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  • Question 1 - A 70-year-old female presented with a productive cough and is prescribed a bacteriostatic...

    Incorrect

    • A 70-year-old female presented with a productive cough and is prescribed a bacteriostatic antibiotic?
      Which of the following best explains the mechanism of action of bacteriostatic drugs?

      Your Answer: Peptidoglycan synthesis inhibition

      Correct Answer: Protein synthesis inhibition

      Explanation:

      Cell membrane pore formation, Bacterial DNA damage, Peptidoglycan cross-linking inhibition, and peptidoglycan synthesis inhibitor are always lethal and such mechanisms are possible only in bactericidal drugs. But Protein synthesis inhibition would only prevent cell replication or cell growth and is responsible for bacteriostatic effects of the drug.

    • This question is part of the following fields:

      • Pharmacology
      33.2
      Seconds
  • Question 2 - Which of the following statements about the central venous pressure (CVP) waveform is...

    Incorrect

    • Which of the following statements about the central venous pressure (CVP) waveform is true?

      Your Answer: Tricuspid regurgitation causes large A waves

      Correct Answer: Third degree heart block causes canon A waves

      Explanation:

      The central venous pressure (CVP) waveform depicts changes of pressure within the right atrium. Different parts of the waveform are:

      A wave: which represents atrial contraction. It is synonymous with the P wave seen during an ECG. It is often eliminated in the presence of atrial fibrillation, and increased tricuspid stenosis, pulmonary stenosis and pulmonary hypertension.

      C wave: which represents right ventricle contraction at the point where the tricuspid valve bulges into the right atrium. It is synonymous with the QRS complex seen on ECG.

      X descent: which represents relaxation of the atrial diastole and a decrease in atrial pressure, due to the downward movement of the right ventricle as it contracts. It is synonymous with the point before the T wave on ECG.

      V wave: which represents an increase in atrial pressure just before the opening of the tricuspid valve. It is synonymous with the point after the T wave on ECG. It is increased in the background of a tricuspid regurgitation.

      Y descent: which represents the emptying of the atrium as the tricuspid valve opens to allow for blood flow into the ventricle in early diastole.

      Canon waves: which refer to large waves present on the trace that do not correspond to the A, V or C waves. They usually occur in a background of complete heart blocks or junctional arrythmias.

    • This question is part of the following fields:

      • Clinical Measurement
      23.9
      Seconds
  • Question 3 - You draw a patient's blood sample from the median cubital vein in the...

    Correct

    • You draw a patient's blood sample from the median cubital vein in the antecubital fossa.

      Which of the following veins also connects to the cephalic vein other than the median cubital vein?

      Your Answer: Basilic vein

      Explanation:

      The upper limb venous drainage is divided into superficial and deep. The superficial veins are accessible to draw blood for investigations. The cephalic, basilic, and median cubital veins are superficial veins.

      The median cubital vein connects the cephalic vein and basilic vein. It is located anteriorly in the antecubital fossa and is preferred for venepuncture due to its palpability and ease of access.

      The basilic vein and cephalic vein are the primary veins that drain the upper limb. They begin as the dorsal venous arch. The basilic vein originates from the ulnar side, while the cephalic vein originates from the radial side of the dorsal arch of the upper limb.

    • This question is part of the following fields:

      • Anatomy
      9.5
      Seconds
  • Question 4 - In endurance athletes, which of the following physiological adaptations to exercise is the...

    Incorrect

    • In endurance athletes, which of the following physiological adaptations to exercise is the best predictor of performance?

      Your Answer: Reduction in heart rate for a given exercise intensity

      Correct Answer: Velocity of blood lactate accumulation

      Explanation:

      Multiple regression analysis revealed that velocity of lactate accumulation (VOBLA) accounted for 92 percent of the variation in marathon running velocity (VM), and VOBLA plus training volume prior to the marathon accounted for 96 percent of the variation. Percent ST muscle fibre distribution (r = 0.55-0.69) and capillary density (r = 052-0.63) were found to be positively correlated with all performance variables. As a result, marathon running performance was linked to VOBLA and the ability to run at a pace close to it during the race. The percent ST, capillary density, and training volume were all related to these properties.

      Another metabolic adaptation compared to normal people is the early selection of fat for oxidation by muscle, especially when glucose availability is limited during high-intensity exercise. This helps to delay the onset of muscle fatigue, but it does not prevent VOBLA.

      For a given level of exercise, training can also result in cardiovascular adaptation, such as increased heart size, increased contractility, and a slower heart rate. All of these factors contribute to an increase in maximal oxygen consumption (VO2 max), but genetic factors, despite intensive training, play a large role in an athlete’s performance.

    • This question is part of the following fields:

      • Pathophysiology
      10.1
      Seconds
  • Question 5 - All of the following are true when describing the autonomic nervous system except:...

    Incorrect

    • All of the following are true when describing the autonomic nervous system except:

      Your Answer: The sympathetic trunk begins at the base of the skull and extends to the coccyx

      Correct Answer: Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole parasympathetic control

      Explanation:

      With regards to the autonomic nervous system (ANS)

      1. It is not under voluntary control
      2. It uses reflex pathways and different to the somatic nervous system.
      3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.

      With regards to the central nervous system (CNS)
      1. There are myelinated preganglionic fibres which lead to the
      ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
      2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.

      Most organs are under control of both systems although one system normally predominates.

      The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.

      There are short pre-ganglionic and long post ganglionic fibres.
      Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
      Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
      However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.

      The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.

      There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.

      Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.

      The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.

      The cranial outflow consists of
      1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
      2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
      3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
      4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreas

      The sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.

      The PNS has long preganglionic and short post ganglionic fibres.
      Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
      Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.

      Different types of these muscarinic receptors are present in different organs:
      There are:
      M1 = pupillary constriction, gastric acid secretion stimulation
      M2 = inhibition of cardiac stimulation
      M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
      M4 = brain and adrenal medulla
      M5 = brain

      The lacrimal glands are solely under parasympathetic control.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      24
      Seconds
  • Question 6 - Cells use adenosine-5-triphosphate (ATP) as a coenzyme and is a source of energy.

    Glucose...

    Correct

    • Cells use adenosine-5-triphosphate (ATP) as a coenzyme and is a source of energy.

      Glucose metabolism produces the most ATP from which of the following biochemical processes?



      Your Answer: Electron transport phosphorylation in the mitochondria

      Explanation:

      Glycolysis occurs in the cytoplasm of the cell. It converts 1 glucose molecule (6-carbon) to pyruvate (two 3-carbon molecules) and produces 4 ATP molecules and 2NADH but uses 2 ATP in the process with an overall net energy production of 2 ATP.

      Pyruvate is then oxidised to acetyl coenzyme A (generating 2 NADH per pyruvate molecule). This takes place in the mitochondria and then enters the Krebs cycle (citric acid cycle). It produces 2 ATP, 8 NADH and 2 FADH2 per glucose molecule.

      Electron transport phosphorylation takes place in the mitochondria. The aim of this process is to break down NADH and FADH2 and also to pump H+ into the outer compartment of the mitochondria. It produces 32 ATP with an overall net production of 36ATP.

      In anaerobic respiration which occurs in the cytoplasm, pyruvate is reduced to NAD producing 2 ATP.

    • This question is part of the following fields:

      • Physiology
      35.7
      Seconds
  • Question 7 - After consuming 12 g of paracetamol, a 37-year-old man is admitted to the...

    Correct

    • After consuming 12 g of paracetamol, a 37-year-old man is admitted to the medical admissions unit. He has hepatocellular necrosis in both clinical and biochemical aspects.

      The most significant reason for paracetamol causing toxicity is?

      Your Answer: Glutathione is rapidly exhausted

      Explanation:

      Phase I and phase II metabolism are used by the liver to break down paracetamol.

      1st Phase:

      Prostaglandin synthetase and cytochrome P450 (CYP1A2, CYP2E2, CYP3A4 and CYP2D6) to N-acetyl-p-benzoquinoneimine (NAPQI) and N-acetylbenzo-semiquinoneimine. NAPQI is a toxic metabolite that binds to the sulfhydryl groups of cellular proteins in hepatocytes, making it toxic. This can result in centrilobular necrosis.

      Glutathione and glutathione transferases prevent NAPQI from binding to hepatocytes at low paracetamol doses by preferentially binding to these toxic metabolites. The cysteine and mercapturic acid conjugates are then excreted in the urine. Depletion of glutathione occurs at higher doses of paracetamol, resulting in high levels of NAPQI and the risk of hepatocellular damage. Hepatotoxicity would not be an issue if the body’s glutathione stores were sufficient.

      N-acetylcysteine is a precursor for glutathione synthesis and is the drug of choice for the treatment of paracetamol overdose.

      Phase II:

      Conjugation with glucuronic acid to paracetamol glucuronide is the most common method of metabolism and excretion, accounting for 60% of renally excreted metabolites. Paracetamol sulphate (35%), unchanged paracetamol (5%), and mercapturic acid are among the other renally excreted metabolites (3 percent ). The capacity of conjugation pathways is limited. The capacity of the sulphate conjugation pathway is lower than that of the glucuronidation pathway.

      Because of the low pH in the stomach, paracetamol absorption is minimal (pKa value is 9.5). Paracetamol is absorbed quickly and completely in the alkaline environment of the small intestine. Oral bioavailability is extremely high, approaching 100%.

      As a result, measuring paracetamol levels in plasma after an injury is important. Peak plasma concentrations are reached after 30-60 minutes, with a volume of distribution of 0.95 L/kg. It binds to plasma proteins at a rate of 10% to 25%.

    • This question is part of the following fields:

      • Pharmacology
      18.2
      Seconds
  • Question 8 - Which of the following is correct for gas pipeline pressure? ...

    Incorrect

    • Which of the following is correct for gas pipeline pressure?

      Your Answer: 4 bar for oxygen

      Correct Answer:

      Explanation:

      Pipeline gases (in the UK this includes: Oxygen, Nitrous oxide, Medical air, and Entonox) are supplied at 4 bar (or 400 kPa), and compressed air is supplied at 7 bar for power tools.

      Carbon dioxide and nitric oxide are usually only supplied in cylinders.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      7.2
      Seconds
  • Question 9 - Which of the following can be measured directly using spirometry? ...

    Correct

    • Which of the following can be measured directly using spirometry?

      Your Answer: Vital capacity

      Explanation:

      Spirometry measures the total volume of air that can be forced out in one maximum breath, that is the total lung capacity (TLC), to maximal expiration, that is the residual volume (RV).

      It is conducted using a spirometer which is capable of measuring lung volumes using techniques of dilution.

      During spirometry, the following measurements can be determined:
      Forced vital capacity (FVC)/vital capacity (VC): The maximum volume of air exhaled in one single forced breathe.
      Forced expiratory volume in one second (FEV1)
      FEV1/FVC ratio
      Peak expiratory flow (PEF): the maximum amount of air flow exhaled in one blow.
      Forced expiratory flow (mid expiratory flow): the flow at 25%, 50% and 75% of FVC
      Inspiratory vital capacity (IVC): The maximum volume of air inhaled after a full total expiration.

      Anatomical dead space is measured using a single breath nitrogen washout called the Fowler’s method.

      Residual volume and total lung capacity are both measured using the body plethysmograph or helium dilution

      The functional residual capacity is usually measured using a nitrogen washout or the helium dilution technique.

    • This question is part of the following fields:

      • Clinical Measurement
      18
      Seconds
  • Question 10 - A double blind placebo control clinical trial is done. Which of these is...

    Correct

    • A double blind placebo control clinical trial is done. Which of these is correct about it?

      Your Answer: The clinician assessing the effects of the treatment does not know which treatment the patient has been given

      Explanation:

      A ‘double blind crossover study’ happens when every patient receive both treatments.

      It is incorrect to say that only half of the patients do not know which treatment they receive because in a double blind placebo control clinical trial ALL of the patients are blind to their treatment choice .

      If some of the patients are not treated, they would be aware that they were not being treated and it could not be considered a blind trial.

      In a double blind placebo control clinical trial both the clinician and the patient are blind to the treatment choice. The clinician assessing the effects of the treatment, therefore, does not know which treatment the patient has been given.

    • This question is part of the following fields:

      • Statistical Methods
      29.6
      Seconds
  • Question 11 - All the following statements are false regarding carbamazepine except ...

    Incorrect

    • All the following statements are false regarding carbamazepine except

      Your Answer: Has an elimination half life of six hours

      Correct Answer: Has neurotoxic side effects

      Explanation:

      Phenytoin, Carbamazepine, and Valproate act by inhibiting the sodium channels when these are open. These drugs also prolong the inactivated stage of these channels (Sodium channels are refractory to stimulation till these reach the closed/ resting phase from inactivated phase)

      Carbamazepine is the drug of choice for partial seizures and trigeminal neuralgia

      It can have neurotoxic side effects. Major neurotoxic effects include dizziness, headache, ataxia, vertigo, and diplopia

      After single oral doses of carbamazepine, the absorption is fairly complete and the elimination half-life is about 35 hours (range 18 to 65 hours). During multiple dosing, the half-life is decreased to 10-20 hours, probably due to autoinduction of the oxidative metabolism of the drug.

      It is metabolized in liver into active metabolite, carbamazepine-10,11-epoxide.

    • This question is part of the following fields:

      • Pharmacology
      8.7
      Seconds
  • Question 12 - Compared to the parasympathetic nervous system (PNS), the sympathetic nervous system (SNS) has:...

    Incorrect

    • Compared to the parasympathetic nervous system (PNS), the sympathetic nervous system (SNS) has:

      Your Answer: Long preganglionic fibres

      Correct Answer: Nicotinic receptors in pre and post ganglionic synapses

      Explanation:

      With regards to the autonomic nervous system (ANS)

      1. It is not under voluntary control
      2. It uses reflex pathways and different to the somatic nervous system.
      3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.

      With regards to the central nervous system (CNS)
      1. There are myelinated preganglionic fibres which lead to the
      ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
      2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.

      Most organs are under control of both systems although one system normally predominates.

      The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.

      There are short pre-ganglionic and long post ganglionic fibres.
      Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
      Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
      However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.

      The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.

      There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.

      Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.

      The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.

      The cranial outflow consists of
      1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
      2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
      3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
      4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreas

      The sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.

      The PNS has long preganglionic and short post ganglionic fibres.
      Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
      Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.

      Different types of these muscarinic receptors are present in different organs:
      There are:
      M1 = pupillary constriction, gastric acid secretion stimulation
      M2 = inhibition of cardiac stimulation
      M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
      M4 = brain and adrenal medulla
      M5 = brain

      The lacrimal glands are solely under parasympathetic control.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      23.2
      Seconds
  • Question 13 - Campylobacter is which type of bacteria? ...

    Incorrect

    • Campylobacter is which type of bacteria?

      Your Answer: sgfg

      Correct Answer: sdgsdf

      Explanation:

      Campylobacter is the commonest bacterial cause of infectious intestinal disease in the UK. The majority of cases are caused by the Gram-negative bacillus Campylobacter jejuni which is spread by the faecal-oral route. The incubation period is 1-6 days.

      Features include a prodrome phase with headaches and malaise, then diarrhoea occurs which is often bloody.
      There is often abdominal pain which may mimic appendicitis.

      It is usually self-limiting but treatment is warranted if the infection is severe or the infection occurs in an immunocompromised patient.
      Severe infection comprises of high fever, bloody diarrhoea, or more than eight stools per day or symptoms last for more than one week.
      This management would include antibiotics and the first-line antibiotic is clarithromycin.
      Ciprofloxacin is an alternative but there are strains with decreased sensitivity to ciprofloxacin which can be frequently isolated.

      Complications include:
      1.Guillain-Barre syndrome may follow Campylobacter
      2. Jejuniinfections
      3. Reactive arthritis
      4. Septicaemia, endocarditis, arthritis

    • This question is part of the following fields:

      • Physiology And Biochemistry
      4.9
      Seconds
  • Question 14 - What makes the ultrasound nebulizer efficient? ...

    Incorrect

    • What makes the ultrasound nebulizer efficient?

      Your Answer: Water droplets of size 1 micron

      Correct Answer: Reduction in gas flow resistance

      Explanation:

      Smallest drops reach not only the upper but also the lower respiratory tracks. As a result, the ultrasonic nebulizer is most efficient for the therapy of pulmonary diseases and stands out as a robust and reliable support within the clinical setting.

    • This question is part of the following fields:

      • Basic Physics
      23.8
      Seconds
  • Question 15 - Which of the following is a correctly stated fundamental (base) SI unit? ...

    Correct

    • Which of the following is a correctly stated fundamental (base) SI unit?

      Your Answer: A metre is the unit of length

      Explanation:

      The international system of units, or system international d’unites (SI) is a collection of measurements derived from expanding the metric system.

      There are seven base units, which are:

      Metre (m): a unit of length
      Second (s): a unit of time
      Kilogram (kg): a unit of mass
      Ampere (A): a unit of electrical current
      Kelvin (K): a unit of thermodynamic temperature
      Candela (cd): a unit of luminous intensity
      Mole (mol): a unit of substance.

    • This question is part of the following fields:

      • Clinical Measurement
      21.1
      Seconds
  • Question 16 - A global cerebral blood flow (CBF) of 35 ml/100 g/min (Normal CBF =...

    Incorrect

    • A global cerebral blood flow (CBF) of 35 ml/100 g/min (Normal CBF = 54 ml/100 g/min) can lead to which of the following?

      Your Answer: More damage than complete ischaemia

      Correct Answer: Poor prognostic EEG

      Explanation:

      CBF is defined as the blood volume that flows per unit mass per unit time in brain tissue and is typically expressed in units of ml blood/100 g tissue/minute. The normal average CBF in adults human is about 50 ml/100 g/min, with lower values in the white matter (,20 ml/100 g/min) and greater values in the gray matter (,80 ml/100 g/min).

      Low CBF levels between 30-40 ml/100 g/min may begin to show poor prognostic EEG. EEG findings consistently associated with a poor outcome are isoelectric EEG, low voltage EEG, and burst suppression (specifically burst suppression with identical bursts), as well as the absence of EEG reactivity.

    • This question is part of the following fields:

      • Physiology
      28.5
      Seconds
  • Question 17 - A study was concerned with finding out the normal reference range of IgE...

    Incorrect

    • A study was concerned with finding out the normal reference range of IgE levels in adults was conducted. Presuming that the curve follows a normal distribution, what is the percentage of individuals having IgE levels greater than 2 standard deviations from mean?

      Your Answer: 1.96%

      Correct Answer: 2.30%

      Explanation:

      Since the data is normally distributed, 95.4% of the values lie with in 2 standard deviations from mean. The rest of the 4.6% are distributed symmetrically outside of that range which means 2.3% of the values lie above 2 standard deviations of the mean.

    • This question is part of the following fields:

      • Statistical Methods
      23.4
      Seconds
  • Question 18 - A study aimed at assessing the validity of a novel diagnostic test for...

    Incorrect

    • A study aimed at assessing the validity of a novel diagnostic test for heart failure is being performed. The curators are worried that not all the patients will get the prevalent gold standard test.

      Which type of bias is that?

      Your Answer: Co-intervention bias

      Correct Answer: Work-up bias

      Explanation:

      Work up bias involves comparing the novel diagnostic test with the current standard test. A portion of the patients undergo the standard test while others undergo the new test as the standard test is costly. The result can be alteration in specify and sensitivity.

      Selection bias is when randomisation is not achieved.

      Attention bias refers to the person’s failure to consider various alternatives when he pre occupied by some other thoughts.

      Instrument bias is related to the experience and extent of familiarization of the participating individuals with the test.

      Co intervention bias is characterized by the groups receiving different co interventions.

    • This question is part of the following fields:

      • Statistical Methods
      25.9
      Seconds
  • Question 19 - Regarding pre-eclampsia with warning signs, which of the following laboratory tests is the...

    Incorrect

    • Regarding pre-eclampsia with warning signs, which of the following laboratory tests is the most appropriate to establish a platelet dysfunction or disorder?

      Your Answer: Template bleeding time

      Correct Answer: Platelet count

      Explanation:

      Decreased platelet concentrations with eclampsia were described as early as 1922 by Stancke. The platelet count is routinely measured in women with any form of gestational hypertension. The frequency and intensity of thrombocytopenia vary and are dependent on the severity and duration of the preeclampsia syndrome and the frequency with which platelet counts are performed.

      Overt thrombocytopenia defined by a platelet count < 100,000/microliter - indicates severe disease. In general, the lower the platelet count, the higher the rates of maternal and fetal morbidity and mortality. In most cases, delivery is advisable because thrombocytopenia usually continues to worsen. After delivery, the platelet count may continue to decline for the first day or so. It then usually increases progressively to reach a normal level within 3-5 days. In some instances with HELLP syndrome, the platelet count continues to fall after delivery. If these do not reach a nadir until 48 to 72 hours, then preeclampsia syndrome may be incorrectly attributed to one of the thrombotic microangiopathies. The following are other severe features associated with preeclampsia: Proteinuria: >/= 300 mg/24 hours; or urine protein: creatinine ratio >/= 0.3; or dipstick 1+

      Renal insufficiency: serum creatinine > 1.1 mg/dL or doubling of creatinine in the absence of other renal disease

      Impaired liver function: two times elevated AST/ALT or unexplained right upper quadrant pain or epigastric pain unresponsive to medications

      Pulmonary oedema

      Cerebral or visual symptoms: headache, visual disturbances

    • This question is part of the following fields:

      • Pathophysiology
      10.6
      Seconds
  • Question 20 - What structure is most critical in providing support for the duodenojejunal flexure? ...

    Correct

    • What structure is most critical in providing support for the duodenojejunal flexure?

      Your Answer: Ligament of Treitz

      Explanation:

      The duodenojejunal flexure is the point where the duodenum becomes the jejunum.

      The ligament of Treitz, which arises from the right crus of diaphragm, provides suspension for support.

      Between the ileum and the caecum is the ligament of Treves.

    • This question is part of the following fields:

      • Anatomy
      7.1
      Seconds
  • Question 21 - Regarding the use of soda lime as part of a modern circle system...

    Correct

    • Regarding the use of soda lime as part of a modern circle system with a vaporiser outside the circuit (VOC), which of the following is its most deleterious consequence?

      Your Answer: Carbon monoxide formation

      Explanation:

      When using dry soda lime for VOCs, very high amounts of carbon monoxide may be produced, regardless of the inhalational anaesthetic agent used. The carbon monoxide produced is sufficient enough to cause cytotoxic and anaemic hypoxia. To prevent this, soda lime canisters are shaken well to even out the packing of granules. This can help to evenly distribute gas flow for proper CO2 absorption and ventilation.

      Compound A is formed when dry soda lime, or soda lime in high temperature, reacts with the inhalational anaesthetic Sevoflurane. Animal studies have shown renal toxicity in rats, but renal adverse effects in humans are yet to be observed.

      When monitors are not employed with VOCs, deleterious effects are not for certain. However, monitors not employed with vaporiser inside the circuit (VIC) can lead to significant adverse events.

    • This question is part of the following fields:

      • Pathophysiology
      60.3
      Seconds
  • Question 22 - You are shown the summary of a publication recommending use of their company's...

    Correct

    • You are shown the summary of a publication recommending use of their company's antiemetic to prevent postoperative nausea and vomiting by a pharmaceutical representative. You read the article, which is in a peer reviewed journal, and consider whether to change your current practice of using cyclizine intraoperatively.

      Which type of publication will provide the best evidence on which to base changes to your practice?

      Your Answer: A prospective randomised double blind controlled trial against cyclizine in multiple centres

      Explanation:

      A prospective randomised double blind controlled trial against cyclizine in multiple centres is the most likely to change your practice.

      Case controlled studies are efficient in identifying an association between a drug treatment and outcome and are usually conducted retrospectively. They are generally less valued than prospective randomised trials. They cannot generate incidence data, are subject to bias, have difficult selection of controls and can be made more difficult if note keeping is not reliable.

      The gold standard in intervention-based studies is randomised controlled double blind trials. Its features are:

      Treating all intervention groups identically
      Reduction of bias by random allocation to intervention groups
      Patients and researchers unaware of which treatment was given until at completion of study
      Patients analysed within the group to which they were allocated, and
      Analysis focused on estimating the size of the difference in predefined outcomes between intervention groups.

      New healthcare interventions should be evaluated through properly designed randomised controlled trials (though there are some potential ethical disadvantages)

      Conducting trials in multiple centres is an accepted way of evaluating a new drug as it may be the only way of recruiting sufficient number of patients within a reasonable time frame to satisfy the objectives of the trial. Type II statistical errors will occur if a small numbers of patients is used in study group.

    • This question is part of the following fields:

      • Statistical Methods
      24.8
      Seconds
  • Question 23 - Which compound of ketamine hydrochloride has the most significant anaesthetic property or effect?...

    Incorrect

    • Which compound of ketamine hydrochloride has the most significant anaesthetic property or effect?

      Your Answer: (S)-norketamine

      Correct Answer: (S)-ketamine

      Explanation:

      Ketamine is usually used as a racemic mixture, i.e. (R/S)-ketamine. For over 20 years, use of the more potent (S)-enantiomer by anaesthesiologists has become a preferred option due to the assumption of increased anaesthetic and analgesic properties, a more suitable control of anaesthesia, and of an improved recovery from anaesthesia.

      The use of ketamine in anaesthesia and psychiatry may be accompanied by the manifestation of somatic and especially psychomimetic symptoms such as perceptual disturbances, experiences of dissociation, euphoria, and anxiety.

    • This question is part of the following fields:

      • Pharmacology
      8.3
      Seconds
  • Question 24 - Of the following, which of these oxygen carrying molecules causes the greatest shift...

    Incorrect

    • Of the following, which of these oxygen carrying molecules causes the greatest shift of the oxygen-dissociation curve to the left?

      Your Answer: Carboxyhaemoglobin (HbCO)

      Correct Answer: Myoglobin (Mb)

      Explanation:

      Myoglobin is a haemoglobin-like, iron-containing pigment that is found in muscle fibres. It has a high affinity for oxygen and it consists of a single alpha polypeptide chain. It binds only one oxygen molecule, unlike haemoglobin, which binds 4 oxygen molecules.

      The myoglobin ODC is a rectangular hyperbola. There is a very low P50 0.37 kPa (2.75 mmHg). This means that it needs a lower P50 to facilitate oxygen offloading from haemoglobin. It is low enough to be able to offload oxygen onto myoglobin where it is stored. Myoglobin releases its oxygen at the very low PO2 values found inside the mitochondria.

      P50 is defined as the affinity of haemoglobin for oxygen: It is the PO2 at which the haemoglobin becomes 50% saturated with oxygen. Normally, the P50 of adult haemoglobin is 3.47 kPa(26 mmHg).

      Foetal haemoglobin has 2 ? and 2 ?chains. The ODC is left shifted – this means that P50 lies between 2.34-2.67 kPa [18-20 mmHg]) compared with the adult curve and it has a higher affinity for oxygen. Foetal haemoglobin has no ? chains so this means that there is less binding of 2.3 diphosphoglycerate (2,3 DPG).

      Carbon monoxide binds to haemoglobin with an affinity more than 200-fold higher than that of oxygen. This therefore decreases the amount of haemoglobin that is available for oxygen transport. Carbon monoxide binding also increases the affinity of haemoglobin for oxygen, which shifts the oxygen-haemoglobin dissociation curve to the left and thus impedes oxygen unloading in the tissues.

      In sickle cell disease, (HbSS) has a P50 of 4.53 kPa(34 mmHg).

    • This question is part of the following fields:

      • Physiology
      14.7
      Seconds
  • Question 25 - A 68-year old man, is admitted in hospital. He is scheduled to undergo...

    Incorrect

    • A 68-year old man, is admitted in hospital. He is scheduled to undergo a femoro-popliteal bypass graft, for which he has been administered a spinal-epidural anaesthetic. Intrathecal heavy bupivacaine (0.5%) was injected at L3-4 with good effect. On insertion of the epidural catheter, he remained asymptomatic.

      During surgery, 5000 I.U. of IV heparin was given. The surgery is successful and required no epidural top-ups.

      Six hours later, he complains of a severe back pain with weakness in his lower limbs.

      What is the most important first step?

      Your Answer: Arrange an MRI scan

      Correct Answer: A full neurological examination to establish the nature of the problem

      Explanation:

      The most likely diagnosis is a spinal epidural haematoma, a neurological emergency. A full examination must be carried out to determine the nature of the neurological problem before conducting any investigations or imaging.

      The effects of spinal anaesthesia should have worn off by this time point, and the severe back pain is a red flag.

      The patient will also require an urgent neurological team referral as a spinal epidural haematoma requires immediate evacuation for spinal decompression. Analgesics may be prescribed for pain management.

      Heparin would have been fully metabolised and so a reversal is unnecessary.

      A spinal epidural haematoma is a pooling of blood in the epidural space, which can cause compression of the spinal cord. Its presenting symptoms are:

      Usually begins with severe backpain and percussion tenderness
      Cauda equina syndrome
      Paralysis of the lower extremities.
      If infected, a fever occurs in 66% of cases
      Lower limb weakness developing after stopping an epidural infusion or weakness of the lower limbs which does not resolve within four hours of cessation of infusion of epidural local anaesthetic
      Meningism.

    • This question is part of the following fields:

      • Pathophysiology
      42.4
      Seconds
  • Question 26 - Which of the following statements is true regarding the relation to the liver?...

    Incorrect

    • Which of the following statements is true regarding the relation to the liver?

      Your Answer: Ligamentum venosum is an anterior relation of the liver

      Correct Answer: The caudate lobe is superior to the porta hepatis

      Explanation:

      Ligamentum venosum is an anterior relation of the liver: The ligamentum venosum, the fibrous remnant of the ductus venosus of the fetal circulation, lies posterior to the liver. It lies in the fossa for ductus venosus that separates the caudate lobe and the left lobe of the liver.

      The portal triad contains three important tubes: 1. Proper hepatic artery 2. Hepatic portal vein 3. Bile ductules It also contains lymphatic vessels and a branch of the vagus nerve.

      The bare area of the liver is a large triangular area that is devoid of any peritoneal covering. The bare area is attached directly to the diaphragm by loose connective tissue. This nonperitoneal area is created by a wide separation between the coronary ligaments.

      The porta hepatis is a fissure in the inferior surface of the liver. All the neurovascular structures (except the hepatic veins) and hepatic ducts enter or leave the liver via the porta hepatis. It contains the sympathetic branch to the liver and gallbladder and the parasympathetic, hepatic branch of the vagus nerve. The caudate lobe (segment I) lies in the lesser sac on the inferior surface of the liver between the IVC on the right, the ligamentum venosum on the left, and the porta hepatis in front

    • This question is part of the following fields:

      • Anatomy
      25.3
      Seconds
  • Question 27 - An experiment is designed to investigate that how three diets having different sugar...

    Incorrect

    • An experiment is designed to investigate that how three diets having different sugar content affect the body weight to a different level.

      Which one of the following test will determine a statistically significant difference among the diets?

      Your Answer: Mann Whitney U

      Correct Answer: ANOVA

      Explanation:

      Chi-square test is used to determine the statistically significant different between categorical variables. It also determines the difference between expected frequencies and the observed frequencies.

      Mann Whitney U test is used to determine the statistically significant different between two independent groups.

      Wilcoxon’s test is the test of dependency. it determines the statistically significant difference between two dependent groups.

      Student t-test is one of the most commonly used method to test the hypothesis. It determines the significant difference between the means of two different groups.

      ANOVA (analysis of variance) is similar to student’s t-test.

      ANOVA is a statistical method used to determines the statistically significant difference between the mean of more than two group. In this experiment as we are dealing with three different group, ANOVA is most suitable test to determine the difference between each groups.

    • This question is part of the following fields:

      • Statistical Methods
      13.3
      Seconds
  • Question 28 - Which of the following facts about T cells is true? ...

    Correct

    • Which of the following facts about T cells is true?

      Your Answer: Secrete IL-2 when activated

      Explanation:

      T cells function as a part of the body’s adaptive immune system. There are different types of T cells, including:

      Cytotoxic T cells: Function as killer cells by releasing cytotoxic granules into the membrane of targeted cells.

      T-Helper cells: When activated, they function to activate other immune cell types, assist in antibody production with B cells and releasing cytokines including IL-2.

      Memory T cells: Function as to provide immune memory against already encountered antigens.

      T cells possess specific glycoproteins and receptors on their surface.

      T-Helper cells work with HLA class II antigens on the cell surfaces in order to recognise foreign antigens

      T cells survive ranges from a few weeks, to a lifetime depending on the subtype in question.

      Immunoglobulins are expressed on the surface of, and secreted by B-lymphocytes.

      Native antigens are recognised by B cells. T cells only recognise antigens that have been processed by the cells and presented on the surface of the cell.

    • This question is part of the following fields:

      • Pathophysiology
      13.3
      Seconds
  • Question 29 - Noradrenaline is used as an infusion to increase blood pressure in a 43-year-old...

    Incorrect

    • Noradrenaline is used as an infusion to increase blood pressure in a 43-year-old woman with pneumonia admitted to ICU.
      Which of the following statements is true regarding Noradrenaline?

      Your Answer: Is metabolised mainly by hepatic esterases

      Correct Answer: Has a short half life about 2 minutes

      Explanation:

      Noradrenaline has a short half-life of about 2 minutes. It is rapidly cleared from plasma by a combination of cellular reuptake and metabolism.

      It acts as sympathomimetics by acting on ?1 receptors and also on ? receptors.

      It decreases renal and hepatic blood flow.

      Norepinephrine is metabolized by the enzymes monoamine oxidase and catechol-O-methyltransferase to 3-methoxy-4-hydroxymandelic acid and 3-methoxy-4-hydroxyphenylglycol (MHPG).

      Natural catecholamines are Adrenaline, Noradrenaline, and Dopamine

    • This question is part of the following fields:

      • Pharmacology
      7
      Seconds
  • Question 30 - Which of the following organism is highly resistant to penicillin? ...

    Incorrect

    • Which of the following organism is highly resistant to penicillin?

      Your Answer:

      Correct Answer: Escherichia coli

      Explanation:

      Penicillinase is a narrow spectrum ?-lactamase that opens the ?-lactam ring and inactivates Penicillin G and some closely related congeners. The majority of Staphylococci and some strains of gonococci, B. subtilis, E. coli, and a few other bacteria produce penicillinase.

      N. meningitidis is sensitive to penicillin and less than 20% resistance is found in pseudomonas.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Pharmacology (1/5) 20%
Clinical Measurement (2/3) 67%
Anatomy (2/3) 67%
Pathophysiology (2/5) 40%
Physiology And Biochemistry (0/3) 0%
Physiology (1/3) 33%
Anaesthesia Related Apparatus (0/1) 0%
Statistical Methods (2/5) 40%
Basic Physics (0/1) 0%
Passmed