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  • Question 1 - How many unpaired branches leave the abdominal aorta to supply the abdominal viscera?...

    Incorrect

    • How many unpaired branches leave the abdominal aorta to supply the abdominal viscera?

      Your Answer: Two

      Correct Answer: Three

      Explanation:

      The abdominal arteries are divided into 3 branches;
      – 3 main unpaired trunks (celiac trunk, superior mesenteric, inferior mesenteric arteries)
      – 6 paired branches
      – unpaired median sacral artery.

      We can group the abdominal aorta as follows;
      -Ventral which includes: Coeliac trunk, superior mesenteric and inferior mesenteric arteries
      -Lateral: Inferior phrenic, middle suprarenal, renal and gonadal arteries
      -Dorsal: Lumbar and median sacral arteries
      -Terminal : Right and left common iliac arteries

      The celiac trunk (L1) takes blood the foregut and its found posterior to the stomach. The unpaired superior mesenteric artery supplies blood to the mid-gut.

      The paired renal arteries form the inferior suprarenal arteries. The renal arteries arise around L1/L2 and takes blood to either side of the kidneys.

      The median sacral artery supplies blood to the lumbar vertebrae the L4 and L5.

    • This question is part of the following fields:

      • Anatomy
      52.6
      Seconds
  • Question 2 - In a diagnosis of a compensated respiratory acidosis, which of the following arterial...

    Incorrect

    • In a diagnosis of a compensated respiratory acidosis, which of the following arterial blood gas results is likely to be seen?

      Your Answer: pH = 7.34
      PaCO2 = 7.2 kPa
      HCO3 = 29

      Correct Answer:

      Explanation:

      During normal tissue metabolism, there is production of CO2 (acid) which is then expired by the lungs. If metabolism switches from aerobic to anaerobic due to a lack of oxygen, the tissues are unable to completely oxidise sugars to CO2. As a consequence, the sugars can only be partially oxidised to lactic acid. Since lactic acid cannot be expired by the lungs, it remains in the circulation leading to metabolic acidosis.

      Also, normal tissue metabolism leads to the production of some amount of acid from the breakdown of proteins. These acids are excreted from the body by kidney filtration. Renal failure will therefore results in acidosis after several days.

      An increased acidosis stimulates the brain’s respiratory centres to increase the respiratory rate. This lowers the CO2 in the blood, leading to a decrease in its acidity. Renal excretion removes the excess acid, resulting in a normal pH, and a reduced PaCO2 and HCO3.

      pH PaCO2 (kPa) HCO3
      Compensated respiratory acidosis 7.34 7.2 29
      Acute respiratory acidosis 7.25 7.3 22
      Compensated metabolic acidosis 7.34 3.6 14
      Metabolic acidosis 7.21 5.3 15
      Metabolic alkalosis 7.51 5.1 30

    • This question is part of the following fields:

      • Pathophysiology
      7.6
      Seconds
  • Question 3 - Which of the following statement is true regarding the mechanism of action of...

    Incorrect

    • Which of the following statement is true regarding the mechanism of action of doxycycline?

      Your Answer: Inhibit 50S subunit of ribosomes

      Correct Answer: Inhibit 30S subunit of ribosomes

      Explanation:

      Doxycycline belongs to the family of tetracyclines and inhibits protein synthesis through reversible binding to bacterial 30s ribosomal subunits, which prevent binding of new incoming amino acids (aminoacyl-tRNA) and thus interfere with peptide growth.

    • This question is part of the following fields:

      • Pharmacology
      13.8
      Seconds
  • Question 4 - A 56-year old man, presents to emergency department following a cardiac arrest. On...

    Correct

    • A 56-year old man, presents to emergency department following a cardiac arrest. On history and examination, he is found to be suffering from both metabolic and respiratory acidosis as a result of his cardiac arrest.

      What is the best way to reduce the risk of acidaemia during cardiac arrest

      Your Answer: Chest compressions

      Explanation:

      Chest compressions are an essential part of cardiopulmonary resuscitation (CPR) which helps restore spontaneous circulation (ROSC).

      Sodium bicarbonate is only prescribed in patients with cardiac arrests as a result of an overdose of tricyclic antidepressants or hyperkalaemia. Its use causes the body to produce more CO2 which causes:

      Exacerbation of intracellular acidosis
      Negative inotropy to ischaemic myocardium
      Increased osmotic load of sodium into failing brain and body
      Shift of oxygen dissociation curve to the left.

      THAM is often used to treat metabolic acidosis as a result of cardiac bypass surgery and also cardiac arrest, when other standard methods have failed.

      Carbicarb (Na2CO3 0.33 molar NaHCO3 0.33 molar) has only mild effects on acidosis. It also causes an increase in arterial CO2 pressure and lactate concentration.

    • This question is part of the following fields:

      • Pathophysiology
      17.6
      Seconds
  • Question 5 - The solutions that contains the most sodium is? ...

    Incorrect

    • The solutions that contains the most sodium is?

      Your Answer: 6000 mL 0.45% N saline with 5% glucose

      Correct Answer: 3500 mL 0.9% N saline

      Explanation:

      Sodium concentration for different fluids
      3% N saline 513 mmol/L
      5% N saline 856 mmol/L
      0.9% N saline 154 mmol/L
      Hartmann’s solution 131 mmol/L
      0.45% N saline with 5% glucose 77 mmol/L

      This means that:

      500 mL 5% N saline contains 428 mmol of sodium
      1000 mL 3% N saline contains 513 mmol of sodium
      3500 mL 0.9% N saline contains 539 mmol of sodium
      4000 mL Hartmann’s contains 524 mmol of sodium
      6000 mL 0.45% N saline with 5% glucose contains 462 mmol of sodium.

    • This question is part of the following fields:

      • Physiology
      8.9
      Seconds
  • Question 6 - A controlled retrospective study's level of evidence is? ...

    Correct

    • A controlled retrospective study's level of evidence is?

      Your Answer: Level 3

      Explanation:

      Level 1 – High-quality randomised controlled trial with statistically significant difference or no statistically significant difference but narrow confidence intervals (prospective controlled)

      Level 2 – Prospective comparative study (prospective uncontrolled)

      Level 3 – Case-control study, retrospective comparative study (retrospective controlled)

      Level 4 – Case series (retrospective uncontrolled)

      Level 5 – Expert opinion.

    • This question is part of the following fields:

      • Statistical Methods
      9.4
      Seconds
  • Question 7 - A young woman presented with a gynaecological related infection and was prescribed a...

    Incorrect

    • A young woman presented with a gynaecological related infection and was prescribed a cephalosporin. Which of the following is correct about the mechanism of action of this drug?

      Your Answer: Bacterial folate metabolism inhibition

      Correct Answer: Bacterial cell wall synthesis inhibition

      Explanation:

      Cephalosporin belongs to a family of beta-lactam antibiotics. All ?-lactam antibiotics interfere with the synthesis of the bacterial cell walls. The ?-lactam antibiotics inhibit the transpeptidases so that cross-linking (which maintains the close-knit structure of the cell wall) does not take place i.e. they inhibit bacterial cell wall formation.

    • This question is part of the following fields:

      • Pharmacology
      22.3
      Seconds
  • Question 8 - Concerning the pathway of endothelial nitric oxide (eNO), one of the following best...

    Incorrect

    • Concerning the pathway of endothelial nitric oxide (eNO), one of the following best describes it.

      Your Answer: Inhibition of guanylyl cyclase, decreases cGMP concentration leading to vasoconstriction

      Correct Answer: Stimulation of guanylyl cyclase, increases cGMP concentration leading to vasodilation

      Explanation:

      Nitric oxide (NO), an endothelial-derived relaxant factor (EDRF), is a powerful vasodilator. Its cell-signalling molecule is calcium-dependant and generated endogenous by nitric oxide synthetases from the precursor L-arginine, oxygen and NADPH. Three main isoforms have been isolated and they are inducible (iNO), neuronal (nNO) and endothelial (eNO).

      Endothelial NO stimulates intracellular guanylyl cyclase which generates cyclic GMP (cGMP) from its action on guanylyl tri-phosphate (GTP). The cGMP goes on to activate protein kinase G (PKG). PKG phosphorylates cell membrane proteins that regulate intracellular calcium concentrations and level of calcium sensitisation.

      Smooth muscle vasodilatation results from:

      1. Light chain phosphatase activation.
      2. Inhibition of calcium entry into the cell (reducing Ca2+ concentrations) and
      3. Hyperpolarisation of cells by activation of H+ channels.

    • This question is part of the following fields:

      • Pathophysiology
      8.1
      Seconds
  • Question 9 - Which of the following statement is true regarding hypoxic pulmonary vasoconstriction (HPV)? ...

    Incorrect

    • Which of the following statement is true regarding hypoxic pulmonary vasoconstriction (HPV)?

      Your Answer: Is increased by volatile anaesthetic agents

      Correct Answer: 20 parts per million (ppm) of nitric oxide will reduce hypoxic pulmonary vasoconstriction

      Explanation:

      Hypoxic Pulmonary vasoconstriction (HPV) reflects the constriction of small pulmonary arteries in response to hypoxic alveoli (.i.e.; PO2 below 80-100mmHg or 11-13kPa).

      These blood vessels become independent of the nerve stimulus, when blood with a high PO2 flows through the lung which contains a low alveolar PO2.

      Thus a low PO2 within the alveoli has been shown to impact on hypoxic pulmonary vasoconstriction (HPV) more than a low PO2 within the blood.

      HPV results in the blood flow being directed away from poorly ventilated areas of the lung and helps to reduce the ventilation/perfusion mismatch (not increase).

      In animals, volatile anaesthetic agents can diminish HPV, while in adults, the evidence proves less persuading, in spite of the fact that it certainly doesn’t strengthen the effects.

      HPV response will be suppressed by 20 parts per million (ppm) of nitric oxide.

    • This question is part of the following fields:

      • Physiology
      6.8
      Seconds
  • Question 10 - A 25 year-old female came to the out-patient department with complaints of vaginal...

    Incorrect

    • A 25 year-old female came to the out-patient department with complaints of vaginal discharge with a distinct fishy odour. She was later diagnosed with bacterial vaginosis and was prescribed to take metronidazole.

      The mechanism of action of metronidazole is?

      Your Answer: Interferes with bacterial cell wall synthesis

      Correct Answer: Interferes with bacterial DNA synthesis

      Explanation:

      Metronidazole is a nitroimidazole antiprotozoal drug that is selectively absorbed by anaerobic bacteria and sensitive protozoa. Once taken up be anaerobes, it is nonenzymatically reduced by reacting with reduced ferredoxin. This reduction results in products that accumulate in and are toxic to anaerobic cells. The metabolites of metronidazole are taken up into bacterial DNA, forming unstable molecules. This action occurs only when metronidazole is partially reduced, and, because this reduction usually happens only in anaerobic cells, it has relatively little effect on human cells or aerobic bacteria.

    • This question is part of the following fields:

      • Pharmacology
      11
      Seconds
  • Question 11 - A peripheral nerve stimulator is used to stimulate the ulnar nerve at the...

    Incorrect

    • A peripheral nerve stimulator is used to stimulate the ulnar nerve at the wrist to indicate the degree of neuromuscular blockade.

      Which single muscle or group of muscles of the hand supplied by the ulnar nerve is best for monitoring the twitch function during neuromuscular blockade?

      Your Answer: Palmaris brevis

      Correct Answer: Adductor pollicis

      Explanation:

      In anaesthesia, adductor pollicis neuromuscular monitoring with ulnar nerve stimulation is commonly used. It is the gold standard for measuring the degree of block and comparing neuromuscular blocking drugs and their effects on other muscles.

      Electrodes are usually placed over the ulnar nerve at the wrist to monitor the adductor pollicis.

      Neuromuscular blocking drugs have different sensitivity levels in different muscle groups.

      To achieve the same level of blockade, the diaphragm requires 1.4 to 2 times the amount of neuromuscular blocking agent as the adductor pollicis muscle. The small muscles of the larynx and the ocular muscles are two other respiratory muscles that are less resistant than the diaphragm (especially corrugator supercilii).

      The abdominal muscles, Orbicularis oculi, peripheral muscles of the limbs, Geniohyoid, Masseter, and Upper airway muscles are the most sensitive to neuromuscular blocking agents.

      The C8-T1 nerve roots, which are part of the medial cord of the brachial plexus, form the ulnar nerve. It enters the hand via the ulnar canal, superficial to the flexor retinaculum, after following the ulnar artery at the wrist.

      The nerve then splits into two branches: superficial and deep. The palmaris brevis is supplied by the superficial branch, which also provides palmar digital nerves to one and a half fingers. The dorsal surface of the medial/ulnar 1.5 fingers, as well as the corresponding skin over the hand, are also supplied by it (as well as the palmar surface).

      The ulnar nerve’s deep branch runs between the abductor and flexor digiti minimi, which it supplies. It also innervates the opponens, and with the deep palmar arch, it curves around the hook of the hamate and laterally across the palm. All of the interossei, the medial two lumbricals, the adductor pollicis, and, in most cases, the flexor pollicis brevis are supplied there.

    • This question is part of the following fields:

      • Anatomy
      18.5
      Seconds
  • Question 12 - Which of the following statements is true regarding drug dose and response? ...

    Incorrect

    • Which of the following statements is true regarding drug dose and response?

      Your Answer: Antagonists must have a higher receptor affinity than agonists

      Correct Answer: Intrinsic activity determines maximal response

      Explanation:

      There are two types of drug dose-response relationships, namely, the graded dose-response and the quantal dose-response relationships.

      Drug response curves are plotted as percentage response again LOG drug concentration. This graph is sigmoid in shape.

      Agonists are drugs with high affinity and high intrinsic activity. Meanwhile, the antagonist is a drug with high affinity but no intrinsic activity. Intrinsic activity determines the maximal response. The maximal response can be achieved even by activation of a small proportion of receptor sites.

    • This question is part of the following fields:

      • Pharmacology
      83.5
      Seconds
  • Question 13 - A 30-year-old man has been diagnosed with a direct inguinal hernia.

    A direct...

    Incorrect

    • A 30-year-old man has been diagnosed with a direct inguinal hernia.

      A direct inguinal hernia passes through Hesselbach's triangle. What forms the medial edge of this triangle?

      Your Answer: Inferior epigastric artery

      Correct Answer: Rectus abdominis muscle

      Explanation:

      The inguinal triangle of Hesselbach’s is an important clinical landmark on the posterior wall of the inguinal canal. It has the following relations:
      Inferiorly – medial third of the inguinal ligament
      Medially – lower lateral border of the rectus abdominis
      Laterally – inferior epigastric vessels

      Direct inguinal hernia is when the bowel bulges directly through the abdominal wall. These hernias usually protrude through Hesselbach’s triangle

    • This question is part of the following fields:

      • Anatomy
      6.9
      Seconds
  • Question 14 - Which of the following organism is highly resistant to penicillin? ...

    Incorrect

    • Which of the following organism is highly resistant to penicillin?

      Your Answer: Haemophilus influenzae

      Correct Answer: Escherichia coli

      Explanation:

      Penicillinase is a narrow spectrum ?-lactamase that opens the ?-lactam ring and inactivates Penicillin G and some closely related congeners. The majority of Staphylococci and some strains of gonococci, B. subtilis, E. coli, and a few other bacteria produce penicillinase.

      N. meningitidis is sensitive to penicillin and less than 20% resistance is found in pseudomonas.

    • This question is part of the following fields:

      • Pharmacology
      2.8
      Seconds
  • Question 15 - Which of the following is correct regarding correlation? ...

    Incorrect

    • Which of the following is correct regarding correlation?

      Your Answer: The terms correlation and regression are synonymous

      Correct Answer: Complete absence of correlation is expressed by a value of 0

      Explanation:

      In statistical terms, correlation is used to denote association between two quantitative variables.

      The degree of association is measured by a correlation coefficient, denoted by r. The correlation coefficient is measured on a scale that varies from + 1 through 0 to – 1. Complete correlation between two variables is expressed by either + 1 or -1. When one variable increases as the other increases the correlation is positive; when one decreases as the other increases it is negative. Complete absence of correlation is represented by 0.

      The two methods are not synonymous as correlation measures the degree of relationship between two variables whereas regression analysis is about how one variable affects another or what changes it has on the other variable. Both are also shown by a different graphical representation.

    • This question is part of the following fields:

      • Statistical Methods
      7.8
      Seconds
  • Question 16 - A patient is evaluated for persistent dysphonia six months after undergoing a subtotal...

    Incorrect

    • A patient is evaluated for persistent dysphonia six months after undergoing a subtotal thyroidectomy.

      Which of the following is the most likely reason for the change in this patient's voice?

      Your Answer: Oedema of vocal cords

      Correct Answer: Damage to recurrent laryngeal nerve

      Explanation:

      After thyroid surgery, about 10-15% of patients experience a temporary subjective voice change of varying degrees. A frog in the throat or cracking of the voice, or a weak voice, are common descriptions. These modifications are only temporary, lasting a few days to a few weeks.

      Swelling of the muscles in the area of the dissection, as well as inflammation and oedema of the larynx due to the dissection, or minor trauma from the tracheal tube, are all suspected causes.

      On both sides of the thyroid gland, the superior laryngeal nerve (EBSLN) runs along the upper part. The muscles that fine-tune the vocal cords are innervated by these nerves. The quality of their voice is usually normal if they are injured, but making high-pitched sounds may be difficult. Injury to the EBSLN occurs in about 2% of the population.

      Injuries to the recurrent laryngeal nerve (RLN) have been reported to occur in 1 percent to 14 percent of people. Except for the cricothyroid muscle, the RLN supplies all of the laryngeal intrinsic muscles.

      This complication is usually unilateral and temporary, but it can also be bilateral and permanent, and it can be intentional or unintentional. The most common complication following thyroid surgery is a permanent lesion of damaged RLN, which manifests as an irreversible phonation dysfunction.

      The crico-arytenoid joint dislocation is a relatively uncommon complication of tracheal intubation and blunt neck trauma. The probability is less than one in a thousand.

      Vocal cord polyps affect 0.8 percent of people.

    • This question is part of the following fields:

      • Pathophysiology
      18
      Seconds
  • Question 17 - Following a near drowning accident, a 5-year-old child is admitted to the emergency...

    Correct

    • Following a near drowning accident, a 5-year-old child is admitted to the emergency department and advanced paediatric life support is started.

      What is the child's approximate weight, according to the preferred formulae of the Resuscitation Council (UK), the European Resuscitation Council, and the Royal College of Anaesthetists?

      Your Answer: 20-25kg

      Explanation:

      For estimating a child’s weight, the Resuscitation Council (UK) and European Resuscitation Council teach the following formula:

      Weight = (age + 4) × 2

      The weight of the child will be around 20 kg.

      This formula is used in the Primary FRCA exam by the Royal College of Anaesthetists.

      In ‘developed’ countries, the traditional ‘APLS formula’ for estimating weight in children based on age (wt in kg = [age+4] x 2) is acknowledged as underestimating weight by 33.4 percent on average, with the degree of underestimation increasing with increasing age.

      However, more recently, the APLS formula ‘Weight=3(age)+7’ has been found to provide a mean underestimate of only 6.9%. This formula is applicable to children aged 1 to 13 years.

      The estimated weight based on age using this formula is 25 kg.

    • This question is part of the following fields:

      • Physiology
      18.9
      Seconds
  • Question 18 - What does therapeutic index in humans mean? ...

    Correct

    • What does therapeutic index in humans mean?

      Your Answer: The TD50 divided by the ED50

      Explanation:

      Therapeutic index is a measure which relates the dose of a drug required to produce a desired effect to that which produces an undesired effect.

      In humans, it is usually defined as the ratio of the toxic dose for 50% of the population (TD50) to the minimum effective dose for 50% of the population (ED50) for some therapeutically relevant effect. In animal studies, the therapeutic index can be defined as the ratio of the median lethal dose (LD50) to the ED50.

    • This question is part of the following fields:

      • Pharmacology
      13.6
      Seconds
  • Question 19 - International colour coding is used on medical gas cylinders. Other characteristics also play...

    Incorrect

    • International colour coding is used on medical gas cylinders. Other characteristics also play a role in determining the gas's identity within a cylinder.

      Which of the following options best describes a cylinder containing analgesics for obstetrics?

      Your Answer: Grey body, grey shoulder, full cylinder; 5000 KPa, single gas, requires a single stage pressure regulator

      Correct Answer: Blue body, blue/white shoulder, full cylinder; 13700 KPa, gas mixture, requires a dual stage pressure regulator

      Explanation:

      The body of the Entonox cylinder is usually blue (occasionally white), with blue and white shoulders. Entonox contains a 50:50 mixture of oxygen and nitrous oxide, with a full cylinder pressure of 13700 KPa (137 bar). The cylinder is equipped with a two-stage pressure regulator for safe operation.

      The cylinder body and shoulder of nitrous oxide are (French) blue.

      In today’s anaesthetic workstations, carbon dioxide cylinders are no longer used.

      The body of an oxygen cylinder is black, with a white shoulder.

      The white Heliox (21 percent oxygen and 79 percent helium) cylinder has a brown and white shoulder. The administration of this gas mixture, which is less dense than air, is used to reduce turbulence (stridor) of inspiratory flow in patients with upper airway obstruction.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      3
      Seconds
  • Question 20 - Drug X, a new intravenous induction drug, is being administered as a bolus...

    Incorrect

    • Drug X, a new intravenous induction drug, is being administered as a bolus at regular time intervals, and the following data were observed:

      Time following injection (hours) vs Plasma concentration of drug X (mcg/mL)
      2 / 400
      6 / 100
      10 / 25
      14 / 6.25

      Which of the following values estimate the plasma half-life (T½) of drug X?

      Your Answer: 4 hours

      Correct Answer: 2 hours

      Explanation:

      Half life (T½) is the time required to change the amount of drug in the body by one-half (or 50%) during elimination. The time course of a drug in the body will depend on both the volume of distribution and the clearance.

      Extrapolating the values from the plasma concentration vs time:

      Plasma concentration at 0 hours = 800 mcg/mL
      Plasma concentration at 2 hours = 400 mcg/mL
      Plasma concentration at 4 hours = 200 mcg/mL
      Plasma concentration at 6 hours = 100 mcg/mL
      Plasma concentration at 8 hours = 50 mcg/mL
      Plasma concentration at 10 hours = 25 mcg/mL
      Plasma concentration at 12 hours = 12.5 mcg/mL
      Plasma concentration at 14 hours = 6.25 mcg/mL

    • This question is part of the following fields:

      • Statistical Methods
      6.6
      Seconds
  • Question 21 - A 45-year old male who was involved in a road traffic accident has...

    Incorrect

    • A 45-year old male who was involved in a road traffic accident has had to receive a large blood transfusion of whole blood which is two weeks old. Which of these best describes the oxygen carrying capacity of this blood?

      Your Answer: It will have a low affinity for oxygen

      Correct Answer: It will have an increased affinity for oxygen

      Explanation:

      With respect to oxygen transport in cells, almost all oxygen is transported within erythrocytes. There is limited solubility and only 1% is carried as solution. Thus, the amount of oxygen transported depends upon haemoglobin concentration and its degree of saturation.

      Haemoglobin is a globular protein composed of 4 subunits. Haem is made up of a protoporphyrin ring surrounding an iron atom in its ferrous state. The iron can form two additional bonds – one is with oxygen and the other with a polypeptide chain.
      There are two alpha and two beta subunits to this polypeptide chain in an adult and together these form globin. Globin cannot bind oxygen but can bind to CO2 and hydrogen ions.
      The beta chains are able to bind to 2,3 diphosphoglycerate. The oxygenation of haemoglobin is a reversible reaction. The molecular shape of haemoglobin is such that binding of one oxygen molecule facilitates the binding of subsequent molecules.

      The oxygen dissociation curve (ODC) describes the relationship between the percentage of saturated haemoglobin and partial pressure of oxygen in the blood.
      Of note, it is not affected by haemoglobin concentration.

      Chronic anaemia causes 2, 3 DPG levels to increase, hence shifting the curve to the right

      Haldane effect – Causes the ODC to shift to the left. For a given oxygen tension there is increased saturation of Hb with oxygen i.e. Decreased oxygen delivery to tissues.
      This can be caused by:
      -HbF, methaemoglobin, carboxyhaemoglobin
      -low [H+] (alkali)
      -low pCO2
      -ow 2,3-DPG
      -ow temperature

      Bohr effect – causes the ODC to shifts to the right = for given oxygen tension there is reduced saturation of Hb with oxygen i.e. Enhanced oxygen delivery to tissues. This can be caused by:
      – raised [H+] (acidic)
      – raised pCO2
      -raised 2,3-DPG
      -raised temperature

    • This question is part of the following fields:

      • Physiology And Biochemistry
      5.2
      Seconds
  • Question 22 - Which of the following drugs would cause the most clinical concern if accidentally...

    Incorrect

    • Which of the following drugs would cause the most clinical concern if accidentally administered intravenously to a 4-year-old boy?

      Your Answer: 400 mg cefuroxime

      Correct Answer: 20 mg codeine

      Explanation:

      To begin, one must determine the child’s approximate weight. There are a variety of formulas to choose from. It is acceptable to use the advanced paediatric life support formula:

      (age + 4) 2 = weight

      A 5-year-old child will weigh around 18 kilogrammes.

      The following are the appropriate doses of the drugs listed above:

      Gentamicin (once daily) – 5-7 mg/kg = 90-126 mg and subsequent dose modified according to plasma levels
      Ondansetron – 0.1 mg/kg, but a maximum of 4 mg as a single dose = 1.8 mg
      Codeine should be administered orally at a dose of 1 mg/kg rather than intravenously, as the latter can cause ‘dangerous’ hypotension due to histamine release.
      15 mg/kg paracetamol = 270 mg orally or intravenously (a loading dose of 20 mg/kg, or 360 mg, is sometimes recommended, which is not far short of the doses listed above).
      Cefuroxime – the initial intravenous dose is 20 mg/kg (360 mg) depending on the indication (again, similar to the dose given in the answer options above).

    • This question is part of the following fields:

      • Pharmacology
      12.5
      Seconds
  • Question 23 - A young male is undergoing inguinal hernia repair. During the procedure, the surgeons...

    Incorrect

    • A young male is undergoing inguinal hernia repair. During the procedure, the surgeons approach the inguinal canal and expose the superficial inguinal ring.

      Which structure forms the lateral edge of the superficial inguinal ring?

      Your Answer: Transversalis fascia

      Correct Answer: External oblique aponeurosis

      Explanation:

      The superficial inguinal ring is an opening in the aponeurosis of the external oblique muscle, just above and lateral to the pubic crest.

      The superficial ring resembles a triangle more than a ring with the base lying on the pubic crest and its apex pointing towards the anterior superior iliac spine. The sides of the triangle are crura of the opening in the external oblique aponeurosis. The lateral crura of the triangle is attached to the pubic tubercle. The medial crura of the triangle is attached to the pubic crest.

      The external oblique aponeurosis forms the anterior wall of the inguinal canal and also the lateral edge of the superficial inguinal ring. The rectus abdominis lies posteromedially, and the transversalis posterior to this.

    • This question is part of the following fields:

      • Anatomy
      11.3
      Seconds
  • Question 24 - Substitution at different positions of the barbituric ring give rise to different pharmacologic...

    Incorrect

    • Substitution at different positions of the barbituric ring give rise to different pharmacologic properties.

      Substitution with and at which specific site of the ring affects lipid solubility the most?

      Your Answer: Aromatic group at position 5

      Correct Answer: Sulphur atom at position 2

      Explanation:

      Barbiturates are derived from barbituric acid, which itself is nondepressant, but appropriate side-chain substitutions result in CNS depressant activity that varies in potency and duration with carbon chain length, branching, and saturation.

      Oxybarbiturates retain an oxygen atom on number 2-carbon atom of the barbituric acid ring.

      Thiobarbiturates replace this oxygen atom with a sulphur atom, which confers greater lipid solubility. Generally speaking, a substitution such as sulphuration that increases lipid solubility is associated with greater hypnotic potency and more rapid onset, but shorter duration of action.

      Addition of a methyl group to the nitrogen atom of the barbituric acid ring, as with oxybarbiturate methohexital, also results in a compound with a short duration of action.

    • This question is part of the following fields:

      • Pharmacology
      3.5
      Seconds
  • Question 25 - A 21-year-old female was brought to the Emergency department with a ruptured ectopic...

    Incorrect

    • A 21-year-old female was brought to the Emergency department with a ruptured ectopic pregnancy.

      On clinical examination, the following were the findings:
      Pulse: 120 beats per minute
      BP: 120/95 mmHg
      Respiratory rate: 22 breaths per minute
      Capillary refill time: three seconds
      Cool peripheries.

      Which of the following best describes the cause for this clinical finding?

      Your Answer: Reduction in blood volume of 40-50%

      Correct Answer: Reduction in blood volume of 15-30%

      Explanation:

      Classification of hemorrhagic shock according to Advanced Trauma Life Support is as follows:

      – Class I haemorrhage (blood loss up to 15%) in which there is no change in blood pressure, RR, or pulse pressure.

      – Class II haemorrhage (15-30% blood volume loss) where there is tachycardia, tachypnoea, and a decrease in pulse pressure.

      – Class III haemorrhage (30-40% blood volume loss) where clinical signs of inadequate perfusion, marked tachycardia, tachypnoea, significant changes in mental state, and measurable fall in systolic pressure is seen. It almost always requires a blood transfusion.

      – Class IV haemorrhage (> 40% blood volume loss) in which marked tachycardia, significant depression in systolic pressure and very narrow pulse pressure, and markedly depressed mental state with cold and pale skin are seen.

      Loss of >50% results in loss of consciousness, pulse, and blood pressure.

    • This question is part of the following fields:

      • Pathophysiology
      10.6
      Seconds
  • Question 26 - Among the following which one is not a criterion for the assessment of...

    Incorrect

    • Among the following which one is not a criterion for the assessment of causality?

      Your Answer: Coherence

      Correct Answer: Sensitivity

      Explanation:

      For establishing a cause effect relationship, following criteria must be met:

      1. Coherence & Consistency

      2. Temporal Precedence

      3. Specificity

      As can be seen, sensitivity (The probability of a positive test) is not among these deciding factors..

    • This question is part of the following fields:

      • Statistical Methods
      7.1
      Seconds
  • Question 27 - Which of the following statements is true with regards to acetylcholine? ...

    Incorrect

    • Which of the following statements is true with regards to acetylcholine?

      Your Answer: Edrophonium will make a myasthenic crisis worse and a cholinergic crisis better

      Correct Answer: Excess cholinesterase inhibitor medication causes cholinergic crisis

      Explanation:

      Myasthenic and cholinergic crises are two crises which are similar in their clinical presentation.

      Myasthenic crisis can be caused by:
      -lack of acetylcholine,
      -poor compliance with medication,
      -infection

      Cholinergic crisis can be caused by excess cholinesterase inhibitor medication (mimicking organophosphate poisoning) causing excess acetylcholine.

      Differentiation between the 2 crises is made by giving incremental doses of the short acting cholinesterase inhibitor, Edrophonium.
      This increase acetylcholine levels and will make a myasthenic crisis better and a cholinergic crisis worse.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      11.7
      Seconds
  • Question 28 - A 65-year-old man has been diagnosed with transitional cell carcinoma of the left...

    Incorrect

    • A 65-year-old man has been diagnosed with transitional cell carcinoma of the left kidney. He will be operated on, and as part of the surgery, the left renal artery has to be located and dissected.

      Which of the following vertebral levels gives rise to this artery?

      Your Answer: T12

      Correct Answer: L1

      Explanation:

      The renal arteries branch from the abdominal aorta just below the origin of the superior mesenteric artery. The right renal artery is higher and longer than the left renal artery. The left renal artery passes behind the left renal vein, the body of the pancreas, and the splenic vein.

      The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:

      T10 – oesophageal opening in the diaphragm

      T12 – Coeliac trunk, aortic hiatus in the diaphragm

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta

    • This question is part of the following fields:

      • Anatomy
      35.6
      Seconds
  • Question 29 - A 50-year-old female is having her central venous pressure (CVP) measured. A long...

    Incorrect

    • A 50-year-old female is having her central venous pressure (CVP) measured. A long femoral line was inserted that passes from the common iliac vein into the inferior vena cava.

      At which level of vertebra does this occur?

      Your Answer: L2

      Correct Answer: L5

      Explanation:

      The inferior vena cava is formed by the union of the right and left common iliac veins. This occurs at the L5 vertebral level. The IVC courses along the right anterolateral side of the vertebral column and ascends through the central tendon of the diaphragm at the T8 vertebral level.

    • This question is part of the following fields:

      • Anatomy
      2.5
      Seconds
  • Question 30 - Which of the following causes a left shift of the haemoglobin dissociation curve?...

    Incorrect

    • Which of the following causes a left shift of the haemoglobin dissociation curve?

      Your Answer:

      Correct Answer:

      Explanation:

      With respect to oxygen transport in cells, almost all oxygen is transported within erythrocytes. There is limited solubility and only 1% is carried as solution. Thus, the amount of oxygen transported depends upon haemoglobin concentration and its degree of saturation.

      Haemoglobin is a globular protein composed of 4 subunits. Haem is made up of a protoporphyrin ring surrounding an iron atom in its ferrous state. The iron can form two additional bonds – one is with oxygen and the other with a polypeptide chain.
      There are two alpha and two beta subunits to this polypeptide chain in an adult and together these form globin. Globin cannot bind oxygen but can bind to CO2 and hydrogen ions.
      The beta chains are able to bind to 2,3 diphosphoglycerate. The oxygenation of haemoglobin is a reversible reaction. The molecular shape of haemoglobin is such that binding of one oxygen molecule facilitates the binding of subsequent molecules.

      The oxygen dissociation curve (ODC) describes the relationship between the percentage of saturated haemoglobin and partial pressure of oxygen in the blood.
      Of note, it is not affected by haemoglobin concentration.

      Chronic anaemia causes 2, 3 DPG levels to increase, hence shifting the curve to the right

      Haldane effect – Causes the ODC to shift to the left. For a given oxygen tension there is increased saturation of Hb with oxygen i.e. Decreased oxygen delivery to tissues.
      This can be caused by:
      -HbF, methaemoglobin, carboxyhaemoglobin
      -low [H+] (alkali)
      -low pCO2
      -ow 2,3-DPG
      -ow temperature

      Bohr effect – causes the ODC to shifts to the right = for given oxygen tension there is reduced saturation of Hb with oxygen i.e. Enhanced oxygen delivery to tissues. This can be caused by:
      – raised [H+] (acidic)
      – raised pCO2
      -raised 2,3-DPG
      -raised temperature

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Pathophysiology (4/5) 80%
Pharmacology (8/8) 100%
Physiology (3/3) 100%
Statistical Methods (4/4) 100%
Anatomy (5/5) 100%
Anaesthesia Related Apparatus (1/1) 100%
Physiology And Biochemistry (2/3) 67%
Passmed