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Question 1
Incorrect
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A 23-year-old man who is currently on fluoxetine for depression was anaesthetized two hours ago for knee arthroscopy. He seems agitated, confused, with a heart rate of 120 beats per minute, a temperature of 38.2oC, and developed difficulty moving his limbs.
He is on paracetamol and tramadol for analgesia. Which of the following is the most likely cause for his condition?Your Answer: Residual anaesthetic effects
Correct Answer: Tramadol
Explanation: -
This question is part of the following fields:
- Pharmacology
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Question 2
Correct
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A 49-year-old female has presented to her physician with complaints of a lump in her groin area. The lump is painless and is more prominent in coughing.
On examination, the lump's location is inferior and lateral to the pubic tubercle. This points towards the diagnosis of femoral hernia, where part of her intestines has entered the femoral canal, causing a bulge in the femoral triangle. The femoral triangle is an anatomical region in the upper thigh.
Name the structures found in the femoral triangle, laterally to medially.Your Answer: Femoral nerve, femoral artery, femoral vein, empty space, lymphatics
Explanation:The femoral triangle is a wedge-shaped area found within the superomedial aspect of the anterior thigh. It is a passageway for structures to leave and enter the anterior thigh.
Superior: Inguinal ligament
Medial: Adductor longus
Lateral: Sartorius
Floor: Iliopsoas, adductor longus and pectineusThe contents include: (medial to lateral)
Femoral vein
Femoral artery-pulse palpated at the mid inguinal point
Femoral nerve
Deep and superficial inguinal lymph nodes
Lateral cutaneous nerve
Great saphenous vein
Femoral branch of the genitofemoral nerve -
This question is part of the following fields:
- Anatomy
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Question 3
Incorrect
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Which of these statements regarding the basilar artery and its branches is not true?
Your Answer:
Correct Answer: The posterior inferior cerebellar artery is the largest of the cerebellar arteries arising from the basilar artery
Explanation:The posterior inferior cerebellar artery is the largest branch arising from the distal portion of the vertebral artery which forms the basilar artery. It is one of the arteries responsible for providing blood supply to the brain’s cerebellum.
The labyrinthine artery (auditory artery) is a long and slender artery which arises from the basilar artery and runs alongside the facial and vestibulocochlear nerves into the internal auditory meatus.
The posterior cerebellar artery is one of two cerebral arteries supplying the occipital lobe with oxygenated blood. It is usually bigger than the superior cerebellar artery. It is separated from the vessel near its origin by the oculomotor nerve.
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This question is part of the following fields:
- Anatomy
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Question 4
Incorrect
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A 55-year-old man has been diagnosed with transitional cell carcinoma involving the ureter. He is due to undergo a left nephroureterectomy.
Which structure has no relation to the left ureter's anatomy?Your Answer:
Correct Answer: Round ligament of the uterus
Explanation:The ureter starts from the hilum of the kidney and has different relations with structures along its journey to the bladder.
It runs anterior to the psoas major muscle.
The testicular vessels (males) or the ovarian vessels (females) cross in front of the ureter.
The ureter passes in front of the common iliac artery where it bifurcates into the internal and external iliac arteries.
The ureter passes medial to the branches of the internal iliac vessel downwards and forwards to towards the bladder.
In males, the ductus deferens crosses the pelvic ureter medially.
In females. the ureter passes through the base of the broad ligament
In females, the pelvic part initially has the same relations as in males but, anterior to the internal iliac artery, it is immediately behind the ovary, forming the posterior boundary of the ovarian fossa. It is in extraperitoneal connective tissue in the inferomedial part of the broad ligament of the uterus. In the broad ligament, the uterine artery is anterosuperior to the ureter for approximately 2.5 cm and then crosses to its medial side to ascend alongside the uterus. The ureter turns forwards slightly above the lateral vaginal fornix and is, generally, 2 cm lateral to the supravaginal part of the uterine cervix in this location. It then inclines medially to reach the bladder. -
This question is part of the following fields:
- Anatomy
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Question 5
Incorrect
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Which of the following factors significantly increases the risk of hepatotoxicity and fulminant hepatic failure in halothane administration?
Your Answer:
Correct Answer: Multiple exposure
Explanation:Hepatotoxicity due to halothane administration is relatively common and is a major factor in its rapidly declining use. Type 1 hepatotoxicity has an incidence of 20% to 30%. A comprehensive report in 1969 demonstrated an incidence of type 2 hepatotoxicity (hepatitis) of 1 case per 6000 to 20000 cases, with fatal cases occurring approximately once in 35000 patients following a single exposure to the anaesthetic. This incidence of fatal cases increases to approximately 1 in 1000 patients following multiple exposures. Following this study was a large-scale review in the United Kingdom, which showed similar results. To put this into perspective, there is only a single case of hepatotoxicity confirmed after the administration of desflurane and 2 cases per 1 million after enflurane. By the 1970s, halothane was the most common cause of drug-induced liver failure.
Halothane-induced hepatotoxicity has a female to male ratio of two to one. Younger patients are less likely to be affected; 80% of the cases are typically in patients 40 years or older. Other risk factors include obesity and underlying liver dysfunction. Medications such as phenobarbital, alcohol, and isoniazid may play a role in affecting CYP2E1 metabolism, increasing one’s risk.
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This question is part of the following fields:
- Pharmacology
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Question 6
Incorrect
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A laser is a device that stimulates atoms or molecules to emit light at particular wavelengths and amplifies that light, typically producing a very narrow beam of radiation. This can be of visible, infrared, or ultraviolet wavelengths. They have been widely utilized in theatre environment.
Which of the following safety measures is most likely to reduce chances of eye injury to the theatre personnel?Your Answer:
Correct Answer: Wearing laser protective goggles
Explanation:Eye damage is the most common potential hazard associated with laser energy. Everyone in the laser treatment room has the risk of eye exposure when working with a Class 3b or Class 4 healthcare laser system, and damage to various structures in the eye depending on wavelength of the laser if they are unprotected.
Red and near-infrared light (400-1400 nm) has very high penetration power. The light causes painless burns on the retina after it is absorbed by melanin in the pigment epithelium just behind the photoreceptors.
Infrared radiation (IR), or infrared light (>1060 nm), is a type of radiant energy that’s invisible to human eyes and hence won’t elicit the protective blink.
Ultraviolet light (<400 nm) is also a form of electromagnetic radiation which is can penetrate the cornea and be absorbed by the iris or the pupil and cause burn injuries or cataract occur due to irreversible photochemical retinal damage. Safety eyewear is the best method of providing eye protection and are designed to absorb light specific to the laser being used. Laser protective eyewear (LPE) includes glasses or goggles of proper optical density (OD). The lenses should not be glass or plastic. The LPE should withstand direct and diffuse scattered laser beams. The laser protection supervisor (LPS) or LSO is an individual who is responsible for any clinical area in which lasers are used. They are expected to have a certain level of equipment and determine what control measures are appropriate, for each individual system, but their presence does not guarantee the chances of having an eye injury. Class 1 lasers are generally safe under every conceivable condition and is not likely to cause any eye damage. Class 3b or Class 4 medical laser systems are utilized in healthcare which have their own safety precautions. Polarized spectacles can make your eyes more comfortable by eliminated glare, however, they will not be able to offer any protection against wavelengths at which laser act.
Using short bursts to reduce energy is also not correct as it would still be harmful to eye. -
This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 7
Incorrect
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A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a 57-year-old woman. Her vision is causing her problems.
A macroadenoma compressing the optic chiasm is visible on MRI.
What is the most likely visual field defect to be discovered during an examination?Your Answer:
Correct Answer: Bitemporal hemianopia
Explanation:The pituitary gland plays a crucial role in the neuro-endocrine axis. It is located at the base of the skull in the sella turcica of the sphenoid bone. It is connected superiorly to the hypothalamus, third ventricle, and visual pathways, and laterally to the cavernous sinuses, internal carotid arteries, and cranial nerves III, IV, V, and VI.
Pituitary tumours make up about 10-15% of all intracranial tumours. The majority of adenomas are benign. Over-secretion of pituitary hormones (most commonly prolactin, growth hormone, or ACTH), under-secretion of hormones, or localised or generalised pressure effects can all cause symptoms.
Compression of the optic chiasm can result in visual field defects, the most common of which is bitemporal hemianopia. This is caused by compression of the nasal retinal fibres, which carry visual impulses from temporal vision across the optic chiasm to the contralateral sides before continuing to the optic tracts.
The interruption of the visual pathways distal to the optic chiasm causes a homonymous visual field defect. The loss of the right or left halves of each eye’s visual field is referred to as homonymous hemianopia. It’s usually caused by a middle or posterior cerebral artery territory stroke that affects the occipital lobe’s optic radiation or visual cortex.
Binasal hemianopia is a condition in which vision is lost in the inner half of both eyes (nasal or medial). It’s caused by compression of the temporal visual pathways, which don’t cross at the optic chiasm and instead continue to the ipsilateral optic tracts. Binasal hemianopia is a rare complication caused by the internal carotid artery impinging on the temporal (lateral) visual fibres.
A monocular visual loss (that is, loss of vision in only one eye) can be caused by a variety of factors, but if caused by nerve damage, the damage would be proximal to the optic chiasm on the ipsilateral side.
A central scotoma is another name for central visual field loss. Every normal mammalian eye has a scotoma, also known as a blind spot, in its field of vision. The optic disc is a region of the retina that lacks photoreceptor cells and is where the retinal ganglion cell axons that make up the optic nerve exit the retina. When both eyes are open, visual signals that are absent in one eye’s blind spot are provided for the other eye by the opposite visual cortex, even if the other eye is closed.
Scotomata can be caused by a variety of factors, including demyelinating disease such as multiple sclerosis, damage to nerve fibre layer in the retina, methyl alcohol, ethambutol, quinine, nutritional deficiencies, and vascular blockages either in the retina or in the optic nerve.
Bilateral scotoma can occur when a pituitary tumour compresses the optic chiasm, causing a bitemporal paracentral scotoma, which then spreads out to the periphery, causing bitemporal hemianopsia. A central scotoma in a pregnant woman could be a sign of severe pre-eclampsia.
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This question is part of the following fields:
- Pathophysiology
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Question 8
Incorrect
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While administering a general anaesthetic to a 65-year-old man booked for a hip hemiarthroplasty, with a weight 70 kg, and an ASA 1 score, you give 1 g of paracetamol IV but notice that he had received the same dose on the ward one hour prior.
What is the most appropriate subsequent management of this patient?Your Answer:
Correct Answer: Do nothing and give the next doses of paracetamol at standard 6 hour intervals
Explanation:After ingestion of more than 150 mg/kg paracetamol within 24 hours, hepatotoxicity can occur but can also develop rarely after ingestion of doses as low as 75 mg/kg within 24 hours. Hepatocellular damage will not occur in this patient and therefore no need to engage management pathway for paracetamol overdose. If his weight was <33 kg or he already had a history of impaired liver function, then the management would bde different. Subsequent post-operative doses will be a standard dose of 1 g 6 hourly. This is a drug administration error and should be reported as an incident even though the patient will not be harmed.
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This question is part of the following fields:
- Pharmacology
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Question 9
Incorrect
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A 55-year-old businesswoman presents to the emergency department complaining of shortness of breath and pleuritic chest pain. Her work requires her to travel internationally frequently. The consultant makes a diagnosis and treats her.
Now, the consultant recommends placing a filter that will prevent future incidents. A needle is placed into the femoral vein and passed up into the abdomen to insert the filter.
What is true regarding the organ where the filter is placed for this patient's condition?Your Answer:
Correct Answer: It is located posteriorly to the peritoneum
Explanation:The patient likely suffers from pulmonary embolism due to her history of frequent international travels. A filter is placed in the inferior vena cava to decrease the risk of future episodes of pulmonary embolism. The IVC filter is a small, wiry device that can catch blood clots and stop them from going into the heart and lungs. Your IVC is a major vessel that brings deoxygenated blood from the lower body to the heart, from where it is pumped into the lungs.
The filter is placed via a thin catheter inserted into the femoral vein in the groin. The catheter is gently moved up into your IVC, and a filter is introduced.
The IVC is a retroperitoneal organ.
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This question is part of the following fields:
- Anatomy
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Question 10
Incorrect
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One of the following sets of arterial blood gases best demonstrates compensated respiratory acidosis?
Your Answer:
Correct Answer: pH=7.36, PaCO2=8.5kPa, PaO2=7.5kPa, HCO3- = 43mmol/L
Explanation:pH=7.36, PaCO2=8.5kPa, PaO2=7.5kPa, HCO3- = 43mmol/L is the correct answer.
Since the pH is the lower limit of normal, it is compensated despite a raised PaCO2. Retention of bicarbonate ions by the renal system suggests this process is chronic.
pH=7.24, PaCO2=3.5kPa, PaO2=8.5kPa, HCO3- =18mmol/L represents an acute uncompensated metabolic acidosis
The remaining stems are degrees of uncompensated respiratory acidosis and therefore incorrect.
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This question is part of the following fields:
- Pathophysiology
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Question 11
Incorrect
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A 40-year old female comes to the GP's office with unexplained weight gain, cold intolerance and fatigue. Her thyroid function tests are performed as there is a suspicion of hypothyroidism. A negative feedback mechanism is incorporated in the control of thyroid hormone release. All of choices below are also controlled by a negative feedback loop except:
Your Answer:
Correct Answer: Clotting cascade
Explanation:The correct answer is the clotting cascade, which occurs via a positive feedback mechanism. As clotting factors are attracted to a site, their presence attracts further clotting factors. This continues until a functioning clot is formed.
This patient has presented with symptoms of hypothyroidism and symptoms include weight gain, lethargy, cold intolerance, dry skin, coarse hair and constipation. It can be treated by replacing the missing thyroid hormone with levothyroxine which is a synthetic version of thyroxine (T4).
Serum carbon dioxide (CO2) is controlled via a negative feedback mechanism as well. Chemoreceptors can detect when the serum CO2 is high, and send an impulse to the respiratory centre of the brain to increase the respiratory rate. As a result, more CO2 is exhaled which lowers the serum concentration.
Cortisol is also released according to a negative feedback mechanism. Cortisol acts on both the hypothalamus and the anterior pituitary. Its action serve to decrease the formation of corticotrophin releasing hormone (CRH) and adrenocorticotropic hormone (ACTH), respectively. CRH acts on the anterior pituitary to release ACTH. This then acts on the adrenal gland to cause the release of cortisol. Thus, inhibition of CRH and ACTH formation results in high levels of cortisol which inhibit its further release.
Blood pressure (BP) is controlled via a negative feedback mechanism. Low BP results in renin-angiotensin-aldosterone system (RAAS) activation. This leads to vasoconstriction and retention of salt and water which increased BP.
Blood sugar is controlled via a negative feedback mechanism. A rise in blood sugar causes insulin to be released. Insulin acts to transport glucose into the cell which lowers blood sugar. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 12
Incorrect
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The following statements are about chronic obstructive pulmonary disease (COPD). Which is true?
Your Answer:
Correct Answer: Inhaled corticosteroid usage slows the decline in health status
Explanation:Chronic obstructive pulmonary disease (COPD) is an obstructive, inflammatory lung condition. It encompasses symptoms of emphysema, chronic bronchitis and asthma.
Inhaling high dose steroids are prescribed to treat COPD. They are effective at reducing symptoms and improving lung function. They also work to reduce the number of hospitalisations by decreasing the number of acute exacerbation events. Despite providing effective symptom relief, it cannot slow down the decline of FEV1 as COPD is an irreversible condition.
COPD reduces the FEV1 measurements, as well as the FEV1/FVC ratio.
Breathlessness is a major COPD symptom and can occur at any point in the disease progression, including at an FEV1 >50%.
FEV1 is used in COPD staging, and it is classed as follows:
>80%: Mild or stage I
50 – 79%: Moderate or stage II
30 – 49%: Severe or stage III
<30%: Very severe or stage IV
Patients with mild COPD are usually able to manage their condition on their own, however once the disease progresses to moderate, more GP visits are required, with those in the severe category requiring frequent hospitalisation.Asthma is correlated to an increase in transfer factor. COPD (emphysema) is correlated to a decreased transfer factor.
COPD predisposes to eventual pulmonary hypertension as a result of an increase in pulmonary vascular resistance.
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This question is part of the following fields:
- Pathophysiology
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Question 13
Incorrect
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When compared to unipolar diathermy, which of the following is more specific to bipolar diathermy?
Your Answer:
Correct Answer: Has a power output of up to 140 joules per second
Explanation:Electrocautery, also known as diathermy, is a technique for coagulation, tissue cutting, and fulguration that uses a high-frequency current to generate heat (cell destruction from dehydration).
The two electrodes in bipolar diathermy are the tips of forceps, and current passes between the tips rather than through the patient. Bipolar diathermy’s power output (40-140 W) is lower than unipolar diathermy’s typical output (400 W). There is no earthing in the bipolar circuit.
A cutting electrode and a indifferent electrode in the form of a metal plate are used in unipolar diathermy. The high-frequency current completes a circuit by passing through the patient from the active electrode to the metal plate. When used correctly, the current density at the indifferent electrode is low, and the patient is unlikely to be burned. Between the patient plate and the earth is placed an isolating capacitor. This has a low impedance to a high frequency current, such as diathermy current, and is used in modern diathermy machines. The capacitor has a high impedance to current at 50 Hz, which protects the patient from electrical shock.
High frequency currents (500 KHz – 1 MHz) are used in both unipolar and bipolar diathermy, which can cause tissue damage and interfere with pacemaker function (less so with bipolar diathermy).
The effect of diathermy is determined by the current density and waveform employed. The current is a pulsed square wave pattern in coagulation mode and a continuous square wave pattern in cutting mode.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 14
Incorrect
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A current flows through a simple electric circuit.
Which of the following electrical component configurations has the greatest potential difference?Your Answer:
Correct Answer: Two 5 ohm resistors in series with a passing current of 10 ampere
Explanation: -
This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 15
Incorrect
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What is the primary purpose of funnel plots?
Your Answer:
Correct Answer: Demonstrate the existence of publication bias in meta-analyses
Explanation:Funnel plot is essentially a scatterplot of the effect of treatment against a particular measure of study precision. Its primal purpose is to serve as a visual aid and help in detection of bias or systematic heterogenity.
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This question is part of the following fields:
- Statistical Methods
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Question 16
Incorrect
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Which of the following options will cause an artificial increase in pulse oximeter (SpO2) readings?
Your Answer:
Correct Answer: Heavy smoker
Explanation:A pulse oximeter is a piece of medical equipment used as a non-invasive method of measuring the oxygen saturation of blood.
It works by measuring the ratio of absorption of red and infrared light in a section of blood flow, as red light is largely absorbed by deoxygenated blood, and infrared light is largely absorbed by oxygenated blood.
Pulse oximetry relies on photoplethysmography (PPG) waveforms. The oximeter has 2 sides, with different functions. One side houses light-emitting diodes which are responsible for transmitting 2 light wavelengths, 660nm for red light and 940nm for near infrared light. The other side is a photodetector. The light emitted travels through the body and the amount that is not absorbed is measured by the photodetector.
Smokers often have increased levels of carboxy haemoglobin (COHb). This leads to artificial increases in pulse oximeter readings as it is unable to differentiate between COHb and oxyhaemoglobin (O2HB) as they both absorb red light at 660nm. Every 1% increase of circulating carboxyhaemoglobin, results in a correlative 1% increase in oximeter readings.
Prilocaine toxicity will cause an artificial decrease in oximeter readings. This is because prilocaine metabolites cause methemoglobinemia (MetHB), which are dysfunctional haemoglobins unable to properly transport oxygen. In this case, a laboratory multiwavelength co-oximeter is recommended for a more accurate reading.
Anaemia will not affect oximeter readings as long as haemoglobins in the blood are normal.
Sickle cell disease does not affect oximeter readings despite its ability to cause hypoxia and shift the oxygen dissociation curve to the right.
Brown-red fingernail polish will cause an underestimation of pulse oximeter readings.
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This question is part of the following fields:
- Clinical Measurement
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Question 17
Incorrect
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A 26-year old male patient was admitted to the surgery department for appendectomy. Medical history revealed that he has major depressive disorder and was on Phenelzine. Aside from abdominal pain, initial assessment was unremarkable. However, thirty minutes after, the patient was referred to you for generalized seizures. He was given an analgesic and it was noted that, during the first 15 minutes of administration, he became anxious, with profuse sweating, which later developed into seizures. Upon physical examination, he was febrile at 38.3°C.
Which of the following statements is the best explanation for the patient's symptoms?Your Answer:
Correct Answer: Drug interaction with pethidine
Explanation:The clinical picture best describes a probable drug interaction with pethidine.
Phenelzine, a monoamine oxidase (MAO) inhibitor, when given with pethidine, an opioid analgesic, may lead to episodes of hypertension, rigidity, excitation, hyperpyrexia, seizures, coma and death. Studies have shown that pethidine reacts more significantly with MAO inhibitors than morphine.
When pethidine is metabolised to normeperidine, it acts as a serotonin reuptake inhibitor and cause an increase in serotonin levels in the brain. MAO inhibitors can also lead to elevated levels of serotonin because of its mechanism of action by inhibiting the enzyme monoamine oxidase that degrades serotonin.
The excess serotonin levels may lead to serotonin syndrome, of which some of the common precipitating drugs are selective serotonin reuptake inhibitors, MAO inhibitors, tricyclic antidepressants, meperidine, and St. John’s Wort. Onset of symptoms is within hours, which includes fever, agitation, tremor, clonus, hyperreflexia and diaphoresis.
Drug interaction between phenelzine and paracetamol do not commonly precipitate serotonin syndrome.
Neuroleptic malignant syndrome is due to dopamine antagonism, precipitated commonly by antipsychotics. Its onset of symptoms occur in 1 to 3 days, and is characterized by fever, encephalopathy, unstable vitals signs, elevated CPK, and rigidity.
Altered mental status is the most common manifestation of sepsis-associated encephalopathy. Patient also exhibit confusional states and inappropriate behaviour. In some cases, this may lead to coma and death.
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This question is part of the following fields:
- Pharmacology
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Question 18
Incorrect
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Regarding the plateau phase of the cardiac potential, which electrolyte is the main determinant?
Your Answer:
Correct Answer: Ca2+
Explanation:The cardiac action potential has several phases which have different mechanisms of action as seen below:
Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
These channels automatically deactivate after a few msPhase 1: caused by early repolarisation and an efflux of potassium.
Phase 2: Plateau – caused by a slow influx of calcium.
Phase 3 – Final repolarisation – caused by an efflux of potassium.
Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potentialOf note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.
Different sites have different conduction velocities:
1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec2. AV node conduction – 0.05 m/sec
3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles
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This question is part of the following fields:
- Physiology
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Question 19
Incorrect
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Compared to the parasympathetic nervous system (PNS), the sympathetic nervous system (SNS) has:
Your Answer:
Correct Answer: Nicotinic receptors in pre and post ganglionic synapses
Explanation:With regards to the autonomic nervous system (ANS)
1. It is not under voluntary control
2. It uses reflex pathways and different to the somatic nervous system.
3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.With regards to the central nervous system (CNS)
1. There are myelinated preganglionic fibres which lead to the
ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.Most organs are under control of both systems although one system normally predominates.
The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.
There are short pre-ganglionic and long post ganglionic fibres.
Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.
There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.
Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.
The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.
The cranial outflow consists of
1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreasThe sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.
The PNS has long preganglionic and short post ganglionic fibres.
Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.Different types of these muscarinic receptors are present in different organs:
There are:
M1 = pupillary constriction, gastric acid secretion stimulation
M2 = inhibition of cardiac stimulation
M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
M4 = brain and adrenal medulla
M5 = brainThe lacrimal glands are solely under parasympathetic control.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 20
Incorrect
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At which of the following location is there no physiological oesophageal constriction?
Your Answer:
Correct Answer: Lower oesophageal sphincter
Explanation:The oesophagus is a muscular tube that connects the pharynx to the stomach. It begins at the lower border of the cricoid cartilage and C6 vertebra. It ends at T11.
The oesophagus has physiological constrictions at the following levels:
1. Cervical constriction: Pharyngo-oesophageal junction (15 cm from the incisor teeth) produced by the cricopharyngeal part of the inferior pharyngeal constrictor muscle
2. Thoracic constrictions:
i. where the oesophagus is first crossed by the arch of the aorta (22.5 cm from the incisor teeth)
ii. where the oesophagus is crossed by the left main bronchus (27.5 cm from the incisor teeth)
3. Diaphragmatic constriction: where the oesophagus passes through the oesophageal hiatus of the diaphragm (40 cm from the incisor teeth)Awareness of these constrictions is important for clinical purposes when it is required to pass instruments through the oesophagus into the stomach or when viewing radiographs of patients’ oesophagus.
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This question is part of the following fields:
- Anatomy
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Question 21
Incorrect
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After establishing a cardiopulmonary bypass, the right atrium is opened to repair the tricuspid valve.
Out of the following, which is NOT a part of the right atrium?Your Answer:
Correct Answer: Trabeculae carnae
Explanation:The right atrium receives blood supply from the SVC, IVC, and coronary sinus. It forms the right border of the heart.
The interior of the right atrium has 5 distinct features:
1. Sinus venarum – smooth, thin-walled posterior part of the right atrium where the SVC, IVC, and coronary sinus open
2. Musculi pectinati – an anterior rough, wall of pectinate muscles
3. Tricuspid valve orifice – the opening through which the right atrium empties blood into the right ventricle
4. Crista terminalis – separates the rough (musculi pectinati) from the smooth (sinus venarum) internally
5. Fossa ovalis – a thumbprint size depression in the interatrial septum which is a remnant of the oval foramen and its valve in the foetusThe trabeculae carneae are irregular muscular elevations that form the interior of the right ventricle.
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This question is part of the following fields:
- Anatomy
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Question 22
Incorrect
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What vessel is NOT considered a major branch of the descending thoracic aorta?
Your Answer:
Correct Answer: Inferior thyroid artery
Explanation:The descending thoracic aorta begins at the lower border of T4 near the midline as a continuation of the arch of the aorta. It descends and ends at the level of T12 at the aortic hiatus in the diaphragm, where it becomes the abdominal aorta.
The aorta gives off the following branches: (descending order)
1. Bronchial arteries
2. Mediastinal arteries
3. Oesophageal arteries
4. Pericardial arteries
5. Superior phrenic arteriesThe posterior intercostal arteries are branches that originate throughout the length of the posterior aspect of the descending thoracic aorta.
The inferior thyroid artery is usually derived from the thyrocervical trunk, a branch of the subclavian artery.
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This question is part of the following fields:
- Anatomy
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Question 23
Incorrect
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With respect to the peripheral nerve stimulators, which one is used to perform nerve blocking?
Your Answer:
Correct Answer:
Explanation:The nerve stimulators deliver a stimulus lasting for 1-2 milliseconds (not second) to perform nerve blockage.
There are just 2 leads (not 3); one for the skin and other for the needle.
Prior to the administration of the local anaesthesia, a current of 0.25 – 0.5 mA (not 1-2mA) at the frequency of 1-2 Hz is preferred.
If the needle tip is close to the nerve, muscular contraction could be possible at the lowest possible current.
Insulated needles have improved the block success rate, as the current is only conducting through needle tip.
Stimulus to the femoral nerve which is placed in the mid lingual line causes withdrawer of the quadriceps and knee extension, that’s the dancing patella ( not plantar flexion).
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 24
Incorrect
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What does therapeutic index in humans mean?
Your Answer:
Correct Answer: The TD50 divided by the ED50
Explanation:Therapeutic index is a measure which relates the dose of a drug required to produce a desired effect to that which produces an undesired effect.
In humans, it is usually defined as the ratio of the toxic dose for 50% of the population (TD50) to the minimum effective dose for 50% of the population (ED50) for some therapeutically relevant effect. In animal studies, the therapeutic index can be defined as the ratio of the median lethal dose (LD50) to the ED50.
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This question is part of the following fields:
- Pharmacology
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Question 25
Incorrect
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The phenomenon that the patients behaved in a different manner when they know that they are being observed is termed as?
Your Answer:
Correct Answer: Hawthorne effect
Explanation:Hawthorne effect explains the change in any behavioural aspect owing to the awareness that the person is being observed.
Simpson’s Paradox explains the association developed when the data from several groups is combined to form a single larger group.The remaining terms are made up.
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This question is part of the following fields:
- Statistical Methods
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Question 26
Incorrect
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Venepuncture is being performed on the basilic vein in the cubital fossa. At which of the following points does the basilic vein pass deep under the muscle?
Your Answer:
Correct Answer: Midway up the humerus
Explanation:The basilic vein is one of the primary veins that drain the upper limb, like the cephalic vein. It begins as the dorsal venous arch. The basilic vein originates from the ulnar side of the dorsal arch of the upper limb passes along the posteromedial aspect of the forearm, moving towards the anterior surface of the elbow.
The basilic vein pierces the deep fascia at the elbow and joins the venae commitantes of the brachial vein to form the axillary vein.
The basilic vein passes deep under the muscles as it moves midway up the humerus. At the lower border of the teres major muscle, the anterior and posterior circumflex humeral veins feed into it.
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This question is part of the following fields:
- Anatomy
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Question 27
Incorrect
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The whole water content of the body is calculated by multiplying body mass with 0.6. This water is diffused into distinct compartments.
Which fluid compartment can be measured indirectly?Your Answer:
Correct Answer: Intracellular volume
Explanation:The total body water content of a 70kg man is (70 × 0.6) = 42 litres. For a woman, the calculation is (70 × 0.55) = 38.5 litres.
For a man, it is subdivided into:
Extracellular fluid (ECF) = 14L (1/3)
Intracellular fluid (ICF) = 28L (2/3).The ECF volume is further divided into:
Interstitial fluid = 10.5 litres
Plasma = 3 litres
Transcellular fluid (CSF/synovial fluid) = 0.5 litres.Directly measured fluid compartments:
Heavy water (deuterium) can be used to measure total body water content, which is freely distributed.
Albumin labelled with a radioactive isotope or using a dye called Evans blue can be used to measure Plasma volume . They do not diffuse into red blood cells.
Radiolabelled (Cr-51) red blood cells can be used to measure total erythrocyte volume.
Inulin as the tracer can be used to measure ECF volume as it circulate freely in the interstitial and plasma volumes.Indirectly measured fluid compartments:
Total blood volume can be calculated with the level of haematocrit and the volume of total circulating red blood cells.
ICF volume can be calculated by subtracting ECF volume from total blood volume. -
This question is part of the following fields:
- Basic Physics
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Question 28
Incorrect
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A 68-year old female is brought to the Emergency Room for abdominal pain. Medical history revealed that she is on long-term warfarin therapy for deep vein thrombosis.
Upon further investigation, the patient is hypotensive at 80/60 mmHg, and an abdominal mass is palpable on the umbilical area. An initial diagnosis of ruptured abdominal aortic aneurysm (AAA) is made. Moreover, blood tests show an international normalised ratio (INR) of 4.2.
Which of the following products should be initially transfused or administered to the patient to reverse the anticoagulation?Your Answer:
Correct Answer: Prothrombin complex
Explanation:Warfarin prevents reductive metabolism of the inactive vitamin K epoxide back to its active hydroquinone form. Thus, warfarin inhibits the synthesis of vitamin K dependent clotting factors: X, IX, VII, II (prothrombin), and of the anticoagulants protein C and protein S. The therapeutic range for oral anticoagulant therapy is defined in terms of an international normalized ratio (INR). The INR is the prothrombin time ratio (patient prothrombin time/mean of normal prothrombin time for lab)ISI, where the ISI exponent refers to the International Sensitivity Index and is dependent on the specific reagents and instruments used for the determination. A prolonged INR is widely used as an indication of integrity of the coagulation system in liver disease and other disorders, it has been validated only in patients in steady state on chronic warfarin therapy.
Prothrombin complex concentrate (PCC) is used to replace congenital or acquired vitamin-K deficiency warfarin-induced anticoagulant effect, particularly in the emergent setting.
Intravenous vitamin K has a slower onset of action compared to PCC, but is useful for long term therapy.
Fresh frozen plasma (FFP) prepared from freshly donated blood is the usual source of the vitamin K-dependent factors and is the only source of factor V. The factors needed, however, are found in small quantities compared to PCC.
Cryoprecipitate is indicated for hypofibrinogenemia/dysfibrinogenemia, von Willebrand disease, haemophilia A, factor XIII deficiency, and management of bleeding related to thrombolytic therapy.
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This question is part of the following fields:
- Pathophysiology
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Question 29
Incorrect
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What can you see within the tunica media of a blood vessel on examination?
Your Answer:
Correct Answer: Smooth muscle
Explanation:The blood vessel well is divided into 3 parts, namely:
The tunica intima, which is the deepest layer. It contains endothelial cells separated by gap junctions
The tunica media, primarily consisting of the involuntary smooth muscle fibres, laid out in spiral layers with elastic fibres and connective tissue.
The tunica adventitia, which is the most superficial layer. It consists of the vasa vasorum, fibroblast and collagen.
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This question is part of the following fields:
- Anatomy
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Question 30
Incorrect
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A 46-year old man was taken to the emergency room due to slow, laboured breathing. A relative reported that he's maintained on codeine 60 mg, taken orally every 6 hours for severe pain from oesophageal cancer. His creatinine was elevated, and glomerular filtration rate was severely decreased at 27 ml/minute.
Given the scenario above, which of the metabolites of codeine is the culprit for his clinical findings?Your Answer:
Correct Answer: Morphine-6-glucuronide
Explanation:Accumulation of morphine-6-glucuronide is a risk factor for opioid toxicity during morphine treatment. Morphine is metabolized in the liver to morphine-6-glucuronide and morphine-3-glucuronide, both of which are excreted by the kidneys. In the setting of renal failure, these metabolites can accumulate, resulting in a lowering of the seizure threshold. However, it does not occur in all patients with renal insufficiency, which is the most common reason for accumulation of morphine-6-glucuronide; this suggests that other risk factors can contribute to morphine-6-glucuronide toxicity.
The active metabolites of codeine are morphine and the morphine metabolite morphine-6-glucuronide. The enzyme systems responsible for this metabolism are: CYP2D for codeine and UGT2B7 for morphine, codeine-6-gluronide, and morphine-6-glucuronide. Both of these systems are subject to genetic variation. Some patients are ultrarapid metabolizers of codeine and produce higher levels of morphine and active metabolites in a very short period of time after administration. These increased levels will produce increased side effects, especially drowsiness and central nervous system depression.
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This question is part of the following fields:
- Pharmacology
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