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  • Question 1 - A 26-year-old female patient had the following blood report: RBC count =...

    Incorrect

    • A 26-year-old female patient had the following blood report: RBC count = 4. 0 × 106/μl, haematocrit = 27% and haemoglobin = 11 g/dl, mean corpuscular volume (MCV) = 90 fl, mean corpuscular haemoglobin concentration (MCHC) = 41 g/dl. Further examination of blood sample revealed increased osmotic fragility of the erythrocytes. Which of the following is the most likely cause of this patient’s findings?

      Your Answer: Thalassaemia

      Correct Answer: Spherocytosis

      Explanation:

      Spherocytes are small rounded RBCs. It is due to an inherited defect of the RBC cytoskeleton membrane tethering proteins. Membrane blebs form that are lost over time and cells become round instead of biconcave. As it is a normochromic anaemia, the MCV is normal. it is diagnosed by osmotic fragility test which reveals increased fragility in a hypotonic solution.

    • This question is part of the following fields:

      • General
      • Physiology
      29.9
      Seconds
  • Question 2 - What will the destruction of endoplasmic reticulum stop? ...

    Correct

    • What will the destruction of endoplasmic reticulum stop?

      Your Answer: Synthesis of proteins

      Explanation:

      The rough endoplasmic reticulum is the factory for the manufacturing of proteins. It contains ribosomes attached to it and transports proteins that are destined for membranes and secretions. The rough ER is connected to the nuclear envelope and to the cisternae of the Golgi apparatus by vesicles that shuttle between the two compartments.

    • This question is part of the following fields:

      • General
      • Physiology
      6.1
      Seconds
  • Question 3 - A 38-year-old woman with end-stage renal disease, is undergoing haemodialysis. She has normocytic...

    Correct

    • A 38-year-old woman with end-stage renal disease, is undergoing haemodialysis. She has normocytic normochromic anaemia. What is the best treatment for her?

      Your Answer: Erythropoietin

      Explanation:

      E erythropoietin (EPO) is a hormone that is released by the kidney. It is responsible for the regulation of red blood cell production in the body. It can be made using recombinant technology and is used in the treatment of anaemia of chronic renal failure and in patients under going chemotherapy

    • This question is part of the following fields:

      • General
      • Physiology
      7.1
      Seconds
  • Question 4 - Which statement is correct regarding coagulation? ...

    Correct

    • Which statement is correct regarding coagulation?

      Your Answer: Thrombin converts fibrinogen to fibrin

      Explanation:

      Coagulation of blood is a complex process and an important part of haemostasis. There are two main pathways related to coagulation: the contact activation pathway/intrinsic pathway and tissue factor/extrinsic pathway. The extrinsic pathway is activated by external trauma that causes blood to escape from the vascular system. This pathway is quicker than the intrinsic pathway and involves factor VII. The intrinsic pathway is activated by trauma inside the vascular system, and initiated by platelets, exposed endothelium, chemicals, or collagen. This pathway is slower than the extrinsic pathway, but more important. It involves factors XII, XI, IX, VIII. Both pathways meet to finish the formation of a clot in what is known as the common pathway. The common pathway involves factors I, II, V, and X. They converge on the common pathway in which activation of prothrombin to thrombin leads to conversion of fibrinogen to fibrin and clot formation.

    • This question is part of the following fields:

      • General
      • Physiology
      20.2
      Seconds
  • Question 5 - A 60 year old patient with a history of carcinoma of the head...

    Correct

    • A 60 year old patient with a history of carcinoma of the head of the pancreas, and obstructive jaundice presents with a spontaneous nose bleed and easy bruising. What is the most likely reason for this?

      Your Answer: Vitamin-K-dependent clotting factors deficiency

      Explanation:

      Vitamin K is a fat soluble vitamin requiring fat metabolism to function properly to allow for its absorption. People with obstructive jaundice develop vitamin k deficiency as fat digestion is impaired. Vit K causes carboxylation of glutamate residue and hence regulates blood coagulation including: prothrombin (factor II), factors VII, IX, X, protein C, protein S and protein Z.

    • This question is part of the following fields:

      • General
      • Physiology
      12.2
      Seconds
  • Question 6 - Skeletal muscle fibres are divided into two basic types, type I (slow-twitch fibres)...

    Correct

    • Skeletal muscle fibres are divided into two basic types, type I (slow-twitch fibres) and type II (fast-twitch fibres). Fast muscle fibres do which of the following:

      Your Answer: Use anaerobic metabolism

      Explanation:

      Skeletal muscles are divided into two types:

      1) type I also known as the slow twitch fibres. They use oxygen for their metabolism and as a result they have a high endurance potential. To support this they have abundant mitochondria and myoglobin, so they appear red/dark.

      2) type II fibres also called fast twitch fibres, are low endurance fibres used during anaerobic metabolism. They are required for short bursts of strength and cannot sustain contractions for long periods of time.

    • This question is part of the following fields:

      • General
      • Physiology
      6.6
      Seconds
  • Question 7 - A 26-year-old female patient had the following blood report: RBC count = 4....

    Correct

    • A 26-year-old female patient had the following blood report: RBC count = 4. 0 × 106/μl, haematocrit = 27% and haemoglobin = 11 g/dl, mean corpuscular volume (MCV) = 80–100 fl, mean corpuscular haemoglobin concentration (MCHC) = 31–37 g/dl. Which of the following is correct regarding this patient’s erythrocytes:

      Your Answer: Normal MCV

      Explanation:

      MCV is the mean corpuscular volume and it is calculated from the haematocrit and the RBC count. It is normally 90 fl. Mean corpuscular haemoglobin concentration (MCHC) [g/dl] = haemoglobin [g/dl]/haematocrit = 11/0.27 = 41 g/dl and is higher than normal range (32 to 36 g/dL).

    • This question is part of the following fields:

      • General
      • Physiology
      19.8
      Seconds
  • Question 8 - what is the cause of a prolonged PT(prothrombin time)? ...

    Incorrect

    • what is the cause of a prolonged PT(prothrombin time)?

      Your Answer: Heparin therapy

      Correct Answer: Liver disease

      Explanation:

      PT measure the intrinsic pathway of coagulation. It determines the measure of the warfarin dose regime, liver disease and vit K deficiency status along with the clotting tendency of blood. PT measured factors are II,V,VII,X and fibrinogen. It is used along with aPTT which measure the intrinsic pathway.

    • This question is part of the following fields:

      • General
      • Physiology
      3.1
      Seconds
  • Question 9 - A 50 year old man on warfarin therapy following insertion of a pacemaker...

    Incorrect

    • A 50 year old man on warfarin therapy following insertion of a pacemaker presented with epistaxis. Which of the following is true regarding blood coagulation?

      Your Answer: von Willebrand factor suppresses platelet adhesion

      Correct Answer: Patients with haemophilia A usually have a normal bleeding time

      Explanation:

      A prolonged bleeding time is seen in platelet disorders like thrombocytopenia. Patients with haemophilia A or B have a prolonged PTT but not a prolonged bleeding time.

      Ca2+ is necessary for coagulation.

      von Willebrand factor is an important part of the factor VIII complex and promotes platelet adhesion and aggregation.

      DIC results in depleted coagulation factors and accumulation of fibrin.

    • This question is part of the following fields:

      • General
      • Physiology
      43.5
      Seconds
  • Question 10 - A 50 year old man was admitted to the surgical ICU following a...

    Incorrect

    • A 50 year old man was admitted to the surgical ICU following a hemicolectomy for carcinoma of the caecum. A full blood count revealed: haematocrit = 30%, erythrocytes = 4 × 106/μ, haemoglobin level = 8 g/dl. To determine the likely cause of his anaemia, red blood cell indices were calculated. Which RBC indices are correct?

      Your Answer: MCV = haemoglobin concentration/haematocrit

      Correct Answer: MCHC = haemoglobin concentration/haematocrit

      Explanation:

      Mean corpuscular haemoglobin concentration (MCHC) is calculated simply by dividing the haemoglobin concentration (8 g/dl) by the haematocrit (0.3). The normal range is 31–36 g/dl. This patient has a hypochromic anaemia (MCHC = 8/0.3 = 26.7 g/dl). Dividing the haemoglobin concentration × 10 by erythrocyte number yields mean corpuscular haemoglobin (MCH). Normal range is 25.4–34.6 pg/cell and this patient has a significantly reduced cellular haemoglobin content (MCH = 8 × 10/4 = 20 pg/cell). Mean corpuscular volume (MCV) is calculated by dividing haematocrit × 1000 by erythrocyte number (4 × 106/μl). Normal range is 80–100 fl and this patient has a microcytic anaemia (MCV = 0.3 × 1000/4 = 75 fl). Microcytic, hypochromic anaemia is characteristic for iron-deficiency.

    • This question is part of the following fields:

      • General
      • Physiology
      39.6
      Seconds
  • Question 11 - An experiment was conducted in which the skeletal muscle protein (not smooth muscle)...

    Incorrect

    • An experiment was conducted in which the skeletal muscle protein (not smooth muscle) involved in contraction was selectively inhibited. Which protein was inhibited?

      Your Answer: Actin

      Correct Answer: Troponin

      Explanation:

      The mechanism of contraction of smooth muscles is different from that of skeletal muscles in which the contractile protein is troponin whilst in smooth muscle contraction is a protein called calmodulin. Calmodulin reacts with calcium ions and stimulates the formation of myosin crossbridges.

    • This question is part of the following fields:

      • General
      • Physiology
      28.4
      Seconds
  • Question 12 - A 47 year-old woman was admitted for elective cholecystectomy, with a past...

    Correct

    • A 47 year-old woman was admitted for elective cholecystectomy, with a past history of easy bruising and heavy menstrual periods. The patient was also diagnosed with Willebrand's disease. Willebrand's disease is:

      Your Answer: Autosomal dominant

      Explanation:

      von Willebrand disease is an autosomal dominant disorder marked by the deficiency of vWF, a large protein synthesized by the endothelial cells and megakaryocytes. It mediates adhesion of platelets to the subendothelium at site of vascular injury. Disease characteristics include impaired platelet adhesion, prolonged bleeding time and a functional deficiency of factor VIII (vWF is its carrier protein).

    • This question is part of the following fields:

      • General
      • Physiology
      9.6
      Seconds
  • Question 13 - Electrophoresis is used to detect antibodies (immunoglobulins) in a blood sample from the...

    Correct

    • Electrophoresis is used to detect antibodies (immunoglobulins) in a blood sample from the umbilical artery of a new born. Which antibodies have the highest percentage in a new-born?

      Your Answer: IgG

      Explanation:

      IgG is a monomeric immunoglobulin. It is formed by two heavy chains and two light chains and has two binding sites. Its is the most abundant antibody that is equally distributed in the blood and the tissues. It is the only antibody that can pass through the placenta and thus the only antibody present in the baby after it is born. There are four subclasses: IgG1 (66%), IgG2 (23%), IgG3 (7%) and IgG4 (4%). IgG1, IgG3 and IgG4 cross the placenta easily

    • This question is part of the following fields:

      • General
      • Physiology
      9
      Seconds
  • Question 14 - Which of the following organelles have the capacity to regenerate and spontaneously replicate?...

    Correct

    • Which of the following organelles have the capacity to regenerate and spontaneously replicate?

      Your Answer: Mitochondrion

      Explanation:

      A mitochondria is a membrane bound organelle found in eukaryotic cells. They are called the powerhouse of the cell and are the place where ATP is formed from energy generated through metabolism. They are capable of replication as well as repair and regeneration.

    • This question is part of the following fields:

      • General
      • Physiology
      4.1
      Seconds
  • Question 15 - A 50 year old woman presented with excessive bleeding after an inguinal hernia...

    Correct

    • A 50 year old woman presented with excessive bleeding after an inguinal hernia repair. Labs are suggestive of a primary haemostasis defect. Deficiency of which of the following is most likely to cause it?

      Your Answer: Platelets

      Explanation:

      Primary haemostatic control means the first line of defence against immediate bleeding. This is carried out by the platelets. They immediately form a haemostatic plug at the site of injury. Coagulation starts within 20s after an injury to the blood vessel which damage the endothelial cells. Secondary haemostasis follows which includes activation of the coagulation factors to form fibrin strands which mesh together forming the platelet plug. Platelets interact with platelet collagen receptor, glycoprotein Ia/IIa and to collagen fibres in the vascular endothelium. This adhesion is mediated by von Willebrand factor (vWF), which forms links between the platelet glycoprotein Ib/IX/V and collagen fibrils. The platelets are then activated and release the contents of their granules into the plasma, in turn activating other platelets and white blood cells.

    • This question is part of the following fields:

      • General
      • Physiology
      25.1
      Seconds
  • Question 16 - Selective destruction of which of the following cells will affect antibody synthesis? ...

    Incorrect

    • Selective destruction of which of the following cells will affect antibody synthesis?

      Your Answer: T lymphocytes

      Correct Answer: Plasma cells

      Explanation:

      Plasma cell are memory cells. After the antigen Is engulfed by the B cells it is presented to the CD4+ helper cells via the MCH II receptor and this leads to their activation which in turn stimulates the B cells to form antibodies against that specific antigen. Some B cells differentiate into plasma cells also called memory cells that get activated after subsequent infection.

    • This question is part of the following fields:

      • General
      • Physiology
      13.6
      Seconds
  • Question 17 - A 25 year old man presented with a history of headache and peripheral...

    Correct

    • A 25 year old man presented with a history of headache and peripheral cyanosis. He had been living in the Himalayas for 6 months prior to this. What is the reason for his condition?

      Your Answer: Physiological polycythaemia

      Explanation:

      Polycythaemia is a condition that results in an increase in the total number of red blood cells (RBCs) in the blood. It can be due to myeloproliferative syndrome or due to chronically low oxygen levels or rarely malignancy. In primary polycythaemia/polycythaemia vera the increase is due to an abnormality in the bone marrow, resulting in increases RBCs, white blood cells (WBCs) and platelets. In secondary polycythaemia the increase occurs due to high levels of erythropoietin either artificially or naturally. The increase is about 6-8 million/cm3 of blood. A type of secondary polycythaemia is physiological polycythaemia where people living in high altitudes who are exposed to hypoxic conditions produce more erythropoietin as a compensatory mechanism for thin oxygen and low oxygen partial pressure.

    • This question is part of the following fields:

      • General
      • Physiology
      23
      Seconds
  • Question 18 - Atractyloside is an inhibitor of electron transport chain. It is expected to have...

    Correct

    • Atractyloside is an inhibitor of electron transport chain. It is expected to have little or no effect on the functioning of which of the following cell types?

      Your Answer: Red blood cells

      Explanation:

      Electron transport chain is a series of electron carriers that are embedded in the mitochondrial membrane. It is the place where ATP is made. Inhibiting the electron transport chain will stop production of ATP. Red blood cells are the only cell in the given option which do not contain ATP.

    • This question is part of the following fields:

      • General
      • Physiology
      5.4
      Seconds
  • Question 19 - Signals pass through neuromuscular junctions via the neurotransmitter acetylcholine. After release from the...

    Correct

    • Signals pass through neuromuscular junctions via the neurotransmitter acetylcholine. After release from the skeletal neuromuscular junction, acetylcholine:

      Your Answer: Causes postsynaptic depolarisation

      Explanation:

      Acetylcholine is released from the presynaptic membrane into the cleft where it binds to the ion gated channels on the post synaptic membrane, causing them to open. This results in sodium entering into the fibre and further depolarizing it, creating an action potential.

    • This question is part of the following fields:

      • General
      • Physiology
      6.7
      Seconds
  • Question 20 - Where is factor VIII predominantly synthesised? ...

    Correct

    • Where is factor VIII predominantly synthesised?

      Your Answer: Vascular endothelium

      Explanation:

      Factor VIII is an important part of the coagulation cascade. Deficiency causes haemophilia A. It is synthesised predominantly by the vascular endothelium and is not affected by liver disease. In the circulation it is bound to von Willebrand factor and it forms a stable complex with it. It is activated by thrombin or factor Xa and acts as a co factor to factor IXa to activate factor X which is a co factor to factor Va. Thrombin cleaves fibrinogen in fibrin and forms a meshwork to trap RBC and platelets to form a clot.

    • This question is part of the following fields:

      • General
      • Physiology
      6.1
      Seconds
  • Question 21 - A young women following a road traffic accident suffered heavy blood loss and...

    Correct

    • A young women following a road traffic accident suffered heavy blood loss and developed subsequent anaemia. Which of the following is a consequence of this?

      Your Answer: A high reticulocyte count

      Explanation:

      Anaemia refers to a decrease in the circulating levels of haemoglobin in the blood resulting in a reduced ability of the body to transport oxygen effectively. Anaemia from blood loss results in the body further compensating by releasing stored RBCs and immature RBCs from the bone marrow. Thus resulting in a high reticulocyte count.

    • This question is part of the following fields:

      • General
      • Physiology
      22.8
      Seconds
  • Question 22 - Which of the following cytokines produced by the T cell induce MHC-II proteins?...

    Correct

    • Which of the following cytokines produced by the T cell induce MHC-II proteins?

      Your Answer: γ-Interferon

      Explanation:

      Interferons elicit a non-specific antiviral activity by inducing specific RNA synthesis and expression of proteins in neighbouring cells. Common interferon inducers are viruses, double-stranded RNA and micro-organisms. INF-γ is produced mainly by CD4+, CD8+ T cells and less commonly by B cells and natural killer cells. INF-γ has antiviral and antiparasitic activity but its main biological activity appears to be immunomodulatory. Among its many functions are activation of macrophages and enhanced expression of MHC-II proteins or macrophages.

    • This question is part of the following fields:

      • General
      • Physiology
      2.6
      Seconds
  • Question 23 - A patient came into the emergency in a state of shock. His blood...

    Incorrect

    • A patient came into the emergency in a state of shock. His blood group is not known, but on testing it clotted when mixed with Type A antibodies. Which blood should be transfused?

      Your Answer: A +ve

      Correct Answer: B +ve

      Explanation:

      There are two stages to determine the blood group, known as ABO typing. The first stage is called forward typing. In this method, RBCs are mixed with two separate solutions of type A or type B antibodies to see if they agglutinate. If this blood clumps, this indicates the presence of antigens within the blood sample. For example, a sample of type B blood will clump when tested with type A antibodies as it contains type B antigens. Group B – has only the B antigen on red cells (and A antibody in the plasma)

      Group B – has only the B antigen on red cells (and A antibody in the plasma)

      Group AB – has both A and B antigens on red cells (but neither A nor B antibody in the plasma)

      Group O – has neither A nor B antigens on red cells (but both A and B antibody are in the plasma). Many people also have a Rh factor on the red blood cell’s surface. This is also an antigen and those who have it are called Rh+. Those who have not are called Rh–. A person with Rh– blood does not have Rh antibodies naturally in the blood plasma (as one can have A or B antibodies, for instance) but they can develop Rh antibodies in the blood plasma if they receive blood from a person with Rh+ blood, whose Rh antigens can trigger the production of Rh antibodies. A person with Rh+ blood can receive blood from a person with Rh– blood without any problems. The patient’s blood group is B positive as he has antigen B, antibody A and Rh antigens.

    • This question is part of the following fields:

      • General
      • Physiology
      18.3
      Seconds
  • Question 24 - Regarding the coagulation cascade, Factor VII: ...

    Correct

    • Regarding the coagulation cascade, Factor VII:

      Your Answer: Is a serine protease

      Explanation:

      Factor VII (FVII) is a zymogen for a vitamin K-dependent serine protease essential for the initiation of blood coagulation. It is synthesized primarily in the liver and circulates in plasma. Within the liver, hepatocytes are involved in the synthesis of most blood coagulation factors, such as fibrinogen, prothrombin, factor V, VII, IX, X, XI, XII, as well as protein C and S, and antithrombin, whereas liver sinusoidal endothelial cells produce factor VIII and von Willebrand factor.

    • This question is part of the following fields:

      • General
      • Physiology
      35.2
      Seconds
  • Question 25 - Which of the following is a potential cause of a positive D-dimer assay?...

    Incorrect

    • Which of the following is a potential cause of a positive D-dimer assay?

      Your Answer: von Willebrand’s disease

      Correct Answer: Deep venous thrombosis

      Explanation:

      A D-dimer test is performed to detect and diagnose thrombotic conditions and thrombosis. A negative result would rule out thrombosis and a positive result although not diagnostic, is highly suspicious of thrombotic conditions like a deep vein thrombosis, pulmonary embolism as well as DIC.

    • This question is part of the following fields:

      • General
      • Physiology
      12.3
      Seconds
  • Question 26 - The mechanism of action of streptokinase involves: ...

    Incorrect

    • The mechanism of action of streptokinase involves:

      Your Answer: Proteolytic activation of fibrinogen

      Correct Answer: Direct conversion of plasminogen to plasmin

      Explanation:

      Streptokinase is an enzyme that is produced by group A beta haemolytic streptococcus and is an effective and cost efficient method for the dissolution of a clot used in cases of MI and pulmonary embolism. It works by directly converting plasminogen to plasmin which breaks down the blood components in the clot and fibrin, dissolving the clot. Streptokinase is a bacterial product and thus the body will develop immunity against it.

    • This question is part of the following fields:

      • General
      • Physiology
      29.6
      Seconds
  • Question 27 - A teenage Somalian boy presents with a complaint of an enlarged lower jaw....

    Correct

    • A teenage Somalian boy presents with a complaint of an enlarged lower jaw. His blood film shows blast cells and macrophages. Which virus is responsible for this?

      Your Answer: Epstein–Barr virus

      Explanation:

      Burkitt’s lymphoma is a type of non-Hodgkin’s lymphoma. Histologically it is characterised by a starry sky appearance due to numerous neoplastic macrophages which are required to clear the rapidly dividing tumour cells/blast cells. Burkitt’s lymphoma commonly affects the jaw bone, forming a huge tumour mass. It is associated with translocation of c-myc gene and has three types: 1) endemic/African type, 2)sporadic and 3)immunodeficiency-associated. The first type is strongly associated with EBV.

    • This question is part of the following fields:

      • General
      • Physiology
      3.5
      Seconds
  • Question 28 - What is the mostly likely cause of prolonged activated partial thromboplastin time (aPPT)...

    Correct

    • What is the mostly likely cause of prolonged activated partial thromboplastin time (aPPT) ?

      Your Answer: Heparin therapy

      Explanation:

      The partial thromboplastin time (PTT) or activated partial thromboplastin time (aPTT) is an indicator for measuring the efficacy of both the intrinsic and common coagulation pathway. Prolonged aPTT may indicate: use of heparin, antiphospholipid antibody and coagulation factor deficiency (e.g., haemophilia). Deficiencies of factors VIII, IX, XI and XII and rarely von Willebrand factor (if causing a low factor VIII level) may lead to a prolonged aPTT correcting on mixing studies.

    • This question is part of the following fields:

      • General
      • Physiology
      4.2
      Seconds
  • Question 29 - Multiple cells were labelled using a fluorescent dye that doesn’t cross the cell...

    Incorrect

    • Multiple cells were labelled using a fluorescent dye that doesn’t cross the cell membrane. One cell in the middle was bleached with a light that destroys the dye, but the cell soon recovers its stain. The presence of which structures best explains this?

      Your Answer: Tight junctions

      Correct Answer: Gap junctions

      Explanation:

      Gap junctions are attachments between cells that permit intercellular communication e.g. they permit current flow and electrical coupling between myocardial cells. They allow direct electrical transmission among cells and also permit certain substance to pass through as well. They are either homotypic, formed by two identical hemichannels or heterotypic, formed by different hemichannels.

    • This question is part of the following fields:

      • General
      • Physiology
      47
      Seconds
  • Question 30 - Depression of the normal coagulation system and excessive bleeding after surgery can occur...

    Correct

    • Depression of the normal coagulation system and excessive bleeding after surgery can occur in which of the following medical conditions?

      Your Answer: Liver disease

      Explanation:

      As most of the coagulation factors are synthesized in the liver, liver diseases like hepatitis or cirrhosis will depress the coagulation system. Vitamin K deficiency can also decrease the production of vitamin K dependent coagulation factors VII, XI, X and prothrombin.

    • This question is part of the following fields:

      • General
      • Physiology
      17.5
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

General (20/30) 67%
Physiology (20/30) 67%
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