00
Correct
00
Incorrect
00 : 00 : 00
Session Time
00 : 00
Average Question Time ( Secs)
  • Question 1 - A 72-year-old long-term rheumatoid arthritis patient is having shoulder replacement surgery.

    He has chronic...

    Incorrect

    • A 72-year-old long-term rheumatoid arthritis patient is having shoulder replacement surgery.

      He has chronic obstructive pulmonary disease with a limited exercise tolerance. He agrees to the procedure being performed with an interscalene brachial plexus block.

      Which of the following neurological complications puts this patient at the greatest risk?

      Your Answer: Cranial nerve X and XII block

      Correct Answer: Phrenic nerve block

      Explanation:

      An ipsilateral phrenic nerve block will result from a successful interscalene block (ISB).

      The phrenic nerve is the diaphragm’s sole motor supply, and ipsilateral hemidiaphragmatic paresis affects up to 100% of patients who receive ISBs. Phrenic nerve palsy is usually well tolerated and goes unnoticed by healthy people. However, forced vital capacity decreases by approximately 25%, which can produce ventilatory compromise in patients with limited pulmonary reserve, requiring assisted ventilation.

      Vocal cord palsy occurs when the recurrent laryngeal nerve is inadvertently blocked, causing hoarseness and possibly acute respiratory insufficiency. Unless bilateral laryngeal nerve palsy occurs, which can cause severe laryngeal obstruction, this complication is usually of little consequence.

      ISB can also cause cranial nerve X and XII palsy (Tapia’s syndrome). One-sided cord paralysis, aphonia, and the patient’s tongue deviating toward the block’s side are all symptoms.

      When a local anaesthetic spreads to the stellate ganglion and its cervical sympathetic nerves, Horner’s syndrome can develop. Ptosis of the eyelid, miosis, and anhidrosis of the face are all symptoms. Horner’s syndrome, on the other hand, may not indicate that the brachial plexus is sufficiently blocked.

    • This question is part of the following fields:

      • Pathophysiology
      149.5
      Seconds
  • Question 2 - Under general anaesthesia, a 48-year-old patient is scheduled for some dental extractions. He...

    Correct

    • Under general anaesthesia, a 48-year-old patient is scheduled for some dental extractions. He tells you that he has a heart murmur and that he has always received antibiotic prophylaxis at the dentist. There are no allergies that he is aware of.

      Which antibiotic prophylaxis strategy is most appropriate for this patient?

      Your Answer: Prophylactic antibiotics are unnecessary for this patient

      Explanation:

      The National Institute for Health and Care Excellence (NICE) has published guidelines on infective endocarditis prophylaxis (IE). The goal was to create clear guidelines for antibiotic prophylaxis in patients undergoing dental procedures as well as certain non-dental interventional procedures. A number of studies have found an inconsistent link between recent interventional procedures and the development of infective endocarditis in both dental and non-dental procedures.

      Antibiotic prophylaxis against infective endocarditis is not advised or required in the following situations:

      Dental patients undergoing procedures
      Patients undergoing procedures involving the upper and lower gastrointestinal tracts, the genitourinary tract (including urological, gynaecological, and obstetric procedures, as well as childbirth), and the upper and lower respiratory tract (including ear, nose and throat procedures and bronchoscopy).

      Antibiotic resistance can be exacerbated by the indiscriminate use of prophylactic antibiotics, but this is not the primary reason for avoiding their use in these situations.

      To reduce the risk of endocarditis, any patient who is at risk of developing IE should be investigated and treated as soon as possible. Patients with the following conditions are at risk of developing IE:
      acquired valvular heart disease with regurgitation or stenosis
      previous valve replacement
      structural congenital heart disease
      past history of IE, or
      hypertrophic cardiomyopathy (HOCM)

      It would also be appropriate for high-risk dental procedures and those with severe gingival disease.

      Although this patient may not have structural heart disease, ABs should be administered on a case-by-case basis.

    • This question is part of the following fields:

      • Pharmacology
      31.1
      Seconds
  • Question 3 - Systemic vascular resistance (multiplied by 80) to produce the units of dynes.s.cm-5 is...

    Incorrect

    • Systemic vascular resistance (multiplied by 80) to produce the units of dynes.s.cm-5 is represented by?

      Your Answer: Mean pulmonary artery pressure (MPAP) - pulmonary artery occlusion pressure (PAOP)/ cardiac output (CO)

      Correct Answer: Mean arterial pressure (MAP) - central venous pressure (CVP)/cardiac output (CO)

      Explanation:

      Systemic vascular resistance (SVR) is a derived value based on:

      SVR = (MAP-CVP)/CO x 80

      = (60 -10)/5 x 80 = 800 dynes.s.cm-5

      A correction factor of 80 is needed in converting mmHg to dynes.s.cm-5
      Normal values is between 700 -1600 dynes.s.cm-5

      Pulmonary resistance (PVR) = (MPAP-PCWP)/CO x 80

      = (10 – 5)/5 x 80 = 80 dynes.s.cm-5

      To account for body size, cardiac index (CI) can be used instead of CO. CI = CO/body surface area (m2) or mL/minute/m2.
      N/B: either MAP and CVP, or MPAP and PCWP are used in calculation to get dynes.s.cm-5

    • This question is part of the following fields:

      • Clinical Measurement
      7
      Seconds
  • Question 4 - The spinal cord in a neonate terminates at the lower border of: ...

    Correct

    • The spinal cord in a neonate terminates at the lower border of:

      Your Answer: L3

      Explanation:

      The spinal cord and the vertebral canal are as long as each other in early fetal life. The length of the cord increases faster than the growth of the vertebrae during development. By the time of birth, the spinal cord is at the level of the lower border of the 3rd lumbar vertebra, compared to its original position at the level of the 2nd coccygeal vertebra.

    • This question is part of the following fields:

      • Anatomy
      28.1
      Seconds
  • Question 5 - An orthopaedic surgery is scheduled for a 68-year-old man. He is normally in...

    Incorrect

    • An orthopaedic surgery is scheduled for a 68-year-old man. He is normally in good shape. His routine biochemistry results are checked and found to be within normal limits.

      Which of the following pairs has the greatest impact on his plasma osmolarity?

      Your Answer: Calcium and phosphate ions

      Correct Answer: Sodium and potassium cations

      Explanation:

      The number of osmoles (Osm) of solute per litre (L) of solution (Osmol/L) is the unit of measurement for solute concentration. The calculated serum osmolality assumes that the primary solutes in the serum are sodium salts (chloride and bicarbonate), glucose, and urea nitrogen.

      2 (Na + K) + Glucose + Urea (all in mmol/L) = calculated osmolarity

      313 mOsm/L = 2 (144 + 6) + 9.5 + 3.5

      Sodium and potassium ions clearly contribute the most to plasma osmolarity. Glucose and urea, on the other hand, are less so.

      The osmolarity of normal serum is 285-295 mOsm/L. Temperature and pressure affect osmolality, and this calculated variable is less than osmolality for a given solution.

      The number of osmoles (Osm) of solute per kilogramme (Osm/kg) is a measure of osmolality, which is also a measure of solute concentration. Temperature and pressure have no effect on the value. An osmometer is used to measure it in the lab. Osmometers rely on a solution’s colligative properties, such as a decrease in freezing point or a rise in vapour pressure.

      The osmolar gap (OG) is calculated as follows:

      OG = osmolaRity calculated from measured serum osmolaLity

      Excess alcohols, lipids, and proteins in the blood can all contribute to the difference.

    • This question is part of the following fields:

      • Physiology
      95.3
      Seconds
  • Question 6 - A 50-year-old man is admitted in hospital. Over four hours, he produces 240...

    Incorrect

    • A 50-year-old man is admitted in hospital. Over four hours, he produces 240 mL of urine and has a plasma creatinine concentration is 10 mcg/mL. The normal concentration of creatinine in urine is 1.25 mg/mL.

      Calculate his approximate creatinine clearance.

      Your Answer: 1.25 ml/minute

      Correct Answer: 125 ml/minute

      Explanation:

      Creatinine clearance is a test used to approximate the glomerular filtration rate (GFR) as an assessment of kidney function.

      Creatinine is formed during the breakdown of dietary sources of meat and skeletal muscle. It is secreted at a consistent concentration and pace into the body’s circulation, and is easily filtered across the glomerulus without being reabsorbed or metabolized by the kidney.

      It is represented mathematically as:
      Creatinine clearance (CL) = U x V/P
      where,
      U: Urinary creatinine concentration (mg/mL)
      V: Volume of urine (mL/min)
      P: Plasma creatinine concentration (mg/mL)

      Therefore, in this case:
      CL: 1.25 x 1 = 125mL/min
      0.1

    • This question is part of the following fields:

      • Clinical Measurement
      10.5
      Seconds
  • Question 7 - Which of the following statements is true with regards to the Krebs' cycle...

    Incorrect

    • Which of the following statements is true with regards to the Krebs' cycle (also known as the tricarboxylic acid cycle or citric acid cycle)?

      Your Answer: Krebs' cycle can function under anaerobic conditions

      Correct Answer: Alpha-ketoglutarate is a five carbon molecule

      Explanation:

      Krebs’ cycle (tricarboxylic acid cycle or citric acid cycle) is a sequence of reactions in which acetyl coenzyme A (acetyl-CoA) is metabolised and this results in carbon dioxide and hydrogen atoms production.

      This series of reactions occur in the mitochondria of eukaryotic cells, not the cytoplasm. The cycle requires oxygen and so, cannot function under anaerobic conditions.

      It is the common pathway for carbohydrate, fat and some amino acids oxidation and is required for high energy phosphate bond formation in adenosine triphosphate (ATP).

      When pyruvate enters the mitochondria, it is converted into acetyl-CoA. This represents the formation of a 2 carbon molecule from a 3 carbon molecule. There is loss of one CO2 but formation of one NADH molecule. Acetyl-CoA is condensed with oxaloacetate, the anion of a 4 carbon acid, to form citrate which is a 6 carbon molecule.

      Citrate is then converted into isocitrate, alpha-ketoglutarate, succinyl-CoA, succinate, fumarate, malate and finally oxaloacetate.

      The only 5 carbon molecule in the cycle is alpha-ketoglutarate.

    • This question is part of the following fields:

      • Physiology
      162.7
      Seconds
  • Question 8 - A 40-year-old obese woman has complaints of heartburn and regurgitation that is worse...

    Incorrect

    • A 40-year-old obese woman has complaints of heartburn and regurgitation that is worse on lying flat. The doctor suspects gastroesophageal reflux due to a hiatus hernia. Lifestyle modifications to lose weight and antacids are prescribed to her.

      At which level of the diaphragm will you find an opening for this problem?

      Your Answer: T8

      Correct Answer: T10

      Explanation:

      Hiatus is an opening in the diaphragm. A hiatal hernia is a protrusion of the upper part of the stomach through an opening in the diaphragm, the oesophageal hiatus, into the thorax. The oesophageal hiatus occurs at the level of T10 in the right crus of the diaphragm.

      Other important openings in the diaphragm:
      T8: vena cava, terminal branches of the right phrenic nerve
      T10: oesophagus, vagal trunks, left anterior phrenic vessels, oesophageal branches of the left gastric vessels
      T12: descending aorta, thoracic duct, azygous and hemi-azygous vein

      An opening in the diaphragm is called a hiatus. The oesophageal hiatus is at vertebral level T10. A hiatus hernia is where the stomach bulges through the oesophageal hiatus hence the name – hiatus hernia.

    • This question is part of the following fields:

      • Anatomy
      17.7
      Seconds
  • Question 9 - Levels of serum potassium in around 1000 patients that were on ACE inhibitor...

    Incorrect

    • Levels of serum potassium in around 1000 patients that were on ACE inhibitor were measured. The mean value was calculated to be 4.6mmol/L and a standard deviation of 0.3mmol/L was recorded.

      Which among the given options is correct?

      Your Answer: 99.7% of values lie between 4.0 and 5.2 mmol/l

      Correct Answer: 68.3% of values lie between 4.3 and 4.9 mmol/l

      Explanation:

      Its known that 68.3% of the total values of a normally distributed variable are found within a range of 1 standard deviation from the mean which makes the range to be 4.3 to 4.9 mmol/L.

    • This question is part of the following fields:

      • Statistical Methods
      5.1
      Seconds
  • Question 10 - What is the percentage of values that lie within 3 standard deviations of...

    Incorrect

    • What is the percentage of values that lie within 3 standard deviations of the mean?

      Your Answer: 98.30%

      Correct Answer: 99.70%

      Explanation:

      99.7% of the values within 3 standard deviations of the mean.

      For 99.7% confidence interval, you can find the range as follows:

      1. Multiply the standard error by 3.

      2. Subtract the answer from mean value to get the lower limit.

      3. Add the answer obtained in step 1 from the mean value to get the upper limit.

      For a confidence interval of 68%, multiply the standard error with 1 and repeat the process. For a 95% confidence interval, Standard Error is multiplied by 1.96 to get the interval.

    • This question is part of the following fields:

      • Statistical Methods
      14.2
      Seconds
  • Question 11 - A delayed hypersensitivity reaction is type ____? ...

    Correct

    • A delayed hypersensitivity reaction is type ____?

      Your Answer: IV

      Explanation:

      Type I – immediate hypersensitivity reaction

      Examples are: Atopy, urticaria, Anaphylaxis, Asthma( IgE mediated).

      Type II – Antibody mediated cytotoxic reaction

      Examples are: Autoimmune haemolytic anaemia, Thrombocytopenia( IgM or IgG mediated).

      Type III – Immune complex mediated reaction

      Examples are: Serum sickness,SLE – IgG., Farmers lungs, rheumatoid arthritis

      Type IV – Delayed hypersensitivity reaction

      Examples are: Contact dermatitis, drug allergies.

      Type V – Autoimmune

      Graves’
      Myasthenia – IgM or IgG.

    • This question is part of the following fields:

      • Pathophysiology
      22.6
      Seconds
  • Question 12 - In the erect position, the partial pressure of oxygen in the alveoli (PAO2)...

    Incorrect

    • In the erect position, the partial pressure of oxygen in the alveoli (PAO2) is higher in the apical lung units than in the basal lung units.

      What is the most significant reason for this?

      Your Answer: The apical units are better ventilated

      Correct Answer: The V/Q ratio of apical units is greater than that of basal units

      Explanation:

      In any alveolar unit, the V/Q ratio affects alveolar oxygen (PAO2) and carbon dioxide tension (PACO2).

      The partial pressure of alveolar carbon dioxide (PACO2) is plotted against the partial pressure of alveolar oxygen in a Ventilation-Perfusion (V/Q) ratio graph (PAO2). Given a set of model assumptions, the curve represents all of the possible values for PACO2 and PAO2 that an individual alveolus could have.

      In the case of an infinity V/Q ratio (ventilation but no perfusion or dead space), the PACO2 of the alveolus will equal zero, while the PAO2 will approach that of external air (150mmmHg). At the apex of the lung, the V/Q ratio is 3.3, compared to 0.67 at the base.

      PACO2 and PAO2 approach the partial pressures for these gases in the venous blood when the V/Q ratio is zero (no ventilation but perfusion). At the base of the lung, the V/Q ratio is 0.67, whereas at the apex, it is 3.3.

      PAO2 at the apex is typically 132mmHg, and PACO2 is typically 28mmHg.

      The average PAO2 at the base is 89 mmHg, while the average PACO2 is 42 mmHg.

    • This question is part of the following fields:

      • Physiology
      31.5
      Seconds
  • Question 13 - A strain gauge operates on which of the following principles? ...

    Incorrect

    • A strain gauge operates on which of the following principles?

      Your Answer:

      Correct Answer: Varying resistance of a wire when stretched

      Explanation:

      The principle by which a strain gauge works is that when a wire is stretched, it becomes longer and thinner, and as a result, its resistance increases.

      A strain gauge, which is used in pressure transducers, acts as a resistor. When the pressure in a pressure transducer changes, the diaphragm moves, changing the tension in the resistance wire and thus changing the resistance.

      Changes in current flow through the resistor are amplified and displayed as a pressure change measure.

      A Wheatstone bridge, on the other hand, is frequently used to measure or monitor these changes in resistance.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 14 - What is the mechanism of the pupillary reflex arc? ...

    Incorrect

    • What is the mechanism of the pupillary reflex arc?

      Your Answer:

      Correct Answer: Oculomotor nerve fibres from the Edinger-Westphal nuclei

      Explanation:

      Pupil size is reduced by the pupillary light reflex and during accommodation for near vision. In the pupillary light reflex, light that strikes the retina is processed by retinal circuits that excite W-type retinal ganglion cells. These cells respond to diffuse illumination. The axons of some of the W-type cells project through the optic nerve and tract to the pretectal area, where they synapse in the olivary pretectal nucleus. This nucleus contains neurons that also respond to diffuse illumination. Activity of neurons of the olivary pretectal nucleus causes pupillary constriction by means of bilateral connections with parasympathetic preganglionic neurons in the Edinger-Westphal nuclei. The reflex results in contraction of the pupillary sphincter muscles in both eyes, even when light is shone into only one eye.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 15 - Gentamicin is a drug used for the treatment of bronchiectasis. Which of the...

    Incorrect

    • Gentamicin is a drug used for the treatment of bronchiectasis. Which of the following is true regarding the mechanism of action of gentamicin?

      Your Answer:

      Correct Answer: Inhibit the 30S subunit of ribosomes

      Explanation:

      Gentamicin is a broad-spectrum antibiotic whose mechanism of action involves inhibition of protein synthesis by binding to 30s ribosomes. Its major adverse effect is nephrotoxicity and ototoxicity

      Aminoglycoside bind to 30s subunit of ribosome causing misreading of mRNA

      Tetracyclines inhibit protein synthesis through reversible binding to bacterial 30s ribosomal subunits, which prevent binding of new incoming amino acids (aminoacyl-tRNA) and thus interfere with peptide growth.

      Chloramphenicol binds to the 50s subunit and inhibits peptidyl transferase

      Clindamycin binds to the 50s ribosomal subunit of bacteria and disrupts protein synthesis by interfering with the transpeptidation reaction, which thereby inhibits early chain elongation.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 16 - Which of the following statement is not true regarding the effects of Dopamine...

    Incorrect

    • Which of the following statement is not true regarding the effects of Dopamine infusions?

      Your Answer:

      Correct Answer: Decreasing gastric transit time

      Explanation:

      Moderately high doses of dopamine produce a positive inotropic (direct?1 and D1 action + that due to Noradrenaline release), but the little chronotropic effect on the heart.

      Vasoconstriction (?1 action) occurs only when large doses are infused.

      At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 17 - A previously fit 26-year-old is undergoing surgery to repair an inguinal hernia. He...

    Incorrect

    • A previously fit 26-year-old is undergoing surgery to repair an inguinal hernia. He is breathing on his own, and a supraglottic airway is being maintained via a circle system with air/oxygen and sevoflurane.

      With a fresh gas flow of 14 L/min, the end-tidal CO2 reading is 8.1 kPa. CO2 pressure is 1.9 kPa. The percentages of oxygen inhaled and exhaled are 38 and 33 percent, respectively.

      What do you think is the most likely source for these readings?

      Your Answer:

      Correct Answer: Incompetent expiratory valve

      Explanation:

      The patient is rebreathing carbon dioxide that has been exhaled.

      Exhaustion of the soda lime and failure of the expiratory valve are the two most likely causes. A leak in the inspiratory limb is a less likely cause. Increased inhaled and exhaled carbon dioxide levels may appear with a normal-looking capnogram if the expiratory valve is ineffective.

      The patient will exhale into both the inspiratory and expiratory limbs if the inspiratory valve is inoperable. A slanted downstroke inspiratory phase (as the patient inhales carbon dioxide-containing gas from the inspiratory limb) and increased end-tidal carbon dioxide can be seen on the capnogram.

      Even if the soda lime were exhausted, a high fresh gas flow would be enough to prevent rebreathing. The difference in oxygen concentrations in inspired and expired breaths would be less pronounced.

      Hypercapnia is caused by respiratory obstruction and malignant hyperthermia, but not by rebreathing.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 18 - The statement that best describes lactic acidosis is: ...

    Incorrect

    • The statement that best describes lactic acidosis is:

      Your Answer:

      Correct Answer: It can be precipitated by intravenous fructose

      Explanation:

      An elevated arterial blood lactate level and an increase anion gap ([Na + K] – [Cl + HCO3]) of >20mmol gives rise to lactic acidosis. It can also be a result of overproduction and/or reduced metabolism of lactic acid.

      The liver and kidney are the main sites of lactate metabolism, not skeletal muscle.

      The two types of lactic acidosis that are known are:

      Type A – due to tissue hypoxia, inadequate tissue perfusion and anaerobic glycolysis. These may be seen in cardiac arrest, shock, hypoxaemia and anaemia. The management of type A lactic acidosis involves reversing the underlying cause of the tissue hypoxia.

      Type B – occurs in the absence of tissue hypoxia. Some of the causes of this include hepatic failure, renal failure, diabetes mellitus, pancreatitis and infection. Some drugs can also cause this lie aspirin, ethanol, methanol, biguanides and intravenous fructose.

      The mainstay of treatment involves:
      1. Optimising tissue oxygen delivery
      2. Correcting the cause
      3. Intravenous sodium bicarbonate

      In resistant cases, peritoneal dialysis can be performed.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 19 - Which term among the following is used for the proportion of a particular...

    Incorrect

    • Which term among the following is used for the proportion of a particular disease that would be eradicated from a population if the rate of disease were to be reduced to that of the group that has not been exposed to it?

      Your Answer:

      Correct Answer: Attributable proportion

      Explanation:

      The attributable risk is the rate of a disease in an exposed group to that of a group that has not been exposed to it. It involves the measure of association that is pertinent to making decisions for the individuals.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 20 - Prior to rapid sequence induction of anaesthesia, a man with a BMI of...

    Incorrect

    • Prior to rapid sequence induction of anaesthesia, a man with a BMI of 35 is pre-oxygenated.

      Which method of pre-oxygenation with a tight-fitting face mask is the most effective?

      Your Answer:

      Correct Answer: Oxygen 6 litres per minute via a Mapleson A breathing system, with patient sitting up at 30 degrees breathing four vital capacity breaths

      Explanation:

      This patient is morbidly obese and has a high risk of developing hypoxia. This will be exacerbated by the patient’s supine position, as a result of:

      Functional residual capacity has been reduced (FRC)
      Increased closing capacity (CC)
      Reduced tidal volume due to increased airway resistance, decreased thoracic cage compliance, and decreased respiratory muscle strength and endurance
      Following induction of general anaesthesia, there is a tendency for atelectasis and increased O2 consumption due to the increased workload of respiratory muscles and the overall increase in metabolism.

      Pre-oxygenation with 100 percent oxygen via a tight-fitting mask can be done using either tidal volume breaths for three to five minutes or four vital capacity breaths in normal circumstances. In the head-up position, this patient is much more likely to be adequately pre-oxygenated, maximising the FRC and minimising the CC. In spontaneously breathing patients, the Mapleson A and circle systems are both effective, but the Mapleson D requires 160-200 ml/kg/minute to prevent rebreathing.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 21 - A 70-year-old man presents with central crushing chest pain that radiates to the...

    Incorrect

    • A 70-year-old man presents with central crushing chest pain that radiates to the jaw in the emergency department. He has associated symptoms of nausea and diaphoresis.

      A 12 lead ECG is performed. ST-elevation is observed in leads V2-V4. The diagnosis of anteroseptal ST-elevation myocardial infarction is made.

      Which coronary vessel is responsible for this condition and runs in the interventricular septum on the anterior surface of the heart to reach the apex?

      Your Answer:

      Correct Answer: Left anterior descending artery

      Explanation:

      The heart receives blood supply from coronary arteries. The right and left coronary arteries branch off the aorta and supply oxygenated blood to all heart muscle parts.

      The left main coronary artery branches into:
      1. Circumflex artery – supplies the left atrium, side, and back of the left ventricle. The left marginal artery arises from the left circumflex artery. It travels along the obtuse margin of the heart.
      2. Left Anterior Descending (LAD) artery – supplies the front and bottom of the left ventricle and front of the interventricular septum

      The left anterior descending coronary artery is the largest coronary artery. It courses anterior to the interventricular septum in the anterior interventricular groove, extending from the base of the heart to its apex. Around the apex, the LAD anastomosis with the terminal branches of the posterior descending artery (branch of the right coronary artery).
      Atherosclerosis or thrombotic occlusion of LAD causes myocardial infarction in large areas of the anterior, septal, and apical portions of the heart muscle. It can lead to a serious deterioration in heart performance.

      Occlusion of the LAD causes anteroseptal myocardial infarction, which is evident on the ECG with changes in leads V1-V4. Occlusion of the left circumflex artery causes lateral, posterior, or anterolateral MI. However, as it does not run towards the apex in the interventricular septum of the heart, it is not the correct answer for this question.

      The right coronary artery branches into:
      1. Right marginal artery
      2. Posterior descending artery

      The right coronary artery supplies the right atrium, right ventricle, interatrial septum, and the inferior posterior third of the interventricular septum. Occlusion of the right coronary artery causes inferior MI, which is indicated on ECG with changes in leads II, III, and aVF.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 22 - A 26-year-old male was diagnosed with hypovolaemic shock following a road traffic accident....

    Incorrect

    • A 26-year-old male was diagnosed with hypovolaemic shock following a road traffic accident. On clinical examination:
      Heart rate: 125 beats/min
      Blood pressure: 120/105 mmHg.

      On physical examination, his abdomen was found to be tense and tender. Which of the following receptors is responsible for the compensation of blood loss?

      Your Answer:

      Correct Answer: Alpha 1 adrenergic

      Explanation:

      Alpha 1 adrenergic receptor stimulation results in vasoconstriction of peripheral arteries mainly of those of skin, gut and kidney arterioles. This would cause and increase in total peripheral resistance and mean arterial pressure and as a result the perfusion of vital organs i.e. brain, heart and lungs are maintained.

      Muscarinic M2 receptor also known as cholinergic receptor are located in heart, where they act to slow the heart rate down to normal sinus rhythm after negative stimulatory actions of parasympathetic nervous system. They also reduce contractile forces of the atrial cardiac muscle, and reduce conduction velocity of AV node. This could worsen the compensation.

      Stimulation of beta 2 adrenergic receptor result in dilation of smooth muscle as in bronchodilation.

      Beta 3 adrenergic receptors are present on cell surface f both white and brown adipocytes and are responsible for lipolysis, thermogenesis, and relaxation of intestinal smooth muscle.

      Alpha 2 adrenergic receptor stimulation results in inhibition of the release of noradrenaline in a form of negative feedback.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 23 - When there is a relation between two variables due to the existence of...

    Incorrect

    • When there is a relation between two variables due to the existence of a confounding factor, this association is termed as:

      Your Answer:

      Correct Answer: Indirect

      Explanation:

      When the association among any two classes of object is defined by the presence of a third entity it is termed as indirect association. For an instance, the age of the employee may affect the rate of pay, which would have implications on job satisfaction. So, in this example, an indirect relationship between age and job satisfaction exists due to a third party i.e. rate of pay.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 24 - An 80-year-old man will be operated on for an arterial bypass procedure to...

    Incorrect

    • An 80-year-old man will be operated on for an arterial bypass procedure to treat claudication and foot ulceration. The anterior tibial artery will be the target for distal arterial anastomosis.

      Which structure is NOT closely related to the anterior tibial artery?

      Your Answer:

      Correct Answer: Tibialis posterior

      Explanation:

      The anterior tibial artery originates from the distal border of the popliteus. In the posterior compartment, it passes between the heads of the tibialis posterior and the oval aperture of the interosseous membrane to reach the anterior compartment.

      On entry into the anterior compartment, it runs medially along the deep peroneal nerve.
      The upper third of the artery courses between the tibialis anterior and extensor digitorum longus muscles, while the middle third runs between the tibialis anterior and extensor hallucis longus muscles.

      At the ankle, the anterior tibial artery is located approximately midway between the malleoli. It continues on the dorsum of the foot, lateral to extensor hallucis longus, as the dorsalis pedis artery.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 25 - A 35-year-old female, presents to the emergency department via ambulance. The paramedics have...

    Incorrect

    • A 35-year-old female, presents to the emergency department via ambulance. The paramedics have noted the patient's symptoms as unilateral left-sided weakness of the upper and lower limbs, homonymous hemianopia and dysphasia.
      She has previous personal and family history of deep vein thromboses.
      The report of her CT scan suggests a stroke involving the middle cerebral artery.
      Post recovery, she undergoes further diagnostic investigations to determine the cause of a stroke at her young age. She is eventually diagnosed with a hypercoagulable state disease called Factor V Leiden thrombophilia.

      An emboli in the middle cerebral artery results in dysfunction of which areas of the brain?

      Your Answer:

      Correct Answer: Frontal, temporal and parietal lobes

      Explanation:

      The middle cerebral artery is a part of the circle of Willis system of anastomosis within the brain, and the most often affected by brain pathology.

      The primary function of the middle cerebral artery is providing oxygenated blood to related regions of the brain. It achieves this by giving off different branches to supply different brain regions, namely:

      The cortical branches: which supplies the primary motor and somatosensory cortical areas of some parts of the face, trunk and upper limbs.

      The small central branches: which supply the basal ganglia and internal capsule via the lenticulostriate vessels.

      The superior division: which supplies the lateral inferior frontal lobe, including the Broca area which is responsible for production of speech, language comprehension, and writing.

      The inferior division: which supplies the superior temporal gyrus, including Wernicke’s area which controls speech comprehension and language development.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 26 - Out of the following, which therapy for acute severe asthma or life-threatening asthma...

    Incorrect

    • Out of the following, which therapy for acute severe asthma or life-threatening asthma has been NOT been approved in recent guidelines?

      Your Answer:

      Correct Answer: Heliox

      Explanation:

      Recommendations from the British Thoracic Society for acute severe asthma or life-threatening asthma are:

      1. Give controlled supplementary oxygen to all hypoxemic patients with acute severe asthma titrated to maintain a SpOâ‚‚ level of 94 98%.
      2. Use high-dose inhaled ?â‚‚ agonists as first-line agents in patients with acute asthma and administer them as early as possible. Reserve
      intravenous ?â‚‚ agonists for those patients in whom inhaled therapy cannot be used reliably.
      3. Give steroids in adequate doses to all patients with an acute asthma attack.
      4. Add nebulized ipratropium bromide (0.5 mg 4–6 hourly) to ?₂ agonist treatment for acute severe or life-threatening asthma or those with a poor initial response to ?₂ agonist therapy.
      5. Consider aminophylline for children with severe or life-threatening asthma unresponsive to maximal doses of bronchodilators and steroids.

      A review (including 12 case reports, three RCTs, and five other observational studies) of ketamine use in adults and children in status asthmaticus reported that ketamine is a potential bronchodilator. Still, prospective trials are needed before conclusions about effectiveness can be drawn.

      Heliox has no place in the current guidelines issued by the British Thoracic Society.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 27 - Which of the following is true in the Kreb's cycle? ...

    Incorrect

    • Which of the following is true in the Kreb's cycle?

      Your Answer:

      Correct Answer: Alpha-ketoglutarate is a five carbon molecule

      Explanation:

      Krebs’ cycle (tricarboxylic acid cycle or citric acid cycle) is a sequence of reactions to release stored energy through oxidation of acetyl coenzyme A (acetyl-CoA). Some of the products are carbon dioxide and hydrogen atoms.

      The sequence of reactions, known collectively as oxidative phosphorylation, only occurs in the mitochondria (not cytoplasm).

      The Krebs cycle can only take place when oxygen is present, though it does not require oxygen directly, because it relies on the by-products from the electron transport chain, which requires oxygen. It is therefore considered an aerobic process. It is the common pathway for the oxidation of carbohydrate, fat and some amino acids, required for the formation of adenosine triphosphate (ATP).

      Pyruvate enters the mitochondria and is converted into acetyl-CoA. Acetyl-CoA is then condensed with oxaloacetate, to form citrate which is a six carbon molecule. Citrate is subsequently converted into isocitrate, alpha-ketoglutarate, succinyl-CoA, succinate, fumarate, malate and finally oxaloacetate.

      The only five carbon molecule in the cycle is Alpha-ketoglutarate.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 28 - A 56-year-old man, presents to his general practitioner with a lump in his...

    Incorrect

    • A 56-year-old man, presents to his general practitioner with a lump in his groin area. He is diagnosed with an indirect inguinal hernia and is scheduled for a laparoscopic inguinal hernia repair. During the repair, the surgeon sees several structures surrounding the inguinal canal.

      Name the structure that forms the anterior borders of the inguinal canal.

      Your Answer:

      Correct Answer: Aponeurosis of external oblique

      Explanation:

      The inguinal canal is the pathway leading from the wall of the abdomen to the external genitalia.

      The borders of the inguinal canal are:

      Anterior wall: formed by the aponeurosis of the external oblique, supported by the internal oblique muscle laterally.

      Posterior wall: formed laterally by the transversalis fascia, and medially by the conjoint tendon

      Roof: formed by the internal oblique and transversus abdominis muscles

      Floor: formed by the inguinal ligament and supported medially by the lacunar ligament

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 29 - The most abundant intracellular ion is? ...

    Incorrect

    • The most abundant intracellular ion is?

      Your Answer:

      Correct Answer: Phosphate

      Explanation:

      Phosphate is the principal anion of the intracellular fluid, most of which is bound to either lipids or proteins. They dissociate or associate with different compounds, depending on the enzymatic reaction, thus forming a constantly shifting pool.

      Calcium and magnesium are also present intracellularly, however in lesser amounts than phosphate.

      Sodium is the most abundant extracellular cation, and Chloride and is the most abundant extracellular anion.

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 30 - The rapid depolarisation phase of the myocardial action potential is caused by: ...

    Incorrect

    • The rapid depolarisation phase of the myocardial action potential is caused by:

      Your Answer:

      Correct Answer: Rapid sodium influx

      Explanation:

      The cardiac action potential has several phases which have different mechanisms of action as seen below:
      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Pharmacology (3/4) 75%
Clinical Measurement (1/2) 50%
Anatomy (1/1) 100%
Physiology (0/2) 0%
Statistical Methods (1/2) 50%
Anaesthesia Related Apparatus (0/1) 0%
Passmed