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  • Question 1 - A 65-year old patient with altered bowl movement experienced the worsening of...

    Incorrect

    • A 65-year old patient with altered bowl movement experienced the worsening of shortness of breath and exertional chest pains over the course of 8 weeks. Examination shows pallor and jugular venous distension. Furthermore, a test of the stool for occult blood is positive. Laboratory studies show:

      Haemoglobin 7.4 g/dl

      Mean corpuscular volume 70 fl Leukocyte count 5400/mm3

      Platelet count 580 000/mm3 Erythrocyte sedimentation 33 mm/h

      A blood smear shows hypochromic, microcytic RBCs with moderate poikilocytosis. Which of the following is the most likely diagnosis?

      Your Answer: Amyloidosis

      Correct Answer: Iron deficiency anaemia

      Explanation:

      Iron deficiency anaemia is the most common type of anaemia. It can occur due to deficiency of iron due to decreased intake or due to faulty absorption. An MCV less than 80 will indicated iron deficiency anaemia. On the smear the RBC will be microcytic hypochromic and will also show piokilocytosis. iron profiles tests are important to make a diagnosis. Clinically the patient will be pale and lethargic.

    • This question is part of the following fields:

      • General
      • Physiology
      50.1
      Seconds
  • Question 2 - A 7-year-old boy is diagnosed with metabolic acidosis as a result of severe...

    Correct

    • A 7-year-old boy is diagnosed with metabolic acidosis as a result of severe dehydration. Which of the following conditions is most likely to cause severe dehydration and metabolic acidosis?

      Your Answer: Severe diarrhoea

      Explanation:

      Diarrhoea is defined as having three or more loose or liquid stools per day, or as having more stools than is normal for that person. Severe diarrhoea, causing fluid loss and loss of bicarbonate, will result in marked dehydration and metabolic acidosis.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Physiology
      20
      Seconds
  • Question 3 - Basal Metabolic Rate (BMR) will most likely be reduced by which of the...

    Correct

    • Basal Metabolic Rate (BMR) will most likely be reduced by which of the following?

      Your Answer: Decrease in body temperature

      Explanation:

      The basal metabolic rate (BMR) is defined as the rate of calorie consumption after an overnight fast, in the absence of any muscular activity, with the patient in a restful state. Various factors affect the BMR including weight, body surface area and age. The BMR is 30 kcal/m2 per hour at birth; at age 2, the rate is 57 kcal/m2 per hour; and at age 20, 41 kcal/m2 per hour. After this, the BMR decreases by 10% between 20-60 years of age. Women are known to have a 10% lower BMR than men (due to higher fat content). A one-degree change in body temperature leads to a 10% change in BMR in the same direction. However, shivering and increasing ambient temperature brings about a rise in BMR, and so does stress, physical activity, caffeine, theophylline and hyperthyroidism. Also, thermogenesis induced by diet results in increased metabolic rate and hence, BMR should be ideally measured after overnight fasting.

    • This question is part of the following fields:

      • Gastroenterology
      • Physiology
      11.3
      Seconds
  • Question 4 - Evaluation of a 60-year old gentleman, who has been a coal miner all...

    Incorrect

    • Evaluation of a 60-year old gentleman, who has been a coal miner all his life and is suspected to have pulmonary fibrosis reveals the following: FEV1 of 75% (normal > 65%), arterial oxygen saturation 92%, alveolar ventilation 6000 ml/min at a tidal volume of 600 ml and a breathing rate of 12 breaths/min. There are also pathological changes in lung compliance and residual volume. Calculate his anatomical dead space.

      Your Answer: 150 ml

      Correct Answer: 100 ml

      Explanation:

      Dead space refers to inhaled air that does not take part in gas exchange. Because of this dead space, taking deep breaths slowly is more effective for gas exchange than taking quick, shallow breaths where a large proportion is dead space. Use of a snorkel by a diver increases the dead space marginally. Anatomical dead space refers to the gas in conducting areas such as mouth and trachea, and is roughly 150 ml (2.2 ml/kg body weight). This corresponds to a third of the tidal volume (400-500 ml). It can be measured by Fowler’s method, a nitrogen wash-out technique. It is posture-dependent and increases with increase in tidal volume. Physiological dead space is equal to the anatomical dead space plus the alveolar dead space, where alveolar dead space is the area in the alveoli where no effective exchange takes place due to poor blood flow in capillaries. This physiological dead space is very small normally (< 5 ml) but can increase in lung diseases. Physiological dead space can be measured by Bohr’s method. Total ventilation per minute (minute ventilation) is given by the product of tidal volume and the breathing rate. Here, the total ventilation is 600 ml times 12 breaths/min = 7200 ml/min. The problem mentions alveolar ventilation to be 6000 ml/min. Thus, the difference between the alveolar ventilation and total ventilation is 7200 – 6000 ml/min = 1200 ml/min, or 100 ml per breath at 12 breaths per min. This 100 ml is the dead space volume.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      45.8
      Seconds
  • Question 5 - A syndrome responsible for failure to absorb vitamin B12 from the GIT is...

    Correct

    • A syndrome responsible for failure to absorb vitamin B12 from the GIT is called?

      Your Answer: Pernicious anaemia

      Explanation:

      Pernicious anaemia is a type of autoimmune disease in which antibodies form against the parietal cells or intrinsic factor. Intrinsic factor is required for the absorption of vitamin B12. Blood testing typically shows a macrocytic, normochromic anaemia and low levels of serum vitamin B12. A Schilling test can then be used to distinguish between pernicious anaemia, vitamin B12 malabsorption and vitamin B12 deficiency. Symptoms include shortness of breath, pallor and diarrhoea etc.

    • This question is part of the following fields:

      • General
      • Physiology
      13.2
      Seconds
  • Question 6 - A 50 year old man on warfarin therapy following insertion of a pacemaker...

    Incorrect

    • A 50 year old man on warfarin therapy following insertion of a pacemaker presented with epistaxis. Which of the following is true regarding blood coagulation?

      Your Answer: von Willebrand factor suppresses platelet adhesion

      Correct Answer: Patients with haemophilia A usually have a normal bleeding time

      Explanation:

      A prolonged bleeding time is seen in platelet disorders like thrombocytopenia. Patients with haemophilia A or B have a prolonged PTT but not a prolonged bleeding time.

      Ca2+ is necessary for coagulation.

      von Willebrand factor is an important part of the factor VIII complex and promotes platelet adhesion and aggregation.

      DIC results in depleted coagulation factors and accumulation of fibrin.

    • This question is part of the following fields:

      • General
      • Physiology
      22.6
      Seconds
  • Question 7 - Which of the following conditions is characterized by generalised oedema due to effusion...

    Correct

    • Which of the following conditions is characterized by generalised oedema due to effusion of fluid into the extracellular space?

      Your Answer: Anasarca

      Explanation:

      Anasarca (or ‘generalised oedema’) is a condition characterised by widespread swelling of the skin due to effusion of fluid into the extracellular space. It is usually caused by liver failure (cirrhosis of the liver), renal failure/disease, right-sided heart failure, as well as severe malnutrition/protein deficiency.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Physiology
      8.5
      Seconds
  • Question 8 - Renin is secreted by pericytes in the vicinity of the afferent arterioles of the...

    Correct

    • Renin is secreted by pericytes in the vicinity of the afferent arterioles of the kidney from the juxtaglomerular cells. Plasma renin levels are decreased in patients with:

      Your Answer: Primary aldosteronism

      Explanation:

      Primary aldosteronism, also known as primary hyperaldosteronism or Conn’s syndrome, is excess production of the hormone aldosterone by the adrenal glands resulting in low renin levels. Most patients with primary aldosteronism (Conn’s syndrome) have an adrenal adenoma. The increased plasma aldosterone concentration leads to increased renal Na+ reabsorption, which results in plasma volume expansion. The increase in plasma volume suppresses renin release from the juxtaglomerular apparatus and these patients usually have low plasma renin levels. Salt restriction and upright posture decrease renal perfusion pressure and therefore increases renin release from the juxtaglomerular apparatus. Secondary aldosteronism is due to elevated renin levels and may be caused by heart failure or renal artery stenosis.

    • This question is part of the following fields:

      • Physiology
      • Renal
      15.4
      Seconds
  • Question 9 - A 50 year old man was admitted to the surgical ICU following a...

    Incorrect

    • A 50 year old man was admitted to the surgical ICU following a hemicolectomy for carcinoma of the caecum. A full blood count revealed: haematocrit = 30%, erythrocytes = 4 × 106/μ, haemoglobin level = 8 g/dl. To determine the likely cause of his anaemia, red blood cell indices were calculated. Which RBC indices are correct?

      Your Answer: MCHC = reticulocyte count/ haemoglobin conc.

      Correct Answer: MCHC = haemoglobin concentration/haematocrit

      Explanation:

      Mean corpuscular haemoglobin concentration (MCHC) is calculated simply by dividing the haemoglobin concentration (8 g/dl) by the haematocrit (0.3). The normal range is 31–36 g/dl. This patient has a hypochromic anaemia (MCHC = 8/0.3 = 26.7 g/dl). Dividing the haemoglobin concentration × 10 by erythrocyte number yields mean corpuscular haemoglobin (MCH). Normal range is 25.4–34.6 pg/cell and this patient has a significantly reduced cellular haemoglobin content (MCH = 8 × 10/4 = 20 pg/cell). Mean corpuscular volume (MCV) is calculated by dividing haematocrit × 1000 by erythrocyte number (4 × 106/μl). Normal range is 80–100 fl and this patient has a microcytic anaemia (MCV = 0.3 × 1000/4 = 75 fl). Microcytic, hypochromic anaemia is characteristic for iron-deficiency.

    • This question is part of the following fields:

      • General
      • Physiology
      109.9
      Seconds
  • Question 10 - In the kidney, the macula densa is an area of closely packed specialized cells lining the wall of...

    Incorrect

    • In the kidney, the macula densa is an area of closely packed specialized cells lining the wall of the:

      Your Answer: Juxtaglomerular cells

      Correct Answer: Distal convoluted tubule

      Explanation:

      In the kidney, the macula densa is an area of closely packed specialised cells lining the region of the distal convoluted tubule (DCT) lying next to the glomerular vascular pole. The cells of the macula densa are sensitive to the ionic content and water volume of the fluid in the DCT, producing signals that promote renin secretion by other cells of the juxtaglomerular apparatus.

    • This question is part of the following fields:

      • Physiology
      • Renal
      21.5
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

General (1/4) 25%
Physiology (5/10) 50%
Fluids & Electrolytes (2/2) 100%
Gastroenterology (1/1) 100%
Respiratory (0/1) 0%
Renal (1/2) 50%
Passmed