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  • Question 1 - The renal glomerulus is able to filter 180 litres of blood per day,...

    Correct

    • The renal glomerulus is able to filter 180 litres of blood per day, as determined by the starling forces present in the glomerulus. Ninety-nine percent of which is reabsorbed thereafter.

      Water is reabsorbed in the highest proportion in which segment of the nephron?

      Your Answer: Proximal convoluted tubule

      Explanation:

      Sixty-seven percent of filtered water is reabsorbed in the proximal tubule. The driving force for water reabsorption is a transtubular osmotic gradient established by reabsorption of solutes (e.g., NaCl, Na+-glucose).

      Henle’s loop reabsorbs approximately 25% of filtered NaCl and 15% of filtered water. The thin ascending limb reabsorbs NaCl by a passive mechanism, and is impermeable to water. Reabsorption of water, but not NaCl, in the descending thin limb increases the concentration of NaCl in the tubule fluid entering the ascending thin limb. As the NaCl-rich fluid moves toward the cortex, NaCl diffuses out of the tubule lumen across the ascending thin limb and into the medullary interstitial fluid, down a concentration gradient as directed from the tubule fluid to the interstitium. This mechanism is known as the counter current multiplier.

      The distal tubule and collecting duct reabsorb approximately 8% of filtered NaCl, secrete variable amounts of K+ and H+, and reabsorb a variable amount of water (approximately 8%-17%).

    • This question is part of the following fields:

      • Physiology
      69.8
      Seconds
  • Question 2 - Drug A has a 1 L/kg volume of distribution and a 0.1 elimination...

    Correct

    • Drug A has a 1 L/kg volume of distribution and a 0.1 elimination rate constant (k).

      Drug B has a 2 L/kg volume of distribution and a 0.2 elimination rate constant (k).

      Which of the following statements best describes the pharmacokinetics of drug A in a single compartment?

      Your Answer: Drug A has a lower clearance than drug B

      Explanation:

      The fall in plasma concentration of a drug with time decreases exponentially in a single compartment pharmacokinetic model (wash-out curve).

      A straight line is produced when the logarithm (ln) of a drug’s plasma concentration is plotted against time because a constant proportion of the drug is removed from the plasma per unit time. The line’s gradient or slope can be expressed mathematically as k. (the rate constant). The gradient is related to the half life (T1/2) because it can be used to predict a drug’s plasma concentration at any time.

      According to the following formula, clearance (CL), volume of distribution (Vd), and elimination rate constant (k) are mathematically related.

      CL = Vd x k

      For drug A, CL = 1 x 0.1 = 0.1units per minute

      For drug B, Cl = 2 x 0.2 = 0.4 units per minute

      Hence, it is proved that Drug A has a lower clearance than drug B.

    • This question is part of the following fields:

      • Pharmacology
      89.5
      Seconds
  • Question 3 - A 70-year-old man presents with bilateral buttock claudication that spreads down the thigh...

    Correct

    • A 70-year-old man presents with bilateral buttock claudication that spreads down the thigh and erectile dysfunction in a vascular clinic.

      The left femoral pulse is not palpable on examination, and the right is weakly palpable. Leriche syndrome is diagnosed as the blood flow at the abdominal aortic bifurcation is blocked due to atherosclerosis. He is prepared for aortoiliac bypass surgery.

      Which vertebral level will you find the affected artery that requires bypassing?

      Your Answer: L4

      Explanation:

      The bifurcation of the abdominal aorta into common iliac arteries occurs at the level of L4. The bifurcation is a common site for atherosclerotic plaques as it is an area of high turbulence.

      Leriche Syndrome is an aortoiliac occlusive disease and affects the distal abdominal aorta, iliac arteries, and femoropopliteal vessels. It has a triad of symptoms:
      1. Claudication (cramping lower extremities pain that is reproducible by exercise)
      2. Impotence (reduced penile arterial flow)
      3. Absent/weak femoral pulses (hallmark)

      T12 – aorta enters the diaphragm with the thoracic duct and azygous veins

      L2 – testicular or ovarian arteries branch off the aorta

      L3 – inferior mesenteric artery

    • This question is part of the following fields:

      • Anatomy
      168.1
      Seconds
  • Question 4 - Which of the following explains the mode of action of Magnesium sulphate in...

    Incorrect

    • Which of the following explains the mode of action of Magnesium sulphate in preventing eclampsia in susceptible patients?

      Your Answer: Increasing the convulsive threshold by NMDA receptor antagonism

      Correct Answer: Dilatation of cerebral circulation due to calcium channel antagonism reducing cerebral vascular spasm

      Explanation:

      Magnesium is a unique calcium antagonist as it can act on most types of calcium channels in vascular smooth muscle and as such would be expected to decrease intracellular calcium. One major effect of decreased intracellular calcium would be inactivation of calmodulin-dependent myosin light chain kinase activity and decreased contraction, causing arterial relaxation that may subsequently lower peripheral and cerebral vascular resistance, relieve vasospasm, and decrease arterial blood pressure.

      The vasodilatory effect of MgSO4 has been investigated in a wide variety of vessels. For example, both in vivo and in vitro animal studies have shown that it is a vasodilator of large conduit arteries such as the aorta, as well as smaller resistance vessels including mesenteric, skeletal muscle, uterine, and cerebral arteries.

      The theory of cerebrovascular vasospasm as the aetiology of eclampsia seemed to be reinforced by transcranial Doppler (TCD) studies which suggested that MgSO4 treatment caused dilation in the cerebral circulation as well as in animal studies that used large cerebral arteries.

    • This question is part of the following fields:

      • Pathophysiology
      159.3
      Seconds
  • Question 5 - Which of the following anaesthetic is the least powerful trigger of malignant hyperthermia?...

    Correct

    • Which of the following anaesthetic is the least powerful trigger of malignant hyperthermia?

      Your Answer: Desflurane

      Explanation:

      Desflurane is a highly fluorinated methyl ethyl ether used for the maintenance of general anaesthesia. It has been identified as a weak triggering anaesthetic of malignant hyperthermia. That, in the absence of succinylcholine, may produce a delayed onset of symptoms.

    • This question is part of the following fields:

      • Pharmacology
      23.2
      Seconds
  • Question 6 - The following are the pharmacodynamic properties of a neuromuscular blocking agent:

    Effective dose 95...

    Correct

    • The following are the pharmacodynamic properties of a neuromuscular blocking agent:

      Effective dose 95 (ED95) - 0.3 mg/kg
      Time to 95% depression of first twitch of train of four (ToF) - 75 seconds
      Time to 25% recovery of first twitch of train of four (ToF) - 33 minutes.

      Which of the following statements about this neuromuscular blocking agent is the most accurate?

      Your Answer: Can be reversed by a modified gamma-cyclodextrin

      Explanation:

      The aminosteroid rocuronium is the neuromuscular blocking agent in question.

      0.3 mg/kg is the effective dose 95 (ED95) (the dose required to depress the twitch height by 95 percent )
      The dose for intubation is 0.6 mg/kg.
      75 seconds is the time it takes to reach 95 percent depression of the first twitch of the train of four (ToF) or the onset time.
      The clinical duration or time to 25% recovery of the first twitch of the train of four (ToF) is 33 minutes.

      A modified cyclodextrin can quickly reverse both rocuronium and vecuronium (sugammadex).

      It is more fat-soluble than vecuronium, with the liver absorbing the majority of the drug and excreting it in the bile. The only metabolite found in the blood (17-desacetylrocuronium) is 20 times less potent than the parent drug and is unlikely to cause neuromuscular block.

      Despite its quick onset of action (60-90 seconds), suxamethonium arguably is still the neuromuscular blocker of choice for a quick sequence induction. Rocuronium is becoming increasingly popular for this purpose.

    • This question is part of the following fields:

      • Pharmacology
      323.7
      Seconds
  • Question 7 - Among the following options which one compares variance within the group and variance...

    Correct

    • Among the following options which one compares variance within the group and variance between groups?

      Your Answer: ANOVA

      Explanation:

      ANOVA is based upon within group variance (i.e. the variance of the mean of a sample) and between group variance (i.e. the variance between means of different samples). The test works by finding out the ratio of the two variances mentioned above. (Commonly known as F statistic).

    • This question is part of the following fields:

      • Statistical Methods
      210.4
      Seconds
  • Question 8 - A patient was brought to the emergency room after passing black tarry stools....

    Correct

    • A patient was brought to the emergency room after passing black tarry stools. The initial diagnosis was upper gastrointestinal bleeding. The patient was placed on temporary nil per os (NPO) for the next 24 hours, his weight was 110 kg, and the required volume of intravenous fluid for the him was 3 litres. His electrolytes and other biochemistry studies were normal.

      If you were to choose the intravenous fluid regimen that would closely mimic his basic electrolyte and caloric requirements, which one would be the best answer?

      Your Answer: 3000 mL 0.45% N. saline with 5% dextrose, each bag with 40 mmol of potassium

      Explanation:

      The patient in the case has a fluid volume requirement of 30 mL/kg/day. His basic electrolyte requirement per day is:

      Sodium at 2 mmol/kg/day x 110 = 220 mmol/day
      Potassium at 1 mmol/kg/day x 110 = 110 mmol/day

      His energy requirement per day is:

      35 kcal/kg/day x 110 kg = 3850 kcal/day

      One gram of glucose in fluid can provide approximately 4 kilocalories.

      The following are the electrolyte components of the different intravenous fluids:

      Fluid Na (mmol/L) K (mmol/L)
      0.9% Normal saline (NSS) 154 0
      0.45% NSS + 5% dextrose 77 0
      0.18% NSS + 4% dextrose 30 0
      Hartmann’s 131 5
      5% dextrose 0 0

      1000 mL of 5% dextrose has 50 g of glucose

      Option B is inadequate for his sodium and caloric requirements (30 mmol of Na+ and 560 kcal). It is adequate for his K+ requirement (120 mmol of K+).

      Option C is in excess of his Na+ requirement (462 mmol of Na+). Moreover, it does not provide any K+ replacement.

      Option D is inadequate for his caloric requirement (600 kcal) and K+ requirement (60 mmol of K+). Moreover it does not provide any Na+ replacement.

      Option E is in excess of his Na+ requirement (393 mmol of Na+), and is inadequate for his potassium requirement (15 mmol of K+)

      Option A has adequate amounts for his Na+ (231 mmol of Na+) and K+ (120 mmol of K+) requirements. It is inadequate for his caloric requirement (600 kcal).

    • This question is part of the following fields:

      • Physiology
      221.6
      Seconds
  • Question 9 - Which of the following molecules is closely related to the structure of Oxytocin?...

    Correct

    • Which of the following molecules is closely related to the structure of Oxytocin?

      Your Answer: ADH

      Explanation:

      Oxytocin is structurally similar to Antidiuretic Hormone (ADH) and thus oxytocin can cause water intoxication (due to an ADH like action)

      Oxytocin is secreted by the posterior pituitary along with ADH. It increases uterine contractions – the contraction of the upper segment (fundus and body) of the uterus whereas the lower segment is relaxed facilitating the expulsion of the foetus

      Antidiuretic hormone (ADH) also called vasopressin is released from the posterior pituitary in response to hypertonicity and increases fluid reabsorption from the kidney.

    • This question is part of the following fields:

      • Pharmacology
      4.7
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  • Question 10 - Of the following, which is NOT a branch of the subclavian artery? ...

    Correct

    • Of the following, which is NOT a branch of the subclavian artery?

      Your Answer: Superior thyroid artery

      Explanation:

      The left subclavian artery originates from the aortic arch, while the right subclavian artery originates from the brachiocephalic artery.

      The subclavian artery gives off branches on both sides of the body:
      1. Vertebral artery
      2. Internal thoracic artery
      3. Thyrocervical trunk
      4. Costocervical trunk
      5. Dorsal scapular artery

      The superior thyroid artery is the first branch of the external carotid artery. The other branches of the external carotid artery are:
      1. Superior thyroid artery
      2. Ascending pharyngeal artery
      3. Lingual artery
      4. Facial artery
      5. Occipital artery
      6. Posterior auricular artery
      7. Maxillary artery
      8. Superficial temporal artery

    • This question is part of the following fields:

      • Anatomy
      61.6
      Seconds
  • Question 11 - Which of the following statements is correct regarding opioid receptors? ...

    Incorrect

    • Which of the following statements is correct regarding opioid receptors?

      Your Answer:

      Correct Answer: Binding with an opioid agonist increases potassium conductance

      Explanation:

      Opioid receptors are a large family of seven transmembrane domain receptors. They are of four types:

      1) Delta opioid receptor

      2) Mu opioid receptor

      3) Kappa opioid receptor

      4) Orphan receptor-like 1

      They contain about 372-400 amino acids and thus their molecular weight is different.

      Opioid receptor activation reduces the intracellular cAMP formation and opens K+ channels (mainly through µ and δ receptors) or suppresses voltage-gated N-type Ca2+ channels (mainly κ receptor). These actions result in neuronal hyperpolarization and reduced availability of intracellular Ca2+ which results in decreased neurotransmitter release by cerebral, spinal, and myenteric neurons (e.g. glutamate from primary nociceptive afferents).

      However, other mechanisms and second messengers may also be involved, particularly in the long-term

    • This question is part of the following fields:

      • Pharmacology
      0
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  • Question 12 - A 49-year-old female has presented to her physician with complaints of a lump...

    Incorrect

    • A 49-year-old female has presented to her physician with complaints of a lump in her groin area. The lump is painless and is more prominent in coughing.
      On examination, the lump's location is inferior and lateral to the pubic tubercle. This points towards the diagnosis of femoral hernia, where part of her intestines has entered the femoral canal, causing a bulge in the femoral triangle. The femoral triangle is an anatomical region in the upper thigh.

      Name the structures found in the femoral triangle, laterally to medially.

      Your Answer:

      Correct Answer: Femoral nerve, femoral artery, femoral vein, empty space, lymphatics

      Explanation:

      The femoral triangle is a wedge-shaped area found within the superomedial aspect of the anterior thigh. It is a passageway for structures to leave and enter the anterior thigh.

      Superior: Inguinal ligament
      Medial: Adductor longus
      Lateral: Sartorius
      Floor: Iliopsoas, adductor longus and pectineus

      The contents include: (medial to lateral)
      Femoral vein
      Femoral artery-pulse palpated at the mid inguinal point
      Femoral nerve
      Deep and superficial inguinal lymph nodes
      Lateral cutaneous nerve
      Great saphenous vein
      Femoral branch of the genitofemoral nerve

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 13 - A peripheral nerve stimulator is used to stimulate the ulnar nerve at the...

    Incorrect

    • A peripheral nerve stimulator is used to stimulate the ulnar nerve at the wrist to indicate the degree of neuromuscular blockade.

      Which single muscle or group of muscles of the hand supplied by the ulnar nerve is best for monitoring the twitch function during neuromuscular blockade?

      Your Answer:

      Correct Answer: Adductor pollicis

      Explanation:

      In anaesthesia, adductor pollicis neuromuscular monitoring with ulnar nerve stimulation is commonly used. It is the gold standard for measuring the degree of block and comparing neuromuscular blocking drugs and their effects on other muscles.

      Electrodes are usually placed over the ulnar nerve at the wrist to monitor the adductor pollicis.

      Neuromuscular blocking drugs have different sensitivity levels in different muscle groups.

      To achieve the same level of blockade, the diaphragm requires 1.4 to 2 times the amount of neuromuscular blocking agent as the adductor pollicis muscle. The small muscles of the larynx and the ocular muscles are two other respiratory muscles that are less resistant than the diaphragm (especially corrugator supercilii).

      The abdominal muscles, Orbicularis oculi, peripheral muscles of the limbs, Geniohyoid, Masseter, and Upper airway muscles are the most sensitive to neuromuscular blocking agents.

      The C8-T1 nerve roots, which are part of the medial cord of the brachial plexus, form the ulnar nerve. It enters the hand via the ulnar canal, superficial to the flexor retinaculum, after following the ulnar artery at the wrist.

      The nerve then splits into two branches: superficial and deep. The palmaris brevis is supplied by the superficial branch, which also provides palmar digital nerves to one and a half fingers. The dorsal surface of the medial/ulnar 1.5 fingers, as well as the corresponding skin over the hand, are also supplied by it (as well as the palmar surface).

      The ulnar nerve’s deep branch runs between the abductor and flexor digiti minimi, which it supplies. It also innervates the opponens, and with the deep palmar arch, it curves around the hook of the hamate and laterally across the palm. All of the interossei, the medial two lumbricals, the adductor pollicis, and, in most cases, the flexor pollicis brevis are supplied there.

    • This question is part of the following fields:

      • Anatomy
      0
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  • Question 14 - Many of the processes we deal with in anaesthesia are exponential.

    What is the...

    Incorrect

    • Many of the processes we deal with in anaesthesia are exponential.

      What is the underlying mathematical principle of an exponential process?

      Your Answer:

      Correct Answer: The rate of change of x is dependent on the magnitude of x

      Explanation:

      The magnitude of x determines the rate of change of x. First-order drug kinetics is a good example. Most drugs’ plasma levels are controlled by an exponential process. The rate of change in drug metabolism is proportional to the current plasma concentration (so-called non-linear kinetics).

      A tear-away function is just one type of exponential relationship (y = ex), in which e is Euler’s number, x is the power, and e is the base. Natural logarithms rely on Euler’s number.

      Euler’s number is a mathematical constant, not a mathematical principle. It’s referred to as an irrational number. This is a number that cannot be expressed as a simple fraction or a ratio.

      A line or curve that acts as the limit of another line or curve is known as an asymptote. A washout exponential curve, for example, where the value y represents the plasma concentration of a drug in a single compartment model against time on the x axis. This descending curve approaches but never touches the x axis. This curve is asymptotic to the x axis, which is the curve’s asymptote. An asymptote isn’t just a characteristic of exponential curves.

    • This question is part of the following fields:

      • Basic Physics
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  • Question 15 - Which of the following is the maximum volume of 0.5% bupivacaine that should...

    Incorrect

    • Which of the following is the maximum volume of 0.5% bupivacaine that should be administered to a 10kg child?

      Your Answer:

      Correct Answer: 5 ml

      Explanation:

      Bupivacaine is used to decrease sensation in a specific area. It is injected around a nerve that supplies the area, or into the spinal canal’s epidural space.

      The maximum volume of 0.5% bupivacaine that should be administered to a 10kg child is 5 ml

    • This question is part of the following fields:

      • Pharmacology
      0
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  • Question 16 - Of the following, which of these oxygen carrying molecules causes the greatest shift...

    Incorrect

    • Of the following, which of these oxygen carrying molecules causes the greatest shift of the oxygen-dissociation curve to the left?

      Your Answer:

      Correct Answer: Myoglobin (Mb)

      Explanation:

      Myoglobin is a haemoglobin-like, iron-containing pigment that is found in muscle fibres. It has a high affinity for oxygen and it consists of a single alpha polypeptide chain. It binds only one oxygen molecule, unlike haemoglobin, which binds 4 oxygen molecules.

      The myoglobin ODC is a rectangular hyperbola. There is a very low P50 0.37 kPa (2.75 mmHg). This means that it needs a lower P50 to facilitate oxygen offloading from haemoglobin. It is low enough to be able to offload oxygen onto myoglobin where it is stored. Myoglobin releases its oxygen at the very low PO2 values found inside the mitochondria.

      P50 is defined as the affinity of haemoglobin for oxygen: It is the PO2 at which the haemoglobin becomes 50% saturated with oxygen. Normally, the P50 of adult haemoglobin is 3.47 kPa(26 mmHg).

      Foetal haemoglobin has 2 ? and 2 ?chains. The ODC is left shifted – this means that P50 lies between 2.34-2.67 kPa [18-20 mmHg]) compared with the adult curve and it has a higher affinity for oxygen. Foetal haemoglobin has no ? chains so this means that there is less binding of 2.3 diphosphoglycerate (2,3 DPG).

      Carbon monoxide binds to haemoglobin with an affinity more than 200-fold higher than that of oxygen. This therefore decreases the amount of haemoglobin that is available for oxygen transport. Carbon monoxide binding also increases the affinity of haemoglobin for oxygen, which shifts the oxygen-haemoglobin dissociation curve to the left and thus impedes oxygen unloading in the tissues.

      In sickle cell disease, (HbSS) has a P50 of 4.53 kPa(34 mmHg).

    • This question is part of the following fields:

      • Physiology
      0
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  • Question 17 - Regarding the Valsalva manoeuvre, which of the following describes the cardiovascular changes in...

    Incorrect

    • Regarding the Valsalva manoeuvre, which of the following describes the cardiovascular changes in phase III in a normal patient?

      Your Answer:

      Correct Answer: Normal intrathoracic pressure, decrease in blood pressure, and increase in heart rate

      Explanation:

      When a person forcefully expires against a closed glottis, changes occur in intrathoracic pressure that dramatically affect venous return, cardiac output, arterial pressure, and heart rate. This forced expiratory effort is called a Valsalva maneuver.

      Initially during a Valsalva, intrathoracic (intrapleural) pressure becomes very positive due to compression of the thoracic organs by the contracting rib cage. This increased external pressure on the heart and thoracic blood vessels compresses the vessels and cardiac chambers by decreasing the transmural pressure across their walls. Venous compression, and the accompanying large increase in right atrial pressure, impedes venous return into the thorax. This reduced venous return, and along with compression of the cardiac chambers, reduces cardiac filling and preload despite a large increase in intrachamber pressures. Reduced filling and preload leads to a fall in cardiac output by the Frank-Starling mechanism. At the same time, compression of the thoracic aorta transiently increases aortic pressure (phase I); however, aortic pressure begins to fall (phase II) after a few seconds because cardiac output falls. Changes in heart rate are reciprocal to the changes in aortic pressure due to the operation of the baroreceptor reflex. During phase I, heart rate decreases because aortic pressure is elevated; during phase II, heart rate increases as the aortic pressure falls.

      When the person starts to breathe normally again, the intrathoracic pressure declines to normal levels, the aortic pressure briefly decreases as the external compression on the aorta is removed, and heart rate briefly increases reflexively (phase III). This is followed by an increase in aortic pressure (and reflex decrease in heart rate) as the cardiac output suddenly increases in response to a rapid increase in cardiac filling (phase IV). Aortic pressure also rises above normal because of a baroreceptor, sympathetic-mediated increase in systemic vascular resistance that occurred during the Valsava.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 18 - Prophylactic antibiotics are required for which of the following procedures? ...

    Incorrect

    • Prophylactic antibiotics are required for which of the following procedures?

      Your Answer:

      Correct Answer: Caesarean section

      Explanation:

      Staphylococcus aureus infection is the most likely cause.

      Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.

      SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
      The organisms are usually derived from the patient’s own body.

      Measures that may increase the risk of SSI include:
      -Shaving the wound using a single use electrical razor with a disposable head
      -Using a non iodine impregnated surgical drape if one is needed
      -Tissue hypoxia
      -Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.

      Measures that may decrease the risk of SSI include:
      1. Intraoperatively
      – Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
      -Cover surgical site with dressing

      In contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.

      2. Post operatively
      Tissue viability advice for management of surgical wounds healing by secondary intention

      Use of diathermy for skin incisions
      In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used.

    • This question is part of the following fields:

      • Physiology And Biochemistry
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  • Question 19 - The following results were obtained In a new drug trial:

    Improved Not improved
    Placebo...

    Incorrect

    • The following results were obtained In a new drug trial:

      Improved Not improved
      Placebo group 36 26
      Treatment group 44 16

      Regarding the statistical analysis or interpretation of the trial, One of these is true

      Your Answer:

      Correct Answer: The data could be evaluated using the chi square test

      Explanation:

      This data is in a 2 × 2 contingency table so a chi square test can be used. There is a special chi squared formula that gives a value that can be looked up in a table giving the p value.

      Since we are comparing proportions not means, the Student’s t test CANNOT be used.

      There is no linear regression to plot so Pearson’s co-efficient cannot be calculated.

      Nothing is so obvious that no statistical analysis is needed.

    • This question is part of the following fields:

      • Statistical Methods
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  • Question 20 - During a squint surgery, a 5-year-old child developed severe bradycardia as a result...

    Incorrect

    • During a squint surgery, a 5-year-old child developed severe bradycardia as a result of the oculocardiac reflex.

      The afferent limb of this reflex is formed by which nerve?

      Your Answer:

      Correct Answer: Trigeminal nerve

      Explanation:

      When the eye is compressed or the extra-ocular muscles are tractioned, the oculocardiac reflex causes a decrease in heart rate.

      The ophthalmic division of the trigeminal nerve provides the afferent limb. This synapses with the vagus nerve’s visceral motor nucleus in the brainstem. The efferent signal is carried by the vagus nerve to the heart, where increased parasympathetic tone reduces sinoatrial node output and slows heart rate.

      The most common symptom is sinus bradycardia, but junctional rhythm and asystole can also occur.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 21 - The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised...

    Incorrect

    • The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised by which of the following?

      Your Answer:

      Correct Answer: Synthesis of ATP is brought about by anaerobic respiration

      Explanation:

      Muscle fibre myosin ATPase histochemistry is used to divide the biochemical classification into two groups: type 1 and type II.

      Type I (slow twitch) muscle fibres rely on aerobic glycolytic and aerobic oxidative metabolism to function. They have a lot of mitochondria, a good blood supply, a lot of myoglobin, and they don’t get tired easily.

      Because they contain more motor units, Type II (fast twitch) muscle fibres are thicker. They are more easily fatigued, but produce powerful bursts. The capillary networks and mitochondria are less dense in these white muscle fibres than in type I fibres. They have a low myoglobin content as well.

      Muscle fibres of type II (fast twitch) are divided into three types:

      Type IIa – aerobic/oxidative metabolism is used.
      Type IIb – anaerobic/glycolytic metabolism is used by these fibres.

      When compared to skeletal muscle, cardiac and smooth muscle twitch at a slower rate.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 22 - A 70-year-old man presents with central crushing chest pain that radiates to the...

    Incorrect

    • A 70-year-old man presents with central crushing chest pain that radiates to the jaw in the emergency department. He has associated symptoms of nausea and diaphoresis.

      A 12 lead ECG is performed. ST-elevation is observed in leads V2-V4. The diagnosis of anteroseptal ST-elevation myocardial infarction is made.

      Which coronary vessel is responsible for this condition and runs in the interventricular septum on the anterior surface of the heart to reach the apex?

      Your Answer:

      Correct Answer: Left anterior descending artery

      Explanation:

      The heart receives blood supply from coronary arteries. The right and left coronary arteries branch off the aorta and supply oxygenated blood to all heart muscle parts.

      The left main coronary artery branches into:
      1. Circumflex artery – supplies the left atrium, side, and back of the left ventricle. The left marginal artery arises from the left circumflex artery. It travels along the obtuse margin of the heart.
      2. Left Anterior Descending (LAD) artery – supplies the front and bottom of the left ventricle and front of the interventricular septum

      The left anterior descending coronary artery is the largest coronary artery. It courses anterior to the interventricular septum in the anterior interventricular groove, extending from the base of the heart to its apex. Around the apex, the LAD anastomosis with the terminal branches of the posterior descending artery (branch of the right coronary artery).
      Atherosclerosis or thrombotic occlusion of LAD causes myocardial infarction in large areas of the anterior, septal, and apical portions of the heart muscle. It can lead to a serious deterioration in heart performance.

      Occlusion of the LAD causes anteroseptal myocardial infarction, which is evident on the ECG with changes in leads V1-V4. Occlusion of the left circumflex artery causes lateral, posterior, or anterolateral MI. However, as it does not run towards the apex in the interventricular septum of the heart, it is not the correct answer for this question.

      The right coronary artery branches into:
      1. Right marginal artery
      2. Posterior descending artery

      The right coronary artery supplies the right atrium, right ventricle, interatrial septum, and the inferior posterior third of the interventricular septum. Occlusion of the right coronary artery causes inferior MI, which is indicated on ECG with changes in leads II, III, and aVF.

    • This question is part of the following fields:

      • Anatomy
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  • Question 23 - Prior to an urgent appendicectomy, a 49-year-old man requires a rapid sequence induction.

    His...

    Incorrect

    • Prior to an urgent appendicectomy, a 49-year-old man requires a rapid sequence induction.

      His BMI is equal to 50.

      Which of the following formulas is the most appropriate for calculating a suxamethonium dose in order to achieve optimal intubating conditions?

      Your Answer:

      Correct Answer: 1-1.5 × actual body weight (mg)

      Explanation:

      The usual method of calculating the dose of a drug to be given to patients of normal weight is to use total body weight (TBW). This is because the lean body weight (LBW) and ideal body weight (IBW) dosing scalars are similar in these patients.

      Because the LBW and fat mass do not increase in proportion in patients with morbid obesity, this is not the case. Drugs that are lipid soluble, such as propofol or thiopentone, can cause a relative overdose. Lean body mass is a better scalar in these situations.

      Suxamethonium has a small volume of distribution, so the dose is best calculated using the TBW to ensure optimal and deep intubating conditions. The higher dose was justified because these patients’ plasma cholinesterase activity was elevated.

      Other scalars include:

      The dose of highly lipid soluble drugs like benzodiazepines, thiopentone, and propofol can be calculated using lean body weight (LBW). The formula LBW = IBW + 20% can be used on occasion.

      Fentanyl, rocuronium, atracurium, vecuronium, morphine, paracetamol, bupivacaine, and lidocaine are all administered with LBW.

      Formulas can be used to calculate the ideal body weight (IBW). There are a number of drawbacks, including the fact that patients of the same height receive the same dose, and the formulae do not account for changes in body composition associated with obesity. Because IBW is typically lower than LBW, administering a drug based on IBW may result in underdosing. The body mass index (BMI) isn’t used to calculate drug dosage directly.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 24 - The whole water content of the body is calculated by multiplying body mass...

    Incorrect

    • The whole water content of the body is calculated by multiplying body mass with 0.6. This water is diffused into distinct compartments.

      Which fluid compartment can be measured indirectly?

      Your Answer:

      Correct Answer: Intracellular volume

      Explanation:

      The total body water content of a 70kg man is (70 × 0.6) = 42 litres. For a woman, the calculation is (70 × 0.55) = 38.5 litres.

      For a man, it is subdivided into:

      Extracellular fluid (ECF) = 14L (1/3)
      Intracellular fluid (ICF) = 28L (2/3).

      The ECF volume is further divided into:

      Interstitial fluid = 10.5 litres
      Plasma = 3 litres
      Transcellular fluid (CSF/synovial fluid) = 0.5 litres.

      Directly measured fluid compartments:

      Heavy water (deuterium) can be used to measure total body water content, which is freely distributed.
      Albumin labelled with a radioactive isotope or using a dye called Evans blue can be used to measure Plasma volume . They do not diffuse into red blood cells.
      Radiolabelled (Cr-51) red blood cells can be used to measure total erythrocyte volume.
      Inulin as the tracer can be used to measure ECF volume as it circulate freely in the interstitial and plasma volumes.

      Indirectly measured fluid compartments:

      Total blood volume can be calculated with the level of haematocrit and the volume of total circulating red blood cells.
      ICF volume can be calculated by subtracting ECF volume from total blood volume.

    • This question is part of the following fields:

      • Basic Physics
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  • Question 25 - A 78-year-old man with a previous history of ischaemic heart disease is admitted...

    Incorrect

    • A 78-year-old man with a previous history of ischaemic heart disease is admitted to hospital. He is scheduled for a cardiopulmonary exercise test (CPX) before he undergoes an elective abdominal aneurysm repair.

      What measurement obtained during a CPX test alone provides the best indication for postoperative mortality?

      Your Answer:

      Correct Answer: Anaerobic threshold

      Explanation:

      Cardiopulmonary exercise testing (CPX, CPEX, CPET) is a non-invasive testing method used to determine the performance of the heart, lungs and skeletal muscle. It measures the exercise tolerance of the patient.

      The parameters measured include:

      ECG and ST-segment analysis and blood pressure
      Oxygen consumption (VO2)
      Carbon dioxide production (VCO2)
      Gas flows and volumes
      Respiratory exchange ratio (RER)
      Respiratory rate
      Anaerobic threshold (AT)

      The anaerobic threshold (AT) is an estimate of exercise ability. Any measurement below 11 ml/kg/min is usually related with an increase in mortality, especially when there is a background of myocardial ischaemia occurring during the test.

      Peak VO2 <20 mL/kg with a low AT have a correlation with postoperative complications and a 30 day mortality. The CPX test is used for risk-testing patients prior to surgery to determine the appropriate postoperative care facilities. The V slope measured in CPX testing represents VO2 versus VCO2 relationship. During AT, the ramp of V slope increases, but does not provide a picture of postoperative mortality.

    • This question is part of the following fields:

      • Clinical Measurement
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  • Question 26 - A 21-year-old woman presents to ER following the deliberate ingestion of 2 g...

    Incorrect

    • A 21-year-old woman presents to ER following the deliberate ingestion of 2 g of amitriptyline. On clinical examination:
      Glasgow coma score: 10
      Pulse rate: 140 beats per minute
      Blood pressure: 80/50 mmHg.
      ECG showed a QRS duration of 233 Ms.

      Which of the following statement describes the most important initial course of action?

      Your Answer:

      Correct Answer: Give fluid boluses

      Explanation:

      The first line of treatment in case of hypotension is fluid resuscitation.

      Activated charcoal can be used within one hour of tricyclic antidepressant ingestion but an intact and secure airway must be checked before intervention. The risk of aspiration should be assessed.

      Vasopressors are indicated for the treatment of hypotension following (Tricyclic Antidepressant) TCA overdose when patients fail to respond to fluids and bicarbonate.

    • This question is part of the following fields:

      • Pharmacology
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  • Question 27 - Out of the following, which is NOT a part of the contents of...

    Incorrect

    • Out of the following, which is NOT a part of the contents of the porta hepatis?

      Your Answer:

      Correct Answer: Cystic duct

      Explanation:

      The porta hepatis is a fissure in the inferior surface of the liver. All the neurovascular structures that enter and leave the porta hepatis are:
      1. hepatic portal vein
      2. hepatic artery
      3. hepatic ducts
      4. hepatic nerve plexus (It contains the sympathetic branch to the liver and gallbladder and the parasympathetic, hepatic branch of the vagus nerve.)

      These structures supply and drain the liver. Only the hepatic vein is not part of the porta hepatis.
      The porta hepatis is also surrounded by lymph nodes, that may enlarge to produce obstructive jaundice.
      These structures divide immediately after or within the porta hepatis to supply the functional left and right lobes of the liver.

      The cystic duct lies outside the porta hepatis and is an important landmark in laparoscopic cholecystectomy.

    • This question is part of the following fields:

      • Anatomy
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  • Question 28 - A healthy 27-year old male who weighs 70kg has appendicitis. He is currently...

    Incorrect

    • A healthy 27-year old male who weighs 70kg has appendicitis. He is currently in the operating room and is being positioned to have a rapid sequence induction.

      Prior to preoxygenation, the compartment likely to have the best oxygen reserve is:

      Your Answer:

      Correct Answer: Red blood cells

      Explanation:

      The following table shows the compartments and their relative oxygen reserve:
      Compartment Factors Room air (mL) 100% O2 (mL)
      Lung FAO2, FRC 630 2850
      Plasma PaO2, DF, PV 7 45
      Red blood cells Hb, TGV, SaO2 788 805
      Myoglobin 200 200
      Interstitial space 25 160

      Oxygen reserves in the body, with room air and after oxygenation.

      FAO2-alveolar fraction of oxygen rises to 95% after administration of 100% oxygen (CO2 = 5%)
      FRC- Functional residual capacity – (the most important store of oxygen in the body) – 2,500-3,000 mL in medium sized adults
      PaO2-partial pressure of oxygen dissolved in arterial blood (80 mmHg breathing room air and 500 mmHg breathing 100% oxygen)
      DF -dissolved form (0.3%)
      PV-plasma volume (3L)
      TG-total globular volume (5L)
      Hb-haemoglobin concentration
      SaO2-arterial oxygen concentration (98% breathing air and 100% when preoxygenated)

    • This question is part of the following fields:

      • Physiology
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  • Question 29 - From the following electromagnetic waves, which one has the shortest wavelength? ...

    Incorrect

    • From the following electromagnetic waves, which one has the shortest wavelength?

      Your Answer:

      Correct Answer: X rays

      Explanation:

      Electromagnetic waves are categorized according to their frequency or equivalently according to their wavelength. Visible light makes up a small part of the full electromagnetic spectrum.

      Electromagnetic waves with shorter wavelengths and higher frequencies include ultraviolet light, X-rays, and gamma rays. Electromagnetic waves with longer wavelengths and lower frequencies include infrared light, microwaves, and radio and televisions waves.

      Different electromagnetic waves according to their wavelength from shorter to longer are X-rays, ultraviolet radiations, visible light, infrared radiation, radio waves. X-ray among electromagnetic waves has the shortest wavelength and higher frequency with wavelengths ranging from 10*-8 to 10* -12 and corresponding frequencies.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
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  • Question 30 - Which of the following statement is false regarding dopamine? ...

    Incorrect

    • Which of the following statement is false regarding dopamine?

      Your Answer:

      Correct Answer: Urine output decreases due to inhibition of proximal tubule Na+ reabsorption

      Explanation:

      Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic ? and?1 (but not ?2 ) agonist.

      The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of Dopamine dilates these vessels (by raising intracellular cAMP). This increases g.f.r. In addition, DA exerts a natriuretic effect by D1 receptors on proximal tubular cells.

      Moderately high doses produce a positive inotropic (direct?1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.

      Vasoconstriction (?1 action) occurs only when large doses are infused.

      At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.

      Dopamine is less arrhythmogenic than adrenaline

      Regarding dopamine part of the dose is converted to Noradrenaline in sympathetic nerve terminals.

    • This question is part of the following fields:

      • Pharmacology
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SESSION STATS - PERFORMANCE PER SPECIALTY

Physiology (2/2) 100%
Pharmacology (4/4) 100%
Anatomy (2/2) 100%
Pathophysiology (0/1) 0%
Statistical Methods (1/1) 100%
Passmed