-
Question 1
Incorrect
-
Which of the following is incorrect with regards to atrial natriuretic peptide?
Your Answer: Promotes excretion of sodium
Correct Answer: Secreted mainly by the left atrium
Explanation:Atrial natriuretic peptide (ANP) is secreted mainly from myocytes of right atrium and ventricle in response to increased blood volume.
It is secreted by both the right and left atria (right >> left).It is a 28 amino acid peptide hormone, which acts via cGMP
degraded by endopeptidases.It serves to promote the excretion of sodium, lowers blood pressure, and antagonise the actions of angiotensin II and aldosterone.
-
This question is part of the following fields:
- Physiology And Biochemistry
-
-
Question 2
Incorrect
-
Following an acute appendicectomy, a 6-year-old child is admitted to the recovery unit.
Your consultant has requested that you prescribe maintenance fluids for the next 12 hours. The child is 21 kg in weight.
What is the most suitable fluid volume to be prescribed?Your Answer: 61 ml
Correct Answer: 732 ml
Explanation:After a paediatric case, you’ll frequently have to calculate and prescribe maintenance fluids. The ‘4-2-1 rule’ should be used as a guideline:
1st 10 kg – 4 ml/kg/hr
2nd 10 kg – 2 ml/kg/hr
Subsequent kg – 1 ml/kg/hrHence
1st 10 kg = 4 × 10 = 40 ml
2nd 10 kg = 2 × 10 = 20 ml
Subsequent kg = 1 × 1 = 1 ml
Total = 61 ml/hr61 × 12 = 732 ml over 12 hrs.
-
This question is part of the following fields:
- Physiology
-
-
Question 3
Incorrect
-
During a critical liver resection surgery, a 65-year-old man suffers uncontrolled hepatic bleeding. The 'Pringle manoeuvre is performed to stop the bleeding where the hepatic artery, portal vein, and common bile duct are clamped. These structures form the anterior boundary of the epiploic foramen.
Which of the following vessels also contributes to the boundary of this region?Your Answer: Common hepatic artery
Correct Answer: Inferior vena cava
Explanation:The epiploic foramen (foramen of Winslow or aditus to the lesser sac) is found behind the free right border of the lesser omentum. A short, 3 cm slit serves as the entrance to the lesser sac from the greater sac.
The epiploic foramen has the following boundaries:
Anteriorly: hepatoduodenal ligament, the bile duct (anteriorly on the right), the hepatic artery (anteriorly on the left), and the portal vein (posteriorly) together with nerves and lymphatics
Superiorly: the peritoneum of the posterior layer of the hepatoduodenal ligament runs over the caudate process of the liver
Posteriorly: inferior vena cava
Floor: upper border of the first part of the duodenum
The anterior and posterior walls of the foramen are normally
apposed, which partly explains why patients can develop large fluid
collections isolated to the greater or lesser sacRapid control of the hepatic artery and portal vein can be obtained by compression of the free edge of the lesser omentum (a ‘Pringle’ manoeuvre), which is a potentially useful technique in liver trauma and surgery.
-
This question is part of the following fields:
- Anatomy
-
-
Question 4
Correct
-
Regarding oxygen consumption, which of these organs has the highest consumption at rest?
Your Answer: Kidney
Explanation:Oxygen delivery is related to blood flow as most of the oxygen binds to haemoglobin in red blood cells, although a small amount is dissolved in the plasma. Blood flow per 100 g of tissue is greatest in the kidneys.
The following is the oxygen consumption rate of different organs in ml/minute/100g
Hepatoportal = 2.2
Kidney = 6.8
Brain = 3.7
Skin = 0.38
Skeletal muscle = 0.18
Heart = 11 -
This question is part of the following fields:
- Pathophysiology
-
-
Question 5
Correct
-
With regards to this state of matter which has a volume but no definite shape, particles are not tightly packed together. These are incompressible although there is free movement within the volume.
This statement best describes which one of the following states of matter?Your Answer: Liquid
Explanation:The solid state of matter has a definite volume and shape and particles are packed closely together and are incompressible. Within this tight lattice, there is enough thermal energy to produce vibration of particles.
Liquids however have a volume but no definite shape. These particles are less tightly packed together. Although there is free movement within the volume, they are incompressible.
Gases, however, have no finite shape or volume and particles are free to move rapidly in a state of random motion. They are compressible and are completely shaped by the space in which they are held. Vapours exist as a gas phase in equilibrium with identical liquid or solid matter below its boiling point.
The most prevalent state of matter in the universe is plasma which is formed by heating atoms to very high temperatures to form ions.
-
This question is part of the following fields:
- Basic Physics
-
-
Question 6
Correct
-
A subject in a study is to take 100 mg of tramadol tablets for the next eight hours. Urine samples will be taken during the 8-hour course, which will undergo analysis via liquid chromatography.
Given the following metabolites, which one would have the highest analgesic property?Your Answer: Mono-O-desmethyl-tramadol
Explanation: -
This question is part of the following fields:
- Pharmacology
-
-
Question 7
Correct
-
The prospects of setting up a health facility to help patients with ischaemic heart disease in a remote area are under consideration and you have been asked to look into it.
What's the crucial factor in finding out the amount of resources needed to go ahead with the idea?Your Answer: Prevalence
Explanation:Both incidence and prevalence are indicators of the disease frequency. While incidence tells us about the number of cases reported per population in a provided time period, prevalence is the factor you should be vigilant about as it tells us about the total number of cases that have been reported in a population at a particular point of time.
-
This question is part of the following fields:
- Statistical Methods
-
-
Question 8
Correct
-
In North America, there have been reports of paediatric patients dying after undergoing adenotonsillectomy for obstructive sleep apnoea.
Respiratory depression/obstruction is thought to be the cause of death. The codeine dose was 0.5-1 mg/kg, given every 4-6 hours.
In this group of patients, which of the following is the most likely cause of respiratory depression and obstruction?Your Answer: Exaggerated metabolism of codeine
Explanation:Codeine is easily absorbed from the gastrointestinal tract and converted to morphine and norcodeine in the liver via O- and N-demethylation. Morphine and norcodeine are excreted almost entirely by the kidney, primarily as conjugates with glucuronic acid.
By glucuronidation, phase II metabolism enzyme UDP-glucuronosyl transferase-2B7 converts morphine to morphine-3-glucuronide (M3G) and morphine-6-glucuronide (M6G) (UGT2B7).
Approximately 60% of morphine is converted to M3G, with the remaining 6-10% converted to M6G. M3G is inactive, but M6G is said to be 4 to 650 times more potent on the MOP receptor than morphine.
When codeine is consumed, cytochrome P450 2D6 in the liver converts it to morphine (CYP2D6).
Some people have DNA variations that increase the activity of this enzyme, causing codeine to be converted to morphine more quickly and completely than in others. After taking codeine, these ultra-rapid metabolisers are more likely to have higher than normal levels of morphine in their blood.
Respiratory depression/obstruction can be caused by high levels of morphine and M6G, especially in people who have a history of obstructive sleep apnoea. The estimated number of ultra-rapid metabolisers ranges from 1 to 7 per 100 people, but some ethnic groups may have as many as 28 per 100 people.
-
This question is part of the following fields:
- Pathophysiology
-
-
Question 9
Incorrect
-
Very large SI units are easily expressed using mathematical prefixes.
One terabyte is equal to which of the following numbers?Your Answer: 1,000,000,000 bytes
Correct Answer: 1,000,000,000,000 bytes
Explanation:To denote large measured units, the following SI mathematical prefixes are used:
1 deca = 10 bytes (101)
1 hecto (h) = 100 bytes
1 kilo (k)= 1,000 bytes
1 mega (M) = 1,000,000 bytes
1 giga (G) = 1,000,000,000 bytes
1 Tera (T) = 1,000,000,000,000 bytes
1 Peta (P) = 1,000,000,000,000,000 bytes -
This question is part of the following fields:
- Basic Physics
-
-
Question 10
Incorrect
-
A 55-year-old male is diagnosed with superior vena cava obstruction. What is the number of collateral circulations that exist for alternate pathways for venous return?
Your Answer: None
Correct Answer: Four
Explanation:Superior vena cava is the main vein bringing blood back to the heart. It can get partially or completely blocked by various causes, the most common being due to malignant tumours of the mediastinum.
There are collateral pathways that form in long-standing cases with 60% or more stenosis and continue venous drainage in cases of superior vena obstruction. The collaterals are classified into four as follows:
1. The azygos-hemiazygos pathway
Azygos, hemiazygos, intercostal, and lumbar veins.2. The internal and external mammary pathway
internal mammary, superior epigastric, and inferior epigastric veins and superficial veins of the thorax.3. The lateral thoracic pathway
Lateral thoracic, thoracoepigastric, superficial circumflex, long saphenous, and femoral veins to collateralize to the IVC.4. The vertebral pathway
Innominate, vertebral, intercostal, lumbar, and sacral veins to collateralize to the azygos and internal mammary pathways. -
This question is part of the following fields:
- Anatomy
-
-
Question 11
Correct
-
A 60-year-old man, with a history of excessive alcohol intake, presents for the first time in the emergency department with acute abdominal pain in the epigastric region.
On examination, the man is sweating and has a high-grade fever. His heart rate is 140/min and a BP of 92/59 mmHg.
The patient is diagnosed with acute pancreatitis. Which of the following is a complication you are most likely to see in this patient?Your Answer: Blue discolouration of the flank regions
Explanation:Bulky, greasy stools are associated with improper digestion that can be expected if the pancreas loses its exocrine function. This is common in long-term chronic pancreatitis but since this is the patient’s first presentation with such symptoms, this complication is unlikely.
Peripheral neuropathy is a common complication of chronic diabetes but has been reported with cases of chronic pancreatitis too.
Abdominal distention with shifting dullness is a classic symptom of underlying ascites. Ascites is a complication of many diseases but it is not common with the acute first-time presentation of pancreatitis.
Option E: This points towards abdominal obstruction but in the absence of the more common symptoms, nausea and bilious vomiting, this is unlikely.
Option A: Grey Turner’s sign is the pooling of blood in the retroperitoneal space between the last rib and the top of the hip. The pancreas is a retroperitoneal organ and inflammation of the pancreas can cause retroperitoneal haemorrhage. The sign takes 24-48 hours to develop and can predict a severe attack of acute pancreatitis. The patient has presented with acute pancreatitis due to his history of high alcohol intake, and acute on chronic is unlikely as this is his first presentation. He also has low blood pressure and an increased heart rate, which suggest blood loss with acute pancreatitis.
-
This question is part of the following fields:
- Anatomy
-
-
Question 12
Correct
-
Which of the following organism is highly resistant to penicillin?
Your Answer: Escherichia coli
Explanation:Penicillinase is a narrow spectrum ?-lactamase that opens the ?-lactam ring and inactivates Penicillin G and some closely related congeners. The majority of Staphylococci and some strains of gonococci, B. subtilis, E. coli, and a few other bacteria produce penicillinase.
N. meningitidis is sensitive to penicillin and less than 20% resistance is found in pseudomonas.
-
This question is part of the following fields:
- Pharmacology
-
-
Question 13
Incorrect
-
A 70-year-old female presented with a productive cough and is prescribed a bacteriostatic antibiotic?
Which of the following best explains the mechanism of action of bacteriostatic drugs?Your Answer: Peptidoglycan cross-linking inhibition
Correct Answer: Protein synthesis inhibition
Explanation:Cell membrane pore formation, Bacterial DNA damage, Peptidoglycan cross-linking inhibition, and peptidoglycan synthesis inhibitor are always lethal and such mechanisms are possible only in bactericidal drugs. But Protein synthesis inhibition would only prevent cell replication or cell growth and is responsible for bacteriostatic effects of the drug.
-
This question is part of the following fields:
- Pharmacology
-
-
Question 14
Correct
-
Which oral hypoglycaemic agent has no effect on insulin sensitivity or secretion?
Your Answer: Alpha glucosidase inhibitors
Explanation:Because alpha glucosidase inhibitors slow starch digestion in the small intestine, glucose from a meal enters the bloodstream more slowly and can be matched more effectively by an impaired insulin response or sensitivity, glucose from a meal enters the bloodstream more slowly and can be matched more effectively by an impaired insulin response or sensitivity.
Biguanides decrease hepatic glucose output while increasing glucose uptake in peripheral cells.
The meglitinides are secretagogues that act on a different site of the KATP receptors.
Insulin secretion is stimulated by sulphonylureas, which stimulate insulin secretion from pancreatic beta cells. The KATP channels are inhibited by these substances.
Insulin-sensitive genes are influenced by thiazolidinediones, which increase the production of mRNAs for insulin-dependent enzymes. As a result, the cells make better use of glucose.
-
This question is part of the following fields:
- Pharmacology
-
-
Question 15
Incorrect
-
Transthoracic echocardiogram (TTE) can be used to investigate the function of the heart in patients with suspected heart failure. The aim is to measure the ejection fraction, but to do that, the stroke volume must first be measured. How is stroke volume calculated?
Your Answer: End systolic volume - end diastolic volume
Correct Answer: End diastolic volume - end systolic volume
Explanation:Cardiac output = stroke volume x heart rate
Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%
Stroke volume = end diastolic LV volume – end systolic LV volume
Pulse pressure = Systolic Pressure – Diastolic Pressure
Systemic vascular resistance = mean arterial pressure / cardiac output
Factors that increase pulse pressure include:
-a less compliant aorta (this tends to occur with advancing age)
-increased stroke volume -
This question is part of the following fields:
- Physiology And Biochemistry
-
-
Question 16
Incorrect
-
Calcium homeostasis is regulated by parathormone (PTH).
Which of the following PTH actions is most likely to cause calcium to be released from bone?Your Answer: Direct stimulation of osteoclasts
Correct Answer: Indirect stimulation of osteoclasts
Explanation:The hormone parathyroid hormone (PTH) and the receptor parathyroid hormone type 1 (PTH1-Rc) are important regulators of blood calcium homeostasis.
PTH can cause a rapid release of calcium from the matrix in bone, but it also affects long-term calcium metabolism by acting directly on bone-forming osteoblasts (by binding to PTH1-Rc) and indirectly on bone-resorbing osteoclasts.
PTH causes changes in the synthesis and/or activity of several proteins, including osteoclast-differentiating factor, also known as TRANCE or RANKL, when it acts on osteoblasts.
RANK receptors are found on the cell surfaces of osteoclast precursors. The osteoclasts are activated when RANKL binds to the RANK receptors. Osteoclasts lack PTH receptors, whereas osteoblasts do. Osteoclasts are activated indirectly when the RANK receptor binds to the RANKL secreted by osteoblasts, resulting in bone resorption. PTH1 receptors are found in osteoclasts, but they are few.
PTH activates G-protein coupled receptors in all target cells via adenylate cyclase.
The PTH2 receptor is most abundant in the nervous system and pancreas, but it is not a calcium metabolism regulator. It is abundant in the septum, midline thalamic nuclei, several hypothalamic nuclei, and the dorsal horn of the spinal cord, as well as the cerebral cortex and basal ganglia. Expression in pancreatic islet somatostatin cells is the most prominent on the periphery.
The distribution of the receptor is being used to test functional hypotheses. It may play a role in pain modulation and hypothalamic releasing-factor secretion control.
-
This question is part of the following fields:
- Pathophysiology
-
-
Question 17
Incorrect
-
Regarding gas laws, which one best explains the ability of a Bourdon gauge to measure temperature?
Your Answer: Boyle's law
Correct Answer: Charles's law
Explanation:Charles’ Law states that there is a direct correlation between temperature and volume, where pressure and amount gas are constant. As temperature increases, volume also increases.
Boyle’s Law states that Pressure is inversely proportional to volume, assuming that temperature and amount of gas are constant. As volume increases, pressure decreases. In Dalton’s law of partial pressure, the total pressure exerted by a mixture of gases is equal to the sum of the partial pressure of the gases in mixture.
According to Henry’s Law for concentration of dissolved gases, at a constant temperature, the amount of a given gas that dissolves in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid. An equivalent way of stating the law is that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid.
Gay-Lussac’s Law states that the pressure of a given mass of gas varies directly with the absolute temperature of the gas, when the volume is kept constant. This law is very similar to Charles’ Law, with the only difference being the type of container. Whereas the container in a Charles’ Law experiment is flexible, it is rigid in a Gay-Lussac’s Law experiment.
-
This question is part of the following fields:
- Basic Physics
-
-
Question 18
Incorrect
-
A transport ventilator is powered by an air/oxygen mix using a full oxygen cylinder (class CD) with an internal capacity of 2 litres, and pressure of 23,000 kPa, with a gas flow of 4 litres/minute.
The ventilator also has a control resulting in an additional gas consumption of 1 litre/minute.
How long will it take for the cylinder to empty?Your Answer: 55 minutes
Correct Answer: 92 minutes
Explanation:The Drager Oxylog® 1000 is a pneumatically powered, time-dependent, volume-titrated emergency ventilator with a pressure limit. It is compatible with CD cylinder oxygen. The CD cylinder is a strong and lightweight cylinder usually composed of aluminium or Kevlar. The internal cylinder volume is 2 litres, and the pressure of a full cylinder is 230 bar. The volume of the full cylinder is determined by applying Boyle’s law: P1 × V1 = P2 × V2
Where:
P1= pressure of a full cylinder (230 bar)
V1= volume of oxygen at that pressure (2 litres)
P2= final pressure (1 bar), and
V2= volume of oxygen in the full cylinder.Substituting values into the equation:
230 × 2 = 1 x V2
V2 = 460 litres. The flow of fresh gas is 4 litres/minute + 1 litre/minute required by the control, making a total of 5 litres/minute. The amount of time it takes for the cylinder to empty would be the total volume of oxygen in the full cylinder divided by the amount of oxygen expelled per minute: 460/5 = 92, meaning it would take 92 minutes for the cylinder to empty. -
This question is part of the following fields:
- Anaesthesia Related Apparatus
-
-
Question 19
Correct
-
A 72-year old man is experiencing a cardiac risk evaluation for the management of obstructive umbilical hernia. Echocardiogram demonstrates an aortic valve area=0.59cm with a pressure of 70mmHg. Five years ago, he had mild myocardial infarction complicated with pulmonary oedema. Now he encounters angina with little exertion.
Which of the following factor is the foremost profoundly weighted using Deysky's cardiac risk scoring system in this case?Your Answer: Aortic stenosis
Explanation:Detsky’s Modified cardiac risk classification system in patients undergoing non-cardiac surgery:
Age more than 70: 05 points
History of myocardial infarction:
Less than 6 months: 10 points
More than 6 months: 5 pointsAngina Pectoris:
Angina with minimal exertion: 10 points
Angina at any level of exertion: 20 points
Pulmonary Oedema:
Within 7 days: 10 points
At any time: 5 pointsSuspected aortic valve stenosis with valve area <0.6cm2: 20 points Arrhythmia: Any rhythm other than sinus or sinus with premature atrial complexes (PACs): 5 points More than 5 premature ventricular contractions: 5 points
Emergency Surgery: 10 points
Deficient general medical condition: 5 pointsRisk classification:
Grade I: 0-15 points = low risk
Grade II: 15-30 points = moderate risk
Grade III: >30 points = high risk -
This question is part of the following fields:
- Pathophysiology
-
-
Question 20
Incorrect
-
With a cervical dilation of 9 cm, a 23-year-old term primigravida is in labour. She is otherwise in good health. She's been in labour for 14 hours and counting.
Early foetal pulse decelerations can be seen on the cardiotocograph, and a recent foetal scalp blood sample revealed a pH of 7.25.
Which of the following is true about this patient's care and management?Your Answer: The patient requires a category 1 caesarean section under spinal anaesthetic
Correct Answer: Monitor for downward trend in fetal scalp blood pH as caesarean section is not indicated at the present time
Explanation:Once the decision to deliver a baby by caesarean section has been made, it should be carried out with a level of urgency commensurate with the risk to the baby and the mother’s safety.
There are four types of caesarean section urgency:
Category 1 – Endangering the life of the mother or the foetus
Category 2 – Maternal or foetal compromise that is not immediately life threatening
Category 3 – Early delivery is required, but there is no risk to the mother or the foetus.
Category 4: Elective delivery at a time that is convenient for both the mother and the maternity staff.Caesarean sections for categories 1 and 2 should be performed as soon as possible after the decision is made, especially for category 1. For category 1 caesarean sections, a decision to deliver time of 30 minutes is currently used.
In most cases, Category 2 caesarean sections should be performed within 75 minutes of making the decision.
The condition of the woman and the unborn baby should be considered when making a decision for a quick delivery, as it may be harmful in some cases.
There is no evidence of foetal compromise in the example above (early foetal pulse decelerations and a pH of less than 7.25). Early foetal pulse decelerations are most likely caused by the uterus compressing the foetal head. The foetus is not harmed by these. A spinal anaesthetic is preferred over a general anaesthetic whenever possible.
If the foetal scalp blood pH is greater than 7.25, it’s a good idea to repeat the test later and look for any changes. When a foetus decelerates, the mother should be given oxygen, kept in a left lateral position, and kept hydrated to avoid the need for a caesarean section.
-
This question is part of the following fields:
- Pathophysiology
-
-
Question 21
Incorrect
-
About the mechanism of action of bendroflumethiazide, Which of the following is correct?
Your Answer: Carbonic anhydrase inhibitor
Correct Answer: Sodium-chloride symporter inhibitor
Explanation:Sodium-chloride symporter inhibitor.
The thiazide sensitive sodium chloride symporter is inhibited by thiazides at the proximal portion of the distal convoluted tubule leading to increased sodium and water excretion. Increased delivery of sodium to the distal portion of the distal convoluted tubule promotes potassium loss. This is why thiazides are associated with hyponatraemia and hypokalaemia.
Carbonic anhydrase inhibitors are used mainly in the treatment of glaucoma. They act on the proximal convoluted tubule to promote bicarbonate, sodium and potassium loss.
Sodium potassium chloride symporter is inhibited by Loop diuretics.
Epithelial sodium channels are inhibited by Amiloride.
Drugs which lead to nephrogenic diabetes insipidus such as lithium and demeclocycline, are Inhibitors of vasopressin. -
This question is part of the following fields:
- Pharmacology
-
-
Question 22
Incorrect
-
Which of the following hormones is secreted by the posterior pituitary?
Your Answer: Oestradiol
Correct Answer: Oxytocin
Explanation:The posterior pituitary is made up mostly of neural tissue. It is responsible for the storage and release of 2 hormones:
– antidiuretic hormone (ADH)
– oxytocin.These two hormones are synthesised in the supraoptic and paraventricular nuclei of the hypothalamus.
-
This question is part of the following fields:
- Pathophysiology
-
-
Question 23
Correct
-
A 89-year old male has hypertension, with a blood pressure of 170/68 mmHg and has been admitted to the hospital. He is on no regular medications. His large pulse pressure can be accounted for by which of the following?
Your Answer: Reduced aortic compliance
Explanation:Cardiac output = stroke volume x heart rate
Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%
Stroke volume = end diastolic LV volume – end systolic LV volume
Pulse pressure = Systolic Pressure – Diastolic Pressure
Systemic vascular resistance = mean arterial pressure / cardiac output
Factors that increase pulse pressure include:
-a less compliant aorta (this tends to occur with advancing age)
-increased stroke volume -
This question is part of the following fields:
- Physiology And Biochemistry
-
-
Question 24
Correct
-
Clearance techniques are used to assess renal glomerular function.
Which of the following is the most accurate marker for glomerular filtration rate measurement?Your Answer: Inulin
Explanation:The perfect glomerular filtration marker is:
The human body is not harmed by it.
Chemical or physical methods are used to accurately measure
Extracellular fluid (ECF) compartment is freely and evenly diffusible.
Inability to access the intracellular fluid (ICF) compartment
Filtration in the kidney is the only way to remove it from the blood.The ideal marker should not be reabsorbed into the bloodstream by the renal tubules or other urinary system components.
Creatinine is an endogenous substance that is filtered freely by the glomerulus and secreted by the proximal tubule. As a result, creatinine clearance consistently underestimates GFR. In healthy people, this overestimation ranges from 10% to 40%, but it is higher and more unpredictable in patients with chronic kidney disease.
The gold standard method of inulin clearance necessitates an intravenous infusion and several hours of timed urine collection, making it costly and time-consuming. Inulin is hard to come by and is difficult to mix and keep as a solution.
Exogenous filtration markers include the following:
Although plasma clearance of 51chromium EDTA is a widely used method in Europe, tubular reabsorption can occur.
Because 125I-iothalamate can be excreted by renal tubules in the urine, it cannot be used in patients who have an iodine assay.Radioactive substances must be stored, administered, and disposed of according to these methods.
The glomerulus filters para-aminohippuric acid (PAH) freely, and any that remains in the peritubular capillaries is secreted into the proximal convoluted tubules. This marker is used to determine the amount of blood flowing through the kidneys.
-
This question is part of the following fields:
- Pathophysiology
-
-
Question 25
Incorrect
-
A paediatric patient was referred to the surgery department after an initial assessment of acute gastroenteritis was proven otherwise to be a case acute appendicitis. History revealed multiple episodes of non-bloody emesis. In the paediatric ward, the patient had already undergone fluid resuscitation and replacement, and electrolytes were already corrected. Other pertinent laboratory studies were the following:
Serum Na: 138 mmol/l
Blood glucose: 6.4 mmol/l
If the patient weighed 25 kg, which intravenous fluid maintenance regimen would be best for the child?
Your Answer: 40 ml/hr 0.45% NaCl with 5% glucose
Correct Answer: 65 ml/hr Hartmann's solution with 0% glucose
Explanation:Maintenance therapy aims to replace water and electrolytes lost under ordinary conditions. In the perioperative period, maintenance fluid administration may not sufficiently account for the increased fluid requirements caused by third-space losses into the interstitium and gut. Specific recommendations vary with the patient, the procedure, and the type and amount of fluid administered during the operation. The fluid for maintenance therapy replaces deficits arising primarily from insensible losses and urinary or gastrointestinal (GI) losses.
The maintenance fluid volume can be computed using the Holliday-Segar method.
Body weight Fluid volume
first 10 kg 4 ml/kg/hr
next 10-20 kg 2 ml/kg/hr
>20 kg 1 ml/kg/hrIn the past few years, there has been growing recognition of the increased risk of hyponatremia in hospitalized children in intensive care and postoperative settings who receive hypotonic maintenance fluids. Several studies, including a randomized controlled trial and a Cochrane analysis, found that the use of isotonic fluids is associated with fewer electrolyte derangements and concluded that isotonic maintenance fluids are preferable to hypotonic solutions in hospitalized children.
A European consensus statement suggests that an intraoperative fluid should have an osmolarity close to the physiologic range in children in order to avoid hyponatremia, an addition of 1-2.5% in order to avoid hypoglycaemia, lipolysis or hyperglycaemia and should also include metabolic anions as bicarbonate precursors to prevent hyperchloremic acidosis.
A rate of 40 ml/hr is suboptimal.
If 0.9% NaCl with 0% glucose is given at a rate of 65 ml/hr, despite of the correct infusion rate, large volumes can lead to hyperchloremic acidosis.
If 0.18% NaCl with 4% glucose is given at a rate of 65 ml/hr, infusion of this fluid regimen can lead to hyponatremia because of its hypotonicity.
-
This question is part of the following fields:
- Physiology And Biochemistry
-
-
Question 26
Incorrect
-
A transport ventilator connected to a size CD oxygen cylinder has a setting of air/oxygen entrainment ratio of 1:1 and a minute volume set at 10 litres/minute.
Which value best approximates to the FiO2?Your Answer: 0.5
Correct Answer: 0.6
Explanation:A nominal volume of 2 litres is contained in a CD cylinder. It has a pressure of 230 bar when full and contains litres 460 L of useable oxygen at STP.
For every 1000 mL 100% oxygen there will be an entrainment of 1000 mL or air (20% oxygen) in an air/oxygen mix.
The average concentration is, therefore, 120/2=60% or 0.6.
-
This question is part of the following fields:
- Physiology
-
-
Question 27
Correct
-
A delayed hypersensitivity reaction is type ____?
Your Answer: IV
Explanation:Type I – immediate hypersensitivity reaction
Examples are: Atopy, urticaria, Anaphylaxis, Asthma( IgE mediated).
Type II – Antibody mediated cytotoxic reaction
Examples are: Autoimmune haemolytic anaemia, Thrombocytopenia( IgM or IgG mediated).
Type III – Immune complex mediated reaction
Examples are: Serum sickness,SLE – IgG., Farmers lungs, rheumatoid arthritis
Type IV – Delayed hypersensitivity reaction
Examples are: Contact dermatitis, drug allergies.
Type V – Autoimmune
Graves’
Myasthenia – IgM or IgG. -
This question is part of the following fields:
- Pathophysiology
-
-
Question 28
Incorrect
-
An experiment is designed to investigate that how three diets having different sugar content affect the body weight to a different level.
Which one of the following test will determine a statistically significant difference among the diets?Your Answer: Students t-test
Correct Answer: ANOVA
Explanation:Chi-square test is used to determine the statistically significant different between categorical variables. It also determines the difference between expected frequencies and the observed frequencies.
Mann Whitney U test is used to determine the statistically significant different between two independent groups.
Wilcoxon’s test is the test of dependency. it determines the statistically significant difference between two dependent groups.
Student t-test is one of the most commonly used method to test the hypothesis. It determines the significant difference between the means of two different groups.
ANOVA (analysis of variance) is similar to student’s t-test.
ANOVA is a statistical method used to determines the statistically significant difference between the mean of more than two group. In this experiment as we are dealing with three different group, ANOVA is most suitable test to determine the difference between each groups.
-
This question is part of the following fields:
- Statistical Methods
-
-
Question 29
Correct
-
Which of the following is the best marker of mast cell degranulation in a patient with suspected anaphylaxis who became hypotensive and developed widespread urticarial rash after administration of Augmentin?
Your Answer: Tryptase
Explanation:Mast cell tryptase is a reliable marker of mast cell degranulation. Tryptase is a protease enzyme that acts via widespread protease-activated receptors (PARs).
-
This question is part of the following fields:
- Pharmacology
-
-
Question 30
Incorrect
-
A breakthrough lipid-lowering therapy for stroke had a number needed to treat (NNT) of 20 for the prevention of the primary end-point. These results can be best described as:
Your Answer: For 1000 patients treated with active therapy, there would be 20 fewer strokes
Correct Answer: For 1000 patients treated with active therapy, there would be 50 fewer strokes
Explanation:Number needed to treat (NNT) is a time specific epidemiological measure that indicates how many patients would be require for an intervention to prevent one additional bad outcome. A perfect NNT would be 1, where everyone improves with treatment, thus the higher the NNT, the less effective the treatment.
Thus if you treat 1000 patients then you will expect to have 50 fewer strokes.
-
This question is part of the following fields:
- Statistical Methods
-
00
Correct
00
Incorrect
00
:
00
:
0
00
Session Time
00
:
00
Average Question Time (
Secs)