-
Question 1
Incorrect
-
Question 2
Incorrect
-
Fixed performance devices like high air flow oxygen enrichment (HAFOE) masks have large volumes of air entrained into a flow of 100% oxygen.
The term that best describes the physics behind air entrainment is?Your Answer: Venturi effect
Correct Answer: Bernoulli's principle
Explanation:Bernoulli’s principle states that as the speed of a moving fluid increases, there is a simultaneously decrease in static pressure or a decrease in the fluid’s potential energy.
This is seen in the simultaneous increase in speed and kinetic energy and fall in pressure that causes entrainment of large volumes of air into a flow of 100% oxygen in the nozzle of HAFOE masks.The reduction in fluid pressure that happens when a fluid flows through a constriction in a tube is the Venturi effect.
When a flow of gas or liquid attaches itself to a nearby surface and remains attached even when the surface curves away from the initial direction of flow, this is the Coanda effect.
The branch of engineering and technology that is concerned with the building of devices that use the flow and pressure of a fluid for functions usually performed by electronic devices is Fluidics . Fluidic logic is used to power some ventilators.
The branch of engineering that utilises pressurised gases is Pneumatics.
-
This question is part of the following fields:
- Basic Physics
-
-
Question 3
Incorrect
-
Intracellular effectors are activated by receptors on the cell surface. These receptors receive signals that are relayed by second messenger systems.
In the human body, which second messenger is most abundant?Your Answer: Cyclic AMP (cAMP)
Correct Answer: Calcium ions
Explanation:Second messengers relay signals to target molecules in the cytoplasm or nucleus when an agonist interacts with a receptor on the cell surface. They also amplify the strength of the signal. The most ubiquitous and abundant second messenger is calcium and it regulates multiple cellular functions in the body.
These include:
Muscle contraction (skeletal, smooth and cardiac)
Exocytosis (neurotransmitter release at synapses and insulin secretion)
Apoptosis
Cell adhesion to the extracellular matrix
Lymphocyte activation
Biochemical changes mediated by protein kinase C.cAMP is either inhibited or stimulated by G proteins.
The receptors in the body that stimulate G proteins and increase cAMP include:
Beta (?1, ?2, and ?3)
Dopamine (D1 and D5)
Histamine (H2)
Glucagon
Vasopressin (V2).The second messenger for the action of nitric oxide (NO) and atrial natriuretic peptide (ANP) is cGMP.
The second messengers for angiotensin and thyroid stimulating hormone are inositol triphosphate (IP3) and diacylglycerol (DAG).
-
This question is part of the following fields:
- Physiology
-
-
Question 4
Incorrect
-
According to the statements given which one is most correct concerning the spinal cord?
Your Answer: The anterior and posterior spinal arteries form a direct anastomosis at each spinal level
Correct Answer: There are 31 pairs of spinal roots
Explanation:The cylindrical structure(spine), starts from the foramen magnum in medulla oblongata at the skull’s base. Its length varies in gender with men having 45cm and women having up to 43 cm. The spine contains 31 pairs of spinal nerves, named according to the spinal region:
– 8 cervical nerve pairs ( C1-C8)
– 12 thoracic nerve pairs ( T1-T12)
– 5 lumbar nerve pairs (L1-L5)
– 5 sacral nerves (S1-S5) and
– 1 coccygeal nerve pair.
These spinal nerves are classified as the peripheral nervous system though they branch from the spinal cord and central nervous system. They interact directly with the spinal cord to modulate the motor and sensory information from the peripheral’s region. As the nerves emerges form the spinal cords they are known as rootlets. They join to form nerve roots, and depending on their position, we have anterior nerve roots and posterior.The spinal cord is supplied by two posterior and one anterior spinal arteries which anastomoses caudally, at the conus medullaris.
The anterior spinal artery supplies the anterior two-thirds of the spinal cord and medulla. Disruption of the anterior spinal artery supply is characterised by ischaemia or infarction of motor tracts (corticospinal) and loss of pain and temperature sensation below the level of the lesion.
The posterior spinal arteries supply the posterior columns (posterior third of the spinal cord). Infarction of the posterior columns results in the loss of proprioceptive, vibration and two-point discrimination.
The spinal cord normally ends at the level of L1 or L2 in an adult and L3 in a newborn.
-
This question is part of the following fields:
- Anatomy
-
-
Question 5
Correct
-
You are asked about the relative risk associated with a drug. You happened to have read a report in which the same drug was compared with a placebo and your initial thoughts after reading the study were that the drug will have significant side effects.
What do you expect the value of relative risk to be?Your Answer: Greater than 1
Explanation:Risk ratio (relative risk) compares the probability of an event in an exposed (experimental) group to that of an event in the unexposed (control) group.
A relative risk of 1 suggests that there is no discernible difference in the outcome whether or not it has been exposed.
A relative risk of less than 1 indicates that probability of occurrence of an event is less if there is exposure.
A relative risk of greater than 1 highlights that an event is most likely to occur if it was provided exposure. Since you believe that exposure (the new drug) would have side effects, the value should be greater than 1.
-
This question is part of the following fields:
- Statistical Methods
-
-
Question 6
Correct
-
A 70-year-old female presented with a productive cough and is prescribed a bacteriostatic antibiotic?
Which of the following best explains the mechanism of action of bacteriostatic drugs?Your Answer: Protein synthesis inhibition
Explanation:Cell membrane pore formation, Bacterial DNA damage, Peptidoglycan cross-linking inhibition, and peptidoglycan synthesis inhibitor are always lethal and such mechanisms are possible only in bactericidal drugs. But Protein synthesis inhibition would only prevent cell replication or cell growth and is responsible for bacteriostatic effects of the drug.
-
This question is part of the following fields:
- Pharmacology
-
-
Question 7
Correct
-
These proprietary preparations of local anaesthetic are available in your hospital:
Solution A contains 10 mL 0.5% bupivacaine (plain), and
Solution B contains 10 mL 0.5% bupivacaine with adrenaline 1 in 200,000.
What is the pharmacokinetic difference between the two solutions?Your Answer: The onset of action of solution A is quicker than solution B
Explanation:The reasons for adding adrenaline to a local anaesthetic solution are:
1. To Increase the duration of block
2. To reduce absorption of the local anaesthetic into the circulation
3. To Increase the upper safe limit of local anaesthetic (2.5 mg/kg instead of 2 mg/kg, in this case).The addition of adrenaline to bupivacaine does not affect its potency, lipid solubility, protein binding, or pKa(8.1 with or without adrenaline).
The pH of bupivacaine is between 5-7. Premixed with adrenaline, it is 3.3-5.5.
The onset of a local anaesthetic and its ability to penetrate membranes depends upon degree of ionisation. Compared with the ionised fraction, unionised local anaesthetic readily penetrates tissue membranes to site of action. The onset of action of solution B is slower. this is because the relationship between pKa(8.1) and pH(3.3-5.5) of the solution results in a greater proportion of ionised local anaesthetic molecules compared with solution A. -
This question is part of the following fields:
- Pharmacology
-
-
Question 8
Correct
-
In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five minutes is indicated during in-hospital cardiac arrest due to ventricular fibrillation (VF) following three DC shocks.
Which of the following indicates the most important reason for using epinephrine?Your Answer: Preferential distribution of blood to the coronary and cerebral circulation
Explanation:Epinephrine is used for the treatment of cardiac arrest because it causes vasoconstriction via the alpha-adrenergic (?1) receptor. This vasoconstriction increases cerebral and coronary blood flow by increasing mean arterial, aortic diastolic, and cerebral pressures. Furthermore, epinephrine is also a?1 and ?2 adrenoreceptor agonist which shows inotrope, chronotrope, and bronchodilator effects.
– Adrenaline is also used to prolong the duration of action and decrease the systemic toxicity of local anaesthetics.
– Preferred route of adrenaline in patients with cardiac arrest is i.v. followed by intra-osseous and endotracheal -
This question is part of the following fields:
- Pathophysiology
-
-
Question 9
Correct
-
Concerning the pathway of endothelial nitric oxide (eNO), one of the following best describes it.
Your Answer: Stimulation of guanylyl cyclase, increases cGMP concentration leading to vasodilation
Explanation:Nitric oxide (NO), an endothelial-derived relaxant factor (EDRF), is a powerful vasodilator. Its cell-signalling molecule is calcium-dependant and generated endogenous by nitric oxide synthetases from the precursor L-arginine, oxygen and NADPH. Three main isoforms have been isolated and they are inducible (iNO), neuronal (nNO) and endothelial (eNO).
Endothelial NO stimulates intracellular guanylyl cyclase which generates cyclic GMP (cGMP) from its action on guanylyl tri-phosphate (GTP). The cGMP goes on to activate protein kinase G (PKG). PKG phosphorylates cell membrane proteins that regulate intracellular calcium concentrations and level of calcium sensitisation.
Smooth muscle vasodilatation results from:
1. Light chain phosphatase activation.
2. Inhibition of calcium entry into the cell (reducing Ca2+ concentrations) and
3. Hyperpolarisation of cells by activation of H+ channels. -
This question is part of the following fields:
- Pathophysiology
-
-
Question 10
Incorrect
-
An adult and a 7-year-old child are anatomically and physiologically very different.
Which of the following physiological characteristics of a 5-year-old most closely resembles those of a healthy adult?Your Answer: Minute ventilation (mL/kg/minute)
Correct Answer: Dead space ratio
Explanation:Whatever the age, the dead space ratio is 0.3. It’s the dead space (Vd) to tidal volume ratio (Vt).
The glottis is the narrowest point of the upper airway in an adult, while the cricoid ring is the narrowest point in a child.
A child’s airway resistance is much higher than an adult’s. The resistance to airflow increases as the diameter of a paediatric airway shrinks. The radius (r) to the power of 4 is inversely proportional to airway resistance (r4). As a result, paediatric patients are more susceptible to changes in airflow caused by a small reduction in airway diameter, such as caused by oedema.
The compliance of a newborn’s lungs is very low (5 mL/cmH2O), but it gradually improves as lung size and elasticity grow. Lung compliance in an adult is 200 mL/cmH2O.
In children, minute ventilation (mL/kg/minute) is much higher.
-
This question is part of the following fields:
- Pathophysiology
-
-
Question 11
Correct
-
Out of the following, which therapy for acute severe asthma or life-threatening asthma has been NOT been approved in recent guidelines?
Your Answer: Heliox
Explanation:Recommendations from the British Thoracic Society for acute severe asthma or life-threatening asthma are:
1. Give controlled supplementary oxygen to all hypoxemic patients with acute severe asthma titrated to maintain a SpO₂ level of 94 98%.
2. Use high-dose inhaled ?₂ agonists as first-line agents in patients with acute asthma and administer them as early as possible. Reserve
intravenous ?₂ agonists for those patients in whom inhaled therapy cannot be used reliably.
3. Give steroids in adequate doses to all patients with an acute asthma attack.
4. Add nebulized ipratropium bromide (0.5 mg 4–6 hourly) to ?₂ agonist treatment for acute severe or life-threatening asthma or those with a poor initial response to ?₂ agonist therapy.
5. Consider aminophylline for children with severe or life-threatening asthma unresponsive to maximal doses of bronchodilators and steroids.A review (including 12 case reports, three RCTs, and five other observational studies) of ketamine use in adults and children in status asthmaticus reported that ketamine is a potential bronchodilator. Still, prospective trials are needed before conclusions about effectiveness can be drawn.
Heliox has no place in the current guidelines issued by the British Thoracic Society.
-
This question is part of the following fields:
- Anatomy
-
-
Question 12
Incorrect
-
When compared to unipolar diathermy, which of the following is more specific to bipolar diathermy?
Your Answer: Requires an isolating capacitor
Correct Answer: Has a power output of up to 140 joules per second
Explanation:Electrocautery, also known as diathermy, is a technique for coagulation, tissue cutting, and fulguration that uses a high-frequency current to generate heat (cell destruction from dehydration).
The two electrodes in bipolar diathermy are the tips of forceps, and current passes between the tips rather than through the patient. Bipolar diathermy’s power output (40-140 W) is lower than unipolar diathermy’s typical output (400 W). There is no earthing in the bipolar circuit.
A cutting electrode and a indifferent electrode in the form of a metal plate are used in unipolar diathermy. The high-frequency current completes a circuit by passing through the patient from the active electrode to the metal plate. When used correctly, the current density at the indifferent electrode is low, and the patient is unlikely to be burned. Between the patient plate and the earth is placed an isolating capacitor. This has a low impedance to a high frequency current, such as diathermy current, and is used in modern diathermy machines. The capacitor has a high impedance to current at 50 Hz, which protects the patient from electrical shock.
High frequency currents (500 KHz – 1 MHz) are used in both unipolar and bipolar diathermy, which can cause tissue damage and interfere with pacemaker function (less so with bipolar diathermy).
The effect of diathermy is determined by the current density and waveform employed. The current is a pulsed square wave pattern in coagulation mode and a continuous square wave pattern in cutting mode.
-
This question is part of the following fields:
- Anaesthesia Related Apparatus
-
-
Question 13
Correct
-
An 84-year-old woman has a fall. She fractures the neck of her femur and requires emergency surgery.
On history and examination, she appears to also have a possible heart failure for which an echocardiogram is scheduled.
Her measurements are:
End-diastolic volume: 40mL (70-240)
End-systolic volume: 30mL (16-140)
Calculate her approximate ejection fraction.Your Answer: 25%
Explanation:An echocardiogram provides real-time visualisation of cardiac structures. The ejection fraction (EF) is normally measured using this system.
The ejection fraction (EF) can be deduced mathematically if the patient’s end-diastolic volume (EDV), end-systolic volume (ESV) and stroke volume (SV) are known, as:
SV = EDV – ESV, and
EF = SV/EDV x 100
The normal range for EF is >55-70%.
For this patient,
SV= 40 – 30 = 10 mL, therefore
EF = 10/40 x 100 = 25%
-
This question is part of the following fields:
- Clinical Measurement
-
-
Question 14
Correct
-
A 73-year-old man, presents with abdominal pain, constipation and blood on defecation. He is diagnosed with a distal sigmoid colon carcinoma.
Which artery is most likely to provide its blood supply?Your Answer: Inferior mesenteric artery
Explanation:The inferior mesenteric artery supplies blood to the hindgut, which includes the sigmoid colon.
Note that during high anterior resection of distal sigmoid colon tumours, the inferior mesenteric artery is ligated, interrupting blood supply.
The branches of the internal iliac artery, particularly the middle rectal branch, are essential in retaining vascularity of the rectal stump.
-
This question is part of the following fields:
- Anatomy
-
-
Question 15
Correct
-
The parameter that is indirectly measured from a blood gas analysis is?
Your Answer: Standard bicarbonate
Explanation:Automated blood gas analysers are commonly used to analyse blood gas samples, and they measure specific components of the arterial blood gas sample, whether directly or indirectly.
The following are the components of arterial blood gas:
pH = measured (directly determined) acid-base balance of the blood
PaO2 = measured partial pressure of oxygen in arterial blood
PaCO2 = measured partial pressure of carbon dioxide in arterial blood
HCO3 = calculated (indirectly determined) concentration of bicarbonate in arterial blood
Base excess/deficit = calculated relative excess or deficit of base in arterial blood
SaO2 = calculated arterial oxygen saturation unless a co-oximetry is obtained, in which case it is measured
-
This question is part of the following fields:
- Pathophysiology
-
-
Question 16
Correct
-
Following an acute appendicectomy, a 6-year-old child is admitted to the recovery unit.
Your consultant has requested that you prescribe maintenance fluids for the next 12 hours. The child is 21 kg in weight.
What is the most suitable fluid volume to be prescribed?Your Answer: 732 ml
Explanation:After a paediatric case, you’ll frequently have to calculate and prescribe maintenance fluids. The ‘4-2-1 rule’ should be used as a guideline:
1st 10 kg – 4 ml/kg/hr
2nd 10 kg – 2 ml/kg/hr
Subsequent kg – 1 ml/kg/hrHence
1st 10 kg = 4 × 10 = 40 ml
2nd 10 kg = 2 × 10 = 20 ml
Subsequent kg = 1 × 1 = 1 ml
Total = 61 ml/hr61 × 12 = 732 ml over 12 hrs.
-
This question is part of the following fields:
- Physiology
-
-
Question 17
Incorrect
-
A 25-year old man needs an emergency appendicectomy and has gone to the operating room. During general anaesthesia, ventilation is achieved using a circle system with a fresh gas flow (FGF) of 1L/min, with and air/oxygen and sevoflurane combination. The capnograph trace is normal.
Changes to the end tidal and baseline CO2 measurements at 10 and 20 mins respectively are seen on the capnograph below:
10 minutes 20 minutes
End-tidal CO2 4.9 kPa 8.4 kPa
Baseline end-tidal CO2 0.2 kPa 2.4 kPa
The other vitals were as follows:
Pulse 100-105 beats per minute
Systolic blood pressure 120-133 mmHg
O2 saturation 99%.
The next most important immediate step is which of the following?Your Answer: Replace the soda lime
Correct Answer: Increase the FGF
Explanation:This scenario describes rebreathing management.
Changes is exhaustion of the soda lime and a progressive rise in circuit deadspace is the most likely explanation for the capnograph.
It is important that the soda lime canister is inspected for a change in colour of the granules. Initially fresh gas flow should be increased and then if necessary, replace the soda lime granules. Other strategies include changing to another circuit or bypassing the soda lime canister after the fresh gas flow is increased.
Any other causes of increased equipment deadspace should be excluded.
Intraoperative hypercarbia can be caused by:
1. Hypoventilation – Breathing spontaneously; drugs which include anaesthetic agents, opioids, residual neuromuscular blockade, pre-existing respiratory or neuromuscular disease and cerebrovascular accident.
2. Controlled ventilation- circuit leaks, disconnection, miscalculation of patient’s minute volume.
3. Rebreathing – Soda lime exhaustion with circle, inadequate fresh gas flow into Mapleson circuits, increased breathing system deadspace.
4. Endogenous source – Tourniquet release, hypermetabolic states (MH or thyroid storm) and release of vascular clamps.
5. Exogenous source – Absorption of CO2 absorption from the pneumoperitoneum. -
This question is part of the following fields:
- Physiology
-
-
Question 18
Correct
-
A 60-year-old man, with a history of excessive alcohol intake, presents for the first time in the emergency department with acute abdominal pain in the epigastric region.
On examination, the man is sweating and has a high-grade fever. His heart rate is 140/min and a BP of 92/59 mmHg.
The patient is diagnosed with acute pancreatitis. Which of the following is a complication you are most likely to see in this patient?Your Answer: Blue discolouration of the flank regions
Explanation:Bulky, greasy stools are associated with improper digestion that can be expected if the pancreas loses its exocrine function. This is common in long-term chronic pancreatitis but since this is the patient’s first presentation with such symptoms, this complication is unlikely.
Peripheral neuropathy is a common complication of chronic diabetes but has been reported with cases of chronic pancreatitis too.
Abdominal distention with shifting dullness is a classic symptom of underlying ascites. Ascites is a complication of many diseases but it is not common with the acute first-time presentation of pancreatitis.
Option E: This points towards abdominal obstruction but in the absence of the more common symptoms, nausea and bilious vomiting, this is unlikely.
Option A: Grey Turner’s sign is the pooling of blood in the retroperitoneal space between the last rib and the top of the hip. The pancreas is a retroperitoneal organ and inflammation of the pancreas can cause retroperitoneal haemorrhage. The sign takes 24-48 hours to develop and can predict a severe attack of acute pancreatitis. The patient has presented with acute pancreatitis due to his history of high alcohol intake, and acute on chronic is unlikely as this is his first presentation. He also has low blood pressure and an increased heart rate, which suggest blood loss with acute pancreatitis.
-
This question is part of the following fields:
- Anatomy
-
-
Question 19
Correct
-
Gentamicin is a drug used for the treatment of bronchiectasis. Which of the following is true regarding the mechanism of action of gentamicin?
Your Answer: Inhibit the 30S subunit of ribosomes
Explanation:Gentamicin is a broad-spectrum antibiotic whose mechanism of action involves inhibition of protein synthesis by binding to 30s ribosomes. Its major adverse effect is nephrotoxicity and ototoxicity
Aminoglycoside bind to 30s subunit of ribosome causing misreading of mRNA
Tetracyclines inhibit protein synthesis through reversible binding to bacterial 30s ribosomal subunits, which prevent binding of new incoming amino acids (aminoacyl-tRNA) and thus interfere with peptide growth.
Chloramphenicol binds to the 50s subunit and inhibits peptidyl transferase
Clindamycin binds to the 50s ribosomal subunit of bacteria and disrupts protein synthesis by interfering with the transpeptidation reaction, which thereby inhibits early chain elongation.
-
This question is part of the following fields:
- Pharmacology
-
-
Question 20
Correct
-
The following results were obtained In a new drug trial:
Improved Not improved
Placebo group 36 26
Treatment group 44 16
Regarding the statistical analysis or interpretation of the trial, One of these is trueYour Answer: The data could be evaluated using the chi square test
Explanation:This data is in a 2 × 2 contingency table so a chi square test can be used. There is a special chi squared formula that gives a value that can be looked up in a table giving the p value.
Since we are comparing proportions not means, the Student’s t test CANNOT be used.
There is no linear regression to plot so Pearson’s co-efficient cannot be calculated.
Nothing is so obvious that no statistical analysis is needed.
-
This question is part of the following fields:
- Statistical Methods
-
-
Question 21
Incorrect
-
Regarding the treatment of bladder cancer, a study concerned with the usage of a combined or monotherapy was conducted. A forest plot was used for the visual representation of the data.
Which of the following is true regarding forest plots?Your Answer: Forest plots are typically used in qualitative studies
Correct Answer: Forest plots can present data from multiple studies
Explanation:Being the part of a meta analysis, forest plots are more valued as evidence then randomised control trials.
The notion that forest plots can only be used if the results are substantial is not true. They are good indicators of the significance of the data. If the diamond intersects the central line, the data is rendered significant. It also aggregates means and confidence intervals from studies conducted in the past which makes the study much more reliable as errors associated with individual studies tend to have less of an impact in this way.
The suggestion that forest plots are primarily used for qualitative data is factually incorrect. Forest plots require numerical values to function.
All in all, forest plots help us in determining whether or not there is a significant trend in that particular field of study.
-
This question is part of the following fields:
- Statistical Methods
-
-
Question 22
Incorrect
-
A weakly acidic drug with a pKa of 8.4 is injected intravenously into a patient.
At a normal physiological pH, the percentage of this drug unionised in the plasma is?Your Answer: 1
Correct Answer: 90
Explanation:Primary FRCA is concerned with two issues. The first is a working knowledge of the Henderson-Hasselbalch equation, and the second is a working knowledge of logarithms and antilogarithms.
The pH at which the drug exists in 50 percent ionised and 50 percent unionised forms is known as the pKa.
To calculate the proportion of ionised to unionised form of a drug, use the Henderson-Hasselbalch equation.
pH = pKa + log ([A-]/[HA])
or
pH = pKa + log [(salt)/(acid)]
pH = pKa + log ([ionised]/[unionised])Hence, if the pKa − pH = 0, then 50% of drug is ionised and 50% is unionised.
In this example:
7.4 = 8.4 + log ([ionised]/[unionised])
7.4 − 8.4 = log ([ionised]/[unionised])
log −1 = log ([ionised]/[unionised])Simply put, the antilog is the inverse log calculation. In other words, if you know the logarithm of a number, you can use the antilog to find the value of the number. The antilogarithm’s definition is as follows:
y = antilog x = 10x
Antilog to the base 10 of 0 = 1, −1 = 0.1, −2 = 0.01, −3 = 0.001 and, −4 = 0.0001.
[A-]/[HA] = 0.1
Assuming that we can apply the approximation [A-] << [HA} then this means the acid is 0.1 x 100% = 10% ionised so the percentage of (non-ionized) acid will be 100% – 10% = 90%
-
This question is part of the following fields:
- Pharmacology
-
-
Question 23
Incorrect
-
Which of the following causes a left shift of the haemoglobin dissociation curve?
Your Answer: With decreased 2,3-DPG in transfused red cells
Correct Answer:
Explanation:With respect to oxygen transport in cells, almost all oxygen is transported within erythrocytes. There is limited solubility and only 1% is carried as solution. Thus, the amount of oxygen transported depends upon haemoglobin concentration and its degree of saturation.
Haemoglobin is a globular protein composed of 4 subunits. Haem is made up of a protoporphyrin ring surrounding an iron atom in its ferrous state. The iron can form two additional bonds – one is with oxygen and the other with a polypeptide chain.
There are two alpha and two beta subunits to this polypeptide chain in an adult and together these form globin. Globin cannot bind oxygen but can bind to CO2 and hydrogen ions.
The beta chains are able to bind to 2,3 diphosphoglycerate. The oxygenation of haemoglobin is a reversible reaction. The molecular shape of haemoglobin is such that binding of one oxygen molecule facilitates the binding of subsequent molecules.The oxygen dissociation curve (ODC) describes the relationship between the percentage of saturated haemoglobin and partial pressure of oxygen in the blood.
Of note, it is not affected by haemoglobin concentration.Chronic anaemia causes 2, 3 DPG levels to increase, hence shifting the curve to the right
Haldane effect – Causes the ODC to shift to the left. For a given oxygen tension there is increased saturation of Hb with oxygen i.e. Decreased oxygen delivery to tissues.
This can be caused by:
-HbF, methaemoglobin, carboxyhaemoglobin
-low [H+] (alkali)
-low pCO2
-ow 2,3-DPG
-ow temperatureBohr effect – causes the ODC to shifts to the right = for given oxygen tension there is reduced saturation of Hb with oxygen i.e. Enhanced oxygen delivery to tissues. This can be caused by:
– raised [H+] (acidic)
– raised pCO2
-raised 2,3-DPG
-raised temperature -
This question is part of the following fields:
- Physiology And Biochemistry
-
-
Question 24
Correct
-
Which of the following is true regarding the dose of propofol?
Your Answer: 1-2mg/kg
Explanation:Propofol is a short-acting medication used for starting and maintenance of general anaesthesia, sedation for mechanically ventilated adults, and procedural sedation.
The dose of propofol is 1-2 mg/kg.Dose of some other important drugs are listed below:
Thiopental dose: 3-7 mg/kg
Ketamine dose: 1-2 mg/kg
Etomidate dose: 0.3 mg/kg
Methohexitone dose: 1.0-1.5 mg/kg -
This question is part of the following fields:
- Pharmacology
-
-
Question 25
Incorrect
-
A pharmaceutical company has developed a new drug considered a breakthrough in treating ovarian cancer.
The efficacy of this drug can be assessed by which phase of a clinical trial?Your Answer: Phase III
Correct Answer: Phase IIa
Explanation:Phase IIa studies are usually pilot studies designed to demonstrate clinical efficacy or biological activity (‘proof of concept’ studies) whereas phase IIb studies determine the optimal dose at which the drug shows biological activity with minimal side-effects (definite dose-finding studies).
Phase III and Phase IV studies are performed on larger set of participants (usually hundreds to thousands) when safety and efficacy have been established.
-
This question is part of the following fields:
- Statistical Methods
-
-
Question 26
Incorrect
-
Which of these statements is false relating to the posterior cerebral artery?
Your Answer: It is a branch of the basilar artery
Correct Answer: It is connected to the circle of Willis via the superior cerebellar artery
Explanation:The posterior cerebral arteries are the terminal branches of the basilar artery and are connected to the circle of Willis via the posterior communicating artery. The posterior cerebral artery supplies the visual areas of the cerebral cortex and other structures in the visual pathway.
The posterior cerebral artery is separated from the superior cerebellar artery near its origin by the oculomotor nerve (3rd cranial nerve) and, lateral to the midbrain, by the trochlear nerve.
PCA strokes will primarily cause a visual field loss or homonymous hemianopia to the opposite side. This large occipital or PCA stroke causes people to be “blind” on one side of the visual field. This is the most common symptom of a large occipital lesion or PCA stroke.
-
This question is part of the following fields:
- Anatomy
-
-
Question 27
Correct
-
Which of the following statements is true regarding prazosin?
Your Answer: Is a selective alpha 1 adrenergic receptor antagonist.
Explanation:Selective ?1 -Blockers like prazosin, terazosin, doxazosin, and alfuzosin cause a decrease in blood pressure with lesser tachycardia than nonselective blockers (due to lack of ?2 blocking action.
The major adverse effect of these drugs is postural hypotension. It is seen with the first few doses or on-dose escalation (First dose effect).
Its half-life is approximately three hours.
It is excreted primarily through bile and faeces (not through kidneys)
-
This question is part of the following fields:
- Pharmacology
-
-
Question 28
Correct
-
A 61-year-old woman, present to her general practitioner. She complains of a severe lancinating pain in her forehead that only last a few seconds, possibly triggered by washing her face, occurring over the previous six weeks.
On examination, she is normal with no other signs or symptoms.
Which nerve is the most likely cause of her pain?Your Answer: Sensory branches of the ophthalmic division of the trigeminal nerve
Explanation:Her symptoms are suggestive of trigeminal neuralgia which is a short, sudden, severe sharp unilateral pain in the facial region. The pain often follows the sensory distribution of the trigeminal nerve (CN V).
The trigeminal nerve gives rise to 3 sensory and 1 motor nuclei. Neuralgia can arise from any of the 3 sensory divisions.
The ophthalmic division gives rise to 3 further sensory branches, which are the frontal, lacrimal and nasociliary.
The frontal branch of the ophthalmic division of the trigeminal nerve is responsible for the innervation of the area in question.
The superior alveolar dental, zygomatic and sphenopalatine nerves are all branches arising from the maxillary division of the trigeminal nerve.
The mandibular division of the trigeminal nerve provides sensory and motor innervation. The sensory innervation is carried out by the auriculotemporal nerve which supplies the lower third of the face, while the motor fibres are responsible for controlling the muscles of mastication.
The somatic sensory branches of the vagus nerve are responsible for sensory innervation of the external acoustic meatus and tympanic membrane.
-
This question is part of the following fields:
- Pathophysiology
-
-
Question 29
Correct
-
A 35-year-old male presents to GP presenting an area of erythema which was around a recent cut on his right forearm. He was prescribed a short course of antibiotics and after 5 days again presented with progressive fatigue, headaches, and fevers.
On clinical examination:
Oxygen saturation: 98% on room air
Respiratory rate: 22 per minute
Heart rate: 100 beats per minute
Blood pressure: 105/76 mmHg
Temperature: 38.2 degree Celsius
On physical examination, a dramatic increase in the area of erythema was noted.
Blood culture was done in the patient and indicated the presence of bacterium containing beta-lactamase. Which of the following antibiotics was likely prescribed to the patient?Your Answer: Amoxicillin
Explanation:Ciprofloxacin belongs to the quinolone group of antibiotics, and doxycycline and minocycline are tetracyclines. So, they are not affected by beta-lactamase.
However, amoxicillin is a beta-lactam antibiotic and beta-lactamase cleaves the beta-lactam ring present in amoxicillin. This results in the breakdown of the antibiotic and thus the area of erythema dramatically increased.
Co-amoxiclav contains amoxicillin and clavulanic acid which protects amoxicillin from beta-lactamase. -
This question is part of the following fields:
- Pharmacology
-
-
Question 30
Correct
-
An 80-year old lady has a background history of a previous myocardial infarction which has left permanent damage to her heart's conduction system. The part of the conduction system with the highest velocities is damaged, and this has resulted in desynchronisation of the ventricles. The part of the heart that conducts the fastest is which of the following?
Your Answer: Purkinje fibres
Explanation:The electrical conduction system of the heart starts with the SA node which generates spontaneous action potentials.
This is conducted across both atria by cell to cell conduction, and occurs at around 1 m/s. The only pathway for the action potential to enter the ventricles is through the AV node in a normal heart.
At this site, conduction is very slow at 0.05ms, which allows for the atria to completely contract and fill the ventricles with blood before the ventricles depolarise and contract.The action potentials are conducted through the Bundle of His from the AV node which then splits into the left and right bundle branches. This conduction is very fast, (,2m/s), and brings the action potential to the Purkinje fibres.
Purkinje fibres are specialised conducting cells which allow for a faster conduction speed of the action potential (,2-4m/s). This allows for a strong synchronized contraction from the ventricle and thus efficient generation of pressure in systole.
-
This question is part of the following fields:
- Physiology And Biochemistry
-
00
Correct
00
Incorrect
00
:
00
:
00
Session Time
00
:
00
Average Question Time (
Mins)