-
Question 1
Correct
-
Which of the following is the first symptom or sign of a congenital cataract in a 1-year old?
Your Answer: A strabismus
Explanation:The most obvious sign of a congenital cataract in a child less than 1 year would be a strabismus/squint. A 12 month old child is unable to complain of loss of visual acuity and the child is likely to see well in one eye ruling out clumsiness. Amblyopia may also be difficult to test at this age unless it presents with the strabismus. ‘White’ red reflexes usually only present in very mature congenital cataracts.
-
This question is part of the following fields:
- Ophthalmology
-
-
Question 2
Correct
-
A 16-year-old female presents to the emergency department with recurrent epistaxis and a history of menorrhagia. The physician suspects Von Willebrand disease and requests for blood tests. Lab investigations reveal a prolonged bleeding time and thrombocytopenia. What is the most likely diagnosis?
Your Answer: Bernard - Soulier syndrome
Explanation:Bernard- Soulier Syndrome results from a deficiency of platelet glycoprotein protein Ib, which mediates the initial interaction of platelets with the subendothelial components via the von Willebrand protein. It is a rare but severe bleeding disorder. Platelets do not aggregate to ristocetin. The platelet count is low, but, characteristically, the platelets are large, often the size of red blood cells, and may be missed on complete blood counts because most automatic counters do not count them as platelets.
-
This question is part of the following fields:
- Haematology And Oncology
-
-
Question 3
Incorrect
-
A new-born infant is profoundly hypotonic at birth| he has a good heart rate but is in respiratory distress. Which of the following syndromes is most likely to be the cause?
Your Answer: Down syndrome
Correct Answer: Werdnig–Hoffman disease (spinomuscular atrophy type 1)
Explanation:The spinal muscular atrophies (SMAs) comprise a group of autosomal recessive disorders characterized by progressive weakness of the lower motor neurons. several types of spinal muscular atrophies have been described based on age when accompanying clinical features appear. The most common types are acute infantile (SMA type I, or Werdnig-Hoffman disease), chronic infantile (SMA type II), chronic juvenile (SMA type III or Kugelberg-Welander disease), and adult-onset (SMA type IV) forms.SMA type I – Acute infantile or Werdnig-Hoffman diseasePatients present before 6 months of age, with 95% of patients having signs and symptoms by 3 months. They have severe, progressive muscle weakness and flaccid or reduced muscle tone (hypotonia). Bulbar dysfunction includes poor suck ability, reduced swallowing, and respiratory failure. Patients have no involvement of the extraocular muscles, and facial weakness is often minimal or absent. They have no evidence of cerebral involvement, and infants appear alert.Reports of impaired fetal movements are observed in 30% of cases, and 60% of infants with SMA type I are floppy babies at birth. Prolonged cyanosis may be noted at delivery. In some instances, the disease can cause fulminant weakness in the first few days of life. Such severe weakness and early bulbar dysfunction are associated with short life expectancy, with a mean survival of 5.9 months. In 95% of cases, infants die from complications of the disease by 18 months.
-
This question is part of the following fields:
- Neonatology
-
-
Question 4
Correct
-
A 15-year-old boy, who has a family history of Gilbert's syndrome, presents with signs and symptoms of hepatic dysfunction. Liver function tests reveal raised unconjugated bilirubin levels. Subsequent genetic testing led to a diagnosis of Gilbert's syndrome. What is the reason for the unconjugated hyperbilirubinemia in Gilbert's syndrome?
Your Answer: Reduced levels of UDP-glucuronosyl transferase-1
Explanation:Gilbert’s syndrome is an autosomal recessive condition that results from defective bilirubin conjugation due to a deficiency of UDP glucuronyl transferase – 1. The prevalence is approximately 1-2% in the general population.The clinical presentation of Gilbert’s syndrome include:- Unconjugated hyperbilinaemia- Jaundice can occur during an intercurrent illnessManagement:Blood investigations usually reveal a rise in bilirubin following prolonged fasting or intravenous nicotinic acid.No treatment required for these patients.Other options:- CYP2C9 deficiency causes reduced warfarin metabolism, and subsequent enhanced drug effects. – Pancreatic disease, cholestasis, excessive alcohol consumption and certain drugs are common causes of raised GGT levels- Defective hepatocyte excretion of conjugated bilirubin is related to the pathophysiology of Dubin-Johnson syndrome- Reduced CYP2C19 levels can lead to the disordered metabolism of clopidogrel and other drugs such as proton-pump inhibitors, anticonvulsants and sedatives.
-
This question is part of the following fields:
- Dermatology
-
-
Question 5
Incorrect
-
A 3 month old infant born to an HIV positive mother presented with jaundice, epileptic seizures and microcephaly. What is the most likely cause?
Your Answer: Rubella
Correct Answer: Cytomegalovirus
Explanation:Congenital cytomegalovirus infection causes: jaundice, hepatosplenomegaly, petechia, microcephaly, hearing loss and seizures.
-
This question is part of the following fields:
- Infectious Diseases
-
-
Question 6
Incorrect
-
Intracellular shifting of hydrogen ions can generate a metabolic alkalosis. In which of the following conditions is metabolic alkalosis caused by this mechanism ?
Your Answer: Milk-alkali syndrome
Correct Answer: Hypokalaemia
Explanation:Metabolic alkalosis is characterized by a primary increase in the concentration of serum bicarbonate ions. This may occur as a consequence of a loss of hydrogen ions or a gain in bicarbonate. Hydrogen ions may be lost through the kidneys or the GI tract, as for example during vomiting, nasogastric suction or use of diuretics. Intracellular shifting of hydrogen ions develops mainly during hypokalaemia to maintain neutrality. Gain in bicarbonate ions may develop during administration of sodium bicarbonate in high amounts or in amounts that exceed the capacity of excretion of the kidneys, as seen in renal failure. Fluid losses may be another cause of metabolic alkalosis, causing the reduction of extracellular fluid volume.
-
This question is part of the following fields:
- Fluid And Electrolytes
-
-
Question 7
Incorrect
-
A 12-year-old boy is brought to the hospital following a road traffic accident. A diagnosis of splenic laceration was made, and a splenectomy was performed. Which among the following blood film findings is not a feature associated with hyposplenism?
Your Answer: Monocytosis
Correct Answer: Thrombocytopenia
Explanation:Hyposplenism is associated with thrombocytosis. Other features of hyposplenism are: – Howell-Jolly bodies and acanthocytosis, occurring secondary to haemolysis.- Pappenheimer bodies: These are granular deposits of iron found within the RBCs.- Lymphocytosis and monocytosis.Causes for hyposplenism include:- Congenital asplenia- Iatrogenic splenectomy: Following trauma or treatment for ITP, thalassemia or spherocytosis).- Autosplenectomy: Secondary to sickle cell anaemia, coeliac disease, dermatitis herpetiformis, essential thrombocythemia or splenic arterial thrombosis).
-
This question is part of the following fields:
- Haematology And Oncology
-
-
Question 8
Correct
-
A 17-year-old boy presents with a 2 day history of colicky abdominal pain, vomiting and diarrhoea. He has been passing blood mixed with diarrhoea. He has no significant past medical history and takes no regular medication. On examination he is pyrexial and clinically dehydrated. Cardiorespiratory and abdominal examinations are normal. What is the most likely diagnosis?
Your Answer: Campylobacter infection
Explanation:The patient has bloody diarrhoea that sounds like a food poisoning in the clinical scenario. Campylobacter is the most common cause of this in the United Kingdom. This is then followed by Salmonella and Shigella. The symptoms are usually self limiting. This is more likely to be bacterial from the food than a viral gastroenteritis.
-
This question is part of the following fields:
- Gastroenterology And Hepatology
-
-
Question 9
Correct
-
Surfactant reduces the surface tension at the air/liquid interface in the lung. Which of the following cells produce surfactant in the lung parenchyma?
Your Answer: Type II pneumocyte
Explanation:Pulmonary surfactant is a mixture of lipids and proteins which is secreted by the epithelial type II cells into the alveolar space.
-
This question is part of the following fields:
- Respiratory
-
-
Question 10
Correct
-
An 11-year-old girl presents to the paediatric assessment unit with a widespread macular rash. She had a previous history of flu-like illness and sore throat diagnosed as tonsillitis for which she was prescribed Amoxicillin. On examination, she has widespread cervical lymphadenopathy and petechiae on her palate. What is the most likely underlying pathogen?
Your Answer: Epstein Barr Virus
Explanation:Based on the clinical scenario, the most likely underlying pathogen is the Epstein Barr virus (EBV).An Epstein Barr virus (EBV) infection most commonly results in upper respiratory tract symptoms with fever and sore throat. Lymphadenopathy is frequently palpable on examination. Splenomegaly may also occur, and for this reason, patients diagnosed with glandular fever should be advised to avoid contact sports for one month following diagnosis. The presence of petechiae on the soft palate is also associated with EBV infection. The vast majority of patients with active EBV infection will develop a widespread rash if given amoxicillin, therefore, phenoxymethylpenicillin (Penicillin V) is recommended for the treatment of a suspected bacterial throat infection to prevent this complication occurring for individuals who have EBV infection.Other options:- Coronavirus: This is one of the causes of the common cold and is frequently responsible for sore throats| however, in this case, the presenting features are more suggestive of an EBV infection.- Group A Streptococcus: Streptococci are classified into two main groups| alpha-haemolytic and beta-haemolytic. Group A Streptococcus belongs to the beta-haemolytic group. Group A streptococcal infection is a common cause of bacterial tonsillitis. It is possible that the child, in this case, had streptococcal tonsillitis and has had a drug reaction to the amoxicillin. However her age, flu-like symptoms and petechiae on her palate all point to an EBV infection and amoxicillin resulting in a rash.- Parainfluenza: Parainfluenza viruses are one of many causes of the common cold and can cause pharyngitis. They are the leading cause of viral croup.- Rhinovirus: Rhinoviruses are one of many causes of the common cold and are frequently responsible for sore throats| however, in this case, are other factors suggesting EBV infection.
-
This question is part of the following fields:
- ENT
-
-
Question 11
Correct
-
In a double blind trial of a new diabetes medication, 25% more in the treated group responded positively than those in the control group (95% CI 10% to 50%| P=0.004)
Your Answer: The therapy benefits an additional 1 in 4 (95% CI 2 to 10), patients who receive it
Explanation:In the final result of this double blind study, 25% or one in four of patients who received the treatment responded positively. Though the difference is significant at P<0.05, it is better to present this as a significant difference at 0.4%. The number needed to treat (NNT) is defined as the inverse of the absolute risk reduction. Taking this as 0.25 (25%), the NNT is 1/0.25 = 4. However given the 95% confidence interval is between 10-50% for absolute risk reduction, the NNT with 95% CI is between 2 and 10. Therefore we cannot say with certainty that the NNT is at least 4.
-
This question is part of the following fields:
- Epidemiology And Statistics
-
-
Question 12
Correct
-
Which organs amongst these are the derivatives of the endoderm?
Your Answer: Epithelial part of the tympanic cavity
Explanation:Endoderm derivatives include the epithelium of the following: gastrointestinal tract and its glands, glandular cells of the liver and pancreases, urachus and urinary bladder, pharynx, trachea and alveoli, part of the tonsils, thyroid and parathyroid, tympanic cavity and thymus and part of the anterior pituitary gland.
-
This question is part of the following fields:
- Embryology
-
-
Question 13
Correct
-
A 3-month-old baby was brought to the paediatrics ward by her mother with a complaint of noisy breathing and difficulty feeding. On examination, the baby had a mild inspiratory stridor, and subsequent laryngoscopy reveals an omega-shaped epiglottis. Which of the following is the most likely diagnosis in this case?
Your Answer: Laryngomalacia
Explanation:Omega-shaped epiglottis is a characteristic feature in the X-ray of a patient with laryngomalacia.
-
This question is part of the following fields:
- ENT
-
-
Question 14
Incorrect
-
A child presents with hypertension. Serum potassium analysis shows hypokalaemia. What is the most likely diagnosis?
Your Answer:
Correct Answer: Liddle syndrome
Explanation:Liddle’s syndrome, is an autosomal dominant disorder, that is characterized by early, and frequently severe, high blood pressure associated with low plasma renin activity, metabolic alkalosis, low blood potassium, and normal to low levels of aldosterone. Liddle syndrome involves abnormal kidney function, with excess reabsorption of sodium and loss of potassium from the renal tubule. Bartter Syndrome also presents with hypokalaemia, however blood pressure of these patients is usually low or normal.
-
This question is part of the following fields:
- Fluid And Electrolytes
-
-
Question 15
Incorrect
-
What is the most common position of the appendix?
Your Answer:
Correct Answer: Retrocecal
Explanation:The most common position of the appendix is the retrocecal position.Note: If a retrocecal appendix is difficult to remove, then mobilisation of the right colon significantly improves access.Other options:The various positions of the appendix are:- Retrocecal (74%)- Pelvic (21%)- Postileal- Subcaecal- Paracaecal- Preileal
-
This question is part of the following fields:
- Gastroenterology And Hepatology
-
-
Question 16
Incorrect
-
What is the most common cardiac abnormality found in Noonan syndrome?
Your Answer:
Correct Answer: Pulmonary stenosis
Explanation:Noonan syndrome is one of the most common genetic diseases associated with congenital heart defects, being second in frequency only to Down syndrome.Pulmonary stenosis and hypertrophic cardiomyopathy are generally the most common congenital heart defects found in Noonan syndrome.Pulmonary stenosis is often associated with a thickened and dysplastic valve. It is usually difficult to obtain a satisfactory result using the transcatheter balloon dilatation of such dysplastic valves, so surgical intervention is more likely to be needed.Hypertrophic cardiomyopathy involves predominantly the ventricular septum as asymmetric septal hypertrophy, but may also affect the ventricular free walls. Left ventricular outflow tract obstruction may occasionally be produced.
-
This question is part of the following fields:
- Neonatology
-
-
Question 17
Incorrect
-
Which of the following is true of mother to child transmission in the case of a mother with HIV infection?
Your Answer:
Correct Answer: The risk of HIV vertical transmission is increased by concurrent maternal Hepatitis C infection
Explanation:To prevent mother to child transmission in the case of an HIV infected mother, guidelines have been put in place in the that guide practices. During pregnancy the risk of intrauterine transmission is quite low, as is the risk of transmission during vaginal delivery. As a result the number of women that choose to have caesarean sections have fallen, with vaginal births increasing by 40%. One factor that can however increase the risk of mother to child HIV transmission is concurrent Hepatitis C infection which double the risk of vertical transmission.
-
This question is part of the following fields:
- HIV
-
-
Question 18
Incorrect
-
Which of following statements with regards to the developmental problems found in Fragile X syndrome is the most accurate?
Your Answer:
Correct Answer: Around one third of children with FXS meet diagnostic criteria for autistic spectrum disorder
Explanation:Fragile X syndrome is a genetic syndrome associated with neuro-developmental problems such as learning disabilities and cognitive impairment, with many affected children having mild to moderate intellectual disability. About a third of children have features of autism spectrum disorder and ADHD which affects their communication skills and social interactions. As such, affected individuals usually have delayed speech development and poor nonverbal skills such as gaze aversion. Symptoms tend to worsen with age into adolescence as the demands on their intellect becomes greater. Pre-mutation carriers, who posses smaller genetic repeat expansions, have been found to be associated with some neurodevelopment and other medical problems.
-
This question is part of the following fields:
- Neurology And Neurodisability
-
-
Question 19
Incorrect
-
A young man has ingested 25 tablets of paracetamol 500 mg. What is the suggested minimum time interval between ingestion and measuring the blood plasma paracetamol levels?
Your Answer:
Correct Answer: 4 hours
Explanation:The post-ingestion plasma level, which is required in order to guide the treatment, reaches a peak at 4 hours. Levels requiring antidote (N-acetyl cysteine) include: 100 mcg per ml at 4 hours, 35 mcg per ml at 10 hours and 25 mcg per ml at 12 hours. These levels are in conjunction with the levels recorded and they should all be put down on a treatment nomogram.
-
This question is part of the following fields:
- Pharmacology
-
-
Question 20
Incorrect
-
The mother of 6 months old girl tests positive for HIV. Doctors test her daughter as well and the results turn out to be positive for HIV, both by polymerase chain reaction (PCR) and serology. The girl is clinically healthy and seems to attain normal developmental milestones. Which of the following is the most appropriate next step?
Your Answer:
Correct Answer: Start co-trimoxazole prophylaxis immediately and plan to start antiretrovirals once further work-up is complete
Explanation:Infants exposed to maternal HIV and with positive results require immediate management with co-trimoxazole prophylaxis, regardless of their CD4 levels. Antiretroviral treatment is necessary as well but it could wait until further work-up is complete.
-
This question is part of the following fields:
- HIV
-
-
Question 21
Incorrect
-
A 15-year-old girl is brought to the clinic by her mother, who is worried that her daughter might be using illicit substances. The patient is sweating and appears agitated, talkative and is repeatedly clenching her jaw. She has generalized piloerection. She has most likely taken which of the following substances?
Your Answer:
Correct Answer: MDMA (ecstasy)
Explanation:3,4-methylenedioxy-methamphetamine (MDMA) is a synthetic drug that alters mood and perception (awareness of surrounding objects and conditions). It is chemically similar to both stimulants and hallucinogens, producing feelings of increased energy, pleasure, emotional warmth, and distorted sensory and time perception. MDMA’s effects last about 3 to 6 hours, although many users take a second dose as the effects of the first dose begin to fade. Over the course of the week following moderate use of the drug, a person may experience:irritabilityimpulsiveness and aggressiondepressionsleep problemsanxietymemory and attention problemsdecreased appetitedecreased interest in and pleasure from sex
-
This question is part of the following fields:
- Adolescent Health
-
-
Question 22
Incorrect
-
A 16-year-old boy presents to the emergency department with abdominal pain, fever, and vomiting. On examination, palpation of the left lower quadrant of the abdomen elicits pain in the right lower quadrant. What is this sign?
Your Answer:
Correct Answer: Rovsing's sign
Explanation:Based on the findings presented, the sign elicited is Rovsing’s sign.Rovsing’s sign:It is a sign suggestive of appendicitis. A positive sign is determined when palpation in the left lower quadrant of a patient’s abdomen causes pain in the right lower quadrant.Other options:- Murphy’s sign is positive in gallbladder inflammation. With the upper border of the examiner’s hand in the right upper quadrant of the abdomen under the rib cage, the patient is asked to inhale. Inhalation causes the gallbladder to descend, which catches on the fingers, causing pain.- Cullen’s sign is suggestive of ectopic pregnancy or acute pancreatitis and describes the bruising around the umbilicus.- Tinel’s sign is positive in those with carpal tunnel syndrome. The examiner’s fingers tap the median nerve over the flexor retinaculum, which causes paraesthesia over the distribution of the median nerve.- Battles’ sign describes bruising behind the ear, suggesting a basal skull fracture of the posterior cranial fossa.
-
This question is part of the following fields:
- Emergency Medicine
-
-
Question 23
Incorrect
-
A term baby with a birth weight of 4.2 kg with meconium aspiration syndrome is intubated and ventilated. Conventional ventilation was unsuccessful and so a trial of high-frequency oscillatory ventilation has commenced. Chest X-ray shows good lung inflation. There is minimal chest “wobble” on the baby. Settings are mean airway pressure 16, delta P 25, rate 10 Hz, FiO2 0.5. Baby’s oxygen saturations are 94%. Blood gas shows pH 7.19, CO2 9.3 kPa, BE –5. What is the first change that should be made to the ventilation?
Your Answer:
Correct Answer: Increase delta P
Explanation:The baby is not clearing CO2 normally despite normal oxygenation so we should increase the delta P. Higher delta P will increase tidal volume and hence CO2 removal.After initial resuscitation and stabilization, the following should be the ventilator settings used:Rate: 30-40/minutePeak inspiratory pressure (PIP) – determined by adequate chest wall movement.An infant weighing less than 1500 grams: 16-28 cm H2O.An infant weighing greater than 1500 grams: 20-30 cm H2O. Positive end expiratory pressure (PEEP): 4 cm of H2O OR 5-6 cm if FiO2 > 0.90.FiO2: 0.4 to 1.0, depending on the clinical situation.Inspiratory time: 0.3-0.5 sec.After 15 to 30 minutes, check arterial blood gases and pH.If the PaO2 or the O2 saturation is below accepted standards, the FiO2 can be raised to a maximum of 1.0. If the PaO2 or O2 saturation is still inadequate, the mean airway pressure can be raised by increasing either the PIP, PEEP, inspiratory time or the rate, leaving inspiratory time constant.If the PaCO2 is elevated, the rate or peak inspiratory pressure can be raised.
-
This question is part of the following fields:
- Neonatology
-
-
Question 24
Incorrect
-
A term baby is born through thick meconium. The baby has not yet cried and is making no respiratory effort. The baby appears to be covered in thick particulate meconium.What is the next most appropriate step?
Your Answer:
Correct Answer: Suction with wide-bore catheter under direct vision
Explanation:Meconium aspiration syndrome (MAS) refers to breathing problems that a new-born baby may have when: – There are no other causes, and- The baby has passed meconium (stool) into the amniotic fluid during labour or deliveryThe most recent guidelines are as follows:- If the baby is vigorous (defined as having a normal respiratory effort and normal muscle tone), the baby may stay with the mother to receive the initial steps of new-born care. A bulb syringe can be used to gently clear secretions from the nose and mouth.- If the baby is not vigorous (defined as having a depressed respiratory effort or poor muscle tone), place the baby on a radiant warmer, clear the secretions with a bulb syringe, and proceed with the normal steps of new-born resuscitation (i.e., warming, repositioning the head, drying, and stimulating). If, after these initial steps are taken, the baby is still not breathing or the heart rate is below 100 beats per minute (bpm), administer positive pressure ventilation.Resuscitation should follow the same principles for infants with meconium-stained fluid as for those with clear fluidContinued care in the neonatal intensive care unit (NICU):Maintain an optimal thermal environment to minimize oxygen consumption.Minimal handling is essential because these infants are easily agitated. Agitation can increase pulmonary hypertension and right-to-left shunting, leading to additional hypoxia and acidosis. Sedation may be necessary to reduce agitation.An umbilical artery catheter should be inserted to monitor blood pH and blood gases without agitating the infant.Continue respiratory care includes oxygen therapy via hood or positive pressure, and it is crucial in maintaining adequate arterial oxygenation. Mechanical ventilation is required by approximately 30% of infants with MAS. Make concerted efforts to minimize the mean airway pressure and to use as short an inspiratory time as possible. Oxygen saturations should be maintained at 90-95%.Surfactant therapy is commonly used to replace displaced or inactivated surfactant and as a detergent to remove meconium. Although surfactant use does not appear to affect mortality rates, it may reduce the severity of disease, progression to extracorporeal membrane oxygenation (ECMO) utilization, and decrease the length of hospital stay.
-
This question is part of the following fields:
- Neonatology
-
-
Question 25
Incorrect
-
Which of the following types best describe the epithelium on the external aspect of the tympanic membrane?
Your Answer:
Correct Answer: Stratified squamous
Explanation:The external aspect of the tympanic membrane is lined by stratified squamous epithelium. Clinical correlation: Following middle ear infections, this type of epithelium can migrate into the middle ear through a perforated tympanic membrane.The ear is composed of three anatomically distinct regions: – External ear: Auricle is composed of elastic cartilage covered by skin. The lobule has no cartilage and contains fat and fibrous tissue. External auditory meatus is variable in length, measuring approximately 2.5cm long in fully grown children. Lateral third of the external auditory meatus is cartilaginous, and the medial two-thirds is bony. The greater auricular nerve innervates the region. The auriculotemporal branch of the trigeminal nerve supplies most of the external auditory meatus and the lateral surface of the auricle. – Middle ear: It is the space between the tympanic membrane and cochlea. The aditus leads to the mastoid air cells is the route through which middle ear infections may cause mastoiditis. Anteriorly the eustachian tube connects the middle ear to the nasopharynx. The tympanic membrane consists of an outer layer of stratified squamous epithelium, a middle layer of fibrous tissue and an inner layer of mucous membrane continuous with the middle ear. The chorda tympani nerve passes on the medial side of the pars flaccida. The glossopharyngeal nerve and pain innervate the middle ear. Thus, pain may radiate to the middle ear following tonsillectomy. – Ossicles:Malleus attaches to the tympanic membrane (the Umbo). Malleus articulates with the incus (synovial joint). Incus attaches to stapes (another synovial joint). – Internal ear:It consists of the cochlea, semicircular canals, and vestibule. Organ of Corti is the sense organ of hearing and is located on the inside of the cochlear duct on the basilar membrane. Vestibule accommodates the utricle and the saccule. These structures contain endolymph and are surrounded by perilymph within the vestibule. The semicircular canals lie at various angles to the petrous temporal bone. All share a common opening into the vestibule.
-
This question is part of the following fields:
- ENT
-
-
Question 26
Incorrect
-
A 15-year-old boy with type 1 DM is recently started on an insulin pump. There has been better glycaemic control and he now subsequently enjoys a healthy, active lifestyle. During the consultation, he seems to acknowledge the risks of missing out his dose and says that he is comfortable with his new pump. he mentions that he changes his site after every 4 days. However, a random blood sugar analysis reveals it to be 22.3 mmol/L. Which of the following is the most likely reason for the raised RBS level?
Your Answer:
Correct Answer: Site change is overdue
Explanation:Insertion sites and sensor sites should be rotated each time the infusion set or glucose sensor is changed. This keeps the tissue healthy and allows previous sites to completely heal before reusing them. Change infusion set every 2 to 3 days to help prevent infection.
-
This question is part of the following fields:
- Endocrinology
-
-
Question 27
Incorrect
-
Childhood absence epilepsy is characterized by which of the given facts?
Your Answer:
Correct Answer: 3-Hz spike-and-slow-wave complexes are seen on electroencephalograms (EEGs)
Explanation:Absence epilepsy is the most common type of generalized childhood epilepsies. It is mainly idiopathic, but 10-40% of the cases have a positive family history. It is characterized by frequent absence seizures and periods of unconsciousness. The hallmark of absence epilepsy on EEG is the bilaterally synchronous 2–4 Hz spike and wave discharges (SWDs). The average age of onset is around 4-8 years, being more prevalent among girls. Treatment resistance is not common.
-
This question is part of the following fields:
- Neurology And Neurodisability
-
-
Question 28
Incorrect
-
A 13-year-old girl presents with a rash in her lower limbs. The rash appeared a few days after an upper respiratory infection and was associated with persistent haematuria. Renal biopsy revealed immunoglobulin G (IgG) glomerular immune deposits. What is the most probable diagnosis?
Your Answer:
Correct Answer: Henoch-Schonlein purpura (HSP)
Explanation:Immunoglobulin G (IgG) glomerular immune deposits are seen more commonly in HSP compared to IgA nephropathy.The presentation of the child is highly suggestive of Henoch-Schönlein purpura (HSP). It is an IgA-mediated, autoimmune hypersensitivity vasculitis that targets the small vessels of the skin, GI tract, kidneys, and joints.It is most commonly seen in children aged 3 – 6years and is twice as common in boys than girls. Preceding viral URTI with low-grade pyrexia is common. The most common organism associated with HSP is, however, Group A streptococcal infection A.A purpuric rash is seen on the back of the legs and buttocks and can less frequently, affect the arms. Arthralgia is common (usually knees/ankles) in these patients. Abdominal pain and bloody diarrhoea may occur. And half of the children with HSP have renal involvement. Rarely, it can lead to end-stage renal failure.Treatment includes adequate hydration, occasionally steroids, and other immunosuppressants. The disease can recur in 1 in 3 children.
-
This question is part of the following fields:
- Nephro-urology
-
-
Question 29
Incorrect
-
A 11-year-old boy is admitted to the hospital with diarrhoea and lethargy. There is a known local outbreak of E coli 0157:H7, and his initial bloods show evidence of acute renal failure. Given the likely diagnosis, which one of the following investigation results would be expected?
Your Answer:
Correct Answer: Fragmented red blood cells
Explanation:The likely diagnosis in this case is Haemolytic Uremic Syndrome (HUS), which is generally seen in young children presenting with a triad of symptoms, namely: acute renal failure, microangiopathic haemolytic anaemia, and thrombocytopenia. The typical cause of HUS is ingestion of a strain of Escherichia coli. The laboratory results will usually include fragmented RBCs, decreased serum haptoglobin, reduced platelet count, nonspecific WBC changes, and normal coagulation tests (PTT included).
-
This question is part of the following fields:
- Renal
-
-
Question 30
Incorrect
-
A 15-year-old boy is diagnosed with aplastic anaemia after presenting with fatigue, dyspnoea and headaches. He lives on a farm and would usually play hide and seek with his siblings in the barn where the family store pesticides and other chemicals. Lab investigations reveal a significant leukopenia. Aplastic anaemia results due to failure of hematopoietic stem cells that give rise to progenitors of immune cells. In which area of the body are these cells primarily located?
Your Answer:
Correct Answer: Bone marrow
Explanation:Hematopoietic stem cells (HSCs) are a rare population of cells residing in the bone marrow (BM) and continuously replenish all mature blood cells throughout their life span.
-
This question is part of the following fields:
- Haematology And Oncology
-
00
Correct
00
Incorrect
00
:
00
:
00
Session Time
00
:
00
Average Question Time (
Secs)