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Question 1
Correct
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A new study is being carried out on the measurement of a new cardiovascular disease biomarker, and its applications in preoperative screening. The data for this study is expected to be normally distributed.
Which of the following statements is true about normal distributions?Your Answer: The mean, median and mode are the same value
Explanation:The correct answer is the mean, median and mode of normally distributed data are the same value. This is as a result of the bell shaped curve which is equal on both sides.
The bell-shape indicates that values around the mean are more frequent in occurrence than the values farther away.
In a normal distribution:
1) +/- one standard deviation of the mean accounts for 68% of the data.
2) +/- two standard deviations of the mean accounts for 95% of the data.
3) +/- three standard deviations of the mean accounts for 99.7% of the data. -
This question is part of the following fields:
- Statistical Methods
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Question 2
Correct
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A patient is evaluated for persistent dysphonia six months after undergoing a subtotal thyroidectomy.
Which of the following is the most likely reason for the change in this patient's voice?Your Answer: Damage to recurrent laryngeal nerve
Explanation:After thyroid surgery, about 10-15% of patients experience a temporary subjective voice change of varying degrees. A frog in the throat or cracking of the voice, or a weak voice, are common descriptions. These modifications are only temporary, lasting a few days to a few weeks.
Swelling of the muscles in the area of the dissection, as well as inflammation and oedema of the larynx due to the dissection, or minor trauma from the tracheal tube, are all suspected causes.
On both sides of the thyroid gland, the superior laryngeal nerve (EBSLN) runs along the upper part. The muscles that fine-tune the vocal cords are innervated by these nerves. The quality of their voice is usually normal if they are injured, but making high-pitched sounds may be difficult. Injury to the EBSLN occurs in about 2% of the population.
Injuries to the recurrent laryngeal nerve (RLN) have been reported to occur in 1 percent to 14 percent of people. Except for the cricothyroid muscle, the RLN supplies all of the laryngeal intrinsic muscles.
This complication is usually unilateral and temporary, but it can also be bilateral and permanent, and it can be intentional or unintentional. The most common complication following thyroid surgery is a permanent lesion of damaged RLN, which manifests as an irreversible phonation dysfunction.
The crico-arytenoid joint dislocation is a relatively uncommon complication of tracheal intubation and blunt neck trauma. The probability is less than one in a thousand.
Vocal cord polyps affect 0.8 percent of people.
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This question is part of the following fields:
- Pathophysiology
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Question 3
Correct
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A bolus of alfentanil has a faster onset of action than an equal dose of fentanyl.
Which of the following statements most accurately describes the difference?Your Answer: The pKa of alfentanil is less than that of fentanyl
Explanation:Unionised molecules are more likely than ionised molecules to cross membranes (such as the blood-brain barrier).
Because alfentanil and fentanyl are weak bases, the Henderson-Hasselbalch equation says that the ratio of ionised to unionised molecules is determined by the parent compound’s pKa in relation to physiological pH.
Alfentanil has a pKa of 6.5, while fentanyl has a pKa of 8.4.
At a pH of 7.4, 89 percent of alfentanil is unionised, whereas 9% of fentanyl is.As a result, alfentanil has a faster onset than fentanyl.
Fentanyl is 83% plasma protein bound
Alfentanil is 90% plasma protein bound.Alfentanil’s pharmacokinetics are affected by its higher plasma protein binding. Because alfentanil has a low hepatic extraction ratio (0.4), clearance is determined by the degree of protein binding rather than the time it takes to take effect.
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This question is part of the following fields:
- Pharmacology
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Question 4
Correct
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A 56-year old man, presents to emergency department following a cardiac arrest. On history and examination, he is found to be suffering from both metabolic and respiratory acidosis as a result of his cardiac arrest.
What is the best way to reduce the risk of acidaemia during cardiac arrestYour Answer: Chest compressions
Explanation:Chest compressions are an essential part of cardiopulmonary resuscitation (CPR) which helps restore spontaneous circulation (ROSC).
Sodium bicarbonate is only prescribed in patients with cardiac arrests as a result of an overdose of tricyclic antidepressants or hyperkalaemia. Its use causes the body to produce more CO2 which causes:
Exacerbation of intracellular acidosis
Negative inotropy to ischaemic myocardium
Increased osmotic load of sodium into failing brain and body
Shift of oxygen dissociation curve to the left.THAM is often used to treat metabolic acidosis as a result of cardiac bypass surgery and also cardiac arrest, when other standard methods have failed.
Carbicarb (Na2CO3 0.33 molar NaHCO3 0.33 molar) has only mild effects on acidosis. It also causes an increase in arterial CO2 pressure and lactate concentration.
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This question is part of the following fields:
- Pathophysiology
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Question 5
Correct
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Which structure passes through the foramen magnum?
Your Answer: Spinal roots of the accessory nerve
Explanation:The structures that pass through the foramen magnum are:
Meningeal lymphatics
Spinal cord
Spinal meninges
Sympathetic plexus of vertebral arteries
Vertebral arteries
Vertebral artery spinal branches
The spinal roots of the accessory nerve.The jugular foramen contains the vagus nerve, the accessory nerve and glossopharyngeal nerve.
The vertebral veins does not pass into the skull.
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This question is part of the following fields:
- Anatomy
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Question 6
Incorrect
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Regarding the anatomical relations of the scalenus muscles, which of these is true?
Your Answer: The subclavian vein forms the brachiocephalic vein at the lateral border of scalenus anterior
Correct Answer: The trunks of the brachial plexus emerge from the lateral border of scalenus anterior
Explanation:The ascending cervical artery lies media the phrenic nerve on scalenus anterior and can easily be mistaken for the phrenic nerve at operation.
The phrenic nerve passes across scalenus anterior and medius inferiorly.
The subclavian artery is separated from the vein by the scalenus anterior.
The brachiocephalic vein is formed at the medial border of scalenus anterior by the subclavian vein and the internal jugular vein.
Emerging from the lateral border of scalenus anterior are the trunks of the brachial plexus .
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This question is part of the following fields:
- Anatomy
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Question 7
Correct
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What can you see within the tunica media of a blood vessel on examination?
Your Answer: Smooth muscle
Explanation:The blood vessel well is divided into 3 parts, namely:
The tunica intima, which is the deepest layer. It contains endothelial cells separated by gap junctions
The tunica media, primarily consisting of the involuntary smooth muscle fibres, laid out in spiral layers with elastic fibres and connective tissue.
The tunica adventitia, which is the most superficial layer. It consists of the vasa vasorum, fibroblast and collagen.
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This question is part of the following fields:
- Anatomy
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Question 8
Incorrect
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A laceration to the upper lateral margin of the popliteal fossa will pose the greatest risk of injury for which nerve?
Your Answer:
Correct Answer: Common peroneal nerve
Explanation:The common peroneal (fibular) nerve descends obliquely along the lateral side of the popliteal fossa to the fibular head, medial to biceps femoris.
The sural nerve exits at the fossa’s lower inferolateral aspect and is more at risk in short saphenous vein surgery.
The tibial nerve lies more medially and is even less likely to be injured in this location.
The boundaries of the popliteal fossa are:
Superolateral – the biceps femoris tendon
Superomedial – semimembranosus reinforced by semitendinosus
Inferomedial and inferolateral – medial and lateral heads of gastrocnemiusThe contents of the Popliteal fossa are:
1. The popliteal artery
2. The popliteal vein
3. The Tibial nerve and common Fibular nerve
4. Posterior femoral cutaneous nerve: descends and pierces the roof
5. Small saphenous vein
6. popliteal lymph nodes
7. fat -
This question is part of the following fields:
- Anatomy
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Question 9
Incorrect
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Suppose the afterload and myocardial contractility remain unchanged, which of the following factors in the pressure-volume loop indicates an increase in the preload of the left ventricle?
Your Answer:
Correct Answer: Increased end-diastolic volume
Explanation:If the afterload and myocardiac contractility remains unchanged, an increase in the preload can be attributed to an increase in end-diastolic volume.
Preload can be defined as the initial stretching of the cardiac myocytes prior to contraction. Preload, therefore, is related to muscle sarcomere length. Because sarcomere length cannot be determined in the intact heart, other indices of preload are used such as ventricular end-diastolic volume or pressure. When venous return to the heart is increased, the end-diastolic pressure and volume of the ventricles are increased, which stretches the sarcomeres, thereby increasing their preload.
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This question is part of the following fields:
- Basic Physics
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Question 10
Incorrect
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Which of the following statements regarding anticholinergic drugs (hyoscine hydrobromide, atropine and glycopyrrolate) is true?
Your Answer:
Correct Answer: Hyoscine hydrobromide use may precipitate excitement and ataxia
Explanation:Anticholinergic agents are a group of drugs that blocks the action of the neurotransmitter called acetylcholine at synapses in the central and peripheral nervous system.
Hyoscine, atropine, and glycopyrrolate are anticholinergic which acts at muscarinic receptors with little activity at the nicotinic receptors.
Hyoscine and atropine are naturally occurring esters. Since Glycopyrrolate is a synthetic quaternary amine, it does not cross the blood brain barrier. Noteworthy, hyoscine, butylbromide also does not cross the blood brain barrier significantly.
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This question is part of the following fields:
- Pharmacology
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Question 11
Incorrect
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A 68-year-old woman is a known case of acute myeloid leukaemia and was treated with chemotherapy as a child. She now presents in casualty, and you are called in to attend this patient as it is getting difficult to gain vascular access in her arms. The medical registrar asks you to site a cannula during the arrest call as intraosseous access is delayed. The intern wants to assist you in performing a venous cutdown of one of the veins in the patients ankle that passes anterior to the medial malleolus. Which vessel is this?
Your Answer:
Correct Answer: Long saphenous vein
Explanation:Venous cutdown is a surgical procedure when venous access is difficult, and other procedures like the Seldinger technique, ultrasound-guided venous access, and intraosseous vascular access have failed.
The vein of choice for venous cutdown is the long/great saphenous vein. It is part of the superficial venous collecting system of the lower extremity. It is the preferred vein as the long saphenous vein has anatomic consistency and is superficially located at the ankle anterior to the medial malleolus. It is also the most commonly used conduit for cardiovascular bypass operations.
Origin- in the foot at the confluence of the dorsal vein of the first digit and the dorsal venous arch of the foot
Route- runs ANTERIOR to the medial malleolus and travels up in the medial leg and upper thigh.
Termination: in the femoral vein within the femoral triangleRegarding the other options:
The short saphenous vein passes posterior to the lateral malleolus.
The dorsalis pedis vein accompanies the dorsalis pedis artery on the anterior foot.
The posterior tibial vein is part of the deep venous system accompanying the posterior tibial artery. There is no significant sural vein (there is a sural nerve), but the sural veins accompany the sural arteries and drain to the popliteal vein. -
This question is part of the following fields:
- Anatomy
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Question 12
Incorrect
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A 48-year-old woman has presented to the emergency with abdominal pain and distension complaints. She is a known case of diabetes mellitus type 2 and has a BMI of 28 kg/m². On investigations, the liver function tests (LFTs) show raised alanine transaminase (ALT).
Liver ultrasound is performed next to visualize the blood flow into and out of the liver.
Which blood vessel supplies approximately one-third of the blood supply to the liver?
Your Answer:
Correct Answer: Hepatic artery proper
Explanation:The liver receives blood supply from two sources.
1. Hepatic artery proper
It arises from the celiac trunk via the common hepatic artery and brings oxygenated blood to the liver.
It contributes to approximately 30% of the blood supply of the liver.
2. Hepatic portal vein – supplies the liver with partially deoxygenated blood, carrying nutrients absorbed from the small intestine. It gets tributaries from the inferior mesenteric vein, splenic vein, and superior mesenteric veinThe inferior mesenteric artery supplies the hindgut.
The superior mesenteric artery supplies the pancreas and intestine up to the proximal two-thirds of the transverse colon.
The inferior phrenic artery supplies the inferior surface of the diaphragm and oesophagus. -
This question is part of the following fields:
- Anatomy
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Question 13
Incorrect
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Question 14
Incorrect
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Which of the following statements is true regarding dopamine?
Your Answer:
Correct Answer: It can increase or decrease cAMP levels
Explanation:Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic ? and?1 (but not ?2 ) agonist.
The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of DA dilates these vessels (by raising intracellular cAMP). This increases g.f.r. In addition, DA exerts a natriuretic effect by D1 receptors on proximal tubular cells.
Moderately high doses produce a positive inotropic (direct?1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.
Vasoconstriction (?1 action) occurs only when large doses are infused.
At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier—no CNS effects.
Dopamine is used in patients with cardiogenic or septic shock and severe CHF wherein it increases BP and urine outflow.
It is administered by i.v. infusion (0.2–1 mg/min) which is regulated by monitoring BP and rate of urine formation
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This question is part of the following fields:
- Pharmacology
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Question 15
Incorrect
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Which of the following statement is true about Loop diuretics?
Your Answer:
Correct Answer: Are useful in the treatment of acute heart failure
Explanation:Loop diuretics act by causing inhibition of Na+ K+ 2Cl– symporter present at the luminal membrane of the ascending limb of the loop of Henle.
Furosemide, torsemide, bumetanide, ethacrynic acid, furosemide, piretanide, tripamide, and mersalyl are the important members of this group
The main use of loop diuretics is to remove the oedema fluid in renal, hepatic, or cardiac diseases. Thus they are useful in the treatment of acute heart failure. These can be administered i.v. for prompt relief of acute pulmonary oedema (due to vasodilatory action).
Hypokalaemia, hypomagnesemia, hyponatremia, alkalosis, hyperglycaemia, hyperuricemia, and dyslipidaemia are seen with both thiazides as well as loop diuretics
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This question is part of the following fields:
- Pharmacology
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Question 16
Incorrect
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All of the following are true when describing the autonomic nervous system except:
Your Answer:
Correct Answer: Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole parasympathetic control
Explanation:With regards to the autonomic nervous system (ANS)
1. It is not under voluntary control
2. It uses reflex pathways and different to the somatic nervous system.
3. The hypothalamus is the central point of integration of the ANS. However, the gut can coordinate some secretions and information from the baroreceptors which are processed in the medulla.With regards to the central nervous system (CNS)
1. There are myelinated preganglionic fibres which lead to the
ganglion where the nerve cell bodies of the non-myelinated post ganglionic nerves are organised.
2. From the ganglion, the post ganglionic nerves then lead on to the innervated organ.Most organs are under control of both systems although one system normally predominates.
The nerves of the sympathetic nervous system (SNS) originate from the lateral horns of the spinal cord, pass into the anterior primary rami and then pass via the white rami communicates into the ganglia from T1-L2.
There are short pre-ganglionic and long post ganglionic fibres.
Pre-ganglionic synapses use acetylcholine (ACh) as a neurotransmitter on nicotinic receptors.
Post ganglionic synapses uses adrenoceptors with norepinephrine / epinephrine as the neurotransmitter.
However, in sweat glands, piloerector muscles and few blood vessels, ACh is still used as a neurotransmitter with nicotinic receptors.The ganglia form the sympathetic trunk – this is a collection of nerves that begin at the base of the skull and travel 2-3 cm lateral to the vertebrae, extending to the coccyx.
There are cervical, thoracic, lumbar and sacral ganglia and visceral sympathetic innervation is by cardiac, coeliac and hypogastric plexi.
Juxta glomerular apparatus, piloerector muscles and adipose tissue are all organs under sole sympathetic control.
The PNS has a craniosacral outflow. It causes reduced arousal and cardiovascular stimulation and increases visceral activity.
The cranial outflow consists of
1. The oculomotor nerve (CN III) to the eye via the ciliary ganglion,
2. Facial nerve (CN VII) to the submandibular, sublingual and lacrimal glands via the pterygopalatine and submandibular ganglions
3. Glossopharyngeal (CN IX) to lungs, larynx and tracheobronchial tree via otic ganglion
4. The vagus nerve (CN X), the largest contributor and carries ¾ of fibres covering innervation of the heart, lungs, larynx, tracheobronchial tree parotid gland and proximal gut to the splenic flexure, liver and pancreasThe sacral outflow (S2 to S4) innervates the bladder, distal gut and genitalia.
The PNS has long preganglionic and short post ganglionic fibres.
Preganglionic synapses, like in the SNS, use ACh as the neuro transmitter with nicotinic receptors.
Post ganglionic synapses also use ACh as the neurotransmitter but have muscarinic receptors.Different types of these muscarinic receptors are present in different organs:
There are:
M1 = pupillary constriction, gastric acid secretion stimulation
M2 = inhibition of cardiac stimulation
M3 = visceral vasodilation, coronary artery constriction, increased secretions in salivary, lacrimal glands and pancreas
M4 = brain and adrenal medulla
M5 = brainThe lacrimal glands are solely under parasympathetic control.
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 17
Incorrect
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With a 10-day history of severe vomiting, a 71-year-old man with a gastric outlet obstruction is admitted to the surgical ward.
The serum biochemical results listed below are available:
Sodium 128 mmol/L (137-144)
Potassium 2.6 mmol/L (3.5-4.9)
Chloride 50 mmol/L (95-107)
Urea 12 mmol/L (2.5-7.5)
Creatinine 180 µmol/L (60-110)
Which of the following do you think you are most likely to encounter?Your Answer:
Correct Answer: The standard base excess will be higher than actual base excess
Explanation:Hydrochloric acid is lost when you vomit for a long time (HCl). As a result, the following can be expected, in varying degrees of severity:
Hypokalaemia
Hypochloraemia
Increased bicarbonate to compensate for chloride loss and metabolic alkalosisThe alkalosis causes potassium to move from the intracellular to the extracellular compartment at first. Long-term vomiting and dehydration cause potassium to be excreted by the kidneys in order to conserve sodium. Dehydration can cause urea and creatinine levels to rise.
The actual base excess is always greater than the standard base excess.
The actual base excess (BE) is a measurement of a base’s contribution to a blood gas picture’s metabolic component. It’s the amount of base that needs to be added to a blood sample to bring the pH back to 7.4 after the respiratory component of a blood gas picture has been corrected (PaCO2 of 40 mmHg or 5.3 kPa). The BE has a normal range of +2 to 2. A large positive BE indicates a severe metabolic alkalosis, while a large negative BE indicates a severe metabolic acidosis. As a result, the actual BE in vitro is unaffected by CO2.
In vivo, however, standard BE is not independent of pCO2 because blood with haemoglobin acts as a better buffer than total ECF.
As a result, it is impossible to tell the difference between compensating for a respiratory disorder and compensating for the presence of a primary metabolic disorder.
The differences between in vitro and in vivo behaviour can be mostly eliminated if the BE is calculated for a haemoglobin concentration of 50 g/L (the ‘effective’ or virtual value of Hb if it was distributed throughout the extracellular space) rather than the actual haemoglobin. Because haemoglobin has a lower buffering capacity, the standard BE is higher than the actual BE. It reflects the BE better in the extracellular space rather than just the intravascular compartment.
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This question is part of the following fields:
- Pathophysiology
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Question 18
Incorrect
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It was hypothesized that people that had lower socio economic status were more prone to developing gastric cancer. After 30 years of studying people with lower socio economic status, it was found that they did have a greater tendency to develop cancer. As a result of that the authors got to the conclusion that a strong association existed between the two. Later on another study conducted found that people from lower socio economic back grounds also had a tendency to be smokers.
Which form of potential bias can be associated with this particular study?Your Answer:
Correct Answer: Confounding bias
Explanation:Selection bias is when randomisation is not achieved and is often a result of in efficient recruiting method.
Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.
Measurement bias can be characterized by gathering of information in a manner that is distorted.
When the participants of a research study are recruited from the hospitals rather than the general population, its called Berkson Bias.
Confounding bias is the major player here because in this case the effects of smoking can be masked behind and can be read as outcomes of lower socio economic status. This extraneous factor (Smoking), distorts the founding.
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This question is part of the following fields:
- Statistical Methods
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Question 19
Incorrect
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Concerning the pathway of endothelial nitric oxide (eNO), one of the following best describes it.
Your Answer:
Correct Answer: Stimulation of guanylyl cyclase, increases cGMP concentration leading to vasodilation
Explanation:Nitric oxide (NO), an endothelial-derived relaxant factor (EDRF), is a powerful vasodilator. Its cell-signalling molecule is calcium-dependant and generated endogenous by nitric oxide synthetases from the precursor L-arginine, oxygen and NADPH. Three main isoforms have been isolated and they are inducible (iNO), neuronal (nNO) and endothelial (eNO).
Endothelial NO stimulates intracellular guanylyl cyclase which generates cyclic GMP (cGMP) from its action on guanylyl tri-phosphate (GTP). The cGMP goes on to activate protein kinase G (PKG). PKG phosphorylates cell membrane proteins that regulate intracellular calcium concentrations and level of calcium sensitisation.
Smooth muscle vasodilatation results from:
1. Light chain phosphatase activation.
2. Inhibition of calcium entry into the cell (reducing Ca2+ concentrations) and
3. Hyperpolarisation of cells by activation of H+ channels. -
This question is part of the following fields:
- Pathophysiology
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Question 20
Incorrect
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Regarding renal autoregulation, which of the following best describes its process?
Your Answer:
Correct Answer: Reduces the effect of changes in arterial blood pressure on renal Na+ excretion
Explanation:Two mechanisms are responsible for autoregulation of RBF and GFR: one mechanism that responds to changes in arterial pressure and another that responds to changes in [NaCl] in tubular fluid. Both regulate the tone of the afferent arteriole. The pressure-sensitive mechanism, the so-called myogenic mechanism, is related to an intrinsic property of vascular smooth muscle: the tendency to contract when stretched. Accordingly, when arterial pressure rises and the renal afferent arteriole is stretched, the smooth muscle contracts in response. Because the increase in resistance of the arteriole offsets the increase in pressure, RBF, and therefore GFR, remains constant.
The second mechanism responsible for autoregulation of GFR and RBF is the [NaCl]-dependent mechanism known as tubuloglomerular feedback. This mechanism involves a feedback loop in which a change in GFR leads to alteration in the concentration of NaCl in tubular fluid, which is sensed by the macula densa of the juxtaglomerular apparatus and converted into signals that affect afferent arteriolar resistance and thus the GFR (Fig. 33.19). For example, when the GFR increases and causes [NaCl] in tubular fluid in the loop of Henle to rise, more NaCl enters the macula densa cells in this segment (Fig. 33.20). This leads to an increase in formation and release of adenosine triphosphate (ATP) and adenosine (a metabolite of ATP) by macula densa cells, which causes vasoconstriction of the afferent arteriole and normalization of GFR. In contrast, when GFR and [NaCl] in tubule fluid decrease, less NaCl enters the macula densa cells, and both ATP and adenosine production and release decline. The fall in [ATP] and [adenosine] results in afferent arteriolar vasodilation, which returns GFR to normal. NO, a vasodilator produced by the macula densa, attenuates tubuloglomerular feedback, whereas angiotensin II enhances tubuloglomerular feedback. Thus the macula densa may release both vasoconstrictors (e.g., ATP and adenosine) and a vasodilator (e.g., NO) that oppose each other’s action at the level of the afferent arteriole. Production plus release of either vasoconstrictors or vasodilators ensures exquisite control over tubuloglomerular feedback.
Renal autoregulation, thus, reduces the effect of changes in arterial blood pressure on renal sodium excretion.
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This question is part of the following fields:
- Pathophysiology
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Question 21
Incorrect
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Which of the following is an expected change in pulmonary function seen during a moderate asthma attack?
Your Answer:
Correct Answer: Decreased forced expiratory volume in 1 sec (FEV1)
Explanation:Asthma is a lung condition that causes reversible narrowing and swelling of airway passages. It is classified by the frequency and severity of symptoms.
The following are symptoms of moderate asthma:
Symptoms include cough, wheezing, chest tightness, or difficulty breathing which occurs daily
Decreased activity levels due to flare-ups
Night-time symptoms 5 or more times a month
Lung function test FEV1 is 60-80% of predicted normal values
Peak flow has more than 30% variabilityWith moderate asthma attacks, the arterial pCO2 levels may decrease, but as severity increases, so does the pCO2, reaching normal levels, and then exceeding them in severe asthma attacks.
Airway obstruction increases the functional residual capacity.
Concentration of serum bicarbonate would not increase in moderate asthma, but it could possibly increase in life-threatening asthma via the same mechanism as what increases arterial PCO2.
FEV1 is a good measure of airway obstruction. and is reduced in acute asthma attacks.
In the case of a pneumothorax, a decrease in arterial PO2 is higher.
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This question is part of the following fields:
- Pathophysiology
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Question 22
Incorrect
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An acidic drug with a pKA of 4.3 is injected intravenously into a patient.
At a normal physiological pH, the approximate ratio of ionised to unionised forms of this drug in the plasma is?Your Answer:
Correct Answer: 1000:01:00
Explanation:The pH at which the drug exists in 50 percent ionised and 50 percent unionised forms is known as the pKa.
To calculate the proportion of ionised to unionised form of an ACID, use the Henderson-Hasselbalch equation.
pH = pKa + log ([A-]/[HA])
or
pH = pKa + log [(salt)/(acid)]
pH = pKa + log ([ionised]/[unionised]).Hence, if the pKa − pH = 0, then 50% of drug is ionised and 50% is unionised.
In this example:
7.4 = 4.3 + log ([ionised]/[unionised])
7.4 − 4.3 = log ([ionised]/[unionised])
log 3.1 = log ([ionised]/[unionised])Simply put, the antilog is the inverse log calculation. In other words, if you know the logarithm of a number, you can use the antilog to find the value of the number. The antilogarithm’s definition is as follows:
y = antilog x = 10x
Antilog to the base 10 of 0 = 1, 1 = 10, 2 =100, 3 = 1000, and 4 = 10,000.
If you want to find the antilogarithm of 3.1, for a number between 3 and 4, the antilogarithm will return a value between 1000 and 10,000. The ratio is 1:1 if pKa = pH, that is, pH pKa = log 0. (50 percent ionised and unionised).
According to the above value, there is only one unionised molecule for every approximately 1000 (1259) ionised molecules of this drug in plasma, implying that this drug is largely ionised in plasma (99.99 percent ).
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This question is part of the following fields:
- Pharmacology
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Question 23
Incorrect
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A 25-year old man needs an emergency appendicectomy and has gone to the operating room. During general anaesthesia, ventilation is achieved using a circle system with a fresh gas flow (FGF) of 1L/min, with and air/oxygen and sevoflurane combination. The capnograph trace is normal.
Changes to the end tidal and baseline CO2 measurements at 10 and 20 mins respectively are seen on the capnograph below:
10 minutes 20 minutes
End-tidal CO2 4.9 kPa 8.4 kPa
Baseline end-tidal CO2 0.2 kPa 2.4 kPa
The other vitals were as follows:
Pulse 100-105 beats per minute
Systolic blood pressure 120-133 mmHg
O2 saturation 99%.
The next most important immediate step is which of the following?Your Answer:
Correct Answer: Increase the FGF
Explanation:This scenario describes rebreathing management.
Changes is exhaustion of the soda lime and a progressive rise in circuit deadspace is the most likely explanation for the capnograph.
It is important that the soda lime canister is inspected for a change in colour of the granules. Initially fresh gas flow should be increased and then if necessary, replace the soda lime granules. Other strategies include changing to another circuit or bypassing the soda lime canister after the fresh gas flow is increased.
Any other causes of increased equipment deadspace should be excluded.
Intraoperative hypercarbia can be caused by:
1. Hypoventilation – Breathing spontaneously; drugs which include anaesthetic agents, opioids, residual neuromuscular blockade, pre-existing respiratory or neuromuscular disease and cerebrovascular accident.
2. Controlled ventilation- circuit leaks, disconnection, miscalculation of patient’s minute volume.
3. Rebreathing – Soda lime exhaustion with circle, inadequate fresh gas flow into Mapleson circuits, increased breathing system deadspace.
4. Endogenous source – Tourniquet release, hypermetabolic states (MH or thyroid storm) and release of vascular clamps.
5. Exogenous source – Absorption of CO2 absorption from the pneumoperitoneum. -
This question is part of the following fields:
- Physiology
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Question 24
Incorrect
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A 72-year-old man complains of severe, central abdominal pain that radiates to the back. He has a past medical history of an abdominal aortic aneurysm.
A focused abdominal ultrasonography test (FAST) is performed, revealing diffuse dilatation of the abdominal aorta. The most prominent dilatation is at the bifurcation site of abdominal aorta into the iliac arteries.
What vertebra level corresponds to the site of the most prominent dilatation as evident on the FAST scan?Your Answer:
Correct Answer: L4
Explanation:The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:
T12 – Coeliac trunk
L1 – Left renal artery
L2 – Testicular or ovarian arteries
L3 – Inferior mesenteric artery
L4 – Bifurcation of the abdominal aorta
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This question is part of the following fields:
- Anatomy
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Question 25
Incorrect
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Which of the following statements is true regarding prazosin?
Your Answer:
Correct Answer: Is a selective alpha 1 adrenergic receptor antagonist.
Explanation:Selective ?1 -Blockers like prazosin, terazosin, doxazosin, and alfuzosin cause a decrease in blood pressure with lesser tachycardia than nonselective blockers (due to lack of ?2 blocking action.
The major adverse effect of these drugs is postural hypotension. It is seen with the first few doses or on-dose escalation (First dose effect).
Its half-life is approximately three hours.
It is excreted primarily through bile and faeces (not through kidneys)
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This question is part of the following fields:
- Pharmacology
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Question 26
Incorrect
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The Kappa statistic (aka Cohen's kappa coefficient) can be used to measure which of the following?
Your Answer:
Correct Answer: Inter-rater reliability
Explanation:The Kappa Statistic or Cohen’s Kappa is a statistical measure of inter-rater reliability for categorical variables. It is used when two raters both apply a criterion based on a tool to assess whether or not some condition occur. A good example can be two doctors rating individuals for diabetes occurrence on the basis of symptoms.
It gives a quantitative measure of the magnitude of agreement between observers.
Kappa can take any value between 0 and 1. 0 implies the observers are in complete disagreement and a value of 1 implies complete agreement.
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This question is part of the following fields:
- Statistical Methods
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Question 27
Incorrect
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The SI unit of measurement is kgm2s-2 in the System international d'unités (SI).
Which of the following derived units of measurement has this format?Your Answer:
Correct Answer: Energy
Explanation:The derived SI unit of force is Newton.
F = m·a (where a is acceleration)
F = 1 kg·m/s2The joule (J) is a converted unit of energy, work, or heat. When a force of one newton (N) is applied over a distance of one metre (Nm), the following amount of energy is expended:
J = 1 kg·m/s2·m =
J = 1 kg·m2/s2 or 1 kg·m2·s-2The unit of velocity is metres per second (m/s or ms-1).
The watt (W), or number of joules expended per second, is the SI unit of power:
J/s = kg·m2·s-2/s
J/s = kg·m2·s-3Pressure is measured in pascal (Pa) and is defined as force (N) per unit area (m2):
Pa = kg·m·s-2/m2
Pa = kg·m-1·s-2 -
This question is part of the following fields:
- Physiology
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Question 28
Incorrect
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Tubes for vascular access and body cavity drainage are available in a variety of sizes.
When choosing an intravenous or intra-arterial cannula, which of the following measurements is used?Your Answer:
Correct Answer: Standard wire gauge (SWG)
Explanation:Standard wire gauge cannulas for intravenous and intraarterial use are available (SWG or G). The SWG is a former imperial unit (which requires metric conversion). The cross sectional area of wires is becoming more popular as a size measurement.
The number of wires that will fit into a standard hole template is referred to as SWG.
This standard sized hole can accommodate 22 thin wires side by side (each wire the diameter of a 22 gauge cannula)
In the same hole, 14 thicker wires would fit (each wire the diameter of a 14 gauge cannula)While the diameter and thus radius of a parallel sided tube are the most important determinants of fluid flow rate, they are not commonly used to compare cannula sizes.
The circumference of French gauge (FG) catheters (urinary or chest drains) is measured. Sizes of double lumen tracheal tubes are FG. Internal diameter is used to measure single lumen tubes.
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This question is part of the following fields:
- Pathophysiology
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Question 29
Incorrect
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Which of the following facts about T cells is true?
Your Answer:
Correct Answer: Secrete IL-2 when activated
Explanation:T cells function as a part of the body’s adaptive immune system. There are different types of T cells, including:
Cytotoxic T cells: Function as killer cells by releasing cytotoxic granules into the membrane of targeted cells.
T-Helper cells: When activated, they function to activate other immune cell types, assist in antibody production with B cells and releasing cytokines including IL-2.
Memory T cells: Function as to provide immune memory against already encountered antigens.
T cells possess specific glycoproteins and receptors on their surface.
T-Helper cells work with HLA class II antigens on the cell surfaces in order to recognise foreign antigens
T cells survive ranges from a few weeks, to a lifetime depending on the subtype in question.
Immunoglobulins are expressed on the surface of, and secreted by B-lymphocytes.
Native antigens are recognised by B cells. T cells only recognise antigens that have been processed by the cells and presented on the surface of the cell.
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This question is part of the following fields:
- Pathophysiology
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Question 30
Incorrect
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Because this benzodiazepine has a half-life of 2-4 hours, it is preferred for clinical use.
This benzodiazepine has which of the following properties that no other benzodiazepine has?Your Answer:
Correct Answer: It is water soluble at a pH of 3.5 and lipid soluble at a pH of 7.4
Explanation:Midazolam is the benzodiazepine in question. It’s the only benzodiazepine that undergoes tautomeric transformation (dynamic isomerism). The molecule is ionised and water soluble at pH 3.5, but when injected into the body at pH 7.4, it becomes unionised and lipid soluble, allowing it to easily pass through the blood brain barrier.
The half-life of midazolam is only 2-4 hours.
It is a GABAA receptor agonist because it is a benzodiazepine. GABAA receptors are found in abundance throughout the central nervous system, particularly in the cerebral cortex, hippocampus, thalamus, basal ganglia, and limbic system. GABAA receptors are ligand-gated ion channels, with the inhibitory neurotransmitter gamma-aminobutyric acid as the endogenous agonist. It is a pentameric protein (2, 2 and one subunit) that spans the cell membrane, and when the agonist interacts with the alpha subunit, a conformational change occurs, allowing chloride ions to enter the cell, resulting in neuronal hyperpolarization.
For status epilepticus, midazolam is not the drug of choice. Lorazepam is the benzodiazepine of choice for status epilepticus.
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This question is part of the following fields:
- Pharmacology
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