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  • Question 1 - A 32-year old gentleman came to the emergency department, complaining of progressively increasing...

    Correct

    • A 32-year old gentleman came to the emergency department, complaining of progressively increasing weakness in his arms and legs over 5 days. On examination, there is symmetrical weakness on both sides of his face, along with weakness of the proximal and distal muscles of all four limbs. No loss of sensation noted. Deep tendon reflexes could not be elicited and plantar responses were downward. On enquiry, it was revealed that he had an upper respiratory tract infection 10 days ago. The likely diagnosis is:

      Your Answer: Guillain–Barré syndrome

      Explanation:

      Guillain–Barré syndrome (GBS) is an acute, autoimmune polyradiculoneuropathy which affects the peripheral nervous system and is usually triggered by an acute infectious process. 75% patients have a history of acute infection within the past 1–4 weeks, usually respiratory or gastrointestinal. immunisations have also been implicated. The most common form is acute inflammatory demyelinating polyneuropathy. It results in an ascending paralysis with complete loss of deep tendon reflexes. Treatment includes immunoglobulins and supportive care. However, the disease may be fatal due to severe pulmonary complications and dysautonomia.

    • This question is part of the following fields:

      • Neurology
      • Physiology
      26.3
      Seconds
  • Question 2 - A young boy fell from a tree, sustaining an injury to the elbow...

    Correct

    • A young boy fell from a tree, sustaining an injury to the elbow area and damaging the nerve behind the medial epicondyle of the humerus. What is the most likely result from that injury?

      Your Answer: Flexion in the distal interphalangeal joint of digit 5

      Explanation:

      The nerve injured in this situation is the ulnar nerve. It passes posterior to the medial epicondyle of the humerus before going between the two heads of the flexor carpi ulnaris muscle. This nerve supplies the muscles and skin of forearm and hand. At the level of medial epicondyle, the injury will led to paralysis in flexor carpi ulnaris and the ulnar half of the flexor digitorum profundus as well as the palmar interossei and hypothenar muscles in the hand. The correct answer will be that the boy will suffer from inability to flex the distal interphalangeal joint of digit 5

    • This question is part of the following fields:

      • Anatomy
      • Upper Limb
      16.8
      Seconds
  • Question 3 - A 60-year old patient presenting with squamous cell carcinoma of the anal canal...

    Incorrect

    • A 60-year old patient presenting with squamous cell carcinoma of the anal canal was brought in to the oncology ward for chemotherapy. In which of the following lymph nodes of this patient would you likely find metastases?

      Your Answer: Superficial inguinal

      Correct Answer: Internal iliac

      Explanation:

      The efferent lymphatics from the anal canal proceed to the internal iliac lymph nodes. This would most likely form the site of enlargement in the lymphatics.

    • This question is part of the following fields:

      • Anatomy
      • Pelvis
      25.5
      Seconds
  • Question 4 - Which of the following is likely to result in hematocolpos in a 12-year...

    Correct

    • Which of the following is likely to result in hematocolpos in a 12-year old girl?

      Your Answer: Imperforate hymen

      Explanation:

      Hematocolpos means accumulation of blood in vagina and hematometra is accumulation of blood in the uterus. These are most likely seen with an imperforate hymen; which is seen I 1 in 2000 females. If spontaneous resolution does not occur, treatment involves making a hole in the hymen to allow discharge of menstrual blood.

    • This question is part of the following fields:

      • Pathology
      • Women's Health
      6.3
      Seconds
  • Question 5 - What is the result of maltase deficiency in the brush border of the...

    Correct

    • What is the result of maltase deficiency in the brush border of the small intestine?

      Your Answer: Results in increased passage of maltose in stool

      Explanation:

      Maltase is an enzyme produced from the surface cells of the villi, lining the small intestine and aids in hydrolysing the disaccharide maltose, which splits into two molecules of α-glucose. It is done by breaking the glycosidic bond between the ‘first’ carbon of one glucose and the ‘fourth’ carbon of the other (a 1–4 bond). Hence, a deficiency of enzyme maltase will result in the increased passage of maltose in the stool.

    • This question is part of the following fields:

      • Gastroenterology
      • Physiology
      11.3
      Seconds
  • Question 6 - Which of these structures is most likely to be damaged if a patient...

    Correct

    • Which of these structures is most likely to be damaged if a patient loses consciousness days or weeks after an otherwise insignificant head trauma, especially in elderly patients?

      Your Answer: Dural bridging vein

      Explanation:

      A subdural haematoma is a type of hematoma, usually associated with traumatic brain injury, in which blood collects between the dura mater and the pia-arachnoid mater. Symptoms of subdural haemorrhage have a slower onset than those of epidural haemorrhages because the lower pressure veins bleed more slowly than arteries. These injuries are more common in elderly patients, especially those taking antiplatelet or anticoagulant drugs. Oedema and increased intracranial pressure are unusual.

    • This question is part of the following fields:

      • Neurology
      • Pathology
      39.4
      Seconds
  • Question 7 - Which of the deep fasciae located in the anterolateral abdominal wall form the...

    Incorrect

    • Which of the deep fasciae located in the anterolateral abdominal wall form the inguinal ligament?

      Your Answer:

      Correct Answer: External abdominal oblique aponeurosis

      Explanation:

      The inguinal ligament is the inferior border of the aponeurosis of the external oblique abdominis and extends from the anterior superior iliac spine to the pubic tubercle from whence it is reflected backward and laterally to attach to the pectineal line and form the lacunar ligament.

    • This question is part of the following fields:

      • Abdomen
      • Anatomy
      0
      Seconds
  • Question 8 - Which tumour marker is associated with medullary carcinoma of thyroid? ...

    Incorrect

    • Which tumour marker is associated with medullary carcinoma of thyroid?

      Your Answer:

      Correct Answer: Calcitonin

      Explanation:

      Medullary carcinoma of thyroid accounts for 3% of thyroid cancers. It arises from the parafollicular cells (C cells) of the thyroid gland that produce calcitonin. It is often familial and caused by mutation of ret proto-oncogene, but can occasionally be sporadic. The familial cases can also occur as part of MEN syndromes IIA and IIB. The high calcitonin leads to down-regulation of the receptors, which does not affect the calcium levels significantly. Medullary carcinoma of thyroid shows characteristic amyloid deposits that stain positively with Congo red. The initial presentation consists of an asymptomatic thyroid nodule. Many cases are diagnosed due to routine screening of relatives of patients with MEN IIA and IIB. Medullary carcinoma can also cause ectopic production of other hormones/peptides such as adrenocorticotrophic hormone, vasoactive intestinal polypeptide, kallikreins and serotonin.

      Metastasis from medullary carcinoma spread via the lymphatics to cervical and mediastinal nodes, and can also affect the liver, lungs and bone. Diagnosis is by raised serum calcitonin levels. A provocative test with calcium (15 mg/kg intravenously over 4 hours) also aids in diagnosis by leading to excessive secretion of calcitonin. X-ray might also show dense, conglomerate calcification.

      CA-125 is frequently elevated in ovarian carcinomas. CA 15-3 is often associated with breast carcinomas. Alpha-fetoprotein is seen raised in hepatomas and gonadal tumours. Elevated HCG is associated with normal pregnancies, gonadal tumours, and choriocarcinomas. Thyroglobulin is used for surveillance in papillary carcinoma of thyroid. CA 19-9 is used in the management of pancreatic cancer.

    • This question is part of the following fields:

      • Endocrine
      • Pathology
      0
      Seconds
  • Question 9 - A 15-day old baby was brought to the emergency department with constipation for...

    Incorrect

    • A 15-day old baby was brought to the emergency department with constipation for 4 days. On examination, the abdomen of the baby was found to be distended and tender all over. No bowel sounds were heard. A sigmoid colon biopsy was carried out, which showed absent ganglion cells. What is the diagnosis?

      Your Answer:

      Correct Answer: Hirschsprung’s disease

      Explanation:

      Hirschsprung’s disease is characterized by congenital absence of the autonomic plexus (Meissner’s and Auerbach’s plexus) in the intestinal wall. Usually limited to the distal colon, it can occasionally involve the entire colon or even the small bowel. There is abnormal or absent peristalsis in the affected segment, resulting in continuous spasm of smooth muscle and partial/complete obstruction. This causes accumulation of intestinal contents and dilatation of proximal segment. Skip lesions are highly uncommon. This disease is seen early in life with 15% patients presenting in first month, 60% by 1 year of age and 85% by the age of 4 years. Symptoms include severe and complete constipation, abdominal distension and vomiting. Patients with involvement of ultra-short segments might have mild constipation with intervening diarrhoea. In older children, symptoms include failure to thrive, anorexia, and lack of an urge to defecate. On examination, an empty rectum is revealed with stool palpable high up in the colon. If not diagnosed in time, it can lead to Hirschsprung’s enterocolitis (toxic megacolon), which can be fulminant and lead to death. Diagnosis involves a barium enema or a rectal suction biopsy. Barium enema shows a transition in diameter between the dilated, normal colon proximal to the narrowed, affected distal segment. It is to be noted that barium enema should be done without prior preparation, which can dilate the abnormal segment, leading to a false-negative result. A 24-hour post-evacuation film can be obtained in the neonatal period – if the colon is still filled with barium, there is a high likelihood of Hirschsprung’s disease. Full-thickness rectal biopsy is diagnostic by showing the absence of ganglion cells. Acetylcholinesterase staining can be done to highlight the enlarged nerve trunks. Abnormal innervation can also be demonstrated by rectal manometry.

    • This question is part of the following fields:

      • Gastrointestinal; Hepatobiliary
      • Pathology
      0
      Seconds
  • Question 10 - Reed-Sternberg cells are characteristic of: ...

    Incorrect

    • Reed-Sternberg cells are characteristic of:

      Your Answer:

      Correct Answer: Hodgkin's lymphoma

      Explanation:

      Reed-Sternberg cells are characteristic of Hodgkin’s lymphoma.

    • This question is part of the following fields:

      • Haematology
      • Pathology
      0
      Seconds
  • Question 11 - Which of the following conditions is likely to result in splenomegaly, hypochromic anaemia...

    Incorrect

    • Which of the following conditions is likely to result in splenomegaly, hypochromic anaemia and hemochromatosis in a young male?

      Your Answer:

      Correct Answer: β-Thalassaemia

      Explanation:

      Beta-thalassaemia is due to decreased production of β-polypeptide chains, with an autosomal inheritance pattern. Carrier patients (heterozygotes) are asymptomatic and have mild to moderate microcytic anaemia. This is known as thalassaemia minor. Homozygotes (β-thalassaemia major, or Cooley’s anaemia) develop severe anaemia and marrow hyperactivity. The disease presents at 1-2 years of age with severe anaemia and transfusional and absorptive iron overload. Patients also present with jaundice, leg ulcers, massive splenomegaly and cholelithiasis. The disease can also lead to splenic sequestration leading to faster destruction of transfused red blood cells. Increased marrow activity causes thickening of cranial bones. Involvement of long bones is also seen, which can cause pathological fractures and growth impairment. There is iron deposition in various organs, which can lead to heart failure or hepatic failure (leading to cirrhosis). Thalassaemias are suspected in presence of family history, or signs suggesting microcytic haemolytic anaemia. Further test and quantitative haemoglobin studies are useful. In beta-thalassaemia, there is an increase in serum bilirubin, iron and ferritin levels. There is severe anaemia, often with haemoglobin < 6 g/dl. There is an elevated red blood cell count, which are microcytic. Peripheral blood smear is diagnostic with nucleated erythroblasts, target cells, small pale red blood cells, and punctate basophilia.

    • This question is part of the following fields:

      • Haematology
      • Pathology
      0
      Seconds
  • Question 12 - In a cardiac cycle, what event does the opening of the atrioventricular (AV)...

    Incorrect

    • In a cardiac cycle, what event does the opening of the atrioventricular (AV) valves coincide with?

      Your Answer:

      Correct Answer: Beginning of diastole

      Explanation:

      Cardiac diastole refers to the time period when the heart is relaxed after contraction and is preparing to refill with blood. Both ventricular and atrial diastole are together known as complete cardiac diastole. At its beginning, the ventricles relax, causing a drop in the ventricular pressure. As soon as the left ventricular pressure drops below that in left atrium, the mitral valve opens and there is ventricular filling of blood. Similarly, the tricuspid valve opens filling the right atrium.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      0
      Seconds
  • Question 13 - A 42-year old woman presents to the doctor with jaundice. Her investigations show...

    Incorrect

    • A 42-year old woman presents to the doctor with jaundice. Her investigations show conjugated hyperbilirubinemia, raised urine bilirubin levels and low urine urobilinogen levels. What is the likely cause of her jaundice?

      Your Answer:

      Correct Answer: Blockage of the common bile duct

      Explanation:

      The description of the patient here fits the diagnosis of obstructive jaundice or cholestasis, which results in conjugated hyperbilirubinemia. Cholestasis occurs due to impairment of bile flow, which can be anywhere from the liver cell canaliculus to the ampulla of Vater. Causes can be divided into intrahepatic and extrahepatic.

      – Intrahepatic causes include hepatitis, drug toxicity, alcoholic liver disease, primary biliary cirrhosis, cholestasis of pregnancy and metastatic cancer.

      – Extrahepatic causes include common duct stone, pancreatic cancer, benign stricture of the common duct, ductal carcinoma, pancreatitis and sclerosing cholangitis.

      There is absence of bile constituents in the intestine, which causes spillage in the systemic circulation. Symptoms include pale stools, dark urine, pruritus, malabsorption leading to steatorrhea and deficiency of fat-soluble vitamins. Chronic cases can result in osteoporosis or osteomalacia due to vitamin D deficiency and Ca2+ malabsorption. Cholesterol and phospholipid retention produces hyperlipidaemia despite fat malabsorption (although increased liver synthesis and decreased plasma esterification of cholesterol also contribute); triglyceride levels are largely unaffected. The lipids circulate as a unique, low-density lipoprotein called lipoprotein X.

    • This question is part of the following fields:

      • Gastroenterology
      • Physiology
      0
      Seconds
  • Question 14 - The nutcracker effect of the alimentary canal is described as a nutcracker-like compression...

    Incorrect

    • The nutcracker effect of the alimentary canal is described as a nutcracker-like compression caused by the aorta and the superior mesenteric arteries on a certain section of the alimentary canal leading to bowel obstruction. Which of the following parts of the alimentary canal is usually obstructed by this nutcracker compression of the two arteries?

      Your Answer:

      Correct Answer: Duodenum

      Explanation:

      The ‘nutcracker effect’ is only seen in one part of the alimentary canal, and that is in the third part of the duodenum. This can happen when the superior mesenteric artery that passes across the duodenum and the aorta, posteriorly to the third part of the duodenum enlarges and starts compressing the duodenum. The result is an obstructed duodenum that inhibits passage of food.

    • This question is part of the following fields:

      • Abdomen
      • Anatomy
      0
      Seconds
  • Question 15 - A 34-year-old woman with severe burns, presented to casualty with a blood pressure...

    Incorrect

    • A 34-year-old woman with severe burns, presented to casualty with a blood pressure of 75/40 mmHg and pulse of 172/minute. Obviously the patient is in shock. Which type of shock is it more likely to be?

      Your Answer:

      Correct Answer: Hypovolaemic shock

      Explanation:

      Shock is a life-threatening condition that occurs when the organs and tissues of the body are not receiving a sufficient flow of blood. Lack of blood flow, oxygen and nutrients results in the inability to function properly and damage to many organs. Shock requires immediate treatment because, if left untreated the impaired tissue perfusion and cellular hypoxia can cause irreversible tissue injury, collapse, coma or even death. There are various types of physiological shock, including: cardiogenic (due to heart damage), hypovolaemic (due to low total volume of blood or plasma), neurogenic (due to nervous system damage), septic (due to infections) and anaphylactic shock (due to allergic reactions). Hypovolaemic shock can be caused by blood loss due to trauma, internal bleeding or other fluid loss due to severe burns, prolonged diarrhoea, vomiting and sweating.

    • This question is part of the following fields:

      • Cardiovascular
      • Pathology
      0
      Seconds
  • Question 16 - What is the linea aspera: ...

    Incorrect

    • What is the linea aspera:

      Your Answer:

      Correct Answer: Serves as an attachment for adductors of the thigh

      Explanation:

      The linea aspera is a prominent longitudinal ridge or crest on the middle third of the femur. It has a medial and a lateral lip and a narrow, rough, intermediate line. The vastus medialis arises from the medial lip of the linea aspera and has superior and inferior prolongations. The vastus lateralis takes origin from the lateral lip . The adductor magnus is inserted into the linea aspera. Two muscles are attached between the vastus lateralis and the adductor magnus: the gluteus maximus is inserted above and the short head of the biceps femoris arises below. Four muscles are inserted between the adductor magnus and the vastus medialis: the iliacus and pectineus superiorly, and the adductor brevis and adductor longus inferiorly.

    • This question is part of the following fields:

      • Anatomy
      • Lower Limb
      0
      Seconds
  • Question 17 - A 60-year old man with a left-sided indirect inguinal hernia underwent emergency surgery...

    Incorrect

    • A 60-year old man with a left-sided indirect inguinal hernia underwent emergency surgery to relieve large bowel obstruction resulting from a segment of the bowel being strangulated in the hernial sac. The most likely intestinal segment involved is:

      Your Answer:

      Correct Answer: Sigmoid colon

      Explanation:

      The sigmoid colon is the most likely segment involved as it is mobile due to the presence of the sigmoid mesocolon. The descending colon, although on the left side, is a bit superior and is also retroperitoneal. The ascending colon and caecum are on the right side of the abdomen. The rectum is too inferior to enter the deep inguinal ring and the transverse colon is too superior to be involved.

    • This question is part of the following fields:

      • Abdomen
      • Anatomy
      0
      Seconds
  • Question 18 - A 55- year old male patient with cancer of the head of the...

    Incorrect

    • A 55- year old male patient with cancer of the head of the pancreas was to undergo whipple's operation to have the tumour removed. During the surgery, the surgeon had to ligate the inferior pancreaticoduodenal artery to stop blood supply to the head of the pancreas. Which of the following arteries does the inferior pancreaticoduodenal artery branch from?

      Your Answer:

      Correct Answer: Superior mesenteric artery

      Explanation:

      The inferior pancreaticoduodenal artery is a branch of the superior mesenteric artery or from the first intestinal branch of the superior mesenteric artery. Once given off, it runs to the right between the pancreatic head and the duodenum and then ascends to form an anastomosis with the superior pancreaticoduodenal artery.

    • This question is part of the following fields:

      • Abdomen
      • Anatomy
      0
      Seconds
  • Question 19 - Which of the following muscles may be affected by a fracture to the...

    Incorrect

    • Which of the following muscles may be affected by a fracture to the tuberosity on the medial surface of the right navicular bone?

      Your Answer:

      Correct Answer: Tibialis posterior

      Explanation:

      The navicular bone is situated at the medial side of the tarsus, between the talus and the cuneiform bones. Its medial surface presents a rounded tuberosity, the lower part of which gives attachment to part of the tendon of the tibialis posterior.

    • This question is part of the following fields:

      • Anatomy
      • Lower Limb
      0
      Seconds
  • Question 20 - A patient had sudden complete loss of vision of the right eye. Fundoscopy...

    Incorrect

    • A patient had sudden complete loss of vision of the right eye. Fundoscopy showed the distinct cherry red spot on the retina. Which of the following arteries was occluded?

      Your Answer:

      Correct Answer: Central artery of the retina

      Explanation:

      The central retinal artery supplies all the nerve fibres that form the optic nerve, which carries the visual information to the lateral geniculate nucleus of the thalamus. Thus if the central retinal artery gets occluded, there is complete loss of vision in that eye and the entire retina (with the exception of the fovea) becomes pale, swollen and opaque while the central fovea still appears reddish (this is because the choroid colour shows through). This is the basis of the famous Cherry red spot seen on examination of the retina on fundoscopy of a central retinal artery occlusion (CRAO).

    • This question is part of the following fields:

      • Anatomy
      • Head & Neck
      0
      Seconds
  • Question 21 - During a laparoscopic inguinal hernia repair, the surgeon finds an artery in the...

    Incorrect

    • During a laparoscopic inguinal hernia repair, the surgeon finds an artery in the extraperitoneal connective tissue (preperitoneal fat) that courses vertically and just medial to the bowel as the bowel passes through the abdominal wall. Which artery is this?

      Your Answer:

      Correct Answer: Inferior epigastric

      Explanation:

      The inferior epigastric artery comes from the external iliac artery just above the inguinal ligament to curve forward in the subperitoneal tissue and then ascend obliquely along the medial margin of the deep inguinal ring. It continues to ascend between the rectus abdominis and the posterior lamella of its sheath after piercing the fascia transversalis and passing anterior to the linea semicircularis. Finally it gives off numerous branches that anastomose above the umbilicus with the superior epigastric branch of the internal mammary artery and with the lower intercostal arteries. As this artery ascends obliquely upwards from its origin it lies along the lower medial margins of the deep inguinal ring and posterior to the start of the spermatic cord. It is found in the preperitoneal fat of the abdomen lying just superficial to the peritoneum and forms the lateral umbilical fold. Hernias that pass lateral to this are indirect and medial to this, direct hernias.

      The deep circumflex artery travels along the iliac crest on the inner surface of the abdominal wall. It is very lateral to the abdominal wall and hernias would pass medial to it.

      The superficial circumflex iliac, superficial epigastric, superficial external pudendal arteries are all superficial arteries found in the superficial fascia.

    • This question is part of the following fields:

      • Abdomen
      • Anatomy
      0
      Seconds
  • Question 22 - Which portion of the renal tubule absorbs amino acids and glucose? ...

    Incorrect

    • Which portion of the renal tubule absorbs amino acids and glucose?

      Your Answer:

      Correct Answer: Proximal convoluted tubule

      Explanation:

      In relation to the morphology of the kidney as a whole, the convoluted segments of the proximal tubules are confined entirely to the renal cortex. Glucose, amino acids, inorganic phosphate and some other solutes are reabsorbed via secondary active transport in the proximal renal tubule through co-transport channels driven by the sodium gradient.

    • This question is part of the following fields:

      • Physiology
      • Renal
      0
      Seconds
  • Question 23 - The operating surgeon notices a structure lying alongside a herniated mass whilst repairing...

    Incorrect

    • The operating surgeon notices a structure lying alongside a herniated mass whilst repairing an indirect inguinal hernia in a female patient. Which structure could this be?

      Your Answer:

      Correct Answer: Round ligament of the uterus

      Explanation:

      The main structure traversing the inguinal canal in women is the round ligament. In men, it is the spermatic cord.

      The iliohypogastric nerve innervates the abdominal wall and runs between the transversus abdominis and internal oblique muscles before piercing the internal oblique at the anterior superior iliac spine to run between the internal and external obliques.

      The inferior epigastric artery is between the peritoneum and the transversus abdominis creating the lateral umbilical fold.

      The ovarian artery and the ovarian vein are branches from the descending aorta and inferior vena cava that supply the ovary in the pelvic cavity.

      The pectineal ligament is a thick fascial layer over the pectineal line of the pubis. It doesn’t traverse the canal.

      The broad ligament if found on the lateral sides of the uterus.

    • This question is part of the following fields:

      • Abdomen
      • Anatomy
      0
      Seconds
  • Question 24 - If your EEG shows waves with a frequency range of 8-12 Hz, the...

    Incorrect

    • If your EEG shows waves with a frequency range of 8-12 Hz, the waves most likely to be seen are:

      Your Answer:

      Correct Answer: Alpha

      Explanation:

      Electroencephalography (EEG) is the neurophysiological measurement of the electrical activity of the brain. It is done by placing electrodes on the scalp or subdurally. In reality, the electrical currents are not measured, but rather the voltage differences between different parts of the brain. Four major types of EEG activity are recognized, which are alpha, beta, delta and theta.

      Alpha waves, also known as Berger’s waves ranges in frequency from 8-12 Hz. Best detected with eyes closed, alpha waves are characteristic of a relaxed, alert state of consciousness. An alpha-like normal variant called mu is sometimes seen over the motor cortex (central scalp) and attenuates with movement or, rather, with the intention to move.

    • This question is part of the following fields:

      • Neurology
      • Physiology
      0
      Seconds
  • Question 25 - Macrolides are a group of antibiotics commonly used to treat respiratory tract and...

    Incorrect

    • Macrolides are a group of antibiotics commonly used to treat respiratory tract and soft-tissue infections. Which of the following antibiotics is a macrolide?

      Your Answer:

      Correct Answer: Erythromycin

      Explanation:

      Erythromycin is a macrolide antibiotic used in the treatment of several bacterial infections, including respiratory tract infections, skin infections, chlamydia infections, pelvic inflammatory disease, and syphilis. It may also be used during pregnancy to prevent Group B streptococcal infection in the new-born.

    • This question is part of the following fields:

      • Pathology
      • Pharmacology
      0
      Seconds
  • Question 26 - A young man came to the emergency room after an accident. The anterior...

    Incorrect

    • A young man came to the emergency room after an accident. The anterior surface of his wrist was lacerated with loss of sensation over the thumb side of his palm. Which nerves have been damaged?

      Your Answer:

      Correct Answer: Median

      Explanation:

      The median nerve provides cutaneous innervation to the skin of the palmar radial three and a half fingers. Also the site of injury indicates that the medial nerve may have been injured as it passes into the hand by crossing over the anterior wrist.

    • This question is part of the following fields:

      • Anatomy
      • Upper Limb
      0
      Seconds
  • Question 27 - A 33-year old lady presented to the gynaecology clinic with amenorrhoea for 6...

    Incorrect

    • A 33-year old lady presented to the gynaecology clinic with amenorrhoea for 6 months and a recent-onset of milk discharge from her breasts. She was not pregnant or on any medication. On enquiry, she admitted to having frequent headaches the last 4 months. Which of the following findings would you expect to see in her condition?

      Your Answer:

      Correct Answer: Hyperprolactinaemia

      Explanation:

      Excessively high levels of prolactin in the blood is called hyperprolactinaemia. Normally, prolactin levels are less than 580 mIU/l in females and less than 450 mIU/l in men. The biologically inactive macroprolactin can lead to a false high reading. However, the patient remains asymptomatic. Dopamine down-regulates prolactin whereas oestrogen upregulates it. Hyperprolactinaemia can be caused due to lack of inhibition (compression of pituitary stalk or low dopamine levels), or increased production due to a pituitary adenoma (prolactinoma). Either of these causes can lead to a prolactin level of 1000-5000 mIU/l. However, levels more than 5000mIU/l are usually associated due to an adenoma and >100,000 mIU/l are seen in macroadenomas (tumours < 1cm in diameter). Increased prolactin causes increased dopamine release from the arcuate nucleus of hypothalamus. This increased dopamine in turn, inhibits the GnRH (Gonadotrophin Releasing Hormone) thus blocking gonadal steroidogenesis resulting in the symptoms of hyperprolactinaemia. In women, it includes hypoestrogenism, anovulatory infertility, decreased or irregular menstruation or complete amenorrhoea. It can even cause production of breast milk, loss of libido, vaginal dryness and osteoporosis. In men, the symptoms include impotence, decreased libido, erectile dysfunction and infertility. In men, treatment can be delayed due to late diagnosis as they have no reliable indicator such as menstruation that might indicate a problem. Most of the male patients seek help only when headaches and visual defects start to surface.

    • This question is part of the following fields:

      • Endocrine
      • Pathology
      0
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  • Question 28 - Skin infiltration by neoplastic T lymphocytes is seen in: ...

    Incorrect

    • Skin infiltration by neoplastic T lymphocytes is seen in:

      Your Answer:

      Correct Answer: Mycosis fungoides

      Explanation:

      Mycosis fungoides is a chronic T-cell lymphoma that involves the skin and less commonly, the internal organs such as nodes, liver, spleen and lungs. It is usually diagnosed in patients above 50 years and the average life expectancy is 7-10 years. It is insidious in onset and presents as a chronic, itchy rash, eventually spreading to involve most of the skin. Lesions are commonly plaque-like, but can be nodular or ulcerated. Symptoms include fever, night sweats and weight loss. Skin biopsy is diagnostic. However, early cases may pose a challenge due to fewer lymphoma cells. The malignant cells are mature T cells (T4+, T11+, T12+). The epidermis shows presence of characteristic Pautrier’s micro abscesses are present in the epidermis.

    • This question is part of the following fields:

      • Haematology
      • Pathology
      0
      Seconds
  • Question 29 - A teenage Somalian boy presents with a complaint of an enlarged lower jaw....

    Incorrect

    • A teenage Somalian boy presents with a complaint of an enlarged lower jaw. His blood film shows blast cells and macrophages. Which virus is responsible for this?

      Your Answer:

      Correct Answer: Epstein–Barr virus

      Explanation:

      Burkitt’s lymphoma is a type of non-Hodgkin’s lymphoma. Histologically it is characterised by a starry sky appearance due to numerous neoplastic macrophages which are required to clear the rapidly dividing tumour cells/blast cells. Burkitt’s lymphoma commonly affects the jaw bone, forming a huge tumour mass. It is associated with translocation of c-myc gene and has three types: 1) endemic/African type, 2)sporadic and 3)immunodeficiency-associated. The first type is strongly associated with EBV.

    • This question is part of the following fields:

      • General
      • Physiology
      0
      Seconds
  • Question 30 - When a patient is standing erect, pleural fluid would tend to accumulate in...

    Incorrect

    • When a patient is standing erect, pleural fluid would tend to accumulate in which part of the pleural space?

      Your Answer:

      Correct Answer: Costodiaphragmatic recess

      Explanation:

      The costo-diaphragmatic recess is the lowest extent of the pleural cavity or sac. Any fluid in the pleura will by gravity accumulate here when a patient is standing erect.

    • This question is part of the following fields:

      • Anatomy
      • Thorax
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  • Question 31 - What are the derivatives of the first brachial arch? ...

    Incorrect

    • What are the derivatives of the first brachial arch?

      Your Answer:

      Correct Answer: Gives rise to the sphenomandibular ligament

      Explanation:

      The first brachial arch (mandibular) gives rise to the mandibular and maxillary processes. Muscles and bones of this process originate within the arch’s mesoderm. The first arch cartilage (Meckel’s) ossifies to form the incus and malleus of the middle ear. Its perichondrium gives rise to he sphenomandibular ligament and through intermembraneous ossification after the mandible forms, the rest of the cartilage disappears. Muscles of the first arch include: mylohyoid, tensor tympany and palati, temporalis, masseter and lateral pterygoids and the anterior belly of the epigastric. This first arch is supplied by the trigeminal nerve.

    • This question is part of the following fields:

      • Anatomy
      • Embryology
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  • Question 32 - A histopathological analysis of a specimen showed loss of individual cell structure with...

    Incorrect

    • A histopathological analysis of a specimen showed loss of individual cell structure with karyorrhexis and fragmentation. The overall integrity of the tissue structure is preserved. This is typical of which of the following pathologies?

      Your Answer:

      Correct Answer: Viral hepatitis

      Explanation:

      Viral infections will cause necrosis of the hepatocytes with characteristic changes of karyorrhexis and cell fragmentation.

      Brown atrophy of the heart is due to accumulation of lipofuscin in the myocardium.

      Tissue destruction associated with transplant rejection leads to widespread loss of structural integrity.

      Single cell necrosis is not characteristically seen in chronic alcoholic liver.

      Barbiturate overdose will result in hypertrophy of the smooth endoplasmic reticulum.

      Carcinoma insitu will cause dysplastic cells without the overall structural integrity being disrupted.

      Atrophy is due to apoptosis with ordered cellular fragmentation and phagocytosis and will not induce an inflammatory process unlike necrosis.

    • This question is part of the following fields:

      • Cell Injury & Wound Healing
      • Pathology
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  • Question 33 - The optic foramen, superior orbital fissure, foramen ovale, foramen rotundum and foramen sinosum...

    Incorrect

    • The optic foramen, superior orbital fissure, foramen ovale, foramen rotundum and foramen sinosum are all located on which bone at the base of the skull?

      Your Answer:

      Correct Answer: Sphenoid

      Explanation:

      The sphenoid bone consists of two parts, a central part and two wing-like structures that extend sideways towards each side of the skull. It forms the base of the skull, and floor and sides of the orbit. On its central part lies the optic foramen. The foramen ovale, foramen spinosum and foramen rotundum lie on its great wing while the superior orbital fissure lies on its lesser wing.

    • This question is part of the following fields:

      • Anatomy
      • Head & Neck
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  • Question 34 - An enlarged lymph node which shows well-defined, prominent paracortical follicles with germinal centres...

    Incorrect

    • An enlarged lymph node which shows well-defined, prominent paracortical follicles with germinal centres is most likely from which of the following patients?

      Your Answer:

      Correct Answer: A 5-year-old boy with a sore throat and runny nose

      Explanation:

      Lymphadenopathy is common in children and is usually reactive in nature. The description fits that of a benign, reactive lymph node.

    • This question is part of the following fields:

      • Haematology
      • Pathology
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  • Question 35 - A 45-year old farmer was referred to the surgical clinic with complaints of...

    Incorrect

    • A 45-year old farmer was referred to the surgical clinic with complaints of pain in his right hypochondrium. Investigations confirmed the diagnosis of hepatocellular carcinoma with malignant ascites. According to you, what is the most likely cause of HCC in this patient?

      Your Answer:

      Correct Answer: Aflatoxin

      Explanation:

      Aflatoxins are naturally occurring toxins produced by the Aspergillus fungus (most often, A. flavus and A. parasiticus). These organisms are common and their native habitat is soil, decaying vegetation and grains. They can contaminate the grain before harvest or after storage, more likely in high-humidity (at least 7%) or high temperature environment of after stressful conditions like drought. Aflatoxins are mycotoxins and also carcinogenic. They get metabolized in the liver to an epoxide, aflatoxin M1. High exposure can lead to acute necrosis, cirrhosis or liver carcinoma. These substances can cause haemorrhage, acute liver damage, oedema, and alteration in digestion, absorption and/or metabolism of nutrients. Although humans are susceptible to these toxins like all other animals, they have a high tolerance level and hence, rarely develop acute aflatoxicosis. However, children are particularly susceptible to exposure leading to growth impairment and delayed development. Chronic exposure carries a high risk of hepatic cancer, due to intercalation of its metabolite aflatoxin M1 into the DNA and alkylation of the bases because of its epoxide moiety.

    • This question is part of the following fields:

      • Gastrointestinal; Hepatobiliary
      • Pathology
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  • Question 36 - A 13 year old girl presented with signs of shortness of breath, chest...

    Incorrect

    • A 13 year old girl presented with signs of shortness of breath, chest pain, non-productive cough, oedema of the lower extremities and cyanosis of the fingertips. She has a history of a ventricular septal defect not surgically corrected. The most probable cause of these symptoms is:

      Your Answer:

      Correct Answer: Shunt reversal

      Explanation:

      A ventricular septal defect (VSD) is a common form of congenital heart defects and is characterised by the presence of a hole in the wall that separates the right from the left ventricle. Medium or large defects can cause many complications. One of these complication is Eisenmenger syndrome, characterised by reversal of the shunt (from left-to-right shunt into a right-to-left) ,cyanosis and pulmonary hypertension.

    • This question is part of the following fields:

      • Cardiovascular
      • Pathology
      0
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  • Question 37 - Multiple, non-tender lymphadenopathy with biopsy showing several crowded follicles of small, monomorphic lymphocytes...

    Incorrect

    • Multiple, non-tender lymphadenopathy with biopsy showing several crowded follicles of small, monomorphic lymphocytes and the absence of Reed-Sternberg cells is seen in which of the following?

      Your Answer:

      Correct Answer: Poorly differentiated lymphocytic lymphoma

      Explanation:

      Malignant lymphoma usually causes non-tender lymphadenopathy, unlike the tender lymphadenopathy caused by infections (including infectious mononucleosis caused by Epstein-Barr virus). Also, the lymphoid hyperplasia seen in infectious mononucleosis is benign and polyclonal.

    • This question is part of the following fields:

      • Haematology
      • Pathology
      0
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  • Question 38 - In a splenectomy procedure, special care is emphasized on the preservation of the...

    Incorrect

    • In a splenectomy procedure, special care is emphasized on the preservation of the tail of the pancreas that is closely associated with the spleen to avoid post operative pancreatic fistula. As a general surgeon conducting a splenectomy where are you most likely to find the tail of the pancreas in the abdominal cavity?

      Your Answer:

      Correct Answer: Splenorenal ligament

      Explanation:

      The tail of the pancreas is the only intraperitoneal part of the pancreas and is found contained in the splenorenal ligament of the peritoneal cavity. The splenorenal ligament is derived from the peritoneum where the wall of the general peritoneal cavity connects to the omental bursa between the spleen and the left kidney. This ligament contains the splenic vessels and the tail of the pancreas.

      The gastrocolic ligament stretches from the greater curvature of the stomach to the transverse colon, connecting the two.

      The gastrosplenic ligament is derived from the greater omentum and is the structure that connects the stomach to the hilum of the spleen. The gastrosplenic ligament continues from the splenic flexure of the colon to the diaphragm and acts as a support to the spleen.

      The transverse colon is connected to the abdominal wall by the mesocolon ligament.

      The falciform ligament on the other hand, attaches the liver to the ventral wall of the abdomen.

      The hepatoduodenal ligament connects the porta hepatis of the liver to the superior part of the duodenum.

    • This question is part of the following fields:

      • Abdomen
      • Anatomy
      0
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  • Question 39 - A 34-year-old woman with pelvic inflammatory disease is administered ceftriaxone. The subclass of...

    Incorrect

    • A 34-year-old woman with pelvic inflammatory disease is administered ceftriaxone. The subclass of antibiotics that ceftriaxone belongs to is:

      Your Answer:

      Correct Answer: Third-generation cephalosporins

      Explanation:

      Ceftriaxone is a third-generation cephalosporin antibiotic. It has a broad spectrum of activity against Gram-positive and Gram-negative bacteria. Its indications include middle ear infections, endocarditis, meningitis, pneumonia, bone and joint infections, intra-abdominal infections, skin infections, urinary tract infections, gonorrhoea, and pelvic inflammatory disease.

    • This question is part of the following fields:

      • Pathology
      • Pharmacology
      0
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  • Question 40 - A 50-year old gentleman who suffered a stroke was brought to the emergency...

    Incorrect

    • A 50-year old gentleman who suffered a stroke was brought to the emergency department by his relatives. The patient however denied the presence of paralysis of his left upper and lower limbs. What is the most likely site of the lesion in this patient?

      Your Answer:

      Correct Answer: Right posterior parietal cortex

      Explanation:

      A large injury to the non-dominant parietal cortex can make the patient neglect or refuse to acknowledge the presence of paralysis on the contralateral side. This can also involve the perception of the external world. Smaller injuries in this area which involve the precentral gyrus (primary motor cortex) or postcentral gyrus (primary sensory cortex) cause contralateral spastic paralysis or contralateral loss of tactile sensation respectively. A lesion in posterior inferior gyrus of the dominant frontal lobe results in motor aphasia. Involvement of the posterior superior gyrus of the dominant frontal lobe produces sensory aphasia.

    • This question is part of the following fields:

      • Neurology
      • Physiology
      0
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  • Question 41 - Glucose is the most important source of energy for cellular respiration. The transport...

    Incorrect

    • Glucose is the most important source of energy for cellular respiration. The transport of glucose in the renal tubular cells occurs via:

      Your Answer:

      Correct Answer: Secondary active transport with sodium

      Explanation:

      In 1960, Robert K. Crane presented for the first time his discovery of the sodium-glucose cotransport as the mechanism for glucose absorption. Glucose transport through biological membranes requires specific transport proteins. Transport of glucose through the apical membrane of renal tubular as well as intestinal epithelial cells depends on the presence of secondary active Na+–glucose symporters, SGLT-1 and SGLT-2, which concentrate glucose inside the cells, using the energy provided by co-transport of Na+ ions down their electrochemical gradient.

    • This question is part of the following fields:

      • Physiology
      • Renal
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  • Question 42 - A biopsy taken from the respiratory passage of a 37 year old male,...

    Incorrect

    • A biopsy taken from the respiratory passage of a 37 year old male, chronic smoker will mostly likely show which cellular adaptation?

      Your Answer:

      Correct Answer: Stratified squamous metaplasia

      Explanation:

      Metaplasia is a change in the cell type caused in part due to an extrinsic stress on the organ. It involves a change in the surface epithelium from one cell type to the another, most commonly squamous to columnar. This is a reversible process, and removal of the stress should theoretically reverse the surface epithelium back to normal morphology. Respiratory tract metaplasia is a classic example, in which the normal pseudostratified columnar epithelium is replaced by stratified squamous epithelium to better cope with the stress. Under continuous stress metaplasia can progress to dysplasia which is a disordered growth of cells eventually leading to the development of carcinoma.

    • This question is part of the following fields:

      • Cell Injury & Wound Healing; Respiratory
      • Pathology
      0
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  • Question 43 - A patient with this condition has extracellular fluid volume expansion: ...

    Incorrect

    • A patient with this condition has extracellular fluid volume expansion:

      Your Answer:

      Correct Answer: Nephrotic syndrome

      Explanation:

      Nephrotic syndrome is a syndrome comprising of signs of nephrosis, including proteinuria, hypoalbuminemia, and oedema. It is a component of glomerulonephritis, in which different degrees of proteinuria occur. Essentially, loss of protein through the kidneys leads to low protein levels in the blood , which causes water to be drawn into soft tissues (oedema). Severe hypoalbuminemia can also cause a variety of secondary problems, such as water in the abdominal cavity (ascites), around the heart or lung (pericardial effusion, pleural effusion), high cholesterol, loss of molecules regulating coagulation (hence increased risk of thrombosis). The most common sign is excess fluid in the body due to the serum hypoalbuminemia. Lower serum oncotic pressure causes fluid to accumulate in the interstitial tissues. Sodium and water retention aggravates the oedema.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Pathology
      0
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  • Question 44 - Both the arytenoid muscles and the lateral cricoarytenoid muscles perform this action on...

    Incorrect

    • Both the arytenoid muscles and the lateral cricoarytenoid muscles perform this action on the glottis:

      Your Answer:

      Correct Answer: Adduction

      Explanation:

      Both the arytenoid and the cricoartenoid muscles close the glottis. The lateral cricoarytenoid muscles extend from the lateral cricoid cartilage to the muscular process of the arytenoid cartilage. By rotating the arytenoid cartilages medially, these muscles adduct the vocal cords and thereby close the rima glottidis. The arytenoid muscle adducts or approximates the arytenoid cartilages, and thus closes the aperture of the glottis.

    • This question is part of the following fields:

      • Anatomy
      • Head & Neck
      0
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  • Question 45 - Cyclophosphamide is used as a chemotherapy and immunosuppressant agent and is indicated in...

    Incorrect

    • Cyclophosphamide is used as a chemotherapy and immunosuppressant agent and is indicated in various diseases. One of the most severe complications of its use is cancer of the:

      Your Answer:

      Correct Answer: Urinary bladder

      Explanation:

      Cyclophosphamide is used to treat various types of cancer and autoimmune disorders. The main use of cyclophosphamide is in combination with other chemotherapy agents in the treatment of lymphomas, some forms of leukaemia and some solid tumours. Side-effects include nausea and vomiting, bone marrow suppression, stomach ache, diarrhoea, darkening of the skin/nails, alopecia, lethargy, and haemorrhagic cystitis. Cyclophosphamide is itself carcinogenic, potentially causing transitional cell carcinoma of the bladder as a long-term complication.

    • This question is part of the following fields:

      • Pathology
      • Pharmacology
      0
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  • Question 46 - The vascular structure found on the right side of the fifth lumbar vertebra...

    Incorrect

    • The vascular structure found on the right side of the fifth lumbar vertebra is?

      Your Answer:

      Correct Answer: Inferior vena cava

      Explanation:

      The most likely vascular structure is the inferior vena cava. The inferior vena cava is formed by the joining of the two common iliac arteries, the right and the left iliac artery, at the level of the fifth lumbar vertebra( L5). The inferior vena cava passes along the right side of the vertebral column. It enters the thoracic cavity into the underside of the heart through the caval opening of the diaphragm at the level of the eight thoracic vertebra (T8).

    • This question is part of the following fields:

      • Abdomen
      • Anatomy
      0
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  • Question 47 - A 54-year-old woman with amyotrophic lateral sclerosis is diagnosed with respiratory acidosis. The...

    Incorrect

    • A 54-year-old woman with amyotrophic lateral sclerosis is diagnosed with respiratory acidosis. The patient’s renal excretion of potassium would be expected to:

      Your Answer:

      Correct Answer: Fall, since tubular secretion of potassium is inversely coupled to acid secretion

      Explanation:

      Respiratory acidosis is a medical emergency in which decreased ventilation (hypoventilation) increases the concentration of carbon dioxide in the blood and decreases the blood’s pH (a condition generally called acidosis). Secretion of acid and potassium by the renal tubule are inversely related. So, increased excretion of H+ during renal compensation for respiratory acidosis will result in decreased secretion (or increased retention) of potassium ions, with the result that the body’s potassium store rises. An increase in K+ excretion would be associated with renal compensation for respiratory alkalosis. The filtered load of K+depends only on K+ plasma concentration and glomerular filtration rate, not on plasma pH.

    • This question is part of the following fields:

      • Physiology
      • Renal
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  • Question 48 - The mandibular nerve, which is the largest of the 3 divisions of the...

    Incorrect

    • The mandibular nerve, which is the largest of the 3 divisions of the trigeminal nerve, exits the cranial cavity through which foramen?

      Your Answer:

      Correct Answer: Foramen ovale

      Explanation:

      At the base of the skull the foramen ovale is one of the larger of the several holes that transmit nerves through the skull. The following structures pass through foramen ovale: mandibular nerve, motor root of the trigeminal nerve, accessory meningeal artery, lesser petrosal nerve, a branch of the glossopharyngeal nerve, emissary vein connecting the cavernous sinus with the pterygoid plexus of veins and occasionally the anterior trunk of the middle meningeal vein.

    • This question is part of the following fields:

      • Anatomy
      • Head & Neck
      0
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  • Question 49 - The lateral thoracic artery: ...

    Incorrect

    • The lateral thoracic artery:

      Your Answer:

      Correct Answer: Accompanies the long thoracic nerve to the serratus anterior muscle

      Explanation:

      The thoracic nerve, along with the lateral thoracic artery, follow the pectoralis minor to the side of the chest which supplies the serratus anterior and the pectoralis. It then sends branches across the axilla to the axillary glands and subscapularis. The pectoral branch of the thoraco-acromial anastomoses with the internal mammary, subscapular and intercostal arteries, which in women, supply an external mammary branch.

    • This question is part of the following fields:

      • Anatomy
      • Breast
      0
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  • Question 50 - A 55 year old man presented with a 4 day history of cough...

    Incorrect

    • A 55 year old man presented with a 4 day history of cough and fever. His sputum culture showed the presence of Strep pneumoniae. Which of the following substances produced by the inflammatory cells will result in effective clearance of this organism from the lung parenchyma?

      Your Answer:

      Correct Answer: Hydrogen peroxide

      Explanation:

      Hydrogen peroxide is produced by myeloperoxidase to form a potent oxidant that eliminates bacteria, but is not effective in chronic granulomatous diseases.

      Platelet activating factor will lead to the activation, adhesion and aggregation of platelets but will not directly kill bacteria.

      Prostaglandins cause vasodilation but do not activate neutrophils.

      Kallikrein promotes formation of bradykinin that leads to vasodilation.

      Leukreines increase vascular permeability.

      Cytokines are communicating molecules between immune cells but directly will not kill bacteria.

      Interleukins will regulate the immune response.

    • This question is part of the following fields:

      • Inflammation & Immunology; Respiratory
      • Pathology
      0
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SESSION STATS - PERFORMANCE PER SPECIALTY

Neurology (2/2) 100%
Physiology (2/2) 100%
Anatomy (1/2) 50%
Upper Limb (1/1) 100%
Pelvis (0/1) 0%
Pathology (2/2) 100%
Women's Health (1/1) 100%
Gastroenterology (1/1) 100%
Passmed