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Question 1
Incorrect
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All of the following options describes a thermistor for the measurement of temperature except:
Your Answer: Two dissimilar metals are joined in a Thermocouple
Correct Answer: Resistance of the bead increases exponentially as the temperature increases
Explanation:There are different types of temperature measurement. These include:
Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially
Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)
Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature
Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output
Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.
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This question is part of the following fields:
- Clinical Measurement
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Question 2
Incorrect
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Among the following which one is not a criterion for the assessment of causality?
Your Answer: Temporality
Correct Answer: Sensitivity
Explanation:For establishing a cause effect relationship, following criteria must be met:
1. Coherence & Consistency
2. Temporal Precedence
3. Specificity
As can be seen, sensitivity (The probability of a positive test) is not among these deciding factors..
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This question is part of the following fields:
- Statistical Methods
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Question 3
Correct
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You're summoned to the emergency room, where a 39-year-old man has been admitted following a cardiac arrest. He was rescued from a river, but little else is known about him.
CPR is being performed on the patient, who has been intubated. He's received three DC shocks and is still in VF. A rectal temperature of 29.5°C is taken with a low-reading thermometer.
Which of the following statements about his resuscitation is correct?Your Answer: No further DC shocks and no drugs should be given until his core temperature is greater than 30°C
Explanation:The guidelines for the management of cardiac arrest in hypothermic patients published by the UK Resuscitation Council differ slightly from the standard algorithm.
In a patient with a core temperature of less than 30°C, do the following:
If you’re on the shockable side of the algorithm (VF/VT), you should give three DC shocks.
Further shocks are not recommended until the patient has been rewarmed to a temperature of more than 30°C because the rhythm is refractory and unlikely to change.
There should be no drugs given because they will be ineffective.In a patient with a core temperature of 30°C to 35°C, do the following:
DC shocks are used as usual.
Because they are metabolised much more slowly, the time between drug doses should be doubled.Active rewarming and protection against hyperthermia should be given to the patient.
Option e is false because there is insufficient information to determine whether resuscitation should be stopped.
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This question is part of the following fields:
- Physiology
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Question 4
Correct
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A 78-year-old man with a previous history of ischaemic heart disease is admitted to hospital. He is scheduled for a cardiopulmonary exercise test (CPX) before he undergoes an elective abdominal aneurysm repair.
What measurement obtained during a CPX test alone provides the best indication for postoperative mortality?Your Answer: Anaerobic threshold
Explanation:Cardiopulmonary exercise testing (CPX, CPEX, CPET) is a non-invasive testing method used to determine the performance of the heart, lungs and skeletal muscle. It measures the exercise tolerance of the patient.
The parameters measured include:
ECG and ST-segment analysis and blood pressure
Oxygen consumption (VO2)
Carbon dioxide production (VCO2)
Gas flows and volumes
Respiratory exchange ratio (RER)
Respiratory rate
Anaerobic threshold (AT)The anaerobic threshold (AT) is an estimate of exercise ability. Any measurement below 11 ml/kg/min is usually related with an increase in mortality, especially when there is a background of myocardial ischaemia occurring during the test.
Peak VO2 <20 mL/kg with a low AT have a correlation with postoperative complications and a 30 day mortality. The CPX test is used for risk-testing patients prior to surgery to determine the appropriate postoperative care facilities. The V slope measured in CPX testing represents VO2 versus VCO2 relationship. During AT, the ramp of V slope increases, but does not provide a picture of postoperative mortality.
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This question is part of the following fields:
- Clinical Measurement
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Question 5
Correct
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Which of the following causes the right-sided shift of the oxygen haemoglobin dissociation curve?
Your Answer: Chronic iron deficiency anaemia
Explanation:With respect to oxygen transport in cells, almost all oxygen is transported within erythrocytes. There is limited solubility and only 1% is carried as solution. Thus, the amount of oxygen transported depends upon haemoglobin concentration and its degree of saturation.
Haemoglobin is a globular protein composed of 4 subunits. Haem is made up of a protoporphyrin ring surrounding an iron atom in its ferrous state. The iron can form two additional bonds – one is with oxygen and the other with a polypeptide chain.
There are two alpha and two beta subunits to this polypeptide chain in an adult and together these form globin. Globin cannot bind oxygen but can bind to CO2 and hydrogen ions.
The beta chains are able to bind to 2,3 diphosphoglycerate. The oxygenation of haemoglobin is a reversible reaction. The molecular shape of haemoglobin is such that binding of one oxygen molecule facilitates the binding of subsequent molecules.The oxygen dissociation curve (ODC) describes the relationship between the percentage of saturated haemoglobin and partial pressure of oxygen in the blood.
Of note, it is not affected by haemoglobin concentration.Chronic anaemia causes 2, 3 DPG levels to increase, hence shifting the curve to the right
Haldane effect – Causes the ODC to shift to the left. For a given oxygen tension there is increased saturation of Hb with oxygen i.e. Decreased oxygen delivery to tissues.
This can be caused by:
-HbF, methaemoglobin, carboxyhaemoglobin
-low [H+] (alkali)
-low pCO2
-ow 2,3-DPG
-ow temperatureBohr effect – causes the ODC to shifts to the right = for given oxygen tension there is reduced saturation of Hb with oxygen i.e. Enhanced oxygen delivery to tissues. This can be caused by:
– raised [H+] (acidic)
– raised pCO2
-raised 2,3-DPG
-raised temperature -
This question is part of the following fields:
- Physiology And Biochemistry
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Question 6
Incorrect
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From the following electromagnetic waves, which one has the shortest wavelength?
Your Answer: Ultraviolet light
Correct Answer: X rays
Explanation:Electromagnetic waves are categorized according to their frequency or equivalently according to their wavelength. Visible light makes up a small part of the full electromagnetic spectrum.
Electromagnetic waves with shorter wavelengths and higher frequencies include ultraviolet light, X-rays, and gamma rays. Electromagnetic waves with longer wavelengths and lower frequencies include infrared light, microwaves, and radio and televisions waves.
Different electromagnetic waves according to their wavelength from shorter to longer are X-rays, ultraviolet radiations, visible light, infrared radiation, radio waves. X-ray among electromagnetic waves has the shortest wavelength and higher frequency with wavelengths ranging from 10*-8 to 10* -12 and corresponding frequencies.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 7
Incorrect
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In a diagnosis of a compensated respiratory acidosis, which of the following arterial blood gas results is likely to be seen?
Your Answer: pH = 7.34
PaCO2 = 7.2 kPa
HCO3 = 29Correct Answer:
Explanation:During normal tissue metabolism, there is production of CO2 (acid) which is then expired by the lungs. If metabolism switches from aerobic to anaerobic due to a lack of oxygen, the tissues are unable to completely oxidise sugars to CO2. As a consequence, the sugars can only be partially oxidised to lactic acid. Since lactic acid cannot be expired by the lungs, it remains in the circulation leading to metabolic acidosis.
Also, normal tissue metabolism leads to the production of some amount of acid from the breakdown of proteins. These acids are excreted from the body by kidney filtration. Renal failure will therefore results in acidosis after several days.
An increased acidosis stimulates the brain’s respiratory centres to increase the respiratory rate. This lowers the CO2 in the blood, leading to a decrease in its acidity. Renal excretion removes the excess acid, resulting in a normal pH, and a reduced PaCO2 and HCO3.
pH PaCO2 (kPa) HCO3
Compensated respiratory acidosis 7.34 7.2 29
Acute respiratory acidosis 7.25 7.3 22
Compensated metabolic acidosis 7.34 3.6 14
Metabolic acidosis 7.21 5.3 15
Metabolic alkalosis 7.51 5.1 30 -
This question is part of the following fields:
- Pathophysiology
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Question 8
Incorrect
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In the Advanced Life Support algorithm, intravenous epinephrine 1mg every three to five minutes is indicated during in-hospital cardiac arrest due to ventricular fibrillation (VF) following three DC shocks.
Which of the following indicates the most important reason for using epinephrine?Your Answer: Positive inotrope effect
Correct Answer: Preferential distribution of blood to the coronary and cerebral circulation
Explanation:Epinephrine is used for the treatment of cardiac arrest because it causes vasoconstriction via the alpha-adrenergic (?1) receptor. This vasoconstriction increases cerebral and coronary blood flow by increasing mean arterial, aortic diastolic, and cerebral pressures. Furthermore, epinephrine is also a?1 and ?2 adrenoreceptor agonist which shows inotrope, chronotrope, and bronchodilator effects.
– Adrenaline is also used to prolong the duration of action and decrease the systemic toxicity of local anaesthetics.
– Preferred route of adrenaline in patients with cardiac arrest is i.v. followed by intra-osseous and endotracheal -
This question is part of the following fields:
- Pathophysiology
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Question 9
Correct
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A study designed to examine the benefits of adding a new antiplatelet to aspirin after a myocardial infraction. The recorded results give us the percentage of patients that reported myocardial infraction within a three month period. The percentage was 4% and 3% for aspirin and the combination of drugs respectively.
How many further patients needed to be treated in order for one patient to avoid any more heart attacks during 3 months?Your Answer: 100
Explanation:Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.
It can be found as:
NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).
where ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)
So,
ARR= (0.04-0.03)
ARR= 0.01
NNT= 1/0.01
NNT=100
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This question is part of the following fields:
- Statistical Methods
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Question 10
Correct
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Prophylactic antibiotics are required for which of the following procedures?
Your Answer: Appendicectomy
Explanation:Correctly used, antibiotic prophylaxis can reduce
the total use of antibiotics.
There is strong scientific support that antibiotic
prophylaxis reduces the development of infection after:- Operations and endoscopic procedures in the large intestine,
the rectum, and the stomach (including appendectomies and
penetrating abdominal trauma), and after percutaneous endoscopic gastrostomy (PEG) - Cardiovascular surgery, and insertion of pacemakers
- Breast cancer surgery
- Hysterectomy
- Reduction of simple fractures and prosthetic limb surgery
- Complicated surgery for cancer in the ear, nose, and throat
regions - Transrectal biopsy and resection of the prostate (febrile urinary
tract infection and blood poisoning).
In most cases the scientific evidence is inadequate to determine
which type of antibiotic is most effective for antibiotic prophylaxis. - Operations and endoscopic procedures in the large intestine,
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 11
Incorrect
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A 46-year-old woman is listed for clipping of a cerebral aneurysm, following a diagnosis of surgical third nerve palsy.
Which of the following clinical findings correlate with surgical third nerve palsy?Your Answer: Ptosis, anhidrosis and miosis
Correct Answer: Ptosis, inferolateral rotation of globe and mydriasis
Explanation:Ptosis and mydriasis are visible in surgical third nerve palsy, and the eye looks ‘down and out.’ The loss of innervation to all of the major structures supplied by the oculomotor nerve is reflected in these characteristics.
Ptosis is caused by the paralysis of the levator palpebrae superioris in oculomotor nerve palsy. Due to the unopposed actions of the superior oblique and lateral rectus muscles, the eye rotates down and out.
Mydriasis is caused by surgical (compressive) causes of third nerve palsy, which disrupt the parasympathetic pupillomotor fibres on the nerve’s periphery.
Medical (ischaemic) causes of a third nerve palsy, on the other hand, leave the superficial parasympathetic fibres relatively unaffected and the pupil unaffected.
Horner’s syndrome is characterised by ptosis, anhidrosis, and miosis, which are caused by a loss of sympathetic innervation to the tarsal muscle of the upper lid, facial skin, and dilator pupillae, respectively.
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This question is part of the following fields:
- Pathophysiology
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Question 12
Correct
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After a bariatric surgery, average weight loss observed in patients is 18 kg. The standard deviation was found to be 3 kg. What is the percentage of patients that lie between 9 and 27 kg?
Note: Assume that the curve is normally distributed.Your Answer: 99.70%
Explanation:9 & 27 can be obtained by subtracting and adding 9 from the mean. 9 is three times the standard deviation and we know that 99.7% values lie within 3 standard deviations from the mean. We can find the interval for 99.7% to verify in the following way:
For 99.7% confidence interval, you can find the range as follows:
1. Multiply the standard error by 3.
2. Subtract the answer from mean value to get the lower limit.
3. Add the answer obtained in step 1 from the mean value to get the upper limit.
4. The range turns out to be 9-27 kg.
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This question is part of the following fields:
- Statistical Methods
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Question 13
Correct
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You are asked about the relative risk associated with a drug. You happened to have read a report in which the same drug was compared with a placebo and your initial thoughts after reading the study were that the drug will have significant side effects.
What do you expect the value of relative risk to be?Your Answer: Greater than 1
Explanation:Risk ratio (relative risk) compares the probability of an event in an exposed (experimental) group to that of an event in the unexposed (control) group.
A relative risk of 1 suggests that there is no discernible difference in the outcome whether or not it has been exposed.
A relative risk of less than 1 indicates that probability of occurrence of an event is less if there is exposure.
A relative risk of greater than 1 highlights that an event is most likely to occur if it was provided exposure. Since you believe that exposure (the new drug) would have side effects, the value should be greater than 1.
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This question is part of the following fields:
- Statistical Methods
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Question 14
Correct
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A 72-year old man is experiencing a cardiac risk evaluation for the management of obstructive umbilical hernia. Echocardiogram demonstrates an aortic valve area=0.59cm with a pressure of 70mmHg. Five years ago, he had mild myocardial infarction complicated with pulmonary oedema. Now he encounters angina with little exertion.
Which of the following factor is the foremost profoundly weighted using Deysky's cardiac risk scoring system in this case?Your Answer: Aortic stenosis
Explanation:Detsky’s Modified cardiac risk classification system in patients undergoing non-cardiac surgery:
Age more than 70: 05 points
History of myocardial infarction:
Less than 6 months: 10 points
More than 6 months: 5 pointsAngina Pectoris:
Angina with minimal exertion: 10 points
Angina at any level of exertion: 20 points
Pulmonary Oedema:
Within 7 days: 10 points
At any time: 5 pointsSuspected aortic valve stenosis with valve area <0.6cm2: 20 points Arrhythmia: Any rhythm other than sinus or sinus with premature atrial complexes (PACs): 5 points More than 5 premature ventricular contractions: 5 points
Emergency Surgery: 10 points
Deficient general medical condition: 5 pointsRisk classification:
Grade I: 0-15 points = low risk
Grade II: 15-30 points = moderate risk
Grade III: >30 points = high risk -
This question is part of the following fields:
- Pathophysiology
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Question 15
Correct
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Question 16
Correct
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Regarding anti diuretic hormone (ADH), one of the following statements is correct:
Your Answer: Increases the total amount of electrolyte free water in the body
Explanation:The major action of ADH is to increase reabsorption of osmotically unencumbered water from the glomerular filtrate and decreases the volume of urine passed. The osmolarity of urine is increased to a maximum of four times that of plasma (approx. 1200 mOsm/kg) by Increasing water reabsorption.
Chronic water loading, Lithium, potassium deficiency, cortisol and calcium excess, all blunt the action of ADH. This leads to nephrogenic diabetes insipidus.
ADH’s primary site of action is the distal tubule and collecting duct.
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This question is part of the following fields:
- Physiology
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Question 17
Incorrect
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A transport ventilator connected to a size CD oxygen cylinder has a setting of air/oxygen entrainment ratio of 1:1 and a minute volume set at 10 litres/minute.
Which value best approximates to the FiO2?Your Answer: 0.8
Correct Answer: 0.6
Explanation:A nominal volume of 2 litres is contained in a CD cylinder. It has a pressure of 230 bar when full and contains litres 460 L of useable oxygen at STP.
For every 1000 mL 100% oxygen there will be an entrainment of 1000 mL or air (20% oxygen) in an air/oxygen mix.
The average concentration is, therefore, 120/2=60% or 0.6.
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This question is part of the following fields:
- Physiology
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Question 18
Correct
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A 50-year-old male is planned for elective parotidectomy for pleomorphic adenoma. The surgeon intends to use a nerve integrity monitor thus avoiding neuromuscular blockade. Which of the following nerves is liable to injury in parotidectomy?
Your Answer: Facial nerve
Explanation:Parotidectomy is basically an anatomical dissection. Identification of the facial nerve trunk is essential during parotid gland surgery because facial nerve injury is the most daunting potential complication of parotid gland surgery owing to the close relation between the gland and the extratemporal course of the facial nerve. After exiting the stylomastoid foramen, the facial nerve enters the substance of the parotid gland and then gives off five terminal branches:
From superior to inferior, these are the:
– Temporal branch supplying the extrinsic ear muscles, occipitofrontalis and orbicularis oculi
– Zygomatic branch supplying orbicularis oculi
– Buccal branch supplying buccinator and the lip muscles
– Mandibular branch supplying the muscles of the lower lip and chin
– Cervical branch supplying platysma.There are two approaches to identify the facial nerve trunk during parotidectomy—conventional antegrade dissection of the facial nerve, and retrograde dissection. Numerous soft tissue and bony landmarks have been proposed to assist the surgeon in the early identification of this nerve. Most commonly used anatomical landmarks to identify facial nerve trunk are stylomastoid foramen, tympanomastoid suture (TMS), posterior belly of digastric (PBD), tragal pointer (TP), mastoid process and peripheral branches of the facial nerve.
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This question is part of the following fields:
- Anatomy
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Question 19
Incorrect
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Which of the following statements is true about fluid balance?
Your Answer: The microvascular endothelium separating interstitial fluid from the intravascular compartment is freely permeable to water
Correct Answer: After intravenous administration of crystalloids, the distribution of these fluids throughout the body depends on its osmotic activity
Explanation:When there is capillary leakage as seen in dependent oedema or ascites, oncotic pressure becomes a problem.
The intracellular sodium concentration is very sensitive to the extracellular sodium concentrations. When there is an imbalance, osmosis occurs resulting in shifts in water between the two compartments.
The microvascular endothelium relies upon osmosis and other processes as it is not freely permeable to water.
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This question is part of the following fields:
- Physiology
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Question 20
Incorrect
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Regarding renal autoregulation, which of the following best describes its process?
Your Answer: The principal alteration is to the diameter of the efferent arterioles
Correct Answer: Reduces the effect of changes in arterial blood pressure on renal Na+ excretion
Explanation:Two mechanisms are responsible for autoregulation of RBF and GFR: one mechanism that responds to changes in arterial pressure and another that responds to changes in [NaCl] in tubular fluid. Both regulate the tone of the afferent arteriole. The pressure-sensitive mechanism, the so-called myogenic mechanism, is related to an intrinsic property of vascular smooth muscle: the tendency to contract when stretched. Accordingly, when arterial pressure rises and the renal afferent arteriole is stretched, the smooth muscle contracts in response. Because the increase in resistance of the arteriole offsets the increase in pressure, RBF, and therefore GFR, remains constant.
The second mechanism responsible for autoregulation of GFR and RBF is the [NaCl]-dependent mechanism known as tubuloglomerular feedback. This mechanism involves a feedback loop in which a change in GFR leads to alteration in the concentration of NaCl in tubular fluid, which is sensed by the macula densa of the juxtaglomerular apparatus and converted into signals that affect afferent arteriolar resistance and thus the GFR (Fig. 33.19). For example, when the GFR increases and causes [NaCl] in tubular fluid in the loop of Henle to rise, more NaCl enters the macula densa cells in this segment (Fig. 33.20). This leads to an increase in formation and release of adenosine triphosphate (ATP) and adenosine (a metabolite of ATP) by macula densa cells, which causes vasoconstriction of the afferent arteriole and normalization of GFR. In contrast, when GFR and [NaCl] in tubule fluid decrease, less NaCl enters the macula densa cells, and both ATP and adenosine production and release decline. The fall in [ATP] and [adenosine] results in afferent arteriolar vasodilation, which returns GFR to normal. NO, a vasodilator produced by the macula densa, attenuates tubuloglomerular feedback, whereas angiotensin II enhances tubuloglomerular feedback. Thus the macula densa may release both vasoconstrictors (e.g., ATP and adenosine) and a vasodilator (e.g., NO) that oppose each other’s action at the level of the afferent arteriole. Production plus release of either vasoconstrictors or vasodilators ensures exquisite control over tubuloglomerular feedback.
Renal autoregulation, thus, reduces the effect of changes in arterial blood pressure on renal sodium excretion.
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This question is part of the following fields:
- Pathophysiology
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Question 21
Incorrect
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The biochemical assessment of malnutrition can be measured by the amount of plasma proteins.
In acute starvation, which of these plasma proteins is the most sensitive indicator?Your Answer: Fibronectin
Correct Answer: Retinol binding globulin
Explanation:The half life of Retinol binding protein (RBP) is 10-12 hours and therefore reflects more acute changes in protein metabolism than any of these proteins. Therefore it is not commonly used as a parameter for nutritional assessment.
The half life of Transthyretin (thyroxine binding pre-albumin) is only one to two days and so levels are less sensitive and this protein is not an albumin precursor. 15 mg/dL represents early malnutrition and a need for nutritional support.
Albumin levels have been frequently as a marker of nutrition but this is not a very sensitive marker. It’s half life more than 30 days and significant change takes some time to be noticed. Also, synthesis of albumin is decreased with the onset of the stress response after burns. Unrelated to nutritional status, the synthesis of acute phase proteins increases and that of albumin decreases.
A more accurate indicator of protein stores is transferrin. It’s response to acute changes in protein status is much faster. The half life of serum transferrin is shorter (8-10 days) and there are smaller body stores than albumin. A low serum transferrin level is below 200 mg/dL and below 100 mg/dL is considered severe. Serum transferrin levels can also affect serum transferrin level.
Fibronectin is used a nutritional marker but levels decrease after seven days of starvation. It is a glycoprotein which plays a role in enhancing the phagocytosis of foreign particles.
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This question is part of the following fields:
- Physiology
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Question 22
Incorrect
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All of the following statements about dopamine are FALSE except:
Your Answer: When given as an infusion dopamine reduces the progression to renal failure.
Correct Answer:
Explanation:Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic ? and ?1 (but not ?2 )agonist.
The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of DA dilates these vessels (by raising intracellular cyclic adenosine monophosphate).
Moderately high doses produce a positive inotropic (direct ?1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.
Vasoconstriction (?1 action) occurs only when large doses are infused.
At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular ? and ? receptors; does not penetrate the blood-brain barrier – no Central nervous system effects.
Dopamine is less arrhythmogenic than adrenaline
Regarding dopamine part of the dose is converted to Noradrenaline in sympathetic nerve terminals.
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This question is part of the following fields:
- Pharmacology
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Question 23
Correct
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Ondansetron is serotonin antagonist indicated for post-operative nausea and vomiting.
In which of the following anatomic structures does ondansetron produce its effects?Your Answer: Nucleus tractus solitarius
Explanation:Ondansetron is a serotonin antagonist at the 5HT3 receptor. 5HT3 receptors in the gastrointestinal tract and in the vomiting centre of the medulla participate in the vomiting reflex. They are particularly important in vomiting caused by chemical triggers such as cancer chemotherapy drugs.
The nucleus solitarius is the recipient of all visceral afferents, and an essential part of the regulatory centres of the internal homeostasis, through its multiple projections with cardiorespiratory and gastrointestinal regulatory centres. It participates in the reflexes of the nerves innervating the nucleus, so it mediates cough reflex, carotid sinus reflex, gag reflex, and vomiting reflex.
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This question is part of the following fields:
- Pharmacology
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Question 24
Incorrect
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A 23-year-old man who is currently on fluoxetine for depression was anaesthetized two hours ago for knee arthroscopy. He seems agitated, confused, with a heart rate of 120 beats per minute, a temperature of 38.2oC, and developed difficulty moving his limbs.
He is on paracetamol and tramadol for analgesia. Which of the following is the most likely cause for his condition?Your Answer: Neuroleptic malignant syndrome
Correct Answer: Tramadol
Explanation: -
This question is part of the following fields:
- Pharmacology
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Question 25
Correct
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A single intravenous dose of 100 mg phenytoin was administered to a 70 kg patient and plasma concentration monitored.
The concentration in plasma over time is recorded as follows:
Time (hours) 1 2 3 4 5
Concentration (mcg/mL) 100 71 50 35.5 25
From the data available, the drug is likely eliminated by?Your Answer: First-order kinetics with a half-life of 2 hours
Explanation:Elimination of phenytoin from the body follows first-order kinetics. This means that the rate of elimination is proportional to plasma concentration.
The rate of elimination can be described by the equation:
C = C0·e-kt
Where:
C = drug concentration
C0 = drug concentration at time zero (extrapolated)
k = Rate constant
t = TimeEnzyme systems become saturated when phenytoin concentrations exceed the normal range and elimination of the drug becomes zero-order. At this point, the drug is metabolised at a fixed rate and metabolism is independent of plasma concentration.
Aspirin and ethyl alcohol are other drugs that behave this way.
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This question is part of the following fields:
- Pharmacology
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Question 26
Correct
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Which of the statements below best describe the total cerebral flow (CBF) in an adult?
Your Answer: Accounts for 15% of the cardiac output
Explanation:While the brain only weighs 3% of the body weight, 15% of the cardiac output goes towards the brain.
Between mean arterial pressures (MAP) of 60-130 mmHg, autoregulation of cerebral blood flow (CBF) occurs. Exceeding this, the CBF is maintained at a constant level. This is controlled mainly by the PaCO2 level, and the autonomic nervous system has minimal role.
Beyond these limits, the CBF is directly proportional to the MAP, not the systolic blood pressure.
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This question is part of the following fields:
- Physiology
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Question 27
Incorrect
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Bacteria and viruses that are smaller than 0.1 ?m in diameter can be filtered out using heat and moisture exchanger (HME) with a typical pore size 0.2 ?m.
Choose the most appropriate mechanisms of particle capture for most bacteria and viruses.Your Answer: Sieve
Correct Answer: Diffusion
Explanation:Warming, humidifying, and filtering inspired anaesthetic gases is done by heat and moisture exchangers (HME) and breathing system filters. They are made of glass fibres materials and are supported by a sturdy frame. Pleating increases the surface area to reduce resistance to air flow and boost efficiency.
Filters’ effectiveness is determined by the amount and size of particles they keep out of the patient’s airway. The efficiency of filters might be classified as 95, 99.95, or 99.97 percent. Pores with a diameter of 0.2 µm are common. The following are examples of typical particle sizes:
Red blood cell – 5 µm
Lymphocyte – 5-8 µm
Viruses – 0.02-0.3 µm
Bacteria – 0.5-1 µm
Depending on particle size, gas flow speed, and charge, particles are collected via a number of processes. Mechanical sieve, interception, diffusion, electrostatic filtration, and inertial impaction are some of the options:Sieve:
The diameter of the particle the filter is supposed to collect is smaller than the apertures of the filter’s fibres.Interception:
When a particle following a gas streamline approaches a fibre within one radius of itself, it becomes attached and captured.
Diffusion:A particle’s random (Brownian) zig-zag path or motion causes it to collide with a fibre.
By attracting and capturing a particle from within the gas flow, it generates a lower-concentration patch within the gas flow into which another particle diffuses, only to be captured. At low gas velocities and with smaller particles (0.1µm diameter), this is more common.Electrostatic:
These filters use large diameter fibre media and rely on electrostatic charges to improve fine particle removal effectiveness.
Impaction due to inertia:
When a particle is too large to respond fast to abrupt changes in streamline direction near a filter fibre, this happens. Because of its inertia, the particle will continue on its original course and collide with the filter fibre. When high gas velocities and dense fibre packing of the filter media are present, this sort of filtration mechanism is most prevalent.
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This question is part of the following fields:
- Anaesthesia Related Apparatus
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Question 28
Incorrect
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Which statement is true with regards to the cardiac action potential?
Your Answer: Opening of fast sodium channels with large influx of sodium initiates rapid repolarisation
Correct Answer: Repolarization due to potassium efflux after calcium channels close causes the relative refractory period to start
Explanation:Cardiac conduction
Phase 0 – Rapid depolarization. Opening of fast sodium channels with large influx of sodium
Phase 1 – Rapid partial depolarization. Opening of potassium channels and efflux of potassium ions. Sodium channels close and influx of sodium ions stop
Phase 2 – Plateau phase with large influx of calcium ions. Offsets action of potassium channels. The absolute refractory period
Phase 3 – Repolarization due to potassium efflux after calcium channels close. Relative refractory period
Phase 4 – Repolarization continues as sodium/potassium pump restores the ionic gradient by pumping out 3 sodium ions in exchange for 2 potassium ions coming into the cell. Relative refractory period
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This question is part of the following fields:
- Physiology And Biochemistry
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Question 29
Correct
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Which type of epithelium lines the luminal surface of the oesophagus?
Your Answer: Non keratinised stratified squamous epithelium
Explanation:Normally, the oesophagus is lined by non-keratinized stratified squamous epithelium. This epithelium can undergo metaplasia and convert to the columnar epithelium (stomach’s lining) in long-standing GERD that leads to Barret’s oesophagus.
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This question is part of the following fields:
- Anatomy
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Question 30
Incorrect
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An 80-year-old female presents to the emergency department with symptoms consistent with mesenteric ischemia. She is quickly shifted to the operation theatre for an emergency laparotomy.
On exploration, the segment of the colon from the splenic flexure down to the rectum is ischemic.
The artery blocked in this scenario arises at what vertebral level from the aorta?Your Answer: L1
Correct Answer: L3
Explanation:The hindgut is from the distal third of the transverse colon down to the upper one-third of the anal canal. The inferior mesenteric artery supplies the hindgut.
The inferior mesenteric artery arises from the aorta behind the inferior border of the third part of the duodenum 3–4 cm above the aortic bifurcation, at the third lumbar vertebra level.
The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:
T12 – Coeliac trunk
L1 – Left renal artery
L2 – Testicular or ovarian arteries
L3 – Inferior mesenteric artery
L4 – Bifurcation of the abdominal aorta
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This question is part of the following fields:
- Anatomy
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