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  • Question 1 - About the vagus nerve, which one of these is true ? ...

    Correct

    • About the vagus nerve, which one of these is true ?

      Your Answer: Gives off the recurrent laryngeal nerve on the right as it passes anteriorly across the subclavian artery

      Explanation:

      The tenth cranial nerve (vagus nerve) has both sensory and motor divisions.

      It emerges from the anterolateral surface of the medulla in a groove between the olive and the inferior cerebellar peduncle as a series of 8-10 rootlets . It leaves the skull through the middle compartment of the jugular foramen and descends within the carotid sheath between the internal carotid artery and internal jugular vein. The right vagus crosses in front of the first part of the subclavian artery. It gives off the right recurrent laryngeal nerve at this point.

      The left recurrent laryngeal nerve passes around the ligamentum arteriosum.

      The external laryngeal nerve supplies the cricothyroid muscle while the recurrent laryngeal nerve supplies the other laryngeal muscles.

      The cranial part of the accessory nerve supplies all the muscles of the palate, via the pharyngeal plexus and the pharyngeal branch of the vagus nerve, except the tensor veli palatini which is supplied by the mandibular branch of the trigeminal nerve.

      The Sternothyroid, Sternohyoid, and Omohyoid muscles are supplied by the ansa cervicalis while the thyrohyoid muscle is supplied by the hypoglossal nerve.

    • This question is part of the following fields:

      • Anatomy
      10.3
      Seconds
  • Question 2 - An emergency appendicectomy is being performed on a 20 year old man. For...

    Correct

    • An emergency appendicectomy is being performed on a 20 year old man. For maintenance of anaesthesia, he is being ventilated using a circle system with a fresh gas flow (FGF) of 1 L/min (air/oxygen and sevoflurane). The trace on the capnograph shows a normal shape.

      The table below demonstrates the changes in the end-tidal and baseline carbon dioxide measurements of the capnograph at 10 and 20 minutes of anaesthesia maintenance.  
      End-tidal CO2: 4.9 kPa vs 8.4kPa (10 minutes vs 20 minutes)
      Baseline end-tidal CO2: 0.2 kPa vs 2.4kPa

      Pulse 100-107 beats per minute, systolic blood pressure 125-133 mmHg and oxygen saturation 98-99%. 

      Which of the following is the single most important immediate course of action?

      Your Answer: Increase the FGF

      Explanation:

      End-tidal carbon dioxide (ETCO2) monitoring has been an important factor in reducing anaesthesia-related mortality and morbidity. Hypercarbia, or hypercapnia, occurs when levels of CO2 in the blood become abnormally high (Paco2 >45 mm Hg). Hypercarbia is confirmed by arterial blood gas analysis. When using capnography to approximate Paco2, remember that the normal arterial–end-tidal carbon dioxide gradient is roughly 5 mm Hg. Hypercarbia, therefore, occurs when PETco2 is greater than 40 mm Hg.

      The most likely explanation for the changes in capnograph is either exhaustion of the soda lime and a progressive rise in circuit dead space.

      Inspect the soda lime canister for a change in colour of the granules. To overcome soda lime exhaustion, the first step is to increase the fresh gas flow (FGF) (Option A). Then, if need arises, replace the soda lime granules. Other strategies that can work are changing to another circuit or bypassing the soda lime canister, but remember that both these strategies are employed only after increasing FGF first. Exclude other causes of equipment deadspace too.

      There are also other causes for hypercarbia to develop intraoperatively:
      1. Hypoventilation is the most common cause of hypercapnia. A. Inadequate ventilation can occur with spontaneous breathing due to drugs like anaesthetic agents, opioids, residual NMDs, chronic respiratory or neuromuscular disease, cerebrovascular accident.
      B. In controlled ventilation, hypercapnia due to circuit leaks, disconnection or miscalculation of patient’s minute volume.
      2. Rebreathing – Soda lime exhaustion with circle, inadequate fresh gas flow into Mapleson circuits and increased breathing system deadspace.
      3. Endogenous source – Tourniquet release, hypermetabolic states (MH or thyroid storm) and release of vascular clamps.
      4. Exogenous source – Absorption of CO2 from pneumoperitoneum.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      44.9
      Seconds
  • Question 3 - Gag reflex was assessed as a part of brain stem death in a...

    Correct

    • Gag reflex was assessed as a part of brain stem death in a 22-year-old man with severe traumatic brain injury.

      Which of the following nerves forms the afferent limb of this reflex?

      Your Answer: Glossopharyngeal nerve

      Explanation:

      The gag reflex is a protective mechanism that prevents any foreign material to enter the aerodigestive tract.

      This reflex has afferent (sensory) and effect (motor) components.
      – Glossopharyngeal nerve form the afferent limb
      – Vagus nerve form the efferent limb

    • This question is part of the following fields:

      • Pathophysiology
      7.9
      Seconds
  • Question 4 - Which of these statements is false relating to the posterior cerebral artery? ...

    Incorrect

    • Which of these statements is false relating to the posterior cerebral artery?

      Your Answer: It is a branch of the basilar artery

      Correct Answer: It is connected to the circle of Willis via the superior cerebellar artery

      Explanation:

      The posterior cerebral arteries are the terminal branches of the basilar artery and are connected to the circle of Willis via the posterior communicating artery. The posterior cerebral artery supplies the visual areas of the cerebral cortex and other structures in the visual pathway.

      The posterior cerebral artery is separated from the superior cerebellar artery near its origin by the oculomotor nerve (3rd cranial nerve) and, lateral to the midbrain, by the trochlear nerve.

      PCA strokes will primarily cause a visual field loss or homonymous hemianopia to the opposite side. This large occipital or PCA stroke causes people to be “blind” on one side of the visual field. This is the most common symptom of a large occipital lesion or PCA stroke.

    • This question is part of the following fields:

      • Anatomy
      37
      Seconds
  • Question 5 - Concerning the physical principles of temperature measurement by a thermocouple, which of the...

    Correct

    • Concerning the physical principles of temperature measurement by a thermocouple, which of the following best describes it?

      Your Answer: The bimetallic strip has a junction potential proportional to temperature

      Explanation:

      A thermocouple, or a thermal junction, is temperature measuring device consisting of a pair of dissimilar metal (bimetallic) wires or strips joined together. Typically, copper and constantan (an alloy of 55% copper and 45% nickel) are used. When there is contact between these metals, a small voltage is generated in the order of millivolts. The magnitude of the thermojunction electromotive force (emf) is proportional to applied temperature (the Seebeck effect). This physical principle is applied in the measurement of temperature. The electromotive force at the measuring junction is proportional to temperature.

      Two wires with different coefficients of expansion, joined together, can be used as a switch for thermostatic control.

      Semiconductors are NOT used in thermocouple. The resistance of the measuring junction of a thermocouple is irrelevant.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      62.9
      Seconds
  • Question 6 - Which of the following options will best reflect the adequacy of preoxygenation prior...

    Correct

    • Which of the following options will best reflect the adequacy of preoxygenation prior to rapid sequence induction of a patient?

      Your Answer: Expired fraction of oxygen (FEO2)

      Explanation:

      The most important determinant of preoxygenation adequacy is expired fraction of oxygen. Denitrogenating of the functional residual capacity is the purpose of preoxygenation. This is dependent on three vital factors: (1) respiratory rate; (2) inspired volume, and; (3) inspired oxygen concentration (FiO2).

      Arterial oxygen saturation does not efficiently determine adequacy of preoxygenation because of its inability to measure tissue reserves. Arterial partial pressure of oxygen is also unsuitable for determining preoxygenation adequacy. Moreover, the absence of central cyanosis is a very crude sign of low tissue oxygenation.

    • This question is part of the following fields:

      • Pathophysiology
      18.7
      Seconds
  • Question 7 - A surgeon infiltrates the tissue layers with local anaesthetic (bupivacaine 0.125%) with 1...

    Correct

    • A surgeon infiltrates the tissue layers with local anaesthetic (bupivacaine 0.125%) with 1 in 120,000 adrenaline in a patient weighing 50 kg as part of an enhanced recovery programme for primary hip replacement surgery.

      What is the maximum volume of local anaesthetic that is permissible in this patient?

      Your Answer: 100 mL

      Explanation:

      The maximum safe amount of bupivacaine is 2mg/kg. Addition of adrenaline slows down absorption of the local anaesthetic and allows a maximum dose of 2.5mg/kg to be used.

      The maximum safe dose of bupivacaine for this patient is 125 mg.

      A 0.125% solution will contain 0.125g/100mL or 125mg/100 mL.

      The maximum volume of local anaesthetic is approximately 80-100 mL.

    • This question is part of the following fields:

      • Pharmacology
      65.1
      Seconds
  • Question 8 - What is the name of the space between the vocal cords? ...

    Correct

    • What is the name of the space between the vocal cords?

      Your Answer: Rima glottidis

      Explanation:

      The rima glottidis is a narrow, triangle-shaped opening between the true vocal cords.

      The vocal folds (true vocal cords) control sound production. The apex of each fold projects medially into the laryngeal cavity.

      Each vocal fold includes these vocal ligaments:

      Vocalis muscle (most medial part of thyroarytenoid muscle)

      The glottis is composed of the vocal folds, processes and rima glottidis.

      The rima glottidis is the narrowest potential site within the larynx, as the vocal cords may be completely opposed, forming a complete barrier.

    • This question is part of the following fields:

      • Anatomy
      2.7
      Seconds
  • Question 9 - A 61-year-old woman, present to her general practitioner. She complains of a severe...

    Correct

    • A 61-year-old woman, present to her general practitioner. She complains of a severe lancinating pain in her forehead that only last a few seconds, possibly triggered by washing her face, occurring over the previous six weeks.

      On examination, she is normal with no other signs or symptoms.

      Which nerve is the most likely cause of her pain?

      Your Answer: Sensory branches of the ophthalmic division of the trigeminal nerve

      Explanation:

      Her symptoms are suggestive of trigeminal neuralgia which is a short, sudden, severe sharp unilateral pain in the facial region. The pain often follows the sensory distribution of the trigeminal nerve (CN V).

      The trigeminal nerve gives rise to 3 sensory and 1 motor nuclei. Neuralgia can arise from any of the 3 sensory divisions.

      The ophthalmic division gives rise to 3 further sensory branches, which are the frontal, lacrimal and nasociliary.

      The frontal branch of the ophthalmic division of the trigeminal nerve is responsible for the innervation of the area in question.

      The superior alveolar dental, zygomatic and sphenopalatine nerves are all branches arising from the maxillary division of the trigeminal nerve.

      The mandibular division of the trigeminal nerve provides sensory and motor innervation. The sensory innervation is carried out by the auriculotemporal nerve which supplies the lower third of the face, while the motor fibres are responsible for controlling the muscles of mastication.

      The somatic sensory branches of the vagus nerve are responsible for sensory innervation of the external acoustic meatus and tympanic membrane.

    • This question is part of the following fields:

      • Pathophysiology
      29
      Seconds
  • Question 10 - Which medical gas cylinders have the correct colour codes? ...

    Correct

    • Which medical gas cylinders have the correct colour codes?

      Your Answer: Oxygen cylinders have a black body with white shoulders

      Explanation:

      The following are the colour codes for medical gas cylinders:

      Oxygen cylinder has a dark body with white shoulders.

      Nitrous oxide is French blue. Air encompasses a grey body with dark and white quarters on the shoulders.

      Entonox contains a French blue body with white and blue quarters on the shoulders.

      Carbon dioxide barrels are grey in colour.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      22
      Seconds
  • Question 11 - A 76-year-old female, presents to her GP. She complains of fatigue and increased...

    Correct

    • A 76-year-old female, presents to her GP. She complains of fatigue and increased shortness of breath. On examination, she is noted to have pallor, an increased respiratory and heart rate. Her GP requests further diagnostic investigations, including a full blood count (FBC) which finds decreased MCV and MCHC.

      What is the most likely cause of her symptoms?

      Your Answer: Iron deficiency

      Explanation:

      The patient’s diagnosis is microcytic hypochromic anaemia which is often as a result of iron deficiency and thalassaemia.

      Macrocytic anaemia is often caused by folate and B12 deficiencies and alcohol abuse.

      Normocytic normochromic anaemia is often caused by acute blood loss, haemolytic anaemia, anaemia of chronic disease and leucoerythroblastic anaemias.

    • This question is part of the following fields:

      • Clinical Measurement
      108.5
      Seconds
  • Question 12 - Which of the following statements is NOT true regarding the internal jugular vein?...

    Correct

    • Which of the following statements is NOT true regarding the internal jugular vein?

      Your Answer: The terminal part of the thoracic duct crosses anterior to it to insert into the right subclavian vein

      Explanation:

      The internal jugular vein is found on both sides of the neck and collects blood from the brain, superficial regions of the face, and neck. It drains into the right atrium.

      It is a continuation of the sigmoid sinus and begins in the posterior cranial fossa and exits the skull via the jugular foramen.
      It runs within the carotid sheath as it descends in the neck and is accompanied by the vagus nerve posteriorly and the common carotid anteromedially.

      The hypoglossal nerve emerges from the hypoglossal canal medial to the internal carotid artery and the internal jugular vein and ninth, tenth, and eleventh cranial nerves.

      The internal jugular vein crosses anterior to the thoracic duct on the left side.

    • This question is part of the following fields:

      • Anatomy
      6.9
      Seconds
  • Question 13 - Which statement is false in regards to the Circle of Willis? ...

    Incorrect

    • Which statement is false in regards to the Circle of Willis?

      Your Answer: Asymmetry of the circle of Willis is a risk factor for the development of intracranial aneurysms

      Correct Answer: Majority of blood passing through the vessels mix together

      Explanation:

      There is minimum mixing of blood passing through the vessels.

      The cerebral hemispheres are supplied by arteries that make up the Circle of Willis. The Circle of Willis is formed by the anastomosis of the two internal carotid arteries and two vertebral arteries. It lies in the subarachnoid space within the basal cisterns that surround the optic chiasma and infundibulum.

      Each half of the circle is formed by:
      1. Anterior communicating artery
      2. Anterior cerebral artery
      3. Internal carotid artery
      4. Posterior communicating artery
      5. Posterior cerebral arteries and the termination of the basilar artery

      The circle and its branches supply; the corpus striatum, internal capsule, diencephalon, and midbrain

    • This question is part of the following fields:

      • Anatomy
      22.4
      Seconds
  • Question 14 - A 45-year-old man is being operated on for emergency laparotomy as he presented...

    Incorrect

    • A 45-year-old man is being operated on for emergency laparotomy as he presented with bowel perforation. During the surgery, the marginal artery of Drummond is encountered and preserved.
      Which of the following two arteries fuse to form the marginal artery of Drummond?

      Your Answer: Inferior mesenteric artery and sigmoid arteries

      Correct Answer: Superior mesenteric artery and inferior mesenteric artery

      Explanation:

      The arteries of the midgut (superior mesenteric artery) and hindgut (inferior mesenteric artery) give off terminal branches that form an anastomotic vessel called the marginal artery of Drummond. It runs in the inner margins of the colon and gives off short terminal branches to the bowel wall.

      The marginal artery is formed by the main branches and arcades arising from the ileocolic, right colic, middle colic, and left colic arteries. It is most apparent in the ascending, transverse, and descending colons and poorly developed in the sigmoid colon.

    • This question is part of the following fields:

      • Anatomy
      52.1
      Seconds
  • Question 15 - All of the following options describes a thermistor for the measurement of temperature...

    Incorrect

    • All of the following options describes a thermistor for the measurement of temperature except:

      Your Answer: Small bead of semiconductor material is incorporated in a Thermistor

      Correct Answer: Resistance of the bead increases exponentially as the temperature increases

      Explanation:

      There are different types of temperature measurement. These include:

      Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially

      Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)

      Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature

      Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output

      Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.

    • This question is part of the following fields:

      • Clinical Measurement
      16.7
      Seconds
  • Question 16 - Which of the following is the best marker of mast cell degranulation in...

    Incorrect

    • Which of the following is the best marker of mast cell degranulation in a patient with suspected anaphylaxis who became hypotensive and developed widespread urticarial rash after administration of Augmentin?

      Your Answer: Beta-tryptase

      Correct Answer: Tryptase

      Explanation:

      Mast cell tryptase is a reliable marker of mast cell degranulation. Tryptase is a protease enzyme that acts via widespread protease-activated receptors (PARs).

    • This question is part of the following fields:

      • Pharmacology
      35.6
      Seconds
  • Question 17 - Which of the following statement is false regarding dopamine? ...

    Incorrect

    • Which of the following statement is false regarding dopamine?

      Your Answer: At higher rates of infusion, ? effects predominate leading to increased systemic vascular resistance and venous return

      Correct Answer: Urine output decreases due to inhibition of proximal tubule Na+ reabsorption

      Explanation:

      Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic ? and?1 (but not ?2 ) agonist.

      The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of Dopamine dilates these vessels (by raising intracellular cAMP). This increases g.f.r. In addition, DA exerts a natriuretic effect by D1 receptors on proximal tubular cells.

      Moderately high doses produce a positive inotropic (direct?1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.

      Vasoconstriction (?1 action) occurs only when large doses are infused.

      At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.

      Dopamine is less arrhythmogenic than adrenaline

      Regarding dopamine part of the dose is converted to Noradrenaline in sympathetic nerve terminals.

    • This question is part of the following fields:

      • Pharmacology
      34.1
      Seconds
  • Question 18 - Which of the following statements is true regarding antibiotics? ...

    Incorrect

    • Which of the following statements is true regarding antibiotics?

      Your Answer: Gram negative organisms are generally susceptible to benzylpenicillin

      Correct Answer: Staphylococcus aureus colonises the nasopharynx in >20% of the general population

      Explanation:

      Staphylococcus aureus colonizes the nasopharynx in >20% of the general population.

      Methicillin-resistant Staphylococcus aureus (MRSA) is resistant to flucloxacillin.

      Trimethoprim binds to dihydrofolate reductase and inhibits the reduction of dihydrofolic acid (DHF) to tetrahydrofolic acid (THF). THF is an essential precursor in the thymidine synthesis pathway and interference with this pathway inhibits bacterial DNA synthesis.

      All ?-lactam antibiotics like penicillin interfere with the synthesis of the bacterial cell walls. The ?-lactam antibiotics inhibit the transpeptidases so that cross-linking (which maintains the close-knit structure of the cell wall) does not take place

    • This question is part of the following fields:

      • Pharmacology
      82.3
      Seconds
  • Question 19 - Many of the processes we deal with in anaesthesia entail a relationship between...

    Incorrect

    • Many of the processes we deal with in anaesthesia entail a relationship between two or more variables.

      Which of the following relationships is a linear relationship?

      Your Answer: The relationship between current and degrees from a mains electricity source

      Correct Answer: The relationship between the junction potential and temperature in a thermocouple

      Explanation:

      Two bonded wires of dissimilar metals, iron/constantan or copper/constantan, make up a thermocouple (constantan is an alloy of copper and nickel). At the tip, a thermojunction voltage is generated that is proportional to temperature (Seebeck effect).

      All of the other connections are non-linear.

      For a single compartment model, the relationship between a decrease in plasma concentration of an intravenous bolus of a drug and time is a washout exponential.

      A sine wave is the relationship between current and degrees or time from a mains power source.

      A sigmoid curve represents the relationship between efficacy and log-dose of a pure agonist on mu receptors.

      The pressure of a fixed mass of gas and its volume (Boyle’s law) at a fixed temperature are inversely proportional, resulting in a hyperbolic curve.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      36.7
      Seconds
  • Question 20 - A 27-year-old woman presents to emergency department. She is experiencing generalised seizures.

    She is...

    Correct

    • A 27-year-old woman presents to emergency department. She is experiencing generalised seizures.

      She is given emergency management of her symptoms before being referred to the neurologist who diagnoses her with new onset of tonic-clonic epilepsy.

      What is the most appropriate first line of treatment?

      Your Answer: Lamotrigine should be offered as first line of treatment

      Explanation:

      Tonic-clonic (Grand mal) epilepsy is characterised by a general loss of consciousness with violent involuntary muscle contractions.

      The NICE guidelines for treatment indicates the use of sodium valproate and lamotrigine, but sodium valproate unsuitable in this case and she is a woman of reproductive age and it is known to have teratogenic effects. Lamotrigine is a more suitable choice, prescribed as 800mg daily.

      NICE guidelines also advice an additional prescription of 5mg of folic acid daily for women on anticonvulsant therapy looking to get pregnant. It also warns of the need for extra contraceptive precaution as there is a possibly that the anticonvulsant agent can reduce levels of contraceptive agents.

      Stimulation of the vagal nerve stimulation is only necessary in patients who are refractory to medical treatment and not candidates for surgical resection.

    • This question is part of the following fields:

      • Pathophysiology
      13.4
      Seconds
  • Question 21 - Which of the following drugs is safe to be used in porphyria? ...

    Incorrect

    • Which of the following drugs is safe to be used in porphyria?

      Your Answer: Etomidate

      Correct Answer:

      Explanation:

      Porphyria is a group of disorders in which there is excess production and excess excretion of porphyrins and their precursors. They are usually genetic and are caused due to defects in the haem metabolic pathway. However, other factors like infection, pregnancy, mensuration, starvation may precipitate the attack.

      Sulphonamides, barbiturates (methohexitone and thiopental), and phenytoin are considered to be precipitants so are not safe to use
      Chloral hydrate is thought to be safe to use.
      Etomidate lacks proper studies and may be used with caution but it is generally advised not to use this drug especially if other alternatives are available.

    • This question is part of the following fields:

      • Pharmacology
      29.1
      Seconds
  • Question 22 - The following statements are about capnography. Which of them is true? ...

    Incorrect

    • The following statements are about capnography. Which of them is true?

      Your Answer: Utilises Lambert's law

      Correct Answer: Collision broadening is due to presence of other polyatomic molecules

      Explanation:

      Capnography is the non-invasive measurement and pictorial display of inhaled and exhaled carbon dioxide (CO2) partial pressure.

      It is depicted graphically as the concentration of CO2 over time.

      It is used in disease diagnosis, determining disease severity, assessing response to treatment and is the best method to for indicating when an endotracheal tube is placed in the trachea after intubation.

      The wavelength of IR light usually absorbed by nitrous oxide is between 4.4-4.6?m (very close to that of CO2). Its absorption of wavelengths at 3.9 ?m is much weaker. It causes a measurable deficit of 0.1% for every 10% of nitrous oxide. The maximal wavelength of infrared (IR) light absorbed by carbon monoxide is 4.7 ?m. The volatile agents have strong absorption bands at 3.3 ?m and throughout the ranges 8-12 ?m.

      IR light is not absorbed by oxygen (O2), but O2 and CO2 molecules are constantly colliding which interrupts the absorption of IR light by CO2. This increases the band of absorption, that is the Collison or pressure broadening). An oxygen percentage of 95 will result in a 0.5 percentage fall in CO2 measure.

      IR light is also absorbed by water vapour which will result in an overlap of the absorption band, collision broadening and a dilution of partial pressure. This is why water trap and water permeable tubing is recommended for use as it reduces measurement inaccuracies.

      The use of multi-gas analysers of modern gases also help reduce the effects of collision broadening.

      Beer’s law is also applied in this system as an increase in the concentrations of CO2 causes a decrease in the amount of IR able to pass through the gas. This IR light is what generated the signal that is analysed for display.

      The capnograph can indicate oesophageal intubation, but cannot determine if it is endotracheal or endobronchial. For this, auscultation is used.

    • This question is part of the following fields:

      • Clinical Measurement
      22.8
      Seconds
  • Question 23 - Concerning platelets one of the following is true ...

    Incorrect

    • Concerning platelets one of the following is true

      Your Answer: Contain adenosine triphosphate and serotonin

      Correct Answer: Are formed in the bone marrow from megakaryocytes

      Explanation:

      Platelets are fragments of megakaryocytes and they are encapsulated by membrane.

      They have no nucleus but are metabolically active and are able to express membrane receptors and release stored substances when triggered. adenosine diphosphate and serotonin are 2 of its content.

      Because they have no nucleus, they are not able to produce new proteins. This is why aspirin and other drugs affect function for their entire lifespan after exposure. Its lifespan is approximately 9-10 days in normal individuals.

      Platelets does NOT PRODUCE prostacyclin but are able to produce nitric oxide, prostaglandins and thromboxane.

    • This question is part of the following fields:

      • Pathophysiology
      71.3
      Seconds
  • Question 24 - Which of the following is a characteristic of a type 1B antiarrhythmic agent...

    Incorrect

    • Which of the following is a characteristic of a type 1B antiarrhythmic agent such as Lidocaine?

      Your Answer: Slows force and rate of contraction

      Correct Answer: Shortens refractory period

      Explanation:

      The action of class 1 anti-arrhythmic is sodium channel blockade. Subclasses of this action reflect effects on the action potential duration (APD) and the kinetics of sodium channel blockade.

      Drugs with class 1A prolong the APD and refractory period, and dissociate from the channel with intermediate kinetics.

      Drugs with class 1B action shorten the APD in some tissues of the heart, shorten the refractory period, and dissociate from the channel with rapid kinetics.

      Drugs with class 1C action have minimal effects on the APD and the refractory period, and dissociate from the channel with slow kinetics.

    • This question is part of the following fields:

      • Pharmacology
      116.9
      Seconds
  • Question 25 - If the speed of an ultrasound in soft tissue is 1540 meters per...

    Incorrect

    • If the speed of an ultrasound in soft tissue is 1540 meters per second, what is the estimated wavelength produced if the frequency of a generated ultrasound is 10 megahertz?

      Your Answer: 1.5 millimetres

      Correct Answer: 0.15 millimetre

      Explanation:

      Wavelength can be computed as follows:

      Wavelength = velocity/frequency

      In the given problem, the values stated are:

      Frequency = 10 x 10^6
      Velocity = 1540 meters per second

      Wavelength = 1540/(10×10^6)
      Wavelength = 1540/10,000,000 meters
      Wavelength = 0.15 millimetres

    • This question is part of the following fields:

      • Clinical Measurement
      24.6
      Seconds
  • Question 26 - Of the following statements, which is true about the measurements of cardiac output...

    Correct

    • Of the following statements, which is true about the measurements of cardiac output using thermodilution?

      Your Answer: Cardiac output should be measured during the end-expiratory pause

      Explanation:

      Thermodilution is the most common dilution method used to measure cardiac output (CO) in a hospital setting.

      During the procedure, a Swan-Ganz catheter, which is a specialized catheter with a thermistor-tip, is inserted into the pulmonary artery via the peripheral vein. 5-10mL of a cold saline solution with a known temperature and volume is injected into the right atrium via a proximal catheter port. The solution is cooled as it mixes with the blood during its travel to the pulmonary artery. The temperature of the blood is the measured by the catheter and is profiled using a computer.

      The computer also uses the profile to measure cardiac output from the right ventricle, over several measurements until an average is selected.

      Cardiac output changes at each point of respiration, therefore to get an accurate measurement, the same point during respiration must be used at each procedure, this is usually the end of expiration, that is the end-expiratory pause.

    • This question is part of the following fields:

      • Clinical Measurement
      40.3
      Seconds
  • Question 27 - A 54-year-old man weighing 70kg, underwent mesh repair for inguinal hernia under general...

    Correct

    • A 54-year-old man weighing 70kg, underwent mesh repair for inguinal hernia under general anaesthesia. He was given intravenous co-amoxiclav (Augmentin) following which the patient developed widespread urticarial ras, became hypotensive (61/30 mmHg), and showed clinical signs of bronchospasm. Anaphylaxis is suspected in this patient.

      Which one of the following is considered as best initial pharmacological treatment for this condition?

      Your Answer: Intravenous adrenaline 50 mcg

      Explanation:

      The drug of choice for the treatment of anaphylaxis is adrenaline. It has an intravenous route of administration. Since the patient already has intravenous access, the intramuscular route is not appropriate.

      Second-line pharmacological intervention includes the use of chlorpheniramine 10mg intravenous, Hydrocortisone 200mg.

    • This question is part of the following fields:

      • Pharmacology
      14.1
      Seconds
  • Question 28 - In North America, there have been reports of paediatric patients dying after undergoing...

    Incorrect

    • In North America, there have been reports of paediatric patients dying after undergoing adenotonsillectomy for obstructive sleep apnoea.

      Respiratory depression/obstruction is thought to be the cause of death. The codeine dose was 0.5-1 mg/kg, given every 4-6 hours.

      In this group of patients, which of the following is the most likely cause of respiratory depression and obstruction?

      Your Answer: Overdose of codeine

      Correct Answer: Exaggerated metabolism of codeine

      Explanation:

      Codeine is easily absorbed from the gastrointestinal tract and converted to morphine and norcodeine in the liver via O- and N-demethylation. Morphine and norcodeine are excreted almost entirely by the kidney, primarily as conjugates with glucuronic acid.

      By glucuronidation, phase II metabolism enzyme UDP-glucuronosyl transferase-2B7 converts morphine to morphine-3-glucuronide (M3G) and morphine-6-glucuronide (M6G) (UGT2B7).

      Approximately 60% of morphine is converted to M3G, with the remaining 6-10% converted to M6G. M3G is inactive, but M6G is said to be 4 to 650 times more potent on the MOP receptor than morphine.

      When codeine is consumed, cytochrome P450 2D6 in the liver converts it to morphine (CYP2D6).

      Some people have DNA variations that increase the activity of this enzyme, causing codeine to be converted to morphine more quickly and completely than in others. After taking codeine, these ultra-rapid metabolisers are more likely to have higher than normal levels of morphine in their blood.

      Respiratory depression/obstruction can be caused by high levels of morphine and M6G, especially in people who have a history of obstructive sleep apnoea. The estimated number of ultra-rapid metabolisers ranges from 1 to 7 per 100 people, but some ethnic groups may have as many as 28 per 100 people.

    • This question is part of the following fields:

      • Pathophysiology
      13.9
      Seconds
  • Question 29 - A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a...

    Correct

    • A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a 57-year-old woman. Her vision is causing her problems.

      A macroadenoma compressing the optic chiasm is visible on MRI.

      What is the most likely visual field defect to be discovered during an examination?

      Your Answer: Bitemporal hemianopia

      Explanation:

      The pituitary gland plays a crucial role in the neuro-endocrine axis. It is located at the base of the skull in the sella turcica of the sphenoid bone. It is connected superiorly to the hypothalamus, third ventricle, and visual pathways, and laterally to the cavernous sinuses, internal carotid arteries, and cranial nerves III, IV, V, and VI.

      Pituitary tumours make up about 10-15% of all intracranial tumours. The majority of adenomas are benign. Over-secretion of pituitary hormones (most commonly prolactin, growth hormone, or ACTH), under-secretion of hormones, or localised or generalised pressure effects can all cause symptoms.

      Compression of the optic chiasm can result in visual field defects, the most common of which is bitemporal hemianopia. This is caused by compression of the nasal retinal fibres, which carry visual impulses from temporal vision across the optic chiasm to the contralateral sides before continuing to the optic tracts.

      The interruption of the visual pathways distal to the optic chiasm causes a homonymous visual field defect. The loss of the right or left halves of each eye’s visual field is referred to as homonymous hemianopia. It’s usually caused by a middle or posterior cerebral artery territory stroke that affects the occipital lobe’s optic radiation or visual cortex.

      Binasal hemianopia is a condition in which vision is lost in the inner half of both eyes (nasal or medial). It’s caused by compression of the temporal visual pathways, which don’t cross at the optic chiasm and instead continue to the ipsilateral optic tracts. Binasal hemianopia is a rare complication caused by the internal carotid artery impinging on the temporal (lateral) visual fibres.

      A monocular visual loss (that is, loss of vision in only one eye) can be caused by a variety of factors, but if caused by nerve damage, the damage would be proximal to the optic chiasm on the ipsilateral side.

      A central scotoma is another name for central visual field loss. Every normal mammalian eye has a scotoma, also known as a blind spot, in its field of vision. The optic disc is a region of the retina that lacks photoreceptor cells and is where the retinal ganglion cell axons that make up the optic nerve exit the retina. When both eyes are open, visual signals that are absent in one eye’s blind spot are provided for the other eye by the opposite visual cortex, even if the other eye is closed.

      Scotomata can be caused by a variety of factors, including demyelinating disease such as multiple sclerosis, damage to nerve fibre layer in the retina, methyl alcohol, ethambutol, quinine, nutritional deficiencies, and vascular blockages either in the retina or in the optic nerve.

      Bilateral scotoma can occur when a pituitary tumour compresses the optic chiasm, causing a bitemporal paracentral scotoma, which then spreads out to the periphery, causing bitemporal hemianopsia. A central scotoma in a pregnant woman could be a sign of severe pre-eclampsia.

    • This question is part of the following fields:

      • Pathophysiology
      20.7
      Seconds
  • Question 30 - A 30-year-old man has been diagnosed with a direct inguinal hernia.

    A direct...

    Incorrect

    • A 30-year-old man has been diagnosed with a direct inguinal hernia.

      A direct inguinal hernia passes through Hesselbach's triangle. What forms the medial edge of this triangle?

      Your Answer: Inferior epigastric vein

      Correct Answer: Rectus abdominis muscle

      Explanation:

      The inguinal triangle of Hesselbach’s is an important clinical landmark on the posterior wall of the inguinal canal. It has the following relations:
      Inferiorly – medial third of the inguinal ligament
      Medially – lower lateral border of the rectus abdominis
      Laterally – inferior epigastric vessels

      Direct inguinal hernia is when the bowel bulges directly through the abdominal wall. These hernias usually protrude through Hesselbach’s triangle

    • This question is part of the following fields:

      • Anatomy
      4
      Seconds
  • Question 31 - Of the following, which is NOT a branch of the external carotid artery?...

    Incorrect

    • Of the following, which is NOT a branch of the external carotid artery?

      Your Answer: Facial artery

      Correct Answer: Mandibular artery

      Explanation:

      The external carotid artery has eight important branches:
      1. Superior thyroid artery
      2. Ascending pharyngeal artery
      3. Lingual artery
      4. Facial artery
      5. Occipital artery
      6. Posterior auricular artery
      7. Maxillary artery (terminal branch)
      8. Superficial temporal artery (terminal branch)

      There is no mandibular artery but the first part of the maxillary artery is called the mandibular part as it is posterior to the lateral pterygoid muscle.
      The maxillary artery is divided into three portions by its relation to the lateral pterygoid muscle:
      first (mandibular) part: posterior to the lateral pterygoid muscle
      second (pterygoid or muscular) part: within the lateral pterygoid muscle
      third (pterygopalatine) part: anterior to the lateral pterygoid muscle

    • This question is part of the following fields:

      • Anatomy
      27.6
      Seconds
  • Question 32 - With a cervical dilation of 9 cm, a 23-year-old term primigravida is in...

    Incorrect

    • With a cervical dilation of 9 cm, a 23-year-old term primigravida is in labour. She is otherwise in good health. She's been in labour for 14 hours and counting.

      Early foetal pulse decelerations can be seen on the cardiotocograph, and a recent foetal scalp blood sample revealed a pH of 7.25.

      Which of the following is true about this patient's care and management?

      Your Answer: The patient requires a category 2 caesarean section under spinal anaesthetic

      Correct Answer: Monitor for downward trend in fetal scalp blood pH as caesarean section is not indicated at the present time

      Explanation:

      Once the decision to deliver a baby by caesarean section has been made, it should be carried out with a level of urgency commensurate with the risk to the baby and the mother’s safety.

      There are four types of caesarean section urgency:

      Category 1 – Endangering the life of the mother or the foetus
      Category 2 – Maternal or foetal compromise that is not immediately life threatening
      Category 3 – Early delivery is required, but there is no risk to the mother or the foetus.
      Category 4: Elective delivery at a time that is convenient for both the mother and the maternity staff.

      Caesarean sections for categories 1 and 2 should be performed as soon as possible after the decision is made, especially for category 1. For category 1 caesarean sections, a decision to deliver time of 30 minutes is currently used.

      In most cases, Category 2 caesarean sections should be performed within 75 minutes of making the decision.

      The condition of the woman and the unborn baby should be considered when making a decision for a quick delivery, as it may be harmful in some cases.

      There is no evidence of foetal compromise in the example above (early foetal pulse decelerations and a pH of less than 7.25). Early foetal pulse decelerations are most likely caused by the uterus compressing the foetal head. The foetus is not harmed by these. A spinal anaesthetic is preferred over a general anaesthetic whenever possible.

      If the foetal scalp blood pH is greater than 7.25, it’s a good idea to repeat the test later and look for any changes. When a foetus decelerates, the mother should be given oxygen, kept in a left lateral position, and kept hydrated to avoid the need for a caesarean section.

    • This question is part of the following fields:

      • Pathophysiology
      28.7
      Seconds
  • Question 33 - A study of blood pressure measurements is being performed in patients with chronic...

    Incorrect

    • A study of blood pressure measurements is being performed in patients with chronic kidney disease.

      Considering that the results are normally distributed, what percentage of values lie within two standard deviations of the mean blood pressure reading?

      Your Answer: 10.00%

      Correct Answer: 95.40%

      Explanation:

      Normal distribution, also called Gaussian distribution, the most common distribution function for independent, randomly generated variables, and describes the spread for many biological and clinical measurements.

      Properties of the Normal distribution

      symmetrical i.e. Mean = mode = median

      68.3% of values lie within 1 SD of the mean

      95.4% of values lie within 2 SD of the mean

      99.7% of values lie within 3 SD of the mean

      The empirical rule, or the 68-95-99.7 rule, tells you where most of the values lie in a normal distribution: Around 68% of values are within 1 standard deviation of the mean.

      Around 95% of values are within 2 standard deviations of the mean. Around 99.7% of values are within 3 standard deviations of the mean.
      the standard deviation (SD) is a measure of how much dispersion exists from the mean.

      SD = square root (variance)

      The empirical rule, or the 68-95-99.7 rule states where most of the values lie in a normal distribution. Around 68% of values fall within 1 S.D of the mean, about 95% within 2 S.D of the mean, and about 99.7% of values within 3 S.D of the mean. Therefore, 95.4% is the most reasonable answer if results are normally distributed.

    • This question is part of the following fields:

      • Statistical Methods
      71.8
      Seconds
  • Question 34 - A 50-year old man for septoplasty has a BMI of 32kg/m2 and neck...

    Incorrect

    • A 50-year old man for septoplasty has a BMI of 32kg/m2 and neck circumference of 44 cm. He is troubled by intermittent nasal obstruction which causes his partner sleeps in a separate bedroom because of snoring. He currently on ramipril for hypertension.

      Which of the following best approximates to his STOP-BANG score from the information above?

      Your Answer: 7

      Correct Answer: 5

      Explanation:

      The STOP-BANG questionnaire is used to screen patients for obstructive sleep apnoea (OSA).

      The scoring system assigns one point for each feature.

      S: Snoring (louder than talking or loud enough to be heard through closed doors)
      T: Feeling tired, fatigued, or sleepy during daytime
      O: Observed apnoeas during sleep
      P: Hypertension
      B: BMI more than 35 kg/m2
      A: Age 50-years of age or greater
      N: Neck circumference (male 17 inches / 43cm or greater and female 16 inches / 41 or greater)
      G: Gender: Male

      Our patient has a score of 5 ( O, P, A, N, G)

      The score helps clinicians stratify patients for unrecognized OSA and target appropriate clinical management. It can also help triage patients for further investigation. A STOP-BANG score of 5-8 will identify patients with high probability of moderate to severe OSA in the surgical population.

    • This question is part of the following fields:

      • Clinical Measurement
      11.3
      Seconds
  • Question 35 - Out of the following, which artery is NOT a branch of the hepatic...

    Incorrect

    • Out of the following, which artery is NOT a branch of the hepatic artery?

      Your Answer: Gastroduodenal artery

      Correct Answer: Pancreatic artery

      Explanation:

      The common hepatic artery arises from the celiac artery and has the following branches:
      1. hepatic artery proper that branches into –
      a. cystic artery to supply the gallbladder
      b. left and right hepatic arteries to supply the liver
      2. gastroduodenal artery that branches into
      a. right gastroepiploic artery
      b. superior pancreaticoduodenal artery
      3. right gastric artery

      The pancreatic artery is a branch of the splenic artery.

    • This question is part of the following fields:

      • Anatomy
      28.1
      Seconds
  • Question 36 - All of the following statements are true regarding calcium except: ...

    Incorrect

    • All of the following statements are true regarding calcium except:

      Your Answer: Bronchospasm may be a sign of severe hypocalcaemia

      Correct Answer: Serum calcium accounts for 10% of total body calcium stores

      Explanation:

      Calcium is a very important ion and is involved in:
      -cell homeostasis
      -coagulation
      -muscle contraction
      -neuronal impulse transmission/membrane stabilization
      -bone formation and skeletal strength
      -secretion processes

      99% is found in bone and 1% in the plasma. Of the 1% that is in the plasma
      -45% is free ionized calcium
      -45% is bound to proteins, mainly Albumin
      -10% is present as an anion complex

      Reduced levels of IONIZED calcium give rise to features of hypocalcaemia , resulting in increased excitability of membranes. This results when the total calcium concentration goes below 2 mmol/L.

      Features of mild to moderate hypocalcaemia are:
      -paraesthesia (peri-oral, fingers)
      -tetany
      -spasm
      -muscle cramps
      -ECG changes (prolonged QT)
      -Trousseau’s sign (inflation of tourniquet induces carpopedal spasm)
      -Chvostek’s sign (tapping the facial nerve – cranial nerve VII – causes facial muscle twitch/spasm)

      Features of severe hypocalcaemia are:
      -cardiogenic shock and congestive cardiac failure due to reduced myocardial contractility
      respiratory distress due to bronchospasm, agitation, confusion, seizures

      Features of hypercalcaemia (remember ‘bones, stones, groans and psychic moans’):
      -Abdominal pain
      -Vomiting
      -Constipation
      -Polyuria
      -Polydipsia
      -Depression
      -Lethargy
      -Anorexia
      -Weight loss
      -Hypertension
      -Confusion
      -Pyrexia
      -Calcification in the cornea
      -Renal stones
      -Renal failure
      -Decreased Q-T interval
      -Cardiac shock/collapse

    • This question is part of the following fields:

      • Physiology And Biochemistry
      28.8
      Seconds
  • Question 37 - In which of the following situations will a regional fall in cerebral blood...

    Incorrect

    • In which of the following situations will a regional fall in cerebral blood flow occur, suppose there is no changes in the mean arterial pressure (MAP)?

      Your Answer: Hypercarbia

      Correct Answer: Hyperoxia

      Explanation:

      The response of cerebral blood flow (CBF) to hyperoxia (PaO2 >15 kPa, 113 mmHg), the cerebral oxygen vasoreactivity is less well defined. A study originally described, using a nitrous oxide washout technique, a reduction in CBF of 13% and a moderate increase in cerebrovascular resistance in subjects inhaling 85-100% oxygen. Subsequent human studies, using a variety of differing methods, have also shown CBF reductions with hyperoxia, although the reported extent of this change is variable. Another study assessed how supra-atmospheric pressures influenced CBF, as estimated by changes in middle cerebral artery flow velocity (MCAFV) in healthy individuals. Atmospheric pressure alone had no effect on MCAFV if PaO2 was kept constant. Increases in PaO2 did lead to a significant reduction in MCAFV; however, there were no further reductions in MCAFV when oxygen was increased from 100% at 1 atmosphere of pressure to 100% oxygen at 2 atmospheres of pressure. This suggests that the ability of cerebral vasculature to constrict in response to increasing partial pressure of oxygen is limited.

      Increases in arterial blood CO2 tension (PaCO2) elicit marked cerebral vasodilation.

      CBF increases with general anaesthesia, ketamine anaesthesia, and hypoviscosity.

    • This question is part of the following fields:

      • Physiology
      20.1
      Seconds
  • Question 38 - Which type of epithelium lines the luminal surface of the oesophagus? ...

    Incorrect

    • Which type of epithelium lines the luminal surface of the oesophagus?

      Your Answer: Non ciliated columnar epithelium

      Correct Answer: Non keratinised stratified squamous epithelium

      Explanation:

      Normally, the oesophagus is lined by non-keratinized stratified squamous epithelium. This epithelium can undergo metaplasia and convert to the columnar epithelium (stomach’s lining) in long-standing GERD that leads to Barret’s oesophagus.

    • This question is part of the following fields:

      • Anatomy
      20
      Seconds
  • Question 39 - The liver plays a major role in drug metabolism.

    Which of the following...

    Correct

    • The liver plays a major role in drug metabolism.

      Which of the following liver cells is most important in phase I of drug metabolism?

      Your Answer: Centrilobular cells

      Explanation:

      The metabolism of drugs in the liver occurs in 3 phases

      Phase I: This involves functionalization reactions, which are of 3 types, namely hydrolysis, oxidation and reduction reactions catalysed by the cytochrome P450 (CYP) enzymes.

      Phase II: This involves conjugation or acetylation reactions. The goal is to create water soluble metabolites that can be excreted from the body.

      The liver is the second largest organ. It’s smallest functional unit is the acinus which is divided into 3 zones:

      Zone I (periportal): This zone receives the largest amount of oxygen supply as it is the closest to the blood vessels. It is the site of plasma protein synthesis.

      Zone II (mediolobular): This is located between the portal triad and central vein.

      Zone III (centrilobular): This is closest to the central vein and receives the least amount of oxygen supply.

      Kupffer cells are specialized macrophages found in the periportal zone of the liver, and function to remove foreign particles and breakdown red blood cells via phagocytosis.

      Ito cells are fat-storing liver cells found in the space of Disse. Their function is to take-uo, store and secrete retinoids, as well as manufacture and release proteins that make up the extracellular matrix.

    • This question is part of the following fields:

      • Pathophysiology
      26.1
      Seconds
  • Question 40 - All of the following statements about intravenous induction agents are false except: ...

    Incorrect

    • All of the following statements about intravenous induction agents are false except:

      Your Answer: Etomidate is an imidazole, which is sometimes used for sedation on ITU.

      Correct Answer:

      Explanation:

      Thiopental is a new British Approved Name for thiopentone and is thio-barbiturate.
      Methohexitone is an oxy- barbiturate. Both thiopental and methohexitone are intravenous induction agents.

      Ketamine cannot cause loss of consciousness in less than 30 seconds. At least 30 seconds is needed to cause loss of consciousness following intravenous administration.

      Etomidate is an imidazole but it is not used in the Intensive Care unit for sedation because it has an antidepressant effect on the steroid axis.

    • This question is part of the following fields:

      • Pharmacology
      23.8
      Seconds
  • Question 41 - A laser is a device that stimulates atoms or molecules to emit light...

    Correct

    • A laser is a device that stimulates atoms or molecules to emit light at particular wavelengths and amplifies that light, typically producing a very narrow beam of radiation. This can be of visible, infrared, or ultraviolet wavelengths. They have been widely utilized in theatre environment.

      Which of the following safety measures is most likely to reduce chances of eye injury to the theatre personnel?

      Your Answer: Wearing laser protective goggles

      Explanation:

      Eye damage is the most common potential hazard associated with laser energy. Everyone in the laser treatment room has the risk of eye exposure when working with a Class 3b or Class 4 healthcare laser system, and damage to various structures in the eye depending on wavelength of the laser if they are unprotected.

      Red and near-infrared light (400-1400 nm) has very high penetration power. The light causes painless burns on the retina after it is absorbed by melanin in the pigment epithelium just behind the photoreceptors.

      Infrared radiation (IR), or infrared light (>1060 nm), is a type of radiant energy that’s invisible to human eyes and hence won’t elicit the protective blink.

      Ultraviolet light (<400 nm) is also a form of electromagnetic radiation which is can penetrate the cornea and be absorbed by the iris or the pupil and cause burn injuries or cataract occur due to irreversible photochemical retinal damage. Safety eyewear is the best method of providing eye protection and are designed to absorb light specific to the laser being used. Laser protective eyewear (LPE) includes glasses or goggles of proper optical density (OD). The lenses should not be glass or plastic. The LPE should withstand direct and diffuse scattered laser beams. The laser protection supervisor (LPS) or LSO is an individual who is responsible for any clinical area in which lasers are used. They are expected to have a certain level of equipment and determine what control measures are appropriate, for each individual system, but their presence does not guarantee the chances of having an eye injury. Class 1 lasers are generally safe under every conceivable condition and is not likely to cause any eye damage. Class 3b or Class 4 medical laser systems are utilized in healthcare which have their own safety precautions. Polarized spectacles can make your eyes more comfortable by eliminated glare, however, they will not be able to offer any protection against wavelengths at which laser act.
      Using short bursts to reduce energy is also not correct as it would still be harmful to eye.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      21.2
      Seconds
  • Question 42 - Rocuronium is substituted for succinylcholine during induction of anaesthesia for a caesarean section...

    Incorrect

    • Rocuronium is substituted for succinylcholine during induction of anaesthesia for a caesarean section delivery.

      Which of the following feature of rocuronium ensures the neonate shows no clinical signs of muscle relaxation?

      Your Answer: A large molecule

      Correct Answer: Highly ionised

      Explanation:

      Drugs cross the placenta by Simple, Ion channel and Facilitated diffusion; Exocytosis and Endocytosis, Osmosis, and Active transport (primary and secondary)

      The following factors influence rate of diffusion across the placenta:

      Protein binding
      Degree of ionisation
      Placental blood flow
      Maternal and foetal blood pH
      Materno-foetal concentration gradient.
      Thickness of placental membrane
      Molecular weight of drug <600 Daltons cross by diffusion
      Lipid solubility (lipid soluble molecules readily diffuse across the placenta)

      Rocuronium has a F/M ratios of 0.16, a 30% plasma protein binding, low lipid solubility, a low volume of distribution (0.25L/kg), and a high molecular weight (530Da).

    • This question is part of the following fields:

      • Pharmacology
      16
      Seconds
  • Question 43 - Following a near drowning accident, a 5-year-old child is admitted to the emergency...

    Correct

    • Following a near drowning accident, a 5-year-old child is admitted to the emergency department and advanced paediatric life support is started.

      What is the child's approximate weight, according to the preferred formulae of the Resuscitation Council (UK), the European Resuscitation Council, and the Royal College of Anaesthetists?

      Your Answer: 20-25kg

      Explanation:

      For estimating a child’s weight, the Resuscitation Council (UK) and European Resuscitation Council teach the following formula:

      Weight = (age + 4) × 2

      The weight of the child will be around 20 kg.

      This formula is used in the Primary FRCA exam by the Royal College of Anaesthetists.

      In ‘developed’ countries, the traditional ‘APLS formula’ for estimating weight in children based on age (wt in kg = [age+4] x 2) is acknowledged as underestimating weight by 33.4 percent on average, with the degree of underestimation increasing with increasing age.

      However, more recently, the APLS formula ‘Weight=3(age)+7’ has been found to provide a mean underestimate of only 6.9%. This formula is applicable to children aged 1 to 13 years.

      The estimated weight based on age using this formula is 25 kg.

    • This question is part of the following fields:

      • Physiology
      36.1
      Seconds
  • Question 44 - A 6-year-old child is scheduled for general anaesthesia day surgery. You decide to...

    Incorrect

    • A 6-year-old child is scheduled for general anaesthesia day surgery. You decide to perform an inhalational induction because he is otherwise medically fit.

      Which of the following is the most important factor in deciding which volatile anaesthetic agents to use?

      Your Answer: The more pleasant smell of halothane

      Correct Answer: The low blood:gas solubility of sevoflurane

      Explanation:

      The ideal volatile agent for a day case surgery inhalational induction should have the following characteristics:

      It has a pleasant scent that is not overpowering.
      Breathing difficulties, coughing, or laryngeal spasm are not caused by this substance.
      The action has a quick onset and a quick reversal.

      The blood:gas partition coefficient is a physicochemical property of a volatile agent that determines the onset and offset of anaesthesia. The greater an agent’s insolubility in plasma, the faster its alveolar concentration rises.

      The blood gas partition coefficients of the most commonly used volatile anaesthetic agents are as follows:
      Halothane 2.3
      Desflurane 0.45
      Sevoflurane 0.6
      Nitrous oxide 0.47
      Isoflurane 1.4

      Although halothane has a pleasant odour, it has a slower offset than sevoflurane.

      Sevoflurane also has a pleasant odour and is less likely than desflurane to cause airway irritation and breath-holding.

      The choice of agent for inhalational induction is unaffected by potency/lipid solubility measures such as the oil: gas partition coefficient and MAC.

      In this case, an agent’s saturated vapour pressure is irrelevant.

    • This question is part of the following fields:

      • Pharmacology
      14.6
      Seconds
  • Question 45 - Which drug, if given to a pregnant woman, can lead to deleterious fetal...

    Incorrect

    • Which drug, if given to a pregnant woman, can lead to deleterious fetal effects due to its ability to cross the placenta?

      Your Answer: Glycopyrrolate

      Correct Answer: Atropine

      Explanation:

      It is well known that atropine will cross the placenta and that maternal administration results in an increase in fetal heart rate.

      Atropine is highly selective for muscarinic receptors. Its potency at nicotinic receptors is much lower, and actions at non-muscarinic receptors are generally undetectable clinically. Atropine does not distinguish among the M1, M2, and M3 subgroups of muscarinic receptors. In contrast, other antimuscarinic drugs are moderately selective for one or another of these subgroups. Most synthetic antimuscarinic drugs are considerably less selective than atropine in interactions with nonmuscarinic receptors.

      A study on glycopyrrolate, a quaternary ammonium salt, was found to have a fetal: maternal serum concentration ratio of 0.4 indicating partial transfer.

      Heparin, suxamethonium, and vecuronium do not cross the placenta.

    • This question is part of the following fields:

      • Pharmacology
      64.5
      Seconds
  • Question 46 - A 70-year-old man will have a PICC line inserted as he requires long-term...

    Incorrect

    • A 70-year-old man will have a PICC line inserted as he requires long-term parenteral nutrition. To gain venous access, the line is inserted into the basilic vein at the elbow region.

      As the catheter tip advances into the basilic vein, which venous structure will it first encounter?

      Your Answer: Subclavian vein

      Correct Answer: Axillary vein

      Explanation:

      A peripherally inserted central catheter (PICC) line is a long, thin tube inserted into the vein of a patient’s arm to gain access to the large central veins near the heart. PICC line is indicated for parenteral nutrition or to deliver medications. They can be used for medium-term venous access, defined as anywhere between several weeks to 6 months.

      The veins of choice for PICC are:
      1. Basilic
      2. Brachial
      3. Cephalic
      4. Medial cubital vein

      The vein of choice is the right basilic vein as it has a large circumference and is located superficially. It has the most straight route to the final destination of PICC (SVC or Right atrium). It courses through the axillary vein, then the subclavian, and finally settles into the SVC. It also has the least number of valves and a shallow angle of insertion when compared to the other veins.

      The basilic vein drains the medial end of the dorsal arch of the upper limb, passes along the medial aspect of the forearm, and pierces the deep fascia at the elbow. The basilic vein joins the venae comitantes of the brachial artery to form the axillary vein at the elbow.
      The posterior circumflex humeral vein is encountered before the axillary vein. However, a PICC line is unlikely to enter this structure because of its entry angle into the basilic vein.

    • This question is part of the following fields:

      • Anatomy
      11.3
      Seconds
  • Question 47 - An otherwise fit 7-year-old boy for an elective tonsillectomy is seen holding a...

    Incorrect

    • An otherwise fit 7-year-old boy for an elective tonsillectomy is seen holding a bottle of sugared orange squash at anaesthetic assessment . He appears to have consumed 120 mL of the bottle's contents.

      What is the minimal safe fasting time prior to proceeding with a general anaesthetic in this patient?

      Your Answer: 2 hours

      Correct Answer: 1 hour

      Explanation:

    • This question is part of the following fields:

      • Pathophysiology
      82.2
      Seconds
  • Question 48 - A study designed to examine the benefits of adding a new antiplatelet to...

    Incorrect

    • A study designed to examine the benefits of adding a new antiplatelet to aspirin after a myocardial infraction. The recorded results give us the percentage of patients that reported myocardial infraction within a three month period. The percentage was 4% and 3% for aspirin and the combination of drugs respectively.

      How many further patients needed to be treated in order for one patient to avoid any more heart attacks during 3 months?

      Your Answer: 0.33

      Correct Answer: 100

      Explanation:

      Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.

      It can be found as:

      NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).

      where ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)

      So,

      ARR= (0.04-0.03)

      ARR= 0.01

      NNT= 1/0.01

      NNT=100

    • This question is part of the following fields:

      • Statistical Methods
      8
      Seconds
  • Question 49 - Using a negative feedback loop, Haem production is controlled by which of these...

    Incorrect

    • Using a negative feedback loop, Haem production is controlled by which of these enzymes?

      Your Answer: Ferrochelatase

      Correct Answer: ALA synthetase

      Explanation:

      Heme a exists in cytochrome a and heme c in cytochrome c; they are both involved in the process of oxidative phosphorylation. 5′-Aminolevulinic acid synthase (ALA-S) is the regulated enzyme for heme synthesis in the liver and erythroid cells.

      There are two forms of ALA Synthase, ALAS1, and ALAS2.

    • This question is part of the following fields:

      • Physiology
      95.9
      Seconds
  • Question 50 - Which of the following is true regarding the mechanism of action of daptomycin?...

    Incorrect

    • Which of the following is true regarding the mechanism of action of daptomycin?

      Your Answer: Damages bacterial DNA

      Correct Answer: Interferes with the outer membrane of gram positive bacteria resulting in cell death

      Explanation:

      Daptomycin alters the curvature of the membrane, which creates holes that leak ions. This causes rapid depolarization, resulting in loss of membrane potential. Thus it interferes with the outer membrane of gram-positive bacteria resulting in cell death.

    • This question is part of the following fields:

      • Pharmacology
      40.6
      Seconds
  • Question 51 - A doctor has recorded the number of times the patient did not attend...

    Incorrect

    • A doctor has recorded the number of times the patient did not attend (DNA) the clinic for a study over a 10 month period.

      Number of DNAs in 10 Months Number of Patients
      1st Month 0
      2nd Month 3
      3rd Month 1
      4th Month 45
      5th Month 2
      6th Month 0
      7th Month 1
      8th Month 4
      9th Month 4
      10th Month 2

      Which among the following is the most apt way of summarizing mean value?

      Your Answer: Mean

      Correct Answer: Median

      Explanation:

      Variance and standard deviation indicate the dispersion of the plot from mean value and thus are not really helpful in summarizing the mean.

      Range is the difference between maximum and minimum value that is 45 in this case.

      The mean in this case is 6.2 due to the presence of an outlier 45. In the presence of outlier mean can be misleading as it is quite sensitive to skewness in data.

      Mode is the most frequent value. In this case mode has 4 values: 0,1,2,4.

      In case of skewedness, median is the most apt representative of the mean as it is not affected by outliers. In this case since the data set has even values i.e. 10. Median is the average of the 5th & 6th entry after arranging the data in ascending order like that in case of the question (0,0,1,1,2,2,3,4,4,45). This turns out to be 2.

    • This question is part of the following fields:

      • Statistical Methods
      94.9
      Seconds
  • Question 52 - A 39-year old man came to the Out-Patient department for symptoms of gastroesophageal...

    Incorrect

    • A 39-year old man came to the Out-Patient department for symptoms of gastroesophageal reflux disease. Medical history revealed he is on anti-epileptic medication Phenytoin. His plasma phenytoin levels are maintained between 10-12 mcg/mL (Therapeutic range: 10-20 mcg/mL). He is given a H2 antagonist receptor agent (Cimetidine) for his GERD symptoms.

      Upon follow-up, his plasma phenytoin levels increased to 38 mcg/mL.

      Regarding metabolism and elimination, which of the following best explains the pharmacokinetics of phenytoin at higher plasma levels?

      Your Answer: Elimination rate is proportional to the plasma concentration

      Correct Answer: Plasma concentration plotted against time is linear

      Explanation:

      Drug elimination is the termination of drug action, and may involve metabolism into inactive state and excretion out of the body. Duration of drug action is determined by the dose administered and the rate of elimination following the last dose.

      There are two types of elimination: first-order and zero-order elimination.

      In first-order elimination, the rate of elimination is proportionate to the concentration; the concentration decreases exponentially over time. It observes the characteristic half-life elimination, where the concentration decreases by 50% for every half-life.

      In zero-order elimination, the rate of elimination is constant regardless of concentration; the concentration decreases linearly over time. A constant amount of the drug being excreted over time, and it occurs when drugs have saturated their elimination mechanisms.

      Since phenytoin is observed in elevated levels, the elimination mechanisms for it has been saturated and, thus, will have to undergo zero-order elimination.

    • This question is part of the following fields:

      • Pharmacology
      30.3
      Seconds
  • Question 53 - A 20-year-old boy is undergoing surgery for indirect inguinal hernia repair. The deep...

    Correct

    • A 20-year-old boy is undergoing surgery for indirect inguinal hernia repair. The deep inguinal ring is exposed and held with a retractor at its medial aspect during the procedure.

      What structure is most likely to lie under the retractor on the medial side?

      Your Answer: Inferior epigastric artery

      Explanation:

      The deep inguinal ring is the entrance of the inguinal canal. It is an opening in the transversalis fascia around 1 cm above the inguinal ligament. Therefore, the superolateral wall is made by the transervalis fascia.

      The inferior epigastric vessels run medially to the deep inguinal ring forming its inferomedial border.

      The inguinal canal extends obliquely from the deep inguinal ring to the superficial inguinal ring.
      An indirect inguinal hernia arises through the deep inguinal ring lateral to the inferior epigastric vessels.

    • This question is part of the following fields:

      • Anatomy
      24.5
      Seconds
  • Question 54 - Because this benzodiazepine has a half-life of 2-4 hours, it is preferred for...

    Incorrect

    • Because this benzodiazepine has a half-life of 2-4 hours, it is preferred for clinical use.

      This benzodiazepine has which of the following properties that no other benzodiazepine has?

      Your Answer: It is the drug of choice for status epilepticus

      Correct Answer: It is water soluble at a pH of 3.5 and lipid soluble at a pH of 7.4

      Explanation:

      Midazolam is the benzodiazepine in question. It’s the only benzodiazepine that undergoes tautomeric transformation (dynamic isomerism). The molecule is ionised and water soluble at pH 3.5, but when injected into the body at pH 7.4, it becomes unionised and lipid soluble, allowing it to easily pass through the blood brain barrier.

      The half-life of midazolam is only 2-4 hours.

      It is a GABAA receptor agonist because it is a benzodiazepine. GABAA receptors are found in abundance throughout the central nervous system, particularly in the cerebral cortex, hippocampus, thalamus, basal ganglia, and limbic system. GABAA receptors are ligand-gated ion channels, with the inhibitory neurotransmitter gamma-aminobutyric acid as the endogenous agonist. It is a pentameric protein (2, 2 and one subunit) that spans the cell membrane, and when the agonist interacts with the alpha subunit, a conformational change occurs, allowing chloride ions to enter the cell, resulting in neuronal hyperpolarization.

      For status epilepticus, midazolam is not the drug of choice. Lorazepam is the benzodiazepine of choice for status epilepticus.

    • This question is part of the following fields:

      • Pharmacology
      29.4
      Seconds
  • Question 55 - Which of the following is an expected change in pulmonary function seen during...

    Incorrect

    • Which of the following is an expected change in pulmonary function seen during a moderate asthma attack?

      Your Answer: Decreased functional residual capacity (FRC)

      Correct Answer: Decreased forced expiratory volume in 1 sec (FEV1)

      Explanation:

      Asthma is a lung condition that causes reversible narrowing and swelling of airway passages. It is classified by the frequency and severity of symptoms.

      The following are symptoms of moderate asthma:

      Symptoms include cough, wheezing, chest tightness, or difficulty breathing which occurs daily
      Decreased activity levels due to flare-ups
      Night-time symptoms 5 or more times a month
      Lung function test FEV1 is 60-80% of predicted normal values
      Peak flow has more than 30% variability

      With moderate asthma attacks, the arterial pCO2 levels may decrease, but as severity increases, so does the pCO2, reaching normal levels, and then exceeding them in severe asthma attacks.

      Airway obstruction increases the functional residual capacity.

      Concentration of serum bicarbonate would not increase in moderate asthma, but it could possibly increase in life-threatening asthma via the same mechanism as what increases arterial PCO2.

      FEV1 is a good measure of airway obstruction. and is reduced in acute asthma attacks.

      In the case of a pneumothorax, a decrease in arterial PO2 is higher.

    • This question is part of the following fields:

      • Pathophysiology
      35.1
      Seconds
  • Question 56 - Considering research studies, which of the following is considered as a limitation of...

    Incorrect

    • Considering research studies, which of the following is considered as a limitation of the Delphi method?

      Your Answer: It involves direct confrontation of experts with one another

      Correct Answer: Potential low response rates

      Explanation:

      The Delphi technique was developed in the 1950s and is a widely used and accepted method for achieving convergence of opinion concerning real-world knowledge solicited from experts within certain topic areas. Choosing the appropriate subjects is the most important step in the entire process because it directly relates to the quality of the results generated, despite this, there is no exact criterion currently listed in the literature concerning the selection of Delphi participants.

      Therefore, due to the potential scarcity of qualified participants and the relatively small number of subjects used in a Delphi study, the ability to achieve and maintain an ideal response rate can either ensure or jeopardize the validity of a Delphi study.

    • This question is part of the following fields:

      • Statistical Methods
      14.4
      Seconds
  • Question 57 - A 27-year-old woman is admitted to the emergency room with an ectopic pregnancy...

    Incorrect

    • A 27-year-old woman is admitted to the emergency room with an ectopic pregnancy that has ruptured.

      The following is a description of the clinical examination:

      Anxious
      Capillary refill time of 3 seconds
      Cool peripheries
      Pulse 120 beats per minute
      Blood pressure 120/95 mmHg
      Respiratory rate 22 breaths per minute.

      Which of the following is the most likely explanation for these clinical findings?

      Your Answer: Reduction in blood volume of 40-50%

      Correct Answer: Reduction in blood volume of 15-30%

      Explanation:

      The following is the Advanced Trauma Life Support (ATLS) classification of haemorrhagic shock:

      Class I haemorrhage:
      It has blood loss up to 15%. There is very less tachycardia, and no changes in blood pressure, RR or pulse pressure. Usually, fluid replacement is not required.

      Class II haemorrhage:
      It has 15-30% blood loss, equivalent to 750 – 1500 ml. There is tachycardia, tachypnoea and a decrease in pulse pressure. Patient may be frightened, hostile and anxious. It can be stabilised by crystalloid and blood transfusion.

      Class III haemorrhage:
      There is 30-40% blood loss. It portrays inadequate perfusion, marked tachycardia, tachypnoea, altered mental state and fall in systolic pressure. It requires blood transfusion.

      Class IV haemorrhage:
      There is > 40% blood volume loss. It is a preterminal event, and the patient will die in minutes. It portrays tachycardia, significant depression in systolic pressure and pulse pressure, altered mental state, and cold clammy skin. There is need for rapid transfusion and surgical intervention.

    • This question is part of the following fields:

      • Physiology
      70
      Seconds
  • Question 58 - Which statement regarding the cardiac action potential is correct? ...

    Incorrect

    • Which statement regarding the cardiac action potential is correct?

      Your Answer: Phase 2 is the plateau phase with large influx of calcium ions

      Correct Answer:

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
      25
      Seconds
  • Question 59 - Arrythmias can develop from abnormal conduction, which may be as a result of...

    Incorrect

    • Arrythmias can develop from abnormal conduction, which may be as a result of impaired blood flow in the coronary arteries which causes hypoxia. Phase 0 depolarisation can be slowed, and this leads to slower conduction speeds.
      Rapid depolarisation in the cardiac action potential is caused by which movement of ions?

      Your Answer: Calcium influx

      Correct Answer: Sodium influx

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
      139.9
      Seconds
  • Question 60 - A 240 volt alternating current (AC) socket from a wall is used to...

    Incorrect

    • A 240 volt alternating current (AC) socket from a wall is used to charge a direct current (DC) cardiac defibrillator.

      Name the electrical component that converts AC to DC.

      Your Answer:

      Correct Answer: Rectifier

      Explanation:

      There are two types of defibrillators
      AC defibrillator
      DC defibrillator

      AC defibrillator,
      consists of a step-up transformer with primary and secondary winding and two switches. Since secondary coil consists of more turns of wire than the primary coil, it induces larger voltage. A voltage value ranging between 250V to 750V is applied for AC external defibrillator. And used to enable the charging of a capacitor.

      DC defibrillator,
      consists of auto transformer T1 that acts as primary of the high voltage transformer T2. Is an iron core that transfers energy between 2 circuits by electromagnetic induction. Transformers are used to isolate circuits, change impedance and alter voltage output. transformers do not convert AC to DC.

      Diode rectifier composed of 4 diodes made of semiconductor material allows current to flow only in one direction. Alternating current (AC) passing through these diodes produces direct current (DC). Capacitor stores the charge in the form of an electrostatic field.

      Capacitor is used to convert the rectified AC voltage to produce DC voltage but capacitors do not directly convert AC to DC.

      Inductor induces a counter electromotive force(emf) that reduces the capacitor discharge value.

      In step-down transformer primary coils has more turns of wire than secondary coil, so induced voltage is smaller in the secondary coil.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 61 - A 20-year old lady has been having excessive bruising and bleeding of her...

    Incorrect

    • A 20-year old lady has been having excessive bruising and bleeding of her gums. She is under investigation for the extrinsic pathway of coagulation. Which is the best investigation to order?

      Your Answer:

      Correct Answer: Prothrombin time (PT)

      Explanation:

      The extrinsic pathway is best assessed by the PT time.

      D-dimer is a fibrin degradation product which is raised in the presence of blood clots.

      A 50:50 mixing study is used to assess if a prolonged PT or aPTT is due to factor deficiency or a factor inhibitor.

      The thrombin time is a test used to assess fibrin formation from fibrinogen in plasma. Factors that prolong the thrombin time include heparin, fibrin degradation products, and fibrinogen deficiency.

      Intrinsic pathway – Best assessed by APTT. Factors 8,9,11,12 are involved. Prolonged aPTT can be seen in haemophilia and use of heparin.

      Extrinsic pathway – Best assessed by Increased PT. Factor 7 involved.

      Common pathway – Best assessed by APTT & PT. Factors 2,5,10 involved.

      Vitamin K dependent factors are factors 2,7,9,10

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 62 - All of the following are true when describing the autonomic nervous system except:...

    Incorrect

    • All of the following are true when describing the autonomic nervous system except:

      Your Answer:

      Correct Answer: Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole parasympathetic control

      Explanation:

      With regards to the autonomic nervous system (ANS)

      1. It is not under voluntary control
      2. It uses reflex pathways and different to the somatic nervous system.
      3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.

      With regards to the central nervous system (CNS)
      1. There are myelinated preganglionic fibres which lead to the
      ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
      2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.

      Most organs are under control of both systems although one system normally predominates.

      The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.

      There are short pre-ganglionic and long post ganglionic fibres.
      Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
      Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
      However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.

      The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.

      There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.

      Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.

      The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.

      The cranial outflow consists of
      1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
      2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
      3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
      4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreas

      The sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.

      The PNS has long preganglionic and short post ganglionic fibres.
      Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
      Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.

      Different types of these muscarinic receptors are present in different organs:
      There are:
      M1 = pupillary constriction, gastric acid secretion stimulation
      M2 = inhibition of cardiac stimulation
      M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
      M4 = brain and adrenal medulla
      M5 = brain

      The lacrimal glands are solely under parasympathetic control.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 63 - A 64-year old lady has been diagnosed with hypertension. Her GP explains how...

    Incorrect

    • A 64-year old lady has been diagnosed with hypertension. Her GP explains how this occurs, and that blood pressure is determined by multiple factors which include action by the heart, nervous system and the diameter of the blood vessels. This lady's cardiac output (CO) is 4L/min. Her exam today revealed a mean arterial pressure (MAP) of 140 mmHg.
      Using these values, her systemic vascular resistance (SVR) is which of these?

      Your Answer:

      Correct Answer: 35mmHg⋅min⋅mL-1

      Explanation:

      Impaired ventricular relaxation reduces diastolic filling and therefore preload.

      Decreased blood volume decreases preload due to reduced venous return.

      Heart failure is characterized by reduced ejection fraction and therefore stroke volume.

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure (is increased by stroke volume) = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume
      Aortic stenosis would decrease stroke volume as end systolic volume would increase.
      This is because of an increase in afterload, an increase in resistance that the heart must pump against due to a hard stenotic valve.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 64 - A 35-year-old male presents to GP presenting an area of erythema which was...

    Incorrect

    • A 35-year-old male presents to GP presenting an area of erythema which was around a recent cut on his right forearm. He was prescribed a short course of antibiotics and after 5 days again presented with progressive fatigue, headaches, and fevers.
      On clinical examination:
      Oxygen saturation: 98% on room air
      Respiratory rate: 22 per minute
      Heart rate: 100 beats per minute
      Blood pressure: 105/76 mmHg
      Temperature: 38.2 degree Celsius

      On physical examination, a dramatic increase in the area of erythema was noted.
      Blood culture was done in the patient and indicated the presence of bacterium containing beta-lactamase. Which of the following antibiotics was likely prescribed to the patient?

      Your Answer:

      Correct Answer: Amoxicillin

      Explanation:

      Ciprofloxacin belongs to the quinolone group of antibiotics, and doxycycline and minocycline are tetracyclines. So, they are not affected by beta-lactamase.
      However, amoxicillin is a beta-lactam antibiotic and beta-lactamase cleaves the beta-lactam ring present in amoxicillin. This results in the breakdown of the antibiotic and thus the area of erythema dramatically increased.
      Co-amoxiclav contains amoxicillin and clavulanic acid which protects amoxicillin from beta-lactamase.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 65 - Which of the following statements is true about the in-hospital management of ventricular...

    Incorrect

    • Which of the following statements is true about the in-hospital management of ventricular fibrillation?

      Your Answer:

      Correct Answer: Amiodarone may be administered following a third DC shock

      Explanation:

      Ventricular fibrillation (VT) is an arrhythmia caused by a distortion in the organized contraction of the ventricles leading to an inability to pump blood out into the body.

      Amiodarone is an anti arrhythmic drug used for the treatment of ventricular and atrial fibrillations. It is the gold standard of treatment for refractory pulseless ventricular tachycardia (VT) and ventricular fibrillation (VF).

      Guidelines for emergency treatment state that only the rescuer carrying out chest compressions on the patient may stand near the defibrillator as it charges.

      Cardio-pulmonary resuscitation (CPR) during cardiac arrest is required for 2 minute cycles.

      Hypovolaemia is as a cause of pulseless electrical activity (PEA) can be reversed using fluid resuscitation, whereas hypotension during cardiac arrest is either persistent or undetectable and is therefore irreversible.

      Hyperkalaemia and hypocalcaemia are treated using calcium salts, but calcium chloride is often preferred over calcium gluconate.

      During a pulseless VT or VF, a single precordial thump will be effective if administered within the first seconds of the occurrence of a shockable rhythm.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 66 - Regarding the following induction agents, which one is cleared at the fastest rate...

    Incorrect

    • Regarding the following induction agents, which one is cleared at the fastest rate from the plasma?

      Your Answer:

      Correct Answer: Propofol

      Explanation:

      Propofol is cleared at the fastest rate at the rate of 60ml/kg/min.

      Clearance rate of other drugs are as follows:
      – Thiopental: 3.5 ml/kg/min
      – Methohexitone: 11 ml/kg/min
      – Ketamine: 17 ml/kg/min
      – Etomidate: 10-20 ml/kg/min

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 67 - Out of the following, which is NOT true regarding the external carotid? ...

    Incorrect

    • Out of the following, which is NOT true regarding the external carotid?

      Your Answer:

      Correct Answer: It ends by bifurcating into the superficial temporal and ascending pharyngeal artery

      Explanation:

      The external carotid artery has eight important branches:
      Anterior surface:
      1. Superior thyroid artery (first branch)
      2. Lingual artery
      3. Facial artery
      Medial branch
      4. Ascending pharyngeal artery
      Posterior branches
      5. Occipital artery
      6. Posterior auricular artery
      Terminal branches
      7. Maxillary artery
      8. Superficial temporal artery

      The external carotid has eight branches, 3 from its anterior surface ; thyroid, lingual and facial. The pharyngeal artery is a medial branch. The posterior auricular and occipital are posterior branches.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 68 - The spinal cord in a neonate terminates at the lower border of: ...

    Incorrect

    • The spinal cord in a neonate terminates at the lower border of:

      Your Answer:

      Correct Answer: L3

      Explanation:

      The spinal cord and the vertebral canal are as long as each other in early fetal life. The length of the cord increases faster than the growth of the vertebrae during development. By the time of birth, the spinal cord is at the level of the lower border of the 3rd lumbar vertebra, compared to its original position at the level of the 2nd coccygeal vertebra.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 69 - A man suffers damage to his vagus nerve during surgery on his neck....

    Incorrect

    • A man suffers damage to his vagus nerve during surgery on his neck. The vagus nerve is cut near its exit from the skull. The man loses his parasympathetic tone raising his heart rate and blood pressure.

      What other feature will be likely present with a vagus nerve injury?

      Your Answer:

      Correct Answer: Hoarse voice

      Explanation:

      The vagus nerve is a mixed nerve with both autonomic and somatic effects. Its most important somatic effect is the motor supply to the larynx via recurrent laryngeal nerves. If one vagus nerve is damaged, the result will be the same as damage to a single recurrent laryngeal nerve, leading to hoarseness of voice.

      The vagus exits the skull via the jugular foramen, accompanied by the accessory nerve.

      Anal tone, erections, and urination are all controlled by the sacral parasympathetic and would not be affected by the loss of the vagus. Parasympathetic controlled pupillary constriction is via the oculomotor nerve and would not be affected by the loss of the vagus.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 70 - All of the following are responses to massive haemorrhage except which of the...

    Incorrect

    • All of the following are responses to massive haemorrhage except which of the following?

      Your Answer:

      Correct Answer: Decreased cardiac output by increased direct parasympathetic stimulation

      Explanation:

      With regards to compensatory response to blood loss, the following sequence of events take place:

      1. Decrease in venous return, right atrial pressure and cardiac output
      2. Baroreceptor reflexes (carotid sinus and aortic arch) are immediately activated
      3. There is decreased afferent input to the cardiovascular centre in medulla. This inhibits parasympathetic reflexes and increases sympathetic response
      4. This results in an increased cardiac output and increased SVR by direct sympathetic stimulation. There is increased circulating catecholamines and local tissue mediators (adenosine, potassium, NO2)
      5. Fluid moves into the intravascular space as a result of decreased capillary hydrostatic pressure absorbing interstitial fluid.

      A slower response is mounted by the hypothalamus-pituitary-adrenal axis.
      6. Reduced renal blood flow is sensed by the intra renal baroreceptors and this stimulates release of renin by the juxta-glomerular apparatus.
      7. There is cleavage of circulating Angiotensinogen to Angiotensin I, which is converted to Angiotensin II in the lungs (by Angiotensin Converting Enzyme ACE)

      Angiotensin II is a powerful vasoconstrictor that sets off other endocrine pathways.
      8. The adrenal cortex releases Aldosterone
      9. There is antidiuretic hormone release from posterior pituitary (also in response to hypovolaemia being sensed by atrial stretch receptors)
      10. This leads to sodium and water retention in the distal convoluted renal tubule to conserve fluid
      Fluid conservation is also aided by an increased amount of cortisol which is secreted in response to the increase in circulating catecholamines and sympathetic stimulation.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 71 - Intracellular effectors are activated by receptors on the cell surface. These receptors receive...

    Incorrect

    • Intracellular effectors are activated by receptors on the cell surface. These receptors receive signals that are relayed by second messenger systems.

      In the human body, which second messenger is most abundant?

      Your Answer:

      Correct Answer: Calcium ions

      Explanation:

      Second messengers relay signals to target molecules in the cytoplasm or nucleus when an agonist interacts with a receptor on the cell surface. They also amplify the strength of the signal. The most ubiquitous and abundant second messenger is calcium and it regulates multiple cellular functions in the body.

      These include:
      Muscle contraction (skeletal, smooth and cardiac)
      Exocytosis (neurotransmitter release at synapses and insulin secretion)
      Apoptosis
      Cell adhesion to the extracellular matrix
      Lymphocyte activation
      Biochemical changes mediated by protein kinase C.

      cAMP is either inhibited or stimulated by G proteins.

      The receptors in the body that stimulate G proteins and increase cAMP include:

      Beta (?1, ?2, and ?3)
      Dopamine (D1 and D5)
      Histamine (H2)
      Glucagon
      Vasopressin (V2).

      The second messenger for the action of nitric oxide (NO) and atrial natriuretic peptide (ANP) is cGMP.

      The second messengers for angiotensin and thyroid stimulating hormone are inositol triphosphate (IP3) and diacylglycerol (DAG).

    • This question is part of the following fields:

      • Physiology
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  • Question 72 - All of the statements describing the blood brain barrier are false EXCEPT:...

    Incorrect

    • All of the statements describing the blood brain barrier are false EXCEPT:

      Your Answer:

      Correct Answer: Inflammation alters its permeability

      Explanation:

      The blood brain barrier (BBB) consists of the ultrafiltration barrier in the choroid plexus and the barrier around cerebral capillaries. The barrier is made by endothelial cells which line the interior of all blood vessels. In the capillaries that form the blood–brain barrier, endothelial cells are wedged extremely close to each other, forming so-called tight junctions.

      Outside of the BBB lies the hypothalamus, third and fourth ventricles and the chemoreceptor trigger zone (CTZ).

      Water, oxygen and carbon dioxide cross the BBB freely but glucose is controlled. The ability of chemicals to cross the barrier is proportional to their lipid solubility, not their water solubility. It’s ability to cross is inversely proportional to their molecular size and charge.

      In neonates, the BBB is less effective than in adults. This is why there is increased passage of opioids and bile salts (kernicterus) into the neonatal brain.

      In meningitis, the effectiveness and permeability of the BBB is affected, and as a result, this effect helps the passage of antibiotics which would otherwise not normally be able to cross.

    • This question is part of the following fields:

      • Physiology
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  • Question 73 - A 55-year-old male is diagnosed with superior vena cava obstruction. What is the...

    Incorrect

    • A 55-year-old male is diagnosed with superior vena cava obstruction. What is the number of collateral circulations that exist for alternate pathways for venous return?

      Your Answer:

      Correct Answer: Four

      Explanation:

      Superior vena cava is the main vein bringing blood back to the heart. It can get partially or completely blocked by various causes, the most common being due to malignant tumours of the mediastinum.

      There are collateral pathways that form in long-standing cases with 60% or more stenosis and continue venous drainage in cases of superior vena obstruction. The collaterals are classified into four as follows:

      1. The azygos-hemiazygos pathway
      Azygos, hemiazygos, intercostal, and lumbar veins.

      2. The internal and external mammary pathway
      internal mammary, superior epigastric, and inferior epigastric veins and superficial veins of the thorax.

      3. The lateral thoracic pathway
      Lateral thoracic, thoracoepigastric, superficial circumflex, long saphenous, and femoral veins to collateralize to the IVC.

      4. The vertebral pathway
      Innominate, vertebral, intercostal, lumbar, and sacral veins to collateralize to the azygos and internal mammary pathways.

    • This question is part of the following fields:

      • Anatomy
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  • Question 74 - A 20-year-old female presents to the emergency department. She complains of increased shortness...

    Incorrect

    • A 20-year-old female presents to the emergency department. She complains of increased shortness of breath and wheezing over the last 48 hours. On examination, she is found to have tachycardia, tachypnoea, and oxygen saturation at 91% on air. She admits to a previous medical history of asthma, diagnosed 4 years ago. She requires further investigations for diagnosis.

      Which of the following is true about the assessment of a patient with symptomatic asthma?

      Your Answer:

      Correct Answer: Oxygen saturations of 91% on air would be an indication for performing arterial blood gases

      Explanation:

      A patient presenting with symptomatic asthma should be assessed for severity to determine appropriate management options. Indications of acute severe asthma are:

      Peak expiratory flow rate (PEFR): 33-50% best/predicted
      Respiratory rate: ≥25/min
      Heart rate: ≥110/min
      Inability to finish a complete sentence in a single breath.

      Oxygen saturation should be measured. Any measurement of an oxygen saturation of 92% or less, either on air or on oxygen, indicates severe, life threatening asthma, and requires an arterial blood gas (ABG) to detect normo- or hypercarbia.

      A chest x-ray would not be routine as it will not provide any relevant information. It is only required in specific cases, including:
      Diagnosis of a subcutaneous emphysema
      Indications of a unilateral pneumothorax
      Indications of a lobar collapse of consolidation
      Treatment-resistance life-threatening asthma
      If mechanical ventilation is indicated

      A peak expiratory flow rate (PEFR) can provide relevant information to help distinguish between acute, moderate, severe and life threatening asthma. However, it is not necessary as other parameters exist that can also help make the same distinction.

      An ECG is indicated in this case as the patient has tachycardia and tachypnoea which are indicative of acute severe asthma. The ECG would indicate if arrhythmia is also present which would suggest life-threatening asthma.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 75 - During the design phase of a study, which among the given is aimed...

    Incorrect

    • During the design phase of a study, which among the given is aimed at addressing confounding factors?

      Your Answer:

      Correct Answer: Randomisation

      Explanation:

      Randomisation allows for performance of experimental trials in a random order. Using this method gives us control over the confounding variables that are not supposed to be held constant.

      For an instance, by employing randomisation we get to control biological differences among individual human beings during experimental trials.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 76 - Two different anti-viral treatments are being evaluated for COVID-19 in a clinical study....

    Incorrect

    • Two different anti-viral treatments are being evaluated for COVID-19 in a clinical study.

      Which of the following statistical method should be opted to compare survival time with?

      Your Answer:

      Correct Answer: Hazard ratio

      Explanation:

      The hazard ratio (HR) is simply a comparison of two hazards in a study. It provides an estimate of the ratio of the hazard rates between the experimental group and a control group over the entire study duration. It is typically used when analysing survival over time, hence is the most suitable statistical method in this case.

      An odds ratio is a statistic that quantifies the strength of the association between two events, A and B. It is the “measure of association” for a case-control study.

      The Pearson product-moment correlation coefficient (Pearson’s correlation, for short) is a measure of the strength and direction of association that exists between two variables. An example would be if scientists wanted to evaluate the relationship between quality of certain population of rice and their genetic make-up.

      Relative risk is the ratio of the risks for an event for the exposure group to the risks for the non-exposure group. Thus relative risk provides an increase or decrease in the likelihood of an event based on some exposure. Relative risk measures the association between the exposure and the outcome.

      Absolute risk reduction is the number of percentage points your own risk goes down if you do a preventive act such as stop drinking alcohol. It depends on what your risk factors are to begin with.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 77 - The action potential in a muscle fibre is initiated by which of these...

    Incorrect

    • The action potential in a muscle fibre is initiated by which of these ions?

      Your Answer:

      Correct Answer: Sodium ions

      Explanation:

      The cardiac action potential has several phases which have different mechanisms of action as seen below:
      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology
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  • Question 78 - Which of the following statements is true regarding oxygen? ...

    Incorrect

    • Which of the following statements is true regarding oxygen?

      Your Answer:

      Correct Answer: Forms molecules containing either two or three atoms

      Explanation:

      Oxygen is formed by a molecule of oxygen and two molecules of hydrogen with a molecular formula of H2O

      The critical temperature is defined as a temperature above which the substance cannot be liquefied, no matter how much pressure is applied.
      Water has a critical temperature of -118.6oC. So, it cannot be liquified at room temperature.

      Medical oxygen cylinder is stored in a cylinder with a white shoulder and black body. Meanwhile, medial air is stored in cylinders with a white and black shoulder and a French grey body.

      The partial pressure of air at a high altitude is less but the relative concentration remains constant.

    • This question is part of the following fields:

      • Basic Physics
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  • Question 79 - A 50-year-old man, presents to the hospital with bilateral inguinal hernias.
    After examination...

    Incorrect

    • A 50-year-old man, presents to the hospital with bilateral inguinal hernias.
      After examination and investigation, the surgical team decides to perform a laparoscopic hernia repair using the extraperitoneal approach. After making an infraumbilical incision, the surgeons perform the repair by placing a prosthetic mesh over the affected area, after shifting the inferior aspect of the rectus abdominis muscle anteriorly.

      Name the structure that would like posterior to the mesh?

      Your Answer:

      Correct Answer: Peritoneum

      Explanation:

      This question is asking which structure would lie posterior to the rectus abdominis muscle and not the prosthetic mesh, as only peritoneum lies posterior to mesh during a total extraperitoneal (TEP) hernia repair.

      The region of the repair lies below the arcuate line, meaning that the transversalis fascia and peritoneum lie posterior to the rectus abdominis.

      The bucks fascia lies within the penis.

    • This question is part of the following fields:

      • Anatomy
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  • Question 80 - The following statements are about the conjugation of bilirubin. Which is true? ...

    Incorrect

    • The following statements are about the conjugation of bilirubin. Which is true?

      Your Answer:

      Correct Answer: Is catalysed by a glucuronyl transferase

      Explanation:

      Bilirubin is formed by metabolizing heme, mostly from haemoglobin in red blood cells.

      Bilirubin is conjugated to glucuronic acid in the hepatocytes by the glucuronyl transferase enzyme in order to enable it to become soluble and allow for its secretion across the canalicular membrane and into bile.

      The conjugation process is increased by rifampicin and decreased by valproate.

      Gilbert’s syndrome is caused by a decrease in glucuronyl transferase in the hepatic system, decreasing the transport of bilirubin into the hepatocyte, causing unconjugated bilirubinaemia.

      Crigler-Najjer syndrome is caused by mutations in the genes responsible for hepatic glucuronyl transferase, decreasing the activity of the enzyme, meaning bilirubin cannot be conjugated, causing unconjugated bilirubinaemia.

      Dubin-Johnson syndrome does not cause an impairment in the conjugation of bilirubin, but it blocks the transport of bilirubin out of the hepatocyte resulting in conjugated bilirubinaemia.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 81 - Which of the following drugs can have significant clinical effects on neonates when...

    Incorrect

    • Which of the following drugs can have significant clinical effects on neonates when used in appropriate doses for a caesarean section?

      Your Answer:

      Correct Answer: Alfentanil

      Explanation:

      Opioid should be avoided in the caesarean section as it crosses the placental membrane and causes respiratory depression.

      Even though inhalational and intravenous anaesthetic agents readily cross the placenta, they do not have significant effects on APGAR score when used in clinical doses.

      Vecuronium and suxamethonium are highly polar molecules and thus do not cross the placenta in significant amounts.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 82 - Of the stated laws, which is correct? ...

    Incorrect

    • Of the stated laws, which is correct?

      Your Answer:

      Correct Answer: Boyle's law states that at constant temperature the volume of a given mass of gas varies inversely with absolute pressure.

      Explanation:

      Boyle’s law is correctly stated as it states that the volume of a gas of known mass is inversely proportional with absolute pressure, at a constant temperature.

      Beer’s law states that radiation absorption by a solution of known thickness and concentration is identical to that of a solution of double thickness and half concentration.

      Bougner’s (or Lambert’s) law states that every layer with the same thickness will absorb the same amount of radiation as it passes through.

      Graham’s law states that the diffusion rate of a gas is inversely related to the square root of its molecular weight.

      Raoult’s law states that the reduction of a solvent’s vapour pressure is directly proportional to the solute’s molar concentration.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 83 - A 64-year old male has shortness of breath on exertion and presented to...

    Incorrect

    • A 64-year old male has shortness of breath on exertion and presented to the cardiology clinic. He has a transthoracic echo performed to help in assessing the function of his heart.
      How can this echo aid in calculating cardiac output?

      Your Answer:

      Correct Answer: (end diastolic LV volume - end systolic LV volume) x heart rate

      Explanation:

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 84 - Which of the following combinations of signs seen in a patient would most...

    Incorrect

    • Which of the following combinations of signs seen in a patient would most likely confirm ingestion of substances with anticholinesterase effects?

      Your Answer:

      Correct Answer: Bradycardia and miosis

      Explanation:

      An acetylcholinesterase inhibitor or anticholinesterase is a chemical that inhibits the cholinesterase enzyme from breaking down acetylcholine (ACh) therefore increasing the level and duration of action of the neurotransmitter acetylcholine(ACh).

      ACh stimulates postganglionic receptors to produce the following effects:

      Salivation
      Lacrimation
      Defecation
      Micturition
      Sweating
      Miosis
      Bradycardia, and
      Bronchospasm.

      Since these effects are produced by muscarine, they are referred to as muscarinic effects, and the postganglionic receptors are called muscarine receptors.

      SLUD (Salivation, Lacrimation, Urination, Defecation – and emesis) is usually encountered only in cases of drug overdose or exposure to nerve gases. It is a syndrome of pathological effects indicating massive discharge of the parasympathetic nervous system.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 85 - Which one of the following statement is true regarding United Kingdom gas cylinders?...

    Incorrect

    • Which one of the following statement is true regarding United Kingdom gas cylinders?

      Your Answer:

      Correct Answer: Tensile tests are performed on sections of one cylinder in every hundred

      Explanation:

      Medical gas cylinders are made up of molybdenum steel but not cast iron. They are checked and assessed at a regular interval.

      At least one cylinder in each hundred are tested for tensile, pressure, smash, twist and straightening.

      Nitrous Oxide cylinders contain a mixture of liquid and vapour at a pressure of approx. 4500 kPa or 45 Bar. Carbon dioxide cylinder contain gas at the pressure of 5000kPa.

      The filling ratio is the ratio of mass of liquified gas in the cylinder to the mass of water required to fill the cylinder at the temperature of 15ºC. In the united kingdom, filling ratio of liquid nitrous oxide is 0.75. The cylinders are usually attached to the anaesthetic machine. As nitrous oxide is an N-methyl-d-aspartate receptor antagonist that may reduce the incidence of chronic post-surgical pain.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 86 - The resistance to flow in a blood vessel is affected by the following...

    Incorrect

    • The resistance to flow in a blood vessel is affected by the following except?

      Your Answer:

      Correct Answer: Thickness of the vessel wall

      Explanation:

    • This question is part of the following fields:

      • Physiology
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  • Question 87 - Clearance techniques are used to assess renal glomerular function.

    Which of the following is...

    Incorrect

    • Clearance techniques are used to assess renal glomerular function.

      Which of the following is the most accurate marker for glomerular filtration rate measurement?

      Your Answer:

      Correct Answer: Inulin

      Explanation:

      The perfect glomerular filtration marker is:

      The human body is not harmed by it.
      Chemical or physical methods are used to accurately measure
      Extracellular fluid (ECF) compartment is freely and evenly diffusible.
      Inability to access the intracellular fluid (ICF) compartment
      Filtration in the kidney is the only way to remove it from the blood.

      The ideal marker should not be reabsorbed into the bloodstream by the renal tubules or other urinary system components.

      Creatinine is an endogenous substance that is filtered freely by the glomerulus and secreted by the proximal tubule. As a result, creatinine clearance consistently underestimates GFR. In healthy people, this overestimation ranges from 10% to 40%, but it is higher and more unpredictable in patients with chronic kidney disease.

      The gold standard method of inulin clearance necessitates an intravenous infusion and several hours of timed urine collection, making it costly and time-consuming. Inulin is hard to come by and is difficult to mix and keep as a solution.

      Exogenous filtration markers include the following:

      Although plasma clearance of 51chromium EDTA is a widely used method in Europe, tubular reabsorption can occur.
      Because 125I-iothalamate can be excreted by renal tubules in the urine, it cannot be used in patients who have an iodine assay.

      Radioactive substances must be stored, administered, and disposed of according to these methods.

      The glomerulus filters para-aminohippuric acid (PAH) freely, and any that remains in the peritubular capillaries is secreted into the proximal convoluted tubules. This marker is used to determine the amount of blood flowing through the kidneys.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 88 - You are asked about the relative risk associated with a drug. You happened...

    Incorrect

    • You are asked about the relative risk associated with a drug. You happened to have read a report in which the same drug was compared with a placebo and your initial thoughts after reading the study were that the drug will have significant side effects.

      What do you expect the value of relative risk to be?

      Your Answer:

      Correct Answer: Greater than 1

      Explanation:

      Risk ratio (relative risk) compares the probability of an event in an exposed (experimental) group to that of an event in the unexposed (control) group.

      A relative risk of 1 suggests that there is no discernible difference in the outcome whether or not it has been exposed.

      A relative risk of less than 1 indicates that probability of occurrence of an event is less if there is exposure.

      A relative risk of greater than 1 highlights that an event is most likely to occur if it was provided exposure. Since you believe that exposure (the new drug) would have side effects, the value should be greater than 1.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 89 - Which of the following is true about Calcium? ...

    Incorrect

    • Which of the following is true about Calcium?

      Your Answer:

      Correct Answer: Only 1% of total body Calcium is found in the plasma

      Explanation:

      Only 1 percent of the calcium in the human body is found in the plasma where it performs the most critical functions.

      Out of this 1 percent, approximately 15% is complexed calcium bound to organic and inorganic anions, 40% is bound to albumin, and the remaining 45% circulates as free ionized calcium.

      The Chvostek sign is a clinical finding associated with hypocalcaemia, or low levels of calcium in the blood. This clinical sign refers to a twitch of the facial muscles that occurs when gently tapping an individual’s cheek, in front of the ear.

      Prolonged QT interval are associated with hypocalcaemia as reported in multiple studies.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 90 - A patient is evaluated for persistent dysphonia six months after undergoing a subtotal...

    Incorrect

    • A patient is evaluated for persistent dysphonia six months after undergoing a subtotal thyroidectomy.

      Which of the following is the most likely reason for the change in this patient's voice?

      Your Answer:

      Correct Answer: Damage to recurrent laryngeal nerve

      Explanation:

      After thyroid surgery, about 10-15% of patients experience a temporary subjective voice change of varying degrees. A frog in the throat or cracking of the voice, or a weak voice, are common descriptions. These modifications are only temporary, lasting a few days to a few weeks.

      Swelling of the muscles in the area of the dissection, as well as inflammation and oedema of the larynx due to the dissection, or minor trauma from the tracheal tube, are all suspected causes.

      On both sides of the thyroid gland, the superior laryngeal nerve (EBSLN) runs along the upper part. The muscles that fine-tune the vocal cords are innervated by these nerves. The quality of their voice is usually normal if they are injured, but making high-pitched sounds may be difficult. Injury to the EBSLN occurs in about 2% of the population.

      Injuries to the recurrent laryngeal nerve (RLN) have been reported to occur in 1 percent to 14 percent of people. Except for the cricothyroid muscle, the RLN supplies all of the laryngeal intrinsic muscles.

      This complication is usually unilateral and temporary, but it can also be bilateral and permanent, and it can be intentional or unintentional. The most common complication following thyroid surgery is a permanent lesion of damaged RLN, which manifests as an irreversible phonation dysfunction.

      The crico-arytenoid joint dislocation is a relatively uncommon complication of tracheal intubation and blunt neck trauma. The probability is less than one in a thousand.

      Vocal cord polyps affect 0.8 percent of people.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 91 - Which of the following statements is true with regards to the Krebs' cycle...

    Incorrect

    • Which of the following statements is true with regards to the Krebs' cycle (also known as the tricarboxylic acid cycle or citric acid cycle)?

      Your Answer:

      Correct Answer: Alpha-ketoglutarate is a five carbon molecule

      Explanation:

      Krebs’ cycle (tricarboxylic acid cycle or citric acid cycle) is a sequence of reactions in which acetyl coenzyme A (acetyl-CoA) is metabolised and this results in carbon dioxide and hydrogen atoms production.

      This series of reactions occur in the mitochondria of eukaryotic cells, not the cytoplasm. The cycle requires oxygen and so, cannot function under anaerobic conditions.

      It is the common pathway for carbohydrate, fat and some amino acids oxidation and is required for high energy phosphate bond formation in adenosine triphosphate (ATP).

      When pyruvate enters the mitochondria, it is converted into acetyl-CoA. This represents the formation of a 2 carbon molecule from a 3 carbon molecule. There is loss of one CO2 but formation of one NADH molecule. Acetyl-CoA is condensed with oxaloacetate, the anion of a 4 carbon acid, to form citrate which is a 6 carbon molecule.

      Citrate is then converted into isocitrate, alpha-ketoglutarate, succinyl-CoA, succinate, fumarate, malate and finally oxaloacetate.

      The only 5 carbon molecule in the cycle is alpha-ketoglutarate.

    • This question is part of the following fields:

      • Physiology
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  • Question 92 - When an inotrope is given to the body, it has the following effects...

    Incorrect

    • When an inotrope is given to the body, it has the following effects on the cardiovascular system:

      The automaticity of the sino-atrial node increases
      Lusitropy is accelerated
      Dromotropy is increased
      Chronotropy is increased
      Inotropy increases
      There is increased excitability of the conducting system

      The most probably mechanism of action of this compound is?

      Your Answer:

      Correct Answer: Increase in intracellular calcium influenced by a conformational change of a Gs protein

      Explanation:

      A beta-1 adrenoreceptor agonist is most likely the ligand that causes increased automaticity, increased chronotropy, increased excitability, and increased inotropy on the sino-atrial node. However, alpha-1 adrenoreceptor effects may cause an increase in systemic vascular resistance. Noradrenaline, adrenaline, dopamine, and ephedrine are examples of drugs with mixed alpha and beta effects.

      Adrenaline, noradrenaline, dopamine, dopexamine, dobutamine, ephedrine, and isoprenaline are examples of drugs that have some beta-1 activity. The beta-1 receptor is a G protein-coupled metabotropic receptor. When the beta-1 agonist binds to the cell surface membrane, it causes a conformational change in the Gs unit, which triggers a cAMP-dependent pathway and a calcium influx into the cell.

      Catecholamines also help to relax the heart muscle (positive lusitropy). Dromotropy is the ability to increase the atrioventricular (AV) node’s conduction velocity.

      Inodilators cause an increase in intracellular calcium as a result of phosphodiesterase III (PDIII) inhibition. Milrinone, enoximone, and amrinone are some examples. Positive inotropy is caused by increased calcium entry into the myocytes. Lusitropy is also increased by phosphodiesterase inhibitors. Increased cAMP inhibits myosin light chain kinase, resulting in reduced phosphorylation of vascular smooth muscle myosin, lowering systemic and pulmonary vascular resistance.

      The mechanism of action of alpha-1 adrenoreceptor agonists is an increase in intracellular calcium caused by an increase in inositol triphosphate (IP3). IP3 is a second messenger that causes an increase in systemic vascular resistance by stimulating the influx of Ca2+ into smooth muscle cells. Reflex bradycardia can occur as a result of the subsequent increase in blood pressure. Phenylephrine and metaraminol are examples of pure alpha-1 agonists.

      Levosimendin is a novel inotrope that makes myocytes more sensitive to intracellular Ca2+. It causes a positive inotropy without changing heart rate or oxygen consumption significantly.

      The Na-K-ATPase membrane pump in the myocardium is inhibited by digoxin. This inhibition promotes sodium-calcium exchange, resulting in an increase in intracellular Ca2+ and increased contraction force. The parasympathetic effects of digoxin on the AV node result in bradycardia. Systemic vascular resistance will not be affected by it.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 93 - The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised...

    Incorrect

    • The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised by which of the following?

      Your Answer:

      Correct Answer: Synthesis of ATP is brought about by anaerobic respiration

      Explanation:

      Muscle fibre myosin ATPase histochemistry is used to divide the biochemical classification into two groups: type 1 and type II.

      Type I (slow twitch) muscle fibres rely on aerobic glycolytic and aerobic oxidative metabolism to function. They have a lot of mitochondria, a good blood supply, a lot of myoglobin, and they don’t get tired easily.

      Because they contain more motor units, Type II (fast twitch) muscle fibres are thicker. They are more easily fatigued, but produce powerful bursts. The capillary networks and mitochondria are less dense in these white muscle fibres than in type I fibres. They have a low myoglobin content as well.

      Muscle fibres of type II (fast twitch) are divided into three types:

      Type IIa – aerobic/oxidative metabolism is used.
      Type IIb – anaerobic/glycolytic metabolism is used by these fibres.

      When compared to skeletal muscle, cardiac and smooth muscle twitch at a slower rate.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 94 - A subject in a study is to take 100 mg of tramadol tablets...

    Incorrect

    • A subject in a study is to take 100 mg of tramadol tablets for the next eight hours. Urine samples will be taken during the 8-hour course, which will undergo analysis via liquid chromatography.

      Given the following metabolites, which one would have the highest analgesic property?

      Your Answer:

      Correct Answer: Mono-O-desmethyl-tramadol

      Explanation:

    • This question is part of the following fields:

      • Pharmacology
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  • Question 95 - Regarding bilirubin, which one of the following statement is true? ...

    Incorrect

    • Regarding bilirubin, which one of the following statement is true?

      Your Answer:

      Correct Answer: Conjugated bilirubin is stored in the gall bladder

      Explanation:

      Bilirubin is the tetrapyrrole and a catabolic product of heme. 70-90% of bilirubin is end product of haemoglobin degradation in the liver.

      Bilirubin circulates in the blood in 2 forms; unconjugated and conjugated bilirubin.

      Unconjugated bilirubin is insoluble in water. It travels through the bloodstream to the liver, where it changes from insoluble into a soluble form (i.e.; unconjugated into conjugated form).

      This conjugated bilirubin travels from the liver into the small intestine and the gut bacteria convert bilirubin into urobilinogen and then into urobilin (not urobilin to urobilinogen). A very small amount passes into the kidneys and is excreted in urine.

    • This question is part of the following fields:

      • Physiology
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  • Question 96 - A 72-year-old man complains of severe, central abdominal pain that radiates to the...

    Incorrect

    • A 72-year-old man complains of severe, central abdominal pain that radiates to the back. He has a past medical history of an abdominal aortic aneurysm.

      A focused abdominal ultrasonography test (FAST) is performed, revealing diffuse dilatation of the abdominal aorta. The most prominent dilatation is at the bifurcation site of abdominal aorta into the iliac arteries.

      What vertebra level corresponds to the site of the most prominent dilatation as evident on the FAST scan?

      Your Answer:

      Correct Answer: L4

      Explanation:

      The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:

      T12 – Coeliac trunk

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta

    • This question is part of the following fields:

      • Anatomy
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  • Question 97 - A pulmonary function tests results are:

    Measurement Predicted result Test result
    Forced vital capacity (FVC)...

    Incorrect

    • A pulmonary function tests results are:

      Measurement Predicted result Test result
      Forced vital capacity (FVC) (btps) 3.85 2.36
      Forced expiratory volume in 1 second (FEV1) (btps) 3.34 0.97
      FEV1/FVC ratio % (btps) 85.1 39.9
      Peak expiratory flow (PEF) (L/second) 7.33 2.11
      Maximum voluntary ventilation (MVV) (L/minute) 116 44.4

      What does this indicate?

      Your Answer:

      Correct Answer: Moderate restrictive and severe obstructive picture

      Explanation:

      Severity of a reduction in restrictive defect (%FVC) or obstructive defect (%FEV1/FVC) predicted are classified as follows:

      Mild 70-80%
      Moderate 60-69%
      Moderately severe 50-59%
      Severe 35-49%
      Very severe <35% This patient has a mixed deficit with a severe obstructive deficit as %FEV1/FVC predicted is 46.9% and a moderate restrictive deficit as %FVC of predicted is 61.3 FEV1/FVC ratio 80% < predicted and VC < 80% = mixed picture. FEV1/FVC ratio 80% < predicted and VC > 80% = obstructive picture.

      FEV1/FVC ratio 80% > predicted and VC > 80% = normal picture.

      FEV1/FVC ratio 80% > predicted and VC < 80% predicted= restrictive picture.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 98 - The rapid depolarisation phase of the myocardial action potential is caused by: ...

    Incorrect

    • The rapid depolarisation phase of the myocardial action potential is caused by:

      Your Answer:

      Correct Answer: Rapid sodium influx

      Explanation:

      The cardiac action potential has several phases which have different mechanisms of action as seen below:
      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 99 - Over the course of 10 minutes, a normally fit and well 22-year-old male...

    Incorrect

    • Over the course of 10 minutes, a normally fit and well 22-year-old male receives a 1 litre intravenous bolus of 20% albumin.

      Which of the following primary physiological responses in this patient has the highest chance to influence a change in urine output?

      Your Answer:

      Correct Answer: Stimulation of atrial natriuretic peptide (ANP) secretion

      Explanation:

      The renal effects of atrial natriuretic peptide (ANP) secretion are as follows:

      Increased glomerular filtration rate by dilating the afferent glomerular arteriole. Moreover, it constricts the efferent glomerular arteriole, and relaxes the mesangial cells.
      Reduces sodium reabsorption in the collecting ducts and distal convoluted tubule.
      The renin-angiotensin system (RAS) is inhibited.
      Blood flow in the vasa recta is increased.

      Because plasma osmolality is unlikely to change, hypothalamic osmoreceptors are unaffected.

      The plasma protein has a molecular weight of 66 kDa, is not normally filtered into the proximal convoluted tubule, and has no osmotic diuretic effect.

      The following are some basic assumptions:

      Extracellular fluid (ECF) makes up one-third of total body water (TBW), while intracellular fluid makes up the other two-thirds (ICF)
      One-quarter plasma and three-quarters interstitial fluid make up ECF (ISF)
      The volume receptors in the atria have a 7-10% blood volume change threshold.
      The osmoreceptors are sensitive to changes in osmolality of 1-2 percent.
      The normal plasma osmolality before the transfusion is 287-290 mOsm/kg.
      The plasma protein solution is a colloid that is only delivered to the intravascular compartment. The tonicity remains unchanged.
      The blood volume increases by 20%, from 5,000 mls to 6,000 mls. This is higher than the volume receptor threshold of 7 to 10%.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 100 - Which of the following is true about the patellar reflex? ...

    Incorrect

    • Which of the following is true about the patellar reflex?

      Your Answer:

      Correct Answer: Is abolished immediately after transection of the spinal cord at T6

      Explanation:

      The patellar (knee jerk) reflex is a monosynaptic stretch reflex arising from L2-L4 nerve roots. It occurs after a tap on the patellar tendon which causes the spindles of the quadriceps muscles to stretch.

      The afferent nerve pathway occurred through A gamma fibres.

      Wesphal’s sign refers to a reduction, or absence of the patellar reflex. It is often indicated of a neurological disease affecting the PNS.

      A transection of the spinal cord results in a degree of shock which causes all reflexes to be reduced or completely absent, and required a period of approximately 6 weeks to recover.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 101 - An arterial pressure transducer is supposedly in direct correlation to change, thus it...

    Incorrect

    • An arterial pressure transducer is supposedly in direct correlation to change, thus it is dependent on zero gradient drift and zero offset. Which of the following values will best compensate for the gradient drift?

      Your Answer:

      Correct Answer: 0 mmHg and 200 mmHg

      Explanation:

      Since an arterial pressure transducer, and every other measuring apparatus, is prone to errors due to offset and gradient drifts, regular calibration is required to maintain accuracy of the instrument. The two-point calibration pressure values of 0 mmHg and 200 mmHg are within the physiologic range and can best compensate for the gradient drift.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 102 - Which of the following is true regarding a laryngoscope? ...

    Incorrect

    • Which of the following is true regarding a laryngoscope?

      Your Answer:

      Correct Answer: The Wisconsin and Seward are examples of straight blade laryngoscopes

      Explanation:

      Direct laryngoscopy are performed using laryngoscopes and they can be classed according to the shape of the blade as curved or straight.

      Miller, Soper, Wisconsin and Seward are examples of straight blade laryngoscopes. Straight blades are commonly used for intubating neonates and infants but can be used in adults too.

      The tip of the miller blade is advanced over the epiglottis to the tracheal entrance then lifted in order to view the vocal cords.

      The RIGHT-SIDED Macintosh blade is used in adults while the left-sided blade may be used in conditions that make intubation with standard blade difficult e.g. facial deformities.

      The McCoy laryngoscope is based on the STANDARD MACINTOSH blade not Robertshaw’s. It has a lever operated hinged tip, which improves the view during laryngoscopy.

      Polio blade is mounted at an angle of 120-135 degrees to the handle. Originally designed for use during the polio epidemic ​in intubation patients within iron lung ventilators, it is now useful in patients with conditions like breast hypertrophy, barrel chest, and restricted neck mobility.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 103 - The most sensitive indicator of mild obstructive airway disease is? ...

    Incorrect

    • The most sensitive indicator of mild obstructive airway disease is?

      Your Answer:

      Correct Answer: Forced expiratory flow (FEF25-75%)

      Explanation:

      The volume expired in the first second of maximal expiration after a maximal inspiration is known as forced expiratory volume in one second (FEV1), and it indicates how quickly full lungs can be emptied. It is the most commonly measured parameter for bronchoconstriction assessment.

      The maximum volume of air exhaled after a maximal inspiration is known as the ‘slow’ vital capacity (VC). VC is normally equal to FVC after a forced vital capacity (FVC) or slow vital capacity (VC) manoeuvre, unless there is an airflow obstruction, in which case VC is usually higher than FVC.

      The FEV1/FVC (Tiffeneau index) is a clinically useful index of airflow restriction that can be used to distinguish between restrictive and obstructive respiratory disorders.

      The average expired flow over the middle half (25-75 percent) of the FVC manoeuvre is the forced expiratory volume (FEF25-75). The airflow from the resistance bronchioles corresponds to this. It’s a more sensitive indicator of mild small airway narrowing than FEV1, but it’s difficult to tell if the VC (or FVC) is decreasing or increasing.

      The maximum expiratory flow rate achieved is called the peak expiratory flow (PEF), which is usually 8-14 L/second.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 104 - A morbidly obese (BMI=48) patient has the following co-morbidities: type II diabetes mellitus...

    Incorrect

    • A morbidly obese (BMI=48) patient has the following co-morbidities: type II diabetes mellitus and hypertension. It is recommended for the patient to undergo bariatric surgery.

      If the patient is laid flat for induction of anaesthesia, what physiologic changes of the respiratory system is the most important to consider?

      Your Answer:

      Correct Answer: Functional residual capacity will decrease

      Explanation:

      A decrease in the functional residual capacity (FRC) is the most important physiologic change to consider for such patients.

      FRC is the sum of the expiratory reserve volume and the residual volume. It is the resting volume of the lung, and is an important marker for lung function. During this time, the alveolar pressure is equal to the atmospheric pressure. When morbidly obese individuals lie supine, the FRC decreases by as much as 40% because the abdominal contents push the diaphragm into the thoracic cavity.

      Chest wall compliance is expected to reduce because of fat deposition surrounding adjacent structures.

      Inspiratory reserve volume (IRV) is expected to increase, and peak expiratory flow is expected to decrease, however the decrease in FRC is more important to consider because of the risk of hypoxia secondary to premature airway closure and ventilation-perfusion mismatch.

    • This question is part of the following fields:

      • Physiology
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  • Question 105 - Activation of which of the following GABA A receptor subunit leads to anxiolytic...

    Incorrect

    • Activation of which of the following GABA A receptor subunit leads to anxiolytic effects of Benzodiazepines?

      Your Answer:

      Correct Answer: Alpha

      Explanation:

    • This question is part of the following fields:

      • Pharmacology
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  • Question 106 - What is the order of the anatomical components of the tracheobronchial tree from...

    Incorrect

    • What is the order of the anatomical components of the tracheobronchial tree from proximal to distal?

      Your Answer:

      Correct Answer: Bronchioles, terminal bronchioles, respiratory bronchioles, alveolar ducts, alveolar sacs

      Explanation:

      The tracheobronchial tree is subdivided into the conducting and the respiratory zones.

      The zones from proximal to distal are:

      Trachea
      Bronchi
      Bronchioles
      Terminal bronchioles
      Respiratory bronchioles
      Alveolar ducts
      Alveolar sacs

      from the trachea to terminal bronchioles are the conducting zone while the respiratory zone is from the respiratory bronchioles to the alveola sacs

    • This question is part of the following fields:

      • Anatomy
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  • Question 107 - An orthopaedic surgery is scheduled for a 68-year-old man. He is normally in...

    Incorrect

    • An orthopaedic surgery is scheduled for a 68-year-old man. He is normally in good shape. His routine biochemistry results are checked and found to be within normal limits.

      Which of the following pairs has the greatest impact on his plasma osmolarity?

      Your Answer:

      Correct Answer: Sodium and potassium cations

      Explanation:

      The number of osmoles (Osm) of solute per litre (L) of solution (Osmol/L) is the unit of measurement for solute concentration. The calculated serum osmolality assumes that the primary solutes in the serum are sodium salts (chloride and bicarbonate), glucose, and urea nitrogen.

      2 (Na + K) + Glucose + Urea (all in mmol/L) = calculated osmolarity

      313 mOsm/L = 2 (144 + 6) + 9.5 + 3.5

      Sodium and potassium ions clearly contribute the most to plasma osmolarity. Glucose and urea, on the other hand, are less so.

      The osmolarity of normal serum is 285-295 mOsm/L. Temperature and pressure affect osmolality, and this calculated variable is less than osmolality for a given solution.

      The number of osmoles (Osm) of solute per kilogramme (Osm/kg) is a measure of osmolality, which is also a measure of solute concentration. Temperature and pressure have no effect on the value. An osmometer is used to measure it in the lab. Osmometers rely on a solution’s colligative properties, such as a decrease in freezing point or a rise in vapour pressure.

      The osmolar gap (OG) is calculated as follows:

      OG = osmolaRity calculated from measured serum osmolaLity

      Excess alcohols, lipids, and proteins in the blood can all contribute to the difference.

    • This question is part of the following fields:

      • Physiology
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  • Question 108 - Which of the following drugs would cause the most clinical concern if accidentally...

    Incorrect

    • Which of the following drugs would cause the most clinical concern if accidentally administered intravenously to a 4-year-old boy?

      Your Answer:

      Correct Answer: 20 mg codeine

      Explanation:

      To begin, one must determine the child’s approximate weight. There are a variety of formulas to choose from. It is acceptable to use the advanced paediatric life support formula:

      (age + 4) 2 = weight

      A 5-year-old child will weigh around 18 kilogrammes.

      The following are the appropriate doses of the drugs listed above:

      Gentamicin (once daily) – 5-7 mg/kg = 90-126 mg and subsequent dose modified according to plasma levels
      Ondansetron – 0.1 mg/kg, but a maximum of 4 mg as a single dose = 1.8 mg
      Codeine should be administered orally at a dose of 1 mg/kg rather than intravenously, as the latter can cause ‘dangerous’ hypotension due to histamine release.
      15 mg/kg paracetamol = 270 mg orally or intravenously (a loading dose of 20 mg/kg, or 360 mg, is sometimes recommended, which is not far short of the doses listed above).
      Cefuroxime – the initial intravenous dose is 20 mg/kg (360 mg) depending on the indication (again, similar to the dose given in the answer options above).

    • This question is part of the following fields:

      • Pharmacology
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  • Question 109 - A 40-year-old woman was diagnosed with hyperparathyroidism. She is undergoing a parathyroidectomy, and...

    Incorrect

    • A 40-year-old woman was diagnosed with hyperparathyroidism. She is undergoing a parathyroidectomy, and during the surgery, the inferior parathyroid gland is found to be enlarged. There is a vessel adjacent to this gland on its lateral side.

      What is this vessel most likely to be?

      Your Answer:

      Correct Answer: Common carotid artery

      Explanation:

      There are four parathyroid glands that lie on the medial half of the posterior surface of each lobe of the thyroid gland, inside its sheath. There are two superior and two inferior parathyroid glands.

      The common carotid artery is a lateral relation of the inferior parathyroid.

    • This question is part of the following fields:

      • Anatomy
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  • Question 110 - A 50-year old female came to the Obstetric and Gynaecology department for an...

    Incorrect

    • A 50-year old female came to the Obstetric and Gynaecology department for an elective hysterectomy under general anaesthesia. Upon physical examination, she was noted to be obese (BMI = 40).

      Regarding the optimal dose of thiopentone, which of the following parameters must be considered for the computation?

      Your Answer:

      Correct Answer: Lean body weight

      Explanation:

      Using a lean body weight metric encompasses a more scientific approach to weight-based dosing. Lean body weight reflects the weight of all ‘non-fat’ body components, including muscle and vascular organs such as the liver and kidneys. As lean body weight contributes to approximately 99% of a drug’s clearance, it is useful for guiding dosing in obesity.

      This metric has undergone a number of transformations. The most commonly cited formula derived by Cheymol is not optimal for dosing across body compositions and can even produce a negative result. A new formula has been developed that appears stable across different body sizes, in particular the obese to morbidly obese.

      A practical downfall of the calculation of lean body weight (and other body size descriptors) is the numerical complexity, which may not be palatable to a busy clinician. Often limited time is available for prescribing and an immediate calculation is required. Lean body weight calculators are available online, for example in the Therapeutic Guidelines.

      Using total body weight assumes that the pharmacokinetics of the drug are linearly scalable from normal-weight patients to those who are obese. This is inaccurate. For example, we cannot assume that a 150 kg patient eliminates a drug twice as fast as a 75 kg patient and therefore double the dose. Clinicians are alert to toxicities with higher doses, for example nephro- and neurotoxicity with some antibiotics and chemotherapeutics, and bleeding with anticoagulants. Arbitrary dose reductions or ‘caps’ are used to avoid these toxicities, but if too low can result in sub-therapeutic exposure and treatment failure.

      Body surface area is traditionally used to dose chemotherapeutics. It is a function of weight and height and has been shown to correlate with cardiac output, blood volume and renal function. However, it is controversial in patients at extremes of size because it does not account for varying body compositions. As a consequence, some older drugs such as cyclophosphamide, paclitaxel and doxorubicin were ‘capped’ (commonly at 2 m^2) potentially resulting in sub-therapeutic treatment. Recent guidelines suggest that unless there is a justifiable reason to reduce the dose (e.g. renal disease), total body weight should be used in the calculation of body surface area, until further research is done. Little research into dosing based on body surface area has been conducted for other medicines.

      Ideal body weight was developed for insurance purposes not for drug dosing. It is a function of height and gender only and, like body surface area, does not take into account body composition. Using ideal body weight, all patients of the same height and sex would receive the same dose, which is inadequate and generally results in under-dosing. For example a male who has a total body weight of 150 kg and a height of 170 cm will have the same ideal body weight as a male who is 80 kg and 170 cm tall. Both could potentially receive a mg/kg dose based on 65 kg (ideal body weight).

    • This question is part of the following fields:

      • Pharmacology
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  • Question 111 - What feature is found in the flowmeters of modern anaesthetic machines ? ...

    Incorrect

    • What feature is found in the flowmeters of modern anaesthetic machines ?

      Your Answer:

      Correct Answer: The use of stannic oxide increases the accuracy of flowmeters

      Explanation:

      Flowmeters measure the rate at which a specific gas, that the flowmeter has been calibrated for, passes through. This calibration is done at room temperature and standard atmospheric pressure with an accuracy of +/- 2%.

      Reading the flowmeter is done from the top of a bobbin (the midpoint of a ball). Oxygen is the last gas to be added downstream to the mixture delivered to the back bar as a safety feature. This prevents delivery of a hypoxic mixture.

      Inaccurate flow measurements occur when the bobbin sticks to the inside wall of the flowmeter. Stannic oxide has been used as a successful antistatic substance thus, reducing the aforementioned risk.

      Carbon dioxide being easily delivered is found on some older machines, but those attached flowmeters are limited by a maximum flow of 500 ml /min. Thus avoiding the delivery of a hypercarbic mixture.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 112 - In reference to confounding variables, which among the given is not true? ...

    Incorrect

    • In reference to confounding variables, which among the given is not true?

      Your Answer:

      Correct Answer: In the analytic stage of a study confounding can be controlled for by randomisation

      Explanation:

      Randomisation can be used to provide control over the confounding variables during the design stage of a study however during analytical stage a technique called stratification is used for controlling confounding variables. Since the question asks for the information that is factually incorrect.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 113 - Which of the following statement is true regarding the mechanism of action of...

    Incorrect

    • Which of the following statement is true regarding the mechanism of action of macrolides?

      Your Answer:

      Correct Answer: Inhibits protein synthesis

      Explanation:

      The mechanism of action of macrolides is inhibition of bacterial protein synthesis by preventing peptidyltransferase from adding to the growing peptide which is attached to tRNA to the next amino acid.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 114 - A 50-year-old man is admitted in hospital. Over four hours, he produces 240...

    Incorrect

    • A 50-year-old man is admitted in hospital. Over four hours, he produces 240 mL of urine and has a plasma creatinine concentration is 10 mcg/mL. The normal concentration of creatinine in urine is 1.25 mg/mL.

      Calculate his approximate creatinine clearance.

      Your Answer:

      Correct Answer: 125 ml/minute

      Explanation:

      Creatinine clearance is a test used to approximate the glomerular filtration rate (GFR) as an assessment of kidney function.

      Creatinine is formed during the breakdown of dietary sources of meat and skeletal muscle. It is secreted at a consistent concentration and pace into the body’s circulation, and is easily filtered across the glomerulus without being reabsorbed or metabolized by the kidney.

      It is represented mathematically as:
      Creatinine clearance (CL) = U x V/P
      where,
      U: Urinary creatinine concentration (mg/mL)
      V: Volume of urine (mL/min)
      P: Plasma creatinine concentration (mg/mL)

      Therefore, in this case:
      CL: 1.25 x 1 = 125mL/min
      0.1

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 115 - Seven days after undergoing an inguinal hernia repair, a 24-year old male presents...

    Incorrect

    • Seven days after undergoing an inguinal hernia repair, a 24-year old male presents with a wound that is erythematous, tender and has a purulent discharge. The most likely cause of this is which of the following?

      Your Answer:

      Correct Answer: Infection with Staphylococcus aureus

      Explanation:

      Staphylococcus aureus infection is the most likely cause.

      Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.

      SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
      The organisms are usually derived from the patient’s own body.

      Measures that may increase the risk of SSI include:
      -Shaving the wound using a single use electrical razor with a disposable head
      -Using a non iodine impregnated surgical drape if one is needed
      -Tissue hypoxia
      -Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.

      Measures that may decrease the risk of SSI include:
      1. Intraoperatively
      – Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
      -Cover surgical site with dressing

      In contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.

      2. Post operatively
      Tissue viability advice for management of surgical wounds healing by secondary intention

      Use of diathermy for skin incisions
      In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 116 - A new volatile anaesthetic agent has been approved for use in clinical testing.

    It's...

    Incorrect

    • A new volatile anaesthetic agent has been approved for use in clinical testing.

      It's a non-irritating, sweet-smelling substance. It has a molecular weight of 170, a 0.6 blood:gas partition coefficient, and a 180 oil:gas partition coefficient. An oxidative pathway converts 2% of the substance to trifluoroacetic acid.

      Which of the following statements best describes this agent's pharmacological profile?

      Your Answer:

      Correct Answer: It has a lower molecular weight than isoflurane

      Explanation:

      Because enflurane is much less soluble in blood and has a blood: gas partition coefficient of 1.8, both wash-in and wash-out should be faster.

      Sevoflurane’s sweet-smelling, non-irritant nature, combined with a low blood: gas partition coefficient, would result in similar offset and onset characteristics.

      Isoflurane and enflurane have a molecular weight of 184.

      The oil: gas partition coefficient on a volatile agent is a measure of lipid solubility, potency, and thus MAC. Halothane has an oil: gas partition coefficient of 220 and a MAC of 0.74. One would expect the MAC to be higher with an oil gas partition coefficient of 180 (less lipid soluble).

      The conversion of halothane (20%) to trifluoroacetic acid via oxidative metabolism has been linked to the development of hepatitis.

      P450 2E1 converts sevoflurane to hexafluoroisopropanol, which results in the release of inorganic fluoride ions. It’s the only fluorinated volatile anaesthetic that doesn’t break down into trifluoracetic acid.

      Desflurane is likely to cause airway irritation, which can lead to coughing, apnoea, and laryngospasm, despite its low blood:gas partition coefficient (0.42).

    • This question is part of the following fields:

      • Pharmacology
      0