-
Question 1
Correct
-
A 16-year-old girl presents to the clinic with a 4-month history of no menstrual bleeding. Menarche was at 11 years of age. She denies experiencing any headache or visual disturbances. Physical examination shows an overweight girl, with facial hair, acne vulgaris on the face and a deep voice. Abdominal examination shows no abnormalities and a pregnancy test is negative. Diagnosis can be confirmed with which of the following lab test?
Your Answer: Raised Testosterone
Explanation:Diagnostic criteria of PCOsAccording to the American Association of Clinical Endocrinologists, at least two of three of the criteria below are required for diagnosis of PCOS after excluding other causes of irregular bleeding and elevated androgen levels.Hyperandrogenism (clinical or laboratory)Oligo- and/or anovulationPolycystic ovaries on ultrasoundDiagnosis of PCOS is possible without the presence of ovarian cysts.Rule out any other causes of hyperandrogenism and anovulation.Blood hormone levels↑ Testosterone (both total and free) or free androgen index↑ LH (LH:FSH ratio > 2:1)Oestrogen is normal or slightly elevated A clinical picture of hyperandrogenism overrules any normal hormone levels and can fulfil a diagnostic criterium of PCOS.
-
This question is part of the following fields:
- Adolescent Health
-
-
Question 2
Correct
-
A 16-year-old boy is being treated with ADH for diabetes insipidus. His blood results show:fasting plasma glucose level: 6 mmol/l (3– 6)sodium 148 mmol/l (137–144)potassium 4.5 mmol/l (3.5–4.9)calcium 2.8 mmol/l (2.2–2.6). However, he still complains of polyuria, polydipsia and nocturia.What could be the most probable cause?
Your Answer: Nephrogenic diabetes insipidus
Explanation:Diabetes insipidus (DI) is defined as the passage of large volumes (>3 L/24 hr) of dilute urine (< 300 mOsm/kg). It has the following 2 major forms:Central (neurogenic, pituitary, or neurohypophyseal) DI, characterized by decreased secretion of antidiuretic hormone (ADH| also referred to as arginine vasopressin [AVP])Nephrogenic DI, characterized by decreased ability to concentrate urine because of resistance to ADH action in the kidney.The boy most probably has nephrogenic diabetes insidious (DI) not central DI so he is not responding to the ADH treatment.
-
This question is part of the following fields:
- Endocrinology
-
-
Question 3
Correct
-
A 16-year-old female presents to the physician with nausea, vomiting and abdominal swelling. Physical examination also reveals digital clubbing and linea nigra on her abdomen. Which of the following is the most likely diagnosis?
Your Answer: Pregnancy
Explanation:Clinical signs of early pregnancy-Amenorrhoea-Nausea and vomiting -Breast enlargement and tenderness -Hyperpigmentation of the areola and formation of linea nigra: Most likely due to increased levels of melanocyte-stimulating hormone produced by the placenta -Increased urinary frequency-Fatigue-Cravings for or aversions to certain foods-Abdominal bloating and constipation
-
This question is part of the following fields:
- Adolescent Health
-
-
Question 4
Incorrect
-
Where does Stensens duct primarily open?
Your Answer: Immediately lateral to the foramen caecum
Correct Answer: Opposite the second molar tooth
Explanation:The parotid duct (Stensen’s duct), which provides an exit for the gland’s secretions, passes through the anterior edge of the gland in the superficial lobe, turns medially at the anterior border of the masseter, penetrates the buccinator, then enters the oral cavity lateral to the second maxillary molar.
-
This question is part of the following fields:
- ENT
-
-
Question 5
Incorrect
-
A 14-year-old boy is referred from his optician with a diagnosis of Lisch nodules of the iris. What is the most likely sign to observe on examination?
Your Answer: Hemangioblastoma of the spinal cord
Correct Answer: Axillary freckles
Explanation:Neurofibromatosis type 1 (NF1) is a common autosomal dominant disease. The Lisch nodule represents one of the most common NF1 ocular manifestations.NF1 is caused by a genetic mutation which can cause tumours to grow on nerve endings| these cutaneous neurofibromas are benign tumours which grow on the skin, often first appearing during the hormonal changes that occur in teenage years. They vary in size and can appear anywhere on the body. The number of neurofibromas present differs greatly between individuals and over a lifetime Café au lait spots (coffee coloured birthmarks) are often the first and most common sign of NF1, and these are often found at birth and are usually evident by 2 years of age.Other features of NF1 can include Lisch nodules of the iris (small pigmentation in the iris which causes no disturbance to vision), skin-fold freckling (freckling/pigmentation in the groyne and armpits), plexiform neurofibromas (or sub cutaneous neurofibromas) which are diffuse tumours that grow along a nerve and are found in at least 25 % of people with NF1, optic gliomas (tumour of the optic nerve), and skeletal complications including pseudarthrosis and scoliosis. Macrocephaly (large head size) is also common, and short stature is found in around a third of people with NF1. Rare complications include a risk of malignancy, organs being compromised by neurofibromas, seizures, and hypertension.
-
This question is part of the following fields:
- Ophthalmology
-
-
Question 6
Correct
-
In females, precocious puberty may be defined as the development of secondary sexual characteristics before which of the following ages?
Your Answer: 8 years of age
Explanation:Precocious puberty is the development of secondary sexual characteristics before the age of 8 in females, and 9 in males. The first sign of early puberty in females is breast enlargement, followed by the appearance of pubic and axillary hair, and finally menarche, 2-3 years after the onset of thelarche. Precocious puberty is caused by the premature activation of the hypothalamic-pituitary-gonadal axis where FSH and LH levels are raised. Less common is the gonadotrophin independent form, which is due to excess sex hormones, but low FSH and LH levels.
-
This question is part of the following fields:
- Endocrinology
-
-
Question 7
Incorrect
-
A 2-year-old child is diagnosed with a left sided cataract after an ophthalmoscopic exam. Which of the following is the least likely diagnosis?
Your Answer: Asthma
Correct Answer: Hyperthyroidism
Explanation:Hyperthyroidism is the least likely cause of cataract development as all of the other mentioned options can lead to eye problems. Asthma and crohn’s can lead to steroid induced cataract formation, while trauma to the eye can cause traumatic cataracts to develop afterwards. JIA often leads to uveitis.
-
This question is part of the following fields:
- Ophthalmology
-
-
Question 8
Correct
-
An 18-year-old homosexual male presents 36 hours after having unprotected sex with his partner whose HIV status is not known. He is concerned about his risk of acquiring HIV. He is feeling well and shows no symptoms. The physician offers him a post exposure prophylaxis, which consists of 3 different antiviral drugs. Two of these drugs act by which of the following mechanisms?
Your Answer: Inhibition of viral reverse transcriptase
Explanation:Recommended regimens3 NRTI (e.g., zidovudine, lamivudine, abacavir) OR2 NRTI (e.g., lamivudine + abacavir) AND1 NNRTI (e.g., efavirenz) OR1 PI (e.g., lopinavir) OR1 INI (e.g., raltegravir)
-
This question is part of the following fields:
- HIV
-
-
Question 9
Correct
-
For a given condition, disease or attribute, there will be a proportion of people in a population who have the given condition, disease or attribute at a specified point in time or over a specified period of time. Which of following is the best term which can describe the above?
Your Answer: Prevalence
Explanation:Prevalence, sometimes referred to as prevalence rate, is the proportion of persons in a population who have a particular disease or attribute at a specified point in time or over a specified period of time.
-
This question is part of the following fields:
- Epidemiology And Statistics
-
-
Question 10
Correct
-
A 15-month-old boy is brought to the clinic by his mother with complaints of recurrent urinary tract infections. As part of the diagnostic work-up, he was noted to have abnormal renal function. An ultrasound scan is performed and shows bilateral hydronephrosis.What is the most probable underlying condition giving rise to the child's symptoms and bilateral hydronephrosis?
Your Answer: Urethral valves
Explanation:The most probable cause for the child’s presenting symptoms and the findings in ultrasound would be the presence of an abnormal posterior urethral valve. A posterior urethral valve is a developmental anomaly that usually affects male infants (incidence 1 in 8000) leading to obstructive uropathy. Diagnostic features include bladder wall hypertrophy, hydronephrosis and bladder diverticula.Note:Posterior urethral valves are the most common cause of infra-vesical outflow obstruction in males. They can be diagnosed on antenatal ultrasonography. Due to the necessity of the fetal bladder to develop high emptying pressures in utero secondary to this anomaly, the child may develop renal parenchymal damage. This leads to renal impairment noted in 70% of boys at the time of presentation. Management:The immediate treatment would be to place a bladder catheter to relieve the acutely retained urine. The definitive treatment of choice would be an endoscopic valvotomy with a cystoscopic and renal follow up.
-
This question is part of the following fields:
- Nephro-urology
-
-
Question 11
Incorrect
-
Regarding normal gross motor development of a 3-year-old child, which of the following statements is correct?
Your Answer: A child will be able to ride a bike (with stabilisers) by age 3
Correct Answer: A child age three should be able to throw a ball both under and over hand
Explanation:A three-year child’s typical developmental milestones include walking up and down the stairs with alternating feet, jumping in a place with two feet together, and jumping forward for about 2 feet. The child can pedal a tricycle and can throw a ball over and underhand. An average child should start walking around 12-14 months of age and should be investigated as early as 18 months if they do not begin to walk. Skipping can be done by a child of 5 years of age. A child of 6-7 years of age can ride a bike with stabilizers and can balance on one foot for 20 seconds.
-
This question is part of the following fields:
- Child Development
-
-
Question 12
Incorrect
-
The differentiation of type I and type II epithelial cells in the developing lung is evident in which gestational age?
Your Answer: Embryonic: 4-5 weeks gestation
Correct Answer: Canalicular: 16-24 weeks gestation
Explanation:The differentiation between type 1 and type 2 epithelia in the developing lung buds is evident from 16-24 weeks of gestation.Development of the respiratory tract has five stages:- Embryonic (at 4 – 5 weeks of gestation):Formation of lung buds, trachea and mainstem bronchi occur. These structures are formed from a ventral outpouching of foregut pharynx. At this stage, the beginnings of the five lung lobes are present.- Pseudoglandular (at 5 – 16 weeks of gestation):Formation of terminal bronchioles, cartilage and smooth muscles occur in this stage. – Canalicular (at 16-24 weeks gestation): Differentiation of type I and II epithelial cells can be done in this stage. There is also an increase in the size of proximal airways).- Saccular (at 24 – 40 weeks of gestation): Terminal saccule formation occurs. Production of surfactant takes place at this stage with an increase in the number of goblet cellsUp to half the adult number of alveoli are in place by this stage.- Alveolar (occurs between 32 weeks of gestation till the post-natal age 8): Formation of alveoli and septation occurs with the expansion of air spaces.
-
This question is part of the following fields:
- ENT
-
-
Question 13
Incorrect
-
A child with a history of developmental delay presents with plaque-like lesions in the retina. The doctor suspects they are probably hamartomas. Which of the following is the most probable association?
Your Answer: Neurofibromatosis type 2
Correct Answer: Tuberous sclerosis
Explanation:Tuberous sclerosis, an autosomal dominant disorder, may present with a variety of symptoms, including seizures, developmental delay, behavioural problems, skin abnormalities, and lung and kidney disease. Hamartomas are often associated.
-
This question is part of the following fields:
- Genetics And Dysmorphology
-
-
Question 14
Incorrect
-
A 26-year-old doctor who has recently been diagnosed with melanoma asks about survival rates associated with this condition. Which of the following statistical methods is employed to predict the survival rates?
Your Answer: Student t-test
Correct Answer: Kaplan-Meier estimator
Explanation:The Kaplan–Meier estimator, also known as the product limit estimator, is a non-parametric statistic used to estimate the survival function from lifetime data. In medical research, it is often used to measure the fraction of patients living for a certain amount of time after treatment.
-
This question is part of the following fields:
- Adolescent Health
-
-
Question 15
Incorrect
-
A 10-year-old boy presents with severe abdominal pain and jaundice. His family is originally from Ghana.An ultrasound shows evidence of gallstones. What is the most likely risk factor for the child to develop gallstones?
Your Answer: Obesity
Correct Answer: Sickle cell disease
Explanation:Based on the clinical scenario, the most likely risk factor in this child to develop gallstones is sickle cell disease.Note:Haemolysis is the most frequent cause for gallstones in children and the likeliest cause because of his ethnicity would be sickle cell disease. The gallstones are pigmented which form from bilirubin. 70% of patients with sickle cell disease will develop gallstones| the prevalence of gallstones is related to the rate of haemolysis.Other options:- Gilbert’s syndrome: it is a common condition in which bilirubin glucuronidation (i.e. converting bilirubin into a water-soluble form) is affected. During times of stress (viral illness, fasting, etc.) there is an excess bilirubin production, and jaundice may develop. It is a benign condition but there is some evidence of an increased risk of developing gallstones. However, sickle cell disease is a more likely risk factor in this case.- Hereditary spherocytosis: Hereditary spherocytosis is a disease of the white population and is less likely to be the underlying cause in this case.- Male gender: After puberty, the incidence of gallstones is higher in women. Before puberty, the incidence is equal.- Obesity: Obesity is a risk factor for gallstones and is thought to be behind the rising incidence among young adults. Nevertheless, haemolytic states remain the most common reason for gallstones in children.
-
This question is part of the following fields:
- Gastroenterology And Hepatology
-
-
Question 16
Incorrect
-
Which of the following features is consistent with ventricular septal defect (VSD) murmur?
Your Answer: Loud P2
Correct Answer: Short diamond shaped diastolic murmur after the third heart sound
Explanation:Auscultatory findings of VSD vary with the size of the defect. Small VSDs typically produce murmurs ranging from a grade 1 to 2/6 high-pitched, short systolic murmur (due to tiny defects that actually close during late systole) to a grade 3 to 4/6 holosystolic murmur (with or without thrill) at the lower left sternal border| this murmur is usually audible within the first few days of life (see table Heart Murmur Intensity). The precordium is not hyperactive, and the 2nd heart sound (S2) is normally split and has normal intensity.Moderate to large VSDs produce a holosystolic murmur that is present by age 2 to 3 wk| S2 is usually narrowly split with an accentuated pulmonary component. An apical diastolic rumble (due to increased flow through the mitral valve) and findings of heart failure (e.g., tachypnoea, dyspnoea with feeding, failure to thrive, gallop, crackles, hepatomegaly) may be present. In moderate, high-flow VSDs, the murmur is often very loud and accompanied by a thrill (grade 4 or 5 murmur). With large defects allowing equalization of left ventricular and right ventricular pressures, the systolic murmur is often attenuated.
-
This question is part of the following fields:
- Cardiovascular
-
-
Question 17
Correct
-
As the junior doctor on call in the neonatal unit, you have been informed of a case of ambiguous genitalia in which the midwife was unable to decide the gender at birth. What is the most appropriate course of action in this case?
Your Answer: Inform the parents that a number of investigations will need to be performed and that they will need to wait before a sex is assigned
Explanation:Cases of neonatal infant ambiguous genitalia can be a great source of psychological stress for families. One of the most important next steps in managing the case is reassuring the parents that the best care will be given to the baby and then informing them about the investigations that will need to be performed before a sex can be assigned. The sex should not be guessed just by examination nor assigned by karyotyping. Thorough investigations must be completed with the help of endocrinologists for the best outcome.
-
This question is part of the following fields:
- Endocrinology
-
-
Question 18
Incorrect
-
Which of the following best describes odds ratios?
Your Answer: Close to the relative risk when events occur frequently
Correct Answer: The odds of an event in one group divided by the odds of the event in another
Explanation:Odds ratios are best described as the odds of an event in one group divided by the odds of the event in another. They form an alternative to the relative risk in case–control studies and are close to the relative risk when events are rare. The odds are the number of the event divided by the number without the event, which is less intuitive than the risk, which is the number with the event divided by the total. Odds ratios are therefore less intuitive than relative risks. Logistic regression analysis outputs variable coefficients which are the log of the odds ratio.
-
This question is part of the following fields:
- Epidemiology And Statistics
-
-
Question 19
Incorrect
-
A 6-year-old girl develops central precocious puberty. Which of the following conditions is the most likely aetiology for her condition?
Your Answer: Congenital adrenal hyperplasia
Correct Answer: Hypothyroidism
Explanation:Precocious puberty is the attainment of normal pubertal biochemical and physical features at an abnormally early age. The age cut-offs commonly used to define precocious puberty are 8 years for females and 9 years for males. Precocious puberty may be central (true) or peripheral (false) based on the aetiology. Central precocious puberty is due to the premature activation of the hypothalamic-pituitary-gonadal axis, which in turn leads to the development of secondary sexual characteristics at an earlier than usual age. Central precocious puberty is mostly idiopathic, but other causes include congenital or prolonged, untreated hypothyroidism, congenital or acquired central nervous system pathologies, and several genetic syndromes like Silver-Russell syndrome. The other mentioned choices cause peripheral or false precocious puberty.
-
This question is part of the following fields:
- Endocrinology
-
-
Question 20
Correct
-
A 17-year-old male presented to the OPD with complaints of abdominal pain and diarrhoea. There is a history of pubertal delay. On examination, he has pallor and looks short for his age. Tissue biopsy of the small intestines reveals damaged villi. Which of the following is the most likely cause of this condition?
Your Answer: Coeliac disease
Explanation:Celiac disease has characteristic shortened intestinal villi. When patients with celiac disease eat products containing gluten, they are unable to absorb the nutrients due to flattened or shortened intestinal villi. The blistering rash present on the patient’s elbows strongly suggests celiac disease. This rash is a sign of the condition Dermatitis Herpetiformis which is associate with celiac disease. Therefore, it is also often called ‘gluten rash’.
-
This question is part of the following fields:
- Gastroenterology And Hepatology
-
-
Question 21
Incorrect
-
Which of the following does not cause painless gastrointestinal bleeding?
Your Answer: Polyps
Correct Answer: Intussusception
Explanation:Intussusception causes abdominal pain leading to painful lower GI bleeding. Intussusception is a condition in which part of the intestine folds into the section next to it. It most commonly involves the small bowel and rarely the large bowel. Intussusception doesn’t usually require surgical correction. 80% of cases can be both confirmed and reduced using barium, water-soluble or air-contrast enema.However, up to 10% of cases can experience recurrence within 24 hours after reduction, warranting close monitoring during this period.Most children have self-limiting and minor bleeds. However, children with massive bleeds will need emergency care and stabilisation.The various causes of lower GI bleeding in neonates include:- Anal fissures- Milk protein or soy allergy- Intussusception- Volvulus- Coagulopathies including haemorrhagic disease of the new-born- Arteriovenous malformations- Necrotising enterocolitis- Hirschsprung enterocolitis- Meckel’s diverticulitis- Drugs (NSAIDs, heparin, indomethacin used for patent duct closure, dexamethasone)The various causes of lower GI bleeding in children aged between 1 month to 2 years include:- Infection- Anal fissures- Intussusception- Malrotation with volvulus- Milk protein or soy allergy- Polyp- Meckel’s diverticulum- Duplication cyst- Foreign body- AV malformation- Colitis of immune deficiency- Tumour- HaematomaThe causes of lower GI bleeding in children older than 2 years include:- Polyp- Inflammatory bowel disease (IBD)- Infectious diarrhoea (caused by Escherichia coli and Shigella)- Intussusception- Haemangiomas- Arteriovenous malformations- Vasculitis- Tumour
-
This question is part of the following fields:
- Emergency Medicine
-
-
Question 22
Incorrect
-
Which among the following is a type of acquired anterior pituitary disorder?
Your Answer: Idiopathic precocious puberty with arachnoid cyst
Correct Answer: Pituitary adenoma
Explanation:Among the given options, pituitary adenoma is an acquired anterior pituitary disorder which represent between 10 and 25% of all intracranial neoplasms.Other options:- Agenesis of the corpus callosum is characterised by the partial or complete absence of the corpus callosum. This condition is associated with pituitary hormone deficiencies.- Congenital disorders such as hydrocephalus or arachnoid cysts may be a cause of precocious puberty.- Pituitary hypoplasia and septo-optic dysplasia are congenital disorders of the pituitary gland.
-
This question is part of the following fields:
- Endocrinology
-
-
Question 23
Correct
-
A young male sustains a skull-base fracture at the middle cranial fossa which injures his right abducent (VI) nerve.Which signs are most likely to be present on clinical examination?
Your Answer: The patient is unable to deviate his right eye laterally
Explanation:Cranial nerve VI, also known as the abducent nerve, innervates the ipsilateral lateral rectus (LR), which functions to abduct the ipsilateral eye. Patients usually present with an isolated abduction deficit, binocular horizontal diplopia, worse in the distance, and esotropia in primary gaze. Patients also may present with a head-turn to maintain binocularity and binocular fusion and to minimize diplopiaExamination for a sixth nerve palsy involves documenting the presence or absence of papilledema, examining the ocular motility, evaluating the eyelids and pupils, and excluding involvement of other cranial nerves (e.g., V, VII, VIII).
-
This question is part of the following fields:
- Anatomy
-
-
Question 24
Correct
-
A 30-year-old female presents to her OBGYN for a 20-week anomaly scan of the foetus. During her visit, she is informed she is going to have a baby boy. What will be the chromosomal arrangement of the baby?
Your Answer: 22 pairs of autosomes and 1 pair of sex hormones (XY)
Explanation:In humans, each cell normally contains 23 pairs of chromosomes, for a total of 46. Twenty-two of these pairs, called autosomes, look the same in both males and females. The 23rd pair, the sex chromosomes, differ between males and females. Females have two copies of the X chromosome, while males have one X and one Y chromosome.
-
This question is part of the following fields:
- Genetics And Dysmorphology
-
-
Question 25
Incorrect
-
A 16-year-old boy, known case of Crohn's disease presents to the clinic with jaundice. His labs reveal an elevated alkaline phosphatase level. AST, ALT, albumin and clotting are in normal range. Antineutrophil cytoplasmic antibody level is positive. Radiological examination shows multi-focal strictures and irregularity of both intra and extra hepatic bile ducts which has resulted in a 'beads on a string' appearance. Which of the following is the most likely diagnosis?
Your Answer: Acute obstructive cholangitis
Correct Answer: Primary sclerosing cholangitis
Explanation:Primary sclerosing cholangitis (PSC) is a long-term progressive disease of the liver and gallbladder characterized by inflammation and scarring of the bile ducts which normally allow bile to drain from the gallbladder. Early cholangiographic changes can include fine or deep ulcerations of the common bile duct. As PSC progresses, segmental fibrosis develops within the bile ducts, with saccular dilatation of the normal areas between them, leading to the typical beads-on-a-string appearance seen on cholangiography. Although these strictures can be found anywhere on the biliary tree, the intrahepatic and extrahepatic bile ducts are simultaneously involved in the vast majority of cases.
-
This question is part of the following fields:
- Gastroenterology And Hepatology
-
-
Question 26
Incorrect
-
Which one of the following factors is the most likely etiological factor for abnormally short stature amongst children?
Your Answer: Maternal deprivation
Correct Answer: Familial short stature
Explanation:Familial/inherited short stature is the most likely and commonest factor resulting in short stature among the children. Klinefelter syndrome is characterised by tall stature, widely spaces nipples and infertility. Other factors include congenital heart disease, maternal deprivation and diabetes mellitus but these are the rare causes.
-
This question is part of the following fields:
- Genetics And Dysmorphology
-
-
Question 27
Incorrect
-
Which of the given choices accurately defines perinatal mortality rate?
Your Answer: Number of deaths from12 weeks gestation up to delivery divided by 100 births
Correct Answer: Number of stillbirths and deaths within 7 days of life divided by 1000 births
Explanation:The perinatal mortality rate is defined as the number of perinatal deaths per 1000 total births. Perinatal death includes the death of a live-born neonate within 7-days of life (early neonatal death) and the death of a fetus ≥ 22 weeks of gestation (stillbirth). Hence, the perinatal mortality rate is calculated by dividing the number of still births+ the number of early neonatal deaths by 1000 births.
-
This question is part of the following fields:
- Neonatology
-
-
Question 28
Incorrect
-
Scarring type of alopecia occurs in which of the following conditions?
Your Answer: Tinea capitis
Correct Answer: Discoid lupus
Explanation:Alopecia is a scalp condition characterized by either overall baldness or patches of hair loss over the head. It can be broadly classified as scarring alopecia and non-scarring alopecia. Non-scarring is the most common type and is seen in various conditions like nutritional deficiencies, alopecia areata, hypothyroidism, tinea capitis, and SLE. Scarring alopecia is commonly seen in cases of discoid lupus erythematosus, which is a common cause of widespread inflammatory and scarring lesions all over the body and scalp.
-
This question is part of the following fields:
- Dermatology
-
-
Question 29
Incorrect
-
A 3-year-old girl presents to A&E following a few days of being lethargic, having runny nose, sore throat, and fever. She has unceasing stridor and drooling of saliva while her body is inclined forward. What is the most important next step in her management?
Your Answer: Immediate bronchoscopy
Correct Answer: Call ENT specialist
Explanation:A consultation with an ENT is required to establish the reason for the child’s drooling and stridor indicating and obstructive process. Enlarged tonsils and adenoids should be checked.
-
This question is part of the following fields:
- ENT
-
-
Question 30
Incorrect
-
A woman gives birth to a baby at 36 weeks of gestation through spontaneous, vaginal delivery. She had rupture of membranes 30 hours before birth, however looked healthy and did not receive antibiotics. On admission, doctors obtained a vaginal swab. Which of the following is the most appropriate management for the baby?
Your Answer: Await result of vaginal swab and treat the baby according to this
Correct Answer: Perform an infection screen and treat with intravenous antibiotics for at least 48 hours pending results
Explanation:Doctors must perform an infection screen and treat with intravenous antibiotics for at least 48 hours pending results to prevent neonatal sepsis. Risk factors for neonatal sepsis include rupture of the membranes. Risk factors for neonatal sepsis include rupture of membranes greater than 12–24 hours, intrapartum maternal pyrexia (> 38°C), fetal tachycardia, chorioamnionitis, pre-term birth and maternal colonisation with group B Streptococcus. In this case there are two risk factors: prolonged rupture of membranes, and pre-term birth.
-
This question is part of the following fields:
- Neonatology
-
00
Correct
00
Incorrect
00
:
00
:
00
Session Time
00
:
00
Average Question Time (
Mins)