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  • Question 1 - A 15-day old male baby was brought to the emergency department with sweating...

    Correct

    • A 15-day old male baby was brought to the emergency department with sweating and his lips turning blue while feeding. He was born full term. On examination, his temperature was 37.9°C, blood pressure 75/45 mmHg, pulse was 175/min, and respiratory rate was 42/min. A harsh systolic ejection murmur could be heard at the left upper sternal border. X-ray chest showed small, boot-shaped heart with decreased pulmonary vascular markings. He most likely has:

      Your Answer: Tetralogy of Fallot

      Explanation:

      The most common congenital cyanotic heart disease and the most common cause of blue baby syndrome, Tetralogy of Fallot shows four cardiac malformations occurring together. These are ventricular septal defect (VSD), pulmonary stenosis (right ventricular outflow obstruction), overriding aorta (degree of which is variable), and right ventricular hypertrophy. The primary determinant of severity of disease is the degree of pulmonary stenosis. Tetralogy of Fallot is seen in 3-6 per 10,000 births and is responsible for 5-7% congenital heart defects, with slightly higher incidence in males. It has also been associated with chromosome 22 deletions and DiGeorge syndrome. It gives rise to right-to-left shunt leading to poor oxygenation of blood. Primary symptom is low oxygen saturation in the blood with or without cyanosis at birth of within first year of life. Affected children ay develop acute severe cyanosis or ‘tet spells’ (sudden, marked increase in cyanosis, with syncope, and may result in hypoxic brain injury and death). Other symptoms include heart murmur, failure to gain weight, poor development, clubbing, dyspnoea on exertion and polycythaemia. Chest X-ray reveals characteristic coeur-en-sabot (boot-shaped) appearance of the heart. Treatment consists of immediate care for cyanotic spells and Blalock–Taussig shunt (BT shunt) followed by corrective surgery.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      193.3
      Seconds
  • Question 2 - A teenage Somalian boy presents with a complaint of an enlarged lower jaw....

    Incorrect

    • A teenage Somalian boy presents with a complaint of an enlarged lower jaw. His blood film shows blast cells and macrophages. Which virus is responsible for this?

      Your Answer: Rubella

      Correct Answer: Epstein–Barr virus

      Explanation:

      Burkitt’s lymphoma is a type of non-Hodgkin’s lymphoma. Histologically it is characterised by a starry sky appearance due to numerous neoplastic macrophages which are required to clear the rapidly dividing tumour cells/blast cells. Burkitt’s lymphoma commonly affects the jaw bone, forming a huge tumour mass. It is associated with translocation of c-myc gene and has three types: 1) endemic/African type, 2)sporadic and 3)immunodeficiency-associated. The first type is strongly associated with EBV.

    • This question is part of the following fields:

      • General
      • Physiology
      23.9
      Seconds
  • Question 3 - Arterial blood gas analysis of a man admitted with acute exacerbation of chronic...

    Incorrect

    • Arterial blood gas analysis of a man admitted with acute exacerbation of chronic obstructive pulmonary disease (COPD) showed the following: pH = 7.28, p(CO2) = 65.5 mmHg, p(O2)= 60 mmHg and standard bicarbonate = 30.5 mmol/l. This patient had:

      Your Answer: Mixed acidosis

      Correct Answer: Respiratory acidosis

      Explanation:

      Acidosis with high p(CO2) and normal standard bicarbonate indicates respiratory acidosis, commonly seen in acute worsening of COPD patients. Respiratory acidosis occurs due to alveolar hypoventilation which leads to increased arterial carbon dioxide concentration (p(CO2)). This in turn decreases the HCO3 –/p(CO2) and decreases pH. In acute respiratory acidosis, the p(CO2) is raised above the upper limit of normal (over 45 mm Hg) with a low pH. However, in chronic cases, the raised p(CO2) is accompanied with a normal or near-normal pH due to renal compensation and an increased serum bicarbonate (HCO3 – > 30 mmHg).

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      8.3
      Seconds
  • Question 4 - Chronic obstructive pulmonary disease (COPD) is likely to result in: ...

    Incorrect

    • Chronic obstructive pulmonary disease (COPD) is likely to result in:

      Your Answer: Metabolic alkalosis

      Correct Answer: Respiratory acidosis

      Explanation:

      COPD leads to respiratory acidosis (chronic). This occurs due to hypoventilation which involves multiple causes, such as poor responsiveness to hypoxia and hypercapnia, increased ventilation/perfusion mismatch leading to increased dead space ventilation and decreased diaphragm function.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      10.2
      Seconds
  • Question 5 - Which of the following can occur even in the absence of brainstem co-ordination?...

    Incorrect

    • Which of the following can occur even in the absence of brainstem co-ordination?

      Your Answer: Defecation

      Correct Answer: Gastric emptying

      Explanation:

      Although gastric emptying is under both neural and hormonal control, it does not require brainstem co-ordination. Increased motility of the orad stomach (decreased distensibility) or of the distal stomach (increased peristalsis), decreased pyloric tone, decreased duodenal motility or a combination of these, all increase the rate of gastric emptying. The major control mechanism for gastric emptying is through duodenal gastric feedback. The duodenum has receptors for the presence of acid, carbohydrate, fat and protein digestion products, osmolarity different from that of plasma, and distension. Activating these receptors decreases the rate of gastric emptying. Neural mechanisms involve both enteric and vagal pathways and a vagotomy impairs the gastric emptying regulation. CCK (cholecystokinin) slows gastric emptying at physiological levels of the hormone. Gastrin, secretin and glucose-1-phosphate also slow gastric emptying, but require higher doses.

    • This question is part of the following fields:

      • Gastroenterology
      • Physiology
      8.6
      Seconds
  • Question 6 - Production of pain is most likely associated with: ...

    Incorrect

    • Production of pain is most likely associated with:

      Your Answer: Acetylcholine

      Correct Answer: Substance P

      Explanation:

      Substance P is a short-chain polypeptide that functions as a neurotransmitter and as a neuromodulator, and is thus, a neuropeptide. It has been linked with pain regulation, mood disorders, stress, reinforcement, neurogenesis, respiratory rhythm, neurotoxicity, nausea and emesis. It is also a potent vasodilator as it brings about release of nitric oxide from the endothelium. Its release can also cause hypotension.

    • This question is part of the following fields:

      • Neurology
      • Physiology
      16
      Seconds
  • Question 7 - A 47 year-old woman was admitted for elective cholecystectomy, with a past...

    Incorrect

    • A 47 year-old woman was admitted for elective cholecystectomy, with a past history of easy bruising and heavy menstrual periods. The patient was also diagnosed with Willebrand's disease. Willebrand's disease is:

      Your Answer: Y-linked

      Correct Answer: Autosomal dominant

      Explanation:

      von Willebrand disease is an autosomal dominant disorder marked by the deficiency of vWF, a large protein synthesized by the endothelial cells and megakaryocytes. It mediates adhesion of platelets to the subendothelium at site of vascular injury. Disease characteristics include impaired platelet adhesion, prolonged bleeding time and a functional deficiency of factor VIII (vWF is its carrier protein).

    • This question is part of the following fields:

      • General
      • Physiology
      6.9
      Seconds
  • Question 8 - upon stroking the plantar surface of a patient's foot, extension of toes was...

    Incorrect

    • upon stroking the plantar surface of a patient's foot, extension of toes was noted. This is likely to be accompanied with:

      Your Answer: Hyporeflexia

      Correct Answer: Spasticity

      Explanation:

      An upper motor neuron lesion affects the neural pathway above the anterior horn cell or motor nuclei of the cranial nerves, whereas a lower motor neurone lesion affects nerve fibres travelling from the anterior horn of the spinal cord to the relevant muscles. An upper motor neurone lesions results in the following:

      – Spasticity in the extensor muscles (lower limbs) or flexor muscles (upper limbs).

      – ‘clasp-knife’ response where initial resistance to movement is followed by relaxation

      – Weakness in the flexors (lower limbs) or extensors (upper limbs) with no muscle wasting

      – Brisk tendon jerk reflexes

      – Positive Babinski sign (on stimulation of the sole of the foot, the big toe is raised rather than curled downwards)

    • This question is part of the following fields:

      • Neurology
      • Physiology
      25
      Seconds
  • Question 9 - Hormones of the anterior pituitary include which of the following? ...

    Correct

    • Hormones of the anterior pituitary include which of the following?

      Your Answer: Prolactin

      Explanation:

      The anterior pituitary gland (adenohypophysis or pars distalis) synthesizes and secretes:

      1. FSH (follicle-stimulating hormone)

      2. LH (luteinizing hormone)

      3. Growth hormone

      4. Prolactin

      5. ACTH (adrenocorticotropic hormone)

      6. TSH (thyroid-stimulating hormone).

      The posterior pituitary gland (neurohypophysis) stores and secretes 2 hormones produced by the hypothalamus:

      1. ADH (antidiuretic hormone or vasopressin)

      2. Oxytocin

    • This question is part of the following fields:

      • Endocrine
      • Physiology
      32
      Seconds
  • Question 10 - After surgery, a patient developed a stitch granuloma . Which leukocyte in the...

    Correct

    • After surgery, a patient developed a stitch granuloma . Which leukocyte in the peripheral blood will become an activated macrophage in this granuloma?

      Your Answer: Monocyte

      Explanation:

      Monocytes are leukocytes that protect the body against infections and move to the site of infection within 8-12 hours to deal with it. They are produced in the bone marrow and shortly after being produced are released into the blood stream where they circulate until an infection is detected. When called upon they leave the circulation and transform into macrophages within the tissue fluid and thus gain the capability to phagocytose the offending substance. Monocyte count is part of a complete blood picture. Monocytosis is the state of excess monocytes in the peripheral blood and may be indicative of various disease states. Examples of processes that can increase a monocyte count include: • chronic inflammation • stress response • hyperadrenocorticism • immune-mediated disease • pyogranulomatous disease • necrosis • red cell regeneration.

    • This question is part of the following fields:

      • General
      • Physiology
      8.8
      Seconds
  • Question 11 - Signals pass through neuromuscular junctions via the neurotransmitter acetylcholine. After release from the...

    Incorrect

    • Signals pass through neuromuscular junctions via the neurotransmitter acetylcholine. After release from the skeletal neuromuscular junction, acetylcholine:

      Your Answer: Is triggered by acetylcholinesterase

      Correct Answer: Causes postsynaptic depolarisation

      Explanation:

      Acetylcholine is released from the presynaptic membrane into the cleft where it binds to the ion gated channels on the post synaptic membrane, causing them to open. This results in sodium entering into the fibre and further depolarizing it, creating an action potential.

    • This question is part of the following fields:

      • General
      • Physiology
      3.5
      Seconds
  • Question 12 - Under normal conditions, what is the major source of energy of cardiac muscles?...

    Incorrect

    • Under normal conditions, what is the major source of energy of cardiac muscles?

      Your Answer: Pyruvate

      Correct Answer: Fatty acids

      Explanation:

      Under basal conditions, most of the energy needed by cardiac muscle for metabolism is derived from fats (60%), 35% by carbohydrates, and 5% by ketones and amino acids. However, after intake of large amounts of glucose, lactate and pyruvate are mainly used. During prolonged starvation, fat acts as the primary source. 50% of the used lipids are sourced from circulating fatty acids.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      7.4
      Seconds
  • Question 13 - C5a (a complement component) is a potent? ...

    Correct

    • C5a (a complement component) is a potent?

      Your Answer: Anaphylotoxin

      Explanation:

      C5a is a strong chemoattractant as well as an anaphylotoxin and is involved in the recruitment of inflammatory cells such as neutrophils, eosinophils, monocytes, and T lymphocytes. It is also involved in activation of phagocytic cells, release of granule-based enzymes and generation of oxidants. All of which contribute to innate immune functions.

    • This question is part of the following fields:

      • General
      • Physiology
      33.3
      Seconds
  • Question 14 - A sudden loud sound is more likely to result in cochlear damage than...

    Correct

    • A sudden loud sound is more likely to result in cochlear damage than a slowly developing loud sound. This is because:

      Your Answer: There is a latent period before the attenuation reflex can occur

      Explanation:

      On transmission of a loud sound into the central nervous system, an attenuation reflex occurs after a latent period of 40-80 ms. This reflex contracts the two muscles that pull malleus and stapes closer, developing a high degree of rigidity in the entire ossicular chain. This reduces the ossicular conduction of low frequency sounds to the cochlea by 30-40 decibels. In this way, the cochlea is protected from damage due to loud sounds (these are low frequency sounds) when they develop slowly.

    • This question is part of the following fields:

      • Neurology
      • Physiology
      145.6
      Seconds
  • Question 15 - Calculate the stroke volume in an adult male with the following parameters:

    Heart...

    Correct

    • Calculate the stroke volume in an adult male with the following parameters:

      Heart rate 70 beats/min

      Arterial [O2] 0.24 ml O2/min

      Venous [O2] 0.16 ml O2/mi

      Whole body O2 consumption 500 ml/min

      Pulmonary diastolic pressure 15 mmHg

      Pulmonary systolic pressure 25 mmHg

      Wedge pressure 5 mmHg.

      Your Answer: 90 ml

      Explanation:

      Fick’s principle states that, VO2 = (CO × CAO2) – (CO × CVO2) where VO2 = oxygen consumption, CO = cardiac output, CAO2 = oxygen concentration of arterial blood and CVO2 = oxygen concentration of venous blood. Thus, CO = VO2/CAO2– CVO2, CO = 500/0.24–0.16, CO = 500/0.8, CO = 6.25 l/min. Cardiac output is also given by product of stroke volume and heart rate. Thus, stroke volume = cardiac output / heart rate = 6.25/70 × 1000 stroke volume = 90 ml approximately.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      75.4
      Seconds
  • Question 16 - A 26-year-old female patient had the following blood report: RBC count =...

    Correct

    • A 26-year-old female patient had the following blood report: RBC count = 4. 0 × 106/μl, haematocrit = 27% and haemoglobin = 11 g/dl, mean corpuscular volume (MCV) = 90 fl, mean corpuscular haemoglobin concentration (MCHC) = 41 g/dl. Further examination of blood sample revealed increased osmotic fragility of the erythrocytes. Which of the following is the most likely cause of this patient’s findings?

      Your Answer: Spherocytosis

      Explanation:

      Spherocytes are small rounded RBCs. It is due to an inherited defect of the RBC cytoskeleton membrane tethering proteins. Membrane blebs form that are lost over time and cells become round instead of biconcave. As it is a normochromic anaemia, the MCV is normal. it is diagnosed by osmotic fragility test which reveals increased fragility in a hypotonic solution.

    • This question is part of the following fields:

      • General
      • Physiology
      7.6
      Seconds
  • Question 17 - A 35-year-old ultra marathon runner becomes severely dehydrated and collapses. This patient most...

    Correct

    • A 35-year-old ultra marathon runner becomes severely dehydrated and collapses. This patient most likely has:

      Your Answer: Decreased baroreceptor firing rate

      Explanation:

      Baroreceptors are sensors located in the blood vessels of all vertebrate animals. They sense the blood pressure and relay the information to the brain, so that a proper blood pressure can be maintained. Acute dehydration results in decreased plasma volume and increased plasma osmolarity, since more water than salt is lost in sweat. The decrease in plasma volume leads to an inhibition of the baroreceptors and a lower firing rate. The increase in plasma osmolarity leads to increased ADH secretion and high plasma ADH levels, which increases water permeability of collecting duct cells. Therefore more water is reabsorbed by the kidneys and renal water excretion is low.

    • This question is part of the following fields:

      • Physiology
      • Renal
      18.5
      Seconds
  • Question 18 - A 43-year-old diabetic man complains of headaches, palpitations, anxiety, abdominal pain and weakness....

    Incorrect

    • A 43-year-old diabetic man complains of headaches, palpitations, anxiety, abdominal pain and weakness. He is administered sodium bicarbonate used to treat:

      Your Answer: Respiratory acidosis

      Correct Answer: Metabolic acidosis

      Explanation:

      Sodium bicarbonate is indicated in the management of metabolic acidosis, which may occur in severe renal disease, uncontrolled diabetes, circulatory insufficiency due to shock or severe dehydration, extracorporeal circulation of blood, cardiac arrest and severe primary lactic acidosis. Bicarbonate is given at 50-100 mmol at a time under scrupulous monitoring of the arterial blood gas readings. This intervention, however, has some serious complications including lactic acidosis, and in those cases, should be used with great care.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Physiology
      7.4
      Seconds
  • Question 19 - A 30 year old female presented in the emergency with an irregular pulse....

    Incorrect

    • A 30 year old female presented in the emergency with an irregular pulse. Her ECG showed absent P-waves with irregular RR interval. What is the most likely diagnosis?

      Your Answer: Ventricular fibrillation

      Correct Answer: Atrial fibrillation

      Explanation:

      Atrial fibrillation is one of the most common cardiac arrhythmias. It is often asymptomatic but may present with symptoms of palpitations, fainting, chest pain and heart failure. Characteristic findings are: absence of P-waves, unorganised electrical activity in their place, irregularity of RR interval due to irregular conduction of impulses to the ventricles and if paroxysmal AF is suspected, episodes may be documented with the use of Holter monitoring

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      9.5
      Seconds
  • Question 20 - One sensitive indicator of heavy alcohol dependence is: ...

    Incorrect

    • One sensitive indicator of heavy alcohol dependence is:

      Your Answer: Decreased serum alkaline phosphatase

      Correct Answer: Elevated serum gamma-glutamyl transpeptidase

      Explanation:

      Elevated serum gamma-glutamyl transpeptidase (GGT) may be the only laboratory abnormality in patients who are dependent on alcohol. Heavy drinkers may also have an increased MCV.

    • This question is part of the following fields:

      • Hepatobiliary
      • Physiology
      2.4
      Seconds
  • Question 21 - What is the pH of freshly formed saliva at ultimate stimulation? ...

    Correct

    • What is the pH of freshly formed saliva at ultimate stimulation?

      Your Answer: 8

      Explanation:

      Saliva has four major components: mucus (lubricant), α-amylase (enzyme that initiates digestion of starch), lingual lipase (enzyme that begins fat digestion), and a slightly alkaline electrolyte solution for moistening food. As the secretion rate of saliva increases, its osmolality increases. Moreover, the pH changes from slightly acidic (at rest) to basic (pH 8) at ultimate stimulation. This occurs due to increase of HCO3-. Amylase and mucus also increase in concentration after stimulation.

    • This question is part of the following fields:

      • Gastroenterology
      • Physiology
      7.8
      Seconds
  • Question 22 - The anatomical dead space in a patient with low oxygen saturation, is 125...

    Correct

    • The anatomical dead space in a patient with low oxygen saturation, is 125 ml, with a tidal volume of 500 ml and pa(CO2) of 40 mm Hg. The dead space was determined by Fowler's method. If we assume that the patient's lungs are healthy, what will his mixed expired CO2 tension [pE(CO2)] be?

      Your Answer: 30 mmHg

      Explanation:

      According to Bohr’s equation, VD/VT = (pA(CO2) − pE(CO2))/pA(CO2), where pE(CO2) is mixed expired CO2 and pA(CO2) is alveolar CO2pressure. Normally, the pa(CO2) is virtually identical to pA(CO2). Thus, VD/VT = (pa(CO2)) − pE(CO2)/pa(CO2). By Fowler’s method, VD/VT= 0.25. In the given problem, (pa(CO2) − pE(CO2)/pa(CO2) = (40 − pE(CO2)/40 = 0.25. Thus, pE(CO2) = 30 mmHg. If there is a great perfusion/ventilation inequality, pE(CO2) could be significantly lower than 30 mm Hg, and the patient’s physiological dead space would exceed the anatomical dead space.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      50.9
      Seconds
  • Question 23 - Different substances have different renal clearance rates. Which of the following substances should...

    Incorrect

    • Different substances have different renal clearance rates. Which of the following substances should have the lowest renal clearance rate in a healthy patient?

      Your Answer: Sodium

      Correct Answer: Glucose

      Explanation:

      Under normal conditions the renal clearance of glucose is zero, since glucose is completely reabsorbed in the renal tubules and not excreted. Glycosuria – the excretion of glucose into the urine- is nearly always caused by elevated blood glucose levels, most commonly due to untreated diabetes mellitus.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Physiology
      15
      Seconds
  • Question 24 - Which organ is responsible for the secretion of enzymes that aid in digestion...

    Incorrect

    • Which organ is responsible for the secretion of enzymes that aid in digestion of complex starches?

      Your Answer: Large intestine

      Correct Answer: Pancreas

      Explanation:

      α-amylase is secreted by the pancreas, which is responsible for hydrolysis of starch, glycogen and other carbohydrates into simpler compounds.

    • This question is part of the following fields:

      • Gastroenterology
      • Physiology
      216.7
      Seconds
  • Question 25 - Work of breathing (WOB) is the energy expended to inhale and exhale a breathing gas. Normally, maximal amount of work...

    Correct

    • Work of breathing (WOB) is the energy expended to inhale and exhale a breathing gas. Normally, maximal amount of work of breathing is required to overcome:

      Your Answer: Elastic lung compliance

      Explanation:

      The forces of elastance (compliance), frictional resistance and inertia have been identified as the forces that oppose lung inflation and deflation. The normal relaxed state of the lung and chest is partially empty. Further exhalation requires muscular work. Inhalation is an active process requiring work. About 60–66% of the total work performed by the respiratory muscles is used to overcome the elastic or compliance characteristics of the lung–chest cage, 30–35% is used to overcome frictional resistance and only 2–5% of the work is used for inertia.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      6
      Seconds
  • Question 26 - A 59-year-old woman with hyperaldosteronism is prescribed a diuretic. Which of the following...

    Incorrect

    • A 59-year-old woman with hyperaldosteronism is prescribed a diuretic. Which of the following diuretics promotes diuresis by opposing the action of aldosterone?

      Your Answer: Mannitol

      Correct Answer: Potassium-sparing diuretic

      Explanation:

      The term potassium-sparing refers to an effect rather than a mechanism or location. Potassium-sparing diuretics act by either antagonising the action of aldosterone (spironolactone) or inhibiting Na+ reabsorption in the distal tubules (amiloride). This group of drugs is often used as adjunctive therapy, in combination with other drugs, for the management of chronic heart failure. Spironolactone, the first member of the class, is also used in the management of hyperaldosteronism (including Conn’s syndrome) and female hirsutism (due to additional antiandrogen actions).

    • This question is part of the following fields:

      • Physiology
      • Renal
      127.4
      Seconds
  • Question 27 - Ventricular filling follows a delay caused by? ...

    Incorrect

    • Ventricular filling follows a delay caused by?

      Your Answer: SA node

      Correct Answer: AV node

      Explanation:

      The AV node is a conducting tissue found between the atria and the ventricles of the heart. It conducts electrical signal from the atria to the ventricles and acts a delaying mechanism preventing the atria and the ventricles from contracting at the same time. This decremental conduction prevents premature ventricular contraction in cases such as atrial fibrillation. A delay in the AV node is the reason for the PR segment seen on the ECG. In certain types of supraventricular tachycardia, a person could have two AV nodes; this will cause a loop in electrical current and uncontrollably rapid heart beat. When this electricity catches up with itself, it will dissipate and return to a normal heart rate.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      37.4
      Seconds
  • Question 28 - A 55-year old gentleman presented to the doctor with worsening dysphagia for both...

    Correct

    • A 55-year old gentleman presented to the doctor with worsening dysphagia for both solids and liquids over 6 months. This was associated with regurgitation of undigested food and occasional chest pain. Barium swallow revealed distal oesophageal dilatation with lack of peristalsis in the distal two-third oesophagus. The likely diagnosis is:

      Your Answer: Achalasia

      Explanation:

      Achalasia is an oesophageal motility disorder where inappropriate contractions in the oesophagus lead to reduced peristalsis and failure of the lower oesophageal sphincter to relax properly in response to swallowing. Classical triad of symptoms include dysphagia to fluids followed by solids, chest pain and regurgitation of undigested food. Other symptoms include belching, hiccups, weight loss and cough. Diagnosis is by:

      – X-ray with a barium swallow or oesophagography : narrowing at the gastroesophageal junction (‘bird/parrot beak’ or ‘rat tail’ appearance) and various degrees of mega-oesophagus (oesophageal dilatation) as the oesophagus is gradually stretched by retained food. Effectiveness of treatment can be measured with a 5-minute timed barium swallow.

      – Manometry – probe measures the pressure waves in different parts of oesophagus and stomach while swallowing.

      – Endoscopy

      – CT scan to exclude other causes like malignancy

      – Pathological examination showing defect in the nerves which control oesophageal motility (myenteric plexus).

      In Chagas disease, there is destruction of ganglion cells by Trypanosoma cruzi.

    • This question is part of the following fields:

      • Gastroenterology
      • Physiology
      35.7
      Seconds
  • Question 29 - A 45-year-old pregnant woman develops high blood pressure at 20 weeks. She complains...

    Incorrect

    • A 45-year-old pregnant woman develops high blood pressure at 20 weeks. She complains of headaches and swollen feet, and a test reveals proteinuria (350 mg/day). Which of the following is the most likely diagnosis?

      Your Answer: Polycystic kidney disease

      Correct Answer: Pre-eclampsia

      Explanation:

      Pre-eclampsia (PE) is a disorder of pregnancy characterized by the onset of high blood pressure (two separate readings taken at least 6 h apart of 140/90 or more) and often a significant amount of protein in the urine (>300 mg of protein in a 24-h urine sample). While blood pressure elevation is the most visible sign of the disease, it involves generalised damage to the maternal endothelium of the kidneys and liver, with the release of vasopressive factors only secondary to the original damage. Pre-eclampsia may develop at varying times within pregnancy and its progress differs among patients; most cases present pre-term. It has no known cure apart from ending the pregnancy (induction of labour or abortion). It may also present up to 6 weeks post partum. Risk factors for pre-eclampsia include obesity, prior hypertension, older age, and diabetes mellitus.

    • This question is part of the following fields:

      • Physiology
      • Renal
      14.4
      Seconds
  • Question 30 - A 7-year-old boy is diagnosed with metabolic acidosis as a result of severe...

    Incorrect

    • A 7-year-old boy is diagnosed with metabolic acidosis as a result of severe dehydration. Which of the following conditions is most likely to cause severe dehydration and metabolic acidosis?

      Your Answer:

      Correct Answer: Severe diarrhoea

      Explanation:

      Diarrhoea is defined as having three or more loose or liquid stools per day, or as having more stools than is normal for that person. Severe diarrhoea, causing fluid loss and loss of bicarbonate, will result in marked dehydration and metabolic acidosis.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Physiology
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Cardiovascular (4/5) 80%
Physiology (25/29) 86%
Respiratory (4/4) 100%
Gastroenterology (3/4) 75%
Neurology (2/3) 67%
General (4/5) 80%
Endocrine (1/1) 100%
Renal (3/3) 100%
Fluids & Electrolytes (3/3) 100%
Hepatobiliary (1/1) 100%
Passmed