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  • Question 1 - A 63-year old man has palpitations and goes to the emergency room. An...

    Incorrect

    • A 63-year old man has palpitations and goes to the emergency room. An ECG shows tall tented T waves, which corresponds to phase 3 of the cardiac action potential.
      The shape of the T wave is as a result of which of the following?

      Your Answer: Repolarisation due to efflux of calcium

      Correct Answer: Repolarisation due to efflux of potassium

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
      45.1
      Seconds
  • Question 2 - Buffers are solutions that resist a change in pH when protons are produced...

    Correct

    • Buffers are solutions that resist a change in pH when protons are produced or consumed. They consist of weak acids and their conjugate bases. Buffers are also present in our bodies, and they are known as physiologic buffers.

      Which of these is the most effective buffer in the blood?

      Your Answer: Bicarbonate

      Explanation:

      The first line of defence against acid-base disorder is buffering. The blood mainly utilizes bicarbonate ion (HCO3-) for its buffering capacity (total of 53%, plasma and red blood cells combined).

      Strong acids, when acted upon by a buffer, release H+, which then combines to HCO3- and forms carbonic acid (H2CO3). When acted upon by the enzyme carbonic anhydrase, H2CO3 dissociates into H2O and CO.

      The rest are the percentage of utilization for the following buffers:
      Haemoglobin (by RBCs) – 35%
      Plasma proteins (by plasma) – 7%
      Organic phosphates (by RBCs) – 3%
      Inorganic phosphates (by plasma) – 2%

    • This question is part of the following fields:

      • Pharmacology
      445.6
      Seconds
  • Question 3 - A 5-year-old child is scheduled for squint surgery requiring general anaesthesia.

    To begin, she...

    Correct

    • A 5-year-old child is scheduled for squint surgery requiring general anaesthesia.

      To begin, she is given sevoflurane for the inhalation induction, then intravenous access is established along with the insertion of a supraglottic airway. Anaesthesia is maintained with fentanyl 1 mcg/kg, with an air/oxygen/sevoflurane mix with spontaneous respirations.

      Once the surgery begins, her pulse rate drastically reduces from 120 beats/min to 8 beats/min.

      What is the most appropriate next step for this patient?

      Your Answer: Tell surgeon to stop surgical retraction

      Explanation:

      This sudden change in pulse rate is due to the oculocardiac reflex. It is a >20% reduction in pulse rate as a result of placing pressure directly on the eyeball. The reflex arc has an afferent and efferent arm:

      The afferent (sensory) arm: The trigeminal nerve (CN V)

      The efferent arm: The vagus nerve (CN X)

      The most appropriate action is to ask the surgeon to stop retraction of the extraocular muscles, Assess for hypoxia, and give 100% oxygen if indicated.

      Atropine of glycopyrrolate can be administered to counteract the reflex, and also prevent any further vagal reflexes.

      Administration of fentanyl may increase patient’s risk of bradycardia and sinus arrest in this case.

      Adrenaline is not indicated here as other treatment options will provide sufficient relief from arrhythmia.

    • This question is part of the following fields:

      • Pathophysiology
      21.6
      Seconds
  • Question 4 - A 67-year-old man, presents with an embolus in the lower limbs. He has...

    Correct

    • A 67-year-old man, presents with an embolus in the lower limbs. He has previous medical history of atrial fibrillation. After examination and diagnostic investigations, he is scheduled for a transpopliteal embolectomy, which will require the surgeons to explore the central region of the popliteal fossa.

      What structures will the surgeons come across after incising the deep fascia?

      Your Answer: Tibial nerve

      Explanation:

      The tibial nerve lies on top of the vessels contained within the inferior aspect of the popliteal fossa.

      In the superior aspect of the fossa, the tibial nerve runs lateral to the vessels, before then travelling superficial to the vessels, and then finally changing course to lie medial to the vessels.

      The popliteal artery is the most deep structure present in the popliteal fossa

    • This question is part of the following fields:

      • Anatomy
      7
      Seconds
  • Question 5 - A caudal anaesthetic block is planned for a 3-year-old girl presenting for inguinal...

    Correct

    • A caudal anaesthetic block is planned for a 3-year-old girl presenting for inguinal hernia repair. Choose the best answer that explains why the caudal epidural space is accessed via the sacral hiatus.

      Your Answer: The failure of fusion of the laminae of S4 and S5 provides a suitable point of entry

      Explanation:

      The sacral hiatus is shaped by incomplete midline fusion of the posterior elements of the distal portion of S4 and S5. This inverted U shaped space is covered by the posterior aspect of the sacrococcygeal membrane and is an important landmark in caudal anaesthetic block. Distal most portion of the dural sac and the sacral hiatus usually terminate between levels S1 and S3. The dural sac ends at the level of S2 in adults and S3 in children.

      An equilateral triangle is formed between the apex of the sacral hiatus and the posterior superior iliac spines. This triangle is used to determine the location of the sacral hiatus during caudal anaesthetic block.

    • This question is part of the following fields:

      • Anatomy
      13.7
      Seconds
  • Question 6 - During a stabbing incident, a 30-year-old injured his inferior vena cava. What number...

    Correct

    • During a stabbing incident, a 30-year-old injured his inferior vena cava. What number of functional valves can be usually found in this vessel?

      Your Answer: 0

      Explanation:

      The inferior vena cava is formed by the union of the right and left common iliac veins. The inferior vena cava has no functional valves like the one-way valves commonly found in many veins. The forward flow to the heart is driven by the differential pressure created by normal respiration.

      The absence of functional valves has an important clinical role when cannulating during cardiopulmonary bypass.

      There is a valve that is non-functioning called the eustachian valve that lies at the junction of the IVC and the right atrium. This valve has a role to help direct the flow of oxygen-rich blood through the right atrium to the left atrium via the foramen ovale during fetal life. It has no specific function in adult life.

    • This question is part of the following fields:

      • Anatomy
      5.6
      Seconds
  • Question 7 - During 2015 it was reported in the New England Journal of Medicine that...

    Correct

    • During 2015 it was reported in the New England Journal of Medicine that the usage of empagliflozin(a sodium-glucose-co-transporter 2 inhibitor) caused a decrease in the cardiovascular deaths, non fatal heart attacks and strokes in patients suffering from type 2 diabetes. The results were published per 1000 patient years. With the above mentioned drug, the event rate turned out to be 37.3/1000 patient years whereas the placebo had an event rate of 43.9/1000 patient years.

      How many further patients need to be treated with empagliflozin to avoid any further incidence of cardiovascular death or non fatal myocardial infraction and non fatal stroke?

      Your Answer: 150

      Explanation:

      Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.

      It can be found as:

      NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).

      where ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)

      So,

      ARR= (43.9-37.3)

      ARR= 6.6

      NNT= 1000/6.6

      NNT=151.5

    • This question is part of the following fields:

      • Statistical Methods
      14.2
      Seconds
  • Question 8 - The rapid depolarisation phase of the myocardial action potential is caused by: ...

    Incorrect

    • The rapid depolarisation phase of the myocardial action potential is caused by:

      Your Answer: Slow efflux of calcium

      Correct Answer: Rapid sodium influx

      Explanation:

      The cardiac action potential has several phases which have different mechanisms of action as seen below:
      Phase 0: Rapid depolarisation – caused by a rapid sodium influx.
      These channels automatically deactivate after a few ms

      Phase 1: caused by early repolarisation and an efflux of potassium.

      Phase 2: Plateau – caused by a slow influx of calcium.

      Phase 3 – Final repolarisation – caused by an efflux of potassium.

      Phase 4 – Restoration of ionic concentrations – The resting potential is restored by Na+/K+ATPase.
      There is slow entry of Na+into the cell which decreases the potential difference until the threshold potential is reached. This then triggers a new action potential

      Of note, cardiac muscle remains contracted 10-15 times longer than skeletal muscle.

      Different sites have different conduction velocities:
      1. Atrial conduction – Spreads along ordinary atrial myocardial fibres at 1 m/sec

      2. AV node conduction – 0.05 m/sec

      3. Ventricular conduction – Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec, the fastest conduction in the heart. This allows a rapid and coordinated contraction of the ventricles

    • This question is part of the following fields:

      • Physiology And Biochemistry
      34.6
      Seconds
  • Question 9 - A patient under brachial plexus regional block complains of pain under the cuff...

    Correct

    • A patient under brachial plexus regional block complains of pain under the cuff after the torniquet is inflated.

      Which nerve was most probably 'missed' by the local anaesthetic?

      Your Answer: Intercostobrachial nerve

      Explanation:

      The area described in the question is supplied by the intercostobrachial nerve, which provides sensory innervation to the portions of the axilla, tail of the breast, lateral chest wall and medial side of the arm.

      It is a common for it to be ‘missed’ during administration of local anaesthesia because of its very superficial anatomic course. It may be anesthetized by giving an analgesia from the upper border of the biceps at the anterior axillary fold, to the margin of the triceps by the axillary floor.

    • This question is part of the following fields:

      • Pathophysiology
      9.1
      Seconds
  • Question 10 - Which of the following statement is correct regarding the difference between dabigatran and...

    Incorrect

    • Which of the following statement is correct regarding the difference between dabigatran and other anticoagulants?

      Your Answer: Active orally

      Correct Answer: Competitive thrombin inhibitor blocking both free and bound thrombin

      Explanation:

      Dabigatran template is a prodrug and its active metabolite is a direct thrombin inhibitor. It is a synthetic, reversible, non-peptide thrombin inhibitor. This inhibition of thrombin results in a decrease of fibrin and reduces platelet aggregation.

      Drugs like warfarin act by inhibiting the activation of vitamin K-dependent clotting factors. These factors are synthesized by the liver and activated by gamma-carboxylation of glutamate residues with the help of vitamin K. Hydroquinone form of vitamin K is converted to epoxide form in this reaction and regeneration of hydroquinone form by enzyme vitamin K epoxide reductase (VKOR) is required for this activity. Oral anticoagulants prevent this regeneration by inhibiting VKOR, thus vitamin K-dependent factors are not activated. These factors include clotting factors II, VII, IX, and X as well as anti-clotting proteins, protein C and protein S.

    • This question is part of the following fields:

      • Pharmacology
      22.1
      Seconds
  • Question 11 - A 79-year-old female complains of painful legs, especially in her thigh region. The...

    Correct

    • A 79-year-old female complains of painful legs, especially in her thigh region. The pain starts after walking and settles with rest. She occasionally has to take paracetamol to relieve the pain. She is a known case of hyperlipidaemia, type 2 diabetes mellitus, hypertension, and depression.

      Her physician makes a provisional diagnosis of claudication of the femoral artery, which is a continuation of the external iliac artery.
      Which of the following anatomical landmarks does the external iliac artery cross to become the femoral artery?

      Your Answer: Inguinal ligament

      Explanation:

      The external iliac artery is the larger of the two branches of the common iliac artery. It forms the main blood supply to the lower limbs. The common iliac bifurcates into the internal and external iliac artery anterior to the sacroiliac joint.

      The external iliac artery courses on the medial border of the psoas major muscles and exits the pelvic girdle posterior to the inguinal ligament. Here, midway between the anterior superior iliac spine and the pubic symphysis, the external iliac artery becomes the femoral artery and descends along the anteromedial part of the thigh in the femoral triangle.

      The pectineus forms the posterior border of the femoral canal.
      The femoral vein forms the lateral border of the femoral canal.
      The medial border of the adductor longus muscle forms the medial wall of the femoral triangle.
      The medial border of the sartorius muscle forms the lateral wall of the femoral triangle.

    • This question is part of the following fields:

      • Anatomy
      23.7
      Seconds
  • Question 12 - Left ventricular afterload is mostly calculated from systemic vascular resistance.

    Which...

    Correct

    • Left ventricular afterload is mostly calculated from systemic vascular resistance.

      Which one of the following factors has most impact on systemic vascular resistance?

      Your Answer: Small arterioles

      Explanation:

      Systemic vascular resistance (SVR), also known as total peripheral resistance (TPR), is the amount of force exerted on circulating blood by the vasculature of the body. Three factors determine the force: the length of the blood vessels in the body, the diameter of the vessels, and the viscosity of the blood within them. The most important factor that determines the systemic vascular resistance (SVR) is the tone of the small arterioles.

      These are otherwise known as resistance arterioles. Their diameter ranges between 100 and 450 µm. Smaller resistance vessels, less than 100 µm in diameter (pre-capillary arterioles), play a less significant role in determining SVR. They are subject to autoregulation.

      Any change in the viscosity of blood and therefore flow (such as due to a change in haematocrit) might also have a small effect on the measured vascular resistance.

      Changes of blood temperature can also affect blood rheology and therefore flow through resistance vessels.

      Systemic vascular resistance (SVR) is measured in dynes·s·cm-5

      It can be calculated from the following equation:

      SVR = (mean arterial pressure − mean right atrial pressure) × 80 cardiac output

    • This question is part of the following fields:

      • Physiology
      14.5
      Seconds
  • Question 13 - A 70-year-old male presented to an outpatient clinic with a complaint of a...

    Correct

    • A 70-year-old male presented to an outpatient clinic with a complaint of a lump in his groin. Physical examination reveals the lumps increase in size while coughing and reduces in size after lying down flat. Based on his age and examination, a diagnosis of direct inguinal hernia was made.
      Which structures does the bowel pass through in order to be classed as direct inguinal hernia?

      Your Answer: Hesselbach's triangle

      Explanation:

      A hernia is a protrusion of the abdominal viscera through a defect in the abdominal wall. Inguinal hernias are of two types; Indirect inguinal hernia and Direct inguinal hernia.
      – Indirect inguinal hernia is common at young age commonly due to a patent processes vaginalis and bowel passes through the deep inguinal ring lateral to the inferior epigastric artery.
      – Direct hernia forms as a result of the weakening of the posterior wall of the inguinal canal more specifically within a region called ‘Hasselbach triangle. It is defined medially by the rectus abdominis muscle, laterally by the epigastric vessels, and inferiorly by the inguinal ligament.

      Direct and indirect hernias can be differentiated based on their relation to the inferior epigastric artery. Direct inguinal hernia lies medial to it while indirect inguinal hernia lies lateral to the inferior epigastric artery.

      The femoral ring is the site of the femoral hernia.

    • This question is part of the following fields:

      • Anatomy
      5.5
      Seconds
  • Question 14 - A 72-year-old long-term rheumatoid arthritis patient is having shoulder replacement surgery.

    He has chronic...

    Correct

    • A 72-year-old long-term rheumatoid arthritis patient is having shoulder replacement surgery.

      He has chronic obstructive pulmonary disease with a limited exercise tolerance. He agrees to the procedure being performed with an interscalene brachial plexus block.

      Which of the following neurological complications puts this patient at the greatest risk?

      Your Answer: Phrenic nerve block

      Explanation:

      An ipsilateral phrenic nerve block will result from a successful interscalene block (ISB).

      The phrenic nerve is the diaphragm’s sole motor supply, and ipsilateral hemidiaphragmatic paresis affects up to 100% of patients who receive ISBs. Phrenic nerve palsy is usually well tolerated and goes unnoticed by healthy people. However, forced vital capacity decreases by approximately 25%, which can produce ventilatory compromise in patients with limited pulmonary reserve, requiring assisted ventilation.

      Vocal cord palsy occurs when the recurrent laryngeal nerve is inadvertently blocked, causing hoarseness and possibly acute respiratory insufficiency. Unless bilateral laryngeal nerve palsy occurs, which can cause severe laryngeal obstruction, this complication is usually of little consequence.

      ISB can also cause cranial nerve X and XII palsy (Tapia’s syndrome). One-sided cord paralysis, aphonia, and the patient’s tongue deviating toward the block’s side are all symptoms.

      When a local anaesthetic spreads to the stellate ganglion and its cervical sympathetic nerves, Horner’s syndrome can develop. Ptosis of the eyelid, miosis, and anhidrosis of the face are all symptoms. Horner’s syndrome, on the other hand, may not indicate that the brachial plexus is sufficiently blocked.

    • This question is part of the following fields:

      • Pathophysiology
      6.5
      Seconds
  • Question 15 - All of the following are causes of hypalbuminaemia except: ...

    Correct

    • All of the following are causes of hypalbuminaemia except:

      Your Answer: Starvation

      Explanation:

      Major surgery induces the systemic inflammatory response and this causes endothelial leakage and a low albumin level.

      Albumin is a single polypeptide which is made but not stored in the liver. Therefore, levels are a reflection of synthetic activity. It is negatively charged and very soluble.

      Only 40% of albumin is intravascular, and the rest in the in interstitial compartment.

      If there was normal liver function during starvation, albumin will be maintained and proteolysis will occur elsewhere.
      It is not catabolised during starvation.
      Starvation and malnutrition may, however, present as part of other disease processes that are associated with hypalbuminaemia.

      Causes of low albumin are

      1. Decreased production (hepatic dysfunction)
      2. Increased loss (renal dysfunction)
      3. Redistribution (endothelial leak/damage)
      4. Increased catabolism (very rare)

    • This question is part of the following fields:

      • Physiology And Biochemistry
      6
      Seconds
  • Question 16 - Which muscle separates the subclavian artery and the subclavian vein? ...

    Correct

    • Which muscle separates the subclavian artery and the subclavian vein?

      Your Answer: Scalenus anterior

      Explanation:

      The subclavian artery and vein have a similar path throughout their course, with the subclavian vein running anterior to the subclavian artery. The artery and vein are separated by the insertion of the scalenus anterior muscle.

      There are three scalene muscles, found on each side of the neck:
      1. Anterior scalene
      2. Middle scalene
      3. Posterior scalene

      The scalenus anterior muscle is the anterior most of the three scalene muscles. It originates from the transverse processes of vertebrae C3-C6 and is inserted in the first rib.

    • This question is part of the following fields:

      • Anatomy
      8.5
      Seconds
  • Question 17 - A 24-year old female is brought to the emergency room due to urticarial...

    Correct

    • A 24-year old female is brought to the emergency room due to urticarial rash and shortness of breath. Her mother reported that, prior to the symptoms, she took Co-amoxiclav (Augmentin) for her present ear infection. She also reported that she had no previous exposure to penicillin or any other related antibiotics.

      Which of the following can help to differentiate between type 1 and type II hypersensitivity reaction in this case?

      Your Answer: IgE assay specific for amoxycilloyl

      Explanation:

      Serum specific IgE assays against allergen sources/molecules are the most commonly used in vitro diagnostic approach. The measurement of specific IgE recognizing allergenic epitopes can be achieved both through the usage of single reagents (singleplex) or with a pre-defined panel of a number of molecules to be tested simultaneously (multiplex).

      Several clinical entities have been described and those occurring immediately after drug exposure are immunoglobulin E (IgE)-mediated and explored by skin testing and by the in vitro measurement of serum-specific IgE. The sensitivity of these tests is not 100% and even for patients with a clear positive history, a drug provocation test may be required in order to confirm the diagnosis. The advantages of the in vitro determination of specific IgE antibodies when compared with in vivo testing are that the former poses no direct risk to the patient and does not require personnel with expertise. Even though in vitro tests are recommended in immediate hypersensitivity reactions, their exact place in the diagnostic procedure is not clear and certain authors do not use this method in daily practice. In one study, in terms of sensitivity, 11 of 26 patients (42%) with negative skin tests and a positive drug provocation challenge (or repeated clinical history) had specific IgE to benzylpenicilloyl or amoxicilloyl (4). The specificity of the test was 95–100%. Therefore, IgE measurements can avoid a potentially harmful drug provocation test.

      An elevated serum tryptase does not differentiate between type 1 and type 2 hypersensitivity reaction. It indicates mast cell degranulation.

      RAST is a useful aid to improve the overall diagnosis of drug allergies by using radioactive detection. This, however, is now rarely used.

      Quantification of basophil activation by CD63 expression can be done by flow cytometry, which forms the basis of experimental drug-induced basophil stimulation tests.

    • This question is part of the following fields:

      • Pathophysiology
      26.2
      Seconds
  • Question 18 - A chain smoker is interested in knowing how many years of his life...

    Incorrect

    • A chain smoker is interested in knowing how many years of his life would be lessened by smoking. You tell him explicitly that precise determination is impossible but you can tell him the proportion of people who died due to smoking. Which of the following epidemiological term is apt in this regard?

      Your Answer: Attributable proportion - the risk of an event relative to exposure.

      Correct Answer: Attributable risk - the rate in the exposed group minus the rate in the unexposed group

      Explanation:

      Attributable proportion is the proportion of disease that is caused due to exposure. It refers to the proportion of disease that would be eradicated from a particular population if the disease rate was diminished to match that of the unexposed group.

      Risk ratio (relative risk) compares the probability of an event in an exposed (experimental) group to that of an event in the unexposed (control) group. Thus two are not the same.

      The attributable risk is the rate of a disease in an exposed group to that of a group that has not been exposed to it i.e. how many deaths did the exposure cause.

    • This question is part of the following fields:

      • Statistical Methods
      23.7
      Seconds
  • Question 19 - In medical testing, there are true negative, true positive, false positive and false...

    Correct

    • In medical testing, there are true negative, true positive, false positive and false negative results for some test.

      How are the sensitivity of these predictive tests calculated?

      Your Answer: True positives / (true positives + false negatives)

      Explanation:

      The following terms are used in medical testing:

      True negative – The test is negative and the patient does not have the disease.
      True positive – The test is positive and the patient has the disease.
      False positive – The test is positive but the patient does not have the disease.
      False negative – The test is negative but the patient has the disease.

      The sensitivity of a predictive test = true positives / (true positives + false negatives).

      The specificity of a test = true negatives / (false positives + true negatives).

      The negative predictive value of a test = true negatives / (false negatives + true negatives).

    • This question is part of the following fields:

      • Statistical Methods
      27.6
      Seconds
  • Question 20 - A 25-year old lady is in the operating room and has had general...

    Correct

    • A 25-year old lady is in the operating room and has had general anaesthesia for a knee arthroscopy.

      Induction was done with fentanyl 1mcg/kg and propofol 2mg/kg. A supra-glottic airway was inserted and using and air oxygen mixture with 2.5% sevoflurane, her anaesthesia was maintained. The patient is allowed to spontaneously breathe using a Bain circuit, and the fresh gas flow is 9L/min. Over the next 30 minutes, the end-tidal Co2 rises from 4.5kPa to 8.4kPa, and the baseline reading on the capnograph is 0kPa.

      The most appropriate initial action is which of the following?

      Your Answer: Hypoventilation

      Explanation:

      The commonest and most likely cause of a gradual rise in end-tidal CO2 (EtCO2) occurring during anaesthesia in a spontaneously breathing patient is hypoventilation. This occurs from the respiratory depressant effects of the opioid and sevoflurane.

      Malignant hyperthermia should be sought if the EtCO2 shows further progressive rise.

      Causes of rebreathing and a rise in the baseline of the capnograph can be caused by exhausted soda lime and inadequate fresh gas flow into the Bain circuit.

      A sudden rise in EtCO2 can be caused deflation of the tourniquet.

    • This question is part of the following fields:

      • Physiology
      12.5
      Seconds
  • Question 21 - Which statement regarding the cardiac action potential is correct? ...

    Incorrect

    • Which statement regarding the cardiac action potential is correct?

      Your Answer: The absolute refractory period is in Phase 3

      Correct Answer:

      Explanation:

      Cardiac conduction

      Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium

      Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop

      Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period

      Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period

      Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period

    • This question is part of the following fields:

      • Physiology And Biochemistry
      22.3
      Seconds
  • Question 22 - The spinal cord tracts that transmits the sensations of pain, crude temperature, and...

    Correct

    • The spinal cord tracts that transmits the sensations of pain, crude temperature, and light touch is?

      Your Answer: Spinothalamic

      Explanation:

      Dorsal column (ascending tract) – Proprioception, vibration, discriminative

      Spinocerebellar (ascending tract) – Subconscious muscle position and tone

      Corticospinal (descending tract) – Voluntary muscle

      Rubrospinal (descending tract) – Flexor muscle tone

      Vestibulospinal (descending tract) – Reflexes and muscle tone

      Reticulospinal(descending tract) – Voluntary movements, head position.-

      Autonomic – Descending tract.

    • This question is part of the following fields:

      • Anatomy
      5.6
      Seconds
  • Question 23 - A young male is operated on for an open inguinal hernia repair. During...

    Incorrect

    • A young male is operated on for an open inguinal hernia repair. During the procedure, the cord is mobilized, and the deep inguinal ring is located.

      What structure forms the lateral wall of the deep inguinal ring?

      Your Answer: Inferior epigastric artery

      Correct Answer: Transversalis fascia

      Explanation:

      The deep inguinal ring is the entrance of the inguinal canal. It is an opening in the transversalis fascia around 1 cm above the inguinal ligament. Therefore, the superolateral wall is made by the transervalis fascia.

      The inferior epigastric vessels run medially to the deep inguinal ring forming its inferomedial border.

      The inguinal canal extends obliquely from the deep inguinal ring to the superficial inguinal ring.
      An indirect inguinal hernia arises through the deep inguinal ring lateral to the inferior epigastric vessels.

    • This question is part of the following fields:

      • Anatomy
      8.4
      Seconds
  • Question 24 - A transport ventilator is powered by an air/oxygen mix using a full oxygen...

    Correct

    • A transport ventilator is powered by an air/oxygen mix using a full oxygen cylinder (class CD) with an internal capacity of 2 litres, and pressure of 23,000 kPa, with a gas flow of 4 litres/minute.
      The ventilator also has a control resulting in an additional gas consumption of 1 litre/minute.

      How long will it take for the cylinder to empty?

      Your Answer: 92 minutes

      Explanation:

      The Drager Oxylog® 1000 is a pneumatically powered, time-dependent, volume-titrated emergency ventilator with a pressure limit. It is compatible with CD cylinder oxygen. The CD cylinder is a strong and lightweight cylinder usually composed of aluminium or Kevlar. The internal cylinder volume is 2 litres, and the pressure of a full cylinder is 230 bar. The volume of the full cylinder is determined by applying Boyle’s law: P1 × V1 = P2 × V2

      Where:
      P1= pressure of a full cylinder (230 bar)
      V1= volume of oxygen at that pressure (2 litres)
      P2= final pressure (1 bar), and
      V2= volume of oxygen in the full cylinder.

      Substituting values into the equation:

      230 × 2 = 1 x V2
      V2 = 460 litres. The flow of fresh gas is 4 litres/minute + 1 litre/minute required by the control, making a total of 5 litres/minute. The amount of time it takes for the cylinder to empty would be the total volume of oxygen in the full cylinder divided by the amount of oxygen expelled per minute: 460/5 = 92, meaning it would take 92 minutes for the cylinder to empty.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      8.5
      Seconds
  • Question 25 - A paediatric patient was referred to the surgery department after an initial assessment...

    Correct

    • A paediatric patient was referred to the surgery department after an initial assessment of acute gastroenteritis was proven otherwise to be a case acute appendicitis. History revealed multiple episodes of non-bloody emesis. In the paediatric ward, the patient had already undergone fluid resuscitation and replacement, and electrolytes were already corrected. Other pertinent laboratory studies were the following:

      Serum Na: 138 mmol/l
      Blood glucose: 6.4 mmol/l

      If the patient weighed 25 kg, which intravenous fluid maintenance regimen would be best for the child?

      Your Answer: 65 ml/hr Hartmann's solution with 0% glucose

      Explanation:

      Maintenance therapy aims to replace water and electrolytes lost under ordinary conditions. In the perioperative period, maintenance fluid administration may not sufficiently account for the increased fluid requirements caused by third-space losses into the interstitium and gut. Specific recommendations vary with the patient, the procedure, and the type and amount of fluid administered during the operation. The fluid for maintenance therapy replaces deficits arising primarily from insensible losses and urinary or gastrointestinal (GI) losses.

      The maintenance fluid volume can be computed using the Holliday-Segar method.

      Body weight Fluid volume
      first 10 kg 4 ml/kg/hr
      next 10-20 kg 2 ml/kg/hr
      >20 kg 1 ml/kg/hr

      In the past few years, there has been growing recognition of the increased risk of hyponatremia in hospitalized children in intensive care and postoperative settings who receive hypotonic maintenance fluids. Several studies, including a randomized controlled trial and a Cochrane analysis, found that the use of isotonic fluids is associated with fewer electrolyte derangements and concluded that isotonic maintenance fluids are preferable to hypotonic solutions in hospitalized children.

      A European consensus statement suggests that an intraoperative fluid should have an osmolarity close to the physiologic range in children in order to avoid hyponatremia, an addition of 1-2.5% in order to avoid hypoglycaemia, lipolysis or hyperglycaemia and should also include metabolic anions as bicarbonate precursors to prevent hyperchloremic acidosis.

      A rate of 40 ml/hr is suboptimal.

      If 0.9% NaCl with 0% glucose is given at a rate of 65 ml/hr, despite of the correct infusion rate, large volumes can lead to hyperchloremic acidosis.

      If 0.18% NaCl with 4% glucose is given at a rate of 65 ml/hr, infusion of this fluid regimen can lead to hyponatremia because of its hypotonicity.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      37.1
      Seconds
  • Question 26 - Which of the following is the most appropriate first-line pharmacologic treatment for status...

    Correct

    • Which of the following is the most appropriate first-line pharmacologic treatment for status epilepticus?

      Your Answer: Lorazepam

      Explanation:

      Lorazepam is an intermediate-acting benzodiazepine that binds to the GABA-A receptor subunit to increase the frequency of chloride channel opening and cause membrane hyperpolarization.

      Lorazepam has emerged as the preferred benzodiazepine for acute management of status epilepticus. Lorazepam differs from diazepam in two important respects. It is less lipid-soluble than diazepam, with a distribution half-life of two to three hours versus 15 minutes for diazepam. Therefore, it should have a longer duration of clinical effect. Lorazepam also binds the GABAergic receptor more tightly than diazepam, resulting in a longer duration of action. The anticonvulsant effects of lorazepam last six to 12 hours, and the typical dose ranges from 4 to 8 mg. This agent also has a broad spectrum of efficacy, terminating seizures in 75-80% of cases. Its adverse effects are identical to those of diazepam. Thus, lorazepam also is an effective choice for acute seizure management, with the added possibility of a longer duration of action than diazepam.

      Phenobarbitone is a long-acting barbiturate that binds to GABA-A receptor site and increase the duration of chloride channel opening. It also blocks glutamic acid neurotransmission, and, at high doses, can block sodium channels. It is considered as the drug of choice for seizures in infants.

      Phenytoin is an anti-seizure drug that blocks voltage-gated sodium channels. It is preferred in prolonged therapy of status epilepticus because it is less sedating.

      In cases wherein airway protection is required, thiopentone and propofol are the preferred drugs.

    • This question is part of the following fields:

      • Pharmacology
      5.8
      Seconds
  • Question 27 - General anaesthesia is administered to a patient in a hospital in Lhasa which...

    Correct

    • General anaesthesia is administered to a patient in a hospital in Lhasa which is one of the highest cities in the world (at 11,975 feet). An Anaesthetic rotameter is normally calibrated at 20 C and 1 bar pressure and is known to be underread at altitude. The temperature of the theatre was 10 C.

      Which one of the following physical properties is responsible for the rotameter inaccuracy in these conditions?

      Your Answer: Density of the gas

      Explanation:

      Since the gas is less dense at higher altitudes, the density of a gas influences flows when passing through the orifice. Due to this reason, for a given flow rate, the bobbin will not be forced as far up the rotameter tube.

      At higher altitudes, the volume of a fixed mass of gas increases, and therefore the molecules of gas are widely spaced resulting in a decrease in density with an increase in altitude.

      Viscosity is simply termed as friction of gas. The viscosity of a gas is important only at low flow rates when the flow characteristic of the gas is laminar.

      Charle’s law stated that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature (T) provided the pressure remains constant.

      Boyle’s law for a fixed amount of gas at constant temperature, the pressure (P) and volume (V) are inversely proportional.

    • This question is part of the following fields:

      • Basic Physics
      13.3
      Seconds
  • Question 28 - A current flows through a simple electric circuit.

    Which of the following electrical component...

    Incorrect

    • A current flows through a simple electric circuit.

      Which of the following electrical component configurations has the greatest potential difference?

      Your Answer: One resistor of 5 ohm with a passing current of 10 ampere

      Correct Answer: Two 5 ohm resistors in series with a passing current of 10 ampere

      Explanation:

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      17.6
      Seconds
  • Question 29 - A strict diet is mandatory for which of the following drugs for mood...

    Correct

    • A strict diet is mandatory for which of the following drugs for mood disorders?

      Your Answer: Tranylcypromine

      Explanation:

      Tranylcypromine is a monoamine oxidase inhibitor that binds irreversibly to target enzyme.

      Monoamine oxidase inhibitors are responsible for blocking the monoamine oxidase enzyme. The monoamine oxidase enzyme breaks down different types of neurotransmitters from the brain: norepinephrine, serotonin, dopamine, and tyramine. MAOIs inhibit the breakdown of these neurotransmitters thus, increasing their levels and allowing them to continue to influence the cells that have been affected by depression.

      There are two types of monoamine oxidase, A and B. The MAO A is mostly distributed in the placenta, gut, and liver, but MAO B is present in the brain, liver, and platelets. Serotonin and noradrenaline are substrates of MAO A, but phenylethylamine, methylhistamine, and tryptamine are substrates of MAO B. Dopamine and tyramine are metabolized by both MAO A and B. Selegiline and rasagiline are irreversible and selective inhibitors of MAO type B, but safinamide is a reversible and selective MAO B inhibitor.

      MAOIs prevent the breakdown of tyramine found in the body and certain foods, drinks, and other medications. Patients that take MAOIs and consume tyramine-containing foods or drinks will exhibit high serum tyramine level. A high level of tyramine can cause a sudden increase in blood pressure, called the tyramine pressor response. Even though it is rare, a high tyramine level can trigger a cerebral haemorrhage, which can even result in death.

      Eating foods with high tyramine can trigger a reaction that can have serious consequences. Patients should know that tyramine can increase with the aging of food; they should be encouraged to have fresh foods instead of leftovers or food prepared hours earlier. Examples of high levels of tyramine in food are types of fish and types of meat, including sausage, turkey, liver, and salami. Also, certain fruits can contain tyramine, like overripe fruits, avocados, bananas, raisins, or figs. Further examples are cheeses, alcohol, and fava beans; all of these should be avoided even after two weeks of stopping MAOIs. Anyone taking MAOIs is at risk for an adverse hypertensive reaction, with accompanying morbidity. Patients taking reversible MAOIs have fewer dietary restrictions.

      Amitriptyline is a tricyclic antidepressant, and citalopram and escitalopram are selective serotonin reuptake inhibitors.

    • This question is part of the following fields:

      • Pharmacology
      10.3
      Seconds
  • Question 30 - In a normal healthy adult breathing 100 percent oxygen, which of the following...

    Correct

    • In a normal healthy adult breathing 100 percent oxygen, which of the following is the most likely cause of an alveolar-arterial (A-a) oxygen difference of 30 kPa?

      Your Answer: Atelectasis

      Explanation:

      The ‘ideal’ alveolar PO2 minus arterial PO2 is the alveolar-arterial (A-a) oxygen difference.

      The ‘ideal’ alveolar PO2 is derived from the alveolar air equation and is the PO2 that the lung would have if there was no ventilation-perfusion (V/Q) inequality and it was exchanging gas at the same respiratory exchange ratio as real lung.

      The amount of oxygen in the blood is measured directly in the arteries.

      The A-a oxygen difference (or gradient) is a useful measure of shunt and V/Q mismatch, and it is less than 2 kPa in normal adults breathing air (15 mmHg). Because the shunt component is not corrected, the A-a difference increases when breathing 100 percent oxygen, and it can be up to 15 kPa (115 mmHg).

      An abnormally low or abnormally high V/Q ratio within the lung can cause an increased A-a difference, though the former is more common. Atelectasis, which results in a low V/Q ratio, is the most likely cause of an A-a difference in a healthy adult breathing 100 percent oxygen.

      Hypoventilation may cause an increase in alveolar (and thus arterial) CO2, lowering alveolar PO2 according to the alveolar air equation.

      The alveolar PO2 is also reduced at high altitude.

      Healthy people are unlikely to have a right-to-left shunt or an oxygen transport diffusion defect.

    • This question is part of the following fields:

      • Physiology
      42.3
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Physiology And Biochemistry (2/5) 40%
Pharmacology (3/4) 75%
Pathophysiology (4/4) 100%
Anatomy (7/8) 88%
Statistical Methods (2/3) 67%
Physiology (3/3) 100%
Anaesthesia Related Apparatus (1/2) 50%
Basic Physics (1/1) 100%
Passmed