macroshocks, but some risk of microshocks.
      Class I and II electrical appliances are further divided into subtypes developed to limit current leakage in the event of a singular fault:
      B (body): Upper limit of current leakage is 500 µA. This current can cause skin tingling and microshocks, but is not sufficient to cause injury.
      BF (body floating): These appliances have an isolating capacitor or transformer which separate the secondary circuit from the protective earth. The upper limit of current leakage is the same as type B.
      CF (cardiac floating): Upper limit of leakage current during a singular fault is 50 microamps. It is least likely to result in a microshock

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 51 - Which of the following lung parameters can be measured directly using spirometry? ...

    Incorrect

    • Which of the following lung parameters can be measured directly using spirometry?

      Your Answer:

      Correct Answer: Vital capacity

      Explanation:

      Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).

      It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.

      During spirometry, the following measurements can be determined:
      Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
      Forced expiratory volume in one second (FEV1)
      FEV1/FVC ratio
      Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
      Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
      Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.

      Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.

      Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution

      The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 52 - Which of the following statements is the most correct about ketamine? ...

    Incorrect

    • Which of the following statements is the most correct about ketamine?

      Your Answer:

      Correct Answer: The S (+) isomer is more potent that the R (-) isomer

      Explanation:

      Ketamine, a phencyclidine derivative, is an antagonist at the NMDA receptor. It causes depression of the CNS that is dose dependent and induces a dissociative anaesthetic state with profound analgesia and amnesia.

      Ketamine has a chiral centre usually presented as a racemic mixture with two optical isomers, S (+) and R (-) forms. These isomers are in equal proportions. The S (+) isomer is about three times more potent than the R (-) form. The S (+) form is less likely to cause emergence delirium and hallucinations.

      Ketamine is extensively metabolised by hepatic microsomal cytochrome P450 enzymes producing norketamine as its main metabolite. Norketamine has a one third to one fifth as potency as its parent compound.
      It increases the CMRO2, cerebral blood flow and potentially increase intracranial pressure.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 53 - During a critical liver resection surgery, a 65-year-old man suffers uncontrolled hepatic bleeding....

    Incorrect

    • During a critical liver resection surgery, a 65-year-old man suffers uncontrolled hepatic bleeding. The 'Pringle manoeuvre is performed to stop the bleeding where the hepatic artery, portal vein, and common bile duct are clamped. These structures form the anterior boundary of the epiploic foramen.

      Which of the following vessels also contributes to the boundary of this region?

      Your Answer:

      Correct Answer: Inferior vena cava

      Explanation:

      The epiploic foramen (foramen of Winslow or aditus to the lesser sac) is found behind the free right border of the lesser omentum. A short, 3 cm slit serves as the entrance to the lesser sac from the greater sac.

      The epiploic foramen has the following boundaries:
      Anteriorly: hepatoduodenal ligament, the bile duct (anteriorly on the right), the hepatic artery (anteriorly on the left), and the portal vein (posteriorly) together with nerves and lymphatics
      Superiorly: the peritoneum of the posterior layer of the hepatoduodenal ligament runs over the caudate process of the liver
      Posteriorly: inferior vena cava
      Floor: upper border of the first part of the duodenum
      The anterior and posterior walls of the foramen are normally
      apposed, which partly explains why patients can develop large fluid
      collections isolated to the greater or lesser sac

      Rapid control of the hepatic artery and portal vein can be obtained by compression of the free edge of the lesser omentum (a ‘Pringle’ manoeuvre), which is a potentially useful technique in liver trauma and surgery.

    • This question is part of the following fields:

      • Anatomy
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  • Question 54 - A 40-year-old woman was diagnosed with hyperparathyroidism. She is undergoing a parathyroidectomy, and...

    Incorrect

    • A 40-year-old woman was diagnosed with hyperparathyroidism. She is undergoing a parathyroidectomy, and during the surgery, the inferior parathyroid gland is found to be enlarged. There is a vessel adjacent to this gland on its lateral side.

      What is this vessel most likely to be?

      Your Answer:

      Correct Answer: Common carotid artery

      Explanation:

      There are four parathyroid glands that lie on the medial half of the posterior surface of each lobe of the thyroid gland, inside its sheath. There are two superior and two inferior parathyroid glands.

      The common carotid artery is a lateral relation of the inferior parathyroid.

    • This question is part of the following fields:

      • Anatomy
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  • Question 55 - Patient’s having disease (Test Positive: 60, Test Negative:40)


    Patient’s not having...

    Incorrect

    • Patient’s having disease (Test Positive: 60, Test Negative:40)


      Patient’s not having the disease (Test Positive:20, Test Negative: 80)

      This is a result of a new tumour marker blood test, that was performed on 200 women for breast cancer screening. The director of the screening programme ask you to evaluate the observations and inform them the specificity of this new test.

      Which one of the following figure you will relay to the programme director?

      Your Answer:

      Correct Answer: 80%

      Explanation:

      The positive predictive value is the ratio of patients truly diagnosed as positive to all those who had positive test results. In this case, this is 60/(60+20)=75%.

      The negative predictive value is the ratio of patients truly diagnosed as negative to all those who had negative test results. In this case, this is 80/(80+40)=67%.

      The sensitivity is the ratio of patients with the disease who test positive i.e. true positive patients to the total number of people with the disease. In this case, this is 60/(60+40)=60%.

      The specificity is the ratio of people who don’t have the disease who test negative i.e. true negatives to the total number of people without the disease. In this case, this is 80/(20+80)=80%.

      70% is not the result of any screening measurements

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 56 - A 72-year-old woman with a medical history of ischaemic heart disease, hypertension, and...

    Incorrect

    • A 72-year-old woman with a medical history of ischaemic heart disease, hypertension, and hypothyroidism was brought to ER with a change in her mental state over the past few hours. Medications used by her were hydrochlorothiazide, aspirin, ramipril, and levothyroxine.

      On physical examination, decreased skin turgor, orthostatic hypotension, and disorientation of time and place were found. There were no significant neurological signs.

      Initial biochemical tests are as follows:

      Na: 111 mmol/L (135-145)
      K: 4.1 mmol/L (3.5-5.1)
      Cl: 105 mmol/L (99-101)
      Bic: 29 mmol/L (22-29)
      Urea: 16.4 mmol/L (1.7-8.3)
      Creatinine: 320µmol/L (44-80)
      Glucose: 13.5mmol/L (3.5-5.5)
      Plasma osmolality: 278mOsm/kg
      Urinary osmolality: 450mOsm/kg
      TSH: 6.2 miu/L (0.1-6.0)
      Free T4: 10.1 pmol/L (10-25)
      Free T3: 1.4nm/L (1.0-2.5)

      Which of the following is most likely cause for this condition of the patient?

      Your Answer:

      Correct Answer: Drug idiosyncrasy

      Explanation:

      Based on the laboratory reports, the patient is suffering from significant hyponatremia. The symptoms of hyponatremia are mainly neurological and depend on the severity and rapidity of onset of hyponatremia.

      Patient symptom according to the hyponatremia level is correlated below:

      125 – 130mmol/L – Nausea and malaise
      115 – 125mmol/L – Headache, lethargy, seizures, and coma
      <120mmol/L - Up to 11% present with coma.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 57 - An 18-year old female was brought into the emergency room because of active...

    Incorrect

    • An 18-year old female was brought into the emergency room because of active seizures. The informant reported that it has been more than 5 minutes since the patient started seizing. The attending physician gave an initial diagnosis of status epilepticus.

      According to the paramedics who brought in the patient, 10 mg of diazepam was given rectally. Upon physical examination, she was normotensive at 120/80 mmHg; tachycardic at 138 beats per minute; tachypnoeic at 24 breaths per minute; and well-saturated at 99% on high flow oxygen. Her random blood glucose level was normal at 7.0 mmol/L.

      Given this situation and an initial diagnosis of status epilepticus, what would be the best initial anti-epileptic drug to administer to the patient?

      Your Answer:

      Correct Answer: Lorazepam

      Explanation:

      Lorazepam is an intermediate-acting benzodiazepine that binds to the GABA-A receptor subunit to increase the frequency of chloride channel opening and facilitate membrane hyperpolarization. It is the preferred treatment for status epilepticus, although Diazepam can also be used as an alternative.

      Lorazepam has a longer duration of action than Diazepam, and binds with greater affinity to the GABA-A receptor subunit.

      Phenobarbital is a barbiturate that acts on the GABA-A receptor site to increase the duration of chloride channel opening. Barbiturates, particularly phenobarbital, is considered the drug of choice for seizures in infants.

      Phenytoin is a sodium-channel blocker that is given for generalized tonic-clonic seizures, partial seizures, and status epilepticus. Phenytoin is preferred in prolonged therapy for status epilepticus because it is less sedating.

      Propofol or thiopentone is preferred when airway protection is required.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 58 - A 33-year-old woman known to be hypothyroid and taking 150 mcg l-thyroxine daily...

    Incorrect

    • A 33-year-old woman known to be hypothyroid and taking 150 mcg l-thyroxine daily is reviewed in the preoperative assessment clinic prior to a laparoscopic cholecystectomy.

      She has required three increases in her thyroid replacement therapy in the last six months.

      Her thyroid function tests are as follows:

      TSH 11 (normal range 0.4-4mU/L)
      T3 20 (normal range 9-25mU/L)
      T4 6.2 (normal range 3.5-7.8mU/L)

      What will explain this biochemical picture?

      Your Answer:

      Correct Answer: Poor compliance with medication

      Explanation:

      In patients with an intact hypothalamic-pituitary axis, serial TSH measurements are used to determine the adequacy of treatment with thyroid hormones . changes in TSH levels becoming apparent after approximately eight weeks of therapy with thyroid hormone replacement. Change in T3/T4 levels are seen before changes in TSH .

      In patients taking thyroid replacement therapy, the most frequent reason for persistent elevation of serum TSH is poor compliance. Patients who do not regularly take their L-thyroxine try and catch up just before a visit to a clinician for blood test.

      Tissue-level unresponsiveness to thyroid hormone is caused by mutation in the gene controlling a receptor for T3 and is rare.

      Reduced responsiveness of target tissues to thyroid hormone aka resistance to thyroid hormones (rTH) occurs when there is a mutation in the thyroid hormone receptor ? gene. It is a rare autosomal dominant inherited syndrome of reduced end-organ responsiveness to thyroid hormone and has two types:

      Generalised resistance (GrTH)
      Pituitary resistance (PrTH)

      Patients with rTH have normal or slightly elevated serum thyroid stimulating hormone (TSH) level, elevated serum free thyroxine (FT4) and free triiodothyronine (FT3) concentrations.

      Drugs that increase metabolism of thyroxine include:

      Warfarin
      Rifampin
      Phenytoin
      Phenobarbital
      St John’s Wort
      Carbamazepine

      These drugs lower circulating thyroid hormones and would be associated with a raised TSH but low T3/T4.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 59 - A patient is evaluated for persistent dysphonia six months after undergoing a subtotal...

    Incorrect

    • A patient is evaluated for persistent dysphonia six months after undergoing a subtotal thyroidectomy.

      Which of the following is the most likely reason for the change in this patient's voice?

      Your Answer:

      Correct Answer: Damage to recurrent laryngeal nerve

      Explanation:

      After thyroid surgery, about 10-15% of patients experience a temporary subjective voice change of varying degrees. A frog in the throat or cracking of the voice, or a weak voice, are common descriptions. These modifications are only temporary, lasting a few days to a few weeks.

      Swelling of the muscles in the area of the dissection, as well as inflammation and oedema of the larynx due to the dissection, or minor trauma from the tracheal tube, are all suspected causes.

      On both sides of the thyroid gland, the superior laryngeal nerve (EBSLN) runs along the upper part. The muscles that fine-tune the vocal cords are innervated by these nerves. The quality of their voice is usually normal if they are injured, but making high-pitched sounds may be difficult. Injury to the EBSLN occurs in about 2% of the population.

      Injuries to the recurrent laryngeal nerve (RLN) have been reported to occur in 1 percent to 14 percent of people. Except for the cricothyroid muscle, the RLN supplies all of the laryngeal intrinsic muscles.

      This complication is usually unilateral and temporary, but it can also be bilateral and permanent, and it can be intentional or unintentional. The most common complication following thyroid surgery is a permanent lesion of damaged RLN, which manifests as an irreversible phonation dysfunction.

      The crico-arytenoid joint dislocation is a relatively uncommon complication of tracheal intubation and blunt neck trauma. The probability is less than one in a thousand.

      Vocal cord polyps affect 0.8 percent of people.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 60 - A weakly acidic drug with a pKa of 8.4 is injected intravenously into...

    Incorrect

    • A weakly acidic drug with a pKa of 8.4 is injected intravenously into a patient.

      At a normal physiological pH, the percentage of this drug unionised in the plasma is?

      Your Answer:

      Correct Answer: 90

      Explanation:

      Primary FRCA is concerned with two issues. The first is a working knowledge of the Henderson-Hasselbalch equation, and the second is a working knowledge of logarithms and antilogarithms.

      The pH at which the drug exists in 50 percent ionised and 50 percent unionised forms is known as the pKa.

      To calculate the proportion of ionised to unionised form of a drug, use the Henderson-Hasselbalch equation.

      pH = pKa + log ([A-]/[HA])

      or

      pH = pKa + log [(salt)/(acid)]
      pH = pKa + log ([ionised]/[unionised])

      Hence, if the pKa − pH = 0, then 50% of drug is ionised and 50% is unionised.

      In this example:
      7.4 = 8.4 + log ([ionised]/[unionised])
      7.4 − 8.4 = log ([ionised]/[unionised])
      log −1 = log ([ionised]/[unionised])

      Simply put, the antilog is the inverse log calculation. In other words, if you know the logarithm of a number, you can use the antilog to find the value of the number. The antilogarithm’s definition is as follows:

      y = antilog x = 10x

      Antilog to the base 10 of 0 = 1, −1 = 0.1, −2 = 0.01, −3 = 0.001 and, −4 = 0.0001.

      [A-]/[HA] = 0.1

      Assuming that we can apply the approximation [A-] << [HA} then this means the acid is 0.1 x 100% = 10% ionised so the percentage of (non-ionized) acid will be 100% – 10% = 90%

    • This question is part of the following fields:

      • Pharmacology
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  • Question 61 - A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath...

    Incorrect

    • A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath and pleuritic chest pain. Her work requires her to travel internationally frequently. The consultant makes a diagnosis and treats her.

      Now, the consultant recommends placing a filter that will prevent future incidents. A needle is placed into the femoral vein and passed up into the abdomen to insert the filter.

      What is true regarding the organ where the filter is placed for this patient's condition?

      Your Answer:

      Correct Answer: It is located posteriorly to the peritoneum

      Explanation:

      The patient likely suffers from pulmonary embolism due to her history of frequent international travels. A filter is placed in the inferior vena cava to decrease the risk of future episodes of pulmonary embolism. The IVC filter is a small, wiry device that can catch blood clots and stop them from going into the heart and lungs. Your IVC is a major vessel that brings deoxygenated blood from the lower body to the heart, from where it is pumped into the lungs.

      The filter is placed via a thin catheter inserted into the femoral vein in the groin. The catheter is gently moved up into your IVC, and a filter is introduced.

      The IVC is a retroperitoneal organ.

    • This question is part of the following fields:

      • Anatomy
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  • Question 62 - Under general anaesthesia, a 48-year-old patient is scheduled for some dental extractions. He...

    Incorrect

    • Under general anaesthesia, a 48-year-old patient is scheduled for some dental extractions. He tells you that he has a heart murmur and that he has always received antibiotic prophylaxis at the dentist. There are no allergies that he is aware of.

      Which antibiotic prophylaxis strategy is most appropriate for this patient?

      Your Answer:

      Correct Answer: Prophylactic antibiotics are unnecessary for this patient

      Explanation:

      The National Institute for Health and Care Excellence (NICE) has published guidelines on infective endocarditis prophylaxis (IE). The goal was to create clear guidelines for antibiotic prophylaxis in patients undergoing dental procedures as well as certain non-dental interventional procedures. A number of studies have found an inconsistent link between recent interventional procedures and the development of infective endocarditis in both dental and non-dental procedures.

      Antibiotic prophylaxis against infective endocarditis is not advised or required in the following situations:

      Dental patients undergoing procedures
      Patients undergoing procedures involving the upper and lower gastrointestinal tracts, the genitourinary tract (including urological, gynaecological, and obstetric procedures, as well as childbirth), and the upper and lower respiratory tract (including ear, nose and throat procedures and bronchoscopy).

      Antibiotic resistance can be exacerbated by the indiscriminate use of prophylactic antibiotics, but this is not the primary reason for avoiding their use in these situations.

      To reduce the risk of endocarditis, any patient who is at risk of developing IE should be investigated and treated as soon as possible. Patients with the following conditions are at risk of developing IE:
      acquired valvular heart disease with regurgitation or stenosis
      previous valve replacement
      structural congenital heart disease
      past history of IE, or
      hypertrophic cardiomyopathy (HOCM)

      It would also be appropriate for high-risk dental procedures and those with severe gingival disease.

      Although this patient may not have structural heart disease, ABs should be administered on a case-by-case basis.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 63 - Substitution at different positions of the barbituric ring give rise to different pharmacologic...

    Incorrect

    • Substitution at different positions of the barbituric ring give rise to different pharmacologic properties.

      Substitution with and at which specific site of the ring affects lipid solubility the most?

      Your Answer:

      Correct Answer: Sulphur atom at position 2

      Explanation:

      Barbiturates are derived from barbituric acid, which itself is nondepressant, but appropriate side-chain substitutions result in CNS depressant activity that varies in potency and duration with carbon chain length, branching, and saturation.

      Oxybarbiturates retain an oxygen atom on number 2-carbon atom of the barbituric acid ring.

      Thiobarbiturates replace this oxygen atom with a sulphur atom, which confers greater lipid solubility. Generally speaking, a substitution such as sulphuration that increases lipid solubility is associated with greater hypnotic potency and more rapid onset, but shorter duration of action.

      Addition of a methyl group to the nitrogen atom of the barbituric acid ring, as with oxybarbiturate methohexital, also results in a compound with a short duration of action.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 64 - A 49-year-old female has presented to her physician with complaints of a lump...

    Incorrect

    • A 49-year-old female has presented to her physician with complaints of a lump in her groin area. The lump is painless and is more prominent in coughing.
      On examination, the lump's location is inferior and lateral to the pubic tubercle. This points towards the diagnosis of femoral hernia, where part of her intestines has entered the femoral canal, causing a bulge in the femoral triangle. The femoral triangle is an anatomical region in the upper thigh.

      Name the structures found in the femoral triangle, laterally to medially.

      Your Answer:

      Correct Answer: Femoral nerve, femoral artery, femoral vein, empty space, lymphatics

      Explanation:

      The femoral triangle is a wedge-shaped area found within the superomedial aspect of the anterior thigh. It is a passageway for structures to leave and enter the anterior thigh.

      Superior: Inguinal ligament
      Medial: Adductor longus
      Lateral: Sartorius
      Floor: Iliopsoas, adductor longus and pectineus

      The contents include: (medial to lateral)
      Femoral vein
      Femoral artery-pulse palpated at the mid inguinal point
      Femoral nerve
      Deep and superficial inguinal lymph nodes
      Lateral cutaneous nerve
      Great saphenous vein
      Femoral branch of the genitofemoral nerve

    • This question is part of the following fields:

      • Anatomy
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  • Question 65 - When describing the surface anatomy of the sacrum, which of the following anatomical...

    Incorrect

    • When describing the surface anatomy of the sacrum, which of the following anatomical landmarks refers to the base of an equilateral triangle is formed by the sacral hiatus?

      Your Answer:

      Correct Answer: A line connecting the posterior superior iliac spines

      Explanation:

      The apex of an equilateral triangle completed by the posterior superior iliac spines is where the sacral hiatus or sacrococcygeal membrane can normally located. The failure of posterior fusion of the laminae of the fourth and fifth sacral vertebrae allows the sacral canal to be accessible via the membrane.

      In adults, the spine of L4 usually lies on a line drawn between the highest points of the iliac crests (Tuffier’s line). A line connecting each anterior iliac spine, approximates to the L3/4 interspace in the sitting position. Both of these options are incorrect.

      A line connecting the greater trochanters is also incorrect.

      A line connecting the posterior superior iliac spines is correct, but in adults the presence of a sacral fat pad can still make identification of this landmark less straightforward.

      The processes of S5 are remnants only and form the sacral cornua, which are also used to help identify the sacral hiatus.

    • This question is part of the following fields:

      • Anatomy
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  • Question 66 - An 82-year-old male has severe abdominal pain that is out of proportion to...

    Incorrect

    • An 82-year-old male has severe abdominal pain that is out of proportion to the examination. He is a known case of atrial fibrillation and diverticulitis. Suspecting mesenteric ischemia, he was thoroughly investigated, and a mesenteric angiography shows ischemia of the left colic flexure.

      Which artery gives off branches that supply this region directly?

      Your Answer:

      Correct Answer: Inferior mesenteric artery (IMA)

      Explanation:

      Mesenteric ischemia is ischemia of the blood vessels of the intestines. It can be life-threatening, especially if the small intestine is involved.

      The inferior mesenteric artery originates 3-4 cm above the bifurcation of the abdominal aorta.
      The left colic artery branches off the inferior mesenteric artery to supply the following:
      – distal 1/3 of the transverse colon
      – descending colon

      At approximately the left colic flexure (splenic flexure), a transition occurs in the blood supply of the GI tract. The SMA supplies the proximal part to the flexure, and the IMA supplies the part distal to the flexure. This is why the left colic flexure is a watershed area and is prone to ischemia exacerbated by atherosclerotic changes or hypotension. The dominant arterial supply of the splenic flexure is usually from the left colic artery, but it may also get collaterals from the left branch of the middle colic artery.

      The AMA and PMA do not exist.
      The splenic artery directly supplies the spleen and has branches that supply the stomach and the pancreas.
      The proximal two-thirds of the transverse colon is supplied by the middle colic artery, a branch of the SMA.

    • This question is part of the following fields:

      • Anatomy
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  • Question 67 - Which drug, if given to a pregnant woman, can lead to deleterious fetal...

    Incorrect

    • Which drug, if given to a pregnant woman, can lead to deleterious fetal effects due to its ability to cross the placenta?

      Your Answer:

      Correct Answer: Atropine

      Explanation:

      It is well known that atropine will cross the placenta and that maternal administration results in an increase in fetal heart rate.

      Atropine is highly selective for muscarinic receptors. Its potency at nicotinic receptors is much lower, and actions at non-muscarinic receptors are generally undetectable clinically. Atropine does not distinguish among the M1, M2, and M3 subgroups of muscarinic receptors. In contrast, other antimuscarinic drugs are moderately selective for one or another of these subgroups. Most synthetic antimuscarinic drugs are considerably less selective than atropine in interactions with nonmuscarinic receptors.

      A study on glycopyrrolate, a quaternary ammonium salt, was found to have a fetal: maternal serum concentration ratio of 0.4 indicating partial transfer.

      Heparin, suxamethonium, and vecuronium do not cross the placenta.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 68 - At which of the following location is there no physiological oesophageal constriction? ...

    Incorrect

    • At which of the following location is there no physiological oesophageal constriction?

      Your Answer:

      Correct Answer: Lower oesophageal sphincter

      Explanation:

      The oesophagus is a muscular tube that connects the pharynx to the stomach. It begins at the lower border of the cricoid cartilage and C6 vertebra. It ends at T11.

      The oesophagus has physiological constrictions at the following levels:
      1. Cervical constriction: Pharyngo-oesophageal junction (15 cm from the incisor teeth) produced by the cricopharyngeal part of the inferior pharyngeal constrictor muscle
      2. Thoracic constrictions:
      i. where the oesophagus is first crossed by the arch of the aorta (22.5 cm from the incisor teeth)
      ii. where the oesophagus is crossed by the left main bronchus (27.5 cm from the incisor teeth)
      3. Diaphragmatic constriction: where the oesophagus passes through the oesophageal hiatus of the diaphragm (40 cm from the incisor teeth)

      Awareness of these constrictions is important for clinical purposes when it is required to pass instruments through the oesophagus into the stomach or when viewing radiographs of patients’ oesophagus.

    • This question is part of the following fields:

      • Anatomy
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  • Question 69 - A 240 volt alternating current (AC) socket from a wall is used to...

    Incorrect

    • A 240 volt alternating current (AC) socket from a wall is used to charge a direct current (DC) cardiac defibrillator.

      Name the electrical component that converts AC to DC.

      Your Answer:

      Correct Answer: Rectifier

      Explanation:

      There are two types of defibrillators
      AC defibrillator
      DC defibrillator

      AC defibrillator,
      consists of a step-up transformer with primary and secondary winding and two switches. Since secondary coil consists of more turns of wire than the primary coil, it induces larger voltage. A voltage value ranging between 250V to 750V is applied for AC external defibrillator. And used to enable the charging of a capacitor.

      DC defibrillator,
      consists of auto transformer T1 that acts as primary of the high voltage transformer T2. Is an iron core that transfers energy between 2 circuits by electromagnetic induction. Transformers are used to isolate circuits, change impedance and alter voltage output. transformers do not convert AC to DC.

      Diode rectifier composed of 4 diodes made of semiconductor material allows current to flow only in one direction. Alternating current (AC) passing through these diodes produces direct current (DC). Capacitor stores the charge in the form of an electrostatic field.

      Capacitor is used to convert the rectified AC voltage to produce DC voltage but capacitors do not directly convert AC to DC.

      Inductor induces a counter electromotive force(emf) that reduces the capacitor discharge value.

      In step-down transformer primary coils has more turns of wire than secondary coil, so induced voltage is smaller in the secondary coil.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 70 - A 27-year-old woman is admitted to the emergency room with an ectopic pregnancy...

    Incorrect

    • A 27-year-old woman is admitted to the emergency room with an ectopic pregnancy that has ruptured.

      The following is a description of the clinical examination:

      Anxious
      Capillary refill time of 3 seconds
      Cool peripheries
      Pulse 120 beats per minute
      Blood pressure 120/95 mmHg
      Respiratory rate 22 breaths per minute.

      Which of the following is the most likely explanation for these clinical findings?

      Your Answer:

      Correct Answer: Reduction in blood volume of 15-30%

      Explanation:

      The following is the Advanced Trauma Life Support (ATLS) classification of haemorrhagic shock:

      Class I haemorrhage:
      It has blood loss up to 15%. There is very less tachycardia, and no changes in blood pressure, RR or pulse pressure. Usually, fluid replacement is not required.

      Class II haemorrhage:
      It has 15-30% blood loss, equivalent to 750 – 1500 ml. There is tachycardia, tachypnoea and a decrease in pulse pressure. Patient may be frightened, hostile and anxious. It can be stabilised by crystalloid and blood transfusion.

      Class III haemorrhage:
      There is 30-40% blood loss. It portrays inadequate perfusion, marked tachycardia, tachypnoea, altered mental state and fall in systolic pressure. It requires blood transfusion.

      Class IV haemorrhage:
      There is > 40% blood volume loss. It is a preterminal event, and the patient will die in minutes. It portrays tachycardia, significant depression in systolic pressure and pulse pressure, altered mental state, and cold clammy skin. There is need for rapid transfusion and surgical intervention.

    • This question is part of the following fields:

      • Physiology
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  • Question 71 - A 19-year-old woman presents to the emergency department. She complains of symptoms indicative...

    Incorrect

    • A 19-year-old woman presents to the emergency department. She complains of symptoms indicative of an acute exacerbation of known 'brittle' asthma. On history, she reveals her asthma is normally controlled using inhalers and she has never had an acute exacerbation requiring hospitalisation.

      On her admission into the ICU, further examination and diagnostic investigations are conducted. Her readings are:

      Physical state: Alert, anxious and non-cyanotic.
      Respiratory rate: 30 breaths/min
      Pulse: 120 beats/min
      Blood pressure: 150/90 mmHg
      SPO2: 95% on air
      Auscultation: Quiet breath sounds at both lung bases

      What is the next most important step of investigation?

      Your Answer:

      Correct Answer: Peak expiratory flow rate

      Explanation:

      Peak expiratory flow rate (PEFR) is the maximum speed of air flow generated during a single forced exhaled breath. It is most useful when expressed as a percentage of the best value obtained from the patient.

      Forced expiratory volume over 1 second (FEV1) is a lung parameter measured using spirometry. It is the amount of air forced out of the lung in one exhaled breath. It is a more accurate measure of lung obstructions as it doesn’t rely on effort like PEFR

      PEFR and FEV1 are usually similar, but become more different in asthmatic patients as airflow becomes increasingly obstructed.

      Acute severe asthma is most often diagnosed on history taking and examinations:

      Respiratory rate: >25 breaths/min
      Heart rate: >110 beats/min
      PEFR: 33 – 50% predicted (<200L/min)
      Patient state: Unable to complete a sentence in a single breath.

      A chest x-ray is not routinely required, and is only indicated in specific circumstances, which are:

      If a pneumomediastinum or pneumothorax is suspected
      Possible life threatening asthma
      Possible consolidation
      Unresponsive asthma
      If ventilation is required.

      An echocardiograph (ECG) is not necessary in this case

      Routine haematological and biochemical investigations are not urgent in this case as any abnormalities they detect will be secondary to the patient’s presentation.

      An arterial blood gas (ABG) will only be indicated if SPO2 was <92% or if patient presented with life threatening symptoms.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 72 - A 25-year old male with palpitations and dizziness presents to the emergency room....

    Incorrect

    • A 25-year old male with palpitations and dizziness presents to the emergency room. In the triage process, cardiac monitoring shows supraventricular tachycardia with a heart rate of 200 beats per minute. This high heart rate arises as a result of different specialised cells and nerve fibres in the heart which are responsible for conducting that action potential which is generated in the event of systole.
      The fastest conduction velocity is carried out by which of the following?

      Your Answer:

      Correct Answer: Purkinje fibres

      Explanation:

      The correct answer is the Purkinje fibres, which conducts at a velocity of about 4m/sec.

      The electrical conduction system of the heart starts with the SA node which generates spontaneous action potentials.

      This is conducted across both atria by cell to cell conduction, and occurs at around 1 m/s. The only pathway for the action potential to enter the ventricles is through the AV node in a normal heart.
      At this site, conduction is very slow at 0.05ms, which allows for the atria to completely contract and fill the ventricles with blood before the ventricles depolarise and contract.

      The action potentials are conducted through the Bundle of His from the AV node which then splits into the left and right bundle branches. This conduction is very fast, (,2m/s), and brings the action potential to the Purkinje fibres.

      Purkinje fibres are specialised conducting cells which allow for a faster conduction speed of the action potential (,2-4m/s). This allows for a strong synchronized contraction from the ventricle and thus efficient generation of pressure in systole.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 73 - All of the following statements about dopamine are FALSE except: ...

    Incorrect

    • All of the following statements about dopamine are FALSE except:

      Your Answer:

      Correct Answer:

      Explanation:

      Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic ? and ?1 (but not ?2 )agonist.

      The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of DA dilates these vessels (by raising intracellular cyclic adenosine monophosphate).

      Moderately high doses produce a positive inotropic (direct ?1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.

      Vasoconstriction (?1 action) occurs only when large doses are infused.

      At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier – no Central nervous system effects.

      Dopamine is less arrhythmogenic than adrenaline

      Regarding dopamine part of the dose is converted to Noradrenaline in sympathetic nerve terminals.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 74 - Which of the following drugs would cause the most clinical concern if accidentally...

    Incorrect

    • Which of the following drugs would cause the most clinical concern if accidentally administered intravenously to a 4-year-old boy?

      Your Answer:

      Correct Answer: 20 mg codeine

      Explanation:

      To begin, one must determine the child’s approximate weight. There are a variety of formulas to choose from. It is acceptable to use the advanced paediatric life support formula:

      (age + 4) 2 = weight

      A 5-year-old child will weigh around 18 kilogrammes.

      The following are the appropriate doses of the drugs listed above:

      Gentamicin (once daily) – 5-7 mg/kg = 90-126 mg and subsequent dose modified according to plasma levels
      Ondansetron – 0.1 mg/kg, but a maximum of 4 mg as a single dose = 1.8 mg
      Codeine should be administered orally at a dose of 1 mg/kg rather than intravenously, as the latter can cause ‘dangerous’ hypotension due to histamine release.
      15 mg/kg paracetamol = 270 mg orally or intravenously (a loading dose of 20 mg/kg, or 360 mg, is sometimes recommended, which is not far short of the doses listed above).
      Cefuroxime – the initial intravenous dose is 20 mg/kg (360 mg) depending on the indication (again, similar to the dose given in the answer options above).

    • This question is part of the following fields:

      • Pharmacology
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  • Question 75 - A peripheral nerve stimulator is used to stimulate the ulnar nerve at the...

    Incorrect

    • A peripheral nerve stimulator is used to stimulate the ulnar nerve at the wrist to indicate the degree of neuromuscular blockade.

      Which single muscle or group of muscles of the hand supplied by the ulnar nerve is best for monitoring the twitch function during neuromuscular blockade?

      Your Answer:

      Correct Answer: Adductor pollicis

      Explanation:

      In anaesthesia, adductor pollicis neuromuscular monitoring with ulnar nerve stimulation is commonly used. It is the gold standard for measuring the degree of block and comparing neuromuscular blocking drugs and their effects on other muscles.

      Electrodes are usually placed over the ulnar nerve at the wrist to monitor the adductor pollicis.

      Neuromuscular blocking drugs have different sensitivity levels in different muscle groups.

      To achieve the same level of blockade, the diaphragm requires 1.4 to 2 times the amount of neuromuscular blocking agent as the adductor pollicis muscle. The small muscles of the larynx and the ocular muscles are two other respiratory muscles that are less resistant than the diaphragm (especially corrugator supercilii).

      The abdominal muscles, Orbicularis oculi, peripheral muscles of the limbs, Geniohyoid, Masseter, and Upper airway muscles are the most sensitive to neuromuscular blocking agents.

      The C8-T1 nerve roots, which are part of the medial cord of the brachial plexus, form the ulnar nerve. It enters the hand via the ulnar canal, superficial to the flexor retinaculum, after following the ulnar artery at the wrist.

      The nerve then splits into two branches: superficial and deep. The palmaris brevis is supplied by the superficial branch, which also provides palmar digital nerves to one and a half fingers. The dorsal surface of the medial/ulnar 1.5 fingers, as well as the corresponding skin over the hand, are also supplied by it (as well as the palmar surface).

      The ulnar nerve’s deep branch runs between the abductor and flexor digiti minimi, which it supplies. It also innervates the opponens, and with the deep palmar arch, it curves around the hook of the hamate and laterally across the palm. All of the interossei, the medial two lumbricals, the adductor pollicis, and, in most cases, the flexor pollicis brevis are supplied there.

    • This question is part of the following fields:

      • Anatomy
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  • Question 76 - Radical prostatectomy is being performed on a 60-year-old man for carcinoma of the...

    Incorrect

    • Radical prostatectomy is being performed on a 60-year-old man for carcinoma of the prostate gland.

      What is the direct blood supply of the prostate?

      Your Answer:

      Correct Answer: Inferior vesical artery

      Explanation:

      The prostate gland is primarily supplied by the inferior vesical artery, which branches off from the anterior division of the internal iliac artery. The inferior vesical artery supplies the base of the bladder, the distal ureters, and the prostate. The branches to the prostate communicate with the corresponding vessels of the opposite side.

      The inferior vesical artery branches into two main arteries:
      1. Urethral artery – supplies the transition zone and is the main arterial supply for the adenomas in BPH
      2. Capsular artery – supplies the glandular tissue

      The venous drainage of the prostate is from the prostatic venous plexus, which drains into the paravertebral veins.

    • This question is part of the following fields:

      • Anatomy
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  • Question 77 - Which of the following statements is true about data analysed from a new...

    Incorrect

    • Which of the following statements is true about data analysed from a new drug trial?

      Your Answer:

      Correct Answer: The data could be evaluated using the chi square test

      Explanation:

      The data is ideal for chi square test evaluation as it will help determine if observed outcomes are in line with expected outcomes, and also if results are significant or due to chance.

      The student’s t test is not ideal as it requires comparison of means from different populations, rather than proportions.

      Pearson’s coefficient of linear regression is not ideal as it requires the plotting of a linear regression.

      The numbers should be analysed before determining if there are any statistical conclusions that can be drawn from the population.

      Statistical analysis is always required to determine the performance of any treatment during a clinical drug trial. Conclusions cannot be drawn simply by looking at the data.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 78 - Which of the following statements is true regarding sucralfate? ...

    Incorrect

    • Which of the following statements is true regarding sucralfate?

      Your Answer:

      Correct Answer:

      Explanation:

      Sucralfate is an octasulfate of glucose to which Al(OH)3 has been added. It undergoes extensive cross-linking in an acidic environment and forms a polymer which adheres to the ulcer base for up to 6 hours and protects it from further erosion. Since it is not systemically absorbed it is virtually devoid of side effects. However, it may cause constipation in about 2% of cases due to the Aluminium component in it.

      Sucralfate does not have antibacterial action against Helicobacter pylori. However, Bismuth has antibacterial action due to its oligodynamic effect.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 79 - A 64-year old lady has been diagnosed with hypertension. Her GP explains how...

    Incorrect

    • A 64-year old lady has been diagnosed with hypertension. Her GP explains how this occurs, and that blood pressure is determined by multiple factors which include action by the heart, nervous system and the diameter of the blood vessels. This lady's cardiac output (CO) is 4L/min. Her exam today revealed a mean arterial pressure (MAP) of 140 mmHg.
      Using these values, her systemic vascular resistance (SVR) is which of these?

      Your Answer:

      Correct Answer: 35mmHgâ‹…minâ‹…mL-1

      Explanation:

      Impaired ventricular relaxation reduces diastolic filling and therefore preload.

      Decreased blood volume decreases preload due to reduced venous return.

      Heart failure is characterized by reduced ejection fraction and therefore stroke volume.

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure (is increased by stroke volume) = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume
      Aortic stenosis would decrease stroke volume as end systolic volume would increase.
      This is because of an increase in afterload, an increase in resistance that the heart must pump against due to a hard stenotic valve.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 80 - What can you see within the tunica media of a blood vessel on...

    Incorrect

    • What can you see within the tunica media of a blood vessel on examination?

      Your Answer:

      Correct Answer: Smooth muscle

      Explanation:

      The blood vessel well is divided into 3 parts, namely:

      The tunica intima, which is the deepest layer. It contains endothelial cells separated by gap junctions

      The tunica media, primarily consisting of the involuntary smooth muscle fibres, laid out in spiral layers with elastic fibres and connective tissue.

      The tunica adventitia, which is the most superficial layer. It consists of the vasa vasorum, fibroblast and collagen.

    • This question is part of the following fields:

      • Anatomy
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  • Question 81 - About the mechanism of action of bendroflumethiazide, Which of the following is correct?...

    Incorrect

    • About the mechanism of action of bendroflumethiazide, Which of the following is correct?

      Your Answer:

      Correct Answer: Sodium-chloride symporter inhibitor

      Explanation:

      Sodium-chloride symporter inhibitor.

      The thiazide sensitive sodium chloride symporter is inhibited by thiazides at the proximal portion of the distal convoluted tubule leading to increased sodium and water excretion. Increased delivery of sodium to the distal portion of the distal convoluted tubule promotes potassium loss. This is why thiazides are associated with hyponatraemia and hypokalaemia.

      Carbonic anhydrase inhibitors are used mainly in the treatment of glaucoma. They act on the proximal convoluted tubule to promote bicarbonate, sodium and potassium loss.

      Sodium potassium chloride symporter is inhibited by Loop diuretics.
      Epithelial sodium channels are inhibited by Amiloride.
      Drugs which lead to nephrogenic diabetes insipidus such as lithium and demeclocycline, are Inhibitors of vasopressin.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 82 - A 58-year-old man is being operated on for a radical gastrectomy for carcinoma...

    Incorrect

    • A 58-year-old man is being operated on for a radical gastrectomy for carcinoma of the stomach.

      Which structure needs to be divided to gain access to the coeliac axis?

      Your Answer:

      Correct Answer: Lesser omentum

      Explanation:

      The lesser omentum will need to be divided. This forms one of the nodal stations that will need to be taken during a radical gastrectomy.

      The celiac axis is the first branch of the abdominal aorta and supplies the entire foregut (mouth to the major duodenal papilla). It arises at the level of vertebra T12. It has three major branches:
      1. Left gastric
      2. Common hepatic
      3. Splenic arteries

    • This question is part of the following fields:

      • Anatomy
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  • Question 83 - During the design phase of a study, which among the given is aimed...

    Incorrect

    • During the design phase of a study, which among the given is aimed at addressing confounding factors?

      Your Answer:

      Correct Answer: Randomisation

      Explanation:

      Randomisation allows for performance of experimental trials in a random order. Using this method gives us control over the confounding variables that are not supposed to be held constant.

      For an instance, by employing randomisation we get to control biological differences among individual human beings during experimental trials.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 84 - Which among the given choices can be used to describe a persistent and...

    Incorrect

    • Which among the given choices can be used to describe a persistent and expected level of disease in a particular population?

      Your Answer:

      Correct Answer: Endemic

      Explanation:

      Phase 0 trials assist the scientists in studying the behaviour of drugs in humans by micro dosing patients. They are used to speed up the developmental process. They have no measurable therapeutic effect and efficiency.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 85 - In endurance athletes, which of the following physiological adaptations to exercise is the...

    Incorrect

    • In endurance athletes, which of the following physiological adaptations to exercise is the best predictor of performance?

      Your Answer:

      Correct Answer: Velocity of blood lactate accumulation

      Explanation:

      Multiple regression analysis revealed that velocity of lactate accumulation (VOBLA) accounted for 92 percent of the variation in marathon running velocity (VM), and VOBLA plus training volume prior to the marathon accounted for 96 percent of the variation. Percent ST muscle fibre distribution (r = 0.55-0.69) and capillary density (r = 052-0.63) were found to be positively correlated with all performance variables. As a result, marathon running performance was linked to VOBLA and the ability to run at a pace close to it during the race. The percent ST, capillary density, and training volume were all related to these properties.

      Another metabolic adaptation compared to normal people is the early selection of fat for oxidation by muscle, especially when glucose availability is limited during high-intensity exercise. This helps to delay the onset of muscle fatigue, but it does not prevent VOBLA.

      For a given level of exercise, training can also result in cardiovascular adaptation, such as increased heart size, increased contractility, and a slower heart rate. All of these factors contribute to an increase in maximal oxygen consumption (VO2 max), but genetic factors, despite intensive training, play a large role in an athlete’s performance.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 86 - Which statement is true with regards to the cardiac action potential? ...

    Incorrect

    • Which statement is true with regards to the cardiac action potential?

      Your Answer:

      Correct Answer: Repolarization due to potassium efflux after calcium channels close causes the relative refractory period to start

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 87 - Which of the following statements is true with regards to the Krebs' cycle...

    Incorrect

    • Which of the following statements is true with regards to the Krebs' cycle (also known as the tricarboxylic acid cycle or citric acid cycle)?

      Your Answer:

      Correct Answer: Alpha-ketoglutarate is a five carbon molecule

      Explanation:

      Krebs’ cycle (tricarboxylic acid cycle or citric acid cycle) is a sequence of reactions in which acetyl coenzyme A (acetyl-CoA) is metabolised and this results in carbon dioxide and hydrogen atoms production.

      This series of reactions occur in the mitochondria of eukaryotic cells, not the cytoplasm. The cycle requires oxygen and so, cannot function under anaerobic conditions.

      It is the common pathway for carbohydrate, fat and some amino acids oxidation and is required for high energy phosphate bond formation in adenosine triphosphate (ATP).

      When pyruvate enters the mitochondria, it is converted into acetyl-CoA. This represents the formation of a 2 carbon molecule from a 3 carbon molecule. There is loss of one CO2 but formation of one NADH molecule. Acetyl-CoA is condensed with oxaloacetate, the anion of a 4 carbon acid, to form citrate which is a 6 carbon molecule.

      Citrate is then converted into isocitrate, alpha-ketoglutarate, succinyl-CoA, succinate, fumarate, malate and finally oxaloacetate.

      The only 5 carbon molecule in the cycle is alpha-ketoglutarate.

    • This question is part of the following fields:

      • Physiology
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  • Question 88 - A 65-year-old man, presents to the emergency department. He explains that an hour...

    Incorrect

    • A 65-year-old man, presents to the emergency department. He explains that an hour ago, he experienced central chest pain, which moved down his left arm.
      On ECG, elevation in the ST-segment was noted in the anterior leads. He undergoes emergency percutaneous coronary intervention (PCI) which requires the cardiologist to access the heart via the femoral artery.

      Where is the surface marking for identifying the femoral artery?

      Your Answer:

      Correct Answer: Midway between the ASIS and the pubic symphysis

      Explanation:

      The surface marking for locating the femoral artery is the mid-inguinal point, which is the halfway point between the anterior superior iliac spine (ASIS) and the pubic symphysis.

      The other mentioned options are not specific for any landmark.

      However, it is important to note the difference between the mid inguinal point and the midpoint of the inguinal ligament, which is travels from the ASIS to the pubic tubercle.

    • This question is part of the following fields:

      • Anatomy
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  • Question 89 - A 89-year old male has hypertension, with a blood pressure of 170/68 mmHg...

    Incorrect

    • A 89-year old male has hypertension, with a blood pressure of 170/68 mmHg and has been admitted to the hospital. He is on no regular medications. His large pulse pressure can be accounted for by which of the following?

      Your Answer:

      Correct Answer: Reduced aortic compliance

      Explanation:

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 90 - Regarding bilirubin, which one of the following statement is true? ...

    Incorrect

    • Regarding bilirubin, which one of the following statement is true?

      Your Answer:

      Correct Answer: Conjugated bilirubin is stored in the gall bladder

      Explanation:

      Bilirubin is the tetrapyrrole and a catabolic product of heme. 70-90% of bilirubin is end product of haemoglobin degradation in the liver.

      Bilirubin circulates in the blood in 2 forms; unconjugated and conjugated bilirubin.

      Unconjugated bilirubin is insoluble in water. It travels through the bloodstream to the liver, where it changes from insoluble into a soluble form (i.e.; unconjugated into conjugated form).

      This conjugated bilirubin travels from the liver into the small intestine and the gut bacteria convert bilirubin into urobilinogen and then into urobilin (not urobilin to urobilinogen). A very small amount passes into the kidneys and is excreted in urine.

    • This question is part of the following fields:

      • Physiology
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  • Question 91 - A 64-year-old man is admitted to the critical care unit. He has a...

    Incorrect

    • A 64-year-old man is admitted to the critical care unit. He has a recent medical history of faecal peritonitis for which a laparotomy was performed. His vitals have been monitored using an invasive pulmonary artery flotation catheter.

      His vital readings are:

      Temperature: 38.1°C
      Blood pressure: 79/51 mmHg (mean 58 mmHg)
      Pulmonary artery pressure: 19/6 mmHg (mean 10 mmHg)
      Pulmonary capillary occlusion pressure: 5 mmHg
      Central venous pressure: 12 mmHg
      Cardiac output: 5 L/min
      Mixed venous oxygen saturation: 82%

      Calculate his approximate pulmonary vascular resistance.

      Note: A correction factor of 80 is require to convert mmHg to dynes·s·cm-5

      Your Answer:

      Correct Answer: 80 dynes·s·cm-5

      Explanation:

      Pulmonary vascular resistance (PVR) refers to the resistance to blood flow to the left atrium from the pulmonary artery.
      It is derived mathematically by:

      PVR = MPAP – PCWP
      CO
      where,
      MPAP: Mean pulmonary artery pressure
      PCWP: Pulmonary capillary occlusion pressure
      CO: Cardiac output

      For this patient:
      PVR = 10 – 5 = 1mmHg
      5

      Remember, multiply by correction factor 80 to change units:

      PVR = 1mmHg x 80 = 80 dynes·s·cm-5

      Normal values range between 20-130 dynes·s·cm-5

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 92 - During a fight, a 20-year-old male is stabbed in the thigh with a...

    Incorrect

    • During a fight, a 20-year-old male is stabbed in the thigh with a bottle. He is admitted for treatment.

      Which feature, if present, suggests an injury to the femoral nerve?

      Your Answer:

      Correct Answer: Loss of knee reflex

      Explanation:

      Femoral nerve lesion (L2,L3 and L4) is characterised by weakness of the quadriceps femoris muscle. This results in weakness of extension of the knee, loss of sensation over the front of the thigh, and loss of the knee jerk reflex.

      The skin over the lateral aspect of the thigh and knee, and the lower lateral quadrant of the buttock is supplied by the lateral cutaneous nerve of the thigh (L1,2).

      The adductors of the hip are supplied by the obturator nerve (L2-4). This nerve also supplies sensation to the inner thigh.

    • This question is part of the following fields:

      • Anatomy
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  • Question 93 - An individual who recently moved his residence from the plains to the mountains...

    Incorrect

    • An individual who recently moved his residence from the plains to the mountains will experience immediately which physiologic response to high altitude and hypoxia?

      Your Answer:

      Correct Answer: Increased cardiac output

      Explanation:

      A person remaining at high altitudes for days, weeks, or years becomes more and more acclimatized to the low PO2, so it causes fewer deleterious effects on the body.

      After acclimatization, it becomes possible for the person to work harder without hypoxic effects or to ascend to still higher altitudes. The principal means by which acclimatization comes about are (1) a great increase in pulmonary ventilation, (2) increased numbers of red blood cells, (3) diffusing capacity of the lungs, (4) increased vascularity of the peripheral tissues, and (5) increased ability of the tissue cells to use oxygen despite low PO2.

      The cardiac output often increases as much as 30% immediately after a person ascends to high altitude but then decreases back toward normal over a period of weeks as the blood haematocrit increases, so the amount of oxygen transported to the peripheral body tissues remains about normal.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 94 - The SI unit of energy is the joule. Energy can be kinetic, potential,...

    Incorrect

    • The SI unit of energy is the joule. Energy can be kinetic, potential, electrical or chemical energy.

      Which of these correlates with the most energy?

      Your Answer:

      Correct Answer: Energy released when 1 kg fat is metabolised to CO2 and water (the energy content of fat is 37 kJ/g)

      Explanation:

      The derived unit of energy, work or amount of heat is joule (J). It is defined as the amount of energy expended if a force of one newton (N) is applied through a distance of one metre (N·m)

      J = 1 kg·m/s2·m = 1 kg·m2/s2 or 1 kg·m2·s-2

      Kinetic energy (KE) = ½ MV2

      An object with a mass of 1500 kg moving at 30 m/s correlates to 675 kJ:

      KE = ½ (1500) × (30)2 = 750 × 900 = 675 kJ

      Total energy released when 1 kg fat is metabolised to CO2 and water is 37 MJ. 1 g fat produces 37 kJ/g, therefore 1 kg fat produces 37,000 × 1000 = 37 MJ.

      Raising the temperature of 1 kg water from 0°C to 100°C correlates to 420 kJ. The amount of energy needed to change the temperature of 1 kg of the substance by 1°C is the specific heat capacity. We have 1 kg water therefore:

      4,200 J × 100 = 420,000 J = 420 kJ

      In order to calculate the energy involved in raising a 100 kg mass to a height of 1 km against gravity, we need to calculate the potential energy (PE) of the mass:

      PE = mass × height attained × acceleration due to gravity
      PE = 100 kg × 1000 m × 10 m/s2 = 1 MJ

      The heat generated when a direct current of 10 amps flows through a heating element for 10 seconds when the potential difference across the element is 1000 volts can be calculated by applying Joule’s law of heating:

      Work done (WD) = V (potential difference) × I (current) × t (time)
      WD = 10 × 10 × 1000 = 100 kJ

    • This question is part of the following fields:

      • Physiology
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  • Question 95 - The lung volume that is commonly measured indirectly is? ...

    Incorrect

    • The lung volume that is commonly measured indirectly is?

      Your Answer:

      Correct Answer: Functional residual capacity

      Explanation:

      The functional residual capacity (FRC) is the volume in the lungs at the end of passive expiration. It is determined by opposing forces of the expanding chest wall and the elastic recoil of the lung. A normal FRC = 1.7 to 3.5 L. It a marker for lung function, and, during this time, the alveolar pressure is equal to the atmospheric pressure.

      FRC cannot be measured by spirometry because it contains the residual volume.

      Tidal volume, inspiratory reserve volume, forced expiratory volume in 1 second, and vital capacity can be measured directly.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 96 - A 42 year old man came to the out-patient department with attacks of...

    Incorrect

    • A 42 year old man came to the out-patient department with attacks of facial pain. Upon further questioning, he reported that the pain was intermittent, often occurring spontaneously. The quality of the pain was sharp, and severity was moderate to moderately severe. The pain was non-radiating, and often involved the left maxillary and mandibular areas.

      Other medical information of the patient, such as allergies and co-morbidities, were unremarkable.

      Which of the following is the most probable diagnosis of the patient?

      Your Answer:

      Correct Answer: Trigeminal neuralgia

      Explanation:

      Trigeminal neuralgia is characterized by excruciating paroxysms of pain in the lips, gums, cheek, or chin and, very rarely, in the distribution of the fifth nerve. The pain seldom lasts more than a few seconds or a minute or two but may be so intense that the patient winces, hence the term tic. The paroxysms, experienced as single jabs or clusters, tend to recur frequently, both day and night, for several weeks at a time. They may occur spontaneously or with movements of affected areas evoked by speaking, chewing, or smiling. Another characteristic feature is the presence of trigger zones, typically on the face, lips, or tongue, that provoke attacks; patients may report that tactile stimuli – e.g., washing the face, brushing the teeth, or exposure to a draft of air – generate excruciating pain. An essential feature of trigeminal neuralgia is that objective signs of sensory loss cannot be demonstrated on examination.

      Trigeminal neuralgia is relatively common, with an estimated annual incidence of 4–8 per 100,000 individuals. Middle-aged and elderly persons are affected primarily, and ,60% of cases occur in women. Onset is typically sudden, and bouts tend to persist for weeks or months before remitting spontaneously. Remissions may be long-lasting, but in most patients, the disorder ultimately recurs.

      An ESR or CRP is indicated if temporal arteritis is suspected. In typical cases of trigeminal neuralgia, neuroimaging studies are usually unnecessary but may be valuable if MS is a consideration or in assessing overlying vascular lesions in order to plan for decompression surgery.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 97 - Suppose the afterload and myocardial contractility remain unchanged, which of the following factors...

    Incorrect

    • Suppose the afterload and myocardial contractility remain unchanged, which of the following factors in the pressure-volume loop indicates an increase in the preload of the left ventricle?

      Your Answer:

      Correct Answer: Increased end-diastolic volume

      Explanation:

      If the afterload and myocardiac contractility remains unchanged, an increase in the preload can be attributed to an increase in end-diastolic volume.

      Preload can be defined as the initial stretching of the cardiac myocytes prior to contraction. Preload, therefore, is related to muscle sarcomere length. Because sarcomere length cannot be determined in the intact heart, other indices of preload are used such as ventricular end-diastolic volume or pressure. When venous return to the heart is increased, the end-diastolic pressure and volume of the ventricles are increased, which stretches the sarcomeres, thereby increasing their preload.

    • This question is part of the following fields:

      • Basic Physics
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  • Question 98 - Out of the following, which is NOT a part of the contents of...

    Incorrect

    • Out of the following, which is NOT a part of the contents of the porta hepatis?

      Your Answer:

      Correct Answer: Cystic duct

      Explanation:

      The porta hepatis is a fissure in the inferior surface of the liver. All the neurovascular structures that enter and leave the porta hepatis are:
      1. hepatic portal vein
      2. hepatic artery
      3. hepatic ducts
      4. hepatic nerve plexus (It contains the sympathetic branch to the liver and gallbladder and the parasympathetic, hepatic branch of the vagus nerve.)

      These structures supply and drain the liver. Only the hepatic vein is not part of the porta hepatis.
      The porta hepatis is also surrounded by lymph nodes, that may enlarge to produce obstructive jaundice.
      These structures divide immediately after or within the porta hepatis to supply the functional left and right lobes of the liver.

      The cystic duct lies outside the porta hepatis and is an important landmark in laparoscopic cholecystectomy.

    • This question is part of the following fields:

      • Anatomy
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  • Question 99 - Which of the following is true regarding correlation coefficient? ...

    Incorrect

    • Which of the following is true regarding correlation coefficient?

      Your Answer:

      Correct Answer: It can assume any value between -1 and 1

      Explanation:

      The degree of correlation is summarised by the correlation coefficient (r). This indicates how closely the points lie to a line drawn through the plotted data. In parametric data this is called Pearson’s correlation coefficient and can take any value between -1 to +1. A correlation of -1.0 indicates a perfect negative correlation, and a correlation of 1.0 indicates a perfect positive correlation.

      For example

      r = 1 – strong positive correlation (e.g. systolic blood pressure always increases with age)

      r = 0 – no correlation (e.g. there is no correlation between systolic blood pressure and age)

      r = – 1 – strong negative correlation (e.g. systolic blood pressure always decreases with age)

      Whilst correlation coefficients give information about how one variable may increase or decrease as another variable increases they do not give information about how much the variable will change. They also do not provide information on cause and effect.

      In contrast to the correlation coefficient, linear regression may be used to predict how much one variable changes when a second variable is changed.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 100 - A 26-year-old doctor has recently been diagnosed with lung cancer. He would like...

    Incorrect

    • A 26-year-old doctor has recently been diagnosed with lung cancer. He would like to find out his survival time for the condition.

      Which statistical method is used to predict survival rate?

      Your Answer:

      Correct Answer: Kaplan-Meier estimator

      Explanation:

      The Weibull distribution are used to describe various types of observed failures of the components. it is used in reliability and survival analysis.

      Regression Analysis is used to measure the relationship between among two or more variable. It determines the effect of independent variables on the dependent variables.

      Student t-test is one of the most commonly used method to test the hypothesis. It determines the significant difference between the means of two different groups.

      A time series is a collection of observations of well-defined data obtained at regular interval of time.

      Kaplan-Meier estimator is used to estimate the survival function from lifetime data. It can be derived from maximum likelihood estimation of hazard function. It is most likely used to measure the fraction of patient’s life for a certain amount of time after treatment.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 101 - A 72-year-old female is diagnosed with acute mesenteric ischemia.

    On CT angiogram, the...

    Incorrect

    • A 72-year-old female is diagnosed with acute mesenteric ischemia.

      On CT angiogram, the origin of the superior mesenteric artery is stenosed.

      At which vertebra level does the superior mesenteric artery branch from the aorta?

      Your Answer:

      Correct Answer: L1

      Explanation:

      The superior mesenteric artery branches from the abdominal aorta just 1-2 cm below the origin of the celiac trunk. It lies posterior to the body of the pancreas and splenic vein and is separated from the aorta by the left renal vein. It passes forwards and inferiorly, anterior to the uncinate process of the pancreas and the third part of the duodenum, to enter the root of the small bowel mesentery and supply the midgut.

      The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:

      T10 – oesophageal opening in the diaphragm

      T12 – Coeliac trunk, aortic hiatus in the diaphragm

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta

    • This question is part of the following fields:

      • Anatomy
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  • Question 102 - A 62-year-old woman, presents to emergency department with an ischaemic left colon.

    Multiple...

    Incorrect

    • A 62-year-old woman, presents to emergency department with an ischaemic left colon.

      Multiple arteries arise from the aorta at the level of the L3 vertebrae, which is most likely to be involved in this pathology?

      Your Answer:

      Correct Answer: Inferior mesenteric artery

      Explanation:

      The inferior mesenteric artery arises from the abdominal aorta at the level of the L3 vertebrae and supplies blood to the final third of the transverse colon, the descending colon, the sigmoid colon and the uppermost part of the rectum.

      It is the artery most likely to affect the left colon.

    • This question is part of the following fields:

      • Anatomy
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  • Question 103 - About low molecular weight (LMW) heparin, Which of these is true? ...

    Incorrect

    • About low molecular weight (LMW) heparin, Which of these is true?

      Your Answer:

      Correct Answer: Is excreted in the urine

      Explanation:

      Low molecular weight heparin (LMWH) creates a complex by binding to antithrombin. This complex binds with and inactivates factor Xa.

      There is less risk of bleeding with LMWH because it binds less to platelets, endothelium and von Willebrand factor.

      LMW binds Xa more readily. The shorter chains are less likely to bind both antithrombin and thrombin.

      There is need for monitoring in renal impairment because LMHW is excreted in the urine (and partly by hepatic metabolism)

      LMWH have been shown to be as efficacious as unfractionated heparin. It is also safer and have improved inpatient stay and reduced hospital cost.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 104 - Among the following, which statement is true regarding electrical safety in an operation...

    Incorrect

    • Among the following, which statement is true regarding electrical safety in an operation theatre?

      Your Answer:

      Correct Answer: The higher the frequency of the current the less risk to the patient

      Explanation:

      The operating theatre is an unusual place with several applications of electrical equipment to the human body. This can lead to potential dangers associated with it that need to be prevented. Electrical safety in the operation theatre is the understanding of how these potential dangers can occur and how they can be prevented.

      Electricity can cause morbidity or mortality by one of the following ways:
      (i) electrocution
      (ii) burns
      (iii) ignition of a flammable material, causing a fire or explosion.

      Electrocution is dependant on factors like duration of contact with electric current, the current pathway and the frequency and size of current.

      Option A: The higher the frequency, the less effects of electrocution on the body.

      Option B & D: Equipment can be classified in classes and types.
      The class designation describes the method used for protection against electrocution. Class I is basic protection, class II is double insulation and class III is safety extra low voltage.
      The type designation describes the degree of protection based on the maximum permissible leakage currents under normal and fault conditions.
      Type B:
      can be class I, II or III but the maximum leakage current must not exceed 100 µA. It is therefore not suitable for direct connection to the heart.
      Type BF
      Similar to type B, but uses an isolated (or floating) circuit.
      Type CF
      Only type CF protect against microshock as they allow leakage currents of 0.05 mA per electrode for class I and 0.01 mA for class II. Microshock is a small leakage current that can cause harm because of direct connection to the heart via transvenous lines or wires, bypassing the impedance of the skin, leading to ventricular fibrillation. Microshock current of 100 ?A is sufficient to cause VF.

      Option C: A 75mA electrocution can cause ventricular fibrillation. Use the following as a general guide to understand the effect of current size on the body.
      1 mA – tingling pain
      5 mA – pain
      15 mA – tonic muscular contraction
      50 mA – respiratory muscle paralysis
      75 mA – ventricular fibrillation.

      Option E: Wet skin reduces the resistance to current flow and therefore increases the effects of electrocution.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 105 - A 24-year old female is brought to the emergency room due to urticarial...

    Incorrect

    • A 24-year old female is brought to the emergency room due to urticarial rash and shortness of breath. Her mother reported that, prior to the symptoms, she took Co-amoxiclav (Augmentin) for her present ear infection. She also reported that she had no previous exposure to penicillin or any other related antibiotics.

      Which of the following can help to differentiate between type 1 and type II hypersensitivity reaction in this case?

      Your Answer:

      Correct Answer: IgE assay specific for amoxycilloyl

      Explanation:

      Serum specific IgE assays against allergen sources/molecules are the most commonly used in vitro diagnostic approach. The measurement of specific IgE recognizing allergenic epitopes can be achieved both through the usage of single reagents (singleplex) or with a pre-defined panel of a number of molecules to be tested simultaneously (multiplex).

      Several clinical entities have been described and those occurring immediately after drug exposure are immunoglobulin E (IgE)-mediated and explored by skin testing and by the in vitro measurement of serum-specific IgE. The sensitivity of these tests is not 100% and even for patients with a clear positive history, a drug provocation test may be required in order to confirm the diagnosis. The advantages of the in vitro determination of specific IgE antibodies when compared with in vivo testing are that the former poses no direct risk to the patient and does not require personnel with expertise. Even though in vitro tests are recommended in immediate hypersensitivity reactions, their exact place in the diagnostic procedure is not clear and certain authors do not use this method in daily practice. In one study, in terms of sensitivity, 11 of 26 patients (42%) with negative skin tests and a positive drug provocation challenge (or repeated clinical history) had specific IgE to benzylpenicilloyl or amoxicilloyl (4). The specificity of the test was 95–100%. Therefore, IgE measurements can avoid a potentially harmful drug provocation test.

      An elevated serum tryptase does not differentiate between type 1 and type 2 hypersensitivity reaction. It indicates mast cell degranulation.

      RAST is a useful aid to improve the overall diagnosis of drug allergies by using radioactive detection. This, however, is now rarely used.

      Quantification of basophil activation by CD63 expression can be done by flow cytometry, which forms the basis of experimental drug-induced basophil stimulation tests.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 106 - The clavipectoral fascia is penetrated by the cephalic vein to terminate in which...

    Incorrect

    • The clavipectoral fascia is penetrated by the cephalic vein to terminate in which of the listed veins?

      Your Answer:

      Correct Answer: Axillary

      Explanation:

      The cephalic vein is a superficial vein that runs through the forearm and the arm, before draining into the axillary vein where it terminates.

    • This question is part of the following fields:

      • Anatomy
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  • Question 107 - Which of the following statements is not correct regarding Noradrenaline? ...

    Incorrect

    • Which of the following statements is not correct regarding Noradrenaline?

      Your Answer:

      Correct Answer: Predominantly work through effects on ?-adrenergic receptors

      Explanation:

      Noradrenaline also called norepinephrine belongs to the catecholamine family that functions in the brain and body as both a hormone and neurotransmitter.

      They have sympathomimetic effects acting via adrenoceptors (?1, ?2,?1, ?2, ?3) or dopamine receptors (D1, D2).

      May cause reflex bradycardia, reduce cardiac output and increase myocardial oxygen consumption

    • This question is part of the following fields:

      • Pharmacology
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  • Question 108 - All of the following are responses to massive haemorrhage except which of the...

    Incorrect

    • All of the following are responses to massive haemorrhage except which of the following?

      Your Answer:

      Correct Answer: Decreased cardiac output by increased direct parasympathetic stimulation

      Explanation:

      With regards to compensatory response to blood loss, the following sequence of events take place:

      1. Decrease in venous return, right atrial pressure and cardiac output
      2. Baroreceptor reflexes (carotid sinus and aortic arch) are immediately activated
      3. There is decreased afferent input to the cardiovascular centre in medulla. This inhibits parasympathetic reflexes and increases sympathetic response
      4. This results in an increased cardiac output and increased SVR by direct sympathetic stimulation. There is increased circulating catecholamines and local tissue mediators (adenosine, potassium, NO2)
      5. Fluid moves into the intravascular space as a result of decreased capillary hydrostatic pressure absorbing interstitial fluid.

      A slower response is mounted by the hypothalamus-pituitary-adrenal axis.
      6. Reduced renal blood flow is sensed by the intra renal baroreceptors and this stimulates release of renin by the juxta-glomerular apparatus.
      7. There is cleavage of circulating Angiotensinogen to Angiotensin I, which is converted to Angiotensin II in the lungs (by Angiotensin Converting Enzyme ACE)

      Angiotensin II is a powerful vasoconstrictor that sets off other endocrine pathways.
      8. The adrenal cortex releases Aldosterone
      9. There is antidiuretic hormone release from posterior pituitary (also in response to hypovolaemia being sensed by atrial stretch receptors)
      10. This leads to sodium and water retention in the distal convoluted renal tubule to conserve fluid
      Fluid conservation is also aided by an increased amount of cortisol which is secreted in response to the increase in circulating catecholamines and sympathetic stimulation.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 109 - Regarding renal autoregulation, which of the following best describes its process? ...

    Incorrect

    • Regarding renal autoregulation, which of the following best describes its process?

      Your Answer:

      Correct Answer: Reduces the effect of changes in arterial blood pressure on renal Na+ excretion

      Explanation:

      Two mechanisms are responsible for autoregulation of RBF and GFR: one mechanism that responds to changes in arterial pressure and another that responds to changes in [NaCl] in tubular fluid. Both regulate the tone of the afferent arteriole. The pressure-sensitive mechanism, the so-called myogenic mechanism, is related to an intrinsic property of vascular smooth muscle: the tendency to contract when stretched. Accordingly, when arterial pressure rises and the renal afferent arteriole is stretched, the smooth muscle contracts in response. Because the increase in resistance of the arteriole offsets the increase in pressure, RBF, and therefore GFR, remains constant.

      The second mechanism responsible for autoregulation of GFR and RBF is the [NaCl]-dependent mechanism known as tubuloglomerular feedback. This mechanism involves a feedback loop in which a change in GFR leads to alteration in the concentration of NaCl in tubular fluid, which is sensed by the macula densa of the juxtaglomerular apparatus and converted into signals that affect afferent arteriolar resistance and thus the GFR (Fig. 33.19). For example, when the GFR increases and causes [NaCl] in tubular fluid in the loop of Henle to rise, more NaCl enters the macula densa cells in this segment (Fig. 33.20). This leads to an increase in formation and release of adenosine triphosphate (ATP) and adenosine (a metabolite of ATP) by macula densa cells, which causes vasoconstriction of the afferent arteriole and normalization of GFR. In contrast, when GFR and [NaCl] in tubule fluid decrease, less NaCl enters the macula densa cells, and both ATP and adenosine production and release decline. The fall in [ATP] and [adenosine] results in afferent arteriolar vasodilation, which returns GFR to normal. NO, a vasodilator produced by the macula densa, attenuates tubuloglomerular feedback, whereas angiotensin II enhances tubuloglomerular feedback. Thus the macula densa may release both vasoconstrictors (e.g., ATP and adenosine) and a vasodilator (e.g., NO) that oppose each other’s action at the level of the afferent arteriole. Production plus release of either vasoconstrictors or vasodilators ensures exquisite control over tubuloglomerular feedback.

      Renal autoregulation, thus, reduces the effect of changes in arterial blood pressure on renal sodium excretion.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 110 - Which of the following statement is not true regarding the effects of Dopamine...

    Incorrect

    • Which of the following statement is not true regarding the effects of Dopamine in CNS?

      Your Answer:

      Correct Answer: Most of the administered dose is converted to Noradrenaline in sympathetic nerve terminals

      Explanation:

      Nausea and vomiting occur commonly due to Chemoreceptor Trigger Zone (CTZ) stimulation by dopamine (Domperidone but not metoclopramide can be used for the treatment of this vomiting)

      Dopamine itself cannot cross the blood-brain barrier (BBB) but its precursor levodopa can cross BBB.

      Dopamine can modulate extrapyramidal symptoms like acute dyskinesia, tardive dyskinesia, Parkinsonism, and Neuroleptic malignant syndrome.

      Dopamine inhibits the secretion of prolactin from the pituitary gland.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 111 - You are preparing to anaesthetize a 27-year-old woman for an acute diagnostic laparoscopy...

    Incorrect

    • You are preparing to anaesthetize a 27-year-old woman for an acute diagnostic laparoscopy to rule out appendicitis.

      She has no medical history and does not take any medications on a regular basis. You're going to do a quick sequence induction.

      Which method of preoxygenation is the most effective and efficient?

      Your Answer:

      Correct Answer: Mapleson A circuit with a fresh gas flow of 100 ml/kg

      Explanation:

      Professor Mapleson classified non-rebreathing circuits based on the position of the APL valve, which controls fresh gas flow.

      The Mapleson A (Magill) circuit is most effective in spontaneous breathing, requiring only 70-100 ml/kg (the patient’s minute volume) of fresh gas flow. The patient inhales fresh gas from the reservoir bag and tubing during inspiration. During expiration, the patient adds dead space gas (gas that hasn’t been exchanged) to the tubing and reservoir bag in addition to the fresh gas flow. At the patient’s end, alveolar gas is vented through the APL valve. During the expiratory pause, the fresh gas flow causes more gas to be released.

      The Mapleson A is inefficient during controlled ventilation. Venting occurs during inspiration rather than during the expiratory phase, as it does during spontaneous ventilation. As a result, unless a high fresh gas flow of >20 L/minute is used, alveolar gas is rebreathed.

      During spontaneous ventilation, the Mapleson D circuit is inefficient.

      The oxygen concentration in a Hudson mask is insufficient to allow for adequate pre-oxygenation.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 112 - An elective left colectomy is being performed on a 60-year old male for...

    Incorrect

    • An elective left colectomy is being performed on a 60-year old male for left-sided colon cancer. The upper and lower parts of the descending colon are supplied by the left colic artery.

      Which of the following arteries gives rise to the left colic artery?

      Your Answer:

      Correct Answer: Inferior mesenteric artery

      Explanation:

      The inferior mesenteric artery originates 3-4 cm above the bifurcation of the abdominal aorta. The left colic artery branches off the inferior mesenteric artery, arising close to its origin from the abdominal aorta. Other branches of IMA include the three sigmoid arteries that supply the sigmoid colon.

      The left colic artery branches off from IMA to supply the distal 1/3 of the transverse colon and the descending colon. It moves upwards posterior to the left colic mesentery and then travels anteriorly to the psoas major muscle, left ureter, and left internal spermatic vessels, before dividing into ascending and descending branches.

    • This question is part of the following fields:

      • Anatomy
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  • Question 113 - A 72-year old man has presented to the emergency room with sweating, nausea,...

    Incorrect

    • A 72-year old man has presented to the emergency room with sweating, nausea, chest pain, and an ECG that shows ST elevation. The ST segment of the ECG corresponds to a period of slow calcium influx in the cardiac action potential.
      This equates to which phase in the cardiac action potential?

      Your Answer:

      Correct Answer: Phase 2

      Explanation:

      Understanding of the cardiac action potential helps with the understanding of the ECG which measures the electrical activity of the heart. This is reflected in its waveform.
      The rapid depolarisation phase is reflected in the QRS complex. After this phase comes the plateau phase which is represented by the ST segment. Lastly, the T wave shows repolarisation, phase 3.

      The cardiac action potential has several phases which have different mechanisms of action as seen below:
      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium. (ST segment)

      Phase 3 – Final repolarisation – caused by an efflux of potassium. (T wave)

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 114 - A log-dose response curve is plotted after drug A is given. The shape...

    Incorrect

    • A log-dose response curve is plotted after drug A is given. The shape of this curve is sigmoid, with a maximum response of 100%.

      The log-dose response curve of drug A shifts to the right with a maximum response of 100 percent when drug B is administered.

      What does this mean in terms of drug B?

      Your Answer:

      Correct Answer: Drug B has affinity for the receptor but has no intrinsic efficacy

      Explanation:

      Drug A is a pure agonist for the receptor, with high intrinsic efficacy and affinity, according to the log-dose response curve.

      Drug B, on the other hand, works as a competitive antagonist. It binds to the receptor but has no inherent efficacy. Drug A’s efficacy will not change, but its potency will be reduced.

      A partial agonist is a drug with partial intrinsic efficacy and affinity for the receptor. Giving a partial agonist after a pure agonist will not increase receptor occupancy or decrease receptor activity, and thus will not affect drug A’s efficacy. The inverse agonist flumazenil can reverse all benzodiazepines.

      An inverse agonist is a drug that binds to the receptor but has the opposite pharmacological effect.

      A non-competitive antagonist is a drug that has affinity for a receptor but has different pharmacological effects and reduces the efficacy of an agonist for that receptor.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 115 - Which of the following closely estimates the interstitial oncotic pressure acting on a...

    Incorrect

    • Which of the following closely estimates the interstitial oncotic pressure acting on a pulmonary capillary?

      Your Answer:

      Correct Answer: 17 mmHg

      Explanation:

      The starling forces operate to maintain a homeostatic flow across the pulmonary capillary bed.

      The outward driving force comprises of the capillary hydrostatic pressure (13 mmHg), negative interstitial fluid pressure (zero to slightly negative), and interstitial colloid osmotic pressure (17 mmHg). The inward driving force is controlled by the plasma colloid osmotic pressure (25 mmHg).

    • This question is part of the following fields:

      • Basic Physics
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  • Question 116 - The following results were obtained In a new drug trial:

    Improved Not improved
    Placebo...

    Incorrect

    • The following results were obtained In a new drug trial:

      Improved Not improved
      Placebo group 36 26
      Treatment group 44 16

      Regarding the statistical analysis or interpretation of the trial, One of these is true

      Your Answer:

      Correct Answer: The data could be evaluated using the chi square test

      Explanation:

      This data is in a 2 × 2 contingency table so a chi square test can be used. There is a special chi squared formula that gives a value that can be looked up in a table giving the p value.

      Since we are comparing proportions not means, the Student’s t test CANNOT be used.

      There is no linear regression to plot so Pearson’s co-efficient cannot be calculated.

      Nothing is so obvious that no statistical analysis is needed.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 117 - A study of blood pressure measurements is being performed in patients with chronic...

    Incorrect

    • A study of blood pressure measurements is being performed in patients with chronic kidney disease.

      Considering that the results are normally distributed, what percentage of values lie within two standard deviations of the mean blood pressure reading?

      Your Answer:

      Correct Answer: 95.40%

      Explanation:

      Normal distribution, also called Gaussian distribution, the most common distribution function for independent, randomly generated variables, and describes the spread for many biological and clinical measurements.

      Properties of the Normal distribution

      symmetrical i.e. Mean = mode = median

      68.3% of values lie within 1 SD of the mean

      95.4% of values lie within 2 SD of the mean

      99.7% of values lie within 3 SD of the mean

      The empirical rule, or the 68-95-99.7 rule, tells you where most of the values lie in a normal distribution: Around 68% of values are within 1 standard deviation of the mean.

      Around 95% of values are within 2 standard deviations of the mean. Around 99.7% of values are within 3 standard deviations of the mean.
      the standard deviation (SD) is a measure of how much dispersion exists from the mean.

      SD = square root (variance)

      The empirical rule, or the 68-95-99.7 rule states where most of the values lie in a normal distribution. Around 68% of values fall within 1 S.D of the mean, about 95% within 2 S.D of the mean, and about 99.7% of values within 3 S.D of the mean. Therefore, 95.4% is the most reasonable answer if results are normally distributed.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 118 - Which muscle separates the subclavian artery and the subclavian vein? ...

    Incorrect

    • Which muscle separates the subclavian artery and the subclavian vein?

      Your Answer:

      Correct Answer: Scalenus anterior

      Explanation:

      The subclavian artery and vein have a similar path throughout their course, with the subclavian vein running anterior to the subclavian artery. The artery and vein are separated by the insertion of the scalenus anterior muscle.

      There are three scalene muscles, found on each side of the neck:
      1. Anterior scalene
      2. Middle scalene
      3. Posterior scalene

      The scalenus anterior muscle is the anterior most of the three scalene muscles. It originates from the transverse processes of vertebrae C3-C6 and is inserted in the first rib.

    • This question is part of the following fields:

      • Anatomy
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  • Question 119 - Which of the following statements is true about monoamine oxidase (MOA) enzymes? ...

    Incorrect

    • Which of the following statements is true about monoamine oxidase (MOA) enzymes?

      Your Answer:

      Correct Answer: Type A and type B are found in the liver and brain

      Explanation:

      Monoamine oxidase (MOA) enzymes are responsible for the catalyses of monoamine oxidative deamination. It assists the degradation of serotonin, norepinephrine (NE) and dopamine.

      They are found in the mitochondria of most central and peripheral nerve tissues.

      There are 2 different types:

      Type A: Whose main function it to inactivate dopamine, tyramine, norepinephrine and 5-hydroxytryptamine. In addition to the nervous system, it is also found in the liver, brain gastrointestinal tract, pulmonary endothelium and placenta
      Type B: Whose main function is to inactivate dopamine, tyramine, tryptamine and phenylethylamine. In addition to the nervous system, it is also found in the liver, brain (especially in the basal ganglia) and blood platelets.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 120 - A 28-year-old man is admitted to the critical care unit. He has been...

    Incorrect

    • A 28-year-old man is admitted to the critical care unit. He has been diagnosed with adult respiratory distress syndrome and is being ventilated. His haemodynamic condition is improved using a pulmonary artery flotation.

      His readings are listed below:

      Haemoglobin concentration: 10 g/dL
      Mixed venous oxygen saturation: 70%
      Mixed venous oxygen tensions (PvO2): 50 mmHg

      Estimate his mixed venous oxygen content (mL/100mL).

      Your Answer:

      Correct Answer: 9.5

      Explanation:

      Mixed venous oxygen content (CvO2) is the oxygen concentration in 100mL of mixed venous blood taken from the pulmonary artery. It is usually 12-17 mL/dL (70-75%). It is represented mathematically as:

      CvO2 = (1.34 x Hgb x SvO2 x 0.01) + (0.003 x PvO2)

      Where,

      1.34 = Huffner’s constant
      Hgb = Haemoglobin level (g/dL)
      SvO2 = % oxyhaemoglobin saturation of mixed venous blood
      PvO2 = 0.0225 = mL of O2 dissolved per 100mL plasma per kPa, or 0.003 mL per mmHg

      Therefore,

      CvO2 = (1.34 x 10 x 70 x 0.01) + (0.003 x 50)

      CvO2 = 9.38 + 0.15 = 9.53 mL/100mL

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 121 - If the speed of an ultrasound in soft tissue is 1540 meters per...

    Incorrect

    • If the speed of an ultrasound in soft tissue is 1540 meters per second, what is the estimated wavelength produced if the frequency of a generated ultrasound is 10 megahertz?

      Your Answer:

      Correct Answer: 0.15 millimetre

      Explanation:

      Wavelength can be computed as follows:

      Wavelength = velocity/frequency

      In the given problem, the values stated are:

      Frequency = 10 x 10^6
      Velocity = 1540 meters per second

      Wavelength = 1540/(10×10^6)
      Wavelength = 1540/10,000,000 meters
      Wavelength = 0.15 millimetres

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 122 - A 32-year-old man has multiple stab wounds to his abdomen and is rushed...

    Incorrect

    • A 32-year-old man has multiple stab wounds to his abdomen and is rushed into the emergency. Resuscitative measures are performed, but the patient remains hypotensive.

      Emergency laparotomy is performed, and it reveals a vessel is bleeding profusely at a certain level of lumbar vertebrae. The vessel is the testicular artery and is ligated.

      At which lumbar vertebrae is the testicular artery identified?

      Your Answer:

      Correct Answer: L2

      Explanation:

      The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:

      T12 – Coeliac trunk

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta

    • This question is part of the following fields:

      • Anatomy
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  • Question 123 - Which structure passes through the foramen magnum? ...

    Incorrect

    • Which structure passes through the foramen magnum?

      Your Answer:

      Correct Answer: Spinal roots of the accessory nerve

      Explanation:

      The structures that pass through the foramen magnum are:

      Meningeal lymphatics
      Spinal cord
      Spinal meninges
      Sympathetic plexus of vertebral arteries
      Vertebral arteries
      Vertebral artery spinal branches
      The spinal roots of the accessory nerve.

      The jugular foramen contains the vagus nerve, the accessory nerve and glossopharyngeal nerve.

      The vertebral veins does not pass into the skull.

    • This question is part of the following fields:

      • Anatomy
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  • Question 124 - Concerning the trachea, which of these is true? ...

    Incorrect

    • Concerning the trachea, which of these is true?

      Your Answer:

      Correct Answer: In an adult is approximately 15 cm long

      Explanation:

      In an adult, the trachea is approximately 15 cm long. It extends at the level of the 6th cervical vertebra, from the lower border of the cricoid cartilage.

      The trachea terminates between T4 and T6 at the carina or bronchial bifurcation. This variation is because of changes during respiration.

      The trachea has 16-20 C-shaped cartilaginous rings that maintain its patency.

      The trachea is first of the 23 generations of air passages in the tracheobronchial tree (not 25), from the trachea to the alveoli..

      The inferior thyroid arteries which are branches of the thyrocervical trunk, arise from the first part of the subclavian artery and supplies the trachea.

    • This question is part of the following fields:

      • Anatomy
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  • Question 125 - An 80-year-old presents to the emergency department with symptoms raising suspicion of mesenteric...

    Incorrect

    • An 80-year-old presents to the emergency department with symptoms raising suspicion of mesenteric ischemia. To diagnose the condition, an angiogram is performed. The radiologist needs to cannulate the coeliac axis from the aorta for the angiogram.

      What vertebral level does the coeliac axis originate from the aorta?



      Your Answer:

      Correct Answer: T12

      Explanation:

      Mesenteric ischemia is ischemia of the blood vessels of the intestines. It can be life-threatening especially if the small intestine is involved.

      A critical factor for survival of acute mesenteric ischemia is early diagnosis and intervention. Angiography uses X-ray and contrast dye to image arteries and identify the severity of ischemia or obstruction.

      The celiac axis is the first branch of the abdominal aorta and supplies the entire foregut (mouth to the major duodenal papilla). It arises at the level of vertebra T12. It has three major branches:
      1. Left gastric
      2. Common hepatic
      3. Splenic arteries

      There are some important landmarks of vessels at different levels of vertebrae that need to be memorized.

      T12 – Coeliac trunk

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta

    • This question is part of the following fields:

      • Anatomy
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  • Question 126 - Of the stated laws, which is correct? ...

    Incorrect

    • Of the stated laws, which is correct?

      Your Answer:

      Correct Answer: Boyle's law states that at constant temperature the volume of a given mass of gas varies inversely with absolute pressure.

      Explanation:

      Boyle’s law is correctly stated as it states that the volume of a gas of known mass is inversely proportional with absolute pressure, at a constant temperature.

      Beer’s law states that radiation absorption by a solution of known thickness and concentration is identical to that of a solution of double thickness and half concentration.

      Bougner’s (or Lambert’s) law states that every layer with the same thickness will absorb the same amount of radiation as it passes through.

      Graham’s law states that the diffusion rate of a gas is inversely related to the square root of its molecular weight.

      Raoult’s law states that the reduction of a solvent’s vapour pressure is directly proportional to the solute’s molar concentration.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 127 - Provided below is an abstract of a study conducted recently.

    A consensus...

    Incorrect

    • Provided below is an abstract of a study conducted recently.

      A consensus was developed among international experts. A total of 27 experts were invited. 91% of them decided to show up. A systematic review was performed. This comprised of open ended questions and the participants were encouraged to provide suggestions by e-mail. In the second phase google forms were used. Participants were asked to rate survey items on a scale of 5 points. Items that were rated critical by no less than 80% of the experts were included. Items that were rendered important by 65-79% of experts were inducted in the next survey for re rating. Items that were rated below 65% were rejected.

      Which of the following methods was used in the study from which the abstract has been taken?

      Your Answer:

      Correct Answer: The Delphi method

      Explanation:

      The process used in the study is Delphi method. This method kicks off with an open ended questionnaire and uses its responses as a survey instrument for the next round in which each of the participants is asked to rate the items that the investigators have summarized on the basis of the data collected in the first round.

      Any disagreement is further discussed in phases to come on the basis of information obtained from previous phases.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 128 - A new intravenous neuromuscular blocking agent has been developed. It has a hepatic...

    Incorrect

    • A new intravenous neuromuscular blocking agent has been developed. It has a hepatic extraction ratio of 0.25 and three quaternary nitrogen atoms in its structure. It has been discovered that it has a half-life of fifteen minutes in healthy volunteers.

      Which of the following elimination mechanisms is the most likely to explain this pharmacological behaviour?

      Your Answer:

      Correct Answer: It is filtered and not reabsorbed by the renal tubules

      Explanation:

      The neuromuscular blocking agent is likely to be filtered and not reabsorbed by the renal tubules due to an exclusion process.

      Neuromuscular blocking agents that contain one or more quaternary nitrogen atoms are polar and ionised. As a result, the molecules have low lipid solubility, low membrane diffusion capacity, and low distribution volume.

      It’s unlikely that a compound with three quaternary nitrogen atoms is an ester. Its high polarity would prevent molecules from moving quickly into tissues.

      When drugs have a low hepatic extraction ratio (0.3), the venous and arterial drug concentrations are nearly identical. The liver is not the primary site of drug metabolism.

      Therefore:

      Changes in liver blood flow have no effect on clearance.
      Protein binding, intrinsic metabolism, and excretion are all very sensitive to changes in clearance.
      When taken orally, there is no first-pass metabolism.

      There is no reason for the lungs to eliminate any neuromuscular blocking agent.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 129 - What is the number of valves between the superior vena cava and the...

    Incorrect

    • What is the number of valves between the superior vena cava and the right atrium?

      Your Answer:

      Correct Answer: None

      Explanation:

      The inflow of blood from the superior vena cava is directed towards the right atrioventricular orifice. It returns deoxygenated blood from all structures superior to the diaphragm, except the lungs and heart.

      There are no valves in the superior vena cava which is why it is relatively easy to insert a CVP line from the internal jugular vein into the right atrium. The brachiocephalic vein is similar as it also has no valves.

    • This question is part of the following fields:

      • Anatomy
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  • Question 130 - A 60 year old non insulin dependent diabetic on metformin undergoes hip arthroscopy...

    Incorrect

    • A 60 year old non insulin dependent diabetic on metformin undergoes hip arthroscopy under general anaesthesia.

      Her preoperative blood glucose is 6.5mmol/L. Anaesthesia is induced with 200 mg propofol and 100 mcg fentanyl and maintained with sevoflurane and air/oxygen mixture. she is given 8 mg dexamethasone, 40 mg parecoxib, 1 g paracetamol and 500 mL Hartmann's solution Intraoperatively.

      The procedure took thirty minutes and her blood glucose in recovery is 14 mmol/L.

      What is the most likely cause for her rise in blood sugar?

      Your Answer:

      Correct Answer: Stress response

      Explanation:

      A significant early feature of the metabolic response to trauma and surgery is hyperglycaemia. It is due to an increased glucose production and decreased glucose utilisation bought on by neuroendocrine stimulation. Catecholamines, Growth hormone, ACTH and cortisol, and Glucagon are all increased.

      There is also a decreased insulin sensitivity peripherally and an inhibition of insulin production from the beta cells of the pancreas. These changes lead to hyperglycaemia.

      The stress response to endoscopic surgery will only be prevented with use of high dose opioids or central neuraxial block at anaesthesia.
      To reduce the risk of inducing hyperchloremic acidosis, Ringer’s lactate/acetate or Hartmann’s solution is preferred to 0.9% sodium chloride as routine maintenance fluids.

      Though it has been suggested that administration of Hartmann’s solution to patients with type 2 diabetes leads to hyperglycaemia, one Litre of Hartmann’s solution would yield a maximum of 14.5 mmol of glucose. A rapid infusion of this volume would increase the plasma glucose by no more than 1 mmol/L..

      Dexamethasone, a glucocorticoid, produces hyperglycaemia by stimulating gluconeogenesis . Glucocorticoids are agonists of intracellular glucocorticoid receptors. Their effects are mainly mediated via altered protein synthesis via gene transcription and so the onset of action is slow. The onset of action of dexamethasone is about one to four hours and therefore would NOT contribute to the hyperglycaemia in this patient in the time given.

      0.9% Normal saline with or without adrenaline is the usual irrigation fluid. With this type of surgery, systemic absorption is unlikely to occur.

      Fentanyl is not likely the primary cause of hyperglycaemia in this patient. In high doses (50 mcg/Kg) it has been shown to reduce the hyperglycaemic responses to surgery.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 131 - Which of the following is true regarding Noradrenaline (Norepinephrine)? ...

    Incorrect

    • Which of the following is true regarding Noradrenaline (Norepinephrine)?

      Your Answer:

      Correct Answer: Sympathomimetic effects work mainly through ?1 but also ? receptors

      Explanation:

      Noradrenaline acts as a sympathomimetic effect via alpha as well as a beta receptor. However, they have weak ?2 action.

      Natural catecholamines are Adrenaline, Noradrenaline, and Dopamine

    • This question is part of the following fields:

      • Pharmacology
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  • Question 132 - A 70-year-old man collapsed at home. He was brought into the emergency department...

    Incorrect

    • A 70-year-old man collapsed at home. He was brought into the emergency department in an ambulance. His wife tells you that he complained of sudden lower back pain just before he collapsed.

      He is pale and hypotensive. You suspect a ruptured abdominal aortic aneurysm.
      What vertebral level does this affected vessel terminate?

      Your Answer:

      Correct Answer: L4

      Explanation:

      The abdominal aorta begins at the level of the body of T12 near the midline, as a continuation of the thoracic aorta. It descends and bifurcates at the level of L4 into the common iliac arteries.

      An abdominal aortic aneurysm is a swelling in the abdominal aorta. It most commonly occurs in men over 65 years old of age. Smoking, diabetes, hypertension, and hypercholesterolemia are other risk factors contributing to the disease.

      The NHS screening program for abdominal aortic aneurysms involves an ultrasound test for men aged 65 or over if they have not undergone screening for a one-off screening test.

    • This question is part of the following fields:

      • Anatomy
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  • Question 133 - Which one of the following causes vasoconstriction? ...

    Incorrect

    • Which one of the following causes vasoconstriction?

      Your Answer:

      Correct Answer: Angiotensin II

      Explanation:

      Prostacyclin is a strong vasodilator. It is administered as an intravenous infusion for critical ischemia. Commercially, it is available as sodium epoprodtenol.

      Atrial Natriuretic peptide (ANP) hormone secreted from the atria, kidney, and neural tissues. It primarily acts on renal vessel to maintain normal blood pressure and reduce plasma volume by: increasing the renal excretion of salt and water, glomerular filtration rate, vasodilation, and by increasing the vascular permeability. It also inhibits the release of renin and aldosterone.

      Indoramin is an alpha-adrenoceptor blocking agent. which act selectively on post-synaptic-alpha adrenoreceptor, leading to decease in peripheral resistance.

      Angiotensin II is a vasoconstrictor, causing high sodium retention. It also increases the secretion of antidiuretic hormone (ADH) and aldosterone level.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 134 - All of the following are part of the endocrine response to uncontrolled bleeding...

    Incorrect

    • All of the following are part of the endocrine response to uncontrolled bleeding except:

      Your Answer:

      Correct Answer: Increased secretion of insulin

      Explanation:

      With regards to compensatory response to blood loss, the following sequence of events take place:

      1. Decrease in venous return, right atrial pressure and cardiac output
      2. Baroreceptor reflexes (carotid sinus and aortic arch) are immediately activated
      3. There is decreased afferent input to the cardiovascular centre in medulla. This inhibits parasympathetic reflexes and increases sympathetic response
      4. This results in an increased cardiac output and increased SVR by direct sympathetic stimulation. There is increased circulating catecholamines and local tissue mediators (adenosine, potassium, NO2)
      5. Fluid moves into the intravascular space as a result of decreased capillary hydrostatic pressure absorbing interstitial fluid.

      A slower response is mounted by the hypothalamus-pituitary-adrenal axis.
      6. Reduced renal blood flow is sensed by the intra renal baroreceptors and this stimulates release of renin by the juxta-glomerular apparatus.
      7. There is cleavage of circulating Angiotensinogen to Angiotensin I, which is converted to Angiotensin II in the lungs (by Angiotensin Converting Enzyme ACE)

      Angiotensin II is a powerful vasoconstrictor that sets off other endocrine pathways.
      8. The adrenal cortex releases Aldosterone
      9. There is antidiuretic hormone release from posterior pituitary (also in response to hypovolaemia being sensed by atrial stretch receptors)
      10. This leads to sodium and water retention in the distal convoluted renal tubule to conserve fluid
      Fluid conservation is also aided by an increased amount of cortisol which is secreted in response to the increase in circulating catecholamines and sympathetic stimulation.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 135 - Regarding management of chronic pain, which of the following describes the mode of...

    Incorrect

    • Regarding management of chronic pain, which of the following describes the mode of action of gabapentin?

      Your Answer:

      Correct Answer: Modulation of voltage dependent calcium channels and NMDA receptor transmission

      Explanation:

      Gabapentin is an amino acid-like molecules that was originally synthesized as an analogue of GABA but is now known not to act through GABA mechanisms. It is used in the treatment of focal seizures and various nonepilepsy indications, such as neuropathic pain, restless legs syndrome, and anxiety disorders.

      Despite its close structural resemblance to GABA, gabapentin does not act through effects on GABA receptors or any other mechanism related to GABA-mediated neurotransmission. Rather gabapentin binds avidly to ?2?, a protein that serves as an auxiliary subunit of voltage-gated calcium channels. Moreover, it binds to NMDA receptor to modulate its transmission.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 136 - Which one of the following statement is true regarding United Kingdom gas cylinders?...

    Incorrect

    • Which one of the following statement is true regarding United Kingdom gas cylinders?

      Your Answer:

      Correct Answer: Tensile tests are performed on sections of one cylinder in every hundred

      Explanation:

      Medical gas cylinders are made up of molybdenum steel but not cast iron. They are checked and assessed at a regular interval.

      At least one cylinder in each hundred are tested for tensile, pressure, smash, twist and straightening.

      Nitrous Oxide cylinders contain a mixture of liquid and vapour at a pressure of approx. 4500 kPa or 45 Bar. Carbon dioxide cylinder contain gas at the pressure of 5000kPa.

      The filling ratio is the ratio of mass of liquified gas in the cylinder to the mass of water required to fill the cylinder at the temperature of 15ºC. In the united kingdom, filling ratio of liquid nitrous oxide is 0.75. The cylinders are usually attached to the anaesthetic machine. As nitrous oxide is an N-methyl-d-aspartate receptor antagonist that may reduce the incidence of chronic post-surgical pain.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 137 - A 4-year-old boy with status epilepticus was brought to ER and has already...

    Incorrect

    • A 4-year-old boy with status epilepticus was brought to ER and has already received two doses of intravenous lorazepam but is still continuing to have seizures.

      Which of the following drug would be best for his treatment?

      Your Answer:

      Correct Answer: Phenytoin 20 mg/kg IV

      Explanation:

      When the convulsion lasts for five or more than five minutes, or if there are recurrent episodes of convulsions in a 5 minute period without returning to the baseline, it is termed as Status Epilepticus.
      The first priority in the patient with seizures is maintaining the airway, breathing, and circulation.

      Guideline for the management of Status Epilepticus in children by Advanced Life Support Group is as follow:

      Step 1 (Five minutes after the start of seizures):

      If intravascular access is available start treatment with lorazepam 0.1 mg/kg IV
      If no intravascular access then give buccal midazolam 0.5 mg/kg or rectal diazepam 0.5 mg/kg.

      Step 2 (Ten minutes after the start of seizure):

      If the convulsions continue then a second dose of benzodiazepine should be given. Senior should be called on-site and phenytoin should be prepared.
      No more than two doses or benzodiazepines should be given (including any doses given before arrival at the hospital)
      If still no IV access then obtain intraosseous access (IO).

      Step 3 (Ten minutes after step 2)

      Senior help along with anaesthetic/ICU help should be sought
      Phenytoin 20 mg/kg IV over 20 minutes
      If the seizure stops before the full dose of phenytoin is given then the infusion should be completed as this provides up to 24 hours of anticonvulsant effect
      In children already receiving phenytoin as treatment for epilepsy then an alternative is phenobarbitone 20 mg/kg IV over five minutes
      Once the phenytoin is started, senior staff may wish to give rectal paraldehyde 0.4 mg/kg although this is no longer included in the routine algorithm recommended by APLS.

      Step 4 (20 minutes after step 3)

      If 20 minutes after starting phenytoin the child remains in status epilepticus then rapid sequence induction of anaesthesia with thiopentone and a short acting paralysing agent is needed and the child transferred to paediatric intensive care.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 138 - Which of the following statements is correct regarding hypomagnesaemia? ...

    Incorrect

    • Which of the following statements is correct regarding hypomagnesaemia?

      Your Answer:

      Correct Answer: Causes tetany

      Explanation:

      The ECG changes seen in hypomagnesaemia include:

      Prolonged PR interval
      Prolonged QT interval
      Flattening of T waves
      ST segment depression
      Prominent U waves

      These changes are almost the same as those of hypokalaemia.

      There is an increased risk of digoxin toxicity and a risk of atrial and ventricular ectopic and ventricular arrhythmias.

      There is impaired synthesis and release of parathyroid hormone (PTH) in chronic hypomagnesaemia leading to impaired target organ response to PTH. This produces secondary hypocalcaemia.

      The use of potassium ‘wasting’ diuretics (e.g. loop diuretics like furosemide) may lead to Hypomagnesaemia.

      A tall T wave is seen in hypermagnesemia.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 139 - The arterial-venous oxygen (a-vO2) difference is the difference between the oxygen content of...

    Incorrect

    • The arterial-venous oxygen (a-vO2) difference is the difference between the oxygen content of arterial blood (CaO2) and mixed-venous blood (CvO2).

      At rest, which organ has the greatest a-vO2 difference?

      Your Answer:

      Correct Answer: Heart

      Explanation:

      At rest, the heart has the greatest a-vO2 difference, a high capillary to myocyte ratio, short diffusion distances, and a high mitochondrial density. The flow of blood through the coronary arteries is also tightly controlled. At rest, 70-80 percent of the oxygen available to the cardiac muscle is extracted, increasing to 90 percent during exercise.

      The a-vO2 difference indicates the body’s or an individual organ’s ability to extract oxygen from the blood.

      CaO2 is influenced by a number of factors, including Hb concentration, PaO2 and pulmonary diffusion capacity.

      CvO2 is influenced by a number of factors, including capillary density, regional blood flow, heart, resting skeletal muscle, kidney, intestine and skin.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 140 - A 27-year-old woman takes part in a study looking into the effects of...

    Incorrect

    • A 27-year-old woman takes part in a study looking into the effects of different dietary substrates on metabolism. She receives a 24-hour ethyl alcohol infusion.

      A constant volume, closed system respirometer is used to measure CO2 production and consumption. The production of carbon dioxide is found to be 200 mL/minute.

      Which of the following values most closely resembles her anticipated O2 consumption at the conclusion of the trial?

      Your Answer:

      Correct Answer: 300 mL/minute

      Explanation:

      The respiratory quotient (RQ) is the ratio of CO2 produced by the body to O2 consumed in a given amount of time.

      CO2 produced / O2 consumed = RQ

      CO2 is produced at a rate of 200 mL per minute, while O2 is consumed at a rate of 250 mL per minute. An RQ of around 0.8 is typical for a mixed diet.

      The RQ will change depending on the energy substrates consumed in the diet. Granulated sugar is a refined carbohydrate that contains 99.999 percent carbohydrate and no lipids, proteins, minerals, or vitamins.

      Glucose and other hexose sugars (glucose and other hexose sugars):
      RQ=1

      Fats:
      RQ = 0.7

      Proteins:
      Approximately 0.9 RQ

      Ethyl alcohol is a type of alcohol.

      200/300 = 0.67 RQ

      For complete oxidation, lipids and alcohol require more oxygen than carbohydrates.

      When carbohydrate is converted to fat, the RQ can rise above 1.0. Fat deposition and weight gain are likely to occur in these circumstances.

    • This question is part of the following fields:

      • Physiology
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  • Question 141 - Which of the following hormones is secreted by the posterior pituitary? ...

    Incorrect

    • Which of the following hormones is secreted by the posterior pituitary?

      Your Answer:

      Correct Answer: Oxytocin

      Explanation:

      The posterior pituitary is made up mostly of neural tissue. It is responsible for the storage and release of 2 hormones:
      – antidiuretic hormone (ADH)
      – oxytocin.

      These two hormones are synthesised in the supraoptic and paraventricular nuclei of the hypothalamus.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 142 - An 80-year old lady has a background history of a previous myocardial infarction...

    Incorrect

    • An 80-year old lady has a background history of a previous myocardial infarction which has left permanent damage to her heart's conduction system. The part of the conduction system with the highest velocities is damaged, and this has resulted in desynchronisation of the ventricles. The part of the heart that conducts the fastest is which of the following?

      Your Answer:

      Correct Answer: Purkinje fibres

      Explanation:

      The electrical conduction system of the heart starts with the SA node which generates spontaneous action potentials.

      This is conducted across both atria by cell to cell conduction, and occurs at around 1 m/s. The only pathway for the action potential to enter the ventricles is through the AV node in a normal heart.
      At this site, conduction is very slow at 0.05ms, which allows for the atria to completely contract and fill the ventricles with blood before the ventricles depolarise and contract.

      The action potentials are conducted through the Bundle of His from the AV node which then splits into the left and right bundle branches. This conduction is very fast, (,2m/s), and brings the action potential to the Purkinje fibres.

      Purkinje fibres are specialised conducting cells which allow for a faster conduction speed of the action potential (,2-4m/s). This allows for a strong synchronized contraction from the ventricle and thus efficient generation of pressure in systole.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 143 - A normal woman at term, not in labour, has her arterial blood gas...

    Incorrect

    • A normal woman at term, not in labour, has her arterial blood gas analysed.

      Which set of results is most likely her own?

      Option - pH - PaCO2 - HCO3 - PaO2
      A - 7.35 - 28 mmHg (3.73 kPa) - 27 mmol/L - 104 mmHg (13.8kPa)
      B - 7.43 - 32 mmHg (4.27 kPa) - 21 mmol/L - 104 mmHg (13.8kPa)
      C - 7.44 - 36 mmHg (4.8 kPa) - 27 mmol/L - 104 mmHg (13.8kPa)
      D - 7.45 - 40 mmHg (5.33 kPa) - 21 mmol/L - 104 mmHg (13.8kPa)
      E - 7.46 - 44 mmHg (5.87kPa) - 21 mmol/L - 104 mmHg (13.8kPa)

      Your Answer:

      Correct Answer: B

      Explanation:

      Due to an increased tidal volume with little change or slight increase in respiratory rate, Minute ventilation at term is increased by about 50%. Hypothalamic function are thought to influence by Progesterone, oestradiol and prostaglandins. This causes a mild compensated respiratory alkalosis.

      Maternal PaCO2 is usually decreased to about 32 mmHg (4.27 kPa) as a result of this increased alveolar ventilation at term . A compensatory decrease in serum bicarbonate from 27 to 21 mmol/L by renal excretion lessens the impact of maternal alkalosis.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 144 - Using a negative feedback loop, Haem production is controlled by which of these...

    Incorrect

    • Using a negative feedback loop, Haem production is controlled by which of these enzymes?

      Your Answer:

      Correct Answer: ALA synthetase

      Explanation:

      Heme a exists in cytochrome a and heme c in cytochrome c; they are both involved in the process of oxidative phosphorylation. 5′-Aminolevulinic acid synthase (ALA-S) is the regulated enzyme for heme synthesis in the liver and erythroid cells.

      There are two forms of ALA Synthase, ALAS1, and ALAS2.

    • This question is part of the following fields:

      • Physiology
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  • Question 145 - A 54-year-old lady comes in for a right-sided elective bunionectomy with a realignment...

    Incorrect

    • A 54-year-old lady comes in for a right-sided elective bunionectomy with a realignment osteotomy under local anaesthetic on her first (large) toe.

      For the operation, which of the following nerve blocks will be most effective?

      Your Answer:

      Correct Answer: Superficial peroneal, deep peroneal and posterior tibial nerves

      Explanation:

      An ankle block is commonly used for anaesthesia and postoperative analgesia when operating on bunions. It results in the selective block of the superficial peroneal, deep peroneal, and posterior tibial nerves.

      The deep peroneal nerve supplies sensory input to the web space between the first and second toes (L4-5).

      The L2-S1 nerve, often known as the superficial peroneal nerve, is a mixed motor and sensory neuron. It gives sensory supply to the anterolateral region of the leg, the anterior aspect of the 1st, 2nd, 3rd, and 4th toes, and innervates the peroneus longus and brevis muscles (with the exception of the web space between 1st and 2nd toes).

      The sensory area of the saphenous nerve (L3-4) in the foot stretches from the proximal portion of the midfoot on the medial side to the proximal part of the midfoot on the lateral side.

      The lateral side of the little (fifth) toe is innervated by the sural nerve’s sensory supply (S1-2). The heel, medial (medial plantar nerve), and lateral (lateral plantar nerve) soles of the foot are all served by the posterior tibial nerve.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 146 - What is factually correct regarding correlation and regression? ...

    Incorrect

    • What is factually correct regarding correlation and regression?

      Your Answer:

      Correct Answer: Regression allows one variable to be predicted from another variable

      Explanation:

      Linear regression, using a technique called curve fitting, allows us to make predictions regarding a certain variable.

      Correlation coefficient gives us an idea whether or not the two parameters provide have any relation of some sort or not i.e. does change in one prompt any change in other?

    • This question is part of the following fields:

      • Statistical Methods
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      Seconds
  • Question 147 - The cardiac muscle will primarily utilize which metabolic substrate to produce energy when...

    Incorrect

    • The cardiac muscle will primarily utilize which metabolic substrate to produce energy when at rest?

      Your Answer:

      Correct Answer: Fatty acids

      Explanation:

      Approximately 70% of the heart’s ATP requirement is met by cardiac mitochondria through beta-oxidation of fatty acids at rest. The remaining 30% is supplied by glucose.

      Amino acids and ketones, in the presence of ketoacidosis, may supply at most 10% of the ATP requirement. And, when in high levels, lactate may also contribute to the ATP requirement of the heart, particularly during moments of high muscular activity.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 148 - A 70-year old male has diverticular disease and is undergoing a sigmoid colectomy....

    Incorrect

    • A 70-year old male has diverticular disease and is undergoing a sigmoid colectomy. His risk of developing a post operative would infection can be minimized by which of the following interventions?

      Your Answer:

      Correct Answer: Administration of single dose of broad spectrum antibiotics prior to the procedure

      Explanation:

      Staphylococcus aureus infection is the most likely cause.

      Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.

      SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
      The organisms are usually derived from the patient’s own body.

      Measures that may increase the risk of SSI include:
      -Shaving the wound using a single use electrical razor with a disposable head
      -Using a non iodine impregnated surgical drape if one is needed
      -Tissue hypoxia
      -Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.

      Measures that may decrease the risk of SSI include:
      1. Intraoperatively
      – Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
      -Cover surgical site with dressing

      In contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.

      2. Post operatively
      Tissue viability advice for management of surgical wounds healing by secondary intention

      Use of diathermy for skin incisions
      In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 149 - A 25-year -old man, presents with a suspected uretic colic and is placed...

    Incorrect

    • A 25-year -old man, presents with a suspected uretic colic and is placed on admission. An abdominal x-ray of the kidney, ureter and bladder (KUB) is ordered.

      Where is the stone most likely to be located on x-ray?

      Your Answer:

      Correct Answer: The tips of the transverse processes between L2 and L5

      Explanation:

      The ureter runs anterior to the vertebrae at the level of L2 to L5, and stones are usually seen at these points on x-ray.

      They can also be seen at the level of the sacro-iliac joints.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 150 - The following statements are about capnography. Which of them is true? ...

    Incorrect

    • The following statements are about capnography. Which of them is true?

      Your Answer:

      Correct Answer: Collision broadening is due to presence of other polyatomic molecules

      Explanation:

      Capnography is the non-invasive measurement and pictorial display of inhaled and exhaled carbon dioxide (CO2) partial pressure.

      It is depicted graphically as the concentration of CO2 over time.

      It is used in disease diagnosis, determining disease severity, assessing response to treatment and is the best method to for indicating when an endotracheal tube is placed in the trachea after intubation.

      The wavelength of IR light usually absorbed by nitrous oxide is between 4.4-4.6?m (very close to that of CO2). Its absorption of wavelengths at 3.9 ?m is much weaker. It causes a measurable deficit of 0.1% for every 10% of nitrous oxide. The maximal wavelength of infrared (IR) light absorbed by carbon monoxide is 4.7 ?m. The volatile agents have strong absorption bands at 3.3 ?m and throughout the ranges 8-12 ?m.

      IR light is not absorbed by oxygen (O2), but O2 and CO2 molecules are constantly colliding which interrupts the absorption of IR light by CO2. This increases the band of absorption, that is the Collison or pressure broadening). An oxygen percentage of 95 will result in a 0.5 percentage fall in CO2 measure.

      IR light is also absorbed by water vapour which will result in an overlap of the absorption band, collision broadening and a dilution of partial pressure. This is why water trap and water permeable tubing is recommended for use as it reduces measurement inaccuracies.

      The use of multi-gas analysers of modern gases also help reduce the effects of collision broadening.

      Beer’s law is also applied in this system as an increase in the concentrations of CO2 causes a decrease in the amount of IR able to pass through the gas. This IR light is what generated the signal that is analysed for display.

      The capnograph can indicate oesophageal intubation, but cannot determine if it is endotracheal or endobronchial. For this, auscultation is used.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 151 - A pulmonary function tests results are:

    Measurement Predicted result Test result
    Forced vital capacity (FVC)...

    Incorrect

    • A pulmonary function tests results are:

      Measurement Predicted result Test result
      Forced vital capacity (FVC) (btps) 3.85 2.36
      Forced expiratory volume in 1 second (FEV1) (btps) 3.34 0.97
      FEV1/FVC ratio % (btps) 85.1 39.9
      Peak expiratory flow (PEF) (L/second) 7.33 2.11
      Maximum voluntary ventilation (MVV) (L/minute) 116 44.4

      What does this indicate?

      Your Answer:

      Correct Answer: Moderate restrictive and severe obstructive picture

      Explanation:

      Severity of a reduction in restrictive defect (%FVC) or obstructive defect (%FEV1/FVC) predicted are classified as follows:

      Mild 70-80%
      Moderate 60-69%
      Moderately severe 50-59%
      Severe 35-49%
      Very severe <35% This patient has a mixed deficit with a severe obstructive deficit as %FEV1/FVC predicted is 46.9% and a moderate restrictive deficit as %FVC of predicted is 61.3 FEV1/FVC ratio 80% < predicted and VC < 80% = mixed picture. FEV1/FVC ratio 80% < predicted and VC > 80% = obstructive picture.

      FEV1/FVC ratio 80% > predicted and VC > 80% = normal picture.

      FEV1/FVC ratio 80% > predicted and VC < 80% predicted= restrictive picture.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 152 - The prostate and the rectum are separated by which anatomical plane? ...

    Incorrect

    • The prostate and the rectum are separated by which anatomical plane?

      Your Answer:

      Correct Answer: Denonvilliers fascia

      Explanation:

      The prostate is separated from the rectum by the Denonvilliers fascia (rectoprostatic fascia).

      Waldeyers fascia functions to separate the rectum and the sacrum.

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 153 - Considering research studies, which of the following is considered as a limitation of...

    Incorrect

    • Considering research studies, which of the following is considered as a limitation of the Delphi method?

      Your Answer:

      Correct Answer: Potential low response rates

      Explanation:

      The Delphi technique was developed in the 1950s and is a widely used and accepted method for achieving convergence of opinion concerning real-world knowledge solicited from experts within certain topic areas. Choosing the appropriate subjects is the most important step in the entire process because it directly relates to the quality of the results generated, despite this, there is no exact criterion currently listed in the literature concerning the selection of Delphi participants.

      Therefore, due to the potential scarcity of qualified participants and the relatively small number of subjects used in a Delphi study, the ability to achieve and maintain an ideal response rate can either ensure or jeopardize the validity of a Delphi study.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 154 - A patient is being prepped for major bowel surgery. Alice, a final-year medical...

    Incorrect

    • A patient is being prepped for major bowel surgery. Alice, a final-year medical student, observes the surgery but is asked to scrub in and assist the anaesthetist during intubation. The anaesthetist inserts the laryngoscope and asks Alex to locate the larynx.

      What anatomical landmark corresponds to the position of the larynx?

      Your Answer:

      Correct Answer: C3-C6

      Explanation:

      The larynx is an air passage, sphincter, and organ of phonation that extends from the tongue to the trachea. It lies in the anterior part of the neck at the vertebral levels C3 to C6.

      Important anatomical landmarks:
      C1-C2 – Atlas and axis, respectively

      C3-C6 – Larynx

      C5 – Thyroid cartilage

      T5-T7 – Pulmonary hilum

      T12-L1 – Duodenum

    • This question is part of the following fields:

      • Anatomy
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  • Question 155 - Which of these anaesthetics has the best chance of preventing HPV (hypoxic pulmonary...

    Incorrect

    • Which of these anaesthetics has the best chance of preventing HPV (hypoxic pulmonary vasoconstriction)?

      Your Answer:

      Correct Answer: Desflurane 2 MAC

      Explanation:

      Resistance pulmonary arteries constrict in response to alveolar and airway hypoxia, diverting blood to better-oxygenated alveoli.

      In atelectasis, pneumonia, asthma, and adult respiratory distress syndrome, hypoxic pulmonary vasoconstriction optimises O2 uptake. Hypoxic pulmonary vasoconstriction helps maintain systemic oxygenation during single-lung anaesthesia.

      A redox-based O2 sensor within pulmonary artery smooth muscle cells is involved in hypoxic pulmonary vasoconstriction. The production of reactive oxygen species by smooth muscle cells in the pulmonary artery varies in proportion to PaO2. Hypoxic removal of these redox second messengers inhibits voltage-gated potassium channels, depolarizing smooth muscle cells in the pulmonary artery.

      L-type calcium channels are activated by depolarization, which raises cytosolic calcium and causes hypoxic pulmonary vasoconstriction. Some anaesthetics suppress this response, increasing the risk of further deterioration in ventilation perfusion mismatch.

      Agents that inhibit HPV are ether, halothane, and desflurane (>1.6 MAC).
      Agents with no effect on HPV include thiopentone, fentanyl, desflurane (1MAC), isoflurane (<1.5MAC), sevoflurane(1MAC), and propofol.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 156 - During a stabbing incident, a 30-year-old injured his inferior vena cava. What number...

    Incorrect

    • During a stabbing incident, a 30-year-old injured his inferior vena cava. What number of functional valves can be usually found in this vessel?

      Your Answer:

      Correct Answer: 0

      Explanation:

      The inferior vena cava is formed by the union of the right and left common iliac veins. The inferior vena cava has no functional valves like the one-way valves commonly found in many veins. The forward flow to the heart is driven by the differential pressure created by normal respiration.

      The absence of functional valves has an important clinical role when cannulating during cardiopulmonary bypass.

      There is a valve that is non-functioning called the eustachian valve that lies at the junction of the IVC and the right atrium. This valve has a role to help direct the flow of oxygen-rich blood through the right atrium to the left atrium via the foramen ovale during fetal life. It has no specific function in adult life.

    • This question is part of the following fields:

      • Anatomy
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  • Question 157 - A 27-year-old woman presents to emergency department. She is experiencing generalised seizures.

    She is...

    Incorrect

    • A 27-year-old woman presents to emergency department. She is experiencing generalised seizures.

      She is given emergency management of her symptoms before being referred to the neurologist who diagnoses her with new onset of tonic-clonic epilepsy.

      What is the most appropriate first line of treatment?

      Your Answer:

      Correct Answer: Lamotrigine should be offered as first line of treatment

      Explanation:

      Tonic-clonic (Grand mal) epilepsy is characterised by a general loss of consciousness with violent involuntary muscle contractions.

      The NICE guidelines for treatment indicates the use of sodium valproate and lamotrigine, but sodium valproate unsuitable in this case and she is a woman of reproductive age and it is known to have teratogenic effects. Lamotrigine is a more suitable choice, prescribed as 800mg daily.

      NICE guidelines also advice an additional prescription of 5mg of folic acid daily for women on anticonvulsant therapy looking to get pregnant. It also warns of the need for extra contraceptive precaution as there is a possibly that the anticonvulsant agent can reduce levels of contraceptive agents.

      Stimulation of the vagal nerve stimulation is only necessary in patients who are refractory to medical treatment and not candidates for surgical resection.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 158 - Which statement is correct about the Mapleson anaesthetic breathing circuits? ...

    Incorrect

    • Which statement is correct about the Mapleson anaesthetic breathing circuits?

      Your Answer:

      Correct Answer: Mapleson A is most efficient for spontaneous ventilation

      Explanation:

      Mapleson breathing system (or circuit) analysed five different arrangements of components of the breathing system:
      Mapleson A – It is the most efficient for spontaneous respiration. The flow of fresh gas required is 70-85 ml/kg/min, i.e., approximately 5-6 lit./min fresh gas flow for an average adult.
      Mapleson B and C – inefficient for both SV and PPV; requires gas flow of two to three times minute volume (100 ml/kg/min). Not commonly used but category C may be used for emergency resuscitation.
      Mapleson D – efficient for PPV at gas flow equivalent to patient’s minute volume; the Bain’s circuit is a coaxial version of the Mapleson D
      Mapleson E and F – for paediatric use; requires gas flow at two to three times the patient’s minute volume. The Mapleson F consists of an open-ended reservoir bag (Jackson-Rees modification).

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 159 - A paediatric patient was referred to the surgery department after an initial assessment...

    Incorrect

    • A paediatric patient was referred to the surgery department after an initial assessment of acute gastroenteritis was proven otherwise to be a case acute appendicitis. History revealed multiple episodes of non-bloody emesis. In the paediatric ward, the patient had already undergone fluid resuscitation and replacement, and electrolytes were already corrected. Other pertinent laboratory studies were the following:

      Serum Na: 138 mmol/l
      Blood glucose: 6.4 mmol/l

      If the patient weighed 25 kg, which intravenous fluid maintenance regimen would be best for the child?

      Your Answer:

      Correct Answer: 65 ml/hr Hartmann's solution with 0% glucose

      Explanation:

      Maintenance therapy aims to replace water and electrolytes lost under ordinary conditions. In the perioperative period, maintenance fluid administration may not sufficiently account for the increased fluid requirements caused by third-space losses into the interstitium and gut. Specific recommendations vary with the patient, the procedure, and the type and amount of fluid administered during the operation. The fluid for maintenance therapy replaces deficits arising primarily from insensible losses and urinary or gastrointestinal (GI) losses.

      The maintenance fluid volume can be computed using the Holliday-Segar method.

      Body weight Fluid volume
      first 10 kg 4 ml/kg/hr
      next 10-20 kg 2 ml/kg/hr
      >20 kg 1 ml/kg/hr

      In the past few years, there has been growing recognition of the increased risk of hyponatremia in hospitalized children in intensive care and postoperative settings who receive hypotonic maintenance fluids. Several studies, including a randomized controlled trial and a Cochrane analysis, found that the use of isotonic fluids is associated with fewer electrolyte derangements and concluded that isotonic maintenance fluids are preferable to hypotonic solutions in hospitalized children.

      A European consensus statement suggests that an intraoperative fluid should have an osmolarity close to the physiologic range in children in order to avoid hyponatremia, an addition of 1-2.5% in order to avoid hypoglycaemia, lipolysis or hyperglycaemia and should also include metabolic anions as bicarbonate precursors to prevent hyperchloremic acidosis.

      A rate of 40 ml/hr is suboptimal.

      If 0.9% NaCl with 0% glucose is given at a rate of 65 ml/hr, despite of the correct infusion rate, large volumes can lead to hyperchloremic acidosis.

      If 0.18% NaCl with 4% glucose is given at a rate of 65 ml/hr, infusion of this fluid regimen can lead to hyponatremia because of its hypotonicity.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 160 - A new proton pump inhibitor (PPI) is being evaluated in elderly patients who...

    Incorrect

    • A new proton pump inhibitor (PPI) is being evaluated in elderly patients who are taking aspiring. Study designed has 120 patients receiving the PPI, while a control group of 240 individuals is given the standard PPI. Over a span of 6 years, 24 of the group receiving the new PPI had an upper GI bleed compared to 60 individuals who received the standard PPI.

      How would you calculate the absolute risk reduction?

      Your Answer:

      Correct Answer: 5%

      Explanation:

      Absolute risk reduction = (Control event rate) – (Experimental event rate)

      Experimental event rate = 24 / 120 = 0.2

      Control event rate = 60 / 240 = 0.25

      Absolute risk reduction = 0.25 – 0.2 = 0.05 = 5% reduction

    • This question is part of the following fields:

      • Statistical Methods
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      Seconds
  • Question 161 - Out of the following, which anatomical structure lies within the spiral groove of...

    Incorrect

    • Out of the following, which anatomical structure lies within the spiral groove of the humerus?

      Your Answer:

      Correct Answer: Radial nerve

      Explanation:

      The shaft of the humerus has two prominent features:
      1. Deltoid tuberosity – attachment for the deltoid muscle
      2. Radial or spiral groove – The radial nerve and profunda brachii artery lie in the groove

      Mid-shaft fractures of the humerus usually occur after a direct blow to the upper arm, which can occur after a fall or RTAs. The most important clinical significance of a mid-shaft humeral fracture is an injury to the radial nerve. The radial nerve originates from the brachial plexus and has roots of C5-T1. It crosses the spiral groove on the posterior side of the shaft of the humerus.
      On examination, the patient may have a wrist drop, loss or weakness of finger extension, and decreased or absent sensation to the posterior forearm, digits 1 to 3, and the radial half of the fourth digit.

      The following parts of the humerus are in direct contact with the indicated
      nerves:
      Surgical neck: axillary nerve.
      Radial groove: radial nerve.
      Distal end of humerus: median nerve.
      Medial epicondyle: ulnar nerve.

    • This question is part of the following fields:

      • Anatomy
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  • Question 162 - Infrared radiation is absorbed by asymmetric, polyatomic polar molecules like carbon dioxide (CO2).

    When...

    Incorrect

    • Infrared radiation is absorbed by asymmetric, polyatomic polar molecules like carbon dioxide (CO2).

      When measuring CO2 in gas samples, mainstream capnography uses this physical principle.

      Which of the following gases is most likely to interfere with carbon dioxide's absorption spectrum?

      Your Answer:

      Correct Answer: Nitrous oxide

      Explanation:

      Carbon dioxide absorbs the most infrared (IR) light between the wavelengths of 4.2-4.4m (4.26m is ideal).

      Nitrous oxide absorbs infrared light at wavelengths of 4.4-4.6m (very similar to CO2) and less so at 3.9m.

      At a frequency of 4.7m, carbon monoxide absorbs the most IR light.

      At 3.3 m and throughout the ranges 8-12 m, the volatile agents have strong absorption bands.

      Although oxygen does not absorb infrared light, it collides with CO2 molecules, interfering with absorption. The absorption band is widened as a result of this (so called collision or pressure broadening). A drop of 0.5 percent in measured CO2 can be caused by 95% oxygen.

      Nitrous oxide causes a greater inaccuracy of 0.1 percent per ten percent of nitrous oxide.

      Water vapour absorbs infrared light as well, resulting in absorption band overlap, collision broadening, and partial pressure dilution. Water traps and water permeable tubing are used to reduce inaccuracies.

      Collision broadening is compensated for in modern gas multi-gas analysers.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 163 - The tissue layer in a patient is infiltrated with local anaesthetic (marcaine 0.125%)...

    Incorrect

    • The tissue layer in a patient is infiltrated with local anaesthetic (marcaine 0.125%) with 1 in 120,000 adrenaline as part of an enhanced recovery programme for primary hip replacement surgery. The total volume of solution is 120mL.

      What is the appropriate combination of constituents in the final solution?

      Your Answer:

      Correct Answer: 30mL 0.5% bupivacaine, 1mL 1 in 1,000 adrenaline and 89mL 0.9% N. Saline

      Explanation:

      30mL 0.5% bupivacaine, 1mL 1 in 1,000 adrenaline and 89mL 0.9% N. Saline is the correct answer.
      Initial concentration of bupivacaine is 0.5% with a volume of 30mL

      The volume is doubled (60mL) by the addition of 0.9% N. saline (30mls) and the concentration of bupivacaine is halved to (0.25%).

      If the volume is doubled again (120mL) by the addition of further 0.9% N. saline (59mls) the final concentration of bupivacaine is halved again to 0.125%. Total N. saline = 89mls

      The 1 mL of 1 in 1000 adrenaline has also been diluted into the final volume of 120 mL making it a 1 in 120000 concentration.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 164 - Which measurements is the most accurate for predicting fluid responsiveness? ...

    Incorrect

    • Which measurements is the most accurate for predicting fluid responsiveness?

      Your Answer:

      Correct Answer: Change in stroke volume following passive straight leg raise

      Explanation:

      The passive leg raising (PLR) manoeuvre is a method of altering left and right ventricular preload and it is done with real-time measurement of stroke volume. It is a simple, quick, relatively unbiased, and accurate bedside test to guide fluid management and avoid fluid overload.

      Pulse pressure variation (PPV), Stroke volume variation (SVV), superior vena cava diameter variation (threshold 36%) and end-expiratory occlusion test are used for dynamic tests of fluid responsiveness.

      PPV is derived peripherally from the arterial pressure waveform.

      Stroke volume variation (SVV) can be derived peripherally through pulse contour analysis of the arterial waveform. PPV and SVV have a threshold of 12% but since they are not used in patients who have cardiac arrhythmias, are spontaneous breathing, and in ventilated patients with low lung compliance and tidal volumes, they are of limited value.

      The tests of fluid responsiveness’ accuracy is determined by calculating the area under the receiver operating characteristic curve (UROC) obtained by plotting the sensitivity of the parameter in predicting fluid responsiveness vs. 1-specificity.

      Under optimal conditions, the ability to determine the need for fluid is best with PPV>SVV>LVEDA>CVP.

      Central venous pressure (CVP) is a static test of preload (not preload responsiveness) and a key determinant of cardiac function. The left ventricular end-diastolic area (LVEDA) a static test of fluid responsiveness, is derived using echocardiography

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 165 - A transport ventilator connected to a size CD oxygen cylinder has a setting...

    Incorrect

    • A transport ventilator connected to a size CD oxygen cylinder has a setting of air/oxygen entrainment ratio of 1:1 and a minute volume set at 10 litres/minute.

      Which value best approximates to the FiO2?

      Your Answer:

      Correct Answer: 0.6

      Explanation:

      A nominal volume of 2 litres is contained in a CD cylinder. It has a pressure of 230 bar when full and contains litres 460 L of useable oxygen at STP.

      For every 1000 mL 100% oxygen there will be an entrainment of 1000 mL or air (20% oxygen) in an air/oxygen mix.

      The average concentration is, therefore, 120/2=60% or 0.6.

    • This question is part of the following fields:

      • Physiology
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  • Question 166 - The liver plays a major role in drug metabolism.

    Which of the following...

    Incorrect

    • The liver plays a major role in drug metabolism.

      Which of the following liver cells is most important in phase I of drug metabolism?

      Your Answer:

      Correct Answer: Centrilobular cells

      Explanation:

      The metabolism of drugs in the liver occurs in 3 phases

      Phase I: This involves functionalization reactions, which are of 3 types, namely hydrolysis, oxidation and reduction reactions catalysed by the cytochrome P450 (CYP) enzymes.

      Phase II: This involves conjugation or acetylation reactions. The goal is to create water soluble metabolites that can be excreted from the body.

      The liver is the second largest organ. It’s smallest functional unit is the acinus which is divided into 3 zones:

      Zone I (periportal): This zone receives the largest amount of oxygen supply as it is the closest to the blood vessels. It is the site of plasma protein synthesis.

      Zone II (mediolobular): This is located between the portal triad and central vein.

      Zone III (centrilobular): This is closest to the central vein and receives the least amount of oxygen supply.

      Kupffer cells are specialized macrophages found in the periportal zone of the liver, and function to remove foreign particles and breakdown red blood cells via phagocytosis.

      Ito cells are fat-storing liver cells found in the space of Disse. Their function is to take-uo, store and secrete retinoids, as well as manufacture and release proteins that make up the extracellular matrix.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 167 - A global cerebral blood flow (CBF) of 35 ml/100 g/min (Normal CBF =...

    Incorrect

    • A global cerebral blood flow (CBF) of 35 ml/100 g/min (Normal CBF = 54 ml/100 g/min) can lead to which of the following?

      Your Answer:

      Correct Answer: Poor prognostic EEG

      Explanation:

      CBF is defined as the blood volume that flows per unit mass per unit time in brain tissue and is typically expressed in units of ml blood/100 g tissue/minute. The normal average CBF in adults human is about 50 ml/100 g/min, with lower values in the white matter (,20 ml/100 g/min) and greater values in the gray matter (,80 ml/100 g/min).

      Low CBF levels between 30-40 ml/100 g/min may begin to show poor prognostic EEG. EEG findings consistently associated with a poor outcome are isoelectric EEG, low voltage EEG, and burst suppression (specifically burst suppression with identical bursts), as well as the absence of EEG reactivity.

    • This question is part of the following fields:

      • Physiology
      0
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  • Question 168 - A 74-year-old man presents to a hospital for manipulation of Colles fracture. The...

    Incorrect

    • A 74-year-old man presents to a hospital for manipulation of Colles fracture. The patient is 50 kg and the anaesthetic plan is to perform an intravenous regional (Bier's) block.

      Which of the following is the appropriate dose of local anaesthetic for the procedure?

      Your Answer:

      Correct Answer: 0.5% prilocaine (40 ml)

      Explanation:

      Prilocaine is the drug of choice for intravenous regional anaesthesia. 0.5% prilocaine (40 ml) is indicated for this condition.
      Lidocaine is another alternative for this condition but volume and dose are likely to be inadequate for the procedure.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 169 - The plateau phase of the myocardial action potential is as a result of:...

    Incorrect

    • The plateau phase of the myocardial action potential is as a result of:

      Your Answer:

      Correct Answer: Slow influx of calcium

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 170 - What is the mechanism of the pupillary reflex arc? ...

    Incorrect

    • What is the mechanism of the pupillary reflex arc?

      Your Answer:

      Correct Answer: Oculomotor nerve fibres from the Edinger-Westphal nuclei

      Explanation:

      Pupil size is reduced by the pupillary light reflex and during accommodation for near vision. In the pupillary light reflex, light that strikes the retina is processed by retinal circuits that excite W-type retinal ganglion cells. These cells respond to diffuse illumination. The axons of some of the W-type cells project through the optic nerve and tract to the pretectal area, where they synapse in the olivary pretectal nucleus. This nucleus contains neurons that also respond to diffuse illumination. Activity of neurons of the olivary pretectal nucleus causes pupillary constriction by means of bilateral connections with parasympathetic preganglionic neurons in the Edinger-Westphal nuclei. The reflex results in contraction of the pupillary sphincter muscles in both eyes, even when light is shone into only one eye.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 171 - Clearance techniques are used to assess renal glomerular function.

    Which of the following is...

    Incorrect

    • Clearance techniques are used to assess renal glomerular function.

      Which of the following is the most accurate marker for glomerular filtration rate measurement?

      Your Answer:

      Correct Answer: Inulin

      Explanation:

      The perfect glomerular filtration marker is:

      The human body is not harmed by it.
      Chemical or physical methods are used to accurately measure
      Extracellular fluid (ECF) compartment is freely and evenly diffusible.
      Inability to access the intracellular fluid (ICF) compartment
      Filtration in the kidney is the only way to remove it from the blood.

      The ideal marker should not be reabsorbed into the bloodstream by the renal tubules or other urinary system components.

      Creatinine is an endogenous substance that is filtered freely by the glomerulus and secreted by the proximal tubule. As a result, creatinine clearance consistently underestimates GFR. In healthy people, this overestimation ranges from 10% to 40%, but it is higher and more unpredictable in patients with chronic kidney disease.

      The gold standard method of inulin clearance necessitates an intravenous infusion and several hours of timed urine collection, making it costly and time-consuming. Inulin is hard to come by and is difficult to mix and keep as a solution.

      Exogenous filtration markers include the following:

      Although plasma clearance of 51chromium EDTA is a widely used method in Europe, tubular reabsorption can occur.
      Because 125I-iothalamate can be excreted by renal tubules in the urine, it cannot be used in patients who have an iodine assay.

      Radioactive substances must be stored, administered, and disposed of according to these methods.

      The glomerulus filters para-aminohippuric acid (PAH) freely, and any that remains in the peritubular capillaries is secreted into the proximal convoluted tubules. This marker is used to determine the amount of blood flowing through the kidneys.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 172 - Which of the following statements is true regarding Adrenaline or Epinephrine? ...

    Incorrect

    • Which of the following statements is true regarding Adrenaline or Epinephrine?

      Your Answer:

      Correct Answer: Stimulates ACTH secretion

      Explanation:

      Adrenaline is released by the adrenal glands, acts on ? 1 and 2, ? 1 and 2 receptors, and is responsible for fight or flight response.

      It acts on ? 2 receptors in skeletal muscle vessels-causing vasodilation.

      It acts on ? adrenergic receptors to inhibit insulin secretion by the pancreas. It also stimulates glycogenolysis in the liver and muscle, stimulates glycolysis in muscle.

      It acts on ? adrenergic receptors to stimulate glucagon secretion in the pancreas
      It also stimulates Adrenocorticotrophic Hormone (ACTH) and stimulates lipolysis by adipose tissue

    • This question is part of the following fields:

      • Pharmacology
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  • Question 173 - Regarding a paramagnetic oxygen analyser, the following statements are TRUE: ...

    Incorrect

    • Regarding a paramagnetic oxygen analyser, the following statements are TRUE:

      Your Answer:

      Correct Answer: Utilises null deflection

      Explanation:

      The electrons in the outer shell of an oxygen molecule are unpaired, thus it has paramagnetic properties and is attracted into a magnetic field.

      It utilizes null deflection -True
      Null deflection is a crucial principle in paramagnetic analysers (reflected beam of light on two photocells) which gives very accurate results (typically 0.1%).

      It can be used to measure the concentration of diamagnetic gases – False
      Since most other gases are weakly diamagnetic they are repelled by a magnetic field (nitric oxide is also paramagnetic).

      Can measure gases dissolved in the blood – False
      For accurate analysis the sample gas must be dried before passing into the analysis cell, for example, by passage through silica gel. Therefore, they are unsuitable to measure gases dissolved in blood.

      Does not require calibration – False
      As with most measurement instruments paramagnetic analysers must be calibrated before use.

      E) The readings are unaffected by water vapour – False
      Water vapour affects the readings hence for accurate analysis the sample gas must be dried before passing into the analysis cell, for example, by passage through silica gel. That is why they are unsuitable to measure dissolved blood gases.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 174 - Which of the following is a true statement about invasive arterial pressure monitoring?...

    Incorrect

    • Which of the following is a true statement about invasive arterial pressure monitoring?

      Your Answer:

      Correct Answer: Increased resonance elevates the systolic and lower the diastolic pressures

      Explanation:

      The arterial cannula inserted should have parallel walls in order to reduce the risk of interruption of blood flow to distal limbs.

      It is essential that the monitor used to display the arterial pressure waves has a frequency capacity of 0.5-40Hz. This is because the pressure waves are a combination of different sine waves of varying frequencies and amplitudes.

      The diameter of the catheter is directly proportional to the natural frequency which is the frequency at which the system responsible for monitoring the waves resonates and amplifies the signals. This should be at least ten fold in comparison to the fundamental frequency. The diameter of the catheter is also inversely proportional to the square root of the system compliance, the tubing length and the fluid density within the system.

      The presence of an air bubble, a clot or an easily malleable diaphragm and tube can result in wave damping. Increased damping will cause a reduction in the systolic pressure, and an increase in diastolic pressure. The maximum damping value of an appropriate monitoring system would be 0.64.

      A rigid, non-malleable diaphragm and tubing can cause a resonance within the system. This resonance will result in an increase in the systolic pressure and a reduction in the diastolic pressure

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 175 - A young male is undergoing inguinal hernia repair. During the procedure, the surgeons...

    Incorrect

    • A young male is undergoing inguinal hernia repair. During the procedure, the surgeons approach the inguinal canal and expose the superficial inguinal ring.

      Which structure forms the lateral edge of the superficial inguinal ring?

      Your Answer:

      Correct Answer: External oblique aponeurosis

      Explanation:

      The superficial inguinal ring is an opening in the aponeurosis of the external oblique muscle, just above and lateral to the pubic crest.

      The superficial ring resembles a triangle more than a ring with the base lying on the pubic crest and its apex pointing towards the anterior superior iliac spine. The sides of the triangle are crura of the opening in the external oblique aponeurosis. The lateral crura of the triangle is attached to the pubic tubercle. The medial crura of the triangle is attached to the pubic crest.

      The external oblique aponeurosis forms the anterior wall of the inguinal canal and also the lateral edge of the superficial inguinal ring. The rectus abdominis lies posteromedially, and the transversalis posterior to this.

    • This question is part of the following fields:

      • Anatomy
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  • Question 176 - Which of the following statement is true regarding the mechanism of action of...

    Incorrect

    • Which of the following statement is true regarding the mechanism of action of macrolides?

      Your Answer:

      Correct Answer: Inhibits protein synthesis

      Explanation:

      The mechanism of action of macrolides is inhibition of bacterial protein synthesis by preventing peptidyltransferase from adding to the growing peptide which is attached to tRNA to the next amino acid.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 177 - Which of the following statement is not true regarding the effects of Dopamine...

    Incorrect

    • Which of the following statement is not true regarding the effects of Dopamine infusions?

      Your Answer:

      Correct Answer: Decreasing gastric transit time

      Explanation:

      Moderately high doses of dopamine produce a positive inotropic (direct?1 and D1 action + that due to Noradrenaline release), but the little chronotropic effect on the heart.

      Vasoconstriction (?1 action) occurs only when large doses are infused.

      At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 178 - Prophylactic antibiotics are required for which of the following procedures? ...

    Incorrect

    • Prophylactic antibiotics are required for which of the following procedures?

      Your Answer:

      Correct Answer: Appendicectomy

      Explanation:

      Correctly used, antibiotic prophylaxis can reduce
      the total use of antibiotics.
      There is strong scientific support that antibiotic
      prophylaxis reduces the development of infection after:

      • Operations and endoscopic procedures in the large intestine,
        the rectum, and the stomach (including appendectomies and
        penetrating abdominal trauma), and after percutaneous endoscopic gastrostomy (PEG)
      • Cardiovascular surgery, and insertion of pacemakers
      • Breast cancer surgery
      • Hysterectomy
      • Reduction of simple fractures and prosthetic limb surgery
      • Complicated surgery for cancer in the ear, nose, and throat
        regions
      • Transrectal biopsy and resection of the prostate (febrile urinary
        tract infection and blood poisoning).

      In most cases the scientific evidence is inadequate to determine
      which type of antibiotic is most effective for antibiotic prophylaxis.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 179 - A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a...

    Incorrect

    • A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a 57-year-old woman. Her vision is causing her problems.

      A macroadenoma compressing the optic chiasm is visible on MRI.

      What is the most likely visual field defect to be discovered during an examination?

      Your Answer:

      Correct Answer: Bitemporal hemianopia

      Explanation:

      The pituitary gland plays a crucial role in the neuro-endocrine axis. It is located at the base of the skull in the sella turcica of the sphenoid bone. It is connected superiorly to the hypothalamus, third ventricle, and visual pathways, and laterally to the cavernous sinuses, internal carotid arteries, and cranial nerves III, IV, V, and VI.

      Pituitary tumours make up about 10-15% of all intracranial tumours. The majority of adenomas are benign. Over-secretion of pituitary hormones (most commonly prolactin, growth hormone, or ACTH), under-secretion of hormones, or localised or generalised pressure effects can all cause symptoms.

      Compression of the optic chiasm can result in visual field defects, the most common of which is bitemporal hemianopia. This is caused by compression of the nasal retinal fibres, which carry visual impulses from temporal vision across the optic chiasm to the contralateral sides before continuing to the optic tracts.

      The interruption of the visual pathways distal to the optic chiasm causes a homonymous visual field defect. The loss of the right or left halves of each eye’s visual field is referred to as homonymous hemianopia. It’s usually caused by a middle or posterior cerebral artery territory stroke that affects the occipital lobe’s optic radiation or visual cortex.

      Binasal hemianopia is a condition in which vision is lost in the inner half of both eyes (nasal or medial). It’s caused by compression of the temporal visual pathways, which don’t cross at the optic chiasm and instead continue to the ipsilateral optic tracts. Binasal hemianopia is a rare complication caused by the internal carotid artery impinging on the temporal (lateral) visual fibres.

      A monocular visual loss (that is, loss of vision in only one eye) can be caused by a variety of factors, but if caused by nerve damage, the damage would be proximal to the optic chiasm on the ipsilateral side.

      A central scotoma is another name for central visual field loss. Every normal mammalian eye has a scotoma, also known as a blind spot, in its field of vision. The optic disc is a region of the retina that lacks photoreceptor cells and is where the retinal ganglion cell axons that make up the optic nerve exit the retina. When both eyes are open, visual signals that are absent in one eye’s blind spot are provided for the other eye by the opposite visual cortex, even if the other eye is closed.

      Scotomata can be caused by a variety of factors, including demyelinating disease such as multiple sclerosis, damage to nerve fibre layer in the retina, methyl alcohol, ethambutol, quinine, nutritional deficiencies, and vascular blockages either in the retina or in the optic nerve.

      Bilateral scotoma can occur when a pituitary tumour compresses the optic chiasm, causing a bitemporal paracentral scotoma, which then spreads out to the periphery, causing bitemporal hemianopsia. A central scotoma in a pregnant woman could be a sign of severe pre-eclampsia.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 180 - Intracellular effectors are activated by receptors on the cell surface. These receptors receive...

    Incorrect

    • Intracellular effectors are activated by receptors on the cell surface. These receptors receive signals that are relayed by second messenger systems.

      In the human body, which second messenger is most abundant?

      Your Answer:

      Correct Answer: Calcium ions

      Explanation:

      Second messengers relay signals to target molecules in the cytoplasm or nucleus when an agonist interacts with a receptor on the cell surface. They also amplify the strength of the signal. The most ubiquitous and abundant second messenger is calcium and it regulates multiple cellular functions in the body.

      These include:
      Muscle contraction (skeletal, smooth and cardiac)
      Exocytosis (neurotransmitter release at synapses and insulin secretion)
      Apoptosis
      Cell adhesion to the extracellular matrix
      Lymphocyte activation
      Biochemical changes mediated by protein kinase C.

      cAMP is either inhibited or stimulated by G proteins.

      The receptors in the body that stimulate G proteins and increase cAMP include:

      Beta (?1, ?2, and ?3)
      Dopamine (D1 and D5)
      Histamine (H2)
      Glucagon
      Vasopressin (V2).

      The second messenger for the action of nitric oxide (NO) and atrial natriuretic peptide (ANP) is cGMP.

      The second messengers for angiotensin and thyroid stimulating hormone are inositol triphosphate (IP3) and diacylglycerol (DAG).

    • This question is part of the following fields:

      • Physiology
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  • Question 181 - A graph is created to show the exponential relationship between bacterial growth (y-axis)...

    Incorrect

    • A graph is created to show the exponential relationship between bacterial growth (y-axis) and time (x-axis).

      Which of the following statements is most true about this kind of exponential relationship?

      Your Answer:

      Correct Answer: y = ex

      Explanation:

      The relationship between bacterial growth and time is a tear-away exponential. The mathematical relationship between y and x in this case is:

      y = ex

      Where: the power is x, and the base is e.

      Euler’s number (e) is a mathematical constant that is the base for all logarithms occurring naturally. Its value is 2.718.

      The statement X increasing with an increase in Y is proportional to Y refers to the change in y in terms of x when considering any exponential relationship.

      This is not a build-up exponential, and that is mathematically stated as y = 1-e-kt.

      The negative x axis being a horizontal asymptote and the y intercept being 0, 1 are examples of tearaway exponentials , but do not describe an exponential process.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 182 - Which of the following does Lidocaine 1% solution equate to? ...

    Incorrect

    • Which of the following does Lidocaine 1% solution equate to?

      Your Answer:

      Correct Answer: 1000 mg per 100 ml

      Explanation:

      Lidocaine 1% is formulated as 1000 mg/100 mL.

      % solution is based on (grams of medicine) / 100 ml

      % solution ~ (1000 mg) / 100 ml

      % solution ~ 10 mg/ml

      Examples:

        • Lidocaine 4% = 40 mg/ml of Lidocaine
        • Lidocaine 2% = 20 mg/ml of Lidocaine
        • Lidocaine 1% = 10 mg/ml of Lidocaine

    • This question is part of the following fields:

      • Pharmacology
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  • Question 183 - A trail has analysed that a new screening test may increase the survival...

    Incorrect

    • A trail has analysed that a new screening test may increase the survival time of ovarian cancer patients. But analyst say that the apparent increase in the patients survival time is just because of earlier detection instead of actual improvement.

      What kind of bias is in this experiment?

      Your Answer:

      Correct Answer: Lead time bias

      Explanation:

      Observation bias occurs when the behaviour of an individual changes that results from their awareness of being observed.

      Recall bias introduced when participants in a study are systematically more or less likely to recall and relate information on exposure depending on their outcome status.

      Attrition bias is a systematic error caused by unequal loss of participants from a randomized controlled trial (RCT). In clinical trials, participants might dropout due to unsatisfactory treatment or efficacy, intolerable adverse events, or even death.

      Selection bias introduced when the individuals are not chosen randomly to take a part in the study. It usually occurs when the research decides who is going to be studied, they are not the representative of the population.

      Lead-time bias occurs when a disease is detected by a screening test at an earlier time point rather than it would have been diagnosed by its clinical appearance. In this bias, earlier detection improves the survival time in the intervention group.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 184 - Which of the following anaesthetic is the least powerful trigger of malignant hyperthermia?...

    Incorrect

    • Which of the following anaesthetic is the least powerful trigger of malignant hyperthermia?

      Your Answer:

      Correct Answer: Desflurane

      Explanation:

      Desflurane is a highly fluorinated methyl ethyl ether used for the maintenance of general anaesthesia. It has been identified as a weak triggering anaesthetic of malignant hyperthermia. That, in the absence of succinylcholine, may produce a delayed onset of symptoms.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 185 - Regarding metal wires, which of the following is the most important determinant of...

    Incorrect

    • Regarding metal wires, which of the following is the most important determinant of their resistance?

      Your Answer:

      Correct Answer: Resistivity

      Explanation:

    • This question is part of the following fields:

      • Basic Physics
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  • Question 186 - In a study lasting over a period of two years, in which the...

    Incorrect

    • In a study lasting over a period of two years, in which the mean age of 800 patients was 82 years, the efficacy of hip protectors in reducing femoral neck fractures was discussed.

      Both experimental and control group had 400 members. Instances of fractures reported over the two year time duration were 10 for the control group (that were prescribed hip protector) and 20 for the control group.

      What is the value of Absolute Risk Reduction?

      Your Answer:

      Correct Answer: 0.025

      Explanation:

      ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)

      So,

      ARR= (10/400)-(20/400)

      ARR= 0.025-0.05

      ARR= 0.025 (Numerical Value)

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 187 - A 52-year-old patient is brought to ER with a chief complaint of chest...

    Incorrect

    • A 52-year-old patient is brought to ER with a chief complaint of chest pain for two hours. Chest pain was tightness in nature, located in the centre of the chest and radiate into the neck and left arm. The patient otherwise looks fit and well.

      Just after admitting the patient, he suffered VF cardiac arrest and is immediately defibrillated with the return of spontaneous circulation (ROSC).

      On clinical examination following was the finding:
      BP: 82/45 mmHg
      Heart rate: 120 beats/min
      Oxygen saturation on air: 25%
      Heart sounds: Normal
      There is no sign of pulmonary oedema. The patient is anxious, cold, and clammy.

      A 12 lead ECG was done which revealed a sinus rhythm of 120 with ST-segment depression and T wave inversion in leads II, III, and aVF. Which of the following is considered best for the initial treatment of the patient?

      Your Answer:

      Correct Answer: Oral aspirin

      Explanation:

      This is a classical case of unstable angina or NSTEMI (Non-ST-elevation myocardial infarction). As soon as the diagnosis of unstable angina or NSTEMI is made the initial treatment is Aspirin and antithrombin therapy.

      Betablocker is known to reduce mortality from acute myocardial infarction by reducing oxygen demand. If there is no contraindication (heart block, bradycardia, hypotension, severe left ventricular dysfunction, and asthma), a beta-blocker should be given early. This patient has hypotension and therefore metoprolol is contraindicated.

      If three doses of nitroglycerine tablets or Nitrolingual sprays and intravenous beta-blockers too cannot relieve the symptoms intravenous Glyceryl Trinitrate (GTN) should be considered provided that there is no hypotension. But in this case, the patient is hypotensive, and therefore, it is contraindicated.

      If the symptoms are not relieved after three serial doses of nitroglycerine or if symptoms recur despite adequate anti-anginal treatment morphine sulphate is indicated.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 188 - A 20-year-old woman, presented to her GP after swallowing a tiny, sharp bone...

    Incorrect

    • A 20-year-old woman, presented to her GP after swallowing a tiny, sharp bone and is referred to an ENT. She explains that the bone feels stuck in her throat. A laryngoscopy is performed and it shows the bone is lodged in the piriform recess.

      Name the nerve at highest risk of damage by the bone?

      Your Answer:

      Correct Answer: Internal laryngeal nerve

      Explanation:

      The internal laryngeal nerve lies inferior to the piriform recess mucous membrane, placing it at high risk of irritation or damage by sharp foreign objects which become lodged in the recess.

      Any attempt to retrieve lodged foreign objects must be done careful as there is also a high risk of damage during this process.

      The other mentioned nerves are not at risk of being affected.

    • This question is part of the following fields:

      • Anatomy
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  • Question 189 - A post-operative patient was given paracetamol and pethidine for post-operative analgesia. A few...

    Incorrect

    • A post-operative patient was given paracetamol and pethidine for post-operative analgesia. A few hours later, the patient developed fever of 38°C, hypertension, and agitation.

      According to the patient's medical history, he is maintained on Levodopa and Selegiline for Parkinson's disease.

      Which of the following is the most probable cause of his manifestation?

      Your Answer:

      Correct Answer: Pethidine

      Explanation:

      Selegiline is a monoamine oxidase inhibitor. Inhibition of monoamine oxidase leads to increased levels of norepinephrine and serotonin in the central nervous system.

      Pethidine, also known as meperidine, is a strong agonist at the mu and kappa receptors. It inhibits pain neurotransmission and blocks muscarinic-specific actions.

      Administering opioid analgesic is relatively contraindicated to individuals taking monoamine oxidase inhibitors. This is because of the high incidence of serotonin syndrome, which is characterized by fever, agitation, tremor, clonus, hyperreflexia and diaphoresis. Onset of symptoms is within hours, and the treatment is mainly through sedation, paralysis, intubation and ventilation.

      The clinical findings are more consistent with Serotonin syndrome rather than exacerbation of Parkinson’s. Parkinson’s Disease (PD) exacerbations are defined as patient-reported or caregiver-reported episodes of subacute worsening of PD motor function in 1 or more domains (bradykinesia, tremor, rigidity, or PD-related postural instability/gait disturbance) that caused a decline in functional status, developed over a period of < 2 months, did not fluctuate with medication timing, and are not caused by intentional adjustments of PD medications by the treating neurologist. Malignant hyperthermia usually occurs within minutes of administration of a volatile anaesthetic, such as halothane, or succinylcholine. There is massive release of calcium from the sarcoplasmic reticulum, leading to fever, acidosis, rhabdomyolysis, trismus, clonus, and hypertension. In sepsis, it more common for patients to present with hypotension rather than hypertension.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 190 - Which of the following nerves is responsible for carrying taste sensation from the...

    Incorrect

    • Which of the following nerves is responsible for carrying taste sensation from the given part of the tongue?

      Your Answer:

      Correct Answer: Anterior two thirds of tongue - facial nerve

      Explanation:

      Taste sensation from the anterior two-thirds of the tongue is carried by chorda tympani, a branch of the facial nerve.

      The general somatic sensation of the anterior two-third of the tongue is supplied by the lingual nerve, a branch of the mandibular nerve.

      Both general somatic sensation and taste from the posterior third of the tongue are carried by the glossopharyngeal nerve.

      All the muscles of the tongue except palatoglossus are supplied by the hypoglossal nerve whereas palatoglossus is supplied by the vagus nerve. (This is because palatoglossus is the only tongue muscle derived from the fourth branchial arch)

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 191 - Of the following, which is NOT a branch of the abdominal aorta? ...

    Incorrect

    • Of the following, which is NOT a branch of the abdominal aorta?

      Your Answer:

      Correct Answer: Superior phrenic artery

      Explanation:

      The abdominal aorta begins at the level of the body of T12 near the midline, as a continuation of the thoracic aorta. It descends and bifurcates at the level of L4 into the common iliac arteries.

      The branches of the abdominal aorta (with their vertebra level) are:
      1. Inferior phrenic arteries: T12 (upper border)
      2. Coeliac artery: T12
      3. Superior mesenteric artery: L1
      4. Middle suprarenal arteries: L1
      5. Renal arteries: Between L1 and L2
      6. Gonadal arteries: L2 (in males, it is the testicular artery, and in females, the ovarian artery)
      7. Inferior mesenteric artery: L3
      8. Median sacral artery: L4
      9. Lumbar arteries: Between L1 and L4

      The superior phrenic artery branches from the thoracic aorta.

    • This question is part of the following fields:

      • Anatomy
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  • Question 192 - A 20-year old lady has been having excessive bruising and bleeding of her...

    Incorrect

    • A 20-year old lady has been having excessive bruising and bleeding of her gums. She is under investigation for the extrinsic pathway of coagulation. Which is the best investigation to order?

      Your Answer:

      Correct Answer: Prothrombin time (PT)

      Explanation:

      The extrinsic pathway is best assessed by the PT time.

      D-dimer is a fibrin degradation product which is raised in the presence of blood clots.

      A 50:50 mixing study is used to assess if a prolonged PT or aPTT is due to factor deficiency or a factor inhibitor.

      The thrombin time is a test used to assess fibrin formation from fibrinogen in plasma. Factors that prolong the thrombin time include heparin, fibrin degradation products, and fibrinogen deficiency.

      Intrinsic pathway – Best assessed by APTT. Factors 8,9,11,12 are involved. Prolonged aPTT can be seen in haemophilia and use of heparin.

      Extrinsic pathway – Best assessed by Increased PT. Factor 7 involved.

      Common pathway – Best assessed by APTT & PT. Factors 2,5,10 involved.

      Vitamin K dependent factors are factors 2,7,9,10

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 193 - All of the following statements are true regarding calcium except: ...

    Incorrect

    • All of the following statements are true regarding calcium except:

      Your Answer:

      Correct Answer: Serum calcium accounts for 10% of total body calcium stores

      Explanation:

      Calcium is a very important ion and is involved in:
      -cell homeostasis
      -coagulation
      -muscle contraction
      -neuronal impulse transmission/membrane stabilization
      -bone formation and skeletal strength
      -secretion processes

      99% is found in bone and 1% in the plasma. Of the 1% that is in the plasma
      -45% is free ionized calcium
      -45% is bound to proteins, mainly Albumin
      -10% is present as an anion complex

      Reduced levels of IONIZED calcium give rise to features of hypocalcaemia , resulting in increased excitability of membranes. This results when the total calcium concentration goes below 2 mmol/L.

      Features of mild to moderate hypocalcaemia are:
      -paraesthesia (peri-oral, fingers)
      -tetany
      -spasm
      -muscle cramps
      -ECG changes (prolonged QT)
      -Trousseau’s sign (inflation of tourniquet induces carpopedal spasm)
      -Chvostek’s sign (tapping the facial nerve – cranial nerve VII – causes facial muscle twitch/spasm)

      Features of severe hypocalcaemia are:
      -cardiogenic shock and congestive cardiac failure due to reduced myocardial contractility
      respiratory distress due to bronchospasm, agitation, confusion, seizures

      Features of hypercalcaemia (remember ‘bones, stones, groans and psychic moans’):
      -Abdominal pain
      -Vomiting
      -Constipation
      -Polyuria
      -Polydipsia
      -Depression
      -Lethargy
      -Anorexia
      -Weight loss
      -Hypertension
      -Confusion
      -Pyrexia
      -Calcification in the cornea
      -Renal stones
      -Renal failure
      -Decreased Q-T interval
      -Cardiac shock/collapse

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 194 - A delayed hypersensitivity reaction is type ____? ...

    Incorrect

    • A delayed hypersensitivity reaction is type ____?

      Your Answer:

      Correct Answer: IV

      Explanation:

      Type I – immediate hypersensitivity reaction

      Examples are: Atopy, urticaria, Anaphylaxis, Asthma( IgE mediated).

      Type II – Antibody mediated cytotoxic reaction

      Examples are: Autoimmune haemolytic anaemia, Thrombocytopenia( IgM or IgG mediated).

      Type III – Immune complex mediated reaction

      Examples are: Serum sickness,SLE – IgG., Farmers lungs, rheumatoid arthritis

      Type IV – Delayed hypersensitivity reaction

      Examples are: Contact dermatitis, drug allergies.

      Type V – Autoimmune

      Graves’
      Myasthenia – IgM or IgG.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 195 - The Medical Admissions unit receives a 71-year-old woman. She has type 2 diabetes,...

    Incorrect

    • The Medical Admissions unit receives a 71-year-old woman. She has type 2 diabetes, which she manages with diet, but she has been feeling ill for the past 48 hours.

      Her pulse rate is 110 beats per minute, her blood pressure is 90/50 mmHg, and she is clinically dehydrated. Her respiratory rate is 20 breaths per minute, and chest auscultation reveals no focal signs.

      The following are the lab results:

      Glucose 27.4 mmol/L (3.5-5.5)
      Ketones 2.5 mmol/L (<0.1)
      Urinary glucose is zero (dipstick) with ketones

      A random blood glucose of 15.3 mmol/L was measured during a visit to the diabetic clinic one month prior to admission, according to her notes, and a urinary dipstick registered a high glucose and ketones++.

      The discrepancy between plasma and urinary glucose measurements is best explained by which of the following physiological mechanisms?

      Your Answer:

      Correct Answer: The glomerular filtration rate is abnormally low

      Explanation:

      The glucose molecule enters the Bowman’s capsule freely and becomes part of the filtrate.

      All glucose is reabsorbed in the proximal convoluted tubule when blood glucose concentrations are below a certain threshold (approximately 11 mmol/L) (PCT). Active transportation makes this possible. In the proximal tubular cells, sodium/glucose cotransporters (SGLT1 and SGLT2) are the proteins responsible.

      Glucose does not normally appear in the urine below the renal threshold.

      The renal glucose threshold is not set in stone and is affected by a variety of factors, including GFR, TmG, and the quantity of splay.

      The different absorptive and filtering capacities of individual nephrons cause splay, which is the rounding of a glucose reabsorption curve.

      The SGLT proteins have a high affinity for glucose, but not an infinite affinity. As a result, some glucose may escape reabsorption before the TmG. A decrease in renal threshold may be caused by an increase in splay.

      Because the filtered glucose load is reduced and the PCT can reabsorb all of the filtered glucose despite hyperglycaemia, a low GFR causes an increase in TmG. In contrast, lowering the TmG lowers the threshold because the tubules’ ability to reabsorb glucose is reduced.

      A reduction in GFR caused by severe dehydration and reduced perfusion pressure is the most obvious cause of the discrepancy between plasma and urinary glucose in this scenario.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 196 - A 53-year old female with a diagnosis of anaplastic thyroid carcinoma is admitted...

    Incorrect

    • A 53-year old female with a diagnosis of anaplastic thyroid carcinoma is admitted in the surgery department for an elective total thyroidectomy with radical neck dissection. The operation is expected to last for 10 hours.

      Which of the following is the most suitable humidifier to use in an anaesthetic circuit for this case?

      Your Answer:

      Correct Answer: Heat and moisture exchanger (HME)

      Explanation:

      Adequate humidification is vital to maintain homeostasis of the airway. Heat and moisture exchangers conserve some of the exhaled water, heat and return them to inspired gases. Many heat and moisture exchangers also perform bacterial/viral filtration and prevent inhalation of small particles. Heat and moisture exchangers are also called condenser humidifier, artificial nose, etc. Most of them are disposable devices with exchanging medium enclosed in a plastic housing. For adult and paediatric age group different dead space types are available. Heat and moisture exchangers are helpful during anaesthesia and ventilatory breathing system. To reduce the damage of the upper respiratory tract through cooling and dehydration inspiratory air can be heated and humidified, thus preventing the serious complications. Moreover, they are the most appropriate humidification devices used for routine anaesthesia.

      Gases can be bubbled through water to increase humidity. Passing gas through water at room temperature causes the gas to cool due to latent heat of vaporisation. The water bath can be heated. This improves the efficiency of the device and also reduces the incidence of bacterial colonisation.

      Nebulisers use a venturi system which employs the Bernoulli effect. A gas at high flow passes through a constriction causing the gas to accelerate, reducing its potential energy allowing other gases or liquids to be entrained. This can include medications or in the case of humidification, water vapour. The size of the water droplet produced by nebulisation determines where in the airway it is deposited. Standard nebulisers produced droplets of 4 microns in diameter and these are deposited in the upper airway and trachea. Efficacy can be improved by passing the droplets over an anvil which further reduces particle size. The most efficient form of nebuliser is the ultrasonic nebuliser. Here a transducer immersed in water and vibrated at a frequency of 3MHz produces1-2micron droplets. These particles easily reach the bronchioles and provide excellent humidification.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 197 - The outer muscular layer of the oesophagus is covered by? ...

    Incorrect

    • The outer muscular layer of the oesophagus is covered by?

      Your Answer:

      Correct Answer: Loose connective tissue

      Explanation:

      The oesophagus has four layers namely; 1. the mucosal layer, 2. the submucosal layer, 3. the muscular layer and 4. the layer of loose connective tissue which binds to the outer mucosal layer. The oesophagus lacks the serosal layer and therefore holds sutures poorly.

      The mucosal layer consists of muscularis mucosa and the lamina propria and is made up of non keratinised stratified squamous epithelium. The mucosal layer is the innermost layer of the oesophagus.

      The submucosal layer being the strongest layer of all has mucous glands which are called as the tuboalveolar mucous glands.

      The outer muscular layer has two types of muscle layers of which one is the circular layer and the other the longitudinal layer. The Auerbach’s and Meissner’s nerve plexuses lie in between the longitudinal and circular muscle layers and submucosally. The muscle fibres present in the upper 1/3rd part of the oesophagus are skeletal muscle fibres, the middle 1/3rd layer has both smooth and skeletal muscle fibres, but the lower 1/3rd only has smooth muscle fibres.

      The loose connective tissue layer or the adventitious layer has dense fibrous tissue.

    • This question is part of the following fields:

      • Anatomy
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  • Question 198 - A 21-year-old female was brought to the Emergency department with a ruptured ectopic...

    Incorrect

    • A 21-year-old female was brought to the Emergency department with a ruptured ectopic pregnancy.

      On clinical examination, the following were the findings:
      Pulse: 120 beats per minute
      BP: 120/95 mmHg
      Respiratory rate: 22 breaths per minute
      Capillary refill time: three seconds
      Cool peripheries.

      Which of the following best describes the cause for this clinical finding?

      Your Answer:

      Correct Answer: Reduction in blood volume of 15-30%

      Explanation:

      Classification of hemorrhagic shock according to Advanced Trauma Life Support is as follows:

      – Class I haemorrhage (blood loss up to 15%) in which there is no change in blood pressure, RR, or pulse pressure.

      – Class II haemorrhage (15-30% blood volume loss) where there is tachycardia, tachypnoea, and a decrease in pulse pressure.

      – Class III haemorrhage (30-40% blood volume loss) where clinical signs of inadequate perfusion, marked tachycardia, tachypnoea, significant changes in mental state, and measurable fall in systolic pressure is seen. It almost always requires a blood transfusion.

      – Class IV haemorrhage (> 40% blood volume loss) in which marked tachycardia, significant depression in systolic pressure and very narrow pulse pressure, and markedly depressed mental state with cold and pale skin are seen.

      Loss of >50% results in loss of consciousness, pulse, and blood pressure.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 199 - An 80-year-old man has a swelling in his left groin with moderate pain...

    Incorrect

    • An 80-year-old man has a swelling in his left groin with moderate pain and discomfort complaints. Diagnosed with an inguinal hernia, he is scheduled for elective surgery to repair the defect.

      Of the following, which nerve runs in the inguinal canal and is at risk of being damaged during surgery?

      Your Answer:

      Correct Answer: Ilioinguinal nerve

      Explanation:

      The inguinal canal is a passage in the lower anterior abdominal wall just above the inguinal ligament. It transmits the following structures:
      1. genital branch of genitofemoral nerve
      2. ilioinguinal nerve
      3. spermatic cord (males only)
      4. round ligament of the uterus (females only)

      The ilioinguinal is a direct branch of the first lumbar nerve. The ilioinguinal nerve enters the inguinal canal via the abdominal musculature (and not through the deep (internal) inguinal ring) and exits through the superficial (or external) inguinal ring.

      The openings for the other nerves in the answer options are:
      Sciatic nerve – exits the pelvis via the greater sciatic foramen
      Obturator nerve – descends into pelvis via the obturator foramen
      Femoral nerve – descends from the abdomen through the pelvis behind the inguinal canal

      The Iliohypogastric nerve also arises from the first lumbar root with the ilioinguinal nerve but pierces the transversus abdominis muscle posteriorly, just above the iliac crest, and continues anteriorly between the transversus abdominis and the internal abdominal oblique muscles.

    • This question is part of the following fields:

      • Anatomy
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  • Question 200 - Regarding the following induction agents, which one is cleared at the fastest rate...

    Incorrect

    • Regarding the following induction agents, which one is cleared at the fastest rate from the plasma?

      Your Answer:

      Correct Answer: Propofol

      Explanation:

      Propofol is cleared at the fastest rate at the rate of 60ml/kg/min.

      Clearance rate of other drugs are as follows:
      – Thiopental: 3.5 ml/kg/min
      – Methohexitone: 11 ml/kg/min
      – Ketamine: 17 ml/kg/min
      – Etomidate: 10-20 ml/kg/min

    • This question is part of the following fields:

      • Pharmacology
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SESSION STATS - PERFORMANCE PER SPECIALTY

Physiology (0/1) 0%
Physiology And Biochemistry (1/1) 100%
Pharmacology (0/1) 0%
Pathophysiology (0/1) 0%
Anaesthesia Related Apparatus (0/1) 0%
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