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  • Question 1 - A 27-year-old woman arrives at the emergency room after intentionally ingesting 2 g...

    Correct

    • A 27-year-old woman arrives at the emergency room after intentionally ingesting 2 g of amitriptyline.

      A Glasgow coma score of 6 was discovered, as well as a pulse rate of 140 beats per minute and a blood pressure of 80/50 mmHg.

      Which of the following ECG changes is most likely to indicate the onset of life-threatening arrhythmias?

      Your Answer: Prolongation of the QRS complex

      Explanation:

      Arrhythmias and/or hypotension are the most common causes of death from tricyclic antidepressant (TCA) overdose.

      The quinidine-like actions of tricyclic antidepressants on cardiac tissues are primarily responsible for their toxicity. Conduction through the His-Purkinje system and the myocardium slows as phase 0 depolarisation of the action potential slows. QRS prolongation and atrioventricular block are caused by slowed impulse conduction, which also contributes to ventricular arrhythmias and hypotension.

      Arrhythmias can also be caused by abnormal repolarization, impaired automaticity, cholinergic blockade, and inhibition of neuronal catecholamine uptake, among other things.

      Acidaemia, hypotension, and hyperthermia can all exacerbate toxicity.

      The anticholinergic effects of tricyclic antidepressants, as well as the blockade of neuronal catecholamine reuptake, cause sinus tachycardia. Sinus tachycardia is usually well tolerated and does not require treatment. It can be difficult to tell the difference between sinus tachycardia and ventricular tachycardia with QRS prolongation.

      A QRS duration of more than 100 milliseconds indicates a higher risk of arrhythmia and should be treated with systemic sodium bicarbonate.

      The tricyclic is dissociated from myocardial sodium channels by serum alkalinization, and the extracellular sodium load improves sodium channel function.

    • This question is part of the following fields:

      • Clinical Measurement
      32.9
      Seconds
  • Question 2 - The most sensitive indicator of mild obstructive airway disease is? ...

    Incorrect

    • The most sensitive indicator of mild obstructive airway disease is?

      Your Answer: Peak expiratory flow (PEF)

      Correct Answer: Forced expiratory flow (FEF25-75%)

      Explanation:

      The volume expired in the first second of maximal expiration after a maximal inspiration is known as forced expiratory volume in one second (FEV1), and it indicates how quickly full lungs can be emptied. It is the most commonly measured parameter for bronchoconstriction assessment.

      The maximum volume of air exhaled after a maximal inspiration is known as the ‘slow’ vital capacity (VC). VC is normally equal to FVC after a forced vital capacity (FVC) or slow vital capacity (VC) manoeuvre, unless there is an airflow obstruction, in which case VC is usually higher than FVC.

      The FEV1/FVC (Tiffeneau index) is a clinically useful index of airflow restriction that can be used to distinguish between restrictive and obstructive respiratory disorders.

      The average expired flow over the middle half (25-75 percent) of the FVC manoeuvre is the forced expiratory volume (FEF25-75). The airflow from the resistance bronchioles corresponds to this. It’s a more sensitive indicator of mild small airway narrowing than FEV1, but it’s difficult to tell if the VC (or FVC) is decreasing or increasing.

      The maximum expiratory flow rate achieved is called the peak expiratory flow (PEF), which is usually 8-14 L/second.

    • This question is part of the following fields:

      • Pathophysiology
      79.4
      Seconds
  • Question 3 - A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise....

    Correct

    • A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise. On urine culture and sensitivity testing, E.coli was detected with resistance to ampicillin.
      What is the mechanism of resistance to ampicillin?

      Your Answer: Beta-lactamase production

      Explanation:

      Ampicillin belongs to the family of penicillin. Resistance to this group of drugs is due to ?-lactamase production which opens the ?-lactam ring and inactivates Penicillin G and some closely related congeners. The majority of Staphylococci and some strains of gonococci, B. subtilis, E. coli, and a few other bacteria produce penicillinase.

      Resistance to cephalosporins is due to changes in penicillin-binding proteins.

      Resistance to macrolides are due to post-transcriptional methylation of 23s bacterial ribosomal RNA

      Resistance to fluoroquinolones is due to mutations in DNA gyrase.

    • This question is part of the following fields:

      • Pharmacology
      12.4
      Seconds
  • Question 4 - Which of the following is the best associated option with Kaplan-Meier survival plot?...

    Incorrect

    • Which of the following is the best associated option with Kaplan-Meier survival plot?

      Your Answer: An accurate prediction of decreasing survival with time after an event.

      Correct Answer: An estimate of decreasing survival with time after an event.

      Explanation:

      Also known as the “product limit estimate’’, the Kaplan-Meier survival plot is used to estimate the true survival function from the collected data.

      Using this plot, probabilities of occurrence of an event at a certain point in time can be computed. The successive probabilities are multiplied by any earlier computed probabilities to get the final estimate. For a given population, the survival probability at any particular time on the plot = (number of subjects living at the start – number of subjects who died)/number of subjects living at the start.

      The description of a scatter plot is a graphical representation using Cartesian coordinates to display values for more than two variables for data set. It is used for to assess the relationship between 2 different variables.

    • This question is part of the following fields:

      • Statistical Methods
      15.1
      Seconds
  • Question 5 - Which of the following statements is NOT true regarding soda lime? ...

    Incorrect

    • Which of the following statements is NOT true regarding soda lime?

      Your Answer: When dry can lead to the formation of carbon monoxide when used with sevoflurane

      Correct Answer: It mostly contains sodium hydroxide

      Explanation:

      Soda-lime contains mostly calcium hydroxide (about 94%) and remaining sodium hydroxide.

      CO2 + Ca(OH)2 → CaCO3 + H2O + heat
      Here in this exothermic reaction, we can see that the production of calcium carbonate does not require heat.

      When soda lime is allowed to dry with subsequent use of desflurane, isoflurane, and enflurane, it can lead to the generation of carbon monoxide.

      Silica hardens the granules and can thus prevent disintegration.

      The size of soda-lime granules is 4-8 mesh because it allows sufficient surface area for chemical reaction to occur without critically increasing the resistance to airflow.

    • This question is part of the following fields:

      • Pharmacology
      115.2
      Seconds
  • Question 6 - Among the following options which one compares variance within the group and variance...

    Incorrect

    • Among the following options which one compares variance within the group and variance between groups?

      Your Answer: Chi squared test

      Correct Answer: ANOVA

      Explanation:

      ANOVA is based upon within group variance (i.e. the variance of the mean of a sample) and between group variance (i.e. the variance between means of different samples). The test works by finding out the ratio of the two variances mentioned above. (Commonly known as F statistic).

    • This question is part of the following fields:

      • Statistical Methods
      12.9
      Seconds
  • Question 7 - A laceration to the upper lateral margin of the popliteal fossa will pose...

    Correct

    • A laceration to the upper lateral margin of the popliteal fossa will pose the greatest risk of injury for which nerve?

      Your Answer: Common peroneal nerve

      Explanation:

      The common peroneal (fibular) nerve descends obliquely along the lateral side of the popliteal fossa to the fibular head, medial to biceps femoris.

      The sural nerve exits at the fossa’s lower inferolateral aspect and is more at risk in short saphenous vein surgery.

      The tibial nerve lies more medially and is even less likely to be injured in this location.

      The boundaries of the popliteal fossa are:
      Superolateral – the biceps femoris tendon
      Superomedial – semimembranosus reinforced by semitendinosus
      Inferomedial and inferolateral – medial and lateral heads of gastrocnemius

      The contents of the Popliteal fossa are:

      1. The popliteal artery
      2. The popliteal vein
      3. The Tibial nerve and common Fibular nerve
      4. Posterior femoral cutaneous nerve: descends and pierces the roof
      5. Small saphenous vein
      6. popliteal lymph nodes
      7. fat

    • This question is part of the following fields:

      • Anatomy
      7.8
      Seconds
  • Question 8 - A 42 year old lady has acute onset of painless weakness on her...

    Correct

    • A 42 year old lady has acute onset of painless weakness on her left side of the face with a drooping mouth and difficulty speaking. With no significant past medical history and after relevant investigations, you rule out stroke as a possible cause. The lady is suspected to have suffered Bell's palsy, an idiopathic paralysis of the facial nerve.

      What symptoms are you most likely to find on examination in a patient with Bell's palsy?

      Your Answer: Taste impairment of the anterior tongue

      Explanation:

      Bell’s palsy is facial muscle weakness or paralysis that arises from idiopathic damage to the facial nerve. It can occur at any age but is commonly associated with some conditions:
      1. pregnancy
      2. diabetes
      3. upper respiratory ailment
      4. GBS
      5. Toxins

      The common symptoms of Bell’s palsy are:
      1. Abnormal corneal reflex as the facial nerve controls the motor aspect of the corneal reflex.
      2. The loss of control of facial muscles and eyelids leads to decreased tear production.
      3. mild weakness to total paralysis on one side of the face, occurring within hours to days.
      4. Bell’s palsy is a lower motor neuron lesion that usually spares the forehead while the upper motor near lesions, like stroke, involves the entire face.
      5. The anterior two-thirds of the tongue is supplied by the chorda tympani branch of the facial nerve, thus resulting in loss of taste.
      6. Ptosis can be a feature of Bell’s palsy but Bell’s palsy would typically show unilateral symptoms rather than bilateral.

    • This question is part of the following fields:

      • Anatomy
      20.6
      Seconds
  • Question 9 - Which of these statements is false relating to the posterior cerebral artery? ...

    Incorrect

    • Which of these statements is false relating to the posterior cerebral artery?

      Your Answer: It is closely related to the 3rd cranial nerve

      Correct Answer: It is connected to the circle of Willis via the superior cerebellar artery

      Explanation:

      The posterior cerebral arteries are the terminal branches of the basilar artery and are connected to the circle of Willis via the posterior communicating artery. The posterior cerebral artery supplies the visual areas of the cerebral cortex and other structures in the visual pathway.

      The posterior cerebral artery is separated from the superior cerebellar artery near its origin by the oculomotor nerve (3rd cranial nerve) and, lateral to the midbrain, by the trochlear nerve.

      PCA strokes will primarily cause a visual field loss or homonymous hemianopia to the opposite side. This large occipital or PCA stroke causes people to be “blind” on one side of the visual field. This is the most common symptom of a large occipital lesion or PCA stroke.

    • This question is part of the following fields:

      • Anatomy
      7.7
      Seconds
  • Question 10 - Among the following, which statement is true regarding electrical safety in an operation...

    Incorrect

    • Among the following, which statement is true regarding electrical safety in an operation theatre?

      Your Answer: Class III equipment are double-insulated

      Correct Answer: The higher the frequency of the current the less risk to the patient

      Explanation:

      The operating theatre is an unusual place with several applications of electrical equipment to the human body. This can lead to potential dangers associated with it that need to be prevented. Electrical safety in the operation theatre is the understanding of how these potential dangers can occur and how they can be prevented.

      Electricity can cause morbidity or mortality by one of the following ways:
      (i) electrocution
      (ii) burns
      (iii) ignition of a flammable material, causing a fire or explosion.

      Electrocution is dependant on factors like duration of contact with electric current, the current pathway and the frequency and size of current.

      Option A: The higher the frequency, the less effects of electrocution on the body.

      Option B & D: Equipment can be classified in classes and types.
      The class designation describes the method used for protection against electrocution. Class I is basic protection, class II is double insulation and class III is safety extra low voltage.
      The type designation describes the degree of protection based on the maximum permissible leakage currents under normal and fault conditions.
      Type B:
      can be class I, II or III but the maximum leakage current must not exceed 100 µA. It is therefore not suitable for direct connection to the heart.
      Type BF
      Similar to type B, but uses an isolated (or floating) circuit.
      Type CF
      Only type CF protect against microshock as they allow leakage currents of 0.05 mA per electrode for class I and 0.01 mA for class II. Microshock is a small leakage current that can cause harm because of direct connection to the heart via transvenous lines or wires, bypassing the impedance of the skin, leading to ventricular fibrillation. Microshock current of 100 ?A is sufficient to cause VF.

      Option C: A 75mA electrocution can cause ventricular fibrillation. Use the following as a general guide to understand the effect of current size on the body.
      1 mA – tingling pain
      5 mA – pain
      15 mA – tonic muscular contraction
      50 mA – respiratory muscle paralysis
      75 mA – ventricular fibrillation.

      Option E: Wet skin reduces the resistance to current flow and therefore increases the effects of electrocution.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      21.1
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Clinical Measurement (1/1) 100%
Pathophysiology (0/1) 0%
Pharmacology (1/2) 50%
Statistical Methods (0/2) 0%
Anatomy (2/3) 67%
Anaesthesia Related Apparatus (0/1) 0%
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