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  • Question 1 - Which of the following is true regarding Noradrenaline (Norepinephrine)? ...

    Incorrect

    • Which of the following is true regarding Noradrenaline (Norepinephrine)?

      Your Answer: Increases systolic but decreases diastolic blood pressure

      Correct Answer: Sympathomimetic effects work mainly through ?1 but also ? receptors

      Explanation:

      Noradrenaline acts as a sympathomimetic effect via alpha as well as a beta receptor. However, they have weak ?2 action.

      Natural catecholamines are Adrenaline, Noradrenaline, and Dopamine

    • This question is part of the following fields:

      • Pharmacology
      157.1
      Seconds
  • Question 2 - Prior to rapid sequence induction of anaesthesia, a man with a BMI of...

    Correct

    • Prior to rapid sequence induction of anaesthesia, a man with a BMI of 35 is pre-oxygenated.

      Which method of pre-oxygenation with a tight-fitting face mask is the most effective?

      Your Answer: Oxygen 6 litres per minute via a Mapleson A breathing system, with patient sitting up at 30 degrees breathing four vital capacity breaths

      Explanation:

      This patient is morbidly obese and has a high risk of developing hypoxia. This will be exacerbated by the patient’s supine position, as a result of:

      Functional residual capacity has been reduced (FRC)
      Increased closing capacity (CC)
      Reduced tidal volume due to increased airway resistance, decreased thoracic cage compliance, and decreased respiratory muscle strength and endurance
      Following induction of general anaesthesia, there is a tendency for atelectasis and increased O2 consumption due to the increased workload of respiratory muscles and the overall increase in metabolism.

      Pre-oxygenation with 100 percent oxygen via a tight-fitting mask can be done using either tidal volume breaths for three to five minutes or four vital capacity breaths in normal circumstances. In the head-up position, this patient is much more likely to be adequately pre-oxygenated, maximising the FRC and minimising the CC. In spontaneously breathing patients, the Mapleson A and circle systems are both effective, but the Mapleson D requires 160-200 ml/kg/minute to prevent rebreathing.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      89.3
      Seconds
  • Question 3 - A 63-year-old woman, is admitted into hospital. She has undergone a thoracoscopic sympathectomy.

    To...

    Incorrect

    • A 63-year-old woman, is admitted into hospital. She has undergone a thoracoscopic sympathectomy.

      To enable ease of access during surgery, her right arm has been abducted.

      On examination, immediately after surgery, she is noted to have lost the ability to abduct her right arm, with the presence a weak lateral rotation in the same arm. She has also lost sensation in the outer aspect of the lower deltoid area of the skin.

      Her symptoms are as a result of injury to a nerve during surgery. What nerve is it?

      Your Answer: Radial nerve

      Correct Answer: Axillary nerve

      Explanation:

      The axillary nerve arises from spinal roots C5-C6. It has both sensory and motor functions:

      Sensory: Provides innervation to the skin over the lower deltoid area

      Motor: Provides innervation to the teres minor (responsible for stabilisation of glenohumeral joint and external rotation of shoulder joint) and deltoid muscles (responsible for abduction of arms glenohumeral joint).

      Injury to the axillary nerve will result in the patient being unable to abduct the arm beyond 15 degrees and a loss of sensory feeling over lower deltoid area.

      These symptoms could also be a result of over-abduction of the arm (>90°) which would cause the head of the humerus to become dislocated.

    • This question is part of the following fields:

      • Pathophysiology
      478.4
      Seconds
  • Question 4 - In a normal healthy adult breathing 100 percent oxygen, which of the following...

    Incorrect

    • In a normal healthy adult breathing 100 percent oxygen, which of the following is the most likely cause of an alveolar-arterial (A-a) oxygen difference of 30 kPa?

      Your Answer: A diffusion defect in oxygen transport

      Correct Answer: Atelectasis

      Explanation:

      The ‘ideal’ alveolar PO2 minus arterial PO2 is the alveolar-arterial (A-a) oxygen difference.

      The ‘ideal’ alveolar PO2 is derived from the alveolar air equation and is the PO2 that the lung would have if there was no ventilation-perfusion (V/Q) inequality and it was exchanging gas at the same respiratory exchange ratio as real lung.

      The amount of oxygen in the blood is measured directly in the arteries.

      The A-a oxygen difference (or gradient) is a useful measure of shunt and V/Q mismatch, and it is less than 2 kPa in normal adults breathing air (15 mmHg). Because the shunt component is not corrected, the A-a difference increases when breathing 100 percent oxygen, and it can be up to 15 kPa (115 mmHg).

      An abnormally low or abnormally high V/Q ratio within the lung can cause an increased A-a difference, though the former is more common. Atelectasis, which results in a low V/Q ratio, is the most likely cause of an A-a difference in a healthy adult breathing 100 percent oxygen.

      Hypoventilation may cause an increase in alveolar (and thus arterial) CO2, lowering alveolar PO2 according to the alveolar air equation.

      The alveolar PO2 is also reduced at high altitude.

      Healthy people are unlikely to have a right-to-left shunt or an oxygen transport diffusion defect.

    • This question is part of the following fields:

      • Physiology
      96.6
      Seconds
  • Question 5 - A new study is being carried out on the measurement of a new...

    Incorrect

    • A new study is being carried out on the measurement of a new cardiovascular disease biomarker, and its applications in preoperative screening. The data for this study is expected to be normally distributed.

      Which of the following statements is true about normal distributions?

      Your Answer:

      Correct Answer: The mean, median and mode are the same value

      Explanation:

      The correct answer is the mean, median and mode of normally distributed data are the same value. This is as a result of the bell shaped curve which is equal on both sides.

      The bell-shape indicates that values around the mean are more frequent in occurrence than the values farther away.

      In a normal distribution:
      1) +/- one standard deviation of the mean accounts for 68% of the data.
      2) +/- two standard deviations of the mean accounts for 95% of the data.
      3) +/- three standard deviations of the mean accounts for 99.7% of the data.

    • This question is part of the following fields:

      • Statistical Methods
      0
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  • Question 6 - Buffers are solutions that resist a change in pH when protons are produced...

    Incorrect

    • Buffers are solutions that resist a change in pH when protons are produced or consumed. They consist of weak acids and their conjugate bases. Buffers are also present in our bodies, and they are known as physiologic buffers.

      Which of these is the most effective buffer in the blood?

      Your Answer:

      Correct Answer: Bicarbonate

      Explanation:

      The first line of defence against acid-base disorder is buffering. The blood mainly utilizes bicarbonate ion (HCO3-) for its buffering capacity (total of 53%, plasma and red blood cells combined).

      Strong acids, when acted upon by a buffer, release H+, which then combines to HCO3- and forms carbonic acid (H2CO3). When acted upon by the enzyme carbonic anhydrase, H2CO3 dissociates into H2O and CO.

      The rest are the percentage of utilization for the following buffers:
      Haemoglobin (by RBCs) – 35%
      Plasma proteins (by plasma) – 7%
      Organic phosphates (by RBCs) – 3%
      Inorganic phosphates (by plasma) – 2%

    • This question is part of the following fields:

      • Pharmacology
      0
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  • Question 7 - A 43-year-old patient was brought to the emergency department with a traumatic amputation...

    Incorrect

    • A 43-year-old patient was brought to the emergency department with a traumatic amputation of his leg at mid-thigh level. Resuscitation with 1 L gelofusine was done and four units of packed red blood cells were given before theatre. Thirty minutes following blood transfusion, the patient became flushed, breathless, hypotensive, develops haemoglobinuria, and had a fever of 38oC.

      Which one of the following correctly explains the patient signs and symptoms?

      Your Answer:

      Correct Answer: Activation of classic complement pathway

      Explanation:

      This may be the classical case of blood transfusion reaction due to ABO incompatibility.

      Here red cells are destroyed in the bloodstream with the release of haemoglobin in circulation (causing haemoglobinuria). Here, IgM or IgG anti-A or anti-B antibody can cause rapid activation of complement cascade usually the classical pathway. This is called intravascular haemolysis.

      There may be extravascular haemolysis by cells of the mononuclear phagocyte system situated in the liver and spleen. Extravascular red cell destruction can increase breakdown products of haemoglobin, such as bilirubin and urobilinogen.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 8 - A study was concerned with finding out the normal reference range of IgE...

    Incorrect

    • A study was concerned with finding out the normal reference range of IgE levels in adults was conducted. Presuming that the curve follows a normal distribution, what is the percentage of individuals having IgE levels greater than 2 standard deviations from mean?

      Your Answer:

      Correct Answer: 2.30%

      Explanation:

      Since the data is normally distributed, 95.4% of the values lie with in 2 standard deviations from mean. The rest of the 4.6% are distributed symmetrically outside of that range which means 2.3% of the values lie above 2 standard deviations of the mean.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 9 - The Control of Substances Hazardous to Health (COSHH) regulations recommend air supply rates...

    Incorrect

    • The Control of Substances Hazardous to Health (COSHH) regulations recommend air supply rates to specific environments. Which of the following statements is true?

      Your Answer:

      Correct Answer: Preparation rooms receive a volume of 0.1 m3 of air per second

      Explanation:

      Control of Substances Hazardous to Health (COSHH) was established by government under the Health and Safety at Work act in 1989. Their employers work on identification and management of those substances that are dangerous to health. The implications for anaesthetists include gas scavenging, equipment contamination and environmental safety. Adequate ventilation is required in areas where anaesthetic gases are present. The minimum air supply that is legally required in each specific area is: Operating theatres: 0.65 m3/second. Anaesthetic rooms: 0.15 m3/s. Preparation rooms: 0.1 m3/s. Recovery rooms need 15 air changes per hour

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 10 - Which of the following statement is true or false regarding to the respiratory...

    Incorrect

    • Which of the following statement is true or false regarding to the respiratory tract?

      Your Answer:

      Correct Answer: The sympathetic innervation of the bronchi is derived from T2 - T4

      Explanation:

      The diaphragm has three opening through which different structures pass from the thoracic cavity to the abdominal cavity:

      Inferior vena cava passes at the level of T8.

      Oesophagus, oesophageal vessels and vagi at T10.

      Aorta, thoracic duct and azygous vein through T12.

      Sympathetic trunk and pulmonary branches of vagus nerve form a posterior pulmonary plexus at the root of the lung. Fibres continue posteriorly from superficial cardiac plexus to form Anterior pulmonary plexus. It contains vagi nerves and superficial cardiac plexus. These fibres then follow the blood vessel and bronchi into the lungs.

      The lower border of the pleura is at the level of:

      8th rib in the midclavicular line

      10th rib in the lower level of midaxillary line

      T12 at its termination.

      Both lungs have oblique fissure while right lung has transverse fissure too.

      The trachea expands from the lower edge of the cricoid cartilage (at the level of the 6th cervical vertebra) to the carina.

    • This question is part of the following fields:

      • Physiology
      0
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  • Question 11 - Suppose a diabetic patient is to undergo an elective surgery under general anaesthesia,...

    Incorrect

    • Suppose a diabetic patient is to undergo an elective surgery under general anaesthesia, which of the following will most effectively prevent a hyperglycaemic stress response during the surgical procedure?

      Your Answer:

      Correct Answer: Spinal block to T4

      Explanation:

      Every surgical procedure is associated with a stress response which comprises a number of endocrine, metabolic, and immunological changes triggered by neuronal activation of the hypothalamic-pituitary-adrenal axis. The overall metabolic effect of the stress response to surgery includes an increase in secretion of catabolic hormones, such as cortisol and catecholamine, and a decrease in secretion of anabolic hormones, such as insulin and testosterone. The increase in levels of catabolic hormones in plasma stimulates glucose production, and there is a relative lack of insulin together with impaired tissue insulin sensitivity and glucose utilization, which is called insulin resistance. Consequently, blood glucose concentrations will increase, even in the absence of pre-existing diabetes.

      A study compared the effects of spinal and general anaesthesia on changes in blood glucose concentrations during surgery in nondiabetic patients. Although mean blood glucose concentrations showed a significant proportional increase during surgery in both groups, this effect was much more significant with general anaesthesia than with spinal anaesthesia. These results indicate that spinal anaesthesia is more effective than general anaesthesia in attenuating the hyperglycaemic response to surgery.

    • This question is part of the following fields:

      • Pathophysiology
      0
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  • Question 12 - A 40-year old farmer came into the emergency room with a chief complaint...

    Incorrect

    • A 40-year old farmer came into the emergency room with a chief complaint of 4 episodes of non-bloody diarrhoea. This was associated with frequent urination, vomiting and salivation. History also revealed frequent use of insecticides. Upon physical examination, there was miosis and bradycardia.

      Given the different types of bonds, which is the most likely bond formed between insecticide poisoning and receptors?

      Your Answer:

      Correct Answer: Covalent

      Explanation:

      Organophosphate poisoning occurs most often due to accidental exposure to toxic amounts of pesticides. Signs and symptoms include diarrhoea, urination, miosis, bradycardia, emesis, lacrimation, lethargy and salivation.

      Organophosphates are classified as indirect acting cholinomimetics, and their mode of action involves: (1) the inhibition of acetylcholinesterase (AChE) by forming a stable covalent bond on the active site serine; and, (2) amplification of endogenously release acetylcholine (ACh), hence the clinical manifestation.

      There are 4 types of bonds or interactions: ionic, covalent, hydrogen bonds, and van der Waals interactions. Ionic and covalent bonds are strong interactions that require a larger energy input to break apart. When an element donates an electron from its outer shell, a positive ion is formed. The element accepting the electron is now negatively charged. Because positive and negative charges attract, these ions stay together and form an ionic bond. Covalent bonds form when an electron is shared between two elements and are the strongest and most common form of chemical bond in living organisms. Covalent bonds form between the elements that make up the biological molecules in our cells. Unlike ionic bonds, covalent bonds do not dissociate in water.

      When polar covalent bonds containing a hydrogen atom form, the hydrogen atom in that bond has a slightly positive charge. This is because the shared electron is pulled more strongly toward the other element and away from the hydrogen nucleus. Because the hydrogen atom is slightly positive, it will be attracted to neighbouring negative partial charges. When this happens, a weak interaction occurs between the slightly positive charge of the hydrogen atom of one molecule and the slightly negative charge of the other molecule. This interaction is called a hydrogen bond.

    • This question is part of the following fields:

      • Pathophysiology
      0
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  • Question 13 - A strict diet is mandatory for which of the following drugs for mood...

    Incorrect

    • A strict diet is mandatory for which of the following drugs for mood disorders?

      Your Answer:

      Correct Answer: Tranylcypromine

      Explanation:

      Tranylcypromine is a monoamine oxidase inhibitor that binds irreversibly to target enzyme.

      Monoamine oxidase inhibitors are responsible for blocking the monoamine oxidase enzyme. The monoamine oxidase enzyme breaks down different types of neurotransmitters from the brain: norepinephrine, serotonin, dopamine, and tyramine. MAOIs inhibit the breakdown of these neurotransmitters thus, increasing their levels and allowing them to continue to influence the cells that have been affected by depression.

      There are two types of monoamine oxidase, A and B. The MAO A is mostly distributed in the placenta, gut, and liver, but MAO B is present in the brain, liver, and platelets. Serotonin and noradrenaline are substrates of MAO A, but phenylethylamine, methylhistamine, and tryptamine are substrates of MAO B. Dopamine and tyramine are metabolized by both MAO A and B. Selegiline and rasagiline are irreversible and selective inhibitors of MAO type B, but safinamide is a reversible and selective MAO B inhibitor.

      MAOIs prevent the breakdown of tyramine found in the body and certain foods, drinks, and other medications. Patients that take MAOIs and consume tyramine-containing foods or drinks will exhibit high serum tyramine level. A high level of tyramine can cause a sudden increase in blood pressure, called the tyramine pressor response. Even though it is rare, a high tyramine level can trigger a cerebral haemorrhage, which can even result in death.

      Eating foods with high tyramine can trigger a reaction that can have serious consequences. Patients should know that tyramine can increase with the aging of food; they should be encouraged to have fresh foods instead of leftovers or food prepared hours earlier. Examples of high levels of tyramine in food are types of fish and types of meat, including sausage, turkey, liver, and salami. Also, certain fruits can contain tyramine, like overripe fruits, avocados, bananas, raisins, or figs. Further examples are cheeses, alcohol, and fava beans; all of these should be avoided even after two weeks of stopping MAOIs. Anyone taking MAOIs is at risk for an adverse hypertensive reaction, with accompanying morbidity. Patients taking reversible MAOIs have fewer dietary restrictions.

      Amitriptyline is a tricyclic antidepressant, and citalopram and escitalopram are selective serotonin reuptake inhibitors.

    • This question is part of the following fields:

      • Pharmacology
      0
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  • Question 14 - A cannula is inserted into the cephalic vein of a 30-year-old man. Which...

    Incorrect

    • A cannula is inserted into the cephalic vein of a 30-year-old man. Which of the following structures does the cephalic vein pass through?

      Your Answer:

      Correct Answer: Clavipectoral fascia

      Explanation:

      The cephalic vein is one of the primary superficial veins of the upper limb. The superficial group of upper limb veins begin as an irregular dorsal arch on the back of the hand.

      The cephalic vein originates in the anatomical snuffbox from the radial side of the arch and travels laterally up, within the superficial fascia to join the basilic vein via the median cubital vein at the elbow.

      Near the shoulder, it passes between the deltoid and pectoralis major muscles. It pierces the coracoid membrane (continuation of the clavipectoral fascia) to terminate in the axillary vein’s first part.

    • This question is part of the following fields:

      • Anatomy
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  • Question 15 - The plateau phase of the myocardial action potential is as a result of:...

    Incorrect

    • The plateau phase of the myocardial action potential is as a result of:

      Your Answer:

      Correct Answer: Slow influx of calcium

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 16 - What is the most sensitive method of detecting an intra-operative air embolism? ...

    Incorrect

    • What is the most sensitive method of detecting an intra-operative air embolism?

      Your Answer:

      Correct Answer: Transoesophageal echocardiogram

      Explanation:

      An intra-operative air embolism occurs when air becomes trapped in the blood vessels during surgery.

      A transoesophageal echocardiography (OE) uses invasive echocardiography to monitor the integrity and performance of the heart. It is the gold standard as it provides real-time imaging of the heart to enable early diagnosis and treatment.

      Precordial doppler ultrasonography can also be used to detect into-operative air emboli. It is non-invasive and more practical, but is less sensitive.

      A change in end-tidal CO2 could be indicative of and increase in physiological dead-space, but could also be indicative of any processes that reduces the excretion or increases the production of CO2, making it non-specific.

      A transoesophageal stethoscope can be used to listen for the classic mill-wheel murmur produced by a large air embolus.

    • This question is part of the following fields:

      • Pathophysiology
      0
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  • Question 17 - A 40-year-old woman was diagnosed with hyperparathyroidism. She is undergoing a parathyroidectomy, and...

    Incorrect

    • A 40-year-old woman was diagnosed with hyperparathyroidism. She is undergoing a parathyroidectomy, and during the surgery, the inferior parathyroid gland is found to be enlarged. There is a vessel adjacent to this gland on its lateral side.

      What is this vessel most likely to be?

      Your Answer:

      Correct Answer: Common carotid artery

      Explanation:

      There are four parathyroid glands that lie on the medial half of the posterior surface of each lobe of the thyroid gland, inside its sheath. There are two superior and two inferior parathyroid glands.

      The common carotid artery is a lateral relation of the inferior parathyroid.

    • This question is part of the following fields:

      • Anatomy
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  • Question 18 - Which of the following does Lidocaine 1% solution equate to? ...

    Incorrect

    • Which of the following does Lidocaine 1% solution equate to?

      Your Answer:

      Correct Answer: 1000 mg per 100 ml

      Explanation:

      Lidocaine 1% is formulated as 1000 mg/100 mL.

      % solution is based on (grams of medicine) / 100 ml

      % solution ~ (1000 mg) / 100 ml

      % solution ~ 10 mg/ml

      Examples:

        • Lidocaine 4% = 40 mg/ml of Lidocaine
        • Lidocaine 2% = 20 mg/ml of Lidocaine
        • Lidocaine 1% = 10 mg/ml of Lidocaine

    • This question is part of the following fields:

      • Pharmacology
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  • Question 19 - A mercury barometer can be used to determine absolute pressure. A mercury manometer...

    Incorrect

    • A mercury barometer can be used to determine absolute pressure. A mercury manometer can be used to check blood pressure. The SI units of length(mm) are used to measure pressure.

      Why is pressure expressed in millimetres of mercury (mmHg)?

      Your Answer:

      Correct Answer: Pressure is directly proportional to length of the mercury column and is variable

      Explanation:

      A mercury barometer can be used to determine absolute pressure. A glass tube with one closed end serves as the barometer. The open end is inserted into a mercury-filled open vessel. The mercury in the container is pushed into the tube by atmospheric pressure exerted on its surface. Absolute pressure is the distance between the tube’s meniscus and the mercury surface.

      Pressure is defined as force in newtons per unit area (F) (A). 

      Mass of mercury = area (A) × density (ρ) × length (L)
      Pressure = ((A × ρ × L) × 9.8 m/s2)/A
      Pressure = ρ × L x 9.8
      Pressure is proportional to L

      The numerator and denominator of the above equation, area (A), cancel out. The constants are density and the gravitational acceleration value.

      The length is proportional to the applied pressure.

    • This question is part of the following fields:

      • Physiology
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  • Question 20 - An intravenous drug infusion is started at a rate of 20 ml/hour. The...

    Incorrect

    • An intravenous drug infusion is started at a rate of 20 ml/hour. The drug concentration in the syringe is 5 mg/mL. The drug's plasma clearance is 20 L/hour.

      Which of the following values, assuming that the infusion rate remains constant, best approximates the drug's plasma concentration at steady state?

      Your Answer:

      Correct Answer: 5 mcg/mL

      Explanation:

      When a drug is given via intravenous infusion, the plasma concentration rises exponentially as a wash-in curve until it reaches steady-state concentration (the point at which the infusion rate is balanced by the elimination rate or clearance). To reach this steady state, the drug will take 4-5 half-lives.

      Cpss (target plasma concentration at steady state) and clearance (CL) in ml/minute or litre/hour are the two factors that determine the infusion rate or dose (ID) in mg/hour of a drug.

      ID = Cpss × CL

      We know the infusion rate is 20 ml/hour in this case. The drug’s concentration is 5 mg/mL. The patient is receiving 100 mg of the drug per hour, with a 20 L/hour clearance rate.

      ID = Cpss × 20

      Therefore,

      Cpss = 100 mg/20000 ml

      Cpss = 0.005 mg/mL or 5 mcg/mL

    • This question is part of the following fields:

      • Pharmacology
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  • Question 21 - A young male is undergoing inguinal hernia repair. During the procedure, the surgeons...

    Incorrect

    • A young male is undergoing inguinal hernia repair. During the procedure, the surgeons approach the inguinal canal and expose the superficial inguinal ring.

      Which structure forms the lateral edge of the superficial inguinal ring?

      Your Answer:

      Correct Answer: External oblique aponeurosis

      Explanation:

      The superficial inguinal ring is an opening in the aponeurosis of the external oblique muscle, just above and lateral to the pubic crest.

      The superficial ring resembles a triangle more than a ring with the base lying on the pubic crest and its apex pointing towards the anterior superior iliac spine. The sides of the triangle are crura of the opening in the external oblique aponeurosis. The lateral crura of the triangle is attached to the pubic tubercle. The medial crura of the triangle is attached to the pubic crest.

      The external oblique aponeurosis forms the anterior wall of the inguinal canal and also the lateral edge of the superficial inguinal ring. The rectus abdominis lies posteromedially, and the transversalis posterior to this.

    • This question is part of the following fields:

      • Anatomy
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  • Question 22 - A 70-year-old male is brought to the Emergency department with:
    Pulse rate:...

    Incorrect

    • A 70-year-old male is brought to the Emergency department with:
      Pulse rate: 32 beats per minute
      Blood pressure: 82/35 mmHg
      12 lead ECG shows a sinus bradycardia of 35 beats per minute with no evidence of myocardial ischemia or infarction. There was no chest pain but the patient feels light-headed.

      Which of the following would be the best initial treatment for this condition?

      Your Answer:

      Correct Answer: Atropine

      Explanation:

      Based on the presenting symptoms and clinical examination, it is a case of an adult sinus bradycardia with adverse signs. The first pharmacological treatment for this condition is atropine 500mcg intravenously and if necessary repeat every three to five minutes up to a maximum of 3 mg.

      If the bradycardia does not subside even after the administration of atropine, cardiac pacing should be considered. If pacing cannot be achieved promptly, we should consider the use of second-line drugs like adrenaline, dobutamine, or isoprenaline.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 23 - Which is the most appropriate statement describing the function of flowmeters? ...

    Incorrect

    • Which is the most appropriate statement describing the function of flowmeters?

      Your Answer:

      Correct Answer: Constant pressure, variable orifice - Heidbrink flowmeters

      Explanation:

      There are different models of flowmeters determined by the applied pressure and its orifice. For instance, the watersight flowmeter functions through applying variable pressure, and it has a variable orifice. In contrast, the bubble flowmeter is operated using a constant pressure and orifice. Flowmeters such as rotameters, Heidbrink and Peak have a constant pressure but variable orifice. On the other hand, flowmeters including a simple pressure gauge, water depression, and pneumotachograph have a constant orifice but variable pressure.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 24 - During a stabbing incident, a 30-year-old injured his inferior vena cava. What number...

    Incorrect

    • During a stabbing incident, a 30-year-old injured his inferior vena cava. What number of functional valves can be usually found in this vessel?

      Your Answer:

      Correct Answer: 0

      Explanation:

      The inferior vena cava is formed by the union of the right and left common iliac veins. The inferior vena cava has no functional valves like the one-way valves commonly found in many veins. The forward flow to the heart is driven by the differential pressure created by normal respiration.

      The absence of functional valves has an important clinical role when cannulating during cardiopulmonary bypass.

      There is a valve that is non-functioning called the eustachian valve that lies at the junction of the IVC and the right atrium. This valve has a role to help direct the flow of oxygen-rich blood through the right atrium to the left atrium via the foramen ovale during fetal life. It has no specific function in adult life.

    • This question is part of the following fields:

      • Anatomy
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  • Question 25 - Which of the following derived SI units is correctly expressed as their base...

    Incorrect

    • Which of the following derived SI units is correctly expressed as their base units?

      Your Answer:

      Correct Answer: Volt: m2.kg.s-3.A-1

      Explanation:

      The following units are derived SI units of measurement.

      Energy or work: kg.m2.s-2
      The Joule (J) is the energy transferred to an object when a force of one newton acts on that object in the direction of its motion through a distance of one meter or N.m.

      Power: kg.m2.s-3
      The Watt (W) = rate of transfer of energy or Joule per second J/s.

      Force: kg.m.s-2
      One Newton (N) which is the international unit of measure for force = 1 kilogram meter per second squared. 1 Newton of force is the force required to accelerate an object with a mass of 1 kilogram 1 meter per second per second.

      Volt: kg.m2.s-3.A-1
      The volt (V) is defined as the potential difference across a conductor when a current of one ampere dissipates one watt of power or W/A.

      Pressure: kg.m-1.s-2
      A pascal (Pa) is force per unit area or N/m2.

    • This question is part of the following fields:

      • Basic Physics
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  • Question 26 - Which of the following structures does the vertebral artery NOT traverse? ...

    Incorrect

    • Which of the following structures does the vertebral artery NOT traverse?

      Your Answer:

      Correct Answer: Intervertebral foramen

      Explanation:

      The vertebral artery originates from the subclavian artery and ascends through the neck in the transverse foramen of the C1-C6 vertebrae. C2 vertebra is called the axis vertebra. A part of the vertebral artery lies in a groove on the upper surface of the atlas’s (C1) posterior arch. It enters the vertebral canal below the inferior border of the posterior atlantooccipital membrane. The vertebral arteries then enter the skull via the foramen magnum.

    • This question is part of the following fields:

      • Anatomy
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  • Question 27 - A 60-year-old man had previously been diagnosed with Type 2 diabetes. He had...

    Incorrect

    • A 60-year-old man had previously been diagnosed with Type 2 diabetes. He had recently started gliclazide, a sulphonyl urea, as his diabetes was not controlled by metformin alone.

      Now, he presents to his physician with complaints of anxiety, sweating, and palpitations since the morning. On physical examination, he is pale and clammy and has mydriasis and increased bowel sounds.

      Which biological site primarily synthesizes the hormone responsible for this patient's condition?

      Your Answer:

      Correct Answer: Chromaffin cells of the adrenal medulla

      Explanation:

      This patient has been shifted to a sulfonylurea drug whose most common side effect is hypoglycaemia. Similar symptoms can arise in a patient on insulin too. The signs and symptoms are consistent with a hypoglycaemic attack and include tachycardia, altered consciousness, and behaviour. This needs to be treated as an emergency with rapid correction of the blood glucose level using glucose or IV 20% dextrose.

      In a hypoglycaemic attack, the body undergoes stress and releases hormones to increase blood glucose levels. These include:
      Glucagon
      Cortisol
      Adrenaline

      Adrenaline or epinephrine is the hormone responsible for this patient’s condition and is primarily produced in the medulla of the adrenal gland. It functions primarily to raise cardiac output and raise blood glucose levels in the blood.

      Alpha-cells of the islets of Langerhans produce the hormone glucagon, which has opposing effects to insulin.

      Follicular cells of the thyroid gland produce and secrete thyroid hormones. Thyroid hormones can cause similar symptoms, but it is unlikely with the patient’s medical history.

      Post-ganglionic neurons of the sympathetic nervous system use norepinephrine as a neurotransmitter. Adrenaline can be made in these cells, but it is not their primary production site.

      Zona fasciculata of the adrenal cortex is the main site for the production of cortisol.

    • This question is part of the following fields:

      • Anatomy
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  • Question 28 - A 89-year old male has hypertension, with a blood pressure of 170/68 mmHg...

    Incorrect

    • A 89-year old male has hypertension, with a blood pressure of 170/68 mmHg and has been admitted to the hospital. He is on no regular medications. His large pulse pressure can be accounted for by which of the following?

      Your Answer:

      Correct Answer: Reduced aortic compliance

      Explanation:

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 29 - Regarding the carbon dioxide monitoring, which of the following statements is correct? ...

    Incorrect

    • Regarding the carbon dioxide monitoring, which of the following statements is correct?

      Your Answer:

      Correct Answer: Carbon dioxide absorbs infrared radiation at 4.28 µm

      Explanation:

      Carbon dioxide (CO2), is a carbonic gas made up of two dissimilar atoms, namely one carbon atom and two oxygen atoms. Capnography is a technique used to measure carbon dioxide during a respiratory cycle, and it consists in calculating the concentration of the partial pressure of CO2, through the absorption of the infrared light, namely that CO2 absorbs infrared radiation at a wavelength of 4.28 µm.

      End-tidal CO2 (ETCO2), referring to the level of the carbon dioxide released at the end of an exhaled breath, is required to be continuously monitored, especially in ventilated patients, as it is a sensitive and a non invasive technique that provides immediate information about ventilation, circulation, and metabolism functions. ETCO2 is normally lower than the arterial partial pressure and varies between 0.6 and 0.7 kPa.

      There are two methods used to measure carbon dioxide. The sidestream capnometer method samples gases at a set flow rate (150-200 mL/min) from a sampling area through small diameter tubing, and the mainstream analyser method that uses a direct measurement of the patient exhaled CO2 by a relatively large and heavy sensors. Sidestram method allows the analysis of multiple gases and anaesthetic vapours comparing to the mainstream method that does not allow the measurement of other gases.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 30 - Dinamap is an automated blood pressure monitoring device. Which of these statements best...

    Incorrect

    • Dinamap is an automated blood pressure monitoring device. Which of these statements best fit its properties?

      Your Answer:

      Correct Answer: The cuff should be positioned at the same level as the heart

      Explanation:

      Dinamap continuously measures the systolic, diastolic and mean arterial pressure along with pulse rate, thereby providing a continuous monitoring of the blood pressure using the osscillitonometric principle of measurement.

      The device loses accuracy towards the extremes of BP and is more accurate with systolic compared with diastolic pressure. In arrhythmias such as AF, the devices are also inaccurate due to the major fluctuations associated with the individual pulse pressure variations.

      The manual BP device is still the gold standard for BP measurement and monitoring.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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SESSION STATS - PERFORMANCE PER SPECIALTY

Pharmacology (0/1) 0%
Anaesthesia Related Apparatus (1/1) 100%
Pathophysiology (0/1) 0%
Physiology (0/1) 0%
Passmed