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  • Question 1 - Given the following hormones, which of these will stimulate glycogenesis and gluconeogenesis? ...

    Incorrect

    • Given the following hormones, which of these will stimulate glycogenesis and gluconeogenesis?

      Your Answer: Insulin

      Correct Answer: Corticosteroids

      Explanation:

      Insulin is the primary anabolic hormone that dominates regulation of metabolism during digestive phase. It promotes glucose uptake in skeletal myocytes and adipocytes, and other insulin-target cells. It promotes glycogenesis and inhibits gluconeogenesis.

      Glucagon is the primary counterregulatory hormone that increases blood glucose levels, primarily through its effects on liver glucose output.

      Similar to glucagon, growth hormone, catecholamines and corticosteroids are also counterregulatory factors released in response to decreased glucose concentrations. Growth hormone promotes glycogenolysis and inhibits gluconeogenesis; catecholamines stimulate glycogenolysis and gluconeogenesis; while corticosteroids stimulate glycogenesis and gluconeogenesis.

    • This question is part of the following fields:

      • Pathophysiology
      44.2
      Seconds
  • Question 2 - A 64-year old lady has been diagnosed with hypertension. Her GP explains how...

    Correct

    • A 64-year old lady has been diagnosed with hypertension. Her GP explains how this occurs, and that blood pressure is determined by multiple factors which include action by the heart, nervous system and the diameter of the blood vessels. This lady's cardiac output (CO) is 4L/min. Her exam today revealed a mean arterial pressure (MAP) of 140 mmHg.
      Using these values, her systemic vascular resistance (SVR) is which of these?

      Your Answer: 35mmHgâ‹…minâ‹…mL-1

      Explanation:

      Impaired ventricular relaxation reduces diastolic filling and therefore preload.

      Decreased blood volume decreases preload due to reduced venous return.

      Heart failure is characterized by reduced ejection fraction and therefore stroke volume.

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure (is increased by stroke volume) = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume
      Aortic stenosis would decrease stroke volume as end systolic volume would increase.
      This is because of an increase in afterload, an increase in resistance that the heart must pump against due to a hard stenotic valve.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      157.2
      Seconds
  • Question 3 - Weight of all of your patients in the ICU is analysed, and shows...

    Incorrect

    • Weight of all of your patients in the ICU is analysed, and shows that your date set is skewed.

      Which of the following will correctly show the average weight of your patients?

      Your Answer: Variance

      Correct Answer: Median

      Explanation:

      The question mentions a quantitative, ratio scale data set. The use of mean would be ideal under normal circumstances, however, in this situation median is preferred as it is less sensitive to the skewness of data. The median is usually preferred to other measures of central tendency when your data set is skewed (i.e., forms a skewed distribution)

    • This question is part of the following fields:

      • Statistical Methods
      46.2
      Seconds
  • Question 4 - A doctor has recorded the number of times the patient did not attend...

    Incorrect

    • A doctor has recorded the number of times the patient did not attend (DNA) the clinic for a study over a 10 month period.

      Number of DNAs in 10 Months Number of Patients
      1st Month 0
      2nd Month 3
      3rd Month 1
      4th Month 45
      5th Month 2
      6th Month 0
      7th Month 1
      8th Month 4
      9th Month 4
      10th Month 2

      Which among the following is the most apt way of summarizing mean value?

      Your Answer: Standard deviation

      Correct Answer: Median

      Explanation:

      Variance and standard deviation indicate the dispersion of the plot from mean value and thus are not really helpful in summarizing the mean.

      Range is the difference between maximum and minimum value that is 45 in this case.

      The mean in this case is 6.2 due to the presence of an outlier 45. In the presence of outlier mean can be misleading as it is quite sensitive to skewness in data.

      Mode is the most frequent value. In this case mode has 4 values: 0,1,2,4.

      In case of skewedness, median is the most apt representative of the mean as it is not affected by outliers. In this case since the data set has even values i.e. 10. Median is the average of the 5th & 6th entry after arranging the data in ascending order like that in case of the question (0,0,1,1,2,2,3,4,4,45). This turns out to be 2.

    • This question is part of the following fields:

      • Statistical Methods
      61.9
      Seconds
  • Question 5 - Which of the following statements is true with regards to the Krebs' cycle...

    Incorrect

    • Which of the following statements is true with regards to the Krebs' cycle (also known as the tricarboxylic acid cycle or citric acid cycle)?

      Your Answer:

      Correct Answer: Alpha-ketoglutarate is a five carbon molecule

      Explanation:

      Krebs’ cycle (tricarboxylic acid cycle or citric acid cycle) is a sequence of reactions in which acetyl coenzyme A (acetyl-CoA) is metabolised and this results in carbon dioxide and hydrogen atoms production.

      This series of reactions occur in the mitochondria of eukaryotic cells, not the cytoplasm. The cycle requires oxygen and so, cannot function under anaerobic conditions.

      It is the common pathway for carbohydrate, fat and some amino acids oxidation and is required for high energy phosphate bond formation in adenosine triphosphate (ATP).

      When pyruvate enters the mitochondria, it is converted into acetyl-CoA. This represents the formation of a 2 carbon molecule from a 3 carbon molecule. There is loss of one CO2 but formation of one NADH molecule. Acetyl-CoA is condensed with oxaloacetate, the anion of a 4 carbon acid, to form citrate which is a 6 carbon molecule.

      Citrate is then converted into isocitrate, alpha-ketoglutarate, succinyl-CoA, succinate, fumarate, malate and finally oxaloacetate.

      The only 5 carbon molecule in the cycle is alpha-ketoglutarate.

    • This question is part of the following fields:

      • Physiology
      0
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  • Question 6 - Which of the following is correct about the action of bile salts? ...

    Incorrect

    • Which of the following is correct about the action of bile salts?

      Your Answer:

      Correct Answer: Emulsification of lipids

      Explanation:

      The emulsification and absorption of fats requires Bile salts.

      Absorption of fats is associated with the activation of lipases in the intestine.

      Bile salts are involved in fat soluble vitamin absorption and are reabsorbed in the terminal ileum (B12 is NOT fat soluble).

      Although Vitamin B12 is also absorbed in the terminal ileum, it is a water soluble vitamin (as are B1, nicotinic acid, folic acid and vitamin C) .

      The gastric parietal cells secretes Intrinsic factor that is essential for the absorption of B12.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 7 - A 68-year-old man presents worried about his risk of motor neurone disease. No...

    Incorrect

    • A 68-year-old man presents worried about his risk of motor neurone disease. No symptoms have developed, but his father suffered from motor neurone disease. Recently, his cousin has also been diagnosed with amyotrophic lateral sclerosis. He searched the internet for screening tests for motor neurone disease and found a blood test called ‘neuron’, and requests to have it done. You search this blood test and find a prospective study going on evaluating the potential benefits of this blood test. On average, this test diagnosed patients with the disease 8 months earlier than the patients who are diagnosed on the basis of their clinical symptoms. The patients diagnosed using this neuron test also survived, on average, 48 months from the diagnosis, whereas the patients diagnosed clinically survived an average of 39 months from the diagnosis. Considering the clear benefits, you decide to have it done on the patient.

      Which of the following options best relate to the above scenario?

      Your Answer:

      Correct Answer: Lead-time bias

      Explanation:

      Hypochondriasis is an illness anxiety disorder, and describes excessively worriedness about the presence of a disease. While the woman is concerned about her possibility of developing motor neurone disease, she understands that no symptoms have yet appeared. Hypochondriasis involves patients who refuse to accept that they don’t have the disease, even if the results come back negative.

      Late Look Bias occurs when the data is gathered or analysed at an inappropriate time e.g. when many of the subjects suffering from a fatal disease have died. This type of biasness might occur in some retrospective studies of motor neurone disease, but is not applicable to this prospective study.

      In procedure bias, the researcher decides assignment of a treatment versus control and assigns particular patients to one group or the other non-randomly. This is unlikely to have occurred in this case, although it is not mentioned specifically. Of all the options, lead time-bias is a better answer.

      The Hawthorne Effect refers to groups modifying their behaviour simply because they are aware of being observed. Any differences in the behaviour have not been mentioned in the question, and it is highly unlikely that a change in patient’s behaviour would have affected their length of survival in this case.

      The correct option is lead-time bias. Even if the new blood test diagnoses the disease earlier, it doesn’t affect the outcome, as the survival time was still on average 43 months from the onset of symptoms in both groups. With the help of blood test, the disease was only detected 8 months earlier.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 8 - Concerning platelets one of the following is true ...

    Incorrect

    • Concerning platelets one of the following is true

      Your Answer:

      Correct Answer: Are formed in the bone marrow from megakaryocytes

      Explanation:

      Platelets are fragments of megakaryocytes and they are encapsulated by membrane.

      They have no nucleus but are metabolically active and are able to express membrane receptors and release stored substances when triggered. adenosine diphosphate and serotonin are 2 of its content.

      Because they have no nucleus, they are not able to produce new proteins. This is why aspirin and other drugs affect function for their entire lifespan after exposure. Its lifespan is approximately 9-10 days in normal individuals.

      Platelets does NOT PRODUCE prostacyclin but are able to produce nitric oxide, prostaglandins and thromboxane.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 9 - Which of the following is the best associated option with Kaplan-Meier survival plot?...

    Incorrect

    • Which of the following is the best associated option with Kaplan-Meier survival plot?

      Your Answer:

      Correct Answer: An estimate of decreasing survival with time after an event.

      Explanation:

      Also known as the “product limit estimate’’, the Kaplan-Meier survival plot is used to estimate the true survival function from the collected data.

      Using this plot, probabilities of occurrence of an event at a certain point in time can be computed. The successive probabilities are multiplied by any earlier computed probabilities to get the final estimate. For a given population, the survival probability at any particular time on the plot = (number of subjects living at the start – number of subjects who died)/number of subjects living at the start.

      The description of a scatter plot is a graphical representation using Cartesian coordinates to display values for more than two variables for data set. It is used for to assess the relationship between 2 different variables.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 10 - Which of these anaesthetics has the best chance of preventing HPV (hypoxic pulmonary...

    Incorrect

    • Which of these anaesthetics has the best chance of preventing HPV (hypoxic pulmonary vasoconstriction)?

      Your Answer:

      Correct Answer: Desflurane 2 MAC

      Explanation:

      Resistance pulmonary arteries constrict in response to alveolar and airway hypoxia, diverting blood to better-oxygenated alveoli.

      In atelectasis, pneumonia, asthma, and adult respiratory distress syndrome, hypoxic pulmonary vasoconstriction optimises O2 uptake. Hypoxic pulmonary vasoconstriction helps maintain systemic oxygenation during single-lung anaesthesia.

      A redox-based O2 sensor within pulmonary artery smooth muscle cells is involved in hypoxic pulmonary vasoconstriction. The production of reactive oxygen species by smooth muscle cells in the pulmonary artery varies in proportion to PaO2. Hypoxic removal of these redox second messengers inhibits voltage-gated potassium channels, depolarizing smooth muscle cells in the pulmonary artery.

      L-type calcium channels are activated by depolarization, which raises cytosolic calcium and causes hypoxic pulmonary vasoconstriction. Some anaesthetics suppress this response, increasing the risk of further deterioration in ventilation perfusion mismatch.

      Agents that inhibit HPV are ether, halothane, and desflurane (>1.6 MAC).
      Agents with no effect on HPV include thiopentone, fentanyl, desflurane (1MAC), isoflurane (<1.5MAC), sevoflurane(1MAC), and propofol.

    • This question is part of the following fields:

      • Pharmacology
      0
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  • Question 11 - A young male is operated on for an open inguinal hernia repair. During...

    Incorrect

    • A young male is operated on for an open inguinal hernia repair. During the procedure, the cord is mobilized, and the deep inguinal ring is located.

      What structure forms the lateral wall of the deep inguinal ring?

      Your Answer:

      Correct Answer: Transversalis fascia

      Explanation:

      The deep inguinal ring is the entrance of the inguinal canal. It is an opening in the transversalis fascia around 1 cm above the inguinal ligament. Therefore, the superolateral wall is made by the transervalis fascia.

      The inferior epigastric vessels run medially to the deep inguinal ring forming its inferomedial border.

      The inguinal canal extends obliquely from the deep inguinal ring to the superficial inguinal ring.
      An indirect inguinal hernia arises through the deep inguinal ring lateral to the inferior epigastric vessels.

    • This question is part of the following fields:

      • Anatomy
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  • Question 12 - Campylobacter is which type of bacteria? ...

    Incorrect

    • Campylobacter is which type of bacteria?

      Your Answer:

      Correct Answer: sdgsdf

      Explanation:

      Campylobacter is the commonest bacterial cause of infectious intestinal disease in the UK. The majority of cases are caused by the Gram-negative bacillus Campylobacter jejuni which is spread by the faecal-oral route. The incubation period is 1-6 days.

      Features include a prodrome phase with headaches and malaise, then diarrhoea occurs which is often bloody.
      There is often abdominal pain which may mimic appendicitis.

      It is usually self-limiting but treatment is warranted if the infection is severe or the infection occurs in an immunocompromised patient.
      Severe infection comprises of high fever, bloody diarrhoea, or more than eight stools per day or symptoms last for more than one week.
      This management would include antibiotics and the first-line antibiotic is clarithromycin.
      Ciprofloxacin is an alternative but there are strains with decreased sensitivity to ciprofloxacin which can be frequently isolated.

      Complications include:
      1.Guillain-Barre syndrome may follow Campylobacter
      2. Jejuniinfections
      3. Reactive arthritis
      4. Septicaemia, endocarditis, arthritis

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 13 - The fluids with the highest osmolarity is? ...

    Incorrect

    • The fluids with the highest osmolarity is?

      Your Answer:

      Correct Answer: 0.45% N. Saline with 5% glucose

      Explanation:

      The concentration of solute particles per litre (mosm/L) = the osmolarity of a solution. Changes in water content, ambient temperature, and pressure affects osmolarity. The osmolarity of any solution can be calculated by adding the concentration of key solutes in it.

      Individual manufacturers of crystalloids and colloids may have different absolute values but they are similar to these.

      0.45% N. Saline with 5% glucose:
      Tonicity – hypertonic
      Osmolarity – 405 mosm/L
      Kilocalories (kCal) – 107

      0.9% N. Saline:
      Tonicity – isotonic
      Osmolarity – 308 mosm/L
      Kilocalories (kCal) – 0

      5% Dextrose:
      Tonicity – isotonic
      Osmolarity – 253 mosm/L
      Kilocalories (kCal) – 170

      Gelofusine (154 mmol/L Na, 120 mmol/L Cl):
      Tonicity – isotonic
      Osmolarity – 274 mosm/L
      Kilocalories (kCal) – 0

      Hartmann’s solution:
      Tonicity – isotonic
      Osmolarity – 273 mosm/L
      Kilocalories (kCal) – 9

    • This question is part of the following fields:

      • Physiology
      0
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  • Question 14 - A randomized controlled trail has been conducted to compare two drugs used for...

    Incorrect

    • A randomized controlled trail has been conducted to compare two drugs used for the early management of acute severe asthma in the emergency department. After being allocated to the randomized groups, many patients have been excluded due to deleterious effect to the drugs.

      How the data would be analysed?

      Your Answer:

      Correct Answer: Include the patients who drop out in the final data set

      Explanation:

      Randomized controlled trails will be analysed by the intention-to-treat (ITT) approach. It provides unbiased comparisons among the treatment groups. ITT analyses are done to avoid the effects of dropout, which may break the random assignment to the treatment groups in a study.

      ITT analysis is a comparison of the treatment groups that includes all patients as originally allocated after randomization.

      In order to include such participants in an analysis, outcome data could be imputed which involves making assumptions about the outcomes in the lost participants.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 15 - Monitoring of which of the following is indicated in the prevention of propofol...

    Incorrect

    • Monitoring of which of the following is indicated in the prevention of propofol infusion syndrome?

      Your Answer:

      Correct Answer: Lactate

      Explanation:

      Propofol infusion syndrome (PRIS) is characterized by lactic acidosis, bradyarrhythmia, rhabdomyolysis, cardiac and renal failure, and often leads to death. So, lactate monitoring is advised in patients with propofol infusion syndrome.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 16 - A medical student performed a case control study for her final dissertation. It...

    Incorrect

    • A medical student performed a case control study for her final dissertation. It involved examining marijuana exposure in a group of patients with and without COPD.

      What form of bias is the study most susceptible to?

      Your Answer:

      Correct Answer: Recall bias

      Explanation:

      Case control studies in particular are prone to recall bias, people who are suffering from COPD might sometimes relate the ailment to marijuana usage in past and hence contrary to the control group, they are more able to describe to what extent they have been using the drug in the past.

      As recommended, all the doctors should make sure that there practice is based on evidence and thus it is paramount that the doctors learn to appraise the paper in a critical manner i.e. ability to detect any potential source of bias.

      Detection Bias: Outcomes are more looked for in one group than the other.

      Observer Bias: Subjectivity of observers regarding the outcome.

      Publication bias: Not publishing the results of a valid study just because they are negative or uninteresting can be termed as publication bias.

      Recall bias: Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.

      Response Bias: The participants that filled out the response forms containing information that was going to be used for a trial, don’t represent the target population.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 17 - Regarding a drug whose elimination exhibits first-order kinetics, which of the following statements...

    Incorrect

    • Regarding a drug whose elimination exhibits first-order kinetics, which of the following statements is correct?

      Your Answer:

      Correct Answer: The rate of elimination is proportional to plasma concentration

      Explanation:

      The elimination of phenytoin follows first order kinetics. Plasma concentrations determine the rate of elimination. The relationship between drug X plasma concentration and time is described by an exponential process in the following equation used to describe the rate of elimination:

      C = C0. e-kt

      C=drug concentration, C0= drug concentration at time zero (extrapolated), k = rate constant and t=time

      As enzyme systems become saturated when phenytoin concentrations are above the usual range, clearance of the medication becomes zero-order. The medication is metabolised at a constant pace, regardless of its plasma levels. Aspirin and ethyl alcohol are two more significant examples of medications that operate in this way.

      A plot of drug concentration with time is a washout exponential curve.

      A graph of concentration with time is a straight line i.e. Zero-order kinetics

      The amount eliminated per unit time is constant defines the point at which zero order kinetics commences.

      Elimination involves a rate-limiting reaction operating at its maximal velocity is incorrect.

      The half life of the drug is proportional to the drug concentration in the plasma corresponds to a definition of first-order kinetics.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 18 - Intracellular effectors are activated by receptors on the cell surface. These receptors receive...

    Incorrect

    • Intracellular effectors are activated by receptors on the cell surface. These receptors receive signals that are relayed by second messenger systems.

      In the human body, which second messenger is most abundant?

      Your Answer:

      Correct Answer: Calcium ions

      Explanation:

      Second messengers relay signals to target molecules in the cytoplasm or nucleus when an agonist interacts with a receptor on the cell surface. They also amplify the strength of the signal. The most ubiquitous and abundant second messenger is calcium and it regulates multiple cellular functions in the body.

      These include:
      Muscle contraction (skeletal, smooth and cardiac)
      Exocytosis (neurotransmitter release at synapses and insulin secretion)
      Apoptosis
      Cell adhesion to the extracellular matrix
      Lymphocyte activation
      Biochemical changes mediated by protein kinase C.

      cAMP is either inhibited or stimulated by G proteins.

      The receptors in the body that stimulate G proteins and increase cAMP include:

      Beta (?1, ?2, and ?3)
      Dopamine (D1 and D5)
      Histamine (H2)
      Glucagon
      Vasopressin (V2).

      The second messenger for the action of nitric oxide (NO) and atrial natriuretic peptide (ANP) is cGMP.

      The second messengers for angiotensin and thyroid stimulating hormone are inositol triphosphate (IP3) and diacylglycerol (DAG).

    • This question is part of the following fields:

      • Physiology
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  • Question 19 - What structure is most posterior at the porta hepatis? ...

    Incorrect

    • What structure is most posterior at the porta hepatis?

      Your Answer:

      Correct Answer: Portal vein

      Explanation:

      The structures in the porta hepatis from anterior to posterior are:

      The ducts: Most anterior are the left and right hepatic ducts.

      The arteries: Next are the left and right hepatic arteries

      The veins: Next is the portal vein

      The epiploic foramen of Winslow lies most posterior at the porta hepatis.

    • This question is part of the following fields:

      • Anatomy
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  • Question 20 - A 2-year old male is admitted to the surgery ward for repair of...

    Incorrect

    • A 2-year old male is admitted to the surgery ward for repair of an inguinal hernia. He weighs 10 kg. To provide post-operative analgesia, levobupivacaine was administered into the epidural space.

      Given the information above, what is the most appropriate dose for the hernia repair?

      Your Answer:

      Correct Answer: 0.25% 7.5 ml

      Explanation:

      Caudal analgesia using bupivacaine is a widely employed technique for achieving both intraoperative and early postoperative pain relief. 0.5 ml/kg of 0.25% plain bupivacaine is favoured by many practitioners who employ this fixed scheme for procedures involving sacral dermatomes (circumcision, hypospadias repair) as well as lower thoracic dermatomes (orchidopexy). However, there are other dosing regimens for caudal blocks with variable analgesic success rates: These include 0.75 ml/kg, 1.0 ml/kg and 1.25 ml/kg.

      A study indicated that plain bupivacaine 0.25% at a dose of 0.75 ml/kg compared to a dose of 0.5 ml/kg when administered for herniotomies provided improved quality of caudal analgesia with a low side effects profile. There were consistently more patients with favourable objective pain scale (OPS) scores at all timelines, increased the time to the analgesic request with similar postoperative consumption of paracetamol in the group of patients who received 0.75 ml/kg of 0.25% bupivacaine.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 21 - An experiment is designed to investigate that how three diets having different sugar...

    Incorrect

    • An experiment is designed to investigate that how three diets having different sugar content affect the body weight to a different level.

      Which one of the following test will determine a statistically significant difference among the diets?

      Your Answer:

      Correct Answer: ANOVA

      Explanation:

      Chi-square test is used to determine the statistically significant different between categorical variables. It also determines the difference between expected frequencies and the observed frequencies.

      Mann Whitney U test is used to determine the statistically significant different between two independent groups.

      Wilcoxon’s test is the test of dependency. it determines the statistically significant difference between two dependent groups.

      Student t-test is one of the most commonly used method to test the hypothesis. It determines the significant difference between the means of two different groups.

      ANOVA (analysis of variance) is similar to student’s t-test.

      ANOVA is a statistical method used to determines the statistically significant difference between the mean of more than two group. In this experiment as we are dealing with three different group, ANOVA is most suitable test to determine the difference between each groups.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 22 - A 50-year old female came to the Obstetric and Gynaecology department for an...

    Incorrect

    • A 50-year old female came to the Obstetric and Gynaecology department for an elective hysterectomy under general anaesthesia. Upon physical examination, she was noted to be obese (BMI = 40).

      Regarding the optimal dose of thiopentone, which of the following parameters must be considered for the computation?

      Your Answer:

      Correct Answer: Lean body weight

      Explanation:

      Using a lean body weight metric encompasses a more scientific approach to weight-based dosing. Lean body weight reflects the weight of all ‘non-fat’ body components, including muscle and vascular organs such as the liver and kidneys. As lean body weight contributes to approximately 99% of a drug’s clearance, it is useful for guiding dosing in obesity.

      This metric has undergone a number of transformations. The most commonly cited formula derived by Cheymol is not optimal for dosing across body compositions and can even produce a negative result. A new formula has been developed that appears stable across different body sizes, in particular the obese to morbidly obese.

      A practical downfall of the calculation of lean body weight (and other body size descriptors) is the numerical complexity, which may not be palatable to a busy clinician. Often limited time is available for prescribing and an immediate calculation is required. Lean body weight calculators are available online, for example in the Therapeutic Guidelines.

      Using total body weight assumes that the pharmacokinetics of the drug are linearly scalable from normal-weight patients to those who are obese. This is inaccurate. For example, we cannot assume that a 150 kg patient eliminates a drug twice as fast as a 75 kg patient and therefore double the dose. Clinicians are alert to toxicities with higher doses, for example nephro- and neurotoxicity with some antibiotics and chemotherapeutics, and bleeding with anticoagulants. Arbitrary dose reductions or ‘caps’ are used to avoid these toxicities, but if too low can result in sub-therapeutic exposure and treatment failure.

      Body surface area is traditionally used to dose chemotherapeutics. It is a function of weight and height and has been shown to correlate with cardiac output, blood volume and renal function. However, it is controversial in patients at extremes of size because it does not account for varying body compositions. As a consequence, some older drugs such as cyclophosphamide, paclitaxel and doxorubicin were ‘capped’ (commonly at 2 m^2) potentially resulting in sub-therapeutic treatment. Recent guidelines suggest that unless there is a justifiable reason to reduce the dose (e.g. renal disease), total body weight should be used in the calculation of body surface area, until further research is done. Little research into dosing based on body surface area has been conducted for other medicines.

      Ideal body weight was developed for insurance purposes not for drug dosing. It is a function of height and gender only and, like body surface area, does not take into account body composition. Using ideal body weight, all patients of the same height and sex would receive the same dose, which is inadequate and generally results in under-dosing. For example a male who has a total body weight of 150 kg and a height of 170 cm will have the same ideal body weight as a male who is 80 kg and 170 cm tall. Both could potentially receive a mg/kg dose based on 65 kg (ideal body weight).

    • This question is part of the following fields:

      • Pharmacology
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  • Question 23 - A 61-year-old woman with myasthenia gravis is admitted to the ER with type...

    Incorrect

    • A 61-year-old woman with myasthenia gravis is admitted to the ER with type II respiratory failure. There is a suspicion of myasthenic crisis.

      She is in a semiconscious state. Her blood pressure is 160/90 mmHg, pulse is 110 beats per minute, temperature is 37°C, and oxygen saturation is 84 percent.

      With a PaCO2 of 75 mmHg (10 kPa) breathing air, blood gas analysis confirms she is hypoventilating.

      Which of the following values is the most accurate representation of her alveolar oxygen tension (PAO2)?

      Your Answer:

      Correct Answer: 7.3

      Explanation:

      The following is the alveolar gas equation:

      PAO2 = PiO2 − PaCO2/R

      Where:

      PAO2 is the partial pressure of oxygen in the alveoli.
      PiO2 is the partial pressure of oxygen inhaled.
      PaCO2 stands for partial pressure of carbon dioxide in the arteries.
      The amount of carbon dioxide produced (200 mL/minute) divided by the amount of oxygen consumed (250 mL/minute) equals R = respiratory quotient. With a normal diet, the value is 0.8.

      By subtracting the partial pressure exerted by water vapour at body temperature, the PiO2 can be calculated:

      PiO2 = 0.21 × (100 kPa − 6.3 kPa)
      PiO2 = 19.8

      Substituting:
      PAO2 = 19.8 − 10/0.8
      PAO2 = 19.8 − 12.5
      PAO2 = 7.3k Pa

    • This question is part of the following fields:

      • Physiology
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  • Question 24 - The plateau phase of the myocardial action potential is as a result of:...

    Incorrect

    • The plateau phase of the myocardial action potential is as a result of:

      Your Answer:

      Correct Answer: Slow influx of calcium

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 25 - Which of the following nerves is responsible for relaying sensory information from the...

    Incorrect

    • Which of the following nerves is responsible for relaying sensory information from the laryngeal mucosa?

      Your Answer:

      Correct Answer: Laryngeal branches of the vagus

      Explanation:

      Sensory innervation of the larynx is controlled by branches of the vagus nerve.

      The internal and external bifurcations of the superior laryngeal nerve is responsible for sensory innervation of the aspect of the larynx superior to the vocal cords, while the recurrent laryngeal nerve is responsible for sensory innervation of the intrinsic musculature of the larynx except for the cricothyroid muscle.

    • This question is part of the following fields:

      • Anatomy
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  • Question 26 - A patient in the post-anaesthesia care unit was put on ephedrine for episodes...

    Incorrect

    • A patient in the post-anaesthesia care unit was put on ephedrine for episodes of hypotension. Initial bolus doses were effective and the patient became normotensive, until, a few hours later, there was a noticeable drop in the blood pressure despite administration of another dose of ephedrine.

      Which of the following best explains the situation above?

      Your Answer:

      Correct Answer: Tachyphylaxis

      Explanation:

      When responsiveness diminishes rapidly after administration of a drug, the response is said to be subject to tachyphylaxis. This may be due to frequent or continuous exposure to agonists, which often results in short-term diminution of the receptor response.

      Many mechanisms may be responsible, such as blocking access of G protein to activated receptor, or receptor molecules internalized by endocytosis to prevent exposure to extracellular molecules.

      Tolerance occurs when larger doses are required to produce the same effect. This may be due to changes in receptor number or function due to exposure to the drug.

      Desensitization refers to the common situation where the biological response to a drug diminishes when it is given continuously or repeatedly. It is a chronic loss of response, occurring over a longer period than tachyphylaxis. It may be possible to restore the response by increasing the dose (or concentration) of the drug but, in some cases, the tissues may become completely refractory to its effect.

      Drug dependence is defined as a psychic and physical state of the person characterized by behavioural and other responses resulting in compulsions to take a drug, on a continuous or periodic basis in order to experience its psychic effect and at times to avoid the discomfort of its absence.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 27 - A 59-year-old smoker booked for an emergency laparotomy is in the anaesthetic room...

    Incorrect

    • A 59-year-old smoker booked for an emergency laparotomy is in the anaesthetic room prior to intubation. He is breathing room air and an arterial blood gas is obtained on insertion of an arterial cannula and sent for analysis.

      The following results are available:

      Haemoglobin 75 g/L
      PaO2 10.7 kPa
      PaCO2 5.2 kPa

      After intravenous induction, intubation is difficult and he rapidly begins to de-saturate.

      Which of the following is most effective in prolonging the oxygen de-saturation time?

      Your Answer:

      Correct Answer: Pre-oxygenation with 100% O2 for three minutes

      Explanation:

      Breathing 100% oxygen for three minutes will provide the best reservoir of oxygen during apnoea by oxygenating the functional residual capacity (FRC).

      Sitting at 45 degrees might increase the FRC and improve oxygen reserve but not compared with 100% oxygenation.

      The following table compares the oxygen reserves in the body following pre-oxygenation with room air and 100% oxygen:

      Compartment Factors Room air (mL) 100% O2 (mL)
      Lung FAO2, FRC 630 2850
      Plasma PaO2, DF, PV 7 45
      Red blood cells Hb, TGV, SaO2 788 805
      Myoglobin – 200 200
      Interstitial space – 25 160

      FAO2 = alveolar fraction of oxygen.
      FRC = Functional residual capacity.
      PaO2 = partial pressure of oxygen dissolved in arterial blood
      DF = dissolved form.
      PV = plasma volume.
      TG = total globular volume .
      Hb = haemoglobin concentration.
      SaO2 = arterial oxygen saturation

      Stopping smoking one month prior to surgery will not be more effective than pre-oxygenation with 100% oxygen though it may reduce postoperative pulmonary complications. Note that both long term and short term abstinence reduces pulse rate and blood pressure thus reducing oxygen consumption and also reduce carboxyhaemoglobin levels.

      Blood transfusion will not make a big difference in oxygen reserve, particularly if a blood transfusion is administered within 12-24-hours before surgery.

      Heliox (79% helium and 21% oxygen) despite its lower viscosity is unlikely to be more effective than 100% oxygen .

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 28 - Which one is true with respect to the first rib? ...

    Incorrect

    • Which one is true with respect to the first rib?

      Your Answer:

      Correct Answer: Scalenus anterior is inserted onto the scalene tubercle

      Explanation:

      Specific knowledge of the anatomical relationship is required to address this examination question.

      The first rib is small and thick and contains a single facet that articulates at the costovertebral joint. It consist of a head, neck and shaft but a discrete angle is deficit. Along the side the shaft is indented with a groove for the subclavian artery and the lower brachial plexus trunk. Front to the scalene tubercle is a space for the subclavian vein.

      The first rib has the scalenus front muscle joined to the scalene tubercle, isolating the subclavian vein (anteriorly) from the subclavian artery (posteriorly). This anatomical relationship is of major significance with respect to subclavian vein cannulation.

      The 1st rib has the following relationships:

      superior: lower trunk of the brachial plexus, subclavian vessels, clavicle.

      inferior: intercostal vessels and nerves

      posterior and inferior: pleura

      anterior: sympathetic trunk (over neck)

      superior intercostal artery, ventral T1 nerve root

    • This question is part of the following fields:

      • Anatomy
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  • Question 29 - A study aimed at assessing a novel proton pump inhibitor (PPI) in aged...

    Incorrect

    • A study aimed at assessing a novel proton pump inhibitor (PPI) in aged patients taking aspirin. The new PPI is prescribed to 120 patients and the already prevalent PPI is given to the 240 members of the control group. In the next 5 years, the instances of upper GI bleed reported in the experimental and control group were 24 and 60 respectively.

      What is the value of absolute risk reduction?

      Your Answer:

      Correct Answer: 5%

      Explanation:

      ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)

      So,

      ARR= (24/120)-(60/240)

      ARR= 0.2-0.25

      ARR= 0.05 (Numerical Value)

      ARR= 5%

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 30 - The following foetal anatomical features functionally closes earliest at birth? ...

    Incorrect

    • The following foetal anatomical features functionally closes earliest at birth?

      Your Answer:

      Correct Answer: Foramen ovale

      Explanation:

      Foramen ovale, ductus arteriosus (DA) and ductus venosus (DV) are the three important cardiac shunts in-utero.

      At birth the umbilical vessels constrict in response to stretch as they are clamped. Blood flow through the ductus venosus (DV) decreases but the DV closes passively in 3-10 days.

      As the pulmonary circulation is established, there is a drastic fall in pulmonary vascular resistance and an increased pulmonary blood flow. This increases flow and pressure in the Left Atrium that exceeds that of the right atrium. The difference in pressure usually leads to the IMMEDIATE closure of the foramen ovale.

      The DA is functionally closed within the first 36-hours of birth in a healthy full-term newborn. Subsequent endothelial and fibroblast proliferation leads to permanent anatomical closure within 2 – 3 weeks.

      Oxygenated blood from the placenta passes via the umbilical vein to the liver. Blood also bypasses the liver via the ductus venosus into the inferior vena cava (IVC). The Crista dividens is a tissue flap situated at the junction of the IVC and the right atrium (RA). This flap directs the oxygen-rich blood, along the posterior aspect of the IVC, through the foramen ovale into the left atrium (LA).

      The Eustachian valve also known as the valve of The IVC is a remnant of the crista dividens.

    • This question is part of the following fields:

      • Anatomy
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Pathophysiology (0/1) 0%
Physiology And Biochemistry (1/1) 100%
Statistical Methods (0/2) 0%
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