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Question 1
Correct
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The SI unit of energy is the joule. Energy can be kinetic, potential, electrical or chemical energy.
Which of these correlates with the most energy?Your Answer: Energy released when 1 kg fat is metabolised to CO2 and water (the energy content of fat is 37 kJ/g)
Explanation:The derived unit of energy, work or amount of heat is joule (J). It is defined as the amount of energy expended if a force of one newton (N) is applied through a distance of one metre (N·m)
J = 1 kg·m/s2·m = 1 kg·m2/s2 or 1 kg·m2·s-2
Kinetic energy (KE) = ½ MV2
An object with a mass of 1500 kg moving at 30 m/s correlates to 675 kJ:
KE = ½ (1500) × (30)2 = 750 × 900 = 675 kJ
Total energy released when 1 kg fat is metabolised to CO2 and water is 37 MJ. 1 g fat produces 37 kJ/g, therefore 1 kg fat produces 37,000 × 1000 = 37 MJ.
Raising the temperature of 1 kg water from 0°C to 100°C correlates to 420 kJ. The amount of energy needed to change the temperature of 1 kg of the substance by 1°C is the specific heat capacity. We have 1 kg water therefore:
4,200 J × 100 = 420,000 J = 420 kJ
In order to calculate the energy involved in raising a 100 kg mass to a height of 1 km against gravity, we need to calculate the potential energy (PE) of the mass:
PE = mass × height attained × acceleration due to gravity
PE = 100 kg × 1000 m × 10 m/s2 = 1 MJThe heat generated when a direct current of 10 amps flows through a heating element for 10 seconds when the potential difference across the element is 1000 volts can be calculated by applying Joule’s law of heating:
Work done (WD) = V (potential difference) × I (current) × t (time)
WD = 10 × 10 × 1000 = 100 kJ -
This question is part of the following fields:
- Physiology
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Question 2
Correct
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A patient is evaluated for persistent dysphonia six months after undergoing a subtotal thyroidectomy.
Which of the following is the most likely reason for the change in this patient's voice?Your Answer: Damage to recurrent laryngeal nerve
Explanation:After thyroid surgery, about 10-15% of patients experience a temporary subjective voice change of varying degrees. A frog in the throat or cracking of the voice, or a weak voice, are common descriptions. These modifications are only temporary, lasting a few days to a few weeks.
Swelling of the muscles in the area of the dissection, as well as inflammation and oedema of the larynx due to the dissection, or minor trauma from the tracheal tube, are all suspected causes.
On both sides of the thyroid gland, the superior laryngeal nerve (EBSLN) runs along the upper part. The muscles that fine-tune the vocal cords are innervated by these nerves. The quality of their voice is usually normal if they are injured, but making high-pitched sounds may be difficult. Injury to the EBSLN occurs in about 2% of the population.
Injuries to the recurrent laryngeal nerve (RLN) have been reported to occur in 1 percent to 14 percent of people. Except for the cricothyroid muscle, the RLN supplies all of the laryngeal intrinsic muscles.
This complication is usually unilateral and temporary, but it can also be bilateral and permanent, and it can be intentional or unintentional. The most common complication following thyroid surgery is a permanent lesion of damaged RLN, which manifests as an irreversible phonation dysfunction.
The crico-arytenoid joint dislocation is a relatively uncommon complication of tracheal intubation and blunt neck trauma. The probability is less than one in a thousand.
Vocal cord polyps affect 0.8 percent of people.
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This question is part of the following fields:
- Pathophysiology
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Question 3
Incorrect
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The solutions that contains the most sodium is?
Your Answer: 500 mL 5% N saline
Correct Answer: 3500 mL 0.9% N saline
Explanation:Sodium concentration for different fluids
3% N saline 513 mmol/L
5% N saline 856 mmol/L
0.9% N saline 154 mmol/L
Hartmann’s solution 131 mmol/L
0.45% N saline with 5% glucose 77 mmol/LThis means that:
500 mL 5% N saline contains 428 mmol of sodium
1000 mL 3% N saline contains 513 mmol of sodium
3500 mL 0.9% N saline contains 539 mmol of sodium
4000 mL Hartmann’s contains 524 mmol of sodium
6000 mL 0.45% N saline with 5% glucose contains 462 mmol of sodium. -
This question is part of the following fields:
- Physiology
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Question 4
Correct
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An 82-year-old male has severe abdominal pain that is out of proportion to the examination. He is a known case of atrial fibrillation and diverticulitis. Suspecting mesenteric ischemia, he was thoroughly investigated, and a mesenteric angiography shows ischemia of the left colic flexure.
Which artery gives off branches that supply this region directly?Your Answer: Inferior mesenteric artery (IMA)
Explanation:Mesenteric ischemia is ischemia of the blood vessels of the intestines. It can be life-threatening, especially if the small intestine is involved.
The inferior mesenteric artery originates 3-4 cm above the bifurcation of the abdominal aorta.
The left colic artery branches off the inferior mesenteric artery to supply the following:
– distal 1/3 of the transverse colon
– descending colonAt approximately the left colic flexure (splenic flexure), a transition occurs in the blood supply of the GI tract. The SMA supplies the proximal part to the flexure, and the IMA supplies the part distal to the flexure. This is why the left colic flexure is a watershed area and is prone to ischemia exacerbated by atherosclerotic changes or hypotension. The dominant arterial supply of the splenic flexure is usually from the left colic artery, but it may also get collaterals from the left branch of the middle colic artery.
The AMA and PMA do not exist.
The splenic artery directly supplies the spleen and has branches that supply the stomach and the pancreas.
The proximal two-thirds of the transverse colon is supplied by the middle colic artery, a branch of the SMA. -
This question is part of the following fields:
- Anatomy
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Question 5
Correct
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A 55-year-old woman presents for transsphenoidal surgery following a diagnosis of pituitary macroadenoma.
Which of the following is the most common visual field defect caused by such lesions?Your Answer: Bitemporal hemianopia
Explanation:Pituitary tumours that compress the optic chiasma primarily affect the neurones that decussate at this location. Bitemporal hemianopia is caused by neurones that emerge from the nasal half of the retina and transmit the temporal half of the visual field.
The axons of ganglion cells in the retina form the optic nerve.
It exits the orbit through the optic foramen and projects to the thalamic lateral geniculate body. The optic chiasma forms above the sella turcica as the nasal fibres decussate along the way. The optic radiation travels from the lateral geniculate body to the occipital cortex.
Lesions at various points along this pathway cause the following visual field defects:
Scotoma implies partial retinal or optic nerve damage.
Monocular vision loss occurs when the optic nerve is completely damaged.
Pathology at the optic chiasma causes bitemporal hemianopia.
Cortical blindness with occipital cortex pathology and homonymous hemianopia with lesions compromising the optic radiation. -
This question is part of the following fields:
- Pathophysiology
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Question 6
Correct
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A 76-year-old female, presents to her GP. She complains of fatigue and increased shortness of breath. On examination, she is noted to have pallor, an increased respiratory and heart rate. Her GP requests further diagnostic investigations, including a full blood count (FBC) which finds decreased MCV and MCHC.
What is the most likely cause of her symptoms?Your Answer: Iron deficiency
Explanation:The patient’s diagnosis is microcytic hypochromic anaemia which is often as a result of iron deficiency and thalassaemia.
Macrocytic anaemia is often caused by folate and B12 deficiencies and alcohol abuse.
Normocytic normochromic anaemia is often caused by acute blood loss, haemolytic anaemia, anaemia of chronic disease and leucoerythroblastic anaemias.
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This question is part of the following fields:
- Clinical Measurement
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Question 7
Correct
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The following is normally higher in concentration extracellularly than intracellularly
Your Answer: Sodium
Explanation:The ions found in higher concentrations intracellularly than outside the cells are:
ATP
AMP
Potassium
Phosphate, and
Magnesium Adenosine diphosphate (ADP)Sodium is a primarily extracellular ion.
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This question is part of the following fields:
- Physiology
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Question 8
Correct
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Which statement is the most accurate when describing electrical equipment and shock?
Your Answer: Type CF is considered to safe for direct connection with the heart
Explanation:There are different classes of electrical equipment that can be classified in the table below:
Class 1 – provides basic protection only. It must be connected to earth and insulated from the mains supply
Class II – provides double insulation for all equipment. It does not require an earth.
Class III – uses safety extra low voltage (SELV) which does not exceed 24 V AC. There is no risk of gross electrocution but risk of microshock exists.
Type B – All of above with low leakage currents (0.5mA for Class IB, 0.1 mA for Class IIB)
Type BF – Same as with other equipment but has ‘floating circuit’ which means that the equipment applied to patient is isolated from all its other parts.
Type CF – Class I or II equipment with ‘floating circuits’ that is considered to be safe for direct connection with the heart. There are extremely low leakage currents (0.05mA for Class I CF and 0.01mA for Class II CF)
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This question is part of the following fields:
- Clinical Measurement
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Question 9
Correct
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An acidic drug with a pKA of 4.3 is injected intravenously into a patient.
At a normal physiological pH, the approximate ratio of ionised to unionised forms of this drug in the plasma is?Your Answer: 1000:01:00
Explanation:The pH at which the drug exists in 50 percent ionised and 50 percent unionised forms is known as the pKa.
To calculate the proportion of ionised to unionised form of an ACID, use the Henderson-Hasselbalch equation.
pH = pKa + log ([A-]/[HA])
or
pH = pKa + log [(salt)/(acid)]
pH = pKa + log ([ionised]/[unionised]).Hence, if the pKa − pH = 0, then 50% of drug is ionised and 50% is unionised.
In this example:
7.4 = 4.3 + log ([ionised]/[unionised])
7.4 − 4.3 = log ([ionised]/[unionised])
log 3.1 = log ([ionised]/[unionised])Simply put, the antilog is the inverse log calculation. In other words, if you know the logarithm of a number, you can use the antilog to find the value of the number. The antilogarithm’s definition is as follows:
y = antilog x = 10x
Antilog to the base 10 of 0 = 1, 1 = 10, 2 =100, 3 = 1000, and 4 = 10,000.
If you want to find the antilogarithm of 3.1, for a number between 3 and 4, the antilogarithm will return a value between 1000 and 10,000. The ratio is 1:1 if pKa = pH, that is, pH pKa = log 0. (50 percent ionised and unionised).
According to the above value, there is only one unionised molecule for every approximately 1000 (1259) ionised molecules of this drug in plasma, implying that this drug is largely ionised in plasma (99.99 percent ).
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This question is part of the following fields:
- Pharmacology
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Question 10
Correct
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A patient visits the radiology department for a magnetic resonance imaging (MRI) scan (MRI). The presence of metal implants must be ruled out prior to the scan.
In a strong magnetic field, which of the following metals is the safest?Your Answer: Chromium
Explanation:Ferromagnetism is the property of a substance that is magnetically attracted and can be magnetised indefinitely. A material is said to be paramagnetic if it is attracted to a magnetic field. A substance is said to be diamagnetic if it is repelled by a magnetic field.
Cobalt, iron, gadolinium, neodymium, and nickel are ferromagnetic.
Gadolinium is a ferromagnetic rare earth metal that is ferromagnetic below 20 degrees Celsius (its Curie temperature). MRI scans are enhanced with gadolinium-based contrast media.
When ferromagnetic materials are exposed to a magnetic field, they can cause a variety of issues like magnetic field interactions, heating, and image artefacts.
Titanium, lead, chromium, copper, aluminium, silver, gold, and tin are non ferromagnetic.
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This question is part of the following fields:
- Clinical Measurement
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Question 11
Incorrect
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What feature is found in the flowmeters of modern anaesthetic machines ?
Your Answer: Have an accuracy of about +/- 4%
Correct Answer: The use of stannic oxide increases the accuracy of flowmeters
Explanation:Flowmeters measure the rate at which a specific gas, that the flowmeter has been calibrated for, passes through. This calibration is done at room temperature and standard atmospheric pressure with an accuracy of +/- 2%.
Reading the flowmeter is done from the top of a bobbin (the midpoint of a ball). Oxygen is the last gas to be added downstream to the mixture delivered to the back bar as a safety feature. This prevents delivery of a hypoxic mixture.
Inaccurate flow measurements occur when the bobbin sticks to the inside wall of the flowmeter. Stannic oxide has been used as a successful antistatic substance thus, reducing the aforementioned risk.
Carbon dioxide being easily delivered is found on some older machines, but those attached flowmeters are limited by a maximum flow of 500 ml /min. Thus avoiding the delivery of a hypercarbic mixture.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 12
Correct
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An 80 year old woman is due for cataract surgery.
There are no contraindications to regional anaesthesia so a peribulbar block was performed. 8mls of 2% lidocaine was injected using an infratemporal approach. However, there is still movement of the globe after 5 mins.
The least likely extraocular muscle to develop akinesia is:Your Answer: Superior oblique
Explanation:The fibrotendinous ring formed by the congregation of the rectus muscles at the apex of the orbit does not include superior oblique. This muscle is completely outside the ring and so it is the most difficult muscle to anaesthetise completely. A good grasp of the anatomy of the area being anaesthetised is important with all regional anaesthetic techniques so that potential problems and complications with a block can be anticipated.
The borders of this pyramid whose apex points upwards and outwards of the bony orbit are as follows:
Floor – Zygoma and Maxilla
Roof – frontal bone
Medial wall – maxilla, ethmoid, sphenoid and lacrimal bones.
Lateral wall – greater wing of the sphenoid and the zygoma.The four recti muscles (superior, medial, lateral and inferior) originate from a tendinous ring (the annulus of Zinn) and extend anteriorly to insert beyond the equator of the globe. Bands of connective tissue are present between the rectus muscles forming a conical structure and hinder the passage of local anaesthetic.
The superior oblique muscle is situated outside this ring and is the most difficult muscle to anaesthetise completely, particularly with a single inferotemporal peribulbar injection. An additional medial injection may help to prevent this.
The cranial nerve supply to the extraocular muscles are:
3rd (inferior oblique, inferior recti, medial and superior)
4th (superior oblique), and
6th (lateral rectus).The long and short ciliary nerves provide the sensory supply to the globe and these are branches of the nasociliary nerve, (which is itself a branch of the ophthalmic division of the trigeminal nerve).
To achieve anaesthesia for the eye, these nerves which enter the fibrotendinous ring need to be fully blocked to anaesthetise the eye for surgery.
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This question is part of the following fields:
- Anatomy
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Question 13
Correct
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In North America, there have been reports of paediatric patients dying after undergoing adenotonsillectomy for obstructive sleep apnoea.
Respiratory depression/obstruction is thought to be the cause of death. The codeine dose was 0.5-1 mg/kg, given every 4-6 hours.
In this group of patients, which of the following is the most likely cause of respiratory depression and obstruction?Your Answer: Exaggerated metabolism of codeine
Explanation:Codeine is easily absorbed from the gastrointestinal tract and converted to morphine and norcodeine in the liver via O- and N-demethylation. Morphine and norcodeine are excreted almost entirely by the kidney, primarily as conjugates with glucuronic acid.
By glucuronidation, phase II metabolism enzyme UDP-glucuronosyl transferase-2B7 converts morphine to morphine-3-glucuronide (M3G) and morphine-6-glucuronide (M6G) (UGT2B7).
Approximately 60% of morphine is converted to M3G, with the remaining 6-10% converted to M6G. M3G is inactive, but M6G is said to be 4 to 650 times more potent on the MOP receptor than morphine.
When codeine is consumed, cytochrome P450 2D6 in the liver converts it to morphine (CYP2D6).
Some people have DNA variations that increase the activity of this enzyme, causing codeine to be converted to morphine more quickly and completely than in others. After taking codeine, these ultra-rapid metabolisers are more likely to have higher than normal levels of morphine in their blood.
Respiratory depression/obstruction can be caused by high levels of morphine and M6G, especially in people who have a history of obstructive sleep apnoea. The estimated number of ultra-rapid metabolisers ranges from 1 to 7 per 100 people, but some ethnic groups may have as many as 28 per 100 people.
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This question is part of the following fields:
- Pathophysiology
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Question 14
Correct
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An study on post-operative nausea and vomiting (PONV) among paediatric patients who underwent tonsillectomy showed a decrease in incidence from 10% to 5% following a new management protocol.
Which of the following best estimates the numbers needed to treat (NNT) for one additional patient to benefit from the new management of PONV?Your Answer: 20
Explanation:The Number Needed to Treat (NNT) is the number of patients you need to treat to prevent one additional bad outcome. For example, if a drug has an NNT of 5, it means you have to treat 5 people with the drug to prevent one additional bad outcome.
To calculate the NNT, you need to know the Absolute Risk Reduction (ARR); the NNT is the inverse of the ARR:
NNT = 1/ARR
Where ARR = CER (Control Event Rate) – EER (Experimental Event Rate).
NNTs are always rounded up to the nearest whole number.
In this case, the NNT can be computed as follows:
ARR = 10% – 5% = 0.05
NNT = 1/0.05 = 20
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This question is part of the following fields:
- Statistical Methods
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Question 15
Correct
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An individual who recently moved his residence from the plains to the mountains will experience immediately which physiologic response to high altitude and hypoxia?
Your Answer: Increased cardiac output
Explanation:A person remaining at high altitudes for days, weeks, or years becomes more and more acclimatized to the low PO2, so it causes fewer deleterious effects on the body.
After acclimatization, it becomes possible for the person to work harder without hypoxic effects or to ascend to still higher altitudes. The principal means by which acclimatization comes about are (1) a great increase in pulmonary ventilation, (2) increased numbers of red blood cells, (3) diffusing capacity of the lungs, (4) increased vascularity of the peripheral tissues, and (5) increased ability of the tissue cells to use oxygen despite low PO2.
The cardiac output often increases as much as 30% immediately after a person ascends to high altitude but then decreases back toward normal over a period of weeks as the blood haematocrit increases, so the amount of oxygen transported to the peripheral body tissues remains about normal.
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This question is part of the following fields:
- Pathophysiology
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Question 16
Incorrect
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What makes the ultrasound nebulizer efficient?
Your Answer: Humidification of inspired gas by up to 100%
Correct Answer: Reduction in gas flow resistance
Explanation:Smallest drops reach not only the upper but also the lower respiratory tracks. As a result, the ultrasonic nebulizer is most efficient for the therapy of pulmonary diseases and stands out as a robust and reliable support within the clinical setting.
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This question is part of the following fields:
- Basic Physics
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Question 17
Correct
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Prior to rapid sequence induction of anaesthesia, a man with a BMI of 35 is pre-oxygenated.
Which method of pre-oxygenation with a tight-fitting face mask is the most effective?Your Answer: Oxygen 6 litres per minute via a Mapleson A breathing system, with patient sitting up at 30 degrees breathing four vital capacity breaths
Explanation:This patient is morbidly obese and has a high risk of developing hypoxia. This will be exacerbated by the patient’s supine position, as a result of:
Functional residual capacity has been reduced (FRC)
Increased closing capacity (CC)
Reduced tidal volume due to increased airway resistance, decreased thoracic cage compliance, and decreased respiratory muscle strength and endurance
Following induction of general anaesthesia, there is a tendency for atelectasis and increased O2 consumption due to the increased workload of respiratory muscles and the overall increase in metabolism.Pre-oxygenation with 100 percent oxygen via a tight-fitting mask can be done using either tidal volume breaths for three to five minutes or four vital capacity breaths in normal circumstances. In the head-up position, this patient is much more likely to be adequately pre-oxygenated, maximising the FRC and minimising the CC. In spontaneously breathing patients, the Mapleson A and circle systems are both effective, but the Mapleson D requires 160-200 ml/kg/minute to prevent rebreathing.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 18
Incorrect
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Which of the following statements about closing capacity is true?
Your Answer: It increases during anaesthesia
Correct Answer: It is less than the functional residual capacity in a 30-year-old
Explanation:Closing capacity refers to volume of gas within the lungs at which the conducting small airways begin to close, that is, the point during expiration when small airways close.
It is calculated mathematically as:
Closing capacity = Closing volume (CV) + Residual volume (RV)
Functional residual capacity (FRC) is the volume of gas still present within the lungs post expiration.
Closing capacity is lower than the functional residual capacity in younger adults, but begins to rise to eventually equal, and then exceed it with increasing age (at about middle age), increasing intrabdominal pressure, decreasing blood flow in the pulmonary system and parenchymal disease within the pulmonary system.
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This question is part of the following fields:
- Clinical Measurement
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Question 19
Correct
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A 75-year-old man, visits his general practitioner. He complains of changes to his bowel habit and unexpected weight loss in the last 6 months. He is scheduled for a colonoscopy and biopsy where he is diagnosed with a transverse colon malignancy.
The transverse colon is one of many organs tethered to the posterior wall of the abdominal cavity by a double fold of the peritoneum.
Which of the listed organs is also tethered to the peritoneum in a similar way?Your Answer: The stomach
Explanation:The peritoneal cavity is made up of the omentum, the ligaments and the mesentery.
The section of the peritoneum responsible for tethering organs to the posterior abdominal wall is the mesentery.
These tethered organs are classified as intraperitoneal, and these include the stomach, spleen, liver, first and fourth parts of the duodenum, jejunum, ileum, transverse, and sigmoid colon.
Retroperitoneal organs are located posterior to the peritoneum and include: the rest of the duodenum, the ascending colon, the descending colon, the middle third of the rectum, and the remainder of the pancreas
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This question is part of the following fields:
- Anatomy
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Question 20
Correct
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Which vessel is the first to branch from the external carotid artery?
Your Answer: Superior thyroid artery
Explanation:The superior thyroid artery is the first branch of the external carotid artery. The other branches of the external carotid artery are:
1. Superior thyroid artery
2. Ascending pharyngeal artery
3. Lingual artery
4. Facial artery
5. Occipital artery
6. Posterior auricular artery
7. Maxillary artery
8. Superficial temporal arteryThe inferior thyroid artery is derived from the thyrocervical trunk.
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This question is part of the following fields:
- Anatomy
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Question 21
Incorrect
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A 77-year-old woman is scheduled for day case cataract surgery under local anaesthesia. She has no cardiac or respiratory problems. Lisinopril is being used to treat her hypertension, which is under control.
Which of the following preoperative investigations are the most appropriate for this patient?Your Answer: FBC and ECG
Correct Answer: No investigations
Explanation:Because the patient has mild systemic disease, he is ASA 2 and the procedure will be performed under local anaesthesia.
The following factors should be considered when requesting preoperative investigations:
Indications derived from a preliminary clinical examination
Whether or not a general anaesthetic will be used, the possibility of asymptomatic abnormalities, and the scope of the surgery.No special investigations are needed if the patient has no history of significant systemic disease and no abnormal findings on examination during the nurse-led assessment.
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This question is part of the following fields:
- Clinical Measurement
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Question 22
Correct
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Which of the following vertebral levels is the site where the aorta perforates the diaphragm?
Your Answer: T12
Explanation:The diaphragm divides the thoracic cavity from the abdominal cavity. Structures penetrate the diaphragm at different vertebral levels through openings in the diaphragm to communicate between the two cavities. The diaphragm has openings at three vertebral levels:
T8: vena cava, terminal branches of the right phrenic nerve
T10: oesophagus, vagal trunks, left anterior phrenic vessels, oesophageal branches of the left gastric vessels
T12: descending aorta, thoracic duct, azygous and hemi-azygous vein -
This question is part of the following fields:
- Anatomy
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Question 23
Incorrect
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Which of the following statements is true regarding vecuronium?
Your Answer: Has a bisquaternary amino-steroid structure
Correct Answer: Has a similar structure to rocuronium
Explanation:Vecuronium is used as a part of general anaesthesia to provide skeletal muscle relaxation during surgery or mechanical ventilation. It is a monoquaternary aminosteroid (not quaternary) non- depolarising neuromuscular blocking drug.
It has a structure similar to both rocuronium and pancuronium. The only difference is the substitution of specific groups on the steroid structure.
Vecuronium is not associated with the release of norepinephrine from sympathetic nerve endings. However, Pancuronium has norepinephrine releasing the property.
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This question is part of the following fields:
- Pharmacology
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Question 24
Correct
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Regarding a paramagnetic oxygen analyser, the following statements are TRUE:
Your Answer: Utilises null deflection
Explanation:The electrons in the outer shell of an oxygen molecule are unpaired, thus it has paramagnetic properties and is attracted into a magnetic field.
It utilizes null deflection -True
Null deflection is a crucial principle in paramagnetic analysers (reflected beam of light on two photocells) which gives very accurate results (typically 0.1%).It can be used to measure the concentration of diamagnetic gases – False
Since most other gases are weakly diamagnetic they are repelled by a magnetic field (nitric oxide is also paramagnetic).Can measure gases dissolved in the blood – False
For accurate analysis the sample gas must be dried before passing into the analysis cell, for example, by passage through silica gel. Therefore, they are unsuitable to measure gases dissolved in blood.Does not require calibration – False
As with most measurement instruments paramagnetic analysers must be calibrated before use.E) The readings are unaffected by water vapour – False
Water vapour affects the readings hence for accurate analysis the sample gas must be dried before passing into the analysis cell, for example, by passage through silica gel. That is why they are unsuitable to measure dissolved blood gases. -
This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 25
Correct
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An 82-year old male has shortness of breath which is made worse when he lies down but investigations have revealed a normal ejection fraction. Why might this be?
Your Answer: He has diastolic dysfunction
Explanation:Decreased stroke volume causes decreased ejection fraction which results in diastolic dysfunction.
Ejection fraction is not a useful measure in someone with diastolic dysfunction because stroke volume may be reduced whilst end-diastolic volume may be reduced.
Diastolic dysfunction may arise with reduced heart compliance.Ejection fraction measures of the proportion of blood leaving the ventricles with each beat and is calculated as follows:
Stroke volume / end-diastolic volume.A healthy ejection fraction is usually taken as 60% (based on a stroke volume of 70ml and end-diastolic volume of 120ml).
Respiratory inspiration causes a decreased pressure in the thoracic cavity, which in turn causes more blood to flow into the atrium.
Sitting up decreases venous because of the action of gravity on blood in the venous system.
Hypotension also decreases venous return.
A less compliant aorta, like in aortic stenosis increases end systolic left ventricular volume which decreases stroke volume.Systemic vascular resistance = mean arterial pressure / cardiac output.
Increased vascular resistance impedes the flow of blood back to the heart.Increased venous return increases end diastolic LV volume as there is more blood returning to the ventricles.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 26
Correct
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A 68-year-old man presents worried about his risk of motor neurone disease. No symptoms have developed, but his father suffered from motor neurone disease. Recently, his cousin has also been diagnosed with amyotrophic lateral sclerosis. He searched the internet for screening tests for motor neurone disease and found a blood test called ‘neuron’, and requests to have it done. You search this blood test and find a prospective study going on evaluating the potential benefits of this blood test. On average, this test diagnosed patients with the disease 8 months earlier than the patients who are diagnosed on the basis of their clinical symptoms. The patients diagnosed using this neuron test also survived, on average, 48 months from the diagnosis, whereas the patients diagnosed clinically survived an average of 39 months from the diagnosis. Considering the clear benefits, you decide to have it done on the patient.
Which of the following options best relate to the above scenario?Your Answer: Lead-time bias
Explanation:Hypochondriasis is an illness anxiety disorder, and describes excessively worriedness about the presence of a disease. While the woman is concerned about her possibility of developing motor neurone disease, she understands that no symptoms have yet appeared. Hypochondriasis involves patients who refuse to accept that they don’t have the disease, even if the results come back negative.
Late Look Bias occurs when the data is gathered or analysed at an inappropriate time e.g. when many of the subjects suffering from a fatal disease have died. This type of biasness might occur in some retrospective studies of motor neurone disease, but is not applicable to this prospective study.
In procedure bias, the researcher decides assignment of a treatment versus control and assigns particular patients to one group or the other non-randomly. This is unlikely to have occurred in this case, although it is not mentioned specifically. Of all the options, lead time-bias is a better answer.
The Hawthorne Effect refers to groups modifying their behaviour simply because they are aware of being observed. Any differences in the behaviour have not been mentioned in the question, and it is highly unlikely that a change in patient’s behaviour would have affected their length of survival in this case.
The correct option is lead-time bias. Even if the new blood test diagnoses the disease earlier, it doesn’t affect the outcome, as the survival time was still on average 43 months from the onset of symptoms in both groups. With the help of blood test, the disease was only detected 8 months earlier.
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This question is part of the following fields:
- Statistical Methods
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Question 27
Incorrect
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A 70-year-old female presented with a productive cough and is prescribed a bacteriostatic antibiotic?
Which of the following best explains the mechanism of action of bacteriostatic drugs?Your Answer:
Correct Answer: Protein synthesis inhibition
Explanation:Cell membrane pore formation, Bacterial DNA damage, Peptidoglycan cross-linking inhibition, and peptidoglycan synthesis inhibitor are always lethal and such mechanisms are possible only in bactericidal drugs. But Protein synthesis inhibition would only prevent cell replication or cell growth and is responsible for bacteriostatic effects of the drug.
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This question is part of the following fields:
- Pharmacology
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Question 28
Incorrect
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Levels of serum potassium in around 1000 patients that were on ACE inhibitor were measured. The mean value was calculated to be 4.6mmol/L and a standard deviation of 0.3mmol/L was recorded.
Which among the given options is correct?Your Answer:
Correct Answer: 68.3% of values lie between 4.3 and 4.9 mmol/l
Explanation:Its known that 68.3% of the total values of a normally distributed variable are found within a range of 1 standard deviation from the mean which makes the range to be 4.3 to 4.9 mmol/L.
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This question is part of the following fields:
- Statistical Methods
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Question 29
Incorrect
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An 81-year old man was admitted to the Pulmonology Ward due to chronic obstructive airway disease (COPD) exacerbation. Upon physical examination, he was hypertensive at 140/90 mmHg, tachycardic at 114 beats per minute, and tachypnoeic at 33 breaths per minute.
Arterial blood gas analysis was obtained and showed the following results:
pH: 7.25 (Reference range: 7.35-7.45)
PaO2: 73 mmHg (9.7 kPa) (Reference range: 11.3-12.6 kPa)
PaCO2: 56 mmHg (7.5 kPa) (Reference range: 4.7-6.0 kPa)
SaO2: 90%
Standard bicarbonate: 29 mmol/L (Reference range: 20-28)
BE: +4 mmol/L (± 2)
Which of the following options has the most significant impact on his respiratory rate?Your Answer:
Correct Answer: CSF pH
Explanation:The arterial blood gas analysis indicates presence of acute respiratory acidosis.
Central chemoreceptors are located in the ventral medulla and respond directly to presence of hydrogen ions in the CSF. When stimulated, it causes an increase in respiratory rate.
It is believed that hydrogen ions may be the only important direct stimulus for these neurons, however, CO2 is believed to stimulate these neurons secondarily by changing the hydrogen ion concentration.
Changes in O2 concentration have virtually no direct effect on the respiratory centre itself to alter respiratory drive. Although, O2 changes do have an indirect effect by acting through the peripheral chemoreceptors.
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This question is part of the following fields:
- Pathophysiology
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Question 30
Incorrect
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Regarding the use of soda lime as part of a modern circle system with a vaporiser outside the circuit (VOC), which of the following is its most deleterious consequence?
Your Answer:
Correct Answer: Carbon monoxide formation
Explanation:When using dry soda lime for VOCs, very high amounts of carbon monoxide may be produced, regardless of the inhalational anaesthetic agent used. The carbon monoxide produced is sufficient enough to cause cytotoxic and anaemic hypoxia. To prevent this, soda lime canisters are shaken well to even out the packing of granules. This can help to evenly distribute gas flow for proper CO2 absorption and ventilation.
Compound A is formed when dry soda lime, or soda lime in high temperature, reacts with the inhalational anaesthetic Sevoflurane. Animal studies have shown renal toxicity in rats, but renal adverse effects in humans are yet to be observed.
When monitors are not employed with VOCs, deleterious effects are not for certain. However, monitors not employed with vaporiser inside the circuit (VIC) can lead to significant adverse events.
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This question is part of the following fields:
- Pathophysiology
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Question 31
Incorrect
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An otherwise fit 7-year-old boy for an elective tonsillectomy is seen holding a bottle of sugared orange squash at anaesthetic assessment . He appears to have consumed 120 mL of the bottle's contents.
What is the minimal safe fasting time prior to proceeding with a general anaesthetic in this patient?Your Answer:
Correct Answer: 1 hour
Explanation: -
This question is part of the following fields:
- Pathophysiology
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Question 32
Incorrect
-
An 80-year-old female presents to the emergency department with symptoms consistent with mesenteric ischemia. She is quickly shifted to the operation theatre for an emergency laparotomy.
On exploration, the segment of the colon from the splenic flexure down to the rectum is ischemic.
The artery blocked in this scenario arises at what vertebral level from the aorta?Your Answer:
Correct Answer: L3
Explanation:The hindgut is from the distal third of the transverse colon down to the upper one-third of the anal canal. The inferior mesenteric artery supplies the hindgut.
The inferior mesenteric artery arises from the aorta behind the inferior border of the third part of the duodenum 3–4 cm above the aortic bifurcation, at the third lumbar vertebra level.
The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:
T12 – Coeliac trunk
L1 – Left renal artery
L2 – Testicular or ovarian arteries
L3 – Inferior mesenteric artery
L4 – Bifurcation of the abdominal aorta
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This question is part of the following fields:
- Anatomy
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Question 33
Incorrect
-
Patient’s having disease (Test Positive: 60, Test Negative:40)
Patient’s not having the disease (Test Positive:20, Test Negative: 80)
This is a result of a new tumour marker blood test, that was performed on 200 women for breast cancer screening. The director of the screening programme ask you to evaluate the observations and inform them the specificity of this new test.
Which one of the following figure you will relay to the programme director?Your Answer:
Correct Answer: 80%
Explanation:The positive predictive value is the ratio of patients truly diagnosed as positive to all those who had positive test results. In this case, this is 60/(60+20)=75%.
The negative predictive value is the ratio of patients truly diagnosed as negative to all those who had negative test results. In this case, this is 80/(80+40)=67%.
The sensitivity is the ratio of patients with the disease who test positive i.e. true positive patients to the total number of people with the disease. In this case, this is 60/(60+40)=60%.
The specificity is the ratio of people who don’t have the disease who test negative i.e. true negatives to the total number of people without the disease. In this case, this is 80/(20+80)=80%.
70% is not the result of any screening measurements
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This question is part of the following fields:
- Statistical Methods
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Question 34
Incorrect
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An orthopaedic surgery is scheduled for a 68-year-old man. He is normally in good shape. His routine biochemistry results are checked and found to be within normal limits.
Which of the following pairs has the greatest impact on his plasma osmolarity?Your Answer:
Correct Answer: Sodium and potassium cations
Explanation:The number of osmoles (Osm) of solute per litre (L) of solution (Osmol/L) is the unit of measurement for solute concentration. The calculated serum osmolality assumes that the primary solutes in the serum are sodium salts (chloride and bicarbonate), glucose, and urea nitrogen.
2 (Na + K) + Glucose + Urea (all in mmol/L) = calculated osmolarity
313 mOsm/L = 2 (144 + 6) + 9.5 + 3.5
Sodium and potassium ions clearly contribute the most to plasma osmolarity. Glucose and urea, on the other hand, are less so.
The osmolarity of normal serum is 285-295 mOsm/L. Temperature and pressure affect osmolality, and this calculated variable is less than osmolality for a given solution.
The number of osmoles (Osm) of solute per kilogramme (Osm/kg) is a measure of osmolality, which is also a measure of solute concentration. Temperature and pressure have no effect on the value. An osmometer is used to measure it in the lab. Osmometers rely on a solution’s colligative properties, such as a decrease in freezing point or a rise in vapour pressure.
The osmolar gap (OG) is calculated as follows:
OG = osmolaRity calculated from measured serum osmolaLity
Excess alcohols, lipids, and proteins in the blood can all contribute to the difference.
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This question is part of the following fields:
- Physiology
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Question 35
Incorrect
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The clavipectoral fascia is penetrated by the cephalic vein to terminate in which of the listed veins?
Your Answer:
Correct Answer: Axillary
Explanation:The cephalic vein is a superficial vein that runs through the forearm and the arm, before draining into the axillary vein where it terminates.
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This question is part of the following fields:
- Anatomy
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Question 36
Incorrect
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A 21-year-old female was brought to the Emergency department with a ruptured ectopic pregnancy.
On clinical examination, the following were the findings:
Pulse: 120 beats per minute
BP: 120/95 mmHg
Respiratory rate: 22 breaths per minute
Capillary refill time: three seconds
Cool peripheries.
Which of the following best describes the cause for this clinical finding?Your Answer:
Correct Answer: Reduction in blood volume of 15-30%
Explanation:Classification of hemorrhagic shock according to Advanced Trauma Life Support is as follows:
– Class I haemorrhage (blood loss up to 15%) in which there is no change in blood pressure, RR, or pulse pressure.
– Class II haemorrhage (15-30% blood volume loss) where there is tachycardia, tachypnoea, and a decrease in pulse pressure.
– Class III haemorrhage (30-40% blood volume loss) where clinical signs of inadequate perfusion, marked tachycardia, tachypnoea, significant changes in mental state, and measurable fall in systolic pressure is seen. It almost always requires a blood transfusion.
– Class IV haemorrhage (> 40% blood volume loss) in which marked tachycardia, significant depression in systolic pressure and very narrow pulse pressure, and markedly depressed mental state with cold and pale skin are seen.
Loss of >50% results in loss of consciousness, pulse, and blood pressure.
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This question is part of the following fields:
- Pathophysiology
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Question 37
Incorrect
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Question 38
Incorrect
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A 25-year-old male has tonsillitis and is in considerable pain.
Which nerve is responsible for the sensory innervation of the tonsillar fossa?Your Answer:
Correct Answer: Glossopharyngeal nerve
Explanation:A tonsillar sinus or fossa is a space that is bordered by the triangular fold of the palatoglossal and palatopharyngeal arches in the lateral wall of the oral cavity. The palatine tonsils are in these sinuses.
The glossopharyngeal nerve is the main sensory nerve for the tonsillar fossa. The tonsillar branches of the glossopharyngeal nerve supply the palatine tonsils forming a plexus around it. Filaments from this plexus are distributed to the soft palate and fauces where they communicate with the palatine nerves. A lesser contribution is made by the lesser palatine nerve. Because of this otalgia may occur following tonsillectomy.
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This question is part of the following fields:
- Anatomy
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Question 39
Incorrect
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A 240 volt alternating current (AC) socket from a wall is used to charge a direct current (DC) cardiac defibrillator.
Name the electrical component that converts AC to DC.Your Answer:
Correct Answer: Rectifier
Explanation:There are two types of defibrillators
AC defibrillator
DC defibrillatorAC defibrillator,
consists of a step-up transformer with primary and secondary winding and two switches. Since secondary coil consists of more turns of wire than the primary coil, it induces larger voltage. A voltage value ranging between 250V to 750V is applied for AC external defibrillator. And used to enable the charging of a capacitor.DC defibrillator,
consists of auto transformer T1 that acts as primary of the high voltage transformer T2. Is an iron core that transfers energy between 2 circuits by electromagnetic induction. Transformers are used to isolate circuits, change impedance and alter voltage output. transformers do not convert AC to DC.Diode rectifier composed of 4 diodes made of semiconductor material allows current to flow only in one direction. Alternating current (AC) passing through these diodes produces direct current (DC). Capacitor stores the charge in the form of an electrostatic field.
Capacitor is used to convert the rectified AC voltage to produce DC voltage but capacitors do not directly convert AC to DC.
Inductor induces a counter electromotive force(emf) that reduces the capacitor discharge value.
In step-down transformer primary coils has more turns of wire than secondary coil, so induced voltage is smaller in the secondary coil.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 40
Incorrect
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A 60-year old male has anaemia and is being investigated. The most common combination of globin chains in a normal adult is:
Your Answer:
Correct Answer: α2β2
Explanation:There are 4 different types of globin chains which surround 4 heme molecules in haemoglobin (Hb) – α (alpha), β (beta), γ (gamma), and δ (delta)
α chains are essential.
δ2β2 and β2γ2 are not found in a healthy adult.
97% of the Hb in a healthy adult is made of α2β2 (2 α chains and 2 β chains).
α2δ2 accounts for around 1.5-3% of the adult Hb.
α2γ2 accounts for less than 1%.With respect to oxygen transport in cells, almost all oxygen is transported within erythrocytes. There is limited solubility and only 1% is carried as solution. Thus, the amount of oxygen transported depends upon haemoglobin concentration and its degree of saturation.
Haemoglobin is a globular protein composed of 4 subunits. Haem is made up of a protoporphyrin ring surrounding an iron atom in its ferrous state. The iron can form two additional bonds – one is with oxygen and the other with a polypeptide chain. There are two alpha and two beta subunits to this polypeptide chain in an adult and together these form globin. Globin cannot bind oxygen but can bind to CO2 and hydrogen ions. The beta chains are able to bind to 2,3 diphosphoglycerate. The oxygenation of haemoglobin is a reversible reaction. The molecular shape of haemoglobin is such that binding of one oxygen molecule facilitates the binding of subsequent molecules.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 41
Incorrect
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What is NOT a feature of Propofol infusion syndrome?
Your Answer:
Correct Answer: Hypotriglyceridaemia
Explanation:Propofol infusion syndrome is a rare but extremely dangerous complication of propofol administration
Common organ systems affected by PRIS include the following:
1. cardiovascular
widening of QRS complex, Brugada syndrome-like patterns (particularly type 1), ventricular tachyarrhythmias, cardiogenic shock, and asystole2. hepatic
Liver enzymes elevation, hepatomegaly, and steatosis3. skeletal muscular
myopathy and overt rhabdomyolysis4. renal
Hyperkalaemia, acute kidney injury5. metabolic
High anion gap metabolic acidosis (due to elevation in lactic acid) -
This question is part of the following fields:
- Anatomy
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Question 42
Incorrect
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A subject in a study is to take 100 mg of tramadol tablets for the next eight hours. Urine samples will be taken during the 8-hour course, which will undergo analysis via liquid chromatography.
Given the following metabolites, which one would have the highest analgesic property?Your Answer:
Correct Answer: Mono-O-desmethyl-tramadol
Explanation: -
This question is part of the following fields:
- Pharmacology
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Question 43
Incorrect
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Which of the following is true about number needed to harm?
Your Answer:
Correct Answer: The number of patients that must receive a particular treatment for one additional patient to experience an adverse outcome.
Explanation:Number needed to harm are a measure of the impact of a treatment or intervention that is often used to communicate results to patients, clinicians, the public and policymakers. It states how many patients need to be treated for one additional patient to experience an adverse outcome (e.g. a death). It is calculated as the inverse of the absolute risk reduction. It can equally well be applied to harmful outcomes as well as beneficial ones, where it becomes numbers needed to treat (NNT) instead.
In this way, they are both calculated the same but NNT usually refers to a therapeutic treatment whereas NNH refers to a risk-factor for disease.
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This question is part of the following fields:
- Statistical Methods
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Question 44
Incorrect
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When nitrous oxide is stored in cylinders at room temperature, it is a gas.
Which of its property is responsible for this?
Your Answer:
Correct Answer: Critical temperature
Explanation:The temperature above which a gas cannot be liquefied no matter how much pressure is applied is its critical temperature. The critical temperature of nitrous oxide is 36.5°C
The minimum pressure that causes liquefaction is the critical pressure of that gas.
The Poynting effect refers to the phenomenon where mixing of liquid nitrous oxide at low pressure with oxygen at high pressure (in Entonox) leads to formation of gas of nitrous oxide.
There is no relevance of molecular weight to this question. it does not change with phase of a substance.
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This question is part of the following fields:
- Pharmacology
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Question 45
Incorrect
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A double blind placebo control clinical trial is done. Which of these is correct about it?
Your Answer:
Correct Answer: The clinician assessing the effects of the treatment does not know which treatment the patient has been given
Explanation:A ‘double blind crossover study’ happens when every patient receive both treatments.
It is incorrect to say that only half of the patients do not know which treatment they receive because in a double blind placebo control clinical trial ALL of the patients are blind to their treatment choice .
If some of the patients are not treated, they would be aware that they were not being treated and it could not be considered a blind trial.
In a double blind placebo control clinical trial both the clinician and the patient are blind to the treatment choice. The clinician assessing the effects of the treatment, therefore, does not know which treatment the patient has been given.
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This question is part of the following fields:
- Statistical Methods
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Question 46
Incorrect
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A 32-year-old male is admitted to the critical care unit. He has suffered a heroin overdose and requires intubation and ventilatory support.
What would be his predicted total static compliance (lung and chest wall) measurements.Your Answer:
Correct Answer: 100 ml/cmH2O
Explanation:Static lung compliance refers to the change in volume within the lung per given change in unit pressure. It is usually measured when air flow is absent, such as during pauses in inhalation and exhalation.
It is a combination of:
Chest wall compliance: normal value is 200 mL/cmH2O
Lung tissue compliance: normal value is 200 mL/ cmH2OIt is represented mathematically as:
1/Crs = 1/Cl + 1/Ccw
Where,
Crs = total compliance of the respiratory system
Cl = compliance of the lung
Ccw = compliance of the chest wallTherefore in this case:
1/Crs = 1/200 + 1/200
1/Crs = 0.005 + 0.005 = 0.01
1/Ct = 0.01
Rearranging equation gives:
Ct = 1/0.01 = 100 mL/cmH2O.
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This question is part of the following fields:
- Clinical Measurement
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Question 47
Incorrect
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Which one of the following causes vasoconstriction?
Your Answer:
Correct Answer: Angiotensin II
Explanation:Prostacyclin is a strong vasodilator. It is administered as an intravenous infusion for critical ischemia. Commercially, it is available as sodium epoprodtenol.
Atrial Natriuretic peptide (ANP) hormone secreted from the atria, kidney, and neural tissues. It primarily acts on renal vessel to maintain normal blood pressure and reduce plasma volume by: increasing the renal excretion of salt and water, glomerular filtration rate, vasodilation, and by increasing the vascular permeability. It also inhibits the release of renin and aldosterone.
Indoramin is an alpha-adrenoceptor blocking agent. which act selectively on post-synaptic-alpha adrenoreceptor, leading to decease in peripheral resistance.
Angiotensin II is a vasoconstrictor, causing high sodium retention. It also increases the secretion of antidiuretic hormone (ADH) and aldosterone level.
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This question is part of the following fields:
- Pharmacology
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Question 48
Incorrect
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A breakthrough lipid-lowering therapy for stroke had a number needed to treat (NNT) of 20 for the prevention of the primary end-point. These results can be best described as:
Your Answer:
Correct Answer: For 1000 patients treated with active therapy, there would be 50 fewer strokes
Explanation:Number needed to treat (NNT) is a time specific epidemiological measure that indicates how many patients would be require for an intervention to prevent one additional bad outcome. A perfect NNT would be 1, where everyone improves with treatment, thus the higher the NNT, the less effective the treatment.
Thus if you treat 1000 patients then you will expect to have 50 fewer strokes.
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This question is part of the following fields:
- Statistical Methods
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Question 49
Incorrect
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The phenomenon that the patients behaved in a different manner when they know that they are being observed is termed as?
Your Answer:
Correct Answer: Hawthorne effect
Explanation:Hawthorne effect explains the change in any behavioural aspect owing to the awareness that the person is being observed.
Simpson’s Paradox explains the association developed when the data from several groups is combined to form a single larger group.The remaining terms are made up.
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This question is part of the following fields:
- Statistical Methods
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Question 50
Incorrect
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Which of the following drugs is safe to be used in porphyria?
Your Answer:
Correct Answer:
Explanation:Porphyria is a group of disorders in which there is excess production and excess excretion of porphyrins and their precursors. They are usually genetic and are caused due to defects in the haem metabolic pathway. However, other factors like infection, pregnancy, mensuration, starvation may precipitate the attack.
Sulphonamides, barbiturates (methohexitone and thiopental), and phenytoin are considered to be precipitants so are not safe to use
Chloral hydrate is thought to be safe to use.
Etomidate lacks proper studies and may be used with caution but it is generally advised not to use this drug especially if other alternatives are available. -
This question is part of the following fields:
- Pharmacology
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Question 51
Incorrect
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Which of the following nerves is responsible for relaying sensory information from the laryngeal mucosa?
Your Answer:
Correct Answer: Laryngeal branches of the vagus
Explanation:Sensory innervation of the larynx is controlled by branches of the vagus nerve.
The internal and external bifurcations of the superior laryngeal nerve is responsible for sensory innervation of the aspect of the larynx superior to the vocal cords, while the recurrent laryngeal nerve is responsible for sensory innervation of the intrinsic musculature of the larynx except for the cricothyroid muscle.
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This question is part of the following fields:
- Anatomy
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Question 52
Incorrect
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Compared to the parasympathetic nervous system (PNS), the sympathetic nervous system (SNS) has:
Your Answer:
Correct Answer: Nicotinic receptors in pre and post ganglionic synapses
Explanation:With regards to the autonomic nervous system (ANS)
1. It is not under voluntary control
2. It uses reflex pathways and different to the somatic nervous system.
3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.With regards to the central nervous system (CNS)
1. There are myelinated preganglionic fibres which lead to the
ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.Most organs are under control of both systems although one system normally predominates.
The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.
There are short pre-ganglionic and long post ganglionic fibres.
Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.
There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.
Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.
The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.
The cranial outflow consists of
1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreasThe sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.
The PNS has long preganglionic and short post ganglionic fibres.
Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.Different types of these muscarinic receptors are present in different organs:
There are:
M1 = pupillary constriction, gastric acid secretion stimulation
M2 = inhibition of cardiac stimulation
M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
M4 = brain and adrenal medulla
M5 = brainThe lacrimal glands are solely under parasympathetic control.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 53
Incorrect
-
You have always been curious about the effects of statins. While going through a study, something ticks you off and makes you think that they are way more common then the data suggests and are mostly under reported. In search of some concrete evidence, you decide to conduct a study of your own. While doing research, you come across a recent study that highlights the long term effects of statins.
Which of the following types of study could that have been?Your Answer:
Correct Answer: Clinical trial, Phase 4
Explanation:In general practice, majority of phase 3 trials and some of the trials conducted in phase 2 are randomized. Because phase 4 trials require a huge sample size, they are not randomized as much. The primal reason behind conducting phase 3 trials is to test the efficiency and safety in a significant sample population. At this point it is assumed that the drug is effective up to a certain extent.
During a case-control study, subjects that exhibit outcomes of interest are compared with those who don’t show the expected outcome. The extent of exposure to a particular risk factor is then matched between cases and controls. If the exposure among cases surpasses controls, it becomes a risk factor for the outcome that is being studied.
Pilot studies are conducted on a lower and much smaller level, to assess if a randomized controlled trial of the crucial components of a study will be plausible.
Phase 4 trials are the ones that are conducted after its established that the drug is effective and is approved by the regulating authority for use. These trials are concerned with the side effects and potential risks associated with the long term usage of the drug.
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This question is part of the following fields:
- Statistical Methods
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Question 54
Incorrect
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Which of the following is true about the patellar reflex?
Your Answer:
Correct Answer: Is abolished immediately after transection of the spinal cord at T6
Explanation:The patellar (knee jerk) reflex is a monosynaptic stretch reflex arising from L2-L4 nerve roots. It occurs after a tap on the patellar tendon which causes the spindles of the quadriceps muscles to stretch.
The afferent nerve pathway occurred through A gamma fibres.
Wesphal’s sign refers to a reduction, or absence of the patellar reflex. It is often indicated of a neurological disease affecting the PNS.
A transection of the spinal cord results in a degree of shock which causes all reflexes to be reduced or completely absent, and required a period of approximately 6 weeks to recover.
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This question is part of the following fields:
- Pathophysiology
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Question 55
Incorrect
-
Calcium homeostasis is regulated by parathormone (PTH).
Which of the following PTH actions is most likely to cause calcium to be released from bone?Your Answer:
Correct Answer: Indirect stimulation of osteoclasts
Explanation:The hormone parathyroid hormone (PTH) and the receptor parathyroid hormone type 1 (PTH1-Rc) are important regulators of blood calcium homeostasis.
PTH can cause a rapid release of calcium from the matrix in bone, but it also affects long-term calcium metabolism by acting directly on bone-forming osteoblasts (by binding to PTH1-Rc) and indirectly on bone-resorbing osteoclasts.
PTH causes changes in the synthesis and/or activity of several proteins, including osteoclast-differentiating factor, also known as TRANCE or RANKL, when it acts on osteoblasts.
RANK receptors are found on the cell surfaces of osteoclast precursors. The osteoclasts are activated when RANKL binds to the RANK receptors. Osteoclasts lack PTH receptors, whereas osteoblasts do. Osteoclasts are activated indirectly when the RANK receptor binds to the RANKL secreted by osteoblasts, resulting in bone resorption. PTH1 receptors are found in osteoclasts, but they are few.
PTH activates G-protein coupled receptors in all target cells via adenylate cyclase.
The PTH2 receptor is most abundant in the nervous system and pancreas, but it is not a calcium metabolism regulator. It is abundant in the septum, midline thalamic nuclei, several hypothalamic nuclei, and the dorsal horn of the spinal cord, as well as the cerebral cortex and basal ganglia. Expression in pancreatic islet somatostatin cells is the most prominent on the periphery.
The distribution of the receptor is being used to test functional hypotheses. It may play a role in pain modulation and hypothalamic releasing-factor secretion control.
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This question is part of the following fields:
- Pathophysiology
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Question 56
Incorrect
-
A study of 1500 participants is designed to determine the normal range for a number of parameters in a certain population.
Analysis has revealed that there is a strong positive correlation between height and forced expiratory volume (FEV1).
Which of the following statistical technique can be utilized to predict FEV1 at any given height in this cohort?Your Answer:
Correct Answer: Linear regression
Explanation:A forest plot is a graphical representation that summarizes the findings of several research, such as a meta-analysis of a series of randomized controlled trials.
The Kaplan-Meier estimate shows survival over time, for example, plotting the number of patients still alive seven years after chemotherapy for lung cancer.
Fisher’s exact test similarly uses contingency tables to assess statistical significance, however, it is typically used when sample sizes are small.
Chi-square test assesses whether an association exists between two categorical variables using the observed and expected frequencies. For instance, is social class (I-V) related to body mass index (BMI) category? Using the observed and anticipated frequencies, the Chi-square test determines whether a connection exists between two categorical variables. For example, is socio-economic status related to BMI category?
Linear regression is a technique which attempts to model the relationship between two variables by fitting a linear equation to observed data. Linear regression uses correlation between two continuous variables. As correlation only indicates the strength of an association only, it cannot be used to forecast the change in one variable when a second variable is altered.
This equation takes the form y = mx + c, where ‘y’ is the dependent variable, ‘x’ is the independent variable, ‘m’ is the slope of the line and ‘c’ is the intercept. In this example, for a range of heights, it would be possible to map a line of best fit to a scatter plot and thus predict the forced expiratory volume (FEV1) for an individual.
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This question is part of the following fields:
- Statistical Methods
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Question 57
Incorrect
-
Which of the following statement is false regarding dopamine?
Your Answer:
Correct Answer: Urine output decreases due to inhibition of proximal tubule Na+ reabsorption
Explanation:Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic ? and?1 (but not ?2 ) agonist.
The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of Dopamine dilates these vessels (by raising intracellular cAMP). This increases g.f.r. In addition, DA exerts a natriuretic effect by D1 receptors on proximal tubular cells.
Moderately high doses produce a positive inotropic (direct?1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.
Vasoconstriction (?1 action) occurs only when large doses are infused.
At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.
Dopamine is less arrhythmogenic than adrenaline
Regarding dopamine part of the dose is converted to Noradrenaline in sympathetic nerve terminals.
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This question is part of the following fields:
- Pharmacology
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Question 58
Incorrect
-
At a pH of 7, pure water has an hydrogen ion concentration of?
Your Answer:
Correct Answer: 100 nanomol/L
Explanation:pH is the negative log to the base 10 of hydrogen ion concentration:
So, what power produces the answer?
pH = – log10 [H+]
Making [H+] the subject:
[H+] = 10-pH
Substituting, [H+] = 10-7
One nanomole = 1 x 10-9 or 0.000000001
10-7 = 1x 0.0000001 or 10 x 0.00000001 or 100 x 0.000000001
100 nanomole
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This question is part of the following fields:
- Basic Physics
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Question 59
Incorrect
-
Typical sigmoid log dose-response curves are seen in agonists and are used to compare efficacy and potency. Which of the following opioids has a log dose-response curve furthest to the right?
Your Answer:
Correct Answer: Tramadol
Explanation:Lesser the potency of the drug, the higher the dose required to produce maximal receptor occupation. So, the least potent drug will have a log dose-response curve furthest to the right on X-axis.
Based on the option given, tramadol is the least potent drug and thus higher dose is required to produce maximal opioid receptor occupation.
Thus, Tramadol is the least potent opioid with a log dose-response curve furthest to the right on X-axis.
Note, Fentanyl is the most potent opioid with a log dose-response curve furthest to the left on the X-axis.
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This question is part of the following fields:
- Pharmacology
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Question 60
Incorrect
-
A 74-year old male who has a history of heart failure has an exacerbation of his symptoms and goes to the ED. An ultrasound scan is done which shows that there is a decrease in his stroke volume. Which of these choices would one expect to increase his stroke volume0
Your Answer:
Correct Answer: Respiratory inspiration
Explanation:Respiratory inspiration causes a decreased pressure in the thoracic cavity, which in turn causes more blood to flow into the atrium.
Sitting up decreases venous because of the action of gravity on blood in the venous system.
Hypotension also decreases venous return.
A less compliant aorta, like in aortic stenosis increases end systolic left ventricular volume which decreases stroke volume.Systemic vascular resistance = mean arterial pressure / cardiac output. Increased vascular resistance impedes the flow of blood back to the heart.
Increased venous return increases end diastolic LV volume as there is more blood returning to the ventricles.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 61
Incorrect
-
Regarding the anatomical relations of the scalenus muscles, which of these is true?
Your Answer:
Correct Answer: The trunks of the brachial plexus emerge from the lateral border of scalenus anterior
Explanation:The ascending cervical artery lies media the phrenic nerve on scalenus anterior and can easily be mistaken for the phrenic nerve at operation.
The phrenic nerve passes across scalenus anterior and medius inferiorly.
The subclavian artery is separated from the vein by the scalenus anterior.
The brachiocephalic vein is formed at the medial border of scalenus anterior by the subclavian vein and the internal jugular vein.
Emerging from the lateral border of scalenus anterior are the trunks of the brachial plexus .
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This question is part of the following fields:
- Anatomy
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Question 62
Incorrect
-
A balanced general anaesthetic including a muscle relaxant is administered at induction. It is observed that the train-of-four count is two after two hours, with no further doses of the muscle relaxant.
What is most likely reason for this?Your Answer:
Correct Answer: Mivacurium with plasma cholinesterase deficiency
Explanation:Mivacurium is metabolised primarily by plasma cholinesterase at an In vitro rate of about 70% that of succinylcholine. Mivacurium is contraindicated in patients with genetic and acquired plasma cholinesterase deficiencies.
The clearance of atracurium is by Hoffman degradation and ester hydrolysis in the plasma and is independent of both hepatic and renal function.
Rocuronium is eliminated primarily by the liver after metabolises to a less active metabolite, 17-desacetyl-rocuronium. Its duration of action is not affected much by renal impairment.
Vecuronium undergoes hepatic metabolism into 3-desacetyl-vecuronium which has 50-80% the activity of the parent drug. It undergoes biliary (40%) and renal excretion (30%). The aminoglycoside antibiotics possess additional neuromuscular blocking activity. The potency of gentamicin > streptomycin > amikacin. Calcium can be used to reverse the muscle weakness produced by gentamicin but not neostigmine. When vecuronium and gentamycin are given together the effect on neuromuscular blockade is synergistic.
Significant residual neuromuscular block 2 hours after the administration of these drugs is unlikely In this scenario.
Any recovery from neuromuscular blockade with suxamethonium in a patient with deficiency of plasma cholinesterase demonstrate four twitches on a train of four count.
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This question is part of the following fields:
- Pharmacology
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Question 63
Incorrect
-
Dinamap is an automated blood pressure monitoring device. Which of these statements best fit its properties?
Your Answer:
Correct Answer: The cuff should be positioned at the same level as the heart
Explanation:Dinamap continuously measures the systolic, diastolic and mean arterial pressure along with pulse rate, thereby providing a continuous monitoring of the blood pressure using the osscillitonometric principle of measurement.
The device loses accuracy towards the extremes of BP and is more accurate with systolic compared with diastolic pressure. In arrhythmias such as AF, the devices are also inaccurate due to the major fluctuations associated with the individual pulse pressure variations.
The manual BP device is still the gold standard for BP measurement and monitoring.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 64
Incorrect
-
The external laryngeal nerve is responsible for the innervation of which of the following muscles?
Your Answer:
Correct Answer: Cricothyroid
Explanation:The external laryngeal nerve arises from the superior laryngeal nerve and provides innervation to the cricothyroid muscle.
The other muscles mentioned receive their innervations from the recurrent laryngeal nerve.
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This question is part of the following fields:
- Anatomy
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Question 65
Incorrect
-
Which of the following statement is not true regarding the effects of Dopamine infusions?
Your Answer:
Correct Answer: Decreasing gastric transit time
Explanation:Moderately high doses of dopamine produce a positive inotropic (direct?1 and D1 action + that due to Noradrenaline release), but the little chronotropic effect on the heart.
Vasoconstriction (?1 action) occurs only when large doses are infused.
At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.
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This question is part of the following fields:
- Pharmacology
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Question 66
Incorrect
-
Which of the following closely estimates the interstitial oncotic pressure acting on a pulmonary capillary?
Your Answer:
Correct Answer: 17 mmHg
Explanation:The starling forces operate to maintain a homeostatic flow across the pulmonary capillary bed.
The outward driving force comprises of the capillary hydrostatic pressure (13 mmHg), negative interstitial fluid pressure (zero to slightly negative), and interstitial colloid osmotic pressure (17 mmHg). The inward driving force is controlled by the plasma colloid osmotic pressure (25 mmHg).
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This question is part of the following fields:
- Basic Physics
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Question 67
Incorrect
-
A previously fit 26-year-old is undergoing surgery to repair an inguinal hernia. He is breathing on his own, and a supraglottic airway is being maintained via a circle system with air/oxygen and sevoflurane.
With a fresh gas flow of 14 L/min, the end-tidal CO2 reading is 8.1 kPa. CO2 pressure is 1.9 kPa. The percentages of oxygen inhaled and exhaled are 38 and 33 percent, respectively.
What do you think is the most likely source for these readings?Your Answer:
Correct Answer: Incompetent expiratory valve
Explanation:The patient is rebreathing carbon dioxide that has been exhaled.
Exhaustion of the soda lime and failure of the expiratory valve are the two most likely causes. A leak in the inspiratory limb is a less likely cause. Increased inhaled and exhaled carbon dioxide levels may appear with a normal-looking capnogram if the expiratory valve is ineffective.
The patient will exhale into both the inspiratory and expiratory limbs if the inspiratory valve is inoperable. A slanted downstroke inspiratory phase (as the patient inhales carbon dioxide-containing gas from the inspiratory limb) and increased end-tidal carbon dioxide can be seen on the capnogram.
Even if the soda lime were exhausted, a high fresh gas flow would be enough to prevent rebreathing. The difference in oxygen concentrations in inspired and expired breaths would be less pronounced.
Hypercapnia is caused by respiratory obstruction and malignant hyperthermia, but not by rebreathing.
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This question is part of the following fields:
- Pathophysiology
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Question 68
Incorrect
-
Which of the following is an expected change in pulmonary function seen during a moderate asthma attack?
Your Answer:
Correct Answer: Decreased forced expiratory volume in 1 sec (FEV1)
Explanation:Asthma is a lung condition that causes reversible narrowing and swelling of airway passages. It is classified by the frequency and severity of symptoms.
The following are symptoms of moderate asthma:
Symptoms include cough, wheezing, chest tightness, or difficulty breathing which occurs daily
Decreased activity levels due to flare-ups
Night-time symptoms 5 or more times a month
Lung function test FEV1 is 60-80% of predicted normal values
Peak flow has more than 30% variabilityWith moderate asthma attacks, the arterial pCO2 levels may decrease, but as severity increases, so does the pCO2, reaching normal levels, and then exceeding them in severe asthma attacks.
Airway obstruction increases the functional residual capacity.
Concentration of serum bicarbonate would not increase in moderate asthma, but it could possibly increase in life-threatening asthma via the same mechanism as what increases arterial PCO2.
FEV1 is a good measure of airway obstruction. and is reduced in acute asthma attacks.
In the case of a pneumothorax, a decrease in arterial PO2 is higher.
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This question is part of the following fields:
- Pathophysiology
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Question 69
Incorrect
-
For a rapid sequence induction of anaesthesia, you are pre-oxygenating a patient using 100% oxygen and a fresh gas flow equal to the patient's minute ventilation.
Which would be the most suitable choice of anaesthetic breathing system in this situation?Your Answer:
Correct Answer: Mapleson A system
Explanation:The Mapleson A (Magill) and coaxial version of the Mapleson A system (Lack circuit) are more efficient for spontaneous breathing than any of the other Mapleson circuits. The fresh gas flow (FGF) required to prevent rebreathing is slightly greater than the alveolar minute ventilation (4-5 litres/minute). This is delivered to the patient through the outer coaxial tube and exhaust gases are moved to the scavenging system through the inner tube. In the Lack circuit, the expiratory valve is located close to the common gas outlet away from the patient end. This is the main advantage of the Lack circuit over the Mapleson A circuit.
The Mapleson E circuit is a modification of the Ayres T piece and the FGF required to prevent rebreathing is 1.5-2 times the patient’s minute volume.
The Bain circuit is the coaxial version of the Mapleson D circuit.
The FGF for spontaneous respiration to avoid rebreathing is 160-200 ml/kg/minute.
The FGF for controlled ventilation to avoid rebreathing is 70-100 ml/kg/min.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 70
Incorrect
-
Which one of the following patients presenting for elective surgery has an American Society of Anaesthesiologists (ASA) preoperative physical status grading of III?
Your Answer:
Correct Answer: A 50-year old man with a BMI of 41 with a reduced exercise tolerance
Explanation:The ASA physical status classification system is a system for assessing the fitness of patients before surgery. It was last updated in October 2014.
ASA I A normal healthy patient
ASA II A patient with mild systemic disease
ASA III A patient with severe systemic disease
ASA IV A patient with severe systemic disease that is a constant threat to life
ASA V A moribund patient who is not expected to survive without the operation
ASA VI A declared brain-dead patient whose organs are being removed for donor purposesA 20-year old woman who is 39-weeks pregnant with no other medical conditions – ASA II
A 35-year-old man with a BMI of 29 with a good exercise tolerance who smokes-ASA II
A 50-year old man with a BMI of 41 with a reduced exercise tolerance -ASA III
A 65-year old woman with a BMI of 34 with treated hypertension with no functional limitations-ASA II
A 73-year old man who has had a TIA ten-weeks ago but has a good exercise tolerance and is a non-smoker-ASA IV
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This question is part of the following fields:
- Clinical Measurement
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Question 71
Incorrect
-
Which of the following statements is true regarding prazosin?
Your Answer:
Correct Answer: Is a selective alpha 1 adrenergic receptor antagonist.
Explanation:Selective ?1 -Blockers like prazosin, terazosin, doxazosin, and alfuzosin cause a decrease in blood pressure with lesser tachycardia than nonselective blockers (due to lack of ?2 blocking action.
The major adverse effect of these drugs is postural hypotension. It is seen with the first few doses or on-dose escalation (First dose effect).
Its half-life is approximately three hours.
It is excreted primarily through bile and faeces (not through kidneys)
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This question is part of the following fields:
- Pharmacology
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Question 72
Incorrect
-
Of the following, which is NOT a branch of the subclavian artery?
Your Answer:
Correct Answer: Superior thyroid artery
Explanation:The left subclavian artery originates from the aortic arch, while the right subclavian artery originates from the brachiocephalic artery.
The subclavian artery gives off branches on both sides of the body:
1. Vertebral artery
2. Internal thoracic artery
3. Thyrocervical trunk
4. Costocervical trunk
5. Dorsal scapular arteryThe superior thyroid artery is the first branch of the external carotid artery. The other branches of the external carotid artery are:
1. Superior thyroid artery
2. Ascending pharyngeal artery
3. Lingual artery
4. Facial artery
5. Occipital artery
6. Posterior auricular artery
7. Maxillary artery
8. Superficial temporal artery -
This question is part of the following fields:
- Anatomy
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Question 73
Incorrect
-
A 30-year old male has Von Willebrand's disease and attends the hospital to get an infusion of desmopressin acetate. The way this works is by stimulating the release of von Willebrand factor from cells, which in turn increases factor VIII and platelet plug formation in clotting.
In patients that have no clotting abnormalities, the substance that keeps the blood soluble and prevents platelet activation normally is which of these?Your Answer:
Correct Answer: Prostacyclin
Explanation:Even though aprotinin reduces fibrinolysis and therefore bleeding, there is an associated increased risk of death. It was withdrawn in 2007.
Protein C is dependent upon vitamin K and this may paradoxically increase the risk of thrombosis during the early phases of warfarin treatment.The coagulation cascade include two pathways which lead to fibrin formation:
1. Intrinsic pathway – these components are already present in the blood
Minor role in clotting
Subendothelial damage e.g. collagen
Formation of the primary complex on collagen by high-molecular-weight kininogen (HMWK), prekallikrein, and Factor 12
Prekallikrein is converted to kallikrein and Factor 12 becomes activated
Factor 12 activates Factor 11
Factor 11 activates Factor 9, which with its co-factor Factor 8a form the tenase complex which activates Factor 102. Extrinsic pathway – needs tissue factor that is released by damaged tissue)
In tissue damage:
Factor 7 binds to Tissue factor – this complex activates Factor 9
Activated Factor 9 works with Factor 8 to activate Factor 103. Common pathway
Activated Factor 10 causes the conversion of prothrombin to thrombin and this hydrolyses fibrinogen peptide bonds to form fibrin. It also activates factor 8 to form links between fibrin molecules.4. Fibrinolysis
Plasminogen is converted to plasmin to facilitate clot resorption -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 74
Incorrect
-
A graph is created to show the exponential relationship between bacterial growth (y-axis) and time (x-axis).
Which of the following statements is most true about this kind of exponential relationship?Your Answer:
Correct Answer: y = ex
Explanation:The relationship between bacterial growth and time is a tear-away exponential. The mathematical relationship between y and x in this case is:
y = ex
Where: the power is x, and the base is e.
Euler’s number (e) is a mathematical constant that is the base for all logarithms occurring naturally. Its value is 2.718.
The statement X increasing with an increase in Y is proportional to Y refers to the change in y in terms of x when considering any exponential relationship.
This is not a build-up exponential, and that is mathematically stated as y = 1-e-kt.
The negative x axis being a horizontal asymptote and the y intercept being 0, 1 are examples of tearaway exponentials , but do not describe an exponential process.
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This question is part of the following fields:
- Statistical Methods
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Question 75
Incorrect
-
A 68-year-old man has suffered a myocardial infarction. He has a heart rate of 40 beats per minute currently.
Your senior attending explains that the slow heart rate is due to the damage to the conduction pathways between the sinoatrial and atrioventricular nodes. His ventricles are being paced by the AV node alone.
What artery supplies the AV node in the majority of patients?
Your Answer:
Correct Answer: Right coronary artery
Explanation:The AV node has an intrinsic firing rate of 40-60 beats per minute which is clinically significant in cases of damage to the conducting pathways as patients continue to have a ventricular rate of 40-60. Patients who have an AV node supplied by the right coronary are said to be right dominant. The remaining 10% are left dominant and supplied by the left circumflex.
The right coronary artery supplies the right atrium, right ventricle, interatrial septum, and the inferior posterior third of the interventricular septum. It also supplies the atrioventricular node + sinoatrial node in most patients. The posterior descending artery supplies the posterior third of the interventricular septum.
The heart receives blood supply from coronary arteries. The right and left coronary arteries branch off the aorta and supply oxygenated blood to all heart muscle parts.
The left main coronary artery branches into:
1. Circumflex artery – supplies the left atrium, side, and back of the left ventricle. The left marginal artery arises from the left circumflex artery. It travels along the obtuse margin of the heart.
The left marginal artery, a branch of the circumflex artery, supplies the left ventricle.
2. Left Anterior Descending (LAD) artery – supplies the front and bottom of the left ventricle and front of the interventricular septumThe right coronary artery branches into:
1. Right marginal artery
2. Posterior descending artery -
This question is part of the following fields:
- Anatomy
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Question 76
Incorrect
-
A 63-year old man has palpitations and goes to the emergency room. An ECG shows tall tented T waves, which corresponds to phase 3 of the cardiac action potential.
The shape of the T wave is as a result of which of the following?Your Answer:
Correct Answer: Repolarisation due to efflux of potassium
Explanation:Cardiac conduction
Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium
Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop
Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period
Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period
Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 77
Incorrect
-
An 80-year-old female suffered a TIA 2 weeks ago. She has been admitted to the vascular ward as she will be undergoing carotid endarterectomy tomorrow morning. To explain the procedure and its complications, the surgeon gives her information about the procedure, telling her the artery will be tied during the operation.
She inquires about the areas supplied by the different arteries. You explain that the internal carotid artery supplies the brain while the external carotid artery ascends the neck and bifurcates into two arteries. One of these arteries is the superficial temporal artery. Which of the following is the second branch?Your Answer:
Correct Answer: Maxillary artery
Explanation:Carotid endarterectomy is the procedure to relieve an obstruction in the carotid artery by opening the artery at its origin and stripping off the atherosclerotic plaque with the intima. This procedure is performed to prevent further episodes, especially in patients who have suffered ischemic strokes or transient ischemic attacks.
The external carotid artery terminates by dividing into the superficial temporal and maxillary branches. The maxillary artery is the larger of the two terminal branches and arises posterior to the neck of the mandible.
The other arteries mentioned in the answer options branch off from the following:
Temporal arteries from the maxillary artery
Middle meningeal artery from the maxillary artery
Lingual artery from the anterior aspect of the external carotid artery
Facial artery from the anterior aspect of the external carotid artery -
This question is part of the following fields:
- Anatomy
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Question 78
Incorrect
-
Which statement is true about the autonomic nervous system?
Your Answer:
Correct Answer: Preganglionic synapse utilise Acetylcholine as the neurotransmitter in both parasympathetic and sympathetic systems
Explanation:With regards to the autonomic nervous system (ANS)
1. It is not under voluntary control
2. It uses reflex pathways and different to the somatic nervous system.
3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.With regards to the central nervous system (CNS)
1. There are myelinated preganglionic fibres which lead to the
ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.Most organs are under control of both systems although one system normally predominates.
The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.
There are short pre-ganglionic and long post ganglionic fibres.
Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.
There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.
Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.
The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.
The cranial outflow consists of
1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreasThe sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.
The PNS has long preganglionic and short post ganglionic fibres.
Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.Different types of these muscarinic receptors are present in different organs:
There are:
M1 = pupillary constriction, gastric acid secretion stimulation
M2 = inhibition of cardiac stimulation
M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
M4 = brain and adrenal medulla
M5 = brainThe lacrimal glands are solely under parasympathetic control.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 79
Incorrect
-
The half-empty cylinder weighs 4.44 kg.
The tare weight of a nitrous oxide cylinder is 4 kg.
The molecular weight of nitrous oxide is 44gm.
Based on the data, how many litres of nitrous oxide remains in the cylinder for use?Your Answer:
Correct Answer: 224 litres
Explanation:The Tare weight of a cylinder is the weight when it is empty. So,
Weight of cylinder – tare weight = weight of remaining N2O (g).
4.44 kg – 4 kg = 0.44 kg
Here,
0.44 kg of nitrous oxide remains in the cylinderSince the molecular weight of nitrous oxide is 44 g and one mole of an ideal gas will occupy a volume of 22.4 litres at STP
Therefore amount left in the cylinder is several (gN2O/44) x 22.4 litres of N2O.(440/44) x 22.4 = 224 litres.
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This question is part of the following fields:
- Basic Physics
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Question 80
Incorrect
-
Which of the following descriptions best describes enflurane and isoflurane?
Your Answer:
Correct Answer: Have the same molecular formula but different structural formulae
Explanation:Structural isomers have a similar molecular formula, but they have a different structural formula as their atoms are arranged in a different manner. Such small changes lead to the differential pharmacological activity. Enflurane and isoflurane are two prime examples of structural isomers.
Stereoisomers are those substances that have a similar molecular and structural formula, but the arrangement spatially of atoms are different and have optical activity.
Enantiomers are a pair of stereoisomers, which are non-superimposable mirror images of each other. They also have chiral centres of molecular symmetry. Ketamine is considered as an example of racemic mixture (contain 50% R and 50% S enantiomers)
Geometric isomers contain a carbon-carbon double bond (i.e. C=C) or a rigid carbon-carbon single bond in a heterocyclic ring. Cis-atracurium is one example.
Dynamic isomers or Tautomers are a pait of unstable structural isomers, which are present in equilibrium. One isomer can easily change after the change in pH. Midazolam and thiopentone are their examples.
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This question is part of the following fields:
- Pharmacology
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Question 81
Incorrect
-
All of the following are true when describing the autonomic nervous system except:
Your Answer:
Correct Answer: Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole parasympathetic control
Explanation:With regards to the autonomic nervous system (ANS)
1. It is not under voluntary control
2. It uses reflex pathways and different to the somatic nervous system.
3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.With regards to the central nervous system (CNS)
1. There are myelinated preganglionic fibres which lead to the
ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.Most organs are under control of both systems although one system normally predominates.
The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.
There are short pre-ganglionic and long post ganglionic fibres.
Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.
There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.
Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.
The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.
The cranial outflow consists of
1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreasThe sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.
The PNS has long preganglionic and short post ganglionic fibres.
Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.Different types of these muscarinic receptors are present in different organs:
There are:
M1 = pupillary constriction, gastric acid secretion stimulation
M2 = inhibition of cardiac stimulation
M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
M4 = brain and adrenal medulla
M5 = brainThe lacrimal glands are solely under parasympathetic control.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 82
Incorrect
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A 40-year old gentleman has palpitations and has gone to the emergency department. He is found to have monomorphic ventricular tachycardia. The resting potential of ventricular monocytes is maintained by which electrolyte?
Your Answer:
Correct Answer: Potassium
Explanation:Potassium maintains the resting potential of cardiac myocytes, with depolarization triggered by a rapid influx of sodium ions, and repolarization due to efflux of potassium. A slow influx of calcium is responsible for the longer duration of a cardiac action potential compared with skeletal muscle.
The cardiac action potential has several phases which have different mechanisms of action as seen below:
Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
These channels automatically deactivate after a few ms.Phase 1: caused by early repolarisation and an efflux of potassium.
Phase 2: Plateau – caused by a slow influx of calcium.
Phase 3 – Final repolarisation – caused by an efflux of potassium.
Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potentialOf note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.
Different sites have different conduction velocities:
1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec2. AV node conduction – 0.05 m/sec
3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 83
Incorrect
-
The liver plays a major role in drug metabolism.
Which of the following liver cells is most important in phase I of drug metabolism?Your Answer:
Correct Answer: Centrilobular cells
Explanation:The metabolism of drugs in the liver occurs in 3 phases
Phase I: This involves functionalization reactions, which are of 3 types, namely hydrolysis, oxidation and reduction reactions catalysed by the cytochrome P450 (CYP) enzymes.
Phase II: This involves conjugation or acetylation reactions. The goal is to create water soluble metabolites that can be excreted from the body.
The liver is the second largest organ. It’s smallest functional unit is the acinus which is divided into 3 zones:
Zone I (periportal): This zone receives the largest amount of oxygen supply as it is the closest to the blood vessels. It is the site of plasma protein synthesis.
Zone II (mediolobular): This is located between the portal triad and central vein.
Zone III (centrilobular): This is closest to the central vein and receives the least amount of oxygen supply.
Kupffer cells are specialized macrophages found in the periportal zone of the liver, and function to remove foreign particles and breakdown red blood cells via phagocytosis.
Ito cells are fat-storing liver cells found in the space of Disse. Their function is to take-uo, store and secrete retinoids, as well as manufacture and release proteins that make up the extracellular matrix.
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This question is part of the following fields:
- Pathophysiology
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Question 84
Incorrect
-
In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five minutes is indicated during in-hospital cardiac arrest due to ventricular fibrillation (VF) following three DC shocks.
Which of the following indicates the most important reason for using epinephrine?Your Answer:
Correct Answer: Preferential distribution of blood to the coronary and cerebral circulation
Explanation:Epinephrine is used for the treatment of cardiac arrest because it causes vasoconstriction via the alpha-adrenergic (?1) receptor. This vasoconstriction increases cerebral and coronary blood flow by increasing mean arterial, aortic diastolic, and cerebral pressures. Furthermore, epinephrine is also a?1 and ?2 adrenoreceptor agonist which shows inotrope, chronotrope, and bronchodilator effects.
– Adrenaline is also used to prolong the duration of action and decrease the systemic toxicity of local anaesthetics.
– Preferred route of adrenaline in patients with cardiac arrest is i.v. followed by intra-osseous and endotracheal -
This question is part of the following fields:
- Pathophysiology
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Question 85
Incorrect
-
Diagnosis of the neuroleptic malignant syndrome is best supported by which of the following statement?
Your Answer:
Correct Answer: Increased Creatine Kinase
Explanation:The neuroleptic malignant syndrome is a rare complication in response to neuroleptic or antipsychotic medication.
The main features are:
– Elevated creatinine kinase
– Hyperthermia and tachycardia
– Altered mental state
– Increased white cell count
– Insidious onset over 1-3 days
– Extrapyramidal dysfunction (muscle rigidity, tremor, dystonia)
– Autonomic dysfunction (Labile blood pressure, sweating, salivation, urinary incontinence)Management is supportive ICU care, anticholinergic drugs, increasing dopaminergic activity with Amantadine, L-dopa, and dantrolene, and non- depolarising neuromuscular blockade drugs
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This question is part of the following fields:
- Pharmacology
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Question 86
Incorrect
-
Regarding gas laws, which one best explains the ability of a Bourdon gauge to measure temperature?
Your Answer:
Correct Answer: Charles's law
Explanation:Charles’ Law states that there is a direct correlation between temperature and volume, where pressure and amount gas are constant. As temperature increases, volume also increases.
Boyle’s Law states that Pressure is inversely proportional to volume, assuming that temperature and amount of gas are constant. As volume increases, pressure decreases. In Dalton’s law of partial pressure, the total pressure exerted by a mixture of gases is equal to the sum of the partial pressure of the gases in mixture.
According to Henry’s Law for concentration of dissolved gases, at a constant temperature, the amount of a given gas that dissolves in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid. An equivalent way of stating the law is that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid.
Gay-Lussac’s Law states that the pressure of a given mass of gas varies directly with the absolute temperature of the gas, when the volume is kept constant. This law is very similar to Charles’ Law, with the only difference being the type of container. Whereas the container in a Charles’ Law experiment is flexible, it is rigid in a Gay-Lussac’s Law experiment.
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This question is part of the following fields:
- Basic Physics
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Question 87
Incorrect
-
A 59-year-old smoker booked for an emergency laparotomy is in the anaesthetic room prior to intubation. He is breathing room air and an arterial blood gas is obtained on insertion of an arterial cannula and sent for analysis.
The following results are available:
Haemoglobin 75 g/L
PaO2 10.7 kPa
PaCO2 5.2 kPa
After intravenous induction, intubation is difficult and he rapidly begins to de-saturate.
Which of the following is most effective in prolonging the oxygen de-saturation time?Your Answer:
Correct Answer: Pre-oxygenation with 100% O2 for three minutes
Explanation:Breathing 100% oxygen for three minutes will provide the best reservoir of oxygen during apnoea by oxygenating the functional residual capacity (FRC).
Sitting at 45 degrees might increase the FRC and improve oxygen reserve but not compared with 100% oxygenation.
The following table compares the oxygen reserves in the body following pre-oxygenation with room air and 100% oxygen:
Compartment Factors Room air (mL) 100% O2 (mL)
Lung FAO2, FRC 630 2850
Plasma PaO2, DF, PV 7 45
Red blood cells Hb, TGV, SaO2 788 805
Myoglobin – 200 200
Interstitial space – 25 160FAO2 = alveolar fraction of oxygen.
FRC = Functional residual capacity.
PaO2 = partial pressure of oxygen dissolved in arterial blood
DF = dissolved form.
PV = plasma volume.
TG = total globular volume .
Hb = haemoglobin concentration.
SaO2 = arterial oxygen saturationStopping smoking one month prior to surgery will not be more effective than pre-oxygenation with 100% oxygen though it may reduce postoperative pulmonary complications. Note that both long term and short term abstinence reduces pulse rate and blood pressure thus reducing oxygen consumption and also reduce carboxyhaemoglobin levels.
Blood transfusion will not make a big difference in oxygen reserve, particularly if a blood transfusion is administered within 12-24-hours before surgery.
Heliox (79% helium and 21% oxygen) despite its lower viscosity is unlikely to be more effective than 100% oxygen .
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This question is part of the following fields:
- Pathophysiology
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Question 88
Incorrect
-
A 40-year-old woman was diagnosed with hyperparathyroidism. She is undergoing a parathyroidectomy, and during the surgery, the inferior parathyroid gland is found to be enlarged. There is a vessel adjacent to this gland on its lateral side.
What is this vessel most likely to be?Your Answer:
Correct Answer: Common carotid artery
Explanation:There are four parathyroid glands that lie on the medial half of the posterior surface of each lobe of the thyroid gland, inside its sheath. There are two superior and two inferior parathyroid glands.
The common carotid artery is a lateral relation of the inferior parathyroid.
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This question is part of the following fields:
- Anatomy
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Question 89
Incorrect
-
One litre of water at 0°C and a pressure of 1 bar is in a water-bath. A 1 kW element is used in heating it.
Given that the specific heat capacity of water is 4181 J/(kg°C) or J/(kg K), how long will it take to raise the temperature of the water by 10°C?Your Answer:
Correct Answer: 42 seconds
Explanation: -
This question is part of the following fields:
- Physiology
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Question 90
Incorrect
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All the following statements are false regarding carbamazepine except
Your Answer:
Correct Answer: Has neurotoxic side effects
Explanation:Phenytoin, Carbamazepine, and Valproate act by inhibiting the sodium channels when these are open. These drugs also prolong the inactivated stage of these channels (Sodium channels are refractory to stimulation till these reach the closed/ resting phase from inactivated phase)
Carbamazepine is the drug of choice for partial seizures and trigeminal neuralgia
It can have neurotoxic side effects. Major neurotoxic effects include dizziness, headache, ataxia, vertigo, and diplopia
After single oral doses of carbamazepine, the absorption is fairly complete and the elimination half-life is about 35 hours (range 18 to 65 hours). During multiple dosing, the half-life is decreased to 10-20 hours, probably due to autoinduction of the oxidative metabolism of the drug.
It is metabolized in liver into active metabolite, carbamazepine-10,11-epoxide.
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This question is part of the following fields:
- Pharmacology
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Question 91
Incorrect
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You are preparing to anaesthetize a 27-year-old woman for an acute diagnostic laparoscopy to rule out appendicitis.
She has no medical history and does not take any medications on a regular basis. You're going to do a quick sequence induction.
Which method of preoxygenation is the most effective and efficient?Your Answer:
Correct Answer: Mapleson A circuit with a fresh gas flow of 100 ml/kg
Explanation:Professor Mapleson classified non-rebreathing circuits based on the position of the APL valve, which controls fresh gas flow.
The Mapleson A (Magill) circuit is most effective in spontaneous breathing, requiring only 70-100 ml/kg (the patient’s minute volume) of fresh gas flow. The patient inhales fresh gas from the reservoir bag and tubing during inspiration. During expiration, the patient adds dead space gas (gas that hasn’t been exchanged) to the tubing and reservoir bag in addition to the fresh gas flow. At the patient’s end, alveolar gas is vented through the APL valve. During the expiratory pause, the fresh gas flow causes more gas to be released.
The Mapleson A is inefficient during controlled ventilation. Venting occurs during inspiration rather than during the expiratory phase, as it does during spontaneous ventilation. As a result, unless a high fresh gas flow of >20 L/minute is used, alveolar gas is rebreathed.
During spontaneous ventilation, the Mapleson D circuit is inefficient.
The oxygen concentration in a Hudson mask is insufficient to allow for adequate pre-oxygenation.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 92
Incorrect
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What vessel is NOT considered a major branch of the descending thoracic aorta?
Your Answer:
Correct Answer: Inferior thyroid artery
Explanation:The descending thoracic aorta begins at the lower border of T4 near the midline as a continuation of the arch of the aorta. It descends and ends at the level of T12 at the aortic hiatus in the diaphragm, where it becomes the abdominal aorta.
The aorta gives off the following branches: (descending order)
1. Bronchial arteries
2. Mediastinal arteries
3. Oesophageal arteries
4. Pericardial arteries
5. Superior phrenic arteriesThe posterior intercostal arteries are branches that originate throughout the length of the posterior aspect of the descending thoracic aorta.
The inferior thyroid artery is usually derived from the thyrocervical trunk, a branch of the subclavian artery.
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This question is part of the following fields:
- Anatomy
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Question 93
Incorrect
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A 25-year old lady is in the operating room and has had general anaesthesia for a knee arthroscopy.
Induction was done with fentanyl 1mcg/kg and propofol 2mg/kg. A supra-glottic airway was inserted and using and air oxygen mixture with 2.5% sevoflurane, her anaesthesia was maintained. The patient is allowed to spontaneously breathe using a Bain circuit, and the fresh gas flow is 9L/min. Over the next 30 minutes, the end-tidal Co2 rises from 4.5kPa to 8.4kPa, and the baseline reading on the capnograph is 0kPa.
The most appropriate initial action is which of the following?Your Answer:
Correct Answer: Hypoventilation
Explanation:The commonest and most likely cause of a gradual rise in end-tidal CO2 (EtCO2) occurring during anaesthesia in a spontaneously breathing patient is hypoventilation. This occurs from the respiratory depressant effects of the opioid and sevoflurane.
Malignant hyperthermia should be sought if the EtCO2 shows further progressive rise.
Causes of rebreathing and a rise in the baseline of the capnograph can be caused by exhausted soda lime and inadequate fresh gas flow into the Bain circuit.
A sudden rise in EtCO2 can be caused deflation of the tourniquet.
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This question is part of the following fields:
- Physiology
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Question 94
Incorrect
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Which of the following statements is true about fluid balance?
Your Answer:
Correct Answer: After intravenous administration of crystalloids, the distribution of these fluids throughout the body depends on its osmotic activity
Explanation:When there is capillary leakage as seen in dependent oedema or ascites, oncotic pressure becomes a problem.
The intracellular sodium concentration is very sensitive to the extracellular sodium concentrations. When there is an imbalance, osmosis occurs resulting in shifts in water between the two compartments.
The microvascular endothelium relies upon osmosis and other processes as it is not freely permeable to water.
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This question is part of the following fields:
- Physiology
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Question 95
Incorrect
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A morbidly obese (BMI=48) patient has the following co-morbidities: type II diabetes mellitus and hypertension. It is recommended for the patient to undergo bariatric surgery.
If the patient is laid flat for induction of anaesthesia, what physiologic changes of the respiratory system is the most important to consider?Your Answer:
Correct Answer: Functional residual capacity will decrease
Explanation:A decrease in the functional residual capacity (FRC) is the most important physiologic change to consider for such patients.
FRC is the sum of the expiratory reserve volume and the residual volume. It is the resting volume of the lung, and is an important marker for lung function. During this time, the alveolar pressure is equal to the atmospheric pressure. When morbidly obese individuals lie supine, the FRC decreases by as much as 40% because the abdominal contents push the diaphragm into the thoracic cavity.
Chest wall compliance is expected to reduce because of fat deposition surrounding adjacent structures.
Inspiratory reserve volume (IRV) is expected to increase, and peak expiratory flow is expected to decrease, however the decrease in FRC is more important to consider because of the risk of hypoxia secondary to premature airway closure and ventilation-perfusion mismatch.
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This question is part of the following fields:
- Physiology
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Question 96
Incorrect
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A patient with a known history of asymptomatic ventriculoseptal defect (VSD) is to undergo an orthopaedic surgery under general anaesthesia. The rest of the patient's medical history, such as allergies and previous operations, are unremarkable.
What is the best antibiotic prophylaxis prior to surgery?Your Answer:
Correct Answer: No antibiotic prophylaxis required as the defect is repaired and no evidence of benefit from routine prophylaxis
Explanation:According to the 2015 National Institute for Health and Care Excellence (NICE) Guidelines, antibiotic prophylaxis against infective endocarditis (IE) is not recommended routinely for people with any cardiac defect (corrected or uncorrected) due to lack of sufficient evidence regarding its benefits. Instead, antibiotic prophylaxis is recommended for those who are at risk of developing IE, such as those with acquired valvular heart disease with stenosis or regurgitation; hypertrophic cardiomyopathy; valve replacement; and previous IE.
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This question is part of the following fields:
- Pharmacology
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Question 97
Incorrect
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A 50-year-old man is admitted in hospital. Over four hours, he produces 240 mL of urine and has a plasma creatinine concentration is 10 mcg/mL. The normal concentration of creatinine in urine is 1.25 mg/mL.
Calculate his approximate creatinine clearance.Your Answer:
Correct Answer: 125 ml/minute
Explanation:Creatinine clearance is a test used to approximate the glomerular filtration rate (GFR) as an assessment of kidney function.
Creatinine is formed during the breakdown of dietary sources of meat and skeletal muscle. It is secreted at a consistent concentration and pace into the body’s circulation, and is easily filtered across the glomerulus without being reabsorbed or metabolized by the kidney.
It is represented mathematically as:
Creatinine clearance (CL) = U x V/P
where,
U: Urinary creatinine concentration (mg/mL)
V: Volume of urine (mL/min)
P: Plasma creatinine concentration (mg/mL)Therefore, in this case:
CL: 1.25 x 1 = 125mL/min
0.1 -
This question is part of the following fields:
- Clinical Measurement
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Question 98
Incorrect
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The most abundant intracellular ion is?
Your Answer:
Correct Answer: Phosphate
Explanation:Phosphate is the principal anion of the intracellular fluid, most of which is bound to either lipids or proteins. They dissociate or associate with different compounds, depending on the enzymatic reaction, thus forming a constantly shifting pool.
Calcium and magnesium are also present intracellularly, however in lesser amounts than phosphate.
Sodium is the most abundant extracellular cation, and Chloride and is the most abundant extracellular anion.
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This question is part of the following fields:
- Physiology
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Question 99
Incorrect
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Which of the following statements is true regarding oxygen?
Your Answer:
Correct Answer: Forms molecules containing either two or three atoms
Explanation:Oxygen is formed by a molecule of oxygen and two molecules of hydrogen with a molecular formula of H2O
The critical temperature is defined as a temperature above which the substance cannot be liquefied, no matter how much pressure is applied.
Water has a critical temperature of -118.6oC. So, it cannot be liquified at room temperature.Medical oxygen cylinder is stored in a cylinder with a white shoulder and black body. Meanwhile, medial air is stored in cylinders with a white and black shoulder and a French grey body.
The partial pressure of air at a high altitude is less but the relative concentration remains constant.
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This question is part of the following fields:
- Basic Physics
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Question 100
Incorrect
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Drug X, a new intravenous induction drug, is being administered as a bolus at regular time intervals, and the following data were observed:
Time following injection (hours) vs Plasma concentration of drug X (mcg/mL)
2 / 400
6 / 100
10 / 25
14 / 6.25
Which of the following values estimate the plasma half-life (T½) of drug X?
Your Answer:
Correct Answer: 2 hours
Explanation:Half life (T½) is the time required to change the amount of drug in the body by one-half (or 50%) during elimination. The time course of a drug in the body will depend on both the volume of distribution and the clearance.
Extrapolating the values from the plasma concentration vs time:
Plasma concentration at 0 hours = 800 mcg/mL
Plasma concentration at 2 hours = 400 mcg/mL
Plasma concentration at 4 hours = 200 mcg/mL
Plasma concentration at 6 hours = 100 mcg/mL
Plasma concentration at 8 hours = 50 mcg/mL
Plasma concentration at 10 hours = 25 mcg/mL
Plasma concentration at 12 hours = 12.5 mcg/mL
Plasma concentration at 14 hours = 6.25 mcg/mL -
This question is part of the following fields:
- Statistical Methods
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Question 101
Incorrect
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The main site of storage of thyroid hormones in the thyroid gland is?
Your Answer:
Correct Answer: Thyroglobulin
Explanation:The follicle is the functional unit of the thyroid gland. The follicular cells surround the follicle which is filled with colloid. Suspended within the colloid is the is a pro-hormone complex thyroglobulin.
The synthesis and storage of thyroid hormones is done by follicular cells and the thyroglobulin within the colloid.
Iodide ions (I−) are actively transported against a concentration gradient into the follicular cell under the influence of thyroid stimulating hormone (TSH). It then undergoes oxidation to active iodine catalysed by thyroid peroxidase (TPO). The synthesis of thyroglobulin is in the follicular cells and it contains up to 140 tyrosine residues. The tyrosine residues of thyroglobulin and active iodine are merged to form mono- and di-iodotyrosines (MIT and DIT). The iodinated thyroglobulin is then taken up into the colloid where it is stored and dimerised. Two DIT molecules are joined to produce thyroxine (T4) while one MIT and one DIT molecule are joined to produce tri-iodotyrosine (T3) by a process catalysed by TPO.
Thyroglobulin droplets are taken up as vesicles into follicular cells by pinocytosis. This process is stimulated by TSH. When these vesicles fuse with lysosomes, hydrolysis of the thyroglobulin molecules and subsequent release of T4 and T3 into the circulation occurs.
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This question is part of the following fields:
- Pathophysiology
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Question 102
Incorrect
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The production of carbon dioxide and water occurs during cellular respiration, which involves an energy substrate and oxygen. For a patient, the respiratory quotient is calculated as 0.7.
Which of the following energy substrate combinations is the most likely in this patient's diet?Your Answer:
Correct Answer: Low carbohydrate, high fat and low protein
Explanation:The respiratory quotient (RQ) is the proportion of CO2 produced by the body to O2 consumed per unit of time.
CO2 produced / O2 consumed = RQ
CO2 is produced at a rate of 200 mL per minute, while O2 is consumed at a rate of 250 mL per minute. An RQ of around 0.8 is typical for a mixed diet.
The RQ will change depending on the energy substrates consumed in the diet.
Granulated sugar is a refined carbohydrate that contains 99.999 percent carbohydrate and no lipids, proteins, minerals, or vitamins.
Glucose and other hexose sugars – RQ = 1
Fats – RQ = 0.7
Proteins – RQ is 0.9
Ethyl alcohol – RQ = 0.67 -
This question is part of the following fields:
- Pathophysiology
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Question 103
Incorrect
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A transport ventilator connected to a size CD oxygen cylinder has a setting of air/oxygen entrainment ratio of 1:1 and a minute volume set at 10 litres/minute.
Which value best approximates to the FiO2?Your Answer:
Correct Answer: 0.6
Explanation:A nominal volume of 2 litres is contained in a CD cylinder. It has a pressure of 230 bar when full and contains litres 460 L of useable oxygen at STP.
For every 1000 mL 100% oxygen there will be an entrainment of 1000 mL or air (20% oxygen) in an air/oxygen mix.
The average concentration is, therefore, 120/2=60% or 0.6.
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This question is part of the following fields:
- Physiology
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Question 104
Incorrect
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A 42-year-old man presented with a bitemporal hemianopia with enlarged hands and feet. On examination, he was found to be hypertensive.
Which of the following correctly explains the cause of his visual field defect?Your Answer:
Correct Answer: Pituitary macroadenoma secreting growth hormone (GH)
Explanation:Pituitary macroadenoma is a benign tumour with growth larger than 10mm (those under 10mm are called microadenoma)
Compression of optic chiasm by pituitary adenoma is responsible for causing visual field defects like bitemporal hemianopia, optic neuropathy.
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This question is part of the following fields:
- Pathophysiology
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Question 105
Incorrect
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Of the following, which of these oxygen carrying molecules causes the greatest shift of the oxygen-dissociation curve to the left?
Your Answer:
Correct Answer: Myoglobin (Mb)
Explanation:Myoglobin is a haemoglobin-like, iron-containing pigment that is found in muscle fibres. It has a high affinity for oxygen and it consists of a single alpha polypeptide chain. It binds only one oxygen molecule, unlike haemoglobin, which binds 4 oxygen molecules.
The myoglobin ODC is a rectangular hyperbola. There is a very low P50 0.37 kPa (2.75 mmHg). This means that it needs a lower P50 to facilitate oxygen offloading from haemoglobin. It is low enough to be able to offload oxygen onto myoglobin where it is stored. Myoglobin releases its oxygen at the very low PO2 values found inside the mitochondria.
P50 is defined as the affinity of haemoglobin for oxygen: It is the PO2 at which the haemoglobin becomes 50% saturated with oxygen. Normally, the P50 of adult haemoglobin is 3.47 kPa(26 mmHg).
Foetal haemoglobin has 2 ? and 2 ?chains. The ODC is left shifted – this means that P50 lies between 2.34-2.67 kPa [18-20 mmHg]) compared with the adult curve and it has a higher affinity for oxygen. Foetal haemoglobin has no ? chains so this means that there is less binding of 2.3 diphosphoglycerate (2,3 DPG).
Carbon monoxide binds to haemoglobin with an affinity more than 200-fold higher than that of oxygen. This therefore decreases the amount of haemoglobin that is available for oxygen transport. Carbon monoxide binding also increases the affinity of haemoglobin for oxygen, which shifts the oxygen-haemoglobin dissociation curve to the left and thus impedes oxygen unloading in the tissues.
In sickle cell disease, (HbSS) has a P50 of 4.53 kPa(34 mmHg).
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This question is part of the following fields:
- Physiology
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Question 106
Incorrect
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Which of the following herbal drug side effects or herb-drug interactions is the most likely?
Your Answer:
Correct Answer: St. John's Wort : serotonin syndrome
Explanation:Patients who present for surgery may be on prescription medication or natural/herbal therapies. These have relevance for anaesthesia since they can cause drug interactions.
Ephedra (Ma Huang) is a drug derived from the plant Ephedra sinica that is used as a CNS stimulant, weight reduction aid, and asthma therapy. It is a combination of alkaloids that includes ephedrine which stimulates noradrenaline release from pre-synaptic neurones by acting directly on alpha and beta adrenoreceptors. The use of sympathomimetic drugs together can cause cardiovascular instability.
Ginkgo Biloba contains anti-oxidant characteristics and is used to treat Alzheimer’s disease, vascular dementia, and peripheral vascular disease. It lowers platelet adhesiveness and raises the risk of bleeding by decreasing platelet activating factor (PAF), especially in individuals who are also taking anticoagulants and antiplatelet drugs.
The extract from St. John’s Wort is utilised as an antidepressant because it is a cytochrome P450 isoenzyme inhibitor as well as a serotonin uptake inhibitor. When drugs like fentanyl or tramadol are used during an anaesthetic, there is a risk of serotonin syndrome developing.
The root of a pepper is used to make kava (Piper methysticum). It is a weak GABAA agonist which has the potential to augment the effects of propofol and benzodiazepines, which are volatile anaesthetics.
Garlic is made from the allium sativum plant and is used to treat hypertension and hyperlipidaemia. It includes cysteine, which inhibits platelet aggregation irreversibly, amplifying the effects of aspirin and NSAIDs.
Echinacea is a common herbal medicine that stimulates the immune system by modulating cytokine signalling. In individuals who require organ transplantation, it should be avoided.
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This question is part of the following fields:
- Pharmacology
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Question 107
Incorrect
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The statement that best describes lactic acidosis is:
Your Answer:
Correct Answer: It can be precipitated by intravenous fructose
Explanation:An elevated arterial blood lactate level and an increase anion gap ([Na + K] – [Cl + HCO3]) of >20mmol gives rise to lactic acidosis. It can also be a result of overproduction and/or reduced metabolism of lactic acid.
The liver and kidney are the main sites of lactate metabolism, not skeletal muscle.
The two types of lactic acidosis that are known are:
Type A – due to tissue hypoxia, inadequate tissue perfusion and anaerobic glycolysis. These may be seen in cardiac arrest, shock, hypoxaemia and anaemia. The management of type A lactic acidosis involves reversing the underlying cause of the tissue hypoxia.
Type B – occurs in the absence of tissue hypoxia. Some of the causes of this include hepatic failure, renal failure, diabetes mellitus, pancreatitis and infection. Some drugs can also cause this lie aspirin, ethanol, methanol, biguanides and intravenous fructose.
The mainstay of treatment involves:
1. Optimising tissue oxygen delivery
2. Correcting the cause
3. Intravenous sodium bicarbonateIn resistant cases, peritoneal dialysis can be performed.
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This question is part of the following fields:
- Physiology
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Question 108
Incorrect
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Which of the following statements is true with regards to acetylcholine?
Your Answer:
Correct Answer: Excess cholinesterase inhibitor medication causes cholinergic crisis
Explanation:Myasthenic and cholinergic crises are two crises which are similar in their clinical presentation.
Myasthenic crisis can be caused by:
-lack of acetylcholine,
-poor compliance with medication,
-infectionCholinergic crisis can be caused by excess cholinesterase inhibitor medication (mimicking organophosphate poisoning) causing excess acetylcholine.
Differentiation between the 2 crises is made by giving incremental doses of the short acting cholinesterase inhibitor, Edrophonium.
This increase acetylcholine levels and will make a myasthenic crisis better and a cholinergic crisis worse. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 109
Incorrect
-
Among the following, which statement is true regarding electrical safety in an operation theatre?
Your Answer:
Correct Answer: The higher the frequency of the current the less risk to the patient
Explanation:The operating theatre is an unusual place with several applications of electrical equipment to the human body. This can lead to potential dangers associated with it that need to be prevented. Electrical safety in the operation theatre is the understanding of how these potential dangers can occur and how they can be prevented.
Electricity can cause morbidity or mortality by one of the following ways:
(i) electrocution
(ii) burns
(iii) ignition of a flammable material, causing a fire or explosion.Electrocution is dependant on factors like duration of contact with electric current, the current pathway and the frequency and size of current.
Option A: The higher the frequency, the less effects of electrocution on the body.
Option B & D: Equipment can be classified in classes and types.
The class designation describes the method used for protection against electrocution. Class I is basic protection, class II is double insulation and class III is safety extra low voltage.
The type designation describes the degree of protection based on the maximum permissible leakage currents under normal and fault conditions.
Type B:
can be class I, II or III but the maximum leakage current must not exceed 100 µA. It is therefore not suitable for direct connection to the heart.
Type BF
Similar to type B, but uses an isolated (or floating) circuit.
Type CF
Only type CF protect against microshock as they allow leakage currents of 0.05 mA per electrode for class I and 0.01 mA for class II. Microshock is a small leakage current that can cause harm because of direct connection to the heart via transvenous lines or wires, bypassing the impedance of the skin, leading to ventricular fibrillation. Microshock current of 100 ?A is sufficient to cause VF.Option C: A 75mA electrocution can cause ventricular fibrillation. Use the following as a general guide to understand the effect of current size on the body.
1 mA – tingling pain
5 mA – pain
15 mA – tonic muscular contraction
50 mA – respiratory muscle paralysis
75 mA – ventricular fibrillation.Option E: Wet skin reduces the resistance to current flow and therefore increases the effects of electrocution.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 110
Incorrect
-
Seven days after undergoing an inguinal hernia repair, a 24-year old male presents with a wound that is erythematous, tender and has a purulent discharge. The most likely cause of this is which of the following?
Your Answer:
Correct Answer: Infection with Staphylococcus aureus
Explanation:Staphylococcus aureus infection is the most likely cause.
Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.
SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
The organisms are usually derived from the patient’s own body.Measures that may increase the risk of SSI include:
-Shaving the wound using a single use electrical razor with a disposable head
-Using a non iodine impregnated surgical drape if one is needed
-Tissue hypoxia
-Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.Measures that may decrease the risk of SSI include:
1. Intraoperatively
– Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
-Cover surgical site with dressingIn contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.
2. Post operatively
Tissue viability advice for management of surgical wounds healing by secondary intentionUse of diathermy for skin incisions
In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 111
Incorrect
-
The following is true about the extracellular fluid (ECF) in a normal adult woman weighing 60 kg.
Your Answer:
Correct Answer: Has a total volume of about 12 litres
Explanation:Total body water (TBW) is about 50% to 70% in adults depending on how much fat is present. ECF is relatively contracted in an obese person.
The simple rule is 60-40-20. (60% of weight = total body water, 40% of body weight is ICF and 20% is ECF)
For this woman, the total body water is 36 litres (0.6 × 60). ECF is 12 litres (1/3 of TBW) and 24 litres (2/3 of TBW) is intracellular fluid .
Sodium concentration is approximately 135-145 mmol/L in the ECF.
The ECF is made up of both intravascular and extravascular fluid and plasma proteins is found in both.
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This question is part of the following fields:
- Physiology
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Question 112
Incorrect
-
A 66-year-old man with a haemorrhagic stroke is admitted to the medical admissions unit.
He has been taking warfarin for a long time because of atrial fibrillation. His INR at the time of admission was 9.1.
Which of the following treatment options is the most effective in managing his condition?Your Answer:
Correct Answer: Prothrombin complex concentrate
Explanation:Haemorrhage, including intracranial bleeding, is a common and potentially fatal side effect of warfarin therapy, and reversing anticoagulation quickly and completely can save lives. When complete and immediate correction of the coagulation defect is required in orally anticoagulated patients with life-threatening haemorrhage, clotting factor concentrates are the only viable option.
For rapid reversal of vitamin K anticoagulants, prothrombin complex concentrates (PCC) are recommended. They contain the vitamin K-dependent clotting factors II, VII, IX, and X and are derived from human plasma. They can be used as an adjunctive therapy in patients with major bleeding because they normalise vitamin K dependent clotting factors and restore haemostasis.
The most common treatments are fresh frozen plasma (FFP) and vitamin K. The efficacy of this approach is questioned due to the variable content of vitamin K-dependent clotting factors in FFP and the effects of dilution. Significant intravascular volume challenge, as well as the possibility of rare complications like transfusion-associated lung injury or blood-borne infection, are all potential issues.
To avoid anaphylactic reactions, vitamin K should be given as a slow intravenous infusion over 30 minutes. Regardless of the route of administration, the reversal of INRs with vitamin K can take up to 24 hours to reach its maximum effect.
Reversal of anticoagulation in patients with warfarin-associated intracranial haemorrhage may be considered with factor VIIa (recombinant), but its use is controversial. There are concerns about thromboembolic events following treatment, as well as questions about assessing efficacy in changes in the INR. If the drug is to be administered, patients should be screened for an increased risk of thrombosis before the drug is given.
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This question is part of the following fields:
- Pathophysiology
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Question 113
Incorrect
-
Regarding oxygen consumption, which of these organs has the highest consumption at rest?
Your Answer:
Correct Answer: Kidney
Explanation:Oxygen delivery is related to blood flow as most of the oxygen binds to haemoglobin in red blood cells, although a small amount is dissolved in the plasma. Blood flow per 100 g of tissue is greatest in the kidneys.
The following is the oxygen consumption rate of different organs in ml/minute/100g
Hepatoportal = 2.2
Kidney = 6.8
Brain = 3.7
Skin = 0.38
Skeletal muscle = 0.18
Heart = 11 -
This question is part of the following fields:
- Pathophysiology
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Question 114
Incorrect
-
A 45-year-old man is being operated on for emergency laparotomy as he presented with bowel perforation. During the surgery, the marginal artery of Drummond is encountered and preserved.
Which of the following two arteries fuse to form the marginal artery of Drummond?Your Answer:
Correct Answer: Superior mesenteric artery and inferior mesenteric artery
Explanation:The arteries of the midgut (superior mesenteric artery) and hindgut (inferior mesenteric artery) give off terminal branches that form an anastomotic vessel called the marginal artery of Drummond. It runs in the inner margins of the colon and gives off short terminal branches to the bowel wall.
The marginal artery is formed by the main branches and arcades arising from the ileocolic, right colic, middle colic, and left colic arteries. It is most apparent in the ascending, transverse, and descending colons and poorly developed in the sigmoid colon.
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This question is part of the following fields:
- Anatomy
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Question 115
Incorrect
-
A 70-year-old man collapsed at home. He was brought into the emergency department in an ambulance. His wife tells you that he complained of sudden lower back pain just before he collapsed.
He is pale and hypotensive. You suspect a ruptured abdominal aortic aneurysm.
What vertebral level does this affected vessel terminate?Your Answer:
Correct Answer: L4
Explanation:The abdominal aorta begins at the level of the body of T12 near the midline, as a continuation of the thoracic aorta. It descends and bifurcates at the level of L4 into the common iliac arteries.
An abdominal aortic aneurysm is a swelling in the abdominal aorta. It most commonly occurs in men over 65 years old of age. Smoking, diabetes, hypertension, and hypercholesterolemia are other risk factors contributing to the disease.
The NHS screening program for abdominal aortic aneurysms involves an ultrasound test for men aged 65 or over if they have not undergone screening for a one-off screening test.
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This question is part of the following fields:
- Anatomy
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Question 116
Incorrect
-
Which of the following statement is true regarding the mechanism of action of rifampicin?
Your Answer:
Correct Answer: Inhibit RNA synthesis
Explanation:Rifampicin is a derivative of a rifamycin (other derivatives are rifabutin and rifapentine). It is bactericidal against both dividing and non-dividing mycobacterium and acts by inhibiting DNA-dependent RNA polymerase. Thus this drug inhibits RNA synthesis.
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This question is part of the following fields:
- Pharmacology
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Question 117
Incorrect
-
Which oral hypoglycaemic agent has no effect on insulin sensitivity or secretion?
Your Answer:
Correct Answer: Alpha glucosidase inhibitors
Explanation:Because alpha glucosidase inhibitors slow starch digestion in the small intestine, glucose from a meal enters the bloodstream more slowly and can be matched more effectively by an impaired insulin response or sensitivity, glucose from a meal enters the bloodstream more slowly and can be matched more effectively by an impaired insulin response or sensitivity.
Biguanides decrease hepatic glucose output while increasing glucose uptake in peripheral cells.
The meglitinides are secretagogues that act on a different site of the KATP receptors.
Insulin secretion is stimulated by sulphonylureas, which stimulate insulin secretion from pancreatic beta cells. The KATP channels are inhibited by these substances.
Insulin-sensitive genes are influenced by thiazolidinediones, which increase the production of mRNAs for insulin-dependent enzymes. As a result, the cells make better use of glucose.
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This question is part of the following fields:
- Pharmacology
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Question 118
Incorrect
-
Given the following values:
Expired tidal volume = 800 ml
Plateau pressure = 50 cmH2O
PEEP = 10 cmH2O
Compute for the static pulmonary compliance.Your Answer:
Correct Answer: 20 ml/cmH2O
Explanation:Compliance of the respiratory system describes the expandability of the lungs and chest wall. There are two types of compliance: dynamic and static.
Dynamic compliance describes the compliance measured during breathing, which involves a combination of lung compliance and airway resistance. Defined as the change in lung volume per unit change in pressure in the presence of flow.
Static compliance describes pulmonary compliance when there is no airflow, like an inspiratory pause. Defined as the change in lung volume per unit change in pressure in the absence of flow.
For example, if a person was to fill the lung with pressure and then not move it, the pressure would eventually decrease; this is the static compliance measurement. Dynamic compliance is measured by dividing the tidal volume, the average volume of air in one breath cycle, by the difference between the pressure of the lungs at full inspiration and full expiration. Static compliance is always a higher value than dynamic
Static compliance can be computed using the formula:
Cstat = Tidal volume/Plateau pressure – PEEP
Substituting the values given,
Cstat = 800/50-10
Cstat = 20 ml/cmH2O -
This question is part of the following fields:
- Physiology
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Question 119
Incorrect
-
A 56-year old man, presents to emergency department following a cardiac arrest. On history and examination, he is found to be suffering from both metabolic and respiratory acidosis as a result of his cardiac arrest.
What is the best way to reduce the risk of acidaemia during cardiac arrestYour Answer:
Correct Answer: Chest compressions
Explanation:Chest compressions are an essential part of cardiopulmonary resuscitation (CPR) which helps restore spontaneous circulation (ROSC).
Sodium bicarbonate is only prescribed in patients with cardiac arrests as a result of an overdose of tricyclic antidepressants or hyperkalaemia. Its use causes the body to produce more CO2 which causes:
Exacerbation of intracellular acidosis
Negative inotropy to ischaemic myocardium
Increased osmotic load of sodium into failing brain and body
Shift of oxygen dissociation curve to the left.THAM is often used to treat metabolic acidosis as a result of cardiac bypass surgery and also cardiac arrest, when other standard methods have failed.
Carbicarb (Na2CO3 0.33 molar NaHCO3 0.33 molar) has only mild effects on acidosis. It also causes an increase in arterial CO2 pressure and lactate concentration.
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This question is part of the following fields:
- Pathophysiology
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Question 120
Incorrect
-
Rocuronium is substituted for succinylcholine during induction of anaesthesia for a caesarean section delivery.
Which of the following feature of rocuronium ensures the neonate shows no clinical signs of muscle relaxation?Your Answer:
Correct Answer: Highly ionised
Explanation:Drugs cross the placenta by Simple, Ion channel and Facilitated diffusion; Exocytosis and Endocytosis, Osmosis, and Active transport (primary and secondary)
The following factors influence rate of diffusion across the placenta:
Protein binding
Degree of ionisation
Placental blood flow
Maternal and foetal blood pH
Materno-foetal concentration gradient.
Thickness of placental membrane
Molecular weight of drug <600 Daltons cross by diffusion
Lipid solubility (lipid soluble molecules readily diffuse across the placenta)Rocuronium has a F/M ratios of 0.16, a 30% plasma protein binding, low lipid solubility, a low volume of distribution (0.25L/kg), and a high molecular weight (530Da).
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This question is part of the following fields:
- Pharmacology
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Question 121
Incorrect
-
Which of the following statement is not true regarding Adrenaline or Epinephrine?
Your Answer:
Correct Answer: Inhibits Glucagon secretion in the pancreas
Explanation:Adrenaline acts on ?1, ?2,?1, and ?2 receptors and also on dopamine receptors (D1, D2) and have sympathomimetic effects.
Natural catecholamines are Adrenaline, Noradrenaline, and Dopamine
Adrenaline is a sympathomimetic amine with both alpha and beta-adrenergic stimulating properties.
Adrenaline is the drug of choice for anaphylactic shock
Adrenaline is also used in patients with cardiac arrest. The preferred route is i.v. followed by the intra-osseous and endotracheal route.Adrenaline is released by the adrenal glands, acts on ? 1 and 2, ? 1 and 2 receptors, and is responsible for fight or flight response.
It acts on ? 2 receptors in skeletal muscle vessels-causing vasodilation.
It acts on ? adrenergic receptors to inhibit insulin secretion by the pancreas. It also stimulates glycogenolysis in the liver and muscle, stimulates glycolysis in muscle.
It acts on ? adrenergic receptors to stimulate glucagon secretion in the pancreas. It also stimulates Adrenocorticotrophic Hormone (ACTH) and stimulates lipolysis by adipose tissue
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This question is part of the following fields:
- Pharmacology
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Question 122
Incorrect
-
Following a traumatic head injury, you are summoned to the emergency department to transfer a patient to the CT scanner. With a Glasgow coma score of 3, he has already been intubated and ventilated.
It is important to ensure that cerebral protection strategies are implemented during the transfer.
Which of the following methods is the most effective for reducing venous obstruction?Your Answer:
Correct Answer: Position with a head-up tilt of 30°
Explanation:ICP is significant because it influences cerebral perfusion pressure and cerebral blood flow. The normal ICP ranges from 5 to 13 mmHg.
The components within the skull include the brain (80%/1400 ml), blood (10%/150 ml), and cerebrospinal fluid (CSF) (10%/150 ml).
Because the skull is a rigid box, if one of the three components increases in volume, one or more of the remaining components must decrease in volume to compensate, or the ICP will rise (Monroe-Kellie hypothesis).
Primary brain injury occurs as a result of a head injury and is unavoidable unless precautions are taken to reduce the risk of head injury. A reduction in oxygen delivery due to hypoxemia (low arterial PaO2) or anaemia, a reduction in cerebral blood flow due to hypotension or reduced cardiac output, and factors that cause a raised ICP and reduced CPP are all causes of secondary brain injury. Secondary brain injury can be avoided with proper management.
The most important initial management task is to make certain that:
There is protection of the airway and the cervical spine
There is proper ventilation and oxygenation
Blood pressure and cerebral perfusion pressure are both adequate (CPP).Following the implementation of these management principles, additional strategies to reduce ICP and preserve cerebral perfusion are required. The volume of one or more of the contents of the skull can be reduced using techniques that can be used to reduce ICP.
Reduce the volume of brain tissue
Blood volume should be reduced.
CSF volume should be reduced.The following are some methods for reducing the volume of brain tissue:
Abscess removal or tumour resection
Steroids (especially dexamethasone) are used to treat oedema in the brain.
To reduce intracellular volume, use mannitol/furosemide or hypertonic saline.
To increase intracranial volume, a decompressive craniectomy is performed.The following are some methods for reducing blood volume:
Haematomas must be evacuated.
Barbiturate coma reduces cerebral metabolic rate and oxygen consumption, lowering cerebral blood volume as a result.
Hypoxemia, hypercarbia, hyperthermia, vasodilator drugs, and hypotension should all be avoided in the arterial system.
PEEP/airway obstruction/CVP lines in neck: patient positioning with 30° head up, avoid neck compression with ties/excessive rotation, avoid PEEP/airway obstruction/CVP lines in neckThe following are some methods for reducing CSF volume:
To reduce CSF volume, an external ventricular drain or a ventriculoperitoneal shunt is inserted (although more a long term measure).
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This question is part of the following fields:
- Pathophysiology
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Question 123
Incorrect
-
Concerning forced alkaline diuresis, which of the following statements is true?
Your Answer:
Correct Answer: Can be used in a barbiturate overdose
Explanation:In situations of poisoning or drug overdose with acid dugs like salicylates and barbiturates, forced alkaline diuresis may be used.
With regards to overdose with alkaline drugs, forced acid diuresis is used.
By changing the pH of the urine, the ionised portion of the drug stays in the urine, and this prevents its diffusion back into the blood. Charged molecules do not readily cross biological membranes.
The process involves the infusion of specific fluids at a rate of about 500ml per hour. This requires monitoring of the central venous pressure, urine output, plasma electrolytes, especially potassium, and blood gas analysis.
The fluid regimen recommended is:
500ml of 1.26% sodium bicarbonate (not 200ml of 8.4%)
500ml of 5% dextrose and
500ml of 0.9% sodium chloride. -
This question is part of the following fields:
- Physiology
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Question 124
Incorrect
-
A 50-year-old man has complained of persistent hoarseness and dry cough. He has a history of smoking 20 cigarettes per day. The examination reveals no significant clinical signs of cranial nerve damage.
Referred to an ENT specialist, the patient is explained how coughing is usually a defence mechanism of the body which is activated more than usual by the chemical irritants in cigarette smoke. However, the ENT doctor suspects a nerve involvement in the cough reflex as the patient also presents with hoarseness with the dry cough.
Which nerves is the ENT doctor suspecting to have been affected in this patient?Your Answer:
Correct Answer: CN IX and X
Explanation:Cough is an important defensive reflex that helps clear secretions and particulates from the airways. A complex reflex arc generates each cough.
The cough reflex begins with irritation of the cough receptors present in the epithelium of the trachea, main carina, branching points of large airways, and more distal smaller airways. These receptors are responsive to both mechanical and chemical stimuli.
Afferent pathway:
Impulses from stimulated receptors are transmitted via sensory nerve fibres of the vagus nerve (mainly) and glossopharyngeal nerve and travel to the medulla diffusely. CN 5 is also thought to contribute to the afferent limb. However, the vagus is the main nerve.Central pathway:
The cough centre is located in the upper brain stem and ponsEfferent pathway:
Impulses from the centre travel via the vagus, phrenic nerve, and spinal motor nerves to the diaphragm, abdominal wall, and muscles. -
This question is part of the following fields:
- Anatomy
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Question 125
Incorrect
-
A 77-year-old man is admitted to hospital for colorectal surgery. He is scheduled to undergo a preoperative assessment, which includes cardiopulmonary exercise test (CPX).
During the CPX, his maximum oxygen consumption (VO2 max) is determined to be 2,100 mL/minute. His weight is measured to be 100 kg.
Calculate the metabolic equivalent (MET) that is the best estimate for his VO2 max.Your Answer:
Correct Answer: 6 METs
Explanation:Metabolic equivalent (MET) measures the energy expenditure of an individual.
It is calculated mathematically by:
MET = (VO2 max/weight)/3.5 = 21/3.5 = 6 METs
Where 1 MET = 3.5 mL O2/kg/minute is utilized by the body.
Note:
1 MET Eating
Dressing
Use toilet
Walking slowly on level ground at 2-3 mph
2 METs Playing a musical instrument
Walking indoors around house
Light housework
4 METs Climbing a flight of stairs
Walking up hill
Running a short distance
Heavy housework, scrubbing floors, moving heavy furniture
Walking on level ground at 4 mph
Recreational activity, e.g. golf, bowling, dancing, tennis
6 METs Leisurely swimming
Leisurely cycling along the flat (8-10 mph)
8 METs Cycling along the flat (10-14 mph)
Basketball game
10 METs Moderate to hard swimming
Competitive football
Fast cycling (14-16 mph) -
This question is part of the following fields:
- Clinical Measurement
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Question 126
Incorrect
-
The structure most likely to be damaged during cannulation of the subclavian vein is?
Your Answer:
Correct Answer: Subclavian artery
Explanation:The subclavian artery lies behind and partly above the subclavian vein. 3-4% of the time, it can be inadvertently cannulated during cannulation of the subclavian vein
Because of its anatomical position, putting pressure on the subclavian artery is impossible so arresting bleeding with pressure when it is punctured is not viable.
One of the consequences of subclavian vein cannulation (1%) is pleural puncture leading to a pneumothorax. This is because the apical pleura is inferior and caudal to the subclavian vein.
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This question is part of the following fields:
- Anatomy
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Question 127
Incorrect
-
Your manager asks you to inform patients that are suffering from a chronic pain about a trial that is going to be conducted in order to determine the efficacy of a novel analgesic. What phase is the trial currently in?
Your Answer:
Correct Answer: Phase 2
Explanation:Phase 0 trials assist the scientists in studying the behaviour of drugs in humans by micro dosing patients. They are used to speed up the developmental process. They have no measurable therapeutic effect and efficiency.
Phase 1 is associated with assessing whether a drug is safe to use or not. The process is extensive and can take up to several months. It also involves healthy participants (less than 100) that are paid to take part in the study. The side effects upon increasing dosage are also addressed by the study. The effects the drug has on humans including how its absorbed, metabolized and excreted are studied. Approximately 70% of the drugs pass this phase.
Phase 2 trials involve patients that are suffering from the disease under study and are associated with determining the efficiency and the optimum dosage of the drug.
Phase 3 also assesses the efficacy but at a higher scale with larger population sample.
Phase 4 trials are involved with the long term effects and side effects of the drug.
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This question is part of the following fields:
- Statistical Methods
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Question 128
Incorrect
-
Among the following options, which one can not be the value of Pearson's correlation coefficient?
Your Answer:
Correct Answer: 1.5
Explanation:The correlation coefficient gives us the idea about relation between two parameters. i.e. to what extent change in parameter A could prompt a change in parameter B. The numerical value of correlation coefficient could not be greater than 1.
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This question is part of the following fields:
- Statistical Methods
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Question 129
Incorrect
-
Which of the following is true about the pulse oximeter?
Your Answer:
Correct Answer: Is accurate to within +/- 2% in the range of 70% to 100% saturation
Explanation:The pulse oximeter provides a continuous non-invasive measurement of the arterial oxygen saturation. The light emitting diodes (LEDs) produce beams of red and infrared light at 660 nm and 940 nm respectively (not 640 and 960 nm), which travel through a finger (toe, ear lobe or nose) and are then detected by a sensitive photodetector.
The light absorbed by non-pulsatile tissues is constant (DC), and the non-constant absorption (AC) is the result of arterial blood pulsation. The DC and AC components at 660 and 940 nm are then analysed by the microprocessor and the result is related to the arterial saturation.
An isosbestic point is a point at which two substances absorb a wavelength of light to the same degree. In pulse oximetry the different absorption profiles of oxyhaemoglobin and deoxyhaemoglobin are used to quantify the haemoglobin saturation (in %). Isosbestic points occur at 590 and 805 nm (not 490 and 805 nm), where the light absorbed is independent of the degree of saturation, and are used as reference points.
The pulse oximeter is accurate to within +/- 2% in the range of 70% to 100% saturation, and below 70% the readings are extrapolated. Pulse oximeters average their readings every 10 to 20 seconds and thus they cannot detect acute desaturation events. Consequently, they are often referred to as ‘lag’ monitors, due to the time delay in identifying the desaturation episode.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 130
Incorrect
-
Regarding thyroid hormones, one of the following is true.
Your Answer:
Correct Answer: Thyroid binding globulin (TBG) is increased in pregnancy
Explanation:T3 is produced by peripheral de-iodination of T4. It is more active than T4.
TBG, like most binding proteins, is increased in pregnancy. Because of this, measurement of free thyroid hormone concentration is more important than total.
T4 and T3 concentrations are decreased in Illness and starvation.
L-T4 that is the active molecule while D-T4 is inactive.
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This question is part of the following fields:
- Pathophysiology
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Question 131
Incorrect
-
A pulmonary function tests results are:
Measurement Predicted result Test result
Forced vital capacity (FVC) (btps) 3.85 2.36
Forced expiratory volume in 1 second (FEV1) (btps) 3.34 0.97
FEV1/FVC ratio % (btps) 85.1 39.9
Peak expiratory flow (PEF) (L/second) 7.33 2.11
Maximum voluntary ventilation (MVV) (L/minute) 116 44.4
What does this indicate?Your Answer:
Correct Answer: Moderate restrictive and severe obstructive picture
Explanation:Severity of a reduction in restrictive defect (%FVC) or obstructive defect (%FEV1/FVC) predicted are classified as follows:
Mild 70-80%
Moderate 60-69%
Moderately severe 50-59%
Severe 35-49%
Very severe <35% This patient has a mixed deficit with a severe obstructive deficit as %FEV1/FVC predicted is 46.9% and a moderate restrictive deficit as %FVC of predicted is 61.3 FEV1/FVC ratio 80% < predicted and VC < 80% = mixed picture. FEV1/FVC ratio 80% < predicted and VC > 80% = obstructive picture.FEV1/FVC ratio 80% > predicted and VC > 80% = normal picture.
FEV1/FVC ratio 80% > predicted and VC < 80% predicted= restrictive picture.
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This question is part of the following fields:
- Clinical Measurement
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Question 132
Incorrect
-
The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised by which of the following?
Your Answer:
Correct Answer: Synthesis of ATP is brought about by anaerobic respiration
Explanation:Muscle fibre myosin ATPase histochemistry is used to divide the biochemical classification into two groups: type 1 and type II.
Type I (slow twitch) muscle fibres rely on aerobic glycolytic and aerobic oxidative metabolism to function. They have a lot of mitochondria, a good blood supply, a lot of myoglobin, and they don’t get tired easily.
Because they contain more motor units, Type II (fast twitch) muscle fibres are thicker. They are more easily fatigued, but produce powerful bursts. The capillary networks and mitochondria are less dense in these white muscle fibres than in type I fibres. They have a low myoglobin content as well.
Muscle fibres of type II (fast twitch) are divided into three types:
Type IIa – aerobic/oxidative metabolism is used.
Type IIb – anaerobic/glycolytic metabolism is used by these fibres.When compared to skeletal muscle, cardiac and smooth muscle twitch at a slower rate.
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This question is part of the following fields:
- Pharmacology
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Question 133
Incorrect
-
If a large volume of 0.9% N. saline is administered during resuscitation, it is most likely to cause?
Your Answer:
Correct Answer: Hyperchloremic metabolic acidosis
Explanation:Crystalloids recommended for fluid resuscitation include 0.9% N saline and Hartmann’s solution(a physiological solution). 0.9% N. saline is not a physiological solution for the following reasons:
Compared with the normal range of 98-102 mmol/L, its chloride concentration is high (154 mmol/L)
It lacks calcium, magnesium, glucose and potassium
It does not have bicarbonate or bicarbonate precursor buffer necessary to maintain plasma pH within normal limitsThere is a difference in the activity (concentration) of strong ions at a physiological pH. This imbalance can explain abnormalities of acid base balance. A normal strong ion difference (SID) is in the order of 40.
SID = ([Na+] + [K+] + [Ca2+] + [Mg2+]) – ([Cl-] + [lactate] + [SO42-])
This imbalance is made up with the weaker anions to maintain electrical neutrality.
Administration of a large volume of 0.9% normal saline during resuscitation results in excessive chloride administration and this impairs renal bicarbonate reabsorption. The SID of 0.9% normal saline is 0 (Na+ = 154mmol/L and Cl- = 154mmol/L = 154 – 154 = 0). A large volume of NS will decrease the plasma SID causing an acidosis.Other causes of a hyperchloremic acidosis are:
Diabetic ketoacidosis
Total Parenteral Nutrition
Overdose of ammonium chloride and hydrochloric acid
Gastrointestinal losses of bicarbonate like in diarrhoea and pancreatic fistula
Proximal renal tubular acidosis with failure of bicarbonate reabsorption -
This question is part of the following fields:
- Physiology
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Question 134
Incorrect
-
A 45-year-old woman complains of pain in her upper abdomen to her physician. The pain comes intermittently in waves and gets worse after eating food. There are no associated complaints of fever or bowel problems.
The pain intensity is 6/10, and paracetamol relieves it a little. There is suspicion that part of the biliary tree is blocked.
Which area of the duodenum does this blocked tube open into?Your Answer:
Correct Answer: 2nd part of the duodenum
Explanation:The patient is likely suffering from biliary colic since her pain is intermittent and comes and goes in waves. Biliary colic pain gets worse after eating, especially fatty food as bile helps digest fats. Gallstones are the most common cause of biliary colic and are usually located in the cystic duct or common bile duct. But since this patient has no signs of jaundice or steatorrhea, the duct most likely blocked is the cystic duct.
The cystic duct drains the gallbladder and combines with the common hepatic duct to form the common bile duct. The common bile duct then merges with the pancreatic duct and opens into the second part of the duodenum (major duodenal papilla).
The duodenojejunal flexure is attached to the diaphragm by the ligament of Treitz and is not associated with any common pathology.
The fourth part of the duodenum passes very close to the abdominal aorta and can be compressed by an abdominal aortic aneurysm.
The third part of the duodenum can be affected by superior mesenteric artery syndrome, where the duodenum is compressed between the SMA and the aorta, often in cases of reduced body fat.
The first part of the duodenum is the most common location for peptic ulcers affecting this organ. -
This question is part of the following fields:
- Anatomy
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Question 135
Incorrect
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The Fick principle can be used to determine the blood flow to any organ of the body.
At rest, which one of these organs has the highest blood flow (ml/min/100g)?Your Answer:
Correct Answer: Thyroid gland
Explanation:After the carotid body, the thyroid gland is the second most richly vascular organ in the body.
The global blood flow to the thyroid gland can be measured using:
1. Colour ultrasound sonography
2. Quantitative perfusion maps using MRI of the thyroid gland using an arterial spin labelling (ASL) method.This table shows the blood flow to various organs of the body at rest:
Organ Blood Flow(ml/minute/100g)
Hepatoportal 58
Kidney 420
Brain 54
Skin 13
Skeletal muscle 2.7
Heart 87
Carotid body 2000
Thyroid gland 560 -
This question is part of the following fields:
- Physiology
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Question 136
Incorrect
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Which of the following statement is true or false regarding to the respiratory tract?
Your Answer:
Correct Answer: The sympathetic innervation of the bronchi is derived from T2 - T4
Explanation:The diaphragm has three opening through which different structures pass from the thoracic cavity to the abdominal cavity:
Inferior vena cava passes at the level of T8.
Oesophagus, oesophageal vessels and vagi at T10.
Aorta, thoracic duct and azygous vein through T12.
Sympathetic trunk and pulmonary branches of vagus nerve form a posterior pulmonary plexus at the root of the lung. Fibres continue posteriorly from superficial cardiac plexus to form Anterior pulmonary plexus. It contains vagi nerves and superficial cardiac plexus. These fibres then follow the blood vessel and bronchi into the lungs.
The lower border of the pleura is at the level of:
8th rib in the midclavicular line
10th rib in the lower level of midaxillary line
T12 at its termination.
Both lungs have oblique fissure while right lung has transverse fissure too.
The trachea expands from the lower edge of the cricoid cartilage (at the level of the 6th cervical vertebra) to the carina.
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This question is part of the following fields:
- Physiology
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Question 137
Incorrect
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A man suffers damage to his vagus nerve during surgery on his neck. The vagus nerve is cut near its exit from the skull. The man loses his parasympathetic tone raising his heart rate and blood pressure.
What other feature will be likely present with a vagus nerve injury?Your Answer:
Correct Answer: Hoarse voice
Explanation:The vagus nerve is a mixed nerve with both autonomic and somatic effects. Its most important somatic effect is the motor supply to the larynx via recurrent laryngeal nerves. If one vagus nerve is damaged, the result will be the same as damage to a single recurrent laryngeal nerve, leading to hoarseness of voice.
The vagus exits the skull via the jugular foramen, accompanied by the accessory nerve.
Anal tone, erections, and urination are all controlled by the sacral parasympathetic and would not be affected by the loss of the vagus. Parasympathetic controlled pupillary constriction is via the oculomotor nerve and would not be affected by the loss of the vagus.
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This question is part of the following fields:
- Anatomy
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Question 138
Incorrect
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Which of the following is a characteristic of a type 1B antiarrhythmic agent such as Lidocaine?
Your Answer:
Correct Answer: Shortens refractory period
Explanation:The action of class 1 anti-arrhythmic is sodium channel blockade. Subclasses of this action reflect effects on the action potential duration (APD) and the kinetics of sodium channel blockade.
Drugs with class 1A prolong the APD and refractory period, and dissociate from the channel with intermediate kinetics.
Drugs with class 1B action shorten the APD in some tissues of the heart, shorten the refractory period, and dissociate from the channel with rapid kinetics.
Drugs with class 1C action have minimal effects on the APD and the refractory period, and dissociate from the channel with slow kinetics.
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This question is part of the following fields:
- Pharmacology
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Question 139
Incorrect
-
Regarding the anatomical relations of the first rib, one of the following is right
Your Answer:
Correct Answer: The subclavius muscle attaches to the upper surface
Explanation:The first rib is an atypical rib. It is short, wide, and flattened and lies in an oblique plane.
It has a small scalene tubercle on its medial border which marks the point of attachment of scalenus anterior. The lower surface lies on the pleura and is smooth.
The tubercle on the upper surface separates an anterior groove for the subclavian vein and a posterior groove for the subclavian artery and lower trunk of the brachial plexus.
Scalenus medius is attached to a roughened area posterior to the groove for the subclavian artery.
The upper surface gives attachment anteriorly to the subclavius muscle and costoclavicular ligament.
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This question is part of the following fields:
- Anatomy
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Question 140
Incorrect
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Which of the following does Lidocaine 1% solution equate to?
Your Answer:
Correct Answer: 1000 mg per 100 ml
Explanation:Lidocaine 1% is formulated as 1000 mg/100 mL.
% solution is based on (grams of medicine) / 100 ml
% solution ~ (1000 mg) / 100 ml
% solution ~ 10 mg/ml
Examples:
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- Lidocaine 4% = 40 mg/ml of Lidocaine
- Lidocaine 2% = 20 mg/ml of Lidocaine
- Lidocaine 1% = 10 mg/ml of Lidocaine
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This question is part of the following fields:
- Pharmacology
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Question 141
Incorrect
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Which statement is true of albumin?
Your Answer:
Correct Answer: Is synthesised and stored in the liver
Explanation:Major surgery induces the systemic inflammatory response and this causes endothelial leakage and a low albumin level.
Albumin is a single polypeptide which is made but not stored in the liver. Therefore, levels are a reflection of synthetic activity. It is negatively charged and very soluble.
Only 40% of albumin is intravascular, and the rest in the in interstitial compartment.
If there was normal liver function during starvation, albumin will be maintained and proteolysis will occur elsewhere.
It is not catabolised during starvation.
Starvation and malnutrition may, however, present as part of other disease processes that are associated with hypalbuminaemia.Causes of low albumin are
1. Decreased production (hepatic dysfunction)
2. Increased loss (renal dysfunction)
3. Redistribution (endothelial leak/damage)
4. Increased catabolism (very rare) -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 142
Incorrect
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Which of the following is the most appropriate first-line pharmacologic treatment for status epilepticus?
Your Answer:
Correct Answer: Lorazepam
Explanation:Lorazepam is an intermediate-acting benzodiazepine that binds to the GABA-A receptor subunit to increase the frequency of chloride channel opening and cause membrane hyperpolarization.
Lorazepam has emerged as the preferred benzodiazepine for acute management of status epilepticus. Lorazepam differs from diazepam in two important respects. It is less lipid-soluble than diazepam, with a distribution half-life of two to three hours versus 15 minutes for diazepam. Therefore, it should have a longer duration of clinical effect. Lorazepam also binds the GABAergic receptor more tightly than diazepam, resulting in a longer duration of action. The anticonvulsant effects of lorazepam last six to 12 hours, and the typical dose ranges from 4 to 8 mg. This agent also has a broad spectrum of efficacy, terminating seizures in 75-80% of cases. Its adverse effects are identical to those of diazepam. Thus, lorazepam also is an effective choice for acute seizure management, with the added possibility of a longer duration of action than diazepam.
Phenobarbitone is a long-acting barbiturate that binds to GABA-A receptor site and increase the duration of chloride channel opening. It also blocks glutamic acid neurotransmission, and, at high doses, can block sodium channels. It is considered as the drug of choice for seizures in infants.
Phenytoin is an anti-seizure drug that blocks voltage-gated sodium channels. It is preferred in prolonged therapy of status epilepticus because it is less sedating.
In cases wherein airway protection is required, thiopentone and propofol are the preferred drugs.
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This question is part of the following fields:
- Pharmacology
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Question 143
Incorrect
-
Which of the following is true about the bispectral index (BIS)?
Your Answer:
Correct Answer: Sevoflurane lowers BIS more than ketamine
Explanation:The bispectral index (BIS) monitors works to determine the level of consciousness of a patient by processing electroencephalographic (EEG) signals to obtain a value between 0 and 100, where 0 reflects no brain activity, and 100 reflects a patient is completely awake.
The general meaning of BIS values are:
>95: Patient is in an awake state.
65-85: Patient is in a sedated state.
40-65: Patient is in a state that is optimal for general surgery.
<40: Patient is in a deep hypnotic state It is important in measuring the depths of anaesthesia to prevent haemodynamic changes or patient awareness during surgery. The nature of anaesthetic agent used is a determinant factor in resultant BIS values. Intravenous agents, such as propofol, thiopental and midazolam, result in a deeper hypnotic state, whilst inhalation agents have a lesser hypnotic effect at the same BIS values. Certain agents result in inaccurate BIS values such as ketamine and nitrous oxide (NO). These two agents appear to increase the BIS value, whilst putting the patient in a deeper hypnotic state, and should therefore not be used with BIS monitoring. Hypothermia also affects the BIS value as it causes a 1.12 per °C decrease in body temperature. -
This question is part of the following fields:
- Clinical Measurement
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Question 144
Incorrect
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The plateau phase of the myocardial action potential is as a result of:
Your Answer:
Correct Answer: Slow influx of calcium
Explanation:Cardiac conduction
Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium
Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop
Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period
Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period
Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 145
Incorrect
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One of the causes of increased pulse pressure is when the aorta becomes less compliant because of age-related changes. Another cause of increased pulse pressure is which of the following?
Your Answer:
Correct Answer: Increased stroke volume
Explanation:Impaired ventricular relaxation reduces diastolic filling and therefore preload.
Decreased blood volume decreases preload due to reduced venous return.
Heart failure is characterized by reduced ejection fraction and therefore stroke volume.
Cardiac output = stroke volume x heart rate
Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%
Stroke volume = end diastolic LV volume – end systolic LV volume
Pulse pressure (is increased by stroke volume) = Systolic Pressure – Diastolic Pressure
Systemic vascular resistance = mean arterial pressure / cardiac output
Factors that increase pulse pressure include:
-a less compliant aorta (this tends to occur with advancing age)
-increased stroke volume
Aortic stenosis would decrease stroke volume as end systolic volume would increase.
This is because of an increase in afterload, an increase in resistance that the heart must pump against due to a hard stenotic valve. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 146
Incorrect
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Which of the following statements is true regarding Adrenaline or Epinephrine?
Your Answer:
Correct Answer: Stimulates ACTH secretion
Explanation:Adrenaline is released by the adrenal glands, acts on ? 1 and 2, ? 1 and 2 receptors, and is responsible for fight or flight response.
It acts on ? 2 receptors in skeletal muscle vessels-causing vasodilation.
It acts on ? adrenergic receptors to inhibit insulin secretion by the pancreas. It also stimulates glycogenolysis in the liver and muscle, stimulates glycolysis in muscle.
It acts on ? adrenergic receptors to stimulate glucagon secretion in the pancreas
It also stimulates Adrenocorticotrophic Hormone (ACTH) and stimulates lipolysis by adipose tissue -
This question is part of the following fields:
- Pharmacology
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Question 147
Incorrect
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The equipment used for patient monitoring in theatre and intensive care settings have electrical safety requirements for the protection of hospital staff and patients.
Of the different classes of electrical equipment listed, which is least likely to cause a patient to suffer a microshock?Your Answer:
Correct Answer: II (CF)
Explanation:Microshock refers to ventricular fibrillation caused by miniscule amounts of currents or voltages (100-150 microamperes) passing through the myocardial tissue from external cables arising from electrical components within the cardiac muscle, for example, pacemaker electrodes or saline filled venous catheters.
The risk of shock changes with the construction of electrical equipment in question. The main classes of electrical equipment include: I: Appliances have a protective earth connected to an outer casing which prevents live elements from coming in contact with conductive elements. A fault in this equipment class will result in live elements coming in contact with the outer casing and allowing electrical flow into the protective earth. This triggers the protective fuse to disconnect the electric supply to the appliance.
II: These appliances have reinforced insulation. In the event of a fault which causes the first layer of insulation to fail, the second layer is able to prevent contact of live elements with outer casing.
III: These appliances have no insulation to provide safety, and rely solely on the use of separated extra low voltage source (SELV) which limits voltage to 25V AC or 60V DC allowing for a person to come in contact with it without risk of a shock under normal dry conditions. Under wet conditions, voltage supply should be lowered to reduce risk of shock. These devices have no risk of macroshocks, but some risk of microshocks.
Class I and II electrical appliances are further divided into subtypes developed to limit current leakage in the event of a singular fault:
B (body): Upper limit of current leakage is 500 µA. This current can cause skin tingling and microshocks, but is not sufficient to cause injury.
BF (body floating): These appliances have an isolating capacitor or transformer which separate the secondary circuit from the protective earth. The upper limit of current leakage is the same as type B.
CF (cardiac floating): Upper limit of leakage current during a singular fault is 50 microamps. It is least likely to result in a microshock -
This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 148
Incorrect
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A 68-year old female is brought to the Emergency Room for abdominal pain. Medical history revealed that she is on long-term warfarin therapy for deep vein thrombosis.
Upon further investigation, the patient is hypotensive at 80/60 mmHg, and an abdominal mass is palpable on the umbilical area. An initial diagnosis of ruptured abdominal aortic aneurysm (AAA) is made. Moreover, blood tests show an international normalised ratio (INR) of 4.2.
Which of the following products should be initially transfused or administered to the patient to reverse the anticoagulation?Your Answer:
Correct Answer: Prothrombin complex
Explanation:Warfarin prevents reductive metabolism of the inactive vitamin K epoxide back to its active hydroquinone form. Thus, warfarin inhibits the synthesis of vitamin K dependent clotting factors: X, IX, VII, II (prothrombin), and of the anticoagulants protein C and protein S. The therapeutic range for oral anticoagulant therapy is defined in terms of an international normalized ratio (INR). The INR is the prothrombin time ratio (patient prothrombin time/mean of normal prothrombin time for lab)ISI, where the ISI exponent refers to the International Sensitivity Index and is dependent on the specific reagents and instruments used for the determination. A prolonged INR is widely used as an indication of integrity of the coagulation system in liver disease and other disorders, it has been validated only in patients in steady state on chronic warfarin therapy.
Prothrombin complex concentrate (PCC) is used to replace congenital or acquired vitamin-K deficiency warfarin-induced anticoagulant effect, particularly in the emergent setting.
Intravenous vitamin K has a slower onset of action compared to PCC, but is useful for long term therapy.
Fresh frozen plasma (FFP) prepared from freshly donated blood is the usual source of the vitamin K-dependent factors and is the only source of factor V. The factors needed, however, are found in small quantities compared to PCC.
Cryoprecipitate is indicated for hypofibrinogenemia/dysfibrinogenemia, von Willebrand disease, haemophilia A, factor XIII deficiency, and management of bleeding related to thrombolytic therapy.
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This question is part of the following fields:
- Pathophysiology
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Question 149
Incorrect
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When an inotrope is given to the body, it has the following effects on the cardiovascular system:
The automaticity of the sino-atrial node increases
Lusitropy is accelerated
Dromotropy is increased
Chronotropy is increased
Inotropy increases
There is increased excitability of the conducting system
The most probably mechanism of action of this compound is?Your Answer:
Correct Answer: Increase in intracellular calcium influenced by a conformational change of a Gs protein
Explanation:A beta-1 adrenoreceptor agonist is most likely the ligand that causes increased automaticity, increased chronotropy, increased excitability, and increased inotropy on the sino-atrial node. However, alpha-1 adrenoreceptor effects may cause an increase in systemic vascular resistance. Noradrenaline, adrenaline, dopamine, and ephedrine are examples of drugs with mixed alpha and beta effects.
Adrenaline, noradrenaline, dopamine, dopexamine, dobutamine, ephedrine, and isoprenaline are examples of drugs that have some beta-1 activity. The beta-1 receptor is a G protein-coupled metabotropic receptor. When the beta-1 agonist binds to the cell surface membrane, it causes a conformational change in the Gs unit, which triggers a cAMP-dependent pathway and a calcium influx into the cell.
Catecholamines also help to relax the heart muscle (positive lusitropy). Dromotropy is the ability to increase the atrioventricular (AV) node’s conduction velocity.
Inodilators cause an increase in intracellular calcium as a result of phosphodiesterase III (PDIII) inhibition. Milrinone, enoximone, and amrinone are some examples. Positive inotropy is caused by increased calcium entry into the myocytes. Lusitropy is also increased by phosphodiesterase inhibitors. Increased cAMP inhibits myosin light chain kinase, resulting in reduced phosphorylation of vascular smooth muscle myosin, lowering systemic and pulmonary vascular resistance.
The mechanism of action of alpha-1 adrenoreceptor agonists is an increase in intracellular calcium caused by an increase in inositol triphosphate (IP3). IP3 is a second messenger that causes an increase in systemic vascular resistance by stimulating the influx of Ca2+ into smooth muscle cells. Reflex bradycardia can occur as a result of the subsequent increase in blood pressure. Phenylephrine and metaraminol are examples of pure alpha-1 agonists.
Levosimendin is a novel inotrope that makes myocytes more sensitive to intracellular Ca2+. It causes a positive inotropy without changing heart rate or oxygen consumption significantly.
The Na-K-ATPase membrane pump in the myocardium is inhibited by digoxin. This inhibition promotes sodium-calcium exchange, resulting in an increase in intracellular Ca2+ and increased contraction force. The parasympathetic effects of digoxin on the AV node result in bradycardia. Systemic vascular resistance will not be affected by it.
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This question is part of the following fields:
- Pathophysiology
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Question 150
Incorrect
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All of the following statements are false regarding tetracyclines except:
Your Answer:
Correct Answer:
Explanation:Tetracyclines inhibit protein synthesis through reversible binding to bacterial 30s ribosomal subunits (not 50s) which prevent binding of new incoming amino acids (aminoacyl-tRNA) and thus interfere with peptide growth.
They penetrate macrophages and are thus a drug of choice for treating infections due to intracellular organisms.
Tetracycline does not inhibit transpeptidation. Meanwhile, it is chloramphenicol which is responsible for inhibiting transpeptidation.
Tetracycline can get deposited in growing bone and teeth due to its calcium-binding effect and thus causes dental discoloration and dental hypoplasia. Due to this reason, they should be avoided in pregnant or lactating mothers.
Simultaneous administration of aluminium hydroxide can impede the absorption of tetracyclines.
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This question is part of the following fields:
- Pharmacology
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Question 151
Incorrect
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Risk stratification is done prior to a major cardiac surgery using cardiopulmonary exercise testing. Given the following options, which one is most likely to have the highest risk for post-operative cardiac morbidity?
Your Answer:
Correct Answer: Anaerobic threshold (AT) of less than 11 mL/kg/minute
Explanation:The ventilatory anaerobic threshold (VAT), formerly referred to as the anaerobic threshold, is an index used to estimate exercise capacity. During the initial (aerobic) phase of CPET, which lasts until 50–60% of Vo2max is reached, expired ventilation (VE) increases linearly with Vo2 and reflects aerobically produced CO2 in the muscles. Blood lactate levels do not change substantially during this phase, since muscle lactic acid production is minimal.
During the latter half of exercise, anaerobic metabolism occurs because oxygen supply cannot keep up with the increasing metabolic requirements of exercising muscles. At this time, there is a significant increase in lactic acid production in the muscles and in the blood lactate concentration. The Vo2 at the onset of blood lactate accumulation is called the lactate threshold or the VAT. The VAT is also defined as the point at which minute ventilation increases disproportionately relative to Vo2, a response that is generally seen at 60–70% of Vo2max.
The VAT is a useful measure as work below this level encompasses most daily living activities. The ability to achieve the VAT can help distinguish cardiac and non‐cardiac (pulmonary or musculoskeletal) causes of exercise limitation, since patients who fatigue before reaching VAT are likely to have a non‐cardiac problem.
When VAT is detected, patients with PVo2 of ⩽10 ml/kg/min have a high event rate.
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This question is part of the following fields:
- Pathophysiology
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Question 152
Incorrect
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A 70-year old male has diverticular disease and is undergoing a sigmoid colectomy. His risk of developing a post operative would infection can be minimized by which of the following interventions?
Your Answer:
Correct Answer: Administration of single dose of broad spectrum antibiotics prior to the procedure
Explanation:Staphylococcus aureus infection is the most likely cause.
Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.
SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
The organisms are usually derived from the patient’s own body.Measures that may increase the risk of SSI include:
-Shaving the wound using a single use electrical razor with a disposable head
-Using a non iodine impregnated surgical drape if one is needed
-Tissue hypoxia
-Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.Measures that may decrease the risk of SSI include:
1. Intraoperatively
– Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
-Cover surgical site with dressingIn contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.
2. Post operatively
Tissue viability advice for management of surgical wounds healing by secondary intentionUse of diathermy for skin incisions
In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used. -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 153
Incorrect
-
A 53-year old female with a diagnosis of anaplastic thyroid carcinoma is admitted in the surgery department for an elective total thyroidectomy with radical neck dissection. The operation is expected to last for 10 hours.
Which of the following is the most suitable humidifier to use in an anaesthetic circuit for this case?Your Answer:
Correct Answer: Heat and moisture exchanger (HME)
Explanation:Adequate humidification is vital to maintain homeostasis of the airway. Heat and moisture exchangers conserve some of the exhaled water, heat and return them to inspired gases. Many heat and moisture exchangers also perform bacterial/viral filtration and prevent inhalation of small particles. Heat and moisture exchangers are also called condenser humidifier, artificial nose, etc. Most of them are disposable devices with exchanging medium enclosed in a plastic housing. For adult and paediatric age group different dead space types are available. Heat and moisture exchangers are helpful during anaesthesia and ventilatory breathing system. To reduce the damage of the upper respiratory tract through cooling and dehydration inspiratory air can be heated and humidified, thus preventing the serious complications. Moreover, they are the most appropriate humidification devices used for routine anaesthesia.
Gases can be bubbled through water to increase humidity. Passing gas through water at room temperature causes the gas to cool due to latent heat of vaporisation. The water bath can be heated. This improves the efficiency of the device and also reduces the incidence of bacterial colonisation.
Nebulisers use a venturi system which employs the Bernoulli effect. A gas at high flow passes through a constriction causing the gas to accelerate, reducing its potential energy allowing other gases or liquids to be entrained. This can include medications or in the case of humidification, water vapour. The size of the water droplet produced by nebulisation determines where in the airway it is deposited. Standard nebulisers produced droplets of 4 microns in diameter and these are deposited in the upper airway and trachea. Efficacy can be improved by passing the droplets over an anvil which further reduces particle size. The most efficient form of nebuliser is the ultrasonic nebuliser. Here a transducer immersed in water and vibrated at a frequency of 3MHz produces1-2micron droplets. These particles easily reach the bronchioles and provide excellent humidification.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 154
Incorrect
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Which statement is true when describing carbonic anhydrase?
Your Answer:
Correct Answer: Isoenzyme IV is found in the brush border of the proximal convoluted tubule
Explanation:Carbonic anhydrase is an enzyme which contains zinc and can be found in:
1. Erythrocytes
2. Pulmonary endothelium
3. The intestine
4. Pancreas
5. Cardiac muscle and skeletal muscle.To date, there have been seven isoenzymes identified. Of note, isoenzyme IV is found in the brush border of the proximal convoluted tubule and isoenzyme II is found within the luminal cells.
Acetazolamides a carbonic anhydrase inhibitor and is used as prophylaxis against mountain sickness and in glaucoma management.
Spironolactone is a potassium diuretic and is an aldosterone antagonist.
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This question is part of the following fields:
- Physiology
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Question 155
Incorrect
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Where should you insert a needle to obtain a femoral artery sample to be used for an arterial blood gas?
Your Answer:
Correct Answer: Mid inguinal point
Explanation:The needle should be inserted just below the skin at the mid inguinal point which is the surface indicator for the femoral artery.
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This question is part of the following fields:
- Anatomy
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Question 156
Incorrect
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You are asked about the relative risk associated with a drug. You happened to have read a report in which the same drug was compared with a placebo and your initial thoughts after reading the study were that the drug will have significant side effects.
What do you expect the value of relative risk to be?Your Answer:
Correct Answer: Greater than 1
Explanation:Risk ratio (relative risk) compares the probability of an event in an exposed (experimental) group to that of an event in the unexposed (control) group.
A relative risk of 1 suggests that there is no discernible difference in the outcome whether or not it has been exposed.
A relative risk of less than 1 indicates that probability of occurrence of an event is less if there is exposure.
A relative risk of greater than 1 highlights that an event is most likely to occur if it was provided exposure. Since you believe that exposure (the new drug) would have side effects, the value should be greater than 1.
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This question is part of the following fields:
- Statistical Methods
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Question 157
Incorrect
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Which of the following statements is not true regarding Adrenaline?
Your Answer:
Correct Answer: Exerts its effect by decreasing intracellular calcium
Explanation:Noradrenaline also called norepinephrine belongs to the catecholamine family that functions in the brain and body as both a hormone and neurotransmitter.
They have sympathomimetic effects acting via adrenoceptors (?1, ?2,?1, ?2, ?3) or dopamine receptors (D1, D2).
May cause reflex bradycardia, reduce cardiac output and increase myocardial oxygen consumption
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This question is part of the following fields:
- Pharmacology
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Question 158
Incorrect
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What structure is most posterior at the porta hepatis?
Your Answer:
Correct Answer: Portal vein
Explanation:The structures in the porta hepatis from anterior to posterior are:
The ducts: Most anterior are the left and right hepatic ducts.
The arteries: Next are the left and right hepatic arteries
The veins: Next is the portal vein
The epiploic foramen of Winslow lies most posterior at the porta hepatis.
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This question is part of the following fields:
- Anatomy
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Question 159
Incorrect
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Of the following statements, which is true about the measurements of cardiac output using thermodilution?
Your Answer:
Correct Answer: Cardiac output should be measured during the end-expiratory pause
Explanation:Thermodilution is the most common dilution method used to measure cardiac output (CO) in a hospital setting.
During the procedure, a Swan-Ganz catheter, which is a specialized catheter with a thermistor-tip, is inserted into the pulmonary artery via the peripheral vein. 5-10mL of a cold saline solution with a known temperature and volume is injected into the right atrium via a proximal catheter port. The solution is cooled as it mixes with the blood during its travel to the pulmonary artery. The temperature of the blood is the measured by the catheter and is profiled using a computer.
The computer also uses the profile to measure cardiac output from the right ventricle, over several measurements until an average is selected.
Cardiac output changes at each point of respiration, therefore to get an accurate measurement, the same point during respiration must be used at each procedure, this is usually the end of expiration, that is the end-expiratory pause.
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This question is part of the following fields:
- Clinical Measurement
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Question 160
Incorrect
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A 20-year old lady has been having excessive bruising and bleeding of her gums. She is under investigation for the extrinsic pathway of coagulation. Which is the best investigation to order?
Your Answer:
Correct Answer: Prothrombin time (PT)
Explanation:The extrinsic pathway is best assessed by the PT time.
D-dimer is a fibrin degradation product which is raised in the presence of blood clots.
A 50:50 mixing study is used to assess if a prolonged PT or aPTT is due to factor deficiency or a factor inhibitor.
The thrombin time is a test used to assess fibrin formation from fibrinogen in plasma. Factors that prolong the thrombin time include heparin, fibrin degradation products, and fibrinogen deficiency.
Intrinsic pathway – Best assessed by APTT. Factors 8,9,11,12 are involved. Prolonged aPTT can be seen in haemophilia and use of heparin.
Extrinsic pathway – Best assessed by Increased PT. Factor 7 involved.
Common pathway – Best assessed by APTT & PT. Factors 2,5,10 involved.
Vitamin K dependent factors are factors 2,7,9,10
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This question is part of the following fields:
- Physiology And Biochemistry
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