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Question 1
Incorrect
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Heights of 100 individuals(adults) who were administered steroids at any stage during childhood was studied. The mean height was found to be 169cm with the data having a standard deviation of 16cm. What will be the standard error associated with the mean?
Your Answer: 1.69
Correct Answer: 1.6
Explanation:Standard error can be calculated by the following formula:
Standard Error= (Standard Deviation)/√(Sample Size)
= (16) / √(100)
= 16 / 10
= 1.6 -
This question is part of the following fields:
- Statistical Methods
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Question 2
Correct
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A double blind placebo control clinical trial is done. Which of these is correct about it?
Your Answer: The clinician assessing the effects of the treatment does not know which treatment the patient has been given
Explanation:A ‘double blind crossover study’ happens when every patient receive both treatments.
It is incorrect to say that only half of the patients do not know which treatment they receive because in a double blind placebo control clinical trial ALL of the patients are blind to their treatment choice .
If some of the patients are not treated, they would be aware that they were not being treated and it could not be considered a blind trial.
In a double blind placebo control clinical trial both the clinician and the patient are blind to the treatment choice. The clinician assessing the effects of the treatment, therefore, does not know which treatment the patient has been given.
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This question is part of the following fields:
- Statistical Methods
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Question 3
Incorrect
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Your manager asks you to inform patients that are suffering from a chronic pain about a trial that is going to be conducted in order to determine the efficacy of a novel analgesic. What phase is the trial currently in?
Your Answer: Phase 0
Correct Answer: Phase 2
Explanation:Phase 0 trials assist the scientists in studying the behaviour of drugs in humans by micro dosing patients. They are used to speed up the developmental process. They have no measurable therapeutic effect and efficiency.
Phase 1 is associated with assessing whether a drug is safe to use or not. The process is extensive and can take up to several months. It also involves healthy participants (less than 100) that are paid to take part in the study. The side effects upon increasing dosage are also addressed by the study. The effects the drug has on humans including how its absorbed, metabolized and excreted are studied. Approximately 70% of the drugs pass this phase.
Phase 2 trials involve patients that are suffering from the disease under study and are associated with determining the efficiency and the optimum dosage of the drug.
Phase 3 also assesses the efficacy but at a higher scale with larger population sample.
Phase 4 trials are involved with the long term effects and side effects of the drug.
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This question is part of the following fields:
- Statistical Methods
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Question 4
Correct
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Of the stated laws, which is correct?
Your Answer: Boyle's law states that at constant temperature the volume of a given mass of gas varies inversely with absolute pressure.
Explanation:Boyle’s law is correctly stated as it states that the volume of a gas of known mass is inversely proportional with absolute pressure, at a constant temperature.
Beer’s law states that radiation absorption by a solution of known thickness and concentration is identical to that of a solution of double thickness and half concentration.
Bougner’s (or Lambert’s) law states that every layer with the same thickness will absorb the same amount of radiation as it passes through.
Graham’s law states that the diffusion rate of a gas is inversely related to the square root of its molecular weight.
Raoult’s law states that the reduction of a solvent’s vapour pressure is directly proportional to the solute’s molar concentration.
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This question is part of the following fields:
- Statistical Methods
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Question 5
Incorrect
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A controlled retrospective study's level of evidence is?
Your Answer: Level 4
Correct Answer: Level 3
Explanation:Level 1 – High-quality randomised controlled trial with statistically significant difference or no statistically significant difference but narrow confidence intervals (prospective controlled)
Level 2 – Prospective comparative study (prospective uncontrolled)
Level 3 – Case-control study, retrospective comparative study (retrospective controlled)
Level 4 – Case series (retrospective uncontrolled)
Level 5 – Expert opinion.
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This question is part of the following fields:
- Statistical Methods
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Question 6
Incorrect
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A doctor has recorded the number of times the patient did not attend (DNA) the clinic for a study over a 10 month period.
Number of DNAs in 10 Months Number of Patients
1st Month 0
2nd Month 3
3rd Month 1
4th Month 45
5th Month 2
6th Month 0
7th Month 1
8th Month 4
9th Month 4
10th Month 2
Which among the following is the most apt way of summarizing mean value?Your Answer: Range
Correct Answer: Median
Explanation:Variance and standard deviation indicate the dispersion of the plot from mean value and thus are not really helpful in summarizing the mean.
Range is the difference between maximum and minimum value that is 45 in this case.
The mean in this case is 6.2 due to the presence of an outlier 45. In the presence of outlier mean can be misleading as it is quite sensitive to skewness in data.
Mode is the most frequent value. In this case mode has 4 values: 0,1,2,4.
In case of skewedness, median is the most apt representative of the mean as it is not affected by outliers. In this case since the data set has even values i.e. 10. Median is the average of the 5th & 6th entry after arranging the data in ascending order like that in case of the question (0,0,1,1,2,2,3,4,4,45). This turns out to be 2.
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This question is part of the following fields:
- Statistical Methods
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Question 7
Incorrect
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A survey aimed at finding out mean glucose level in individuals that took antipsychotics medicines was conducted. The results were as follows:
Mean Value: 7mmol/L
Standard Deviation: 6mmol/L
Sample Size: 9
Standard Error: 2mmol/L
For a confidence interval of 95%, which of the option presents the correct range up to the nearest value?Your Answer: 2-12 mmol/L
Correct Answer: 3-11 mmol/L
Explanation:Key Point: While finding out confidence intervals, standard errors are used. Standard error and Standard deviation are two distinct entities and should not be confused.
For 99.7% confidence interval, you can find the range as follows:
Multiply the standard error by 3.
Subtract the answer from mean value to get the lower limit.
Add the answer obtained in step 1 from the mean value to get the upper limit.
The range turns out to be 1-13 mmol/L.
For a confidence interval of 68%, multiply the standard error with 1 and repeat the process. The range found for this interval is 3-11 mmol/L.
For a 95% confidence interval. Standard Error is multiplied by 1.96 which gives us the limit ranging from 3.08 to 10.92 mmol/L which could be approximated to 3-11 mmol/L.
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This question is part of the following fields:
- Statistical Methods
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Question 8
Incorrect
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The population incidence of a disease is best described by?
Your Answer: The number of cases of a disease in a population over a defined time period
Correct Answer: The number of new cases of a disease per population in a defined period
Explanation:The incidence of a disease is the number of new cases of the disease in a population over a defined time period.
The prevalence of a disease is the number of cases of the disease in a population over a defined time period describes. It is NOT the number of new cases.
The number of new cases of a disease only, has no denominator (time period or population) from which to derive an incidence.
The number of new cases of a disease seeking medical treatment is the incidence of patients seeking medical treatment NOT the incidence of the disease in a population.
The death rate from a disease is the number of patients dying from the disease in a population.
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This question is part of the following fields:
- Statistical Methods
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Question 9
Correct
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The Kappa statistic (aka Cohen's kappa coefficient) can be used to measure which of the following?
Your Answer: Inter-rater reliability
Explanation:The Kappa Statistic or Cohen’s Kappa is a statistical measure of inter-rater reliability for categorical variables. It is used when two raters both apply a criterion based on a tool to assess whether or not some condition occur. A good example can be two doctors rating individuals for diabetes occurrence on the basis of symptoms.
It gives a quantitative measure of the magnitude of agreement between observers.
Kappa can take any value between 0 and 1. 0 implies the observers are in complete disagreement and a value of 1 implies complete agreement.
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This question is part of the following fields:
- Statistical Methods
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Question 10
Correct
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Which among the following is not true regarding disease rates?
Your Answer: The odds ratio is synonymous with the risk ratio
Explanation:The relative risk (also known as risk ratio [RR]) is the ratio of risk of an event in one group (e.g., exposed group) versus the risk of the event in the other group (e.g., nonexposed group).
The odds ratio (OR) is the ratio of odds of an event in one group versus the odds of the event in the other group.
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This question is part of the following fields:
- Statistical Methods
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Question 11
Incorrect
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The average diastolic blood pressure of a control group was found out to be 80 with a standard deviation of 5 in a study aimed at exploring the efficiency of a novel anti-hypertensive drug. The trial was randomised.
Making an assumption that the data is normally distributed, find out the number of patients that had diastolic blood pressure over 90.Your Answer: 10%
Correct Answer: 3%
Explanation:Since the data is normally distributed, 95% of the values lie with in the interval 70 to 90. This can be calculated as follows:
Interval= Mean ± ( 2 times standard deviation)
= 80 ± 2(5)
= 80 ± 10
= 70 & 90The rest of the 5% are distributed symmetrically beyond 90 and below 70 which means 2.5% of the values lie above 90.
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This question is part of the following fields:
- Statistical Methods
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Question 12
Incorrect
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Which term among the following is used for the proportion of a particular disease that would be eradicated from a population if the rate of disease were to be reduced to that of the group that has not been exposed to it?
Your Answer: Risk ratio
Correct Answer: Attributable proportion
Explanation:The attributable risk is the rate of a disease in an exposed group to that of a group that has not been exposed to it. It involves the measure of association that is pertinent to making decisions for the individuals.
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This question is part of the following fields:
- Statistical Methods
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Question 13
Incorrect
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When there is a relation between two variables due to the existence of a confounding factor, this association is termed as:
Your Answer: Direct
Correct Answer: Indirect
Explanation:When the association among any two classes of object is defined by the presence of a third entity it is termed as indirect association. For an instance, the age of the employee may affect the rate of pay, which would have implications on job satisfaction. So, in this example, an indirect relationship between age and job satisfaction exists due to a third party i.e. rate of pay.
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This question is part of the following fields:
- Statistical Methods
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Question 14
Incorrect
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Two different anti-viral treatments are being evaluated for COVID-19 in a clinical study.
Which of the following statistical method should be opted to compare survival time with?Your Answer: Absolute risk reduction
Correct Answer: Hazard ratio
Explanation:The hazard ratio (HR) is simply a comparison of two hazards in a study. It provides an estimate of the ratio of the hazard rates between the experimental group and a control group over the entire study duration. It is typically used when analysing survival over time, hence is the most suitable statistical method in this case.
An odds ratio is a statistic that quantifies the strength of the association between two events, A and B. It is the “measure of association” for a case-control study.
The Pearson product-moment correlation coefficient (Pearson’s correlation, for short) is a measure of the strength and direction of association that exists between two variables. An example would be if scientists wanted to evaluate the relationship between quality of certain population of rice and their genetic make-up.
Relative risk is the ratio of the risks for an event for the exposure group to the risks for the non-exposure group. Thus relative risk provides an increase or decrease in the likelihood of an event based on some exposure. Relative risk measures the association between the exposure and the outcome.
Absolute risk reduction is the number of percentage points your own risk goes down if you do a preventive act such as stop drinking alcohol. It depends on what your risk factors are to begin with.
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This question is part of the following fields:
- Statistical Methods
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Question 15
Incorrect
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Which among the following is summed up by F statistic?
Your Answer: Wilcoxon's test
Correct Answer: ANOVA
Explanation:ANOVA is based upon within group variance (i.e. the variance of the mean of a sample) and between group variance (i.e. the variance between means of different samples). The test works by finding out the ratio of the two variances mentioned above. (Commonly known as F statistic).
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This question is part of the following fields:
- Statistical Methods
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Question 16
Incorrect
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You have always been curious about the effects of statins. While going through a study, something ticks you off and makes you think that they are way more common then the data suggests and are mostly under reported. In search of some concrete evidence, you decide to conduct a study of your own. While doing research, you come across a recent study that highlights the long term effects of statins.
Which of the following types of study could that have been?Your Answer: Case-control study
Correct Answer: Clinical trial, Phase 4
Explanation:In general practice, majority of phase 3 trials and some of the trials conducted in phase 2 are randomized. Because phase 4 trials require a huge sample size, they are not randomized as much. The primal reason behind conducting phase 3 trials is to test the efficiency and safety in a significant sample population. At this point it is assumed that the drug is effective up to a certain extent.
During a case-control study, subjects that exhibit outcomes of interest are compared with those who don’t show the expected outcome. The extent of exposure to a particular risk factor is then matched between cases and controls. If the exposure among cases surpasses controls, it becomes a risk factor for the outcome that is being studied.
Pilot studies are conducted on a lower and much smaller level, to assess if a randomized controlled trial of the crucial components of a study will be plausible.
Phase 4 trials are the ones that are conducted after its established that the drug is effective and is approved by the regulating authority for use. These trials are concerned with the side effects and potential risks associated with the long term usage of the drug.
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This question is part of the following fields:
- Statistical Methods
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Question 17
Incorrect
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The required sample size in a trial of a new therapeutic agent varies with?
Your Answer: Experience of the investigator
Correct Answer: Level of statistical significance required
Explanation:The level of statistical significance required influences the sample size used. This is because sample size is used in the calculation of SD/SE.
Sample size does not affect
The level of acceptance
The alternative hypothesis with a general level set at p<0.05
The test to be used.Experience of the investigator and the type of patient recruited should have no bearing on the required sample size.
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This question is part of the following fields:
- Statistical Methods
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Question 18
Incorrect
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The phenomenon that the patients behaved in a different manner when they know that they are being observed is termed as?
Your Answer: Murrays predicament
Correct Answer: Hawthorne effect
Explanation:Hawthorne effect explains the change in any behavioural aspect owing to the awareness that the person is being observed.
Simpson’s Paradox explains the association developed when the data from several groups is combined to form a single larger group.The remaining terms are made up.
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This question is part of the following fields:
- Statistical Methods
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Question 19
Correct
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A study designed to examine the benefits of adding a new antiplatelet to aspirin after a myocardial infraction. The recorded results give us the percentage of patients that reported myocardial infraction within a three month period. The percentage was 4% and 3% for aspirin and the combination of drugs respectively.
How many further patients needed to be treated in order for one patient to avoid any more heart attacks during 3 months?Your Answer: 100
Explanation:Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.
It can be found as:
NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).
where ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)
So,
ARR= (0.04-0.03)
ARR= 0.01
NNT= 1/0.01
NNT=100
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This question is part of the following fields:
- Statistical Methods
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Question 20
Correct
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A 68-year-old man presents worried about his risk of motor neurone disease. No symptoms have developed, but his father suffered from motor neurone disease. Recently, his cousin has also been diagnosed with amyotrophic lateral sclerosis. He searched the internet for screening tests for motor neurone disease and found a blood test called ‘neuron’, and requests to have it done. You search this blood test and find a prospective study going on evaluating the potential benefits of this blood test. On average, this test diagnosed patients with the disease 8 months earlier than the patients who are diagnosed on the basis of their clinical symptoms. The patients diagnosed using this neuron test also survived, on average, 48 months from the diagnosis, whereas the patients diagnosed clinically survived an average of 39 months from the diagnosis. Considering the clear benefits, you decide to have it done on the patient.
Which of the following options best relate to the above scenario?Your Answer: Lead-time bias
Explanation:Hypochondriasis is an illness anxiety disorder, and describes excessively worriedness about the presence of a disease. While the woman is concerned about her possibility of developing motor neurone disease, she understands that no symptoms have yet appeared. Hypochondriasis involves patients who refuse to accept that they don’t have the disease, even if the results come back negative.
Late Look Bias occurs when the data is gathered or analysed at an inappropriate time e.g. when many of the subjects suffering from a fatal disease have died. This type of biasness might occur in some retrospective studies of motor neurone disease, but is not applicable to this prospective study.
In procedure bias, the researcher decides assignment of a treatment versus control and assigns particular patients to one group or the other non-randomly. This is unlikely to have occurred in this case, although it is not mentioned specifically. Of all the options, lead time-bias is a better answer.
The Hawthorne Effect refers to groups modifying their behaviour simply because they are aware of being observed. Any differences in the behaviour have not been mentioned in the question, and it is highly unlikely that a change in patient’s behaviour would have affected their length of survival in this case.
The correct option is lead-time bias. Even if the new blood test diagnoses the disease earlier, it doesn’t affect the outcome, as the survival time was still on average 43 months from the onset of symptoms in both groups. With the help of blood test, the disease was only detected 8 months earlier.
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This question is part of the following fields:
- Statistical Methods
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Question 21
Incorrect
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A study of blood pressure measurements is being performed in patients with chronic kidney disease.
Considering that the results are normally distributed, what percentage of values lie within two standard deviations of the mean blood pressure reading?Your Answer: 97.50%
Correct Answer: 95.40%
Explanation:Normal distribution, also called Gaussian distribution, the most common distribution function for independent, randomly generated variables, and describes the spread for many biological and clinical measurements.
Properties of the Normal distribution
symmetrical i.e. Mean = mode = median
68.3% of values lie within 1 SD of the mean
95.4% of values lie within 2 SD of the mean
99.7% of values lie within 3 SD of the mean
The empirical rule, or the 68-95-99.7 rule, tells you where most of the values lie in a normal distribution: Around 68% of values are within 1 standard deviation of the mean.
Around 95% of values are within 2 standard deviations of the mean. Around 99.7% of values are within 3 standard deviations of the mean.
the standard deviation (SD) is a measure of how much dispersion exists from the mean.SD = square root (variance)
The empirical rule, or the 68-95-99.7 rule states where most of the values lie in a normal distribution. Around 68% of values fall within 1 S.D of the mean, about 95% within 2 S.D of the mean, and about 99.7% of values within 3 S.D of the mean. Therefore, 95.4% is the most reasonable answer if results are normally distributed.
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This question is part of the following fields:
- Statistical Methods
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Question 22
Correct
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In medical testing, there are true negative, true positive, false positive and false negative results for some test.
How are the sensitivity of these predictive tests calculated?Your Answer: True positives / (true positives + false negatives)
Explanation:The following terms are used in medical testing:
True negative – The test is negative and the patient does not have the disease.
True positive – The test is positive and the patient has the disease.
False positive – The test is positive but the patient does not have the disease.
False negative – The test is negative but the patient has the disease.The sensitivity of a predictive test = true positives / (true positives + false negatives).
The specificity of a test = true negatives / (false positives + true negatives).
The negative predictive value of a test = true negatives / (false negatives + true negatives).
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This question is part of the following fields:
- Statistical Methods
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Question 23
Incorrect
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A graph was plotted after administration of fentanyl infusion to a patient. The following are the x- and y-axis of the graph:
X-axis: Dose of fentanyl
Y-axis: Mu receptor occupancy, measured using positron emission tomography
Given the data above, what would be the best representation of the graph if the data on the x-axis are converted to logarithms?Your Answer: Sigmoid curve to a straight line (Hill plot)
Correct Answer: Rectangular hyperbola to sigmoid curve
Explanation:The dose-response curve plots the graph of the dose (drug concentration) versus the response. As doses increase, the response increment diminishes; finally, doses may be reached at which no further increase in response can be achieved. This relation between drug concentration and effect is traditionally described by a hyperbolic curve. When the x-axis is plotted in log scale, the graph yields a sigmoid curve.
Efficacy (Emax) and potency (EC50) can be derived from this curve. Emax is the maximal effect achievable, with increasing concentration of a drug. EC50 is the concentration of the drug, wherein half of the maximal effect is achieved.
When the graph is plotted using a log [response/1-response] against log dose, the sigmoid curve becomes a straight line (Hill plot). A graph that transforms from a straight line to exponential curve is mathematically incorrect. A graph that transforms from either a wash-in or wash-out exponential curve to a straight line comes from an initial set of data plotted against time, to a logarithmic transformation of the initial data set against time.
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This question is part of the following fields:
- Statistical Methods
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Question 24
Incorrect
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During the analysis phase, which of the provided options serves to control confounding factors?
Your Answer: Blinding
Correct Answer: Stratification
Explanation:During analytical stage a technique called stratification is used for controlling confounding variables. This technique involves sorting out the data into discernible groups.
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This question is part of the following fields:
- Statistical Methods
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Question 25
Incorrect
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After a bariatric surgery, average weight loss observed in patients is 18 kg. The standard deviation was found to be 3 kg. What is the percentage of patients that lie between 9 and 27 kg?
Note: Assume that the curve is normally distributed.Your Answer: 95.40%
Correct Answer: 99.70%
Explanation:9 & 27 can be obtained by subtracting and adding 9 from the mean. 9 is three times the standard deviation and we know that 99.7% values lie within 3 standard deviations from the mean. We can find the interval for 99.7% to verify in the following way:
For 99.7% confidence interval, you can find the range as follows:
1. Multiply the standard error by 3.
2. Subtract the answer from mean value to get the lower limit.
3. Add the answer obtained in step 1 from the mean value to get the upper limit.
4. The range turns out to be 9-27 kg.
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This question is part of the following fields:
- Statistical Methods
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Question 26
Incorrect
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A double-blinded randomised controlled trial is proposed to assess the effectiveness of a new blood pressure medication.
Which type of bias can be avoided by ensuring the patient and doctor are blinded?Your Answer: Non-responder bias
Correct Answer: Expectation bias
Explanation:Observers may subconsciously measure or report data in a way that favours the expected study outcome. Therefore, by blinding the study we can eliminate expectation bias.
Recall bias is a systematic error that occurs when the study participants omit details or do not remember previous events or experiences accurately.
Verification can occur during investigations when there is a difference in testing strategy between groups of individuals, which might lead to biasness due to differing ways of verifying the disease of interest.
Nonresponse bias is the bias that occurs when the people who respond to a survey differ significantly from the people who do not respond to the survey.
A distortion that modifies an association between an exposure and an outcome because a factor is independently associated with the exposure and the outcome. Randomization is the best way to reduce the risk of confounding.
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This question is part of the following fields:
- Statistical Methods
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Question 27
Incorrect
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In the United Kingdom, a new breast cancer screening test is being conducted compared to the conventional use of mammography. This test predicts that if the breast cancer is diagnosed at an earlier stage, it could improve the survival rate but the overall results remains constant.
This is an example of what kind of bias?Your Answer: Length time bias
Correct Answer: Lead time bias
Explanation:Recall bias introduced when participants in a study are systematically more or less likely to recall and relate information on exposure depending on their outcome status.
In procedure bias, the researcher decides assignment of a treatment versus control and assigns particular patients to one group or the other non-randomly. This is unlikely to have occurred in this case, although it is not mentioned specifically.
Self Selection or volunteer bias occur when those subjects are selected to participate in the study who are not the representative of the entire target population. those subjects may be from high socio-economic status and practice those activities or lifestyle that improves their health.
Lead-time bias occurs when a disease is detected by a screening test at an earlier time point rather than it would have been diagnosed by its clinical appearance. In this bias, earlier detection improves the survival time in the intervention group.
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This question is part of the following fields:
- Statistical Methods
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Question 28
Correct
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A new proton pump inhibitor (PPI) is being evaluated in elderly patients who are taking aspiring. Study designed has 120 patients receiving the PPI, while a control group of 240 individuals is given the standard PPI. Over a span of 6 years, 24 of the group receiving the new PPI had an upper GI bleed compared to 60 individuals who received the standard PPI.
How would you calculate the absolute risk reduction?Your Answer: 5%
Explanation:Absolute risk reduction = (Control event rate) – (Experimental event rate)
Experimental event rate = 24 / 120 = 0.2
Control event rate = 60 / 240 = 0.25
Absolute risk reduction = 0.25 – 0.2 = 0.05 = 5% reduction
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This question is part of the following fields:
- Statistical Methods
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Question 29
Correct
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A new study is being carried out on the measurement of a new cardiovascular disease biomarker, and its applications in preoperative screening. The data for this study is expected to be normally distributed.
Which of the following statements is true about normal distributions?Your Answer: The mean, median and mode are the same value
Explanation:The correct answer is the mean, median and mode of normally distributed data are the same value. This is as a result of the bell shaped curve which is equal on both sides.
The bell-shape indicates that values around the mean are more frequent in occurrence than the values farther away.
In a normal distribution:
1) +/- one standard deviation of the mean accounts for 68% of the data.
2) +/- two standard deviations of the mean accounts for 95% of the data.
3) +/- three standard deviations of the mean accounts for 99.7% of the data. -
This question is part of the following fields:
- Statistical Methods
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Question 30
Correct
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Which measure of central tendency is most useful for a continuous, non-skewed data?
Your Answer: Mean
Explanation:Mean, also known as the average, is the most common measure of central tendency. It is the sum of all observed values divided by the number of observation. It is not useful for skewed data, which has an abnormal distribution. It is useful, instead, for numerical data that have symmetric distribution. It reflects the contributions of each data in the group, and are sensitive to outliers.
The median is the value that falls in the middle position when the observations are ranked in order from the smallest to the largest. If the number of observations is odd, the median is the middle number. If it is even, the median is the average of the two middle numbers. Unlike the mean, the median is useful on skewed data, and can be used for ordinal or numerical data if skewed.
The mode is the value that occurs with the greatest frequency in a set of observations, and is utilized for bimodal distribution.
The variance and the standard deviation are not measures of central tendency, but of dispersion.
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This question is part of the following fields:
- Statistical Methods
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