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Question 1
Correct
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A mercury barometer can be used to determine absolute pressure. A mercury manometer can be used to check blood pressure. The SI units of length(mm) are used to measure pressure.
Why is pressure expressed in millimetres of mercury (mmHg)?Your Answer: Pressure is directly proportional to length of the mercury column and is variable
Explanation:A mercury barometer can be used to determine absolute pressure. A glass tube with one closed end serves as the barometer. The open end is inserted into a mercury-filled open vessel. The mercury in the container is pushed into the tube by atmospheric pressure exerted on its surface. Absolute pressure is the distance between the tube’s meniscus and the mercury surface.
Pressure is defined as force in newtons per unit area (F) (A).
Mass of mercury = area (A) × density (ρ) × length (L)
Pressure = ((A × ρ × L) × 9.8 m/s2)/A
Pressure = ρ × L x 9.8
Pressure is proportional to LThe numerator and denominator of the above equation, area (A), cancel out. The constants are density and the gravitational acceleration value.
The length is proportional to the applied pressure.
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This question is part of the following fields:
- Physiology
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Question 2
Incorrect
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Levels of serum potassium in around 1000 patients that were on ACE inhibitor were measured. The mean value was calculated to be 4.6mmol/L and a standard deviation of 0.3mmol/L was recorded.
Which among the given options is correct?Your Answer: 95.4% of values lie between 4.3 and 4.9 mmol/l
Correct Answer: 68.3% of values lie between 4.3 and 4.9 mmol/l
Explanation:Its known that 68.3% of the total values of a normally distributed variable are found within a range of 1 standard deviation from the mean which makes the range to be 4.3 to 4.9 mmol/L.
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This question is part of the following fields:
- Statistical Methods
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Question 3
Incorrect
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A medical student performed a case control study for her final dissertation. It involved examining marijuana exposure in a group of patients with and without COPD.
What form of bias is the study most susceptible to?Your Answer: Response bias
Correct Answer: Recall bias
Explanation:Case control studies in particular are prone to recall bias, people who are suffering from COPD might sometimes relate the ailment to marijuana usage in past and hence contrary to the control group, they are more able to describe to what extent they have been using the drug in the past.
As recommended, all the doctors should make sure that there practice is based on evidence and thus it is paramount that the doctors learn to appraise the paper in a critical manner i.e. ability to detect any potential source of bias.
Detection Bias: Outcomes are more looked for in one group than the other.
Observer Bias: Subjectivity of observers regarding the outcome.
Publication bias: Not publishing the results of a valid study just because they are negative or uninteresting can be termed as publication bias.
Recall bias: Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.
Response Bias: The participants that filled out the response forms containing information that was going to be used for a trial, don’t represent the target population.
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This question is part of the following fields:
- Statistical Methods
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Question 4
Incorrect
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A 64-year-old man is admitted to the critical care unit. He has a recent medical history of faecal peritonitis for which a laparotomy was performed. His vitals have been monitored using an invasive pulmonary artery flotation catheter.
His vital readings are:
Temperature: 38.1°C
Blood pressure: 79/51 mmHg (mean 58 mmHg)
Pulmonary artery pressure: 19/6 mmHg (mean 10 mmHg)
Pulmonary capillary occlusion pressure: 5 mmHg
Central venous pressure: 12 mmHg
Cardiac output: 5 L/min
Mixed venous oxygen saturation: 82%
Calculate his approximate pulmonary vascular resistance.
Note: A correction factor of 80 is require to convert mmHg to dynes·s·cm-5Your Answer: 40 dynes·s·cm-5
Correct Answer: 80 dynes·s·cm-5
Explanation:Pulmonary vascular resistance (PVR) refers to the resistance to blood flow to the left atrium from the pulmonary artery.
It is derived mathematically by:PVR = MPAP – PCWP
CO
where,
MPAP: Mean pulmonary artery pressure
PCWP: Pulmonary capillary occlusion pressure
CO: Cardiac outputFor this patient:
PVR = 10 – 5 = 1mmHg
5Remember, multiply by correction factor 80 to change units:
PVR = 1mmHg x 80 = 80 dynes·s·cm-5
Normal values range between 20-130 dynes·s·cm-5
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This question is part of the following fields:
- Clinical Measurement
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Question 5
Incorrect
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An otherwise fit 7-year-old boy for an elective tonsillectomy is seen holding a bottle of sugared orange squash at anaesthetic assessment . He appears to have consumed 120 mL of the bottle's contents.
What is the minimal safe fasting time prior to proceeding with a general anaesthetic in this patient?Your Answer: 6 hours
Correct Answer: 1 hour
Explanation: -
This question is part of the following fields:
- Pathophysiology
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Question 6
Incorrect
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Bacteria and viruses that are smaller than 0.1 ?m in diameter can be filtered out using heat and moisture exchanger (HME) with a typical pore size 0.2 ?m.
Choose the most appropriate mechanisms of particle capture for most bacteria and viruses.Your Answer: Inertial impaction
Correct Answer: Diffusion
Explanation:Warming, humidifying, and filtering inspired anaesthetic gases is done by heat and moisture exchangers (HME) and breathing system filters. They are made of glass fibres materials and are supported by a sturdy frame. Pleating increases the surface area to reduce resistance to air flow and boost efficiency.
Filters’ effectiveness is determined by the amount and size of particles they keep out of the patient’s airway. The efficiency of filters might be classified as 95, 99.95, or 99.97 percent. Pores with a diameter of 0.2 µm are common. The following are examples of typical particle sizes:
Red blood cell – 5 µm
Lymphocyte – 5-8 µm
Viruses – 0.02-0.3 µm
Bacteria – 0.5-1 µm
Depending on particle size, gas flow speed, and charge, particles are collected via a number of processes. Mechanical sieve, interception, diffusion, electrostatic filtration, and inertial impaction are some of the options:Sieve:
The diameter of the particle the filter is supposed to collect is smaller than the apertures of the filter’s fibres.Interception:
When a particle following a gas streamline approaches a fibre within one radius of itself, it becomes attached and captured.
Diffusion:A particle’s random (Brownian) zig-zag path or motion causes it to collide with a fibre.
By attracting and capturing a particle from within the gas flow, it generates a lower-concentration patch within the gas flow into which another particle diffuses, only to be captured. At low gas velocities and with smaller particles (0.1µm diameter), this is more common.Electrostatic:
These filters use large diameter fibre media and rely on electrostatic charges to improve fine particle removal effectiveness.
Impaction due to inertia:
When a particle is too large to respond fast to abrupt changes in streamline direction near a filter fibre, this happens. Because of its inertia, the particle will continue on its original course and collide with the filter fibre. When high gas velocities and dense fibre packing of the filter media are present, this sort of filtration mechanism is most prevalent.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 7
Correct
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A 68-year old female is brought to the Emergency Room for abdominal pain. Medical history revealed that she is on long-term warfarin therapy for deep vein thrombosis.
Upon further investigation, the patient is hypotensive at 80/60 mmHg, and an abdominal mass is palpable on the umbilical area. An initial diagnosis of ruptured abdominal aortic aneurysm (AAA) is made. Moreover, blood tests show an international normalised ratio (INR) of 4.2.
Which of the following products should be initially transfused or administered to the patient to reverse the anticoagulation?Your Answer: Prothrombin complex
Explanation:Warfarin prevents reductive metabolism of the inactive vitamin K epoxide back to its active hydroquinone form. Thus, warfarin inhibits the synthesis of vitamin K dependent clotting factors: X, IX, VII, II (prothrombin), and of the anticoagulants protein C and protein S. The therapeutic range for oral anticoagulant therapy is defined in terms of an international normalized ratio (INR). The INR is the prothrombin time ratio (patient prothrombin time/mean of normal prothrombin time for lab)ISI, where the ISI exponent refers to the International Sensitivity Index and is dependent on the specific reagents and instruments used for the determination. A prolonged INR is widely used as an indication of integrity of the coagulation system in liver disease and other disorders, it has been validated only in patients in steady state on chronic warfarin therapy.
Prothrombin complex concentrate (PCC) is used to replace congenital or acquired vitamin-K deficiency warfarin-induced anticoagulant effect, particularly in the emergent setting.
Intravenous vitamin K has a slower onset of action compared to PCC, but is useful for long term therapy.
Fresh frozen plasma (FFP) prepared from freshly donated blood is the usual source of the vitamin K-dependent factors and is the only source of factor V. The factors needed, however, are found in small quantities compared to PCC.
Cryoprecipitate is indicated for hypofibrinogenemia/dysfibrinogenemia, von Willebrand disease, haemophilia A, factor XIII deficiency, and management of bleeding related to thrombolytic therapy.
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This question is part of the following fields:
- Pathophysiology
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Question 8
Incorrect
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Post thyroidectomy, a 50-year-old male singer noticed some hoarseness in his voice. Now, he presents to his general physician as it has been the same for the past few weeks.
A complication is noted in the post-thyroidectomy report regarding an injury to the external laryngeal nerve.
Which muscle has been affected due to loss of innervation by the damaged nerve, and whose improper functioning can lead to hoarseness in the patient's voice?Your Answer: Lateral cricoarytenoid
Correct Answer: Cricothyroid
Explanation:All of the muscles of the larynx are innervated by the recurrent laryngeal nerve, except the cricothyroid muscle.
Cricothyroid muscle is located deep in the anterior neck, between the cricoid and thyroid cartilage and is innervated by the external laryngeal nerve. Any injury to this muscle can cause paralysis and lead to hoarseness. When cricothyroid muscle contracts, it leads to tightening, stretching and thinning of the vocal folds. This produces higher-pitched sounds during vocalization.
A patient experiencing hoarseness due to possible injury to the external laryngeal nerve should be reassured that the hoarseness will resolve in time due to increased compensation from the other muscles.
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This question is part of the following fields:
- Anatomy
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Question 9
Incorrect
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Which of the following statements about the cricoid cartilage is true?
Your Answer: Represents the narrowest part of the airway in adults
Correct Answer: The lower border is attached to the first tracheal ring
Explanation:The cricoid cartilage is a hyaline cartilage ring surrounding the trachea. It provides support for key phonation muscles.
The inferior border of the cricoid cartilage is attached to the thyroid cartilage and the inferior border is attached to the first tracheal ring through the cricotracheal ligament.
Application of pressure to the cricoid cartilage to reduce risk of aspiration of gastric contents (Sellick manoeuvre) does not stop tracheal aspiration and cannot stop regurgitation into the oesophagus.
A force of 44 newtons to the cricoid cartilage is needed to control regurgitation.
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This question is part of the following fields:
- Antomy
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Question 10
Incorrect
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A new clinical trial evaluates the effect of a new drug Z on all-cause mortality. The rate of death in the group receiving this drug is 8%, compared with 16% in the control group.
What is the number needed to treat with drug Z to prevent death?Your Answer:
Correct Answer: 13
Explanation:Number needed to treat is a measure of the impact of a treatment or intervention that is often used to communicate results to patients, clinicians, the public and policymakers. It states how many patients need to be treated for one additional patient to experience an adverse outcome (e.g. a death).
It is calculated as the inverse of the absolute risk reduction and is rounded to the next highest whole number.
The absolute risk reduction is 8% (16% – 8%). 100/8 = 12.5, so rounding up the next integer this gives at NNT of 13. i.e. you would need to give the new drug to 13 people to ensure that you prevented one death.
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This question is part of the following fields:
- Statistical Methods
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Question 11
Incorrect
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Sugammadex binds to certain drugs that affect neuromuscular function during anaesthesia in a stereospecific, non-covalent, and irreversible manner.
It has the greatest impact on the activity of which of the following drugs?Your Answer:
Correct Answer: Vecuronium
Explanation:Sugammadex is a modified cyclodextrin that works as an aminosteroid neuromuscular blocking (nmb) reversal agent. By encapsulating each molecule in the plasma, it rapidly reverses rocuronium and, to a lesser extent, vecuronium-induced neuromuscular blockade. Consequently, a concentration gradient favours the movement of these nmb agents away from the neuromuscular junction. Pancuronium-induced neuromuscular blockade at low levels has also been reversed.
By inhibiting voltage-dependent calcium channels at the neuromuscular junction, antibiotics in the aminoglycoside group potentiate neuromuscular blocking agents. This can be reversed by giving calcium but not neostigmine or sugammadex.
Sugammadex will not reverse the effects of mivacurium, which belongs to the benzylisoquinolinium class of drugs.
A phase II or desensitisation block occurs when the motor end-plate becomes less sensitive to acetylcholine as a result of an overdose or repeated administration of suxamethonium. The use of neostigmine has been shown to be effective in reversing this weakness.
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This question is part of the following fields:
- Pharmacology
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Question 12
Incorrect
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Which of the following statement is true or false regarding to the respiratory tract?
Your Answer:
Correct Answer: The sympathetic innervation of the bronchi is derived from T2 - T4
Explanation:The diaphragm has three opening through which different structures pass from the thoracic cavity to the abdominal cavity:
Inferior vena cava passes at the level of T8.
Oesophagus, oesophageal vessels and vagi at T10.
Aorta, thoracic duct and azygous vein through T12.
Sympathetic trunk and pulmonary branches of vagus nerve form a posterior pulmonary plexus at the root of the lung. Fibres continue posteriorly from superficial cardiac plexus to form Anterior pulmonary plexus. It contains vagi nerves and superficial cardiac plexus. These fibres then follow the blood vessel and bronchi into the lungs.
The lower border of the pleura is at the level of:
8th rib in the midclavicular line
10th rib in the lower level of midaxillary line
T12 at its termination.
Both lungs have oblique fissure while right lung has transverse fissure too.
The trachea expands from the lower edge of the cricoid cartilage (at the level of the 6th cervical vertebra) to the carina.
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This question is part of the following fields:
- Physiology
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Question 13
Incorrect
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Which of the following statements is true regarding Adrenaline or Epinephrine?
Your Answer:
Correct Answer: Stimulates ACTH secretion
Explanation:Adrenaline is released by the adrenal glands, acts on ? 1 and 2, ? 1 and 2 receptors, and is responsible for fight or flight response.
It acts on ? 2 receptors in skeletal muscle vessels-causing vasodilation.
It acts on ? adrenergic receptors to inhibit insulin secretion by the pancreas. It also stimulates glycogenolysis in the liver and muscle, stimulates glycolysis in muscle.
It acts on ? adrenergic receptors to stimulate glucagon secretion in the pancreas
It also stimulates Adrenocorticotrophic Hormone (ACTH) and stimulates lipolysis by adipose tissue -
This question is part of the following fields:
- Pharmacology
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Question 14
Incorrect
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The following results were obtained In a new drug trial:
Improved Not improved
Placebo group 36 26
Treatment group 44 16
Regarding the statistical analysis or interpretation of the trial, One of these is trueYour Answer:
Correct Answer: The data could be evaluated using the chi square test
Explanation:This data is in a 2 × 2 contingency table so a chi square test can be used. There is a special chi squared formula that gives a value that can be looked up in a table giving the p value.
Since we are comparing proportions not means, the Student’s t test CANNOT be used.
There is no linear regression to plot so Pearson’s co-efficient cannot be calculated.
Nothing is so obvious that no statistical analysis is needed.
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This question is part of the following fields:
- Statistical Methods
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Question 15
Incorrect
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Which of the following is true when testing for statistical significance?
Your Answer:
Correct Answer: The probability associated with a type I error is the significance level
Explanation:The null hypothesis states that there is no significant difference between two groups.
The alternative hypothesis states that there is a significant difference between two groups.
A type I error (false positive) occurs when a null hypothesis is rejected when it should be accepted.
A type II error (false negative) occurs when the alternative hypothesis is rejected when it should be accepted.
The probability determines the rejection of a null hypothesis.
The level of significance is set at p <0.05.
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This question is part of the following fields:
- Statistical Methods
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Question 16
Incorrect
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A 10-year-old boy is undergoing investigations for coeliac disease. Tissue biopsies were taken from both the small and large intestinal linings.
Which of the following is found in the small intestine lining but not in that of the large intestine in a normal biopsy?Your Answer:
Correct Answer: Villi
Explanation:The small and large intestinal walls are composed of the following common layers:
1. Mucosa
2. Submucosa
3. Muscularis Externa
4. AdventitiaIntestinal villi are highly vascular projections of the mucosal surface that cover the entire small intestinal mucosa. They increase the lumen’s surface area, which aids in absorption and digestion, the primary functions of the small intestine. Villi are large and most abundant in the duodenum and jejunum.
In both the small and large intestines, the muscularis mucosae are found within the mucosa. The myenteric nerve plexus is found innervating the muscularis externa. The mucosa is lined with columnar epithelial cells, and goblet cells may be present to secrete mucins.
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This question is part of the following fields:
- Anatomy
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Question 17
Incorrect
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A participant of a metabolism study is to be fed only granulated sugar and water for 48 hours. What would be his expected respiratory quotient at the end of the study?
Your Answer:
Correct Answer: 1
Explanation:The respiratory quotient is the ratio of CO2 produced to O2 consumed while food is being metabolized:
RQ = CO2 eliminated/O2 consumed
Most energy sources are food containing carbon, hydrogen and oxygen. Examples include fat, carbohydrates, protein, and ethanol. The normal range of respiratory coefficients for organisms in metabolic balance usually ranges from 1.0-0.7.
Granulated sugar is a refined carbohydrate with no significant fat, protein or ethanol content.
The RQ for carbohydrates is = 1.0
The RQ for the rest of the compounds are:
Fats RQ = 0.7
The chemical composition of fats differs from that of carbohydrates in that fats contain considerably fewer oxygen atoms in proportion to atoms of carbon and hydrogen.Protein RQ = 0.8
Due to the complexity of various ways in which different amino acids can be metabolized, no single RQ can be assigned to the oxidation of protein in the diet; however, 0.8 is a frequently utilized estimate. -
This question is part of the following fields:
- Physiology
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Question 18
Incorrect
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Which of the following is an expected change in pulmonary function seen during a moderate asthma attack?
Your Answer:
Correct Answer: Decreased forced expiratory volume in 1 sec (FEV1)
Explanation:Asthma is a lung condition that causes reversible narrowing and swelling of airway passages. It is classified by the frequency and severity of symptoms.
The following are symptoms of moderate asthma:
Symptoms include cough, wheezing, chest tightness, or difficulty breathing which occurs daily
Decreased activity levels due to flare-ups
Night-time symptoms 5 or more times a month
Lung function test FEV1 is 60-80% of predicted normal values
Peak flow has more than 30% variabilityWith moderate asthma attacks, the arterial pCO2 levels may decrease, but as severity increases, so does the pCO2, reaching normal levels, and then exceeding them in severe asthma attacks.
Airway obstruction increases the functional residual capacity.
Concentration of serum bicarbonate would not increase in moderate asthma, but it could possibly increase in life-threatening asthma via the same mechanism as what increases arterial PCO2.
FEV1 is a good measure of airway obstruction. and is reduced in acute asthma attacks.
In the case of a pneumothorax, a decrease in arterial PO2 is higher.
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This question is part of the following fields:
- Pathophysiology
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Question 19
Incorrect
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These proprietary preparations of local anaesthetic are available in your hospital:
Solution A contains 10 mL 0.5% bupivacaine (plain), and
Solution B contains 10 mL 0.5% bupivacaine with adrenaline 1 in 200,000.
What is the pharmacokinetic difference between the two solutions?Your Answer:
Correct Answer: The onset of action of solution A is quicker than solution B
Explanation:The reasons for adding adrenaline to a local anaesthetic solution are:
1. To Increase the duration of block
2. To reduce absorption of the local anaesthetic into the circulation
3. To Increase the upper safe limit of local anaesthetic (2.5 mg/kg instead of 2 mg/kg, in this case).The addition of adrenaline to bupivacaine does not affect its potency, lipid solubility, protein binding, or pKa(8.1 with or without adrenaline).
The pH of bupivacaine is between 5-7. Premixed with adrenaline, it is 3.3-5.5.
The onset of a local anaesthetic and its ability to penetrate membranes depends upon degree of ionisation. Compared with the ionised fraction, unionised local anaesthetic readily penetrates tissue membranes to site of action. The onset of action of solution B is slower. this is because the relationship between pKa(8.1) and pH(3.3-5.5) of the solution results in a greater proportion of ionised local anaesthetic molecules compared with solution A. -
This question is part of the following fields:
- Pharmacology
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Question 20
Incorrect
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An older woman has been brought into the emergency department with symptoms of a stroke. A CT angiogram is performed for diagnosis, which displays narrowing in the artery that supplies the right common carotid. Which of the following artery is the cause of stroke in this patient?
Your Answer:
Correct Answer: Brachiocephalic artery
Explanation:The arch of aorta gives rise to three main branches:
1. Brachiocephalic artery
2. Left common carotid artery
3. Left subclavian arteryThe brachiocephalic artery then gives rise to the right subclavian artery and the right common carotid artery.
The right common carotid artery arises from the brachiocephalic trunk posterior to the sternoclavicular joint.
The coeliac trunk is a branch of the abdominal aorta.
The ascending aorta supplies the coronary arteries. -
This question is part of the following fields:
- Anatomy
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Question 21
Incorrect
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A 5-year-old child is scheduled for squint surgery requiring general anaesthesia.
To begin, she is given sevoflurane for the inhalation induction, then intravenous access is established along with the insertion of a supraglottic airway. Anaesthesia is maintained with fentanyl 1 mcg/kg, with an air/oxygen/sevoflurane mix with spontaneous respirations.
Once the surgery begins, her pulse rate drastically reduces from 120 beats/min to 8 beats/min.
What is the most appropriate next step for this patient?Your Answer:
Correct Answer: Tell surgeon to stop surgical retraction
Explanation:This sudden change in pulse rate is due to the oculocardiac reflex. It is a >20% reduction in pulse rate as a result of placing pressure directly on the eyeball. The reflex arc has an afferent and efferent arm:
The afferent (sensory) arm: The trigeminal nerve (CN V)
The efferent arm: The vagus nerve (CN X)
The most appropriate action is to ask the surgeon to stop retraction of the extraocular muscles, Assess for hypoxia, and give 100% oxygen if indicated.
Atropine of glycopyrrolate can be administered to counteract the reflex, and also prevent any further vagal reflexes.
Administration of fentanyl may increase patient’s risk of bradycardia and sinus arrest in this case.
Adrenaline is not indicated here as other treatment options will provide sufficient relief from arrhythmia.
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This question is part of the following fields:
- Pathophysiology
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Question 22
Incorrect
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After establishing a cardiopulmonary bypass, the right atrium is opened to repair the tricuspid valve.
Out of the following, which is NOT a part of the right atrium?Your Answer:
Correct Answer: Trabeculae carnae
Explanation:The right atrium receives blood supply from the SVC, IVC, and coronary sinus. It forms the right border of the heart.
The interior of the right atrium has 5 distinct features:
1. Sinus venarum – smooth, thin-walled posterior part of the right atrium where the SVC, IVC, and coronary sinus open
2. Musculi pectinati – an anterior rough, wall of pectinate muscles
3. Tricuspid valve orifice – the opening through which the right atrium empties blood into the right ventricle
4. Crista terminalis – separates the rough (musculi pectinati) from the smooth (sinus venarum) internally
5. Fossa ovalis – a thumbprint size depression in the interatrial septum which is a remnant of the oval foramen and its valve in the foetusThe trabeculae carneae are irregular muscular elevations that form the interior of the right ventricle.
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This question is part of the following fields:
- Anatomy
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Question 23
Incorrect
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What part of the male urethra is completely surrounded by Bucks fascia?
Your Answer:
Correct Answer: Spongiosa part
Explanation:Bucks fascia refers to the layer of loose connective tissue, nerves and blood vessels that encapsulates the penile erectile bodies, the corpa cavernosa and the anterior part of the urethra, including the entirety of the spongiose part of the urethra.
It runs with the external spermatic fascia and the penile suspensory ligament.
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This question is part of the following fields:
- Anatomy
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Question 24
Incorrect
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Seven days after undergoing an inguinal hernia repair, a 24-year old male presents with a wound that is erythematous, tender and has a purulent discharge. The most likely cause of this is which of the following?
Your Answer:
Correct Answer: Infection with Staphylococcus aureus
Explanation:Staphylococcus aureus infection is the most likely cause.
Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.
SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
The organisms are usually derived from the patient’s own body.Measures that may increase the risk of SSI include:
-Shaving the wound using a single use electrical razor with a disposable head
-Using a non iodine impregnated surgical drape if one is needed
-Tissue hypoxia
-Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.Measures that may decrease the risk of SSI include:
1. Intraoperatively
– Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
-Cover surgical site with dressingIn contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.
2. Post operatively
Tissue viability advice for management of surgical wounds healing by secondary intentionUse of diathermy for skin incisions
In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 25
Incorrect
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An 80-year-old female presents to the emergency department with symptoms consistent with mesenteric ischemia. She is quickly shifted to the operation theatre for an emergency laparotomy.
On exploration, the segment of the colon from the splenic flexure down to the rectum is ischemic.
The artery blocked in this scenario arises at what vertebral level from the aorta?Your Answer:
Correct Answer: L3
Explanation:The hindgut is from the distal third of the transverse colon down to the upper one-third of the anal canal. The inferior mesenteric artery supplies the hindgut.
The inferior mesenteric artery arises from the aorta behind the inferior border of the third part of the duodenum 3–4 cm above the aortic bifurcation, at the third lumbar vertebra level.
The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:
T12 – Coeliac trunk
L1 – Left renal artery
L2 – Testicular or ovarian arteries
L3 – Inferior mesenteric artery
L4 – Bifurcation of the abdominal aorta
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This question is part of the following fields:
- Anatomy
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Question 26
Incorrect
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In asthmatic patients, non-steroidal anti-inflammatory analgesics (NSAIDs) are generally contraindicated.
Which of the following membrane phospholipid metabolism products is most likely to cause NSAID-induced bronchospasm in asthmatic patients who are predisposed to it?Your Answer:
Correct Answer: Leukotrienes
Explanation:Nonsteroidal anti-inflammatory drugs (NSAIDs) cause bronchospasm, rhinorrhoea, and nasal obstruction in some asthma patients.
The inhibition of cyclooxygenase-1 (Cox-1) appears to be the cause of NSAID-induced reactions. This activates the lipoxygenase pathway, which increases the release of cysteinyl leukotrienes (Cys-LTs), which causes bronchospasm and nasal obstruction.
The following changes in arachidonic acid (AA) metabolism have been observed in NSAID-intolerant asthmatic patients:
Prostaglandin E2 production is low, possibly due to a lack of Cox-2 regulation.
An increase in leukotriene-C4 synthase expression and
A decrease in the production of metabolites (lipoxins) released by AA’s transcellular metabolism.Phospholipase A produces membrane phospholipids, which are converted to arachidonic acid.
TXA2 causes vasoconstriction as well as platelet aggregation and adhesion.
PGI2 causes vasodilation and a reduction in platelet adhesion.
PGE2 is involved in parturition initiation and maintenance, as well as thermoregulation.
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This question is part of the following fields:
- Pharmacology
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Question 27
Incorrect
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A paediatric patient was referred to the surgery department after an initial assessment of acute gastroenteritis was proven otherwise to be a case acute appendicitis. History revealed multiple episodes of non-bloody emesis. In the paediatric ward, the patient had already undergone fluid resuscitation and replacement, and electrolytes were already corrected. Other pertinent laboratory studies were the following:
Serum Na: 138 mmol/l
Blood glucose: 6.4 mmol/l
If the patient weighed 25 kg, which intravenous fluid maintenance regimen would be best for the child?
Your Answer:
Correct Answer: 65 ml/hr Hartmann's solution with 0% glucose
Explanation:Maintenance therapy aims to replace water and electrolytes lost under ordinary conditions. In the perioperative period, maintenance fluid administration may not sufficiently account for the increased fluid requirements caused by third-space losses into the interstitium and gut. Specific recommendations vary with the patient, the procedure, and the type and amount of fluid administered during the operation. The fluid for maintenance therapy replaces deficits arising primarily from insensible losses and urinary or gastrointestinal (GI) losses.
The maintenance fluid volume can be computed using the Holliday-Segar method.
Body weight Fluid volume
first 10 kg 4 ml/kg/hr
next 10-20 kg 2 ml/kg/hr
>20 kg 1 ml/kg/hrIn the past few years, there has been growing recognition of the increased risk of hyponatremia in hospitalized children in intensive care and postoperative settings who receive hypotonic maintenance fluids. Several studies, including a randomized controlled trial and a Cochrane analysis, found that the use of isotonic fluids is associated with fewer electrolyte derangements and concluded that isotonic maintenance fluids are preferable to hypotonic solutions in hospitalized children.
A European consensus statement suggests that an intraoperative fluid should have an osmolarity close to the physiologic range in children in order to avoid hyponatremia, an addition of 1-2.5% in order to avoid hypoglycaemia, lipolysis or hyperglycaemia and should also include metabolic anions as bicarbonate precursors to prevent hyperchloremic acidosis.
A rate of 40 ml/hr is suboptimal.
If 0.9% NaCl with 0% glucose is given at a rate of 65 ml/hr, despite of the correct infusion rate, large volumes can lead to hyperchloremic acidosis.
If 0.18% NaCl with 4% glucose is given at a rate of 65 ml/hr, infusion of this fluid regimen can lead to hyponatremia because of its hypotonicity.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 28
Incorrect
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Which of the following derived SI units is correctly expressed as their base units?
Your Answer:
Correct Answer: Volt: m2.kg.s-3.A-1
Explanation:The following units are derived SI units of measurement.
Energy or work: kg.m2.s-2
The Joule (J) is the energy transferred to an object when a force of one newton acts on that object in the direction of its motion through a distance of one meter or N.m.Power: kg.m2.s-3
The Watt (W) = rate of transfer of energy or Joule per second J/s.Force: kg.m.s-2
One Newton (N) which is the international unit of measure for force = 1 kilogram meter per second squared. 1 Newton of force is the force required to accelerate an object with a mass of 1 kilogram 1 meter per second per second.Volt: kg.m2.s-3.A-1
The volt (V) is defined as the potential difference across a conductor when a current of one ampere dissipates one watt of power or W/A.Pressure: kg.m-1.s-2
A pascal (Pa) is force per unit area or N/m2. -
This question is part of the following fields:
- Basic Physics
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Question 29
Incorrect
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Concerning the intercostal nerves, which one of the following is true?
Your Answer:
Correct Answer: Each is connected to a ganglion of the sympathetic trunk
Explanation:The intercostal nerves arise from the ventral rami of the first 11 thoracic spinal nerves. they course along the costal groove on the lower margin of the rib.
The twelfth intercoastal nerve is called the subcostal nerve. This is because it is below the 12th rib.
Each intercostal nerve is connected to a ganglion of the sympathetic trunk from which it carries preganglionic and postganglionic fibres that innervate blood vessels, sweat glands, and muscles.
The lateral and medial pectoral nerves innervates pectoralis major muscle.
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This question is part of the following fields:
- Anatomy
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Question 30
Incorrect
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The plateau phase of the myocardial action potential is as a result of:
Your Answer:
Correct Answer: Slow influx of calcium
Explanation:Cardiac conduction
Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium
Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop
Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period
Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period
Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period
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This question is part of the following fields:
- Physiology And Biochemistry
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